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| 1 | +package easy; |
| 2 | + |
| 3 | +/** |
| 4 | + * Have the function FindIntersection(strArr) read the array of strings |
| 5 | + * stored in strArr which will contain 2 elements: the first element |
| 6 | + * will represent a list of comma-separated numbers sorted in ascending order, |
| 7 | + * the second element will represent a second list of comma-separated numbers (also sorted). |
| 8 | + * Your goal is to return a comma-separated string containing |
| 9 | + * the numbers that occur in elements of strArr in sorted order. |
| 10 | + * If there is no intersection, return the string false. |
| 11 | + */ |
| 12 | +public class FindIntersection { |
| 13 | + |
| 14 | + /** |
| 15 | + * Binary Search helper function. |
| 16 | + * |
| 17 | + * @param coll an array of integers |
| 18 | + * @param key a value to find |
| 19 | + * @return index of the key |
| 20 | + */ |
| 21 | + private static int binarySearch(Integer[] coll, Integer key) { |
| 22 | + int lo = 0; |
| 23 | + int hi = coll.length - 1; |
| 24 | + while (lo <= hi) { |
| 25 | + int mid = lo + (hi - lo) / 2; |
| 26 | + if (key < coll[mid]) { |
| 27 | + hi = mid - 1; |
| 28 | + } else if (key > coll[mid]) { |
| 29 | + lo = mid + 1; |
| 30 | + } else { |
| 31 | + return mid; |
| 32 | + } |
| 33 | + } |
| 34 | + return -1; |
| 35 | + } |
| 36 | + |
| 37 | + /** |
| 38 | + * Convert a string to an array of integers. |
| 39 | + * |
| 40 | + * @param strArr comma-delimited string of numbers |
| 41 | + * @return array of integers |
| 42 | + */ |
| 43 | + private static Integer[] toIntArray(String strArr) { |
| 44 | + String[] tmpArr = strArr.split(", "); |
| 45 | + Integer[] intArr = new Integer[tmpArr.length]; |
| 46 | + for (int i = 0; i < tmpArr.length; i++) { |
| 47 | + intArr[i] = Integer.parseInt(tmpArr[i].trim()); |
| 48 | + } |
| 49 | + return intArr; |
| 50 | + } |
| 51 | + |
| 52 | + /** |
| 53 | + * Find Intersection function. |
| 54 | + * |
| 55 | + * @param arr input array containing two strings of comma-delimited integers |
| 56 | + * @return the numbers that occur in elements of strArr in sorted order. |
| 57 | + */ |
| 58 | + private static String findIntersection(String[] arr) { |
| 59 | + Integer[] arr1 = toIntArray(arr[0]); |
| 60 | + Integer[] arr2 = toIntArray(arr[1]); |
| 61 | + StringBuilder builder = new StringBuilder(); |
| 62 | + for (int i : arr1.length > arr2.length ? arr2 : arr1) { |
| 63 | + int findIndex = binarySearch(arr1.length > arr2.length ? arr1 : arr2, i); |
| 64 | + if (findIndex > -1) { |
| 65 | + builder.append(i).append(","); |
| 66 | + } |
| 67 | + } |
| 68 | + String result = builder.toString(); |
| 69 | + return result.length() == 0 ? "false" : builder.substring(0, result.length() - 1); |
| 70 | + } |
| 71 | + |
| 72 | + /** |
| 73 | + * Entry point. |
| 74 | + * |
| 75 | + * @param args command line arguments |
| 76 | + */ |
| 77 | + public static void main(String[] args) { |
| 78 | + var result1 = findIntersection(new String[]{"11, 12, 14, 16, 20", "11, 12, 13, 18, 21"}); |
| 79 | + System.out.println(result1); |
| 80 | + var result2 = findIntersection(new String[]{"1, 3, 4, 7, 13", "1, 2, 4, 13, 15"}); |
| 81 | + System.out.println(result2); |
| 82 | + var result3 = findIntersection(new String[]{"21, 22, 23, 25, 27, 28", "21, 24, 25, 29"}); |
| 83 | + System.out.println(result3); |
| 84 | + } |
| 85 | + |
| 86 | +} |
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