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package com.chen.algorithm.study.test240;
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/**
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* https://leetcode-cn.com/problems/search-a-2d-matrix-ii/solution/er-fen-fa-pai-chu-fa-python-dai-ma-java-dai-ma-by-/
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*
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* @author : chen weijie
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* @Date: 2019-12-22 14:26
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*/
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public class Solution {
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/**
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* 从左下角开始
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* <p>
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* 如果当前数比目标元素小,当前列就不可能存在目标值,“指针”就向右移一格(纵坐标加 11);
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* 如果当前数比目标元素大,当前行就不可能存在目标值,“指针”就向上移一格(横坐标减 11)。
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*
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* @param matrix
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* @param target
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* @return
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*/
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public boolean searchMatrix(int[][] matrix, int target) {
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int rows = matrix.length;
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if (rows == 0) {
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return false;
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}
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int col = matrix[0].length;
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if (col == 0) {
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return false;
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}
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int x = rows - 1;
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int y = 0;
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int value;
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while (x >= 0 && y < col) {
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value = matrix[x][y];
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if (value > target) {
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x--;
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} else if (value < target) {
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y++;
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} else {
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return true;
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}
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}
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return false;
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}
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}
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package com.chen.algorithm.study.test279;
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/**
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* @author : chen weijie
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* @Date: 2019-12-22 15:13
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*/
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public class Solution {
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int[] memo;
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public int numSquares(int n) {
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memo = new int[n + 1];
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return numSqu(n);
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}
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public int numSqu(int n) {
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if (memo[n] != 0) {
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return memo[n];
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}
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int val = (int) Math.sqrt(n);
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if (val * val == n) {
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return memo[0] = 1;
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}
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int res = Integer.MAX_VALUE;
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for (int i = 1; i * i < n; i++) {
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res = Math.min(res, numSqu(n - i * i) + 1);
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}
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return memo[n] = res;
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}
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}
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package com.chen.algorithm.study.test287;
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import java.util.Arrays;
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/**
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* @author : chen weijie
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* @Date: 2019-12-22 16:22
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*/
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public class Solution {
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public int findDuplicate(int[] nums) {
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Arrays.sort(nums);
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for (int i = 1; i < nums.length; i++) {
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if (nums[i] == nums[i - 1]) {
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return nums[i];
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}
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}
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return -1;
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}
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}
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package com.chen.algorithm.study.test300;
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/**
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* @author : chen weijie
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* @Date: 2019-12-22 16:28
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*/
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public class Solution {
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public int lengthOfLIST(int[] nums) {
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if (nums.length == 0) {
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return 0;
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}
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int max = 1;
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int length = 1;
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int temp = nums[0];
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for (int i = 1; i < nums.length; i++) {
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if (nums[i] > temp) {
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length++;
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max = Math.max(length, max);
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temp = nums[i];
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} else {
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temp = nums[i - 1];
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length = 1;
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}
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}
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return max;
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}
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}

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