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| 1 | +package medium; |
| 2 | + |
| 3 | +import java.util.ArrayList; |
| 4 | +import java.util.LinkedList; |
| 5 | +import java.util.List; |
| 6 | +import java.util.Queue; |
| 7 | + |
| 8 | +import classes.TreeNode; |
| 9 | + |
| 10 | +/**199. Binary Tree Right Side View |
| 11 | +
|
| 12 | + Total Accepted: 50496 |
| 13 | + Total Submissions: 138613 |
| 14 | + Difficulty: Medium |
| 15 | +
|
| 16 | +Given a binary tree, imagine yourself standing on the right side of it, return the values of the nodes you can see ordered from top to bottom. |
| 17 | +
|
| 18 | +For example: |
| 19 | +Given the following binary tree, |
| 20 | +
|
| 21 | + 1 <--- |
| 22 | + / \ |
| 23 | +2 3 <--- |
| 24 | + \ \ |
| 25 | + 5 4 <--- |
| 26 | +
|
| 27 | +You should return [1, 3, 4]. */ |
| 28 | +public class BinaryTreeRightSideView { |
| 29 | + //Using BFS is pretty straightforward. But there might be a smarter way. |
| 30 | + public List<Integer> rightSideView(TreeNode root) { |
| 31 | + List<Integer> res = new ArrayList<Integer>(); |
| 32 | + if(root == null) return res; |
| 33 | + Queue<TreeNode> q = new LinkedList<TreeNode>(); |
| 34 | + q.offer(root); |
| 35 | + while(!q.isEmpty()){ |
| 36 | + int currentSize = q.size(); |
| 37 | + int i = 0; |
| 38 | + for(; i < currentSize-1; i++){ |
| 39 | + TreeNode currentNode = q.poll(); |
| 40 | + if(currentNode.left != null) q.offer(currentNode.left); |
| 41 | + if(currentNode.right != null) q.offer(currentNode.right); |
| 42 | + } |
| 43 | + TreeNode currentNode = q.poll(); |
| 44 | + if(currentNode.left != null) q.offer(currentNode.left); |
| 45 | + if(currentNode.right != null) q.offer(currentNode.right); |
| 46 | + res.add(currentNode.val); |
| 47 | + } |
| 48 | + return res; |
| 49 | + } |
| 50 | + |
| 51 | + public static void main(String...strings){ |
| 52 | + BinaryTreeRightSideView test = new BinaryTreeRightSideView(); |
| 53 | + TreeNode root = new TreeNode(1); |
| 54 | + root.left = new TreeNode(2); |
| 55 | + root.right = new TreeNode(3); |
| 56 | + root.left.right = new TreeNode(5); |
| 57 | + root.right.right = new TreeNode(4); |
| 58 | + List<Integer> result = test.rightSideView(root); |
| 59 | + for(int i : result){ |
| 60 | + System.out.print(i + ", "); |
| 61 | + } |
| 62 | + } |
| 63 | +} |
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