refactor 514

fishercoder1534 · fishercoder1534 · commit 7d9069a78d8b · 2020-07-15T09:03:28.000-07:00
diff --git a/src/main/java/com/fishercoder/solutions/_514.java b/src/main/java/com/fishercoder/solutions/_514.java
@@ -1,42 +1,5 @@
 package com.fishercoder.solutions;
 
-/**
- * 514. Freedom Trail
- *
- * In the video game Fallout 4, the quest "Road to Freedom" requires players to reach a metal dial called
- * the "Freedom Trail Ring", and use the dial to spell a specific keyword in order to open the door.
-
- Given a string ring, which represents the code engraved on the outer ring and another string key,
- which represents the keyword needs to be spelled.
- You need to find the minimum number of steps in order to spell all the characters in the keyword.
-
- Initially, the first character of the ring is aligned at 12:00 direction.
- You need to spell all the characters in the string key one by one by
- rotating the ring clockwise or anticlockwise to make each character of the string key
- aligned at 12:00 direction and then by pressing the center button.
-
- At the stage of rotating the ring to spell the key character key[i]:
- You can rotate the ring clockwise or anticlockwise one place, which counts as 1 step.
- The final purpose of the rotation is to align one of the string ring's characters at the 12:00 direction,
- where this character must equal to the character key[i].
- If the character key[i] has been aligned at the 12:00 direction,
- you need to press the center button to spell, which also counts as 1 step.
- After the pressing, you could begin to spell the next character in the key (next stage), otherwise, you've finished all the spelling.
-
- Example:
- Input: ring = "godding", key = "gd"
- Output: 4
- Explanation:
- For the first key character 'g', since it is already in place, we just need 1 step to spell this character.
- For the second key character 'd', we need to rotate the ring "godding" anticlockwise by two steps to make it become "ddinggo".
- Also, we need 1 more step for spelling.
- So the final output is 4.
-
- Note:
- Length of both ring and key will be in range 1 to 100.
- There are only lowercase letters in both strings and might be some duplcate characters in both strings.
- It's guaranteed that string key could always be spelled by rotating the string ring.
- */
 public class _514 {
 
     public static class Solution1 {
