diff --git a/ADVANCED SELECT AND JOINS/1204. Last Person to Fit in the Bus.sql b/ADVANCED SELECT AND JOINS/1204. Last Person to Fit in the Bus.sql
new file mode 100644
index 0000000..e69de29
diff --git a/ADVANCED SELECT AND JOINS/1731. The Number of Employees Which Report to Each Employee.sql b/ADVANCED SELECT AND JOINS/1731. The Number of Employees Which Report to Each Employee.sql
index c8c10c9..6e4630e 100644
--- a/ADVANCED SELECT AND JOINS/1731. The Number of Employees Which Report to Each Employee.sql	
+++ b/ADVANCED SELECT AND JOINS/1731. The Number of Employees Which Report to Each Employee.sql	
@@ -1,13 +1,13 @@
-# Write your MySQL query statement below
-SELECT m.employee_id,
-        m.name,
-        count(e.employee_id) AS reports_count,
-        round(avg(e.age)) AS average_age
-FROM
-    employees e JOIN employees m
-ON
-    e.reports_to = m.employee_id
-GROUP BY 
-    employee_id 
-ORDER BY
+# Write your MySQL query statement below
+SELECT m.employee_id,
+        m.name,
+        count(e.employee_id) AS reports_count,
+        round(avg(e.age)) AS average_age
+FROM
+    employees e JOIN employees m
+ON
+    e.reports_to = m.employee_id
+GROUP BY 
+    employee_id 
+ORDER BY
     employee_id;
\ No newline at end of file
diff --git a/ADVANCED SELECT AND JOINS/1789. Primary Department for Each Employee.sql b/ADVANCED SELECT AND JOINS/1789. Primary Department for Each Employee.sql
index 0ffc107..a9f6673 100644
--- a/ADVANCED SELECT AND JOINS/1789. Primary Department for Each Employee.sql	
+++ b/ADVANCED SELECT AND JOINS/1789. Primary Department for Each Employee.sql	
@@ -1,11 +1,11 @@
-# Write your MySQL query statement below
-SELECT employee_id, department_id
-FROM  Employee
-WHERE primary_flag = 'Y'
-    OR
-    employee_id IN (
-        SELECT employee_id
-        FROM Employee
-        GROUP BY employee_id
-        HAVING COUNT(employee_id) = 1
+# Write your MySQL query statement below
+SELECT employee_id, department_id
+FROM  Employee
+WHERE primary_flag = 'Y'
+    OR
+    employee_id IN (
+        SELECT employee_id
+        FROM Employee
+        GROUP BY employee_id
+        HAVING COUNT(employee_id) = 1
     );
\ No newline at end of file
diff --git a/ADVANCED SELECT AND JOINS/180. Consecutive Numbers.sql b/ADVANCED SELECT AND JOINS/180. Consecutive Numbers.sql
index 3ba7866..49ccce5 100644
--- a/ADVANCED SELECT AND JOINS/180. Consecutive Numbers.sql	
+++ b/ADVANCED SELECT AND JOINS/180. Consecutive Numbers.sql	
@@ -1,6 +1,6 @@
--- Write your MySQL/PostgreSQL query statement below
-SELECT DISTINCT l1.num as ConsecutiveNums
-FROM Logs l1
-JOIN Logs l2 ON l1.num = l2.num and l1.id = l2.id + 1
-JOIN Logs l3 ON l2.num = l3.num and l2.id = l3.id + 1;
-
+-- Write your MySQL/PostgreSQL query statement below
+SELECT DISTINCT l1.num as ConsecutiveNums
+FROM Logs l1
+JOIN Logs l2 ON l1.num = l2.num and l1.id = l2.id + 1
+JOIN Logs l3 ON l2.num = l3.num and l2.id = l3.id + 1;
+
diff --git a/ADVANCED SELECT AND JOINS/1907. Count Salary Categories.sql b/ADVANCED SELECT AND JOINS/1907. Count Salary Categories.sql
index 945b33e..8102411 100644
--- a/ADVANCED SELECT AND JOINS/1907. Count Salary Categories.sql	
+++ b/ADVANCED SELECT AND JOINS/1907. Count Salary Categories.sql	
@@ -1,15 +1,15 @@
-SELECT "Low Salary" AS category,
-       sum(income < 20000) AS accounts_count
-  FROM Accounts
-
-UNION
-
-SELECT "Average Salary" AS category,
-       sum(income BETWEEN 20000 AND 50000) AS accounts_count
-  FROM Accounts
-
-UNION
-
-SELECT "High Salary" AS category,
-       sum(income > 50000) AS accounts_count
+SELECT "Low Salary" AS category,
+       sum(income < 20000) AS accounts_count
+  FROM Accounts
+
+UNION
+
+SELECT "Average Salary" AS category,
+       sum(income BETWEEN 20000 AND 50000) AS accounts_count
+  FROM Accounts
+
+UNION
+
+SELECT "High Salary" AS category,
+       sum(income > 50000) AS accounts_count
   FROM Accounts;
\ No newline at end of file
diff --git a/ADVANCED SELECT AND JOINS/610. Triangle Judgement.sql b/ADVANCED SELECT AND JOINS/610. Triangle Judgement.sql
index f667669..68e84c1 100644
--- a/ADVANCED SELECT AND JOINS/610. Triangle Judgement.sql	
+++ b/ADVANCED SELECT AND JOINS/610. Triangle Judgement.sql	
@@ -1,10 +1,10 @@
-# Write your MySQL query statement below
--- Using the triangle inequality:
-
--- x + y > z
--- x + z > y
--- y + z > x
-
-SELECT x, y, z, CASE WHEN (x+y) > z AND (x+z) > y AND (y+z) > x THEN
-'Yes' ELSE 'No' END AS triangle
-FROM Triangle;
+# Write your MySQL query statement below
+-- Using the triangle inequality:
+
+-- x + y > z
+-- x + z > y
+-- y + z > x
+
+SELECT x, y, z, CASE WHEN (x+y) > z AND (x+z) > y AND (y+z) > x THEN
+'Yes' ELSE 'No' END AS triangle
+FROM Triangle;
diff --git a/ADVANCED STRING FUNCTIONS + REGEX + CLAUSE/1517. Find Users With Valid E-Mails.sql b/ADVANCED STRING FUNCTIONS + REGEX + CLAUSE/1517. Find Users With Valid E-Mails.sql
index 89cc677..78a821f 100644
--- a/ADVANCED STRING FUNCTIONS + REGEX + CLAUSE/1517. Find Users With Valid E-Mails.sql	
+++ b/ADVANCED STRING FUNCTIONS + REGEX + CLAUSE/1517. Find Users With Valid E-Mails.sql	
@@ -1,3 +1,3 @@
-# Write your MySQL query statement below
-SELECT * FROM users
-WHERE mail REGEXP '^[a-zA-Z][a-zA-Z0-9_.-]*@leetcode[.]com$';
+# Write your MySQL query statement below
+SELECT * FROM users
+WHERE mail REGEXP '^[a-zA-Z][a-zA-Z0-9_.-]*@leetcode[.]com$';
diff --git a/ADVANCED STRING FUNCTIONS + REGEX + CLAUSE/1667. Fix Names in a Table.sql b/ADVANCED STRING FUNCTIONS + REGEX + CLAUSE/1667. Fix Names in a Table.sql
index 5ba47f2..5dd5ead 100644
--- a/ADVANCED STRING FUNCTIONS + REGEX + CLAUSE/1667. Fix Names in a Table.sql	
+++ b/ADVANCED STRING FUNCTIONS + REGEX + CLAUSE/1667. Fix Names in a Table.sql	
@@ -1,4 +1,4 @@
-# Write your MySQL query statement below
-SELECT user_id, CONCAT(UPPER(LEFT(name, 1)), LOWER(RIGHT(name, LENGTH(name)-1))) AS name
-FROM Users
+# Write your MySQL query statement below
+SELECT user_id, CONCAT(UPPER(LEFT(name, 1)), LOWER(RIGHT(name, LENGTH(name)-1))) AS name
+FROM Users
 ORDER BY user_id;
\ No newline at end of file
diff --git a/BASIC AGGREGATION FUNCTION/1075. Project Employees I.sql b/BASIC AGGREGATION FUNCTION/1075. Project Employees I.sql
index b7856ac..fd4f694 100644
--- a/BASIC AGGREGATION FUNCTION/1075. Project Employees I.sql	
+++ b/BASIC AGGREGATION FUNCTION/1075. Project Employees I.sql	
@@ -1,5 +1,5 @@
--- Write your PostgreSQL query statement below
-SELECT p.project_id, ROUND(AVG(e.experience_years), 2) AS average_years
-FROM Project p
-LEFT JOIN Employee e ON p.employee_id = e.employee_id
-GROUP BY p.project_id;
+-- Write your PostgreSQL query statement below
+SELECT p.project_id, ROUND(AVG(e.experience_years), 2) AS average_years
+FROM Project p
+LEFT JOIN Employee e ON p.employee_id = e.employee_id
+GROUP BY p.project_id;
diff --git a/BASIC AGGREGATION FUNCTION/1251. Average Selling Price.sql b/BASIC AGGREGATION FUNCTION/1251. Average Selling Price.sql
index 520ebc1..7c2bdc2 100644
--- a/BASIC AGGREGATION FUNCTION/1251. Average Selling Price.sql	
+++ b/BASIC AGGREGATION FUNCTION/1251. Average Selling Price.sql	
@@ -1,6 +1,6 @@
-# Write your MySQL query statement below
-SELECT p.product_id, IFNULL(ROUND(SUM(units*price)/SUM(units),2),0) AS average_price
-FROM Prices p LEFT JOIN UnitsSold u
-ON p.product_id = u.product_id AND
-u.purchase_date BETWEEN start_date AND end_date
+# Write your MySQL query statement below
+SELECT p.product_id, IFNULL(ROUND(SUM(units*price)/SUM(units),2),0) AS average_price
+FROM Prices p LEFT JOIN UnitsSold u
+ON p.product_id = u.product_id AND
+u.purchase_date BETWEEN start_date AND end_date
 group by product_id
\ No newline at end of file
diff --git a/BASIC AGGREGATION FUNCTION/1633. Percentage of Users Attended a Contest.sql b/BASIC AGGREGATION FUNCTION/1633. Percentage of Users Attended a Contest.sql
index a7e9500..5c260b0 100644
--- a/BASIC AGGREGATION FUNCTION/1633. Percentage of Users Attended a Contest.sql	
+++ b/BASIC AGGREGATION FUNCTION/1633. Percentage of Users Attended a Contest.sql	
@@ -1,7 +1,7 @@
-# Write your MySQL query statement below
-SELECT contest_id, ROUND((COUNT(DISTINCT user_id)*100)/(
-    SELECT COUNT(user_id) FROM Users
-), 2) AS percentage
-FROM Register
-GROUP BY contest_id
+# Write your MySQL query statement below
+SELECT contest_id, ROUND((COUNT(DISTINCT user_id)*100)/(
+    SELECT COUNT(user_id) FROM Users
+), 2) AS percentage
+FROM Register
+GROUP BY contest_id
 ORDER BY percentage DESC, contest_id;
\ No newline at end of file
diff --git a/BASIC AGGREGATION FUNCTION/620. Not Boring Movies.sql b/BASIC AGGREGATION FUNCTION/620. Not Boring Movies.sql
index d74782f..47b5906 100644
--- a/BASIC AGGREGATION FUNCTION/620. Not Boring Movies.sql	
+++ b/BASIC AGGREGATION FUNCTION/620. Not Boring Movies.sql	
@@ -1,5 +1,5 @@
-# Write your MySQL query statement below
-SELECT id, movie, description, rating
-FROM Cinema
-WHERE MOD(id, 2) <> 0 AND description <> "boring"
+# Write your MySQL query statement below
+SELECT id, movie, description, rating
+FROM Cinema
+WHERE MOD(id, 2) <> 0 AND description <> "boring"
 ORDER BY rating DESC;
\ No newline at end of file
diff --git a/BASIC JOIN/1068. Product Sales Analysis I.sql b/BASIC JOIN/1068. Product Sales Analysis I.sql
index 40c9ec1..847f25f 100644
--- a/BASIC JOIN/1068. Product Sales Analysis I.sql	
+++ b/BASIC JOIN/1068. Product Sales Analysis I.sql	
@@ -1,3 +1,3 @@
-# Write your MySQL query statement below
-SELECT p.product_name, s.year, s.price
+# Write your MySQL query statement below
+SELECT p.product_name, s.year, s.price
 FROM Sales s LEFT JOIN Product p ON s.product_id = p.product_id;
\ No newline at end of file
diff --git a/BASIC JOIN/1378. Replace Employee ID With The Unique Identifier.sql b/BASIC JOIN/1378. Replace Employee ID With The Unique Identifier.sql
index 3bdf113..a1619de 100644
--- a/BASIC JOIN/1378. Replace Employee ID With The Unique Identifier.sql	
+++ b/BASIC JOIN/1378. Replace Employee ID With The Unique Identifier.sql	
@@ -1,3 +1,3 @@
-# Write your MySQL query statement below
-SELECT eu.unique_id AS unique_id, e.name AS name
+# Write your MySQL query statement below
+SELECT eu.unique_id AS unique_id, e.name AS name
 FROM Employees e LEFT JOIN EmployeeUNI eu ON e.id = eu.id;
\ No newline at end of file
diff --git a/BASIC JOIN/1581. Customer Who Visited but Did Not Make Any Transactions.sql b/BASIC JOIN/1581. Customer Who Visited but Did Not Make Any Transactions.sql
index a8f0d31..8bbe792 100644
--- a/BASIC JOIN/1581. Customer Who Visited but Did Not Make Any Transactions.sql	
+++ b/BASIC JOIN/1581. Customer Who Visited but Did Not Make Any Transactions.sql	
@@ -1,6 +1,6 @@
-# Write your MySQL query statement below
-SELECT v.customer_id, COUNT(v.visit_id) AS count_no_trans
-FROM Visits v LEFT JOIN Transactions t 
-ON v.visit_id = t.visit_id
-WHERE t.transaction_id IS NULL
+# Write your MySQL query statement below
+SELECT v.customer_id, COUNT(v.visit_id) AS count_no_trans
+FROM Visits v LEFT JOIN Transactions t 
+ON v.visit_id = t.visit_id
+WHERE t.transaction_id IS NULL
 GROUP BY v.customer_id;
\ No newline at end of file
diff --git a/BASIC JOIN/197. Rising Temperature.sql b/BASIC JOIN/197. Rising Temperature.sql
index b5cc4b8..44d57c3 100644
--- a/BASIC JOIN/197. Rising Temperature.sql	
+++ b/BASIC JOIN/197. Rising Temperature.sql	
@@ -1,4 +1,4 @@
-# Write your MySQL query statement below
-SELECT W1.id  
-FROM Weather AS W1, Weather AS W2
+# Write your MySQL query statement below
+SELECT W1.id  
+FROM Weather AS W1, Weather AS W2
 WHERE W1.Temperature > W2.Temperature AND DATEDIFF(W1.recordDate, W2.recordDate) = 1;
\ No newline at end of file
diff --git a/README.md b/README.md
index 08a11db..614cfd5 100644
--- a/README.md
+++ b/README.md
@@ -1,44 +1,44 @@
-# LeetCode SQL TOP 50 Solutions
-
-This repository contains solutions to the top 50 SQL problems on LeetCode, covering advanced string functions, regex, clauses, basic aggregation functions, joins, sorting, grouping, subqueries, and more.
-
-## Repository Structure
-
-- `README.md`: An overview of the repository and how to use it.
-- `advanced_string_functions_regex_clauses.sql`: Solutions for advanced string functions, regex, and clause-based problems.
-- `basic_aggregation_function.sql`: Solutions focusing on basic aggregation functions like COUNT, SUM, AVG, etc.
-- `basic_join.sql`: Solutions demonstrating various types of SQL joins (INNER JOIN, LEFT JOIN, RIGHT JOIN, FULL JOIN).
-- `select.sql`: Basic SELECT statement solutions.
-- `sorting_and_group.sql`: Solutions for sorting and grouping data using ORDER BY and GROUP BY.
-- `subqueries.sql`: Solutions involving subqueries.
-
-## How to Use This Repository
-
-1. Clone this repository to your local machine.
-2. Open each SQL file in a text editor or IDE that supports SQL syntax highlighting.
-3. Review the provided solutions and explanations.
-4. Try solving the problems on your own before looking at the solutions.
-5. Use these solutions as a reference or learning tool to improve your SQL skills.
-
-## Latest Commit
-
-**Author:** deepak14ri  
-**Commit Message:** new problem solved  
-**Latest Commit Hash:** b6bce78  
-**Date:** 12 hours ago  
-
-## History
-- **SELECT**: Basic SELECT statement solutions to retrieve data from one or more tables.
-- **BASIC AGGREGATION FUNCTION**: Solutions for filtering employee information using basic aggregation functions.
-- **BASIC JOIN**: Demonstrates various join techniques to combine rows from two or more tables based on a related column.
-- **SORTING AND GROUP**: Solutions for sorting and grouping employee information.
-- **SUBQUERIES**: Solutions involving subqueries to perform operations within a query.
-- **ADVANCED STRING FUNCTIONS + REGEX + CLAUSE**: Solutions for problems requiring advanced string manipulation, regular expressions, and specific SQL clauses.
-
-## Contributing
-
-Contributions are welcome Please feel free to submit a pull request if you have improvements or additional solutions.
-
-## License
-
-This project is licensed under the MIT License - see the [LICENSE](LICENSE) file for details.
+# LeetCode SQL TOP 50 Solutions
+
+This repository contains solutions to the top 50 SQL problems on LeetCode, covering advanced string functions, regex, clauses, basic aggregation functions, joins, sorting, grouping, subqueries, and more.
+
+## Repository Structure
+
+- `README.md`: An overview of the repository and how to use it.
+- `advanced_string_functions_regex_clauses.sql`: Solutions for advanced string functions, regex, and clause-based problems.
+- `basic_aggregation_function.sql`: Solutions focusing on basic aggregation functions like COUNT, SUM, AVG, etc.
+- `basic_join.sql`: Solutions demonstrating various types of SQL joins (INNER JOIN, LEFT JOIN, RIGHT JOIN, FULL JOIN).
+- `select.sql`: Basic SELECT statement solutions.
+- `sorting_and_group.sql`: Solutions for sorting and grouping data using ORDER BY and GROUP BY.
+- `subqueries.sql`: Solutions involving subqueries.
+
+## How to Use This Repository
+
+1. Clone this repository to your local machine.
+2. Open each SQL file in a text editor or IDE that supports SQL syntax highlighting.
+3. Review the provided solutions and explanations.
+4. Try solving the problems on your own before looking at the solutions.
+5. Use these solutions as a reference or learning tool to improve your SQL skills.
+
+## Latest Commit
+
+**Author:** deepak14ri  
+**Commit Message:** new problem solved  
+**Latest Commit Hash:** b6bce78  
+**Date:** 12 hours ago  
+
+## History
+- **SELECT**: Basic SELECT statement solutions to retrieve data from one or more tables.
+- **BASIC AGGREGATION FUNCTION**: Solutions for filtering employee information using basic aggregation functions.
+- **BASIC JOIN**: Demonstrates various join techniques to combine rows from two or more tables based on a related column.
+- **SORTING AND GROUP**: Solutions for sorting and grouping employee information.
+- **SUBQUERIES**: Solutions involving subqueries to perform operations within a query.
+- **ADVANCED STRING FUNCTIONS + REGEX + CLAUSE**: Solutions for problems requiring advanced string manipulation, regular expressions, and specific SQL clauses.
+
+## Contributing
+
+Contributions are welcome Please feel free to submit a pull request if you have improvements or additional solutions.
+
+## License
+
+This project is licensed under the MIT License - see the [LICENSE](LICENSE) file for details.
diff --git a/SELECT/1148. Article Views I.sql b/SELECT/1148. Article Views I.sql
index 122ffe7..881117d 100644
--- a/SELECT/1148. Article Views I.sql	
+++ b/SELECT/1148. Article Views I.sql	
@@ -1,4 +1,4 @@
-# Write your MySQL query statement below
-SELECT DISTINCT author_id as id from Views
-WHERE author_id = viewer_id
+# Write your MySQL query statement below
+SELECT DISTINCT author_id as id from Views
+WHERE author_id = viewer_id
 ORDER BY id;
\ No newline at end of file
diff --git a/SELECT/1683. Invalid Tweets.sql b/SELECT/1683. Invalid Tweets.sql
index e3e56c4..dbcb81a 100644
--- a/SELECT/1683. Invalid Tweets.sql	
+++ b/SELECT/1683. Invalid Tweets.sql	
@@ -1,2 +1,2 @@
-# Write your MySQL query statement below
+# Write your MySQL query statement below
 SELECT tweet_id FROM Tweets WHERE length(content) > 15;
\ No newline at end of file
diff --git a/SELECT/1757. Recyclable and Low Fat Products.sql b/SELECT/1757. Recyclable and Low Fat Products.sql
index 48001a3..57edd1e 100644
--- a/SELECT/1757. Recyclable and Low Fat Products.sql	
+++ b/SELECT/1757. Recyclable and Low Fat Products.sql	
@@ -1,5 +1,5 @@
-# Write your MySQL query statement below
-SELECT product_id 
-FROM Products
-WHERE low_fats = 'Y' 
-AND recyclable = 'Y';
+# Write your MySQL query statement below
+SELECT product_id 
+FROM Products
+WHERE low_fats = 'Y' 
+AND recyclable = 'Y';
diff --git a/SELECT/584. Find Customer Referee.sql b/SELECT/584. Find Customer Referee.sql
index 8cea979..11c5268 100644
--- a/SELECT/584. Find Customer Referee.sql	
+++ b/SELECT/584. Find Customer Referee.sql	
@@ -1,3 +1,3 @@
--- Write your PostgreSQL query statement below
-SELECT name from Customer
-WHERE referee_id is null or referee_id != 2;
+-- Write your PostgreSQL query statement below
+SELECT name from Customer
+WHERE referee_id is null or referee_id != 2;
diff --git a/SELECT/595. Big Countries.sql b/SELECT/595. Big Countries.sql
index 23f745b..1e39d52 100644
--- a/SELECT/595. Big Countries.sql	
+++ b/SELECT/595. Big Countries.sql	
@@ -1,5 +1,5 @@
-# Write your MySQL query statement below
-SELECT name, population, area
-FROM World
-WHERE area >= 3000000 
+# Write your MySQL query statement below
+SELECT name, population, area
+FROM World
+WHERE area >= 3000000 
 OR population >= 25000000;
\ No newline at end of file
diff --git a/SORTING AND GROUP/1070. Product Sales Analysis III.sql b/SORTING AND GROUP/1070. Product Sales Analysis III.sql
index 1a64cf0..9d064da 100644
--- a/SORTING AND GROUP/1070. Product Sales Analysis III.sql	
+++ b/SORTING AND GROUP/1070. Product Sales Analysis III.sql	
@@ -1,11 +1,11 @@
-# Write your MySQL query statement below
-SELECT product_id, year as first_year, quantity, price
-FROM Sales
-WHERE (product_id, year) 
-IN (SELECT product_id,
-        min(year)
-    FROM Sales
-    GROUP BY
-        product_id
-    );
-
+# Write your MySQL query statement below
+SELECT product_id, year as first_year, quantity, price
+FROM Sales
+WHERE (product_id, year) 
+IN (SELECT product_id,
+        min(year)
+    FROM Sales
+    GROUP BY
+        product_id
+    );
+
diff --git a/SORTING AND GROUP/1141. User Activity for the Past 30 Days I.sql b/SORTING AND GROUP/1141. User Activity for the Past 30 Days I.sql
index 6a99f9e..40de4ae 100644
--- a/SORTING AND GROUP/1141. User Activity for the Past 30 Days I.sql	
+++ b/SORTING AND GROUP/1141. User Activity for the Past 30 Days I.sql	
@@ -1,5 +1,5 @@
-# Write your MySQL query statement below
-SELECT activity_date AS day, COUNT(DISTINCT user_id) AS active_users 
-FROM Activity
-WHERE activity_date BETWEEN '2019-06-28' AND '2019-07-27'
+# Write your MySQL query statement below
+SELECT activity_date AS day, COUNT(DISTINCT user_id) AS active_users 
+FROM Activity
+WHERE activity_date BETWEEN '2019-06-28' AND '2019-07-27'
 GROUP BY activity_date;
\ No newline at end of file
diff --git a/SORTING AND GROUP/2356. Number of Unique Subjects Taught by Each Teacher.sql b/SORTING AND GROUP/2356. Number of Unique Subjects Taught by Each Teacher.sql
index 59d9ce1..a6e2e69 100644
--- a/SORTING AND GROUP/2356. Number of Unique Subjects Taught by Each Teacher.sql	
+++ b/SORTING AND GROUP/2356. Number of Unique Subjects Taught by Each Teacher.sql	
@@ -1,4 +1,4 @@
-# Write your MySQL query statement below
-SELECT teacher_id, COUNT(DISTINCT subject_id) AS cnt
-FROM Teacher
+# Write your MySQL query statement below
+SELECT teacher_id, COUNT(DISTINCT subject_id) AS cnt
+FROM Teacher
 GROUP BY teacher_id;
\ No newline at end of file
diff --git a/SORTING AND GROUP/596. Classes More Than 5 Students.sql b/SORTING AND GROUP/596. Classes More Than 5 Students.sql
index 74df932..5e1b408 100644
--- a/SORTING AND GROUP/596. Classes More Than 5 Students.sql	
+++ b/SORTING AND GROUP/596. Classes More Than 5 Students.sql	
@@ -1,3 +1,3 @@
-# Write your MySQL query statement below
-SELECT class FROM Courses
+# Write your MySQL query statement below
+SELECT class FROM Courses
 GROUP BY class HAVING COUNT(class) >= 5; 
\ No newline at end of file
diff --git a/SUBQUERIES/1321. Restaurant Growth.sql b/SUBQUERIES/1321. Restaurant Growth.sql
index becc06b..87ac687 100644
--- a/SUBQUERIES/1321. Restaurant Growth.sql	
+++ b/SUBQUERIES/1321. Restaurant Growth.sql	
@@ -1,6 +1,6 @@
-SELECT visited_on, 
-       SUM(amount) OVER (ORDER BY visited_on ROWS BETWEEN 6 PRECEDING AND CURRENT ROW) AS amount,
-       ROUND(SUM(amount) OVER (ORDER BY visited_on ROWS BETWEEN 6 PRECEDING AND CURRENT ROW) / 7, 2) AS average_amount
-FROM customer
-WHERE visited_on >= (SELECT DATE_ADD(MIN(visited_on), INTERVAL 6 DAY) FROM customer)
-ORDER BY visited_on;
+SELECT visited_on, 
+       SUM(amount) OVER (ORDER BY visited_on ROWS BETWEEN 6 PRECEDING AND CURRENT ROW) AS amount,
+       ROUND(SUM(amount) OVER (ORDER BY visited_on ROWS BETWEEN 6 PRECEDING AND CURRENT ROW) / 7, 2) AS average_amount
+FROM customer
+WHERE visited_on >= (SELECT DATE_ADD(MIN(visited_on), INTERVAL 6 DAY) FROM customer)
+ORDER BY visited_on;
diff --git a/SUBQUERIES/1341. Movie Rating.sql b/SUBQUERIES/1341. Movie Rating.sql
index 5d5a048..8847f0c 100644
--- a/SUBQUERIES/1341. Movie Rating.sql	
+++ b/SUBQUERIES/1341. Movie Rating.sql	
@@ -1,17 +1,17 @@
-# Write your MySQL query statement below
-(SELECT name AS results
-FROM Users 
-INNER JOIN MovieRating USING(user_id)
-GROUP BY user_id
-ORDER BY COUNT(rating) DESC, name
-LIMIT 1)
-
-UNION ALL
-
-(SELECT title as results
-FROM Movies 
-INNER JOIN MovieRating USING(movie_id)
-WHERE MONTH(created_at) = '02' AND YEAR(created_at) = '2020'
-GROUP BY title
-ORDER BY AVG(rating) DESC, title
+# Write your MySQL query statement below
+(SELECT name AS results
+FROM Users 
+INNER JOIN MovieRating USING(user_id)
+GROUP BY user_id
+ORDER BY COUNT(rating) DESC, name
+LIMIT 1)
+
+UNION ALL
+
+(SELECT title as results
+FROM Movies 
+INNER JOIN MovieRating USING(movie_id)
+WHERE MONTH(created_at) = '02' AND YEAR(created_at) = '2020'
+GROUP BY title
+ORDER BY AVG(rating) DESC, title
 LIMIT 1)
\ No newline at end of file
diff --git a/SUBQUERIES/185. Department Top Three Salaries.sql b/SUBQUERIES/185. Department Top Three Salaries.sql
index 1f31892..2de346d 100644
--- a/SUBQUERIES/185. Department Top Three Salaries.sql	
+++ b/SUBQUERIES/185. Department Top Three Salaries.sql	
@@ -1,13 +1,13 @@
--- Write your MySQL query statement below
-SELECT Department, Employee, Salary
-FROM (
-    SELECT 
-        d.name AS Department,
-        e.name AS Employee,
-        e.salary AS Salary,
-        DENSE_RANK() OVER (PARTITION BY d.name ORDER BY Salary DESC) AS rnk
-    FROM Employee e
-    JOIN Department d
-    ON e.departmentId = d.id
-) AS rnk_tbl
+-- Write your MySQL query statement below
+SELECT Department, Employee, Salary
+FROM (
+    SELECT 
+        d.name AS Department,
+        e.name AS Employee,
+        e.salary AS Salary,
+        DENSE_RANK() OVER (PARTITION BY d.name ORDER BY Salary DESC) AS rnk
+    FROM Employee e
+    JOIN Department d
+    ON e.departmentId = d.id
+) AS rnk_tbl
 WHERE rnk <= 3;
\ No newline at end of file
diff --git a/SUBQUERIES/1978. Employees Whose Manager Left the Company.sql b/SUBQUERIES/1978. Employees Whose Manager Left the Company.sql
index 546e3e4..dde29cc 100644
--- a/SUBQUERIES/1978. Employees Whose Manager Left the Company.sql	
+++ b/SUBQUERIES/1978. Employees Whose Manager Left the Company.sql	
@@ -1,5 +1,5 @@
-SELECT employee_id FROM Employees
-WHERE salary < 30000 AND manager_id NOT IN (
-    SELECT employee_id FROM Employees
-)
+SELECT employee_id FROM Employees
+WHERE salary < 30000 AND manager_id NOT IN (
+    SELECT employee_id FROM Employees
+)
 ORDER BY employee_id;
\ No newline at end of file
diff --git a/SUBQUERIES/626. Exchange Seats.sql b/SUBQUERIES/626. Exchange Seats.sql
index bedc6a6..b61ef4e 100644
--- a/SUBQUERIES/626. Exchange Seats.sql	
+++ b/SUBQUERIES/626. Exchange Seats.sql	
@@ -1,13 +1,13 @@
-# Write your MySQL query statement below
-SELECT 
-    CASE
-        WHEN id = (SELECT MAX(id) FROM seat) AND id % 2 = 1
-            THEN id
-        WHEN id % 2 = 1
-            THEN id + 1
-        WHEN id % 2 = 0
-            THEN id - 1
-    END as id, student
-FROM seat
-ORDER BY id;
-
+# Write your MySQL query statement below
+SELECT 
+    CASE
+        WHEN id = (SELECT MAX(id) FROM seat) AND id % 2 = 1
+            THEN id
+        WHEN id % 2 = 1
+            THEN id + 1
+        WHEN id % 2 = 0
+            THEN id - 1
+    END as id, student
+FROM seat
+ORDER BY id;
+