util: remove getFormat() function

Clement Champetier · Clement Champetier · commit 71875891299d · 2015-06-04T15:59:16.000+02:00
Not necessary since InputFile/OutputFile can return the format name...
And much more!
diff --git a/src/AvTranscoder/util.cpp b/src/AvTranscoder/util.cpp
@@ -12,20 +12,6 @@ extern "C" {
 namespace avtranscoder
 {
 
-std::string getFormat( const std::string& filename )
-{
-	std::string format( "" );
-	
-	AVOutputFormat* avOutputFormat = av_guess_format( NULL, filename.c_str(), NULL);
-	if( avOutputFormat )
-	{
-		if( avOutputFormat->name )
-			format = std::string( avOutputFormat->name );
-	}
-	
-	return format;
-}
-
 bool matchFormat( const std::string& format, const std::string& filename )
 {
 	AVOutputFormat* avOutputFormat = av_guess_format( format.c_str(), filename.c_str(), NULL);
diff --git a/src/AvTranscoder/util.hpp b/src/AvTranscoder/util.hpp
@@ -19,11 +19,6 @@ namespace avtranscoder
 typedef std::map<std::string, OptionArray> OptionArrayMap;
 typedef std::vector< std::pair<std::string, std::string> > NamesArray;  //< short/long names of format/video codec/audio codec
 
-/**
- * @brief Get format name from a given filename 
- */
-std::string AvExport getFormat( const std::string& filename );
-
 /**
  * @brief Check if a format name corresponds to the format of a given filename
  */
