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| 1 | +package com.fishercoder.solutions; |
| 2 | + |
| 3 | +import com.fishercoder.common.classes.TreeNode; |
| 4 | +import com.fishercoder.common.utils.TreeUtils; |
| 5 | + |
| 6 | +import java.lang.reflect.Array; |
| 7 | +import java.util.ArrayList; |
| 8 | +import java.util.Collections; |
| 9 | +import java.util.Deque; |
| 10 | +import java.util.LinkedList; |
| 11 | +import java.util.List; |
| 12 | +import java.util.Queue; |
| 13 | + |
| 14 | +/** |
| 15 | + * 1104. Path In Zigzag Labelled Binary Tree |
| 16 | + * |
| 17 | + * In an infinite binary tree where every node has two children, the nodes are labelled in row order. |
| 18 | + * In the odd numbered rows (ie., the first, third, fifth,...), the labelling is left to right, |
| 19 | + * while in the even numbered rows (second, fourth, sixth,...), the labelling is right to left. |
| 20 | + * |
| 21 | + * Given the label of a node in this tree, return the labels in the path from the root of the tree to the node with that label. |
| 22 | + * |
| 23 | + * Example 1: |
| 24 | + * Input: label = 14 |
| 25 | + * Output: [1,3,4,14] |
| 26 | + * |
| 27 | + * Example 2: |
| 28 | + * Input: label = 26 |
| 29 | + * Output: [1,2,6,10,26] |
| 30 | + * |
| 31 | + * Constraints: |
| 32 | + * 1 <= label <= 10^6 |
| 33 | + * */ |
| 34 | +public class _1104 { |
| 35 | + public static class Solution1 { |
| 36 | + /**This brute force solution is correct but results in TLE on LeetCode.*/ |
| 37 | + public List<Integer> pathInZigZagTree(int label) { |
| 38 | + Deque<Integer> deque = buildZigZagOrderList(label); |
| 39 | + TreeNode root = buildZigZagOrderTree(deque); |
| 40 | + TreeUtils.printBinaryTree(root); |
| 41 | + return dfs(root, label, new ArrayList<>()); |
| 42 | + } |
| 43 | + |
| 44 | + private List<Integer> dfs(TreeNode root, int label, List<Integer> list) { |
| 45 | + if (root == null) { |
| 46 | + return list; |
| 47 | + } |
| 48 | + list.add(root.val); |
| 49 | + if (root.val == label) { |
| 50 | + return list; |
| 51 | + } |
| 52 | + dfs(root.left, label, list); |
| 53 | + dfs(root.right, label, list); |
| 54 | + if (list.get(list.size() - 1) == label) { |
| 55 | + return list; |
| 56 | + } |
| 57 | + list.remove(list.size() - 1); |
| 58 | + return list; |
| 59 | + } |
| 60 | + |
| 61 | + private TreeNode buildZigZagOrderTree(Deque<Integer> deque) { |
| 62 | + TreeNode root = new TreeNode(deque.pollFirst()); |
| 63 | + Queue<TreeNode> queue = new LinkedList<>(); |
| 64 | + queue.offer(root); |
| 65 | + while (!deque.isEmpty()) { |
| 66 | + int size = queue.size(); |
| 67 | + for (int i = 0; i < size; i++) { |
| 68 | + TreeNode curr = queue.poll(); |
| 69 | + curr.left = new TreeNode(deque.pollFirst()); |
| 70 | + curr.right = new TreeNode(deque.pollFirst()); |
| 71 | + queue.offer(curr.left); |
| 72 | + queue.offer(curr.right); |
| 73 | + } |
| 74 | + } |
| 75 | + return root; |
| 76 | + } |
| 77 | + |
| 78 | + private Deque<Integer> buildZigZagOrderList(int label) { |
| 79 | + Deque<Integer> deque = new LinkedList<>(); |
| 80 | + int num = 1; |
| 81 | + int level = 2; |
| 82 | + deque.add(num); |
| 83 | + do { |
| 84 | + num++; |
| 85 | + List<Integer> newLevel = new ArrayList<>(); |
| 86 | + for (; num < Math.pow(2, level); num++) { |
| 87 | + newLevel.add(num); |
| 88 | + } |
| 89 | + num--; |
| 90 | + if (level % 2 == 0) { |
| 91 | + Collections.reverse(newLevel); |
| 92 | + } |
| 93 | + deque.addAll(newLevel); |
| 94 | + newLevel.clear(); |
| 95 | + level++; |
| 96 | + } while (deque.getLast() < label); |
| 97 | + return deque; |
| 98 | + } |
| 99 | + } |
| 100 | +} |
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