解决菜单配置 isShow 异常处理

icssoa · icssoa · commit efa7ea764af2 · 2021-03-18T18:24:18.000+08:00
diff --git a/package.json b/package.json
@@ -1,6 +1,6 @@
 {
 	"name": "cool-admin-vue",
-	"version": "3.1.1",
+	"version": "3.1.2",
 	"scripts": {
 		"serve": "vue-cli-service serve",
 		"build": "vue-cli-service build",
diff --git a/src/cool/modules/base/components/menu/topbar.vue b/src/cool/modules/base/components/menu/topbar.vue
@@ -6,7 +6,7 @@
 			background-color="transparent"
 			@select="onSelect"
 		>
-			<el-menu-item v-for="(item, index) in menuGroup" :index="`${index}`" :key="index">
+			<el-menu-item v-for="(item, index) in list" :index="`${index}`" :key="index">
 				<icon-svg v-if="item.icon" :name="item.icon"></icon-svg>
 				<span>{{ item.name }}</span>
 			</el-menu-item>
@@ -28,7 +28,11 @@ export default {
 	},
 
 	computed: {
-		...mapGetters(["menuGroup"])
+		...mapGetters(["menuGroup"]),
+
+		list() {
+			return this.menuGroup.filter(e => e.isShow);
+		}
 	},
 
 	mounted() {
diff --git a/src/cool/modules/base/store/menu.js b/src/cool/modules/base/store/menu.js
@@ -42,7 +42,7 @@ export default {
 					}
 
 					const routes = res.menus
-						.filter(e => e.type != 2 && e.isShow)
+						.filter(e => e.type != 2)
 						.map(e => {
 							return {
 								moduleName: e.moduleName,
