Merge pull request #44 from yichung279/floatingpoint/3.7

adrianliaw · web-flow · commit 2352742a5c34 · 2018-10-16T17:04:13.000+08:00
Working on floatingpoint
diff --git a/tutorial/floatingpoint.po b/tutorial/floatingpoint.po
@@ -8,7 +8,7 @@ msgstr ""
 "Project-Id-Version: Python 3.7\n"
 "Report-Msgid-Bugs-To: \n"
 "POT-Creation-Date: 2018-06-26 18:54+0800\n"
-"PO-Revision-Date: 2016-11-19 00:37+0000\n"
+"PO-Revision-Date: 2018-10-16 16:15+0800\n"
 "Last-Translator: Liang-Bo Wang <me@liang2.tw>\n"
 "Language-Team: Chinese - TAIWAN (https://github.com/python/python-docs-zh-"
 "tw)\n"
@@ -17,28 +17,37 @@ msgstr ""
 "Content-Type: text/plain; charset=UTF-8\n"
 "Content-Transfer-Encoding: 8bit\n"
 "Plural-Forms: nplurals=1; plural=0;\n"
+"X-Generator: Poedit 2.2\n"
 
 #: ../../tutorial/floatingpoint.rst:9
 msgid "Floating Point Arithmetic:  Issues and Limitations"
-msgstr ""
+msgstr "浮點數運算：問題與限制"
 
 #: ../../tutorial/floatingpoint.rst:14
 msgid ""
 "Floating-point numbers are represented in computer hardware as base 2 "
 "(binary) fractions.  For example, the decimal fraction ::"
 msgstr ""
+"在計算機架構中，浮點數透過二進位小數表示。例如說，在十進位小數中：\n"
+"\n"
+"::"
 
 #: ../../tutorial/floatingpoint.rst:19
 msgid ""
 "has value 1/10 + 2/100 + 5/1000, and in the same way the binary fraction ::"
 msgstr ""
+"可被分為 1/10 + 2/100 + 5/1000，同樣的道理，二進位小數 ：\n"
+"\n"
+"::"
 
 #: ../../tutorial/floatingpoint.rst:23
 msgid ""
 "has value 0/2 + 0/4 + 1/8.  These two fractions have identical values, the "
 "only real difference being that the first is written in base 10 fractional "
 "notation, and the second in base 2."
 msgstr ""
+"可被分為 0/2 + 0/4 + 1/8。這兩個小數有相同的數值，而唯一真正的不同在於前者以"
+"十進位表示，後者以二進位表示。"
 
 #: ../../tutorial/floatingpoint.rst:27
 msgid ""
@@ -47,30 +56,45 @@ msgid ""
 "point numbers you enter are only approximated by the binary floating-point "
 "numbers actually stored in the machine."
 msgstr ""
+"不幸的是，大多數十進位小數無法精準地以二進位小數表示。一般的結果為，您輸入的"
+"十進位浮點數由實際存在計算機中的二進位浮點數近似。"
 
 #: ../../tutorial/floatingpoint.rst:32
 msgid ""
 "The problem is easier to understand at first in base 10.  Consider the "
 "fraction 1/3.  You can approximate that as a base 10 fraction::"
 msgstr ""
+"在十進位中，這個問題更容易被理解。以分數 1/3 為例，您可以將其近似為十進位小"
+"數：\n"
+"\n"
+"::"
 
 #: ../../tutorial/floatingpoint.rst:37 ../../tutorial/floatingpoint.rst:41
 msgid "or, better, ::"
 msgstr ""
+"或者，更好的近似：\n"
+"\n"
+"::"
 
 #: ../../tutorial/floatingpoint.rst:45
 msgid ""
 "and so on.  No matter how many digits you're willing to write down, the "
 "result will never be exactly 1/3, but will be an increasingly better "
 "approximation of 1/3."
 msgstr ""
+"依此類推，不論你使用多少位數表示小數，最後的結果都無法精準地表示 1/3，但你還"
+"是能越來越精準地表示 1/3。"
 
 #: ../../tutorial/floatingpoint.rst:49
 msgid ""
 "In the same way, no matter how many base 2 digits you're willing to use, the "
 "decimal value 0.1 cannot be represented exactly as a base 2 fraction.  In "
 "base 2, 1/10 is the infinitely repeating fraction ::"
 msgstr ""
+"同樣的道理，不論你願意以多少位數表示二進位小數，十進位小數 0.1 都無法被二進位"
+"小數精準地表達。在二進位小數中， 1/10 會是一個無限循環小數：\n"
+"\n"
+"::"
 
 #: ../../tutorial/floatingpoint.rst:55
 msgid ""
