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|1207|[Unique Number of Occurrences](https://leetcode.com/problems/unique-number-of-occurrences/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_1207.java)| O(n) | O(1) ||Easy||
|1185|[Day of the Week](https://leetcode.com/problems/day-of-the-week/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_1185.java)||||Easy||
|1160|[Find Words That Can Be Formed by Characters](https://leetcode.com/problems/find-words-that-can-be-formed-by-characters/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_1160.java)| O(n) | O(m) ||Easy||
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|1154|[Day of the Year](https://leetcode.com/problems/day-of-the-year/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_1154.java)| O(1) | O(1) ||Easy||
* There is a special keyboard with all keys in a single row.
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* Given a string keyboard of length 26 indicating the layout of the keyboard (indexed from 0 to 25),
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* initially your finger is at index 0.
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* To type a character, you have to move your finger to the index of the desired character. The time taken to move your finger from index i to index j is |i - j|.
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*
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* You want to type a string word. Write a function to calculate how much time it takes to type it with one finger.
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*
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* Example 1:
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* Input: keyboard = "abcdefghijklmnopqrstuvwxyz", word = "cba"
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* Output: 4
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* Explanation: The index moves from 0 to 2 to write 'c' then to 1 to write 'b' then to 0 again to write 'a'.
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* Total time = 2 + 1 + 1 = 4.
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*
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* Example 2:
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* Input: keyboard = "pqrstuvwxyzabcdefghijklmno", word = "leetcode"
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* Output: 73
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*
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* Constraints:
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* keyboard.length == 26
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* keyboard contains each English lowercase letter exactly once in some order.
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