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refactor 1083
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database/_1083.sql

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--1083. Sales Analysis II
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--
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--Table: Product
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--
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--+--------------+---------+
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--| Column Name | Type |
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--+--------------+---------+
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--| product_id | int |
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--| product_name | varchar |
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--| unit_price | int |
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--+--------------+---------+
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--product_id is the primary key of this table.
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--Table: Sales
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--
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--+-------------+---------+
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--| Column Name | Type |
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--+-------------+---------+
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--| seller_id | int |
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--| product_id | int |
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--| buyer_id | int |
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--| sale_date | date |
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--| quantity | int |
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--| price | int |
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--+------ ------+---------+
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--This table has no primary key, it can have repeated rows.
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--product_id is a foreign key to Product table.
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--
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--
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--Write an SQL query that reports the buyers who have bought S8 but not iPhone. Note that S8 and iPhone are products present in the Product table.
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--
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--The query result format is in the following example:
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--
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--Product table:
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--+------------+--------------+------------+
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--| product_id | product_name | unit_price |
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--+------------+--------------+------------+
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--| 1 | S8 | 1000 |
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--| 2 | G4 | 800 |
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--| 3 | iPhone | 1400 |
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--+------------+--------------+------------+
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--
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--Sales table:
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--+-----------+------------+----------+------------+----------+-------+
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--| seller_id | product_id | buyer_id | sale_date | quantity | price |
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--+-----------+------------+----------+------------+----------+-------+
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--| 1 | 1 | 1 | 2019-01-21 | 2 | 2000 |
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--| 1 | 2 | 2 | 2019-02-17 | 1 | 800 |
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--| 2 | 1 | 3 | 2019-06-02 | 1 | 800 |
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--| 3 | 3 | 3 | 2019-05-13 | 2 | 2800 |
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--+-----------+------------+----------+------------+----------+-------+
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--
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--Result table:
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--+-------------+
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--| buyer_id |
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--+-------------+
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--| 1 |
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--+-------------+
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--The buyer with id 1 bought an S8 but didn't buy an iPhone. The buyer with id 3 bought both.
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--# Write your MySQL query statement below
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select distinct buyer_id from Sales s
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join Product p
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on p.product_id = s.product_id

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