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7 | 7 | import java.util.Map;
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8 | 8 | import java.util.Set;
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9 | 9 |
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10 |
| -/** |
11 |
| - * 890. Find and Replace Pattern |
12 |
| - * |
13 |
| - * You have a list of words and a pattern, and you want to know which words in words matches the pattern. |
14 |
| - * A word matches the pattern if there exists a permutation of letters p so that after replacing every letter x in the pattern with p(x), we get the desired word. |
15 |
| - * (Recall that a permutation of letters is a bijection from letters to letters: every letter maps to another letter, and no two letters map to the same letter.) |
16 |
| - * Return a list of the words in words that match the given pattern. |
17 |
| - * You may return the answer in any order. |
18 |
| - * |
19 |
| - * Example 1: |
20 |
| - * |
21 |
| - * Input: words = ["abc","deq","mee","aqq","dkd","ccc"], pattern = "abb" |
22 |
| - * Output: ["mee","aqq"] |
23 |
| - * Explanation: "mee" matches the pattern because there is a permutation {a -> m, b -> e, ...}. |
24 |
| - * "ccc" does not match the pattern because {a -> c, b -> c, ...} is not a permutation, |
25 |
| - * since a and b map to the same letter. |
26 |
| - * |
27 |
| - * Note: |
28 |
| - * 1 <= words.length <= 50 |
29 |
| - * 1 <= pattern.length = words[i].length <= 20 |
30 |
| - */ |
31 | 10 | public class _890 {
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32 |
| - public static class Solution1 { |
33 |
| - public List<String> findAndReplacePattern(String[] words, String pattern) { |
34 |
| - List<String> result = new ArrayList<>(); |
35 |
| - for (String word : words) { |
36 |
| - Map<Character, Character> map = new HashMap<>(); |
37 |
| - Set<Character> set = new HashSet<>(); |
38 |
| - boolean match = true; |
39 |
| - for (int i = 0; i < pattern.length(); i++) { |
40 |
| - if (map.containsKey(pattern.charAt(i))) { |
41 |
| - if (word.charAt(i) != map.get(pattern.charAt(i))) { |
42 |
| - match = false; |
43 |
| - break; |
| 11 | + public static class Solution1 { |
| 12 | + public List<String> findAndReplacePattern(String[] words, String pattern) { |
| 13 | + List<String> result = new ArrayList<>(); |
| 14 | + for (String word : words) { |
| 15 | + Map<Character, Character> map = new HashMap<>(); |
| 16 | + Set<Character> set = new HashSet<>(); |
| 17 | + boolean match = true; |
| 18 | + for (int i = 0; i < pattern.length(); i++) { |
| 19 | + if (map.containsKey(pattern.charAt(i))) { |
| 20 | + if (word.charAt(i) != map.get(pattern.charAt(i))) { |
| 21 | + match = false; |
| 22 | + break; |
| 23 | + } |
| 24 | + } else { |
| 25 | + map.put(pattern.charAt(i), word.charAt(i)); |
| 26 | + if (!set.add(word.charAt(i))) { |
| 27 | + match = false; |
| 28 | + } |
| 29 | + } |
| 30 | + } |
| 31 | + if (match) { |
| 32 | + result.add(word); |
| 33 | + } |
44 | 34 | }
|
45 |
| - } else { |
46 |
| - map.put(pattern.charAt(i), word.charAt(i)); |
47 |
| - if (!set.add(word.charAt(i))) { |
48 |
| - match = false; |
49 |
| - } |
50 |
| - } |
51 |
| - } |
52 |
| - if (match) { |
53 |
| - result.add(word); |
| 35 | + return result; |
54 | 36 | }
|
55 |
| - } |
56 |
| - return result; |
57 | 37 | }
|
58 |
| - } |
59 | 38 | }
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