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Copy file name to clipboardExpand all lines: README.md
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-[> Beware of default mutable arguments!/当心默认的可变参数!](#-beware-of-default-mutable-arguments当心默认的可变参数)
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-[> Catching the Exceptions/捕获异常](#-catching-the-exceptions捕获异常)
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-[> Same operands, different story!/同人不同命!](#-same-operands-different-story同人不同命)
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-[> The out of scope variable](#-the-out-of-scope-variable)
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-[> The out of scope variable/外部作用域变量](#-the-out-of-scope-variable外部作用域变量)
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-[> Be careful with chained operations](#-be-careful-with-chained-operations)
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-[> Name resolution ignoring class scope](#-name-resolution-ignoring-class-scope)
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-[> Needle in a Haystack](#-needle-in-a-haystack)
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### > The out of scope variable
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### > The out of scope variable/外部作用域变量
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```py
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a = 1
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UnboundLocalError: local variable 'a' referenced before assignment
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```
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#### 💡 Explanation:
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* When you make an assignment to a variable in scope, it becomes local to that scope. So `a` becomes local to the scope of `another_func`, but it has not been initialized previously in the same scope which throws an error.
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* Read [this](http://sebastianraschka.com/Articles/2014_python_scope_and_namespaces.html) short but an awesome guide to learn more about how namespaces and scope resolution works in Python.
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* To modify the outer scope variable `a` in `another_func`, use `global` keyword.
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