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| 1 | +/// Source : https://leetcode.com/problems/selling-pieces-of-wood/ |
| 2 | +/// Author : liuyubobobo |
| 3 | +/// Time : 2022-06-18 |
| 4 | + |
| 5 | +#include <iostream> |
| 6 | +#include <vector> |
| 7 | +#include <map> |
| 8 | + |
| 9 | +using namespace std; |
| 10 | + |
| 11 | + |
| 12 | +/// DP |
| 13 | +/// Time Complexity: O(m * n * n + n * m * m + m * n * (m + n)) |
| 14 | +/// Space Complexity: O(m * n) |
| 15 | +class Solution { |
| 16 | +public: |
| 17 | + long long sellingWood(int m, int n, vector<vector<int>>& prices) { |
| 18 | + |
| 19 | + // 0 - any, 1 - h is fixed, 2 - w is fixed |
| 20 | + vector<vector<vector<long long>>> dp(3, vector<vector<long long>>(m + 1, vector<long long>(n + 1, -1))); |
| 21 | + |
| 22 | + map<int, map<int, long long>> H, W; |
| 23 | + for(const vector<int>& price: prices){ |
| 24 | + int h = price[0], w = price[1], v = price[2]; |
| 25 | + H[h][w] = max(H[h][w], (long long)v); |
| 26 | + W[w][h] = max(W[w][h], (long long)v); |
| 27 | + } |
| 28 | + |
| 29 | + vector<int> h_choices; |
| 30 | + vector<vector<long long>> Hdp(m + 1, vector<long long>(n + 1, 0)); |
| 31 | + for(const pair<int, map<int, long long>>& p: H){ |
| 32 | + int h = p.first; |
| 33 | + h_choices.push_back(h); |
| 34 | + const map<int, long long>& items = p.second; |
| 35 | + |
| 36 | + for(int W = 1; W <= n; W ++){ |
| 37 | + for(const pair<int, long long>& item: items){ |
| 38 | + int weight = item.first; |
| 39 | + long long value = item.second; |
| 40 | + |
| 41 | + if(W >= weight) |
| 42 | + Hdp[h][W] = max(Hdp[h][W], Hdp[h][W - weight] + value); |
| 43 | + } |
| 44 | + } |
| 45 | + } |
| 46 | + |
| 47 | + vector<int> w_choices; |
| 48 | + vector<vector<long long>> Wdp(n + 1, vector<long long>(m + 1, 0)); |
| 49 | + for(const pair<int, map<int, long long>>& p: W){ |
| 50 | + int w = p.first; |
| 51 | + w_choices.push_back(w); |
| 52 | + const map<int, long long>& items = p.second; |
| 53 | + |
| 54 | + for(int W = 1; W <= m; W ++) { |
| 55 | + for (const pair<int, long long> &item: items) { |
| 56 | + int weight = item.first; |
| 57 | + long long value = item.second; |
| 58 | + |
| 59 | + if(W >= weight) |
| 60 | + Wdp[w][W] = max(Wdp[w][W], Wdp[w][W - weight] + value); |
| 61 | + } |
| 62 | + } |
| 63 | + } |
| 64 | + |
| 65 | + return dfs(0, m, n, h_choices, w_choices, Hdp, Wdp, dp); |
| 66 | + } |
| 67 | + |
| 68 | +private: |
| 69 | + long long dfs(int state, int m, int n, const vector<int>& h_choices, const vector<int>& w_choices, |
| 70 | + const vector<vector<long long>>& Hdp, const vector<vector<long long>>& Wdp, |
| 71 | + vector<vector<vector<long long>>>& dp){ |
| 72 | + |
| 73 | + if(m <= 0 || n <= 0) return 0; |
| 74 | + if(dp[state][m][n] != -1) return dp[state][m][n]; |
| 75 | + |
| 76 | + if(state == 1) return dp[state][m][n] = Hdp[m][n]; |
| 77 | + if(state == 2) return dp[state][m][n] = Wdp[n][m]; |
| 78 | + |
| 79 | + long long res = 0; |
| 80 | + for(int h_option: h_choices){ |
| 81 | + if(h_option > m) break; |
| 82 | + res = max(res, dfs(1, h_option, n, h_choices, w_choices, Hdp, Wdp, dp) + dfs(0, m - h_option, n, h_choices, w_choices, Hdp, Wdp, dp)); |
| 83 | + } |
| 84 | + for(int w_option: w_choices){ |
| 85 | + if(w_option > n) break; |
| 86 | + res = max(res, dfs(2, m, w_option, h_choices, w_choices, Hdp, Wdp, dp) + dfs(0, m, n - w_option, h_choices, w_choices, Hdp, Wdp, dp)); |
| 87 | + } |
| 88 | + return dp[state][m][n] = res; |
| 89 | + } |
| 90 | +}; |
| 91 | + |
| 92 | + |
| 93 | +int main() { |
| 94 | + |
| 95 | + vector<vector<int>> prices1 = {{1, 4, 2}, {2, 2, 7}, {2, 1, 3}}; |
| 96 | + cout << Solution().sellingWood(3, 5, prices1) << '\n'; |
| 97 | + // 19 |
| 98 | + |
| 99 | + vector<vector<int>> prices2 = {{3, 2, 10}, {1, 4, 2}, {4, 1, 3}}; |
| 100 | + cout << Solution().sellingWood(4, 6, prices2) << '\n'; |
| 101 | + // 32 |
| 102 | + |
| 103 | + vector<vector<int>> prices3 = {{4, 1, 18}, {4, 2, 5}, {1, 1, 20}, {3, 1, 21}}; |
| 104 | + cout << Solution().sellingWood(4, 2, prices3) << '\n'; |
| 105 | + // 160 |
| 106 | + |
| 107 | + return 0; |
| 108 | +} |
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