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siddhant2002siriak
andauthored
Add unique paths (fixes #2873) (#2943)
Co-authored-by: Andrii Siriak <siryaka@gmail.com>
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/** Author : Siddhant Swarup Mallick
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* Github : https://github.com/siddhant2002
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*/
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/**
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* A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below).
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* The robot can only move either down or right at any point in time.
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* The robot is trying to reach the bottom-right corner of the grid (marked 'Finish' in the diagram below).
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* How many possible unique paths are there?
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*/
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/** Program description - To find the number of unique paths possible */
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package com.thealgorithms.dynamicprogramming;
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import java.util.*;
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public class UniquePaths {
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public static boolean uniquePaths(int m , int n , int ans) {
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int []dp = new int[n];
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Arrays.fill(dp,1);
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for (int i=1; i<m; i++)
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{
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for (int j=1; j<n; j++)
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{
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dp[j] += dp[j-1];
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}
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}
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return dp[n-1]==ans;
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// return true if predicted answer matches with expected answer
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}
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// The above method runs in O(n) time
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public static boolean uniquePaths2(int m , int n , int ans) {
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int dp[][] = new int[m][n];
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for (int i=0; i<m; i++)
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{
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dp[i][0] = 1;
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}
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for (int j=0; j<n; j++)
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{
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dp[0][j] = 1;
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}
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for (int i=1; i<m; i++)
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{
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for (int j=1; j<n; j++)
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{
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dp[i][j]=dp[i-1][j]+dp[i][j-1];
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}
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}
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return dp[m-1][n-1]==ans;
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// return true if predicted answer matches with expected answer
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}
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// The above mthod takes O(m*n) time
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}
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/**
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* OUTPUT :
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* Input - m = 3, n = 7
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* Output: it returns either true if expected answer matches with the predicted answer else it returns false
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* 1st approach Time Complexity : O(n)
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* Auxiliary Space Complexity : O(n)
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* Input - m = 3, n = 7
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* Output: it returns either true if expected answer matches with the predicted answer else it returns false
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* 2nd approach Time Complexity : O(m*n)
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* Auxiliary Space Complexity : O(m*n)
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*/
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package com.thealgorithms.others;
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import org.junit.jupiter.api.Test;
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import static org.junit.jupiter.api.Assertions.*;
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import com.thealgorithms.dynamicprogramming.UniquePaths;
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public class UniquePathsTests {
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@Test
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void testForOneElement()
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{
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assertTrue(UniquePaths.uniquePaths(3,7,28));
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}
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@Test
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void testForTwoElements()
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{
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assertTrue(UniquePaths.uniquePaths(3,2,3));
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}
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@Test
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void testForThreeElements()
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{
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assertTrue(UniquePaths.uniquePaths(3,3,6));
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}
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@Test
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void testForFourElements()
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{
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assertTrue(UniquePaths.uniquePaths(4,6,56));
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}
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@Test
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void testForFiveElements()
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{
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assertTrue(UniquePaths.uniquePaths2(3,5,15));
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}
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@Test
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void testForSixElements()
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{
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assertTrue(UniquePaths.uniquePaths2(6,2,6));
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}
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@Test
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void testForSevenElements()
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{
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assertTrue(UniquePaths.uniquePaths2(5,9,495));
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}
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@Test
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void testForEightElements()
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{
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assertTrue(UniquePaths.uniquePaths2(4,8,120));
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}
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}

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