Problem: 1108. Defanging an IP Address

Given a valid (IPv4) IP address, return a defanged version of that IP address.

A defanged IP address replaces every period "." with "[.]".

Example 1:

Input: address = "1.1.1.1"

Output: "1[.]1[.]1[.]1"

Example 2:

Input: address = "255.100.50.0"

Output: "255[.]100[.]50[.]0"

Constraints: The given address is a valid IPv4 address.

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Solution:

class Solution:

def defangIPaddr(self, address: str) -> str:

return address.replace('.', '[.]')

# Below are the 2 possible solutions

# return '[.]'.join(address.split('.'))

# return re.sub('\.', '[.]', address)

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