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Create Count Number of Distinct Integers After Reverse Operations.java
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class Solution {
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public int countDistinctIntegers(int[] nums) {
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Set<Integer> set = new HashSet<>();
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for (int num : nums) {
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set.add(num);
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set.add(reverse(num));
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}
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return set.size();
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}
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private int reverse(int num) {
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int reversed = 0;
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while (num > 0) {
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reversed = reversed * 10 + num % 10;
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num /= 10;
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}
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return reversed;
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}
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}

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