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* Assuming that Team A and Team B had previously played as in the game in scenario one, the new tournament NRR for Team A would be: <math>\frac{287+265}{50+ 50}-\frac{243+267}{50+47\frac{2}{6}} = \frac{552}{100}-\frac{510}{97\frac{2}{6}} = 5.52 - 5.24 = 0.28</math>.
===3. Side that bats first is bowled out, side batting second wins with bonus point===
* Team A bat first and are bowled out for 127 off 25.4 overs. Despite their run rate for the balls they faced being 127 / 25.667 = 4.95, because they were bowled out the entire 50 overs are added to their total overs faced tally for the tournament, and Team B are credited with having bowled 50 overs.
* Team B reach the target off 30.5 overs, ending with 128–4. Team B actually scored at a slower pace ((128/30.833 = 4.15) + 1 = 5.15), however they managed to protect their wickets and win. Thus, only the 30.833 overs are added to the seasonal tally.
* Team A's NRR for this game is (127/50) − (128/30.833) = −1.61.
* Team B's NRR for this game is (128/30.833) − (127/50) = +1.61.
* Team B's finally NRR for this game is +1.61 + 1 = -2.61
* If 25.667 had been used for Team A's overs total rather than 50, Team A would have finished the match with a positive match NRR, and improved tournament NRR, despite losing. (Similarly Team B with a worsened NRR, despite winning.)
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