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| 1 | +package org.Ralf.ArrayUtil; |
| 2 | + |
| 3 | +import java.util.ArrayList; |
| 4 | +import java.util.Arrays; |
| 5 | + |
| 6 | +import javax.naming.spi.DirStateFactory.Result; |
| 7 | + |
| 8 | +public class ArrayUtil { |
| 9 | + |
| 10 | + public static void reverseArray(int[] origin) { |
| 11 | + /** |
| 12 | + * 给定一个整形数组a , 对该数组的值进行置换 例如: a = [7, 9 , 30, 3] , 置换后为 [3, 30, 9,7] 如果 |
| 13 | + * a = [7, 9, 30, 3, 4] , 置换后为 [4,3, 30 , 9,7] |
| 14 | + * |
| 15 | + * @param origin |
| 16 | + * @return |
| 17 | + * |
| 18 | + */ |
| 19 | + |
| 20 | + for (int i = 0; i < origin.length / 2; i++) { |
| 21 | + int temp = origin[i]; |
| 22 | + origin[i] = origin[origin.length - i - 1]; |
| 23 | + origin[origin.length - i - 1] = temp; |
| 24 | + } |
| 25 | + |
| 26 | + } |
| 27 | + |
| 28 | + /** |
| 29 | + * 现在有如下的一个数组: int oldArr[]={1,3,4,5,0,0,6,6,0,5,4,7,6,7,0,5} |
| 30 | + * 要求将以上数组中值为0的项去掉,将不为0的值存入一个新的数组,生成的新数组为: {1,3,4,5,6,6,5,4,7,6,7,5} |
| 31 | + * |
| 32 | + * @param oldArray |
| 33 | + * @return int[] |
| 34 | + */ |
| 35 | + public static int[] removeZero(int[] oldArr) { |
| 36 | + |
| 37 | + if (oldArr == null) { |
| 38 | + return null; |
| 39 | + } |
| 40 | + int[] newArr = new int[oldArr.length]; |
| 41 | + int size = 0; |
| 42 | + |
| 43 | + for (int i = 0; i < oldArr.length; i++) { |
| 44 | + if (oldArr[i] != 0) { |
| 45 | + newArr[size] = oldArr[i]; |
| 46 | + size++; |
| 47 | + } |
| 48 | + } |
| 49 | + return Arrays.copyOf(newArr, size); |
| 50 | + |
| 51 | + } |
| 52 | + |
| 53 | + /** |
| 54 | + * 给定两个已经排序好的整形数组, a1和a2 , 创建一个新的数组a3, 使得a3 包含a1和a2 的所有元素, 并且仍然是有序的 例如 a1 = |
| 55 | + * [3, 5, 7,8] a2 = [4, 5, 6,7] 则 a3 为[3,4,5,6,7,8] , 注意: 已经消除了重复 |
| 56 | + * |
| 57 | + * @param array1 |
| 58 | + * @param array2 |
| 59 | + * @return |
| 60 | + */ |
| 61 | + |
| 62 | + public static int[] merge(int[] array1, int[] array2) { |
| 63 | + |
| 64 | + // method |
| 65 | + ArrayList<Integer> arrayList = new ArrayList<>(); |
| 66 | + for (int i = 0; i < array1.length; i++) { |
| 67 | + if (!arrayList.contains(array1[i])) { |
| 68 | + arrayList.add(array1[i]); |
| 69 | + } |
| 70 | + } |
| 71 | + for (int i = 0; i < array2.length; i++) { |
| 72 | + if (!arrayList.contains(array2[i])) {// 可用list的index找到索引,根据索引判断是否包含该元素 |
| 73 | + arrayList.add(array2[i]); |
| 74 | + } |
| 75 | + } |
| 76 | + int[] newArr = new int[arrayList.size()]; |
| 77 | + // arrayList.toArray(newArr); |
| 78 | + for (int i = 0; i < arrayList.size(); i++) { |
| 79 | + newArr[i] = arrayList.get(i); |
| 80 | + } |
| 81 | + Arrays.sort(newArr);// 可用冒泡排序,插入排序,快速排序法等实现 |
| 82 | + return newArr; |
| 83 | + } |
| 84 | + |
| 85 | + /** |
| 86 | + * 把一个已经存满数据的数组 oldArray的容量进行扩展, 扩展后的新数据大小为oldArray.length + size |
| 87 | + * 注意,老数组的元素在新数组中需要保持 例如 oldArray = [2,3,6] , size = 3,则返回的新数组为 |
| 88 | + * [2,3,6,0,0,0] |
| 89 | + * |
| 90 | + * @param oldArray |
| 91 | + * @param size |
| 92 | + * @return |
| 93 | + */ |
| 94 | + public static int[] grow(int[] oldArray, int size) { |
| 95 | + int[] newArray = new int[oldArray.length + size]; |
| 96 | + for (int i = 0; i < oldArray.length; i++) { |
| 97 | + newArray[i] = oldArray[i]; |
| 98 | + } |
| 99 | + return newArray; |
| 100 | + } |
| 101 | + |
| 102 | + /** |
| 103 | + * 斐波那契数列为:1,1,2,3,5,8,13,21...... ,给定一个最大值, 返回小于该值的数列 例如, max = 15 , |
| 104 | + * 则返回的数组应该为 [1,1,2,3,5,8,13] max = 1, 则返回空数组 [] |
| 105 | + * |
| 106 | + * @param max |
| 107 | + * @return |
| 108 | + */ |
| 109 | + public static int[] fibonacci(int max) { |
| 110 | + int[] newArray = {}; |
| 111 | + if (max == 1) { |
| 112 | + return newArray; |
| 113 | + } |
| 114 | + newArray = new int[2 * max]; |
| 115 | + int size = 0; |
| 116 | + int a = 1; |
| 117 | + int b = 1; |
| 118 | + newArray[size++] = a; |
| 119 | + newArray[size++] = b; |
| 120 | + while (b <= max) { |
| 121 | + int temp = b; |
| 122 | + b = a + b; |
| 123 | + newArray[size++] = b; |
| 124 | + a = temp; |
| 125 | + } |
| 126 | + |
| 127 | + return Arrays.copyOf(newArray, size - 1); |
| 128 | + } |
| 129 | + |
| 130 | + /** |
| 131 | + * 返回小于给定最大值max的所有素数数组 例如max = 23, 返回的数组为[2,3,5,7,11,13,17,19] |
| 132 | + * |
| 133 | + * @param max |
| 134 | + * @return |
| 135 | + */ |
| 136 | + public static int[] getPrimes(int max) { |
| 137 | + if (max < 2) { |
| 138 | + return null; |
| 139 | + } |
| 140 | + int[] aar = new int[max]; |
| 141 | + int size = 0; |
| 142 | + for (int i = 2; i < max; i++) { |
| 143 | + if (isPrime(i)) { |
| 144 | + aar[size++] = i; |
| 145 | + } |
| 146 | + } |
| 147 | + return Arrays.copyOf(aar, size); |
| 148 | + } |
| 149 | + |
| 150 | + private static boolean isPrime(int aar) { |
| 151 | + boolean flag = true; |
| 152 | + for (int i = 2; i <= Math.sqrt(aar); i++) { |
| 153 | + if (aar % i == 0) { |
| 154 | + flag = false; |
| 155 | + break; |
| 156 | + } |
| 157 | + } |
| 158 | + return flag; |
| 159 | + } |
| 160 | + |
| 161 | + /** |
| 162 | + * 所谓“完数”, 是指这个数恰好等于它的因子之和,例如6=1+2+3 给定一个最大值max, 返回一个数组, 数组中是小于max 的所有完数 |
| 163 | + * |
| 164 | + * @param max |
| 165 | + * @return |
| 166 | + */ |
| 167 | + public static int[] getPerfectNumbers(int max) { |
| 168 | + if (max < 1) { |
| 169 | + return null; |
| 170 | + } |
| 171 | + int[] arr = new int[max]; |
| 172 | + int size = 0; |
| 173 | + for (int i = 1; i <= max; i++) { |
| 174 | + if (isPerfectNumber(i)) { |
| 175 | + arr[size++] = i; |
| 176 | + } |
| 177 | + } |
| 178 | + return Arrays.copyOf(arr, size); |
| 179 | + } |
| 180 | + |
| 181 | + private static boolean isPerfectNumber(int num) { |
| 182 | + int sum = 0; |
| 183 | + for (int i = 1; i < num; i++) { |
| 184 | + if (num % i == 0) { |
| 185 | + sum += i; |
| 186 | + } |
| 187 | + |
| 188 | + } |
| 189 | + if (sum == num) { |
| 190 | + return true; |
| 191 | + } else |
| 192 | + return false; |
| 193 | + } |
| 194 | + |
| 195 | + /** |
| 196 | + * 用seperator 把数组 array给连接起来 例如array= [3,8,9], seperator = "-" 则返回值为"3-8-9" |
| 197 | + * |
| 198 | + * @param array |
| 199 | + * @param s |
| 200 | + * @return |
| 201 | + */ |
| 202 | + public static String join(int[] array, String seperator) { |
| 203 | + if (array.length < 1) { |
| 204 | + return null; |
| 205 | + } |
| 206 | + StringBuilder string = new StringBuilder(); |
| 207 | + for (int i = 0; i < array.length - 1; i++) { |
| 208 | + string.append(array[i]).append(seperator); |
| 209 | + } |
| 210 | + string.append(array[array.length - 1]); |
| 211 | + return string.toString(); |
| 212 | + } |
| 213 | +} |
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