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1 | 1 | package com.fishercoder.solutions;
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2 | 2 |
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| 3 | +import java.util.Deque; |
3 | 4 | import java.util.HashMap;
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| 5 | +import java.util.LinkedList; |
4 | 6 | import java.util.Map;
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5 | 7 | import java.util.Stack;
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6 | 8 |
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7 | 9 | public class _496 {
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8 | 10 |
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9 | 11 | public static class Solution1 {
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10 |
| - public int[] nextGreaterElement(int[] findNums, int[] nums) { |
11 |
| - Stack<Integer> stack = new Stack(); |
| 12 | + public int[] nextGreaterElement(int[] nums1, int[] nums2) { |
| 13 | + int[] ans = new int[nums1.length]; |
| 14 | + Map<Integer, Integer> map = new HashMap<>(); |
| 15 | + for (int i = 0; i < nums2.length; i++) { |
| 16 | + map.put(nums2[i], i); |
| 17 | + } |
| 18 | + for (int i = 0; i < nums1.length; i++) { |
| 19 | + int start = map.get(nums1[i]); |
| 20 | + for (int j = start + 1; j < nums2.length; j++) { |
| 21 | + if (nums2[j] > nums1[i]) { |
| 22 | + ans[i] = nums2[j]; |
| 23 | + break; |
| 24 | + } |
| 25 | + } |
| 26 | + if (ans[i] == 0) { |
| 27 | + ans[i] = -1; |
| 28 | + } |
| 29 | + } |
| 30 | + return ans; |
| 31 | + } |
| 32 | + } |
| 33 | + |
| 34 | + public static class Solution2 { |
| 35 | + /** |
| 36 | + * Use monotonic stack, using a pen and paper to help visualize this is a great help! |
| 37 | + */ |
| 38 | + public int[] nextGreaterElement(int[] nums1, int[] nums2) { |
| 39 | + Deque<Integer> stack = new LinkedList<>(); |
12 | 40 | Map<Integer, Integer> map = new HashMap();
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13 |
| - for (int i = 0; i < nums.length; i++) { |
14 |
| - while (!stack.isEmpty() && nums[i] > stack.peek()) { |
15 |
| - map.put(stack.pop(), nums[i]); |
| 41 | + for (int i = 0; i < nums2.length; i++) { |
| 42 | + while (!stack.isEmpty() && nums2[i] > stack.peekLast()) { |
| 43 | + map.put(stack.pollLast(), nums2[i]); |
16 | 44 | }
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17 |
| - stack.push(nums[i]); |
| 45 | + stack.addLast(nums2[i]); |
18 | 46 | }
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19 | 47 |
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20 | 48 | while (!stack.isEmpty()) {
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21 |
| - map.put(stack.pop(), -1); |
| 49 | + map.put(stack.pollLast(), -1); |
22 | 50 | }
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23 | 51 |
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24 |
| - int[] result = new int[findNums.length]; |
25 |
| - for (int i = 0; i < findNums.length; i++) { |
26 |
| - result[i] = map.get(findNums[i]); |
| 52 | + int[] result = new int[nums1.length]; |
| 53 | + for (int i = 0; i < nums1.length; i++) { |
| 54 | + result[i] = map.get(nums1[i]); |
27 | 55 | }
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28 | 56 | return result;
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29 | 57 | }
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