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lines changed Original file line number Diff line number Diff line change @@ -333,7 +333,7 @@ void foo() {
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```
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由于 `int&` 不能引用 `double` 类型的参数,因此必须产生一个临时值来保存 `s` 的值,
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- 从而当 `increase()` 修改这个临时值时,从而调用完成后 `s` 本身并没有被修改。
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+ 从而当 `increase()` 修改这个临时值时,调用完成后 `s` 本身并没有被修改。
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第二个问题,为什么常量引用允许绑定到非左值?原因很简单,因为 Fortran 需要。
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Original file line number Diff line number Diff line change @@ -20,7 +20,7 @@ void reference(std::string&& str) {
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int main ()
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{
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std::string lv1 = " string," ; // lv1 is a lvalue
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- // std::string&& r1 = s1 ; // illegal, rvalue can't ref to lvalue
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+ // std::string&& r1 = lv1 ; // illegal, rvalue can't ref to lvalue
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std::string&& rv1 = std::move (lv1); // legal, std::move can convert lvalue to rvalue
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std::cout << rv1 << std::endl; // string,
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