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README.md

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@@ -416,7 +416,7 @@ Your ideas/fixes/algorithms are more than welcome!
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|162|[Find Peak Element](https://leetcode.com/problems/find-peak-element/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_162.java) | O(1) |O(logn)/O(n) | Binary Search|
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|161|[One Edit Distance](https://leetcode.com/problems/one-edit-distance/)|[Solution](../master/src/main/java/com/fishercoder/solutions/OneEditDistance.java) | O(n) |O(1) | |
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|160|[Intersection of Two Linked Lists](https://leetcode.com/problems/intersection-of-two-linked-lists/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_160.java)| O(m+n)|O(1) | Easy| Linked List
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|159|[Longest Substring with At Most Two Distinct Characters](https://leetcode.com/problems/longest-substring-with-at-most-two-distinct-characters/)|[Solution](../master/src/main/java/com/fishercoder/solutions/LongestSubstringwithAtMostTwoDistinctCharacters.java)| O(n)|O(1) | Hard| String, Sliding Window
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|159|[Longest Substring with At Most Two Distinct Characters](https://leetcode.com/problems/longest-substring-with-at-most-two-distinct-characters/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_159.java)| O(n)|O(1) | Hard| String, Sliding Window
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|158|[Read N Characters Given Read4 II - Call multiple times](https://leetcode.com/problems/read-n-characters-given-read4-ii-call-multiple-times/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_158.java)| O(n)|O(1) | Hard|
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|157|[Read N Characters Given Read4](https://leetcode.com/problems/read-n-characters-given-read4/)|[Solution](../master/src/main/java/com/fishercoder/solutions/ReadNCharactersGivenRead4.java)| O(n)|O(1) | Easy|
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|156|[Binary Tree Upside Down](https://leetcode.com/problems/binary-tree-upside-down/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_156.java)| O(n)|O(h) | Medium| Tree, Recursion
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T is "ece" which its length is 3.
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*/
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public class LongestSubstringwithAtMostTwoDistinctCharacters {
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public class _159 {
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public int lengthOfLongestSubstringTwoDistinct(String s) {
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if (s.length() < 1)

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