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| 1 | +package com.fishercoder.solutions; |
| 2 | + |
| 3 | +import com.fishercoder.common.classes.ListNode; |
| 4 | + |
| 5 | +/** |
| 6 | + * 1019. Next Greater Node In Linked List |
| 7 | + * |
| 8 | + * We are given a linked list with head as the first node. Let's number the nodes in the list: node_1, node_2, node_3, ... etc. |
| 9 | + * Each node may have a next larger value: for node_i, next_larger(node_i) is the node_j.val such that j > i, node_j.val > node_i.val, |
| 10 | + * and j is the smallest possible choice. If such a j does not exist, the next larger value is 0. |
| 11 | + * Return an array of integers answer, where answer[i] = next_larger(node_{i+1}). |
| 12 | + * Note that in the example inputs (not outputs) below, arrays such as [2,1,5] represent the serialization of a linked list |
| 13 | + * with a head node value of 2, second node value of 1, and third node value of 5. |
| 14 | + * |
| 15 | + * Example 1: |
| 16 | + * Input: [2,1,5] |
| 17 | + * Output: [5,5,0] |
| 18 | + * |
| 19 | + * Example 2: |
| 20 | + * Input: [2,7,4,3,5] |
| 21 | + * Output: [7,0,5,5,0] |
| 22 | + * |
| 23 | + * Example 3: |
| 24 | + * Input: [1,7,5,1,9,2,5,1] |
| 25 | + * Output: [7,9,9,9,0,5,0,0] |
| 26 | + * |
| 27 | + * Note: |
| 28 | + * 1 <= node.val <= 10^9 for each node in the linked list. |
| 29 | + * The given list has length in the range [0, 10000]. |
| 30 | + * */ |
| 31 | +public class _1019 { |
| 32 | + public static class Solution1 { |
| 33 | + public int[] nextLargerNodes(ListNode head) { |
| 34 | + int len = findLength(head); |
| 35 | + int[] result = new int[len]; |
| 36 | + ListNode tmp = head; |
| 37 | + int i = 0; |
| 38 | + while (tmp != null) { |
| 39 | + result[i++] = findNextLarger(tmp.val, tmp); |
| 40 | + tmp = tmp.next; |
| 41 | + } |
| 42 | + return result; |
| 43 | + } |
| 44 | + |
| 45 | + private int findNextLarger(int val, ListNode head) { |
| 46 | + ListNode tmp = head.next; |
| 47 | + while (tmp != null) { |
| 48 | + if (tmp.val > val) { |
| 49 | + return tmp.val; |
| 50 | + } |
| 51 | + tmp = tmp.next; |
| 52 | + } |
| 53 | + return 0; |
| 54 | + } |
| 55 | + |
| 56 | + private int findLength(ListNode head) { |
| 57 | + ListNode tmp = head; |
| 58 | + int count = 0; |
| 59 | + while (tmp != null) { |
| 60 | + tmp = tmp.next; |
| 61 | + count++; |
| 62 | + } |
| 63 | + return count; |
| 64 | + } |
| 65 | + } |
| 66 | +} |
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