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‎2019校招真题编程题汇总_Java/Main001.java

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package CampusRecruitment2019;
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import java.util.Arrays;
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import java.util.Comparator;
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import java.util.HashMap;
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import java.util.Scanner;
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// 牛牛找工作
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public class Main001 {
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public static void main(String[] args) {
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Scanner sc = new Scanner(System.in);
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int n = sc.nextInt();
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int m = sc.nextInt();
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int[][] job = new int[n][2];
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int[] partner = new int[m];
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for (int i = 0; i < n; i++) {
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job[i][0] = sc.nextInt();
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job[i][1] = sc.nextInt();
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}
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for (int i = 0; i < m; i++) {
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partner[i] = sc.nextInt();
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}
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// 二维数组按照第一个元素升序排序，即对工作难度升序排序
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// Arrays.sort(job, (o1, o2) -> (o1[0] - o2[0])); // 写法一
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// Arrays.sort(job, Comparator.comparingInt(o -> o[0])); // 写法二
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Arrays.sort(job, new Comparator<int[]>() { // 写法三
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@Override
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public int compare(int[] o1, int[] o2) {
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return o1[0] - o2[0];
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}
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});
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// 对小伙伴能量值升序排序
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int[] partner2 = Arrays.copyOf(partner, m);
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Arrays.sort(partner2);
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HashMap<Integer, Integer> map = new HashMap<>();
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int j = 0, power;
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for (int i = 0; i < m; i++) {
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power = partner2[i];
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// 能量值小于最低工作难度，报酬置0
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if (power < job[j][0]) {
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map.put(power, 0);
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continue;
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}
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// 不断提升能量值范围内的工作难度，并逐个将工作难度的报酬置为当前能量范围的最大报酬
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while (j + 1 < n && power >= job[j + 1][0]) {
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if (job[j][1] > job[j + 1][1])
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job[j + 1][1] = job[j][1];
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j++;
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}
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// 记录当前能量值可获得的最大报酬
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map.put(power, job[j][1]);
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}
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// 按照原能量值顺序输出报酬
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for (int i = 0; i < m; i++)
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System.out.println(map.get(partner[i]));
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}
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}

‎2019校招真题编程题汇总_Java/Main041.java

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package CampusRecruitment2019;
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import java.util.HashMap;
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import java.util.Scanner;
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// X游戏
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public class Main041 {
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public static void main(String[] args) {
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Scanner sc = new Scanner(System.in);
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int n = sc.nextInt();
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int res = 0;
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for (int i = 1; i <= n; i++) {
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String str = String.valueOf(i);
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if ((str.contains("2") || str.contains("5") || str.contains("6") || str.contains("9")) && (!str.contains("3") && !str.contains("4") && !str.contains("7")))
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res++;
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}
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System.out.println(res);
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}
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}
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/*
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public class Main041 {
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public static void main(String[] args) {
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Scanner sc = new Scanner(System.in);
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int n = sc.nextInt();
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// 记录旋转规则
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HashMap<Character, Character> map = new HashMap<>();
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map.put('0', '0');
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map.put('1', '1');
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map.put('8', '8');
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map.put('2', '5');
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map.put('5', '2');
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map.put('6', '9');
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map.put('9', '6');
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int res = 0;
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Character newChar;
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for (int i = 1; i <= n; i++) {
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// 数字转化为字符数组
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String str = String.valueOf(i);
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char[] ch = str.toCharArray();
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// 判断是否全部为有效数字
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boolean flag = true;
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for (int j = 0; j < ch.length; j++) {
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newChar = map.get(ch[j]);
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// 获取并替换旧字符
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if (newChar != null) {
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ch[j] = newChar;
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} else {
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// 包含无效数字
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flag = false;
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break;
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}
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}
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// 旋转后数字与原来的不同
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if (flag && !String.valueOf(ch).equals(str))
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res += 1;
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}
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System.out.println(res);
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}
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}
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*/

‎2019校招真题编程题汇总_Java/Main042.java

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package CampusRecruitment2019;
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import java.util.Scanner;
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// 跳格子游戏
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public class Main042 {
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public static void main(String[] args) {
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Scanner sc = new Scanner(System.in);
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int n = sc.nextInt();
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int a = 1, b = 1;
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for (int i = 0; i < n; i++) {
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int temp = a;
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a = b;
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b += temp;
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}
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System.out.println(a);
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}
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}

‎2019校招真题编程题汇总_Java/Main044.java

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package CampusRecruitment2019;
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import java.util.Scanner;
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// 员工考勤记录
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public class Main044 {
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public static void main(String[] args) {
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Scanner sc = new Scanner(System.in);
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int n = sc.nextInt();
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// 1种：全P
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// n种：含1个A
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// (n²-n)/2种：含2个A
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int res = 1 + n + (int)((Math.pow(n, 2) - n) / 2);
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System.out.println(res);
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}
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}

‎2019校招真题编程题汇总_Java/Main045.java

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package CampusRecruitment2019;
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import java.util.Scanner;
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// 解码方法
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// 动态规划,dp[i]表示数字串前i个数字所有的解码方案
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public class Main045 {
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public static void main(String[] args) {
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Scanner sc = new Scanner(System.in);
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String str = sc.next();
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int n = str.length();
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int[] dp = new int[n + 1];
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dp[0] = 1;
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for (int i = 1; i <= n; i++) {
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// 当前字符未组合时，当前解码方案等于上一种解码方案
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if (str.charAt(i - 1) != '0')
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dp[i] += dp[i - 1];
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// 当前字符可组合时，解码方案加上'去除最后两个字符时的解码方案'
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if (i >= 2 && (str.charAt(i - 2) == '1' || (str.charAt(i - 2) == '2' && str.charAt(i - 1) <= '6')))
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dp[i] += dp[i - 2];
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}
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System.out.println(dp[n]);
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}
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}

‎2019校招真题编程题汇总_Java/Main046.java

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package CampusRecruitment2019;
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import java.util.Scanner;
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import java.util.Arrays;
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// 漂流船问题
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// 贪心，先排序数组，再用双指针从左右两端向内移动，两人体重和满足限制条件则两个人一只船，否则重的人单独一只船
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public class Main046 {
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public static void main(String[] args) {
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Scanner sc = new Scanner(System.in);
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String[] people = sc.nextLine().split(" ");
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int limit = sc.nextInt();
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Arrays.sort(people);
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int l = 0, r = people.length - 1, res = 0;
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while (l <= r) {
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if (Integer.parseInt(people[l]) + Integer.parseInt(people[r]) <= limit) {
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l++;
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r--;
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} else {
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r--;
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}
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res += 1;
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}
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System.out.println(res);
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}
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}

‎2019校招真题编程题汇总_Java/Main049.java

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package CampusRecruitment2019;
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import java.util.Scanner;
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// 排队唱歌
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// 直接插入排序并记录交换次数
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public class Main049 {
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public static void main(String[] args) {
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Scanner sc = new Scanner(System.in);
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int n = sc.nextInt();
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int[] high = new int[n];
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for (int i = 0; i < n; i++)
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high[i] = sc.nextInt();
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int res = 0;
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for (int i = 1; i < n; i++) {
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for (int j = i - 1; j >= 0; j--) {
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if (high[j] > high[j + 1]) {
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int temp = high[j];
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high[j] = high[j + 1];
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high[j + 1] = temp;
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res += 1;
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} else {
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break;
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}
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}
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}
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System.out.println(res);
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}
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}

‎2019校招真题编程题汇总_Java/Main051.java

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package CampusRecruitment2019;
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import java.util.Comparator;
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import java.util.Scanner;
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import java.util.Arrays;
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// 挑选代表
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public class Main051 {
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public static void main(String[] args) {
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Scanner sc = new Scanner(System.in);
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int n = sc.nextInt();
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int[][] region = new int[n][2];
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for (int i = 0; i < n; i++) {
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region[i][0] = sc.nextInt();
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region[i][1] = sc.nextInt();
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}
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Arrays.sort(region, new Comparator<int[]>() {
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@Override
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public int compare(int[] a, int[] b) {
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// 差大于0则交换位置，按照数组第二个元素升序排序
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return a[1] - b[1];
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}
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});
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// 取区间的最后两个数
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int p2 = region[0][1] - 1, p1 = region[0][1], res = 2;
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for (int i = 1; i < n; i++) {
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int a = region[i][0];
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int b = region[i][1];
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// 当前区间包含了前一区间的两个数
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if (a <= p1 && p1 <= b && a <= p2 && p2 <= b)
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continue;
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// 当前区间包含了前一区间的一个数
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else if (a <= p1 && p1 <= b) {
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p2 = p1;
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p1 = b;
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res += 1;
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// 当前区间不包含前一区间的数，需要获取当前区间的最后两个数
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} else {
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p2 = b - 1;
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p1 = b;
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res += 2;
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}
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}
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System.out.println(res);
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}
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}

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