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| 1 | +class Solution { |
| 2 | + public boolean isPossible(int n, List<List<Integer>> edges) { |
| 3 | + Map<Integer, Set<Integer>> graph = new HashMap<>(); |
| 4 | + for (List<Integer> edge : edges) { |
| 5 | + graph.computeIfAbsent(edge.get(0), k -> new HashSet<>()).add(edge.get(1)); |
| 6 | + graph.computeIfAbsent(edge.get(1), k -> new HashSet<>()).add(edge.get(0)); |
| 7 | + } |
| 8 | + List<Integer> nodeWithOddEdges = graph.entrySet() |
| 9 | + .stream() |
| 10 | + .filter(e -> e.getValue().size() % 2 != 0) |
| 11 | + .map(Map.Entry::getKey) |
| 12 | + .collect(Collectors.toList()); |
| 13 | + if (nodeWithOddEdges.size() == 0) { |
| 14 | + return true; |
| 15 | + } |
| 16 | + if (nodeWithOddEdges.size() == 2) { |
| 17 | + Integer nodeOne = nodeWithOddEdges.get(0); |
| 18 | + Integer nodeTwo = nodeWithOddEdges.get(1); |
| 19 | + if (!hasEdge(graph, nodeOne, nodeTwo)) { |
| 20 | + return true; |
| 21 | + } |
| 22 | + for (int i = 1; i <= n; i++) { |
| 23 | + if (i == nodeOne || i == nodeTwo) { |
| 24 | + continue; |
| 25 | + } |
| 26 | + if (!hasEdge(graph, i, nodeOne) && !hasEdge(graph, i, nodeTwo)) { |
| 27 | + return true; |
| 28 | + } |
| 29 | + } |
| 30 | + } |
| 31 | + if (nodeWithOddEdges.size() == 4) { |
| 32 | + Integer nodeOne = nodeWithOddEdges.get(0); |
| 33 | + Integer nodeTwo = nodeWithOddEdges.get(1); |
| 34 | + Integer nodeThree = nodeWithOddEdges.get(2); |
| 35 | + Integer nodeFour = nodeWithOddEdges.get(3); |
| 36 | + if ((!hasEdge(graph, nodeOne, nodeTwo) && !hasEdge(graph, nodeThree, nodeFour)) || |
| 37 | + (!hasEdge(graph, nodeOne, nodeThree) && !hasEdge(graph, nodeTwo, nodeFour)) || |
| 38 | + (!hasEdge(graph, nodeOne, nodeFour) && !hasEdge(graph, nodeTwo, nodeThree))) { |
| 39 | + return true; |
| 40 | + } |
| 41 | + } |
| 42 | + return false; |
| 43 | + } |
| 44 | + |
| 45 | + private static boolean hasEdge(Map<Integer, Set<Integer>> graph, int nodeOne, int nodeTwo) { |
| 46 | + return graph.getOrDefault(nodeOne, new HashSet<>()).contains(nodeTwo); |
| 47 | + } |
| 48 | +} |
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