refactor 1179

fishercoder1534 · fishercoder1534 · commit e6e0b29c6288 · 2020-04-25T13:53:23.000-07:00
diff --git a/database/_1179.sql b/database/_1179.sql
@@ -1,49 +1,3 @@
---1179. Reformat Department Table
---
---SQL Schema
---Table: Department
---
---+---------------+---------+
---| Column Name   | Type    |
---+---------------+---------+
---| id            | int     |
---| revenue       | int     |
---| month         | varchar |
---+---------------+---------+
---(id, month) is the primary key of this table.
---The table has information about the revenue of each department per month.
---The month has values in ["Jan","Feb","Mar","Apr","May","Jun","Jul","Aug","Sep","Oct","Nov","Dec"].
---
---Write an SQL query to reformat the table such that there is a department id column and a revenue column for each month.
---
---The query result format is in the following example:
---
---Department table:
---+------+---------+-------+
---| id   | revenue | month |
---+------+---------+-------+
---| 1    | 8000    | Jan   |
---| 2    | 9000    | Jan   |
---| 3    | 10000   | Feb   |
---| 1    | 7000    | Feb   |
---| 1    | 6000    | Mar   |
---+------+---------+-------+
---
---Result table:
---+------+-------------+-------------+-------------+-----+-------------+
---| id   | Jan_Revenue | Feb_Revenue | Mar_Revenue | ... | Dec_Revenue |
---+------+-------------+-------------+-------------+-----+-------------+
---| 1    | 8000        | 7000        | 6000        | ... | null        |
---| 2    | 9000        | null        | null        | ... | null        |
---| 3    | null        | 10000       | null        | ... | null        |
---+------+-------------+-------------+-------------+-----+-------------+
---
---Note that the result table has 13 columns (1 for the department id + 12 for the months).
-
-
--- Write your MySQL query statement below
-
---group by solution
 select id,
 max(case when month = 'Jan' then revenue else null end) as 'Jan_Revenue',
 max(case when month = 'Feb' then revenue else null end) as 'Feb_Revenue',
