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feat: recursive function sum
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# 1. 定义一个函数 `sum_numbers`
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# 2. 能够接受一个 `num` 的整数参数
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# 3. 计算 `1+2+……num` 的结果
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def sum_numbers(num):
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# 1.出口
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if num == 1:
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return 1
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# 2.数字的累加 num + (1 2 3 ... num-1)
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# 假设 sum_numbers 能够正确处理 1 2 ... num-1
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return num + sum_numbers(num-1)
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res = sum_numbers(5)
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print(res)

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