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implement ArrayUitl by Korben
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package org.korben.coderising.array;
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import java.util.ArrayList;
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import java.util.List;
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/**
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* ArrayUtil
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*
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* Created by Korben on 26/02/2017.
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*/
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public class ArrayUtil {
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/**
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* 给定一个整形数组a , 对该数组的值进行置换
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* 例如: a = [7, 9 , 30, 3] , 置换后为 [3, 30, 9,7]
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* 如果 a = [7, 9, 30, 3, 4] , 置换后为 [4,3, 30 , 9,7]
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*/
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public static void reverseArray(int[] origin) {
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ensureNotNull(origin);
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int length = origin.length;
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for (int i = 0; i < length; i++) {
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if (i < length / 2) {
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int tmp = origin[i];
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origin[i] = origin[length - i - 1];
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origin[length - i - 1] = tmp;
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}
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}
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}
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/**
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* 现在有如下的一个数组: int oldArr[]={1,3,4,5,0,0,6,6,0,5,4,7,6,7,0,5}
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* 要求将以上数组中值为0的项去掉,将不为0的值存入一个新的数组,生成的新数组为:
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* {1,3,4,5,6,6,5,4,7,6,7,5}
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*/
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public static int[] removeZero(int[] oldArray) {
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ensureNotNull(oldArray);
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int nonZeroCount = 0;
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for (int i : oldArray) {
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if (i != 0) {
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nonZeroCount++;
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}
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}
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int newArr[] = new int[nonZeroCount];
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int newArrIndex = 0;
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for (int i : oldArray) {
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if (i != 0) {
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newArr[newArrIndex++] = i;
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}
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}
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return newArr;
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}
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/**
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* 给定两个已经排序好的整形数组, a1和a2 , 创建一个新的数组a3, 使得a3 包含a1和a2 的所有元素, 并且仍然是有序的
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* 例如 a1 = [3, 5, 7,8] a2 = [4, 5, 6,7] 则 a3 为[3,4,5,6,7,8] , 注意: 已经消除了重复
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*/
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public static int[] merge(int[] array1, int[] array2) {
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ensureNotNull(array1);
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ensureNotNull(array2);
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int maxArraySize = array1.length + array2.length;
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int[] mergedArray = new int[maxArraySize];
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int index1 = 0;
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int index2 = 0;
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int mergedIndex = -1;
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for (int i = 0; i < maxArraySize; i++) {
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if (index1 == array1.length) {
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System.arraycopy(array2, index2, mergedArray, mergedIndex + 1, array2.length - index2);
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mergedIndex += array2.length - index2;
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break;
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} else if (index2 == array2.length) {
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System.arraycopy(array1, index1, mergedArray, mergedIndex + 1, array1.length - index1);
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mergedIndex += array1.length - index1;
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break;
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} else {
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int compare = Integer.compare(array1[index1], array2[index2]);
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if (compare < 0) {
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mergedArray[++mergedIndex] = array1[index1++];
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} else if (compare > 0) {
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mergedArray[++mergedIndex] = array2[index2++];
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} else {
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mergedArray[++mergedIndex] = array1[index1++];
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index2++;
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}
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}
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}
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// 清除数组多余部分
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if (mergedIndex + 1 < maxArraySize) {
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int[] resultArray = new int[mergedIndex + 1];
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System.arraycopy(mergedArray, 0, resultArray, 0, mergedIndex + 1);
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return resultArray;
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}
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return mergedArray;
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}
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/**
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* 把一个已经存满数据的数组 oldArray的容量进行扩展, 扩展后的新数据大小为oldArray.length + size
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* 注意,老数组的元素在新数组中需要保持
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* 例如 oldArray = [2,3,6] , size = 3,则返回的新数组为
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* [2,3,6,0,0,0]
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*/
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public static int[] grow(int[] oldArray, int size) {
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ensureNotNull(oldArray);
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if (size < 0) {
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throw new IllegalArgumentException("size must > 0");
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}
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int[] newArray = new int[oldArray.length + size];
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System.arraycopy(oldArray, 0, newArray, 0, oldArray.length);
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for (int i = oldArray.length; i < newArray.length; i++) {
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newArray[i] = 0;
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}
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return newArray;
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}
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/**
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* 斐波那契数列为:1,1,2,3,5,8,13,21...... ,给定一个最大值, 返回小于该值的数列
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* 例如, max = 15 , 则返回的数组应该为 [1,1,2,3,5,8,13]
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* max = 1, 则返回空数组 []
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*/
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public static int[] fibonacci(int max) {
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if (max == 1) {
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int[] array = new int[1];
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array[1] = 1;
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return array;
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}
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List<Integer> list = new ArrayList<>();
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for (int i = 1; ; i++) {
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int fibonacciNumber = getFibonacciNumber(i);
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if (fibonacciNumber <= max) {
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list.add(fibonacciNumber);
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} else {
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break;
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}
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}
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return list2Array(list);
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}
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private static int getFibonacciNumber(int index) {
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if (index == 1) {
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return 1;
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}
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if (index == 2) {
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return 1;
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}
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return getFibonacciNumber(index - 2) + getFibonacciNumber(index - 1);
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}
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/**
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* 返回小于给定最大值max的所有素数数组
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* 例如max = 23, 返回的数组为[2,3,5,7,11,13,17,19]
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*/
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public static int[] getPrimes(int max) {
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List<Integer> primeList = new ArrayList<>();
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if (max <= 1) {
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return new int[0];
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}
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if (max >= 2) {
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primeList.add(2);
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}
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// 所有偶数都不是素数, 所以这里采用 i += 2
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for (int i = 3; i < max; i += 2) {
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if (isPrimeNumber(i, primeList)) {
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primeList.add(i);
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}
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}
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return list2Array(primeList);
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}
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private static boolean isPrimeNumber(int number, List<Integer> primeList) {
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for (Integer prime : primeList) {
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if (number % prime == 0) {
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return false;
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}
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}
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return true;
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}
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/**
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* 所谓“完数”, 是指这个数恰好等于它的因子之和,例如6=1+2+3
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* 给定一个最大值max, 返回一个数组, 数组中是小于max 的所有完数
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*/
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public static int[] getPerfectNumbers(int max) {
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if (max <= 1) {
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return new int[0];
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}
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List<Integer> perfectNumberList = new ArrayList<>();
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for (int i = 2; i < max; i++) {
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if (isPerfectNumber(i)) {
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perfectNumberList.add(i);
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}
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}
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return list2Array(perfectNumberList);
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}
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private static boolean isPerfectNumber(int number) {
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int sum = 1;
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for (int i = 2; i <= number / 2; i++) {
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if (number % i == 0) {
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sum += i;
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}
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}
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return sum == number;
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}
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/**
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* 用separator 把数组 array给连接起来
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* 例如array= [3,8,9], separator = "-"
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* 则返回值为"3-8-9"
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*/
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public static String join(int[] array, String separator) {
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ensureNotNull(array);
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if (separator == null) {
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throw new NullPointerException();
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}
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StringBuilder stringBuilder = new StringBuilder();
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for (int i = 0; i < array.length; i++) {
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stringBuilder.append(array[i]);
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if (i != array.length - 1) {
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stringBuilder.append(separator);
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}
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}
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return stringBuilder.toString();
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}
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private static int[] list2Array(List<Integer> list) {
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int[] result = new int[list.size()];
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for (int i = 0; i < list.size(); i++) {
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result[i] = list.get(i);
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}
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return result;
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}
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private static void ensureNotNull(int[] array) {
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if (array == null) {
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throw new NullPointerException();
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}
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}
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}

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