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| 1 | +using LL = long long; |
| 2 | +class Solution { |
| 3 | +public: |
| 4 | + long long subArrayRanges(vector<int>& nums) |
| 5 | + { |
| 6 | + int n = nums.size(); |
| 7 | + |
| 8 | + stack<int>Stack; |
| 9 | + vector<int>nextSmaller(n,n); |
| 10 | + for (int i=0; i<n; i++) |
| 11 | + { |
| 12 | + while (!Stack.empty() && nums[Stack.top()]>nums[i]) |
| 13 | + { |
| 14 | + nextSmaller[Stack.top()] = i; |
| 15 | + Stack.pop(); |
| 16 | + } |
| 17 | + Stack.push(i); |
| 18 | + } |
| 19 | + |
| 20 | + while (!Stack.empty()) Stack.pop(); |
| 21 | + vector<int>prevSmaller(n,-1); |
| 22 | + for (int i=n-1; i>=0; i--) |
| 23 | + { |
| 24 | + while (!Stack.empty() && nums[Stack.top()]>=nums[i]) |
| 25 | + { |
| 26 | + prevSmaller[Stack.top()] = i; |
| 27 | + Stack.pop(); |
| 28 | + } |
| 29 | + Stack.push(i); |
| 30 | + } |
| 31 | + |
| 32 | + while (!Stack.empty()) Stack.pop(); |
| 33 | + vector<int>nextGreater(n,n); |
| 34 | + for (int i=0; i<n; i++) |
| 35 | + { |
| 36 | + while (!Stack.empty() && nums[Stack.top()]<nums[i]) |
| 37 | + { |
| 38 | + nextGreater[Stack.top()] = i; |
| 39 | + Stack.pop(); |
| 40 | + } |
| 41 | + Stack.push(i); |
| 42 | + } |
| 43 | + |
| 44 | + while (!Stack.empty()) Stack.pop(); |
| 45 | + vector<int>prevGreater(n,-1); |
| 46 | + for (int i=n-1; i>=0; i--) |
| 47 | + { |
| 48 | + while (!Stack.empty() && nums[Stack.top()]<=nums[i]) |
| 49 | + { |
| 50 | + prevGreater[Stack.top()] = i; |
| 51 | + Stack.pop(); |
| 52 | + } |
| 53 | + Stack.push(i); |
| 54 | + } |
| 55 | + |
| 56 | + LL ret = 0; |
| 57 | + for (int i=0; i<n; i++) |
| 58 | + { |
| 59 | + int l = prevGreater[i]; |
| 60 | + int r = nextGreater[i]; |
| 61 | + ret += (LL)nums[i]*(i-l)*(r-i); |
| 62 | + } |
| 63 | + for (int i=0; i<n; i++) |
| 64 | + { |
| 65 | + int l = prevSmaller[i]; |
| 66 | + int r = nextSmaller[i]; |
| 67 | + ret -= (LL)nums[i]*(i-l)*(r-i); |
| 68 | + } |
| 69 | + return ret; |
| 70 | + } |
| 71 | +}; |
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