block, bfq: postpone rq preparation to insert or merge

Algodev-github · axboe · commit 18e5a57d7987 · 2018-05-10T10:16:29.000-06:00
When invoked for an I/O request rq, the prepare_request hook of bfq
increments reference counters in the destination bfq_queue for rq. In
this respect, after this hook has been invoked, rq may still be
transformed into a request with no icq attached, i.e., for bfq, a
request not associated with any bfq_queue. No further hook is invoked
to signal this tranformation to bfq (in general, to the destination
elevator for rq). This leads bfq into an inconsistent state, because
bfq has no chance to correctly lower these counters back. This
inconsistency may in its turn cause incorrect scheduling and hangs. It
certainly causes memory leaks, by making it impossible for bfq to free
the involved bfq_queue.

On the bright side, no transformation can still happen for rq after rq
has been inserted into bfq, or merged with another, already inserted,
request. Exploiting this fact, this commit addresses the above issue
by delaying the preparation of an I/O request to when the request is
inserted or merged.

This change also gives a performance bonus: a lock-contention point
gets removed. To prepare a request, bfq needs to hold its scheduler
lock. After postponing request preparation to insertion or merging, no
lock needs to be grabbed any longer in the prepare_request hook, while
the lock already taken to perform insertion or merging is used to
preparare the request as well.

Tested-by: Oleksandr Natalenko &lt;oleksandr@natalenko.name&gt;
Tested-by: Bart Van Assche &lt;bart.vanassche@wdc.com&gt;
Signed-off-by: Paolo Valente &lt;paolo.valente@linaro.org&gt;
Signed-off-by: Jens Axboe &lt;axboe@kernel.dk&gt;
diff --git a/block/bfq-iosched.c b/block/bfq-iosched.c
@@ -1858,6 +1858,8 @@ static int bfq_request_merge(struct request_queue *q, struct request **req,
 	return ELEVATOR_NO_MERGE;
 }
 
+static struct bfq_queue *bfq_init_rq(struct request *rq);
+
 static void bfq_request_merged(struct request_queue *q, struct request *req,
 			       enum elv_merge type)
 {
@@ -1866,7 +1868,7 @@ static void bfq_request_merged(struct request_queue *q, struct request *req,
 	    blk_rq_pos(req) <
 	    blk_rq_pos(container_of(rb_prev(&req->rb_node),
 				    struct request, rb_node))) {
-		struct bfq_queue *bfqq = RQ_BFQQ(req);
+		struct bfq_queue *bfqq = bfq_init_rq(req);
 		struct bfq_data *bfqd = bfqq->bfqd;
 		struct request *prev, *next_rq;
 
@@ -1894,7 +1896,8 @@ static void bfq_request_merged(struct request_queue *q, struct request *req,
 static void bfq_requests_merged(struct request_queue *q, struct request *rq,
 				struct request *next)
 {
-	struct bfq_queue *bfqq = RQ_BFQQ(rq), *next_bfqq = RQ_BFQQ(next);
+	struct bfq_queue *bfqq = bfq_init_rq(rq),
+		*next_bfqq = bfq_init_rq(next);
 
 	if (!RB_EMPTY_NODE(&rq->rb_node))
 		goto end;
@@ -4540,14 +4543,12 @@ static inline void bfq_update_insert_stats(struct request_queue *q,
 					   unsigned int cmd_flags) {}
 #endif
 
-static void bfq_prepare_request(struct request *rq, struct bio *bio);
-
 static void bfq_insert_request(struct blk_mq_hw_ctx *hctx, struct request *rq,
 			       bool at_head)
 {
 	struct request_queue *q = hctx->queue;
 	struct bfq_data *bfqd = q->elevator->elevator_data;
-	struct bfq_queue *bfqq = RQ_BFQQ(rq);
+	struct bfq_queue *bfqq;
 	bool idle_timer_disabled = false;
 	unsigned int cmd_flags;
 
@@ -4562,24 +4563,13 @@ static void bfq_insert_request(struct blk_mq_hw_ctx *hctx, struct request *rq,
 	blk_mq_sched_request_inserted(rq);
 
 	spin_lock_irq(&bfqd->lock);
+	bfqq = bfq_init_rq(rq);
 	if (at_head || blk_rq_is_passthrough(rq)) {
 		if (at_head)
 			list_add(&rq->queuelist, &bfqd->dispatch);
 		else
 			list_add_tail(&rq->queuelist, &bfqd->dispatch);
-	} else {
-		if (WARN_ON_ONCE(!bfqq)) {
-			/*
-			 * This should never happen. Most likely rq is
-			 * a requeued regular request, being
-			 * re-inserted without being first
-			 * re-prepared. Do a prepare, to avoid
-			 * failure.
-			 */
-			bfq_prepare_request(rq, rq->bio);
-			bfqq = RQ_BFQQ(rq);
-		}
-
+	} else { /* bfqq is assumed to be non null here */
 		idle_timer_disabled = __bfq_insert_request(bfqd, rq);
 		/*
 		 * Update bfqq, because, if a queue merge has occurred
@@ -4922,32 +4912,70 @@ static struct bfq_queue *bfq_get_bfqq_handle_split(struct bfq_data *bfqd,
 }
 
 /*
- * Allocate bfq data structures associated with this request.
+ * Only reset private fields. The actual request preparation will be
+ * performed by bfq_init_rq, when rq is either inserted or merged. See
+ * comments on bfq_init_rq for the reason behind this delayed
+ * preparation.
  */
 static void bfq_prepare_request(struct request *rq, struct bio *bio)
+{
+	/*
+	 * Regardless of whether we have an icq attached, we have to
+	 * clear the scheduler pointers, as they might point to
+	 * previously allocated bic/bfqq structs.
+	 */
+	rq->elv.priv[0] = rq->elv.priv[1] = NULL;
+}
+
+/*
+ * If needed, init rq, allocate bfq data structures associated with
+ * rq, and increment reference counters in the destination bfq_queue
+ * for rq. Return the destination bfq_queue for rq, or NULL is rq is
+ * not associated with any bfq_queue.
+ *
+ * This function is invoked by the functions that perform rq insertion
+ * or merging. One may have expected the above preparation operations
+ * to be performed in bfq_prepare_request, and not delayed to when rq
+ * is inserted or merged. The rationale behind this delayed
+ * preparation is that, after the prepare_request hook is invoked for
+ * rq, rq may still be transformed into a request with no icq, i.e., a
+ * request not associated with any queue. No bfq hook is invoked to
+ * signal this tranformation. As a consequence, should these
+ * preparation operations be performed when the prepare_request hook
+ * is invoked, and should rq be transformed one moment later, bfq
+ * would end up in an inconsistent state, because it would have
+ * incremented some queue counters for an rq destined to
+ * transformation, without any chance to correctly lower these
+ * counters back. In contrast, no transformation can still happen for
+ * rq after rq has been inserted or merged. So, it is safe to execute
+ * these preparation operations when rq is finally inserted or merged.
+ */
+static struct bfq_queue *bfq_init_rq(struct request *rq)
 {
 	struct request_queue *q = rq->q;
+	struct bio *bio = rq->bio;
 	struct bfq_data *bfqd = q->elevator->elevator_data;
 	struct bfq_io_cq *bic;
 	const int is_sync = rq_is_sync(rq);
 	struct bfq_queue *bfqq;
 	bool new_queue = false;
 	bool bfqq_already_existing = false, split = false;
 
+	if (unlikely(!rq->elv.icq))
+		return NULL;
+
 	/*
-	 * Even if we don't have an icq attached, we should still clear
-	 * the scheduler pointers, as they might point to previously
-	 * allocated bic/bfqq structs.
+	 * Assuming that elv.priv[1] is set only if everything is set
+	 * for this rq. This holds true, because this function is
+	 * invoked only for insertion or merging, and, after such
+	 * events, a request cannot be manipulated any longer before
+	 * being removed from bfq.
 	 */
-	if (!rq->elv.icq) {
-		rq->elv.priv[0] = rq->elv.priv[1] = NULL;
-		return;
-	}
+	if (rq->elv.priv[1])
+		return rq->elv.priv[1];
 
 	bic = icq_to_bic(rq->elv.icq);
 
-	spin_lock_irq(&bfqd->lock);
-
 	bfq_check_ioprio_change(bic, bio);
 
 	bfq_bic_update_cgroup(bic, bio);
@@ -5006,7 +5034,7 @@ static void bfq_prepare_request(struct request *rq, struct bio *bio)
 	if (unlikely(bfq_bfqq_just_created(bfqq)))
 		bfq_handle_burst(bfqd, bfqq);
 
-	spin_unlock_irq(&bfqd->lock);
+	return bfqq;
 }
 
 static void bfq_idle_slice_timer_body(struct bfq_queue *bfqq)
