What happened

Calling sort on a Seq evaluated the Seq immediately even though I expect it to not evaluate until the Seq is actually used.

How to reproduce

When I run:

Seq([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]).filter(x => {
  console.log('filtering');
  return x >= 5;
});

I see no output, which is expected behavior. However, when I append a .sort() after the filter call:

Seq([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]).filter(x => {
  console.log('filtering');
  return x >= 5;
}).sort();

I receive the following output:

filtering
filtering
filtering
filtering
filtering
filtering
filtering
filtering
filtering
filtering

Is this intended behavior? If so, do you have any suggestions for combining sort functions with lazy evaluation?