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| 1 | +/* |
| 2 | + * Problem: 57 |
| 3 | + * Name: Insert Interval |
| 4 | + * Difficulty: Medium |
| 5 | + * Topic: Intervals |
| 6 | + * Link: https://leetcode.com/problems/insert-interval/ |
| 7 | + */ |
| 8 | + |
| 9 | +#include <algorithm> |
| 10 | +#include <bits/stdc++.h> |
| 11 | +using namespace std; |
| 12 | + |
| 13 | +// Initial Solution (not focused on the global cases) |
| 14 | +// Time Complexity: O(n) |
| 15 | +// Space Complexity: O(n) |
| 16 | +vector<vector<int>> insert(vector<vector<int>>& intervals, vector<int>& newInterval) { |
| 17 | + vector<vector<int>> result; |
| 18 | + bool hasInserted = false; |
| 19 | + for (const vector<int>& interval : intervals){ |
| 20 | + if (!hasInserted){ |
| 21 | + if (interval[1] < newInterval[0]) { |
| 22 | + result.push_back(interval); |
| 23 | + } |
| 24 | + else if (interval[0] < newInterval[0]) { |
| 25 | + result.push_back(interval); |
| 26 | + result.back()[1] = max(interval[1], newInterval[1]); |
| 27 | + hasInserted = true; |
| 28 | + } |
| 29 | + else if (interval[0] <= newInterval[1]) { |
| 30 | + result.push_back(newInterval); |
| 31 | + result.back()[1] = max(interval[1], newInterval[1]); |
| 32 | + hasInserted = true; |
| 33 | + } |
| 34 | + else { |
| 35 | + result.push_back(newInterval); |
| 36 | + result.push_back(interval); |
| 37 | + hasInserted = true; |
| 38 | + } |
| 39 | + } |
| 40 | + else { |
| 41 | + if (result.back()[1] < interval[0]){ |
| 42 | + result.push_back(interval); |
| 43 | + } |
| 44 | + else { |
| 45 | + result.back()[1] = max(interval[1], result.back()[1]); |
| 46 | + } |
| 47 | + } |
| 48 | + } |
| 49 | + if (!hasInserted){ |
| 50 | + result.push_back(newInterval); |
| 51 | + hasInserted = true; |
| 52 | + } |
| 53 | + return result; |
| 54 | +} |
| 55 | + |
| 56 | +// Optimized Solution (3 main cases) |
| 57 | +// Time Complexity: O(n) |
| 58 | +// Space Complexity: O(n) |
| 59 | +vector<vector<int>> insert(vector<vector<int>>& intervals, vector<int>& newInterval) { |
| 60 | + vector<vector<int>> result; |
| 61 | + int i = 0; |
| 62 | + |
| 63 | + while (i < intervals.size() && intervals[i][1] < newInterval[0]){ |
| 64 | + result.push_back(intervals[i]); |
| 65 | + i++; |
| 66 | + } |
| 67 | + |
| 68 | + while (i < intervals.size() && intervals[i][0] <= newInterval[1]){ |
| 69 | + newInterval[0] = min(intervals[i][0], newInterval[0]); |
| 70 | + newInterval[1] = max(intervals[i][1], newInterval[1]); |
| 71 | + i++; |
| 72 | + } |
| 73 | + result.push_back(newInterval); |
| 74 | + |
| 75 | + while (i < intervals.size()){ |
| 76 | + result.push_back(intervals[i]); |
| 77 | + i++; |
| 78 | + } |
| 79 | + |
| 80 | + return result; |
| 81 | +} |
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