diff --git a/.github/FUNDING.yml b/.github/FUNDING.yml new file mode 100644 index 000000000..2f943cf35 --- /dev/null +++ b/.github/FUNDING.yml @@ -0,0 +1,13 @@ +# These are supported funding model platforms + +github: [halfrost] +patreon: # Replace with a single Patreon username +open_collective: # Replace with a single Open Collective username +ko_fi: # Replace with a single Ko-fi username +tidelift: # Replace with a single Tidelift platform-name/package-name e.g., npm/babel +community_bridge: # Replace with a single Community Bridge project-name e.g., cloud-foundry +liberapay: # Replace with a single Liberapay username +issuehunt: # Replace with a single IssueHunt username +otechie: # Replace with a single Otechie username +lfx_crowdfunding: # Replace with a single LFX Crowdfunding project-name e.g., cloud-foundry +custom: # Replace with up to 4 custom sponsorship URLs e.g., ['link1', 'link2'] diff --git a/.github/workflows/deploy.yml b/.github/workflows/deploy.yml index bea6ae885..42d1586b1 100644 --- a/.github/workflows/deploy.yml +++ b/.github/workflows/deploy.yml @@ -28,12 +28,11 @@ jobs: hugo -D --minify - name: Deploy to Server # 第四步，rsync推文件 - uses: AEnterprise/rsync-deploy@v1.0 # 使用别人包装好的步骤镜像 - env: - DEPLOY_KEY: ${{ secrets.DEPLOY_KEY }} # 引用配置，SSH私钥 - ARGS: -avz --delete --exclude='*.pyc' # rsync参数，排除.pyc文件 - SERVER_PORT: '22' # SSH端口 - FOLDER: ./website/public/* #推送的文件夹，路径相对于代码仓库的根目录 - SERVER_IP: ${{ secrets.SSH_HOST }} # 引用配置，服务器的host名（IP或者域名domain.com） - USERNAME: ${{ secrets.SSH_USERNAME }} # 引用配置，服务器登录名 - SERVER_DESTINATION: /var/www/books/leetcode/ # 部署到目标文件夹 + uses: appleboy/ssh-action@v0.1.3 # 使用别人包装好的步骤镜像 + with: + host: ${{ secrets.SSH_HOST }} + username: ${{ secrets.SSH_USERNAME }} + key: ${{ secrets.DEPLOY_KEY }} + port: ${{ secrets.SERVER_PORT }} + script: | + rsync -avz --delete --exclude='*.pyc' ./website/public/ ${{ secrets.SSH_USERNAME }}@${{ secrets.SSH_HOST }}:${{ secrets.SERVER_DESTINATION }} diff --git a/README.md b/README.md index b8c0c40c8..ebb30e7d1 100755 --- a/README.md +++ b/README.md @@ -10,9 +10,9 @@ ![](./website/static/wechat-qr-code.png)

-GitHub All Releases +GitHub All Releases - + @@ -23,7 +23,7 @@

-GitHub +GitHub @@ -126,1860 +126,2463 @@ | | Easy | Medium | Hard | Total | |:--------:|:--------:|:--------:|:--------:|:--------:| -|Optimizing|36|37|17|90| -|Accepted|**277**|**369**|**107**|**753**| -|Total|481|972|388|1841| -|Perfection Rate|87.0%|90.0%|84.1%|88.0%| -|Completion Rate|57.6%|38.0%|27.6%|40.9%| +|Optimizing|31|78|43|152| +|Accepted|**287**|**484**|**142**|**913**| +|Total|600|1305|539|2444| +|Perfection Rate|89.2%|83.9%|69.7%|83.4%| +|Completion Rate|47.8%|37.1%|26.3%|37.4%| |------------|----------------------------|----------------------------|----------------------------|----------------------------| ## 二. 目录 -以下已经收录了 663 道题的题解，还有 11 道题在尝试优化到 beats 100% +以下已经收录了 787 道题的题解，还有 11 道题在尝试优化到 beats 100% | No. | Title | Solution | Acceptance | Difficulty | Frequency | |:--------:|:--------------------------------------------------------------|:--------:|:--------:|:--------:|:--------:| -|0001|Two Sum|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0001.Two-Sum)|46.8%|Easy|| -|0002|Add Two Numbers|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0002.Add-Two-Numbers)|35.8%|Medium|| -|0003|Longest Substring Without Repeating Characters|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0003.Longest-Substring-Without-Repeating-Characters)|31.6%|Medium|| -|0004|Median of Two Sorted Arrays|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0004.Median-of-Two-Sorted-Arrays)|31.5%|Hard|| -|0005|Longest Palindromic Substring|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0005.Longest-Palindromic-Substring)|30.7%|Medium|| -|0006|ZigZag Conversion|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0006.ZigZag-Conversion)|38.4%|Medium|| -|0007|Reverse Integer|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0007.Reverse-Integer)|26.0%|Easy|| -|0008|String to Integer (atoi)|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0008.String-to-Integer-(atoi))|15.8%|Medium|| -|0009|Palindrome Number|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0009.Palindrome-Number)|50.2%|Easy|| -|0010|Regular Expression Matching||27.5%|Hard|| -|0011|Container With Most Water|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0011.Container-With-Most-Water)|52.9%|Medium|| -|0012|Integer to Roman|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0012.Integer-to-Roman)|57.2%|Medium|| -|0013|Roman to Integer|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0013.Roman-to-Integer)|57.1%|Easy|| -|0014|Longest Common Prefix||36.3%|Easy|| -|0015|3Sum|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0015.3Sum)|28.4%|Medium|| -|0016|3Sum Closest|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0016.3Sum-Closest)|46.4%|Medium|| -|0017|Letter Combinations of a Phone Number|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0017.Letter-Combinations-of-a-Phone-Number)|50.0%|Medium|| -|0018|4Sum|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0018.4Sum)|35.2%|Medium|| -|0019|Remove Nth Node From End of List|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0019.Remove-Nth-Node-From-End-of-List)|36.2%|Medium|| -|0020|Valid Parentheses|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0020.Valid-Parentheses)|40.0%|Easy|| -|0021|Merge Two Sorted Lists|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0021.Merge-Two-Sorted-Lists)|56.5%|Easy|| -|0022|Generate Parentheses|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0022.Generate-Parentheses)|65.9%|Medium|| -|0023|Merge k Sorted Lists|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0023.Merge-k-Sorted-Lists)|43.2%|Hard|| -|0024|Swap Nodes in Pairs|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0024.Swap-Nodes-in-Pairs)|53.7%|Medium|| -|0025|Reverse Nodes in k-Group|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0025.Reverse-Nodes-in-k-Group)|45.6%|Hard|| -|0026|Remove Duplicates from Sorted Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0026.Remove-Duplicates-from-Sorted-Array)|46.9%|Easy|| -|0027|Remove Element|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0027.Remove-Element)|49.6%|Easy|| -|0028|Implement strStr()|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0028.Implement-strStr())|35.4%|Easy|| -|0029|Divide Two Integers|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0029.Divide-Two-Integers)|16.9%|Medium|| -|0030|Substring with Concatenation of All Words|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0030.Substring-with-Concatenation-of-All-Words)|26.4%|Hard|| -|0031|Next Permutation|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0031.Next-Permutation)|33.9%|Medium|| -|0032|Longest Valid Parentheses|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0032.Longest-Valid-Parentheses)|29.9%|Hard|| -|0033|Search in Rotated Sorted Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0033.Search-in-Rotated-Sorted-Array)|36.2%|Medium|| -|0034|Find First and Last Position of Element in Sorted Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0034.Find-First-and-Last-Position-of-Element-in-Sorted-Array)|37.6%|Medium|| -|0035|Search Insert Position|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0035.Search-Insert-Position)|42.9%|Easy|| -|0036|Valid Sudoku|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0036.Valid-Sudoku)|51.0%|Medium|| -|0037|Sudoku Solver|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0037.Sudoku-Solver)|47.3%|Hard|| -|0038|Count and Say||46.4%|Medium|| -|0039|Combination Sum|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0039.Combination-Sum)|59.9%|Medium|| -|0040|Combination Sum II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0040.Combination-Sum-II)|50.5%|Medium|| -|0041|First Missing Positive|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0041.First-Missing-Positive)|34.1%|Hard|| -|0042|Trapping Rain Water|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0042.Trapping-Rain-Water)|51.8%|Hard|| -|0043|Multiply Strings|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0043.Multiply-Strings)|35.2%|Medium|| -|0044|Wildcard Matching||25.6%|Hard|| -|0045|Jump Game II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0045.Jump-Game-II)|31.8%|Medium|| -|0046|Permutations|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0046.Permutations)|67.3%|Medium|| -|0047|Permutations II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0047.Permutations-II)|50.0%|Medium|| -|0048|Rotate Image|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0048.Rotate-Image)|61.2%|Medium|| -|0049|Group Anagrams|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0049.Group-Anagrams)|59.9%|Medium|| -|0050|Pow(x, n)|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0050.Pow(x,-n))|31.1%|Medium|| -|0051|N-Queens|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0051.N-Queens)|50.4%|Hard|| -|0052|N-Queens II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0052.N-Queens-II)|60.8%|Hard|| -|0053|Maximum Subarray|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0053.Maximum-Subarray)|47.9%|Easy|| -|0054|Spiral Matrix|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0054.Spiral-Matrix)|36.7%|Medium|| -|0055|Jump Game|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0055.Jump-Game)|35.3%|Medium|| -|0056|Merge Intervals|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0056.Merge-Intervals)|41.5%|Medium|| -|0057|Insert Interval|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0057.Insert-Interval)|35.4%|Medium|| -|0058|Length of Last Word||33.5%|Easy|| -|0059|Spiral Matrix II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0059.Spiral-Matrix-II)|58.4%|Medium|| -|0060|Permutation Sequence|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0060.Permutation-Sequence)|39.7%|Hard|| -|0061|Rotate List|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0061.Rotate-List)|32.0%|Medium|| -|0062|Unique Paths|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0062.Unique-Paths)|56.5%|Medium|| -|0063|Unique Paths II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0063.Unique-Paths-II)|35.4%|Medium|| -|0064|Minimum Path Sum|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0064.Minimum-Path-Sum)|56.6%|Medium|| -|0065|Valid Number||16.1%|Hard|| -|0066|Plus One|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0066.Plus-One)|42.2%|Easy|| -|0067|Add Binary|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0067.Add-Binary)|47.4%|Easy|| -|0068|Text Justification||30.4%|Hard|| -|0069|Sqrt(x)|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0069.Sqrt(x))|35.5%|Easy|| -|0070|Climbing Stairs|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0070.Climbing-Stairs)|48.8%|Easy|| -|0071|Simplify Path|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0071.Simplify-Path)|35.0%|Medium|| -|0072|Edit Distance||47.3%|Hard|| -|0073|Set Matrix Zeroes|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0073.Set-Matrix-Zeroes)|44.7%|Medium|| -|0074|Search a 2D Matrix|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0074.Search-a-2D-Matrix)|38.3%|Medium|| -|0075|Sort Colors|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0075.Sort-Colors)|50.0%|Medium|| -|0076|Minimum Window Substring|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0076.Minimum-Window-Substring)|36.3%|Hard|| -|0077|Combinations|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0077.Combinations)|58.2%|Medium|| -|0078|Subsets|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0078.Subsets)|65.8%|Medium|| -|0079|Word Search|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0079.Word-Search)|37.3%|Medium|| -|0080|Remove Duplicates from Sorted Array II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0080.Remove-Duplicates-from-Sorted-Array-II)|46.5%|Medium|| -|0081|Search in Rotated Sorted Array II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0081.Search-in-Rotated-Sorted-Array-II)|33.7%|Medium|| -|0082|Remove Duplicates from Sorted List II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0082.Remove-Duplicates-from-Sorted-List-II)|39.6%|Medium|| -|0083|Remove Duplicates from Sorted List|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0083.Remove-Duplicates-from-Sorted-List)|46.8%|Easy|| -|0084|Largest Rectangle in Histogram|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0084.Largest-Rectangle-in-Histogram)|37.5%|Hard|| -|0085|Maximal Rectangle||39.8%|Hard|| -|0086|Partition List|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0086.Partition-List)|44.9%|Medium|| -|0087|Scramble String||34.8%|Hard|| -|0088|Merge Sorted Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0088.Merge-Sorted-Array)|40.9%|Easy|| -|0089|Gray Code|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0089.Gray-Code)|50.8%|Medium|| -|0090|Subsets II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0090.Subsets-II)|49.3%|Medium|| -|0091|Decode Ways|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0091.Decode-Ways)|27.0%|Medium|| -|0092|Reverse Linked List II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0092.Reverse-Linked-List-II)|40.9%|Medium|| -|0093|Restore IP Addresses|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0093.Restore-IP-Addresses)|38.0%|Medium|| -|0094|Binary Tree Inorder Traversal|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0094.Binary-Tree-Inorder-Traversal)|66.5%|Medium|| -|0095|Unique Binary Search Trees II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0095.Unique-Binary-Search-Trees-II)|43.2%|Medium|| -|0096|Unique Binary Search Trees|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0096.Unique-Binary-Search-Trees)|54.8%|Medium|| -|0097|Interleaving String||32.8%|Medium|| -|0098|Validate Binary Search Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0098.Validate-Binary-Search-Tree)|29.0%|Medium|| -|0099|Recover Binary Search Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0099.Recover-Binary-Search-Tree)|42.9%|Hard|| -|0100|Same Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0100.Same-Tree)|54.3%|Easy|| -|0101|Symmetric Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0101.Symmetric-Tree)|48.6%|Easy|| -|0102|Binary Tree Level Order Traversal|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0102.Binary-Tree-Level-Order-Traversal)|57.1%|Medium|| -|0103|Binary Tree Zigzag Level Order Traversal|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0103.Binary-Tree-Zigzag-Level-Order-Traversal)|50.6%|Medium|| -|0104|Maximum Depth of Binary Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0104.Maximum-Depth-of-Binary-Tree)|68.5%|Easy|| -|0105|Construct Binary Tree from Preorder and Inorder Traversal|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0105.Construct-Binary-Tree-from-Preorder-and-Inorder-Traversal)|52.6%|Medium|| -|0106|Construct Binary Tree from Inorder and Postorder Traversal|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0106.Construct-Binary-Tree-from-Inorder-and-Postorder-Traversal)|50.3%|Medium|| -|0107|Binary Tree Level Order Traversal II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0107.Binary-Tree-Level-Order-Traversal-II)|55.6%|Medium|| -|0108|Convert Sorted Array to Binary Search Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0108.Convert-Sorted-Array-to-Binary-Search-Tree)|61.1%|Easy|| -|0109|Convert Sorted List to Binary Search Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0109.Convert-Sorted-List-to-Binary-Search-Tree)|50.8%|Medium|| -|0110|Balanced Binary Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0110.Balanced-Binary-Tree)|44.9%|Easy|| -|0111|Minimum Depth of Binary Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0111.Minimum-Depth-of-Binary-Tree)|39.9%|Easy|| -|0112|Path Sum|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0112.Path-Sum)|42.8%|Easy|| -|0113|Path Sum II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0113.Path-Sum-II)|49.7%|Medium|| -|0114|Flatten Binary Tree to Linked List|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0114.Flatten-Binary-Tree-to-Linked-List)|52.6%|Medium|| -|0115|Distinct Subsequences|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0115.Distinct-Subsequences)|40.1%|Hard|| -|0116|Populating Next Right Pointers in Each Node||49.9%|Medium|| -|0117|Populating Next Right Pointers in Each Node II||42.6%|Medium|| -|0118|Pascal's Triangle|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0118.Pascal's-Triangle)|55.7%|Easy|| -|0119|Pascal's Triangle II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0119.Pascal's-Triangle-II)|52.7%|Easy|| -|0120|Triangle|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0120.Triangle)|46.9%|Medium|| -|0121|Best Time to Buy and Sell Stock|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0121.Best-Time-to-Buy-and-Sell-Stock)|51.9%|Easy|| -|0122|Best Time to Buy and Sell Stock II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0122.Best-Time-to-Buy-and-Sell-Stock-II)|58.9%|Easy|| -|0123|Best Time to Buy and Sell Stock III||40.3%|Hard|| -|0124|Binary Tree Maximum Path Sum|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0124.Binary-Tree-Maximum-Path-Sum)|35.7%|Hard|| -|0125|Valid Palindrome|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0125.Valid-Palindrome)|38.7%|Easy|| -|0126|Word Ladder II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0126.Word-Ladder-II)|23.9%|Hard|| -|0127|Word Ladder|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0127.Word-Ladder)|32.3%|Hard|| -|0128|Longest Consecutive Sequence|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0128.Longest-Consecutive-Sequence)|46.6%|Hard|| -|0129|Sum Root to Leaf Numbers|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0129.Sum-Root-to-Leaf-Numbers)|51.5%|Medium|| -|0130|Surrounded Regions|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0130.Surrounded-Regions)|29.9%|Medium|| -|0131|Palindrome Partitioning|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0131.Palindrome-Partitioning)|52.9%|Medium|| -|0132|Palindrome Partitioning II||31.4%|Hard|| -|0133|Clone Graph||40.1%|Medium|| -|0134|Gas Station||41.7%|Medium|| -|0135|Candy||33.4%|Hard|| -|0136|Single Number|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0136.Single-Number)|66.8%|Easy|| -|0137|Single Number II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0137.Single-Number-II)|54.2%|Medium|| -|0138|Copy List with Random Pointer|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0138.Copy-List-with-Random-Pointer)|41.7%|Medium|| -|0139|Word Break||42.0%|Medium|| -|0140|Word Break II||35.7%|Hard|| -|0141|Linked List Cycle|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0141.Linked-List-Cycle)|43.2%|Easy|| -|0142|Linked List Cycle II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0142.Linked-List-Cycle-II)|40.1%|Medium|| -|0143|Reorder List|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0143.Reorder-List)|41.3%|Medium|| -|0144|Binary Tree Preorder Traversal|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0144.Binary-Tree-Preorder-Traversal)|58.0%|Medium|| -|0145|Binary Tree Postorder Traversal|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0145.Binary-Tree-Postorder-Traversal)|58.2%|Medium|| -|0146|LRU Cache|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0146.LRU-Cache)|36.5%|Medium|| -|0147|Insertion Sort List|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0147.Insertion-Sort-List)|44.8%|Medium|| -|0148|Sort List|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0148.Sort-List)|46.9%|Medium|| -|0149|Max Points on a Line||17.8%|Hard|| -|0150|Evaluate Reverse Polish Notation|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0150.Evaluate-Reverse-Polish-Notation)|38.4%|Medium|| -|0151|Reverse Words in a String|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0151.Reverse-Words-in-a-String)|24.3%|Medium|| -|0152|Maximum Product Subarray|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0152.Maximum-Product-Subarray)|32.9%|Medium|| -|0153|Find Minimum in Rotated Sorted Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0153.Find-Minimum-in-Rotated-Sorted-Array)|46.5%|Medium|| -|0154|Find Minimum in Rotated Sorted Array II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0154.Find-Minimum-in-Rotated-Sorted-Array-II)|42.2%|Hard|| -|0155|Min Stack|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0155.Min-Stack)|46.9%|Easy|| -|0156|Binary Tree Upside Down||56.7%|Medium|| -|0157|Read N Characters Given Read4||37.9%|Easy|| -|0158|Read N Characters Given Read4 II - Call multiple times||37.6%|Hard|| -|0159|Longest Substring with At Most Two Distinct Characters||50.8%|Medium|| -|0160|Intersection of Two Linked Lists|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0160.Intersection-of-Two-Linked-Lists)|44.8%|Easy|| -|0161|One Edit Distance||33.2%|Medium|| -|0162|Find Peak Element|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0162.Find-Peak-Element)|44.1%|Medium|| -|0163|Missing Ranges||27.6%|Easy|| -|0164|Maximum Gap|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0164.Maximum-Gap)|37.2%|Hard|| -|0165|Compare Version Numbers||30.8%|Medium|| -|0166|Fraction to Recurring Decimal||22.5%|Medium|| -|0167|Two Sum II - Input array is sorted|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0167.Two-Sum-II---Input-array-is-sorted)|55.8%|Easy|| -|0168|Excel Sheet Column Title|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0168.Excel-Sheet-Column-Title)|32.0%|Easy|| -|0169|Majority Element|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0169.Majority-Element)|60.3%|Easy|| -|0170|Two Sum III - Data structure design||35.1%|Easy|| -|0171|Excel Sheet Column Number|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0171.Excel-Sheet-Column-Number)|57.2%|Easy|| -|0172|Factorial Trailing Zeroes|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0172.Factorial-Trailing-Zeroes)|38.9%|Easy|| -|0173|Binary Search Tree Iterator|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0173.Binary-Search-Tree-Iterator)|60.8%|Medium|| -|0174|Dungeon Game|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0174.Dungeon-Game)|33.5%|Hard|| -|0175|Combine Two Tables||65.0%|Easy|| -|0176|Second Highest Salary||33.6%|Easy|| -|0177|Nth Highest Salary||33.7%|Medium|| -|0178|Rank Scores||51.3%|Medium|| -|0179|Largest Number|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0179.Largest-Number)|30.9%|Medium|| -|0180|Consecutive Numbers||42.8%|Medium|| -|0181|Employees Earning More Than Their Managers||61.3%|Easy|| -|0182|Duplicate Emails||65.2%|Easy|| -|0183|Customers Who Never Order||57.7%|Easy|| -|0184|Department Highest Salary||41.1%|Medium|| -|0185|Department Top Three Salaries||40.1%|Hard|| -|0186|Reverse Words in a String II||46.2%|Medium|| -|0187|Repeated DNA Sequences|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0187.Repeated-DNA-Sequences)|41.8%|Medium|| -|0188|Best Time to Buy and Sell Stock IV||30.2%|Hard|| -|0189|Rotate Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0189.Rotate-Array)|36.8%|Medium|| -|0190|Reverse Bits|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0190.Reverse-Bits)|42.8%|Easy|| -|0191|Number of 1 Bits|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0191.Number-of-1-Bits)|54.5%|Easy|| -|0192|Word Frequency||25.5%|Medium|| -|0193|Valid Phone Numbers||25.4%|Easy|| -|0194|Transpose File||24.4%|Medium|| -|0195|Tenth Line||32.8%|Easy|| -|0196|Delete Duplicate Emails||46.2%|Easy|| -|0197|Rising Temperature||40.3%|Easy|| -|0198|House Robber|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0198.House-Robber)|43.2%|Medium|| -|0199|Binary Tree Right Side View|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0199.Binary-Tree-Right-Side-View)|56.7%|Medium|| -|0200|Number of Islands|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0200.Number-of-Islands)|49.7%|Medium|| -|0201|Bitwise AND of Numbers Range|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0201.Bitwise-AND-of-Numbers-Range)|39.7%|Medium|| -|0202|Happy Number|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0202.Happy-Number)|51.4%|Easy|| -|0203|Remove Linked List Elements|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0203.Remove-Linked-List-Elements)|39.6%|Easy|| -|0204|Count Primes|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0204.Count-Primes)|32.4%|Easy|| -|0205|Isomorphic Strings|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0205.Isomorphic-Strings)|40.7%|Easy|| -|0206|Reverse Linked List|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0206.Reverse-Linked-List)|65.9%|Easy|| -|0207|Course Schedule|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0207.Course-Schedule)|44.4%|Medium|| -|0208|Implement Trie (Prefix Tree)|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0208.Implement-Trie-(Prefix-Tree))|52.8%|Medium|| -|0209|Minimum Size Subarray Sum|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0209.Minimum-Size-Subarray-Sum)|39.9%|Medium|| -|0210|Course Schedule II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0210.Course-Schedule-II)|43.1%|Medium|| -|0211|Design Add and Search Words Data Structure|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0211.Design-Add-and-Search-Words-Data-Structure)|40.7%|Medium|| -|0212|Word Search II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0212.Word-Search-II)|37.6%|Hard|| -|0213|House Robber II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0213.House-Robber-II)|37.7%|Medium|| -|0214|Shortest Palindrome||30.8%|Hard|| -|0215|Kth Largest Element in an Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0215.Kth-Largest-Element-in-an-Array)|59.1%|Medium|| -|0216|Combination Sum III|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0216.Combination-Sum-III)|60.8%|Medium|| -|0217|Contains Duplicate|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0217.Contains-Duplicate)|57.0%|Easy|| -|0218|The Skyline Problem|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0218.The-Skyline-Problem)|36.7%|Hard|| -|0219|Contains Duplicate II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0219.Contains-Duplicate-II)|38.9%|Easy|| -|0220|Contains Duplicate III|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0220.Contains-Duplicate-III)|21.4%|Medium|| -|0221|Maximal Square||39.7%|Medium|| -|0222|Count Complete Tree Nodes|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0222.Count-Complete-Tree-Nodes)|49.9%|Medium|| -|0223|Rectangle Area|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0223.Rectangle-Area)|38.4%|Medium|| -|0224|Basic Calculator|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0224.Basic-Calculator)|38.3%|Hard|| -|0225|Implement Stack using Queues|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0225.Implement-Stack-using-Queues)|48.1%|Easy|| -|0226|Invert Binary Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0226.Invert-Binary-Tree)|67.5%|Easy|| -|0227|Basic Calculator II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0227.Basic-Calculator-II)|38.9%|Medium|| -|0228|Summary Ranges|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0228.Summary-Ranges)|42.8%|Easy|| -|0229|Majority Element II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0229.Majority-Element-II)|39.1%|Medium|| -|0230|Kth Smallest Element in a BST|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0230.Kth-Smallest-Element-in-a-BST)|63.1%|Medium|| -|0231|Power of Two|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0231.Power-of-Two)|43.8%|Easy|| -|0232|Implement Queue using Stacks|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0232.Implement-Queue-using-Stacks)|52.9%|Easy|| -|0233|Number of Digit One||31.9%|Hard|| -|0234|Palindrome Linked List|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0234.Palindrome-Linked-List)|42.2%|Easy|| -|0235|Lowest Common Ancestor of a Binary Search Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0235.Lowest-Common-Ancestor-of-a-Binary-Search-Tree)|52.3%|Easy|| -|0236|Lowest Common Ancestor of a Binary Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0236.Lowest-Common-Ancestor-of-a-Binary-Tree)|49.6%|Medium|| -|0237|Delete Node in a Linked List|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0237.Delete-Node-in-a-Linked-List)|67.7%|Easy|| -|0238|Product of Array Except Self||61.4%|Medium|| -|0239|Sliding Window Maximum|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0239.Sliding-Window-Maximum)|44.8%|Hard|| -|0240|Search a 2D Matrix II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0240.Search-a-2D-Matrix-II)|45.5%|Medium|| -|0241|Different Ways to Add Parentheses||57.7%|Medium|| -|0242|Valid Anagram|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0242.Valid-Anagram)|59.0%|Easy|| -|0243|Shortest Word Distance||62.2%|Easy|| -|0244|Shortest Word Distance II||54.8%|Medium|| -|0245|Shortest Word Distance III||56.2%|Medium|| -|0246|Strobogrammatic Number||46.5%|Easy|| -|0247|Strobogrammatic Number II||48.9%|Medium|| -|0248|Strobogrammatic Number III||40.4%|Hard|| -|0249|Group Shifted Strings||58.7%|Medium|| -|0250|Count Univalue Subtrees||53.6%|Medium|| -|0251|Flatten 2D Vector||46.5%|Medium|| -|0252|Meeting Rooms||55.6%|Easy|| -|0253|Meeting Rooms II||47.2%|Medium|| -|0254|Factor Combinations||47.6%|Medium|| -|0255|Verify Preorder Sequence in Binary Search Tree||46.5%|Medium|| -|0256|Paint House||54.1%|Medium|| -|0257|Binary Tree Paths|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0257.Binary-Tree-Paths)|54.3%|Easy|| -|0258|Add Digits|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0258.Add-Digits)|58.8%|Easy|| -|0259|3Sum Smaller||49.3%|Medium|| -|0260|Single Number III|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0260.Single-Number-III)|65.5%|Medium|| -|0261|Graph Valid Tree||43.4%|Medium|| -|0262|Trips and Users||35.7%|Hard|| +|0001|Two Sum|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0001.Two-Sum)|49.1%|Easy|| +|0002|Add Two Numbers|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0002.Add-Two-Numbers)|39.7%|Medium|| +|0003|Longest Substring Without Repeating Characters|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0003.Longest-Substring-Without-Repeating-Characters)|33.8%|Medium|| +|0004|Median of Two Sorted Arrays|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0004.Median-of-Two-Sorted-Arrays)|35.1%|Hard|| +|0005|Longest Palindromic Substring|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0005.Longest-Palindromic-Substring)|32.4%|Medium|| +|0006|Zigzag Conversion|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0006.Zigzag-Conversion)|43.0%|Medium|| +|0007|Reverse Integer|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0007.Reverse-Integer)|27.2%|Medium|| +|0008|String to Integer (atoi)|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0008.String-to-Integer-atoi)|16.6%|Medium|| +|0009|Palindrome Number|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0009.Palindrome-Number)|52.8%|Easy|| +|0010|Regular Expression Matching||28.3%|Hard|| +|0011|Container With Most Water|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0011.Container-With-Most-Water)|54.3%|Medium|| +|0012|Integer to Roman|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0012.Integer-to-Roman)|60.5%|Medium|| +|0013|Roman to Integer|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0013.Roman-to-Integer)|58.2%|Easy|| +|0014|Longest Common Prefix|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0014.Longest-Common-Prefix)|40.7%|Easy|| +|0015|3Sum|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0015.3Sum)|32.2%|Medium|| +|0016|3Sum Closest|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0016.3Sum-Closest)|46.2%|Medium|| +|0017|Letter Combinations of a Phone Number|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0017.Letter-Combinations-of-a-Phone-Number)|55.5%|Medium|| +|0018|4Sum|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0018.4Sum)|36.5%|Medium|| +|0019|Remove Nth Node From End of List|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0019.Remove-Nth-Node-From-End-of-List)|39.9%|Medium|| +|0020|Valid Parentheses|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0020.Valid-Parentheses)|40.7%|Easy|| +|0021|Merge Two Sorted Lists|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0021.Merge-Two-Sorted-Lists)|61.8%|Easy|| +|0022|Generate Parentheses|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0022.Generate-Parentheses)|71.7%|Medium|| +|0023|Merge k Sorted Lists|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0023.Merge-k-Sorted-Lists)|48.3%|Hard|| +|0024|Swap Nodes in Pairs|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0024.Swap-Nodes-in-Pairs)|60.3%|Medium|| +|0025|Reverse Nodes in k-Group|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0025.Reverse-Nodes-in-k-Group)|53.4%|Hard|| +|0026|Remove Duplicates from Sorted Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0026.Remove-Duplicates-from-Sorted-Array)|50.3%|Easy|| +|0027|Remove Element|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0027.Remove-Element)|52.0%|Easy|| +|0028|Find the Index of the First Occurrence in a String|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0028.Find-the-Index-of-the-First-Occurrence-in-a-String)|37.4%|Medium|| +|0029|Divide Two Integers|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0029.Divide-Two-Integers)|17.4%|Medium|| +|0030|Substring with Concatenation of All Words|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0030.Substring-with-Concatenation-of-All-Words)|30.9%|Hard|| +|0031|Next Permutation|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0031.Next-Permutation)|37.1%|Medium|| +|0032|Longest Valid Parentheses|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0032.Longest-Valid-Parentheses)|32.7%|Hard|| +|0033|Search in Rotated Sorted Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0033.Search-in-Rotated-Sorted-Array)|38.6%|Medium|| +|0034|Find First and Last Position of Element in Sorted Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0034.Find-First-and-Last-Position-of-Element-in-Sorted-Array)|41.5%|Medium|| +|0035|Search Insert Position|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0035.Search-Insert-Position)|42.0%|Easy|| +|0036|Valid Sudoku|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0036.Valid-Sudoku)|56.7%|Medium|| +|0037|Sudoku Solver|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0037.Sudoku-Solver)|56.6%|Hard|| +|0038|Count and Say||51.1%|Medium|| +|0039|Combination Sum|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0039.Combination-Sum)|67.5%|Medium|| +|0040|Combination Sum II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0040.Combination-Sum-II)|53.3%|Medium|| +|0041|First Missing Positive|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0041.First-Missing-Positive)|36.5%|Hard|| +|0042|Trapping Rain Water|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0042.Trapping-Rain-Water)|58.7%|Hard|| +|0043|Multiply Strings|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0043.Multiply-Strings)|38.7%|Medium|| +|0044|Wildcard Matching||26.8%|Hard|| +|0045|Jump Game II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0045.Jump-Game-II)|38.5%|Medium|| +|0046|Permutations|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0046.Permutations)|74.6%|Medium|| +|0047|Permutations II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0047.Permutations-II)|56.6%|Medium|| +|0048|Rotate Image|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0048.Rotate-Image)|69.8%|Medium|| +|0049|Group Anagrams|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0049.Group-Anagrams)|65.9%|Medium|| +|0050|Pow(x, n)|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0050.Powx-n)|32.8%|Medium|| +|0051|N-Queens|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0051.N-Queens)|62.8%|Hard|| +|0052|N-Queens II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0052.N-Queens-II)|70.8%|Hard|| +|0053|Maximum Subarray|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0053.Maximum-Subarray)|50.0%|Medium|| +|0054|Spiral Matrix|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0054.Spiral-Matrix)|43.6%|Medium|| +|0055|Jump Game|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0055.Jump-Game)|38.4%|Medium|| +|0056|Merge Intervals|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0056.Merge-Intervals)|45.9%|Medium|| +|0057|Insert Interval|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0057.Insert-Interval)|37.9%|Medium|| +|0058|Length of Last Word|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0058.Length-of-Last-Word)|40.3%|Easy|| +|0059|Spiral Matrix II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0059.Spiral-Matrix-II)|66.5%|Medium|| +|0060|Permutation Sequence|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0060.Permutation-Sequence)|43.7%|Hard|| +|0061|Rotate List|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0061.Rotate-List)|35.7%|Medium|| +|0062|Unique Paths|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0062.Unique-Paths)|62.2%|Medium|| +|0063|Unique Paths II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0063.Unique-Paths-II)|39.1%|Medium|| +|0064|Minimum Path Sum|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0064.Minimum-Path-Sum)|60.6%|Medium|| +|0065|Valid Number|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0065.Valid-Number)|18.6%|Hard|| +|0066|Plus One|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0066.Plus-One)|43.3%|Easy|| +|0067|Add Binary|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0067.Add-Binary)|51.3%|Easy|| +|0068|Text Justification||36.6%|Hard|| +|0069|Sqrt(x)|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0069.Sqrtx)|37.0%|Easy|| +|0070|Climbing Stairs|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0070.Climbing-Stairs)|51.7%|Easy|| +|0071|Simplify Path|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0071.Simplify-Path)|39.2%|Medium|| +|0072|Edit Distance||52.6%|Hard|| +|0073|Set Matrix Zeroes|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0073.Set-Matrix-Zeroes)|49.9%|Medium|| +|0074|Search a 2D Matrix|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0074.Search-a-2D-Matrix)|46.7%|Medium|| +|0075|Sort Colors|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0075.Sort-Colors)|57.1%|Medium|| +|0076|Minimum Window Substring|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0076.Minimum-Window-Substring)|40.0%|Hard|| +|0077|Combinations|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0077.Combinations)|66.0%|Medium|| +|0078|Subsets|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0078.Subsets)|73.7%|Medium|| +|0079|Word Search|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0079.Word-Search)|39.8%|Medium|| +|0080|Remove Duplicates from Sorted Array II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0080.Remove-Duplicates-from-Sorted-Array-II)|51.5%|Medium|| +|0081|Search in Rotated Sorted Array II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0081.Search-in-Rotated-Sorted-Array-II)|35.7%|Medium|| +|0082|Remove Duplicates from Sorted List II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0082.Remove-Duplicates-from-Sorted-List-II)|45.4%|Medium|| +|0083|Remove Duplicates from Sorted List|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0083.Remove-Duplicates-from-Sorted-List)|49.8%|Easy|| +|0084|Largest Rectangle in Histogram|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0084.Largest-Rectangle-in-Histogram)|42.1%|Hard|| +|0085|Maximal Rectangle||44.1%|Hard|| +|0086|Partition List|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0086.Partition-List)|51.3%|Medium|| +|0087|Scramble String||36.1%|Hard|| +|0088|Merge Sorted Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0088.Merge-Sorted-Array)|45.7%|Easy|| +|0089|Gray Code|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0089.Gray-Code)|56.4%|Medium|| +|0090|Subsets II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0090.Subsets-II)|55.2%|Medium|| +|0091|Decode Ways|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0091.Decode-Ways)|32.2%|Medium|| +|0092|Reverse Linked List II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0092.Reverse-Linked-List-II)|45.3%|Medium|| +|0093|Restore IP Addresses|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0093.Restore-IP-Addresses)|43.3%|Medium|| +|0094|Binary Tree Inorder Traversal|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0094.Binary-Tree-Inorder-Traversal)|72.9%|Easy|| +|0095|Unique Binary Search Trees II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0095.Unique-Binary-Search-Trees-II)|51.4%|Medium|| +|0096|Unique Binary Search Trees|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0096.Unique-Binary-Search-Trees)|59.2%|Medium|| +|0097|Interleaving String|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0097.Interleaving-String)|37.1%|Medium|| +|0098|Validate Binary Search Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0098.Validate-Binary-Search-Tree)|31.7%|Medium|| +|0099|Recover Binary Search Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0099.Recover-Binary-Search-Tree)|50.2%|Medium|| +|0100|Same Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0100.Same-Tree)|56.3%|Easy|| +|0101|Symmetric Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0101.Symmetric-Tree)|52.8%|Easy|| +|0102|Binary Tree Level Order Traversal|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0102.Binary-Tree-Level-Order-Traversal)|63.2%|Medium|| +|0103|Binary Tree Zigzag Level Order Traversal|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0103.Binary-Tree-Zigzag-Level-Order-Traversal)|55.0%|Medium|| +|0104|Maximum Depth of Binary Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0104.Maximum-Depth-of-Binary-Tree)|73.0%|Easy|| +|0105|Construct Binary Tree from Preorder and Inorder Traversal|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0105.Construct-Binary-Tree-from-Preorder-and-Inorder-Traversal)|60.6%|Medium|| +|0106|Construct Binary Tree from Inorder and Postorder Traversal|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0106.Construct-Binary-Tree-from-Inorder-and-Postorder-Traversal)|57.3%|Medium|| +|0107|Binary Tree Level Order Traversal II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0107.Binary-Tree-Level-Order-Traversal-II)|60.2%|Medium|| +|0108|Convert Sorted Array to Binary Search Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0108.Convert-Sorted-Array-to-Binary-Search-Tree)|68.9%|Easy|| +|0109|Convert Sorted List to Binary Search Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0109.Convert-Sorted-List-to-Binary-Search-Tree)|57.2%|Medium|| +|0110|Balanced Binary Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0110.Balanced-Binary-Tree)|48.1%|Easy|| +|0111|Minimum Depth of Binary Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0111.Minimum-Depth-of-Binary-Tree)|43.5%|Easy|| +|0112|Path Sum|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0112.Path-Sum)|47.6%|Easy|| +|0113|Path Sum II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0113.Path-Sum-II)|56.5%|Medium|| +|0114|Flatten Binary Tree to Linked List|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0114.Flatten-Binary-Tree-to-Linked-List)|61.0%|Medium|| +|0115|Distinct Subsequences|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0115.Distinct-Subsequences)|43.7%|Hard|| +|0116|Populating Next Right Pointers in Each Node|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0116.Populating-Next-Right-Pointers-in-Each-Node)|59.3%|Medium|| +|0117|Populating Next Right Pointers in Each Node II||49.6%|Medium|| +|0118|Pascal's Triangle|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0118.Pascals-Triangle)|68.9%|Easy|| +|0119|Pascal's Triangle II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0119.Pascals-Triangle-II)|59.5%|Easy|| +|0120|Triangle|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0120.Triangle)|53.8%|Medium|| +|0121|Best Time to Buy and Sell Stock|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0121.Best-Time-to-Buy-and-Sell-Stock)|54.5%|Easy|| +|0122|Best Time to Buy and Sell Stock II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0122.Best-Time-to-Buy-and-Sell-Stock-II)|63.2%|Medium|| +|0123|Best Time to Buy and Sell Stock III||44.8%|Hard|| +|0124|Binary Tree Maximum Path Sum|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0124.Binary-Tree-Maximum-Path-Sum)|38.4%|Hard|| +|0125|Valid Palindrome|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0125.Valid-Palindrome)|43.5%|Easy|| +|0126|Word Ladder II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0126.Word-Ladder-II)|27.6%|Hard|| +|0127|Word Ladder|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0127.Word-Ladder)|36.6%|Hard|| +|0128|Longest Consecutive Sequence|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0128.Longest-Consecutive-Sequence)|49.0%|Medium|| +|0129|Sum Root to Leaf Numbers|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0129.Sum-Root-to-Leaf-Numbers)|58.6%|Medium|| +|0130|Surrounded Regions|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0130.Surrounded-Regions)|35.8%|Medium|| +|0131|Palindrome Partitioning|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0131.Palindrome-Partitioning)|62.3%|Medium|| +|0132|Palindrome Partitioning II||33.6%|Hard|| +|0133|Clone Graph||50.5%|Medium|| +|0134|Gas Station||45.0%|Medium|| +|0135|Candy|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0135.Candy)|40.7%|Hard|| +|0136|Single Number|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0136.Single-Number)|70.0%|Easy|| +|0137|Single Number II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0137.Single-Number-II)|57.7%|Medium|| +|0138|Copy List with Random Pointer|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0138.Copy-List-with-Random-Pointer)|50.4%|Medium|| +|0139|Word Break||45.4%|Medium|| +|0140|Word Break II||44.3%|Hard|| +|0141|Linked List Cycle|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0141.Linked-List-Cycle)|46.8%|Easy|| +|0142|Linked List Cycle II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0142.Linked-List-Cycle-II)|46.2%|Medium|| +|0143|Reorder List|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0143.Reorder-List)|50.9%|Medium|| +|0144|Binary Tree Preorder Traversal|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0144.Binary-Tree-Preorder-Traversal)|64.5%|Easy|| +|0145|Binary Tree Postorder Traversal|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0145.Binary-Tree-Postorder-Traversal)|66.5%|Easy|| +|0146|LRU Cache|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0146.LRU-Cache)|40.5%|Medium|| +|0147|Insertion Sort List|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0147.Insertion-Sort-List)|50.1%|Medium|| +|0148|Sort List|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0148.Sort-List)|54.0%|Medium|| +|0149|Max Points on a Line||21.7%|Hard|| +|0150|Evaluate Reverse Polish Notation|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0150.Evaluate-Reverse-Polish-Notation)|44.1%|Medium|| +|0151|Reverse Words in a String|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0151.Reverse-Words-in-a-String)|30.2%|Medium|| +|0152|Maximum Product Subarray|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0152.Maximum-Product-Subarray)|34.9%|Medium|| +|0153|Find Minimum in Rotated Sorted Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0153.Find-Minimum-in-Rotated-Sorted-Array)|48.4%|Medium|| +|0154|Find Minimum in Rotated Sorted Array II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0154.Find-Minimum-in-Rotated-Sorted-Array-II)|43.4%|Hard|| +|0155|Min Stack|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0155.Min-Stack)|51.7%|Medium|| +|0156|Binary Tree Upside Down||61.5%|Medium|| +|0157|Read N Characters Given Read4||40.7%|Easy|| +|0158|Read N Characters Given read4 II - Call Multiple Times||41.4%|Hard|| +|0159|Longest Substring with At Most Two Distinct Characters||53.5%|Medium|| +|0160|Intersection of Two Linked Lists|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0160.Intersection-of-Two-Linked-Lists)|53.1%|Easy|| +|0161|One Edit Distance||34.1%|Medium|| +|0162|Find Peak Element|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0162.Find-Peak-Element)|46.2%|Medium|| +|0163|Missing Ranges||31.9%|Easy|| +|0164|Maximum Gap|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0164.Maximum-Gap)|42.6%|Hard|| +|0165|Compare Version Numbers||35.3%|Medium|| +|0166|Fraction to Recurring Decimal||24.0%|Medium|| +|0167|Two Sum II - Input Array Is Sorted|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0167.Two-Sum-II-Input-Array-Is-Sorted)|60.0%|Medium|| +|0168|Excel Sheet Column Title|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0168.Excel-Sheet-Column-Title)|34.7%|Easy|| +|0169|Majority Element|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0169.Majority-Element)|63.8%|Easy|| +|0170|Two Sum III - Data structure design||37.3%|Easy|| +|0171|Excel Sheet Column Number|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0171.Excel-Sheet-Column-Number)|61.3%|Easy|| +|0172|Factorial Trailing Zeroes|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0172.Factorial-Trailing-Zeroes)|41.6%|Medium|| +|0173|Binary Search Tree Iterator|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0173.Binary-Search-Tree-Iterator)|69.0%|Medium|| +|0174|Dungeon Game|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0174.Dungeon-Game)|37.2%|Hard|| +|0175|Combine Two Tables||72.8%|Easy|| +|0176|Second Highest Salary||36.4%|Medium|| +|0177|Nth Highest Salary||37.3%|Medium|| +|0178|Rank Scores||59.7%|Medium|| +|0179|Largest Number|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0179.Largest-Number)|33.9%|Medium|| +|0180|Consecutive Numbers||46.7%|Medium|| +|0181|Employees Earning More Than Their Managers||68.4%|Easy|| +|0182|Duplicate Emails||70.5%|Easy|| +|0183|Customers Who Never Order||67.6%|Easy|| +|0184|Department Highest Salary||49.5%|Medium|| +|0185|Department Top Three Salaries||49.9%|Hard|| +|0186|Reverse Words in a String II||52.3%|Medium|| +|0187|Repeated DNA Sequences|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0187.Repeated-DNA-Sequences)|46.1%|Medium|| +|0188|Best Time to Buy and Sell Stock IV||37.8%|Hard|| +|0189|Rotate Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0189.Rotate-Array)|39.2%|Medium|| +|0190|Reverse Bits|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0190.Reverse-Bits)|51.9%|Easy|| +|0191|Number of 1 Bits|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0191.Number-of-1-Bits)|64.5%|Easy|| +|0192|Word Frequency||25.6%|Medium|| +|0193|Valid Phone Numbers||26.0%|Easy|| +|0194|Transpose File||25.3%|Medium|| +|0195|Tenth Line||32.9%|Easy|| +|0196|Delete Duplicate Emails||58.3%|Easy|| +|0197|Rising Temperature||44.4%|Easy|| +|0198|House Robber|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0198.House-Robber)|48.6%|Medium|| +|0199|Binary Tree Right Side View|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0199.Binary-Tree-Right-Side-View)|61.1%|Medium|| +|0200|Number of Islands|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0200.Number-of-Islands)|56.1%|Medium|| +|0201|Bitwise AND of Numbers Range|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0201.Bitwise-AND-of-Numbers-Range)|42.2%|Medium|| +|0202|Happy Number|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0202.Happy-Number)|54.3%|Easy|| +|0203|Remove Linked List Elements|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0203.Remove-Linked-List-Elements)|44.7%|Easy|| +|0204|Count Primes|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0204.Count-Primes)|33.1%|Medium|| +|0205|Isomorphic Strings|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0205.Isomorphic-Strings)|42.5%|Easy|| +|0206|Reverse Linked List|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0206.Reverse-Linked-List)|72.3%|Easy|| +|0207|Course Schedule|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0207.Course-Schedule)|45.3%|Medium|| +|0208|Implement Trie (Prefix Tree)|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0208.Implement-Trie-Prefix-Tree)|60.7%|Medium|| +|0209|Minimum Size Subarray Sum|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0209.Minimum-Size-Subarray-Sum)|44.4%|Medium|| +|0210|Course Schedule II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0210.Course-Schedule-II)|47.9%|Medium|| +|0211|Design Add and Search Words Data Structure|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0211.Design-Add-and-Search-Words-Data-Structure)|43.2%|Medium|| +|0212|Word Search II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0212.Word-Search-II)|37.0%|Hard|| +|0213|House Robber II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0213.House-Robber-II)|40.6%|Medium|| +|0214|Shortest Palindrome||32.2%|Hard|| +|0215|Kth Largest Element in an Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0215.Kth-Largest-Element-in-an-Array)|65.7%|Medium|| +|0216|Combination Sum III|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0216.Combination-Sum-III)|67.0%|Medium|| +|0217|Contains Duplicate|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0217.Contains-Duplicate)|61.2%|Easy|| +|0218|The Skyline Problem|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0218.The-Skyline-Problem)|41.5%|Hard|| +|0219|Contains Duplicate II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0219.Contains-Duplicate-II)|40.9%|Easy|| +|0220|Contains Duplicate III|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0220.Contains-Duplicate-III)|21.8%|Hard|| +|0221|Maximal Square||44.4%|Medium|| +|0222|Count Complete Tree Nodes|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0222.Count-Complete-Tree-Nodes)|57.4%|Medium|| +|0223|Rectangle Area|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0223.Rectangle-Area)|40.8%|Medium|| +|0224|Basic Calculator|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0224.Basic-Calculator)|41.1%|Hard|| +|0225|Implement Stack using Queues|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0225.Implement-Stack-using-Queues)|57.4%|Easy|| +|0226|Invert Binary Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0226.Invert-Binary-Tree)|73.1%|Easy|| +|0227|Basic Calculator II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0227.Basic-Calculator-II)|42.2%|Medium|| +|0228|Summary Ranges|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0228.Summary-Ranges)|46.8%|Easy|| +|0229|Majority Element II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0229.Majority-Element-II)|44.0%|Medium|| +|0230|Kth Smallest Element in a BST|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0230.Kth-Smallest-Element-in-a-BST)|69.2%|Medium|| +|0231|Power of Two|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0231.Power-of-Two)|45.6%|Easy|| +|0232|Implement Queue using Stacks|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0232.Implement-Queue-using-Stacks)|61.0%|Easy|| +|0233|Number of Digit One||34.2%|Hard|| +|0234|Palindrome Linked List|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0234.Palindrome-Linked-List)|49.4%|Easy|| +|0235|Lowest Common Ancestor of a Binary Search Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0235.Lowest-Common-Ancestor-of-a-Binary-Search-Tree)|60.1%|Medium|| +|0236|Lowest Common Ancestor of a Binary Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0236.Lowest-Common-Ancestor-of-a-Binary-Tree)|57.9%|Medium|| +|0237|Delete Node in a Linked List|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0237.Delete-Node-in-a-Linked-List)|75.1%|Medium|| +|0238|Product of Array Except Self||64.7%|Medium|| +|0239|Sliding Window Maximum|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0239.Sliding-Window-Maximum)|46.6%|Hard|| +|0240|Search a 2D Matrix II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0240.Search-a-2D-Matrix-II)|50.5%|Medium|| +|0241|Different Ways to Add Parentheses||63.1%|Medium|| +|0242|Valid Anagram|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0242.Valid-Anagram)|62.7%|Easy|| +|0243|Shortest Word Distance||64.9%|Easy|| +|0244|Shortest Word Distance II||60.7%|Medium|| +|0245|Shortest Word Distance III||57.5%|Medium|| +|0246|Strobogrammatic Number||47.6%|Easy|| +|0247|Strobogrammatic Number II||51.4%|Medium|| +|0248|Strobogrammatic Number III||41.7%|Hard|| +|0249|Group Shifted Strings||64.2%|Medium|| +|0250|Count Univalue Subtrees||55.2%|Medium|| +|0251|Flatten 2D Vector||48.9%|Medium|| +|0252|Meeting Rooms||57.0%|Easy|| +|0253|Meeting Rooms II||50.4%|Medium|| +|0254|Factor Combinations||48.8%|Medium|| +|0255|Verify Preorder Sequence in Binary Search Tree||48.0%|Medium|| +|0256|Paint House||60.5%|Medium|| +|0257|Binary Tree Paths|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0257.Binary-Tree-Paths)|60.5%|Easy|| +|0258|Add Digits|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0258.Add-Digits)|63.3%|Easy|| +|0259|3Sum Smaller||50.7%|Medium|| +|0260|Single Number III|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0260.Single-Number-III)|67.4%|Medium|| +|0261|Graph Valid Tree||46.8%|Medium|| +|0262|Trips and Users||38.4%|Hard|| |0263|Ugly Number|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0263.Ugly-Number)|41.7%|Easy|| -|0264|Ugly Number II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0264.Ugly-Number-II)|43.1%|Medium|| -|0265|Paint House II||46.1%|Hard|| -|0266|Palindrome Permutation||62.9%|Easy|| -|0267|Palindrome Permutation II||37.7%|Medium|| -|0268|Missing Number|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0268.Missing-Number)|55.4%|Easy|| -|0269|Alien Dictionary||33.8%|Hard|| -|0270|Closest Binary Search Tree Value||50.5%|Easy|| -|0271|Encode and Decode Strings||33.2%|Medium|| -|0272|Closest Binary Search Tree Value II||52.8%|Hard|| -|0273|Integer to English Words||28.4%|Hard|| -|0274|H-Index|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0274.H-Index)|36.5%|Medium|| -|0275|H-Index II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0275.H-Index-II)|36.4%|Medium|| -|0276|Paint Fence||39.3%|Medium|| -|0277|Find the Celebrity||44.2%|Medium|| -|0278|First Bad Version||37.9%|Easy|| -|0279|Perfect Squares||49.3%|Medium|| -|0280|Wiggle Sort||64.9%|Medium|| -|0281|Zigzag Iterator||59.7%|Medium|| -|0282|Expression Add Operators||37.0%|Hard|| -|0283|Move Zeroes|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0283.Move-Zeroes)|58.7%|Easy|| -|0284|Peeking Iterator|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0284.Peeking-Iterator)|51.0%|Medium|| -|0285|Inorder Successor in BST||43.9%|Medium|| -|0286|Walls and Gates||57.1%|Medium|| -|0287|Find the Duplicate Number|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0287.Find-the-Duplicate-Number)|58.0%|Medium|| -|0288|Unique Word Abbreviation||23.3%|Medium|| -|0289|Game of Life||59.0%|Medium|| -|0290|Word Pattern|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0290.Word-Pattern)|38.5%|Easy|| -|0291|Word Pattern II||44.5%|Medium|| -|0292|Nim Game||55.1%|Easy|| -|0293|Flip Game||61.5%|Easy|| -|0294|Flip Game II||50.8%|Medium|| -|0295|Find Median from Data Stream||47.6%|Hard|| -|0296|Best Meeting Point||58.2%|Hard|| -|0297|Serialize and Deserialize Binary Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0297.Serialize-and-Deserialize-Binary-Tree)|50.4%|Hard|| -|0298|Binary Tree Longest Consecutive Sequence||48.3%|Medium|| -|0299|Bulls and Cows||44.8%|Medium|| -|0300|Longest Increasing Subsequence|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0300.Longest-Increasing-Subsequence)|44.7%|Medium|| -|0301|Remove Invalid Parentheses||45.0%|Hard|| -|0302|Smallest Rectangle Enclosing Black Pixels||52.8%|Hard|| -|0303|Range Sum Query - Immutable|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0303.Range-Sum-Query---Immutable)|48.5%|Easy|| -|0304|Range Sum Query 2D - Immutable|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0304.Range-Sum-Query-2D---Immutable)|41.4%|Medium|| +|0264|Ugly Number II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0264.Ugly-Number-II)|46.1%|Medium|| +|0265|Paint House II||52.2%|Hard|| +|0266|Palindrome Permutation||65.8%|Easy|| +|0267|Palindrome Permutation II||40.4%|Medium|| +|0268|Missing Number|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0268.Missing-Number)|61.5%|Easy|| +|0269|Alien Dictionary||35.2%|Hard|| +|0270|Closest Binary Search Tree Value||54.5%|Easy|| +|0271|Encode and Decode Strings||41.3%|Medium|| +|0272|Closest Binary Search Tree Value II||58.2%|Hard|| +|0273|Integer to English Words||29.9%|Hard|| +|0274|H-Index|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0274.H-Index)|38.1%|Medium|| +|0275|H-Index II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0275.H-Index-II)|37.4%|Medium|| +|0276|Paint Fence||44.0%|Medium|| +|0277|Find the Celebrity||46.7%|Medium|| +|0278|First Bad Version|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0278.First-Bad-Version)|42.9%|Easy|| +|0279|Perfect Squares|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0279.Perfect-Squares)|52.2%|Medium|| +|0280|Wiggle Sort||66.3%|Medium|| +|0281|Zigzag Iterator||62.3%|Medium|| +|0282|Expression Add Operators||39.2%|Hard|| +|0283|Move Zeroes|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0283.Move-Zeroes)|61.3%|Easy|| +|0284|Peeking Iterator|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0284.Peeking-Iterator)|58.2%|Medium|| +|0285|Inorder Successor in BST||48.3%|Medium|| +|0286|Walls and Gates||60.2%|Medium|| +|0287|Find the Duplicate Number|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0287.Find-the-Duplicate-Number)|59.1%|Medium|| +|0288|Unique Word Abbreviation||25.2%|Medium|| +|0289|Game of Life||66.6%|Medium|| +|0290|Word Pattern|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0290.Word-Pattern)|40.4%|Easy|| +|0291|Word Pattern II||46.9%|Medium|| +|0292|Nim Game||55.8%|Easy|| +|0293|Flip Game||63.0%|Easy|| +|0294|Flip Game II||51.7%|Medium|| +|0295|Find Median from Data Stream||51.1%|Hard|| +|0296|Best Meeting Point||59.6%|Hard|| +|0297|Serialize and Deserialize Binary Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0297.Serialize-and-Deserialize-Binary-Tree)|54.9%|Hard|| +|0298|Binary Tree Longest Consecutive Sequence||52.5%|Medium|| +|0299|Bulls and Cows|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0299.Bulls-and-Cows)|48.5%|Medium|| +|0300|Longest Increasing Subsequence|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0300.Longest-Increasing-Subsequence)|51.5%|Medium|| +|0301|Remove Invalid Parentheses|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0301.Remove-Invalid-Parentheses)|47.1%|Hard|| +|0302|Smallest Rectangle Enclosing Black Pixels||58.2%|Hard|| +|0303|Range Sum Query - Immutable|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0303.Range-Sum-Query-Immutable)|57.9%|Easy|| +|0304|Range Sum Query 2D - Immutable|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0304.Range-Sum-Query-2D-Immutable)|52.1%|Medium|| |0305|Number of Islands II||39.5%|Hard|| -|0306|Additive Number|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0306.Additive-Number)|29.8%|Medium|| -|0307|Range Sum Query - Mutable|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0307.Range-Sum-Query---Mutable)|37.1%|Medium|| -|0308|Range Sum Query 2D - Mutable||38.4%|Hard|| -|0309|Best Time to Buy and Sell Stock with Cooldown|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0309.Best-Time-to-Buy-and-Sell-Stock-with-Cooldown)|48.5%|Medium|| -|0310|Minimum Height Trees||34.9%|Medium|| -|0311|Sparse Matrix Multiplication||64.2%|Medium|| -|0312|Burst Balloons||54.0%|Hard|| -|0313|Super Ugly Number||46.4%|Medium|| -|0314|Binary Tree Vertical Order Traversal||47.4%|Medium|| -|0315|Count of Smaller Numbers After Self|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0315.Count-of-Smaller-Numbers-After-Self)|42.4%|Hard|| -|0316|Remove Duplicate Letters||39.5%|Medium|| -|0317|Shortest Distance from All Buildings||43.1%|Hard|| -|0318|Maximum Product of Word Lengths|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0318.Maximum-Product-of-Word-Lengths)|52.6%|Medium|| -|0319|Bulb Switcher||45.5%|Medium|| -|0320|Generalized Abbreviation||54.1%|Medium|| -|0321|Create Maximum Number||27.6%|Hard|| -|0322|Coin Change|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0322.Coin-Change)|37.8%|Medium|| -|0323|Number of Connected Components in an Undirected Graph||58.4%|Medium|| -|0324|Wiggle Sort II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0324.Wiggle-Sort-II)|30.9%|Medium|| -|0325|Maximum Size Subarray Sum Equals k||47.6%|Medium|| -|0326|Power of Three|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0326.Power-of-Three)|42.3%|Easy|| -|0327|Count of Range Sum|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0327.Count-of-Range-Sum)|36.4%|Hard|| -|0328|Odd Even Linked List|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0328.Odd-Even-Linked-List)|57.3%|Medium|| -|0329|Longest Increasing Path in a Matrix|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0329.Longest-Increasing-Path-in-a-Matrix)|46.4%|Hard|| -|0330|Patching Array||35.1%|Hard|| -|0331|Verify Preorder Serialization of a Binary Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0331.Verify-Preorder-Serialization-of-a-Binary-Tree)|41.2%|Medium|| -|0332|Reconstruct Itinerary||38.3%|Medium|| -|0333|Largest BST Subtree||38.4%|Medium|| -|0334|Increasing Triplet Subsequence||40.9%|Medium|| -|0335|Self Crossing||28.8%|Hard|| -|0336|Palindrome Pairs||35.0%|Hard|| -|0337|House Robber III|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0337.House-Robber-III)|52.0%|Medium|| -|0338|Counting Bits|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0338.Counting-Bits)|70.7%|Medium|| -|0339|Nested List Weight Sum||77.0%|Medium|| -|0340|Longest Substring with At Most K Distinct Characters||45.8%|Medium|| -|0341|Flatten Nested List Iterator|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0341.Flatten-Nested-List-Iterator)|56.0%|Medium|| -|0342|Power of Four|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0342.Power-of-Four)|41.9%|Easy|| -|0343|Integer Break|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0343.Integer-Break)|51.4%|Medium|| -|0344|Reverse String|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0344.Reverse-String)|70.8%|Easy|| -|0345|Reverse Vowels of a String|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0345.Reverse-Vowels-of-a-String)|45.3%|Easy|| -|0346|Moving Average from Data Stream||73.8%|Easy|| -|0347|Top K Frequent Elements|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0347.Top-K-Frequent-Elements)|62.7%|Medium|| -|0348|Design Tic-Tac-Toe||55.8%|Medium|| -|0349|Intersection of Two Arrays|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0349.Intersection-of-Two-Arrays)|65.5%|Easy|| -|0350|Intersection of Two Arrays II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0350.Intersection-of-Two-Arrays-II)|52.2%|Easy|| -|0351|Android Unlock Patterns||49.9%|Medium|| -|0352|Data Stream as Disjoint Intervals||48.9%|Hard|| -|0353|Design Snake Game||36.3%|Medium|| -|0354|Russian Doll Envelopes|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0354.Russian-Doll-Envelopes)|37.8%|Hard|| -|0355|Design Twitter||31.8%|Medium|| -|0356|Line Reflection||33.1%|Medium|| -|0357|Count Numbers with Unique Digits|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0357.Count-Numbers-with-Unique-Digits)|49.0%|Medium|| -|0358|Rearrange String k Distance Apart||35.8%|Hard|| -|0359|Logger Rate Limiter||72.7%|Easy|| -|0360|Sort Transformed Array||50.0%|Medium|| -|0361|Bomb Enemy||47.0%|Medium|| -|0362|Design Hit Counter||65.6%|Medium|| -|0363|Max Sum of Rectangle No Larger Than K||38.6%|Hard|| -|0364|Nested List Weight Sum II||64.1%|Medium|| -|0365|Water and Jug Problem||31.4%|Medium|| -|0366|Find Leaves of Binary Tree||72.3%|Medium|| -|0367|Valid Perfect Square|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0367.Valid-Perfect-Square)|42.3%|Easy|| -|0368|Largest Divisible Subset|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0368.Largest-Divisible-Subset)|38.5%|Medium|| -|0369|Plus One Linked List||59.6%|Medium|| -|0370|Range Addition||63.8%|Medium|| -|0371|Sum of Two Integers|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0371.Sum-of-Two-Integers)|50.6%|Medium|| -|0372|Super Pow|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0372.Super-Pow)|36.8%|Medium|| -|0373|Find K Pairs with Smallest Sums|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0373.Find-K-Pairs-with-Smallest-Sums)|38.1%|Medium|| -|0374|Guess Number Higher or Lower||45.2%|Easy|| -|0375|Guess Number Higher or Lower II||42.6%|Medium|| -|0376|Wiggle Subsequence|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0376.Wiggle-Subsequence)|42.3%|Medium|| -|0377|Combination Sum IV|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0377.Combination-Sum-IV)|47.1%|Medium|| -|0378|Kth Smallest Element in a Sorted Matrix|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0378.Kth-Smallest-Element-in-a-Sorted-Matrix)|56.6%|Medium|| -|0379|Design Phone Directory||48.6%|Medium|| -|0380|Insert Delete GetRandom O(1)||49.2%|Medium|| -|0381|Insert Delete GetRandom O(1) - Duplicates allowed||35.0%|Hard|| -|0382|Linked List Random Node||54.3%|Medium|| -|0383|Ransom Note||53.5%|Easy|| -|0384|Shuffle an Array||54.2%|Medium|| -|0385|Mini Parser|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0385.Mini-Parser)|34.7%|Medium|| -|0386|Lexicographical Numbers|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0386.Lexicographical-Numbers)|54.8%|Medium|| -|0387|First Unique Character in a String|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0387.First-Unique-Character-in-a-String)|54.1%|Easy|| -|0388|Longest Absolute File Path||43.3%|Medium|| -|0389|Find the Difference|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0389.Find-the-Difference)|58.0%|Easy|| -|0390|Elimination Game||45.3%|Medium|| -|0391|Perfect Rectangle||31.3%|Hard|| -|0392|Is Subsequence|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0392.Is-Subsequence)|49.6%|Easy|| -|0393|UTF-8 Validation|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0393.UTF-8-Validation)|38.2%|Medium|| -|0394|Decode String|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0394.Decode-String)|53.1%|Medium|| -|0395|Longest Substring with At Least K Repeating Characters|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0395.Longest-Substring-with-At-Least-K-Repeating-Characters)|43.7%|Medium|| -|0396|Rotate Function||36.8%|Medium|| -|0397|Integer Replacement|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0397.Integer-Replacement)|33.6%|Medium|| -|0398|Random Pick Index||58.6%|Medium|| -|0399|Evaluate Division|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0399.Evaluate-Division)|54.7%|Medium|| -|0400|Nth Digit||32.5%|Medium|| -|0401|Binary Watch|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0401.Binary-Watch)|48.7%|Easy|| -|0402|Remove K Digits|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0402.Remove-K-Digits)|28.7%|Medium|| -|0403|Frog Jump||41.8%|Hard|| -|0404|Sum of Left Leaves|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0404.Sum-of-Left-Leaves)|52.4%|Easy|| -|0405|Convert a Number to Hexadecimal|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0405.Convert-a-Number-to-Hexadecimal)|44.6%|Easy|| -|0406|Queue Reconstruction by Height||68.7%|Medium|| -|0407|Trapping Rain Water II||44.6%|Hard|| -|0408|Valid Word Abbreviation||31.6%|Easy|| -|0409|Longest Palindrome|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0409.Longest-Palindrome)|52.3%|Easy|| -|0410|Split Array Largest Sum|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0410.Split-Array-Largest-Sum)|46.8%|Hard|| -|0411|Minimum Unique Word Abbreviation||37.5%|Hard|| -|0412|Fizz Buzz|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0412.Fizz-Buzz)|63.8%|Easy|| -|0413|Arithmetic Slices|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0413.Arithmetic-Slices)|60.1%|Medium|| -|0414|Third Maximum Number|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0414.Third-Maximum-Number)|30.8%|Easy|| -|0415|Add Strings||48.6%|Easy|| -|0416|Partition Equal Subset Sum|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0416.Partition-Equal-Subset-Sum)|45.0%|Medium|| -|0417|Pacific Atlantic Water Flow|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0417.Pacific-Atlantic-Water-Flow)|44.2%|Medium|| -|0418|Sentence Screen Fitting||33.5%|Medium|| -|0419|Battleships in a Board||71.3%|Medium|| -|0420|Strong Password Checker||13.9%|Hard|| -|0421|Maximum XOR of Two Numbers in an Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0421.Maximum-XOR-of-Two-Numbers-in-an-Array)|54.4%|Medium|| -|0422|Valid Word Square||38.3%|Easy|| -|0423|Reconstruct Original Digits from English|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0423.Reconstruct-Original-Digits-from-English)|50.9%|Medium|| -|0424|Longest Repeating Character Replacement|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0424.Longest-Repeating-Character-Replacement)|48.5%|Medium|| -|0425|Word Squares||50.4%|Hard|| -|0426|Convert Binary Search Tree to Sorted Doubly Linked List||61.7%|Medium|| -|0427|Construct Quad Tree||62.8%|Medium|| -|0428|Serialize and Deserialize N-ary Tree||61.9%|Hard|| -|0429|N-ary Tree Level Order Traversal||67.0%|Medium|| -|0430|Flatten a Multilevel Doubly Linked List||57.1%|Medium|| -|0431|Encode N-ary Tree to Binary Tree||75.0%|Hard|| -|0432|All O`one Data Structure||33.3%|Hard|| -|0433|Minimum Genetic Mutation|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0433.Minimum-Genetic-Mutation)|43.7%|Medium|| -|0434|Number of Segments in a String||37.7%|Easy|| -|0435|Non-overlapping Intervals|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0435.Non-overlapping-Intervals)|44.0%|Medium|| -|0436|Find Right Interval|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0436.Find-Right-Interval)|48.6%|Medium|| -|0437|Path Sum III|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0437.Path-Sum-III)|48.4%|Medium|| -|0438|Find All Anagrams in a String|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0438.Find-All-Anagrams-in-a-String)|45.3%|Medium|| -|0439|Ternary Expression Parser||56.9%|Medium|| -|0440|K-th Smallest in Lexicographical Order||29.9%|Hard|| -|0441|Arranging Coins|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0441.Arranging-Coins)|42.7%|Easy|| -|0442|Find All Duplicates in an Array||69.3%|Medium|| -|0443|String Compression||44.3%|Medium|| -|0444|Sequence Reconstruction||23.7%|Medium|| -|0445|Add Two Numbers II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0445.Add-Two-Numbers-II)|56.7%|Medium|| -|0446|Arithmetic Slices II - Subsequence||33.7%|Hard|| -|0447|Number of Boomerangs|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0447.Number-of-Boomerangs)|52.6%|Medium|| -|0448|Find All Numbers Disappeared in an Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0448.Find-All-Numbers-Disappeared-in-an-Array)|56.3%|Easy|| -|0449|Serialize and Deserialize BST||54.4%|Medium|| -|0450|Delete Node in a BST||45.6%|Medium|| -|0451|Sort Characters By Frequency|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0451.Sort-Characters-By-Frequency)|64.7%|Medium|| -|0452|Minimum Number of Arrows to Burst Balloons||49.8%|Medium|| -|0453|Minimum Moves to Equal Array Elements|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0453.Minimum-Moves-to-Equal-Array-Elements)|51.1%|Easy|| -|0454|4Sum II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0454.4Sum-II)|54.7%|Medium|| -|0455|Assign Cookies|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0455.Assign-Cookies)|50.4%|Easy|| -|0456|132 Pattern|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0456.132-Pattern)|30.7%|Medium|| -|0457|Circular Array Loop|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0457.Circular-Array-Loop)|30.4%|Medium|| -|0458|Poor Pigs||54.6%|Hard|| -|0459|Repeated Substring Pattern||43.3%|Easy|| -|0460|LFU Cache|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0460.LFU-Cache)|36.7%|Hard|| -|0461|Hamming Distance|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0461.Hamming-Distance)|73.3%|Easy|| -|0462|Minimum Moves to Equal Array Elements II||54.5%|Medium|| -|0463|Island Perimeter|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0463.Island-Perimeter)|66.9%|Easy|| +|0306|Additive Number|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0306.Additive-Number)|30.9%|Medium|| +|0307|Range Sum Query - Mutable|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0307.Range-Sum-Query-Mutable)|40.7%|Medium|| +|0308|Range Sum Query 2D - Mutable||42.2%|Hard|| +|0309|Best Time to Buy and Sell Stock with Cooldown|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0309.Best-Time-to-Buy-and-Sell-Stock-with-Cooldown)|54.4%|Medium|| +|0310|Minimum Height Trees||38.5%|Medium|| +|0311|Sparse Matrix Multiplication||67.1%|Medium|| +|0312|Burst Balloons||56.9%|Hard|| +|0313|Super Ugly Number||45.8%|Medium|| +|0314|Binary Tree Vertical Order Traversal||52.0%|Medium|| +|0315|Count of Smaller Numbers After Self|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0315.Count-of-Smaller-Numbers-After-Self)|42.8%|Hard|| +|0316|Remove Duplicate Letters||44.5%|Medium|| +|0317|Shortest Distance from All Buildings||43.0%|Hard|| +|0318|Maximum Product of Word Lengths|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0318.Maximum-Product-of-Word-Lengths)|60.1%|Medium|| +|0319|Bulb Switcher|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0319.Bulb-Switcher)|48.0%|Medium|| +|0320|Generalized Abbreviation||57.3%|Medium|| +|0321|Create Maximum Number||28.8%|Hard|| +|0322|Coin Change|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0322.Coin-Change)|41.5%|Medium|| +|0323|Number of Connected Components in an Undirected Graph||62.0%|Medium|| +|0324|Wiggle Sort II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0324.Wiggle-Sort-II)|32.9%|Medium|| +|0325|Maximum Size Subarray Sum Equals k||49.3%|Medium|| +|0326|Power of Three|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0326.Power-of-Three)|45.2%|Easy|| +|0327|Count of Range Sum|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0327.Count-of-Range-Sum)|36.0%|Hard|| +|0328|Odd Even Linked List|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0328.Odd-Even-Linked-List)|60.2%|Medium|| +|0329|Longest Increasing Path in a Matrix|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0329.Longest-Increasing-Path-in-a-Matrix)|52.1%|Hard|| +|0330|Patching Array||40.0%|Hard|| +|0331|Verify Preorder Serialization of a Binary Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0331.Verify-Preorder-Serialization-of-a-Binary-Tree)|44.2%|Medium|| +|0332|Reconstruct Itinerary||40.9%|Hard|| +|0333|Largest BST Subtree||42.3%|Medium|| +|0334|Increasing Triplet Subsequence||42.7%|Medium|| +|0335|Self Crossing||29.3%|Hard|| +|0336|Palindrome Pairs||35.2%|Hard|| +|0337|House Robber III|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0337.House-Robber-III)|53.8%|Medium|| +|0338|Counting Bits|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0338.Counting-Bits)|75.2%|Easy|| +|0339|Nested List Weight Sum||82.0%|Medium|| +|0340|Longest Substring with At Most K Distinct Characters||47.8%|Medium|| +|0341|Flatten Nested List Iterator|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0341.Flatten-Nested-List-Iterator)|61.5%|Medium|| +|0342|Power of Four|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0342.Power-of-Four)|45.6%|Easy|| +|0343|Integer Break|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0343.Integer-Break)|55.3%|Medium|| +|0344|Reverse String|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0344.Reverse-String)|76.1%|Easy|| +|0345|Reverse Vowels of a String|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0345.Reverse-Vowels-of-a-String)|47.7%|Easy|| +|0346|Moving Average from Data Stream||77.0%|Easy|| +|0347|Top K Frequent Elements|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0347.Top-K-Frequent-Elements)|64.8%|Medium|| +|0348|Design Tic-Tac-Toe||57.6%|Medium|| +|0349|Intersection of Two Arrays|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0349.Intersection-of-Two-Arrays)|70.2%|Easy|| +|0350|Intersection of Two Arrays II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0350.Intersection-of-Two-Arrays-II)|55.5%|Easy|| +|0351|Android Unlock Patterns||51.3%|Medium|| +|0352|Data Stream as Disjoint Intervals|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0352.Data-Stream-as-Disjoint-Intervals)|51.5%|Hard|| +|0353|Design Snake Game||39.0%|Medium|| +|0354|Russian Doll Envelopes|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0354.Russian-Doll-Envelopes)|38.3%|Hard|| +|0355|Design Twitter||36.5%|Medium|| +|0356|Line Reflection||34.6%|Medium|| +|0357|Count Numbers with Unique Digits|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0357.Count-Numbers-with-Unique-Digits)|51.5%|Medium|| +|0358|Rearrange String k Distance Apart||37.5%|Hard|| +|0359|Logger Rate Limiter||75.5%|Easy|| +|0360|Sort Transformed Array||54.6%|Medium|| +|0361|Bomb Enemy||50.9%|Medium|| +|0362|Design Hit Counter||68.3%|Medium|| +|0363|Max Sum of Rectangle No Larger Than K||44.1%|Hard|| +|0364|Nested List Weight Sum II||67.3%|Medium|| +|0365|Water and Jug Problem||36.5%|Medium|| +|0366|Find Leaves of Binary Tree||80.1%|Medium|| +|0367|Valid Perfect Square|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0367.Valid-Perfect-Square)|43.3%|Easy|| +|0368|Largest Divisible Subset|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0368.Largest-Divisible-Subset)|41.2%|Medium|| +|0369|Plus One Linked List||60.9%|Medium|| +|0370|Range Addition||70.8%|Medium|| +|0371|Sum of Two Integers|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0371.Sum-of-Two-Integers)|50.7%|Medium|| +|0372|Super Pow|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0372.Super-Pow)|37.2%|Medium|| +|0373|Find K Pairs with Smallest Sums|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0373.Find-K-Pairs-with-Smallest-Sums)|38.4%|Medium|| +|0374|Guess Number Higher or Lower|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0374.Guess-Number-Higher-or-Lower)|50.4%|Easy|| +|0375|Guess Number Higher or Lower II||46.3%|Medium|| +|0376|Wiggle Subsequence|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0376.Wiggle-Subsequence)|48.2%|Medium|| +|0377|Combination Sum IV|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0377.Combination-Sum-IV)|52.1%|Medium|| +|0378|Kth Smallest Element in a Sorted Matrix|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0378.Kth-Smallest-Element-in-a-Sorted-Matrix)|61.6%|Medium|| +|0379|Design Phone Directory||50.9%|Medium|| +|0380|Insert Delete GetRandom O(1)||52.0%|Medium|| +|0381|Insert Delete GetRandom O(1) - Duplicates allowed||35.7%|Hard|| +|0382|Linked List Random Node|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0382.Linked-List-Random-Node)|59.5%|Medium|| +|0383|Ransom Note|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0383.Ransom-Note)|57.6%|Easy|| +|0384|Shuffle an Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0384.Shuffle-an-Array)|57.6%|Medium|| +|0385|Mini Parser|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0385.Mini-Parser)|36.5%|Medium|| +|0386|Lexicographical Numbers|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0386.Lexicographical-Numbers)|60.5%|Medium|| +|0387|First Unique Character in a String|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0387.First-Unique-Character-in-a-String)|58.8%|Easy|| +|0388|Longest Absolute File Path||46.5%|Medium|| +|0389|Find the Difference|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0389.Find-the-Difference)|60.4%|Easy|| +|0390|Elimination Game|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0390.Elimination-Game)|46.6%|Medium|| +|0391|Perfect Rectangle|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0391.Perfect-Rectangle)|32.5%|Hard|| +|0392|Is Subsequence|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0392.Is-Subsequence)|49.3%|Easy|| +|0393|UTF-8 Validation|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0393.UTF-8-Validation)|45.2%|Medium|| +|0394|Decode String|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0394.Decode-String)|57.5%|Medium|| +|0395|Longest Substring with At Least K Repeating Characters|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0395.Longest-Substring-with-At-Least-K-Repeating-Characters)|44.8%|Medium|| +|0396|Rotate Function|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0396.Rotate-Function)|40.3%|Medium|| +|0397|Integer Replacement|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0397.Integer-Replacement)|35.1%|Medium|| +|0398|Random Pick Index||62.9%|Medium|| +|0399|Evaluate Division|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0399.Evaluate-Division)|59.5%|Medium|| +|0400|Nth Digit|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0400.Nth-Digit)|34.0%|Medium|| +|0401|Binary Watch|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0401.Binary-Watch)|51.4%|Easy|| +|0402|Remove K Digits|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0402.Remove-K-Digits)|30.5%|Medium|| +|0403|Frog Jump||43.1%|Hard|| +|0404|Sum of Left Leaves|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0404.Sum-of-Left-Leaves)|56.2%|Easy|| +|0405|Convert a Number to Hexadecimal|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0405.Convert-a-Number-to-Hexadecimal)|46.1%|Easy|| +|0406|Queue Reconstruction by Height||72.8%|Medium|| +|0407|Trapping Rain Water II||47.4%|Hard|| +|0408|Valid Word Abbreviation||34.8%|Easy|| +|0409|Longest Palindrome|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0409.Longest-Palindrome)|54.6%|Easy|| +|0410|Split Array Largest Sum|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0410.Split-Array-Largest-Sum)|53.2%|Hard|| +|0411|Minimum Unique Word Abbreviation||39.2%|Hard|| +|0412|Fizz Buzz|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0412.Fizz-Buzz)|68.6%|Easy|| +|0413|Arithmetic Slices|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0413.Arithmetic-Slices)|65.0%|Medium|| +|0414|Third Maximum Number|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0414.Third-Maximum-Number)|32.5%|Easy|| +|0415|Add Strings||52.6%|Easy|| +|0416|Partition Equal Subset Sum|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0416.Partition-Equal-Subset-Sum)|46.7%|Medium|| +|0417|Pacific Atlantic Water Flow|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0417.Pacific-Atlantic-Water-Flow)|53.9%|Medium|| +|0418|Sentence Screen Fitting||35.6%|Medium|| +|0419|Battleships in a Board|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0419.Battleships-in-a-Board)|74.6%|Medium|| +|0420|Strong Password Checker||14.3%|Hard|| +|0421|Maximum XOR of Two Numbers in an Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0421.Maximum-XOR-of-Two-Numbers-in-an-Array)|54.6%|Medium|| +|0422|Valid Word Square||38.8%|Easy|| +|0423|Reconstruct Original Digits from English|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0423.Reconstruct-Original-Digits-from-English)|51.3%|Medium|| +|0424|Longest Repeating Character Replacement|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0424.Longest-Repeating-Character-Replacement)|51.4%|Medium|| +|0425|Word Squares||52.6%|Hard|| +|0426|Convert Binary Search Tree to Sorted Doubly Linked List||64.6%|Medium|| +|0427|Construct Quad Tree||66.3%|Medium|| +|0428|Serialize and Deserialize N-ary Tree||65.3%|Hard|| +|0429|N-ary Tree Level Order Traversal|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0429.N-ary-Tree-Level-Order-Traversal)|70.6%|Medium|| +|0430|Flatten a Multilevel Doubly Linked List||59.4%|Medium|| +|0431|Encode N-ary Tree to Binary Tree||78.6%|Hard|| +|0432|All O`one Data Structure||36.6%|Hard|| +|0433|Minimum Genetic Mutation|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0433.Minimum-Genetic-Mutation)|48.1%|Medium|| +|0434|Number of Segments in a String|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0434.Number-of-Segments-in-a-String)|37.7%|Easy|| +|0435|Non-overlapping Intervals|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0435.Non-overlapping-Intervals)|49.8%|Medium|| +|0436|Find Right Interval|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0436.Find-Right-Interval)|50.3%|Medium|| +|0437|Path Sum III|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0437.Path-Sum-III)|48.8%|Medium|| +|0438|Find All Anagrams in a String|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0438.Find-All-Anagrams-in-a-String)|48.9%|Medium|| +|0439|Ternary Expression Parser||58.2%|Medium|| +|0440|K-th Smallest in Lexicographical Order||30.7%|Hard|| +|0441|Arranging Coins|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0441.Arranging-Coins)|46.0%|Easy|| +|0442|Find All Duplicates in an Array||73.3%|Medium|| +|0443|String Compression||48.7%|Medium|| +|0444|Sequence Reconstruction||26.3%|Medium|| +|0445|Add Two Numbers II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0445.Add-Two-Numbers-II)|59.4%|Medium|| +|0446|Arithmetic Slices II - Subsequence||39.8%|Hard|| +|0447|Number of Boomerangs|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0447.Number-of-Boomerangs)|54.6%|Medium|| +|0448|Find All Numbers Disappeared in an Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0448.Find-All-Numbers-Disappeared-in-an-Array)|59.6%|Easy|| +|0449|Serialize and Deserialize BST||56.7%|Medium|| +|0450|Delete Node in a BST||49.9%|Medium|| +|0451|Sort Characters By Frequency|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0451.Sort-Characters-By-Frequency)|68.5%|Medium|| +|0452|Minimum Number of Arrows to Burst Balloons||53.2%|Medium|| +|0453|Minimum Moves to Equal Array Elements|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0453.Minimum-Moves-to-Equal-Array-Elements)|55.6%|Medium|| +|0454|4Sum II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0454.4Sum-II)|57.3%|Medium|| +|0455|Assign Cookies|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0455.Assign-Cookies)|50.6%|Easy|| +|0456|132 Pattern|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0456.132-Pattern)|32.4%|Medium|| +|0457|Circular Array Loop|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0457.Circular-Array-Loop)|32.1%|Medium|| +|0458|Poor Pigs|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0458.Poor-Pigs)|65.0%|Hard|| +|0459|Repeated Substring Pattern||43.7%|Easy|| +|0460|LFU Cache|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0460.LFU-Cache)|40.3%|Hard|| +|0461|Hamming Distance|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0461.Hamming-Distance)|74.8%|Easy|| +|0462|Minimum Moves to Equal Array Elements II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0462.Minimum-Moves-to-Equal-Array-Elements-II)|60.1%|Medium|| +|0463|Island Perimeter|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0463.Island-Perimeter)|69.4%|Easy|| |0464|Can I Win||29.8%|Medium|| -|0465|Optimal Account Balancing||48.6%|Hard|| -|0466|Count The Repetitions||28.7%|Hard|| -|0467|Unique Substrings in Wraparound String||36.2%|Medium|| -|0468|Validate IP Address||25.2%|Medium|| -|0469|Convex Polygon||37.6%|Medium|| -|0470|Implement Rand10() Using Rand7()|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0470.Implement-Rand10()-Using-Rand7())|46.1%|Medium|| -|0471|Encode String with Shortest Length||49.8%|Hard|| -|0472|Concatenated Words||43.6%|Hard|| -|0473|Matchsticks to Square||38.3%|Medium|| -|0474|Ones and Zeroes|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0474.Ones-and-Zeroes)|43.5%|Medium|| -|0475|Heaters|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0475.Heaters)|33.8%|Medium|| -|0476|Number Complement|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0476.Number-Complement)|65.2%|Easy|| -|0477|Total Hamming Distance|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0477.Total-Hamming-Distance)|50.7%|Medium|| -|0478|Generate Random Point in a Circle|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0478.Generate-Random-Point-in-a-Circle)|39.1%|Medium|| -|0479|Largest Palindrome Product||29.7%|Hard|| -|0480|Sliding Window Median|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0480.Sliding-Window-Median)|39.0%|Hard|| -|0481|Magical String||48.2%|Medium|| -|0482|License Key Formatting||43.1%|Easy|| -|0483|Smallest Good Base|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0483.Smallest-Good-Base)|36.4%|Hard|| -|0484|Find Permutation||64.3%|Medium|| -|0485|Max Consecutive Ones|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0485.Max-Consecutive-Ones)|52.7%|Easy|| -|0486|Predict the Winner||49.1%|Medium|| -|0487|Max Consecutive Ones II||48.0%|Medium|| -|0488|Zuma Game||38.1%|Hard|| -|0489|Robot Room Cleaner||73.1%|Hard|| -|0490|The Maze||53.0%|Medium|| -|0491|Increasing Subsequences|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0491.Increasing-Subsequences)|47.9%|Medium|| -|0492|Construct the Rectangle||50.7%|Easy|| -|0493|Reverse Pairs|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0493.Reverse-Pairs)|27.3%|Hard|| +|0465|Optimal Account Balancing||49.3%|Hard|| +|0466|Count The Repetitions||29.2%|Hard|| +|0467|Unique Substrings in Wraparound String||38.2%|Medium|| +|0468|Validate IP Address||26.5%|Medium|| +|0469|Convex Polygon||38.5%|Medium|| +|0470|Implement Rand10() Using Rand7()|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0470.Implement-Rand10-Using-Rand7)|46.7%|Medium|| +|0471|Encode String with Shortest Length||50.7%|Hard|| +|0472|Concatenated Words||45.5%|Hard|| +|0473|Matchsticks to Square|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0473.Matchsticks-to-Square)|40.5%|Medium|| +|0474|Ones and Zeroes|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0474.Ones-and-Zeroes)|46.7%|Medium|| +|0475|Heaters|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0475.Heaters)|36.0%|Medium|| +|0476|Number Complement|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0476.Number-Complement)|67.1%|Easy|| +|0477|Total Hamming Distance|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0477.Total-Hamming-Distance)|52.2%|Medium|| +|0478|Generate Random Point in a Circle|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0478.Generate-Random-Point-in-a-Circle)|39.6%|Medium|| +|0479|Largest Palindrome Product||31.6%|Hard|| +|0480|Sliding Window Median|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0480.Sliding-Window-Median)|41.4%|Hard|| +|0481|Magical String||50.4%|Medium|| +|0482|License Key Formatting||43.2%|Easy|| +|0483|Smallest Good Base|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0483.Smallest-Good-Base)|38.4%|Hard|| +|0484|Find Permutation||67.0%|Medium|| +|0485|Max Consecutive Ones|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0485.Max-Consecutive-Ones)|56.0%|Easy|| +|0486|Predict the Winner||50.8%|Medium|| +|0487|Max Consecutive Ones II||49.2%|Medium|| +|0488|Zuma Game|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0488.Zuma-Game)|34.9%|Hard|| +|0489|Robot Room Cleaner||76.5%|Hard|| +|0490|The Maze||55.4%|Medium|| +|0491|Increasing Subsequences|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0491.Increasing-Subsequences)|52.0%|Medium|| +|0492|Construct the Rectangle|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0492.Construct-the-Rectangle)|53.6%|Easy|| +|0493|Reverse Pairs|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0493.Reverse-Pairs)|30.8%|Hard|| |0494|Target Sum|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0494.Target-Sum)|45.6%|Medium|| -|0495|Teemo Attacking||56.0%|Medium|| -|0496|Next Greater Element I|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0496.Next-Greater-Element-I)|66.0%|Easy|| -|0497|Random Point in Non-overlapping Rectangles|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0497.Random-Point-in-Non-overlapping-Rectangles)|39.1%|Medium|| -|0498|Diagonal Traverse|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0498.Diagonal-Traverse)|50.7%|Medium|| -|0499|The Maze III||42.7%|Hard|| -|0500|Keyboard Row|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0500.Keyboard-Row)|66.0%|Easy|| -|0501|Find Mode in Binary Search Tree||43.9%|Easy|| -|0502|IPO||41.9%|Hard|| -|0503|Next Greater Element II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0503.Next-Greater-Element-II)|58.9%|Medium|| -|0504|Base 7||46.5%|Easy|| -|0505|The Maze II||48.7%|Medium|| -|0506|Relative Ranks||51.6%|Easy|| -|0507|Perfect Number|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0507.Perfect-Number)|36.4%|Easy|| -|0508|Most Frequent Subtree Sum|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0508.Most-Frequent-Subtree-Sum)|59.3%|Medium|| -|0509|Fibonacci Number|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0509.Fibonacci-Number)|67.9%|Easy|| -|0510|Inorder Successor in BST II||60.5%|Medium|| -|0511|Game Play Analysis I||81.5%|Easy|| -|0512|Game Play Analysis II||56.0%|Easy|| -|0513|Find Bottom Left Tree Value|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0513.Find-Bottom-Left-Tree-Value)|62.9%|Medium|| -|0514|Freedom Trail||45.0%|Hard|| -|0515|Find Largest Value in Each Tree Row|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0515.Find-Largest-Value-in-Each-Tree-Row)|62.5%|Medium|| -|0516|Longest Palindromic Subsequence||56.0%|Medium|| -|0517|Super Washing Machines||38.7%|Hard|| -|0518|Coin Change 2||52.2%|Medium|| -|0519|Random Flip Matrix||37.9%|Medium|| -|0520|Detect Capital||54.2%|Easy|| -|0521|Longest Uncommon Subsequence I||59.1%|Easy|| -|0522|Longest Uncommon Subsequence II||34.3%|Medium|| -|0523|Continuous Subarray Sum||24.9%|Medium|| -|0524|Longest Word in Dictionary through Deleting|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0524.Longest-Word-in-Dictionary-through-Deleting)|50.2%|Medium|| -|0525|Contiguous Array||43.7%|Medium|| -|0526|Beautiful Arrangement|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0526.Beautiful-Arrangement)|62.2%|Medium|| -|0527|Word Abbreviation||56.5%|Hard|| -|0528|Random Pick with Weight|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0528.Random-Pick-with-Weight)|44.8%|Medium|| -|0529|Minesweeper|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0529.Minesweeper)|61.6%|Medium|| -|0530|Minimum Absolute Difference in BST|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0530.Minimum-Absolute-Difference-in-BST)|55.1%|Easy|| -|0531|Lonely Pixel I||59.8%|Medium|| -|0532|K-diff Pairs in an Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0532.K-diff-Pairs-in-an-Array)|35.6%|Medium|| -|0533|Lonely Pixel II||48.2%|Medium|| -|0534|Game Play Analysis III||80.1%|Medium|| -|0535|Encode and Decode TinyURL|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0535.Encode-and-Decode-TinyURL)|82.4%|Medium|| -|0536|Construct Binary Tree from String||52.4%|Medium|| -|0537|Complex Number Multiplication|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0537.Complex-Number-Multiplication)|68.4%|Medium|| -|0538|Convert BST to Greater Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0538.Convert-BST-to-Greater-Tree)|60.0%|Medium|| -|0539|Minimum Time Difference||52.5%|Medium|| -|0540|Single Element in a Sorted Array||58.0%|Medium|| -|0541|Reverse String II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0541.Reverse-String-II)|49.6%|Easy|| -|0542|01 Matrix|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0542.01-Matrix)|41.2%|Medium|| -|0543|Diameter of Binary Tree||49.7%|Easy|| -|0544|Output Contest Matches||75.9%|Medium|| -|0545|Boundary of Binary Tree||40.5%|Medium|| -|0546|Remove Boxes||44.1%|Hard|| -|0547|Number of Provinces|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0547.Number-of-Provinces)|60.9%|Medium|| -|0548|Split Array with Equal Sum||48.5%|Medium|| -|0549|Binary Tree Longest Consecutive Sequence II||47.3%|Medium|| -|0550|Game Play Analysis IV||45.8%|Medium|| -|0551|Student Attendance Record I||46.2%|Easy|| -|0552|Student Attendance Record II||37.9%|Hard|| -|0553|Optimal Division||57.6%|Medium|| -|0554|Brick Wall||51.6%|Medium|| -|0555|Split Concatenated Strings||42.9%|Medium|| -|0556|Next Greater Element III||33.5%|Medium|| -|0557|Reverse Words in a String III|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0557.Reverse-Words-in-a-String-III)|72.6%|Easy|| -|0558|Logical OR of Two Binary Grids Represented as Quad-Trees||45.8%|Medium|| -|0559|Maximum Depth of N-ary Tree||69.7%|Easy|| -|0560|Subarray Sum Equals K||43.7%|Medium|| -|0561|Array Partition I|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0561.Array-Partition-I)|73.6%|Easy|| -|0562|Longest Line of Consecutive One in Matrix||46.3%|Medium|| -|0563|Binary Tree Tilt|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0563.Binary-Tree-Tilt)|53.4%|Easy|| -|0564|Find the Closest Palindrome||20.4%|Hard|| -|0565|Array Nesting||56.0%|Medium|| -|0566|Reshape the Matrix|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0566.Reshape-the-Matrix)|61.1%|Easy|| -|0567|Permutation in String|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0567.Permutation-in-String)|44.6%|Medium|| -|0568|Maximum Vacation Days||41.8%|Hard|| -|0569|Median Employee Salary||62.5%|Hard|| -|0570|Managers with at Least 5 Direct Reports||66.9%|Medium|| -|0571|Find Median Given Frequency of Numbers||45.7%|Hard|| -|0572|Subtree of Another Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0572.Subtree-of-Another-Tree)|44.6%|Easy|| -|0573|Squirrel Simulation||54.2%|Medium|| -|0574|Winning Candidate||52.9%|Medium|| -|0575|Distribute Candies|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0575.Distribute-Candies)|64.4%|Easy|| -|0576|Out of Boundary Paths||36.1%|Medium|| -|0577|Employee Bonus||72.1%|Easy|| -|0578|Get Highest Answer Rate Question||42.2%|Medium|| -|0579|Find Cumulative Salary of an Employee||38.6%|Hard|| -|0580|Count Student Number in Departments||52.4%|Medium|| -|0581|Shortest Unsorted Continuous Subarray|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0581.Shortest-Unsorted-Continuous-Subarray)|33.0%|Medium|| -|0582|Kill Process||64.0%|Medium|| -|0583|Delete Operation for Two Strings||50.5%|Medium|| -|0584|Find Customer Referee||74.3%|Easy|| -|0585|Investments in 2016||57.5%|Medium|| -|0586|Customer Placing the Largest Number of Orders||75.5%|Easy|| -|0587|Erect the Fence||36.6%|Hard|| -|0588|Design In-Memory File System||46.8%|Hard|| -|0589|N-ary Tree Preorder Traversal|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0589.N-ary-Tree-Preorder-Traversal)|74.3%|Easy|| -|0590|N-ary Tree Postorder Traversal||73.8%|Easy|| -|0591|Tag Validator||35.0%|Hard|| -|0592|Fraction Addition and Subtraction||50.5%|Medium|| -|0593|Valid Square||43.4%|Medium|| -|0594|Longest Harmonious Subsequence|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0594.Longest-Harmonious-Subsequence)|51.3%|Easy|| -|0595|Big Countries||78.7%|Easy|| -|0596|Classes More Than 5 Students||39.0%|Easy|| -|0597|Friend Requests I: Overall Acceptance Rate||42.0%|Easy|| -|0598|Range Addition II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0598.Range-Addition-II)|50.3%|Easy|| -|0599|Minimum Index Sum of Two Lists|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0599.Minimum-Index-Sum-of-Two-Lists)|52.0%|Easy|| -|0600|Non-negative Integers without Consecutive Ones||34.4%|Hard|| -|0601|Human Traffic of Stadium||46.0%|Hard|| -|0602|Friend Requests II: Who Has the Most Friends||58.1%|Medium|| -|0603|Consecutive Available Seats||66.3%|Easy|| -|0604|Design Compressed String Iterator||38.3%|Easy|| -|0605|Can Place Flowers|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0605.Can-Place-Flowers)|31.7%|Easy|| -|0606|Construct String from Binary Tree||55.8%|Easy|| -|0607|Sales Person||65.6%|Easy|| -|0608|Tree Node||70.1%|Medium|| -|0609|Find Duplicate File in System||61.3%|Medium|| -|0610|Triangle Judgement||69.1%|Easy|| -|0611|Valid Triangle Number||49.5%|Medium|| -|0612|Shortest Distance in a Plane||61.8%|Medium|| -|0613|Shortest Distance in a Line||80.0%|Easy|| -|0614|Second Degree Follower||33.0%|Medium|| -|0615|Average Salary: Departments VS Company||53.2%|Hard|| -|0616|Add Bold Tag in String||45.0%|Medium|| -|0617|Merge Two Binary Trees||75.6%|Easy|| -|0618|Students Report By Geography||60.8%|Hard|| -|0619|Biggest Single Number||45.4%|Easy|| -|0620|Not Boring Movies||70.3%|Easy|| -|0621|Task Scheduler||52.4%|Medium|| -|0622|Design Circular Queue|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0622.Design-Circular-Queue)|47.7%|Medium|| -|0623|Add One Row to Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0623.Add-One-Row-to-Tree)|53.0%|Medium|| -|0624|Maximum Distance in Arrays||39.7%|Medium|| -|0625|Minimum Factorization||33.0%|Medium|| -|0626|Exchange Seats||66.4%|Medium|| -|0627|Swap Salary||78.2%|Easy|| -|0628|Maximum Product of Three Numbers|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0628.Maximum-Product-of-Three-Numbers)|46.8%|Easy|| -|0629|K Inverse Pairs Array||31.8%|Hard|| -|0630|Course Schedule III||33.9%|Hard|| -|0631|Design Excel Sum Formula||32.3%|Hard|| -|0632|Smallest Range Covering Elements from K Lists|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0632.Smallest-Range-Covering-Elements-from-K-Lists)|54.7%|Hard|| -|0633|Sum of Square Numbers|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0633.Sum-of-Square-Numbers)|32.7%|Medium|| -|0634|Find the Derangement of An Array||40.6%|Medium|| -|0635|Design Log Storage System||60.3%|Medium|| -|0636|Exclusive Time of Functions|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0636.Exclusive-Time-of-Functions)|55.2%|Medium|| -|0637|Average of Levels in Binary Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0637.Average-of-Levels-in-Binary-Tree)|66.2%|Easy|| -|0638|Shopping Offers|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0638.Shopping-Offers)|53.3%|Medium|| -|0639|Decode Ways II||27.7%|Hard|| -|0640|Solve the Equation||42.8%|Medium|| -|0641|Design Circular Deque||56.4%|Medium|| -|0642|Design Search Autocomplete System||46.7%|Hard|| -|0643|Maximum Average Subarray I|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0643.Maximum-Average-Subarray-I)|42.1%|Easy|| -|0644|Maximum Average Subarray II||34.3%|Hard|| -|0645|Set Mismatch|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0645.Set-Mismatch)|41.0%|Easy|| -|0646|Maximum Length of Pair Chain||53.2%|Medium|| -|0647|Palindromic Substrings|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0647.Palindromic-Substrings)|62.8%|Medium|| -|0648|Replace Words|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0648.Replace-Words)|59.2%|Medium|| -|0649|Dota2 Senate||39.4%|Medium|| -|0650|2 Keys Keyboard||50.3%|Medium|| -|0651|4 Keys Keyboard||53.2%|Medium|| -|0652|Find Duplicate Subtrees||53.2%|Medium|| -|0653|Two Sum IV - Input is a BST|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0653.Two-Sum-IV---Input-is-a-BST)|56.4%|Easy|| -|0654|Maximum Binary Tree||81.4%|Medium|| -|0655|Print Binary Tree||56.4%|Medium|| -|0656|Coin Path||29.8%|Hard|| -|0657|Robot Return to Origin||74.1%|Easy|| -|0658|Find K Closest Elements|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0658.Find-K-Closest-Elements)|42.4%|Medium|| -|0659|Split Array into Consecutive Subsequences||44.6%|Medium|| -|0660|Remove 9||54.3%|Hard|| -|0661|Image Smoother|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0661.Image-Smoother)|52.4%|Easy|| -|0662|Maximum Width of Binary Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0662.Maximum-Width-of-Binary-Tree)|39.7%|Medium|| -|0663|Equal Tree Partition||39.8%|Medium|| -|0664|Strange Printer||41.6%|Hard|| -|0665|Non-decreasing Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0665.Non-decreasing-Array)|19.9%|Medium|| -|0666|Path Sum IV||56.9%|Medium|| -|0667|Beautiful Arrangement II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0667.Beautiful-Arrangement-II)|59.0%|Medium|| -|0668|Kth Smallest Number in Multiplication Table|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0668.Kth-Smallest-Number-in-Multiplication-Table)|48.0%|Hard|| -|0669|Trim a Binary Search Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0669.Trim-a-Binary-Search-Tree)|64.3%|Medium|| -|0670|Maximum Swap||45.4%|Medium|| -|0671|Second Minimum Node In a Binary Tree||42.9%|Easy|| -|0672|Bulb Switcher II||51.1%|Medium|| -|0673|Number of Longest Increasing Subsequence||38.7%|Medium|| -|0674|Longest Continuous Increasing Subsequence|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0674.Longest-Continuous-Increasing-Subsequence)|46.0%|Easy|| -|0675|Cut Off Trees for Golf Event||35.5%|Hard|| -|0676|Implement Magic Dictionary|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0676.Implement-Magic-Dictionary)|55.4%|Medium|| -|0677|Map Sum Pairs||54.2%|Medium|| -|0678|Valid Parenthesis String||31.8%|Medium|| -|0679|24 Game||47.3%|Hard|| -|0680|Valid Palindrome II||37.2%|Easy|| -|0681|Next Closest Time||46.0%|Medium|| -|0682|Baseball Game|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0682.Baseball-Game)|67.5%|Easy|| -|0683|K Empty Slots||36.2%|Hard|| -|0684|Redundant Connection|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0684.Redundant-Connection)|59.2%|Medium|| -|0685|Redundant Connection II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0685.Redundant-Connection-II)|33.2%|Hard|| -|0686|Repeated String Match||32.9%|Medium|| -|0687|Longest Univalue Path||37.6%|Medium|| -|0688|Knight Probability in Chessboard||50.3%|Medium|| -|0689|Maximum Sum of 3 Non-Overlapping Subarrays||47.4%|Hard|| -|0690|Employee Importance||59.1%|Easy|| -|0691|Stickers to Spell Word||45.3%|Hard|| -|0692|Top K Frequent Words||53.3%|Medium|| -|0693|Binary Number with Alternating Bits|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0693.Binary-Number-with-Alternating-Bits)|60.0%|Easy|| -|0694|Number of Distinct Islands||58.2%|Medium|| -|0695|Max Area of Island|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0695.Max-Area-of-Island)|65.3%|Medium|| -|0696|Count Binary Substrings|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0696.Count-Binary-Substrings)|61.2%|Easy|| -|0697|Degree of an Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0697.Degree-of-an-Array)|54.5%|Easy|| -|0698|Partition to K Equal Sum Subsets||45.5%|Medium|| -|0699|Falling Squares|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0699.Falling-Squares)|43.4%|Hard|| -|0700|Search in a Binary Search Tree||73.5%|Easy|| -|0701|Insert into a Binary Search Tree||75.3%|Medium|| -|0702|Search in a Sorted Array of Unknown Size||69.1%|Medium|| -|0703|Kth Largest Element in a Stream|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0703.Kth-Largest-Element-in-a-Stream)|51.0%|Easy|| -|0704|Binary Search|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0704.Binary-Search)|54.4%|Easy|| -|0705|Design HashSet|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0705.Design-HashSet)|64.5%|Easy|| -|0706|Design HashMap|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0706.Design-HashMap)|64.0%|Easy|| -|0707|Design Linked List|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0707.Design-Linked-List)|26.1%|Medium|| -|0708|Insert into a Sorted Circular Linked List||32.7%|Medium|| -|0709|To Lower Case||80.3%|Easy|| -|0710|Random Pick with Blacklist|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0710.Random-Pick-with-Blacklist)|33.1%|Hard|| -|0711|Number of Distinct Islands II||49.7%|Hard|| -|0712|Minimum ASCII Delete Sum for Two Strings||59.7%|Medium|| -|0713|Subarray Product Less Than K|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0713.Subarray-Product-Less-Than-K)|40.6%|Medium|| -|0714|Best Time to Buy and Sell Stock with Transaction Fee|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0714.Best-Time-to-Buy-and-Sell-Stock-with-Transaction-Fee)|58.2%|Medium|| -|0715|Range Module|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0715.Range-Module)|41.0%|Hard|| -|0716|Max Stack||43.2%|Easy|| -|0717|1-bit and 2-bit Characters|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0717.1-bit-and-2-bit-Characters)|46.8%|Easy|| -|0718|Maximum Length of Repeated Subarray|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0718.Maximum-Length-of-Repeated-Subarray)|50.6%|Medium|| -|0719|Find K-th Smallest Pair Distance|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0719.Find-K-th-Smallest-Pair-Distance)|32.7%|Hard|| -|0720|Longest Word in Dictionary|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0720.Longest-Word-in-Dictionary)|49.6%|Easy|| -|0721|Accounts Merge|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0721.Accounts-Merge)|52.5%|Medium|| -|0722|Remove Comments||36.5%|Medium|| -|0723|Candy Crush||73.2%|Medium|| -|0724|Find Pivot Index|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0724.Find-Pivot-Index)|46.4%|Easy|| -|0725|Split Linked List in Parts|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0725.Split-Linked-List-in-Parts)|53.2%|Medium|| -|0726|Number of Atoms|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0726.Number-of-Atoms)|51.0%|Hard|| -|0727|Minimum Window Subsequence||42.5%|Hard|| -|0728|Self Dividing Numbers||75.8%|Easy|| -|0729|My Calendar I|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0729.My-Calendar-I)|53.7%|Medium|| -|0730|Count Different Palindromic Subsequences||43.5%|Hard|| -|0731|My Calendar II||51.1%|Medium|| -|0732|My Calendar III|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0732.My-Calendar-III)|62.5%|Hard|| -|0733|Flood Fill|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0733.Flood-Fill)|56.0%|Easy|| -|0734|Sentence Similarity||42.5%|Easy|| -|0735|Asteroid Collision|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0735.Asteroid-Collision)|43.4%|Medium|| -|0736|Parse Lisp Expression||49.8%|Hard|| -|0737|Sentence Similarity II||46.7%|Medium|| -|0738|Monotone Increasing Digits||45.8%|Medium|| -|0739|Daily Temperatures|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0739.Daily-Temperatures)|64.9%|Medium|| -|0740|Delete and Earn||50.2%|Medium|| -|0741|Cherry Pickup||35.2%|Hard|| -|0742|Closest Leaf in a Binary Tree||44.6%|Medium|| -|0743|Network Delay Time||45.8%|Medium|| -|0744|Find Smallest Letter Greater Than Target|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0744.Find-Smallest-Letter-Greater-Than-Target)|45.6%|Easy|| -|0745|Prefix and Suffix Search|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0745.Prefix-and-Suffix-Search)|35.6%|Hard|| -|0746|Min Cost Climbing Stairs|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0746.Min-Cost-Climbing-Stairs)|51.2%|Easy|| -|0747|Largest Number At Least Twice of Others||43.3%|Easy|| -|0748|Shortest Completing Word|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0748.Shortest-Completing-Word)|57.7%|Easy|| -|0749|Contain Virus||48.5%|Hard|| -|0750|Number Of Corner Rectangles||67.2%|Medium|| -|0751|IP to CIDR||59.0%|Medium|| -|0752|Open the Lock||53.0%|Medium|| -|0753|Cracking the Safe|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0753.Cracking-the-Safe)|52.7%|Hard|| -|0754|Reach a Number||40.6%|Medium|| -|0755|Pour Water||44.3%|Medium|| -|0756|Pyramid Transition Matrix|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0756.Pyramid-Transition-Matrix)|55.7%|Medium|| -|0757|Set Intersection Size At Least Two||42.6%|Hard|| -|0758|Bold Words in String||47.6%|Easy|| -|0759|Employee Free Time||68.6%|Hard|| -|0760|Find Anagram Mappings||82.0%|Easy|| -|0761|Special Binary String||58.8%|Hard|| -|0762|Prime Number of Set Bits in Binary Representation|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0762.Prime-Number-of-Set-Bits-in-Binary-Representation)|64.7%|Easy|| -|0763|Partition Labels|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0763.Partition-Labels)|78.1%|Medium|| -|0764|Largest Plus Sign||46.7%|Medium|| -|0765|Couples Holding Hands|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0765.Couples-Holding-Hands)|55.6%|Hard|| -|0766|Toeplitz Matrix|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0766.Toeplitz-Matrix)|66.0%|Easy|| -|0767|Reorganize String|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0767.Reorganize-String)|50.3%|Medium|| -|0768|Max Chunks To Make Sorted II||50.0%|Hard|| -|0769|Max Chunks To Make Sorted||56.0%|Medium|| -|0770|Basic Calculator IV||54.5%|Hard|| -|0771|Jewels and Stones|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0771.Jewels-and-Stones)|87.0%|Easy|| -|0772|Basic Calculator III||44.3%|Hard|| -|0773|Sliding Puzzle||61.3%|Hard|| -|0774|Minimize Max Distance to Gas Station||48.8%|Hard|| -|0775|Global and Local Inversions|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0775.Global-and-Local-Inversions)|46.2%|Medium|| -|0776|Split BST||56.7%|Medium|| -|0777|Swap Adjacent in LR String||35.7%|Medium|| -|0778|Swim in Rising Water|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0778.Swim-in-Rising-Water)|55.1%|Hard|| -|0779|K-th Symbol in Grammar||38.9%|Medium|| -|0780|Reaching Points||30.5%|Hard|| -|0781|Rabbits in Forest|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0781.Rabbits-in-Forest)|55.8%|Medium|| -|0782|Transform to Chessboard||47.0%|Hard|| -|0783|Minimum Distance Between BST Nodes|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0783.Minimum-Distance-Between-BST-Nodes)|54.3%|Easy|| -|0784|Letter Case Permutation|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0784.Letter-Case-Permutation)|68.9%|Medium|| -|0785|Is Graph Bipartite?|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0785.Is-Graph-Bipartite?)|48.8%|Medium|| -|0786|K-th Smallest Prime Fraction|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0786.K-th-Smallest-Prime-Fraction)|43.7%|Hard|| -|0787|Cheapest Flights Within K Stops||39.7%|Medium|| -|0788|Rotated Digits||57.6%|Easy|| -|0789|Escape The Ghosts||58.6%|Medium|| -|0790|Domino and Tromino Tiling||40.3%|Medium|| -|0791|Custom Sort String||65.9%|Medium|| -|0792|Number of Matching Subsequences||48.4%|Medium|| -|0793|Preimage Size of Factorial Zeroes Function|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0793.Preimage-Size-of-Factorial-Zeroes-Function)|40.7%|Hard|| -|0794|Valid Tic-Tac-Toe State||34.1%|Medium|| -|0795|Number of Subarrays with Bounded Maximum||48.1%|Medium|| -|0796|Rotate String||49.1%|Easy|| -|0797|All Paths From Source to Target||78.7%|Medium|| -|0798|Smallest Rotation with Highest Score||45.2%|Hard|| -|0799|Champagne Tower||44.1%|Medium|| -|0800|Similar RGB Color||62.6%|Easy|| -|0801|Minimum Swaps To Make Sequences Increasing||38.9%|Medium|| -|0802|Find Eventual Safe States|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0802.Find-Eventual-Safe-States)|50.1%|Medium|| -|0803|Bricks Falling When Hit|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0803.Bricks-Falling-When-Hit)|32.0%|Hard|| -|0804|Unique Morse Code Words||79.1%|Easy|| -|0805|Split Array With Same Average||27.0%|Hard|| -|0806|Number of Lines To Write String||65.5%|Easy|| -|0807|Max Increase to Keep City Skyline||84.5%|Medium|| -|0808|Soup Servings||41.2%|Medium|| -|0809|Expressive Words||46.4%|Medium|| -|0810|Chalkboard XOR Game||50.3%|Hard|| -|0811|Subdomain Visit Count|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0811.Subdomain-Visit-Count)|71.8%|Easy|| -|0812|Largest Triangle Area|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0812.Largest-Triangle-Area)|59.1%|Easy|| -|0813|Largest Sum of Averages||51.3%|Medium|| -|0814|Binary Tree Pruning||71.9%|Medium|| -|0815|Bus Routes|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0815.Bus-Routes)|43.6%|Hard|| -|0816|Ambiguous Coordinates||48.2%|Medium|| -|0817|Linked List Components|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0817.Linked-List-Components)|57.8%|Medium|| -|0818|Race Car||40.5%|Hard|| -|0819|Most Common Word|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0819.Most-Common-Word)|45.5%|Easy|| -|0820|Short Encoding of Words|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0820.Short-Encoding-of-Words)|54.9%|Medium|| -|0821|Shortest Distance to a Character|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0821.Shortest-Distance-to-a-Character)|70.1%|Easy|| -|0822|Card Flipping Game||43.8%|Medium|| -|0823|Binary Trees With Factors|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0823.Binary-Trees-With-Factors)|43.7%|Medium|| -|0824|Goat Latin||67.0%|Easy|| -|0825|Friends Of Appropriate Ages||44.4%|Medium|| -|0826|Most Profit Assigning Work|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0826.Most-Profit-Assigning-Work)|39.4%|Medium|| -|0827|Making A Large Island||47.2%|Hard|| -|0828|Count Unique Characters of All Substrings of a Given String|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0828.Count-Unique-Characters-of-All-Substrings-of-a-Given-String)|46.9%|Hard|| -|0829|Consecutive Numbers Sum||39.2%|Hard|| -|0830|Positions of Large Groups|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0830.Positions-of-Large-Groups)|50.5%|Easy|| -|0831|Masking Personal Information||44.8%|Medium|| -|0832|Flipping an Image|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0832.Flipping-an-Image)|78.4%|Easy|| -|0833|Find And Replace in String||51.5%|Medium|| -|0834|Sum of Distances in Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0834.Sum-of-Distances-in-Tree)|46.8%|Hard|| -|0835|Image Overlap||61.6%|Medium|| -|0836|Rectangle Overlap|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0836.Rectangle-Overlap)|43.5%|Easy|| -|0837|New 21 Game||35.6%|Medium|| -|0838|Push Dominoes|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0838.Push-Dominoes)|50.1%|Medium|| -|0839|Similar String Groups|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0839.Similar-String-Groups)|41.8%|Hard|| -|0840|Magic Squares In Grid||37.9%|Medium|| -|0841|Keys and Rooms|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0841.Keys-and-Rooms)|66.5%|Medium|| -|0842|Split Array into Fibonacci Sequence|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0842.Split-Array-into-Fibonacci-Sequence)|37.0%|Medium|| -|0843|Guess the Word||46.3%|Hard|| -|0844|Backspace String Compare|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0844.Backspace-String-Compare)|47.2%|Easy|| -|0845|Longest Mountain in Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0845.Longest-Mountain-in-Array)|38.7%|Medium|| -|0846|Hand of Straights||55.5%|Medium|| -|0847|Shortest Path Visiting All Nodes||54.3%|Hard|| -|0848|Shifting Letters||45.2%|Medium|| -|0849|Maximize Distance to Closest Person||44.6%|Medium|| -|0850|Rectangle Area II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0850.Rectangle-Area-II)|48.5%|Hard|| -|0851|Loud and Rich|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0851.Loud-and-Rich)|52.9%|Medium|| -|0852|Peak Index in a Mountain Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0852.Peak-Index-in-a-Mountain-Array)|71.8%|Easy|| -|0853|Car Fleet|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0853.Car-Fleet)|44.6%|Medium|| -|0854|K-Similar Strings||38.7%|Hard|| +|0495|Teemo Attacking|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0495.Teemo-Attacking)|57.0%|Easy|| +|0496|Next Greater Element I|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0496.Next-Greater-Element-I)|71.3%|Easy|| +|0497|Random Point in Non-overlapping Rectangles|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0497.Random-Point-in-Non-overlapping-Rectangles)|39.3%|Medium|| +|0498|Diagonal Traverse|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0498.Diagonal-Traverse)|58.0%|Medium|| +|0499|The Maze III||46.9%|Hard|| +|0500|Keyboard Row|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0500.Keyboard-Row)|69.0%|Easy|| +|0501|Find Mode in Binary Search Tree||48.5%|Easy|| +|0502|IPO||44.9%|Hard|| +|0503|Next Greater Element II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0503.Next-Greater-Element-II)|63.0%|Medium|| +|0504|Base 7|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0504.Base-7)|47.9%|Easy|| +|0505|The Maze II||52.4%|Medium|| +|0506|Relative Ranks|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0506.Relative-Ranks)|58.8%|Easy|| +|0507|Perfect Number|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0507.Perfect-Number)|37.7%|Easy|| +|0508|Most Frequent Subtree Sum|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0508.Most-Frequent-Subtree-Sum)|64.2%|Medium|| +|0509|Fibonacci Number|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0509.Fibonacci-Number)|69.2%|Easy|| +|0510|Inorder Successor in BST II||61.1%|Medium|| +|0511|Game Play Analysis I||78.8%|Easy|| +|0512|Game Play Analysis II||54.1%|Easy|| +|0513|Find Bottom Left Tree Value|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0513.Find-Bottom-Left-Tree-Value)|66.3%|Medium|| +|0514|Freedom Trail||46.8%|Hard|| +|0515|Find Largest Value in Each Tree Row|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0515.Find-Largest-Value-in-Each-Tree-Row)|64.6%|Medium|| +|0516|Longest Palindromic Subsequence||60.6%|Medium|| +|0517|Super Washing Machines||39.7%|Hard|| +|0518|Coin Change II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0518.Coin-Change-II)|59.7%|Medium|| +|0519|Random Flip Matrix|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0519.Random-Flip-Matrix)|39.6%|Medium|| +|0520|Detect Capital|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0520.Detect-Capital)|55.6%|Easy|| +|0521|Longest Uncommon Subsequence I||60.3%|Easy|| +|0522|Longest Uncommon Subsequence II||40.4%|Medium|| +|0523|Continuous Subarray Sum|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0523.Continuous-Subarray-Sum)|27.7%|Medium|| +|0524|Longest Word in Dictionary through Deleting|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0524.Longest-Word-in-Dictionary-through-Deleting)|51.2%|Medium|| +|0525|Contiguous Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0525.Contiguous-Array)|46.8%|Medium|| +|0526|Beautiful Arrangement|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0526.Beautiful-Arrangement)|64.6%|Medium|| +|0527|Word Abbreviation||60.3%|Hard|| +|0528|Random Pick with Weight|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0528.Random-Pick-with-Weight)|46.1%|Medium|| +|0529|Minesweeper|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0529.Minesweeper)|65.5%|Medium|| +|0530|Minimum Absolute Difference in BST|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0530.Minimum-Absolute-Difference-in-BST)|56.7%|Easy|| +|0531|Lonely Pixel I||62.0%|Medium|| +|0532|K-diff Pairs in an Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0532.K-diff-Pairs-in-an-Array)|40.7%|Medium|| +|0533|Lonely Pixel II||48.4%|Medium|| +|0534|Game Play Analysis III||82.5%|Medium|| +|0535|Encode and Decode TinyURL|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0535.Encode-and-Decode-TinyURL)|85.7%|Medium|| +|0536|Construct Binary Tree from String||56.1%|Medium|| +|0537|Complex Number Multiplication|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0537.Complex-Number-Multiplication)|71.3%|Medium|| +|0538|Convert BST to Greater Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0538.Convert-BST-to-Greater-Tree)|67.3%|Medium|| +|0539|Minimum Time Difference||56.3%|Medium|| +|0540|Single Element in a Sorted Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0540.Single-Element-in-a-Sorted-Array)|58.5%|Medium|| +|0541|Reverse String II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0541.Reverse-String-II)|50.5%|Easy|| +|0542|01 Matrix|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0542.01-Matrix)|44.1%|Medium|| +|0543|Diameter of Binary Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0543.Diameter-of-Binary-Tree)|55.9%|Easy|| +|0544|Output Contest Matches||76.7%|Medium|| +|0545|Boundary of Binary Tree||44.2%|Medium|| +|0546|Remove Boxes||47.6%|Hard|| +|0547|Number of Provinces|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0547.Number-of-Provinces)|63.2%|Medium|| +|0548|Split Array with Equal Sum||50.1%|Hard|| +|0549|Binary Tree Longest Consecutive Sequence II||49.5%|Medium|| +|0550|Game Play Analysis IV||44.1%|Medium|| +|0551|Student Attendance Record I|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0551.Student-Attendance-Record-I)|48.0%|Easy|| +|0552|Student Attendance Record II||41.1%|Hard|| +|0553|Optimal Division||59.7%|Medium|| +|0554|Brick Wall|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0554.Brick-Wall)|53.1%|Medium|| +|0555|Split Concatenated Strings||43.5%|Medium|| +|0556|Next Greater Element III||34.1%|Medium|| +|0557|Reverse Words in a String III|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0557.Reverse-Words-in-a-String-III)|81.5%|Easy|| +|0558|Logical OR of Two Binary Grids Represented as Quad-Trees||48.2%|Medium|| +|0559|Maximum Depth of N-ary Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0559.Maximum-Depth-of-N-ary-Tree)|71.6%|Easy|| +|0560|Subarray Sum Equals K|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0560.Subarray-Sum-Equals-K)|44.0%|Medium|| +|0561|Array Partition|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0561.Array-Partition)|76.5%|Easy|| +|0562|Longest Line of Consecutive One in Matrix||50.0%|Medium|| +|0563|Binary Tree Tilt|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0563.Binary-Tree-Tilt)|59.3%|Easy|| +|0564|Find the Closest Palindrome||21.9%|Hard|| +|0565|Array Nesting||56.5%|Medium|| +|0566|Reshape the Matrix|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0566.Reshape-the-Matrix)|62.7%|Easy|| +|0567|Permutation in String|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0567.Permutation-in-String)|43.8%|Medium|| +|0568|Maximum Vacation Days||44.8%|Hard|| +|0569|Median Employee Salary||68.3%|Hard|| +|0570|Managers with at Least 5 Direct Reports||67.1%|Medium|| +|0571|Find Median Given Frequency of Numbers||44.7%|Hard|| +|0572|Subtree of Another Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0572.Subtree-of-Another-Tree)|45.9%|Easy|| +|0573|Squirrel Simulation||55.0%|Medium|| +|0574|Winning Candidate||59.7%|Medium|| +|0575|Distribute Candies|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0575.Distribute-Candies)|66.1%|Easy|| +|0576|Out of Boundary Paths|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0576.Out-of-Boundary-Paths)|44.3%|Medium|| +|0577|Employee Bonus||75.3%|Easy|| +|0578|Get Highest Answer Rate Question||41.7%|Medium|| +|0579|Find Cumulative Salary of an Employee||45.0%|Hard|| +|0580|Count Student Number in Departments||58.2%|Medium|| +|0581|Shortest Unsorted Continuous Subarray|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0581.Shortest-Unsorted-Continuous-Subarray)|36.2%|Medium|| +|0582|Kill Process||68.4%|Medium|| +|0583|Delete Operation for Two Strings|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0583.Delete-Operation-for-Two-Strings)|59.2%|Medium|| +|0584|Find Customer Referee||76.0%|Easy|| +|0585|Investments in 2016||53.5%|Medium|| +|0586|Customer Placing the Largest Number of Orders||72.5%|Easy|| +|0587|Erect the Fence||43.2%|Hard|| +|0588|Design In-Memory File System||48.8%|Hard|| +|0589|N-ary Tree Preorder Traversal|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0589.N-ary-Tree-Preorder-Traversal)|76.3%|Easy|| +|0590|N-ary Tree Postorder Traversal||77.1%|Easy|| +|0591|Tag Validator||37.0%|Hard|| +|0592|Fraction Addition and Subtraction||52.1%|Medium|| +|0593|Valid Square||44.1%|Medium|| +|0594|Longest Harmonious Subsequence|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0594.Longest-Harmonious-Subsequence)|53.1%|Easy|| +|0595|Big Countries||73.8%|Easy|| +|0596|Classes More Than 5 Students||46.5%|Easy|| +|0597|Friend Requests I: Overall Acceptance Rate||42.9%|Easy|| +|0598|Range Addition II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0598.Range-Addition-II)|55.0%|Easy|| +|0599|Minimum Index Sum of Two Lists|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0599.Minimum-Index-Sum-of-Two-Lists)|52.7%|Easy|| +|0600|Non-negative Integers without Consecutive Ones||39.0%|Hard|| +|0601|Human Traffic of Stadium||50.6%|Hard|| +|0602|Friend Requests II: Who Has the Most Friends||61.3%|Medium|| +|0603|Consecutive Available Seats||68.2%|Easy|| +|0604|Design Compressed String Iterator||39.4%|Easy|| +|0605|Can Place Flowers|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0605.Can-Place-Flowers)|33.0%|Easy|| +|0606|Construct String from Binary Tree||63.5%|Easy|| +|0607|Sales Person||72.1%|Easy|| +|0608|Tree Node||74.9%|Medium|| +|0609|Find Duplicate File in System|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0609.Find-Duplicate-File-in-System)|67.8%|Medium|| +|0610|Triangle Judgement||71.1%|Easy|| +|0611|Valid Triangle Number|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0611.Valid-Triangle-Number)|50.3%|Medium|| +|0612|Shortest Distance in a Plane||63.5%|Medium|| +|0613|Shortest Distance in a Line||81.5%|Easy|| +|0614|Second Degree Follower||36.9%|Medium|| +|0615|Average Salary: Departments VS Company||57.3%|Hard|| +|0616|Add Bold Tag in String||48.6%|Medium|| +|0617|Merge Two Binary Trees|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0617.Merge-Two-Binary-Trees)|78.5%|Easy|| +|0618|Students Report By Geography||64.2%|Hard|| +|0619|Biggest Single Number||48.7%|Easy|| +|0620|Not Boring Movies||73.3%|Easy|| +|0621|Task Scheduler||55.6%|Medium|| +|0622|Design Circular Queue|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0622.Design-Circular-Queue)|51.8%|Medium|| +|0623|Add One Row to Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0623.Add-One-Row-to-Tree)|59.4%|Medium|| +|0624|Maximum Distance in Arrays||41.7%|Medium|| +|0625|Minimum Factorization||33.4%|Medium|| +|0626|Exchange Seats||70.6%|Medium|| +|0627|Swap Salary||82.8%|Easy|| +|0628|Maximum Product of Three Numbers|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0628.Maximum-Product-of-Three-Numbers)|46.4%|Easy|| +|0629|K Inverse Pairs Array||43.0%|Hard|| +|0630|Course Schedule III|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0630.Course-Schedule-III)|40.2%|Hard|| +|0631|Design Excel Sum Formula||43.3%|Hard|| +|0632|Smallest Range Covering Elements from K Lists|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0632.Smallest-Range-Covering-Elements-from-K-Lists)|60.4%|Hard|| +|0633|Sum of Square Numbers|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0633.Sum-of-Square-Numbers)|34.7%|Medium|| +|0634|Find the Derangement of An Array||41.8%|Medium|| +|0635|Design Log Storage System||62.7%|Medium|| +|0636|Exclusive Time of Functions|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0636.Exclusive-Time-of-Functions)|61.0%|Medium|| +|0637|Average of Levels in Binary Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0637.Average-of-Levels-in-Binary-Tree)|71.6%|Easy|| +|0638|Shopping Offers|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0638.Shopping-Offers)|54.3%|Medium|| +|0639|Decode Ways II||30.4%|Hard|| +|0640|Solve the Equation||43.3%|Medium|| +|0641|Design Circular Deque||57.6%|Medium|| +|0642|Design Search Autocomplete System||48.7%|Hard|| +|0643|Maximum Average Subarray I|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0643.Maximum-Average-Subarray-I)|43.8%|Easy|| +|0644|Maximum Average Subarray II||35.7%|Hard|| +|0645|Set Mismatch|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0645.Set-Mismatch)|41.4%|Easy|| +|0646|Maximum Length of Pair Chain||56.4%|Medium|| +|0647|Palindromic Substrings|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0647.Palindromic-Substrings)|66.3%|Medium|| +|0648|Replace Words|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0648.Replace-Words)|62.7%|Medium|| +|0649|Dota2 Senate||40.4%|Medium|| +|0650|2 Keys Keyboard||53.1%|Medium|| +|0651|4 Keys Keyboard||54.5%|Medium|| +|0652|Find Duplicate Subtrees||56.5%|Medium|| +|0653|Two Sum IV - Input is a BST|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0653.Two-Sum-IV-Input-is-a-BST)|60.9%|Easy|| +|0654|Maximum Binary Tree||84.4%|Medium|| +|0655|Print Binary Tree||61.3%|Medium|| +|0656|Coin Path||31.6%|Hard|| +|0657|Robot Return to Origin||75.3%|Easy|| +|0658|Find K Closest Elements|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0658.Find-K-Closest-Elements)|46.7%|Medium|| +|0659|Split Array into Consecutive Subsequences||50.6%|Medium|| +|0660|Remove 9||56.8%|Hard|| +|0661|Image Smoother|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0661.Image-Smoother)|55.0%|Easy|| +|0662|Maximum Width of Binary Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0662.Maximum-Width-of-Binary-Tree)|40.6%|Medium|| +|0663|Equal Tree Partition||41.4%|Medium|| +|0664|Strange Printer||46.8%|Hard|| +|0665|Non-decreasing Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0665.Non-decreasing-Array)|24.1%|Medium|| +|0666|Path Sum IV||59.1%|Medium|| +|0667|Beautiful Arrangement II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0667.Beautiful-Arrangement-II)|59.7%|Medium|| +|0668|Kth Smallest Number in Multiplication Table|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0668.Kth-Smallest-Number-in-Multiplication-Table)|51.5%|Hard|| +|0669|Trim a Binary Search Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0669.Trim-a-Binary-Search-Tree)|66.3%|Medium|| +|0670|Maximum Swap||47.8%|Medium|| +|0671|Second Minimum Node In a Binary Tree||44.0%|Easy|| +|0672|Bulb Switcher II||50.9%|Medium|| +|0673|Number of Longest Increasing Subsequence||42.1%|Medium|| +|0674|Longest Continuous Increasing Subsequence|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0674.Longest-Continuous-Increasing-Subsequence)|49.0%|Easy|| +|0675|Cut Off Trees for Golf Event||34.3%|Hard|| +|0676|Implement Magic Dictionary|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0676.Implement-Magic-Dictionary)|56.9%|Medium|| +|0677|Map Sum Pairs|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0677.Map-Sum-Pairs)|57.0%|Medium|| +|0678|Valid Parenthesis String||33.9%|Medium|| +|0679|24 Game||49.1%|Hard|| +|0680|Valid Palindrome II||39.3%|Easy|| +|0681|Next Closest Time||46.4%|Medium|| +|0682|Baseball Game|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0682.Baseball-Game)|73.6%|Easy|| +|0683|K Empty Slots||36.9%|Hard|| +|0684|Redundant Connection|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0684.Redundant-Connection)|62.0%|Medium|| +|0685|Redundant Connection II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0685.Redundant-Connection-II)|34.1%|Hard|| +|0686|Repeated String Match||34.0%|Medium|| +|0687|Longest Univalue Path||40.1%|Medium|| +|0688|Knight Probability in Chessboard||52.0%|Medium|| +|0689|Maximum Sum of 3 Non-Overlapping Subarrays||48.8%|Hard|| +|0690|Employee Importance|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0690.Employee-Importance)|65.1%|Medium|| +|0691|Stickers to Spell Word||46.3%|Hard|| +|0692|Top K Frequent Words|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0692.Top-K-Frequent-Words)|55.2%|Medium|| +|0693|Binary Number with Alternating Bits|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0693.Binary-Number-with-Alternating-Bits)|61.2%|Easy|| +|0694|Number of Distinct Islands||60.6%|Medium|| +|0695|Max Area of Island|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0695.Max-Area-of-Island)|71.6%|Medium|| +|0696|Count Binary Substrings|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0696.Count-Binary-Substrings)|65.5%|Easy|| +|0697|Degree of an Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0697.Degree-of-an-Array)|55.8%|Easy|| +|0698|Partition to K Equal Sum Subsets||41.1%|Medium|| +|0699|Falling Squares|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0699.Falling-Squares)|44.4%|Hard|| +|0700|Search in a Binary Search Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0700.Search-in-a-Binary-Search-Tree)|77.1%|Easy|| +|0701|Insert into a Binary Search Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0701.Insert-into-a-Binary-Search-Tree)|74.6%|Medium|| +|0702|Search in a Sorted Array of Unknown Size||71.4%|Medium|| +|0703|Kth Largest Element in a Stream|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0703.Kth-Largest-Element-in-a-Stream)|55.5%|Easy|| +|0704|Binary Search|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0704.Binary-Search)|55.1%|Easy|| +|0705|Design HashSet|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0705.Design-HashSet)|66.0%|Easy|| +|0706|Design HashMap|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0706.Design-HashMap)|65.1%|Easy|| +|0707|Design Linked List|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0707.Design-Linked-List)|27.5%|Medium|| +|0708|Insert into a Sorted Circular Linked List||34.5%|Medium|| +|0709|To Lower Case|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0709.To-Lower-Case)|81.9%|Easy|| +|0710|Random Pick with Blacklist|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0710.Random-Pick-with-Blacklist)|33.6%|Hard|| +|0711|Number of Distinct Islands II||51.8%|Hard|| +|0712|Minimum ASCII Delete Sum for Two Strings||62.2%|Medium|| +|0713|Subarray Product Less Than K|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0713.Subarray-Product-Less-Than-K)|45.0%|Medium|| +|0714|Best Time to Buy and Sell Stock with Transaction Fee|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0714.Best-Time-to-Buy-and-Sell-Stock-with-Transaction-Fee)|64.2%|Medium|| +|0715|Range Module|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0715.Range-Module)|44.6%|Hard|| +|0716|Max Stack||45.3%|Hard|| +|0717|1-bit and 2-bit Characters|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0717.1-bit-and-2-bit-Characters)|46.0%|Easy|| +|0718|Maximum Length of Repeated Subarray|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0718.Maximum-Length-of-Repeated-Subarray)|51.6%|Medium|| +|0719|Find K-th Smallest Pair Distance|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0719.Find-K-th-Smallest-Pair-Distance)|36.3%|Hard|| +|0720|Longest Word in Dictionary|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0720.Longest-Word-in-Dictionary)|51.8%|Medium|| +|0721|Accounts Merge|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0721.Accounts-Merge)|56.3%|Medium|| +|0722|Remove Comments||38.0%|Medium|| +|0723|Candy Crush||76.3%|Medium|| +|0724|Find Pivot Index|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0724.Find-Pivot-Index)|53.3%|Easy|| +|0725|Split Linked List in Parts|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0725.Split-Linked-List-in-Parts)|57.2%|Medium|| +|0726|Number of Atoms|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0726.Number-of-Atoms)|52.2%|Hard|| +|0727|Minimum Window Subsequence||42.8%|Hard|| +|0728|Self Dividing Numbers|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0728.Self-Dividing-Numbers)|77.5%|Easy|| +|0729|My Calendar I|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0729.My-Calendar-I)|57.2%|Medium|| +|0730|Count Different Palindromic Subsequences||44.4%|Hard|| +|0731|My Calendar II||54.7%|Medium|| +|0732|My Calendar III|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0732.My-Calendar-III)|71.6%|Hard|| +|0733|Flood Fill|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0733.Flood-Fill)|60.3%|Easy|| +|0734|Sentence Similarity||43.1%|Easy|| +|0735|Asteroid Collision|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0735.Asteroid-Collision)|44.4%|Medium|| +|0736|Parse Lisp Expression||51.6%|Hard|| +|0737|Sentence Similarity II||48.7%|Medium|| +|0738|Monotone Increasing Digits||47.0%|Medium|| +|0739|Daily Temperatures|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0739.Daily-Temperatures)|66.5%|Medium|| +|0740|Delete and Earn||57.4%|Medium|| +|0741|Cherry Pickup||36.3%|Hard|| +|0742|Closest Leaf in a Binary Tree||45.8%|Medium|| +|0743|Network Delay Time||51.4%|Medium|| +|0744|Find Smallest Letter Greater Than Target|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0744.Find-Smallest-Letter-Greater-Than-Target)|44.6%|Easy|| +|0745|Prefix and Suffix Search|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0745.Prefix-and-Suffix-Search)|41.3%|Hard|| +|0746|Min Cost Climbing Stairs|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0746.Min-Cost-Climbing-Stairs)|62.3%|Easy|| +|0747|Largest Number At Least Twice of Others|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0747.Largest-Number-At-Least-Twice-of-Others)|46.3%|Easy|| +|0748|Shortest Completing Word|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0748.Shortest-Completing-Word)|59.1%|Easy|| +|0749|Contain Virus||50.8%|Hard|| +|0750|Number Of Corner Rectangles||67.5%|Medium|| +|0751|IP to CIDR||54.7%|Medium|| +|0752|Open the Lock|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0752.Open-the-Lock)|55.5%|Medium|| +|0753|Cracking the Safe|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0753.Cracking-the-Safe)|55.4%|Hard|| +|0754|Reach a Number||42.5%|Medium|| +|0755|Pour Water||46.1%|Medium|| +|0756|Pyramid Transition Matrix|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0756.Pyramid-Transition-Matrix)|53.3%|Medium|| +|0757|Set Intersection Size At Least Two||43.8%|Hard|| +|0758|Bold Words in String||50.6%|Medium|| +|0759|Employee Free Time||71.7%|Hard|| +|0760|Find Anagram Mappings||82.8%|Easy|| +|0761|Special Binary String||60.3%|Hard|| +|0762|Prime Number of Set Bits in Binary Representation|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0762.Prime-Number-of-Set-Bits-in-Binary-Representation)|67.6%|Easy|| +|0763|Partition Labels|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0763.Partition-Labels)|79.8%|Medium|| +|0764|Largest Plus Sign||48.4%|Medium|| +|0765|Couples Holding Hands|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0765.Couples-Holding-Hands)|56.9%|Hard|| +|0766|Toeplitz Matrix|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0766.Toeplitz-Matrix)|68.1%|Easy|| +|0767|Reorganize String|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0767.Reorganize-String)|52.7%|Medium|| +|0768|Max Chunks To Make Sorted II||52.7%|Hard|| +|0769|Max Chunks To Make Sorted||58.2%|Medium|| +|0770|Basic Calculator IV||56.0%|Hard|| +|0771|Jewels and Stones|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0771.Jewels-and-Stones)|88.0%|Easy|| +|0772|Basic Calculator III||48.4%|Hard|| +|0773|Sliding Puzzle||63.7%|Hard|| +|0774|Minimize Max Distance to Gas Station||51.4%|Hard|| +|0775|Global and Local Inversions|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0775.Global-and-Local-Inversions)|43.8%|Medium|| +|0776|Split BST||58.7%|Medium|| +|0777|Swap Adjacent in LR String||37.1%|Medium|| +|0778|Swim in Rising Water|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0778.Swim-in-Rising-Water)|59.6%|Hard|| +|0779|K-th Symbol in Grammar||40.7%|Medium|| +|0780|Reaching Points||32.3%|Hard|| +|0781|Rabbits in Forest|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0781.Rabbits-in-Forest)|55.3%|Medium|| +|0782|Transform to Chessboard||51.9%|Hard|| +|0783|Minimum Distance Between BST Nodes|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0783.Minimum-Distance-Between-BST-Nodes)|56.8%|Easy|| +|0784|Letter Case Permutation|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0784.Letter-Case-Permutation)|73.4%|Medium|| +|0785|Is Graph Bipartite?|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0785.Is-Graph-Bipartite)|52.6%|Medium|| +|0786|K-th Smallest Prime Fraction|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0786.K-th-Smallest-Prime-Fraction)|50.6%|Medium|| +|0787|Cheapest Flights Within K Stops||35.9%|Medium|| +|0788|Rotated Digits||56.9%|Medium|| +|0789|Escape The Ghosts||60.6%|Medium|| +|0790|Domino and Tromino Tiling||48.4%|Medium|| +|0791|Custom Sort String|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0791.Custom-Sort-String)|69.4%|Medium|| +|0792|Number of Matching Subsequences|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0792.Number-of-Matching-Subsequences)|51.9%|Medium|| +|0793|Preimage Size of Factorial Zeroes Function|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0793.Preimage-Size-of-Factorial-Zeroes-Function)|42.7%|Hard|| +|0794|Valid Tic-Tac-Toe State|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0794.Valid-Tic-Tac-Toe-State)|35.2%|Medium|| +|0795|Number of Subarrays with Bounded Maximum|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0795.Number-of-Subarrays-with-Bounded-Maximum)|52.7%|Medium|| +|0796|Rotate String||54.0%|Easy|| +|0797|All Paths From Source to Target||81.4%|Medium|| +|0798|Smallest Rotation with Highest Score||49.6%|Hard|| +|0799|Champagne Tower||51.2%|Medium|| +|0800|Similar RGB Color||66.4%|Easy|| +|0801|Minimum Swaps To Make Sequences Increasing||39.2%|Hard|| +|0802|Find Eventual Safe States|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0802.Find-Eventual-Safe-States)|54.9%|Medium|| +|0803|Bricks Falling When Hit|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0803.Bricks-Falling-When-Hit)|34.3%|Hard|| +|0804|Unique Morse Code Words||82.6%|Easy|| +|0805|Split Array With Same Average||25.9%|Hard|| +|0806|Number of Lines To Write String||66.1%|Easy|| +|0807|Max Increase to Keep City Skyline|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0807.Max-Increase-to-Keep-City-Skyline)|85.9%|Medium|| +|0808|Soup Servings||43.1%|Medium|| +|0809|Expressive Words||46.3%|Medium|| +|0810|Chalkboard XOR Game|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0810.Chalkboard-XOR-Game)|55.1%|Hard|| +|0811|Subdomain Visit Count|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0811.Subdomain-Visit-Count)|75.1%|Medium|| +|0812|Largest Triangle Area|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0812.Largest-Triangle-Area)|60.1%|Easy|| +|0813|Largest Sum of Averages||52.9%|Medium|| +|0814|Binary Tree Pruning||72.6%|Medium|| +|0815|Bus Routes|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0815.Bus-Routes)|45.7%|Hard|| +|0816|Ambiguous Coordinates|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0816.Ambiguous-Coordinates)|56.0%|Medium|| +|0817|Linked List Components|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0817.Linked-List-Components)|58.1%|Medium|| +|0818|Race Car||43.6%|Hard|| +|0819|Most Common Word|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0819.Most-Common-Word)|45.0%|Easy|| +|0820|Short Encoding of Words|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0820.Short-Encoding-of-Words)|60.7%|Medium|| +|0821|Shortest Distance to a Character|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0821.Shortest-Distance-to-a-Character)|71.3%|Easy|| +|0822|Card Flipping Game||45.4%|Medium|| +|0823|Binary Trees With Factors|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0823.Binary-Trees-With-Factors)|50.0%|Medium|| +|0824|Goat Latin||67.8%|Easy|| +|0825|Friends Of Appropriate Ages|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0825.Friends-Of-Appropriate-Ages)|46.3%|Medium|| +|0826|Most Profit Assigning Work|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0826.Most-Profit-Assigning-Work)|44.3%|Medium|| +|0827|Making A Large Island||44.7%|Hard|| +|0828|Count Unique Characters of All Substrings of a Given String|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0828.Count-Unique-Characters-of-All-Substrings-of-a-Given-String)|51.5%|Hard|| +|0829|Consecutive Numbers Sum||41.5%|Hard|| +|0830|Positions of Large Groups|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0830.Positions-of-Large-Groups)|51.7%|Easy|| +|0831|Masking Personal Information||46.8%|Medium|| +|0832|Flipping an Image|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0832.Flipping-an-Image)|80.3%|Easy|| +|0833|Find And Replace in String||54.1%|Medium|| +|0834|Sum of Distances in Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0834.Sum-of-Distances-in-Tree)|54.1%|Hard|| +|0835|Image Overlap||61.0%|Medium|| +|0836|Rectangle Overlap|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0836.Rectangle-Overlap)|43.3%|Easy|| +|0837|New 21 Game||36.2%|Medium|| +|0838|Push Dominoes|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0838.Push-Dominoes)|57.0%|Medium|| +|0839|Similar String Groups|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0839.Similar-String-Groups)|47.5%|Hard|| +|0840|Magic Squares In Grid||38.5%|Medium|| +|0841|Keys and Rooms|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0841.Keys-and-Rooms)|70.1%|Medium|| +|0842|Split Array into Fibonacci Sequence|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0842.Split-Array-into-Fibonacci-Sequence)|38.2%|Medium|| +|0843|Guess the Word||42.0%|Hard|| +|0844|Backspace String Compare|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0844.Backspace-String-Compare)|48.0%|Easy|| +|0845|Longest Mountain in Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0845.Longest-Mountain-in-Array)|40.1%|Medium|| +|0846|Hand of Straights|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0846.Hand-of-Straights)|56.5%|Medium|| +|0847|Shortest Path Visiting All Nodes||61.3%|Hard|| +|0848|Shifting Letters||45.4%|Medium|| +|0849|Maximize Distance to Closest Person||47.6%|Medium|| +|0850|Rectangle Area II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0850.Rectangle-Area-II)|53.7%|Hard|| +|0851|Loud and Rich|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0851.Loud-and-Rich)|58.1%|Medium|| +|0852|Peak Index in a Mountain Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0852.Peak-Index-in-a-Mountain-Array)|69.5%|Medium|| +|0853|Car Fleet|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0853.Car-Fleet)|50.0%|Medium|| +|0854|K-Similar Strings||40.0%|Hard|| |0855|Exam Room||43.5%|Medium|| -|0856|Score of Parentheses|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0856.Score-of-Parentheses)|64.9%|Medium|| -|0857|Minimum Cost to Hire K Workers||50.6%|Hard|| -|0858|Mirror Reflection||59.6%|Medium|| -|0859|Buddy Strings||29.0%|Easy|| -|0860|Lemonade Change||51.9%|Easy|| -|0861|Score After Flipping Matrix||73.8%|Medium|| -|0862|Shortest Subarray with Sum at Least K|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0862.Shortest-Subarray-with-Sum-at-Least-K)|25.3%|Hard|| -|0863|All Nodes Distance K in Binary Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0863.All-Nodes-Distance-K-in-Binary-Tree)|58.3%|Medium|| -|0864|Shortest Path to Get All Keys|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0864.Shortest-Path-to-Get-All-Keys)|42.5%|Hard|| -|0865|Smallest Subtree with all the Deepest Nodes||65.2%|Medium|| -|0866|Prime Palindrome||25.0%|Medium|| -|0867|Transpose Matrix|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0867.Transpose-Matrix)|61.9%|Easy|| -|0868|Binary Gap||61.0%|Easy|| -|0869|Reordered Power of 2|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0869.Reordered-Power-of-2)|61.2%|Medium|| -|0870|Advantage Shuffle|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0870.Advantage-Shuffle)|50.8%|Medium|| -|0871|Minimum Number of Refueling Stops||32.5%|Hard|| -|0872|Leaf-Similar Trees|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0872.Leaf-Similar-Trees)|64.5%|Easy|| -|0873|Length of Longest Fibonacci Subsequence||48.2%|Medium|| -|0874|Walking Robot Simulation||36.7%|Easy|| -|0875|Koko Eating Bananas|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0875.Koko-Eating-Bananas)|53.5%|Medium|| -|0876|Middle of the Linked List|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0876.Middle-of-the-Linked-List)|69.3%|Easy|| -|0877|Stone Game||67.2%|Medium|| -|0878|Nth Magical Number|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0878.Nth-Magical-Number)|28.9%|Hard|| -|0879|Profitable Schemes||40.0%|Hard|| -|0880|Decoded String at Index|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0880.Decoded-String-at-Index)|28.2%|Medium|| -|0881|Boats to Save People|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0881.Boats-to-Save-People)|49.1%|Medium|| -|0882|Reachable Nodes In Subdivided Graph||43.2%|Hard|| -|0883|Projection Area of 3D Shapes||68.5%|Easy|| -|0884|Uncommon Words from Two Sentences|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0884.Uncommon-Words-from-Two-Sentences)|64.3%|Easy|| -|0885|Spiral Matrix III|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0885.Spiral-Matrix-III)|71.1%|Medium|| -|0886|Possible Bipartition||45.4%|Medium|| -|0887|Super Egg Drop|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0887.Super-Egg-Drop)|27.0%|Hard|| -|0888|Fair Candy Swap|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0888.Fair-Candy-Swap)|59.2%|Easy|| -|0889|Construct Binary Tree from Preorder and Postorder Traversal||68.0%|Medium|| -|0890|Find and Replace Pattern||74.2%|Medium|| -|0891|Sum of Subsequence Widths|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0891.Sum-of-Subsequence-Widths)|33.2%|Hard|| -|0892|Surface Area of 3D Shapes|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0892.Surface-Area-of-3D-Shapes)|60.0%|Easy|| -|0893|Groups of Special-Equivalent Strings||69.7%|Easy|| -|0894|All Possible Full Binary Trees||77.5%|Medium|| -|0895|Maximum Frequency Stack|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0895.Maximum-Frequency-Stack)|63.3%|Hard|| -|0896|Monotonic Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0896.Monotonic-Array)|57.9%|Easy|| -|0897|Increasing Order Search Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0897.Increasing-Order-Search-Tree)|74.7%|Easy|| -|0898|Bitwise ORs of Subarrays|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0898.Bitwise-ORs-of-Subarrays)|34.5%|Medium|| -|0899|Orderly Queue||53.4%|Hard|| -|0900|RLE Iterator||55.8%|Medium|| -|0901|Online Stock Span|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0901.Online-Stock-Span)|61.5%|Medium|| -|0902|Numbers At Most N Given Digit Set||36.1%|Hard|| -|0903|Valid Permutations for DI Sequence||54.4%|Hard|| -|0904|Fruit Into Baskets|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0904.Fruit-Into-Baskets)|43.0%|Medium|| -|0905|Sort Array By Parity||75.0%|Easy|| -|0906|Super Palindromes||32.7%|Hard|| -|0907|Sum of Subarray Minimums|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0907.Sum-of-Subarray-Minimums)|33.1%|Medium|| -|0908|Smallest Range I||66.4%|Easy|| -|0909|Snakes and Ladders||39.3%|Medium|| -|0910|Smallest Range II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0910.Smallest-Range-II)|31.2%|Medium|| -|0911|Online Election|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0911.Online-Election)|51.5%|Medium|| -|0912|Sort an Array||64.5%|Medium|| -|0913|Cat and Mouse||34.9%|Hard|| -|0914|X of a Kind in a Deck of Cards|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0914.X-of-a-Kind-in-a-Deck-of-Cards)|33.9%|Easy|| -|0915|Partition Array into Disjoint Intervals||46.5%|Medium|| -|0916|Word Subsets|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0916.Word-Subsets)|52.8%|Medium|| -|0917|Reverse Only Letters||59.5%|Easy|| -|0918|Maximum Sum Circular Subarray|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0918.Maximum-Sum-Circular-Subarray)|34.4%|Medium|| -|0919|Complete Binary Tree Inserter||59.2%|Medium|| -|0920|Number of Music Playlists|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0920.Number-of-Music-Playlists)|48.2%|Hard|| -|0921|Minimum Add to Make Parentheses Valid|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0921.Minimum-Add-to-Make-Parentheses-Valid)|75.0%|Medium|| +|0856|Score of Parentheses|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0856.Score-of-Parentheses)|65.1%|Medium|| +|0857|Minimum Cost to Hire K Workers||52.0%|Hard|| +|0858|Mirror Reflection||63.3%|Medium|| +|0859|Buddy Strings|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0859.Buddy-Strings)|29.0%|Easy|| +|0860|Lemonade Change||52.8%|Easy|| +|0861|Score After Flipping Matrix||75.1%|Medium|| +|0862|Shortest Subarray with Sum at Least K|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0862.Shortest-Subarray-with-Sum-at-Least-K)|26.1%|Hard|| +|0863|All Nodes Distance K in Binary Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0863.All-Nodes-Distance-K-in-Binary-Tree)|62.1%|Medium|| +|0864|Shortest Path to Get All Keys|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0864.Shortest-Path-to-Get-All-Keys)|45.3%|Hard|| +|0865|Smallest Subtree with all the Deepest Nodes||68.5%|Medium|| +|0866|Prime Palindrome||25.8%|Medium|| +|0867|Transpose Matrix|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0867.Transpose-Matrix)|63.4%|Easy|| +|0868|Binary Gap||61.9%|Easy|| +|0869|Reordered Power of 2|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0869.Reordered-Power-of-2)|64.1%|Medium|| +|0870|Advantage Shuffle|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0870.Advantage-Shuffle)|51.6%|Medium|| +|0871|Minimum Number of Refueling Stops||39.9%|Hard|| +|0872|Leaf-Similar Trees|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0872.Leaf-Similar-Trees)|65.2%|Easy|| +|0873|Length of Longest Fibonacci Subsequence||48.6%|Medium|| +|0874|Walking Robot Simulation|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0874.Walking-Robot-Simulation)|38.3%|Medium|| +|0875|Koko Eating Bananas|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0875.Koko-Eating-Bananas)|52.4%|Medium|| +|0876|Middle of the Linked List|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0876.Middle-of-the-Linked-List)|73.7%|Easy|| +|0877|Stone Game|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0877.Stone-Game)|69.7%|Medium|| +|0878|Nth Magical Number|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0878.Nth-Magical-Number)|35.7%|Hard|| +|0879|Profitable Schemes||40.5%|Hard|| +|0880|Decoded String at Index|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0880.Decoded-String-at-Index)|28.3%|Medium|| +|0881|Boats to Save People|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0881.Boats-to-Save-People)|52.7%|Medium|| +|0882|Reachable Nodes In Subdivided Graph||50.3%|Hard|| +|0883|Projection Area of 3D Shapes||70.7%|Easy|| +|0884|Uncommon Words from Two Sentences|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0884.Uncommon-Words-from-Two-Sentences)|65.9%|Easy|| +|0885|Spiral Matrix III|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0885.Spiral-Matrix-III)|73.0%|Medium|| +|0886|Possible Bipartition||48.4%|Medium|| +|0887|Super Egg Drop|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0887.Super-Egg-Drop)|27.2%|Hard|| +|0888|Fair Candy Swap|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0888.Fair-Candy-Swap)|60.5%|Easy|| +|0889|Construct Binary Tree from Preorder and Postorder Traversal||70.8%|Medium|| +|0890|Find and Replace Pattern|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0890.Find-and-Replace-Pattern)|77.9%|Medium|| +|0891|Sum of Subsequence Widths|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0891.Sum-of-Subsequence-Widths)|36.4%|Hard|| +|0892|Surface Area of 3D Shapes|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0892.Surface-Area-of-3D-Shapes)|63.0%|Easy|| +|0893|Groups of Special-Equivalent Strings||70.8%|Medium|| +|0894|All Possible Full Binary Trees||80.0%|Medium|| +|0895|Maximum Frequency Stack|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0895.Maximum-Frequency-Stack)|66.8%|Hard|| +|0896|Monotonic Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0896.Monotonic-Array)|58.2%|Easy|| +|0897|Increasing Order Search Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0897.Increasing-Order-Search-Tree)|78.4%|Easy|| +|0898|Bitwise ORs of Subarrays|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0898.Bitwise-ORs-of-Subarrays)|36.8%|Medium|| +|0899|Orderly Queue||59.0%|Hard|| +|0900|RLE Iterator||59.5%|Medium|| +|0901|Online Stock Span|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0901.Online-Stock-Span)|63.9%|Medium|| +|0902|Numbers At Most N Given Digit Set||41.4%|Hard|| +|0903|Valid Permutations for DI Sequence||57.7%|Hard|| +|0904|Fruit Into Baskets|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0904.Fruit-Into-Baskets)|42.6%|Medium|| +|0905|Sort Array By Parity||75.7%|Easy|| +|0906|Super Palindromes||39.2%|Hard|| +|0907|Sum of Subarray Minimums|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0907.Sum-of-Subarray-Minimums)|34.3%|Medium|| +|0908|Smallest Range I||67.6%|Easy|| +|0909|Snakes and Ladders|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0909.Snakes-and-Ladders)|40.8%|Medium|| +|0910|Smallest Range II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0910.Smallest-Range-II)|34.4%|Medium|| +|0911|Online Election|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0911.Online-Election)|52.1%|Medium|| +|0912|Sort an Array||60.0%|Medium|| +|0913|Cat and Mouse||35.3%|Hard|| +|0914|X of a Kind in a Deck of Cards|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0914.X-of-a-Kind-in-a-Deck-of-Cards)|32.2%|Easy|| +|0915|Partition Array into Disjoint Intervals||48.6%|Medium|| +|0916|Word Subsets|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0916.Word-Subsets)|54.1%|Medium|| +|0917|Reverse Only Letters||61.4%|Easy|| +|0918|Maximum Sum Circular Subarray|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0918.Maximum-Sum-Circular-Subarray)|38.1%|Medium|| +|0919|Complete Binary Tree Inserter||64.9%|Medium|| +|0920|Number of Music Playlists|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0920.Number-of-Music-Playlists)|50.6%|Hard|| +|0921|Minimum Add to Make Parentheses Valid|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0921.Minimum-Add-to-Make-Parentheses-Valid)|76.4%|Medium|| |0922|Sort Array By Parity II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0922.Sort-Array-By-Parity-II)|70.7%|Easy|| -|0923|3Sum With Multiplicity|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0923.3Sum-With-Multiplicity)|41.0%|Medium|| -|0924|Minimize Malware Spread|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0924.Minimize-Malware-Spread)|41.9%|Hard|| -|0925|Long Pressed Name|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0925.Long-Pressed-Name)|37.1%|Easy|| -|0926|Flip String to Monotone Increasing||53.4%|Medium|| -|0927|Three Equal Parts|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0927.Three-Equal-Parts)|34.7%|Hard|| -|0928|Minimize Malware Spread II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0928.Minimize-Malware-Spread-II)|41.5%|Hard|| +|0923|3Sum With Multiplicity|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0923.3Sum-With-Multiplicity)|45.4%|Medium|| +|0924|Minimize Malware Spread|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0924.Minimize-Malware-Spread)|42.1%|Hard|| +|0925|Long Pressed Name|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0925.Long-Pressed-Name)|33.8%|Easy|| +|0926|Flip String to Monotone Increasing||59.6%|Medium|| +|0927|Three Equal Parts|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0927.Three-Equal-Parts)|39.6%|Hard|| +|0928|Minimize Malware Spread II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0928.Minimize-Malware-Spread-II)|42.6%|Hard|| |0929|Unique Email Addresses||67.2%|Easy|| -|0930|Binary Subarrays With Sum|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0930.Binary-Subarrays-With-Sum)|44.9%|Medium|| -|0931|Minimum Falling Path Sum||63.9%|Medium|| -|0932|Beautiful Array||61.4%|Medium|| -|0933|Number of Recent Calls|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0933.Number-of-Recent-Calls)|72.4%|Easy|| -|0934|Shortest Bridge||50.0%|Medium|| -|0935|Knight Dialer||46.8%|Medium|| -|0936|Stamping The Sequence||53.3%|Hard|| -|0937|Reorder Data in Log Files||54.9%|Easy|| -|0938|Range Sum of BST|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0938.Range-Sum-of-BST)|83.3%|Easy|| -|0939|Minimum Area Rectangle||52.3%|Medium|| -|0940|Distinct Subsequences II||41.5%|Hard|| -|0941|Valid Mountain Array||33.0%|Easy|| -|0942|DI String Match|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0942.DI-String-Match)|73.8%|Easy|| -|0943|Find the Shortest Superstring||43.4%|Hard|| -|0944|Delete Columns to Make Sorted||70.8%|Easy|| -|0945|Minimum Increment to Make Array Unique||46.9%|Medium|| -|0946|Validate Stack Sequences|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0946.Validate-Stack-Sequences)|64.5%|Medium|| -|0947|Most Stones Removed with Same Row or Column|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0947.Most-Stones-Removed-with-Same-Row-or-Column)|55.7%|Medium|| -|0948|Bag of Tokens||46.1%|Medium|| -|0949|Largest Time for Given Digits|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0949.Largest-Time-for-Given-Digits)|36.2%|Medium|| -|0950|Reveal Cards In Increasing Order||75.6%|Medium|| -|0951|Flip Equivalent Binary Trees||65.8%|Medium|| -|0952|Largest Component Size by Common Factor|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0952.Largest-Component-Size-by-Common-Factor)|36.5%|Hard|| -|0953|Verifying an Alien Dictionary|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0953.Verifying-an-Alien-Dictionary)|52.5%|Easy|| -|0954|Array of Doubled Pairs||35.1%|Medium|| -|0955|Delete Columns to Make Sorted II||33.9%|Medium|| -|0956|Tallest Billboard||39.9%|Hard|| -|0957|Prison Cells After N Days||40.1%|Medium|| -|0958|Check Completeness of a Binary Tree||52.5%|Medium|| -|0959|Regions Cut By Slashes|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0959.Regions-Cut-By-Slashes)|67.2%|Medium|| -|0960|Delete Columns to Make Sorted III||55.2%|Hard|| -|0961|N-Repeated Element in Size 2N Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0961.N-Repeated-Element-in-Size-2N-Array)|74.7%|Easy|| -|0962|Maximum Width Ramp||46.7%|Medium|| -|0963|Minimum Area Rectangle II||52.3%|Medium|| -|0964|Least Operators to Express Number||45.3%|Hard|| -|0965|Univalued Binary Tree||68.0%|Easy|| -|0966|Vowel Spellchecker|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0966.Vowel-Spellchecker)|51.9%|Medium|| -|0967|Numbers With Same Consecutive Differences||45.3%|Medium|| -|0968|Binary Tree Cameras|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0968.Binary-Tree-Cameras)|39.0%|Hard|| -|0969|Pancake Sorting|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0969.Pancake-Sorting)|68.8%|Medium|| -|0970|Powerful Integers|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0970.Powerful-Integers)|40.1%|Medium|| -|0971|Flip Binary Tree To Match Preorder Traversal|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0971.Flip-Binary-Tree-To-Match-Preorder-Traversal)|50.1%|Medium|| -|0972|Equal Rational Numbers||42.0%|Hard|| -|0973|K Closest Points to Origin|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0973.K-Closest-Points-to-Origin)|64.7%|Medium|| -|0974|Subarray Sums Divisible by K||51.1%|Medium|| -|0975|Odd Even Jump||41.4%|Hard|| -|0976|Largest Perimeter Triangle|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0976.Largest-Perimeter-Triangle)|59.4%|Easy|| -|0977|Squares of a Sorted Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0977.Squares-of-a-Sorted-Array)|71.8%|Easy|| -|0978|Longest Turbulent Subarray|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0978.Longest-Turbulent-Subarray)|46.7%|Medium|| -|0979|Distribute Coins in Binary Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0979.Distribute-Coins-in-Binary-Tree)|70.0%|Medium|| -|0980|Unique Paths III|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0980.Unique-Paths-III)|77.1%|Hard|| -|0981|Time Based Key-Value Store|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0981.Time-Based-Key-Value-Store)|54.3%|Medium|| -|0982|Triples with Bitwise AND Equal To Zero||56.5%|Hard|| -|0983|Minimum Cost For Tickets||62.8%|Medium|| -|0984|String Without AAA or BBB|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0984.String-Without-AAA-or-BBB)|38.8%|Medium|| -|0985|Sum of Even Numbers After Queries|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0985.Sum-of-Even-Numbers-After-Queries)|60.6%|Easy|| -|0986|Interval List Intersections|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0986.Interval-List-Intersections)|68.6%|Medium|| -|0987|Vertical Order Traversal of a Binary Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0987.Vertical-Order-Traversal-of-a-Binary-Tree)|39.1%|Hard|| -|0988|Smallest String Starting From Leaf||46.9%|Medium|| -|0989|Add to Array-Form of Integer|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0989.Add-to-Array-Form-of-Integer)|44.9%|Easy|| -|0990|Satisfiability of Equality Equations|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0990.Satisfiability-of-Equality-Equations)|47.2%|Medium|| -|0991|Broken Calculator|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0991.Broken-Calculator)|49.7%|Medium|| -|0992|Subarrays with K Different Integers|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0992.Subarrays-with-K-Different-Integers)|50.9%|Hard|| -|0993|Cousins in Binary Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0993.Cousins-in-Binary-Tree)|52.3%|Easy|| -|0994|Rotting Oranges||49.7%|Medium|| -|0995|Minimum Number of K Consecutive Bit Flips|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0995.Minimum-Number-of-K-Consecutive-Bit-Flips)|50.2%|Hard|| -|0996|Number of Squareful Arrays|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0996.Number-of-Squareful-Arrays)|48.6%|Hard|| -|0997|Find the Town Judge||49.8%|Easy|| -|0998|Maximum Binary Tree II||64.2%|Medium|| -|0999|Available Captures for Rook|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0999.Available-Captures-for-Rook)|67.7%|Easy|| -|1000|Minimum Cost to Merge Stones||40.6%|Hard|| -|1001|Grid Illumination||36.1%|Hard|| -|1002|Find Common Characters|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1002.Find-Common-Characters)|68.7%|Easy|| -|1003|Check If Word Is Valid After Substitutions|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1003.Check-If-Word-Is-Valid-After-Substitutions)|56.7%|Medium|| -|1004|Max Consecutive Ones III|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1004.Max-Consecutive-Ones-III)|61.0%|Medium|| -|1005|Maximize Sum Of Array After K Negations|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1005.Maximize-Sum-Of-Array-After-K-Negations)|52.3%|Easy|| -|1006|Clumsy Factorial|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1006.Clumsy-Factorial)|53.7%|Medium|| -|1007|Minimum Domino Rotations For Equal Row||50.9%|Medium|| -|1008|Construct Binary Search Tree from Preorder Traversal||78.8%|Medium|| -|1009|Complement of Base 10 Integer||61.5%|Easy|| -|1010|Pairs of Songs With Total Durations Divisible by 60||50.8%|Medium|| -|1011|Capacity To Ship Packages Within D Days|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1011.Capacity-To-Ship-Packages-Within-D-Days)|60.0%|Medium|| -|1012|Numbers With Repeated Digits||37.9%|Hard|| -|1013|Partition Array Into Three Parts With Equal Sum||47.9%|Easy|| -|1014|Best Sightseeing Pair||53.0%|Medium|| -|1015|Smallest Integer Divisible by K||41.9%|Medium|| -|1016|Binary String With Substrings Representing 1 To N||58.6%|Medium|| -|1017|Convert to Base -2|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1017.Convert-to-Base--2)|59.2%|Medium|| -|1018|Binary Prefix Divisible By 5|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1018.Binary-Prefix-Divisible-By-5)|47.7%|Easy|| -|1019|Next Greater Node In Linked List|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1019.Next-Greater-Node-In-Linked-List)|58.3%|Medium|| -|1020|Number of Enclaves|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1020.Number-of-Enclaves)|59.3%|Medium|| -|1021|Remove Outermost Parentheses|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1021.Remove-Outermost-Parentheses)|79.2%|Easy|| -|1022|Sum of Root To Leaf Binary Numbers||71.7%|Easy|| -|1023|Camelcase Matching||57.7%|Medium|| -|1024|Video Stitching||48.9%|Medium|| -|1025|Divisor Game|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1025.Divisor-Game)|66.1%|Easy|| -|1026|Maximum Difference Between Node and Ancestor|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1026.Maximum-Difference-Between-Node-and-Ancestor)|69.8%|Medium|| -|1027|Longest Arithmetic Subsequence||49.7%|Medium|| -|1028|Recover a Tree From Preorder Traversal|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1028.Recover-a-Tree-From-Preorder-Traversal)|71.1%|Hard|| -|1029|Two City Scheduling||58.3%|Medium|| -|1030|Matrix Cells in Distance Order|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1030.Matrix-Cells-in-Distance-Order)|68.3%|Easy|| -|1031|Maximum Sum of Two Non-Overlapping Subarrays||58.8%|Medium|| -|1032|Stream of Characters||48.6%|Hard|| -|1033|Moving Stones Until Consecutive||43.4%|Easy|| -|1034|Coloring A Border||45.8%|Medium|| -|1035|Uncrossed Lines||56.2%|Medium|| -|1036|Escape a Large Maze||34.3%|Hard|| +|0930|Binary Subarrays With Sum|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0930.Binary-Subarrays-With-Sum)|50.9%|Medium|| +|0931|Minimum Falling Path Sum||68.4%|Medium|| +|0932|Beautiful Array||65.1%|Medium|| +|0933|Number of Recent Calls|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0933.Number-of-Recent-Calls)|73.2%|Easy|| +|0934|Shortest Bridge||53.9%|Medium|| +|0935|Knight Dialer||49.9%|Medium|| +|0936|Stamping The Sequence||63.3%|Hard|| +|0937|Reorder Data in Log Files||56.4%|Medium|| +|0938|Range Sum of BST|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0938.Range-Sum-of-BST)|85.3%|Easy|| +|0939|Minimum Area Rectangle||53.2%|Medium|| +|0940|Distinct Subsequences II||44.4%|Hard|| +|0941|Valid Mountain Array||33.5%|Easy|| +|0942|DI String Match|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0942.DI-String-Match)|76.6%|Easy|| +|0943|Find the Shortest Superstring||45.0%|Hard|| +|0944|Delete Columns to Make Sorted||69.7%|Easy|| +|0945|Minimum Increment to Make Array Unique||49.8%|Medium|| +|0946|Validate Stack Sequences|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0946.Validate-Stack-Sequences)|67.6%|Medium|| +|0947|Most Stones Removed with Same Row or Column|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0947.Most-Stones-Removed-with-Same-Row-or-Column)|57.0%|Medium|| +|0948|Bag of Tokens||52.0%|Medium|| +|0949|Largest Time for Given Digits|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0949.Largest-Time-for-Given-Digits)|35.2%|Medium|| +|0950|Reveal Cards In Increasing Order||77.6%|Medium|| +|0951|Flip Equivalent Binary Trees||66.8%|Medium|| +|0952|Largest Component Size by Common Factor|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0952.Largest-Component-Size-by-Common-Factor)|40.3%|Hard|| +|0953|Verifying an Alien Dictionary|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0953.Verifying-an-Alien-Dictionary)|52.7%|Easy|| +|0954|Array of Doubled Pairs||39.1%|Medium|| +|0955|Delete Columns to Make Sorted II||34.6%|Medium|| +|0956|Tallest Billboard||40.0%|Hard|| +|0957|Prison Cells After N Days||39.2%|Medium|| +|0958|Check Completeness of a Binary Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0958.Check-Completeness-of-a-Binary-Tree)|53.8%|Medium|| +|0959|Regions Cut By Slashes|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0959.Regions-Cut-By-Slashes)|69.1%|Medium|| +|0960|Delete Columns to Make Sorted III||57.1%|Hard|| +|0961|N-Repeated Element in Size 2N Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0961.N-Repeated-Element-in-Size-2N-Array)|75.8%|Easy|| +|0962|Maximum Width Ramp||48.9%|Medium|| +|0963|Minimum Area Rectangle II||54.7%|Medium|| +|0964|Least Operators to Express Number||47.8%|Hard|| +|0965|Univalued Binary Tree||69.2%|Easy|| +|0966|Vowel Spellchecker|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0966.Vowel-Spellchecker)|51.5%|Medium|| +|0967|Numbers With Same Consecutive Differences||57.0%|Medium|| +|0968|Binary Tree Cameras|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0968.Binary-Tree-Cameras)|46.8%|Hard|| +|0969|Pancake Sorting|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0969.Pancake-Sorting)|70.0%|Medium|| +|0970|Powerful Integers|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0970.Powerful-Integers)|43.6%|Medium|| +|0971|Flip Binary Tree To Match Preorder Traversal|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0971.Flip-Binary-Tree-To-Match-Preorder-Traversal)|49.9%|Medium|| +|0972|Equal Rational Numbers||43.0%|Hard|| +|0973|K Closest Points to Origin|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0973.K-Closest-Points-to-Origin)|65.9%|Medium|| +|0974|Subarray Sums Divisible by K||53.6%|Medium|| +|0975|Odd Even Jump||38.9%|Hard|| +|0976|Largest Perimeter Triangle|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0976.Largest-Perimeter-Triangle)|54.8%|Easy|| +|0977|Squares of a Sorted Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0977.Squares-of-a-Sorted-Array)|71.9%|Easy|| +|0978|Longest Turbulent Subarray|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0978.Longest-Turbulent-Subarray)|47.4%|Medium|| +|0979|Distribute Coins in Binary Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0979.Distribute-Coins-in-Binary-Tree)|72.0%|Medium|| +|0980|Unique Paths III|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0980.Unique-Paths-III)|79.6%|Hard|| +|0981|Time Based Key-Value Store|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0981.Time-Based-Key-Value-Store)|53.6%|Medium|| +|0982|Triples with Bitwise AND Equal To Zero||57.6%|Hard|| +|0983|Minimum Cost For Tickets||64.4%|Medium|| +|0984|String Without AAA or BBB|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0984.String-Without-AAA-or-BBB)|42.9%|Medium|| +|0985|Sum of Even Numbers After Queries|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0985.Sum-of-Even-Numbers-After-Queries)|68.3%|Medium|| +|0986|Interval List Intersections|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0986.Interval-List-Intersections)|71.4%|Medium|| +|0987|Vertical Order Traversal of a Binary Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0987.Vertical-Order-Traversal-of-a-Binary-Tree)|44.6%|Hard|| +|0988|Smallest String Starting From Leaf||49.6%|Medium|| +|0989|Add to Array-Form of Integer|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0989.Add-to-Array-Form-of-Integer)|45.5%|Easy|| +|0990|Satisfiability of Equality Equations|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0990.Satisfiability-of-Equality-Equations)|50.7%|Medium|| +|0991|Broken Calculator|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0991.Broken-Calculator)|54.1%|Medium|| +|0992|Subarrays with K Different Integers|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0992.Subarrays-with-K-Different-Integers)|54.3%|Hard|| +|0993|Cousins in Binary Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0993.Cousins-in-Binary-Tree)|54.1%|Easy|| +|0994|Rotting Oranges||52.4%|Medium|| +|0995|Minimum Number of K Consecutive Bit Flips|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0995.Minimum-Number-of-K-Consecutive-Bit-Flips)|51.1%|Hard|| +|0996|Number of Squareful Arrays|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0996.Number-of-Squareful-Arrays)|49.2%|Hard|| +|0997|Find the Town Judge|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0997.Find-the-Town-Judge)|49.4%|Easy|| +|0998|Maximum Binary Tree II||66.3%|Medium|| +|0999|Available Captures for Rook|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0999.Available-Captures-for-Rook)|67.8%|Easy|| +|1000|Minimum Cost to Merge Stones||42.3%|Hard|| +|1001|Grid Illumination||36.2%|Hard|| +|1002|Find Common Characters|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1002.Find-Common-Characters)|68.3%|Easy|| +|1003|Check If Word Is Valid After Substitutions|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1003.Check-If-Word-Is-Valid-After-Substitutions)|58.2%|Medium|| +|1004|Max Consecutive Ones III|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1004.Max-Consecutive-Ones-III)|63.5%|Medium|| +|1005|Maximize Sum Of Array After K Negations|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1005.Maximize-Sum-Of-Array-After-K-Negations)|51.1%|Easy|| +|1006|Clumsy Factorial|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1006.Clumsy-Factorial)|54.7%|Medium|| +|1007|Minimum Domino Rotations For Equal Row||52.4%|Medium|| +|1008|Construct Binary Search Tree from Preorder Traversal||80.9%|Medium|| +|1009|Complement of Base 10 Integer|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1009.Complement-of-Base-10-Integer)|62.0%|Easy|| +|1010|Pairs of Songs With Total Durations Divisible by 60|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1010.Pairs-of-Songs-With-Total-Durations-Divisible-by-60)|53.0%|Medium|| +|1011|Capacity To Ship Packages Within D Days|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1011.Capacity-To-Ship-Packages-Within-D-Days)|64.4%|Medium|| +|1012|Numbers With Repeated Digits||40.4%|Hard|| +|1013|Partition Array Into Three Parts With Equal Sum||43.5%|Easy|| +|1014|Best Sightseeing Pair||59.5%|Medium|| +|1015|Smallest Integer Divisible by K||47.1%|Medium|| +|1016|Binary String With Substrings Representing 1 To N||57.6%|Medium|| +|1017|Convert to Base -2|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1017.Convert-to-Base-2)|60.9%|Medium|| +|1018|Binary Prefix Divisible By 5|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1018.Binary-Prefix-Divisible-By-5)|47.4%|Easy|| +|1019|Next Greater Node In Linked List|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1019.Next-Greater-Node-In-Linked-List)|59.8%|Medium|| +|1020|Number of Enclaves|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1020.Number-of-Enclaves)|64.8%|Medium|| +|1021|Remove Outermost Parentheses|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1021.Remove-Outermost-Parentheses)|80.1%|Easy|| +|1022|Sum of Root To Leaf Binary Numbers|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1022.Sum-of-Root-To-Leaf-Binary-Numbers)|73.8%|Easy|| +|1023|Camelcase Matching||60.1%|Medium|| +|1024|Video Stitching||50.5%|Medium|| +|1025|Divisor Game|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1025.Divisor-Game)|67.1%|Easy|| +|1026|Maximum Difference Between Node and Ancestor|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1026.Maximum-Difference-Between-Node-and-Ancestor)|73.4%|Medium|| +|1027|Longest Arithmetic Subsequence||47.2%|Medium|| +|1028|Recover a Tree From Preorder Traversal|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1028.Recover-a-Tree-From-Preorder-Traversal)|72.8%|Hard|| +|1029|Two City Scheduling||64.5%|Medium|| +|1030|Matrix Cells in Distance Order|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1030.Matrix-Cells-in-Distance-Order)|69.3%|Easy|| +|1031|Maximum Sum of Two Non-Overlapping Subarrays||59.4%|Medium|| +|1032|Stream of Characters||51.5%|Hard|| +|1033|Moving Stones Until Consecutive||45.6%|Medium|| +|1034|Coloring A Border|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1034.Coloring-A-Border)|48.9%|Medium|| +|1035|Uncrossed Lines||58.7%|Medium|| +|1036|Escape a Large Maze||34.2%|Hard|| |1037|Valid Boomerang|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1037.Valid-Boomerang)|37.5%|Easy|| -|1038|Binary Search Tree to Greater Sum Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1038.Binary-Search-Tree-to-Greater-Sum-Tree)|82.7%|Medium|| -|1039|Minimum Score Triangulation of Polygon||50.5%|Medium|| -|1040|Moving Stones Until Consecutive II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1040.Moving-Stones-Until-Consecutive-II)|54.3%|Medium|| -|1041|Robot Bounded In Circle||55.1%|Medium|| -|1042|Flower Planting With No Adjacent||48.8%|Medium|| -|1043|Partition Array for Maximum Sum||67.6%|Medium|| -|1044|Longest Duplicate Substring||31.3%|Hard|| -|1045|Customers Who Bought All Products||68.3%|Medium|| -|1046|Last Stone Weight||62.4%|Easy|| -|1047|Remove All Adjacent Duplicates In String|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1047.Remove-All-Adjacent-Duplicates-In-String)|71.5%|Easy|| -|1048|Longest String Chain||55.7%|Medium|| -|1049|Last Stone Weight II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1049.Last-Stone-Weight-II)|46.2%|Medium|| +|1038|Binary Search Tree to Greater Sum Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1038.Binary-Search-Tree-to-Greater-Sum-Tree)|85.3%|Medium|| +|1039|Minimum Score Triangulation of Polygon||54.5%|Medium|| +|1040|Moving Stones Until Consecutive II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1040.Moving-Stones-Until-Consecutive-II)|55.6%|Medium|| +|1041|Robot Bounded In Circle||55.3%|Medium|| +|1042|Flower Planting With No Adjacent||50.4%|Medium|| +|1043|Partition Array for Maximum Sum||71.2%|Medium|| +|1044|Longest Duplicate Substring||30.7%|Hard|| +|1045|Customers Who Bought All Products||67.6%|Medium|| +|1046|Last Stone Weight||64.7%|Easy|| +|1047|Remove All Adjacent Duplicates In String|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1047.Remove-All-Adjacent-Duplicates-In-String)|70.5%|Easy|| +|1048|Longest String Chain|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1048.Longest-String-Chain)|59.2%|Medium|| +|1049|Last Stone Weight II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1049.Last-Stone-Weight-II)|52.4%|Medium|| |1050|Actors and Directors Who Cooperated At Least Three Times||72.4%|Easy|| -|1051|Height Checker|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1051.Height-Checker)|72.4%|Easy|| -|1052|Grumpy Bookstore Owner|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1052.Grumpy-Bookstore-Owner)|56.0%|Medium|| -|1053|Previous Permutation With One Swap||51.3%|Medium|| -|1054|Distant Barcodes|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1054.Distant-Barcodes)|44.3%|Medium|| -|1055|Shortest Way to Form String||57.3%|Medium|| -|1056|Confusing Number||47.1%|Easy|| -|1057|Campus Bikes||58.0%|Medium|| -|1058|Minimize Rounding Error to Meet Target||44.1%|Medium|| -|1059|All Paths from Source Lead to Destination||43.0%|Medium|| -|1060|Missing Element in Sorted Array||54.9%|Medium|| -|1061|Lexicographically Smallest Equivalent String||66.9%|Medium|| -|1062|Longest Repeating Substring||58.5%|Medium|| -|1063|Number of Valid Subarrays||72.0%|Hard|| -|1064|Fixed Point||64.6%|Easy|| -|1065|Index Pairs of a String||61.0%|Easy|| -|1066|Campus Bikes II||54.3%|Medium|| -|1067|Digit Count in Range||41.8%|Hard|| -|1068|Product Sales Analysis I||81.9%|Easy|| -|1069|Product Sales Analysis II||83.1%|Easy|| -|1070|Product Sales Analysis III||50.0%|Medium|| -|1071|Greatest Common Divisor of Strings||51.8%|Easy|| -|1072|Flip Columns For Maximum Number of Equal Rows||61.7%|Medium|| -|1073|Adding Two Negabinary Numbers|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1073.Adding-Two-Negabinary-Numbers)|34.8%|Medium|| -|1074|Number of Submatrices That Sum to Target|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1074.Number-of-Submatrices-That-Sum-to-Target)|64.9%|Hard|| -|1075|Project Employees I||66.3%|Easy|| -|1076|Project Employees II||52.7%|Easy|| -|1077|Project Employees III||78.2%|Medium|| -|1078|Occurrences After Bigram|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1078.Occurrences-After-Bigram)|65.0%|Easy|| -|1079|Letter Tile Possibilities|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1079.Letter-Tile-Possibilities)|76.0%|Medium|| -|1080|Insufficient Nodes in Root to Leaf Paths||50.1%|Medium|| -|1081|Smallest Subsequence of Distinct Characters||53.6%|Medium|| -|1082|Sales Analysis I||74.0%|Easy|| -|1083|Sales Analysis II||50.9%|Easy|| -|1084|Sales Analysis III||54.6%|Easy|| -|1085|Sum of Digits in the Minimum Number||75.2%|Easy|| -|1086|High Five||77.2%|Easy|| -|1087|Brace Expansion||63.3%|Medium|| -|1088|Confusing Number II||45.7%|Hard|| +|1051|Height Checker|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1051.Height-Checker)|75.0%|Easy|| +|1052|Grumpy Bookstore Owner|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1052.Grumpy-Bookstore-Owner)|57.0%|Medium|| +|1053|Previous Permutation With One Swap||50.8%|Medium|| +|1054|Distant Barcodes|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1054.Distant-Barcodes)|45.7%|Medium|| +|1055|Shortest Way to Form String||59.1%|Medium|| +|1056|Confusing Number||46.1%|Easy|| +|1057|Campus Bikes||57.7%|Medium|| +|1058|Minimize Rounding Error to Meet Target||44.9%|Medium|| +|1059|All Paths from Source Lead to Destination||40.5%|Medium|| +|1060|Missing Element in Sorted Array||54.6%|Medium|| +|1061|Lexicographically Smallest Equivalent String||70.4%|Medium|| +|1062|Longest Repeating Substring||59.1%|Medium|| +|1063|Number of Valid Subarrays||74.1%|Hard|| +|1064|Fixed Point||63.6%|Easy|| +|1065|Index Pairs of a String||63.0%|Easy|| +|1066|Campus Bikes II||54.5%|Medium|| +|1067|Digit Count in Range||44.6%|Hard|| +|1068|Product Sales Analysis I||80.4%|Easy|| +|1069|Product Sales Analysis II||82.0%|Easy|| +|1070|Product Sales Analysis III||49.2%|Medium|| +|1071|Greatest Common Divisor of Strings||51.0%|Easy|| +|1072|Flip Columns For Maximum Number of Equal Rows||63.1%|Medium|| +|1073|Adding Two Negabinary Numbers|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1073.Adding-Two-Negabinary-Numbers)|36.4%|Medium|| +|1074|Number of Submatrices That Sum to Target|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1074.Number-of-Submatrices-That-Sum-to-Target)|69.8%|Hard|| +|1075|Project Employees I||67.2%|Easy|| +|1076|Project Employees II||51.0%|Easy|| +|1077|Project Employees III||78.7%|Medium|| +|1078|Occurrences After Bigram|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1078.Occurrences-After-Bigram)|63.9%|Easy|| +|1079|Letter Tile Possibilities|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1079.Letter-Tile-Possibilities)|76.1%|Medium|| +|1080|Insufficient Nodes in Root to Leaf Paths||52.8%|Medium|| +|1081|Smallest Subsequence of Distinct Characters||57.6%|Medium|| +|1082|Sales Analysis I||75.4%|Easy|| +|1083|Sales Analysis II||50.5%|Easy|| +|1084|Sales Analysis III||52.2%|Easy|| +|1085|Sum of Digits in the Minimum Number||75.9%|Easy|| +|1086|High Five||75.2%|Easy|| +|1087|Brace Expansion||66.1%|Medium|| +|1088|Confusing Number II||46.5%|Hard|| |1089|Duplicate Zeros|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1089.Duplicate-Zeros)|51.5%|Easy|| -|1090|Largest Values From Labels||60.1%|Medium|| -|1091|Shortest Path in Binary Matrix|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1091.Shortest-Path-in-Binary-Matrix)|40.2%|Medium|| -|1092|Shortest Common Supersequence||53.3%|Hard|| -|1093|Statistics from a Large Sample|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1093.Statistics-from-a-Large-Sample)|48.6%|Medium|| -|1094|Car Pooling||59.7%|Medium|| -|1095|Find in Mountain Array||36.1%|Hard|| -|1096|Brace Expansion II||62.7%|Hard|| -|1097|Game Play Analysis V||57.1%|Hard|| -|1098|Unpopular Books||45.5%|Medium|| -|1099|Two Sum Less Than K||60.8%|Easy|| -|1100|Find K-Length Substrings With No Repeated Characters||73.1%|Medium|| -|1101|The Earliest Moment When Everyone Become Friends||67.8%|Medium|| -|1102|Path With Maximum Minimum Value||50.9%|Medium|| -|1103|Distribute Candies to People||63.4%|Easy|| -|1104|Path In Zigzag Labelled Binary Tree||73.4%|Medium|| -|1105|Filling Bookcase Shelves|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1105.Filling-Bookcase-Shelves)|57.5%|Medium|| -|1106|Parsing A Boolean Expression||59.5%|Hard|| -|1107|New Users Daily Count||46.0%|Medium|| -|1108|Defanging an IP Address|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1108.Defanging-an-IP-Address)|88.4%|Easy|| -|1109|Corporate Flight Bookings||54.3%|Medium|| -|1110|Delete Nodes And Return Forest|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1110.Delete-Nodes-And-Return-Forest)|67.9%|Medium|| -|1111|Maximum Nesting Depth of Two Valid Parentheses Strings|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1111.Maximum-Nesting-Depth-of-Two-Valid-Parentheses-Strings)|72.8%|Medium|| -|1112|Highest Grade For Each Student||72.4%|Medium|| +|1090|Largest Values From Labels||60.9%|Medium|| +|1091|Shortest Path in Binary Matrix|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1091.Shortest-Path-in-Binary-Matrix)|44.5%|Medium|| +|1092|Shortest Common Supersequence||57.8%|Hard|| +|1093|Statistics from a Large Sample|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1093.Statistics-from-a-Large-Sample)|44.7%|Medium|| +|1094|Car Pooling||57.4%|Medium|| +|1095|Find in Mountain Array||35.8%|Hard|| +|1096|Brace Expansion II||63.5%|Hard|| +|1097|Game Play Analysis V||55.2%|Hard|| +|1098|Unpopular Books||45.2%|Medium|| +|1099|Two Sum Less Than K||60.4%|Easy|| +|1100|Find K-Length Substrings With No Repeated Characters||74.7%|Medium|| +|1101|The Earliest Moment When Everyone Become Friends||65.0%|Medium|| +|1102|Path With Maximum Minimum Value||53.3%|Medium|| +|1103|Distribute Candies to People||63.9%|Easy|| +|1104|Path In Zigzag Labelled Binary Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1104.Path-In-Zigzag-Labelled-Binary-Tree)|74.9%|Medium|| +|1105|Filling Bookcase Shelves|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1105.Filling-Bookcase-Shelves)|58.9%|Medium|| +|1106|Parsing A Boolean Expression||58.5%|Hard|| +|1107|New Users Daily Count||45.9%|Medium|| +|1108|Defanging an IP Address|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1108.Defanging-an-IP-Address)|89.3%|Easy|| +|1109|Corporate Flight Bookings||60.3%|Medium|| +|1110|Delete Nodes And Return Forest|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1110.Delete-Nodes-And-Return-Forest)|69.4%|Medium|| +|1111|Maximum Nesting Depth of Two Valid Parentheses Strings|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1111.Maximum-Nesting-Depth-of-Two-Valid-Parentheses-Strings)|73.3%|Medium|| +|1112|Highest Grade For Each Student||73.8%|Medium|| |1113|Reported Posts||66.1%|Easy|| -|1114|Print in Order||67.4%|Easy|| -|1115|Print FooBar Alternately||58.9%|Medium|| -|1116|Print Zero Even Odd||57.9%|Medium|| -|1117|Building H2O||53.0%|Medium|| -|1118|Number of Days in a Month||57.3%|Easy|| -|1119|Remove Vowels from a String||90.6%|Easy|| -|1120|Maximum Average Subtree||64.1%|Medium|| -|1121|Divide Array Into Increasing Sequences||58.4%|Hard|| -|1122|Relative Sort Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1122.Relative-Sort-Array)|68.1%|Easy|| -|1123|Lowest Common Ancestor of Deepest Leaves|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1123.Lowest-Common-Ancestor-of-Deepest-Leaves)|68.1%|Medium|| -|1124|Longest Well-Performing Interval||33.3%|Medium|| +|1114|Print in Order||68.1%|Easy|| +|1115|Print FooBar Alternately||61.7%|Medium|| +|1116|Print Zero Even Odd||60.1%|Medium|| +|1117|Building H2O||55.7%|Medium|| +|1118|Number of Days in a Month||56.7%|Easy|| +|1119|Remove Vowels from a String||90.7%|Easy|| +|1120|Maximum Average Subtree||65.5%|Medium|| +|1121|Divide Array Into Increasing Sequences||60.0%|Hard|| +|1122|Relative Sort Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1122.Relative-Sort-Array)|68.4%|Easy|| +|1123|Lowest Common Ancestor of Deepest Leaves|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1123.Lowest-Common-Ancestor-of-Deepest-Leaves)|70.6%|Medium|| +|1124|Longest Well-Performing Interval||34.6%|Medium|| |1125|Smallest Sufficient Team||47.1%|Hard|| -|1126|Active Businesses||68.5%|Medium|| -|1127|User Purchase Platform||50.8%|Hard|| -|1128|Number of Equivalent Domino Pairs|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1128.Number-of-Equivalent-Domino-Pairs)|46.3%|Easy|| -|1129|Shortest Path with Alternating Colors||40.5%|Medium|| -|1130|Minimum Cost Tree From Leaf Values||67.3%|Medium|| -|1131|Maximum of Absolute Value Expression||51.4%|Medium|| -|1132|Reported Posts II||34.6%|Medium|| -|1133|Largest Unique Number||67.4%|Easy|| -|1134|Armstrong Number||77.9%|Easy|| -|1135|Connecting Cities With Minimum Cost||59.8%|Medium|| -|1136|Parallel Courses||61.1%|Medium|| -|1137|N-th Tribonacci Number|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1137.N-th-Tribonacci-Number)|55.8%|Easy|| -|1138|Alphabet Board Path||51.4%|Medium|| -|1139|Largest 1-Bordered Square||48.6%|Medium|| -|1140|Stone Game II||64.6%|Medium|| -|1141|User Activity for the Past 30 Days I||54.5%|Easy|| -|1142|User Activity for the Past 30 Days II||35.4%|Easy|| -|1143|Longest Common Subsequence|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1143.Longest-Common-Subsequence)|58.7%|Medium|| -|1144|Decrease Elements To Make Array Zigzag||46.3%|Medium|| -|1145|Binary Tree Coloring Game|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1145.Binary-Tree-Coloring-Game)|51.2%|Medium|| -|1146|Snapshot Array||36.8%|Medium|| -|1147|Longest Chunked Palindrome Decomposition||59.6%|Hard|| -|1148|Article Views I||77.1%|Easy|| -|1149|Article Views II||48.3%|Medium|| -|1150|Check If a Number Is Majority Element in a Sorted Array||57.1%|Easy|| -|1151|Minimum Swaps to Group All 1's Together||58.8%|Medium|| -|1152|Analyze User Website Visit Pattern||43.1%|Medium|| -|1153|String Transforms Into Another String||35.8%|Hard|| -|1154|Day of the Year|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1154.Day-of-the-Year)|49.1%|Easy|| -|1155|Number of Dice Rolls With Target Sum||47.6%|Medium|| -|1156|Swap For Longest Repeated Character Substring||47.0%|Medium|| -|1157|Online Majority Element In Subarray|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1157.Online-Majority-Element-In-Subarray)|41.0%|Hard|| -|1158|Market Analysis I||64.2%|Medium|| -|1159|Market Analysis II||56.6%|Hard|| -|1160|Find Words That Can Be Formed by Characters|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1160.Find-Words-That-Can-Be-Formed-by-Characters)|67.9%|Easy|| -|1161|Maximum Level Sum of a Binary Tree||68.6%|Medium|| -|1162|As Far from Land as Possible||45.7%|Medium|| -|1163|Last Substring in Lexicographical Order||36.2%|Hard|| -|1164|Product Price at a Given Date||68.9%|Medium|| -|1165|Single-Row Keyboard||85.4%|Easy|| -|1166|Design File System||58.6%|Medium|| -|1167|Minimum Cost to Connect Sticks||64.6%|Medium|| -|1168|Optimize Water Distribution in a Village||61.3%|Hard|| -|1169|Invalid Transactions||30.8%|Medium|| -|1170|Compare Strings by Frequency of the Smallest Character|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1170.Compare-Strings-by-Frequency-of-the-Smallest-Character)|60.4%|Medium|| -|1171|Remove Zero Sum Consecutive Nodes from Linked List|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1171.Remove-Zero-Sum-Consecutive-Nodes-from-Linked-List)|41.5%|Medium|| -|1172|Dinner Plate Stacks||37.5%|Hard|| -|1173|Immediate Food Delivery I||82.8%|Easy|| -|1174|Immediate Food Delivery II||62.3%|Medium|| -|1175|Prime Arrangements|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1175.Prime-Arrangements)|51.8%|Easy|| -|1176|Diet Plan Performance||53.8%|Easy|| -|1177|Can Make Palindrome from Substring||36.0%|Medium|| -|1178|Number of Valid Words for Each Puzzle|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1178.Number-of-Valid-Words-for-Each-Puzzle)|39.8%|Hard|| -|1179|Reformat Department Table||82.1%|Easy|| -|1180|Count Substrings with Only One Distinct Letter||78.0%|Easy|| -|1181|Before and After Puzzle||44.6%|Medium|| -|1182|Shortest Distance to Target Color||53.7%|Medium|| -|1183|Maximum Number of Ones||58.0%|Hard|| -|1184|Distance Between Bus Stops|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1184.Distance-Between-Bus-Stops)|53.9%|Easy|| -|1185|Day of the Week|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1185.Day-of-the-Week)|61.0%|Easy|| -|1186|Maximum Subarray Sum with One Deletion||39.2%|Medium|| -|1187|Make Array Strictly Increasing||42.3%|Hard|| -|1188|Design Bounded Blocking Queue||73.0%|Medium|| +|1126|Active Businesses||67.9%|Medium|| +|1127|User Purchase Platform||51.2%|Hard|| +|1128|Number of Equivalent Domino Pairs|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1128.Number-of-Equivalent-Domino-Pairs)|46.9%|Easy|| +|1129|Shortest Path with Alternating Colors||42.9%|Medium|| +|1130|Minimum Cost Tree From Leaf Values||68.5%|Medium|| +|1131|Maximum of Absolute Value Expression||49.5%|Medium|| +|1132|Reported Posts II||33.6%|Medium|| +|1133|Largest Unique Number||67.5%|Easy|| +|1134|Armstrong Number||78.1%|Easy|| +|1135|Connecting Cities With Minimum Cost||61.1%|Medium|| +|1136|Parallel Courses||62.0%|Medium|| +|1137|N-th Tribonacci Number|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1137.N-th-Tribonacci-Number)|63.3%|Easy|| +|1138|Alphabet Board Path||52.3%|Medium|| +|1139|Largest 1-Bordered Square||50.0%|Medium|| +|1140|Stone Game II||64.9%|Medium|| +|1141|User Activity for the Past 30 Days I||50.2%|Easy|| +|1142|User Activity for the Past 30 Days II||36.0%|Easy|| +|1143|Longest Common Subsequence|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1143.Longest-Common-Subsequence)|58.8%|Medium|| +|1144|Decrease Elements To Make Array Zigzag||47.0%|Medium|| +|1145|Binary Tree Coloring Game|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1145.Binary-Tree-Coloring-Game)|51.4%|Medium|| +|1146|Snapshot Array||37.3%|Medium|| +|1147|Longest Chunked Palindrome Decomposition||60.0%|Hard|| +|1148|Article Views I||77.0%|Easy|| +|1149|Article Views II||47.6%|Medium|| +|1150|Check If a Number Is Majority Element in a Sorted Array||56.8%|Easy|| +|1151|Minimum Swaps to Group All 1's Together||60.9%|Medium|| +|1152|Analyze User Website Visit Pattern||43.4%|Medium|| +|1153|String Transforms Into Another String||35.3%|Hard|| +|1154|Day of the Year|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1154.Day-of-the-Year)|50.3%|Easy|| +|1155|Number of Dice Rolls With Target Sum||53.6%|Medium|| +|1156|Swap For Longest Repeated Character Substring||45.5%|Medium|| +|1157|Online Majority Element In Subarray|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1157.Online-Majority-Element-In-Subarray)|42.0%|Hard|| +|1158|Market Analysis I||63.9%|Medium|| +|1159|Market Analysis II||58.7%|Hard|| +|1160|Find Words That Can Be Formed by Characters|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1160.Find-Words-That-Can-Be-Formed-by-Characters)|67.8%|Easy|| +|1161|Maximum Level Sum of a Binary Tree||66.2%|Medium|| +|1162|As Far from Land as Possible||48.5%|Medium|| +|1163|Last Substring in Lexicographical Order||35.1%|Hard|| +|1164|Product Price at a Given Date||68.4%|Medium|| +|1165|Single-Row Keyboard||85.7%|Easy|| +|1166|Design File System||61.8%|Medium|| +|1167|Minimum Cost to Connect Sticks||67.7%|Medium|| +|1168|Optimize Water Distribution in a Village||64.4%|Hard|| +|1169|Invalid Transactions||31.0%|Medium|| +|1170|Compare Strings by Frequency of the Smallest Character|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1170.Compare-Strings-by-Frequency-of-the-Smallest-Character)|61.3%|Medium|| +|1171|Remove Zero Sum Consecutive Nodes from Linked List|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1171.Remove-Zero-Sum-Consecutive-Nodes-from-Linked-List)|42.9%|Medium|| +|1172|Dinner Plate Stacks||33.7%|Hard|| +|1173|Immediate Food Delivery I||83.4%|Easy|| +|1174|Immediate Food Delivery II||63.9%|Medium|| +|1175|Prime Arrangements|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1175.Prime-Arrangements)|53.5%|Easy|| +|1176|Diet Plan Performance||52.4%|Easy|| +|1177|Can Make Palindrome from Substring||37.8%|Medium|| +|1178|Number of Valid Words for Each Puzzle|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1178.Number-of-Valid-Words-for-Each-Puzzle)|46.6%|Hard|| +|1179|Reformat Department Table||82.7%|Easy|| +|1180|Count Substrings with Only One Distinct Letter||78.9%|Easy|| +|1181|Before and After Puzzle||45.1%|Medium|| +|1182|Shortest Distance to Target Color||55.5%|Medium|| +|1183|Maximum Number of Ones||60.9%|Hard|| +|1184|Distance Between Bus Stops|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1184.Distance-Between-Bus-Stops)|54.1%|Easy|| +|1185|Day of the Week|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1185.Day-of-the-Week)|57.8%|Easy|| +|1186|Maximum Subarray Sum with One Deletion||41.2%|Medium|| +|1187|Make Array Strictly Increasing||45.3%|Hard|| +|1188|Design Bounded Blocking Queue||72.9%|Medium|| |1189|Maximum Number of Balloons|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1189.Maximum-Number-of-Balloons)|62.2%|Easy|| -|1190|Reverse Substrings Between Each Pair of Parentheses||64.3%|Medium|| -|1191|K-Concatenation Maximum Sum||24.9%|Medium|| -|1192|Critical Connections in a Network||51.4%|Hard|| -|1193|Monthly Transactions I||69.0%|Medium|| -|1194|Tournament Winners||52.4%|Hard|| -|1195|Fizz Buzz Multithreaded||70.9%|Medium|| -|1196|How Many Apples Can You Put into the Basket||68.3%|Easy|| -|1197|Minimum Knight Moves||37.6%|Medium|| -|1198|Find Smallest Common Element in All Rows||76.2%|Medium|| -|1199|Minimum Time to Build Blocks||39.0%|Hard|| -|1200|Minimum Absolute Difference|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1200.Minimum-Absolute-Difference)|67.1%|Easy|| -|1201|Ugly Number III|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1201.Ugly-Number-III)|26.5%|Medium|| -|1202|Smallest String With Swaps|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1202.Smallest-String-With-Swaps)|49.1%|Medium|| -|1203|Sort Items by Groups Respecting Dependencies|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1203.Sort-Items-by-Groups-Respecting-Dependencies)|48.4%|Hard|| -|1204|Last Person to Fit in the Elevator||72.3%|Medium|| -|1205|Monthly Transactions II||45.7%|Medium|| -|1206|Design Skiplist||59.0%|Hard|| -|1207|Unique Number of Occurrences|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1207.Unique-Number-of-Occurrences)|72.0%|Easy|| -|1208|Get Equal Substrings Within Budget|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1208.Get-Equal-Substrings-Within-Budget)|44.4%|Medium|| -|1209|Remove All Adjacent Duplicates in String II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1209.Remove-All-Adjacent-Duplicates-in-String-II)|57.7%|Medium|| -|1210|Minimum Moves to Reach Target with Rotations||46.7%|Hard|| -|1211|Queries Quality and Percentage||70.3%|Easy|| -|1212|Team Scores in Football Tournament||56.7%|Medium|| -|1213|Intersection of Three Sorted Arrays||79.5%|Easy|| -|1214|Two Sum BSTs||67.7%|Medium|| -|1215|Stepping Numbers||43.7%|Medium|| +|1190|Reverse Substrings Between Each Pair of Parentheses|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1190.Reverse-Substrings-Between-Each-Pair-of-Parentheses)|65.9%|Medium|| +|1191|K-Concatenation Maximum Sum||24.0%|Medium|| +|1192|Critical Connections in a Network||54.5%|Hard|| +|1193|Monthly Transactions I||67.2%|Medium|| +|1194|Tournament Winners||51.7%|Hard|| +|1195|Fizz Buzz Multithreaded||72.5%|Medium|| +|1196|How Many Apples Can You Put into the Basket||67.0%|Easy|| +|1197|Minimum Knight Moves||39.8%|Medium|| +|1198|Find Smallest Common Element in All Rows||76.0%|Medium|| +|1199|Minimum Time to Build Blocks||40.7%|Hard|| +|1200|Minimum Absolute Difference|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1200.Minimum-Absolute-Difference)|69.8%|Easy|| +|1201|Ugly Number III|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1201.Ugly-Number-III)|28.5%|Medium|| +|1202|Smallest String With Swaps|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1202.Smallest-String-With-Swaps)|57.5%|Medium|| +|1203|Sort Items by Groups Respecting Dependencies|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1203.Sort-Items-by-Groups-Respecting-Dependencies)|50.6%|Hard|| +|1204|Last Person to Fit in the Bus||74.1%|Medium|| +|1205|Monthly Transactions II||43.8%|Medium|| +|1206|Design Skiplist||60.5%|Hard|| +|1207|Unique Number of Occurrences|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1207.Unique-Number-of-Occurrences)|70.9%|Easy|| +|1208|Get Equal Substrings Within Budget|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1208.Get-Equal-Substrings-Within-Budget)|47.6%|Medium|| +|1209|Remove All Adjacent Duplicates in String II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1209.Remove-All-Adjacent-Duplicates-in-String-II)|56.0%|Medium|| +|1210|Minimum Moves to Reach Target with Rotations||48.9%|Hard|| +|1211|Queries Quality and Percentage||71.9%|Easy|| +|1212|Team Scores in Football Tournament||57.6%|Medium|| +|1213|Intersection of Three Sorted Arrays||80.0%|Easy|| +|1214|Two Sum BSTs||66.2%|Medium|| +|1215|Stepping Numbers||45.8%|Medium|| |1216|Valid Palindrome III||50.1%|Hard|| -|1217|Minimum Cost to Move Chips to The Same Position|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1217.Minimum-Cost-to-Move-Chips-to-The-Same-Position)|70.9%|Easy|| -|1218|Longest Arithmetic Subsequence of Given Difference||46.9%|Medium|| -|1219|Path with Maximum Gold||66.0%|Medium|| -|1220|Count Vowels Permutation||54.1%|Hard|| -|1221|Split a String in Balanced Strings|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1221.Split-a-String-in-Balanced-Strings)|84.3%|Easy|| -|1222|Queens That Can Attack the King||69.5%|Medium|| -|1223|Dice Roll Simulation||46.7%|Hard|| -|1224|Maximum Equal Frequency||35.7%|Hard|| -|1225|Report Contiguous Dates||63.2%|Hard|| -|1226|The Dining Philosophers||60.1%|Medium|| -|1227|Airplane Seat Assignment Probability||62.3%|Medium|| -|1228|Missing Number In Arithmetic Progression||51.3%|Easy|| -|1229|Meeting Scheduler||54.4%|Medium|| -|1230|Toss Strange Coins||50.5%|Medium|| -|1231|Divide Chocolate||53.7%|Hard|| -|1232|Check If It Is a Straight Line|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1232.Check-If-It-Is-a-Straight-Line)|43.1%|Easy|| -|1233|Remove Sub-Folders from the Filesystem||62.6%|Medium|| -|1234|Replace the Substring for Balanced String|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1234.Replace-the-Substring-for-Balanced-String)|34.7%|Medium|| -|1235|Maximum Profit in Job Scheduling|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1235.Maximum-Profit-in-Job-Scheduling)|47.8%|Hard|| -|1236|Web Crawler||64.8%|Medium|| -|1237|Find Positive Integer Solution for a Given Equation||70.2%|Medium|| -|1238|Circular Permutation in Binary Representation||66.5%|Medium|| -|1239|Maximum Length of a Concatenated String with Unique Characters||50.1%|Medium|| -|1240|Tiling a Rectangle with the Fewest Squares||52.9%|Hard|| -|1241|Number of Comments per Post||67.8%|Easy|| -|1242|Web Crawler Multithreaded||47.8%|Medium|| -|1243|Array Transformation||50.1%|Easy|| -|1244|Design A Leaderboard||66.7%|Medium|| -|1245|Tree Diameter||61.4%|Medium|| -|1246|Palindrome Removal||45.7%|Hard|| -|1247|Minimum Swaps to Make Strings Equal||63.0%|Medium|| -|1248|Count Number of Nice Subarrays||56.2%|Medium|| -|1249|Minimum Remove to Make Valid Parentheses|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1249.Minimum-Remove-to-Make-Valid-Parentheses)|64.3%|Medium|| -|1250|Check If It Is a Good Array||56.5%|Hard|| -|1251|Average Selling Price||82.8%|Easy|| +|1217|Minimum Cost to Move Chips to The Same Position|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1217.Minimum-Cost-to-Move-Chips-to-The-Same-Position)|72.2%|Easy|| +|1218|Longest Arithmetic Subsequence of Given Difference||51.8%|Medium|| +|1219|Path with Maximum Gold||64.4%|Medium|| +|1220|Count Vowels Permutation||60.7%|Hard|| +|1221|Split a String in Balanced Strings|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1221.Split-a-String-in-Balanced-Strings)|84.7%|Easy|| +|1222|Queens That Can Attack the King||71.7%|Medium|| +|1223|Dice Roll Simulation||48.4%|Hard|| +|1224|Maximum Equal Frequency||36.8%|Hard|| +|1225|Report Contiguous Dates||63.4%|Hard|| +|1226|The Dining Philosophers||56.6%|Medium|| +|1227|Airplane Seat Assignment Probability||64.9%|Medium|| +|1228|Missing Number In Arithmetic Progression||51.4%|Easy|| +|1229|Meeting Scheduler||55.4%|Medium|| +|1230|Toss Strange Coins||53.4%|Medium|| +|1231|Divide Chocolate||56.9%|Hard|| +|1232|Check If It Is a Straight Line|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1232.Check-If-It-Is-a-Straight-Line)|41.2%|Easy|| +|1233|Remove Sub-Folders from the Filesystem||65.4%|Medium|| +|1234|Replace the Substring for Balanced String|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1234.Replace-the-Substring-for-Balanced-String)|36.8%|Medium|| +|1235|Maximum Profit in Job Scheduling|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1235.Maximum-Profit-in-Job-Scheduling)|51.1%|Hard|| +|1236|Web Crawler||66.3%|Medium|| +|1237|Find Positive Integer Solution for a Given Equation||69.3%|Medium|| +|1238|Circular Permutation in Binary Representation||68.8%|Medium|| +|1239|Maximum Length of a Concatenated String with Unique Characters|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1239.Maximum-Length-of-a-Concatenated-String-with-Unique-Characters)|50.6%|Medium|| +|1240|Tiling a Rectangle with the Fewest Squares||54.0%|Hard|| +|1241|Number of Comments per Post||68.0%|Easy|| +|1242|Web Crawler Multithreaded||49.0%|Medium|| +|1243|Array Transformation||50.7%|Easy|| +|1244|Design A Leaderboard||68.8%|Medium|| +|1245|Tree Diameter||61.7%|Medium|| +|1246|Palindrome Removal||45.9%|Hard|| +|1247|Minimum Swaps to Make Strings Equal||63.7%|Medium|| +|1248|Count Number of Nice Subarrays||59.5%|Medium|| +|1249|Minimum Remove to Make Valid Parentheses|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1249.Minimum-Remove-to-Make-Valid-Parentheses)|65.6%|Medium|| +|1250|Check If It Is a Good Array||58.7%|Hard|| +|1251|Average Selling Price||83.2%|Easy|| |1252|Cells with Odd Values in a Matrix|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1252.Cells-with-Odd-Values-in-a-Matrix)|78.6%|Easy|| -|1253|Reconstruct a 2-Row Binary Matrix||41.9%|Medium|| -|1254|Number of Closed Islands|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1254.Number-of-Closed-Islands)|62.0%|Medium|| -|1255|Maximum Score Words Formed by Letters||70.3%|Hard|| -|1256|Encode Number||67.9%|Medium|| -|1257|Smallest Common Region||61.2%|Medium|| -|1258|Synonymous Sentences||61.7%|Medium|| -|1259|Handshakes That Don't Cross||54.2%|Hard|| -|1260|Shift 2D Grid|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1260.Shift-2D-Grid)|61.8%|Easy|| -|1261|Find Elements in a Contaminated Binary Tree||74.6%|Medium|| -|1262|Greatest Sum Divisible by Three||50.1%|Medium|| -|1263|Minimum Moves to Move a Box to Their Target Location||43.6%|Hard|| -|1264|Page Recommendations||69.2%|Medium|| -|1265|Print Immutable Linked List in Reverse||94.2%|Medium|| -|1266|Minimum Time Visiting All Points|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1266.Minimum-Time-Visiting-All-Points)|79.3%|Easy|| -|1267|Count Servers that Communicate||57.7%|Medium|| -|1268|Search Suggestions System||64.8%|Medium|| -|1269|Number of Ways to Stay in the Same Place After Some Steps||43.3%|Hard|| -|1270|All People Report to the Given Manager||88.2%|Medium|| -|1271|Hexspeak||55.6%|Easy|| -|1272|Remove Interval||58.6%|Medium|| -|1273|Delete Tree Nodes||61.9%|Medium|| -|1274|Number of Ships in a Rectangle||65.9%|Hard|| -|1275|Find Winner on a Tic Tac Toe Game|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1275.Find-Winner-on-a-Tic-Tac-Toe-Game)|52.9%|Easy|| -|1276|Number of Burgers with No Waste of Ingredients||50.2%|Medium|| -|1277|Count Square Submatrices with All Ones||72.9%|Medium|| -|1278|Palindrome Partitioning III||61.2%|Hard|| -|1279|Traffic Light Controlled Intersection||76.4%|Easy|| -|1280|Students and Examinations||75.5%|Easy|| -|1281|Subtract the Product and Sum of Digits of an Integer|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1281.Subtract-the-Product-and-Sum-of-Digits-of-an-Integer)|85.6%|Easy|| -|1282|Group the People Given the Group Size They Belong To||84.5%|Medium|| -|1283|Find the Smallest Divisor Given a Threshold|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1283.Find-the-Smallest-Divisor-Given-a-Threshold)|50.0%|Medium|| -|1284|Minimum Number of Flips to Convert Binary Matrix to Zero Matrix||70.2%|Hard|| -|1285|Find the Start and End Number of Continuous Ranges||87.4%|Medium|| -|1286|Iterator for Combination||70.9%|Medium|| -|1287|Element Appearing More Than 25% In Sorted Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1287.Element-Appearing-More-Than-25%-In-Sorted-Array)|60.3%|Easy|| -|1288|Remove Covered Intervals||57.5%|Medium|| -|1289|Minimum Falling Path Sum II||62.6%|Hard|| -|1290|Convert Binary Number in a Linked List to Integer|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1290.Convert-Binary-Number-in-a-Linked-List-to-Integer)|81.7%|Easy|| -|1291|Sequential Digits||57.4%|Medium|| -|1292|Maximum Side Length of a Square with Sum Less than or Equal to Threshold||50.8%|Medium|| -|1293|Shortest Path in a Grid with Obstacles Elimination||43.0%|Hard|| -|1294|Weather Type in Each Country||66.7%|Easy|| -|1295|Find Numbers with Even Number of Digits|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1295.Find-Numbers-with-Even-Number-of-Digits)|78.7%|Easy|| -|1296|Divide Array in Sets of K Consecutive Numbers||55.8%|Medium|| -|1297|Maximum Number of Occurrences of a Substring||51.0%|Medium|| -|1298|Maximum Candies You Can Get from Boxes||59.9%|Hard|| -|1299|Replace Elements with Greatest Element on Right Side|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1299.Replace-Elements-with-Greatest-Element-on-Right-Side)|74.6%|Easy|| -|1300|Sum of Mutated Array Closest to Target|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1300.Sum-of-Mutated-Array-Closest-to-Target)|43.0%|Medium|| -|1301|Number of Paths with Max Score||38.2%|Hard|| -|1302|Deepest Leaves Sum|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1302.Deepest-Leaves-Sum)|85.4%|Medium|| -|1303|Find the Team Size||89.9%|Easy|| -|1304|Find N Unique Integers Sum up to Zero|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1304.Find-N-Unique-Integers-Sum-up-to-Zero)|76.7%|Easy|| -|1305|All Elements in Two Binary Search Trees|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1305.All-Elements-in-Two-Binary-Search-Trees)|77.8%|Medium|| -|1306|Jump Game III|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1306.Jump-Game-III)|62.1%|Medium|| -|1307|Verbal Arithmetic Puzzle||36.3%|Hard|| -|1308|Running Total for Different Genders||88.1%|Medium|| -|1309|Decrypt String from Alphabet to Integer Mapping||77.8%|Easy|| -|1310|XOR Queries of a Subarray||69.5%|Medium|| -|1311|Get Watched Videos by Your Friends||44.3%|Medium|| -|1312|Minimum Insertion Steps to Make a String Palindrome||60.2%|Hard|| -|1313|Decompress Run-Length Encoded List|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1313.Decompress-Run-Length-Encoded-List)|85.4%|Easy|| -|1314|Matrix Block Sum||73.8%|Medium|| -|1315|Sum of Nodes with Even-Valued Grandparent||84.3%|Medium|| +|1253|Reconstruct a 2-Row Binary Matrix||43.8%|Medium|| +|1254|Number of Closed Islands|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1254.Number-of-Closed-Islands)|64.2%|Medium|| +|1255|Maximum Score Words Formed by Letters||72.8%|Hard|| +|1256|Encode Number||69.9%|Medium|| +|1257|Smallest Common Region||64.1%|Medium|| +|1258|Synonymous Sentences||56.4%|Medium|| +|1259|Handshakes That Don't Cross||56.2%|Hard|| +|1260|Shift 2D Grid|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1260.Shift-2D-Grid)|68.0%|Easy|| +|1261|Find Elements in a Contaminated Binary Tree||76.1%|Medium|| +|1262|Greatest Sum Divisible by Three||50.9%|Medium|| +|1263|Minimum Moves to Move a Box to Their Target Location||49.0%|Hard|| +|1264|Page Recommendations||67.8%|Medium|| +|1265|Print Immutable Linked List in Reverse||94.3%|Medium|| +|1266|Minimum Time Visiting All Points|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1266.Minimum-Time-Visiting-All-Points)|79.1%|Easy|| +|1267|Count Servers that Communicate||59.1%|Medium|| +|1268|Search Suggestions System|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1268.Search-Suggestions-System)|66.7%|Medium|| +|1269|Number of Ways to Stay in the Same Place After Some Steps||43.6%|Hard|| +|1270|All People Report to the Given Manager||88.0%|Medium|| +|1271|Hexspeak||57.0%|Easy|| +|1272|Remove Interval||63.3%|Medium|| +|1273|Delete Tree Nodes||61.2%|Medium|| +|1274|Number of Ships in a Rectangle||69.3%|Hard|| +|1275|Find Winner on a Tic Tac Toe Game|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1275.Find-Winner-on-a-Tic-Tac-Toe-Game)|54.3%|Easy|| +|1276|Number of Burgers with No Waste of Ingredients||50.6%|Medium|| +|1277|Count Square Submatrices with All Ones||74.4%|Medium|| +|1278|Palindrome Partitioning III||60.8%|Hard|| +|1279|Traffic Light Controlled Intersection||74.5%|Easy|| +|1280|Students and Examinations||74.5%|Easy|| +|1281|Subtract the Product and Sum of Digits of an Integer|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1281.Subtract-the-Product-and-Sum-of-Digits-of-an-Integer)|86.7%|Easy|| +|1282|Group the People Given the Group Size They Belong To||85.7%|Medium|| +|1283|Find the Smallest Divisor Given a Threshold|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1283.Find-the-Smallest-Divisor-Given-a-Threshold)|55.3%|Medium|| +|1284|Minimum Number of Flips to Convert Binary Matrix to Zero Matrix||72.1%|Hard|| +|1285|Find the Start and End Number of Continuous Ranges||88.2%|Medium|| +|1286|Iterator for Combination||73.5%|Medium|| +|1287|Element Appearing More Than 25% In Sorted Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1287.Element-Appearing-More-Than-25-In-Sorted-Array)|59.5%|Easy|| +|1288|Remove Covered Intervals||57.3%|Medium|| +|1289|Minimum Falling Path Sum II||59.6%|Hard|| +|1290|Convert Binary Number in a Linked List to Integer|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1290.Convert-Binary-Number-in-a-Linked-List-to-Integer)|82.6%|Easy|| +|1291|Sequential Digits||61.2%|Medium|| +|1292|Maximum Side Length of a Square with Sum Less than or Equal to Threshold||53.1%|Medium|| +|1293|Shortest Path in a Grid with Obstacles Elimination|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1293.Shortest-Path-in-a-Grid-with-Obstacles-Elimination)|43.6%|Hard|| +|1294|Weather Type in Each Country||67.9%|Easy|| +|1295|Find Numbers with Even Number of Digits|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1295.Find-Numbers-with-Even-Number-of-Digits)|76.9%|Easy|| +|1296|Divide Array in Sets of K Consecutive Numbers|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1296.Divide-Array-in-Sets-of-K-Consecutive-Numbers)|56.6%|Medium|| +|1297|Maximum Number of Occurrences of a Substring||52.1%|Medium|| +|1298|Maximum Candies You Can Get from Boxes||61.1%|Hard|| +|1299|Replace Elements with Greatest Element on Right Side|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1299.Replace-Elements-with-Greatest-Element-on-Right-Side)|74.7%|Easy|| +|1300|Sum of Mutated Array Closest to Target|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1300.Sum-of-Mutated-Array-Closest-to-Target)|43.1%|Medium|| +|1301|Number of Paths with Max Score||38.7%|Hard|| +|1302|Deepest Leaves Sum|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1302.Deepest-Leaves-Sum)|87.0%|Medium|| +|1303|Find the Team Size||90.8%|Easy|| +|1304|Find N Unique Integers Sum up to Zero|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1304.Find-N-Unique-Integers-Sum-up-to-Zero)|77.1%|Easy|| +|1305|All Elements in Two Binary Search Trees|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1305.All-Elements-in-Two-Binary-Search-Trees)|79.8%|Medium|| +|1306|Jump Game III|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1306.Jump-Game-III)|63.0%|Medium|| +|1307|Verbal Arithmetic Puzzle||34.5%|Hard|| +|1308|Running Total for Different Genders||88.3%|Medium|| +|1309|Decrypt String from Alphabet to Integer Mapping||79.4%|Easy|| +|1310|XOR Queries of a Subarray|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1310.XOR-Queries-of-a-Subarray)|72.1%|Medium|| +|1311|Get Watched Videos by Your Friends||45.9%|Medium|| +|1312|Minimum Insertion Steps to Make a String Palindrome||65.5%|Hard|| +|1313|Decompress Run-Length Encoded List|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1313.Decompress-Run-Length-Encoded-List)|85.9%|Easy|| +|1314|Matrix Block Sum||75.4%|Medium|| +|1315|Sum of Nodes with Even-Valued Grandparent||85.6%|Medium|| |1316|Distinct Echo Substrings||49.8%|Hard|| -|1317|Convert Integer to the Sum of Two No-Zero Integers|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1317.Convert-Integer-to-the-Sum-of-Two-No-Zero-Integers)|56.9%|Easy|| -|1318|Minimum Flips to Make a OR b Equal to c||63.9%|Medium|| -|1319|Number of Operations to Make Network Connected|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1319.Number-of-Operations-to-Make-Network-Connected)|55.6%|Medium|| -|1320|Minimum Distance to Type a Word Using Two Fingers||61.7%|Hard|| -|1321|Restaurant Growth||71.8%|Medium|| -|1322|Ads Performance||58.4%|Easy|| -|1323|Maximum 69 Number||77.9%|Easy|| -|1324|Print Words Vertically||59.0%|Medium|| -|1325|Delete Leaves With a Given Value||73.8%|Medium|| -|1326|Minimum Number of Taps to Open to Water a Garden||47.6%|Hard|| -|1327|List the Products Ordered in a Period||77.7%|Easy|| -|1328|Break a Palindrome||48.1%|Medium|| -|1329|Sort the Matrix Diagonally|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1329.Sort-the-Matrix-Diagonally)|81.6%|Medium|| -|1330|Reverse Subarray To Maximize Array Value||36.9%|Hard|| -|1331|Rank Transform of an Array||57.3%|Easy|| -|1332|Remove Palindromic Subsequences|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1332.Remove-Palindromic-Subsequences)|68.4%|Easy|| -|1333|Filter Restaurants by Vegan-Friendly, Price and Distance||57.5%|Medium|| -|1334|Find the City With the Smallest Number of Neighbors at a Threshold Distance||47.4%|Medium|| -|1335|Minimum Difficulty of a Job Schedule||56.6%|Hard|| -|1336|Number of Transactions per Visit||49.4%|Hard|| -|1337|The K Weakest Rows in a Matrix|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1337.The-K-Weakest-Rows-in-a-Matrix)|72.0%|Easy|| -|1338|Reduce Array Size to The Half||67.7%|Medium|| -|1339|Maximum Product of Splitted Binary Tree||38.6%|Medium|| -|1340|Jump Game V||59.4%|Hard|| -|1341|Movie Rating||59.0%|Medium|| +|1317|Convert Integer to the Sum of Two No-Zero Integers|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1317.Convert-Integer-to-the-Sum-of-Two-No-Zero-Integers)|56.2%|Easy|| +|1318|Minimum Flips to Make a OR b Equal to c||66.0%|Medium|| +|1319|Number of Operations to Make Network Connected|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1319.Number-of-Operations-to-Make-Network-Connected)|58.3%|Medium|| +|1320|Minimum Distance to Type a Word Using Two Fingers||59.8%|Hard|| +|1321|Restaurant Growth||72.2%|Medium|| +|1322|Ads Performance||60.9%|Easy|| +|1323|Maximum 69 Number||79.1%|Easy|| +|1324|Print Words Vertically||60.0%|Medium|| +|1325|Delete Leaves With a Given Value||74.8%|Medium|| +|1326|Minimum Number of Taps to Open to Water a Garden||47.8%|Hard|| +|1327|List the Products Ordered in a Period||77.1%|Easy|| +|1328|Break a Palindrome||53.4%|Medium|| +|1329|Sort the Matrix Diagonally|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1329.Sort-the-Matrix-Diagonally)|83.6%|Medium|| +|1330|Reverse Subarray To Maximize Array Value||39.9%|Hard|| +|1331|Rank Transform of an Array||59.0%|Easy|| +|1332|Remove Palindromic Subsequences|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1332.Remove-Palindromic-Subsequences)|76.1%|Easy|| +|1333|Filter Restaurants by Vegan-Friendly, Price and Distance||59.4%|Medium|| +|1334|Find the City With the Smallest Number of Neighbors at a Threshold Distance||52.9%|Medium|| +|1335|Minimum Difficulty of a Job Schedule||58.8%|Hard|| +|1336|Number of Transactions per Visit||51.4%|Hard|| +|1337|The K Weakest Rows in a Matrix|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1337.The-K-Weakest-Rows-in-a-Matrix)|73.1%|Easy|| +|1338|Reduce Array Size to The Half||69.8%|Medium|| +|1339|Maximum Product of Splitted Binary Tree||43.3%|Medium|| +|1340|Jump Game V||62.6%|Hard|| +|1341|Movie Rating||58.6%|Medium|| |1342|Number of Steps to Reduce a Number to Zero||85.6%|Easy|| -|1343|Number of Sub-arrays of Size K and Average Greater than or Equal to Threshold||65.1%|Medium|| -|1344|Angle Between Hands of a Clock||61.3%|Medium|| -|1345|Jump Game IV||42.0%|Hard|| -|1346|Check If N and Its Double Exist||35.9%|Easy|| -|1347|Minimum Number of Steps to Make Two Strings Anagram||75.1%|Medium|| -|1348|Tweet Counts Per Frequency||37.5%|Medium|| -|1349|Maximum Students Taking Exam||44.4%|Hard|| +|1343|Number of Sub-arrays of Size K and Average Greater than or Equal to Threshold||67.7%|Medium|| +|1344|Angle Between Hands of a Clock||63.4%|Medium|| +|1345|Jump Game IV||44.1%|Hard|| +|1346|Check If N and Its Double Exist||36.1%|Easy|| +|1347|Minimum Number of Steps to Make Two Strings Anagram||77.2%|Medium|| +|1348|Tweet Counts Per Frequency||43.5%|Medium|| +|1349|Maximum Students Taking Exam||48.0%|Hard|| |1350|Students With Invalid Departments||90.5%|Easy|| -|1351|Count Negative Numbers in a Sorted Matrix||75.8%|Easy|| -|1352|Product of the Last K Numbers||45.2%|Medium|| -|1353|Maximum Number of Events That Can Be Attended|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1353.Maximum-Number-of-Events-That-Can-Be-Attended)|30.6%|Medium|| -|1354|Construct Target Array With Multiple Sums||31.2%|Hard|| -|1355|Activity Participants||74.5%|Medium|| -|1356|Sort Integers by The Number of 1 Bits||70.5%|Easy|| -|1357|Apply Discount Every n Orders||67.0%|Medium|| -|1358|Number of Substrings Containing All Three Characters||60.6%|Medium|| -|1359|Count All Valid Pickup and Delivery Options||55.9%|Hard|| -|1360|Number of Days Between Two Dates||46.6%|Easy|| -|1361|Validate Binary Tree Nodes||43.2%|Medium|| -|1362|Closest Divisors||57.9%|Medium|| -|1363|Largest Multiple of Three||34.2%|Hard|| -|1364|Number of Trusted Contacts of a Customer||79.2%|Medium|| -|1365|How Many Numbers Are Smaller Than the Current Number||86.0%|Easy|| -|1366|Rank Teams by Votes||55.7%|Medium|| -|1367|Linked List in Binary Tree||41.0%|Medium|| -|1368|Minimum Cost to Make at Least One Valid Path in a Grid||57.9%|Hard|| -|1369|Get the Second Most Recent Activity||69.1%|Hard|| +|1351|Count Negative Numbers in a Sorted Matrix||75.3%|Easy|| +|1352|Product of the Last K Numbers||49.4%|Medium|| +|1353|Maximum Number of Events That Can Be Attended|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1353.Maximum-Number-of-Events-That-Can-Be-Attended)|32.9%|Medium|| +|1354|Construct Target Array With Multiple Sums||36.3%|Hard|| +|1355|Activity Participants||74.4%|Medium|| +|1356|Sort Integers by The Number of 1 Bits||72.0%|Easy|| +|1357|Apply Discount Every n Orders||69.9%|Medium|| +|1358|Number of Substrings Containing All Three Characters||62.9%|Medium|| +|1359|Count All Valid Pickup and Delivery Options||63.0%|Hard|| +|1360|Number of Days Between Two Dates||47.5%|Easy|| +|1361|Validate Binary Tree Nodes||40.4%|Medium|| +|1362|Closest Divisors||59.8%|Medium|| +|1363|Largest Multiple of Three||33.5%|Hard|| +|1364|Number of Trusted Contacts of a Customer||79.0%|Medium|| +|1365|How Many Numbers Are Smaller Than the Current Number||86.6%|Easy|| +|1366|Rank Teams by Votes||58.6%|Medium|| +|1367|Linked List in Binary Tree||43.4%|Medium|| +|1368|Minimum Cost to Make at Least One Valid Path in a Grid||61.3%|Hard|| +|1369|Get the Second Most Recent Activity||69.6%|Hard|| |1370|Increasing Decreasing String||77.5%|Easy|| -|1371|Find the Longest Substring Containing Vowels in Even Counts||60.8%|Medium|| -|1372|Longest ZigZag Path in a Binary Tree||55.0%|Medium|| -|1373|Maximum Sum BST in Binary Tree||37.0%|Hard|| -|1374|Generate a String With Characters That Have Odd Counts||76.9%|Easy|| -|1375|Bulb Switcher III||64.2%|Medium|| -|1376|Time Needed to Inform All Employees||56.8%|Medium|| -|1377|Frog Position After T Seconds||35.5%|Hard|| -|1378|Replace Employee ID With The Unique Identifier||90.4%|Easy|| -|1379|Find a Corresponding Node of a Binary Tree in a Clone of That Tree||84.6%|Medium|| -|1380|Lucky Numbers in a Matrix|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1380.Lucky-Numbers-in-a-Matrix)|70.4%|Easy|| -|1381|Design a Stack With Increment Operation||76.4%|Medium|| -|1382|Balance a Binary Search Tree||76.2%|Medium|| -|1383|Maximum Performance of a Team||36.1%|Hard|| -|1384|Total Sales Amount by Year||65.3%|Hard|| -|1385|Find the Distance Value Between Two Arrays|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1385.Find-the-Distance-Value-Between-Two-Arrays)|66.5%|Easy|| -|1386|Cinema Seat Allocation||36.2%|Medium|| -|1387|Sort Integers by The Power Value||70.6%|Medium|| -|1388|Pizza With 3n Slices||46.4%|Hard|| -|1389|Create Target Array in the Given Order|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1389.Create-Target-Array-in-the-Given-Order)|84.9%|Easy|| -|1390|Four Divisors||39.6%|Medium|| -|1391|Check if There is a Valid Path in a Grid||45.0%|Medium|| -|1392|Longest Happy Prefix||42.2%|Hard|| +|1371|Find the Longest Substring Containing Vowels in Even Counts||63.0%|Medium|| +|1372|Longest ZigZag Path in a Binary Tree||59.6%|Medium|| +|1373|Maximum Sum BST in Binary Tree||39.2%|Hard|| +|1374|Generate a String With Characters That Have Odd Counts||77.5%|Easy|| +|1375|Number of Times Binary String Is Prefix-Aligned||65.9%|Medium|| +|1376|Time Needed to Inform All Employees||58.4%|Medium|| +|1377|Frog Position After T Seconds||36.1%|Hard|| +|1378|Replace Employee ID With The Unique Identifier||91.4%|Easy|| +|1379|Find a Corresponding Node of a Binary Tree in a Clone of That Tree||87.1%|Easy|| +|1380|Lucky Numbers in a Matrix|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1380.Lucky-Numbers-in-a-Matrix)|70.5%|Easy|| +|1381|Design a Stack With Increment Operation||77.4%|Medium|| +|1382|Balance a Binary Search Tree||80.7%|Medium|| +|1383|Maximum Performance of a Team|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1383.Maximum-Performance-of-a-Team)|49.0%|Hard|| +|1384|Total Sales Amount by Year||67.6%|Hard|| +|1385|Find the Distance Value Between Two Arrays|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1385.Find-the-Distance-Value-Between-Two-Arrays)|65.3%|Easy|| +|1386|Cinema Seat Allocation||40.9%|Medium|| +|1387|Sort Integers by The Power Value||69.9%|Medium|| +|1388|Pizza With 3n Slices||50.1%|Hard|| +|1389|Create Target Array in the Given Order|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1389.Create-Target-Array-in-the-Given-Order)|85.8%|Easy|| +|1390|Four Divisors||41.2%|Medium|| +|1391|Check if There is a Valid Path in a Grid||47.0%|Medium|| +|1392|Longest Happy Prefix||45.0%|Hard|| |1393|Capital Gain/Loss||91.1%|Medium|| -|1394|Find Lucky Integer in an Array||63.1%|Easy|| -|1395|Count Number of Teams||74.6%|Medium|| -|1396|Design Underground System|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1396.Design-Underground-System)|71.8%|Medium|| -|1397|Find All Good Strings||38.8%|Hard|| -|1398|Customers Who Bought Products A and B but Not C||82.3%|Medium|| -|1399|Count Largest Group||65.4%|Easy|| -|1400|Construct K Palindrome Strings||63.0%|Medium|| -|1401|Circle and Rectangle Overlapping||42.6%|Medium|| +|1394|Find Lucky Integer in an Array||63.5%|Easy|| +|1395|Count Number of Teams||68.3%|Medium|| +|1396|Design Underground System|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1396.Design-Underground-System)|73.7%|Medium|| +|1397|Find All Good Strings||42.1%|Hard|| +|1398|Customers Who Bought Products A and B but Not C||77.7%|Medium|| +|1399|Count Largest Group||67.2%|Easy|| +|1400|Construct K Palindrome Strings||63.3%|Medium|| +|1401|Circle and Rectangle Overlapping||44.2%|Medium|| |1402|Reducing Dishes||72.0%|Hard|| -|1403|Minimum Subsequence in Non-Increasing Order||71.9%|Easy|| -|1404|Number of Steps to Reduce a Number in Binary Representation to One||50.1%|Medium|| -|1405|Longest Happy String||52.8%|Medium|| -|1406|Stone Game III||58.1%|Hard|| -|1407|Top Travellers||84.0%|Easy|| -|1408|String Matching in an Array||63.7%|Easy|| -|1409|Queries on a Permutation With Key||81.9%|Medium|| -|1410|HTML Entity Parser||54.1%|Medium|| -|1411|Number of Ways to Paint N × 3 Grid||60.6%|Hard|| -|1412|Find the Quiet Students in All Exams||63.9%|Hard|| -|1413|Minimum Value to Get Positive Step by Step Sum||65.4%|Easy|| -|1414|Find the Minimum Number of Fibonacci Numbers Whose Sum Is K||63.1%|Medium|| -|1415|The k-th Lexicographical String of All Happy Strings of Length n||70.0%|Medium|| -|1416|Restore The Array||36.7%|Hard|| -|1417|Reformat The String||56.6%|Easy|| -|1418|Display Table of Food Orders in a Restaurant||69.4%|Medium|| -|1419|Minimum Number of Frogs Croaking||47.8%|Medium|| -|1420|Build Array Where You Can Find The Maximum Exactly K Comparisons||64.2%|Hard|| -|1421|NPV Queries||82.2%|Medium|| -|1422|Maximum Score After Splitting a String||57.5%|Easy|| -|1423|Maximum Points You Can Obtain from Cards|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1423.Maximum-Points-You-Can-Obtain-from-Cards)|47.0%|Medium|| -|1424|Diagonal Traverse II||46.4%|Medium|| -|1425|Constrained Subsequence Sum||45.0%|Hard|| -|1426|Counting Elements||59.1%|Easy|| -|1427|Perform String Shifts||53.5%|Easy|| -|1428|Leftmost Column with at Least a One||49.6%|Medium|| -|1429|First Unique Number||50.0%|Medium|| -|1430|Check If a String Is a Valid Sequence from Root to Leaves Path in a Binary Tree||45.2%|Medium|| -|1431|Kids With the Greatest Number of Candies||88.2%|Easy|| -|1432|Max Difference You Can Get From Changing an Integer||42.8%|Medium|| -|1433|Check If a String Can Break Another String||67.4%|Medium|| -|1434|Number of Ways to Wear Different Hats to Each Other||39.5%|Hard|| -|1435|Create a Session Bar Chart||78.1%|Easy|| -|1436|Destination City||77.3%|Easy|| -|1437|Check If All 1's Are at Least Length K Places Away|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1437.Check-If-All-1's-Are-at-Least-Length-K-Places-Away)|61.8%|Easy|| -|1438|Longest Continuous Subarray With Absolute Diff Less Than or Equal to Limit|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1438.Longest-Continuous-Subarray-With-Absolute-Diff-Less-Than-or-Equal-to-Limit)|44.5%|Medium|| -|1439|Find the Kth Smallest Sum of a Matrix With Sorted Rows|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1439.Find-the-Kth-Smallest-Sum-of-a-Matrix-With-Sorted-Rows)|60.5%|Hard|| -|1440|Evaluate Boolean Expression||75.0%|Medium|| -|1441|Build an Array With Stack Operations||70.4%|Easy|| -|1442|Count Triplets That Can Form Two Arrays of Equal XOR||72.0%|Medium|| -|1443|Minimum Time to Collect All Apples in a Tree||54.4%|Medium|| -|1444|Number of Ways of Cutting a Pizza||54.0%|Hard|| -|1445|Apples & Oranges||91.1%|Medium|| -|1446|Consecutive Characters||61.3%|Easy|| -|1447|Simplified Fractions||62.2%|Medium|| -|1448|Count Good Nodes in Binary Tree||71.6%|Medium|| -|1449|Form Largest Integer With Digits That Add up to Target||44.5%|Hard|| -|1450|Number of Students Doing Homework at a Given Time||77.0%|Easy|| -|1451|Rearrange Words in a Sentence||60.0%|Medium|| -|1452|People Whose List of Favorite Companies Is Not a Subset of Another List||55.2%|Medium|| -|1453|Maximum Number of Darts Inside of a Circular Dartboard||35.7%|Hard|| -|1454|Active Users||38.8%|Medium|| -|1455|Check If a Word Occurs As a Prefix of Any Word in a Sentence|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1455.Check-If-a-Word-Occurs-As-a-Prefix-of-Any-Word-in-a-Sentence)|65.4%|Easy|| -|1456|Maximum Number of Vowels in a Substring of Given Length||55.1%|Medium|| -|1457|Pseudo-Palindromic Paths in a Binary Tree||69.8%|Medium|| -|1458|Max Dot Product of Two Subsequences||43.5%|Hard|| -|1459|Rectangles Area||65.7%|Medium|| -|1460|Make Two Arrays Equal by Reversing Sub-arrays||72.2%|Easy|| -|1461|Check If a String Contains All Binary Codes of Size K|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1461.Check-If-a-String-Contains-All-Binary-Codes-of-Size-K)|54.2%|Medium|| -|1462|Course Schedule IV||44.9%|Medium|| -|1463|Cherry Pickup II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1463.Cherry-Pickup-II)|68.8%|Hard|| -|1464|Maximum Product of Two Elements in an Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1464.Maximum-Product-of-Two-Elements-in-an-Array)|77.1%|Easy|| -|1465|Maximum Area of a Piece of Cake After Horizontal and Vertical Cuts||34.1%|Medium|| -|1466|Reorder Routes to Make All Paths Lead to the City Zero||62.0%|Medium|| -|1467|Probability of a Two Boxes Having The Same Number of Distinct Balls||60.6%|Hard|| -|1468|Calculate Salaries||82.0%|Medium|| -|1469|Find All The Lonely Nodes||80.5%|Easy|| -|1470|Shuffle the Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1470.Shuffle-the-Array)|88.1%|Easy|| -|1471|The k Strongest Values in an Array||58.6%|Medium|| -|1472|Design Browser History||72.2%|Medium|| -|1473|Paint House III||48.6%|Hard|| -|1474|Delete N Nodes After M Nodes of a Linked List||73.7%|Easy|| -|1475|Final Prices With a Special Discount in a Shop||74.9%|Easy|| -|1476|Subrectangle Queries||88.0%|Medium|| -|1477|Find Two Non-overlapping Sub-arrays Each With Target Sum||35.2%|Medium|| -|1478|Allocate Mailboxes||53.8%|Hard|| -|1479|Sales by Day of the Week||83.0%|Hard|| -|1480|Running Sum of 1d Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1480.Running-Sum-of-1d-Array)|88.5%|Easy|| -|1481|Least Number of Unique Integers after K Removals||55.9%|Medium|| -|1482|Minimum Number of Days to Make m Bouquets||51.1%|Medium|| -|1483|Kth Ancestor of a Tree Node||32.0%|Hard|| -|1484|Group Sold Products By The Date||85.3%|Easy|| +|1403|Minimum Subsequence in Non-Increasing Order||72.2%|Easy|| +|1404|Number of Steps to Reduce a Number in Binary Representation to One||52.0%|Medium|| +|1405|Longest Happy String||57.4%|Medium|| +|1406|Stone Game III||59.7%|Hard|| +|1407|Top Travellers||68.7%|Easy|| +|1408|String Matching in an Array||63.9%|Easy|| +|1409|Queries on a Permutation With Key||83.3%|Medium|| +|1410|HTML Entity Parser||52.1%|Medium|| +|1411|Number of Ways to Paint N × 3 Grid||62.3%|Hard|| +|1412|Find the Quiet Students in All Exams||63.0%|Hard|| +|1413|Minimum Value to Get Positive Step by Step Sum||68.4%|Easy|| +|1414|Find the Minimum Number of Fibonacci Numbers Whose Sum Is K||65.4%|Medium|| +|1415|The k-th Lexicographical String of All Happy Strings of Length n||72.0%|Medium|| +|1416|Restore The Array||38.4%|Hard|| +|1417|Reformat The String||55.8%|Easy|| +|1418|Display Table of Food Orders in a Restaurant||73.7%|Medium|| +|1419|Minimum Number of Frogs Croaking||49.9%|Medium|| +|1420|Build Array Where You Can Find The Maximum Exactly K Comparisons||63.6%|Hard|| +|1421|NPV Queries||84.1%|Easy|| +|1422|Maximum Score After Splitting a String||57.8%|Easy|| +|1423|Maximum Points You Can Obtain from Cards|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1423.Maximum-Points-You-Can-Obtain-from-Cards)|52.3%|Medium|| +|1424|Diagonal Traverse II||50.3%|Medium|| +|1425|Constrained Subsequence Sum||47.4%|Hard|| +|1426|Counting Elements||59.5%|Easy|| +|1427|Perform String Shifts||54.2%|Easy|| +|1428|Leftmost Column with at Least a One||53.0%|Medium|| +|1429|First Unique Number||52.7%|Medium|| +|1430|Check If a String Is a Valid Sequence from Root to Leaves Path in a Binary Tree||46.1%|Medium|| +|1431|Kids With the Greatest Number of Candies||87.5%|Easy|| +|1432|Max Difference You Can Get From Changing an Integer||43.0%|Medium|| +|1433|Check If a String Can Break Another String||68.8%|Medium|| +|1434|Number of Ways to Wear Different Hats to Each Other||42.8%|Hard|| +|1435|Create a Session Bar Chart||78.3%|Easy|| +|1436|Destination City||77.6%|Easy|| +|1437|Check If All 1's Are at Least Length K Places Away|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1437.Check-If-All-1s-Are-at-Least-Length-K-Places-Away)|59.2%|Easy|| +|1438|Longest Continuous Subarray With Absolute Diff Less Than or Equal to Limit|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1438.Longest-Continuous-Subarray-With-Absolute-Diff-Less-Than-or-Equal-to-Limit)|48.0%|Medium|| +|1439|Find the Kth Smallest Sum of a Matrix With Sorted Rows|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1439.Find-the-Kth-Smallest-Sum-of-a-Matrix-With-Sorted-Rows)|61.4%|Hard|| +|1440|Evaluate Boolean Expression||76.5%|Medium|| +|1441|Build an Array With Stack Operations||71.3%|Medium|| +|1442|Count Triplets That Can Form Two Arrays of Equal XOR|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1442.Count-Triplets-That-Can-Form-Two-Arrays-of-Equal-XOR)|75.6%|Medium|| +|1443|Minimum Time to Collect All Apples in a Tree||56.0%|Medium|| +|1444|Number of Ways of Cutting a Pizza||58.6%|Hard|| +|1445|Apples & Oranges||91.3%|Medium|| +|1446|Consecutive Characters|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1446.Consecutive-Characters)|61.7%|Easy|| +|1447|Simplified Fractions||64.6%|Medium|| +|1448|Count Good Nodes in Binary Tree||74.6%|Medium|| +|1449|Form Largest Integer With Digits That Add up to Target||47.1%|Hard|| +|1450|Number of Students Doing Homework at a Given Time||75.9%|Easy|| +|1451|Rearrange Words in a Sentence||62.5%|Medium|| +|1452|People Whose List of Favorite Companies Is Not a Subset of Another List||56.8%|Medium|| +|1453|Maximum Number of Darts Inside of a Circular Dartboard||36.8%|Hard|| +|1454|Active Users||38.4%|Medium|| +|1455|Check If a Word Occurs As a Prefix of Any Word in a Sentence|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1455.Check-If-a-Word-Occurs-As-a-Prefix-of-Any-Word-in-a-Sentence)|64.2%|Easy|| +|1456|Maximum Number of Vowels in a Substring of Given Length||57.9%|Medium|| +|1457|Pseudo-Palindromic Paths in a Binary Tree||68.1%|Medium|| +|1458|Max Dot Product of Two Subsequences||46.2%|Hard|| +|1459|Rectangles Area||70.0%|Medium|| +|1460|Make Two Arrays Equal by Reversing Subarrays||72.2%|Easy|| +|1461|Check If a String Contains All Binary Codes of Size K|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1461.Check-If-a-String-Contains-All-Binary-Codes-of-Size-K)|56.8%|Medium|| +|1462|Course Schedule IV||48.9%|Medium|| +|1463|Cherry Pickup II|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1463.Cherry-Pickup-II)|70.2%|Hard|| +|1464|Maximum Product of Two Elements in an Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1464.Maximum-Product-of-Two-Elements-in-an-Array)|79.2%|Easy|| +|1465|Maximum Area of a Piece of Cake After Horizontal and Vertical Cuts|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1465.Maximum-Area-of-a-Piece-of-Cake-After-Horizontal-and-Vertical-Cuts)|40.8%|Medium|| +|1466|Reorder Routes to Make All Paths Lead to the City Zero||61.8%|Medium|| +|1467|Probability of a Two Boxes Having The Same Number of Distinct Balls||60.8%|Hard|| +|1468|Calculate Salaries||81.9%|Medium|| +|1469|Find All The Lonely Nodes||81.7%|Easy|| +|1470|Shuffle the Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1470.Shuffle-the-Array)|88.5%|Easy|| +|1471|The k Strongest Values in an Array||60.1%|Medium|| +|1472|Design Browser History||76.1%|Medium|| +|1473|Paint House III||62.0%|Hard|| +|1474|Delete N Nodes After M Nodes of a Linked List||73.8%|Easy|| +|1475|Final Prices With a Special Discount in a Shop||75.4%|Easy|| +|1476|Subrectangle Queries||88.5%|Medium|| +|1477|Find Two Non-overlapping Sub-arrays Each With Target Sum||37.0%|Medium|| +|1478|Allocate Mailboxes||55.3%|Hard|| +|1479|Sales by Day of the Week||82.4%|Hard|| +|1480|Running Sum of 1d Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1480.Running-Sum-of-1d-Array)|89.8%|Easy|| +|1481|Least Number of Unique Integers after K Removals||57.2%|Medium|| +|1482|Minimum Number of Days to Make m Bouquets|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1482.Minimum-Number-of-Days-to-Make-m-Bouquets)|56.7%|Medium|| +|1483|Kth Ancestor of a Tree Node||33.8%|Hard|| +|1484|Group Sold Products By The Date||84.1%|Easy|| |1485|Clone Binary Tree With Random Pointer||79.5%|Medium|| -|1486|XOR Operation in an Array||84.0%|Easy|| -|1487|Making File Names Unique||31.5%|Medium|| -|1488|Avoid Flood in The City||24.6%|Medium|| -|1489|Find Critical and Pseudo-Critical Edges in Minimum Spanning Tree||51.5%|Hard|| -|1490|Clone N-ary Tree||83.2%|Medium|| -|1491|Average Salary Excluding the Minimum and Maximum Salary||68.4%|Easy|| -|1492|The kth Factor of n||63.1%|Medium|| -|1493|Longest Subarray of 1's After Deleting One Element||57.7%|Medium|| +|1486|XOR Operation in an Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1486.XOR-Operation-in-an-Array)|84.2%|Easy|| +|1487|Making File Names Unique||35.6%|Medium|| +|1488|Avoid Flood in The City||26.1%|Medium|| +|1489|Find Critical and Pseudo-Critical Edges in Minimum Spanning Tree||53.4%|Hard|| +|1490|Clone N-ary Tree||83.6%|Medium|| +|1491|Average Salary Excluding the Minimum and Maximum Salary||63.1%|Easy|| +|1492|The kth Factor of n||62.3%|Medium|| +|1493|Longest Subarray of 1's After Deleting One Element||60.1%|Medium|| |1494|Parallel Courses II||31.1%|Hard|| -|1495|Friendly Movies Streamed Last Month||51.2%|Easy|| -|1496|Path Crossing||55.3%|Easy|| -|1497|Check If Array Pairs Are Divisible by k||40.3%|Medium|| -|1498|Number of Subsequences That Satisfy the Given Sum Condition||39.0%|Medium|| -|1499|Max Value of Equation||45.4%|Hard|| -|1500|Design a File Sharing System||46.8%|Medium|| -|1501|Countries You Can Safely Invest In||60.4%|Medium|| -|1502|Can Make Arithmetic Progression From Sequence||71.0%|Easy|| -|1503|Last Moment Before All Ants Fall Out of a Plank||53.3%|Medium|| -|1504|Count Submatrices With All Ones||60.6%|Medium|| -|1505|Minimum Possible Integer After at Most K Adjacent Swaps On Digits||36.4%|Hard|| -|1506|Find Root of N-Ary Tree||80.0%|Medium|| -|1507|Reformat Date||60.2%|Easy|| -|1508|Range Sum of Sorted Subarray Sums||60.2%|Medium|| -|1509|Minimum Difference Between Largest and Smallest Value in Three Moves||53.6%|Medium|| -|1510|Stone Game IV||59.0%|Hard|| -|1511|Customer Order Frequency||74.3%|Easy|| -|1512|Number of Good Pairs|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1512.Number-of-Good-Pairs)|87.6%|Easy|| -|1513|Number of Substrings With Only 1s||42.1%|Medium|| -|1514|Path with Maximum Probability||41.2%|Medium|| -|1515|Best Position for a Service Centre||38.5%|Hard|| -|1516|Move Sub-Tree of N-Ary Tree||64.5%|Hard|| -|1517|Find Users With Valid E-Mails||70.9%|Easy|| -|1518|Water Bottles||60.5%|Easy|| -|1519|Number of Nodes in the Sub-Tree With the Same Label||37.4%|Medium|| -|1520|Maximum Number of Non-Overlapping Substrings||36.6%|Hard|| -|1521|Find a Value of a Mysterious Function Closest to Target||44.2%|Hard|| -|1522|Diameter of N-Ary Tree||69.4%|Medium|| -|1523|Count Odd Numbers in an Interval Range||54.1%|Easy|| -|1524|Number of Sub-arrays With Odd Sum||40.2%|Medium|| -|1525|Number of Good Ways to Split a String||67.6%|Medium|| -|1526|Minimum Number of Increments on Subarrays to Form a Target Array||61.9%|Hard|| -|1527|Patients With a Condition||61.6%|Easy|| +|1495|Friendly Movies Streamed Last Month||49.8%|Easy|| +|1496|Path Crossing||55.8%|Easy|| +|1497|Check If Array Pairs Are Divisible by k||39.8%|Medium|| +|1498|Number of Subsequences That Satisfy the Given Sum Condition||38.4%|Medium|| +|1499|Max Value of Equation||46.5%|Hard|| +|1500|Design a File Sharing System||44.9%|Medium|| +|1501|Countries You Can Safely Invest In||58.3%|Medium|| +|1502|Can Make Arithmetic Progression From Sequence||68.3%|Easy|| +|1503|Last Moment Before All Ants Fall Out of a Plank||55.2%|Medium|| +|1504|Count Submatrices With All Ones||57.9%|Medium|| +|1505|Minimum Possible Integer After at Most K Adjacent Swaps On Digits||38.1%|Hard|| +|1506|Find Root of N-Ary Tree||78.1%|Medium|| +|1507|Reformat Date||62.4%|Easy|| +|1508|Range Sum of Sorted Subarray Sums||59.4%|Medium|| +|1509|Minimum Difference Between Largest and Smallest Value in Three Moves||54.6%|Medium|| +|1510|Stone Game IV||60.6%|Hard|| +|1511|Customer Order Frequency||73.1%|Easy|| +|1512|Number of Good Pairs|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1512.Number-of-Good-Pairs)|88.2%|Easy|| +|1513|Number of Substrings With Only 1s||45.2%|Medium|| +|1514|Path with Maximum Probability||48.3%|Medium|| +|1515|Best Position for a Service Centre||38.4%|Hard|| +|1516|Move Sub-Tree of N-Ary Tree||63.9%|Hard|| +|1517|Find Users With Valid E-Mails||57.1%|Easy|| +|1518|Water Bottles|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1518.Water-Bottles)|60.3%|Easy|| +|1519|Number of Nodes in the Sub-Tree With the Same Label||40.9%|Medium|| +|1520|Maximum Number of Non-Overlapping Substrings||37.9%|Hard|| +|1521|Find a Value of a Mysterious Function Closest to Target||43.6%|Hard|| +|1522|Diameter of N-Ary Tree||73.4%|Medium|| +|1523|Count Odd Numbers in an Interval Range||46.4%|Easy|| +|1524|Number of Sub-arrays With Odd Sum||43.6%|Medium|| +|1525|Number of Good Ways to Split a String||69.5%|Medium|| +|1526|Minimum Number of Increments on Subarrays to Form a Target Array||68.6%|Hard|| +|1527|Patients With a Condition||42.9%|Easy|| |1528|Shuffle String||85.7%|Easy|| -|1529|Bulb Switcher IV||71.0%|Medium|| -|1530|Number of Good Leaf Nodes Pairs||56.7%|Medium|| -|1531|String Compression II||34.1%|Hard|| -|1532|The Most Recent Three Orders||72.8%|Medium|| -|1533|Find the Index of the Large Integer||54.5%|Medium|| -|1534|Count Good Triplets||80.3%|Easy|| -|1535|Find the Winner of an Array Game||47.7%|Medium|| -|1536|Minimum Swaps to Arrange a Binary Grid||43.7%|Medium|| -|1537|Get the Maximum Score||36.6%|Hard|| -|1538|Guess the Majority in a Hidden Array||61.0%|Medium|| -|1539|Kth Missing Positive Number|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1539.Kth-Missing-Positive-Number)|54.8%|Easy|| -|1540|Can Convert String in K Moves||31.3%|Medium|| -|1541|Minimum Insertions to Balance a Parentheses String||43.2%|Medium|| -|1542|Find Longest Awesome Substring||36.7%|Hard|| -|1543|Fix Product Name Format||66.7%|Easy|| -|1544|Make The String Great||55.5%|Easy|| -|1545|Find Kth Bit in Nth Binary String||57.7%|Medium|| -|1546|Maximum Number of Non-Overlapping Subarrays With Sum Equals Target||44.2%|Medium|| -|1547|Minimum Cost to Cut a Stick||52.8%|Hard|| -|1548|The Most Similar Path in a Graph||55.2%|Hard|| -|1549|The Most Recent Orders for Each Product||67.2%|Medium|| -|1550|Three Consecutive Odds||64.5%|Easy|| -|1551|Minimum Operations to Make Array Equal|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1551.Minimum-Operations-to-Make-Array-Equal)|80.8%|Medium|| -|1552|Magnetic Force Between Two Balls||49.4%|Medium|| -|1553|Minimum Number of Days to Eat N Oranges||29.9%|Hard|| -|1554|Strings Differ by One Character||64.2%|Medium|| +|1529|Minimum Suffix Flips||72.5%|Medium|| +|1530|Number of Good Leaf Nodes Pairs||60.5%|Medium|| +|1531|String Compression II||50.2%|Hard|| +|1532|The Most Recent Three Orders||71.1%|Medium|| +|1533|Find the Index of the Large Integer||50.7%|Medium|| +|1534|Count Good Triplets||80.8%|Easy|| +|1535|Find the Winner of an Array Game||48.8%|Medium|| +|1536|Minimum Swaps to Arrange a Binary Grid||46.4%|Medium|| +|1537|Get the Maximum Score||39.3%|Hard|| +|1538|Guess the Majority in a Hidden Array||63.0%|Medium|| +|1539|Kth Missing Positive Number|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1539.Kth-Missing-Positive-Number)|55.9%|Easy|| +|1540|Can Convert String in K Moves||33.1%|Medium|| +|1541|Minimum Insertions to Balance a Parentheses String||49.9%|Medium|| +|1542|Find Longest Awesome Substring||41.6%|Hard|| +|1543|Fix Product Name Format||62.4%|Easy|| +|1544|Make The String Great||57.0%|Easy|| +|1545|Find Kth Bit in Nth Binary String||58.2%|Medium|| +|1546|Maximum Number of Non-Overlapping Subarrays With Sum Equals Target||47.2%|Medium|| +|1547|Minimum Cost to Cut a Stick||56.8%|Hard|| +|1548|The Most Similar Path in a Graph||56.9%|Hard|| +|1549|The Most Recent Orders for Each Product||67.9%|Medium|| +|1550|Three Consecutive Odds||63.7%|Easy|| +|1551|Minimum Operations to Make Array Equal|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1551.Minimum-Operations-to-Make-Array-Equal)|81.1%|Medium|| +|1552|Magnetic Force Between Two Balls||56.8%|Medium|| +|1553|Minimum Number of Days to Eat N Oranges||34.4%|Hard|| +|1554|Strings Differ by One Character||43.6%|Medium|| |1555|Bank Account Summary||53.0%|Medium|| -|1556|Thousand Separator||57.1%|Easy|| -|1557|Minimum Number of Vertices to Reach All Nodes||75.8%|Medium|| -|1558|Minimum Numbers of Function Calls to Make Target Array||63.3%|Medium|| -|1559|Detect Cycles in 2D Grid||44.7%|Hard|| -|1560|Most Visited Sector in a Circular Track||56.9%|Easy|| -|1561|Maximum Number of Coins You Can Get||77.2%|Medium|| -|1562|Find Latest Group of Size M||39.7%|Medium|| -|1563|Stone Game V||40.0%|Hard|| -|1564|Put Boxes Into the Warehouse I||65.7%|Medium|| -|1565|Unique Orders and Customers Per Month||82.9%|Easy|| -|1566|Detect Pattern of Length M Repeated K or More Times||42.6%|Easy|| -|1567|Maximum Length of Subarray With Positive Product||37.1%|Medium|| -|1568|Minimum Number of Days to Disconnect Island||50.1%|Hard|| -|1569|Number of Ways to Reorder Array to Get Same BST||50.0%|Hard|| -|1570|Dot Product of Two Sparse Vectors||91.1%|Medium|| -|1571|Warehouse Manager||90.0%|Easy|| -|1572|Matrix Diagonal Sum||77.7%|Easy|| -|1573|Number of Ways to Split a String|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1573.Number-of-Ways-to-Split-a-String)|31.4%|Medium|| -|1574|Shortest Subarray to be Removed to Make Array Sorted||34.1%|Medium|| -|1575|Count All Possible Routes||57.0%|Hard|| -|1576|Replace All ?'s to Avoid Consecutive Repeating Characters||50.1%|Easy|| -|1577|Number of Ways Where Square of Number Is Equal to Product of Two Numbers||38.0%|Medium|| -|1578|Minimum Deletion Cost to Avoid Repeating Letters||60.7%|Medium|| -|1579|Remove Max Number of Edges to Keep Graph Fully Traversable|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1579.Remove-Max-Number-of-Edges-to-Keep-Graph-Fully-Traversable)|46.4%|Hard|| -|1580|Put Boxes Into the Warehouse II||61.8%|Medium|| -|1581|Customer Who Visited but Did Not Make Any Transactions||89.6%|Easy|| -|1582|Special Positions in a Binary Matrix||64.1%|Easy|| -|1583|Count Unhappy Friends||55.2%|Medium|| -|1584|Min Cost to Connect All Points||53.6%|Medium|| -|1585|Check If String Is Transformable With Substring Sort Operations||48.5%|Hard|| -|1586|Binary Search Tree Iterator II||66.9%|Medium|| -|1587|Bank Account Summary II||90.0%|Easy|| -|1588|Sum of All Odd Length Subarrays||81.7%|Easy|| -|1589|Maximum Sum Obtained of Any Permutation||35.0%|Medium|| -|1590|Make Sum Divisible by P||26.9%|Medium|| -|1591|Strange Printer II||55.6%|Hard|| -|1592|Rearrange Spaces Between Words||43.5%|Easy|| -|1593|Split a String Into the Max Number of Unique Substrings||50.1%|Medium|| -|1594|Maximum Non Negative Product in a Matrix||32.4%|Medium|| -|1595|Minimum Cost to Connect Two Groups of Points||43.6%|Hard|| -|1596|The Most Frequently Ordered Products for Each Customer||85.3%|Medium|| -|1597|Build Binary Expression Tree From Infix Expression||59.3%|Hard|| -|1598|Crawler Log Folder||63.8%|Easy|| +|1556|Thousand Separator||55.1%|Easy|| +|1557|Minimum Number of Vertices to Reach All Nodes||79.6%|Medium|| +|1558|Minimum Numbers of Function Calls to Make Target Array||64.3%|Medium|| +|1559|Detect Cycles in 2D Grid||48.1%|Medium|| +|1560|Most Visited Sector in a Circular Track||58.4%|Easy|| +|1561|Maximum Number of Coins You Can Get||78.6%|Medium|| +|1562|Find Latest Group of Size M||42.4%|Medium|| +|1563|Stone Game V||40.6%|Hard|| +|1564|Put Boxes Into the Warehouse I||67.1%|Medium|| +|1565|Unique Orders and Customers Per Month||83.6%|Easy|| +|1566|Detect Pattern of Length M Repeated K or More Times||43.6%|Easy|| +|1567|Maximum Length of Subarray With Positive Product||43.7%|Medium|| +|1568|Minimum Number of Days to Disconnect Island||47.1%|Hard|| +|1569|Number of Ways to Reorder Array to Get Same BST||48.2%|Hard|| +|1570|Dot Product of Two Sparse Vectors||90.4%|Medium|| +|1571|Warehouse Manager||90.1%|Easy|| +|1572|Matrix Diagonal Sum|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1572.Matrix-Diagonal-Sum)|79.7%|Easy|| +|1573|Number of Ways to Split a String|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1573.Number-of-Ways-to-Split-a-String)|32.4%|Medium|| +|1574|Shortest Subarray to be Removed to Make Array Sorted||36.5%|Medium|| +|1575|Count All Possible Routes||56.9%|Hard|| +|1576|Replace All ?'s to Avoid Consecutive Repeating Characters|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1576.Replace-All-s-to-Avoid-Consecutive-Repeating-Characters)|49.2%|Easy|| +|1577|Number of Ways Where Square of Number Is Equal to Product of Two Numbers||39.9%|Medium|| +|1578|Minimum Time to Make Rope Colorful||63.7%|Medium|| +|1579|Remove Max Number of Edges to Keep Graph Fully Traversable|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1579.Remove-Max-Number-of-Edges-to-Keep-Graph-Fully-Traversable)|52.7%|Hard|| +|1580|Put Boxes Into the Warehouse II||63.5%|Medium|| +|1581|Customer Who Visited but Did Not Make Any Transactions||89.0%|Easy|| +|1582|Special Positions in a Binary Matrix||65.3%|Easy|| +|1583|Count Unhappy Friends||59.8%|Medium|| +|1584|Min Cost to Connect All Points||64.3%|Medium|| +|1585|Check If String Is Transformable With Substring Sort Operations||48.4%|Hard|| +|1586|Binary Search Tree Iterator II||70.8%|Medium|| +|1587|Bank Account Summary II||90.2%|Easy|| +|1588|Sum of All Odd Length Subarrays||83.6%|Easy|| +|1589|Maximum Sum Obtained of Any Permutation||37.0%|Medium|| +|1590|Make Sum Divisible by P||28.1%|Medium|| +|1591|Strange Printer II||58.4%|Hard|| +|1592|Rearrange Spaces Between Words||43.8%|Easy|| +|1593|Split a String Into the Max Number of Unique Substrings||55.1%|Medium|| +|1594|Maximum Non Negative Product in a Matrix||33.1%|Medium|| +|1595|Minimum Cost to Connect Two Groups of Points||46.3%|Hard|| +|1596|The Most Frequently Ordered Products for Each Customer||85.1%|Medium|| +|1597|Build Binary Expression Tree From Infix Expression||62.2%|Hard|| +|1598|Crawler Log Folder||64.3%|Easy|| |1599|Maximum Profit of Operating a Centennial Wheel||43.7%|Medium|| -|1600|Throne Inheritance||60.7%|Medium|| -|1601|Maximum Number of Achievable Transfer Requests||48.0%|Hard|| -|1602|Find Nearest Right Node in Binary Tree||73.4%|Medium|| -|1603|Design Parking System|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1603.Design-Parking-System)|86.3%|Easy|| -|1604|Alert Using Same Key-Card Three or More Times in a One Hour Period||43.0%|Medium|| -|1605|Find Valid Matrix Given Row and Column Sums||77.2%|Medium|| -|1606|Find Servers That Handled Most Number of Requests||37.6%|Hard|| -|1607|Sellers With No Sales||55.4%|Easy|| -|1608|Special Array With X Elements Greater Than or Equal X|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1608.Special-Array-With-X-Elements-Greater-Than-or-Equal-X)|61.4%|Easy|| -|1609|Even Odd Tree||52.2%|Medium|| -|1610|Maximum Number of Visible Points||31.3%|Hard|| -|1611|Minimum One Bit Operations to Make Integers Zero||58.0%|Hard|| +|1600|Throne Inheritance|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1600.Throne-Inheritance)|63.6%|Medium|| +|1601|Maximum Number of Achievable Transfer Requests||51.3%|Hard|| +|1602|Find Nearest Right Node in Binary Tree||75.3%|Medium|| +|1603|Design Parking System|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1603.Design-Parking-System)|88.1%|Easy|| +|1604|Alert Using Same Key-Card Three or More Times in a One Hour Period||47.4%|Medium|| +|1605|Find Valid Matrix Given Row and Column Sums||78.1%|Medium|| +|1606|Find Servers That Handled Most Number of Requests||42.8%|Hard|| +|1607|Sellers With No Sales||55.3%|Easy|| +|1608|Special Array With X Elements Greater Than or Equal X|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1608.Special-Array-With-X-Elements-Greater-Than-or-Equal-X)|60.0%|Easy|| +|1609|Even Odd Tree|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1609.Even-Odd-Tree)|53.6%|Medium|| +|1610|Maximum Number of Visible Points||37.4%|Hard|| +|1611|Minimum One Bit Operations to Make Integers Zero||63.2%|Hard|| |1612|Check If Two Expression Trees are Equivalent||69.9%|Medium|| -|1613|Find the Missing IDs||74.7%|Medium|| +|1613|Find the Missing IDs||75.9%|Medium|| |1614|Maximum Nesting Depth of the Parentheses|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1614.Maximum-Nesting-Depth-of-the-Parentheses)|82.7%|Easy|| -|1615|Maximal Network Rank||53.2%|Medium|| -|1616|Split Two Strings to Make Palindrome||36.1%|Medium|| -|1617|Count Subtrees With Max Distance Between Cities||63.3%|Hard|| -|1618|Maximum Font to Fit a Sentence in a Screen||57.4%|Medium|| -|1619|Mean of Array After Removing Some Elements|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1619.Mean-of-Array-After-Removing-Some-Elements)|64.5%|Easy|| -|1620|Coordinate With Maximum Network Quality||37.2%|Medium|| -|1621|Number of Sets of K Non-Overlapping Line Segments||41.6%|Medium|| -|1622|Fancy Sequence||14.8%|Hard|| -|1623|All Valid Triplets That Can Represent a Country||89.1%|Easy|| -|1624|Largest Substring Between Two Equal Characters|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1624.Largest-Substring-Between-Two-Equal-Characters)|58.5%|Easy|| -|1625|Lexicographically Smallest String After Applying Operations||64.4%|Medium|| -|1626|Best Team With No Conflicts||38.6%|Medium|| -|1627|Graph Connectivity With Threshold||40.5%|Hard|| -|1628|Design an Expression Tree With Evaluate Function||80.4%|Medium|| -|1629|Slowest Key|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1629.Slowest-Key)|59.2%|Easy|| -|1630|Arithmetic Subarrays||77.6%|Medium|| -|1631|Path With Minimum Effort|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1631.Path-With-Minimum-Effort)|50.0%|Medium|| -|1632|Rank Transform of a Matrix||32.4%|Hard|| -|1633|Percentage of Users Attended a Contest||71.3%|Easy|| -|1634|Add Two Polynomials Represented as Linked Lists||53.9%|Medium|| -|1635|Hopper Company Queries I||56.1%|Hard|| -|1636|Sort Array by Increasing Frequency|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1636.Sort-Array-by-Increasing-Frequency)|67.0%|Easy|| -|1637|Widest Vertical Area Between Two Points Containing No Points||83.7%|Medium|| -|1638|Count Substrings That Differ by One Character||70.4%|Medium|| -|1639|Number of Ways to Form a Target String Given a Dictionary||40.1%|Hard|| -|1640|Check Array Formation Through Concatenation|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1640.Check-Array-Formation-Through-Concatenation)|59.7%|Easy|| -|1641|Count Sorted Vowel Strings|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1641.Count-Sorted-Vowel-Strings)|75.4%|Medium|| -|1642|Furthest Building You Can Reach|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1642.Furthest-Building-You-Can-Reach)|47.3%|Medium|| -|1643|Kth Smallest Instructions||44.8%|Hard|| -|1644|Lowest Common Ancestor of a Binary Tree II||56.3%|Medium|| -|1645|Hopper Company Queries II||39.3%|Hard|| -|1646|Get Maximum in Generated Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1646.Get-Maximum-in-Generated-Array)|53.1%|Easy|| -|1647|Minimum Deletions to Make Character Frequencies Unique|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1647.Minimum-Deletions-to-Make-Character-Frequencies-Unique)|55.6%|Medium|| -|1648|Sell Diminishing-Valued Colored Balls|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1648.Sell-Diminishing-Valued-Colored-Balls)|30.7%|Medium|| -|1649|Create Sorted Array through Instructions|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1649.Create-Sorted-Array-through-Instructions)|36.7%|Hard|| -|1650|Lowest Common Ancestor of a Binary Tree III||76.8%|Medium|| -|1651|Hopper Company Queries III||66.6%|Hard|| -|1652|Defuse the Bomb|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1652.Defuse-the-Bomb)|61.6%|Easy|| -|1653|Minimum Deletions to Make String Balanced|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1653.Minimum-Deletions-to-Make-String-Balanced)|51.8%|Medium|| -|1654|Minimum Jumps to Reach Home|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1654.Minimum-Jumps-to-Reach-Home)|24.9%|Medium|| -|1655|Distribute Repeating Integers|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1655.Distribute-Repeating-Integers)|40.0%|Hard|| -|1656|Design an Ordered Stream|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1656.Design-an-Ordered-Stream)|81.9%|Easy|| -|1657|Determine if Two Strings Are Close|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1657.Determine-if-Two-Strings-Are-Close)|55.1%|Medium|| -|1658|Minimum Operations to Reduce X to Zero|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1658.Minimum-Operations-to-Reduce-X-to-Zero)|33.3%|Medium|| -|1659|Maximize Grid Happiness|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1659.Maximize-Grid-Happiness)|35.6%|Hard|| -|1660|Correct a Binary Tree||76.0%|Medium|| -|1661|Average Time of Process per Machine||79.7%|Easy|| -|1662|Check If Two String Arrays are Equivalent|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1662.Check-If-Two-String-Arrays-are-Equivalent)|82.5%|Easy|| -|1663|Smallest String With A Given Numeric Value|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1663.Smallest-String-With-A-Given-Numeric-Value)|64.2%|Medium|| -|1664|Ways to Make a Fair Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1664.Ways-to-Make-a-Fair-Array)|62.0%|Medium|| -|1665|Minimum Initial Energy to Finish Tasks|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1665.Minimum-Initial-Energy-to-Finish-Tasks)|64.7%|Hard|| -|1666|Change the Root of a Binary Tree||68.8%|Medium|| -|1667|Fix Names in a Table||62.6%|Easy|| -|1668|Maximum Repeating Substring|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1668.Maximum-Repeating-Substring)|38.6%|Easy|| -|1669|Merge In Between Linked Lists|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1669.Merge-In-Between-Linked-Lists)|75.5%|Medium|| -|1670|Design Front Middle Back Queue|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1670.Design-Front-Middle-Back-Queue)|54.1%|Medium|| -|1671|Minimum Number of Removals to Make Mountain Array||45.0%|Hard|| -|1672|Richest Customer Wealth|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1672.Richest-Customer-Wealth)|88.2%|Easy|| -|1673|Find the Most Competitive Subsequence|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1673.Find-the-Most-Competitive-Subsequence)|45.5%|Medium|| -|1674|Minimum Moves to Make Array Complementary|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1674.Minimum-Moves-to-Make-Array-Complementary)|35.0%|Medium|| -|1675|Minimize Deviation in Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1675.Minimize-Deviation-in-Array)|48.2%|Hard|| -|1676|Lowest Common Ancestor of a Binary Tree IV||79.4%|Medium|| -|1677|Product's Worth Over Invoices||65.9%|Easy|| -|1678|Goal Parser Interpretation|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1678.Goal-Parser-Interpretation)|85.2%|Easy|| -|1679|Max Number of K-Sum Pairs|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1679.Max-Number-of-K-Sum-Pairs)|53.7%|Medium|| -|1680|Concatenation of Consecutive Binary Numbers|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1680.Concatenation-of-Consecutive-Binary-Numbers)|52.3%|Medium|| -|1681|Minimum Incompatibility|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1681.Minimum-Incompatibility)|35.9%|Hard|| -|1682|Longest Palindromic Subsequence II||51.4%|Medium|| -|1683|Invalid Tweets||90.9%|Easy|| +|1615|Maximal Network Rank||58.1%|Medium|| +|1616|Split Two Strings to Make Palindrome||31.3%|Medium|| +|1617|Count Subtrees With Max Distance Between Cities||65.9%|Hard|| +|1618|Maximum Font to Fit a Sentence in a Screen||59.1%|Medium|| +|1619|Mean of Array After Removing Some Elements|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1619.Mean-of-Array-After-Removing-Some-Elements)|64.6%|Easy|| +|1620|Coordinate With Maximum Network Quality||37.3%|Medium|| +|1621|Number of Sets of K Non-Overlapping Line Segments||42.3%|Medium|| +|1622|Fancy Sequence||16.1%|Hard|| +|1623|All Valid Triplets That Can Represent a Country||88.0%|Easy|| +|1624|Largest Substring Between Two Equal Characters|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1624.Largest-Substring-Between-Two-Equal-Characters)|59.0%|Easy|| +|1625|Lexicographically Smallest String After Applying Operations||66.0%|Medium|| +|1626|Best Team With No Conflicts||41.1%|Medium|| +|1627|Graph Connectivity With Threshold||45.5%|Hard|| +|1628|Design an Expression Tree With Evaluate Function||82.7%|Medium|| +|1629|Slowest Key|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1629.Slowest-Key)|59.4%|Easy|| +|1630|Arithmetic Subarrays||79.9%|Medium|| +|1631|Path With Minimum Effort|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1631.Path-With-Minimum-Effort)|55.3%|Medium|| +|1632|Rank Transform of a Matrix||41.0%|Hard|| +|1633|Percentage of Users Attended a Contest||68.8%|Easy|| +|1634|Add Two Polynomials Represented as Linked Lists||53.4%|Medium|| +|1635|Hopper Company Queries I||53.0%|Hard|| +|1636|Sort Array by Increasing Frequency|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1636.Sort-Array-by-Increasing-Frequency)|68.6%|Easy|| +|1637|Widest Vertical Area Between Two Points Containing No Points||84.2%|Medium|| +|1638|Count Substrings That Differ by One Character||71.5%|Medium|| +|1639|Number of Ways to Form a Target String Given a Dictionary||42.9%|Hard|| +|1640|Check Array Formation Through Concatenation|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1640.Check-Array-Formation-Through-Concatenation)|56.1%|Easy|| +|1641|Count Sorted Vowel Strings|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1641.Count-Sorted-Vowel-Strings)|77.3%|Medium|| +|1642|Furthest Building You Can Reach|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1642.Furthest-Building-You-Can-Reach)|48.3%|Medium|| +|1643|Kth Smallest Instructions||46.3%|Hard|| +|1644|Lowest Common Ancestor of a Binary Tree II||59.3%|Medium|| +|1645|Hopper Company Queries II||38.8%|Hard|| +|1646|Get Maximum in Generated Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1646.Get-Maximum-in-Generated-Array)|50.2%|Easy|| +|1647|Minimum Deletions to Make Character Frequencies Unique|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1647.Minimum-Deletions-to-Make-Character-Frequencies-Unique)|59.2%|Medium|| +|1648|Sell Diminishing-Valued Colored Balls|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1648.Sell-Diminishing-Valued-Colored-Balls)|30.6%|Medium|| +|1649|Create Sorted Array through Instructions|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1649.Create-Sorted-Array-through-Instructions)|37.2%|Hard|| +|1650|Lowest Common Ancestor of a Binary Tree III||77.3%|Medium|| +|1651|Hopper Company Queries III||68.0%|Hard|| +|1652|Defuse the Bomb|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1652.Defuse-the-Bomb)|61.1%|Easy|| +|1653|Minimum Deletions to Make String Balanced|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1653.Minimum-Deletions-to-Make-String-Balanced)|58.7%|Medium|| +|1654|Minimum Jumps to Reach Home|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1654.Minimum-Jumps-to-Reach-Home)|28.6%|Medium|| +|1655|Distribute Repeating Integers|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1655.Distribute-Repeating-Integers)|39.7%|Hard|| +|1656|Design an Ordered Stream|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1656.Design-an-Ordered-Stream)|85.3%|Easy|| +|1657|Determine if Two Strings Are Close|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1657.Determine-if-Two-Strings-Are-Close)|54.2%|Medium|| +|1658|Minimum Operations to Reduce X to Zero|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1658.Minimum-Operations-to-Reduce-X-to-Zero)|37.6%|Medium|| +|1659|Maximize Grid Happiness|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1659.Maximize-Grid-Happiness)|38.4%|Hard|| +|1660|Correct a Binary Tree||72.5%|Medium|| +|1661|Average Time of Process per Machine||79.4%|Easy|| +|1662|Check If Two String Arrays are Equivalent|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1662.Check-If-Two-String-Arrays-are-Equivalent)|81.8%|Easy|| +|1663|Smallest String With A Given Numeric Value|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1663.Smallest-String-With-A-Given-Numeric-Value)|67.0%|Medium|| +|1664|Ways to Make a Fair Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1664.Ways-to-Make-a-Fair-Array)|63.6%|Medium|| +|1665|Minimum Initial Energy to Finish Tasks|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1665.Minimum-Initial-Energy-to-Finish-Tasks)|56.2%|Hard|| +|1666|Change the Root of a Binary Tree||69.4%|Medium|| +|1667|Fix Names in a Table||66.8%|Easy|| +|1668|Maximum Repeating Substring|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1668.Maximum-Repeating-Substring)|39.6%|Easy|| +|1669|Merge In Between Linked Lists|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1669.Merge-In-Between-Linked-Lists)|74.5%|Medium|| +|1670|Design Front Middle Back Queue|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1670.Design-Front-Middle-Back-Queue)|56.4%|Medium|| +|1671|Minimum Number of Removals to Make Mountain Array||42.6%|Hard|| +|1672|Richest Customer Wealth|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1672.Richest-Customer-Wealth)|88.4%|Easy|| +|1673|Find the Most Competitive Subsequence|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1673.Find-the-Most-Competitive-Subsequence)|49.3%|Medium|| +|1674|Minimum Moves to Make Array Complementary|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1674.Minimum-Moves-to-Make-Array-Complementary)|38.5%|Medium|| +|1675|Minimize Deviation in Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1675.Minimize-Deviation-in-Array)|52.1%|Hard|| +|1676|Lowest Common Ancestor of a Binary Tree IV||79.3%|Medium|| +|1677|Product's Worth Over Invoices||39.4%|Easy|| +|1678|Goal Parser Interpretation|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1678.Goal-Parser-Interpretation)|86.0%|Easy|| +|1679|Max Number of K-Sum Pairs|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1679.Max-Number-of-K-Sum-Pairs)|57.4%|Medium|| +|1680|Concatenation of Consecutive Binary Numbers|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1680.Concatenation-of-Consecutive-Binary-Numbers)|57.0%|Medium|| +|1681|Minimum Incompatibility|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1681.Minimum-Incompatibility)|37.3%|Hard|| +|1682|Longest Palindromic Subsequence II||49.7%|Medium|| +|1683|Invalid Tweets||91.0%|Easy|| |1684|Count the Number of Consistent Strings|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1684.Count-the-Number-of-Consistent-Strings)|81.8%|Easy|| -|1685|Sum of Absolute Differences in a Sorted Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1685.Sum-of-Absolute-Differences-in-a-Sorted-Array)|63.2%|Medium|| -|1686|Stone Game VI||50.1%|Medium|| -|1687|Delivering Boxes from Storage to Ports||35.3%|Hard|| -|1688|Count of Matches in Tournament|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1688.Count-of-Matches-in-Tournament)|81.5%|Easy|| -|1689|Partitioning Into Minimum Number Of Deci-Binary Numbers|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1689.Partitioning-Into-Minimum-Number-Of-Deci-Binary-Numbers)|87.0%|Medium|| -|1690|Stone Game VII|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1690.Stone-Game-VII)|49.2%|Medium|| -|1691|Maximum Height by Stacking Cuboids|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1691.Maximum-Height-by-Stacking-Cuboids)|50.5%|Hard|| -|1692|Count Ways to Distribute Candies||60.5%|Hard|| -|1693|Daily Leads and Partners||90.8%|Easy|| -|1694|Reformat Phone Number|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1694.Reformat-Phone-Number)|64.9%|Easy|| -|1695|Maximum Erasure Value|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1695.Maximum-Erasure-Value)|49.2%|Medium|| -|1696|Jump Game VI|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1696.Jump-Game-VI)|51.1%|Medium|| -|1697|Checking Existence of Edge Length Limited Paths||54.0%|Hard|| -|1698|Number of Distinct Substrings in a String||60.6%|Medium|| -|1699|Number of Calls Between Two Persons||86.8%|Medium|| -|1700|Number of Students Unable to Eat Lunch|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1700.Number-of-Students-Unable-to-Eat-Lunch)|67.6%|Easy|| -|1701|Average Waiting Time||61.2%|Medium|| -|1702|Maximum Binary String After Change||59.2%|Medium|| -|1703|Minimum Adjacent Swaps for K Consecutive Ones||40.0%|Hard|| -|1704|Determine if String Halves Are Alike|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1704.Determine-if-String-Halves-Are-Alike)|79.0%|Easy|| -|1705|Maximum Number of Eaten Apples||41.7%|Medium|| -|1706|Where Will the Ball Fall||60.8%|Medium|| -|1707|Maximum XOR With an Element From Array||46.4%|Hard|| -|1708|Largest Subarray Length K||63.2%|Easy|| -|1709|Biggest Window Between Visits||82.5%|Medium|| -|1710|Maximum Units on a Truck|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1710.Maximum-Units-on-a-Truck)|69.9%|Easy|| -|1711|Count Good Meals||26.5%|Medium|| -|1712|Ways to Split Array Into Three Subarrays||29.2%|Medium|| -|1713|Minimum Operations to Make a Subsequence||45.6%|Hard|| -|1714|Sum Of Special Evenly-Spaced Elements In Array||49.0%|Hard|| -|1715|Count Apples and Oranges||79.0%|Medium|| -|1716|Calculate Money in Leetcode Bank|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1716.Calculate-Money-in-Leetcode-Bank)|64.6%|Easy|| -|1717|Maximum Score From Removing Substrings||41.2%|Medium|| -|1718|Construct the Lexicographically Largest Valid Sequence||47.1%|Medium|| -|1719|Number Of Ways To Reconstruct A Tree||39.2%|Hard|| -|1720|Decode XORed Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1720.Decode-XORed-Array)|85.1%|Easy|| -|1721|Swapping Nodes in a Linked List|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1721.Swapping-Nodes-in-a-Linked-List)|67.3%|Medium|| -|1722|Minimize Hamming Distance After Swap Operations||54.3%|Medium|| -|1723|Find Minimum Time to Finish All Jobs||43.8%|Hard|| -|1724|Checking Existence of Edge Length Limited Paths II||57.5%|Hard|| -|1725|Number Of Rectangles That Can Form The Largest Square|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1725.Number-Of-Rectangles-That-Can-Form-The-Largest-Square)|78.0%|Easy|| -|1726|Tuple with Same Product||57.2%|Medium|| -|1727|Largest Submatrix With Rearrangements||58.9%|Medium|| -|1728|Cat and Mouse II||41.0%|Hard|| -|1729|Find Followers Count||70.9%|Easy|| -|1730|Shortest Path to Get Food||54.7%|Medium|| -|1731|The Number of Employees Which Report to Each Employee||49.4%|Easy|| -|1732|Find the Highest Altitude|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1732.Find-the-Highest-Altitude)|79.7%|Easy|| -|1733|Minimum Number of People to Teach||38.0%|Medium|| -|1734|Decode XORed Permutation||54.5%|Medium|| -|1735|Count Ways to Make Array With Product||48.1%|Hard|| -|1736|Latest Time by Replacing Hidden Digits|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1736.Latest-Time-by-Replacing-Hidden-Digits)|41.2%|Easy|| -|1737|Change Minimum Characters to Satisfy One of Three Conditions||30.1%|Medium|| -|1738|Find Kth Largest XOR Coordinate Value||62.5%|Medium|| -|1739|Building Boxes||49.4%|Hard|| -|1740|Find Distance in a Binary Tree||67.8%|Medium|| -|1741|Find Total Time Spent by Each Employee||90.7%|Easy|| -|1742|Maximum Number of Balls in a Box|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1742.Maximum-Number-of-Balls-in-a-Box)|73.5%|Easy|| -|1743|Restore the Array From Adjacent Pairs||63.6%|Medium|| -|1744|Can You Eat Your Favorite Candy on Your Favorite Day?||30.8%|Medium|| -|1745|Palindrome Partitioning IV||49.4%|Hard|| -|1746|Maximum Subarray Sum After One Operation||62.1%|Medium|| -|1747|Leetflex Banned Accounts||68.8%|Medium|| -|1748|Sum of Unique Elements|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1748.Sum-of-Unique-Elements)|74.7%|Easy|| -|1749|Maximum Absolute Sum of Any Subarray||52.7%|Medium|| -|1750|Minimum Length of String After Deleting Similar Ends||42.3%|Medium|| -|1751|Maximum Number of Events That Can Be Attended II||48.5%|Hard|| -|1752|Check if Array Is Sorted and Rotated|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1752.Check-if-Array-Is-Sorted-and-Rotated)|60.0%|Easy|| -|1753|Maximum Score From Removing Stones||62.0%|Medium|| -|1754|Largest Merge Of Two Strings||40.9%|Medium|| -|1755|Closest Subsequence Sum||35.8%|Hard|| -|1756|Design Most Recently Used Queue||77.7%|Medium|| -|1757|Recyclable and Low Fat Products||95.6%|Easy|| -|1758|Minimum Changes To Make Alternating Binary String|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1758.Minimum-Changes-To-Make-Alternating-Binary-String)|58.0%|Easy|| -|1759|Count Number of Homogenous Substrings||42.9%|Medium|| -|1760|Minimum Limit of Balls in a Bag||53.1%|Medium|| -|1761|Minimum Degree of a Connected Trio in a Graph||37.6%|Hard|| -|1762|Buildings With an Ocean View||81.3%|Medium|| -|1763|Longest Nice Substring||61.3%|Easy|| -|1764|Form Array by Concatenating Subarrays of Another Array||54.3%|Medium|| -|1765|Map of Highest Peak||55.4%|Medium|| -|1766|Tree of Coprimes||36.7%|Hard|| -|1767|Find the Subtasks That Did Not Execute||86.2%|Hard|| -|1768|Merge Strings Alternately||75.3%|Easy|| -|1769|Minimum Number of Operations to Move All Balls to Each Box||86.5%|Medium|| -|1770|Maximum Score from Performing Multiplication Operations||29.8%|Medium|| -|1771|Maximize Palindrome Length From Subsequences||34.2%|Hard|| -|1772|Sort Features by Popularity||65.2%|Medium|| -|1773|Count Items Matching a Rule||84.9%|Easy|| -|1774|Closest Dessert Cost||57.6%|Medium|| -|1775|Equal Sum Arrays With Minimum Number of Operations||50.6%|Medium|| -|1776|Car Fleet II||47.5%|Hard|| -|1777|Product's Price for Each Store||87.4%|Easy|| -|1778|Shortest Path in a Hidden Grid||45.7%|Medium|| -|1779|Find Nearest Point That Has the Same X or Y Coordinate||66.9%|Easy|| -|1780|Check if Number is a Sum of Powers of Three||63.1%|Medium|| -|1781|Sum of Beauty of All Substrings||58.2%|Medium|| -|1782|Count Pairs Of Nodes||33.2%|Hard|| -|1783|Grand Slam Titles||90.8%|Medium|| -|1784|Check if Binary String Has at Most One Segment of Ones||41.5%|Easy|| -|1785|Minimum Elements to Add to Form a Given Sum||39.4%|Medium|| -|1786|Number of Restricted Paths From First to Last Node||36.1%|Medium|| -|1787|Make the XOR of All Segments Equal to Zero||36.8%|Hard|| -|1788|Maximize the Beauty of the Garden||69.0%|Hard|| -|1789|Primary Department for Each Employee||78.8%|Easy|| -|1790|Check if One String Swap Can Make Strings Equal||58.8%|Easy|| -|1791|Find Center of Star Graph||84.5%|Medium|| -|1792|Maximum Average Pass Ratio||55.9%|Medium|| -|1793|Maximum Score of a Good Subarray||46.7%|Hard|| -|1794|Count Pairs of Equal Substrings With Minimum Difference||68.6%|Medium|| -|1795|Rearrange Products Table||90.5%|Easy|| -|1796|Second Largest Digit in a String||48.0%|Easy|| -|1797|Design Authentication Manager||49.1%|Medium|| -|1798|Maximum Number of Consecutive Values You Can Make||44.9%|Medium|| -|1799|Maximize Score After N Operations||49.9%|Hard|| -|1800|Maximum Ascending Subarray Sum||65.1%|Easy|| -|1801|Number of Orders in the Backlog||43.8%|Medium|| -|1802|Maximum Value at a Given Index in a Bounded Array||27.7%|Medium|| -|1803|Count Pairs With XOR in a Range||43.7%|Hard|| -|1804|Implement Trie II (Prefix Tree)||59.3%|Medium|| -|1805|Number of Different Integers in a String||47.7%|Easy|| -|1806|Minimum Number of Operations to Reinitialize a Permutation||70.4%|Medium|| -|1807|Evaluate the Bracket Pairs of a String||66.5%|Medium|| -|1808|Maximize Number of Nice Divisors||27.7%|Hard|| -|1809|Ad-Free Sessions||66.3%|Easy|| -|1810|Minimum Path Cost in a Hidden Grid||53.4%|Medium|| -|1811|Find Interview Candidates||70.7%|Medium|| -|1812|Determine Color of a Chessboard Square||78.3%|Easy|| -|1813|Sentence Similarity III||43.8%|Medium|| -|1814|Count Nice Pairs in an Array||38.5%|Medium|| -|1815|Maximum Number of Groups Getting Fresh Donuts||38.9%|Hard|| -|1816|Truncate Sentence||78.8%|Easy|| -|1817|Finding the Users Active Minutes||78.7%|Medium|| -|1818|Minimum Absolute Sum Difference||41.8%|Medium|| -|1819|Number of Different Subsequences GCDs||33.0%|Hard|| +|1685|Sum of Absolute Differences in a Sorted Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1685.Sum-of-Absolute-Differences-in-a-Sorted-Array)|65.3%|Medium|| +|1686|Stone Game VI||54.3%|Medium|| +|1687|Delivering Boxes from Storage to Ports||38.2%|Hard|| +|1688|Count of Matches in Tournament|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1688.Count-of-Matches-in-Tournament)|83.1%|Easy|| +|1689|Partitioning Into Minimum Number Of Deci-Binary Numbers|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1689.Partitioning-Into-Minimum-Number-Of-Deci-Binary-Numbers)|89.7%|Medium|| +|1690|Stone Game VII|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1690.Stone-Game-VII)|58.7%|Medium|| +|1691|Maximum Height by Stacking Cuboids|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1691.Maximum-Height-by-Stacking-Cuboids)|54.2%|Hard|| +|1692|Count Ways to Distribute Candies||62.0%|Hard|| +|1693|Daily Leads and Partners||90.4%|Easy|| +|1694|Reformat Phone Number|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1694.Reformat-Phone-Number)|64.7%|Easy|| +|1695|Maximum Erasure Value|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1695.Maximum-Erasure-Value)|57.7%|Medium|| +|1696|Jump Game VI|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1696.Jump-Game-VI)|46.3%|Medium|| +|1697|Checking Existence of Edge Length Limited Paths||50.5%|Hard|| +|1698|Number of Distinct Substrings in a String||63.1%|Medium|| +|1699|Number of Calls Between Two Persons||85.8%|Medium|| +|1700|Number of Students Unable to Eat Lunch|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1700.Number-of-Students-Unable-to-Eat-Lunch)|67.7%|Easy|| +|1701|Average Waiting Time||62.3%|Medium|| +|1702|Maximum Binary String After Change||46.1%|Medium|| +|1703|Minimum Adjacent Swaps for K Consecutive Ones||41.3%|Hard|| +|1704|Determine if String Halves Are Alike|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1704.Determine-if-String-Halves-Are-Alike)|77.4%|Easy|| +|1705|Maximum Number of Eaten Apples|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1705.Maximum-Number-of-Eaten-Apples)|37.9%|Medium|| +|1706|Where Will the Ball Fall||65.8%|Medium|| +|1707|Maximum XOR With an Element From Array||44.3%|Hard|| +|1708|Largest Subarray Length K||63.5%|Easy|| +|1709|Biggest Window Between Visits||77.8%|Medium|| +|1710|Maximum Units on a Truck|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1710.Maximum-Units-on-a-Truck)|74.0%|Easy|| +|1711|Count Good Meals||29.0%|Medium|| +|1712|Ways to Split Array Into Three Subarrays||32.4%|Medium|| +|1713|Minimum Operations to Make a Subsequence||49.2%|Hard|| +|1714|Sum Of Special Evenly-Spaced Elements In Array||49.8%|Hard|| +|1715|Count Apples and Oranges||77.8%|Medium|| +|1716|Calculate Money in Leetcode Bank|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1716.Calculate-Money-in-Leetcode-Bank)|65.0%|Easy|| +|1717|Maximum Score From Removing Substrings||46.0%|Medium|| +|1718|Construct the Lexicographically Largest Valid Sequence||51.7%|Medium|| +|1719|Number Of Ways To Reconstruct A Tree||42.5%|Hard|| +|1720|Decode XORed Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1720.Decode-XORed-Array)|86.0%|Easy|| +|1721|Swapping Nodes in a Linked List|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1721.Swapping-Nodes-in-a-Linked-List)|67.8%|Medium|| +|1722|Minimize Hamming Distance After Swap Operations||48.6%|Medium|| +|1723|Find Minimum Time to Finish All Jobs||42.7%|Hard|| +|1724|Checking Existence of Edge Length Limited Paths II||51.3%|Hard|| +|1725|Number Of Rectangles That Can Form The Largest Square|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1725.Number-Of-Rectangles-That-Can-Form-The-Largest-Square)|78.7%|Easy|| +|1726|Tuple with Same Product||60.7%|Medium|| +|1727|Largest Submatrix With Rearrangements||60.8%|Medium|| +|1728|Cat and Mouse II||40.5%|Hard|| +|1729|Find Followers Count||71.6%|Easy|| +|1730|Shortest Path to Get Food||54.0%|Medium|| +|1731|The Number of Employees Which Report to Each Employee||51.1%|Easy|| +|1732|Find the Highest Altitude|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1732.Find-the-Highest-Altitude)|78.7%|Easy|| +|1733|Minimum Number of People to Teach||41.6%|Medium|| +|1734|Decode XORed Permutation|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1734.Decode-XORed-Permutation)|62.2%|Medium|| +|1735|Count Ways to Make Array With Product||49.2%|Hard|| +|1736|Latest Time by Replacing Hidden Digits|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1736.Latest-Time-by-Replacing-Hidden-Digits)|42.2%|Easy|| +|1737|Change Minimum Characters to Satisfy One of Three Conditions||35.2%|Medium|| +|1738|Find Kth Largest XOR Coordinate Value|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1738.Find-Kth-Largest-XOR-Coordinate-Value)|61.6%|Medium|| +|1739|Building Boxes||51.7%|Hard|| +|1740|Find Distance in a Binary Tree||68.7%|Medium|| +|1741|Find Total Time Spent by Each Employee||92.0%|Easy|| +|1742|Maximum Number of Balls in a Box|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1742.Maximum-Number-of-Balls-in-a-Box)|73.9%|Easy|| +|1743|Restore the Array From Adjacent Pairs||68.7%|Medium|| +|1744|Can You Eat Your Favorite Candy on Your Favorite Day?|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1744.Can-You-Eat-Your-Favorite-Candy-on-Your-Favorite-Day)|32.8%|Medium|| +|1745|Palindrome Partitioning IV||46.3%|Hard|| +|1746|Maximum Subarray Sum After One Operation||62.2%|Medium|| +|1747|Leetflex Banned Accounts||68.2%|Medium|| +|1748|Sum of Unique Elements|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1748.Sum-of-Unique-Elements)|75.6%|Easy|| +|1749|Maximum Absolute Sum of Any Subarray||58.2%|Medium|| +|1750|Minimum Length of String After Deleting Similar Ends||43.6%|Medium|| +|1751|Maximum Number of Events That Can Be Attended II||55.8%|Hard|| +|1752|Check if Array Is Sorted and Rotated|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1752.Check-if-Array-Is-Sorted-and-Rotated)|49.2%|Easy|| +|1753|Maximum Score From Removing Stones||66.1%|Medium|| +|1754|Largest Merge Of Two Strings||45.0%|Medium|| +|1755|Closest Subsequence Sum||36.6%|Hard|| +|1756|Design Most Recently Used Queue||79.0%|Medium|| +|1757|Recyclable and Low Fat Products||93.9%|Easy|| +|1758|Minimum Changes To Make Alternating Binary String|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1758.Minimum-Changes-To-Make-Alternating-Binary-String)|58.3%|Easy|| +|1759|Count Number of Homogenous Substrings||47.8%|Medium|| +|1760|Minimum Limit of Balls in a Bag||60.3%|Medium|| +|1761|Minimum Degree of a Connected Trio in a Graph||41.7%|Hard|| +|1762|Buildings With an Ocean View||79.2%|Medium|| +|1763|Longest Nice Substring|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1763.Longest-Nice-Substring)|61.7%|Easy|| +|1764|Form Array by Concatenating Subarrays of Another Array||52.7%|Medium|| +|1765|Map of Highest Peak||60.3%|Medium|| +|1766|Tree of Coprimes||38.5%|Hard|| +|1767|Find the Subtasks That Did Not Execute||84.7%|Hard|| +|1768|Merge Strings Alternately||75.9%|Easy|| +|1769|Minimum Number of Operations to Move All Balls to Each Box||85.4%|Medium|| +|1770|Maximum Score from Performing Multiplication Operations||36.3%|Hard|| +|1771|Maximize Palindrome Length From Subsequences||35.2%|Hard|| +|1772|Sort Features by Popularity||65.1%|Medium|| +|1773|Count Items Matching a Rule||84.3%|Easy|| +|1774|Closest Dessert Cost||46.7%|Medium|| +|1775|Equal Sum Arrays With Minimum Number of Operations||52.6%|Medium|| +|1776|Car Fleet II||53.3%|Hard|| +|1777|Product's Price for Each Store||85.4%|Easy|| +|1778|Shortest Path in a Hidden Grid||39.7%|Medium|| +|1779|Find Nearest Point That Has the Same X or Y Coordinate||67.2%|Easy|| +|1780|Check if Number is a Sum of Powers of Three||65.3%|Medium|| +|1781|Sum of Beauty of All Substrings||60.4%|Medium|| +|1782|Count Pairs Of Nodes||37.9%|Hard|| +|1783|Grand Slam Titles||88.9%|Medium|| +|1784|Check if Binary String Has at Most One Segment of Ones||40.5%|Easy|| +|1785|Minimum Elements to Add to Form a Given Sum||42.4%|Medium|| +|1786|Number of Restricted Paths From First to Last Node||39.2%|Medium|| +|1787|Make the XOR of All Segments Equal to Zero||39.5%|Hard|| +|1788|Maximize the Beauty of the Garden||66.4%|Hard|| +|1789|Primary Department for Each Employee||80.0%|Easy|| +|1790|Check if One String Swap Can Make Strings Equal||45.6%|Easy|| +|1791|Find Center of Star Graph|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1791.Find-Center-of-Star-Graph)|83.6%|Easy|| +|1792|Maximum Average Pass Ratio||51.9%|Medium|| +|1793|Maximum Score of a Good Subarray||53.2%|Hard|| +|1794|Count Pairs of Equal Substrings With Minimum Difference||65.2%|Medium|| +|1795|Rearrange Products Table||90.4%|Easy|| +|1796|Second Largest Digit in a String||49.0%|Easy|| +|1797|Design Authentication Manager||56.1%|Medium|| +|1798|Maximum Number of Consecutive Values You Can Make||54.1%|Medium|| +|1799|Maximize Score After N Operations||45.7%|Hard|| +|1800|Maximum Ascending Subarray Sum||63.8%|Easy|| +|1801|Number of Orders in the Backlog||47.2%|Medium|| +|1802|Maximum Value at a Given Index in a Bounded Array||31.8%|Medium|| +|1803|Count Pairs With XOR in a Range||46.8%|Hard|| +|1804|Implement Trie II (Prefix Tree)||59.8%|Medium|| +|1805|Number of Different Integers in a String||36.1%|Easy|| +|1806|Minimum Number of Operations to Reinitialize a Permutation||71.3%|Medium|| +|1807|Evaluate the Bracket Pairs of a String||66.7%|Medium|| +|1808|Maximize Number of Nice Divisors||31.2%|Hard|| +|1809|Ad-Free Sessions||60.0%|Easy|| +|1810|Minimum Path Cost in a Hidden Grid||53.8%|Medium|| +|1811|Find Interview Candidates||65.3%|Medium|| +|1812|Determine Color of a Chessboard Square||77.4%|Easy|| +|1813|Sentence Similarity III||33.0%|Medium|| +|1814|Count Nice Pairs in an Array||41.9%|Medium|| +|1815|Maximum Number of Groups Getting Fresh Donuts||40.1%|Hard|| +|1816|Truncate Sentence|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1816.Truncate-Sentence)|81.9%|Easy|| +|1817|Finding the Users Active Minutes||80.7%|Medium|| +|1818|Minimum Absolute Sum Difference|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1818.Minimum-Absolute-Sum-Difference)|30.1%|Medium|| +|1819|Number of Different Subsequences GCDs||37.9%|Hard|| |1820|Maximum Number of Accepted Invitations||49.7%|Medium|| |1821|Find Customers With Positive Revenue this Year||89.4%|Easy|| -|1822|Sign of the Product of an Array||80.8%|Easy|| -|1823|Find the Winner of the Circular Game||72.0%|Medium|| -|1824|Minimum Sideway Jumps||59.4%|Medium|| -|1825|Finding MK Average||31.3%|Hard|| -|1826|Faulty Sensor||60.0%|Easy|| -|1827|Minimum Operations to Make the Array Increasing||79.2%|Easy|| -|1828|Queries on Number of Points Inside a Circle||87.9%|Medium|| -|1829|Maximum XOR for Each Query||72.6%|Medium|| -|1830|Minimum Number of Operations to Make String Sorted||46.2%|Hard|| -|1831|Maximum Transaction Each Day||87.6%|Medium|| -|1832|Check if the Sentence Is Pangram||85.0%|Easy|| -|1833|Maximum Ice Cream Bars||88.4%|Medium|| -|1834|Single-Threaded CPU||40.2%|Medium|| -|1835|Find XOR Sum of All Pairs Bitwise AND||55.0%|Hard|| -|1836|Remove Duplicates From an Unsorted Linked List||76.8%|Medium|| -|1837|Sum of Digits in Base K||75.4%|Easy|| -|1838|Frequency of the Most Frequent Element||30.7%|Medium|| +|1822|Sign of the Product of an Array||66.3%|Easy|| +|1823|Find the Winner of the Circular Game||77.7%|Medium|| +|1824|Minimum Sideway Jumps||49.8%|Medium|| +|1825|Finding MK Average||35.1%|Hard|| +|1826|Faulty Sensor||49.5%|Easy|| +|1827|Minimum Operations to Make the Array Increasing||78.2%|Easy|| +|1828|Queries on Number of Points Inside a Circle||86.5%|Medium|| +|1829|Maximum XOR for Each Query||77.0%|Medium|| +|1830|Minimum Number of Operations to Make String Sorted||49.2%|Hard|| +|1831|Maximum Transaction Each Day||84.3%|Medium|| +|1832|Check if the Sentence Is Pangram||83.9%|Easy|| +|1833|Maximum Ice Cream Bars||65.5%|Medium|| +|1834|Single-Threaded CPU||41.9%|Medium|| +|1835|Find XOR Sum of All Pairs Bitwise AND||60.0%|Hard|| +|1836|Remove Duplicates From an Unsorted Linked List||69.3%|Medium|| +|1837|Sum of Digits in Base K||76.8%|Easy|| +|1838|Frequency of the Most Frequent Element||38.3%|Medium|| |1839|Longest Substring Of All Vowels in Order||48.5%|Medium|| -|1840|Maximum Building Height||33.3%|Hard|| -|1841|League Statistics||66.3%|Medium|| +|1840|Maximum Building Height||35.3%|Hard|| +|1841|League Statistics||57.4%|Medium|| +|1842|Next Palindrome Using Same Digits||53.6%|Hard|| +|1843|Suspicious Bank Accounts||48.0%|Medium|| +|1844|Replace All Digits with Characters||79.7%|Easy|| +|1845|Seat Reservation Manager||64.2%|Medium|| +|1846|Maximum Element After Decreasing and Rearranging|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1846.Maximum-Element-After-Decreasing-and-Rearranging)|59.1%|Medium|| +|1847|Closest Room||35.1%|Hard|| +|1848|Minimum Distance to the Target Element||58.6%|Easy|| +|1849|Splitting a String Into Descending Consecutive Values||32.1%|Medium|| +|1850|Minimum Adjacent Swaps to Reach the Kth Smallest Number||72.0%|Medium|| +|1851|Minimum Interval to Include Each Query||47.7%|Hard|| +|1852|Distinct Numbers in Each Subarray||71.5%|Medium|| +|1853|Convert Date Format||88.0%|Easy|| +|1854|Maximum Population Year||59.8%|Easy|| +|1855|Maximum Distance Between a Pair of Values||52.6%|Medium|| +|1856|Maximum Subarray Min-Product||37.7%|Medium|| +|1857|Largest Color Value in a Directed Graph||40.6%|Hard|| +|1858|Longest Word With All Prefixes||66.3%|Medium|| +|1859|Sorting the Sentence||84.4%|Easy|| +|1860|Incremental Memory Leak||71.6%|Medium|| +|1861|Rotating the Box||64.7%|Medium|| +|1862|Sum of Floored Pairs||28.3%|Hard|| +|1863|Sum of All Subset XOR Totals||79.0%|Easy|| +|1864|Minimum Number of Swaps to Make the Binary String Alternating||42.0%|Medium|| +|1865|Finding Pairs With a Certain Sum||50.3%|Medium|| +|1866|Number of Ways to Rearrange Sticks With K Sticks Visible||55.4%|Hard|| +|1867|Orders With Maximum Quantity Above Average||75.9%|Medium|| +|1868|Product of Two Run-Length Encoded Arrays||57.8%|Medium|| +|1869|Longer Contiguous Segments of Ones than Zeros||60.2%|Easy|| +|1870|Minimum Speed to Arrive on Time||37.3%|Medium|| +|1871|Jump Game VII||25.1%|Medium|| +|1872|Stone Game VIII||52.4%|Hard|| +|1873|Calculate Special Bonus||64.7%|Easy|| +|1874|Minimize Product Sum of Two Arrays||90.4%|Medium|| +|1875|Group Employees of the Same Salary||75.6%|Medium|| +|1876|Substrings of Size Three with Distinct Characters||70.2%|Easy|| +|1877|Minimize Maximum Pair Sum in Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1877.Minimize-Maximum-Pair-Sum-in-Array)|80.4%|Medium|| +|1878|Get Biggest Three Rhombus Sums in a Grid||46.4%|Medium|| +|1879|Minimum XOR Sum of Two Arrays||44.6%|Hard|| +|1880|Check if Word Equals Summation of Two Words||73.6%|Easy|| +|1881|Maximum Value after Insertion||36.5%|Medium|| +|1882|Process Tasks Using Servers||39.5%|Medium|| +|1883|Minimum Skips to Arrive at Meeting On Time||38.5%|Hard|| +|1884|Egg Drop With 2 Eggs and N Floors||70.3%|Medium|| +|1885|Count Pairs in Two Arrays||59.2%|Medium|| +|1886|Determine Whether Matrix Can Be Obtained By Rotation||55.3%|Easy|| +|1887|Reduction Operations to Make the Array Elements Equal||62.3%|Medium|| +|1888|Minimum Number of Flips to Make the Binary String Alternating||37.8%|Medium|| +|1889|Minimum Space Wasted From Packaging||30.6%|Hard|| +|1890|The Latest Login in 2020||81.8%|Easy|| +|1891|Cutting Ribbons||48.1%|Medium|| +|1892|Page Recommendations II||44.8%|Hard|| +|1893|Check if All the Integers in a Range Are Covered||50.8%|Easy|| +|1894|Find the Student that Will Replace the Chalk||43.6%|Medium|| +|1895|Largest Magic Square||51.9%|Medium|| +|1896|Minimum Cost to Change the Final Value of Expression||54.9%|Hard|| +|1897|Redistribute Characters to Make All Strings Equal||60.0%|Easy|| +|1898|Maximum Number of Removable Characters||39.2%|Medium|| +|1899|Merge Triplets to Form Target Triplet||64.3%|Medium|| +|1900|The Earliest and Latest Rounds Where Players Compete||51.8%|Hard|| +|1901|Find a Peak Element II||53.3%|Medium|| +|1902|Depth of BST Given Insertion Order||45.0%|Medium|| +|1903|Largest Odd Number in String||55.7%|Easy|| +|1904|The Number of Full Rounds You Have Played||45.7%|Medium|| +|1905|Count Sub Islands||67.9%|Medium|| +|1906|Minimum Absolute Difference Queries||43.9%|Medium|| +|1907|Count Salary Categories||64.6%|Medium|| +|1908|Game of Nim||57.3%|Medium|| +|1909|Remove One Element to Make the Array Strictly Increasing||26.0%|Easy|| +|1910|Remove All Occurrences of a Substring||74.0%|Medium|| +|1911|Maximum Alternating Subsequence Sum||59.2%|Medium|| +|1912|Design Movie Rental System||41.2%|Hard|| +|1913|Maximum Product Difference Between Two Pairs||81.4%|Easy|| +|1914|Cyclically Rotating a Grid||48.0%|Medium|| +|1915|Number of Wonderful Substrings||44.8%|Medium|| +|1916|Count Ways to Build Rooms in an Ant Colony||48.7%|Hard|| +|1917|Leetcodify Friends Recommendations||28.9%|Hard|| +|1918|Kth Smallest Subarray Sum||52.9%|Medium|| +|1919|Leetcodify Similar Friends||43.2%|Hard|| +|1920|Build Array from Permutation||91.5%|Easy|| +|1921|Eliminate Maximum Number of Monsters||37.8%|Medium|| +|1922|Count Good Numbers||38.5%|Medium|| +|1923|Longest Common Subpath||27.6%|Hard|| +|1924|Erect the Fence II||53.9%|Hard|| +|1925|Count Square Sum Triples||67.9%|Easy|| +|1926|Nearest Exit from Entrance in Maze||43.1%|Medium|| +|1927|Sum Game||47.0%|Medium|| +|1928|Minimum Cost to Reach Destination in Time||37.6%|Hard|| +|1929|Concatenation of Array||91.5%|Easy|| +|1930|Unique Length-3 Palindromic Subsequences||51.8%|Medium|| +|1931|Painting a Grid With Three Different Colors||57.3%|Hard|| +|1932|Merge BSTs to Create Single BST||35.3%|Hard|| +|1933|Check if String Is Decomposable Into Value-Equal Substrings||50.4%|Easy|| +|1934|Confirmation Rate||77.8%|Medium|| +|1935|Maximum Number of Words You Can Type||71.0%|Easy|| +|1936|Add Minimum Number of Rungs||42.8%|Medium|| +|1937|Maximum Number of Points with Cost||36.2%|Medium|| +|1938|Maximum Genetic Difference Query||39.5%|Hard|| +|1939|Users That Actively Request Confirmation Messages||61.7%|Easy|| +|1940|Longest Common Subsequence Between Sorted Arrays||79.4%|Medium|| +|1941|Check if All Characters Have Equal Number of Occurrences||76.9%|Easy|| +|1942|The Number of the Smallest Unoccupied Chair||40.4%|Medium|| +|1943|Describe the Painting||47.8%|Medium|| +|1944|Number of Visible People in a Queue||69.9%|Hard|| +|1945|Sum of Digits of String After Convert||61.1%|Easy|| +|1946|Largest Number After Mutating Substring||34.5%|Medium|| +|1947|Maximum Compatibility Score Sum||60.9%|Medium|| +|1948|Delete Duplicate Folders in System||58.0%|Hard|| +|1949|Strong Friendship||58.7%|Medium|| +|1950|Maximum of Minimum Values in All Subarrays||50.0%|Medium|| +|1951|All the Pairs With the Maximum Number of Common Followers||72.9%|Medium|| +|1952|Three Divisors||57.0%|Easy|| +|1953|Maximum Number of Weeks for Which You Can Work||39.0%|Medium|| +|1954|Minimum Garden Perimeter to Collect Enough Apples||53.0%|Medium|| +|1955|Count Number of Special Subsequences||51.3%|Hard|| +|1956|Minimum Time For K Virus Variants to Spread||46.5%|Hard|| +|1957|Delete Characters to Make Fancy String||56.6%|Easy|| +|1958|Check if Move is Legal||44.2%|Medium|| +|1959|Minimum Total Space Wasted With K Resizing Operations||41.9%|Medium|| +|1960|Maximum Product of the Length of Two Palindromic Substrings||29.6%|Hard|| +|1961|Check If String Is a Prefix of Array||54.2%|Easy|| +|1962|Remove Stones to Minimize the Total||58.8%|Medium|| +|1963|Minimum Number of Swaps to Make the String Balanced||68.3%|Medium|| +|1964|Find the Longest Valid Obstacle Course at Each Position||46.9%|Hard|| +|1965|Employees With Missing Information||81.1%|Easy|| +|1966|Binary Searchable Numbers in an Unsorted Array||65.5%|Medium|| +|1967|Number of Strings That Appear as Substrings in Word||79.9%|Easy|| +|1968|Array With Elements Not Equal to Average of Neighbors||49.4%|Medium|| +|1969|Minimum Non-Zero Product of the Array Elements||33.7%|Medium|| +|1970|Last Day Where You Can Still Cross||49.5%|Hard|| +|1971|Find if Path Exists in Graph||50.5%|Easy|| +|1972|First and Last Call On the Same Day||54.4%|Hard|| +|1973|Count Nodes Equal to Sum of Descendants||75.3%|Medium|| +|1974|Minimum Time to Type Word Using Special Typewriter||71.5%|Easy|| +|1975|Maximum Matrix Sum||45.6%|Medium|| +|1976|Number of Ways to Arrive at Destination||32.4%|Medium|| +|1977|Number of Ways to Separate Numbers||21.2%|Hard|| +|1978|Employees Whose Manager Left the Company||50.5%|Easy|| +|1979|Find Greatest Common Divisor of Array||76.8%|Easy|| +|1980|Find Unique Binary String||64.2%|Medium|| +|1981|Minimize the Difference Between Target and Chosen Elements||32.4%|Medium|| +|1982|Find Array Given Subset Sums||48.7%|Hard|| +|1983|Widest Pair of Indices With Equal Range Sum||53.1%|Medium|| +|1984|Minimum Difference Between Highest and Lowest of K Scores|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/1984.Minimum-Difference-Between-Highest-and-Lowest-of-K-Scores)|53.5%|Easy|| +|1985|Find the Kth Largest Integer in the Array||44.6%|Medium|| +|1986|Minimum Number of Work Sessions to Finish the Tasks||33.1%|Medium|| +|1987|Number of Unique Good Subsequences||52.2%|Hard|| +|1988|Find Cutoff Score for Each School||70.5%|Medium|| +|1989|Maximum Number of People That Can Be Caught in Tag||53.8%|Medium|| +|1990|Count the Number of Experiments||51.7%|Medium|| +|1991|Find the Middle Index in Array||67.3%|Easy|| +|1992|Find All Groups of Farmland||68.5%|Medium|| +|1993|Operations on Tree||43.5%|Medium|| +|1994|The Number of Good Subsets||34.1%|Hard|| +|1995|Count Special Quadruplets||59.0%|Easy|| +|1996|The Number of Weak Characters in the Game||44.0%|Medium|| +|1997|First Day Where You Have Been in All the Rooms||36.0%|Medium|| +|1998|GCD Sort of an Array||45.5%|Hard|| +|1999|Smallest Greater Multiple Made of Two Digits||50.0%|Medium|| +|2000|Reverse Prefix of Word||77.7%|Easy|| +|2001|Number of Pairs of Interchangeable Rectangles||44.6%|Medium|| +|2002|Maximum Product of the Length of Two Palindromic Subsequences||53.4%|Medium|| +|2003|Smallest Missing Genetic Value in Each Subtree||44.1%|Hard|| +|2004|The Number of Seniors and Juniors to Join the Company||38.8%|Hard|| +|2005|Subtree Removal Game with Fibonacci Tree||62.8%|Hard|| +|2006|Count Number of Pairs With Absolute Difference K||82.2%|Easy|| +|2007|Find Original Array From Doubled Array||41.0%|Medium|| +|2008|Maximum Earnings From Taxi||43.0%|Medium|| +|2009|Minimum Number of Operations to Make Array Continuous||45.5%|Hard|| +|2010|The Number of Seniors and Juniors to Join the Company II||57.8%|Hard|| +|2011|Final Value of Variable After Performing Operations||88.8%|Easy|| +|2012|Sum of Beauty in the Array||46.7%|Medium|| +|2013|Detect Squares||50.1%|Medium|| +|2014|Longest Subsequence Repeated k Times||55.7%|Hard|| +|2015|Average Height of Buildings in Each Segment||58.6%|Medium|| +|2016|Maximum Difference Between Increasing Elements||53.4%|Easy|| +|2017|Grid Game||42.7%|Medium|| +|2018|Check if Word Can Be Placed In Crossword||49.3%|Medium|| +|2019|The Score of Students Solving Math Expression||33.2%|Hard|| +|2020|Number of Accounts That Did Not Stream||73.2%|Medium|| +|2021|Brightest Position on Street|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/2021.Brightest-Position-on-Street)|62.9%|Medium|| +|2022|Convert 1D Array Into 2D Array|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/2022.Convert-1D-Array-Into-2D-Array)|58.3%|Easy|| +|2023|Number of Pairs of Strings With Concatenation Equal to Target||72.8%|Medium|| +|2024|Maximize the Confusion of an Exam||59.4%|Medium|| +|2025|Maximum Number of Ways to Partition an Array||32.0%|Hard|| +|2026|Low-Quality Problems||85.5%|Easy|| +|2027|Minimum Moves to Convert String||53.8%|Easy|| +|2028|Find Missing Observations||43.5%|Medium|| +|2029|Stone Game IX||26.1%|Medium|| +|2030|Smallest K-Length Subsequence With Occurrences of a Letter||38.9%|Hard|| +|2031|Count Subarrays With More Ones Than Zeros||53.2%|Medium|| +|2032|Two Out of Three||72.6%|Easy|| +|2033|Minimum Operations to Make a Uni-Value Grid||52.3%|Medium|| +|2034|Stock Price Fluctuation||49.3%|Medium|| +|2035|Partition Array Into Two Arrays to Minimize Sum Difference||17.9%|Hard|| +|2036|Maximum Alternating Subarray Sum||41.2%|Medium|| +|2037|Minimum Number of Moves to Seat Everyone|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/2037.Minimum-Number-of-Moves-to-Seat-Everyone)|82.2%|Easy|| +|2038|Remove Colored Pieces if Both Neighbors are the Same Color|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/2038.Remove-Colored-Pieces-if-Both-Neighbors-are-the-Same-Color)|58.1%|Medium|| +|2039|The Time When the Network Becomes Idle||50.6%|Medium|| +|2040|Kth Smallest Product of Two Sorted Arrays||29.1%|Hard|| +|2041|Accepted Candidates From the Interviews||79.4%|Medium|| +|2042|Check if Numbers Are Ascending in a Sentence||65.9%|Easy|| +|2043|Simple Bank System|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/2043.Simple-Bank-System)|65.9%|Medium|| +|2044|Count Number of Maximum Bitwise-OR Subsets||74.8%|Medium|| +|2045|Second Minimum Time to Reach Destination||38.5%|Hard|| +|2046|Sort Linked List Already Sorted Using Absolute Values||68.6%|Medium|| +|2047|Number of Valid Words in a Sentence||29.5%|Easy|| +|2048|Next Greater Numerically Balanced Number||47.1%|Medium|| +|2049|Count Nodes With the Highest Score||47.1%|Medium|| +|2050|Parallel Courses III||59.4%|Hard|| +|2051|The Category of Each Member in the Store||73.5%|Medium|| +|2052|Minimum Cost to Separate Sentence Into Rows||51.0%|Medium|| +|2053|Kth Distinct String in an Array||71.9%|Easy|| +|2054|Two Best Non-Overlapping Events||44.8%|Medium|| +|2055|Plates Between Candles||44.7%|Medium|| +|2056|Number of Valid Move Combinations On Chessboard||59.1%|Hard|| +|2057|Smallest Index With Equal Value||71.2%|Easy|| +|2058|Find the Minimum and Maximum Number of Nodes Between Critical Points||57.1%|Medium|| +|2059|Minimum Operations to Convert Number||47.2%|Medium|| +|2060|Check if an Original String Exists Given Two Encoded Strings||41.0%|Hard|| +|2061|Number of Spaces Cleaning Robot Cleaned||54.9%|Medium|| +|2062|Count Vowel Substrings of a String||65.9%|Easy|| +|2063|Vowels of All Substrings||55.0%|Medium|| +|2064|Minimized Maximum of Products Distributed to Any Store||50.0%|Medium|| +|2065|Maximum Path Quality of a Graph||57.7%|Hard|| +|2066|Account Balance||85.5%|Medium|| +|2067|Number of Equal Count Substrings||49.6%|Medium|| +|2068|Check Whether Two Strings are Almost Equivalent||64.7%|Easy|| +|2069|Walking Robot Simulation II||23.0%|Medium|| +|2070|Most Beautiful Item for Each Query||49.5%|Medium|| +|2071|Maximum Number of Tasks You Can Assign||34.8%|Hard|| +|2072|The Winner University||72.4%|Easy|| +|2073|Time Needed to Buy Tickets||62.0%|Easy|| +|2074|Reverse Nodes in Even Length Groups||51.5%|Medium|| +|2075|Decode the Slanted Ciphertext||50.2%|Medium|| +|2076|Process Restricted Friend Requests||53.4%|Hard|| +|2077|Paths in Maze That Lead to Same Room||56.8%|Medium|| +|2078|Two Furthest Houses With Different Colors||67.3%|Easy|| +|2079|Watering Plants||80.2%|Medium|| +|2080|Range Frequency Queries||38.1%|Medium|| +|2081|Sum of k-Mirror Numbers||42.1%|Hard|| +|2082|The Number of Rich Customers||80.7%|Easy|| +|2083|Substrings That Begin and End With the Same Letter||68.0%|Medium|| +|2084|Drop Type 1 Orders for Customers With Type 0 Orders||91.2%|Medium|| +|2085|Count Common Words With One Occurrence||69.6%|Easy|| +|2086|Minimum Number of Buckets Required to Collect Rainwater from Houses||45.0%|Medium|| +|2087|Minimum Cost Homecoming of a Robot in a Grid||51.4%|Medium|| +|2088|Count Fertile Pyramids in a Land||63.3%|Hard|| +|2089|Find Target Indices After Sorting Array||76.9%|Easy|| +|2090|K Radius Subarray Averages||42.4%|Medium|| +|2091|Removing Minimum and Maximum From Array||56.8%|Medium|| +|2092|Find All People With Secret||34.2%|Hard|| +|2093|Minimum Cost to Reach City With Discounts||56.3%|Medium|| +|2094|Finding 3-Digit Even Numbers||57.4%|Easy|| +|2095|Delete the Middle Node of a Linked List||60.7%|Medium|| +|2096|Step-By-Step Directions From a Binary Tree Node to Another|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/2096.Step-By-Step-Directions-From-a-Binary-Tree-Node-to-Another)|48.8%|Medium|| +|2097|Valid Arrangement of Pairs||40.9%|Hard|| +|2098|Subsequence of Size K With the Largest Even Sum||38.7%|Medium|| +|2099|Find Subsequence of Length K With the Largest Sum||42.5%|Easy|| +|2100|Find Good Days to Rob the Bank||49.1%|Medium|| +|2101|Detonate the Maximum Bombs||40.9%|Medium|| +|2102|Sequentially Ordinal Rank Tracker||66.1%|Hard|| +|2103|Rings and Rods||81.5%|Easy|| +|2104|Sum of Subarray Ranges||60.2%|Medium|| +|2105|Watering Plants II||50.2%|Medium|| +|2106|Maximum Fruits Harvested After at Most K Steps||35.1%|Hard|| +|2107|Number of Unique Flavors After Sharing K Candies||57.2%|Medium|| +|2108|Find First Palindromic String in the Array||78.6%|Easy|| +|2109|Adding Spaces to a String||56.2%|Medium|| +|2110|Number of Smooth Descent Periods of a Stock||57.4%|Medium|| +|2111|Minimum Operations to Make the Array K-Increasing||37.7%|Hard|| +|2112|The Airport With the Most Traffic||71.2%|Medium|| +|2113|Elements in Array After Removing and Replacing Elements||73.4%|Medium|| +|2114|Maximum Number of Words Found in Sentences||88.2%|Easy|| +|2115|Find All Possible Recipes from Given Supplies||48.2%|Medium|| +|2116|Check if a Parentheses String Can Be Valid||31.4%|Medium|| +|2117|Abbreviating the Product of a Range||28.1%|Hard|| +|2118|Build the Equation||57.8%|Hard|| +|2119|A Number After a Double Reversal||75.7%|Easy|| +|2120|Execution of All Suffix Instructions Staying in a Grid||83.5%|Medium|| +|2121|Intervals Between Identical Elements||43.0%|Medium|| +|2122|Recover the Original Array||38.1%|Hard|| +|2123|Minimum Operations to Remove Adjacent Ones in Matrix||41.1%|Hard|| +|2124|Check if All A's Appears Before All B's||71.5%|Easy|| +|2125|Number of Laser Beams in a Bank||82.7%|Medium|| +|2126|Destroying Asteroids||49.4%|Medium|| +|2127|Maximum Employees to Be Invited to a Meeting||32.9%|Hard|| +|2128|Remove All Ones With Row and Column Flips||76.4%|Medium|| +|2129|Capitalize the Title||60.1%|Easy|| +|2130|Maximum Twin Sum of a Linked List||81.6%|Medium|| +|2131|Longest Palindrome by Concatenating Two Letter Words||41.3%|Medium|| +|2132|Stamping the Grid||30.6%|Hard|| +|2133|Check if Every Row and Column Contains All Numbers||52.8%|Easy|| +|2134|Minimum Swaps to Group All 1's Together II||50.3%|Medium|| +|2135|Count Words Obtained After Adding a Letter||42.8%|Medium|| +|2136|Earliest Possible Day of Full Bloom||68.4%|Hard|| +|2137|Pour Water Between Buckets to Make Water Levels Equal||67.1%|Medium|| +|2138|Divide a String Into Groups of Size k||65.1%|Easy|| +|2139|Minimum Moves to Reach Target Score||48.4%|Medium|| +|2140|Solving Questions With Brainpower||45.8%|Medium|| +|2141|Maximum Running Time of N Computers||38.7%|Hard|| +|2142|The Number of Passengers in Each Bus I||51.1%|Medium|| +|2143|Choose Numbers From Two Arrays in Range||51.8%|Hard|| +|2144|Minimum Cost of Buying Candies With Discount||60.8%|Easy|| +|2145|Count the Hidden Sequences||36.3%|Medium|| +|2146|K Highest Ranked Items Within a Price Range||41.2%|Medium|| +|2147|Number of Ways to Divide a Long Corridor||39.9%|Hard|| +|2148|Count Elements With Strictly Smaller and Greater Elements||60.0%|Easy|| +|2149|Rearrange Array Elements by Sign||81.0%|Medium|| +|2150|Find All Lonely Numbers in the Array||60.7%|Medium|| +|2151|Maximum Good People Based on Statements||48.4%|Hard|| +|2152|Minimum Number of Lines to Cover Points||46.7%|Medium|| +|2153|The Number of Passengers in Each Bus II||50.4%|Hard|| +|2154|Keep Multiplying Found Values by Two||73.3%|Easy|| +|2155|All Divisions With the Highest Score of a Binary Array||63.3%|Medium|| +|2156|Find Substring With Given Hash Value||21.9%|Hard|| +|2157|Groups of Strings||25.2%|Hard|| +|2158|Amount of New Area Painted Each Day||55.7%|Hard|| +|2159|Order Two Columns Independently||63.5%|Medium|| +|2160|Minimum Sum of Four Digit Number After Splitting Digits||88.2%|Easy|| +|2161|Partition Array According to Given Pivot||84.3%|Medium|| +|2162|Minimum Cost to Set Cooking Time||39.2%|Medium|| +|2163|Minimum Difference in Sums After Removal of Elements||46.5%|Hard|| +|2164|Sort Even and Odd Indices Independently|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/2164.Sort-Even-and-Odd-Indices-Independently)|66.6%|Easy|| +|2165|Smallest Value of the Rearranged Number|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/2165.Smallest-Value-of-the-Rearranged-Number)|51.1%|Medium|| +|2166|Design Bitset|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/2166.Design-Bitset)|31.3%|Medium|| +|2167|Minimum Time to Remove All Cars Containing Illegal Goods|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/2167.Minimum-Time-to-Remove-All-Cars-Containing-Illegal-Goods)|40.1%|Hard|| +|2168|Unique Substrings With Equal Digit Frequency||60.2%|Medium|| +|2169|Count Operations to Obtain Zero|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/2169.Count-Operations-to-Obtain-Zero)|75.6%|Easy|| +|2170|Minimum Operations to Make the Array Alternating|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/2170.Minimum-Operations-to-Make-the-Array-Alternating)|33.2%|Medium|| +|2171|Removing Minimum Number of Magic Beans|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/2171.Removing-Minimum-Number-of-Magic-Beans)|42.0%|Medium|| +|2172|Maximum AND Sum of Array||46.8%|Hard|| +|2173|Longest Winning Streak||59.7%|Hard|| +|2174|Remove All Ones With Row and Column Flips II||68.8%|Medium|| +|2175|The Change in Global Rankings||68.5%|Medium|| +|2176|Count Equal and Divisible Pairs in an Array||80.3%|Easy|| +|2177|Find Three Consecutive Integers That Sum to a Given Number||63.5%|Medium|| +|2178|Maximum Split of Positive Even Integers||59.1%|Medium|| +|2179|Count Good Triplets in an Array||36.7%|Hard|| +|2180|Count Integers With Even Digit Sum|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/2180.Count-Integers-With-Even-Digit-Sum)|64.5%|Easy|| +|2181|Merge Nodes in Between Zeros|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/2181.Merge-Nodes-in-Between-Zeros)|86.9%|Medium|| +|2182|Construct String With Repeat Limit|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/2182.Construct-String-With-Repeat-Limit)|51.8%|Medium|| +|2183|Count Array Pairs Divisible by K|[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/2183.Count-Array-Pairs-Divisible-by-K)|28.3%|Hard|| +|2184|Number of Ways to Build Sturdy Brick Wall||52.1%|Medium|| +|2185|Counting Words With a Given Prefix||77.1%|Easy|| +|2186|Minimum Number of Steps to Make Two Strings Anagram II||71.9%|Medium|| +|2187|Minimum Time to Complete Trips||31.8%|Medium|| +|2188|Minimum Time to Finish the Race||41.9%|Hard|| +|2189|Number of Ways to Build House of Cards||63.2%|Medium|| +|2190|Most Frequent Number Following Key In an Array||60.4%|Easy|| +|2191|Sort the Jumbled Numbers||45.1%|Medium|| +|2192|All Ancestors of a Node in a Directed Acyclic Graph||50.5%|Medium|| +|2193|Minimum Number of Moves to Make Palindrome||50.8%|Hard|| +|2194|Cells in a Range on an Excel Sheet||85.7%|Easy|| +|2195|Append K Integers With Minimal Sum||24.9%|Medium|| +|2196|Create Binary Tree From Descriptions||72.0%|Medium|| +|2197|Replace Non-Coprime Numbers in Array||38.3%|Hard|| +|2198|Number of Single Divisor Triplets||56.2%|Medium|| +|2199|Finding the Topic of Each Post||49.8%|Hard|| +|2200|Find All K-Distant Indices in an Array||64.4%|Easy|| +|2201|Count Artifacts That Can Be Extracted||54.9%|Medium|| +|2202|Maximize the Topmost Element After K Moves||22.7%|Medium|| +|2203|Minimum Weighted Subgraph With the Required Paths||35.6%|Hard|| +|2204|Distance to a Cycle in Undirected Graph||71.4%|Hard|| +|2205|The Number of Users That Are Eligible for Discount||50.4%|Easy|| +|2206|Divide Array Into Equal Pairs||74.8%|Easy|| +|2207|Maximize Number of Subsequences in a String||32.7%|Medium|| +|2208|Minimum Operations to Halve Array Sum||45.1%|Medium|| +|2209|Minimum White Tiles After Covering With Carpets||33.7%|Hard|| +|2210|Count Hills and Valleys in an Array||57.7%|Easy|| +|2211|Count Collisions on a Road||41.7%|Medium|| +|2212|Maximum Points in an Archery Competition||48.7%|Medium|| +|2213|Longest Substring of One Repeating Character||31.1%|Hard|| +|2214|Minimum Health to Beat Game||57.6%|Medium|| +|2215|Find the Difference of Two Arrays||69.1%|Easy|| +|2216|Minimum Deletions to Make Array Beautiful||46.1%|Medium|| +|2217|Find Palindrome With Fixed Length||34.4%|Medium|| +|2218|Maximum Value of K Coins From Piles||48.5%|Hard|| +|2219|Maximum Sum Score of Array||60.6%|Medium|| +|2220|Minimum Bit Flips to Convert Number||82.3%|Easy|| +|2221|Find Triangular Sum of an Array||79.1%|Medium|| +|2222|Number of Ways to Select Buildings||50.7%|Medium|| +|2223|Sum of Scores of Built Strings||36.5%|Hard|| +|2224|Minimum Number of Operations to Convert Time||65.2%|Easy|| +|2225|Find Players With Zero or One Losses||69.3%|Medium|| +|2226|Maximum Candies Allocated to K Children||35.9%|Medium|| +|2227|Encrypt and Decrypt Strings||39.0%|Hard|| +|2228|Users With Two Purchases Within Seven Days||44.8%|Medium|| +|2229|Check if an Array Is Consecutive||61.7%|Easy|| +|2230|The Users That Are Eligible for Discount||51.1%|Easy|| +|2231|Largest Number After Digit Swaps by Parity||60.2%|Easy|| +|2232|Minimize Result by Adding Parentheses to Expression||64.7%|Medium|| +|2233|Maximum Product After K Increments||41.3%|Medium|| +|2234|Maximum Total Beauty of the Gardens||28.1%|Hard|| +|2235|Add Two Integers||90.0%|Easy|| +|2236|Root Equals Sum of Children||87.6%|Easy|| +|2237|Count Positions on Street With Required Brightness||68.6%|Medium|| +|2238|Number of Times a Driver Was a Passenger||75.3%|Medium|| +|2239|Find Closest Number to Zero||45.8%|Easy|| +|2240|Number of Ways to Buy Pens and Pencils||56.8%|Medium|| +|2241|Design an ATM Machine||38.6%|Medium|| +|2242|Maximum Score of a Node Sequence||37.4%|Hard|| +|2243|Calculate Digit Sum of a String||66.9%|Easy|| +|2244|Minimum Rounds to Complete All Tasks||57.0%|Medium|| +|2245|Maximum Trailing Zeros in a Cornered Path||35.2%|Medium|| +|2246|Longest Path With Different Adjacent Characters||44.9%|Hard|| +|2247|Maximum Cost of Trip With K Highways||50.5%|Hard|| +|2248|Intersection of Multiple Arrays||69.5%|Easy|| +|2249|Count Lattice Points Inside a Circle||50.4%|Medium|| +|2250|Count Number of Rectangles Containing Each Point||33.9%|Medium|| +|2251|Number of Flowers in Full Bloom||51.9%|Hard|| +|2252|Dynamic Pivoting of a Table||55.5%|Hard|| +|2253|Dynamic Unpivoting of a Table||67.4%|Hard|| +|2254|Design Video Sharing Platform||65.8%|Hard|| +|2255|Count Prefixes of a Given String||73.3%|Easy|| +|2256|Minimum Average Difference||35.7%|Medium|| +|2257|Count Unguarded Cells in the Grid||52.2%|Medium|| +|2258|Escape the Spreading Fire||34.7%|Hard|| +|2259|Remove Digit From Number to Maximize Result||47.0%|Easy|| +|2260|Minimum Consecutive Cards to Pick Up||51.9%|Medium|| +|2261|K Divisible Elements Subarrays||47.4%|Medium|| +|2262|Total Appeal of A String||58.1%|Hard|| +|2263|Make Array Non-decreasing or Non-increasing||68.0%|Hard|| +|2264|Largest 3-Same-Digit Number in String||58.9%|Easy|| +|2265|Count Nodes Equal to Average of Subtree||85.6%|Medium|| +|2266|Count Number of Texts||47.3%|Medium|| +|2267|Check if There Is a Valid Parentheses String Path||37.9%|Hard|| +|2268|Minimum Number of Keypresses||74.4%|Medium|| +|2269|Find the K-Beauty of a Number||57.2%|Easy|| +|2270|Number of Ways to Split Array||44.2%|Medium|| +|2271|Maximum White Tiles Covered by a Carpet||32.4%|Medium|| +|2272|Substring With Largest Variance||37.1%|Hard|| +|2273|Find Resultant Array After Removing Anagrams||58.0%|Easy|| +|2274|Maximum Consecutive Floors Without Special Floors||52.2%|Medium|| +|2275|Largest Combination With Bitwise AND Greater Than Zero||72.3%|Medium|| +|2276|Count Integers in Intervals||33.9%|Hard|| +|2277|Closest Node to Path in Tree||64.1%|Hard|| +|2278|Percentage of Letter in String||74.0%|Easy|| +|2279|Maximum Bags With Full Capacity of Rocks||62.6%|Medium|| +|2280|Minimum Lines to Represent a Line Chart||23.7%|Medium|| +|2281|Sum of Total Strength of Wizards||27.9%|Hard|| +|2282|Number of People That Can Be Seen in a Grid||50.4%|Medium|| +|2283|Check if Number Has Equal Digit Count and Digit Value||73.6%|Easy|| +|2284|Sender With Largest Word Count||55.8%|Medium|| +|2285|Maximum Total Importance of Roads||60.7%|Medium|| +|2286|Booking Concert Tickets in Groups||15.7%|Hard|| +|2287|Rearrange Characters to Make Target String||57.7%|Easy|| +|2288|Apply Discount to Prices||27.3%|Medium|| +|2289|Steps to Make Array Non-decreasing||21.4%|Medium|| +|2290|Minimum Obstacle Removal to Reach Corner||49.2%|Hard|| +|2291|Maximum Profit From Trading Stocks||46.4%|Medium|| +|2292|Products With Three or More Orders in Two Consecutive Years||39.9%|Medium|| +|2293|Min Max Game||64.2%|Easy|| +|2294|Partition Array Such That Maximum Difference Is K||72.4%|Medium|| +|2295|Replace Elements in an Array||57.6%|Medium|| +|2296|Design a Text Editor||39.5%|Hard|| +|2297|Jump Game VIII||57.0%|Medium|| +|2298|Tasks Count in the Weekend||87.7%|Medium|| +|2299|Strong Password Checker II||56.8%|Easy|| +|2300|Successful Pairs of Spells and Potions||31.5%|Medium|| +|2301|Match Substring After Replacement||39.2%|Hard|| +|2302|Count Subarrays With Score Less Than K||51.9%|Hard|| +|2303|Calculate Amount Paid in Taxes||63.0%|Easy|| +|2304|Minimum Path Cost in a Grid||65.4%|Medium|| +|2305|Fair Distribution of Cookies||62.9%|Medium|| +|2306|Naming a Company||34.4%|Hard|| +|2307|Check for Contradictions in Equations||40.9%|Hard|| +|2308|Arrange Table by Gender||79.5%|Medium|| +|2309|Greatest English Letter in Upper and Lower Case||68.5%|Easy|| +|2310|Sum of Numbers With Units Digit K||25.4%|Medium|| +|2311|Longest Binary Subsequence Less Than or Equal to K||36.1%|Medium|| +|2312|Selling Pieces of Wood||48.0%|Hard|| +|2313|Minimum Flips in Binary Tree to Get Result||67.5%|Hard|| +|2314|The First Day of the Maximum Recorded Degree in Each City||76.9%|Medium|| +|2315|Count Asterisks||82.2%|Easy|| +|2316|Count Unreachable Pairs of Nodes in an Undirected Graph||38.6%|Medium|| +|2317|Maximum XOR After Operations||78.2%|Medium|| +|2318|Number of Distinct Roll Sequences||56.3%|Hard|| +|2319|Check if Matrix Is X-Matrix||67.3%|Easy|| +|2320|Count Number of Ways to Place Houses||39.9%|Medium|| +|2321|Maximum Score Of Spliced Array||55.1%|Hard|| +|2322|Minimum Score After Removals on a Tree||50.3%|Hard|| +|2323|Find Minimum Time to Finish All Jobs II||75.4%|Medium|| +|2324|Product Sales Analysis IV||84.5%|Medium|| +|2325|Decode the Message||84.7%|Easy|| +|2326|Spiral Matrix IV||74.6%|Medium|| +|2327|Number of People Aware of a Secret||44.4%|Medium|| +|2328|Number of Increasing Paths in a Grid||47.7%|Hard|| +|2329|Product Sales Analysis V||70.2%|Easy|| +|2330|Valid Palindrome IV||76.2%|Medium|| +|2331|Evaluate Boolean Binary Tree||79.5%|Easy|| +|2332|The Latest Time to Catch a Bus||22.7%|Medium|| +|2333|Minimum Sum of Squared Difference||24.9%|Medium|| +|2334|Subarray With Elements Greater Than Varying Threshold||40.1%|Hard|| +|2335|Minimum Amount of Time to Fill Cups||55.3%|Easy|| +|2336|Smallest Number in Infinite Set||71.8%|Medium|| +|2337|Move Pieces to Obtain a String||48.0%|Medium|| +|2338|Count the Number of Ideal Arrays||25.3%|Hard|| +|2339|All the Matches of the League||88.8%|Easy|| +|2340|Minimum Adjacent Swaps to Make a Valid Array||76.6%|Medium|| +|2341|Maximum Number of Pairs in Array||76.6%|Easy|| +|2342|Max Sum of a Pair With Equal Sum of Digits||52.9%|Medium|| +|2343|Query Kth Smallest Trimmed Number||40.7%|Medium|| +|2344|Minimum Deletions to Make Array Divisible||56.9%|Hard|| +|2345|Finding the Number of Visible Mountains||44.5%|Medium|| +|2346|Compute the Rank as a Percentage||32.9%|Medium|| +|2347|Best Poker Hand||60.7%|Easy|| +|2348|Number of Zero-Filled Subarrays||56.8%|Medium|| +|2349|Design a Number Container System||46.8%|Medium|| +|2350|Shortest Impossible Sequence of Rolls||68.2%|Hard|| +|2351|First Letter to Appear Twice||76.6%|Easy|| +|2352|Equal Row and Column Pairs||71.1%|Medium|| +|2353|Design a Food Rating System||34.4%|Medium|| +|2354|Number of Excellent Pairs||45.8%|Hard|| +|2355|Maximum Number of Books You Can Take||47.0%|Hard|| +|2356|Number of Unique Subjects Taught by Each Teacher||91.5%|Easy|| +|2357|Make Array Zero by Subtracting Equal Amounts||72.5%|Easy|| +|2358|Maximum Number of Groups Entering a Competition||67.3%|Medium|| +|2359|Find Closest Node to Given Two Nodes||33.8%|Medium|| +|2360|Longest Cycle in a Graph||38.5%|Hard|| +|2361|Minimum Costs Using the Train Line||77.1%|Hard|| +|2362|Generate the Invoice||89.1%|Hard|| +|2363|Merge Similar Items||75.1%|Easy|| +|2364|Count Number of Bad Pairs||40.5%|Medium|| +|2365|Task Scheduler II||46.0%|Medium|| +|2366|Minimum Replacements to Sort the Array||39.5%|Hard|| +|2367|Number of Arithmetic Triplets||83.7%|Easy|| +|2368|Reachable Nodes With Restrictions||57.2%|Medium|| +|2369|Check if There is a Valid Partition For The Array||40.0%|Medium|| +|2370|Longest Ideal Subsequence||37.8%|Medium|| +|2371|Minimize Maximum Value in a Grid||69.5%|Hard|| +|2372|Calculate the Influence of Each Salesperson||88.6%|Medium|| +|2373|Largest Local Values in a Matrix||84.1%|Easy|| +|2374|Node With Highest Edge Score||45.9%|Medium|| +|2375|Construct Smallest Number From DI String||73.7%|Medium|| +|2376|Count Special Integers||36.0%|Hard|| +|2377|Sort the Olympic Table||80.2%|Easy|| +|2378|Choose Edges to Maximize Score in a Tree||61.9%|Medium|| +|2379|Minimum Recolors to Get K Consecutive Black Blocks||56.6%|Easy|| +|2380|Time Needed to Rearrange a Binary String||47.7%|Medium|| +|2381|Shifting Letters II||33.9%|Medium|| +|2382|Maximum Segment Sum After Removals||47.7%|Hard|| +|2383|Minimum Hours of Training to Win a Competition||40.8%|Easy|| +|2384|Largest Palindromic Number||30.1%|Medium|| +|2385|Amount of Time for Binary Tree to Be Infected||56.0%|Medium|| +|2386|Find the K-Sum of an Array||36.2%|Hard|| +|2387|Median of a Row Wise Sorted Matrix||67.7%|Medium|| +|2388|Change Null Values in a Table to the Previous Value||79.7%|Medium|| +|2389|Longest Subsequence With Limited Sum||64.4%|Easy|| +|2390|Removing Stars From a String||62.9%|Medium|| +|2391|Minimum Amount of Time to Collect Garbage||85.4%|Medium|| +|2392|Build a Matrix With Conditions||59.1%|Hard|| +|2393|Count Strictly Increasing Subarrays||76.4%|Medium|| +|2394|Employees With Deductions||50.9%|Medium|| +|2395|Find Subarrays With Equal Sum||63.6%|Easy|| +|2396|Strictly Palindromic Number||87.7%|Medium|| +|2397|Maximum Rows Covered by Columns||52.2%|Medium|| +|2398|Maximum Number of Robots Within Budget||31.6%|Hard|| +|2399|Check Distances Between Same Letters||70.5%|Easy|| +|2400|Number of Ways to Reach a Position After Exactly k Steps||31.8%|Medium|| +|2401|Longest Nice Subarray||47.7%|Medium|| +|2402|Meeting Rooms III||32.7%|Hard|| +|2403|Minimum Time to Kill All Monsters||52.3%|Hard|| +|2404|Most Frequent Even Element||51.7%|Easy|| +|2405|Optimal Partition of String||74.1%|Medium|| +|2406|Divide Intervals Into Minimum Number of Groups||45.0%|Medium|| +|2407|Longest Increasing Subsequence II||20.6%|Hard|| +|2408|Design SQL||87.3%|Medium|| +|2409|Count Days Spent Together||42.3%|Easy|| +|2410|Maximum Matching of Players With Trainers||59.3%|Medium|| +|2411|Smallest Subarrays With Maximum Bitwise OR||40.0%|Medium|| +|2412|Minimum Money Required Before Transactions||38.8%|Hard|| +|2413|Smallest Even Multiple||88.2%|Easy|| +|2414|Length of the Longest Alphabetical Continuous Substring||55.5%|Medium|| +|2415|Reverse Odd Levels of Binary Tree||75.6%|Medium|| +|2416|Sum of Prefix Scores of Strings||42.3%|Hard|| +|2417|Closest Fair Integer||48.5%|Medium|| +|2418|Sort the People||82.7%|Easy|| +|2419|Longest Subarray With Maximum Bitwise AND||47.3%|Medium|| +|2420|Find All Good Indices||36.8%|Medium|| +|2421|Number of Good Paths||37.5%|Hard|| +|2422|Merge Operations to Turn Array Into a Palindrome||74.8%|Medium|| +|2423|Remove Letter To Equalize Frequency||19.4%|Easy|| +|2424|Longest Uploaded Prefix||53.2%|Medium|| +|2425|Bitwise XOR of All Pairings||58.3%|Medium|| +|2426|Number of Pairs Satisfying Inequality||41.1%|Hard|| +|2427|Number of Common Factors||80.3%|Easy|| +|2428|Maximum Sum of an Hourglass||73.6%|Medium|| +|2429|Minimize XOR||41.4%|Medium|| +|2430|Maximum Deletions on a String||32.8%|Hard|| +|2431|Maximize Total Tastiness of Purchased Fruits||76.6%|Medium|| +|2432|The Employee That Worked on the Longest Task||48.5%|Easy|| +|2433|Find The Original Array of Prefix Xor||85.1%|Medium|| +|2434|Using a Robot to Print the Lexicographically Smallest String||37.5%|Medium|| +|2435|Paths in Matrix Whose Sum Is Divisible by K||40.8%|Hard|| +|2436|Minimum Split Into Subarrays With GCD Greater Than One||85.0%|Medium|| +|2437|Number of Valid Clock Times||40.3%|Easy|| +|2438|Range Product Queries of Powers||36.6%|Medium|| +|2439|Minimize Maximum of Array||30.1%|Medium|| +|2440|Create Components With Same Value||53.4%|Hard|| +|2441|Largest Positive Integer That Exists With Its Negative||68.7%|Easy|| +|2442|Count Number of Distinct Integers After Reverse Operations||78.8%|Medium|| +|2443|Sum of Number and Its Reverse||40.6%|Medium|| +|2444|Count Subarrays With Fixed Bounds||38.4%|Hard|| |------------|-------------------------------------------------------|-------| ----------------| ---------------|-------------| ------------------------------------------------------------------ diff --git a/ctl/label.go b/ctl/label.go index 6553508ee..db94bf720 100644 --- a/ctl/label.go +++ b/ctl/label.go @@ -4,20 +4,21 @@ import ( "bufio" "errors" "fmt" - "github.com/halfrost/LeetCode-Go/ctl/util" - "github.com/spf13/cobra" "io" "io/ioutil" "os" "regexp" "strings" + + "github.com/halfrost/LeetCode-Go/ctl/util" + "github.com/spf13/cobra" ) var ( - chapterOneFileOrder = []string{"_index", "Data_Structure", "Algorithm"} - chapterOneMenuOrder = []string{"_index", "#关于作者", "Data_Structure", "Algorithm"} + chapterOneFileOrder = []string{"_index", "Data_Structure", "Algorithm", "Time_Complexity"} + chapterOneMenuOrder = []string{"_index", "#关于作者", "Data_Structure", "Algorithm", "Time_Complexity"} chapterTwoFileOrder = []string{"_index", "Array", "String", "Two_Pointers", "Linked_List", "Stack", "Tree", "Dynamic_Programming", "Backtracking", "Depth_First_Search", "Breadth_First_Search", - "Binary_Search", "Math", "Hash_Table", "Sort", "Bit_Manipulation", "Union_Find", "Sliding_Window", "Segment_Tree", "Binary_Indexed_Tree"} + "Binary_Search", "Math", "Hash_Table", "Sorting", "Bit_Manipulation", "Union_Find", "Sliding_Window", "Segment_Tree", "Binary_Indexed_Tree"} chapterThreeFileOrder = []string{"_index", "Segment_Tree", "UnionFind", "LRUCache", "LFUCache"} preNextHeader = "----------------------------------------------\n

\n" preNextFotter = "
" @@ -34,10 +35,10 @@ var ( chapterMap = map[string]map[string]string{ "ChapterOne": { - "_index": "第一章 序章", - "#关于作者": "1.1 关于作者", - "Data_Structure": "1.2 数据结构知识", - "Algorithm": "1.3 算法知识", + "_index": "第一章 序章", + "Data_Structure": "1.1 数据结构知识", + "Algorithm": "1.2 算法知识", + "Time_Complexity": "1.3 时间复杂度", }, "ChapterTwo": { "_index": "第二章 算法专题", @@ -54,7 +55,7 @@ var ( "Binary_Search": "2.11 Binary Search", "Math": "2.12 Math", "Hash_Table": "2.13 Hash Table", - "Sort": "2.14 ✅ Sort", + "Sorting": "2.14 ✅ Sorting", "Bit_Manipulation": "2.15 ✅ Bit Manipulation", "Union_Find": "2.16 ✅ Union Find", "Sliding_Window": "2.17 ✅ Sliding Window", diff --git a/ctl/meta/PDFPreface b/ctl/meta/PDFPreface index 24bc7a3b1..465400d8a 100644 --- a/ctl/meta/PDFPreface +++ b/ctl/meta/PDFPreface @@ -3,7 +3,7 @@ # 说明 -此版本是 https://books.halfrost.com/leetcode 网页的离线版，由于网页版实时会更新，所以此 PDF 版难免会有一些排版或者错别字。如果读者遇到了，可以到网页版相应页面，点击页面 edit 按钮，提交 pr 进行更改。此 PDF 版本号是 V1.5.20。PDF 永久更新地址是 https://github.com/halfrost/LeetCode-Go/releases/，以版本号区分不同版本。笔者还是强烈推荐看在线版，有任何错误都会立即更新。如果觉得此书对刷题有一点点帮助，可以给此书点一个 star，鼓励一下笔者早点更新更多题解。 +此版本是 https://books.halfrost.com/leetcode 网页的离线版，由于网页版实时会更新，所以此 PDF 版难免会有一些排版或者错别字。如果读者遇到了，可以到网页版相应页面，点击页面 edit 按钮，提交 pr 进行更改。此 PDF 版本号是 V1.5.20。PDF 永久更新地址是 https://github.com/halfrost/leetcode-go/releases/，以版本号区分不同版本。笔者还是强烈推荐看在线版，有任何错误都会立即更新。如果觉得此书对刷题有一点点帮助，可以给此书点一个 star，鼓励一下笔者早点更新更多题解。 > 版本号说明，V1.5.20，1 是大版本号，5 代表当前题解中有几百题，目前是 520 题，所以第二个版本号是 5，20 代表当前题解中有几十题，目前是 520 题，所以第三个版本号是 20 。 diff --git a/ctl/meta/Sort b/ctl/meta/Sorting similarity index 100% rename from ctl/meta/Sort rename to ctl/meta/Sorting diff --git a/ctl/models/go.mod b/ctl/models/go.mod new file mode 100644 index 000000000..2b1389a7f --- /dev/null +++ b/ctl/models/go.mod @@ -0,0 +1,7 @@ +module github.com/halfrost/LeetCode-Go/ctl/models + +go 1.19 + +replace github.com/halfrost/LeetCode-Go/ctl/models => ../util + +require github.com/halfrost/LeetCode-Go/ctl/util v0.0.0-20220910225043-e3bb5aff34d0 diff --git a/ctl/models/go.sum b/ctl/models/go.sum new file mode 100644 index 000000000..2c3eec0c9 --- /dev/null +++ b/ctl/models/go.sum @@ -0,0 +1,2 @@ +github.com/halfrost/LeetCode-Go/ctl/util v0.0.0-20220910225043-e3bb5aff34d0 h1:WAOAj59szR52uAnEQljAt7ucpbGGOsy0xgR/NeP4Xbc= +github.com/halfrost/LeetCode-Go/ctl/util v0.0.0-20220910225043-e3bb5aff34d0/go.mod h1:+cA8KYcbGxP2Itd3NG+QJVGL/MEZISKlei0tvgDeEag= diff --git a/ctl/models/lcproblems.go b/ctl/models/lcproblems.go index 3f6e81394..e73537d64 100644 --- a/ctl/models/lcproblems.go +++ b/ctl/models/lcproblems.go @@ -14,8 +14,8 @@ type LeetCodeProblemAll struct { AcMedium int32 `json:"ac_medium"` AcHard int32 `json:"ac_hard"` StatStatusPairs []StatStatusPairs `json:"stat_status_pairs"` - FrequencyHigh int32 `json:"frequency_high"` - FrequencyMid int32 `json:"frequency_mid"` + FrequencyHigh float64 `json:"frequency_high"` + FrequencyMid float64 `json:"frequency_mid"` CategorySlug string `json:"category_slug"` AcEasyTotal int32 AcMediumTotal int32 diff --git a/ctl/models/mdrow.go b/ctl/models/mdrow.go index 85d4c97d6..5ad90ec0e 100644 --- a/ctl/models/mdrow.go +++ b/ctl/models/mdrow.go @@ -18,18 +18,41 @@ type Mdrow struct { // GenerateMdRows define func GenerateMdRows(solutionIds []int, mdrows []Mdrow) { + mdMap := map[int]Mdrow{} + for _, row := range mdrows { + mdMap[int(row.FrontendQuestionID)] = row + } for i := 0; i < len(solutionIds); i++ { - id := mdrows[solutionIds[i]-1].FrontendQuestionID - if solutionIds[i] == int(id) { - //fmt.Printf("id = %v i = %v solutionIds = %v\n", id, i, solutionIds[i]) - mdrows[id-1].SolutionPath = fmt.Sprintf("[Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/%v)", fmt.Sprintf("%04d.%v", id, strings.Replace(strings.TrimSpace(mdrows[id-1].QuestionTitle), " ", "-", -1))) + if row, ok := mdMap[solutionIds[i]]; ok { + s7 := standardizedTitle(row.QuestionTitle, row.FrontendQuestionID) + mdMap[solutionIds[i]] = Mdrow{ + FrontendQuestionID: row.FrontendQuestionID, + QuestionTitle: strings.TrimSpace(row.QuestionTitle), + QuestionTitleSlug: row.QuestionTitleSlug, + SolutionPath: fmt.Sprintf("[Go](https://github.com/halfrost/leetcode-go/tree/master/leetcode/%v)", fmt.Sprintf("%04d.%v", solutionIds[i], s7)), + Acceptance: row.Acceptance, + Difficulty: row.Difficulty, + Frequency: row.Frequency, + } } else { - fmt.Printf("序号出错了 solutionIds = %v id = %v\n", solutionIds[i], id) + fmt.Printf("序号不存在 len(solutionIds) = %v len(mdrows) = %v len(solutionIds) = %v solutionIds[i] = %v QuestionTitle = %v\n", len(solutionIds), len(mdrows), len(solutionIds), solutionIds[i], mdrows[solutionIds[i]-1].QuestionTitle) + } + } + for i := range mdrows { + mdrows[i] = Mdrow{ + FrontendQuestionID: mdrows[i].FrontendQuestionID, + QuestionTitle: strings.TrimSpace(mdrows[i].QuestionTitle), + QuestionTitleSlug: mdrows[i].QuestionTitleSlug, + SolutionPath: mdMap[int(mdrows[i].FrontendQuestionID)].SolutionPath, + Acceptance: mdrows[i].Acceptance, + Difficulty: mdrows[i].Difficulty, + Frequency: mdrows[i].Frequency, } } + // fmt.Printf("mdrows = %v\n\n", mdrows) } -// | 0001 | Two Sum | [Go](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0001.Two-Sum)| 45.6% | Easy | | +// | 0001 | Two Sum | [Go](https://github.com/halfrost/leetcode-go/tree/master/leetcode/0001.Two-Sum)| 45.6% | Easy | | func (m Mdrow) tableLine() string { return fmt.Sprintf("|%04d|%v|%v|%v|%v||\n", m.FrontendQuestionID, m.QuestionTitle, m.SolutionPath, m.Acceptance, m.Difficulty) } diff --git a/ctl/models/tagproblem.go b/ctl/models/tagproblem.go index 32d851542..5bc04ab8c 100644 --- a/ctl/models/tagproblem.go +++ b/ctl/models/tagproblem.go @@ -32,7 +32,7 @@ type TopicTag struct { TranslatedName string `json:"translatedName"` Slug string `json:"slug"` Questions []Question `json:"questions"` - Frequencies float64 `json:"frequencies"` + Frequencies string `json:"frequencies"` Typename string `json:"__typename"` } @@ -115,6 +115,41 @@ func (t TagList) tableLine() string { return fmt.Sprintf("|%04d|%v|%v|%v|%v|%v|%v|%v|\n", t.FrontendQuestionID, t.QuestionTitle, t.SolutionPath, t.Difficulty, t.TimeComplexity, t.SpaceComplexity, t.Favorite, t.Acceptance) } +func standardizedTitle(orig string, frontendQuestionID int32) string { + s0 := strings.TrimSpace(orig) + s1 := strings.Replace(s0, " ", "-", -1) + s2 := strings.Replace(s1, "'", "", -1) + s3 := strings.Replace(s2, "%", "", -1) + s4 := strings.Replace(s3, "(", "", -1) + s5 := strings.Replace(s4, ")", "", -1) + s6 := strings.Replace(s5, ",", "", -1) + s7 := strings.Replace(s6, "?", "", -1) + count := 0 + // 去掉 --- 这种情况，这种情况是由于题目标题中包含 - ，左右有空格，左右一填充，造成了 ---，3 个 - + for i := 0; i < len(s7)-2; i++ { + if s7[i] == '-' && s7[i+1] == '-' && s7[i+2] == '-' { + fmt.Printf("【需要修正 --- 的标题是 %v】\n", fmt.Sprintf("%04d.%v", int(frontendQuestionID), s7)) + s7 = s7[:i+1] + s7[i+3:] + count++ + } + } + if count > 0 { + fmt.Printf("总共修正了 %v 个标题\n", count) + } + // 去掉 -- 这种情况，这种情况是由于题目标题中包含负号 - + for i := 0; i < len(s7)-2; i++ { + if s7[i] == '-' && s7[i+1] == '-' { + fmt.Printf("【需要修正 -- 的标题是 %v】\n", fmt.Sprintf("%04d.%v", int(frontendQuestionID), s7)) + s7 = s7[:i+1] + s7[i+2:] + count++ + } + } + if count > 0 { + fmt.Printf("总共修正了 %v 个标题\n", count) + } + return s7 +} + // GenerateTagMdRows define func GenerateTagMdRows(solutionIds []int, metaMap map[int]TagList, mdrows []Mdrow, internal bool) []TagList { tl := []TagList{} @@ -123,36 +158,7 @@ func GenerateTagMdRows(solutionIds []int, metaMap map[int]TagList, mdrows []Mdro tmp := TagList{} tmp.FrontendQuestionID = row.FrontendQuestionID tmp.QuestionTitle = strings.TrimSpace(row.QuestionTitle) - s1 := strings.Replace(tmp.QuestionTitle, " ", "-", -1) - s2 := strings.Replace(s1, "'", "", -1) - s3 := strings.Replace(s2, "%", "", -1) - s4 := strings.Replace(s3, "(", "", -1) - s5 := strings.Replace(s4, ")", "", -1) - s6 := strings.Replace(s5, ",", "", -1) - s7 := strings.Replace(s6, "?", "", -1) - count := 0 - // 去掉 --- 这种情况，这种情况是由于题目标题中包含 - ，左右有空格，左右一填充，造成了 ---，3 个 - - for i := 0; i < len(s7)-2; i++ { - if s7[i] == '-' && s7[i+1] == '-' && s7[i+2] == '-' { - fmt.Printf("【需要修正 --- 的标题是 %v】\n", fmt.Sprintf("%04d.%v", int(row.FrontendQuestionID), s7)) - s7 = s7[:i+1] + s7[i+3:] - count++ - } - } - if count > 0 { - fmt.Printf("总共修正了 %v 个标题\n", count) - } - // 去掉 -- 这种情况，这种情况是由于题目标题中包含负号 - - for i := 0; i < len(s7)-2; i++ { - if s7[i] == '-' && s7[i+1] == '-' { - fmt.Printf("【需要修正 -- 的标题是 %v】\n", fmt.Sprintf("%04d.%v", int(row.FrontendQuestionID), s7)) - s7 = s7[:i+1] + s7[i+2:] - count++ - } - } - if count > 0 { - fmt.Printf("总共修正了 %v 个标题\n", count) - } + s7 := standardizedTitle(row.QuestionTitle, row.FrontendQuestionID) if internal { tmp.SolutionPath = fmt.Sprintf("[Go]({{< relref \"/ChapterFour/%v/%v.md\" >}})", util.GetChpaterFourFileNum(int(row.FrontendQuestionID)), fmt.Sprintf("%04d.%v", int(row.FrontendQuestionID), s7)) } else { @@ -174,8 +180,8 @@ type TagLists struct { TagLists []TagList } -//| No. | Title | Solution | Difficulty | TimeComplexity | SpaceComplexity |Favorite| Acceptance | -//|:--------:|:------- | :--------: | :----------: | :----: | :-----: | :-----: |:-----: | +// | No. | Title | Solution | Difficulty | TimeComplexity | SpaceComplexity |Favorite| Acceptance | +// |:--------:|:------- | :--------: | :----------: | :----: | :-----: | :-----: |:-----: | func (tls TagLists) table() string { res := "| No. | Title | Solution | Difficulty | TimeComplexity | SpaceComplexity |Favorite| Acceptance |\n" res += "|:--------:|:------- | :--------: | :----------: | :----: | :-----: | :-----: |:-----: |\n" diff --git a/ctl/models/user.go b/ctl/models/user.go index 2f2964585..d79dc6d5f 100644 --- a/ctl/models/user.go +++ b/ctl/models/user.go @@ -18,9 +18,9 @@ type UserInfo struct { OptimizingEasy int32 OptimizingMedium int32 OptimizingHard int32 - FrequencyHigh int32 `json:"frequency_high"` - FrequencyMid int32 `json:"frequency_mid"` - CategorySlug string `json:"category_slug"` + FrequencyHigh float64 `json:"frequency_high"` + FrequencyMid float64 `json:"frequency_mid"` + CategorySlug string `json:"category_slug"` } // | | Easy | Medium | Hard | Total | optimizing | diff --git a/ctl/pdf.go b/ctl/pdf.go index 342829565..d481df4c5 100644 --- a/ctl/pdf.go +++ b/ctl/pdf.go @@ -3,14 +3,15 @@ package main import ( "bufio" "fmt" - "github.com/halfrost/LeetCode-Go/ctl/util" - "github.com/spf13/cobra" "io" "io/ioutil" "os" "regexp" "strconv" "strings" + + "github.com/halfrost/LeetCode-Go/ctl/util" + "github.com/spf13/cobra" ) var ( @@ -23,7 +24,7 @@ var ( # 说明 -此版本是 https://books.halfrost.com/leetcode 网页的离线版，由于网页版实时会更新，所以此 PDF 版难免会有一些排版或者错别字。如果读者遇到了，可以到网页版相应页面，点击页面 edit 按钮，提交 pr 进行更改。此 PDF 版本号是 V%v.%v.%v。PDF 永久更新地址是 https://github.com/halfrost/LeetCode-Go/releases/，以版本号区分不同版本。笔者还是强烈推荐看在线版，有任何错误都会立即更新。如果觉得此书对刷题有一点点帮助，可以给此书点一个 star，鼓励一下笔者早点更新更多题解。 +此版本是 https://books.halfrost.com/leetcode 网页的离线版，由于网页版实时会更新，所以此 PDF 版难免会有一些排版或者错别字。如果读者遇到了，可以到网页版相应页面，点击页面 edit 按钮，提交 pr 进行更改。此 PDF 版本号是 V%v.%v.%v。PDF 永久更新地址是 https://github.com/halfrost/leetcode-go/releases/，以版本号区分不同版本。笔者还是强烈推荐看在线版，有任何错误都会立即更新。如果觉得此书对刷题有一点点帮助，可以给此书点一个 star，鼓励一下笔者早点更新更多题解。 > 版本号说明，V%v.%v.%v，%v 是大版本号，%v 代表当前题解中有几百题，目前是 %v 题，所以第二个版本号是 %v，%v 代表当前题解中有几十题，目前是 %v 题，所以第三个版本号是 %v 。 diff --git a/ctl/render.go b/ctl/render.go index cbd4dc460..3e62a36eb 100644 --- a/ctl/render.go +++ b/ctl/render.go @@ -18,11 +18,11 @@ import ( var ( chapterTwoList = []string{"Array", "String", "Two Pointers", "Linked List", "Stack", "Tree", "Dynamic Programming", "Backtracking", "Depth First Search", "Breadth First Search", - "Binary Search", "Math", "Hash Table", "Sort", "Bit Manipulation", "Union Find", "Sliding Window", "Segment Tree", "Binary Indexed Tree"} + "Binary Search", "Math", "Hash Table", "Sorting", "Bit Manipulation", "Union Find", "Sliding Window", "Segment Tree", "Binary Indexed Tree"} chapterTwoFileName = []string{"Array", "String", "Two_Pointers", "Linked_List", "Stack", "Tree", "Dynamic_Programming", "Backtracking", "Depth_First_Search", "Breadth_First_Search", - "Binary_Search", "Math", "Hash_Table", "Sort", "Bit_Manipulation", "Union_Find", "Sliding_Window", "Segment_Tree", "Binary_Indexed_Tree"} + "Binary_Search", "Math", "Hash_Table", "Sorting", "Bit_Manipulation", "Union_Find", "Sliding_Window", "Segment_Tree", "Binary_Indexed_Tree"} chapterTwoSlug = []string{"array", "string", "two-pointers", "linked-list", "stack", "tree", "dynamic-programming", "backtracking", "depth-first-search", "breadth-first-search", - "binary-search", "math", "hash-table", "sort", "bit-manipulation", "union-find", "sliding-window", "segment-tree", "binary-indexed-tree"} + "binary-search", "math", "hash-table", "sorting", "bit-manipulation", "union-find", "sliding-window", "segment-tree", "binary-indexed-tree"} ) func newBuildCommand() *cobra.Command { @@ -163,7 +163,8 @@ func renderReadme(filePath string, total, try int, mdrows, omdrows m.Mdrows, use } // internal: true 渲染的链接都是 hugo 内部链接，用户生成 hugo web -// false 渲染的链接是外部 HTTPS 链接，用于生成 PDF +// +// false 渲染的链接是外部 HTTPS 链接，用于生成 PDF func buildChapterTwo(internal bool) { var ( gr m.GraphQLResp diff --git a/ctl/request.go b/ctl/request.go index 056d5e141..8222a1fc0 100644 --- a/ctl/request.go +++ b/ctl/request.go @@ -3,9 +3,10 @@ package main import ( "bytes" "fmt" - "github.com/mozillazg/request" "io/ioutil" "net/http" + + "github.com/mozillazg/request" ) const ( diff --git a/ctl/statistic.go b/ctl/statistic.go index c796dc44e..20b84ccb9 100644 --- a/ctl/statistic.go +++ b/ctl/statistic.go @@ -1,9 +1,10 @@ package main import ( + "sort" + m "github.com/halfrost/LeetCode-Go/ctl/models" "github.com/halfrost/LeetCode-Go/ctl/util" - "sort" ) func statisticalData(problemsMap map[int]m.StatStatusPairs, solutionIds []int) (easyTotal, mediumTotal, hardTotal, optimizingEasy, optimizingMedium, optimizingHard int32, optimizingIds []int) { diff --git a/ctl/template/Sort.md b/ctl/template/Sorting.md similarity index 92% rename from ctl/template/Sort.md rename to ctl/template/Sorting.md index 00ded1063..5038c03cf 100644 --- a/ctl/template/Sort.md +++ b/ctl/template/Sorting.md @@ -1,10 +1,10 @@ --- -title: 2.14 ✅ Sort +title: 2.14 ✅ Sorting type: docs weight: 14 --- -# Sort +# Sorting ![](https://img.halfrost.com/Leetcode/Sort.png) diff --git a/ctl/template/template.markdown b/ctl/template/template.markdown index 089c448a2..c0b24343e 100644 --- a/ctl/template/template.markdown +++ b/ctl/template/template.markdown @@ -10,9 +10,9 @@ ![](./website/static/wechat-qr-code.png)

-GitHub All Releases +GitHub All Releases - + @@ -23,7 +23,7 @@

-GitHub +GitHub @@ -32,7 +32,7 @@ - +

支持 Progressive Web Apps 和 Dark Mode 的题解电子书《LeetCode Cookbook》 Online Reading @@ -42,10 +42,10 @@

-离线版本的电子书《LeetCode Cookbook》PDF Download here +离线版本的电子书《LeetCode Cookbook》PDF Download here

- +

通过 iOS / Android 浏览器安装 PWA 版《LeetCode Cookbook》至设备桌面随时学习 @@ -550,7 +550,7 @@ Problems List in [there](https://books.halfrost.com/leetcode/ChapterTwo/Bit_Mani ![](./topic/Union_Find.png) -- 灵活使用并查集的思想，熟练掌握并查集的[模板](https://github.com/halfrost/LeetCode-Go/blob/master/template/UnionFind.go)，模板中有两种并查集的实现方式，一种是路径压缩 + 秩优化的版本，另外一种是计算每个集合中元素的个数 + 最大集合元素个数的版本，这两种版本都有各自使用的地方。能使用第一类并查集模板的题目有：第 128 题，第 130 题，第 547 题，第 684 题，第 721 题，第 765 题，第 778 题，第 839 题，第 924 题，第 928 题，第 947 题，第 952 题，第 959 题，第 990 题。能使用第二类并查集模板的题目有：第 803 题，第 952 题。第 803 题秩优化和统计集合个数这些地方会卡时间，如果不优化，会 TLE。 +- 灵活使用并查集的思想，熟练掌握并查集的[模板](https://github.com/halfrost/leetcode-go/blob/master/template/UnionFind.go)，模板中有两种并查集的实现方式，一种是路径压缩 + 秩优化的版本，另外一种是计算每个集合中元素的个数 + 最大集合元素个数的版本，这两种版本都有各自使用的地方。能使用第一类并查集模板的题目有：第 128 题，第 130 题，第 547 题，第 684 题，第 721 题，第 765 题，第 778 题，第 839 题，第 924 题，第 928 题，第 947 题，第 952 题，第 959 题，第 990 题。能使用第二类并查集模板的题目有：第 803 题，第 952 题。第 803 题秩优化和统计集合个数这些地方会卡时间，如果不优化，会 TLE。 - 并查集是一种思想，有些题需要灵活使用这种思想，而不是死套模板，如第 399 题，这一题是 stringUnionFind，利用并查集思想实现的。这里每个节点是基于字符串和 map 的，而不是单纯的用 int 节点编号实现的。 - 有些题死套模板反而做不出来，比如第 685 题，这一题不能路径压缩和秩优化，因为题目中涉及到有向图，需要知道节点的前驱节点，如果路径压缩了，这一题就没法做了。这一题不需要路径压缩和秩优化。 - 灵活的抽象题目给的信息，将给定的信息合理的编号，使用并查集解题，并用 map 降低时间复杂度，如第 721 题，第 959 题。 @@ -630,10 +630,10 @@ Problems List in [there](https://books.halfrost.com/leetcode/ChapterTwo/Binary_I ----------------------------------------------------------------------------------------

- +

-Thank you for reading here. This is bonus. You can download my [《ACM-ICPC Algorithm Template》](https://github.com/halfrost/LeetCode-Go/releases/tag/Special/) +Thank you for reading here. This is bonus. You can download my [《ACM-ICPC Algorithm Template》](https://github.com/halfrost/leetcode-go/releases/tag/Special/) diff --git a/ctl/template_render.go b/ctl/template_render.go index 374b36f8c..01c65f28f 100644 --- a/ctl/template_render.go +++ b/ctl/template_render.go @@ -3,11 +3,12 @@ package main import ( "bytes" "fmt" - m "github.com/halfrost/LeetCode-Go/ctl/models" - "github.com/halfrost/LeetCode-Go/ctl/util" "html/template" "io/ioutil" "os" + + m "github.com/halfrost/LeetCode-Go/ctl/models" + "github.com/halfrost/LeetCode-Go/ctl/util" ) func makeReadmeFile(mdrows m.Mdrows) { diff --git a/ctl/util/go.mod b/ctl/util/go.mod new file mode 100644 index 000000000..6127aeea8 --- /dev/null +++ b/ctl/util/go.mod @@ -0,0 +1,3 @@ +module github.com/halfrost/LeetCode-Go/ctl/util + +go 1.19 diff --git a/go.mod b/go.mod index 8fdb4bcec..3b163f0e1 100644 --- a/go.mod +++ b/go.mod @@ -1,13 +1,30 @@ module github.com/halfrost/LeetCode-Go -go 1.15 +go 1.19 + +replace github.com/halfrost/LeetCode-Go/structures => ./structures + +replace github.com/halfrost/LeetCode-Go/template => ./template + +replace github.com/halfrost/LeetCode-Go/ctl/util => ./ctl/util + +replace github.com/halfrost/LeetCode-Go/ctl/models => ./ctl/models + +require ( + github.com/BurntSushi/toml v1.2.0 + github.com/halfrost/LeetCode-Go/ctl/models v0.0.0-20220910225043-e3bb5aff34d0 + github.com/halfrost/LeetCode-Go/ctl/util v0.0.0-20220910225043-e3bb5aff34d0 + github.com/halfrost/LeetCode-Go/structures v0.0.0-20220910233101-aa0e2c897b18 + github.com/halfrost/LeetCode-Go/template v0.0.0-20220910233504-e2a72e6212ce + github.com/mozillazg/request v0.8.0 + github.com/spf13/cobra v1.5.0 +) require ( - github.com/BurntSushi/toml v0.3.1 github.com/bitly/go-simplejson v0.5.0 // indirect github.com/bmizerany/assert v0.0.0-20160611221934-b7ed37b82869 // indirect - github.com/mozillazg/request v0.8.0 - github.com/spf13/cobra v1.1.1 - github.com/stretchr/testify v1.3.0 - golang.org/x/net v0.0.0-20201021035429-f5854403a974 // indirect + github.com/inconshreveable/mousetrap v1.0.0 // indirect + github.com/kr/pretty v0.3.0 // indirect + github.com/spf13/pflag v1.0.5 // indirect + golang.org/x/net v0.7.0 // indirect ) diff --git a/go.sum b/go.sum index 0fbb291ac..d1e5e64b1 100644 --- a/go.sum +++ b/go.sum @@ -1,303 +1,36 @@ -cloud.google.com/go v0.26.0/go.mod h1:aQUYkXzVsufM+DwF1aE+0xfcU+56JwCaLick0ClmMTw= -cloud.google.com/go v0.34.0/go.mod h1:aQUYkXzVsufM+DwF1aE+0xfcU+56JwCaLick0ClmMTw= -cloud.google.com/go v0.38.0/go.mod h1:990N+gfupTy94rShfmMCWGDn0LpTmnzTp2qbd1dvSRU= -cloud.google.com/go v0.44.1/go.mod h1:iSa0KzasP4Uvy3f1mN/7PiObzGgflwredwwASm/v6AU= -cloud.google.com/go v0.44.2/go.mod h1:60680Gw3Yr4ikxnPRS/oxxkBccT6SA1yMk63TGekxKY= -cloud.google.com/go v0.45.1/go.mod h1:RpBamKRgapWJb87xiFSdk4g1CME7QZg3uwTez+TSTjc= -cloud.google.com/go v0.46.3/go.mod h1:a6bKKbmY7er1mI7TEI4lsAkts/mkhTSZK8w33B4RAg0= -cloud.google.com/go/bigquery v1.0.1/go.mod 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h1:hI93XBmqTisBFMUTm0b8Fm+jr3Dg1NNxqwp+5A1VGuI= -gopkg.in/yaml.v2 v2.2.8/go.mod h1:hI93XBmqTisBFMUTm0b8Fm+jr3Dg1NNxqwp+5A1VGuI= -honnef.co/go/tools v0.0.0-20190102054323-c2f93a96b099/go.mod h1:rf3lG4BRIbNafJWhAfAdb/ePZxsR/4RtNHQocxwk9r4= -honnef.co/go/tools v0.0.0-20190106161140-3f1c8253044a/go.mod h1:rf3lG4BRIbNafJWhAfAdb/ePZxsR/4RtNHQocxwk9r4= -honnef.co/go/tools v0.0.0-20190418001031-e561f6794a2a/go.mod h1:rf3lG4BRIbNafJWhAfAdb/ePZxsR/4RtNHQocxwk9r4= -honnef.co/go/tools v0.0.1-2019.2.3/go.mod h1:a3bituU0lyd329TUQxRnasdCoJDkEUEAqEt0JzvZhAg= -rsc.io/binaryregexp v0.2.0/go.mod h1:qTv7/COck+e2FymRvadv62gMdZztPaShugOCi3I+8D8= +gopkg.in/yaml.v2 v2.4.0/go.mod h1:RDklbk79AGWmwhnvt/jBztapEOGDOx6ZbXqjP6csGnQ= +gopkg.in/yaml.v3 v3.0.1 h1:fxVm/GzAzEWqLHuvctI91KS9hhNmmWOoWu0XTYJS7CA= diff --git a/leetcode/0003.Longest-Substring-Without-Repeating-Characters/3. Longest Substring Without Repeating Characters.go b/leetcode/0003.Longest-Substring-Without-Repeating-Characters/3. Longest Substring Without Repeating Characters.go index 672dbdb54..541f868de 100644 --- a/leetcode/0003.Longest-Substring-Without-Repeating-Characters/3. Longest Substring Without Repeating Characters.go +++ b/leetcode/0003.Longest-Substring-Without-Repeating-Characters/3. Longest Substring Without Repeating Characters.go @@ -8,7 +8,7 @@ func lengthOfLongestSubstring(s string) int { var bitSet [256]bool result, left, right := 0, 0, 0 for left < len(s) { - // 右侧字符对应的bitSet被标记true，说明此字符在X位置重复，需要左侧向前移动，直到将X标记为false + // 右侧字符对应的 bitSet 被标记 true，说明此字符在 X 位置重复，需要左侧向前移动，直到将 X 标记为 false if bitSet[s[right]] { bitSet[s[left]] = false left++ @@ -27,19 +27,20 @@ func lengthOfLongestSubstring(s string) int { } // 解法二 滑动窗口 -func lengthOfLongestSubstring_(s string) int { +func lengthOfLongestSubstring1(s string) int { if len(s) == 0 { return 0 } - var freq [256]int + var freq [127]int result, left, right := 0, 0, -1 for left < len(s) { - if right+1 < len(s) && freq[s[right+1]-'a'] == 0 { - freq[s[right+1]-'a']++ + if right+1 < len(s) && freq[s[right+1]] == 0 { + freq[s[right+1]]++ right++ + } else { - freq[s[left]-'a']-- + freq[s[left]]-- left++ } result = max(result, right-left+1) @@ -47,6 +48,21 @@ func lengthOfLongestSubstring_(s string) int { return result } +// 解法三 滑动窗口-哈希桶 +func lengthOfLongestSubstring2(s string) int { + right, left, res := 0, 0, 0 + indexes := make(map[byte]int, len(s)) + for left < len(s) { + if idx, ok := indexes[s[left]]; ok && idx >= right { + right = idx + 1 + } + indexes[s[left]] = left + left++ + res = max(res, left-right) + } + return res +} + func max(a int, b int) int { if a > b { return a diff --git a/leetcode/0003.Longest-Substring-Without-Repeating-Characters/3. Longest Substring Without Repeating Characters_test.go b/leetcode/0003.Longest-Substring-Without-Repeating-Characters/3. Longest Substring Without Repeating Characters_test.go index 5dc9bcd2a..7eebdbfa8 100644 --- a/leetcode/0003.Longest-Substring-Without-Repeating-Characters/3. Longest Substring Without Repeating Characters_test.go +++ b/leetcode/0003.Longest-Substring-Without-Repeating-Characters/3. Longest Substring Without Repeating Characters_test.go @@ -51,7 +51,7 @@ func Test_Problem3(t *testing.T) { for _, q := range qs { _, p := q.ans3, q.para3 - fmt.Printf("【input】:%v 【output】:%v\n", p, lengthOfLongestSubstring_(p.s)) + fmt.Printf("【input】:%v 【output】:%v\n", p, lengthOfLongestSubstring(p.s)) } fmt.Printf("\n\n\n") } diff --git a/leetcode/0003.Longest-Substring-Without-Repeating-Characters/README.md b/leetcode/0003.Longest-Substring-Without-Repeating-Characters/README.md index 15ecc0ebe..9f80ab4a5 100644 --- a/leetcode/0003.Longest-Substring-Without-Repeating-Characters/README.md +++ b/leetcode/0003.Longest-Substring-Without-Repeating-Characters/README.md @@ -34,7 +34,7 @@ Explanation: The answer is "wke", with the length of 3. ## 题目大意 -在一个字符串重寻找没有重复字母的最长子串。 +在一个字符串中寻找没有重复字母的最长子串。 ## 解题思路 diff --git a/leetcode/0014.Longest-Common-Prefix/14.Longest Common Prefix.go b/leetcode/0014.Longest-Common-Prefix/14.Longest Common Prefix.go new file mode 100644 index 000000000..259c5c835 --- /dev/null +++ b/leetcode/0014.Longest-Common-Prefix/14.Longest Common Prefix.go @@ -0,0 +1,16 @@ +package leetcode + +func longestCommonPrefix(strs []string) string { + prefix := strs[0] + + for i := 1; i < len(strs); i++ { + for j := 0; j < len(prefix); j++ { + if len(strs[i]) <= j || strs[i][j] != prefix[j] { + prefix = prefix[0:j] + break + } + } + } + + return prefix +} diff --git a/leetcode/0014.Longest-Common-Prefix/14.Longest Common Prefix_test.go b/leetcode/0014.Longest-Common-Prefix/14.Longest Common Prefix_test.go new file mode 100644 index 000000000..e7635d52f --- /dev/null +++ b/leetcode/0014.Longest-Common-Prefix/14.Longest Common Prefix_test.go @@ -0,0 +1,50 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question14 struct { + para14 + ans14 +} + +// para 是参数 +type para14 struct { + strs []string +} + +// ans 是答案 +type ans14 struct { + ans string +} + +func Test_Problem14(t *testing.T) { + + qs := []question14{ + + { + para14{[]string{"flower", "flow", "flight"}}, + ans14{"fl"}, + }, + + { + para14{[]string{"dog", "racecar", "car"}}, + ans14{""}, + }, + + { + para14{[]string{"ab", "a"}}, + ans14{"a"}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 14------------------------\n") + + for _, q := range qs { + _, p := q.ans14, q.para14 + fmt.Printf("【input】:%v 【output】:%v\n", p.strs, longestCommonPrefix(p.strs)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0014.Longest-Common-Prefix/README.md b/leetcode/0014.Longest-Common-Prefix/README.md new file mode 100644 index 000000000..26b9e03bf --- /dev/null +++ b/leetcode/0014.Longest-Common-Prefix/README.md @@ -0,0 +1,57 @@ +# [14. Longest Common Prefix](https://leetcode.com/problems/longest-common-prefix/) + +## 题目 + +Write a function to find the longest common prefix string amongst an array of strings. + +If there is no common prefix, return an empty string "". + +**Example 1**: + + Input: strs = ["flower","flow","flight"] + Output: "fl" + +**Example 2**: + + Input: strs = ["dog","racecar","car"] + Output: "" + Explanation: There is no common prefix among the input strings. + +**Constraints:** + +- 1 <= strs.length <= 200 +- 0 <= strs[i].length <= 200 +- strs[i] consists of only lower-case English letters. + +## 题目大意 + +编写一个函数来查找字符串数组中的最长公共前缀。 + +如果不存在公共前缀，返回空字符串 ""。 + +## 解题思路 + +- 对 strs 按照字符串长度进行升序排序，求出 strs 中长度最小字符串的长度 minLen +- 逐个比较长度最小字符串与其它字符串中的字符，如果不相等就返回 commonPrefix,否则就把该字符加入 commonPrefix + +## 代码 + +```go + +package leetcode + +func longestCommonPrefix(strs []string) string { + prefix := strs[0] + + for i := 1; i < len(strs); i++ { + for j := 0; j < len(prefix); j++ { + if len(strs[i]) <= j || strs[i][j] != prefix[j] { + prefix = prefix[0:j] + break + } + } + } + + return prefix +} +``` diff --git a/leetcode/0016.3Sum-Closest/16. 3Sum Closest.go b/leetcode/0016.3Sum-Closest/16. 3Sum Closest.go index 0beaac707..ed4465d17 100644 --- a/leetcode/0016.3Sum-Closest/16. 3Sum Closest.go +++ b/leetcode/0016.3Sum-Closest/16. 3Sum Closest.go @@ -11,6 +11,9 @@ func threeSumClosest(nums []int, target int) int { if n > 2 { sort.Ints(nums) for i := 0; i < n-2; i++ { + if i > 0 && nums[i] == nums[i-1] { + continue + } for j, k := i+1, n-1; j < k; { sum := nums[i] + nums[j] + nums[k] if abs(sum-target) < diff { diff --git a/leetcode/0018.4Sum/18. 4Sum.go b/leetcode/0018.4Sum/18. 4Sum.go index 38f8da3d5..be44e5c7f 100644 --- a/leetcode/0018.4Sum/18. 4Sum.go +++ b/leetcode/0018.4Sum/18. 4Sum.go @@ -2,7 +2,92 @@ package leetcode import "sort" -func fourSum(nums []int, target int) [][]int { +// 解法一 双指针 +func fourSum(nums []int, target int) (quadruplets [][]int) { + sort.Ints(nums) + n := len(nums) + for i := 0; i < n-3 && nums[i]+nums[i+1]+nums[i+2]+nums[i+3] <= target; i++ { + if i > 0 && nums[i] == nums[i-1] || nums[i]+nums[n-3]+nums[n-2]+nums[n-1] < target { + continue + } + for j := i + 1; j < n-2 && nums[i]+nums[j]+nums[j+1]+nums[j+2] <= target; j++ { + if j > i+1 && nums[j] == nums[j-1] || nums[i]+nums[j]+nums[n-2]+nums[n-1] < target { + continue + } + for left, right := j+1, n-1; left < right; { + if sum := nums[i] + nums[j] + nums[left] + nums[right]; sum == target { + quadruplets = append(quadruplets, []int{nums[i], nums[j], nums[left], nums[right]}) + for left++; left < right && nums[left] == nums[left-1]; left++ { + } + for right--; left < right && nums[right] == nums[right+1]; right-- { + } + } else if sum < target { + left++ + } else { + right-- + } + } + } + } + return +} + +// 解法二 kSum +func fourSum1(nums []int, target int) [][]int { + res, cur := make([][]int, 0), make([]int, 0) + sort.Ints(nums) + kSum(nums, 0, len(nums)-1, target, 4, cur, &res) + return res +} + +func kSum(nums []int, left, right int, target int, k int, cur []int, res *[][]int) { + if right-left+1 < k || k < 2 || target < nums[left]*k || target > nums[right]*k { + return + } + if k == 2 { + // 2 sum + twoSum(nums, left, right, target, cur, res) + } else { + for i := left; i < len(nums); i++ { + if i == left || (i > left && nums[i-1] != nums[i]) { + next := make([]int, len(cur)) + copy(next, cur) + next = append(next, nums[i]) + kSum(nums, i+1, len(nums)-1, target-nums[i], k-1, next, res) + } + } + } + +} + +func twoSum(nums []int, left, right int, target int, cur []int, res *[][]int) { + for left < right { + sum := nums[left] + nums[right] + if sum == target { + cur = append(cur, nums[left], nums[right]) + temp := make([]int, len(cur)) + copy(temp, cur) + *res = append(*res, temp) + // reset cur to previous state + cur = cur[:len(cur)-2] + left++ + right-- + for left < right && nums[left] == nums[left-1] { + left++ + } + for left < right && nums[right] == nums[right+1] { + right-- + } + } else if sum < target { + left++ + } else { + right-- + } + } +} + +// 解法三 +func fourSum2(nums []int, target int) [][]int { res := [][]int{} counter := map[int]int{} for _, value := range nums { diff --git a/leetcode/0019.Remove-Nth-Node-From-End-of-List/19. Remove Nth Node From End of List.go b/leetcode/0019.Remove-Nth-Node-From-End-of-List/19. Remove Nth Node From End of List.go index a74cffcd8..7c2855bbb 100644 --- a/leetcode/0019.Remove-Nth-Node-From-End-of-List/19. Remove Nth Node From End of List.go +++ b/leetcode/0019.Remove-Nth-Node-From-End-of-List/19. Remove Nth Node From End of List.go @@ -17,31 +17,18 @@ type ListNode = structures.ListNode // 解法一 func removeNthFromEnd(head *ListNode, n int) *ListNode { - if head == nil { - return nil - } - var fast, slow *ListNode - fast = head - slow = head - step := 0 - for i := 0; i < n; i++ { - // n maybe much larger than length of linklist - if fast.Next == nil && step < n-1 { - return head + dummyHead := &ListNode{Next: head} + preSlow, slow, fast := dummyHead, head, head + for fast != nil { + if n <= 0 { + preSlow = slow + slow = slow.Next } + n-- fast = fast.Next - step++ } - if fast == nil { - head = head.Next - return head - } - for fast.Next != nil { - fast = fast.Next - slow = slow.Next - } - slow.Next = slow.Next.Next - return head + preSlow.Next = slow.Next + return dummyHead.Next } // 解法二 diff --git a/leetcode/0019.Remove-Nth-Node-From-End-of-List/19. Remove Nth Node From End of List_test.go b/leetcode/0019.Remove-Nth-Node-From-End-of-List/19. Remove Nth Node From End of List_test.go index 6ff756020..f112b55d3 100644 --- a/leetcode/0019.Remove-Nth-Node-From-End-of-List/19. Remove Nth Node From End of List_test.go +++ b/leetcode/0019.Remove-Nth-Node-From-End-of-List/19. Remove Nth Node From End of List_test.go @@ -31,7 +31,7 @@ func Test_Problem19(t *testing.T) { { para19{[]int{1}, 3}, - ans19{[]int{2}}, + ans19{[]int{1}}, }, { diff --git a/leetcode/0024.Swap-Nodes-in-Pairs/24. Swap Nodes in Pairs.go b/leetcode/0024.Swap-Nodes-in-Pairs/24. Swap Nodes in Pairs.go index 1dc9e41de..ac1e7e09f 100644 --- a/leetcode/0024.Swap-Nodes-in-Pairs/24. Swap Nodes in Pairs.go +++ b/leetcode/0024.Swap-Nodes-in-Pairs/24. Swap Nodes in Pairs.go @@ -16,30 +16,9 @@ type ListNode = structures.ListNode */ func swapPairs(head *ListNode) *ListNode { - if head == nil || head.Next == nil { - return head + dummy := &ListNode{Next: head} + for pt := dummy; pt != nil && pt.Next != nil && pt.Next.Next != nil; { + pt, pt.Next, pt.Next.Next, pt.Next.Next.Next = pt.Next, pt.Next.Next, pt.Next.Next.Next, pt.Next } - s := head.Next - var behind *ListNode - for head.Next != nil { - headNext := head.Next - if behind != nil && behind.Next != nil { - behind.Next = headNext - } - var next *ListNode - if head.Next.Next != nil { - next = head.Next.Next - } - if head.Next.Next != nil { - head.Next = next - } else { - head.Next = nil - } - headNext.Next = head - behind = head - if head.Next != nil { - head = next - } - } - return s + return dummy.Next } diff --git a/leetcode/0028.Implement-strStr/28. Implement strStr().go b/leetcode/0028.Find-the-Index-of-the-First-Occurrence-in-a-String/28. Find the Index of the First Occurrence in a String.go similarity index 100% rename from leetcode/0028.Implement-strStr/28. Implement strStr().go rename to leetcode/0028.Find-the-Index-of-the-First-Occurrence-in-a-String/28. Find the Index of the First Occurrence in a String.go diff --git a/leetcode/0028.Implement-strStr/28. Implement strStr()_test.go b/leetcode/0028.Find-the-Index-of-the-First-Occurrence-in-a-String/28. Find the Index of the First Occurrence in a String_test.go similarity index 100% rename from leetcode/0028.Implement-strStr/28. Implement strStr()_test.go rename to leetcode/0028.Find-the-Index-of-the-First-Occurrence-in-a-String/28. Find the Index of the First Occurrence in a String_test.go diff --git a/leetcode/0028.Implement-strStr/README.md b/leetcode/0028.Find-the-Index-of-the-First-Occurrence-in-a-String/README.md similarity index 85% rename from leetcode/0028.Implement-strStr/README.md rename to leetcode/0028.Find-the-Index-of-the-First-Occurrence-in-a-String/README.md index 5fb575296..d1e643bd9 100644 --- a/leetcode/0028.Implement-strStr/README.md +++ b/leetcode/0028.Find-the-Index-of-the-First-Occurrence-in-a-String/README.md @@ -1,4 +1,4 @@ -# [28. Implement strStr()](https://leetcode.com/problems/implement-strstr/) +# [28. Find the Index of the First Occurrence in a String](https://leetcode.com/problems/find-the-index-of-the-first-occurrence-in-a-string/) ## 题目 diff --git a/leetcode/0031.Next-Permutation/31. Next Permutation.go b/leetcode/0031.Next-Permutation/31. Next Permutation.go index 94493516a..04e07485e 100644 --- a/leetcode/0031.Next-Permutation/31. Next Permutation.go +++ b/leetcode/0031.Next-Permutation/31. Next Permutation.go @@ -1,5 +1,6 @@ package leetcode +// 解法一 func nextPermutation(nums []int) { i, j := 0, 0 for i = len(nums) - 2; i >= 0; i-- { @@ -29,3 +30,43 @@ func reverse(nums *[]int, i, j int) { func swap(nums *[]int, i, j int) { (*nums)[i], (*nums)[j] = (*nums)[j], (*nums)[i] } + +// 解法二 +// [2,(3),6,5,4,1] -> 2,(4),6,5,(3),1 -> 2,4, 1,3,5,6 +func nextPermutation1(nums []int) { + var n = len(nums) + var pIdx = checkPermutationPossibility(nums) + if pIdx == -1 { + reverse(&nums, 0, n-1) + return + } + + var rp = len(nums) - 1 + // start from right most to leftward,find the first number which is larger than PIVOT + for rp > 0 { + if nums[rp] > nums[pIdx] { + swap(&nums, pIdx, rp) + break + } else { + rp-- + } + } + // Finally, Reverse all elements which are right from pivot + reverse(&nums, pIdx+1, n-1) +} + +// checkPermutationPossibility returns 1st occurrence Index where +// value is in decreasing order(from right to left) +// returns -1 if not found(it's already in its last permutation) +func checkPermutationPossibility(nums []int) (idx int) { + // search right to left for 1st number(from right) that is not in increasing order + var rp = len(nums) - 1 + for rp > 0 { + if nums[rp-1] < nums[rp] { + idx = rp - 1 + return idx + } + rp-- + } + return -1 +} diff --git a/leetcode/0040.Combination-Sum-II/README.md b/leetcode/0040.Combination-Sum-II/README.md index 5375739bb..b53f67dcd 100755 --- a/leetcode/0040.Combination-Sum-II/README.md +++ b/leetcode/0040.Combination-Sum-II/README.md @@ -45,4 +45,4 @@ candidates 中的每个数字在每个组合中只能使用一次。 ## 解题思路 - 题目要求出总和为 sum 的所有组合，组合需要去重。这一题是第 39 题的加强版，第 39 题中元素可以重复利用(重复元素可无限次使用)，这一题中元素只能有限次数的利用，因为存在重复元素，并且每个元素只能用一次(重复元素只能使用有限次) -- 这一题和第 47 题类似，只不过元素可以反复使用。 +- 这一题和第 47 题类似。 diff --git a/leetcode/0048.Rotate-Image/48. Rotate Image.go b/leetcode/0048.Rotate-Image/48. Rotate Image.go index a21d5fa80..f27e91e35 100644 --- a/leetcode/0048.Rotate-Image/48. Rotate Image.go +++ b/leetcode/0048.Rotate-Image/48. Rotate Image.go @@ -1,26 +1,61 @@ package leetcode +// 解法一 func rotate(matrix [][]int) { - row := len(matrix) - if row <= 0 { - return - } - column := len(matrix[0]) + length := len(matrix) // rotate by diagonal 对角线变换 - for i := 0; i < row; i++ { - for j := i + 1; j < column; j++ { - tmp := matrix[i][j] - matrix[i][j] = matrix[j][i] - matrix[j][i] = tmp + for i := 0; i < length; i++ { + for j := i + 1; j < length; j++ { + matrix[i][j], matrix[j][i] = matrix[j][i], matrix[i][j] } } // rotate by vertical centerline 竖直轴对称翻转 - halfColumn := column / 2 - for i := 0; i < row; i++ { - for j := 0; j < halfColumn; j++ { - tmp := matrix[i][j] - matrix[i][j] = matrix[i][column-j-1] - matrix[i][column-j-1] = tmp + for i := 0; i < length; i++ { + for j := 0; j < length/2; j++ { + matrix[i][j], matrix[i][length-j-1] = matrix[i][length-j-1], matrix[i][j] } } } + +// 解法二 +func rotate1(matrix [][]int) { + n := len(matrix) + if n == 1 { + return + } + /* rotate clock-wise = 1. transpose matrix => 2. reverse(matrix[i]) + + 1 2 3 4 1 5 9 13 13 9 5 1 + 5 6 7 8 => 2 6 10 14 => 14 10 6 2 + 9 10 11 12 3 7 11 15 15 11 7 3 + 13 14 15 16 4 8 12 16 16 12 8 4 + + */ + + for i := 0; i < n; i++ { + // transpose, i=rows, j=columns + // j = i+1, coz diagonal elements didn't change in a square matrix + for j := i + 1; j < n; j++ { + swap(matrix, i, j) + } + // reverse each row of the image + matrix[i] = reverse(matrix[i]) + } +} + +// swap changes original slice's i,j position +func swap(nums [][]int, i, j int) { + nums[i][j], nums[j][i] = nums[j][i], nums[i][j] +} + +// reverses a row of image, matrix[i] +func reverse(nums []int) []int { + var lp, rp = 0, len(nums) - 1 + + for lp < rp { + nums[lp], nums[rp] = nums[rp], nums[lp] + lp++ + rp-- + } + return nums +} diff --git a/leetcode/0051.N-Queens/51. N-Queens.go b/leetcode/0051.N-Queens/51. N-Queens.go index de68f47bd..ba63a9100 100644 --- a/leetcode/0051.N-Queens/51. N-Queens.go +++ b/leetcode/0051.N-Queens/51. N-Queens.go @@ -47,39 +47,45 @@ func generateBoard(n int, row *[]int) []string { return board } -// 解法二 二进制操作法 -// class Solution -// { -// int n; -// string getNq(int p) -// { -// string s(n, '.'); -// s[p] = 'Q'; -// return s; -// } -// void nQueens(int p, int l, int m, int r, vector> &res) -// { -// static vector ans; -// if (p >= n) -// { -// res.push_back(ans); -// return ; -// } -// int mask = l | m | r; -// for (int i = 0, b = 1; i < n; ++ i, b <<= 1) -// if (!(mask & b)) -// { -// ans.push_back(getNq(i)); -// nQueens(p + 1, (l | b) >> 1, m | b, (r | b) << 1, res); -// ans.pop_back(); -// } -// } -// public: -// vector > solveNQueens(int n) -// { -// this->n = n; -// vector> res; -// nQueens(0, 0, 0, 0, res); -// return res; -// } -// }; +// 解法二 二进制操作法 Signed-off-by: Hanlin Shi shihanlin9@gmail.com +func solveNQueens2(n int) (res [][]string) { + placements := make([]string, n) + for i := range placements { + buf := make([]byte, n) + for j := range placements { + if i == j { + buf[j] = 'Q' + } else { + buf[j] = '.' + } + } + placements[i] = string(buf) + } + var construct func(prev []int) + construct = func(prev []int) { + if len(prev) == n { + plan := make([]string, n) + for i := 0; i < n; i++ { + plan[i] = placements[prev[i]] + } + res = append(res, plan) + return + } + occupied := 0 + for i := range prev { + dist := len(prev) - i + bit := 1 << prev[i] + occupied |= bit | bit<>dist + } + prev = append(prev, -1) + for i := 0; i < n; i++ { + if (occupied>>i)&1 != 0 { + continue + } + prev[len(prev)-1] = i + construct(prev) + } + } + construct(make([]int, 0, n)) + return +} diff --git a/leetcode/0051.N-Queens/README.md b/leetcode/0051.N-Queens/README.md index c2be733ec..6fcabdee5 100755 --- a/leetcode/0051.N-Queens/README.md +++ b/leetcode/0051.N-Queens/README.md @@ -40,4 +40,5 @@ Each solution contains a distinct board configuration of the *n*-queens' placem - 利用 col 数组记录列信息，col 有 `n` 列。用 dia1，dia2 记录从左下到右上的对角线，从左上到右下的对角线的信息，dia1 和 dia2 分别都有 `2*n-1` 个。 - dia1 对角线的规律是 `i + j 是定值`，例如[0,0]，为 0；[1,0]、[0,1] 为 1；[2,0]、[1,1]、[0,2] 为 2； - dia2 对角线的规律是 `i - j 是定值`，例如[0,7]，为 -7；[0,6]、[1,7] 为 -6；[0,5]、[1,6]、[2,7] 为 -5；为了使他们从 0 开始，i - j + n - 1 偏移到 0 开始，所以 dia2 的规律是 `i - j + n - 1 为定值`。 +- 还有一个位运算的方法，每行只能选一个位置放皇后，那么对每行遍历可能放皇后的位置。如何高效判断哪些点不能放皇后呢？这里的做法毕竟巧妙，把所有之前选过的点按照顺序存下来，然后根据之前选的点到当前行的距离，就可以快速判断是不是会有冲突。举个例子: 假如在 4 皇后问题中，如果第一二行已经选择了位置 [1, 3]，那么在第三行选择时，首先不能再选 1, 3 列了，而对于第三行， 1 距离长度为2，所以它会影响到 -1, 3 两个列。同理，3 在第二行，距离第三行为 1，所以 3 会影响到列 2, 4。由上面的结果，我们知道 -1, 4 超出边界了不用去管，别的不能选的点是 1, 2, 3，所以第三行就只能选 0。在代码实现中，可以在每次遍历前根据之前选择的情况生成一个 occupied 用来记录当前这一行，已经被选了的和由于之前皇后攻击范围所以不能选的位置，然后只选择合法的位置进入到下一层递归。另外就是预处理了一个皇后放不同位置的字符串，这样这些字符串在返回结果的时候是可以在内存中复用的，省一点内存。 diff --git a/leetcode/0058.Length-of-Last-Word/58.Length of Last Word.go b/leetcode/0058.Length-of-Last-Word/58.Length of Last Word.go new file mode 100644 index 000000000..5fccdb64a --- /dev/null +++ b/leetcode/0058.Length-of-Last-Word/58.Length of Last Word.go @@ -0,0 +1,16 @@ +package leetcode + +func lengthOfLastWord(s string) int { + last := len(s) - 1 + for last >= 0 && s[last] == ' ' { + last-- + } + if last < 0 { + return 0 + } + first := last + for first >= 0 && s[first] != ' ' { + first-- + } + return last - first +} diff --git a/leetcode/0058.Length-of-Last-Word/58.Length of Last Word_test.go b/leetcode/0058.Length-of-Last-Word/58.Length of Last Word_test.go new file mode 100644 index 000000000..b47de4b7a --- /dev/null +++ b/leetcode/0058.Length-of-Last-Word/58.Length of Last Word_test.go @@ -0,0 +1,50 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question58 struct { + para58 + ans58 +} + +// para 是参数 +type para58 struct { + s string +} + +// ans 是答案 +type ans58 struct { + ans int +} + +func Test_Problem58(t *testing.T) { + + qs := []question58{ + + { + para58{"Hello World"}, + ans58{5}, + }, + + { + para58{" fly me to the moon "}, + ans58{4}, + }, + + { + para58{"luffy is still joyboy"}, + ans58{6}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 58------------------------\n") + + for _, q := range qs { + _, p := q.ans58, q.para58 + fmt.Printf("【input】:%v 【output】:%v\n", p, lengthOfLastWord(p.s)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0058.Length-of-Last-Word/README.md b/leetcode/0058.Length-of-Last-Word/README.md new file mode 100644 index 000000000..39df720a6 --- /dev/null +++ b/leetcode/0058.Length-of-Last-Word/README.md @@ -0,0 +1,70 @@ +# [58. Length of Last Word](https://leetcode.com/problems/length-of-last-word/) + + +## 题目 + +Given a string `s` consisting of some words separated by some number of spaces, return *the length of the **last** word in the string.* + +A **word** is a maximal substring consisting of non-space characters only. + +**Example 1:** + +``` +Input: s = "Hello World" +Output: 5 +Explanation: The last word is "World" with length 5. + +``` + +**Example 2:** + +``` +Input: s = " fly me to the moon " +Output: 4 +Explanation: The last word is "moon" with length 4. + +``` + +**Example 3:** + +``` +Input: s = "luffy is still joyboy" +Output: 6 +Explanation: The last word is "joyboy" with length 6. + +``` + +**Constraints:** + +- `1 <= s.length <= 104` +- `s` consists of only English letters and spaces `' '`. +- There will be at least one word in `s`. + +## 题目大意 + +给你一个字符串 `s`，由若干单词组成，单词前后用一些空格字符隔开。返回字符串中最后一个单词的长度。**单词** 是指仅由字母组成、不包含任何空格字符的最大子字符串。 + +## 解题思路 + +- 先从后过滤掉空格找到单词尾部，再从尾部向前遍历，找到单词头部，最后两者相减，即为单词的长度。 + +## 代码 + +```go +package leetcode + +func lengthOfLastWord(s string) int { + last := len(s) - 1 + for last >= 0 && s[last] == ' ' { + last-- + } + if last < 0 { + return 0 + } + first := last + for first >= 0 && s[first] != ' ' { + first-- + } + return last - first +} +``` \ No newline at end of file diff --git a/leetcode/0062.Unique-Paths/62. Unique Paths.go b/leetcode/0062.Unique-Paths/62. Unique Paths.go index f4d6b2859..aeb84056a 100644 --- a/leetcode/0062.Unique-Paths/62. Unique Paths.go +++ b/leetcode/0062.Unique-Paths/62. Unique Paths.go @@ -5,14 +5,12 @@ func uniquePaths(m int, n int) int { for i := 0; i < n; i++ { dp[i] = make([]int, m) } - for i := 0; i < m; i++ { - dp[0][i] = 1 - } for i := 0; i < n; i++ { - dp[i][0] = 1 - } - for i := 1; i < n; i++ { - for j := 1; j < m; j++ { + for j := 0; j < m; j++ { + if i == 0 || j == 0 { + dp[i][j] = 1 + continue + } dp[i][j] = dp[i-1][j] + dp[i][j-1] } } diff --git a/leetcode/0065.Valid-Number/65. Valid Number.go b/leetcode/0065.Valid-Number/65. Valid Number.go new file mode 100644 index 000000000..c1cd1fe7c --- /dev/null +++ b/leetcode/0065.Valid-Number/65. Valid Number.go @@ -0,0 +1,22 @@ +package leetcode + +func isNumber(s string) bool { + numFlag, dotFlag, eFlag := false, false, false + for i := 0; i < len(s); i++ { + if '0' <= s[i] && s[i] <= '9' { + numFlag = true + } else if s[i] == '.' && !dotFlag && !eFlag { + dotFlag = true + } else if (s[i] == 'e' || s[i] == 'E') && !eFlag && numFlag { + eFlag = true + numFlag = false // reJudge integer after 'e' or 'E' + } else if (s[i] == '+' || s[i] == '-') && (i == 0 || s[i-1] == 'e' || s[i-1] == 'E') { + continue + } else { + return false + } + } + // avoid case: s == '.' or 'e/E' or '+/-' and etc... + // string s must have num + return numFlag +} diff --git a/leetcode/0065.Valid-Number/65. Valid Number_test.go b/leetcode/0065.Valid-Number/65. Valid Number_test.go new file mode 100644 index 000000000..184e1d4ab --- /dev/null +++ b/leetcode/0065.Valid-Number/65. Valid Number_test.go @@ -0,0 +1,41 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +func Test_Problem65(t *testing.T) { + + tcs := []struct { + s string + ans bool + }{ + + { + "0", + true, + }, + + { + "e", + false, + }, + + { + ".", + false, + }, + + { + ".1", + true, + }, + } + fmt.Printf("------------------------Leetcode Problem 65------------------------\n") + + for _, tc := range tcs { + fmt.Printf("【input】:%v 【output】:%v\n", tc, isNumber(tc.s)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0065.Valid-Number/README.md b/leetcode/0065.Valid-Number/README.md new file mode 100644 index 000000000..f64df4566 --- /dev/null +++ b/leetcode/0065.Valid-Number/README.md @@ -0,0 +1,78 @@ +# [65. Valid Number](https://leetcode.com/problems/valid-number/) + + +## 题目 + +A **valid number** can be split up into these components (in order): + + 1. A **decimal number** or an integer. + 2. (Optional) An 'e' or 'E', followed by an **integer.** + +A **decimal number** can be split up into these components (in order): + + 1. (Optional) A sign character (either '+' or '-'). + 2. One of the following formats: + 1. One or more digits, followed by a dot '.'. + 2. One or more digits, followed by a dot '.', followed by one or more digits. + 3. A dot '.', followed by one or more digits. + +An **integer** can be split up into these components (in order): + + 1. (Optional) A sign character (either '+' or '-'). + 2. One or more digits. + +For example, all the following are valid numbers: `["2", "0089", "-0.1", "+3.14", "4.", "-.9", "2e10", "-90E3", "3e+7", "+6e-1", "53.5e93", "-123.456e789"]`, while the following are not valid numbers: `["abc", "1a", "1e", "e3", "99e2.5", "--6", "-+3", "95a54e53"].` + +Given a string s, return true if s is a **valid number.** + +**Example:** + + Input: s = "0" + Output: true + + Input: s = "e" + Output: false + +## 题目大意 + +给定一个字符串S，请根据以上的规则判断该字符串是否是一个有效的数字字符串。 + + +## 解题思路 + +- 用三个变量分别标记是否出现过数字、是否出现过'.'和 是否出现过 'e/E' +- 从左到右依次遍历字符串中的每一个元素 + - 如果是数字，则标记数字出现过 + - 如果是 '.', 则需要 '.'没有出现过，并且 'e/E' 没有出现过，才会进行标记 + - 如果是 'e/E', 则需要 'e/E'没有出现过，并且前面出现过数字，才会进行标记 + - 如果是 '+/-', 则需要是第一个字符，或者前一个字符是 'e/E'，才会进行标记，并重置数字出现的标识 + - 最后返回时，需要字符串中至少出现过数字，避免下列case: s == '.' or 'e/E' or '+/e' and etc... + +## 代码 + +```go + +package leetcode + +func isNumber(s string) bool { + numFlag, dotFlag, eFlag := false, false, false + for i := 0; i < len(s); i++ { + if '0' <= s[i] && s[i] <= '9' { + numFlag = true + } else if s[i] == '.' && !dotFlag && !eFlag { + dotFlag = true + } else if (s[i] == 'e' || s[i] == 'E') && !eFlag && numFlag { + eFlag = true + numFlag = false // reJudge integer after 'e' or 'E' + } else if (s[i] == '+' || s[i] == '-') && (i == 0 || s[i-1] == 'e' || s[i-1] == 'E') { + continue + } else { + return false + } + } + // avoid case: s == '.' or 'e/E' or '+/-' and etc... + // string s must have num + return numFlag +} + +``` \ No newline at end of file diff --git a/leetcode/0066.Plus-One/66. Plus One.go b/leetcode/0066.Plus-One/66. Plus One.go index a396cf45f..9a58ea973 100644 --- a/leetcode/0066.Plus-One/66. Plus One.go +++ b/leetcode/0066.Plus-One/66. Plus One.go @@ -2,16 +2,11 @@ package leetcode func plusOne(digits []int) []int { for i := len(digits) - 1; i >= 0; i-- { - digits[i]++ - if digits[i] != 10 { - // no carry + if digits[i] != 9 { + digits[i]++ return digits } - // carry digits[i] = 0 } - // all carry - digits[0] = 1 - digits = append(digits, 0) - return digits + return append([]int{1}, digits...) } diff --git a/leetcode/0069.Sqrtx/69. Sqrt(x).go b/leetcode/0069.Sqrtx/69. Sqrt(x).go index c228c82d0..33d21aee2 100644 --- a/leetcode/0069.Sqrtx/69. Sqrt(x).go +++ b/leetcode/0069.Sqrtx/69. Sqrt(x).go @@ -1,23 +1,17 @@ package leetcode -// 解法一 二分 +// 解法一 二分, 找到最后一个满足 n^2 <= x 的整数n func mySqrt(x int) int { - if x == 0 { - return 0 - } - left, right, res := 1, x, 0 - for left <= right { - mid := left + ((right - left) >> 1) - if mid < x/mid { - left = mid + 1 - res = mid - } else if mid == x/mid { - return mid + l, r := 0, x + for l < r { + mid := (l + r + 1) / 2 + if mid*mid > x { + r = mid - 1 } else { - right = mid - 1 + l = mid } } - return res + return l } // 解法二 牛顿迭代法 https://en.wikipedia.org/wiki/Integer_square_root diff --git a/leetcode/0075.Sort-Colors/75. Sort Colors.go b/leetcode/0075.Sort-Colors/75. Sort Colors.go index 6440d550c..573ef53fe 100644 --- a/leetcode/0075.Sort-Colors/75. Sort Colors.go +++ b/leetcode/0075.Sort-Colors/75. Sort Colors.go @@ -1,28 +1,16 @@ package leetcode func sortColors(nums []int) { - if len(nums) == 0 { - return - } - - r := 0 - w := 0 - b := 0 // label the end of different colors; - for _, num := range nums { - if num == 0 { - nums[b] = 2 - b++ - nums[w] = 1 - w++ - nums[r] = 0 - r++ - } else if num == 1 { - nums[b] = 2 - b++ - nums[w] = 1 - w++ - } else if num == 2 { - b++ + zero, one := 0, 0 + for i, n := range nums { + nums[i] = 2 + if n <= 1 { + nums[one] = 1 + one++ + } + if n == 0 { + nums[zero] = 0 + zero++ } } } diff --git a/leetcode/0080.Remove-Duplicates-from-Sorted-Array-II/80. Remove Duplicates from Sorted Array II.go b/leetcode/0080.Remove-Duplicates-from-Sorted-Array-II/80. Remove Duplicates from Sorted Array II.go index ae6e64c5b..dfb67fd53 100644 --- a/leetcode/0080.Remove-Duplicates-from-Sorted-Array-II/80. Remove Duplicates from Sorted Array II.go +++ b/leetcode/0080.Remove-Duplicates-from-Sorted-Array-II/80. Remove Duplicates from Sorted Array II.go @@ -1,35 +1,12 @@ package leetcode -func removeDuplicates80(nums []int) int { - if len(nums) == 0 { - return 0 - } - last, finder := 0, 0 - for last < len(nums)-1 { - startFinder := -1 - for nums[finder] == nums[last] { - if startFinder == -1 || startFinder > finder { - startFinder = finder - } - if finder == len(nums)-1 { - break - } - finder++ - } - if finder-startFinder >= 2 && nums[finder-1] == nums[last] && nums[finder] != nums[last] { - nums[last+1] = nums[finder-1] - nums[last+2] = nums[finder] - last += 2 - } else { - nums[last+1] = nums[finder] - last++ - } - if finder == len(nums)-1 { - if nums[finder] != nums[last-1] { - nums[last] = nums[finder] - } - return last + 1 +func removeDuplicates(nums []int) int { + slow := 0 + for fast, v := range nums { + if fast < 2 || nums[slow-2] != v { + nums[slow] = v + slow++ } } - return last + 1 + return slow } diff --git a/leetcode/0080.Remove-Duplicates-from-Sorted-Array-II/80. Remove Duplicates from Sorted Array II_test.go b/leetcode/0080.Remove-Duplicates-from-Sorted-Array-II/80. Remove Duplicates from Sorted Array II_test.go index f64d4c86f..76939aab3 100644 --- a/leetcode/0080.Remove-Duplicates-from-Sorted-Array-II/80. Remove Duplicates from Sorted Array II_test.go +++ b/leetcode/0080.Remove-Duplicates-from-Sorted-Array-II/80. Remove Duplicates from Sorted Array II_test.go @@ -61,7 +61,7 @@ func Test_Problem80(t *testing.T) { for _, q := range qs { _, p := q.ans80, q.para80 - fmt.Printf("【input】:%v 【output】:%v\n", p.one, removeDuplicates80(p.one)) + fmt.Printf("【input】:%v 【output】:%v\n", p.one, removeDuplicates(p.one)) } fmt.Printf("\n\n\n") } diff --git a/leetcode/0080.Remove-Duplicates-from-Sorted-Array-II/README.md b/leetcode/0080.Remove-Duplicates-from-Sorted-Array-II/README.md index e6cbed428..1c1b25e39 100644 --- a/leetcode/0080.Remove-Duplicates-from-Sorted-Array-II/README.md +++ b/leetcode/0080.Remove-Duplicates-from-Sorted-Array-II/README.md @@ -51,6 +51,6 @@ for (int i = 0; i < len; i++) { ## 解题思路 -这道题和第 26 题很像。是第 26 题的加强版。这道题和第 283 题，第 27 题基本一致，283 题是删除 0，27 题是删除指定元素，这一题是删除重复元素，实质是一样的。 - -这里数组的删除并不是真的删除，只是将删除的元素移动到数组后面的空间内，然后返回数组实际剩余的元素个数，OJ 最终判断题目的时候会读取数组剩余个数的元素进行输出。 +- 问题提示有序数组，一般最容易想到使用双指针的解法，双指针的关键点：移动两个指针的条件。 +- 在该题中移动的条件：快指针从头遍历数组，慢指针指向修改后的数组的末端，当慢指针指向倒数第二个数与快指针指向的数不相等时，才移动慢指针，同时赋值慢指针。 +- 处理边界条件：当数组小于两个元素时，不做处理。 diff --git a/leetcode/0084.Largest-Rectangle-in-Histogram/84. Largest Rectangle in Histogram.go b/leetcode/0084.Largest-Rectangle-in-Histogram/84. Largest Rectangle in Histogram.go index 6b782978a..d01401b05 100644 --- a/leetcode/0084.Largest-Rectangle-in-Histogram/84. Largest Rectangle in Histogram.go +++ b/leetcode/0084.Largest-Rectangle-in-Histogram/84. Largest Rectangle in Histogram.go @@ -1,32 +1,25 @@ package leetcode -import "fmt" - func largestRectangleArea(heights []int) int { - maxArea, stack, height := 0, []int{}, 0 - for i := 0; i <= len(heights); i++ { - if i == len(heights) { - height = 0 - } else { - height = heights[i] + maxArea := 0 + n := len(heights) + 2 + // Add a sentry at the beginning and the end + getHeight := func(i int) int { + if i == 0 || n-1 == i { + return 0 } - if len(stack) == 0 || height >= heights[stack[len(stack)-1]] { - stack = append(stack, i) - } else { - tmp := stack[len(stack)-1] - fmt.Printf("1. tmp = %v stack = %v\n", tmp, stack) - stack = stack[:len(stack)-1] - length := 0 - if len(stack) == 0 { - length = i - } else { - length = i - 1 - stack[len(stack)-1] - fmt.Printf("2. length = %v stack = %v i = %v\n", length, stack, i) - } - maxArea = max(maxArea, heights[tmp]*length) - fmt.Printf("3. maxArea = %v heights[tmp]*length = %v\n", maxArea, heights[tmp]*length) - i-- + return heights[i-1] + } + st := make([]int, 0, n/2) + for i := 0; i < n; i++ { + for len(st) > 0 && getHeight(st[len(st)-1]) > getHeight(i) { + // pop stack + idx := st[len(st)-1] + st = st[:len(st)-1] + maxArea = max(maxArea, getHeight(idx)*(i-st[len(st)-1]-1)) } + // push stack + st = append(st, i) } return maxArea } diff --git a/leetcode/0084.Largest-Rectangle-in-Histogram/84. Largest Rectangle in Histogram_test.go b/leetcode/0084.Largest-Rectangle-in-Histogram/84. Largest Rectangle in Histogram_test.go index 7226916aa..0465a1eb6 100644 --- a/leetcode/0084.Largest-Rectangle-in-Histogram/84. Largest Rectangle in Histogram_test.go +++ b/leetcode/0084.Largest-Rectangle-in-Histogram/84. Largest Rectangle in Histogram_test.go @@ -40,6 +40,10 @@ func Test_Problem84(t *testing.T) { para84{[]int{1, 1}}, ans84{2}, }, + { + para84{[]int{2, 1, 2}}, + ans84{3}, + }, } fmt.Printf("------------------------Leetcode Problem 84------------------------\n") diff --git a/leetcode/0091.Decode-Ways/91. Decode Ways.go b/leetcode/0091.Decode-Ways/91. Decode Ways.go index 35a97845b..6746cdc47 100644 --- a/leetcode/0091.Decode-Ways/91. Decode Ways.go +++ b/leetcode/0091.Decode-Ways/91. Decode Ways.go @@ -1,29 +1,16 @@ package leetcode -import ( - "strconv" -) - func numDecodings(s string) int { - if len(s) == 0 { - return 0 - } - dp := make([]int, len(s)+1) + n := len(s) + dp := make([]int, n+1) dp[0] = 1 - if s[:1] == "0" { - dp[1] = 0 - } else { - dp[1] = 1 - } - for i := 2; i <= len(s); i++ { - lastNum, _ := strconv.Atoi(s[i-1 : i]) - if lastNum >= 1 && lastNum <= 9 { + for i := 1; i <= n; i++ { + if s[i-1] != '0' { dp[i] += dp[i-1] } - lastNum, _ = strconv.Atoi(s[i-2 : i]) - if lastNum >= 10 && lastNum <= 26 { + if i > 1 && s[i-2] != '0' && (s[i-2]-'0')*10+(s[i-1]-'0') <= 26 { dp[i] += dp[i-2] } } - return dp[len(s)] + return dp[n] } diff --git a/leetcode/0097.Interleaving-String/97. Interleaving String.go b/leetcode/0097.Interleaving-String/97. Interleaving String.go new file mode 100644 index 000000000..20d62f152 --- /dev/null +++ b/leetcode/0097.Interleaving-String/97. Interleaving String.go @@ -0,0 +1,35 @@ +package leetcode + +func isInterleave(s1 string, s2 string, s3 string) bool { + if len(s1)+len(s2) != len(s3) { + return false + } + visited := make(map[int]bool) + return dfs(s1, s2, s3, 0, 0, visited) +} + +func dfs(s1, s2, s3 string, p1, p2 int, visited map[int]bool) bool { + if p1+p2 == len(s3) { + return true + } + if _, ok := visited[(p1*len(s3))+p2]; ok { + return false + } + visited[(p1*len(s3))+p2] = true + var match1, match2 bool + if p1 < len(s1) && s3[p1+p2] == s1[p1] { + match1 = true + } + if p2 < len(s2) && s3[p1+p2] == s2[p2] { + match2 = true + } + if match1 && match2 { + return dfs(s1, s2, s3, p1+1, p2, visited) || dfs(s1, s2, s3, p1, p2+1, visited) + } else if match1 { + return dfs(s1, s2, s3, p1+1, p2, visited) + } else if match2 { + return dfs(s1, s2, s3, p1, p2+1, visited) + } else { + return false + } +} diff --git a/leetcode/0097.Interleaving-String/97. Interleaving String_test.go b/leetcode/0097.Interleaving-String/97. Interleaving String_test.go new file mode 100644 index 000000000..20ee4e78d --- /dev/null +++ b/leetcode/0097.Interleaving-String/97. Interleaving String_test.go @@ -0,0 +1,54 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question97 struct { + para97 + ans97 +} + +// para 是参数 +// one 代表第一个参数 +type para97 struct { + s1 string + s2 string + s3 string +} + +// ans 是答案 +// one 代表第一个答案 +type ans97 struct { + one bool +} + +func Test_Problem97(t *testing.T) { + + qs := []question97{ + + { + para97{"aabcc", "dbbca", "aadbbcbcac"}, + ans97{true}, + }, + + { + para97{"aabcc", "dbbca", "aadbbbaccc"}, + ans97{false}, + }, + + { + para97{"", "", ""}, + ans97{true}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 97------------------------\n") + + for _, q := range qs { + _, p := q.ans97, q.para97 + fmt.Printf("【input】:%v 【output】:%v\n", p, isInterleave(p.s1, p.s2, p.s3)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0097.Interleaving-String/README.md b/leetcode/0097.Interleaving-String/README.md new file mode 100644 index 000000000..2a720371a --- /dev/null +++ b/leetcode/0097.Interleaving-String/README.md @@ -0,0 +1,104 @@ +# [97. Interleaving String](https://leetcode.com/problems/interleaving-string/) + + +## 题目 + +Given strings `s1`, `s2`, and `s3`, find whether `s3` is formed by an **interleaving** of `s1` and `s2`. + +An **interleaving** of two strings `s` and `t` is a configuration where they are divided into **non-empty** substrings such that: + +- `s = s1 + s2 + ... + sn` +- `t = t1 + t2 + ... + tm` +- `|n - m| <= 1` +- The **interleaving** is `s1 + t1 + s2 + t2 + s3 + t3 + ...` or `t1 + s1 + t2 + s2 + t3 + s3 + ...` + +**Note:** `a + b` is the concatenation of strings `a` and `b`. + +**Example 1:** + +![https://assets.leetcode.com/uploads/2020/09/02/interleave.jpg](https://assets.leetcode.com/uploads/2020/09/02/interleave.jpg) + +``` +Input: s1 = "aabcc", s2 = "dbbca", s3 = "aadbbcbcac" +Output: true + +``` + +**Example 2:** + +``` +Input: s1 = "aabcc", s2 = "dbbca", s3 = "aadbbbaccc" +Output: false + +``` + +**Example 3:** + +``` +Input: s1 = "", s2 = "", s3 = "" +Output: true + +``` + +**Constraints:** + +- `0 <= s1.length, s2.length <= 100` +- `0 <= s3.length <= 200` +- `s1`, `s2`, and `s3` consist of lowercase English letters. + +**Follow up:** Could you solve it using only `O(s2.length)` additional memory space? + +## 题目大意 + +给定三个字符串 s1、s2、s3，请你帮忙验证 s3 是否是由 s1 和 s2 交错 组成的。两个字符串 s 和 t 交错 的定义与过程如下，其中每个字符串都会被分割成若干 非空 子字符串： + +- s = s1 + s2 + ... + sn +- t = t1 + t2 + ... + tm +- |n - m| <= 1 +- 交错 是 s1 + t1 + s2 + t2 + s3 + t3 + ... 或者 t1 + s1 + t2 + s2 + t3 + s3 + ... + +提示：a + b 意味着字符串 a 和 b 连接。 + +## 解题思路 + +- 深搜或者广搜暴力解题。笔者用深搜实现的。记录 s1 和 s2 串当前比较的位置 p1 和 p2。如果 s3[p1+p2] 的位置上等于 s1[p1] 或者 s2[p2] 代表能匹配上，那么继续往后移动 p1 和 p2 相应的位置。因为是交错字符串，所以判断匹配的位置是 s3[p1+p2] 的位置。如果仅仅这么写，会超时，s1 和 s2 两个字符串重复交叉判断的位置太多了。需要加上记忆化搜索。可以用 visited[i][j] 这样的二维数组来记录是否搜索过了。笔者为了压缩空间，将 i 和 j 编码压缩到一维数组了。i * len(s3) + j 是唯一下标，所以可以用这种方式存储是否搜索过。具体代码见下面的实现。 + +## 代码 + +```go +package leetcode + +func isInterleave(s1 string, s2 string, s3 string) bool { + if len(s1)+len(s2) != len(s3) { + return false + } + visited := make(map[int]bool) + return dfs(s1, s2, s3, 0, 0, visited) +} + +func dfs(s1, s2, s3 string, p1, p2 int, visited map[int]bool) bool { + if p1+p2 == len(s3) { + return true + } + if _, ok := visited[(p1*len(s3))+p2]; ok { + return false + } + visited[(p1*len(s3))+p2] = true + var match1, match2 bool + if p1 < len(s1) && s3[p1+p2] == s1[p1] { + match1 = true + } + if p2 < len(s2) && s3[p1+p2] == s2[p2] { + match2 = true + } + if match1 && match2 { + return dfs(s1, s2, s3, p1+1, p2, visited) || dfs(s1, s2, s3, p1, p2+1, visited) + } else if match1 { + return dfs(s1, s2, s3, p1+1, p2, visited) + } else if match2 { + return dfs(s1, s2, s3, p1, p2+1, visited) + } else { + return false + } +} +``` \ No newline at end of file diff --git a/leetcode/0098.Validate-Binary-Search-Tree/98. Validate Binary Search Tree.go b/leetcode/0098.Validate-Binary-Search-Tree/98. Validate Binary Search Tree.go index 801e8ff53..1a4d530b9 100644 --- a/leetcode/0098.Validate-Binary-Search-Tree/98. Validate Binary Search Tree.go +++ b/leetcode/0098.Validate-Binary-Search-Tree/98. Validate Binary Search Tree.go @@ -1,8 +1,8 @@ package leetcode -import "math" - import ( + "math" + "github.com/halfrost/LeetCode-Go/structures" ) diff --git a/leetcode/0101.Symmetric-Tree/101. Symmetric Tree.go b/leetcode/0101.Symmetric-Tree/101. Symmetric Tree.go index 63074f3e4..b8c26b9a1 100644 --- a/leetcode/0101.Symmetric-Tree/101. Symmetric Tree.go +++ b/leetcode/0101.Symmetric-Tree/101. Symmetric Tree.go @@ -18,20 +18,20 @@ type TreeNode = structures.TreeNode // 解法一 dfs func isSymmetric(root *TreeNode) bool { - return root == nil || dfs(root.Left, root.Right) + if root == nil { + return true + } + return isMirror(root.Left, root.Right) } -func dfs(rootLeft, rootRight *TreeNode) bool { - if rootLeft == nil && rootRight == nil { +func isMirror(left *TreeNode, right *TreeNode) bool { + if left == nil && right == nil { return true } - if rootLeft == nil || rootRight == nil { - return false - } - if rootLeft.Val != rootRight.Val { + if left == nil || right == nil { return false } - return dfs(rootLeft.Left, rootRight.Right) && dfs(rootLeft.Right, rootRight.Left) + return (left.Val == right.Val) && isMirror(left.Left, right.Right) && isMirror(left.Right, right.Left) } // 解法二 diff --git a/leetcode/0105.Construct-Binary-Tree-from-Preorder-and-Inorder-Traversal/105. Construct Binary Tree from Preorder and Inorder Traversal.go b/leetcode/0105.Construct-Binary-Tree-from-Preorder-and-Inorder-Traversal/105. Construct Binary Tree from Preorder and Inorder Traversal.go index b1d2b05fa..2654e7381 100644 --- a/leetcode/0105.Construct-Binary-Tree-from-Preorder-and-Inorder-Traversal/105. Construct Binary Tree from Preorder and Inorder Traversal.go +++ b/leetcode/0105.Construct-Binary-Tree-from-Preorder-and-Inorder-Traversal/105. Construct Binary Tree from Preorder and Inorder Traversal.go @@ -16,7 +16,23 @@ type TreeNode = structures.TreeNode * } */ +// 解法一, 直接传入需要的 slice 范围作为输入, 可以避免申请对应 inorder 索引的内存, 内存使用(leetcode test case) 4.7MB -> 4.3MB. func buildTree(preorder []int, inorder []int) *TreeNode { + if len(preorder) == 0 { + return nil + } + root := &TreeNode{Val: preorder[0]} + for pos, node := range inorder { + if node == root.Val { + root.Left = buildTree(preorder[1:pos+1], inorder[:pos]) + root.Right = buildTree(preorder[pos+1:], inorder[pos+1:]) + } + } + return root +} + +// 解法二 +func buildTree1(preorder []int, inorder []int) *TreeNode { inPos := make(map[int]int) for i := 0; i < len(inorder); i++ { inPos[inorder[i]] = i diff --git a/leetcode/0106.Construct-Binary-Tree-from-Inorder-and-Postorder-Traversal/106. Construct Binary Tree from Inorder and Postorder Traversal.go b/leetcode/0106.Construct-Binary-Tree-from-Inorder-and-Postorder-Traversal/106. Construct Binary Tree from Inorder and Postorder Traversal.go index b98a0ec4f..1c7a86b66 100644 --- a/leetcode/0106.Construct-Binary-Tree-from-Inorder-and-Postorder-Traversal/106. Construct Binary Tree from Inorder and Postorder Traversal.go +++ b/leetcode/0106.Construct-Binary-Tree-from-Inorder-and-Postorder-Traversal/106. Construct Binary Tree from Inorder and Postorder Traversal.go @@ -16,7 +16,25 @@ type TreeNode = structures.TreeNode * } */ +// 解法一, 直接传入需要的 slice 范围作为输入, 可以避免申请对应 inorder 索引的内存, 内存使用(leetcode test case) 4.7MB -> 4.3MB. func buildTree(inorder []int, postorder []int) *TreeNode { + postorderLen := len(postorder) + if len(inorder) == 0 { + return nil + } + root := &TreeNode{Val: postorder[postorderLen-1]} + postorder = postorder[:postorderLen-1] + for pos, node := range inorder { + if node == root.Val { + root.Left = buildTree(inorder[:pos], postorder[:len(inorder[:pos])]) + root.Right = buildTree(inorder[pos+1:], postorder[len(inorder[:pos]):]) + } + } + return root +} + +// 解法二 +func buildTree1(inorder []int, postorder []int) *TreeNode { inPos := make(map[int]int) for i := 0; i < len(inorder); i++ { inPos[inorder[i]] = i diff --git a/leetcode/0114.Flatten-Binary-Tree-to-Linked-List/114. Flatten Binary Tree to Linked List.go b/leetcode/0114.Flatten-Binary-Tree-to-Linked-List/114. Flatten Binary Tree to Linked List.go index 5fe89309d..74860eae8 100644 --- a/leetcode/0114.Flatten-Binary-Tree-to-Linked-List/114. Flatten Binary Tree to Linked List.go +++ b/leetcode/0114.Flatten-Binary-Tree-to-Linked-List/114. Flatten Binary Tree to Linked List.go @@ -18,23 +18,21 @@ type TreeNode = structures.TreeNode // 解法一 非递归 func flatten(root *TreeNode) { - list, cur := []int{}, &TreeNode{} - preorder(root, &list) - cur = root + list := preorder(root) for i := 1; i < len(list); i++ { - cur.Left = nil - cur.Right = &TreeNode{Val: list[i], Left: nil, Right: nil} - cur = cur.Right + prev, cur := list[i-1], list[i] + prev.Left, prev.Right = nil, cur } return } -func preorder(root *TreeNode, output *[]int) { +func preorder(root *TreeNode) (ans []*TreeNode) { if root != nil { - *output = append(*output, root.Val) - preorder(root.Left, output) - preorder(root.Right, output) + ans = append(ans, root) + ans = append(ans, preorder(root.Left)...) + ans = append(ans, preorder(root.Right)...) } + return } // 解法二 递归 diff --git a/leetcode/0114.Flatten-Binary-Tree-to-Linked-List/114. Flatten Binary Tree to Linked List_test.go b/leetcode/0114.Flatten-Binary-Tree-to-Linked-List/114. Flatten Binary Tree to Linked List_test.go index 299093969..aa20ab605 100644 --- a/leetcode/0114.Flatten-Binary-Tree-to-Linked-List/114. Flatten Binary Tree to Linked List_test.go +++ b/leetcode/0114.Flatten-Binary-Tree-to-Linked-List/114. Flatten Binary Tree to Linked List_test.go @@ -15,13 +15,13 @@ type question114 struct { // para 是参数 // one 代表第一个参数 type para114 struct { - one []int + one []string } // ans 是答案 // one 代表第一个答案 type ans114 struct { - one []int + one []string } func Test_Problem114(t *testing.T) { @@ -29,8 +29,18 @@ func Test_Problem114(t *testing.T) { qs := []question114{ { - para114{[]int{1, 2, 3, 4, 5, 6}}, - ans114{[]int{1, 2, 3, 4, 5, 6}}, + para114{[]string{"1", "2", "5", "3", "4", "null", "6"}}, + ans114{[]string{"1", "null", "2", "null", "3", "null", "4", "null", "5", "null", "6"}}, + }, + + { + para114{[]string{"0"}}, + ans114{[]string{"0"}}, + }, + + { + para114{[]string{"1", "2", "3", "4", "5", "6"}}, + ans114{[]string{"1", "2", "4", "5", "3", "6", "null"}}, }, } @@ -39,9 +49,10 @@ func Test_Problem114(t *testing.T) { for _, q := range qs { _, p := q.ans114, q.para114 fmt.Printf("【input】:%v \n", p) - rootOne := structures.Ints2TreeNode(p.one) + rootOne := structures.Strings2TreeNode(p.one) flatten(rootOne) - fmt.Printf("【output】:%v \n", structures.Tree2Preorder(rootOne)) + fmt.Printf("【levelorder output】:%v \n", structures.Tree2LevelOrderStrings(rootOne)) + fmt.Printf("【preorder output】:%v \n", structures.Tree2PreOrderStrings(rootOne)) } fmt.Printf("\n\n\n") } diff --git a/leetcode/0116.Populating-Next-Right-Pointers-in-Each-Node/116.Populating Next Right Pointers in Each Node.go b/leetcode/0116.Populating-Next-Right-Pointers-in-Each-Node/116.Populating Next Right Pointers in Each Node.go new file mode 100644 index 000000000..4587c39d5 --- /dev/null +++ b/leetcode/0116.Populating-Next-Right-Pointers-in-Each-Node/116.Populating Next Right Pointers in Each Node.go @@ -0,0 +1,52 @@ +package leetcode + +type Node struct { + Val int + Left *Node + Right *Node + Next *Node +} + +// 解法一：迭代 +func connect(root *Node) *Node { + if root == nil { + return root + } + q := []*Node{root} + for len(q) > 0 { + var p []*Node + // 遍历这一层的所有节点 + for i, node := range q { + if i+1 < len(q) { + node.Next = q[i+1] + } + if node.Left != nil { + p = append(p, node.Left) + } + if node.Right != nil { + p = append(p, node.Right) + } + } + q = p + } + return root +} + +// 解法二 递归 +func connect2(root *Node) *Node { + if root == nil { + return nil + } + connectTwoNode(root.Left, root.Right) + return root +} + +func connectTwoNode(node1, node2 *Node) { + if node1 == nil || node2 == nil { + return + } + node1.Next = node2 + connectTwoNode(node1.Left, node1.Right) + connectTwoNode(node2.Left, node2.Right) + connectTwoNode(node1.Right, node2.Left) +} diff --git a/leetcode/0116.Populating-Next-Right-Pointers-in-Each-Node/116.Populating Next Right Pointers in Each Node_test.go b/leetcode/0116.Populating-Next-Right-Pointers-in-Each-Node/116.Populating Next Right Pointers in Each Node_test.go new file mode 100644 index 000000000..6146f1579 --- /dev/null +++ b/leetcode/0116.Populating-Next-Right-Pointers-in-Each-Node/116.Populating Next Right Pointers in Each Node_test.go @@ -0,0 +1,117 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question116 struct { + para116 + ans116 +} + +// para 是参数 +// one 代表第一个参数 +type para116 struct { + one *Node +} + +// ans 是答案 +// one 代表第一个答案 +type ans116 struct { + one *Node +} + +func newQuestionNode() *Node { + node7 := &Node{} + node7.Val = 7 + + node6 := &Node{} + node6.Val = 6 + + node5 := &Node{} + node5.Val = 5 + + node4 := &Node{} + node4.Val = 4 + + node3 := &Node{} + node3.Val = 3 + + node2 := &Node{} + node2.Val = 2 + + node1 := &Node{} + node1.Val = 1 + + node1.Left = node2 + node1.Right = node3 + + node2.Left = node4 + node2.Right = node5 + + node3.Left = node6 + node3.Right = node7 + return node1 +} + +func newResultNode() *Node { + node7 := &Node{} + node7.Val = 7 + + node6 := &Node{} + node6.Val = 6 + + node5 := &Node{} + node5.Val = 5 + + node4 := &Node{} + node4.Val = 4 + + node3 := &Node{} + node3.Val = 3 + + node2 := &Node{} + node2.Val = 2 + + node1 := &Node{} + node1.Val = 1 + + node1.Left = node2 + node1.Right = node3 + + node2.Left = node4 + node2.Right = node5 + + node3.Left = node6 + node3.Right = node7 + + node1.Next = nil + node2.Next = node3 + node3.Next = nil + node4.Next = node5 + node5.Next = node6 + node6.Next = node7 + node7.Next = nil + + return node1 +} + +func Test_Problem116(t *testing.T) { + + qs := []question116{ + { + para116{newQuestionNode()}, + ans116{newResultNode()}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 116------------------------\n") + + for _, q := range qs { + _, p := q.ans116, q.para116 + fmt.Printf("【input】:%v ", p.one) + fmt.Printf("【output】:%v \n", connect(p.one)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0116.Populating-Next-Right-Pointers-in-Each-Node/README.md b/leetcode/0116.Populating-Next-Right-Pointers-in-Each-Node/README.md new file mode 100644 index 000000000..f25539f42 --- /dev/null +++ b/leetcode/0116.Populating-Next-Right-Pointers-in-Each-Node/README.md @@ -0,0 +1,118 @@ +# [116. Populating Next Right Pointers in Each Node](https://leetcode.com/problems/populating-next-right-pointers-in-each-node/) + + +## 题目 + +You are given a **perfect binary tree** where all leaves are on the same level, and every parent has two children. The binary tree has the following definition: + +``` +struct Node { + int val; + Node *left; + Node *right; + Node *next; +} + +``` + +Populate each next pointer to point to its next right node. If there is no next right node, the next pointer should be set to `NULL`. + +Initially, all next pointers are set to `NULL`. + +**Follow up:** + +- You may only use constant extra space. +- Recursive approach is fine, you may assume implicit stack space does not count as extra space for this problem. + +**Example 1:** + +![https://assets.leetcode.com/uploads/2019/02/14/116_sample.png](https://assets.leetcode.com/uploads/2019/02/14/116_sample.png) + +``` +Input: root = [1,2,3,4,5,6,7] +Output: [1,#,2,3,#,4,5,6,7,#] +Explanation:Given the above perfect binary tree (Figure A), your function should populate each next pointer to point to its next right node, just like in Figure B. The serialized output is in level order as connected by the next pointers, with '#' signifying the end of each level. + +``` + +**Constraints:** + +- The number of nodes in the given tree is less than `4096`. +- `1000 <= node.val <= 1000` + +## 题目大意 + +给定一个 完美二叉树 ，其所有叶子节点都在同一层，每个父节点都有两个子节点。二叉树定义如下： + +```jsx +struct Node { + int val; + Node *left; + Node *right; + Node *next; +} + +``` + +填充它的每个 next 指针，让这个指针指向其下一个右侧节点。如果找不到下一个右侧节点，则将 next 指针设置为 NULL。初始状态下，所有 next 指针都被设置为 NULL。 + +## 解题思路 + +- 本质上是二叉树的层序遍历，基于广度优先搜索，将每层的节点放入队列，并遍历队列进行连接。 + +## 代码 + +```go +package leetcode + +type Node struct { + Val int + Left *Node + Right *Node + Next *Node +} + +//解法一：迭代 +func connect(root *Node) *Node { + if root == nil { + return root + } + q := []*Node{root} + for len(q) > 0 { + var p []*Node + // 遍历这一层的所有节点 + for i, node := range q { + if i+1 < len(q) { + node.Next = q[i+1] + } + if node.Left != nil { + p = append(p, node.Left) + } + if node.Right != nil { + p = append(p, node.Right) + } + } + q = p + } + return root +} + +// 解法二 递归 +func connect2(root *Node) *Node { + if root == nil { + return nil + } + connectTwoNode(root.Left, root.Right) + return root +} + +func connectTwoNode(node1, node2 *Node) { + if node1 == nil || node2 == nil { + return + } + node1.Next = node2 + connectTwoNode(node1.Left, node1.Right) + connectTwoNode(node2.Left, node2.Right) + connectTwoNode(node1.Right, node2.Left) +} +``` \ No newline at end of file diff --git a/leetcode/0118.Pascals-Triangle/118. Pascal's Triangle.go b/leetcode/0118.Pascals-Triangle/118. Pascals Triangle.go similarity index 100% rename from leetcode/0118.Pascals-Triangle/118. Pascal's Triangle.go rename to leetcode/0118.Pascals-Triangle/118. Pascals Triangle.go diff --git a/leetcode/0118.Pascals-Triangle/118. Pascal's Triangle_test.go b/leetcode/0118.Pascals-Triangle/118. Pascals Triangle_test.go similarity index 100% rename from leetcode/0118.Pascals-Triangle/118. Pascal's Triangle_test.go rename to leetcode/0118.Pascals-Triangle/118. Pascals Triangle_test.go diff --git a/leetcode/0119.Pascals-Triangle-II/119. Pascal's Triangle II.go b/leetcode/0119.Pascals-Triangle-II/119. Pascals Triangle II.go similarity index 100% rename from leetcode/0119.Pascals-Triangle-II/119. Pascal's Triangle II.go rename to leetcode/0119.Pascals-Triangle-II/119. Pascals Triangle II.go diff --git a/leetcode/0119.Pascals-Triangle-II/119. Pascal's Triangle II_test.go b/leetcode/0119.Pascals-Triangle-II/119. Pascals Triangle II_test.go similarity index 100% rename from leetcode/0119.Pascals-Triangle-II/119. Pascal's Triangle II_test.go rename to leetcode/0119.Pascals-Triangle-II/119. Pascals Triangle II_test.go diff --git a/leetcode/0124.Binary-Tree-Maximum-Path-Sum/124. Binary Tree Maximum Path Sum.go b/leetcode/0124.Binary-Tree-Maximum-Path-Sum/124. Binary Tree Maximum Path Sum.go index dc7a75e4b..058193b7b 100644 --- a/leetcode/0124.Binary-Tree-Maximum-Path-Sum/124. Binary Tree Maximum Path Sum.go +++ b/leetcode/0124.Binary-Tree-Maximum-Path-Sum/124. Binary Tree Maximum Path Sum.go @@ -1,8 +1,8 @@ package leetcode -import "math" - import ( + "math" + "github.com/halfrost/LeetCode-Go/structures" ) diff --git a/leetcode/0129.Sum-Root-to-Leaf-Numbers/129. Sum Root to Leaf Numbers.go b/leetcode/0129.Sum-Root-to-Leaf-Numbers/129. Sum Root to Leaf Numbers.go index 62fd39bde..fefdd64b9 100644 --- a/leetcode/0129.Sum-Root-to-Leaf-Numbers/129. Sum Root to Leaf Numbers.go +++ b/leetcode/0129.Sum-Root-to-Leaf-Numbers/129. Sum Root to Leaf Numbers.go @@ -1,9 +1,5 @@ package leetcode -import ( - "strconv" -) - import ( "github.com/halfrost/LeetCode-Go/structures" ) @@ -21,29 +17,20 @@ type TreeNode = structures.TreeNode */ func sumNumbers(root *TreeNode) int { - res, nums := 0, binaryTreeNums(root) - for _, n := range nums { - num, _ := strconv.Atoi(n) - res += num - } + res := 0 + dfs(root, 0, &res) return res } -func binaryTreeNums(root *TreeNode) []string { +func dfs(root *TreeNode, sum int, res *int) { if root == nil { - return []string{} + return } - res := []string{} + sum = sum*10 + root.Val if root.Left == nil && root.Right == nil { - return []string{strconv.Itoa(root.Val)} + *res += sum + return } - tmpLeft := binaryTreeNums(root.Left) - for i := 0; i < len(tmpLeft); i++ { - res = append(res, strconv.Itoa(root.Val)+tmpLeft[i]) - } - tmpRight := binaryTreeNums(root.Right) - for i := 0; i < len(tmpRight); i++ { - res = append(res, strconv.Itoa(root.Val)+tmpRight[i]) - } - return res + dfs(root.Left, sum, res) + dfs(root.Right, sum, res) } diff --git a/leetcode/0129.Sum-Root-to-Leaf-Numbers/README.md b/leetcode/0129.Sum-Root-to-Leaf-Numbers/README.md index 3bb303520..7e7dababa 100755 --- a/leetcode/0129.Sum-Root-to-Leaf-Numbers/README.md +++ b/leetcode/0129.Sum-Root-to-Leaf-Numbers/README.md @@ -45,4 +45,4 @@ Find the total sum of all root-to-leaf numbers. ## 解题思路 -- 这一题是第 257 题的变形题，第 257 题要求输出每条从根节点到叶子节点的路径，这一题变成了把每一个从根节点到叶子节点的数字都串联起来，再累加每条路径，求出最后的总和。实际做题思路基本没变 +- 运用前序遍历的思想，当从根节点出发一直加到叶子节点，每个叶子节点汇总一次。 \ No newline at end of file diff --git a/leetcode/0134.Gas-Station/Gas.go b/leetcode/0134.Gas-Station/Gas.go new file mode 100644 index 000000000..4277a791c --- /dev/null +++ b/leetcode/0134.Gas-Station/Gas.go @@ -0,0 +1,26 @@ +package leetcode + +func canCompleteCircuit(gas []int, cost []int) int { + totalGas := 0 + totalCost := 0 + currGas := 0 + start := 0 + + for i := 0; i < len(gas); i++ { + totalGas += gas[i] + totalCost += cost[i] + currGas += gas[i] - cost[i] + + if currGas < 0 { + start = i + 1 + currGas = 0 + } + } + + if totalGas < totalCost { + return -1 + } + + return start + +} diff --git a/leetcode/0134.Gas-Station/Gas_test.go b/leetcode/0134.Gas-Station/Gas_test.go new file mode 100644 index 000000000..f6c2a7893 --- /dev/null +++ b/leetcode/0134.Gas-Station/Gas_test.go @@ -0,0 +1,47 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question134 struct { + para134 + ans134 +} + +// para 是参数 +// one 代表第一个参数 +type para134 struct { + one []int + two []int +} + +// ans 是答案 +// one 代表第一个答案 +type ans134 struct { + one int +} + +func Test_Problem134(t *testing.T) { + qs := []question134{ + + { + para134{[]int{1, 2, 3, 4, 5}, []int{3, 4, 5, 1, 2}}, + ans134{3}, + }, + + { + para134{[]int{2, 3, 4}, []int{3, 4, 3}}, + ans134{-1}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 134------------------------\n") + + for _, q := range qs { + _, p := q.ans134, q.para134 + fmt.Printf("【input】:%v， %v 【output】:%v\n", p.one, p.two, canCompleteCircuit(p.one, p.two)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0134.Gas-Station/README.md b/leetcode/0134.Gas-Station/README.md new file mode 100644 index 000000000..e4cb07821 --- /dev/null +++ b/leetcode/0134.Gas-Station/README.md @@ -0,0 +1,88 @@ +# [134. Gas Stations](https://leetcode.com/problems/gas-station/) + + +## 题目 + +You are given a list of gas stations on a circular route, where the amount of gas at station i is gas[i], and the cost to travel from station i to its next station (i+1) is cost[i]. You have a car with an unlimited gas tank and it costs cost[i] of gas to travel from station i to its next station (i+1). You begin the journey with an empty tank at one of the gas stations. + +Write a function that returns the starting gas station's index if you can travel around the circuit once in the clockwise direction, otherwise return -1. If there exists a solution, it is guaranteed to be unique. + +**Example 1:** + +``` +Input: gas = [1,2,3,4,5], cost = [3,4,5,1,2] +Output: 3 +Explanation: Start at station 3 (index 3), you have 4 liters of gas. Now you have a total of =0+4=4 liters of gas. +Travel to station 4. Now you have 4 - 1 + 5 = 8 liters of gas. +Travel to station 0. Now you have 8 - 2 + 1 = 7 liters of gas. +Travel to station 1. Now you have 7 - 3 + 2 = 6 liters of gas. +Travel to station 2. Now you have 6 - 4 + 3 = 5 liters of gas. +Travel to station 3 again. This time you will have consumed 5 liters of gas, which is exactly enough for you to return to station 3. +Therefore, 3 can be the starting index. +``` + +**Example 2:** + +``` +Input: gas = [2,3,4], cost = [3,4,3] +Output: -1 +Explanation: You cannot start at station 0 or 1 because there is not enough gas to get you to the next station. +We start at station 2, we get 4 liters of gas. Now you have a total of =0+4=4 liters of gas. +Travel to station 0. Now you have 4 - 3 + 2 = 3 liters of gas. +Travel to station 1. Now you have 3 - 3 + 3 = 3 liters of gas. +You cannot return to station 2 because it requires 4 liters of gas but you only have 3 liters in your tank. +Therefore, no matter what, you cannot travel around the ring. +``` + +**Constraints:** + +- `gas.length == n` +- `cost.length == n` +- `1 <= n <= 10^5` +- `0 <= gas[i], cost[i] <= 10^4` + +## 题目大意 + +在一条环路上有 n 个加油站，其中第 i 个加油站有汽油 gas[i] 升。 + +你有一辆油箱容量无限的的汽车，从第 i 个加油站开往第 i+1 个加油站需要消耗汽油 cost[i] 升。你从其中的一个加油站出发，开始时油箱为空。 + +给定两个整数数组 gas 和 cost ，如果你可以按顺序绕环路行驶一周，则返回出发时加油站的编号，否则返回 -1 。如果存在解，则 保证 它是 唯一 的。 + +## 解题思路 + +- 初始化总油量（totalGas）和总消耗（totalCost）为0，起始点（start）为0，当前油量（currGas）为0。 + 遍历每个加油站，累加油量和消耗，计算当前油量。 + 如果当前油量小于0，说明从上一个加油站到当前加油站的油量不足以到达下一个加油站，因此将起始点设置为当前加油站的下一个位置，并将当前油量重置为0。 + 遍历结束后，如果总油量小于总消耗，说明无法完成整个旅程，返回-1；否则返回起始点。 + +## 代码 + +```go +package leetcode + +func canCompleteCircuit(gas []int, cost []int) int { + totalGas := 0 + totalCost := 0 + currGas := 0 + start := 0 + + for i := 0; i < len(gas); i++ { + totalGas += gas[i] + totalCost += cost[i] + currGas += gas[i] - cost[i] + + if currGas < 0 { + start = i + 1 + currGas = 0 + } + } + + if totalGas < totalCost { + return -1 + } + + return start +} + +``` \ No newline at end of file diff --git a/leetcode/0135.Candy/135. Candy.go b/leetcode/0135.Candy/135. Candy.go new file mode 100644 index 000000000..0cf961e0b --- /dev/null +++ b/leetcode/0135.Candy/135. Candy.go @@ -0,0 +1,20 @@ +package leetcode + +func candy(ratings []int) int { + candies := make([]int, len(ratings)) + for i := 1; i < len(ratings); i++ { + if ratings[i] > ratings[i-1] { + candies[i] += candies[i-1] + 1 + } + } + for i := len(ratings) - 2; i >= 0; i-- { + if ratings[i] > ratings[i+1] && candies[i] <= candies[i+1] { + candies[i] = candies[i+1] + 1 + } + } + total := 0 + for _, candy := range candies { + total += candy + 1 + } + return total +} diff --git a/leetcode/0135.Candy/135. Candy_test.go b/leetcode/0135.Candy/135. Candy_test.go new file mode 100644 index 000000000..edb15ad35 --- /dev/null +++ b/leetcode/0135.Candy/135. Candy_test.go @@ -0,0 +1,47 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question135 struct { + para135 + ans135 +} + +// para 是参数 +// one 代表第一个参数 +type para135 struct { + ratings []int +} + +// ans 是答案 +// one 代表第一个答案 +type ans135 struct { + one int +} + +func Test_Problem135(t *testing.T) { + + qs := []question135{ + + { + para135{[]int{1, 0, 2}}, + ans135{5}, + }, + + { + para135{[]int{1, 2, 2}}, + ans135{4}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 135------------------------\n") + + for _, q := range qs { + _, p := q.ans135, q.para135 + fmt.Printf("【input】:%v 【output】:%v\n", p, candy(p.ratings)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0135.Candy/README.md b/leetcode/0135.Candy/README.md new file mode 100644 index 000000000..9f6dc16ad --- /dev/null +++ b/leetcode/0135.Candy/README.md @@ -0,0 +1,74 @@ +# [135. Candy](https://leetcode.com/problems/candy/) + + +## 题目 + +There are `n` children standing in a line. Each child is assigned a rating value given in the integer array `ratings`. + +You are giving candies to these children subjected to the following requirements: + +- Each child must have at least one candy. +- Children with a higher rating get more candies than their neighbors. + +Return *the minimum number of candies you need to have to distribute the candies to the children*. + +**Example 1:** + +``` +Input: ratings = [1,0,2] +Output: 5 +Explanation: You can allocate to the first, second and third child with 2, 1, 2 candies respectively. +``` + +**Example 2:** + +``` +Input: ratings = [1,2,2] +Output: 4 +Explanation: You can allocate to the first, second and third child with 1, 2, 1 candies respectively. +The third child gets 1 candy because it satisfies the above two conditions. +``` + +**Constraints:** + +- `n == ratings.length` +- `1 <= n <= 2 * 10^4` +- `0 <= ratings[i] <= 2 * 10^4` + +## 题目大意 + +老师想给孩子们分发糖果，有 N 个孩子站成了一条直线，老师会根据每个孩子的表现，预先给他们评分。你需要按照以下要求，帮助老师给这些孩子分发糖果： + +- 每个孩子至少分配到 1 个糖果。 +- 评分更高的孩子必须比他两侧的邻位孩子获得更多的糖果。 + +那么这样下来，老师至少需要准备多少颗糖果呢？ + +## 解题思路 + +- 本题的突破口在于，评分更高的孩子必须比他两侧的邻位孩子获得更多的糖果，这句话。这个规则可以理解为 2 条规则，想象成按身高排队，站在下标为 0 的地方往后“看”，评分高即为个子高的，应该比前面个子矮(评分低)的分到糖果多；站在下标为 n - 1 的地方往后“看”，评分高即为个子高的，同样应该比前面个子矮(评分低)的分到糖果多。你可能会有疑问，规则都是一样的，为什么会出现至少需要多少糖果呢？因为可能出现评分一样高的同学。扫描数组两次，处理出每一个学生分别满足左规则或右规则时，最少需要被分得的糖果数量。每个人最终分得的糖果数量即为这两个数量的最大值。两次遍历结束，将所有糖果累加起来即为至少需要准备的糖果数。由于每个人至少分配到 1 个糖果，所以每个人糖果数再加一。 + +## 代码 + +```go +package leetcode + +func candy(ratings []int) int { + candies := make([]int, len(ratings)) + for i := 1; i < len(ratings); i++ { + if ratings[i] > ratings[i-1] { + candies[i] += candies[i-1] + 1 + } + } + for i := len(ratings) - 2; i >= 0; i-- { + if ratings[i] > ratings[i+1] && candies[i] <= candies[i+1] { + candies[i] = candies[i+1] + 1 + } + } + total := 0 + for _, candy := range candies { + total += candy + 1 + } + return total +} +``` \ No newline at end of file diff --git a/leetcode/0136.Single-Number/README.md b/leetcode/0136.Single-Number/README.md index e36ce6b29..fdf307eac 100755 --- a/leetcode/0136.Single-Number/README.md +++ b/leetcode/0136.Single-Number/README.md @@ -26,4 +26,4 @@ Your algorithm should have a linear runtime complexity. Could you implement it w ## 解题思路 - 题目要求不能使用辅助空间，并且时间复杂度只能是线性的。 -- 题目为什么要强调有一个数字出现一次，其他的出现两次？我们想到了异或运算的性质：任何一个数字异或它自己都等于0。也就是说，如果我们从头到尾依次异或数组中的每一个数字，那么最终的结果刚好是那个只出现依次的数字，因为那些出现两次的数字全部在异或中抵消掉了。于是最终做法是从头到尾依次异或数组中的每一个数字，那么最终得到的结果就是两个只出现一次的数字的异或结果。因为其他数字都出现了两次，在异或中全部抵消掉了。**利用的性质是 x^x = 0**。 +- 题目为什么要强调有一个数字出现一次，其他的出现两次？我们想到了异或运算的性质：任何一个数字异或它自己都等于0。也就是说，如果我们从头到尾依次异或数组中的每一个数字，那么最终的结果刚好是那个只出现一次的数字，因为那些出现两次的数字全部在异或中抵消掉了。于是最终做法是从头到尾依次异或数组中的每一个数字，那么最终得到的结果就是两个只出现一次的数字的异或结果。因为其他数字都出现了两次，在异或中全部抵消掉了。**利用的性质是 x^x = 0**。 diff --git a/leetcode/0137.Single-Number-II/README.md b/leetcode/0137.Single-Number-II/README.md index 2bd634144..9733ff3c3 100755 --- a/leetcode/0137.Single-Number-II/README.md +++ b/leetcode/0137.Single-Number-II/README.md @@ -30,9 +30,9 @@ Your algorithm should have a linear runtime complexity. Could you implement it w ## 解题思路 - 这一题是第 136 题的加强版。这类题也可以扩展，在数组中每个元素都出现 5 次，找出只出现 1 次的数。 -- 本题中要求找出只出现 1 次的数，出现 3 次的数都要被消除。第 136 题是消除出现 2 次的数。这一题也会相当相同的解法，出现 3 次的数也要被消除。定义状态，00、10、01，这 3 个状态。当一个数出现 3 次，那么它每个位置上的 1 出现的次数肯定是 3 的倍数，所以当 1 出现 3 次以后，就归零清除。如何能做到这点呢？仿造`三进制(00，10，01)` 就可以做到。 +- 本题中要求找出只出现 1 次的数，出现 3 次的数都要被消除。第 136 题是消除出现 2 次的数。这一题也会相当相同的解法，出现 3 次的数也要被消除。定义状态，00、10、01，这 3 个状态。当一个数出现 3 次，那么它每个位置上的 1 出现的次数肯定是 3 的倍数，所以当 1 出现 3 次以后，就归零清除。如何能做到这点呢？仿造`三进制(00，01，10)` 就可以做到。 - 变量 ones 中记录遍历中每个位上出现 1 的个数。将它与 A[i] 进行异或，目的是： - - 每位上两者都是 1 的，表示历史统计结果 ones 出现1次、A[i]中又出现1次，则是出现 2 次，需要进位到 twos 变量中。 + - 每位上两者都是 1 的，表示历史统计结果 ones 出现1次、A[i]中又出现 1 次，则是出现 2 次，需要进位到 twos 变量中。 - 每位上两者分别为 0、1 的，加入到 ones 统计结果中。 - 最后还要 & ^twos ，是为了能做到三进制，出现 3 次就清零。例如 ones = x，那么 twos = 0，当 twos = x，那么 ones = 0； - 变量 twos 中记录遍历中每个位上出现 1 ，2次 的个数。与 A[i] 进行异或的目的和上述描述相同，不再赘述。 @@ -41,6 +41,31 @@ Your algorithm should have a linear runtime complexity. Could you implement it w > 在 golang 中没有 Java 中的 ~ 位操作运算符，Java 中的 ~ 运算符代表按位取反。这个操作就想当于 golang 中的 ^ 运算符当做一元运算符使用的效果。 +|(twos,ones)|xi|(twos'',ones')|ones'| +|:----:|:----:|:----:|:----:| +|00|0|00|0| +|00|1|01|1| +|01|0|01|1| +|01|1|10|0| +|10|0|10|0| +|10|1|00|0| + +- 第一步，先将 ones -> ones'。通过观察可以看出 ones = (ones ^ nums[i]) & ^twos + +|(twos,ones')|xi|twos'| +|:----:|:----:|:----:| +|00|0|0| +|01|1|0| +|01|0|0| +|00|1|1| +|10|0|1| +|10|1|0| + + +- 第二步，再将 twos -> twos'。这一步需要用到前一步的 ones。通过观察可以看出 twos = (twos ^ nums[i]) & ^ones。 + +-------------------------- + 这一题还可以继续扩展，在数组中每个元素都出现 5 次，找出只出现 1 次的数。那该怎么做呢？思路还是一样的，模拟一个五进制，5 次就会消除。代码如下： // 解法一 diff --git a/leetcode/0141.Linked-List-Cycle/141. Linked List Cycle.go b/leetcode/0141.Linked-List-Cycle/141. Linked List Cycle.go index 10eebf0b2..947c10ce9 100644 --- a/leetcode/0141.Linked-List-Cycle/141. Linked List Cycle.go +++ b/leetcode/0141.Linked-List-Cycle/141. Linked List Cycle.go @@ -9,17 +9,16 @@ type ListNode = structures.ListNode /** * Definition for singly-linked list. - * struct ListNode { - * int val; - * ListNode *next; - * ListNode(int x) : val(x), next(NULL) {} - * }; + * type ListNode struct { + * Val int + * Next *ListNode + * } */ func hasCycle(head *ListNode) bool { fast := head slow := head - for slow != nil && fast != nil && fast.Next != nil { + for fast != nil && fast.Next != nil { fast = fast.Next.Next slow = slow.Next if fast == slow { diff --git a/leetcode/0141.Linked-List-Cycle/141. Linked List Cycle_test.go b/leetcode/0141.Linked-List-Cycle/141. Linked List Cycle_test.go index 06d9b570a..06bf230fd 100644 --- a/leetcode/0141.Linked-List-Cycle/141. Linked List Cycle_test.go +++ b/leetcode/0141.Linked-List-Cycle/141. Linked List Cycle_test.go @@ -1,6 +1,54 @@ package leetcode -import "testing" +import ( + "fmt" + "testing" + + "github.com/halfrost/LeetCode-Go/structures" +) + +type question141 struct { + para141 + ans141 +} + +// para 是参数 +// one 代表第一个参数 +type para141 struct { + one []int +} + +// ans 是答案 +// one 代表第一个答案 +type ans141 struct { + one bool +} func Test_Problem141(t *testing.T) { + + qs := []question141{ + + { + para141{[]int{3, 2, 0, -4}}, + ans141{false}, + }, + + { + para141{[]int{1, 2}}, + ans141{false}, + }, + + { + para141{[]int{1}}, + ans141{false}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 141------------------------\n") + + for _, q := range qs { + _, p := q.ans141, q.para141 + fmt.Printf("【input】:%v 【output】:%v\n", p, hasCycle(structures.Ints2List(p.one))) + } + fmt.Printf("\n\n\n") } diff --git a/leetcode/0143.Reorder-List/README.md b/leetcode/0143.Reorder-List/README.md index 4df8c7ff4..0e0915d02 100644 --- a/leetcode/0143.Reorder-List/README.md +++ b/leetcode/0143.Reorder-List/README.md @@ -31,4 +31,4 @@ Given 1->2->3->4->5, reorder it to 1->5->2->4->3. 更好的做法是结合之前几道题的操作：链表逆序，找中间结点。 -先找到链表的中间结点，然后利用逆序区间的操作，如 [第 92 题](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0092.Reverse-Linked-List-II) 里的 reverseBetween() 操作，只不过这里的反转区间是从中点一直到末尾。最后利用 2 个指针，一个指向头结点，一个指向中间结点，开始拼接最终的结果。这种做法的时间复杂度是 O(n)，空间复杂度是 O(1)。 \ No newline at end of file +先找到链表的中间结点，然后利用逆序区间的操作，如 [第 92 题](https://github.com/halfrost/leetcode-go/tree/master/leetcode/0092.Reverse-Linked-List-II) 里的 reverseBetween() 操作，只不过这里的反转区间是从中点一直到末尾。最后利用 2 个指针，一个指向头结点，一个指向中间结点，开始拼接最终的结果。这种做法的时间复杂度是 O(n)，空间复杂度是 O(1)。 \ No newline at end of file diff --git a/leetcode/0150.Evaluate-Reverse-Polish-Notation/150. Evaluate Reverse Polish Notation.go b/leetcode/0150.Evaluate-Reverse-Polish-Notation/150. Evaluate Reverse Polish Notation.go index eac594102..e91375491 100644 --- a/leetcode/0150.Evaluate-Reverse-Polish-Notation/150. Evaluate Reverse Polish Notation.go +++ b/leetcode/0150.Evaluate-Reverse-Polish-Notation/150. Evaluate Reverse Polish Notation.go @@ -5,46 +5,23 @@ import ( ) func evalRPN(tokens []string) int { - if len(tokens) == 1 { - i, _ := strconv.Atoi(tokens[0]) - return i - } - stack, top := []int{}, 0 - for _, v := range tokens { - switch v { - case "+": - { - sum := stack[top-2] + stack[top-1] - stack = stack[:top-2] - stack = append(stack, sum) - top-- - } - case "-": - { - sub := stack[top-2] - stack[top-1] - stack = stack[:top-2] - stack = append(stack, sub) - top-- - } - case "*": - { - mul := stack[top-2] * stack[top-1] - stack = stack[:top-2] - stack = append(stack, mul) - top-- - } - case "/": - { - div := stack[top-2] / stack[top-1] - stack = stack[:top-2] - stack = append(stack, div) - top-- - } - default: - { - i, _ := strconv.Atoi(v) - stack = append(stack, i) - top++ + stack := make([]int, 0, len(tokens)) + for _, token := range tokens { + v, err := strconv.Atoi(token) + if err == nil { + stack = append(stack, v) + } else { + num1, num2 := stack[len(stack)-2], stack[len(stack)-1] + stack = stack[:len(stack)-2] + switch token { + case "+": + stack = append(stack, num1+num2) + case "-": + stack = append(stack, num1-num2) + case "*": + stack = append(stack, num1*num2) + case "/": + stack = append(stack, num1/num2) } } } diff --git a/leetcode/0160.Intersection-of-Two-Linked-Lists/160. Intersection of Two Linked Lists.go b/leetcode/0160.Intersection-of-Two-Linked-Lists/160. Intersection of Two Linked Lists.go index 93d68a224..b7b2ee342 100644 --- a/leetcode/0160.Intersection-of-Two-Linked-Lists/160. Intersection of Two Linked Lists.go +++ b/leetcode/0160.Intersection-of-Two-Linked-Lists/160. Intersection of Two Linked Lists.go @@ -1,8 +1,8 @@ package leetcode -import "fmt" - import ( + "fmt" + "github.com/halfrost/LeetCode-Go/structures" ) diff --git a/leetcode/0167.Two-Sum-II---Input-array-is-sorted/167. Two Sum II - Input array is sorted.go b/leetcode/0167.Two-Sum-II-Input-array-is-sorted/167. Two Sum II - Input array is sorted.go similarity index 100% rename from leetcode/0167.Two-Sum-II---Input-array-is-sorted/167. Two Sum II - Input array is sorted.go rename to leetcode/0167.Two-Sum-II-Input-array-is-sorted/167. Two Sum II - Input array is sorted.go diff --git a/leetcode/0167.Two-Sum-II---Input-array-is-sorted/167. Two Sum II - Input array is sorted_test.go b/leetcode/0167.Two-Sum-II-Input-array-is-sorted/167. Two Sum II - Input array is sorted_test.go similarity index 100% rename from leetcode/0167.Two-Sum-II---Input-array-is-sorted/167. Two Sum II - Input array is sorted_test.go rename to leetcode/0167.Two-Sum-II-Input-array-is-sorted/167. Two Sum II - Input array is sorted_test.go diff --git a/leetcode/0167.Two-Sum-II---Input-array-is-sorted/README.md b/leetcode/0167.Two-Sum-II-Input-array-is-sorted/README.md similarity index 100% rename from leetcode/0167.Two-Sum-II---Input-array-is-sorted/README.md rename to leetcode/0167.Two-Sum-II-Input-array-is-sorted/README.md diff --git a/leetcode/0168.Excel-Sheet-Column-Title/README.md b/leetcode/0168.Excel-Sheet-Column-Title/README.md index c1ecdd583..4602e86b2 100644 --- a/leetcode/0168.Excel-Sheet-Column-Title/README.md +++ b/leetcode/0168.Excel-Sheet-Column-Title/README.md @@ -7,7 +7,7 @@ Given a positive integer, return its corresponding column title as appear in an For example: ``` - 1 -> A + 1 -> A 2 -> B 3 -> C ... diff --git a/leetcode/0190.Reverse-Bits/190. Reverse Bits_test.go b/leetcode/0190.Reverse-Bits/190. Reverse Bits_test.go index 20c677d65..12c5c23d5 100644 --- a/leetcode/0190.Reverse-Bits/190. Reverse Bits_test.go +++ b/leetcode/0190.Reverse-Bits/190. Reverse Bits_test.go @@ -2,6 +2,7 @@ package leetcode import ( "fmt" + "strconv" "testing" ) @@ -23,7 +24,6 @@ type ans190 struct { } func Test_Problem190(t *testing.T) { - qs := []question190{ { @@ -41,7 +41,12 @@ func Test_Problem190(t *testing.T) { for _, q := range qs { _, p := q.ans190, q.para190 - fmt.Printf("【input】:%v 【output】:%v\n", p, reverseBits(p.one)) + input := strconv.FormatUint(uint64(p.one), 2) // 32位无符号整数转换为二进制字符串 + input = fmt.Sprintf("%0*v", 32, input) // 格式化输出32位,保留前置0 + output := reverseBits(p.one) + outputBin := strconv.FormatUint(uint64(output), 2) // 32位无符号整数转换为二进制字符串 + outputBin = fmt.Sprintf("%0*v", 32, outputBin) // 格式化输出32位,保留前置0 + fmt.Printf("【input】:%v 【output】:%v (%v)\n", input, output, outputBin) } fmt.Printf("\n\n\n") } diff --git a/leetcode/0191.Number-of-1-Bits/191. Number of 1 Bits_test.go b/leetcode/0191.Number-of-1-Bits/191. Number of 1 Bits_test.go index f327977c6..ac789e86e 100644 --- a/leetcode/0191.Number-of-1-Bits/191. Number of 1 Bits_test.go +++ b/leetcode/0191.Number-of-1-Bits/191. Number of 1 Bits_test.go @@ -2,6 +2,7 @@ package leetcode import ( "fmt" + "strconv" "testing" ) @@ -40,7 +41,9 @@ func Test_Problem191(t *testing.T) { for _, q := range qs { _, p := q.ans191, q.para191 - fmt.Printf("【input】:%v 【output】:%v\n", p, hammingWeight(p.one)) + input := strconv.FormatUint(uint64(p.one), 2) // 32位无符号整数转换为二进制字符串 + input = fmt.Sprintf("%0*v", 32, input) // 格式化输出32位,保留前置0 + fmt.Printf("【input】:%v 【output】:%v\n", input, hammingWeight(p.one)) } fmt.Printf("\n\n\n") } diff --git a/leetcode/0199.Binary-Tree-Right-Side-View/199. Binary Tree Right Side View.go b/leetcode/0199.Binary-Tree-Right-Side-View/199. Binary Tree Right Side View.go index e30aec0dd..de53951bb 100644 --- a/leetcode/0199.Binary-Tree-Right-Side-View/199. Binary Tree Right Side View.go +++ b/leetcode/0199.Binary-Tree-Right-Side-View/199. Binary Tree Right Side View.go @@ -17,33 +17,23 @@ type TreeNode = structures.TreeNode */ func rightSideView(root *TreeNode) []int { + res := []int{} if root == nil { - return []int{} + return res } - queue := []*TreeNode{} - queue = append(queue, root) - curNum, nextLevelNum, res, tmp := 1, 0, []int{}, []int{} - for len(queue) != 0 { - if curNum > 0 { - node := queue[0] - if node.Left != nil { - queue = append(queue, node.Left) - nextLevelNum++ + queue := []*TreeNode{root} + for len(queue) > 0 { + n := len(queue) + for i := 0; i < n; i++ { + if queue[i].Left != nil { + queue = append(queue, queue[i].Left) } - if node.Right != nil { - queue = append(queue, node.Right) - nextLevelNum++ + if queue[i].Right != nil { + queue = append(queue, queue[i].Right) } - curNum-- - tmp = append(tmp, node.Val) - queue = queue[1:] - } - if curNum == 0 { - res = append(res, tmp[len(tmp)-1]) - curNum = nextLevelNum - nextLevelNum = 0 - tmp = []int{} } + res = append(res, queue[n-1].Val) + queue = queue[n:] } return res } diff --git a/leetcode/0202.Happy-Number/202. Happy Number.go b/leetcode/0202.Happy-Number/202. Happy Number.go index 3764600ef..bd2b1b2ce 100644 --- a/leetcode/0202.Happy-Number/202. Happy Number.go +++ b/leetcode/0202.Happy-Number/202. Happy Number.go @@ -1,27 +1,26 @@ package leetcode func isHappy(n int) bool { - if n == 0 { - return false - } - res := 0 - num := n record := map[int]int{} - for { - for num != 0 { - res += (num % 10) * (num % 10) - num = num / 10 - } - if _, ok := record[res]; !ok { - if res == 1 { - return true + for n != 1 { + record[n] = n + n = getSquareOfDigits(n) + for _, previous := range record { + if n == previous { + return false } - record[res] = res - num = res - res = 0 - continue - } else { - return false } } + return true +} + +func getSquareOfDigits(n int) int { + squareOfDigits := 0 + temporary := n + for temporary != 0 { + remainder := temporary % 10 + squareOfDigits += remainder * remainder + temporary /= 10 + } + return squareOfDigits } diff --git a/leetcode/0202.Happy-Number/202. Happy Number_test.go b/leetcode/0202.Happy-Number/202. Happy Number_test.go index d8e4e7f9c..a80ff83cf 100644 --- a/leetcode/0202.Happy-Number/202. Happy Number_test.go +++ b/leetcode/0202.Happy-Number/202. Happy Number_test.go @@ -35,6 +35,16 @@ func Test_Problem202(t *testing.T) { para202{19}, ans202{true}, }, + + { + para202{2}, + ans202{false}, + }, + + { + para202{3}, + ans202{false}, + }, } fmt.Printf("------------------------Leetcode Problem 202------------------------\n") diff --git a/leetcode/0209.Minimum-Size-Subarray-Sum/209. Minimum Size Subarray Sum.go b/leetcode/0209.Minimum-Size-Subarray-Sum/209. Minimum Size Subarray Sum.go index 3c7a14365..acedf56c6 100644 --- a/leetcode/0209.Minimum-Size-Subarray-Sum/209. Minimum Size Subarray Sum.go +++ b/leetcode/0209.Minimum-Size-Subarray-Sum/209. Minimum Size Subarray Sum.go @@ -1,24 +1,16 @@ package leetcode -func minSubArrayLen(s int, nums []int) int { - n := len(nums) - if n == 0 { - return 0 - } - left, right, res, sum := 0, -1, n+1, 0 - for left < n { - if (right+1) < n && sum < s { - right++ - sum += nums[right] - } else { +func minSubArrayLen(target int, nums []int) int { + left, sum, res := 0, 0, len(nums)+1 + for right, v := range nums { + sum += v + for sum >= target { + res = min(res, right-left+1) sum -= nums[left] left++ } - if sum >= s { - res = min(res, right-left+1) - } } - if res == n+1 { + if res == len(nums)+1 { return 0 } return res diff --git a/leetcode/0215.Kth-Largest-Element-in-an-Array/215. Kth Largest Element in an Array.go b/leetcode/0215.Kth-Largest-Element-in-an-Array/215. Kth Largest Element in an Array.go index 20a5672e2..c8e3a553b 100644 --- a/leetcode/0215.Kth-Largest-Element-in-an-Array/215. Kth Largest Element in an Array.go +++ b/leetcode/0215.Kth-Largest-Element-in-an-Array/215. Kth Largest Element in an Array.go @@ -1,6 +1,9 @@ package leetcode -import "sort" +import ( + "math/rand" + "sort" +) // 解法一 排序，排序的方法反而速度是最快的 func findKthLargest1(nums []int, k int) int { @@ -9,36 +12,62 @@ func findKthLargest1(nums []int, k int) int { } // 解法二 这个方法的理论依据是 partition 得到的点的下标就是最终排序之后的下标，根据这个下标，我们可以判断第 K 大的数在哪里 +// 时间复杂度 O(n)，空间复杂度 O(log n)，最坏时间复杂度为 O(n^2)，空间复杂度 O(n) func findKthLargest(nums []int, k int) int { - if len(nums) == 0 { - return 0 - } - return selection(nums, 0, len(nums)-1, len(nums)-k) + m := len(nums) - k + 1 // mth smallest, from 1..len(nums) + return selectSmallest(nums, 0, len(nums)-1, m) } -func selection(arr []int, l, r, k int) int { - if l == r { - return arr[l] +func selectSmallest(nums []int, l, r, i int) int { + if l >= r { + return nums[l] + } + q := partition(nums, l, r) + k := q - l + 1 + if k == i { + return nums[q] } - p := partition164(arr, l, r) - if k == p { - return arr[p] - } else if k < p { - return selection(arr, l, p-1, k) + if i < k { + return selectSmallest(nums, l, q-1, i) } else { - return selection(arr, p+1, r, k) + return selectSmallest(nums, q+1, r, i-k) } } -func partition164(a []int, lo, hi int) int { - pivot := a[hi] - i := lo - 1 - for j := lo; j < hi; j++ { - if a[j] < pivot { +func partition(nums []int, l, r int) int { + k := l + rand.Intn(r-l+1) // 此处为优化，使得时间复杂度期望降为 O(n)，最坏时间复杂度为 O(n^2) + nums[k], nums[r] = nums[r], nums[k] + i := l - 1 + // nums[l..i] <= nums[r] + // nums[i+1..j-1] > nums[r] + for j := l; j < r; j++ { + if nums[j] <= nums[r] { i++ - a[j], a[i] = a[i], a[j] + nums[i], nums[j] = nums[j], nums[i] } } - a[i+1], a[hi] = a[hi], a[i+1] + nums[i+1], nums[r] = nums[r], nums[i+1] return i + 1 } + +// 扩展题 剑指 Offer 40. 最小的 k 个数 +func getLeastNumbers(arr []int, k int) []int { + return selectSmallest1(arr, 0, len(arr)-1, k)[:k] +} + +// 和 selectSmallest 实现完全一致，只是返回值不用再截取了，直接返回 nums 即可 +func selectSmallest1(nums []int, l, r, i int) []int { + if l >= r { + return nums + } + q := partition(nums, l, r) + k := q - l + 1 + if k == i { + return nums + } + if i < k { + return selectSmallest1(nums, l, q-1, i) + } else { + return selectSmallest1(nums, q+1, r, i-k) + } +} diff --git a/leetcode/0215.Kth-Largest-Element-in-an-Array/215. Kth Largest Element in an Array_test.go b/leetcode/0215.Kth-Largest-Element-in-an-Array/215. Kth Largest Element in an Array_test.go index 0eef94c40..54a070a43 100644 --- a/leetcode/0215.Kth-Largest-Element-in-an-Array/215. Kth Largest Element in an Array_test.go +++ b/leetcode/0215.Kth-Largest-Element-in-an-Array/215. Kth Largest Element in an Array_test.go @@ -27,6 +27,11 @@ func Test_Problem215(t *testing.T) { qs := []question215{ + { + para215{[]int{3, 2, 1}, 2}, + ans215{2}, + }, + { para215{[]int{3, 2, 1, 5, 6, 4}, 2}, ans215{5}, diff --git a/leetcode/0215.Kth-Largest-Element-in-an-Array/README.md b/leetcode/0215.Kth-Largest-Element-in-an-Array/README.md index 63506d275..b3a2d21f3 100644 --- a/leetcode/0215.Kth-Largest-Element-in-an-Array/README.md +++ b/leetcode/0215.Kth-Largest-Element-in-an-Array/README.md @@ -29,5 +29,5 @@ You may assume k is always valid, 1 ≤ k ≤ array's length. ## 解题思路 -在快排的 partition 操作中，每次 partition 操作结束都会返回一个点，这个标定点的下标和最终排序之后有序数组中这个元素所在的下标是一致的。利用这个特性，我们可以不断的划分数组区间，最终找到第 K 大的元素。执行一次 partition 操作以后，如果这个元素的下标比 K 小，那么接着就在后边的区间继续执行 partition 操作；如果这个元素的下标比 K 大，那么就在左边的区间继续执行 partition 操作；如果相等就直接输出这个下标对应的数组元素即可。 +在快速选择 quickselect 的 partition 操作中，每次 partition 操作结束都会返回一个点，这个标定点的下标和最终排序之后有序数组中这个元素所在的下标是一致的。利用这个特性，我们可以不断的划分数组区间，最终找到第 K 大的元素。执行一次 partition 操作以后，如果这个元素的下标比 K 小，那么接着就在后边的区间继续执行 partition 操作；如果这个元素的下标比 K 大，那么就在左边的区间继续执行 partition 操作；如果相等就直接输出这个下标对应的数组元素即可。 diff --git a/leetcode/0218.The-Skyline-Problem/218. The Skyline Problem.go b/leetcode/0218.The-Skyline-Problem/218. The Skyline Problem.go index aeaffdcd0..ad13dc245 100644 --- a/leetcode/0218.The-Skyline-Problem/218. The Skyline Problem.go +++ b/leetcode/0218.The-Skyline-Problem/218. The Skyline Problem.go @@ -81,7 +81,7 @@ func (bit *BinaryIndexedTree) Query(index int) int { return sum } -// 解法三 线段树 Segment Tree，时间复杂度 O(n log n) +// 解法二 线段树 Segment Tree，时间复杂度 O(n log n) func getSkyline1(buildings [][]int) [][]int { st, ans, lastHeight, check := template.SegmentTree{}, [][]int{}, 0, false posMap, pos := discretization218(buildings) diff --git a/leetcode/0234.Palindrome-Linked-List/234. Palindrome Linked List.go b/leetcode/0234.Palindrome-Linked-List/234. Palindrome Linked List.go index 12cf5e1f9..4a7f05c66 100644 --- a/leetcode/0234.Palindrome-Linked-List/234. Palindrome Linked List.go +++ b/leetcode/0234.Palindrome-Linked-List/234. Palindrome Linked List.go @@ -15,8 +15,26 @@ type ListNode = structures.ListNode * } */ +// 解法一 +func isPalindrome(head *ListNode) bool { + slice := []int{} + for head != nil { + slice = append(slice, head.Val) + head = head.Next + } + for i, j := 0, len(slice)-1; i < j; { + if slice[i] != slice[j] { + return false + } + i++ + j-- + } + return true +} + +// 解法二 // 此题和 143 题 Reorder List 思路基本一致 -func isPalindrome234(head *ListNode) bool { +func isPalindrome1(head *ListNode) bool { if head == nil || head.Next == nil { return true } @@ -28,7 +46,6 @@ func isPalindrome234(head *ListNode) bool { p1 = p1.Next p2 = p2.Next.Next } - // 反转链表后半部分 1->2->3->4->5->6 to 1->2->3->6->5->4 preMiddle := p1 preCurrent := p1.Next @@ -38,7 +55,6 @@ func isPalindrome234(head *ListNode) bool { current.Next = preMiddle.Next preMiddle.Next = current } - // 扫描表，判断是否是回文 p1 = head p2 = preMiddle.Next @@ -59,18 +75,15 @@ func isPalindrome234(head *ListNode) bool { return false } } - return res } // L2ss define func L2ss(head *ListNode) []int { res := []int{} - for head != nil { res = append(res, head.Val) head = head.Next } - return res } diff --git a/leetcode/0234.Palindrome-Linked-List/234. Palindrome Linked List_test.go b/leetcode/0234.Palindrome-Linked-List/234. Palindrome Linked List_test.go index 8fd7a31a1..57cdb5dc5 100644 --- a/leetcode/0234.Palindrome-Linked-List/234. Palindrome Linked List_test.go +++ b/leetcode/0234.Palindrome-Linked-List/234. Palindrome Linked List_test.go @@ -83,7 +83,7 @@ func Test_Problem234(t *testing.T) { for _, q := range qs { _, p := q.ans234, q.para234 - fmt.Printf("【input】:%v 【output】:%v\n", p, isPalindrome234(structures.Ints2List(p.one))) + fmt.Printf("【input】:%v 【output】:%v\n", p, isPalindrome(structures.Ints2List(p.one))) } fmt.Printf("\n\n\n") } diff --git a/leetcode/0237.Delete-Node-in-a-Linked-List/237. Delete Node in a Linked List.go b/leetcode/0237.Delete-Node-in-a-Linked-List/237. Delete Node in a Linked List.go index 78186ba93..bb33b98ad 100644 --- a/leetcode/0237.Delete-Node-in-a-Linked-List/237. Delete Node in a Linked List.go +++ b/leetcode/0237.Delete-Node-in-a-Linked-List/237. Delete Node in a Linked List.go @@ -15,14 +15,6 @@ type ListNode = structures.ListNode * } */ func deleteNode(node *ListNode) { - if node == nil { - return - } - cur := node - for cur.Next.Next != nil { - cur.Val = cur.Next.Val - cur = cur.Next - } - cur.Val = cur.Next.Val - cur.Next = nil + node.Val = node.Next.Val + node.Next = node.Next.Next } diff --git a/leetcode/0237.Delete-Node-in-a-Linked-List/README.md b/leetcode/0237.Delete-Node-in-a-Linked-List/README.md index 7c6e4954a..fa135fa7d 100644 --- a/leetcode/0237.Delete-Node-in-a-Linked-List/README.md +++ b/leetcode/0237.Delete-Node-in-a-Linked-List/README.md @@ -1,35 +1,64 @@ # [237. Delete Node in a Linked List](https://leetcode.com/problems/delete-node-in-a-linked-list/) + ## 题目 -Write a function to delete a node (except the tail) in a singly linked list, given only access to that node. +Write a function to **delete a node** in a singly-linked list. You will **not** be given access to the `head` of the list, instead you will be given access to **the node to be deleted** directly. -Given linked list -- head = [4,5,1,9], which looks like following: +It is **guaranteed** that the node to be deleted is **not a tail node** in the list. -![](https://assets.leetcode.com/uploads/2018/12/28/237_example.png) +**Example 1:** -Example 1: +![https://assets.leetcode.com/uploads/2020/09/01/node1.jpg](https://assets.leetcode.com/uploads/2020/09/01/node1.jpg) -```c +``` Input: head = [4,5,1,9], node = 5 Output: [4,1,9] -Explanation: You are given the second node with value 5, the linked list should become 4 -> 1 -> 9 after calling your function. +Explanation:You are given the second node with value 5, the linked list should become 4 -> 1 -> 9 after calling your function. + ``` -Example 2: +**Example 2:** + +![https://assets.leetcode.com/uploads/2020/09/01/node2.jpg](https://assets.leetcode.com/uploads/2020/09/01/node2.jpg) -```c +``` Input: head = [4,5,1,9], node = 1 Output: [4,5,9] -Explanation: You are given the third node with value 1, the linked list should become 4 -> 5 -> 9 after calling your function. +Explanation:You are given the third node with value 1, the linked list should become 4 -> 5 -> 9 after calling your function. + +``` + +**Example 3:** + +``` +Input: head = [1,2,3,4], node = 3 +Output: [1,2,4] + +``` + +**Example 4:** + +``` +Input: head = [0,1], node = 0 +Output: [1] + ``` -Note: +**Example 5:** + +``` +Input: head = [-3,5,-99], node = -3 +Output: [5,-99] + +``` -- The linked list will have at least two elements. -- All of the nodes' values will be unique. -- The given node will not be the tail and it will always be a valid node of the linked list. -- Do not return anything from your function. +**Constraints:** + +- The number of the nodes in the given list is in the range `[2, 1000]`. +- `1000 <= Node.val <= 1000` +- The value of each node in the list is **unique**. +- The `node` to be deleted is **in the list** and is **not a tail** node ## 题目大意 @@ -37,4 +66,29 @@ Note: ## 解题思路 -其实就是把后面的结点都覆盖上来即可。或者直接当前结点的值等于下一个结点，Next 指针指向下下个结点，这样做也可以，只不过中间有一个结点不被释放，内存消耗多一些。 \ No newline at end of file +其实就是把后面的结点都覆盖上来即可。或者直接当前结点的值等于下一个结点，Next 指针指向下下个结点，这样做也可以，只不过中间有一个结点不被释放，内存消耗多一些。 + +## 代码 + +```go +package leetcode + +import ( + "github.com/halfrost/LeetCode-Go/structures" +) + +// ListNode define +type ListNode = structures.ListNode + +/** + * Definition for singly-linked list. + * type ListNode struct { + * Val int + * Next *ListNode + * } + */ +func deleteNode(node *ListNode) { + node.Val = node.Next.Val + node.Next = node.Next.Next +} +``` \ No newline at end of file diff --git a/leetcode/0242.Valid-Anagram/242. Valid Anagram.go b/leetcode/0242.Valid-Anagram/242. Valid Anagram.go index 81920dd7f..ae3a7287c 100644 --- a/leetcode/0242.Valid-Anagram/242. Valid Anagram.go +++ b/leetcode/0242.Valid-Anagram/242. Valid Anagram.go @@ -24,44 +24,17 @@ func isAnagram(s string, t string) bool { // 解法二 func isAnagram1(s string, t string) bool { - if s == "" && t == "" { - return true + hash := map[rune]int{} + for _, value := range s { + hash[value]++ } - if s == "" || t == "" { - return false + for _, value := range t { + hash[value]-- } - sBytes := []byte(s) - tBytes := []byte(t) - if len(sBytes) != len(tBytes) { - return false - } - quickSortByte(sBytes, 0, len(sBytes)-1) - quickSortByte(tBytes, 0, len(tBytes)-1) - - for i := 0; i < len(sBytes); i++ { - if sBytes[i] != tBytes[i] { + for _, value := range hash { + if value != 0 { return false } } return true } -func partitionByte(a []byte, lo, hi int) int { - pivot := a[hi] - i := lo - 1 - for j := lo; j < hi; j++ { - if a[j] > pivot { - i++ - a[j], a[i] = a[i], a[j] - } - } - a[i+1], a[hi] = a[hi], a[i+1] - return i + 1 -} -func quickSortByte(a []byte, lo, hi int) { - if lo >= hi { - return - } - p := partitionByte(a, lo, hi) - quickSortByte(a, lo, p-1) - quickSortByte(a, p+1, hi) -} diff --git a/leetcode/0242.Valid-Anagram/242. Valid Anagram_test.go b/leetcode/0242.Valid-Anagram/242. Valid Anagram_test.go index 15a108ca0..8ece1c25a 100644 --- a/leetcode/0242.Valid-Anagram/242. Valid Anagram_test.go +++ b/leetcode/0242.Valid-Anagram/242. Valid Anagram_test.go @@ -45,6 +45,21 @@ func Test_Problem242(t *testing.T) { para242{"rat", "car"}, ans242{false}, }, + + { + para242{"a", "ab"}, + ans242{false}, + }, + + { + para242{"ab", "a"}, + ans242{false}, + }, + + { + para242{"aa", "bb"}, + ans242{false}, + }, } fmt.Printf("------------------------Leetcode Problem 242------------------------\n") diff --git a/leetcode/0257.Binary-Tree-Paths/257. Binary Tree Paths.go b/leetcode/0257.Binary-Tree-Paths/257. Binary Tree Paths.go index 4640cf7f6..0759ad1cc 100644 --- a/leetcode/0257.Binary-Tree-Paths/257. Binary Tree Paths.go +++ b/leetcode/0257.Binary-Tree-Paths/257. Binary Tree Paths.go @@ -2,9 +2,7 @@ package leetcode import ( "strconv" -) -import ( "github.com/halfrost/LeetCode-Go/structures" ) diff --git a/leetcode/0263.Ugly-Number/263. Ugly Number.go b/leetcode/0263.Ugly-Number/263. Ugly Number.go index f155ab422..42e66c217 100644 --- a/leetcode/0263.Ugly-Number/263. Ugly Number.go +++ b/leetcode/0263.Ugly-Number/263. Ugly Number.go @@ -1,9 +1,11 @@ package leetcode func isUgly(num int) bool { - for i := 2; i < 6 && num > 0; i++ { - for num%i == 0 { - num /= i + if num > 0 { + for _, i := range []int{2, 3, 5} { + for num%i == 0 { + num /= i + } } } return num == 1 diff --git a/leetcode/0278.First-Bad-Version/278. First Bad Version.go b/leetcode/0278.First-Bad-Version/278. First Bad Version.go new file mode 100644 index 000000000..d4517c087 --- /dev/null +++ b/leetcode/0278.First-Bad-Version/278. First Bad Version.go @@ -0,0 +1,19 @@ +package leetcode + +import "sort" + +/** + * Forward declaration of isBadVersion API. + * @param version your guess about first bad version + * @return true if current version is bad + * false if current version is good + * func isBadVersion(version int) bool; + */ + +func firstBadVersion(n int) int { + return sort.Search(n, func(version int) bool { return isBadVersion(version) }) +} + +func isBadVersion(version int) bool { + return true +} diff --git a/leetcode/0278.First-Bad-Version/278. First Bad Version_test.go b/leetcode/0278.First-Bad-Version/278. First Bad Version_test.go new file mode 100644 index 000000000..5792af66c --- /dev/null +++ b/leetcode/0278.First-Bad-Version/278. First Bad Version_test.go @@ -0,0 +1,46 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question278 struct { + para278 + ans278 +} + +// para 是参数 +// one 代表第一个参数 +type para278 struct { + n int +} + +// ans 是答案 +// one 代表第一个答案 +type ans278 struct { + one int +} + +func Test_Problem278(t *testing.T) { + + qs := []question278{ + + { + para278{5}, + ans278{4}, + }, + { + para278{1}, + ans278{1}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 278------------------------\n") + + for _, q := range qs { + _, p := q.ans278, q.para278 + fmt.Printf("【input】:%v 【output】:%v\n", p, firstBadVersion(p.n)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0278.First-Bad-Version/README.md b/leetcode/0278.First-Bad-Version/README.md new file mode 100644 index 000000000..cb9bfe5ab --- /dev/null +++ b/leetcode/0278.First-Bad-Version/README.md @@ -0,0 +1,62 @@ +# [278. First Bad Version](https://leetcode.com/problems/first-bad-version/) + +## 题目 + +You are a product manager and currently leading a team to develop a new product. Unfortunately, the latest version of your product fails the quality check. Since each version is developed based on the previous version, all the versions after a bad version are also bad. + +Suppose you have `n` versions `[1, 2, ..., n]` and you want to find out the first bad one, which causes all the following ones to be bad. + +You are given an API `bool isBadVersion(version)` which returns whether `version` is bad. Implement a function to find the first bad version. You should minimize the number of calls to the API. + +**Example 1:** + +``` +Input: n = 5, bad = 4 +Output: 4 +Explanation: +call isBadVersion(3) -> false +call isBadVersion(5) -> true +call isBadVersion(4) -> true +Then 4 is the first bad version. + +``` + +**Example 2:** + +``` +Input: n = 1, bad = 1 +Output: 1 + +``` + +**Constraints:** + +- `1 <= bad <= n <= 231 - 1` + +## 题目大意 + +你是产品经理，目前正在带领一个团队开发新的产品。不幸的是，你的产品的最新版本没有通过质量检测。由于每个版本都是基于之前的版本开发的，所以错误的版本之后的所有版本都是错的。假设你有 n 个版本 [1, 2, ..., n]，你想找出导致之后所有版本出错的第一个错误的版本。你可以通过调用 bool isBadVersion(version) 接口来判断版本号 version 是否在单元测试中出错。实现一个函数来查找第一个错误的版本。你应该尽量减少对调用 API 的次数。 + +## 解题思路 + +- 我们知道开发产品迭代的版本，如果当一个版本为正确版本，则该版本之前的所有版本均为正确版本；当一个版本为错误版本，则该版本之后的所有版本均为错误版本。利用这个性质就可以进行二分查找。利用二分搜索，也可以满足减少对调用 API 的次数的要求。时间复杂度：O(logn)，其中 n 是给定版本的数量。空间复杂度：O(1)。 + +## 代码 + +```go +package leetcode + +import "sort" + +/** + * Forward declaration of isBadVersion API. + * @param version your guess about first bad version + * @return true if current version is bad + * false if current version is good + * func isBadVersion(version int) bool; + */ + +func firstBadVersion(n int) int { + return sort.Search(n, func(version int) bool { return isBadVersion(version) }) +} +``` \ No newline at end of file diff --git a/leetcode/0279.Perfect-Squares/279. Perfect Squares.go b/leetcode/0279.Perfect-Squares/279. Perfect Squares.go new file mode 100644 index 000000000..99771598c --- /dev/null +++ b/leetcode/0279.Perfect-Squares/279. Perfect Squares.go @@ -0,0 +1,33 @@ +package leetcode + +import "math" + +func numSquares(n int) int { + if isPerfectSquare(n) { + return 1 + } + if checkAnswer4(n) { + return 4 + } + for i := 1; i*i <= n; i++ { + j := n - i*i + if isPerfectSquare(j) { + return 2 + } + } + return 3 +} + +// 判断是否为完全平方数 +func isPerfectSquare(n int) bool { + sq := int(math.Floor(math.Sqrt(float64(n)))) + return sq*sq == n +} + +// 判断是否能表示为 4^k*(8m+7) +func checkAnswer4(x int) bool { + for x%4 == 0 { + x /= 4 + } + return x%8 == 7 +} diff --git a/leetcode/0279.Perfect-Squares/279. Perfect Squares_test.go b/leetcode/0279.Perfect-Squares/279. Perfect Squares_test.go new file mode 100644 index 000000000..6c8a13ae1 --- /dev/null +++ b/leetcode/0279.Perfect-Squares/279. Perfect Squares_test.go @@ -0,0 +1,46 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question279 struct { + para279 + ans279 +} + +// para 是参数 +// one 代表第一个参数 +type para279 struct { + n int +} + +// ans 是答案 +// one 代表第一个答案 +type ans279 struct { + one int +} + +func Test_Problem279(t *testing.T) { + + qs := []question279{ + + { + para279{13}, + ans279{2}, + }, + { + para279{12}, + ans279{3}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 279------------------------\n") + + for _, q := range qs { + _, p := q.ans279, q.para279 + fmt.Printf("【input】:%v 【output】:%v\n", p, numSquares(p.n)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0279.Perfect-Squares/README.md b/leetcode/0279.Perfect-Squares/README.md new file mode 100644 index 000000000..5e8e466df --- /dev/null +++ b/leetcode/0279.Perfect-Squares/README.md @@ -0,0 +1,78 @@ +# [279. Perfect Squares](https://leetcode.com/problems/perfect-squares/) + + +## 题目 + +Given an integer `n`, return *the least number of perfect square numbers that sum to* `n`. + +A **perfect square** is an integer that is the square of an integer; in other words, it is the product of some integer with itself. For example, `1`, `4`, `9`, and `16` are perfect squares while `3` and `11` are not. + +**Example 1:** + +``` +Input: n = 12 +Output: 3 +Explanation: 12 = 4 + 4 + 4. +``` + +**Example 2:** + +``` +Input: n = 13 +Output: 2 +Explanation: 13 = 4 + 9. +``` + +**Constraints:** + +- `1 <= n <= 104` + +## 题目大意 + +给定正整数 n，找到若干个完全平方数（比如 1, 4, 9, 16, ...）使得它们的和等于 n。你需要让组成和的完全平方数的个数最少。给你一个整数 n ，返回和为 n 的完全平方数的 最少数量 。 + +完全平方数 是一个整数，其值等于另一个整数的平方；换句话说，其值等于一个整数自乘的积。例如，1、4、9 和 16 都是完全平方数，而 3 和 11 不是。 + +## 解题思路 + +- 由拉格朗日的四平方定理可得，每个自然数都可以表示为四个整数平方之和。 其中四个数字是整数。四平方和定理证明了任意一个正整数都可以被表示为至多四个正整数的平方和。这给出了本题的答案的上界。 +- 四平方和定理可以推出三平方和推论：当且仅当 {{< katex >}} n \neq 4^{k} \times (8*m + 7){{< /katex >}} 时，n 可以被表示为至多三个正整数的平方和。所以当 {{< katex >}} n = 4^{k} * (8*m + 7){{< /katex >}} 时，n 只能被表示为四个正整数的平方和。此时我们可以直接返回 4。 +- 当 {{< katex >}} n \neq 4^{k} \times (8*m + 7){{< /katex >}} 时，需要判断 n 到底可以分解成几个完全平方数之和。答案肯定是 1，2，3 中的一个。题目要求我们求最小的，所以从 1 开始一个个判断是否满足。如果答案为 1，代表 n 为完全平方数，这很好判断。如果答案为 2，代表 {{< katex >}} n = a^{2} + b^{2} {{< /katex >}}，枚举 {{< katex >}} 1 \leqslant a \leqslant \sqrt{n} {{< /katex >}}，判断 {{< katex >}} n - a^{2} {{< /katex >}} 是否为完全平方数。当 1 和 2 都排除了，剩下的答案只能为 3 了。 + +## 代码 + +```go +package leetcode + +import "math" + +func numSquares(n int) int { + if isPerfectSquare(n) { + return 1 + } + if checkAnswer4(n) { + return 4 + } + for i := 1; i*i <= n; i++ { + j := n - i*i + if isPerfectSquare(j) { + return 2 + } + } + return 3 +} + +// 判断是否为完全平方数 +func isPerfectSquare(n int) bool { + sq := int(math.Floor(math.Sqrt(float64(n)))) + return sq*sq == n +} + +// 判断是否能表示为 4^k*(8m+7) +func checkAnswer4(x int) bool { + for x%4 == 0 { + x /= 4 + } + return x%8 == 7 +} +``` \ No newline at end of file diff --git a/leetcode/0297.Serialize-and-Deserialize-Binary-Tree/297.Serialize and Deserialize Binary Tree_test.go b/leetcode/0297.Serialize-and-Deserialize-Binary-Tree/297.Serialize and Deserialize Binary Tree_test.go index 6069704e2..cf7031c4a 100644 --- a/leetcode/0297.Serialize-and-Deserialize-Binary-Tree/297.Serialize and Deserialize Binary Tree_test.go +++ b/leetcode/0297.Serialize-and-Deserialize-Binary-Tree/297.Serialize and Deserialize Binary Tree_test.go @@ -31,12 +31,12 @@ func Test_Problem297(t *testing.T) { ans297{[]int{}}, }, { - para297{[]int{1,2,3,-1,-1,4,5}}, - ans297{[]int{1,2,3,-1,-1,4,5}}, + para297{[]int{1, 2, 3, -1, -1, 4, 5}}, + ans297{[]int{1, 2, 3, -1, -1, 4, 5}}, }, { - para297{[]int{1,2}}, - ans297{[]int{1,2}}, + para297{[]int{1, 2}}, + ans297{[]int{1, 2}}, }, } @@ -52,4 +52,4 @@ func Test_Problem297(t *testing.T) { fmt.Printf("【output】:%v \n", structures.Tree2Preorder(tree297.deserialize(serialized))) } fmt.Printf("\n\n\n") -} \ No newline at end of file +} diff --git a/leetcode/0299.Bulls-and-Cows/299.Bulls and Cows.go b/leetcode/0299.Bulls-and-Cows/299.Bulls and Cows.go new file mode 100644 index 000000000..920827f07 --- /dev/null +++ b/leetcode/0299.Bulls-and-Cows/299.Bulls and Cows.go @@ -0,0 +1,31 @@ +package leetcode + +import "strconv" + +func getHint(secret string, guess string) string { + cntA, cntB := 0, 0 + mpS := make(map[byte]int) + var strG []byte + n := len(secret) + var ans string + for i := 0; i < n; i++ { + if secret[i] == guess[i] { + cntA++ + } else { + mpS[secret[i]] += 1 + strG = append(strG, guess[i]) + } + } + for _, v := range strG { + if _, ok := mpS[v]; ok { + if mpS[v] > 1 { + mpS[v] -= 1 + } else { + delete(mpS, v) + } + cntB++ + } + } + ans += strconv.Itoa(cntA) + "A" + strconv.Itoa(cntB) + "B" + return ans +} diff --git a/leetcode/0299.Bulls-and-Cows/299.Bulls and Cows_test.go b/leetcode/0299.Bulls-and-Cows/299.Bulls and Cows_test.go new file mode 100644 index 000000000..72028efb6 --- /dev/null +++ b/leetcode/0299.Bulls-and-Cows/299.Bulls and Cows_test.go @@ -0,0 +1,56 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question299 struct { + para299 + ans299 +} + +// para 是参数 +type para299 struct { + secret string + guess string +} + +// ans 是答案 +type ans299 struct { + ans string +} + +func Test_Problem299(t *testing.T) { + + qs := []question299{ + + { + para299{"1807", "7810"}, + ans299{"1A3B"}, + }, + + { + para299{"1123", "0111"}, + ans299{"1A1B"}, + }, + + { + para299{"1", "0"}, + ans299{"0A0B"}, + }, + + { + para299{"1", "1"}, + ans299{"1A0B"}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 299------------------------\n") + + for _, q := range qs { + _, p := q.ans299, q.para299 + fmt.Printf("【input】:%v 【output】:%v\n", p, getHint(p.secret, p.guess)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0299.Bulls-and-Cows/README.md b/leetcode/0299.Bulls-and-Cows/README.md new file mode 100644 index 000000000..61f7b164b --- /dev/null +++ b/leetcode/0299.Bulls-and-Cows/README.md @@ -0,0 +1,114 @@ +# [299. Bulls and Cows](https://leetcode.com/problems/bulls-and-cows/) + + +## 题目 + +You are playing the Bulls and Cows game with your friend. + +You write down a secret number and ask your friend to guess what the number is. When your friend makes a guess, you provide a hint with the following info: + +The number of "bulls", which are digits in the guess that are in the correct position. +The number of "cows", which are digits in the guess that are in your secret number but are located in the wrong position. Specifically, the non-bull digits in the guess that could be rearranged such that they become bulls. +Given the secret number secret and your friend's guess guess, return the hint for your friend's guess. + +The hint should be formatted as "xAyB", where x is the number of bulls and y is the number of cows. Note that both secret and guess may contain duplicate digits. + +**Example 1:** + +``` +Input: secret = "1807", guess = "7810" +Output: "1A3B" +Explanation: Bulls are connected with a '|' and cows are underlined: +"1807" + | +"7810" +``` + +**Example 2:** + +``` +Input: secret = "1123", guess = "0111" +Output: "1A1B" +Explanation: Bulls are connected with a '|' and cows are underlined: +"1123" "1123" + | or | +"0111" "0111" +Note that only one of the two unmatched 1s is counted as a cow since the non-bull digits can only be rearranged to allow one 1 to be a bull. +``` + +**Example 3:** + +``` +Input: secret = "1", guess = "0" +Output: "0A0B" +``` + +**Example 4:** + +``` +Input: secret = "1", guess = "1" +Output: "1A0B" +``` + +**Constraints:** + +- 1 <= secret.length, guess.length <= 1000 +- secret.length == guess.length +- secret and guess consist of digits only. + +## 题目大意 + +你在和朋友一起玩 猜数字（Bulls and Cows）游戏，该游戏规则如下： + +写出一个秘密数字，并请朋友猜这个数字是多少。朋友每猜测一次，你就会给他一个包含下述信息的提示： + +猜测数字中有多少位属于数字和确切位置都猜对了（称为 "Bulls", 公牛）， +有多少位属于数字猜对了但是位置不对（称为 "Cows", 奶牛）。也就是说，这次猜测中有多少位非公牛数字可以通过重新排列转换成公牛数字。 +给你一个秘密数字secret 和朋友猜测的数字guess ，请你返回对朋友这次猜测的提示。 + +提示的格式为 "xAyB" ，x 是公牛个数， y 是奶牛个数，A 表示公牛，B表示奶牛。 + +请注意秘密数字和朋友猜测的数字都可能含有重复数字。 + +## 解题思路 + +- 计算下标一致并且对应下标的元素一致的个数，即 x +- secret 和 guess 分别去除 x 个公牛的元素,剩下 secret 和 guess 求共同的元素个数就是 y +- 把 x， y 转换成字符串，分别与 "A" 和 "B" 进行拼接返回结果 + +## 代码 + +```go + +package leetcode + +import "strconv" + +func getHint(secret string, guess string) string { + cntA, cntB := 0, 0 + mpS := make(map[byte]int) + var strG []byte + n := len(secret) + var ans string + for i := 0; i < n; i++ { + if secret[i] == guess[i] { + cntA++ + } else { + mpS[secret[i]] += 1 + strG = append(strG, guess[i]) + } + } + for _, v := range strG { + if _, ok := mpS[v]; ok { + if mpS[v] > 1 { + mpS[v] -= 1 + } else { + delete(mpS, v) + } + cntB++ + } + } + ans += strconv.Itoa(cntA) + "A" + strconv.Itoa(cntB) + "B" + return ans +} +``` \ No newline at end of file diff --git a/leetcode/0301.Remove-Invalid-Parentheses/301.Remove Invalid Parentheses.go b/leetcode/0301.Remove-Invalid-Parentheses/301.Remove Invalid Parentheses.go new file mode 100644 index 000000000..0e53f6bdd --- /dev/null +++ b/leetcode/0301.Remove-Invalid-Parentheses/301.Remove Invalid Parentheses.go @@ -0,0 +1,69 @@ +package leetcode + +var ( + res []string + mp map[string]int + n int + length int + maxScore int + str string +) + +func removeInvalidParentheses(s string) []string { + lmoves, rmoves, lcnt, rcnt := 0, 0, 0, 0 + for _, v := range s { + if v == '(' { + lmoves++ + lcnt++ + } else if v == ')' { + if lmoves != 0 { + lmoves-- + } else { + rmoves++ + } + rcnt++ + } + } + n = len(s) + length = n - lmoves - rmoves + res = []string{} + mp = make(map[string]int) + maxScore = min(lcnt, rcnt) + str = s + backtrace(0, "", lmoves, rmoves, 0) + return res +} + +func backtrace(i int, cur string, lmoves int, rmoves int, score int) { + if lmoves < 0 || rmoves < 0 || score < 0 || score > maxScore { + return + } + if lmoves == 0 && rmoves == 0 { + if len(cur) == length { + if _, ok := mp[cur]; !ok { + res = append(res, cur) + mp[cur] = 1 + } + return + } + } + if i == n { + return + } + if str[i] == '(' { + backtrace(i+1, cur+string('('), lmoves, rmoves, score+1) + backtrace(i+1, cur, lmoves-1, rmoves, score) + } else if str[i] == ')' { + backtrace(i+1, cur+string(')'), lmoves, rmoves, score-1) + backtrace(i+1, cur, lmoves, rmoves-1, score) + } else { + backtrace(i+1, cur+string(str[i]), lmoves, rmoves, score) + } +} + +func min(a, b int) int { + if a < b { + return a + } + return b +} diff --git a/leetcode/0301.Remove-Invalid-Parentheses/301.Remove Invalid Parentheses_test.go b/leetcode/0301.Remove-Invalid-Parentheses/301.Remove Invalid Parentheses_test.go new file mode 100644 index 000000000..c49d72df7 --- /dev/null +++ b/leetcode/0301.Remove-Invalid-Parentheses/301.Remove Invalid Parentheses_test.go @@ -0,0 +1,50 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question301 struct { + para301 + ans301 +} + +// s 是参数 +type para301 struct { + s string +} + +// ans 是答案 +type ans301 struct { + ans []string +} + +func Test_Problem301(t *testing.T) { + + qs := []question301{ + + { + para301{"()())()"}, + ans301{[]string{"(())()", "()()()"}}, + }, + + { + para301{"(a)())()"}, + ans301{[]string{"(a())()", "(a)()()"}}, + }, + + { + para301{")("}, + ans301{[]string{""}}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 301------------------------\n") + + for _, q := range qs { + _, p := q.ans301, q.para301 + fmt.Printf("【input】:%v 【output】:%v\n", p, removeInvalidParentheses(p.s)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0301.Remove-Invalid-Parentheses/README.md b/leetcode/0301.Remove-Invalid-Parentheses/README.md new file mode 100644 index 000000000..cd1d80b81 --- /dev/null +++ b/leetcode/0301.Remove-Invalid-Parentheses/README.md @@ -0,0 +1,131 @@ +# [301. Remove Invalid Parentheses](https://leetcode.com/problems/remove-invalid-parentheses/) + + +## 题目 + +Given a string s that contains parentheses and letters, remove the minimum number of invalid parentheses to make the input string valid. + +Return all the possible results. You may return the answer in any order. + +**Example 1:** + + Input: s = "()())()" + Output: ["(())()","()()()"] + +**Example 2:** + + Input: s = "(a)())()" + Output: ["(a())()","(a)()()"] + +**Example 3:** + + Input: s = ")(" + Output: [""] + +**Constraints:** + +- 1 <= s.length <= 25 +- s consists of lowercase English letters and parentheses '(' and ')'. +- There will be at most 20 parentheses in s. + +## 题目大意 + +给你一个由若干括号和字母组成的字符串 s ，删除最小数量的无效括号，使得输入的字符串有效。 + +返回所有可能的结果。答案可以按 任意顺序 返回。 + +说明: + +- 1 <= s.length <= 25 +- s 由小写英文字母以及括号 '(' 和 ')' 组成 +- s 中至多含 20 个括号 + + +## 解题思路 + +回溯和剪枝 +- 计算最大得分数maxScore，合法字符串的长度length，左括号和右括号的移除次数lmoves,rmoves +- 加一个左括号的得分加1；加一个右括号的得分减1 +- 对于一个合法的字符串，左括号等于右括号，得分最终为0； +- 搜索过程中出现以下任何一种情况都直接返回 + - 得分值为负数 + - 得分大于最大得分数 + - 得分小于0 + - lmoves小于0 + - rmoves小于0 + +## 代码 + +```go + +package leetcode + +var ( + res []string + mp map[string]int + n int + length int + maxScore int + str string +) + +func removeInvalidParentheses(s string) []string { + lmoves, rmoves, lcnt, rcnt := 0, 0, 0, 0 + for _, v := range s { + if v == '(' { + lmoves++ + lcnt++ + } else if v == ')' { + if lmoves != 0 { + lmoves-- + } else { + rmoves++ + } + rcnt++ + } + } + n = len(s) + length = n - lmoves - rmoves + res = []string{} + mp = make(map[string]int) + maxScore = min(lcnt, rcnt) + str = s + backtrace(0, "", lmoves, rmoves, 0) + return res +} + +func backtrace(i int, cur string, lmoves int, rmoves int, score int) { + if lmoves < 0 || rmoves < 0 || score < 0 || score > maxScore { + return + } + if lmoves == 0 && rmoves == 0 { + if len(cur) == length { + if _, ok := mp[cur]; !ok { + res = append(res, cur) + mp[cur] = 1 + } + return + } + } + if i == n { + return + } + if str[i] == '(' { + backtrace(i+1, cur+string('('), lmoves, rmoves, score+1) + backtrace(i+1, cur, lmoves-1, rmoves, score) + } else if str[i] == ')' { + backtrace(i+1, cur+string(')'), lmoves, rmoves, score-1) + backtrace(i+1, cur, lmoves, rmoves-1, score) + } else { + backtrace(i+1, cur+string(str[i]), lmoves, rmoves, score) + } +} + +func min(a, b int) int { + if a < b { + return a + } + return b +} + +``` \ No newline at end of file diff --git a/leetcode/0303.Range-Sum-Query---Immutable/303. Range Sum Query - Immutable.go b/leetcode/0303.Range-Sum-Query-Immutable/303. Range Sum Query - Immutable.go similarity index 100% rename from leetcode/0303.Range-Sum-Query---Immutable/303. Range Sum Query - Immutable.go rename to leetcode/0303.Range-Sum-Query-Immutable/303. Range Sum Query - Immutable.go diff --git a/leetcode/0303.Range-Sum-Query---Immutable/303. Range Sum Query - Immutable_test.go b/leetcode/0303.Range-Sum-Query-Immutable/303. Range Sum Query - Immutable_test.go similarity index 100% rename from leetcode/0303.Range-Sum-Query---Immutable/303. Range Sum Query - Immutable_test.go rename to leetcode/0303.Range-Sum-Query-Immutable/303. Range Sum Query - Immutable_test.go diff --git a/leetcode/0303.Range-Sum-Query---Immutable/README.md b/leetcode/0303.Range-Sum-Query-Immutable/README.md similarity index 100% rename from leetcode/0303.Range-Sum-Query---Immutable/README.md rename to leetcode/0303.Range-Sum-Query-Immutable/README.md diff --git a/leetcode/0304.Range-Sum-Query-2D-Immutable/README.md b/leetcode/0304.Range-Sum-Query-2D-Immutable/README.md index 750661b59..3ed2a65d2 100644 --- a/leetcode/0304.Range-Sum-Query-2D-Immutable/README.md +++ b/leetcode/0304.Range-Sum-Query-2D-Immutable/README.md @@ -5,7 +5,7 @@ Given a 2D matrix matrix, find the sum of the elements inside the rectangle defined by its upper left corner (row1, col1) and lower right corner (row2, col2). -![https://leetcode.com/static/images/courses/range_sum_query_2d.png](https://leetcode.com/static/images/courses/range_sum_query_2d.png) +![https://leetcode.com/static/images/courses/range_sum_query_2d.png](https://assets.leetcode.com/uploads/2021/03/14/sum-grid.jpg) The above rectangle (with the red border) is defined by (row1, col1) = **(2, 1)** and (row2, col2) = **(4, 3)**, which contains sum = **8**. diff --git a/leetcode/0306.Additive-Number/306. Additive Number.go b/leetcode/0306.Additive-Number/306. Additive Number.go index 1489b05c8..bd0429a16 100644 --- a/leetcode/0306.Additive-Number/306. Additive Number.go +++ b/leetcode/0306.Additive-Number/306. Additive Number.go @@ -35,7 +35,7 @@ func max(a int, b int) int { return b } -//Propagate for rest of the string +// Propagate for rest of the string func recursiveCheck(num string, x1 int, x2 int, left int) bool { if left == len(num) { return true diff --git a/leetcode/0307.Range-Sum-Query---Mutable/307. Range Sum Query - Mutable.go b/leetcode/0307.Range-Sum-Query-Mutable/307. Range Sum Query - Mutable.go similarity index 100% rename from leetcode/0307.Range-Sum-Query---Mutable/307. Range Sum Query - Mutable.go rename to leetcode/0307.Range-Sum-Query-Mutable/307. Range Sum Query - Mutable.go diff --git a/leetcode/0307.Range-Sum-Query---Mutable/307. Range Sum Query - Mutable_test.go b/leetcode/0307.Range-Sum-Query-Mutable/307. Range Sum Query - Mutable_test.go similarity index 100% rename from leetcode/0307.Range-Sum-Query---Mutable/307. Range Sum Query - Mutable_test.go rename to leetcode/0307.Range-Sum-Query-Mutable/307. Range Sum Query - Mutable_test.go diff --git a/leetcode/0307.Range-Sum-Query---Mutable/README.md b/leetcode/0307.Range-Sum-Query-Mutable/README.md similarity index 100% rename from leetcode/0307.Range-Sum-Query---Mutable/README.md rename to leetcode/0307.Range-Sum-Query-Mutable/README.md diff --git a/leetcode/0319.Bulb-Switcher/319.Bulb Switcher.go b/leetcode/0319.Bulb-Switcher/319.Bulb Switcher.go new file mode 100644 index 000000000..fba8ea41e --- /dev/null +++ b/leetcode/0319.Bulb-Switcher/319.Bulb Switcher.go @@ -0,0 +1,7 @@ +package leetcode + +import "math" + +func bulbSwitch(n int) int { + return int(math.Sqrt(float64(n))) +} diff --git a/leetcode/0319.Bulb-Switcher/319.Bulb Switcher_test.go b/leetcode/0319.Bulb-Switcher/319.Bulb Switcher_test.go new file mode 100644 index 000000000..81f40a62e --- /dev/null +++ b/leetcode/0319.Bulb-Switcher/319.Bulb Switcher_test.go @@ -0,0 +1,50 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question319 struct { + para319 + ans319 +} + +// para 是参数 +type para319 struct { + n int +} + +// ans 是答案 +type ans319 struct { + ans int +} + +func Test_Problem319(t *testing.T) { + + qs := []question319{ + + { + para319{3}, + ans319{1}, + }, + + { + para319{0}, + ans319{0}, + }, + + { + para319{1}, + ans319{1}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 319------------------------\n") + + for _, q := range qs { + _, p := q.ans319, q.para319 + fmt.Printf("【input】:%v 【output】:%v\n", p, bulbSwitch(p.n)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0319.Bulb-Switcher/README.md b/leetcode/0319.Bulb-Switcher/README.md new file mode 100644 index 000000000..830228df8 --- /dev/null +++ b/leetcode/0319.Bulb-Switcher/README.md @@ -0,0 +1,58 @@ +# [319. Bulb Switcher](https://leetcode.com/problems/bulb-switcher/) + + +## 题目 + +There are n bulbs that are initially off. You first turn on all the bulbs, then you turn off every second bulb. + +On the third round, you toggle every third bulb (turning on if it's off or turning off if it's on). For the ith round, you toggle every i bulb. For the nth round, you only toggle the last bulb. + +Return the number of bulbs that are on after n rounds. + +**Example 1:** + + Input: n = 3 + Output: 1 + Explanation: At first, the three bulbs are [off, off, off]. + After the first round, the three bulbs are [on, on, on]. + After the second round, the three bulbs are [on, off, on]. + After the third round, the three bulbs are [on, off, off]. + So you should return 1 because there is only one bulb is on. + +**Example 2:** + + Input: n = 0 + Output: 0 + +**Example 3:** + + Input: n = 1 + Output: 1 + +## 题目大意 + +初始时有 n 个灯泡处于关闭状态。第一轮，你将会打开所有灯泡。接下来的第二轮，你将会每两个灯泡关闭一个。 + +第三轮，你每三个灯泡就切换一个灯泡的开关（即，打开变关闭，关闭变打开）。第 i 轮，你每 i 个灯泡就切换一个灯泡的开关。直到第 n 轮，你只需要切换最后一个灯泡的开关。 + +找出并返回 n 轮后有多少个亮着的灯泡。 + +## 解题思路 + +- 计算 1 到 n 中有奇数个约数的个数 +- 1 到 n 中的某个数 x 有奇数个约数,也即 x 是完全平方数 +- 计算 1 到 n 中完全平方数的个数 sqrt(n) + +## 代码 + +```go + +package leetcode + +import "math" + +func bulbSwitch(n int) int { + return int(math.Sqrt(float64(n))) +} + +``` \ No newline at end of file diff --git a/leetcode/0328.Odd-Even-Linked-List/README.md b/leetcode/0328.Odd-Even-Linked-List/README.md index 760a9e596..4caa26c68 100644 --- a/leetcode/0328.Odd-Even-Linked-List/README.md +++ b/leetcode/0328.Odd-Even-Linked-List/README.md @@ -31,4 +31,4 @@ Note: ## 解题思路 -这道题思路也是一样的，分别把奇数和偶数都放在 2 个链表中，最后首尾拼接就是答案。 \ No newline at end of file +这道题思路也是一样的，分别把奇数节点和偶数节点都放在 2 个链表中，最后首尾拼接就是答案。 diff --git a/leetcode/0345.Reverse-Vowels-of-a-String/345. Reverse Vowels of a String.go b/leetcode/0345.Reverse-Vowels-of-a-String/345. Reverse Vowels of a String.go index 3bd3fbee3..ff1e1be04 100644 --- a/leetcode/0345.Reverse-Vowels-of-a-String/345. Reverse Vowels of a String.go +++ b/leetcode/0345.Reverse-Vowels-of-a-String/345. Reverse Vowels of a String.go @@ -3,25 +3,22 @@ package leetcode func reverseVowels(s string) string { b := []byte(s) for i, j := 0, len(b)-1; i < j; { - if isVowels(b[i]) && isVowels(b[j]) { - b[i], b[j] = b[j], b[i] - i++ - j-- - } else if isVowels(b[i]) && !isVowels(b[j]) { - j-- - } else if !isVowels(b[i]) && isVowels(b[j]) { - i++ - } else { + if !isVowel(b[i]) { i++ + continue + } + if !isVowel(b[j]) { j-- + continue } + b[i], b[j] = b[j], b[i] + i++ + j-- } return string(b) } -func isVowels(s byte) bool { - if s == 'a' || s == 'e' || s == 'i' || s == 'o' || s == 'u' || s == 'A' || s == 'E' || s == 'I' || s == 'O' || s == 'U' { - return true - } - return false +func isVowel(s byte) bool { + return s == 'a' || s == 'e' || s == 'i' || s == 'o' || s == 'u' || s == 'A' || + s == 'E' || s == 'I' || s == 'O' || s == 'U' } diff --git a/leetcode/0352.Data-Stream-as-Disjoint-Intervals/352.Data Stream as Disjoint Intervals.go b/leetcode/0352.Data-Stream-as-Disjoint-Intervals/352.Data Stream as Disjoint Intervals.go new file mode 100644 index 000000000..84d382d12 --- /dev/null +++ b/leetcode/0352.Data-Stream-as-Disjoint-Intervals/352.Data Stream as Disjoint Intervals.go @@ -0,0 +1,49 @@ +package leetcode + +import "sort" + +type SummaryRanges struct { + nums []int + mp map[int]int +} + +func Constructor() SummaryRanges { + return SummaryRanges{ + nums: []int{}, + mp: map[int]int{}, + } +} + +func (this *SummaryRanges) AddNum(val int) { + if _, ok := this.mp[val]; !ok { + this.mp[val] = 1 + this.nums = append(this.nums, val) + } + sort.Ints(this.nums) +} + +func (this *SummaryRanges) GetIntervals() [][]int { + n := len(this.nums) + var ans [][]int + if n == 0 { + return ans + } + if n == 1 { + ans = append(ans, []int{this.nums[0], this.nums[0]}) + return ans + } + start, end := this.nums[0], this.nums[0] + ans = append(ans, []int{start, end}) + index := 0 + for i := 1; i < n; i++ { + if this.nums[i] == end+1 { + end = this.nums[i] + ans[index][1] = end + } else { + start, end = this.nums[i], this.nums[i] + ans = append(ans, []int{start, end}) + index++ + } + } + return ans +} diff --git a/leetcode/0352.Data-Stream-as-Disjoint-Intervals/352.Data Stream as Disjoint Intervals_test.go b/leetcode/0352.Data-Stream-as-Disjoint-Intervals/352.Data Stream as Disjoint Intervals_test.go new file mode 100644 index 000000000..b19897391 --- /dev/null +++ b/leetcode/0352.Data-Stream-as-Disjoint-Intervals/352.Data Stream as Disjoint Intervals_test.go @@ -0,0 +1,63 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question352 struct { + para352 + ans352 +} + +// para 是参数 +type para352 struct { + para string + num int +} + +// ans 是答案 +type ans352 struct { + ans [][]int +} + +func Test_Problem352(t *testing.T) { + + qs := []question352{ + + { + para352{"addNum", 1}, + ans352{[][]int{{1, 1}}}, + }, + + { + para352{"addNum", 3}, + ans352{[][]int{{1, 1}, {3, 3}}}, + }, + + { + para352{"addNum", 7}, + ans352{[][]int{{1, 1}, {3, 3}, {7, 7}}}, + }, + + { + para352{"addNum", 2}, + ans352{[][]int{{1, 3}, {7, 7}}}, + }, + + { + para352{"addNum", 6}, + ans352{[][]int{{1, 3}, {6, 7}}}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 352------------------------\n") + + obj := Constructor() + for _, q := range qs { + _, p := q.ans352, q.para352 + obj.AddNum(p.num) + fmt.Printf("【input】:%v 【output】:%v\n", p, obj.GetIntervals()) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0352.Data-Stream-as-Disjoint-Intervals/README.md b/leetcode/0352.Data-Stream-as-Disjoint-Intervals/README.md new file mode 100644 index 000000000..a3f7abd75 --- /dev/null +++ b/leetcode/0352.Data-Stream-as-Disjoint-Intervals/README.md @@ -0,0 +1,108 @@ +# [352. Data Stream as Disjoint Intervals](https://leetcode.com/problems/data-stream-as-disjoint-intervals/) + + +## 题目 + +Given a data stream input of non-negative integers a1, a2, ..., an, summarize the numbers seen so far as a list of disjoint intervals. + +Implement the SummaryRanges class: + + - SummaryRanges() Initializes the object with an empty stream. + - void addNum(int val) Adds the integer val to the stream. + - int[][] getIntervals() Returns a summary of the integers in the stream currently as a list of disjoint intervals [starti, endi]. + +**Example 1:** + + Input + ["SummaryRanges", "addNum", "getIntervals", "addNum", "getIntervals", "addNum", "getIntervals", "addNum", "getIntervals", "addNum", "getIntervals"] + [[], [1], [], [3], [], [7], [], [2], [], [6], []] + Output + [null, null, [[1, 1]], null, [[1, 1], [3, 3]], null, [[1, 1], [3, 3], [7, 7]], null, [[1, 3], [7, 7]], null, [[1, 3], [6, 7]]] + + Explanation + SummaryRanges summaryRanges = new SummaryRanges(); + summaryRanges.addNum(1); // arr = [1] + summaryRanges.getIntervals(); // return [[1, 1]] + summaryRanges.addNum(3); // arr = [1, 3] + summaryRanges.getIntervals(); // return [[1, 1], [3, 3]] + summaryRanges.addNum(7); // arr = [1, 3, 7] + summaryRanges.getIntervals(); // return [[1, 1], [3, 3], [7, 7]] + summaryRanges.addNum(2); // arr = [1, 2, 3, 7] + summaryRanges.getIntervals(); // return [[1, 3], [7, 7]] + summaryRanges.addNum(6); // arr = [1, 2, 3, 6, 7] + summaryRanges.getIntervals(); // return [[1, 3], [6, 7]] + +**Constraints** + + - 0 <= val <= 10000 + - At most 3 * 10000 calls will be made to addNum and getIntervals. + +## 题目大意 + +给你一个由非负整数a1, a2, ..., an 组成的数据流输入，请你将到目前为止看到的数字总结为不相交的区间列表。 + +实现 SummaryRanges 类： + + - SummaryRanges() 使用一个空数据流初始化对象。 + - void addNum(int val) 向数据流中加入整数 val 。 + - int[][] getIntervals() 以不相交区间[starti, endi] 的列表形式返回对数据流中整数的总结 + +## 解题思路 + +- 使用字典过滤掉重复的数字 +- 把过滤后的数字放到nums中,并进行排序 +- 使用nums构建不重复的区间 + +## 代码 + +```go +package leetcode + +import "sort" + +type SummaryRanges struct { + nums []int + mp map[int]int +} + +func Constructor() SummaryRanges { + return SummaryRanges{ + nums: []int{}, + mp : map[int]int{}, + } +} + +func (this *SummaryRanges) AddNum(val int) { + if _, ok := this.mp[val]; !ok { + this.mp[val] = 1 + this.nums = append(this.nums, val) + } + sort.Ints(this.nums) +} + +func (this *SummaryRanges) GetIntervals() [][]int { + n := len(this.nums) + var ans [][]int + if n == 0 { + return ans + } + if n == 1 { + ans = append(ans, []int{this.nums[0], this.nums[0]}) + return ans + } + start, end := this.nums[0], this.nums[0] + ans = append(ans, []int{start, end}) + index := 0 + for i := 1; i < n; i++ { + if this.nums[i] == end + 1 { + end = this.nums[i] + ans[index][1] = end + } else { + start, end = this.nums[i], this.nums[i] + ans = append(ans, []int{start, end}) + index++ + } + } + return ans +} +``` \ No newline at end of file diff --git a/leetcode/0372.Super-Pow/372. Super Pow.go b/leetcode/0372.Super-Pow/372. Super Pow.go index aacc6c7ae..3f4082c7a 100644 --- a/leetcode/0372.Super-Pow/372. Super Pow.go +++ b/leetcode/0372.Super-Pow/372. Super Pow.go @@ -8,10 +8,11 @@ package leetcode // 模运算性质五：ab % p = ((a % p) * ( b % p)) % p, 其中 ab 是一个数字，如:2874，98374 等等 // 举个例子 // 12345^678 % 1337 = (12345^670 * 12345^8) % 1337 -// = ((12345^670 % 1337) * (12345^8 % 1337)) % 1337 ---> 利用性质 三 +// +// = ((12345^670 % 1337) * (12345^8 % 1337)) % 1337 ---> 利用性质 三 // = (((12345^67)^10 % 1337) * (12345^8 % 1337)) % 1337 ---> 乘方性质 -// = ((12345^67 % 1337)^10) % 1337 * (12345^8 % 1337)) % 1337 ---> 利用性质 四 -// = (((12345^67 % 1337)^10) * (12345^8 % 1337)) % 1337 ---> 反向利用性质 三 +// = ((12345^67 % 1337)^10) % 1337 * (12345^8 % 1337)) % 1337 ---> 利用性质 四 +// = (((12345^67 % 1337)^10) * (12345^8 % 1337)) % 1337 ---> 反向利用性质 三 func superPow(a int, b []int) int { res := 1 for i := 0; i < len(b); i++ { diff --git a/leetcode/0374.Guess-Number-Higher-or-Lower/374. Guess Number Higher or Lower.go b/leetcode/0374.Guess-Number-Higher-or-Lower/374. Guess Number Higher or Lower.go new file mode 100644 index 000000000..fafc4a8c4 --- /dev/null +++ b/leetcode/0374.Guess-Number-Higher-or-Lower/374. Guess Number Higher or Lower.go @@ -0,0 +1,20 @@ +package leetcode + +import "sort" + +/** + * Forward declaration of guess API. + * @param num your guess + * @return -1 if num is lower than the guess number + * 1 if num is higher than the guess number + * otherwise return 0 + * func guess(num int) int; + */ + +func guessNumber(n int) int { + return sort.Search(n, func(x int) bool { return guess(x) <= 0 }) +} + +func guess(num int) int { + return 0 +} diff --git a/leetcode/0374.Guess-Number-Higher-or-Lower/374. Guess Number Higher or Lower_test.go b/leetcode/0374.Guess-Number-Higher-or-Lower/374. Guess Number Higher or Lower_test.go new file mode 100644 index 000000000..9c66680cc --- /dev/null +++ b/leetcode/0374.Guess-Number-Higher-or-Lower/374. Guess Number Higher or Lower_test.go @@ -0,0 +1,58 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question374 struct { + para374 + ans374 +} + +// para 是参数 +// one 代表第一个参数 +type para374 struct { + n int +} + +// ans 是答案 +// one 代表第一个答案 +type ans374 struct { + one int +} + +func Test_Problem374(t *testing.T) { + + qs := []question374{ + + { + para374{10}, + ans374{6}, + }, + + { + para374{1}, + ans374{1}, + }, + + { + para374{2}, + ans374{1}, + }, + + { + para374{2}, + ans374{2}, + }, + // 如需多个测试，可以复制上方元素。 + } + + fmt.Printf("------------------------Leetcode Problem 374------------------------\n") + + for _, q := range qs { + _, p := q.ans374, q.para374 + fmt.Printf("【input】:%v 【output】:%v\n", p, guessNumber(p.n)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0374.Guess-Number-Higher-or-Lower/README.md b/leetcode/0374.Guess-Number-Higher-or-Lower/README.md new file mode 100644 index 000000000..795efe6f3 --- /dev/null +++ b/leetcode/0374.Guess-Number-Higher-or-Lower/README.md @@ -0,0 +1,94 @@ +# [374. Guess Number Higher or Lower](https://leetcode.com/problems/guess-number-higher-or-lower/) + +## 题目 + +We are playing the Guess Game. The game is as follows: + +I pick a number from `1` to `n`. You have to guess which number I picked. + +Every time you guess wrong, I will tell you whether the number I picked is higher or lower than your guess. + +You call a pre-defined API `int guess(int num)`, which returns 3 possible results: + +- `1`: The number I picked is lower than your guess (i.e. `pick < num`). +- `1`: The number I picked is higher than your guess (i.e. `pick > num`). +- `0`: The number I picked is equal to your guess (i.e. `pick == num`). + +Return *the number that I picked*. + +**Example 1:** + +``` +Input: n = 10, pick = 6 +Output: 6 +``` + +**Example 2:** + +``` +Input: n = 1, pick = 1 +Output: 1 +``` + +**Example 3:** + +``` +Input: n = 2, pick = 1 +Output: 1 +``` + +**Example 4:** + +``` +Input: n = 2, pick = 2 +Output: 2 +``` + +**Constraints:** + +- `1 <= n <= 231 - 1` +- `1 <= pick <= n` + +## 题目大意 + +猜数字游戏的规则如下： + +- 每轮游戏，我都会从 1 到 n 随机选择一个数字。 请你猜选出的是哪个数字。 +- 如果你猜错了，我会告诉你，你猜测的数字比我选出的数字是大了还是小了。 + +你可以通过调用一个预先定义好的接口 int guess(int num) 来获取猜测结果，返回值一共有 3 种可能的情况（-1，1 或 0）： + +- 1：我选出的数字比你猜的数字小 pick < num +- 1：我选出的数字比你猜的数字大 pick > num +- 0：我选出的数字和你猜的数字一样。恭喜！你猜对了！pick == num + +返回我选出的数字。 + +## 解题思路 + +- 这一题是简单题，和小时候玩的猜大猜小的游戏一样。思路很简单，二分查找即可。这一题和第 278 题类似。 + +## 代码 + +```go +package leetcode + +import "sort" + +/** + * Forward declaration of guess API. + * @param num your guess + * @return -1 if num is lower than the guess number + * 1 if num is higher than the guess number + * otherwise return 0 + * func guess(num int) int; + */ + +func guessNumber(n int) int { + return sort.Search(n, func(x int) bool { return guess(x) <= 0 }) +} + +func guess(num int) int { + return 0 +} +``` \ No newline at end of file diff --git a/leetcode/0382.Linked-List-Random-Node/382. Linked List Random Node.go b/leetcode/0382.Linked-List-Random-Node/382. Linked List Random Node.go new file mode 100644 index 000000000..892ca7075 --- /dev/null +++ b/leetcode/0382.Linked-List-Random-Node/382. Linked List Random Node.go @@ -0,0 +1,48 @@ +package leetcode + +import ( + "math/rand" + + "github.com/halfrost/LeetCode-Go/structures" +) + +// ListNode define +type ListNode = structures.ListNode + +/** + * Definition for singly-linked list. + * type ListNode struct { + * Val int + * Next *ListNode + * } + */ +type Solution struct { + head *ListNode +} + +/* + - @param head The linked list's head. + Note that the head is guaranteed to be not null, so it contains at least one node. +*/ +func Constructor(head *ListNode) Solution { + return Solution{head: head} +} + +/** Returns a random node's value. */ +func (this *Solution) GetRandom() int { + scope, selectPoint, curr := 1, 0, this.head + for curr != nil { + if rand.Float64() < 1.0/float64(scope) { + selectPoint = curr.Val + } + scope += 1 + curr = curr.Next + } + return selectPoint +} + +/** + * Your Solution object will be instantiated and called as such: + * obj := Constructor(head); + * param_1 := obj.GetRandom(); + */ diff --git a/leetcode/0382.Linked-List-Random-Node/382. Linked List Random Node_test.go b/leetcode/0382.Linked-List-Random-Node/382. Linked List Random Node_test.go new file mode 100644 index 000000000..f33713446 --- /dev/null +++ b/leetcode/0382.Linked-List-Random-Node/382. Linked List Random Node_test.go @@ -0,0 +1,28 @@ +package leetcode + +import ( + "fmt" + "testing" + + "github.com/halfrost/LeetCode-Go/structures" +) + +func Test_Problem382(t *testing.T) { + header := structures.Ints2List([]int{1, 2, 3, 4, 5, 6, 7, 8, 9, 0}) + obj := Constructor(header) + fmt.Printf("obj = %v\n", structures.List2Ints(header)) + param1 := obj.GetRandom() + fmt.Printf("param_1 = %v\n", param1) + param1 = obj.GetRandom() + fmt.Printf("param_1 = %v\n", param1) + param1 = obj.GetRandom() + fmt.Printf("param_1 = %v\n", param1) + param1 = obj.GetRandom() + fmt.Printf("param_1 = %v\n", param1) + param1 = obj.GetRandom() + fmt.Printf("param_1 = %v\n", param1) + param1 = obj.GetRandom() + fmt.Printf("param_1 = %v\n", param1) + + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0382.Linked-List-Random-Node/README.md b/leetcode/0382.Linked-List-Random-Node/README.md new file mode 100644 index 000000000..db5ecc06c --- /dev/null +++ b/leetcode/0382.Linked-List-Random-Node/README.md @@ -0,0 +1,105 @@ +# [382. Linked List Random Node](https://leetcode.com/problems/linked-list-random-node/) + + +## 题目 + +Given a singly linked list, return a random node's value from the linked list. Each node must have the **same probability** of being chosen. + +Implement the `Solution` class: + +- `Solution(ListNode head)` Initializes the object with the integer array nums. +- `int getRandom()` Chooses a node randomly from the list and returns its value. All the nodes of the list should be equally likely to be choosen. + +**Example 1:** + +![https://assets.leetcode.com/uploads/2021/03/16/getrand-linked-list.jpg](https://assets.leetcode.com/uploads/2021/03/16/getrand-linked-list.jpg) + +``` +Input +["Solution", "getRandom", "getRandom", "getRandom", "getRandom", "getRandom"] +[[[1, 2, 3]], [], [], [], [], []] +Output +[null, 1, 3, 2, 2, 3] + +Explanation +Solution solution = new Solution([1, 2, 3]); +solution.getRandom(); // return 1 +solution.getRandom(); // return 3 +solution.getRandom(); // return 2 +solution.getRandom(); // return 2 +solution.getRandom(); // return 3 +// getRandom() should return either 1, 2, or 3 randomly. Each element should have equal probability of returning. + +``` + +**Constraints:** + +- The number of nodes in the linked list will be in the range `[1, 104]`. +- `-10^4 <= Node.val <= 10^4` +- At most `10^4` calls will be made to `getRandom`. + +**Follow up:** + +- What if the linked list is extremely large and its length is unknown to you? +- Could you solve this efficiently without using extra space? + +## 题目大意 + +给定一个单链表，随机选择链表的一个节点，并返回相应的节点值。保证每个节点被选的概率一样。 + +进阶: 如果链表十分大且长度未知，如何解决这个问题？你能否使用常数级空间复杂度实现？ + +## 解题思路 + +- rand.Float64() 可以返回 [0.0,1.0) 之间的随机数。利用这个函数完成我们的随机化取节点的过程。 + +## 代码 + +```go +package leetcode + +import ( + "math/rand" + + "github.com/halfrost/LeetCode-Go/structures" +) + +// ListNode define +type ListNode = structures.ListNode + +/** + * Definition for singly-linked list. + * type ListNode struct { + * Val int + * Next *ListNode + * } + */ +type Solution struct { + head *ListNode +} + +/** @param head The linked list's head. + Note that the head is guaranteed to be not null, so it contains at least one node. */ +func Constructor(head *ListNode) Solution { + return Solution{head: head} +} + +/** Returns a random node's value. */ +func (this *Solution) GetRandom() int { + scope, selectPoint, curr := 1, 0, this.head + for curr != nil { + if rand.Float64() < 1.0/float64(scope) { + selectPoint = curr.Val + } + scope += 1 + curr = curr.Next + } + return selectPoint +} + +/** + * Your Solution object will be instantiated and called as such: + * obj := Constructor(head); + * param_1 := obj.GetRandom(); + */ +``` \ No newline at end of file diff --git a/leetcode/0383.Ransom-Note/383.Ransom Note.go b/leetcode/0383.Ransom-Note/383.Ransom Note.go new file mode 100644 index 000000000..a20162c61 --- /dev/null +++ b/leetcode/0383.Ransom-Note/383.Ransom Note.go @@ -0,0 +1,18 @@ +package leetcode + +func canConstruct(ransomNote string, magazine string) bool { + if len(ransomNote) > len(magazine) { + return false + } + var cnt [26]int + for _, v := range magazine { + cnt[v-'a']++ + } + for _, v := range ransomNote { + cnt[v-'a']-- + if cnt[v-'a'] < 0 { + return false + } + } + return true +} diff --git a/leetcode/0383.Ransom-Note/383.Ransom Note_test.go b/leetcode/0383.Ransom-Note/383.Ransom Note_test.go new file mode 100644 index 000000000..b17147686 --- /dev/null +++ b/leetcode/0383.Ransom-Note/383.Ransom Note_test.go @@ -0,0 +1,51 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question383 struct { + para383 + ans383 +} + +// para 是参数 +type para383 struct { + ransomNote string + magazine string +} + +// ans 是答案 +type ans383 struct { + ans bool +} + +func Test_Problem383(t *testing.T) { + + qs := []question383{ + + { + para383{"a", "b"}, + ans383{false}, + }, + + { + para383{"aa", "ab"}, + ans383{false}, + }, + + { + para383{"aa", "aab"}, + ans383{true}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 383------------------------\n") + + for _, q := range qs { + _, p := q.ans383, q.para383 + fmt.Printf("【input】:%v 【output】:%v\n", p, canConstruct(p.ransomNote, p.magazine)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0383.Ransom-Note/README.md b/leetcode/0383.Ransom-Note/README.md new file mode 100644 index 000000000..9fe9941c5 --- /dev/null +++ b/leetcode/0383.Ransom-Note/README.md @@ -0,0 +1,64 @@ +# [383. Ransom Note](https://leetcode.com/problems/ransom-note/) + +## 题目 + +Given two stings ransomNote and magazine, return true if ransomNote can be constructed from magazine and false otherwise. + +Each letter in magazine can only be used once in ransomNote. + +**Example 1**: + + Input: ransomNote = "a", magazine = "b" + Output: false + +**Example 2**: + + Input: ransomNote = "aa", magazine = "ab" + Output: false + +**Example 3**: + + Input: ransomNote = "aa", magazine = "aab" + Output: true + +**Constraints:** + +- 1 <= ransomNote.length, magazine.length <= 100000 +- ransomNote and magazine consist of lowercase English letters. + +## 题目大意 + +为了不在赎金信中暴露字迹，从杂志上搜索各个需要的字母，组成单词来表达意思。 + +给你一个赎金信 (ransomNote) 字符串和一个杂志(magazine)字符串，判断 ransomNote 能不能由 magazines 里面的字符构成。 + +如果可以构成，返回 true ；否则返回 false 。 + +magazine 中的每个字符只能在 ransomNote 中使用一次。 + +## 解题思路 + +- ransomNote 和 magazine 都是由小写字母组成，所以用数组进行简单的字符统计 + +## 代码 + +````go +package leetcode + +func canConstruct(ransomNote string, magazine string) bool { + if len(ransomNote) > len(magazine) { + return false + } + var cnt [26]int + for _, v := range magazine { + cnt[v-'a']++ + } + for _, v := range ransomNote { + cnt[v-'a']-- + if cnt[v-'a'] < 0 { + return false + } + } + return true +} +```` \ No newline at end of file diff --git a/leetcode/0384.Shuffle-an-Array/384.Shuffle an Array.go b/leetcode/0384.Shuffle-an-Array/384.Shuffle an Array.go new file mode 100644 index 000000000..541908424 --- /dev/null +++ b/leetcode/0384.Shuffle-an-Array/384.Shuffle an Array.go @@ -0,0 +1,28 @@ +package leetcode + +import "math/rand" + +type Solution struct { + nums []int +} + +func Constructor(nums []int) Solution { + return Solution{ + nums: nums, + } +} + +/** Resets the array to its original configuration and return it. */ +func (this *Solution) Reset() []int { + return this.nums +} + +/** Returns a random shuffling of the array. */ +func (this *Solution) Shuffle() []int { + arr := make([]int, len(this.nums)) + copy(arr, this.nums) + rand.Shuffle(len(arr), func(i, j int) { + arr[i], arr[j] = arr[j], arr[i] + }) + return arr +} diff --git a/leetcode/0384.Shuffle-an-Array/384.Shuffle an Array_test.go b/leetcode/0384.Shuffle-an-Array/384.Shuffle an Array_test.go new file mode 100644 index 000000000..9ecebf0f7 --- /dev/null +++ b/leetcode/0384.Shuffle-an-Array/384.Shuffle an Array_test.go @@ -0,0 +1,50 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question384 struct { + para384 + ans384 +} + +// para 是参数 +type para384 struct { + ops []string + value [][]int +} + +// ans 是答案 +type ans384 struct { + ans [][]int +} + +func Test_Problem384(t *testing.T) { + + qs := []question384{ + + { + para384{ops: []string{"Solution", "shuffle", "reset", "shuffle"}, value: [][]int{{1, 2, 3}, {}, {}, {}}}, + ans384{[][]int{nil, {3, 1, 2}, {1, 2, 3}, {1, 3, 2}}}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 384------------------------\n") + + for _, q := range qs { + sol := Constructor(nil) + _, p := q.ans384, q.para384 + for _, op := range p.ops { + if op == "Solution" { + sol = Constructor(q.value[0]) + } else if op == "reset" { + fmt.Printf("【input】:%v 【output】:%v\n", op, sol.Reset()) + } else { + fmt.Printf("【input】:%v 【output】:%v\n", op, sol.Shuffle()) + } + } + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0384.Shuffle-an-Array/README.md b/leetcode/0384.Shuffle-an-Array/README.md new file mode 100644 index 000000000..df22193a8 --- /dev/null +++ b/leetcode/0384.Shuffle-an-Array/README.md @@ -0,0 +1,82 @@ +# [384.Shuffle an Array](https://leetcode.com/problems/shuffle-an-array/) + +## 题目 + +Given an integer array nums, design an algorithm to randomly shuffle the array. All permutations of the array should be equally likely as a result of the shuffling. + +Implement the Solution class: + +- Solution(int[] nums) Initializes the object with the integer array nums. +- int[] reset() Resets the array to its original configuration and returns it. +- int[] shuffle() Returns a random shuffling of the array. + +**Example 1**: + + Input + ["Solution", "shuffle", "reset", "shuffle"] + [[[1, 2, 3]], [], [], []] + Output + [null, [3, 1, 2], [1, 2, 3], [1, 3, 2]] + + Explanation + Solution solution = new Solution([1, 2, 3]); + solution.shuffle(); // Shuffle the array [1,2,3] and return its result. + // Any permutation of [1,2,3] must be equally likely to be returned. + // Example: return [3, 1, 2] + solution.reset(); // Resets the array back to its original configuration [1,2,3]. Return [1, 2, 3] + solution.shuffle(); // Returns the random shuffling of array [1,2,3]. Example: return [1, 3, 2] + +**Constraints:** + +- 1 <= nums.length <= 200 +- -1000000 <= nums[i] <= 1000000 +- All the elements of nums are unique. +- At most 5 * 10000 calls in total will be made to reset and shuffle. + +## 题目大意 + +给你一个整数数组 nums ，设计算法来打乱一个没有重复元素的数组。 + +实现 Solution class: + +- Solution(int[] nums) 使用整数数组 nums 初始化对象 +- int[] reset() 重设数组到它的初始状态并返回 +- int[] shuffle() 返回数组随机打乱后的结果 + +## 解题思路 + +- 使用 rand.Shuffle 进行数组随机打乱 + +## 代码 + +```go + +package leetcode + +import "math/rand" + +type Solution struct { + nums []int +} + +func Constructor(nums []int) Solution { + return Solution{ + nums: nums, + } +} + +/** Resets the array to its original configuration and return it. */ +func (this *Solution) Reset() []int { + return this.nums +} + +/** Returns a random shuffling of the array. */ +func (this *Solution) Shuffle() []int { + arr := make([]int, len(this.nums)) + copy(arr, this.nums) + rand.Shuffle(len(arr), func(i, j int) { + arr[i], arr[j] = arr[j], arr[i] + }) + return arr +} +``` \ No newline at end of file diff --git a/leetcode/0390.Elimination-Game/390. Elimination Game.go b/leetcode/0390.Elimination-Game/390. Elimination Game.go new file mode 100644 index 000000000..d741e387f --- /dev/null +++ b/leetcode/0390.Elimination-Game/390. Elimination Game.go @@ -0,0 +1,18 @@ +package leetcode + +func lastRemaining(n int) int { + start, dir, step := 1, true, 1 + for n > 1 { + if dir { // 正向 + start += step + } else { // 反向 + if n%2 == 1 { + start += step + } + } + dir = !dir + n >>= 1 + step <<= 1 + } + return start +} diff --git a/leetcode/0390.Elimination-Game/390. Elimination Game_test.go b/leetcode/0390.Elimination-Game/390. Elimination Game_test.go new file mode 100644 index 000000000..d7f0c4efd --- /dev/null +++ b/leetcode/0390.Elimination-Game/390. Elimination Game_test.go @@ -0,0 +1,47 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question390 struct { + para390 + ans390 +} + +// para 是参数 +// one 代表第一个参数 +type para390 struct { + n int +} + +// ans 是答案 +// one 代表第一个答案 +type ans390 struct { + one int +} + +func Test_Problem390(t *testing.T) { + + qs := []question390{ + + { + para390{9}, + ans390{6}, + }, + + { + para390{1}, + ans390{1}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 390------------------------\n") + + for _, q := range qs { + _, p := q.ans390, q.para390 + fmt.Printf("【input】:%v 【output】:%v\n", p, lastRemaining(p.n)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0390.Elimination-Game/README.md b/leetcode/0390.Elimination-Game/README.md new file mode 100644 index 000000000..91eea4eea --- /dev/null +++ b/leetcode/0390.Elimination-Game/README.md @@ -0,0 +1,74 @@ +# [390. Elimination Game](https://leetcode.com/problems/elimination-game/) + + +## 题目 + +You have a list `arr` of all integers in the range `[1, n]` sorted in a strictly increasing order. Apply the following algorithm on `arr`: + +- Starting from left to right, remove the first number and every other number afterward until you reach the end of the list. +- Repeat the previous step again, but this time from right to left, remove the rightmost number and every other number from the remaining numbers. +- Keep repeating the steps again, alternating left to right and right to left, until a single number remains. + +Given the integer `n`, return *the last number that remains in* `arr`. + +**Example 1:** + +``` +Input: n = 9 +Output: 6 +Explanation: +arr = [1, 2,3, 4,5, 6,7, 8,9] +arr = [2,4, 6,8] +arr = [2, 6] +arr = [6] + +``` + +**Example 2:** + +``` +Input: n = 1 +Output: 1 + +``` + +**Constraints:** + +- `1 <= n <= 109` + +## 题目大意 + +列表 arr 由在范围 [1, n] 中的所有整数组成，并按严格递增排序。请你对 arr 应用下述算法： + +- 从左到右，删除第一个数字，然后每隔一个数字删除一个，直到到达列表末尾。 +- 重复上面的步骤，但这次是从右到左。也就是，删除最右侧的数字，然后剩下的数字每隔一个删除一个。 +- 不断重复这两步，从左到右和从右到左交替进行，直到只剩下一个数字。 + +给你整数 n ，返回 arr 最后剩下的数字。 + +## 解题思路 + +- 模拟题。按照题意，第一轮从左往右删除数字，第二轮从右往左删除数字。题目要求最后剩下的数字，模拟过程中不需要真的删除元素。只需要标记起始元素，该轮步长和方向即可。最后总元素只剩下一个即为所求。 + +## 代码 + +```go +package leetcode + +func lastRemaining(n int) int { + start, dir, step := 1, true, 1 + for n > 1 { + if dir { // 正向 + start += step + } else { // 反向 + if n%2 == 1 { + start += step + } + } + dir = !dir + n >>= 1 + step <<= 1 + } + return start +} +``` \ No newline at end of file diff --git a/leetcode/0391.Perfect-Rectangle/391.Perfect Rectangle.go b/leetcode/0391.Perfect-Rectangle/391.Perfect Rectangle.go new file mode 100644 index 000000000..0d30790e0 --- /dev/null +++ b/leetcode/0391.Perfect-Rectangle/391.Perfect Rectangle.go @@ -0,0 +1,53 @@ +package leetcode + +type point struct { + x int + y int +} + +func isRectangleCover(rectangles [][]int) bool { + minX, minY, maxA, maxB := rectangles[0][0], rectangles[0][1], rectangles[0][2], rectangles[0][3] + area := 0 + cnt := make(map[point]int) + for _, v := range rectangles { + x, y, a, b := v[0], v[1], v[2], v[3] + area += (a - x) * (b - y) + minX = min(minX, x) + minY = min(minY, y) + maxA = max(maxA, a) + maxB = max(maxB, b) + cnt[point{x, y}]++ + cnt[point{a, b}]++ + cnt[point{x, b}]++ + cnt[point{a, y}]++ + } + if area != (maxA-minX)*(maxB-minY) || + cnt[point{minX, minY}] != 1 || cnt[point{maxA, maxB}] != 1 || + cnt[point{minX, maxB}] != 1 || cnt[point{maxA, minY}] != 1 { + return false + } + delete(cnt, point{minX, minY}) + delete(cnt, point{maxA, maxB}) + delete(cnt, point{minX, maxB}) + delete(cnt, point{maxA, minY}) + for _, v := range cnt { + if v != 2 && v != 4 { + return false + } + } + return true +} + +func min(a, b int) int { + if a < b { + return a + } + return b +} + +func max(a, b int) int { + if a > b { + return a + } + return b +} diff --git a/leetcode/0391.Perfect-Rectangle/391.Perfect Rectangle_test.go b/leetcode/0391.Perfect-Rectangle/391.Perfect Rectangle_test.go new file mode 100644 index 000000000..0efa7efa7 --- /dev/null +++ b/leetcode/0391.Perfect-Rectangle/391.Perfect Rectangle_test.go @@ -0,0 +1,55 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question391 struct { + para391 + ans391 +} + +// para 是参数 +type para391 struct { + rectangles [][]int +} + +// ans 是答案 +type ans391 struct { + ans bool +} + +func Test_Problem391(t *testing.T) { + + qs := []question391{ + + { + para391{[][]int{{1, 1, 3, 3}, {3, 1, 4, 2}, {3, 2, 4, 4}, {1, 3, 2, 4}, {2, 3, 3, 4}}}, + ans391{true}, + }, + + { + para391{[][]int{{1, 1, 2, 3}, {1, 3, 2, 4}, {3, 1, 4, 2}, {3, 2, 4, 4}}}, + ans391{false}, + }, + + { + para391{[][]int{{1, 1, 3, 3}, {3, 1, 4, 2}, {1, 3, 2, 4}, {3, 2, 4, 4}}}, + ans391{false}, + }, + + { + para391{[][]int{{1, 1, 3, 3}, {3, 1, 4, 2}, {1, 3, 2, 4}, {2, 2, 4, 4}}}, + ans391{false}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 391------------------------\n") + + for _, q := range qs { + _, p := q.ans391, q.para391 + fmt.Printf("【input】:%v 【output】:%v\n", p, isRectangleCover(p.rectangles)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0391.Perfect-Rectangle/README.md b/leetcode/0391.Perfect-Rectangle/README.md new file mode 100644 index 000000000..9a66b3b22 --- /dev/null +++ b/leetcode/0391.Perfect-Rectangle/README.md @@ -0,0 +1,114 @@ +# [391. Perfect Rectangle](https://leetcode.com/problems/perfect-rectangle/) + +## 题目 + +Given an array rectangles where rectangles[i] = [xi, yi, ai, bi] represents an axis-aligned rectangle. The bottom-left point of the rectangle is (xi, yi) and the top-right point of it is (ai, bi). + +Return true if all the rectangles together form an exact cover of a rectangular region. + +**Example1:** + +![https://assets.leetcode.com/uploads/2021/03/27/perectrec1-plane.jpg](https://assets.leetcode.com/uploads/2021/03/27/perectrec1-plane.jpg) + + Input: rectangles = [[1,1,3,3],[3,1,4,2],[3,2,4,4],[1,3,2,4],[2,3,3,4]] + Output: true + Explanation: All 5 rectangles together form an exact cover of a rectangular region. + +**Example2:** + +![https://assets.leetcode.com/uploads/2021/03/27/perfectrec2-plane.jpg](https://assets.leetcode.com/uploads/2021/03/27/perfectrec2-plane.jpg) + + Input: rectangles = [[1,1,2,3],[1,3,2,4],[3,1,4,2],[3,2,4,4]] + Output: false + Explanation: Because there is a gap between the two rectangular regions. + +**Example3:** + +![https://assets.leetcode.com/uploads/2021/03/27/perfectrec3-plane.jpg](https://assets.leetcode.com/uploads/2021/03/27/perfectrec3-plane.jpg) + + Input: rectangles = [[1,1,3,3],[3,1,4,2],[1,3,2,4],[3,2,4,4]] + Output: false + Explanation: Because there is a gap in the top center. + +**Example4:** + +![https://assets.leetcode.com/uploads/2021/03/27/perfecrrec4-plane.jpg](https://assets.leetcode.com/uploads/2021/03/27/perfecrrec4-plane.jpg) + + Input: rectangles = [[1,1,3,3],[3,1,4,2],[1,3,2,4],[2,2,4,4]] + Output: false + Explanation: Because two of the rectangles overlap with each other. + +**Constraints:** + +- 1 <= rectangles.length <= 2 * 10000 +- rectangles[i].length == 4 +- -100000 <= xi, yi, ai, bi <= 100000 + +## 题目大意 + +给你一个数组 rectangles ，其中 rectangles[i] = [xi, yi, ai, bi] 表示一个坐标轴平行的矩形。这个矩形的左下顶点是 (xi, yi) ，右上顶点是 (ai, bi) 。 + +如果所有矩形一起精确覆盖了某个矩形区域，则返回 true ；否则，返回 false 。 + +## 解题思路 + +- 矩形区域的面积等于所有矩形的面积之和并且满足矩形区域四角的顶点只能出现一次，且其余顶点的出现次数只能是两次或四次则返回 true,否则返回 false + +## 代码 + +```go + +package leetcode + +type point struct { + x int + y int +} + +func isRectangleCover(rectangles [][]int) bool { + minX, minY, maxA, maxB := rectangles[0][0], rectangles[0][1], rectangles[0][2], rectangles[0][3] + area := 0 + cnt := make(map[point]int) + for _, v := range rectangles { + x, y, a, b := v[0], v[1], v[2], v[3] + area += (a - x) * (b - y) + minX = min(minX, x) + minY = min(minY, y) + maxA = max(maxA, a) + maxB = max(maxB, b) + cnt[point{x, y}]++ + cnt[point{a, b}]++ + cnt[point{x, b}]++ + cnt[point{a, y}]++ + } + if area != (maxA - minX) * (maxB - minY) || + cnt[point{minX, minY}] != 1 || cnt[point{maxA, maxB}] != 1 || + cnt[point{minX, maxB}] != 1 || cnt[point{maxA, minY}] != 1 { + return false + } + delete(cnt, point{minX, minY}) + delete(cnt, point{maxA, maxB}) + delete(cnt, point{minX, maxB}) + delete(cnt, point{maxA, minY}) + for _, v := range cnt { + if v != 2 && v != 4 { + return false + } + } + return true +} + +func min(a, b int) int { + if a < b { + return a + } + return b +} + +func max(a, b int) int { + if a > b { + return a + } + return b +} +``` \ No newline at end of file diff --git a/leetcode/0396.Rotate-Function/396. Rotate Function.go b/leetcode/0396.Rotate-Function/396. Rotate Function.go new file mode 100644 index 000000000..aecc5ae1c --- /dev/null +++ b/leetcode/0396.Rotate-Function/396. Rotate Function.go @@ -0,0 +1,18 @@ +package leetcode + +func maxRotateFunction(nums []int) int { + n := len(nums) + var sum, f int + for i, num := range nums { + sum += num + f += i * num // F(0) + } + ans := f + for i := 1; i < n; i++ { + f += sum - n*nums[n-i] // F(i) = F(i-1) + sum - n*nums[n-i] + if f > ans { + ans = f + } + } + return ans +} diff --git a/leetcode/0396.Rotate-Function/396. Rotate Function_test.go b/leetcode/0396.Rotate-Function/396. Rotate Function_test.go new file mode 100644 index 000000000..855323a15 --- /dev/null +++ b/leetcode/0396.Rotate-Function/396. Rotate Function_test.go @@ -0,0 +1,46 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question396 struct { + para396 + ans396 +} + +// para 是参数 +// one 代表第一个参数 +type para396 struct { + one []int +} + +// ans 是答案 +// one 代表第一个答案 +type ans396 struct { + one int +} + +func Test_Problem396(t *testing.T) { + + qs := []question396{ + { + para396{[]int{4, 3, 2, 6}}, + ans396{26}, + }, + + { + para396{[]int{100}}, + ans396{0}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 396------------------------\n") + + for _, q := range qs { + _, p := q.ans396, q.para396 + fmt.Printf("【input】:%v 【output】:%v\n", p, maxRotateFunction(p.one)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0396.Rotate-Function/README.md b/leetcode/0396.Rotate-Function/README.md new file mode 100644 index 000000000..ed1ab9c5a --- /dev/null +++ b/leetcode/0396.Rotate-Function/README.md @@ -0,0 +1,110 @@ +# [396. Rotate Function](https://leetcode.com/problems/rotate-function/) + +## 题目 + +You are given an integer array `nums` of length `n`. + +Assume `arrk` to be an array obtained by rotating `nums` by `k` positions clock-wise. We define the **rotation function** `F` on `nums` as follow: + +- `F(k) = 0 * arrk[0] + 1 * arrk[1] + ... + (n - 1) * arrk[n - 1]`. + +Return the maximum value of `F(0), F(1), ..., F(n-1)`. + +The test cases are generated so that the answer fits in a **32-bit** integer. + +**Example 1:** + +```c +Input: nums = [4,3,2,6] +Output: 26 +Explanation: +F(0) = (0 * 4) + (1 * 3) + (2 * 2) + (3 * 6) = 0 + 3 + 4 + 18 = 25 +F(1) = (0 * 6) + (1 * 4) + (2 * 3) + (3 * 2) = 0 + 4 + 6 + 6 = 16 +F(2) = (0 * 2) + (1 * 6) + (2 * 4) + (3 * 3) = 0 + 6 + 8 + 9 = 23 +F(3) = (0 * 3) + (1 * 2) + (2 * 6) + (3 * 4) = 0 + 2 + 12 + 12 = 26 +So the maximum value of F(0), F(1), F(2), F(3) is F(3) = 26. +``` + +**Example 2:** + +```c +Input: nums = [100] +Output: 0 +``` + +**Constraints:** + +- `n == nums.length` +- `1 <= n <= 105` +- `-100 <= nums[i] <= 100` + +## 题目大意 + +给定一个长度为`n`的整数数组`nums`，设`arrk`是数组`nums`顺时针旋转`k`个位置后的数组。 + +定义`nums`的旋转函数`F`为： + +- `F(k) = 0 * arrk[0] + 1 * arrk[1] + ... + (n - 1) * arrk[n - 1]` + +返回`F(0), F(1), ..., F(n-1)`中的最大值。 + +## 解题思路 + +**抽象化观察：** + +```c +nums = [A0, A1, A2, A3] + +sum = A0 + A1 + A2+ A3 +F(0) = 0*A0 +0*A0 + 1*A1 + 2*A2 + 3*A3 + +F(1) = 0*A3 + 1*A0 + 2*A1 + 3*A2 + = F(0) + (A0 + A1 + A2) - 3*A3 + = F(0) + (sum-A3) - 3*A3 + = F(0) + sum - 4*A3 + +F(2) = 0*A2 + 1*A3 + 2*A0 + 3*A1 + = F(1) + A3 + A0 + A1 - 3*A2 + = F(1) + sum - 4*A2 + +F(3) = 0*A1 + 1*A2 + 2*A3 + 3*A0 + = F(2) + A2 + A3 + A0 - 3*A1 + = F(2) + sum - 4*A1 + +// 记sum为nums数组中所有元素和 +// 可以猜测当0 ≤ i < n时存在公式: +F(i) = F(i-1) + sum - n * A(n-i) +``` + +**数学归纳法证明迭代公式：** + +根据题目中给定的旋转函数公式可得已知条件： + +- `F(0) = 0×nums[0] + 1×nums[1] + ... + (n−1)×nums[n−1]`； + +- `F(1) = 1×nums[0] + 2×nums[1] + ... + 0×nums[n-1]`。 + +令数组`nums`中所有元素和为`sum`，用数学归纳法验证：当`1 ≤ k < n`时，`F(k) = F(k-1) + sum - n×nums[n-k]`成立。 + +**归纳奠基**：证明`k=1`时命题成立。 + +```c +F(1) = 1×nums[0] + 2×nums[1] + ... + 0×nums[n-1] + = F(0) + sum - n×nums[n-1] +``` + +**归纳假设**：假设`F(k) = F(k-1) + sum - n×nums[n-k]`成立。 + +**归纳递推**：由归纳假设推出`F(k+1) = F(k) + sum - n×nums[n-(k+1)]`成立，则假设的递推公式成立。 + +```c +F(k+1) = (k+1)×nums[0] + k×nums[1] + ... + 0×nums[n-1] + = F(k) + sum - n×nums[n-(k+1)] +``` + +因此可以得到递推公式： + +- 当`n = 0`时，`F(0) = 0×nums[0] + 1×nums[1] + ... + (n−1)×nums[n−1]` +- 当`1 ≤ k < n`时，`F(k) = F(k-1) + sum - n×nums[n-k]`成立。 + +循环遍历`0 ≤ k < n`，计算出不同的`F(k)`并不断更新最大值，就能求出`F(0), F(1), ..., F(n-1)`中的最大值。 diff --git a/leetcode/0400.Nth-Digit/400.Nth Digit.go b/leetcode/0400.Nth-Digit/400.Nth Digit.go new file mode 100644 index 000000000..26d518223 --- /dev/null +++ b/leetcode/0400.Nth-Digit/400.Nth Digit.go @@ -0,0 +1,19 @@ +package leetcode + +import "math" + +func findNthDigit(n int) int { + if n <= 9 { + return n + } + bits := 1 + for n > 9*int(math.Pow10(bits-1))*bits { + n -= 9 * int(math.Pow10(bits-1)) * bits + bits++ + } + idx := n - 1 + start := int(math.Pow10(bits - 1)) + num := start + idx/bits + digitIdx := idx % bits + return num / int(math.Pow10(bits-digitIdx-1)) % 10 +} diff --git a/leetcode/0400.Nth-Digit/400.Nth Digit_test.go b/leetcode/0400.Nth-Digit/400.Nth Digit_test.go new file mode 100644 index 000000000..b7ecfeaf7 --- /dev/null +++ b/leetcode/0400.Nth-Digit/400.Nth Digit_test.go @@ -0,0 +1,45 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question400 struct { + para400 + ans400 +} + +// para 是参数 +type para400 struct { + n int +} + +// ans 是答案 +type ans400 struct { + ans int +} + +func Test_Problem400(t *testing.T) { + + qs := []question400{ + + { + para400{3}, + ans400{3}, + }, + + { + para400{11}, + ans400{0}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 400------------------------\n") + + for _, q := range qs { + _, p := q.ans400, q.para400 + fmt.Printf("【input】:%v 【output】:%v\n", p.n, findNthDigit(p.n)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0400.Nth-Digit/README.md b/leetcode/0400.Nth-Digit/README.md new file mode 100644 index 000000000..fefe14588 --- /dev/null +++ b/leetcode/0400.Nth-Digit/README.md @@ -0,0 +1,67 @@ +# [400. Nth Digit](https://leetcode.com/problems/nth-digit/) + +## 题目 + +Given an integer n, return the nth digit of the infinite integer sequence [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, ...]. + +**Example 1**: + + Input: n = 3 + Output: 3 + +**Example 2**: + + Input: n = 11 + Output: 0 + Explanation: The 11th digit of the sequence 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, ... is a 0, which is part of the number 10. + +**Constraints:** + +- 1 <= n <= int(math.Pow(2, 31)) - 1 + +## 题目大意 + +给你一个整数 n ，请你在无限的整数序列 [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, ...] 中找出并返回第 n 位数字。 + +## 解题思路 + +- bits = 1 的时候有 1,2,3,4,5,6,7,8,9 这 9 个数; 9 = math.Pow10(bits - 1) * bits +- bits = 2 的时候有 10-99 这 90 个数; 90 = math.Pow10(bits - 1) * bits +- n 不断减去 bits 从 1 开始的数字总数,求出 n 所在的数字是几位数即 bits +- 计算 n 所在的数字 num，等于初始值加上 (n - 1) / bits +- 计算 n 所在这个数字的第几位 digitIdx 等于 (n - 1) % bits +- 计算出 digitIdx 位的数字 + + ### 以11 为例: + 11 - 9 = 2 + + (2 - 1) / 2 = 0 + + (2 - 1) % 2 = 1 + + 也就是说第 11 位数字是位数是 2 的第一个数字的第二位，即是 0 + +## 代码 + +```go + +package leetcode + +import "math" + +func findNthDigit(n int) int { + if n <= 9 { + return n + } + bits := 1 + for n > 9*int(math.Pow10(bits-1))*bits { + n -= 9 * int(math.Pow10(bits-1)) * bits + bits++ + } + idx := n - 1 + start := int(math.Pow10(bits - 1)) + num := start + idx/bits + digitIdx := idx % bits + return num / int(math.Pow10(bits-digitIdx-1)) % 10 +} +``` \ No newline at end of file diff --git a/leetcode/0401.Binary-Watch/401. Binary Watch.go b/leetcode/0401.Binary-Watch/401. Binary Watch.go index cd42713a8..39cbf8393 100644 --- a/leetcode/0401.Binary-Watch/401. Binary Watch.go +++ b/leetcode/0401.Binary-Watch/401. Binary Watch.go @@ -5,6 +5,43 @@ import ( "strconv" ) +// 解法一 +func readBinaryWatch(num int) []string { + memo := make([]int, 60) + // count the number of 1 in a binary number + count := func(n int) int { + if memo[n] != 0 { + return memo[n] + } + originN, res := n, 0 + for n != 0 { + n = n & (n - 1) + res++ + } + memo[originN] = res + return res + } + // fmtMinute format minute 0:1 -> 0:01 + fmtMinute := func(m int) string { + if m < 10 { + return "0" + strconv.Itoa(m) + } + return strconv.Itoa(m) + } + + var res []string + // traverse 0:00 -> 12:00 + for i := 0; i < 12; i++ { + for j := 0; j < 60; j++ { + if count(i)+count(j) == num { + res = append(res, strconv.Itoa(i)+":"+fmtMinute(j)) + } + } + } + return res +} + +// 解法二 打表 var ( hour = []string{"1", "2", "4", "8"} minute = []string{"01", "02", "04", "08", "16", "32"} @@ -24,11 +61,11 @@ var ( } ) -func readBinaryWatch(num int) []string { +func readBinaryWatch1(num int) []string { + var res []string if num > 8 { - return []string{} + return res } - res := []string{} for i := 0; i <= num; i++ { for j := 0; j < len(hourMap[i]); j++ { for k := 0; k < len(minuteMap[num-i]); k++ { @@ -39,11 +76,11 @@ func readBinaryWatch(num int) []string { return res } -/// --------------------------------------- -/// --------------------------------------- -/// --------------------------------------- -/// --------------------------------------- -/// --------------------------------------- +// / --------------------------------------- +// / --------------------------------------- +// / --------------------------------------- +// / --------------------------------------- +// / --------------------------------------- // 以下是打表用到的函数 // 调用 findReadBinaryWatchMinute(num, 0, c, &res) 打表 func findReadBinaryWatchMinute(target, index int, c []int, res *[]string) { diff --git a/leetcode/0412.Fizz-Buzz/412. Fizz Buzz.go b/leetcode/0412.Fizz-Buzz/412. Fizz Buzz.go index bfac3f7f4..cd3fbcd2f 100644 --- a/leetcode/0412.Fizz-Buzz/412. Fizz Buzz.go +++ b/leetcode/0412.Fizz-Buzz/412. Fizz Buzz.go @@ -3,18 +3,16 @@ package leetcode import "strconv" func fizzBuzz(n int) []string { - if n < 0 { - return []string{} - } solution := make([]string, n) for i := 1; i <= n; i++ { - if i%3 == 0 && i%5 == 0 { - solution[i-1] = "FizzBuzz" - } else if i%3 == 0 { - solution[i-1] = "Fizz" - } else if i%5 == 0 { - solution[i-1] = "Buzz" - } else { + solution[i-1] = "" + if i%3 == 0 { + solution[i-1] += "Fizz" + } + if i%5 == 0 { + solution[i-1] += "Buzz" + } + if solution[i-1] == "" { solution[i-1] = strconv.Itoa(i) } } diff --git a/leetcode/0419.Battleships-in-a-Board/419. Battleships in a Board.go b/leetcode/0419.Battleships-in-a-Board/419. Battleships in a Board.go new file mode 100644 index 000000000..6e519b858 --- /dev/null +++ b/leetcode/0419.Battleships-in-a-Board/419. Battleships in a Board.go @@ -0,0 +1,21 @@ +package leetcode + +func countBattleships(board [][]byte) (ans int) { + if len(board) == 0 || len(board[0]) == 0 { + return 0 + } + for i := range board { + for j := range board[i] { + if board[i][j] == 'X' { + if i > 0 && board[i-1][j] == 'X' { + continue + } + if j > 0 && board[i][j-1] == 'X' { + continue + } + ans++ + } + } + } + return +} diff --git a/leetcode/0419.Battleships-in-a-Board/419. Battleships in a Board_test.go b/leetcode/0419.Battleships-in-a-Board/419. Battleships in a Board_test.go new file mode 100644 index 000000000..3669aeec3 --- /dev/null +++ b/leetcode/0419.Battleships-in-a-Board/419. Battleships in a Board_test.go @@ -0,0 +1,59 @@ +package leetcode + +import ( + "fmt" + "testing" + "unsafe" +) + +type question419 struct { + para419 + ans419 +} + +// para 是参数 +// one 代表第一个参数 +type para419 struct { + one [][]byte +} + +// ans 是答案 +// one 代表第一个答案 +type ans419 struct { + one int +} + +func Test_Problem419(t *testing.T) { + + qs := []question419{ + + { + para419{[][]byte{{'X', '.', '.', 'X'}, {'.', '.', '.', 'X'}, {'.', '.', '.', 'X'}}}, + ans419{2}, + }, + + { + para419{[][]byte{{'.'}}}, + ans419{0}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 419------------------------\n") + + for _, q := range qs { + _, p := q.ans419, q.para419 + fmt.Printf("【input】:%v 【output】:%v\n", bytesArrayToStringArray(p.one), countBattleships(p.one)) + } + fmt.Printf("\n\n\n") + +} + +// 在运行go test时 为了更直观地显示[][]byte中的字符而非ASCII码数值 +// bytesArrayToStringArray converts [][]byte to []string +func bytesArrayToStringArray(b [][]byte) []string { + s := make([]string, len(b)) + for i := range b { + s[i] = fmt.Sprintf("[%v]", *(*string)(unsafe.Pointer(&b[i]))) + } + return s +} diff --git a/leetcode/0419.Battleships-in-a-Board/README.md b/leetcode/0419.Battleships-in-a-Board/README.md new file mode 100644 index 000000000..8754bfb91 --- /dev/null +++ b/leetcode/0419.Battleships-in-a-Board/README.md @@ -0,0 +1,51 @@ +# [419. Battleships in a Board](https://leetcode.com/problems/battleships-in-a-board/) + +## 题目 + +Given an `m x n` matrix `board` where each cell is a battleship `'X'` or empty `'.'`, return the number of the **battleships** on `board`. + +**Battleships** can only be placed horizontally or vertically on `board`. In other words, they can only be made of the shape `1 x k` (`1` row, `k` columns) or `k x 1` (`k` rows, `1` column), where `k` can be of any size. At least one horizontal or vertical cell separates between two battleships (i.e., there are no adjacent battleships). + +**Example 1:** + +![img](https://assets.leetcode.com/uploads/2021/04/10/battelship-grid.jpg) + +```c +Input: board = [["X",".",".","X"],[".",".",".","X"],[".",".",".","X"]] +Output: 2 +``` + +**Example 2:** + +```c +Input: board = [["."]] +Output: 0 +``` + +**Constraints:** + +- `m == board.length` +- `n == board[i].length` +- `1 <= m, n <= 200` +- `board[i][j] is either '.' or 'X'`. + +**Follow up:** Could you do it in one-pass, using only `O(1)` extra memory and without modifying the values `board`? + +## 题目大意 + +给定一个大小为`m × n`的矩阵 称之为甲板，矩阵单元格中的`'X'`表示战舰，`'.'`表示空位。 + +战舰只能水平或竖直摆放在甲板上（换句话说，可以理解为联通的同一行`'X'`或同一列`'X'`只算作一个“战舰群”），任意俩个“战舰群”间都是不相邻的。返回甲板上“战舰群”的数量。 + +## 解题思路 + +题目进阶要求一次扫描算法，空间复杂度为`O(1)`，且不能修改矩阵中的值。 + +因为题目中给定的两个“战舰群”间至少有一个水平或垂直的空位分隔，所以可以通过枚举每个战舰的左上顶点即可统计“战舰群”的个数。 + +假设当前遍历到矩阵中`'X'`的位置为`(i, j)`，即 `board[i][j]='X'`。如果当前战舰属于一个新的“战舰群”，则需要满足以下条件： + +- 当前位置的上方位为空，即 `board[i-1][j]='.'`； +- 当前位置的左方位为空，即 `board[i][j-1]='.'`； + +统计出所有左方位和上方位为空的战舰个数，即可得到“战舰群”的数量。 \ No newline at end of file diff --git a/leetcode/0429.N-ary-Tree-Level-Order-Traversal/429. N-ary Tree Level Order Traversal.go b/leetcode/0429.N-ary-Tree-Level-Order-Traversal/429. N-ary Tree Level Order Traversal.go new file mode 100644 index 000000000..dfcf57a1e --- /dev/null +++ b/leetcode/0429.N-ary-Tree-Level-Order-Traversal/429. N-ary Tree Level Order Traversal.go @@ -0,0 +1,39 @@ +package leetcode + +/** + * Definition for a Node. + * type Node struct { + * Val int + * Children []*Node + * } + */ + +type Node struct { + Val int + Children []*Node +} + +func levelOrder(root *Node) [][]int { + var res [][]int + var temp []int + if root == nil { + return res + } + queue := []*Node{root, nil} + for len(queue) > 1 { + node := queue[0] + queue = queue[1:] + if node == nil { + queue = append(queue, nil) + res = append(res, temp) + temp = []int{} + } else { + temp = append(temp, node.Val) + if len(node.Children) > 0 { + queue = append(queue, node.Children...) + } + } + } + res = append(res, temp) + return res +} diff --git a/leetcode/0429.N-ary-Tree-Level-Order-Traversal/429. N-ary Tree Level Order Traversal_test.go b/leetcode/0429.N-ary-Tree-Level-Order-Traversal/429. N-ary Tree Level Order Traversal_test.go new file mode 100644 index 000000000..fe56775a4 --- /dev/null +++ b/leetcode/0429.N-ary-Tree-Level-Order-Traversal/429. N-ary Tree Level Order Traversal_test.go @@ -0,0 +1,10 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +func Test_Problem429(t *testing.T) { + fmt.Printf("success\n") +} diff --git a/leetcode/0429.N-ary-Tree-Level-Order-Traversal/README.md b/leetcode/0429.N-ary-Tree-Level-Order-Traversal/README.md new file mode 100644 index 000000000..79d4912d9 --- /dev/null +++ b/leetcode/0429.N-ary-Tree-Level-Order-Traversal/README.md @@ -0,0 +1,85 @@ +# [429. N-ary Tree Level Order Traversal](https://leetcode.com/problems/n-ary-tree-level-order-traversal/) + + +## 题目 + +Given an n-ary tree, return the *level order* traversal of its nodes' values. + +*Nary-Tree input serialization is represented in their level order traversal, each group of children is separated by the null value (See examples).* + +**Example 1:** + +![https://assets.leetcode.com/uploads/2018/10/12/narytreeexample.png](https://assets.leetcode.com/uploads/2018/10/12/narytreeexample.png) + +``` +Input: root = [1,null,3,2,4,null,5,6] +Output: [[1],[3,2,4],[5,6]] + +``` + +**Example 2:** + +![https://assets.leetcode.com/uploads/2019/11/08/sample_4_964.png](https://assets.leetcode.com/uploads/2019/11/08/sample_4_964.png) + +``` +Input: root = [1,null,2,3,4,5,null,null,6,7,null,8,null,9,10,null,null,11,null,12,null,13,null,null,14] +Output: [[1],[2,3,4,5],[6,7,8,9,10],[11,12,13],[14]] + +``` + +**Constraints:** + +- The height of the n-ary tree is less than or equal to `1000` +- The total number of nodes is between `[0, 104]` + +## 题目大意 + +给定一个 N 叉树，返回其节点值的层序遍历。（即从左到右，逐层遍历）。树的序列化输入是用层序遍历，每组子节点都由 null 值分隔（参见示例）。 + +## 解题思路 + +- 这是 n 叉树的系列题，第 589 题也是这一系列的题目。这一题思路不难，既然是层序遍历，用 BFS 解答。 + +## 代码 + +```go +package leetcode + +/** + * Definition for a Node. + * type Node struct { + * Val int + * Children []*Node + * } + */ + +type Node struct { + Val int + Children []*Node +} + +func levelOrder(root *Node) [][]int { + var res [][]int + var temp []int + if root == nil { + return res + } + queue := []*Node{root, nil} + for len(queue) > 1 { + node := queue[0] + queue = queue[1:] + if node == nil { + queue = append(queue, nil) + res = append(res, temp) + temp = []int{} + } else { + temp = append(temp, node.Val) + if len(node.Children) > 0 { + queue = append(queue, node.Children...) + } + } + } + res = append(res, temp) + return res +} +``` \ No newline at end of file diff --git a/leetcode/0434.Number-of-Segments-in-a-String/434.Number of Segments in a String.go b/leetcode/0434.Number-of-Segments-in-a-String/434.Number of Segments in a String.go new file mode 100644 index 000000000..626caebe8 --- /dev/null +++ b/leetcode/0434.Number-of-Segments-in-a-String/434.Number of Segments in a String.go @@ -0,0 +1,18 @@ +package leetcode + +func countSegments(s string) int { + segments := false + cnt := 0 + for _, v := range s { + if v == ' ' && segments { + segments = false + cnt += 1 + } else if v != ' ' { + segments = true + } + } + if segments { + cnt++ + } + return cnt +} diff --git a/leetcode/0434.Number-of-Segments-in-a-String/434.Number of Segments in a String_test.go b/leetcode/0434.Number-of-Segments-in-a-String/434.Number of Segments in a String_test.go new file mode 100644 index 000000000..7c634601e --- /dev/null +++ b/leetcode/0434.Number-of-Segments-in-a-String/434.Number of Segments in a String_test.go @@ -0,0 +1,55 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question434 struct { + para434 + ans434 +} + +// s 是参数 +type para434 struct { + s string +} + +// ans 是答案 +type ans434 struct { + ans int +} + +func Test_Problem434(t *testing.T) { + + qs := []question434{ + + { + para434{"Hello, my name is John"}, + ans434{5}, + }, + + { + para434{"Hello"}, + ans434{1}, + }, + + { + para434{"love live! mu'sic forever"}, + ans434{4}, + }, + + { + para434{""}, + ans434{0}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 434------------------------\n") + + for _, q := range qs { + _, p := q.ans434, q.para434 + fmt.Printf("【input】:%v 【output】:%v\n", p, countSegments(p.s)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0434.Number-of-Segments-in-a-String/README.md b/leetcode/0434.Number-of-Segments-in-a-String/README.md new file mode 100644 index 000000000..48fd4b8da --- /dev/null +++ b/leetcode/0434.Number-of-Segments-in-a-String/README.md @@ -0,0 +1,70 @@ +# [434. Number of Segments in a String](https://leetcode.com/problems/number-of-segments-in-a-string/) + + +## 题目 + +You are given a string s, return the number of segments in the string. + +A segment is defined to be a contiguous sequence of non-space characters. + +**Example 1:** + + Input: s = "Hello, my name is John" + Output: 5 + Explanation: The five segments are ["Hello,", "my", "name", "is", "John"] + +**Example 2:** + + Input: s = "Hello" + Output: 1 + +**Example 3:** + + Input: s = "love live! mu'sic forever" + Output: 4 + +**Example 4:** + + Input: s = "" + Output: 0 + +**Constraints** + + - 0 <= s.length <= 300 + - s consists of lower-case and upper-case English letters, digits or one of the following characters "!@#$%^&*()_+-=',.:". + - The only space character in s is ' '. + +## 题目大意 + +统计字符串中的单词个数，这里的单词指的是连续的不是空格的字符。 + +请注意，你可以假定字符串里不包括任何不可打印的字符。 + +## 解题思路 + +- 以空格为分割计算元素个数 + +## 代码 + +```go + +package leetcode + +func countSegments(s string) int { + segments := false + cnt := 0 + for _, v := range s { + if v == ' ' && segments { + segments = false + cnt += 1 + } else if v != ' ' { + segments = true + } + } + if segments { + cnt++ + } + return cnt +} + +``` \ No newline at end of file diff --git a/leetcode/0437.Path-Sum-III/437. Path Sum III.go b/leetcode/0437.Path-Sum-III/437. Path Sum III.go index 96e208ec6..cdbe52bf6 100644 --- a/leetcode/0437.Path-Sum-III/437. Path Sum III.go +++ b/leetcode/0437.Path-Sum-III/437. Path Sum III.go @@ -16,6 +16,30 @@ type TreeNode = structures.TreeNode * } */ +// 解法一 带缓存 dfs +func pathSum(root *TreeNode, targetSum int) int { + prefixSum := make(map[int]int) + prefixSum[0] = 1 + return dfs(root, prefixSum, 0, targetSum) +} + +func dfs(root *TreeNode, prefixSum map[int]int, cur, sum int) int { + if root == nil { + return 0 + } + cur += root.Val + cnt := 0 + if v, ok := prefixSum[cur-sum]; ok { + cnt = v + } + prefixSum[cur]++ + cnt += dfs(root.Left, prefixSum, cur, sum) + cnt += dfs(root.Right, prefixSum, cur, sum) + prefixSum[cur]-- + return cnt +} + +// 解法二 func pathSumIII(root *TreeNode, sum int) int { if root == nil { return 0 diff --git a/leetcode/0437.Path-Sum-III/437. Path Sum III_test.go b/leetcode/0437.Path-Sum-III/437. Path Sum III_test.go index 4f122a2da..089bef78a 100644 --- a/leetcode/0437.Path-Sum-III/437. Path Sum III_test.go +++ b/leetcode/0437.Path-Sum-III/437. Path Sum III_test.go @@ -45,7 +45,7 @@ func Test_Problem437(t *testing.T) { _, p := q.ans437, q.para437 fmt.Printf("【input】:%v ", p) root := structures.Ints2TreeNode(p.one) - fmt.Printf("【output】:%v \n", pathSumIII(root, p.sum)) + fmt.Printf("【output】:%v \n", pathSum(root, p.sum)) } fmt.Printf("\n\n\n") } diff --git a/leetcode/0437.Path-Sum-III/README.md b/leetcode/0437.Path-Sum-III/README.md old mode 100755 new mode 100644 index cad475bdd..755a4e263 --- a/leetcode/0437.Path-Sum-III/README.md +++ b/leetcode/0437.Path-Sum-III/README.md @@ -3,32 +3,34 @@ ## 题目 -You are given a binary tree in which each node contains an integer value. +Given the `root` of a binary tree and an integer `targetSum`, return *the number of paths where the sum of the values along the path equals* `targetSum`. -Find the number of paths that sum to a given value. +The path does not need to start or end at the root or a leaf, but it must go downwards (i.e., traveling only from parent nodes to child nodes). -The path does not need to start or end at the root or a leaf, but it must go downwards (traveling only from parent nodes to child nodes). +**Example 1:** -The tree has no more than 1,000 nodes and the values are in the range -1,000,000 to 1,000,000. +![https://assets.leetcode.com/uploads/2021/04/09/pathsum3-1-tree.jpg](https://assets.leetcode.com/uploads/2021/04/09/pathsum3-1-tree.jpg) -**Example:** +``` +Input: root = [10,5,-3,3,2,null,11,3,-2,null,1], targetSum = 8 +Output: 3 +Explanation: The paths that sum to 8 are shown. - root = [10,5,-3,3,2,null,11,3,-2,null,1], sum = 8 - - 10 - / \ - 5 -3 - / \ \ - 3 2 11 - / \ \ - 3 -2 1 - - Return 3. The paths that sum to 8 are: - - 1. 5 -> 3 - 2. 5 -> 2 -> 1 - 3. -3 -> 11 +``` +**Example 2:** + +``` +Input: root = [5,4,8,11,null,13,4,7,2,null,null,5,1], targetSum = 22 +Output: 3 + +``` + +**Constraints:** + +- The number of nodes in the tree is in the range `[0, 1000]`. +- `109 <= Node.val <= 109` +- `1000 <= targetSum <= 1000` ## 题目大意 @@ -42,3 +44,76 @@ The tree has no more than 1,000 nodes and the values are in the range -1,000,000 - 注意这一题可能出现负数的情况，节点和为 sum，并不一定是最终情况，有可能下面还有正数节点和负数节点相加正好为 0，那么这也是一种情况。一定要遍历到底。 - 一个点是否为 sum 的起点，有 3 种情况，第一种情况路径包含该 root 节点，如果包含该结点，就在它的左子树和右子树中寻找和为 `sum-root.Val` 的情况。第二种情况路径不包含该 root 节点，那么就需要在它的左子树和右子树中分别寻找和为 sum 的结点。 + + +## 代码 + +```go + +package leetcode + +import ( + "github.com/halfrost/LeetCode-Go/structures" +) + +// TreeNode define +type TreeNode = structures.TreeNode + +/** + * Definition for a binary tree node. + * type TreeNode struct { + * Val int + * Left *TreeNode + * Right *TreeNode + * } + */ + +// 解法一 带缓存 dfs +func pathSum(root *TreeNode, targetSum int) int { + prefixSum := make(map[int]int) + prefixSum[0] = 1 + return dfs(root, prefixSum, 0, targetSum) +} + +func dfs(root *TreeNode, prefixSum map[int]int, cur, sum int) int { + if root == nil { + return 0 + } + cur += root.Val + cnt := 0 + if v, ok := prefixSum[cur-sum]; ok { + cnt = v + } + prefixSum[cur]++ + cnt += dfs(root.Left, prefixSum, cur, sum) + cnt += dfs(root.Right, prefixSum, cur, sum) + prefixSum[cur]-- + return cnt +} + +// 解法二 +func pathSumIII(root *TreeNode, sum int) int { + if root == nil { + return 0 + } + res := findPath437(root, sum) + res += pathSumIII(root.Left, sum) + res += pathSumIII(root.Right, sum) + return res +} + +// 寻找包含 root 这个结点，且和为 sum 的路径 +func findPath437(root *TreeNode, sum int) int { + if root == nil { + return 0 + } + res := 0 + if root.Val == sum { + res++ + } + res += findPath437(root.Left, sum-root.Val) + res += findPath437(root.Right, sum-root.Val) + return res +} + +``` \ No newline at end of file diff --git a/leetcode/0445.Add-Two-Numbers-II/445. Add Two Numbers II.go b/leetcode/0445.Add-Two-Numbers-II/445. Add Two Numbers II.go index 3211805ad..e4ddee058 100644 --- a/leetcode/0445.Add-Two-Numbers-II/445. Add Two Numbers II.go +++ b/leetcode/0445.Add-Two-Numbers-II/445. Add Two Numbers II.go @@ -67,3 +67,72 @@ func getLength(l *ListNode) int { } return count } + +func addTwoNumbers1(l1 *ListNode, l2 *ListNode) *ListNode { + reservedL1 := reverseList(l1) + reservedL2 := reverseList(l2) + + dummyHead := &ListNode{} + head := dummyHead + carry := 0 + for reservedL1 != nil || reservedL2 != nil || carry > 0 { + val := carry + if reservedL1 != nil { + val = reservedL1.Val + val + reservedL1 = reservedL1.Next + } + if reservedL2 != nil { + val = reservedL2.Val + val + reservedL2 = reservedL2.Next + } + carry = val / 10 + head.Next = &ListNode{Val: val % 10} + head = head.Next + } + return reverseList(dummyHead.Next) +} + +func reverseList(head *ListNode) *ListNode { + var prev *ListNode + for head != nil { + tmp := head.Next + head.Next = prev + + prev = head + head = tmp + } + return prev +} + +func addTwoNumbers(l1 *ListNode, l2 *ListNode) *ListNode { + stack1 := pushStack(l1) + stack2 := pushStack(l2) + + dummyHead := &ListNode{} + head := dummyHead + carry := 0 + for len(stack1) > 0 || len(stack2) > 0 || carry > 0 { + val := carry + if len(stack1) > 0 { + val = val + stack1[len(stack1)-1] + stack1 = stack1[:len(stack1)-1] + } + if len(stack2) > 0 { + val = val + stack2[len(stack2)-1] + stack2 = stack2[:len(stack2)-1] + } + carry = val / 10 + tmp := head.Next + head.Next = &ListNode{Val: val % 10, Next: tmp} + } + return dummyHead.Next +} + +func pushStack(l *ListNode) []int { + var stack []int + for l != nil { + stack = append(stack, l.Val) + l = l.Next + } + return stack +} diff --git a/leetcode/0458.Poor-Pigs/458.Poor Pigs.go b/leetcode/0458.Poor-Pigs/458.Poor Pigs.go new file mode 100644 index 000000000..81162d51e --- /dev/null +++ b/leetcode/0458.Poor-Pigs/458.Poor Pigs.go @@ -0,0 +1,8 @@ +package leetcode + +import "math" + +func poorPigs(buckets int, minutesToDie int, minutesToTest int) int { + base := minutesToTest/minutesToDie + 1 + return int(math.Ceil(math.Log10(float64(buckets)) / math.Log10(float64(base)))) +} diff --git a/leetcode/0458.Poor-Pigs/458.Poor Pigs_test.go b/leetcode/0458.Poor-Pigs/458.Poor Pigs_test.go new file mode 100644 index 000000000..50bb561ea --- /dev/null +++ b/leetcode/0458.Poor-Pigs/458.Poor Pigs_test.go @@ -0,0 +1,52 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question458 struct { + para458 + ans458 +} + +// para 是参数 +type para458 struct { + buckets int + minutesToDie int + minutesToTest int +} + +// ans 是答案 +type ans458 struct { + ans int +} + +func Test_Problem458(t *testing.T) { + + qs := []question458{ + + { + para458{1000, 15, 60}, + ans458{5}, + }, + + { + para458{4, 15, 15}, + ans458{2}, + }, + + { + para458{4, 15, 30}, + ans458{2}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 458------------------------\n") + + for _, q := range qs { + _, p := q.ans458, q.para458 + fmt.Printf("【input】:%v 【output】:%v\n", p, poorPigs(p.buckets, p.minutesToDie, p.minutesToTest)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0458.Poor-Pigs/README.md b/leetcode/0458.Poor-Pigs/README.md new file mode 100644 index 000000000..e8dba552d --- /dev/null +++ b/leetcode/0458.Poor-Pigs/README.md @@ -0,0 +1,77 @@ +# [458. Poor Pigs](https://leetcode.com/problems/poor-pigs/) + +## 题目 + +There are buckets buckets of liquid, where exactly one of the buckets is poisonous. To figure out which one is poisonous, you feed some number of (poor) pigs the liquid to see whether they will die or not. Unfortunately, you only have minutesToTest minutes to determine which bucket is poisonous. + +You can feed the pigs according to these steps: + +- Choose some live pigs to feed. +- For each pig, choose which buckets to feed it. The pig will consume all the chosen buckets simultaneously and will take no time. +- Wait for minutesToDie minutes. You may not feed any other pigs during this time. +- After minutesToDie minutes have passed, any pigs that have been fed the poisonous bucket will die, and all others will survive. +- Repeat this process until you run out of time. + +Given buckets, minutesToDie, and minutesToTest, return the minimum number of pigs needed to figure out which bucket is poisonous within the allotted time. + +**Example 1**: + + Input: buckets = 1000, minutesToDie = 15, minutesToTest = 60 + Output: 5 + +**Example 2**: + + Input: buckets = 4, minutesToDie = 15, minutesToTest = 15 + Output: 2 + +**Example 3**: + + Input: buckets = 4, minutesToDie = 15, minutesToTest = 30 + Output: 2 + +**Constraints:** + +- 1 <= buckets <= 1000 +- 1 <= minutesToDie <= minutesToTest <= 100 + +## 题目大意 + +有 buckets 桶液体，其中 正好 有一桶含有毒药，其余装的都是水。它们从外观看起来都一样。为了弄清楚哪只水桶含有毒药，你可以喂一些猪喝，通过观察猪是否会死进行判断。不幸的是，你只有 minutesToTest 分钟时间来确定哪桶液体是有毒的。 + +喂猪的规则如下： + +- 选择若干活猪进行喂养 +- 可以允许小猪同时饮用任意数量的桶中的水，并且该过程不需要时间。 +- 小猪喝完水后，必须有 minutesToDie 分钟的冷却时间。在这段时间里，你只能观察，而不允许继续喂猪。 +- 过了 minutesToDie 分钟后，所有喝到毒药的猪都会死去，其他所有猪都会活下来。 +- 重复这一过程，直到时间用完。 + +给你桶的数目 buckets ，minutesToDie 和 minutesToTest ，返回在规定时间内判断哪个桶有毒所需的 最小 猪数。 + +## 解题思路 + +使用数学方法,以 minutesToDie=15, minutesToTest=60, 1 只小猪为例,可以测试 5 只桶 + +- 0-15 小猪吃第一个桶中的液体,如果死去，则第一个桶有毒,否则继续测试 +- 15-30 小猪吃第二个桶中的液体，如果死去，则第二个桶有毒,否则继续测试 +- 30-45 小猪吃第三个桶中的液体，如果死去，则第三个桶有毒,否则继续测试 +- 45-60 小猪吃第四个桶中的液体，如果死去，则第四个桶有毒 +- 如果最后小猪没有死去，则第五个桶有毒 + +所以一只小猪在 minutesToDie 和 minutesToTest 时间一定的情况下可以最多判断 base = minutesToTest / minutesToDie + 1 个桶 + +假设小猪的数量是 num,那么 pow(base, num) >= buckets,根据对数运算规则，两边分别取对数得到: num >= Log10(buckets) / Log10(base) + +## 代码 + +```go + +package leetcode + +import "math" + +func poorPigs(buckets int, minutesToDie int, minutesToTest int) int { + base := minutesToTest/minutesToDie + 1 + return int(math.Ceil(math.Log10(float64(buckets)) / math.Log10(float64(base)))) +} +``` \ No newline at end of file diff --git a/leetcode/0462.Minimum-Moves-to-Equal-Array-Elements-II/462. Minimum Moves to Equal Array Elements II.go b/leetcode/0462.Minimum-Moves-to-Equal-Array-Elements-II/462. Minimum Moves to Equal Array Elements II.go new file mode 100644 index 000000000..cd38e4787 --- /dev/null +++ b/leetcode/0462.Minimum-Moves-to-Equal-Array-Elements-II/462. Minimum Moves to Equal Array Elements II.go @@ -0,0 +1,21 @@ +package leetcode + +import ( + "math" + "sort" +) + +func minMoves2(nums []int) int { + if len(nums) == 0 { + return 0 + } + moves, mid := 0, len(nums)/2 + sort.Ints(nums) + for i := range nums { + if i == mid { + continue + } + moves += int(math.Abs(float64(nums[mid] - nums[i]))) + } + return moves +} diff --git a/leetcode/0462.Minimum-Moves-to-Equal-Array-Elements-II/462. Minimum Moves to Equal Array Elements II_test.go b/leetcode/0462.Minimum-Moves-to-Equal-Array-Elements-II/462. Minimum Moves to Equal Array Elements II_test.go new file mode 100644 index 000000000..bdbae051f --- /dev/null +++ b/leetcode/0462.Minimum-Moves-to-Equal-Array-Elements-II/462. Minimum Moves to Equal Array Elements II_test.go @@ -0,0 +1,57 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question462 struct { + para462 + ans462 +} + +// para 是参数 +// one 代表第一个参数 +type para462 struct { + nums []int +} + +// ans 是答案 +// one 代表第一个答案 +type ans462 struct { + one int +} + +func Test_Problem462(t *testing.T) { + + qs := []question462{ + + { + para462{[]int{}}, + ans462{0}, + }, + + { + para462{[]int{1, 2, 3}}, + ans462{2}, + }, + + { + para462{[]int{1, 10, 2, 9}}, + ans462{16}, + }, + + { + para462{[]int{1, 0, 0, 8, 6}}, + ans462{14}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 462------------------------\n") + + for _, q := range qs { + _, p := q.ans462, q.para462 + fmt.Printf("【input】:%v 【output】:%v\n", p, minMoves2(p.nums)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0462.Minimum-Moves-to-Equal-Array-Elements-II/README.md b/leetcode/0462.Minimum-Moves-to-Equal-Array-Elements-II/README.md new file mode 100644 index 000000000..c030b1de0 --- /dev/null +++ b/leetcode/0462.Minimum-Moves-to-Equal-Array-Elements-II/README.md @@ -0,0 +1,66 @@ +# [462. Minimum Moves to Equal Array Elements II](https://leetcode.com/problems/minimum-moves-to-equal-array-elements-ii/) + + +## 题目 + +Given an integer array `nums` of size `n`, return *the minimum number of moves required to make all array elements equal*. + +In one move, you can increment or decrement an element of the array by `1`. + +**Example 1:** + +``` +Input: nums = [1,2,3] +Output: 2 +Explanation: +Only two moves are needed (remember each move increments or decrements one element): +[1,2,3] => [2,2,3] => [2,2,2] +``` + +**Example 2:** + +``` +Input: nums = [1,10,2,9] +Output: 16 +``` + +**Constraints:** + +- `n == nums.length` +- `1 <= nums.length <= 10^5` +- `109 <= nums[i] <= 10^9` + +## 题目大意 + +给定一个非空整数数组，找到使所有数组元素相等所需的最小移动数，其中每次移动可将选定的一个元素加 1 或减 1。 您可以假设数组的长度最多为10000。 + +## 解题思路 + +- 这题抽象成数学问题是，如果我们把数组 a 中的每个数看成水平轴上的一个点，那么根据上面的移动次数公式，我们需要找到在水平轴上找到一个点 x，使得这 N 个点到 x 的距离之和最小。有 2 个点值得我们考虑，一个是中位数，另外一个是平均值。举个简单的例子，[1,0,0,8,6] 这组数据，中位数是 1，平均值是 3 。分别计算移动的步数，按照中位数对齐是 14，按照平均值对齐是 16 。所以选择中位数。 +- 此题可以用数学证明，证明出，按照平均值移动的步数 ≥ 按照中位数移动的步数。具体证明笔者这里不证明了，感兴趣的同学可以自己证明试试。 + +## 代码 + +```go +package leetcode + +import ( + "math" + "sort" +) + +func minMoves2(nums []int) int { + if len(nums) == 0 { + return 0 + } + moves, mid := 0, len(nums)/2 + sort.Ints(nums) + for i := range nums { + if i == mid { + continue + } + moves += int(math.Abs(float64(nums[mid] - nums[i]))) + } + return moves +} +``` \ No newline at end of file diff --git a/leetcode/0473.Matchsticks-to-Square/473. Matchsticks to Square.go b/leetcode/0473.Matchsticks-to-Square/473. Matchsticks to Square.go new file mode 100644 index 000000000..8930f35a4 --- /dev/null +++ b/leetcode/0473.Matchsticks-to-Square/473. Matchsticks to Square.go @@ -0,0 +1,49 @@ +package leetcode + +import "sort" + +func makesquare(matchsticks []int) bool { + if len(matchsticks) < 4 { + return false + } + total := 0 + for _, v := range matchsticks { + total += v + } + if total%4 != 0 { + return false + } + sort.Slice(matchsticks, func(i, j int) bool { + return matchsticks[i] > matchsticks[j] + }) + visited := make([]bool, 16) + return dfs(matchsticks, 0, 0, 0, total, &visited) +} + +func dfs(matchsticks []int, cur, group, sum, total int, visited *[]bool) bool { + if group == 4 { + return true + } + if sum > total/4 { + return false + } + if sum == total/4 { + return dfs(matchsticks, 0, group+1, 0, total, visited) + } + last := -1 + for i := cur; i < len(matchsticks); i++ { + if (*visited)[i] { + continue + } + if last == matchsticks[i] { + continue + } + (*visited)[i] = true + last = matchsticks[i] + if dfs(matchsticks, i+1, group, sum+matchsticks[i], total, visited) { + return true + } + (*visited)[i] = false + } + return false +} diff --git a/leetcode/0473.Matchsticks-to-Square/473. Matchsticks to Square_test.go b/leetcode/0473.Matchsticks-to-Square/473. Matchsticks to Square_test.go new file mode 100644 index 000000000..7636f00fb --- /dev/null +++ b/leetcode/0473.Matchsticks-to-Square/473. Matchsticks to Square_test.go @@ -0,0 +1,47 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question473 struct { + para473 + ans473 +} + +// para 是参数 +// one 代表第一个参数 +type para473 struct { + arr []int +} + +// ans 是答案 +// one 代表第一个答案 +type ans473 struct { + one bool +} + +func Test_Problem473(t *testing.T) { + + qs := []question473{ + + { + para473{[]int{1, 1, 2, 2, 2}}, + ans473{true}, + }, + + { + para473{[]int{3, 3, 3, 3, 4}}, + ans473{false}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 473------------------------\n") + + for _, q := range qs { + _, p := q.ans473, q.para473 + fmt.Printf("【input】:%v 【output】:%v\n", p, makesquare(p.arr)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0473.Matchsticks-to-Square/README.md b/leetcode/0473.Matchsticks-to-Square/README.md new file mode 100644 index 000000000..d58d6b1c4 --- /dev/null +++ b/leetcode/0473.Matchsticks-to-Square/README.md @@ -0,0 +1,94 @@ +# [473. Matchsticks to Square](https://leetcode.com/problems/matchsticks-to-square/) + + +## 题目 + +You are given an integer array `matchsticks` where `matchsticks[i]` is the length of the `ith` matchstick. You want to use **all the matchsticks** to make one square. You **should not break** any stick, but you can link them up, and each matchstick must be used **exactly one time**. + +Return `true` if you can make this square and `false` otherwise. + +**Example 1:** + +![https://assets.leetcode.com/uploads/2021/04/09/matchsticks1-grid.jpg](https://assets.leetcode.com/uploads/2021/04/09/matchsticks1-grid.jpg) + +``` +Input: matchsticks = [1,1,2,2,2] +Output: true +Explanation: You can form a square with length 2, one side of the square came two sticks with length 1. +``` + +**Example 2:** + +``` +Input: matchsticks = [3,3,3,3,4] +Output: false +Explanation: You cannot find a way to form a square with all the matchsticks. +``` + +**Constraints:** + +- `1 <= matchsticks.length <= 15` +- `0 <= matchsticks[i] <= 109` + +## 题目大意 + +现在已知小女孩有多少根火柴，请找出一种能使用所有火柴拼成一个正方形的方法。不能折断火柴，可以把火柴连接起来，并且每根火柴都要用到。输入为小女孩拥有火柴的数目，每根火柴用其长度表示。输出即为是否能用所有的火柴拼成正方形。 + +## 解题思路 + +- 将火柴拼成一个正方形，可以将它们分成四组，每一根火柴恰好属于其中的一组；并且每一组火柴的长度之和都相同，等于所有火柴长度之和的四分之一。 +- 考虑暴力解法，使用深度优先搜索枚举出所有的分组情况，并对于每一种情况，判断是否满足上述的两个条件(每根火柴属于其中一组，每组火柴长度之和相同)。依次对每一根火柴进行搜索，当搜索到第 i 根火柴时，可以考虑把它放到四组中的任意一种。对于每一种放置方法，继续对第 i + 1 根火柴进行深搜。当我们搜索完全部的 N 根火柴后，再判断每一组火柴的长度之和是否都相同。 + +## 代码 + +```go +package leetcode + +import "sort" + +func makesquare(matchsticks []int) bool { + if len(matchsticks) < 4 { + return false + } + total := 0 + for _, v := range matchsticks { + total += v + } + if total%4 != 0 { + return false + } + sort.Slice(matchsticks, func(i, j int) bool { + return matchsticks[i] > matchsticks[j] + }) + visited := make([]bool, 16) + return dfs(matchsticks, 0, 0, 0, total, &visited) +} + +func dfs(matchsticks []int, cur, group, sum, total int, visited *[]bool) bool { + if group == 4 { + return true + } + if sum > total/4 { + return false + } + if sum == total/4 { + return dfs(matchsticks, 0, group+1, 0, total, visited) + } + last := -1 + for i := cur; i < len(matchsticks); i++ { + if (*visited)[i] { + continue + } + if last == matchsticks[i] { + continue + } + (*visited)[i] = true + last = matchsticks[i] + if dfs(matchsticks, i+1, group, sum+matchsticks[i], total, visited) { + return true + } + (*visited)[i] = false + } + return false +} +``` \ No newline at end of file diff --git a/leetcode/0483.Smallest-Good-Base/483. Smallest Good Base.go b/leetcode/0483.Smallest-Good-Base/483. Smallest Good Base.go index 6c8f72d2a..7dc0430f3 100644 --- a/leetcode/0483.Smallest-Good-Base/483. Smallest Good Base.go +++ b/leetcode/0483.Smallest-Good-Base/483. Smallest Good Base.go @@ -2,34 +2,23 @@ package leetcode import ( "math" + "math/bits" "strconv" ) func smallestGoodBase(n string) string { - num, _ := strconv.ParseUint(n, 10, 64) - for bit := uint64(math.Log2(float64(num))); bit >= 1; bit-- { - low, high := uint64(2), uint64(math.Pow(float64(num), 1.0/float64(bit))) - for low < high { - mid := uint64(low + (high-low)>>1) - sum := findBase(mid, bit) - if sum == num { - return strconv.FormatUint(mid, 10) - } else if sum > num { - high = mid - 1 - } else { - low = mid + 1 - } + nVal, _ := strconv.Atoi(n) + mMax := bits.Len(uint(nVal)) - 1 + for m := mMax; m > 1; m-- { + k := int(math.Pow(float64(nVal), 1/float64(m))) + mul, sum := 1, 1 + for i := 0; i < m; i++ { + mul *= k + sum += mul + } + if sum == nVal { + return strconv.Itoa(k) } } - return strconv.FormatUint(num-1, 10) -} - -// 计算 k^m + k^(m-1) + ... + k + 1 -func findBase(mid, bit uint64) uint64 { - sum, base := uint64(1), uint64(1) - for i := uint64(1); i <= bit; i++ { - base *= mid - sum += base - } - return sum + return strconv.Itoa(nVal - 1) } diff --git a/leetcode/0488.Zuma-Game/488.Zuma Game.go b/leetcode/0488.Zuma-Game/488.Zuma Game.go new file mode 100644 index 000000000..7fa5e2595 --- /dev/null +++ b/leetcode/0488.Zuma-Game/488.Zuma Game.go @@ -0,0 +1,50 @@ +package leetcode + +func findMinStep(board string, hand string) int { + q := [][]string{{board, hand}} + mp := make(map[string]bool) + minStep := 0 + for len(q) > 0 { + length := len(q) + minStep++ + for length > 0 { + length-- + cur := q[0] + q = q[1:] + curB, curH := cur[0], cur[1] + for i := 0; i < len(curB); i++ { + for j := 0; j < len(curH); j++ { + curB2 := del3(curB[0:i] + string(curH[j]) + curB[i:]) + curH2 := curH[0:j] + curH[j+1:] + if len(curB2) == 0 { + return minStep + } + if _, ok := mp[curB2+curH2]; ok { + continue + } + mp[curB2+curH2] = true + q = append(q, []string{curB2, curH2}) + } + } + } + } + return -1 +} + +func del3(str string) string { + cnt := 1 + for i := 1; i < len(str); i++ { + if str[i] == str[i-1] { + cnt++ + } else { + if cnt >= 3 { + return del3(str[0:i-cnt] + str[i:]) + } + cnt = 1 + } + } + if cnt >= 3 { + return str[0 : len(str)-cnt] + } + return str +} diff --git a/leetcode/0488.Zuma-Game/488.Zuma Game_test.go b/leetcode/0488.Zuma-Game/488.Zuma Game_test.go new file mode 100644 index 000000000..841c8168b --- /dev/null +++ b/leetcode/0488.Zuma-Game/488.Zuma Game_test.go @@ -0,0 +1,56 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question488 struct { + para488 + ans488 +} + +// para 是参数 +type para488 struct { + board string + hand string +} + +// ans 是答案 +type ans488 struct { + ans int +} + +func Test_Problem488(t *testing.T) { + + qs := []question488{ + + { + para488{"WRRBBW", "RB"}, + ans488{-1}, + }, + + { + para488{"WWRRBBWW", "WRBRW"}, + ans488{2}, + }, + + { + para488{"G", "GGGGG"}, + ans488{2}, + }, + + { + para488{"RBYYBBRRB", "YRBGB"}, + ans488{3}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 488------------------------\n") + + for _, q := range qs { + _, p := q.ans488, q.para488 + fmt.Printf("【input】:%v 【output】:%v\n", p, findMinStep(p.board, p.hand)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0488.Zuma-Game/README.md b/leetcode/0488.Zuma-Game/README.md new file mode 100644 index 000000000..2e05d9d76 --- /dev/null +++ b/leetcode/0488.Zuma-Game/README.md @@ -0,0 +1,141 @@ +# [488. Zuma Game](https://leetcode.com/problems/zuma-game/) + + +## 题目 + +You are playing a variation of the game Zuma. + +In this variation of Zuma, there is a single row of colored balls on a board, where each ball can be colored red 'R', yellow 'Y', blue 'B', green 'G', or white 'W'. You also have several colored balls in your hand. + +Your goal is to clear all of the balls from the board. On each turn: + +Pick any ball from your hand and insert it in between two balls in the row or on either end of the row. +If there is a group of three or more consecutive balls of the same color, remove the group of balls from the board. +If this removal causes more groups of three or more of the same color to form, then continue removing each group until there are none left. +If there are no more balls on the board, then you win the game. +Repeat this process until you either win or do not have any more balls in your hand. +Given a string board, representing the row of balls on the board, and a string hand, representing the balls in your hand, return the minimum number of balls you have to insert to clear all the balls from the board. If you cannot clear all the balls from the board using the balls in your hand, return -1. + +**Example 1**: + +``` +Input: board = "WRRBBW", hand = "RB" +Output: -1 +Explanation: It is impossible to clear all the balls. The best you can do is: +- Insert 'R' so the board becomes WRRRBBW. WRRRBBW -> WBBW. +- Insert 'B' so the board becomes WBBBW. WBBBW -> WW. +There are still balls remaining on the board, and you are out of balls to insert. +``` + +**Example 2**: +``` +Input: board = "WWRRBBWW", hand = "WRBRW" +Output: 2 +Explanation: To make the board empty: +- Insert 'R' so the board becomes WWRRRBBWW. WWRRRBBWW -> WWBBWW. +- Insert 'B' so the board becomes WWBBBWW. WWBBBWW -> WWWW -> empty. +2 balls from your hand were needed to clear the board. +``` + +**Example 3**: +``` +Input: board = "G", hand = "GGGGG" +Output: 2 +Explanation: To make the board empty: +- Insert 'G' so the board becomes GG. +- Insert 'G' so the board becomes GGG. GGG -> empty. +2 balls from your hand were needed to clear the board. +``` + +**Example 4**: +``` +Input: board = "RBYYBBRRB", hand = "YRBGB" +Output: 3 +Explanation: To make the board empty: +- Insert 'Y' so the board becomes RBYYYBBRRB. RBYYYBBRRB -> RBBBRRB -> RRRB -> B. +- Insert 'B' so the board becomes BB. +- Insert 'B' so the board becomes BBB. BBB -> empty. +3 balls from your hand were needed to clear the board. +``` + +**Constraints**: + +- 1 <= board.length <= 16 +- 1 <= hand.length <= 5 +- board and hand consist of the characters 'R', 'Y', 'B', 'G', and 'W'. +- The initial row of balls on the board will not have any groups of three or more consecutive balls of the same color. + +## 题目大意 + +你正在参与祖玛游戏的一个变种。 + +在这个祖玛游戏变体中，桌面上有 一排 彩球，每个球的颜色可能是：红色 'R'、黄色 'Y'、蓝色 'B'、绿色 'G' 或白色 'W' 。你的手中也有一些彩球。 + +你的目标是 清空 桌面上所有的球。每一回合： + +从你手上的彩球中选出 任意一颗 ，然后将其插入桌面上那一排球中：两球之间或这一排球的任一端。 +接着，如果有出现 三个或者三个以上 且 颜色相同 的球相连的话，就把它们移除掉。 +如果这种移除操作同样导致出现三个或者三个以上且颜色相同的球相连，则可以继续移除这些球，直到不再满足移除条件。 +如果桌面上所有球都被移除，则认为你赢得本场游戏。 +重复这个过程，直到你赢了游戏或者手中没有更多的球。 +给你一个字符串 board ，表示桌面上最开始的那排球。另给你一个字符串 hand ，表示手里的彩球。请你按上述操作步骤移除掉桌上所有球，计算并返回所需的 最少 球数。如果不能移除桌上所有的球，返回 -1 。 + +## 解题思路 + +- 使用广度优先搜索和剪枝 + +## 代码 + +```go + +package leetcode + +func findMinStep(board string, hand string) int { + q := [][]string{{board, hand}} + mp := make(map[string]bool) + minStep := 0 + for len(q) > 0 { + length := len(q) + minStep++ + for length > 0 { + length-- + cur := q[0] + q = q[1:] + curB, curH := cur[0], cur[1] + for i := 0; i < len(curB); i++ { + for j := 0; j < len(curH); j++ { + curB2 := del3(curB[0:i] + string(curH[j]) + curB[i:]) + curH2 := curH[0:j] + curH[j+1:] + if len(curB2) == 0 { + return minStep + } + if _, ok := mp[curB2+curH2]; ok { + continue + } + mp[curB2+curH2] = true + q = append(q, []string{curB2, curH2}) + } + } + } + } + return -1 +} + +func del3(str string) string { + cnt := 1 + for i := 1; i < len(str); i++ { + if str[i] == str[i-1] { + cnt++ + } else { + if cnt >= 3 { + return del3(str[0:i-cnt] + str[i:]) + } + cnt = 1 + } + } + if cnt >= 3 { + return str[0 : len(str)-cnt] + } + return str +} +``` \ No newline at end of file diff --git a/leetcode/0491.Increasing-Subsequences/491. Increasing Subsequences.go b/leetcode/0491.Non-decreasing-Subsequences/491. Non-decreasing Subsequences.go similarity index 100% rename from leetcode/0491.Increasing-Subsequences/491. Increasing Subsequences.go rename to leetcode/0491.Non-decreasing-Subsequences/491. Non-decreasing Subsequences.go diff --git a/leetcode/0491.Increasing-Subsequences/491. Increasing Subsequences_test.go b/leetcode/0491.Non-decreasing-Subsequences/491. Non-decreasing Subsequences_test.go similarity index 100% rename from leetcode/0491.Increasing-Subsequences/491. Increasing Subsequences_test.go rename to leetcode/0491.Non-decreasing-Subsequences/491. Non-decreasing Subsequences_test.go diff --git a/leetcode/0491.Increasing-Subsequences/README.md b/leetcode/0491.Non-decreasing-Subsequences/README.md similarity index 95% rename from leetcode/0491.Increasing-Subsequences/README.md rename to leetcode/0491.Non-decreasing-Subsequences/README.md index 79063dbc5..f5c5e34a6 100755 --- a/leetcode/0491.Increasing-Subsequences/README.md +++ b/leetcode/0491.Non-decreasing-Subsequences/README.md @@ -1,4 +1,4 @@ -# [491. Increasing Subsequences](https://leetcode.com/problems/increasing-subsequences/) +# [491. Non-decreasing Subsequences](https://leetcode.com/problems/non-decreasing-subsequences/) ## 题目 diff --git a/leetcode/0492.Construct-the-Rectangle/492.Construct the Rectangle.go b/leetcode/0492.Construct-the-Rectangle/492.Construct the Rectangle.go new file mode 100644 index 000000000..3314fbc13 --- /dev/null +++ b/leetcode/0492.Construct-the-Rectangle/492.Construct the Rectangle.go @@ -0,0 +1,16 @@ +package leetcode + +import "math" + +func constructRectangle(area int) []int { + ans := make([]int, 2) + W := int(math.Sqrt(float64(area))) + for W >= 1 { + if area%W == 0 { + ans[0], ans[1] = area/W, W + break + } + W -= 1 + } + return ans +} diff --git a/leetcode/0492.Construct-the-Rectangle/492.Construct the Rectangle_test.go b/leetcode/0492.Construct-the-Rectangle/492.Construct the Rectangle_test.go new file mode 100644 index 000000000..b3ed98390 --- /dev/null +++ b/leetcode/0492.Construct-the-Rectangle/492.Construct the Rectangle_test.go @@ -0,0 +1,50 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question492 struct { + para492 + ans492 +} + +// area 是参数 +type para492 struct { + area int +} + +// ans 是答案 +type ans492 struct { + ans []int +} + +func Test_Problem492(t *testing.T) { + + qs := []question492{ + + { + para492{4}, + ans492{[]int{2, 2}}, + }, + + { + para492{37}, + ans492{[]int{37, 1}}, + }, + + { + para492{122122}, + ans492{[]int{427, 286}}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 492------------------------\n") + + for _, q := range qs { + _, p := q.ans492, q.para492 + fmt.Printf("【input】:%v 【output】:%v\n", p, constructRectangle(p.area)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0492.Construct-the-Rectangle/README.md b/leetcode/0492.Construct-the-Rectangle/README.md new file mode 100644 index 000000000..8024d6e16 --- /dev/null +++ b/leetcode/0492.Construct-the-Rectangle/README.md @@ -0,0 +1,72 @@ +# [492. Construct the Rectangle](https://leetcode.com/problems/construct-the-rectangle/) + + +## 题目 + +A web developer needs to know how to design a web page's size. +So, given a specific rectangular web page’s area, your job by now is to design a rectangular web page, +whose length L and width W satisfy the following requirements: + + The area of the rectangular web page you designed must equal to the given target area. + The width W should not be larger than the length L, which means L >= W. + The difference between length L and width W should be as small as possible. + Return an array [L, W] where L and W are the length and width of the web page you designed in sequence. + +**Example 1:** + + Input: area = 4 + Output: [2,2] + Explanation: The target area is 4, and all the possible ways to construct it are [1,4], [2,2], [4,1]. + But according to requirement 2, [1,4] is illegal; according to requirement 3, [4,1] is not optimal compared to [2,2]. So the length L is 2, and the width W is 2. + +**Example 2:** + + Input: area = 37 + Output: [37,1] + +**Example 3:** + + Input: area = 122122 + Output: [427,286] + +**Constraints** + + - 1 <= area <= 10000000 + +## 题目大意 + +作为一位 web 开发者， 懂得怎样去规划一个页面的尺寸是很重要的。 现给定一个具体的矩形页面面积，你的任务是设计一个长度为 L 和宽度为 W 且满足以下要求的矩形的页面。要求： + +1. 你设计的矩形页面必须等于给定的目标面积。 +2. 宽度 W 不应大于长度 L，换言之，要求 L >= W 。 +3. 长度 L 和宽度 W 之间的差距应当尽可能小。 + +你需要按顺序输出你设计的页面的长度 L 和宽度 W。 + +## 解题思路 + +- 令 W 等于根号 area +- 在 W 大于等于 1 的情况下,判断 area%W 是否等于 0,如果不相等 W 就减 1 继续循环,如果相等就返回 [area/W, W] + +## 代码 + +```go + +package leetcode + +import "math" + +func constructRectangle(area int) []int { + ans := make([]int, 2) + W := int(math.Sqrt(float64(area))) + for W >= 1 { + if area%W == 0 { + ans[0], ans[1] = area/W, W + break + } + W -= 1 + } + return ans +} + +`` \ No newline at end of file diff --git a/leetcode/0494.Target-Sum/494. Target Sum.go b/leetcode/0494.Target-Sum/494. Target Sum.go index b9fac40c8..8adde19c7 100644 --- a/leetcode/0494.Target-Sum/494. Target Sum.go +++ b/leetcode/0494.Target-Sum/494. Target Sum.go @@ -6,7 +6,7 @@ func findTargetSumWays(nums []int, S int) int { for _, n := range nums { total += n } - if S > total || (S+total)%2 == 1 { + if S+total < 0 || S > total || (S+total)%2 == 1 { return 0 } target := (S + total) / 2 diff --git a/leetcode/0494.Target-Sum/README.md b/leetcode/0494.Target-Sum/README.md index dd3c2b103..94234e7b9 100644 --- a/leetcode/0494.Target-Sum/README.md +++ b/leetcode/0494.Target-Sum/README.md @@ -42,7 +42,7 @@ There are 5 ways to assign symbols to make the sum of nums be target 3. ## 解题思路 - 给出一个数组，要求在这个数组里面的每个元素前面加上 + 或者 - 号，最终总和等于 S。问有多少种不同的方法。 -- 这一题可以用 DP 和 DFS 解答。DFS 方法就不比较暴力简单了。见代码。这里分析一下 DP 的做法。题目要求在数组元素前加上 + 或者 - 号，其实相当于把数组分成了 2 组，一组全部都加 + 号，一组都加 - 号。记 + 号的一组 P ，记 - 号的一组 N，那么可以推出以下的关系。 +- 这一题可以用 DP 和 DFS 解答。DFS 方法就比较暴力简单了。见代码。这里分析一下 DP 的做法。题目要求在数组元素前加上 + 或者 - 号，其实相当于把数组分成了 2 组，一组全部都加 + 号，一组都加 - 号。记 + 号的一组 P ，记 - 号的一组 N，那么可以推出以下的关系。 ```go sum(P) - sum(N) = target @@ -52,7 +52,7 @@ There are 5 ways to assign symbols to make the sum of nums be target 3. 等号两边都加上 `sum(N) + sum(P)`，于是可以得到结果 `2 * sum(P) = target + sum(nums)`，那么这道题就转换成了，能否在数组中找到这样一个集合，和等于 `(target + sum(nums)) / 2`。那么这题就转化为了第 416 题了。`dp[i]` 中存储的是能使和为 `i` 的方法个数。 -- 如果和不是偶数，即不能被 2 整除，那说明找不到满足题目要求的解了，直接输出 0 。 +- 如果和不是偶数，即不能被 2 整除，或者和是负数，那说明找不到满足题目要求的解了，直接输出 0 。 ## 代码 @@ -63,7 +63,7 @@ func findTargetSumWays(nums []int, S int) int { for _, n := range nums { total += n } - if S > total || (S+total)%2 == 1 { + if S > total || (S+total)%2 == 1 || S+total < 0 { return 0 } target := (S + total) / 2 diff --git a/leetcode/0495.Teemo-Attacking/495.Teemo Attacking.go b/leetcode/0495.Teemo-Attacking/495.Teemo Attacking.go new file mode 100644 index 000000000..4da646d98 --- /dev/null +++ b/leetcode/0495.Teemo-Attacking/495.Teemo Attacking.go @@ -0,0 +1,16 @@ +package leetcode + +func findPoisonedDuration(timeSeries []int, duration int) int { + var ans int + for i := 1; i < len(timeSeries); i++ { + t := timeSeries[i-1] + end := t + duration - 1 + if end < timeSeries[i] { + ans += duration + } else { + ans += timeSeries[i] - t + } + } + ans += duration + return ans +} diff --git a/leetcode/0495.Teemo-Attacking/495.Teemo Attacking_test.go b/leetcode/0495.Teemo-Attacking/495.Teemo Attacking_test.go new file mode 100644 index 000000000..2900a11f8 --- /dev/null +++ b/leetcode/0495.Teemo-Attacking/495.Teemo Attacking_test.go @@ -0,0 +1,46 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question495 struct { + para495 + ans495 +} + +// para 是参数 +type para495 struct { + timeSeries []int + duration int +} + +// ans 是答案 +type ans495 struct { + ans int +} + +func Test_Problem495(t *testing.T) { + + qs := []question495{ + + { + para495{[]int{1, 4}, 2}, + ans495{4}, + }, + + { + para495{[]int{1, 2}, 2}, + ans495{3}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 495------------------------\n") + + for _, q := range qs { + _, p := q.ans495, q.para495 + fmt.Printf("【input】:%v 【output】:%v\n", p, findPoisonedDuration(p.timeSeries, p.duration)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0495.Teemo-Attacking/README.md b/leetcode/0495.Teemo-Attacking/README.md new file mode 100644 index 000000000..3a52e1f27 --- /dev/null +++ b/leetcode/0495.Teemo-Attacking/README.md @@ -0,0 +1,85 @@ +# [495. Teemo Attacking](https://leetcode.com/problems/teemo-attacking/) + + +## 题目 + +Our hero Teemo is attacking an enemy Ashe with poison attacks! When Teemo attacks Ashe, Ashe gets poisoned for a exactly duration seconds. + +More formally, an attack at second t will mean Ashe is poisoned during the inclusive time interval [t, t + duration - 1]. + +If Teemo attacks again before the poison effect ends, the timer for it is reset, and the poison effect will end duration seconds after the new attack. + +You are given a non-decreasing integer array timeSeries, where timeSeries[i] denotes that Teemo attacks Ashe at second timeSeries[i], and an integer duration. + +Return the total number of seconds that Ashe is poisoned. + +**Example 1**: +``` +Input: timeSeries = [1,4], duration = 2 +Output: 4 +Explanation: Teemo's attacks on Ashe go as follows: +- At second 1, Teemo attacks, and Ashe is poisoned for seconds 1 and 2. +- At second 4, Teemo attacks, and Ashe is poisoned for seconds 4 and 5. +Ashe is poisoned for seconds 1, 2, 4, and 5, which is 4 seconds in total. +``` + +**Example 2**: +``` +Input: timeSeries = [1,2], duration = 2 +Output: 3 +Explanation: Teemo's attacks on Ashe go as follows: +- At second 1, Teemo attacks, and Ashe is poisoned for seconds 1 and 2. +- At second 2 however, Teemo attacks again and resets the poison timer. Ashe is poisoned for seconds 2 and 3. +Ashe is poisoned for seconds 1, 2, and 3, which is 3 seconds in total. +``` + +**Constraints**: + +- 1 <= timeSeries.length <= 10000 +- 0 <= timeSeries[i], duration <= 10000000 +- timeSeries is sorted in non-decreasing order. + +## 题目大意 + +在《英雄联盟》的世界中，有一个叫 “提莫” 的英雄。他的攻击可以让敌方英雄艾希（编者注：寒冰射手）进入中毒状态。 + +当提莫攻击艾希，艾希的中毒状态正好持续duration 秒。 + +正式地讲，提莫在t发起发起攻击意味着艾希在时间区间 [t, t + duration - 1]（含 t 和 t + duration - 1）处于中毒状态。 + +如果提莫在中毒影响结束前再次攻击，中毒状态计时器将会重置，在新的攻击之后，中毒影响将会在duration秒后结束。 + +给你一个非递减的整数数组timeSeries，其中timeSeries[i]表示提莫在timeSeries[i]秒时对艾希发起攻击，以及一个表示中毒持续时间的整数duration 。 + +返回艾希处于中毒状态的总秒数。 + +## 解题思路 + +- i 从 1 开始计数，令 t 等于 timeSeries[i - 1] +- 比较 end(t + duration - 1) 和 timeSeries[i] 的大小， + - 如果 end 小于 timeSeries[i],ans+=duration + - 否则 ans += timeSeries[i] - t +- ans += duration 并返回 ans + +## 代码 + +```go + +package leetcode + +func findPoisonedDuration(timeSeries []int, duration int) int { + var ans int + for i := 1; i < len(timeSeries); i++ { + t := timeSeries[i-1] + end := t + duration - 1 + if end < timeSeries[i] { + ans += duration + } else { + ans += timeSeries[i] - t + } + } + ans += duration + return ans +} + +``` diff --git a/leetcode/0498.Diagonal-Traverse/README.md b/leetcode/0498.Diagonal-Traverse/README.md index e4d28abd1..6e5969c78 100755 --- a/leetcode/0498.Diagonal-Traverse/README.md +++ b/leetcode/0498.Diagonal-Traverse/README.md @@ -37,3 +37,10 @@ The total number of elements of the given matrix will not exceed 10,000. - 给出一个二维数组，要求按照如图的方式遍历整个数组。 - 这一题用模拟的方式就可以解出来。需要注意的是边界条件：比如二维数组为空，二维数组退化为一行或者一列，退化为一个元素。具体例子见测试用例。 +- 解题关键是在判断下一个位置，将矩阵想像成一个X,Y坐标轴。那么可分为以下几种情况， + 1、斜角向右上遍历时， + 当右上角在坐标轴内， 正常计算 即， x+1(X轴向右移动)， y-1(Y轴向上移动) + 当右上角在坐标轴外，那么当前位置只能在 第一行X坐标轴 ，或者 最后一列Y坐标轴 ， 即判断该两种情况下�应该X坐标往右，或者 Y坐标往上 + 2、同理 斜角向下遍历时 + 当左下角在坐标轴内，正常计算 即， x-1(X轴向右移动)， y+1(Y轴向下移动) + 当左下角在坐标轴外，那么当前位置只能在 第一列Y坐标轴，或者 最后一行X坐标轴， 即判断该两种情况下�应该X坐标往左，或者 Y坐标往下 diff --git a/leetcode/0504.Base-7/504.Base 7.go b/leetcode/0504.Base-7/504.Base 7.go new file mode 100644 index 000000000..5a143b2be --- /dev/null +++ b/leetcode/0504.Base-7/504.Base 7.go @@ -0,0 +1,28 @@ +package leetcode + +import "strconv" + +func convertToBase7(num int) string { + if num == 0 { + return "0" + } + negative := false + if num < 0 { + negative = true + num = -num + } + var ans string + var nums []int + for num != 0 { + remainder := num % 7 + nums = append(nums, remainder) + num = num / 7 + } + if negative { + ans += "-" + } + for i := len(nums) - 1; i >= 0; i-- { + ans += strconv.Itoa(nums[i]) + } + return ans +} diff --git a/leetcode/0504.Base-7/504.Base 7_test.go b/leetcode/0504.Base-7/504.Base 7_test.go new file mode 100644 index 000000000..1309c1b63 --- /dev/null +++ b/leetcode/0504.Base-7/504.Base 7_test.go @@ -0,0 +1,46 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question504 struct { + para504 + ans504 +} + +// para 是参数 +type para504 struct { + num int +} + +// ans 是答案 +type ans504 struct { + ans string +} + +func Test_Problem504(t *testing.T) { + + qs := []question504{ + + { + para504{100}, + ans504{"202"}, + }, + + { + para504{-7}, + ans504{"-10"}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 504------------------------\n") + + for _, q := range qs { + _, p := q.ans504, q.para504 + fmt.Printf("【input】:%v ", p.num) + fmt.Printf("【output】:%v \n", convertToBase7(p.num)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0504.Base-7/README.md b/leetcode/0504.Base-7/README.md new file mode 100644 index 000000000..359b96a0c --- /dev/null +++ b/leetcode/0504.Base-7/README.md @@ -0,0 +1,60 @@ +# [504. Base 7](https://leetcode.com/problems/base-7/) + +## 题目 + +Given an integer num, return a string of its base 7 representation. + +**Example 1:** + + Input: num = 100 + Output: "202" + +**Example 2:** + + Input: num = -7 + Output: "-10" + +**Constraints:** + +- -10000000 <= num <= 10000000 + +## 题目大意 + +给定一个整数 num，将其转化为 7 进制，并以字符串形式输出。 + +## 解题思路 + + num反复除以7，然后倒排余数 + +# 代码 + +```go +package leetcode + +import "strconv" + +func convertToBase7(num int) string { + if num == 0 { + return "0" + } + negative := false + if num < 0 { + negative = true + num = -num + } + var ans string + var nums []int + for num != 0 { + remainder := num % 7 + nums = append(nums, remainder) + num = num / 7 + } + if negative { + ans += "-" + } + for i := len(nums) - 1; i >= 0; i-- { + ans += strconv.Itoa(nums[i]) + } + return ans +} +``` \ No newline at end of file diff --git a/leetcode/0506.Relative-Ranks/506.Relative Ranks.go b/leetcode/0506.Relative-Ranks/506.Relative Ranks.go new file mode 100644 index 000000000..501b933b2 --- /dev/null +++ b/leetcode/0506.Relative-Ranks/506.Relative Ranks.go @@ -0,0 +1,29 @@ +package leetcode + +import ( + "sort" + "strconv" +) + +func findRelativeRanks(score []int) []string { + mp := make(map[int]int) + for i, v := range score { + mp[v] = i + } + sort.Slice(score, func(i, j int) bool { + return score[i] > score[j] + }) + ans := make([]string, len(score)) + for i, v := range score { + if i == 0 { + ans[mp[v]] = "Gold Medal" + } else if i == 1 { + ans[mp[v]] = "Silver Medal" + } else if i == 2 { + ans[mp[v]] = "Bronze Medal" + } else { + ans[mp[v]] = strconv.Itoa(i + 1) + } + } + return ans +} diff --git a/leetcode/0506.Relative-Ranks/506.Relative Ranks_test.go b/leetcode/0506.Relative-Ranks/506.Relative Ranks_test.go new file mode 100644 index 000000000..b26017d68 --- /dev/null +++ b/leetcode/0506.Relative-Ranks/506.Relative Ranks_test.go @@ -0,0 +1,45 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question506 struct { + para506 + ans506 +} + +// para 是参数 +type para506 struct { + score []int +} + +// ans 是答案 +type ans506 struct { + ans []string +} + +func Test_Problem506(t *testing.T) { + + qs := []question506{ + + { + para506{[]int{5, 4, 3, 2, 1}}, + ans506{[]string{"Gold Medal", "Silver Medal", "Bronze Medal", "4", "5"}}, + }, + + { + para506{[]int{10, 3, 8, 9, 4}}, + ans506{[]string{"Gold Medal", "5", "Bronze Medal", "Silver Medal", "4"}}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 506------------------------\n") + + for _, q := range qs { + _, p := q.ans506, q.para506 + fmt.Printf("【input】:%v 【output】:%v\n", p.score, findRelativeRanks(p.score)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0506.Relative-Ranks/README.md b/leetcode/0506.Relative-Ranks/README.md new file mode 100644 index 000000000..e1eb64330 --- /dev/null +++ b/leetcode/0506.Relative-Ranks/README.md @@ -0,0 +1,84 @@ +# [506. Relative Ranks](https://leetcode.com/problems/relative-ranks/) + +## 题目 + +You are given an integer array score of size n, where score[i] is the score of the ith athlete in a competition. All the scores are guaranteed to be unique. + +The athletes are placed based on their scores, where the 1st place athlete has the highest score, the 2nd place athlete has the 2nd highest score, and so on. The placement of each athlete determines their rank: + +- The 1st place athlete's rank is "Gold Medal". +- The 2nd place athlete's rank is "Silver Medal". +- The 3rd place athlete's rank is "Bronze Medal". +- For the 4th place to the nth place athlete, their rank is their placement number (i.e., the xth place athlete's rank is "x"). + +Return an array answer of size n where answer[i] is the rank of the ith athlete. + +**Example 1**: + + Input: score = [5,4,3,2,1] + Output: ["Gold Medal","Silver Medal","Bronze Medal","4","5"] + Explanation: The placements are [1st, 2nd, 3rd, 4th, 5th]. + +**Example 2**: + + Input: score = [10,3,8,9,4] + Output: ["Gold Medal","5","Bronze Medal","Silver Medal","4"] + Explanation: The placements are [1st, 5th, 3rd, 2nd, 4th]. + +**Constraints:** + +- n == score.length +- 1 <= n <= 10000 +- 0 <= score[i] <= 1000000 +- All the values in score are unique. + +## 题目大意 + +给你一个长度为 n 的整数数组 score ，其中 score[i] 是第 i 位运动员在比赛中的得分。所有得分都 互不相同 。 + +运动员将根据得分 决定名次 ，其中名次第 1 的运动员得分最高，名次第 2 的运动员得分第 2 高，依此类推。运动员的名次决定了他们的获奖情况： + +- 名次第 1 的运动员获金牌 "Gold Medal" 。 +- 名次第 2 的运动员获银牌 "Silver Medal" 。 +- 名次第 3 的运动员获铜牌 "Bronze Medal" 。 +- 从名次第 4 到第 n 的运动员，只能获得他们的名次编号（即，名次第 x 的运动员获得编号 "x"）。 + +使用长度为 n 的数组 answer 返回获奖，其中 answer[i] 是第 i 位运动员的获奖情况。 + +## 解题思路 + +- 用 map 记录原来 score 中元素对应的坐标，然后对 score 进行排序，对排序后的元素我们通过 map 就可以知道它排的名次了 + +## 代码 + +```go +package leetcode + +import ( + "sort" + "strconv" +) + +func findRelativeRanks(score []int) []string { + mp := make(map[int]int) + for i, v := range score { + mp[v] = i + } + sort.Slice(score, func(i, j int) bool { + return score[i] > score[j] + }) + ans := make([]string, len(score)) + for i, v := range score { + if i == 0 { + ans[mp[v]] = "Gold Medal" + } else if i == 1 { + ans[mp[v]] = "Silver Medal" + } else if i == 2 { + ans[mp[v]] = "Bronze Medal" + } else { + ans[mp[v]] = strconv.Itoa(i + 1) + } + } + return ans +} +``` \ No newline at end of file diff --git a/leetcode/0508.Most-Frequent-Subtree-Sum/508. Most Frequent Subtree Sum.go b/leetcode/0508.Most-Frequent-Subtree-Sum/508. Most Frequent Subtree Sum.go index c35b7f7b3..98300692e 100644 --- a/leetcode/0508.Most-Frequent-Subtree-Sum/508. Most Frequent Subtree Sum.go +++ b/leetcode/0508.Most-Frequent-Subtree-Sum/508. Most Frequent Subtree Sum.go @@ -2,9 +2,7 @@ package leetcode import ( "sort" -) -import ( "github.com/halfrost/LeetCode-Go/structures" ) diff --git a/leetcode/0509.Fibonacci-Number/509. Fibonacci Number.go b/leetcode/0509.Fibonacci-Number/509. Fibonacci Number.go index 9fc98a9be..ea6d95a26 100644 --- a/leetcode/0509.Fibonacci-Number/509. Fibonacci Number.go +++ b/leetcode/0509.Fibonacci-Number/509. Fibonacci Number.go @@ -111,19 +111,19 @@ func fib5(N int) int { // 解法七 协程版，但是时间特别慢，不推荐，放在这里只是告诉大家，写 LeetCode 算法题的时候，启动 goroutine 特别慢 func fib6(N int) int { - return <-fibb(N) + return <-fibb(N) } -func fibb(n int) <- chan int { - result := make(chan int) - go func() { - defer close(result) - - if n <= 1 { - result <- n - return - } - result <- <-fibb(n-1) + <-fibb(n-2) - }() - return result -} \ No newline at end of file +func fibb(n int) <-chan int { + result := make(chan int) + go func() { + defer close(result) + + if n <= 1 { + result <- n + return + } + result <- <-fibb(n-1) + <-fibb(n-2) + }() + return result +} diff --git a/leetcode/0515.Find-Largest-Value-in-Each-Tree-Row/515. Find Largest Value in Each Tree Row.go b/leetcode/0515.Find-Largest-Value-in-Each-Tree-Row/515. Find Largest Value in Each Tree Row.go index 042956e8c..54d831dc0 100644 --- a/leetcode/0515.Find-Largest-Value-in-Each-Tree-Row/515. Find Largest Value in Each Tree Row.go +++ b/leetcode/0515.Find-Largest-Value-in-Each-Tree-Row/515. Find Largest Value in Each Tree Row.go @@ -3,9 +3,7 @@ package leetcode import ( "math" "sort" -) -import ( "github.com/halfrost/LeetCode-Go/structures" ) @@ -92,3 +90,25 @@ func largestValues1(root *TreeNode) []int { } return res } + +// 解法三 深度遍历二叉树 +func largestValues3(root *TreeNode) []int { + var res []int + var dfs func(root *TreeNode, level int) + dfs = func(root *TreeNode, level int) { + if root == nil { + return + } + if len(res) == level { + res = append(res, root.Val) + } + if res[level] < root.Val { + res[level] = root.Val + } + + dfs(root.Right, level+1) + dfs(root.Left, level+1) + } + dfs(root, 0) + return res +} diff --git a/leetcode/0518.Coin-Change-II/518. Coin Change II.go b/leetcode/0518.Coin-Change-II/518. Coin Change II.go new file mode 100644 index 000000000..9de3726da --- /dev/null +++ b/leetcode/0518.Coin-Change-II/518. Coin Change II.go @@ -0,0 +1,12 @@ +package leetcode + +func change(amount int, coins []int) int { + dp := make([]int, amount+1) + dp[0] = 1 + for _, coin := range coins { + for i := coin; i <= amount; i++ { + dp[i] += dp[i-coin] + } + } + return dp[amount] +} diff --git a/leetcode/0518.Coin-Change-II/518. Coin Change II_test.go b/leetcode/0518.Coin-Change-II/518. Coin Change II_test.go new file mode 100644 index 000000000..e98639433 --- /dev/null +++ b/leetcode/0518.Coin-Change-II/518. Coin Change II_test.go @@ -0,0 +1,53 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question518 struct { + para518 + ans518 +} + +// para 是参数 +// one 代表第一个参数 +type para518 struct { + amount int + coins []int +} + +// ans 是答案 +// one 代表第一个答案 +type ans518 struct { + one int +} + +func Test_Problem518(t *testing.T) { + + qs := []question518{ + + { + para518{5, []int{1, 2, 5}}, + ans518{4}, + }, + + { + para518{3, []int{2}}, + ans518{0}, + }, + + { + para518{10, []int{10}}, + ans518{1}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 518------------------------\n") + + for _, q := range qs { + _, p := q.ans518, q.para518 + fmt.Printf("【input】:%v 【output】:%v\n", p, change(p.amount, p.coins)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0518.Coin-Change-II/README.md b/leetcode/0518.Coin-Change-II/README.md new file mode 100644 index 000000000..4679d2d3c --- /dev/null +++ b/leetcode/0518.Coin-Change-II/README.md @@ -0,0 +1,73 @@ +# [518. Coin Change II](https://leetcode.com/problems/coin-change-ii/) + + +## 题目 + +You are given an integer array `coins` representing coins of different denominations and an integer `amount` representing a total amount of money. + +Return *the number of combinations that make up that amount*. If that amount of money cannot be made up by any combination of the coins, return `0`. + +You may assume that you have an infinite number of each kind of coin. + +The answer is **guaranteed** to fit into a signed **32-bit** integer. + +**Example 1:** + +``` +Input: amount = 5, coins = [1,2,5] +Output: 4 +Explanation: there are four ways to make up the amount: +5=5 +5=2+2+1 +5=2+1+1+1 +5=1+1+1+1+1 +``` + +**Example 2:** + +``` +Input: amount = 3, coins = [2] +Output: 0 +Explanation: the amount of 3 cannot be made up just with coins of 2. +``` + +**Example 3:** + +``` +Input: amount = 10, coins = [10] +Output: 1 +``` + +**Constraints:** + +- `1 <= coins.length <= 300` +- `1 <= coins[i] <= 5000` +- All the values of `coins` are **unique**. +- `0 <= amount <= 5000` + +## 题目大意 + +给你一个整数数组 coins 表示不同面额的硬币，另给一个整数 amount 表示总金额。请你计算并返回可以凑成总金额的硬币组合数。如果任何硬币组合都无法凑出总金额，返回 0 。假设每一种面额的硬币有无限个。题目数据保证结果符合 32 位带符号整数。 + +## 解题思路 + +- 此题虽然名字叫 Coin Change，但是不是经典的背包九讲问题。题目中 coins 的每个元素可以选取多次，且不考虑选取元素的顺序，因此这道题实际需要计算的是选取硬币的组合数。定义 dp[i] 表示金额之和等于 i 的硬币组合数，目标求 dp[amount]。初始边界条件为 dp[0] = 1，即不取任何硬币，就这一种取法，金额为 0 。状态转移方程 dp[i] += dp[i-coin]，coin 为当前枚举的 coin。 +- 可能有读者会有疑惑，上述做法会不会出现重复计算。答案是不会。外层循环是遍历数组 coins 的值，内层循环是遍历不同的金额之和，在计算 dp[i] 的值时，可以确保金额之和等于 i 的硬币面额的顺序，由于顺序确定，因此不会重复计算不同的排列。 +- 和此题完全一致的解题思路的题有，第 377 题和第 494 题。 + +## 代码 + +```go +package leetcode + +func change(amount int, coins []int) int { + dp := make([]int, amount+1) + dp[0] = 1 + for _, coin := range coins { + for i := coin; i <= amount; i++ { + dp[i] += dp[i-coin] + } + } + return dp[amount] +} +``` \ No newline at end of file diff --git a/leetcode/0519.Random-Flip-Matrix/519.Random Flip Matrix.go b/leetcode/0519.Random-Flip-Matrix/519.Random Flip Matrix.go new file mode 100644 index 000000000..4b0df378a --- /dev/null +++ b/leetcode/0519.Random-Flip-Matrix/519.Random Flip Matrix.go @@ -0,0 +1,43 @@ +package leetcode + +import ( + "math/rand" +) + +type Solution struct { + r int + c int + total int + mp map[int]int +} + +func Constructor(m int, n int) Solution { + return Solution{ + r: m, + c: n, + total: m * n, + mp: map[int]int{}, + } +} + +func (this *Solution) Flip() []int { + k := rand.Intn(this.total) + val := k + if v, ok := this.mp[k]; ok { + val = v + } + if _, ok := this.mp[this.total-1]; ok { + this.mp[k] = this.mp[this.total-1] + } else { + this.mp[k] = this.total - 1 + } + delete(this.mp, this.total-1) + this.total-- + newR, newC := val/this.c, val%this.c + return []int{newR, newC} +} + +func (this *Solution) Reset() { + this.total = this.r * this.c + this.mp = map[int]int{} +} diff --git a/leetcode/0519.Random-Flip-Matrix/519.Random Flip Matrix_test.go b/leetcode/0519.Random-Flip-Matrix/519.Random Flip Matrix_test.go new file mode 100644 index 000000000..847ac79a2 --- /dev/null +++ b/leetcode/0519.Random-Flip-Matrix/519.Random Flip Matrix_test.go @@ -0,0 +1,52 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question519 struct { + para519 + ans519 +} + +// para 是参数 +type para519 struct { + para []string + val [][]int +} + +// ans 是答案 +type ans519 struct { + ans [][]int +} + +func Test_Problem519(t *testing.T) { + + qs := []question519{ + + { + para519{[]string{"Solution", "flip", "flip", "flip", "reset", "flip"}, [][]int{{3, 1}, {}, {}, {}, {}, {}}}, + ans519{[][]int{nil, {1, 0}, {2, 0}, {0, 0}, nil, {2, 0}}}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 519------------------------\n") + + for _, q := range qs { + _, p := q.ans519, q.para519 + sol := Constructor(0, 0) + for _, v := range p.para { + if v == "Solution" { + sol = Constructor(q.val[0][0], q.val[0][1]) + fmt.Printf("【input】:%v 【output】:%v\n", v, nil) + } else if v == "flip" { + fmt.Printf("【input】:%v 【output】:%v\n", v, sol.Flip()) + } else { + sol.Reset() + fmt.Printf("【input】:%v 【output】:%v\n", v, nil) + } + } + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0519.Random-Flip-Matrix/README.md b/leetcode/0519.Random-Flip-Matrix/README.md new file mode 100644 index 000000000..2f9ae71c1 --- /dev/null +++ b/leetcode/0519.Random-Flip-Matrix/README.md @@ -0,0 +1,98 @@ +# [519. Random Flip Matrix](https://leetcode.com/problems/random-flip-matrix/) + +## 题目 + +There is an m x n binary grid matrix with all the values set 0 initially. Design an algorithm to randomly pick an index (i, j) where matrix[i][j] == 0 and flips it to 1. All the indices (i, j) where matrix[i][j] == 0 should be equally likely to be returned. + +Optimize your algorithm to minimize the number of calls made to the built-in random function of your language and optimize the time and space complexity. + +Implement the Solution class: + +- Solution(int m, int n) Initializes the object with the size of the binary matrix m and n. +- int[] flip() Returns a random index [i, j] of the matrix where matrix[i][j] == 0 and flips it to 1. +- void reset() Resets all the values of the matrix to be 0. + +**Example 1**: + + Input + ["Solution", "flip", "flip", "flip", "reset", "flip"] + [[3, 1], [], [], [], [], []] + Output + [null, [1, 0], [2, 0], [0, 0], null, [2, 0]] + + Explanation + Solution solution = new Solution(3, 1); + solution.flip(); // return [1, 0], [0,0], [1,0], and [2,0] should be equally likely to be returned. + solution.flip(); // return [2, 0], Since [1,0] was returned, [2,0] and [0,0] + solution.flip(); // return [0, 0], Based on the previously returned indices, only [0,0] can be returned. + solution.reset(); // All the values are reset to 0 and can be returned. + solution.flip(); // return [2, 0], [0,0], [1,0], and [2,0] should be equally likely to be returned. + +**Constraints:** + +- 1 <= m, n <= 10000 +- There will be at least one free cell for each call to flip. +- At most 1000 calls will be made to flip and reset. + +## 题目大意 + +给你一个 m x n 的二元矩阵 matrix ，且所有值被初始化为 0 。请你设计一个算法，随机选取一个满足 matrix[i][j] == 0 的下标 (i, j) ，并将它的值变为 1 。所有满足 matrix[i][j] == 0 的下标 (i, j) 被选取的概率应当均等。 + +尽量最少调用内置的随机函数，并且优化时间和空间复杂度。 + +实现 Solution 类： + +- Solution(int m, int n) 使用二元矩阵的大小 m 和 n 初始化该对象 +- int[] flip() 返回一个满足 matrix[i][j] == 0 的随机下标 [i, j] ，并将其对应格子中的值变为 1 +- void reset() 将矩阵中所有的值重置为 0 + +## 解题思路 + +- 二维矩阵利用哈希表转换为一维,每次随机选择一维中的任意一个元素，然后与最后一个元素交换，一维元素的总个数减一 +- 哈希表中默认的映射为x->x, 然后将不满足这个映射的特殊键值对存入哈希表 + +## 代码 + +```go +package leetcode + +import "math/rand" + +type Solution struct { + r int + c int + total int + mp map[int]int +} + +func Constructor(m int, n int) Solution { + return Solution{ + r: m, + c: n, + total: m * n, + mp: map[int]int{}, + } +} + +func (this *Solution) Flip() []int { + k := rand.Intn(this.total) + val := k + if v, ok := this.mp[k]; ok { + val = v + } + if _, ok := this.mp[this.total-1]; ok { + this.mp[k] = this.mp[this.total-1] + } else { + this.mp[k] = this.total - 1 + } + delete(this.mp, this.total - 1) + this.total-- + newR, newC := val/this.c, val%this.c + return []int{newR, newC} +} + +func (this *Solution) Reset() { + this.total = this.r * this.c + this.mp = map[int]int{} +} +``` \ No newline at end of file diff --git a/leetcode/0520.Detect-Capital/520.Detect Capital.go b/leetcode/0520.Detect-Capital/520.Detect Capital.go new file mode 100644 index 000000000..c9710484d --- /dev/null +++ b/leetcode/0520.Detect-Capital/520.Detect Capital.go @@ -0,0 +1,13 @@ +package leetcode + +import "strings" + +func detectCapitalUse(word string) bool { + wLower := strings.ToLower(word) + wUpper := strings.ToUpper(word) + wCaptial := strings.ToUpper(string(word[0])) + strings.ToLower(string(word[1:])) + if wCaptial == word || wLower == word || wUpper == word { + return true + } + return false +} diff --git a/leetcode/0520.Detect-Capital/520.Detect Capital_test.go b/leetcode/0520.Detect-Capital/520.Detect Capital_test.go new file mode 100644 index 000000000..20635849b --- /dev/null +++ b/leetcode/0520.Detect-Capital/520.Detect Capital_test.go @@ -0,0 +1,45 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question520 struct { + para520 + ans520 +} + +// para 是参数 +type para520 struct { + word string +} + +// ans 是答案 +type ans520 struct { + ans bool +} + +func Test_Problem520(t *testing.T) { + + qs := []question520{ + + { + para520{"USA"}, + ans520{true}, + }, + + { + para520{"FlaG"}, + ans520{false}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 520------------------------\n") + + for _, q := range qs { + _, p := q.ans520, q.para520 + fmt.Printf("【input】:%v 【output】:%v\n", p, detectCapitalUse(p.word)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0520.Detect-Capital/README.md b/leetcode/0520.Detect-Capital/README.md new file mode 100644 index 000000000..c4532bfd8 --- /dev/null +++ b/leetcode/0520.Detect-Capital/README.md @@ -0,0 +1,68 @@ +# [520. Detect Capital](https://leetcode.com/problems/detect-capital/) + + +## 题目 + +We define the usage of capitals in a word to be right when one of the following cases holds: + +All letters in this word are capitals, like "USA". + +All letters in this word are not capitals, like "leetcode". + +Only the first letter in this word is capital, like "Google". + +Given a string word, return true if the usage of capitals in it is right. + +**Example 1:** + +``` +Input: word = "USA" +Output: true +``` + +**Example 2:** + +``` +Input: word = "FlaG" +Output: false +``` + +**Constraints:** + +- 1 <= word.length <= 100 +- word consists of lowercase and uppercase English letters. + +## 题目大意 + +我们定义，在以下情况时，单词的大写用法是正确的： + +全部字母都是大写，比如 "USA" 。 +单词中所有字母都不是大写，比如 "leetcode" 。 +如果单词不只含有一个字母，只有首字母大写，比如"Google" 。 + +给你一个字符串 word 。如果大写用法正确，返回 true ；否则，返回 false 。 + +## 解题思路 + +- 把 word 分别转换为全部小写 wLower，全部大写 wUpper，首字母大写的字符串 wCaptial +- 判断 word 是否等于 wLower, wUpper, wCaptial 中的一个，如果是返回 true，否则返回 false + +## 代码 + +```go + +package leetcode + +import "strings" + +func detectCapitalUse(word string) bool { + wLower := strings.ToLower(word) + wUpper := strings.ToUpper(word) + wCaptial := strings.ToUpper(string(word[0])) + strings.ToLower(string(word[1:])) + if wCaptial == word || wLower == word || wUpper == word { + return true + } + return false +} + +``` \ No newline at end of file diff --git a/leetcode/0523.Continuous-Subarray-Sum/523. Continuous Subarray Sum.go b/leetcode/0523.Continuous-Subarray-Sum/523. Continuous Subarray Sum.go new file mode 100644 index 000000000..15b23937d --- /dev/null +++ b/leetcode/0523.Continuous-Subarray-Sum/523. Continuous Subarray Sum.go @@ -0,0 +1,18 @@ +package leetcode + +func checkSubarraySum(nums []int, k int) bool { + m := make(map[int]int) + m[0] = -1 + sum := 0 + for i, n := range nums { + sum += n + if r, ok := m[sum%k]; ok { + if i-2 >= r { + return true + } + } else { + m[sum%k] = i + } + } + return false +} diff --git a/leetcode/0523.Continuous-Subarray-Sum/523. Continuous Subarray Sum_test.go b/leetcode/0523.Continuous-Subarray-Sum/523. Continuous Subarray Sum_test.go new file mode 100644 index 000000000..f3147e166 --- /dev/null +++ b/leetcode/0523.Continuous-Subarray-Sum/523. Continuous Subarray Sum_test.go @@ -0,0 +1,53 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question523 struct { + para523 + ans523 +} + +// para 是参数 +// one 代表第一个参数 +type para523 struct { + nums []int + k int +} + +// ans 是答案 +// one 代表第一个答案 +type ans523 struct { + one bool +} + +func Test_Problem523(t *testing.T) { + + qs := []question523{ + + { + para523{[]int{23, 2, 4, 6, 7}, 6}, + ans523{true}, + }, + + { + para523{[]int{23, 2, 6, 4, 7}, 6}, + ans523{true}, + }, + + { + para523{[]int{23, 2, 6, 4, 7}, 13}, + ans523{false}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 523------------------------\n") + + for _, q := range qs { + _, p := q.ans523, q.para523 + fmt.Printf("【input】:%v 【output】:%v\n", p, checkSubarraySum(p.nums, p.k)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0523.Continuous-Subarray-Sum/README.md b/leetcode/0523.Continuous-Subarray-Sum/README.md new file mode 100644 index 000000000..ac6d2df61 --- /dev/null +++ b/leetcode/0523.Continuous-Subarray-Sum/README.md @@ -0,0 +1,75 @@ +# [523. Continuous Subarray Sum](https://leetcode.com/problems/continuous-subarray-sum/) + + +## 题目 + +Given an integer array `nums` and an integer `k`, return `true` *if* `nums` *has a continuous subarray of size **at least two** whose elements sum up to a multiple of* `k`*, or* `false` *otherwise*. + +An integer `x` is a multiple of `k` if there exists an integer `n` such that `x = n * k`. `0` is **always** a multiple of `k`. + +**Example 1:** + +``` +Input: nums = [23,2,4,6,7], k = 6 +Output: true +Explanation: [2, 4] is a continuous subarray of size 2 whose elements sum up to 6. +``` + +**Example 2:** + +``` +Input: nums = [23,2,6,4,7], k = 6 +Output: true +Explanation: [23, 2, 6, 4, 7] is an continuous subarray of size 5 whose elements sum up to 42. +42 is a multiple of 6 because 42 = 7 * 6 and 7 is an integer. +``` + +**Example 3:** + +``` +Input: nums = [23,2,6,4,7], k = 13 +Output: false +``` + +**Constraints:** + +- `1 <= nums.length <= 105` +- `0 <= nums[i] <= 109` +- `0 <= sum(nums[i]) <= 231 - 1` +- `1 <= k <= 231 - 1` + +## 题目大意 + +给你一个整数数组 nums 和一个整数 k ，编写一个函数来判断该数组是否含有同时满足下述条件的连续子数组： + +- 子数组大小至少为 2 ，且 +- 子数组元素总和为 k 的倍数。 + +如果存在，返回 true ；否则，返回 false 。如果存在一个整数 n ，令整数 x 符合 x = n * k ，则称 x 是 k 的一个倍数。 + +## 解题思路 + +- 简单题。题目只要求是否存在，不要求找出所有解。用一个变量 sum 记录累加和。子数组的元素和可以用前缀和相减得到，例如 [i,j] 区间内的元素和，可以由 prefixSum[j] - prefixSum[i] 得到。当 prefixSums[j]−prefixSums[i] 为 k 的倍数时，prefixSums[i] 和 prefixSums[j] 除以 k 的余数相同。因此只需要计算每个下标对应的前缀和除以 k 的余数即可，使用 map 存储每个余数第一次出现的下标即可。在 map 中如果存在相同余数的 key，代表当前下标和 map 中这个 key 记录的下标可以满足总和为 k 的倍数这一条件。再判断一下能否满足大小至少为 2 的条件即可。用 2 个下标相减，长度大于等于 2 即满足条件，可以输出 true。 + +## 代码 + +```go +package leetcode + +func checkSubarraySum(nums []int, k int) bool { + m := make(map[int]int) + m[0] = -1 + sum := 0 + for i, n := range nums { + sum += n + if r, ok := m[sum%k]; ok { + if i-2 >= r { + return true + } + } else { + m[sum%k] = i + } + } + return false +} +``` \ No newline at end of file diff --git a/leetcode/0525.Contiguous-Array/525. Contiguous Array.go b/leetcode/0525.Contiguous-Array/525. Contiguous Array.go new file mode 100644 index 000000000..802a3be9a --- /dev/null +++ b/leetcode/0525.Contiguous-Array/525. Contiguous Array.go @@ -0,0 +1,27 @@ +package leetcode + +func findMaxLength(nums []int) int { + dict := map[int]int{} + dict[0] = -1 + count, res := 0, 0 + for i := 0; i < len(nums); i++ { + if nums[i] == 0 { + count-- + } else { + count++ + } + if idx, ok := dict[count]; ok { + res = max(res, i-idx) + } else { + dict[count] = i + } + } + return res +} + +func max(a, b int) int { + if a > b { + return a + } + return b +} diff --git a/leetcode/0525.Contiguous-Array/525. Contiguous Array_test.go b/leetcode/0525.Contiguous-Array/525. Contiguous Array_test.go new file mode 100644 index 000000000..644885d15 --- /dev/null +++ b/leetcode/0525.Contiguous-Array/525. Contiguous Array_test.go @@ -0,0 +1,47 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question525 struct { + para525 + ans525 +} + +// para 是参数 +// one 代表第一个参数 +type para525 struct { + nums []int +} + +// ans 是答案 +// one 代表第一个答案 +type ans525 struct { + one int +} + +func Test_Problem525(t *testing.T) { + + qs := []question525{ + + { + para525{[]int{0, 1}}, + ans525{2}, + }, + + { + para525{[]int{0, 1, 0}}, + ans525{2}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 525------------------------\n") + + for _, q := range qs { + _, p := q.ans525, q.para525 + fmt.Printf("【input】:%v 【output】:%v\n", p, findMaxLength(p.nums)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0525.Contiguous-Array/README.md b/leetcode/0525.Contiguous-Array/README.md new file mode 100644 index 000000000..7f1dbf157 --- /dev/null +++ b/leetcode/0525.Contiguous-Array/README.md @@ -0,0 +1,67 @@ +# [525. Contiguous Array](https://leetcode.com/problems/contiguous-array/) + + +## 题目 + +Given a binary array `nums`, return *the maximum length of a contiguous subarray with an equal number of* `0` *and* `1`. + +**Example 1:** + +``` +Input: nums = [0,1] +Output: 2 +Explanation: [0, 1] is the longest contiguous subarray with an equal number of 0 and 1. +``` + +**Example 2:** + +``` +Input: nums = [0,1,0] +Output: 2 +Explanation: [0, 1] (or [1, 0]) is a longest contiguous subarray with equal number of 0 and 1. +``` + +**Constraints:** + +- `1 <= nums.length <= 105` +- `nums[i]` is either `0` or `1`. + +## 题目大意 + +给定一个二进制数组 nums , 找到含有相同数量的 0 和 1 的最长连续子数组，并返回该子数组的长度。 + +## 解题思路 + +- 0 和 1 的数量相同可以转化为两者数量相差为 0，如果将 0 看作为 -1，那么原题转化为求最长连续子数组，其元素和为 0 。又变成了区间内求和的问题，自然而然转换为前缀和来处理。假设连续子数组是 [i,j] 区间，这个区间内元素和为 0 意味着 prefixSum[j] - prefixSum[i] = 0，也就是 prefixSum[i] = prefixSum[j]。不断累加前缀和，将每个前缀和存入 map 中。一旦某个 key 存在了，代表之前某个下标的前缀和和当前下标构成的区间，这段区间内的元素和为 0 。这个区间是所求。扫完整个数组，扫描过程中动态更新最大区间长度，扫描完成便可得到最大区间长度，即最长连续子数组。 + +## 代码 + +```go +package leetcode + +func findMaxLength(nums []int) int { + dict := map[int]int{} + dict[0] = -1 + count, res := 0, 0 + for i := 0; i < len(nums); i++ { + if nums[i] == 0 { + count-- + } else { + count++ + } + if idx, ok := dict[count]; ok { + res = max(res, i-idx) + } else { + dict[count] = i + } + } + return res +} + +func max(a, b int) int { + if a > b { + return a + } + return b +} +``` \ No newline at end of file diff --git a/leetcode/0529.Minesweeper/529. Minesweeper.go b/leetcode/0529.Minesweeper/529. Minesweeper.go index aef5d2b86..786405ee7 100644 --- a/leetcode/0529.Minesweeper/529. Minesweeper.go +++ b/leetcode/0529.Minesweeper/529. Minesweeper.go @@ -16,48 +16,31 @@ func updateBoard(board [][]byte, click []int) [][]byte { board[click[0]][click[1]] = 'X' return board } + dfs(board, click[0], click[1]) + return board +} - mineMap := make([][]int, len(board)) - for i := range board { - mineMap[i] = make([]int, len(board[i])) +func dfs(board [][]byte, x, y int) { + cnt := 0 + for i := 0; i < 8; i++ { + nx, ny := x+dir8[i][0], y+dir8[i][1] + if isInBoard(board, nx, ny) && board[nx][ny] == 'M' { + cnt++ + } } - - for i := range board { - for j := range board[i] { - if board[i][j] == 'M' { - mineMap[i][j] = -1 - for _, d := range dir8 { - nx, ny := i+d[0], j+d[1] - if isInBoard(board, nx, ny) && mineMap[nx][ny] >= 0 { - mineMap[nx][ny]++ - } - } - } + if cnt > 0 { + board[x][y] = byte(cnt + '0') + return + } + board[x][y] = 'B' + for i := 0; i < 8; i++ { + nx, ny := x+dir8[i][0], y+dir8[i][1] + if isInBoard(board, nx, ny) && board[nx][ny] != 'B' { + dfs(board, nx, ny) } } - mineSweeper(click[0], click[1], board, mineMap, dir8) - return board } func isInBoard(board [][]byte, x, y int) bool { return x >= 0 && x < len(board) && y >= 0 && y < len(board[0]) } - -func mineSweeper(x, y int, board [][]byte, mineMap [][]int, dir8 [][]int) { - if board[x][y] != 'M' && board[x][y] != 'E' { - return - } - if mineMap[x][y] == -1 { - board[x][y] = 'X' - } else if mineMap[x][y] > 0 { - board[x][y] = '0' + byte(mineMap[x][y]) - } else { - board[x][y] = 'B' - for _, d := range dir8 { - nx, ny := x+d[0], y+d[1] - if isInBoard(board, nx, ny) && mineMap[nx][ny] >= 0 { - mineSweeper(nx, ny, board, mineMap, dir8) - } - } - } -} diff --git a/leetcode/0529.Minesweeper/README.md b/leetcode/0529.Minesweeper/README.md index f2166a692..d25c79c50 100644 --- a/leetcode/0529.Minesweeper/README.md +++ b/leetcode/0529.Minesweeper/README.md @@ -103,43 +103,33 @@ func updateBoard(board [][]byte, click []int) [][]byte { board[click[0]][click[1]] = 'X' return board } - mineMap := make([][]int, len(board)) - for i := range board { - mineMap[i] = make([]int, len(board[i])) - } - for i := range board { - for j := range board[i] { - if board[i][j] == 'M' { - mineMap[i][j] = -1 - for _, d := range dir8 { - nx, ny := i+d[0], j+d[1] - if isInBoard(board, nx, ny) && mineMap[nx][ny] >= 0 { - mineMap[nx][ny]++ - } - } - } - } - } - mineSweeper(click[0], click[1], board, mineMap, dir8) + dfs(board, click[0], click[1]) return board } -func mineSweeper(x, y int, board [][]byte, mineMap [][]int, dir8 [][]int) { - if board[x][y] != 'M' && board[x][y] != 'E' { +func dfs(board [][]byte, x, y int) { + cnt := 0 + for i := 0; i < 8; i++ { + nx, ny := x+dir8[i][0], y+dir8[i][1] + if isInBoard(board, nx, ny) && board[nx][ny] == 'M' { + cnt++ + + } + } + if cnt > 0 { + board[x][y] = byte(cnt + '0') return } - if mineMap[x][y] == -1 { - board[x][y] = 'X' - } else if mineMap[x][y] > 0 { - board[x][y] = '0' + byte(mineMap[x][y]) - } else { - board[x][y] = 'B' - for _, d := range dir8 { - nx, ny := x+d[0], y+d[1] - if isInBoard(board, nx, ny) && mineMap[nx][ny] >= 0 { - mineSweeper(nx, ny, board, mineMap, dir8) - } + board[x][y] = 'B' + for i := 0; i < 8; i++ { + nx, ny := x+dir8[i][0], y+dir8[i][1] + if isInBoard(board, nx, ny) && board[nx][ny] != 'B' { + dfs(board, nx, ny) } } } + +func isInBoard(board [][]byte, x, y int) bool { + return x >= 0 && x < len(board) && y >= 0 && y < len(board[0]) +} ``` \ No newline at end of file diff --git a/leetcode/0540.Single-Element-in-a-Sorted-Array/540.Single Element in a Sorted Array.go b/leetcode/0540.Single-Element-in-a-Sorted-Array/540.Single Element in a Sorted Array.go new file mode 100644 index 000000000..dc718044f --- /dev/null +++ b/leetcode/0540.Single-Element-in-a-Sorted-Array/540.Single Element in a Sorted Array.go @@ -0,0 +1,22 @@ +package leetcode + +func singleNonDuplicate(nums []int) int { + left, right := 0, len(nums)-1 + for left < right { + mid := (left + right) / 2 + if mid%2 == 0 { + if nums[mid] == nums[mid+1] { + left = mid + 1 + } else { + right = mid + } + } else { + if nums[mid] == nums[mid-1] { + left = mid + 1 + } else { + right = mid + } + } + } + return nums[left] +} diff --git a/leetcode/0540.Single-Element-in-a-Sorted-Array/540.Single Element in a Sorted Array_test.go b/leetcode/0540.Single-Element-in-a-Sorted-Array/540.Single Element in a Sorted Array_test.go new file mode 100644 index 000000000..77871f6b0 --- /dev/null +++ b/leetcode/0540.Single-Element-in-a-Sorted-Array/540.Single Element in a Sorted Array_test.go @@ -0,0 +1,46 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question540 struct { + para540 + ans540 +} + +// para 是参数 +type para540 struct { + nums []int +} + +// ans 是答案 +type ans540 struct { + ans int +} + +func Test_Problem540(t *testing.T) { + + qs := []question540{ + + { + para540{[]int{1, 1, 2, 3, 3, 4, 4, 8, 8}}, + ans540{2}, + }, + + { + para540{[]int{3, 3, 7, 7, 10, 11, 11}}, + ans540{10}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 540------------------------\n") + + for _, q := range qs { + _, p := q.ans540, q.para540 + fmt.Printf("【input】:%v ", p.nums) + fmt.Printf("【output】:%v \n", singleNonDuplicate(p.nums)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0540.Single-Element-in-a-Sorted-Array/README.md b/leetcode/0540.Single-Element-in-a-Sorted-Array/README.md new file mode 100644 index 000000000..e9a6e2cdf --- /dev/null +++ b/leetcode/0540.Single-Element-in-a-Sorted-Array/README.md @@ -0,0 +1,64 @@ +# [540. Single Element in a Sorted Array](https://leetcode.com/problems/single-element-in-a-sorted-array/) + +## 题目 + +You are given a sorted array consisting of only integers where every element appears exactly twice, except for one element which appears exactly once. + +Return the single element that appears only once. + +Your solution must run in O(log n) time and O(1) space. + +**Example 1:** + + Input: nums = [1,1,2,3,3,4,4,8,8] + Output: 2 + +**Example 2:** + + Input: nums = [3,3,7,7,10,11,11] + Output: 10 + +**Constraints:** + +- 1 <= nums.length <= 100000 +- 0 <= nums[i] <= 100000 + +## 题目大意 + +给你一个仅由整数组成的有序数组，其中每个元素都会出现两次，唯有一个数只会出现一次。 + +请你找出并返回只出现一次的那个数。 + +你设计的解决方案必须满足 O(log n) 时间复杂度和 O(1) 空间复杂度。 + +## 解题思路 + + 假设下标idx是单独的数字,idx左边的偶数下标x有nums[x] == nums[x + 1], + idx右边的奇数下标y有nums[y] == nums[y + 1],可以根据此特性用二分查找idx对应的值 + +## 代码 + +```go +package leetcode + +func singleNonDuplicate(nums []int) int { + left, right := 0, len(nums)-1 + for left < right { + mid := (left + right) / 2 + if mid%2 == 0 { + if nums[mid] == nums[mid+1] { + left = mid + 1 + } else { + right = mid + } + } else { + if nums[mid] == nums[mid-1] { + left = mid + 1 + } else { + right = mid + } + } + } + return nums[left] +} +``` diff --git a/leetcode/0543.Diameter-of-Binary-Tree/543. Diameter of Binary Tree.go b/leetcode/0543.Diameter-of-Binary-Tree/543. Diameter of Binary Tree.go new file mode 100644 index 000000000..14041158f --- /dev/null +++ b/leetcode/0543.Diameter-of-Binary-Tree/543. Diameter of Binary Tree.go @@ -0,0 +1,40 @@ +package leetcode + +import ( + "github.com/halfrost/LeetCode-Go/structures" +) + +// TreeNode define +type TreeNode = structures.TreeNode + +/** + * Definition for a binary tree node. + * type TreeNode struct { + * Val int + * Left *TreeNode + * Right *TreeNode + * } + */ + +func diameterOfBinaryTree(root *TreeNode) int { + result := 0 + checkDiameter(root, &result) + return result +} + +func checkDiameter(root *TreeNode, result *int) int { + if root == nil { + return 0 + } + left := checkDiameter(root.Left, result) + right := checkDiameter(root.Right, result) + *result = max(*result, left+right) + return max(left, right) + 1 +} + +func max(a int, b int) int { + if a > b { + return a + } + return b +} diff --git a/leetcode/0543.Diameter-of-Binary-Tree/543. Diameter of Binary Tree_test.go b/leetcode/0543.Diameter-of-Binary-Tree/543. Diameter of Binary Tree_test.go new file mode 100644 index 000000000..e88d3aa02 --- /dev/null +++ b/leetcode/0543.Diameter-of-Binary-Tree/543. Diameter of Binary Tree_test.go @@ -0,0 +1,56 @@ +package leetcode + +import ( + "fmt" + "testing" + + "github.com/halfrost/LeetCode-Go/structures" +) + +type question543 struct { + para543 + ans543 +} + +// para 是参数 +// one 代表第一个参数 +type para543 struct { + one []int +} + +// ans 是答案 +// one 代表第一个答案 +type ans543 struct { + one int +} + +func Test_Problem543(t *testing.T) { + + qs := []question543{ + + { + para543{[]int{1, 2, 3, 4, 5}}, + ans543{3}, + }, + + { + para543{[]int{1, 2}}, + ans543{1}, + }, + + { + para543{[]int{4, -7, -3, structures.NULL, structures.NULL, -9, -3, 9, -7, -4, structures.NULL, 6, structures.NULL, -6, -6, structures.NULL, structures.NULL, 0, 6, 5, structures.NULL, 9, structures.NULL, structures.NULL, -1, -4, structures.NULL, structures.NULL, structures.NULL, -2}}, + ans543{8}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 543------------------------\n") + + for _, q := range qs { + _, p := q.ans543, q.para543 + fmt.Printf("【input】:%v ", p) + root := structures.Ints2TreeNode(p.one) + fmt.Printf("【output】:%v \n", diameterOfBinaryTree(root)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0543.Diameter-of-Binary-Tree/README.md b/leetcode/0543.Diameter-of-Binary-Tree/README.md new file mode 100644 index 000000000..78b5655e2 --- /dev/null +++ b/leetcode/0543.Diameter-of-Binary-Tree/README.md @@ -0,0 +1,87 @@ +# [543. Diameter of Binary Tree](https://leetcode.com/problems/diameter-of-binary-tree/) + + +## 题目 + +Given the `root` of a binary tree, return *the length of the **diameter** of the tree*. + +The **diameter** of a binary tree is the **length** of the longest path between any two nodes in a tree. This path may or may not pass through the `root`. + +The **length** of a path between two nodes is represented by the number of edges between them. + +**Example 1:** + +![https://assets.leetcode.com/uploads/2021/03/06/diamtree.jpg](https://assets.leetcode.com/uploads/2021/03/06/diamtree.jpg) + +``` +Input: root = [1,2,3,4,5] +Output: 3 +Explanation: 3 is the length of the path [4,2,1,3] or [5,2,1,3]. + +``` + +**Example 2:** + +``` +Input: root = [1,2] +Output: 1 + +``` + +**Constraints:** + +- The number of nodes in the tree is in the range `[1, 104]`. +- `100 <= Node.val <= 100` + +## 题目大意 + +给定一棵二叉树，你需要计算它的直径长度。一棵二叉树的直径长度是任意两个结点路径长度中的最大值。这条路径可能穿过也可能不穿过根结点。 + +## 解题思路 + +- 简单题。遍历每个节点的左子树和右子树，累加从左子树到右子树的最大长度。遍历每个节点时，动态更新这个最大长度即可。 + +## 代码 + +```go +package leetcode + +import ( + "github.com/halfrost/LeetCode-Go/structures" +) + +// TreeNode define +type TreeNode = structures.TreeNode + +/** + * Definition for a binary tree node. + * type TreeNode struct { + * Val int + * Left *TreeNode + * Right *TreeNode + * } + */ + +func diameterOfBinaryTree(root *TreeNode) int { + result := 0 + checkDiameter(root, &result) + return result +} + +func checkDiameter(root *TreeNode, result *int) int { + if root == nil { + return 0 + } + left := checkDiameter(root.Left, result) + right := checkDiameter(root.Right, result) + *result = max(*result, left+right) + return max(left, right) + 1 +} + +func max(a int, b int) int { + if a > b { + return a + } + return b +} +``` \ No newline at end of file diff --git a/leetcode/0551.Student-Attendance-Record-I/551.Student Attendance Record I.go b/leetcode/0551.Student-Attendance-Record-I/551.Student Attendance Record I.go new file mode 100644 index 000000000..a47630c22 --- /dev/null +++ b/leetcode/0551.Student-Attendance-Record-I/551.Student Attendance Record I.go @@ -0,0 +1,22 @@ +package leetcode + +func checkRecord(s string) bool { + numsA, maxL, numsL := 0, 0, 0 + for _, v := range s { + if v == 'L' { + numsL++ + } else { + if numsL > maxL { + maxL = numsL + } + numsL = 0 + if v == 'A' { + numsA++ + } + } + } + if numsL > maxL { + maxL = numsL + } + return numsA < 2 && maxL < 3 +} diff --git a/leetcode/0551.Student-Attendance-Record-I/551.Student Attendance Record I_test.go b/leetcode/0551.Student-Attendance-Record-I/551.Student Attendance Record I_test.go new file mode 100644 index 000000000..cc9ace7a5 --- /dev/null +++ b/leetcode/0551.Student-Attendance-Record-I/551.Student Attendance Record I_test.go @@ -0,0 +1,45 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question551 struct { + para551 + ans551 +} + +// para 是参数 +type para551 struct { + s string +} + +// ans 是答案 +type ans551 struct { + ans bool +} + +func Test_Problem551(t *testing.T) { + + qs := []question551{ + + { + para551{"PPALLP"}, + ans551{true}, + }, + + { + para551{"PPALLL"}, + ans551{false}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 551------------------------\n") + + for _, q := range qs { + _, p := q.ans551, q.para551 + fmt.Printf("【input】:%v 【output】:%v \n", p, checkRecord(p.s)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0551.Student-Attendance-Record-I/README.md b/leetcode/0551.Student-Attendance-Record-I/README.md new file mode 100644 index 000000000..fe8a01616 --- /dev/null +++ b/leetcode/0551.Student-Attendance-Record-I/README.md @@ -0,0 +1,86 @@ +# [551. Student Attendance Record I](https://leetcode.com/problems/student-attendance-record-i/) + +## 题目 + +You are given a string `s` representing an attendance record for a student where each character signifies whether the student was absent, late, or present on that day. The record only contains the following three characters: + +- `'A'`: Absent. +- `'L'`: Late. +- `'P'`: Present. + +The student is eligible for an attendance award if they meet **both** of the following criteria: + +- The student was absent (`'A'`) for **strictly** fewer than 2 days **total**. +- The student was **never** late (`'L'`) for 3 or more **consecutive** days. + +Return `true` *if the student is eligible for an attendance award, or* `false` *otherwise*. + +**Example 1:** + +``` +Input: s = "PPALLP" +Output: true +Explanation: The student has fewer than 2 absences and was never late 3 or more consecutive days. + +``` + +**Example 2:** + +``` +Input: s = "PPALLL" +Output: false +Explanation: The student was late 3 consecutive days in the last 3 days, so is not eligible for the award. + +``` + +**Constraints:** + +- `1 <= s.length <= 1000` +- `s[i]` is either `'A'`, `'L'`, or `'P'`. + +## 题目大意 + +给你一个字符串 s 表示一个学生的出勤记录，其中的每个字符用来标记当天的出勤情况（缺勤、迟到、到场）。记录中只含下面三种字符： + +- 'A'：Absent，缺勤 +- 'L'：Late，迟到 +- 'P'：Present，到场 + +如果学生能够 同时 满足下面两个条件，则可以获得出勤奖励： + +- 按 总出勤 计，学生缺勤（'A'）严格 少于两天。 +- 学生 不会 存在 连续 3 天或 连续 3 天以上的迟到（'L'）记录。 + +如果学生可以获得出勤奖励，返回 true ；否则，返回 false 。 + +## 解题思路 + +- 遍历字符串 s 求出 'A' 的总数量和连续 'L' 的最大数量。 +- 比较 'A' 的数量是否小于 2 并且 'L' 的连续最大数量是否小于 3。 + +## 代码 + +```go +package leetcode + +func checkRecord(s string) bool { + numsA, maxL, numsL := 0, 0, 0 + for _, v := range s { + if v == 'L' { + numsL++ + } else { + if numsL > maxL { + maxL = numsL + } + numsL = 0 + if v == 'A' { + numsA++ + } + } + } + if numsL > maxL { + maxL = numsL + } + return numsA < 2 && maxL < 3 +} +``` \ No newline at end of file diff --git a/leetcode/0554.Brick-Wall/554. Brick Wall.go b/leetcode/0554.Brick-Wall/554. Brick Wall.go new file mode 100644 index 000000000..022f22010 --- /dev/null +++ b/leetcode/0554.Brick-Wall/554. Brick Wall.go @@ -0,0 +1,19 @@ +package leetcode + +func leastBricks(wall [][]int) int { + m := make(map[int]int) + for _, row := range wall { + sum := 0 + for i := 0; i < len(row)-1; i++ { + sum += row[i] + m[sum]++ + } + } + max := 0 + for _, v := range m { + if v > max { + max = v + } + } + return len(wall) - max +} diff --git a/leetcode/0554.Brick-Wall/554. Brick Wall_test.go b/leetcode/0554.Brick-Wall/554. Brick Wall_test.go new file mode 100644 index 000000000..00dc2d53c --- /dev/null +++ b/leetcode/0554.Brick-Wall/554. Brick Wall_test.go @@ -0,0 +1,57 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question554 struct { + para554 + ans554 +} + +// para 是参数 +// one 代表第一个参数 +type para554 struct { + wall [][]int +} + +// ans 是答案 +// one 代表第一个答案 +type ans554 struct { + one int +} + +func Test_Problem554(t *testing.T) { + + qs := []question554{ + + { + para554{[][]int{{1, 2, 2, 1}, {3, 1, 2}, {1, 3, 2}, {2, 4}, {3, 1, 2}, {1, 3, 1, 1}}}, + ans554{2}, + }, + + { + para554{[][]int{{1}, {1}, {1}}}, + ans554{3}, + }, + + { + para554{[][]int{{1, 1, 0}, {1, 1, 0}, {0, 0, 1}}}, + ans554{1}, + }, + + { + para554{[][]int{{1, 1, 0}, {1, 1, 1}, {0, 1, 1}}}, + ans554{0}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 554------------------------\n") + + for _, q := range qs { + _, p := q.ans554, q.para554 + fmt.Printf("【input】:%v 【output】:%v\n", p, leastBricks(p.wall)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0554.Brick-Wall/README.md b/leetcode/0554.Brick-Wall/README.md new file mode 100644 index 000000000..0a16d12b8 --- /dev/null +++ b/leetcode/0554.Brick-Wall/README.md @@ -0,0 +1,68 @@ +# [554. Brick Wall](https://leetcode.com/problems/brick-wall/) + +## 题目 + +There is a rectangular brick wall in front of you with `n` rows of bricks. The `ith` row has some number of bricks each of the same height (i.e., one unit) but they can be of different widths. The total width of each row is the same. + +Draw a vertical line from the top to the bottom and cross the least bricks. If your line goes through the edge of a brick, then the brick is not considered as crossed. You cannot draw a line just along one of the two vertical edges of the wall, in which case the line will obviously cross no bricks. + +Given the 2D array `wall` that contains the information about the wall, return *the minimum number of crossed bricks after drawing such a vertical line*. + +**Example 1:** + +![https://assets.leetcode.com/uploads/2021/04/24/cutwall-grid.jpg](https://assets.leetcode.com/uploads/2021/04/24/cutwall-grid.jpg) + +``` +Input: wall = [[1,2,2,1],[3,1,2],[1,3,2],[2,4],[3,1,2],[1,3,1,1]] +Output: 2 + +``` + +**Example 2:** + +``` +Input: wall = [[1],[1],[1]] +Output: 3 + +``` + +**Constraints:** + +- `n == wall.length` +- `1 <= n <= 10^4` +- `1 <= wall[i].length <= 10^4` +- `1 <= sum(wall[i].length) <= 2 * 10^4` +- `sum(wall[i])` is the same for each row `i`. +- `1 <= wall[i][j] <= 2^31 - 1` + +## 题目大意 + +你的面前有一堵矩形的、由 n 行砖块组成的砖墙。这些砖块高度相同（也就是一个单位高）但是宽度不同。每一行砖块的宽度之和应该相等。你现在要画一条 自顶向下 的、穿过 最少 砖块的垂线。如果你画的线只是从砖块的边缘经过，就不算穿过这块砖。你不能沿着墙的两个垂直边缘之一画线，这样显然是没有穿过一块砖的。给你一个二维数组 wall ，该数组包含这堵墙的相关信息。其中，wall[i] 是一个代表从左至右每块砖的宽度的数组。你需要找出怎样画才能使这条线 穿过的砖块数量最少 ，并且返回 穿过的砖块数量 。 + +## 解题思路 + +- 既然穿过砖块中缝不算穿过砖块，那么穿过最少砖块数量一定是穿过很多中缝。按行遍历每一行的砖块，累加每行砖块宽度，将每行砖块“缝”的坐标存在 map 中。最后取出 map 中出现频次最高的缝，即为铅垂线要穿过的地方。墙高减去缝出现的频次，剩下的即为穿过砖块的数量。 + +## 代码 + +```go +package leetcode + +func leastBricks(wall [][]int) int { + m := make(map[int]int) + for _, row := range wall { + sum := 0 + for i := 0; i < len(row)-1; i++ { + sum += row[i] + m[sum]++ + } + } + max := 0 + for _, v := range m { + if v > max { + max = v + } + } + return len(wall) - max +} +``` \ No newline at end of file diff --git a/leetcode/0559.Maximum-Depth-of-N-ary-Tree/559.Maximum Depth of N-ary Tree.go b/leetcode/0559.Maximum-Depth-of-N-ary-Tree/559.Maximum Depth of N-ary Tree.go new file mode 100644 index 000000000..30fbc9439 --- /dev/null +++ b/leetcode/0559.Maximum-Depth-of-N-ary-Tree/559.Maximum Depth of N-ary Tree.go @@ -0,0 +1,32 @@ +package leetcode + +type Node struct { + Val int + Children []*Node +} + +func maxDepth(root *Node) int { + if root == nil { + return 0 + } + return 1 + bfs(root) +} + +func bfs(root *Node) int { + var q []*Node + var depth int + q = append(q, root.Children...) + for len(q) != 0 { + depth++ + length := len(q) + for length != 0 { + ele := q[0] + q = q[1:] + length-- + if ele != nil && len(ele.Children) != 0 { + q = append(q, ele.Children...) + } + } + } + return depth +} diff --git a/leetcode/0559.Maximum-Depth-of-N-ary-Tree/559.Maximum Depth of N-ary Tree_test.go b/leetcode/0559.Maximum-Depth-of-N-ary-Tree/559.Maximum Depth of N-ary Tree_test.go new file mode 100644 index 000000000..90da19b30 --- /dev/null +++ b/leetcode/0559.Maximum-Depth-of-N-ary-Tree/559.Maximum Depth of N-ary Tree_test.go @@ -0,0 +1,60 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question559 struct { + para559 + ans559 +} + +// para 是参数 +type para559 struct { + root *Node +} + +// ans 是答案 +type ans559 struct { + ans int +} + +func Test_Problem559(t *testing.T) { + + qs := []question559{ + + { + para559{&Node{ + Val: 1, + Children: []*Node{ + {Val: 3, Children: []*Node{{Val: 5, Children: nil}, {Val: 6, Children: nil}}}, + {Val: 2, Children: nil}, + {Val: 4, Children: nil}, + }, + }}, + ans559{3}, + }, + + { + para559{&Node{ + Val: 1, + Children: []*Node{ + {Val: 2, Children: nil}, + {Val: 3, Children: []*Node{{Val: 6, Children: nil}, {Val: 7, Children: []*Node{{Val: 11, Children: []*Node{{Val: 14, Children: nil}}}}}}}, + {Val: 4, Children: []*Node{{Val: 8, Children: []*Node{{Val: 12, Children: nil}}}}}, + {Val: 5, Children: []*Node{{Val: 9, Children: []*Node{{Val: 13, Children: nil}}}, {Val: 10, Children: nil}}}, + }, + }}, + ans559{5}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 559------------------------\n") + + for _, q := range qs { + _, p := q.ans559, q.para559 + fmt.Printf("【input】:%v 【output】:%v\n", p, maxDepth(p.root)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0559.Maximum-Depth-of-N-ary-Tree/README.md b/leetcode/0559.Maximum-Depth-of-N-ary-Tree/README.md new file mode 100644 index 000000000..9cb575096 --- /dev/null +++ b/leetcode/0559.Maximum-Depth-of-N-ary-Tree/README.md @@ -0,0 +1,78 @@ +# [559. Maximum Depth of N-ary Tree](https://leetcode.com/problems/maximum-depth-of-n-ary-tree/) + +## 题目 + +Given a n-ary tree, find its maximum depth. + +The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. + +Nary-Tree input serialization is represented in their level order traversal, each group of children is separated by the null value (See examples). + +**Example 1**: + +![https://assets.leetcode.com/uploads/2018/10/12/narytreeexample.png](https://assets.leetcode.com/uploads/2018/10/12/narytreeexample.png) + + Input: root = [1,null,3,2,4,null,5,6] + Output: 3 + +**Example 2**: + +![https://assets.leetcode.com/uploads/2019/11/08/sample_4_964.png](https://assets.leetcode.com/uploads/2019/11/08/sample_4_964.png) + + Input: root = [1,null,2,3,4,5,null,null,6,7,null,8,null,9,10,null,null,11,null,12,null,13,null,null,14] + Output: 5 + +**Constraints:** + +- The total number of nodes is in the range [0, 10000]. +- The depth of the n-ary tree is less than or equal to 1000. + +## 题目大意 + +给定一个 N 叉树，找到其最大深度。 + +最大深度是指从根节点到最远叶子节点的最长路径上的节点总数。 + +N 叉树输入按层序遍历序列化表示，每组子节点由空值分隔（请参见示例）。 + +## 解题思路 + +- 使用广度优先遍历 + +## 代码 + +```go + +package leetcode + +type Node struct { + Val int + Children []*Node +} + +func maxDepth(root *Node) int { + if root == nil { + return 0 + } + return 1 + bfs(root) +} + +func bfs(root *Node) int { + var q []*Node + var depth int + q = append(q, root.Children...) + for len(q) != 0 { + depth++ + length := len(q) + for length != 0 { + ele := q[0] + q = q[1:] + length-- + if ele != nil && len(ele.Children) != 0 { + q = append(q, ele.Children...) + } + } + } + return depth +} +``` \ No newline at end of file diff --git a/leetcode/0560.Subarray-Sum-Equals-K/560. Subarray Sum Equals K.go b/leetcode/0560.Subarray-Sum-Equals-K/560. Subarray Sum Equals K.go new file mode 100644 index 000000000..0ca17f3a5 --- /dev/null +++ b/leetcode/0560.Subarray-Sum-Equals-K/560. Subarray Sum Equals K.go @@ -0,0 +1,15 @@ +package leetcode + +func subarraySum(nums []int, k int) int { + count, pre := 0, 0 + m := map[int]int{} + m[0] = 1 + for i := 0; i < len(nums); i++ { + pre += nums[i] + if _, ok := m[pre-k]; ok { + count += m[pre-k] + } + m[pre] += 1 + } + return count +} diff --git a/leetcode/0560.Subarray-Sum-Equals-K/560. Subarray Sum Equals K_test.go b/leetcode/0560.Subarray-Sum-Equals-K/560. Subarray Sum Equals K_test.go new file mode 100644 index 000000000..e9edf9557 --- /dev/null +++ b/leetcode/0560.Subarray-Sum-Equals-K/560. Subarray Sum Equals K_test.go @@ -0,0 +1,63 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question560 struct { + para560 + ans560 +} + +// para 是参数 +// one 代表第一个参数 +type para560 struct { + nums []int + k int +} + +// ans 是答案 +// one 代表第一个答案 +type ans560 struct { + one int +} + +func Test_Problem560(t *testing.T) { + + qs := []question560{ + + { + para560{[]int{1, 1, 1}, 2}, + ans560{2}, + }, + + { + para560{[]int{1, 2, 3}, 3}, + ans560{2}, + }, + + { + para560{[]int{1}, 0}, + ans560{0}, + }, + + { + para560{[]int{-1, -1, 1}, 0}, + ans560{1}, + }, + + { + para560{[]int{1, -1, 0}, 0}, + ans560{3}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 560------------------------\n") + + for _, q := range qs { + _, p := q.ans560, q.para560 + fmt.Printf("【input】:%v 【output】:%v\n", p, subarraySum(p.nums, p.k)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0560.Subarray-Sum-Equals-K/README.md b/leetcode/0560.Subarray-Sum-Equals-K/README.md new file mode 100644 index 000000000..13b588cca --- /dev/null +++ b/leetcode/0560.Subarray-Sum-Equals-K/README.md @@ -0,0 +1,58 @@ +# [560. Subarray Sum Equals K](https://leetcode.com/problems/subarray-sum-equals-k/) + + +## 题目 + +Given an array of integers `nums` and an integer `k`, return *the total number of continuous subarrays whose sum equals to `k`*. + +**Example 1:** + +``` +Input: nums = [1,1,1], k = 2 +Output: 2 + +``` + +**Example 2:** + +``` +Input: nums = [1,2,3], k = 3 +Output: 2 + +``` + +**Constraints:** + +- `1 <= nums.length <= 2 * 104` +- `-1000 <= nums[i] <= 1000` +- `-10^7 <= k <= 10^7` + +## 题目大意 + +给你一个整数数组 `nums` 和一个整数 `k` ，请你统计并返回该数组中和为 `k` ****的连续子数组的个数。 + +## 解题思路 + +- 此题不能使用滑动窗口来解。因为 `nums[i]` 可能为负数。 +- 前缀和的思路可以解答此题，但是时间复杂度有点高了，`O(n^2)`。考虑优化时间复杂度。 +- 题目要求找到连续区间和为 `k` 的子区间总数，即区间 `[i,j]` 内的和为 K ⇒ `prefixSum[j] - prefixSum[i-1] == k`。所以 `prefixSum[j] == k - prefixSum[i-1]` 。这样转换以后，题目就转换成类似 A + B = K 的问题了。LeetCode 第一题的优化思路拿来用。用 map 存储累加过的结果。如此优化以后，时间复杂度 `O(n)`。 + +## 代码 + +```go +package leetcode + +func subarraySum(nums []int, k int) int { + count, pre := 0, 0 + m := map[int]int{} + m[0] = 1 + for i := 0; i < len(nums); i++ { + pre += nums[i] + if _, ok := m[pre-k]; ok { + count += m[pre-k] + } + m[pre] += 1 + } + return count +} +``` \ No newline at end of file diff --git a/leetcode/0561.Array-Partition-I/561. Array Partition I.go b/leetcode/0561.Array-Partition/561. Array Partition.go similarity index 100% rename from leetcode/0561.Array-Partition-I/561. Array Partition I.go rename to leetcode/0561.Array-Partition/561. Array Partition.go diff --git a/leetcode/0561.Array-Partition-I/561. Array Partition I_test.go b/leetcode/0561.Array-Partition/561. Array Partition_test.go similarity index 100% rename from leetcode/0561.Array-Partition-I/561. Array Partition I_test.go rename to leetcode/0561.Array-Partition/561. Array Partition_test.go diff --git a/leetcode/0561.Array-Partition-I/README.md b/leetcode/0561.Array-Partition/README.md similarity index 97% rename from leetcode/0561.Array-Partition-I/README.md rename to leetcode/0561.Array-Partition/README.md index d72ea633d..244bec8c9 100644 --- a/leetcode/0561.Array-Partition-I/README.md +++ b/leetcode/0561.Array-Partition/README.md @@ -1,4 +1,4 @@ -# [561. Array Partition I](https://leetcode.com/problems/array-partition-i/) +# [561. Array Partition](https://leetcode.com/problems/array-partition/) ## 题目 diff --git a/leetcode/0563.Binary-Tree-Tilt/563. Binary Tree Tilt.go b/leetcode/0563.Binary-Tree-Tilt/563. Binary Tree Tilt.go index 74aa00974..96127e720 100644 --- a/leetcode/0563.Binary-Tree-Tilt/563. Binary Tree Tilt.go +++ b/leetcode/0563.Binary-Tree-Tilt/563. Binary Tree Tilt.go @@ -1,8 +1,8 @@ package leetcode -import "math" - import ( + "math" + "github.com/halfrost/LeetCode-Go/structures" ) diff --git a/leetcode/0576.Out-of-Boundary-Paths/576. Out of Boundary Paths.go b/leetcode/0576.Out-of-Boundary-Paths/576. Out of Boundary Paths.go new file mode 100644 index 000000000..e14f434da --- /dev/null +++ b/leetcode/0576.Out-of-Boundary-Paths/576. Out of Boundary Paths.go @@ -0,0 +1,43 @@ +package leetcode + +var dir = [][]int{ + {-1, 0}, + {0, 1}, + {1, 0}, + {0, -1}, +} + +func findPaths(m int, n int, maxMove int, startRow int, startColumn int) int { + visited := make([][][]int, m) + for i := range visited { + visited[i] = make([][]int, n) + for j := range visited[i] { + visited[i][j] = make([]int, maxMove+1) + for l := range visited[i][j] { + visited[i][j][l] = -1 + } + } + } + return dfs(startRow, startColumn, maxMove, m, n, visited) +} + +func dfs(x, y, maxMove, m, n int, visited [][][]int) int { + if x < 0 || x >= m || y < 0 || y >= n { + return 1 + } + if maxMove == 0 { + visited[x][y][maxMove] = 0 + return 0 + } + if visited[x][y][maxMove] >= 0 { + return visited[x][y][maxMove] + } + res := 0 + for i := 0; i < 4; i++ { + nx := x + dir[i][0] + ny := y + dir[i][1] + res += (dfs(nx, ny, maxMove-1, m, n, visited) % 1000000007) + } + visited[x][y][maxMove] = res % 1000000007 + return visited[x][y][maxMove] +} diff --git a/leetcode/0576.Out-of-Boundary-Paths/576. Out of Boundary Paths_test.go b/leetcode/0576.Out-of-Boundary-Paths/576. Out of Boundary Paths_test.go new file mode 100644 index 000000000..b88e29e17 --- /dev/null +++ b/leetcode/0576.Out-of-Boundary-Paths/576. Out of Boundary Paths_test.go @@ -0,0 +1,51 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question576 struct { + para576 + ans576 +} + +// para 是参数 +// one 代表第一个参数 +type para576 struct { + m int + n int + maxMove int + startRow int + startColumn int +} + +// ans 是答案 +// one 代表第一个答案 +type ans576 struct { + one int +} + +func Test_Problem576(t *testing.T) { + + qs := []question576{ + + { + para576{2, 2, 2, 0, 0}, + ans576{6}, + }, + + { + para576{1, 3, 3, 0, 1}, + ans576{12}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 576------------------------\n") + + for _, q := range qs { + _, p := q.ans576, q.para576 + fmt.Printf("【input】:%v 【output】:%v\n", p, findPaths(p.m, p.n, p.maxMove, p.startRow, p.startColumn)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0576.Out-of-Boundary-Paths/README.md b/leetcode/0576.Out-of-Boundary-Paths/README.md new file mode 100644 index 000000000..64b74de58 --- /dev/null +++ b/leetcode/0576.Out-of-Boundary-Paths/README.md @@ -0,0 +1,89 @@ +# [576. Out of Boundary Paths](https://leetcode.com/problems/out-of-boundary-paths/) + + +## 题目 + +There is an `m x n` grid with a ball. The ball is initially at the position `[startRow, startColumn]`. You are allowed to move the ball to one of the four adjacent four cells in the grid (possibly out of the grid crossing the grid boundary). You can apply **at most** `maxMove` moves to the ball. + +Given the five integers `m`, `n`, `maxMove`, `startRow`, `startColumn`, return the number of paths to move the ball out of the grid boundary. Since the answer can be very large, return it **modulo** `109 + 7`. + +**Example 1:** + +![https://assets.leetcode.com/uploads/2021/04/28/out_of_boundary_paths_1.png](https://assets.leetcode.com/uploads/2021/04/28/out_of_boundary_paths_1.png) + +``` +Input: m = 2, n = 2, maxMove = 2, startRow = 0, startColumn = 0 +Output: 6 +``` + +**Example 2:** + +![https://assets.leetcode.com/uploads/2021/04/28/out_of_boundary_paths_2.png](https://assets.leetcode.com/uploads/2021/04/28/out_of_boundary_paths_2.png) + +``` +Input: m = 1, n = 3, maxMove = 3, startRow = 0, startColumn = 1 +Output: 12 +``` + +**Constraints:** + +- `1 <= m, n <= 50` +- `0 <= maxMove <= 50` +- `0 <= startRow <= m` +- `0 <= startColumn <= n` + +## 题目大意 + +给定一个 m × n 的网格和一个球。球的起始坐标为 (i,j) ，你可以将球移到相邻的单元格内，或者往上、下、左、右四个方向上移动使球穿过网格边界。但是，你最多可以移动 N 次。找出可以将球移出边界的路径数量。答案可能非常大，返回 结果 mod 109 + 7 的值。 + +## 解题思路 + +- 单纯暴力的思路，在球的每个方向都遍历一步，直到移动步数用完。这样暴力搜索，解空间是 4^n 。优化思路便是增加记忆化。用三维数组记录位置坐标和步数，对应的出边界的路径数量。加上记忆化以后的深搜解法 runtime beats 100% 了。 + +## 代码 + +```go +package leetcode + +var dir = [][]int{ + {-1, 0}, + {0, 1}, + {1, 0}, + {0, -1}, +} + +func findPaths(m int, n int, maxMove int, startRow int, startColumn int) int { + visited := make([][][]int, m) + for i := range visited { + visited[i] = make([][]int, n) + for j := range visited[i] { + visited[i][j] = make([]int, maxMove+1) + for l := range visited[i][j] { + visited[i][j][l] = -1 + } + } + } + return dfs(startRow, startColumn, maxMove, m, n, visited) +} + +func dfs(x, y, maxMove, m, n int, visited [][][]int) int { + if x < 0 || x >= m || y < 0 || y >= n { + return 1 + } + if maxMove == 0 { + visited[x][y][maxMove] = 0 + return 0 + } + if visited[x][y][maxMove] >= 0 { + return visited[x][y][maxMove] + } + res := 0 + for i := 0; i < 4; i++ { + nx := x + dir[i][0] + ny := y + dir[i][1] + res += (dfs(nx, ny, maxMove-1, m, n, visited) % 1000000007) + } + visited[x][y][maxMove] = res % 1000000007 + return visited[x][y][maxMove] +} +``` \ No newline at end of file diff --git a/leetcode/0583.Delete-Operation-for-Two-Strings/583. Delete Operation for Two Strings.go b/leetcode/0583.Delete-Operation-for-Two-Strings/583. Delete Operation for Two Strings.go new file mode 100644 index 000000000..616ddd8c8 --- /dev/null +++ b/leetcode/0583.Delete-Operation-for-Two-Strings/583. Delete Operation for Two Strings.go @@ -0,0 +1,31 @@ +package leetcode + +func minDistance(word1 string, word2 string) int { + dp := make([][]int, len(word1)+1) + for i := 0; i < len(word1)+1; i++ { + dp[i] = make([]int, len(word2)+1) + } + for i := 0; i < len(word1)+1; i++ { + dp[i][0] = i + } + for i := 0; i < len(word2)+1; i++ { + dp[0][i] = i + } + for i := 1; i < len(word1)+1; i++ { + for j := 1; j < len(word2)+1; j++ { + if word1[i-1] == word2[j-1] { + dp[i][j] = dp[i-1][j-1] + } else { + dp[i][j] = 1 + min(dp[i][j-1], dp[i-1][j]) + } + } + } + return dp[len(word1)][len(word2)] +} + +func min(x, y int) int { + if x < y { + return x + } + return y +} diff --git a/leetcode/0583.Delete-Operation-for-Two-Strings/583. Delete Operation for Two Strings_test.go b/leetcode/0583.Delete-Operation-for-Two-Strings/583. Delete Operation for Two Strings_test.go new file mode 100644 index 000000000..d8d8c46b2 --- /dev/null +++ b/leetcode/0583.Delete-Operation-for-Two-Strings/583. Delete Operation for Two Strings_test.go @@ -0,0 +1,48 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question583 struct { + para583 + ans583 +} + +// para 是参数 +// one 代表第一个参数 +type para583 struct { + word1 string + word2 string +} + +// ans 是答案 +// one 代表第一个答案 +type ans583 struct { + one int +} + +func Test_Problem583(t *testing.T) { + + qs := []question583{ + + { + para583{"sea", "eat"}, + ans583{2}, + }, + + { + para583{"leetcode", "etco"}, + ans583{4}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 583------------------------\n") + + for _, q := range qs { + _, p := q.ans583, q.para583 + fmt.Printf("【input】:%v 【output】:%v\n", p, minDistance(p.word1, p.word2)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0583.Delete-Operation-for-Two-Strings/README.md b/leetcode/0583.Delete-Operation-for-Two-Strings/README.md new file mode 100644 index 000000000..b55d2fbf3 --- /dev/null +++ b/leetcode/0583.Delete-Operation-for-Two-Strings/README.md @@ -0,0 +1,76 @@ +# [583. Delete Operation for Two Strings](https://leetcode.com/problems/delete-operation-for-two-strings/) + + +## 题目 + +Given two strings `word1` and `word2`, return *the minimum number of **steps** required to make* `word1` *and* `word2` *the same*. + +In one **step**, you can delete exactly one character in either string. + +**Example 1:** + +``` +Input: word1 = "sea", word2 = "eat" +Output: 2 +Explanation: You need one step to make "sea" to "ea" and another step to make "eat" to "ea". +``` + +**Example 2:** + +``` +Input: word1 = "leetcode", word2 = "etco" +Output: 4 +``` + +**Constraints:** + +- `1 <= word1.length, word2.length <= 500` +- `word1` and `word2` consist of only lowercase English letters. + +## 题目大意 + +给定两个单词 word1 和 word2，找到使得 word1 和 word2 相同所需的最小步数，每步可以删除任意一个字符串中的一个字符。 + +## 解题思路 + +- 从题目数据量级判断，此题一定是 O(n^2) 动态规划题。定义 `dp[i][j]` 表示 `word1[:i]` 与 `word2[:j]` 匹配所删除的最少步数。如果 `word1[:i-1]` 与 `word2[:j-1]` 匹配，那么 `dp[i][j] = dp[i-1][j-1]`。如果 `word1[:i-1]` 与 `word2[:j-1]` 不匹配，那么需要考虑删除一次，所以 `dp[i][j] = 1 + min(dp[i][j-1], dp[i-1][j])`。所以动态转移方程是： + + $$dp[i][j] = \left\{\begin{matrix}dp[i-1][j-1]&, word1[i-1] == word2[j-1]\\ 1 + min(dp[i][j-1], dp[i-1][j])&, word1[i-1] \neq word2[j-1]\\\end{matrix}\right.$$ + + 最终答案存储在 `dp[len(word1)][len(word2)]` 中。 + +## 代码 + +```go +package leetcode + +func minDistance(word1 string, word2 string) int { + dp := make([][]int, len(word1)+1) + for i := 0; i < len(word1)+1; i++ { + dp[i] = make([]int, len(word2)+1) + } + for i := 0; i < len(word1)+1; i++ { + dp[i][0] = i + } + for i := 0; i < len(word2)+1; i++ { + dp[0][i] = i + } + for i := 1; i < len(word1)+1; i++ { + for j := 1; j < len(word2)+1; j++ { + if word1[i-1] == word2[j-1] { + dp[i][j] = dp[i-1][j-1] + } else { + dp[i][j] = 1 + min(dp[i][j-1], dp[i-1][j]) + } + } + } + return dp[len(word1)][len(word2)] +} + +func min(x, y int) int { + if x < y { + return x + } + return y +} +``` \ No newline at end of file diff --git a/leetcode/0589.N-ary-Tree-Preorder-Traversal/589. N-ary Tree Preorder Traversal.go b/leetcode/0589.N-ary-Tree-Preorder-Traversal/589. N-ary Tree Preorder Traversal.go index 8daad2aa7..c0059ffd1 100644 --- a/leetcode/0589.N-ary-Tree-Preorder-Traversal/589. N-ary Tree Preorder Traversal.go +++ b/leetcode/0589.N-ary-Tree-Preorder-Traversal/589. N-ary Tree Preorder Traversal.go @@ -1,6 +1,6 @@ package leetcode -// Definition for a Node. +// Definition for a Node. type Node struct { Val int Children []*Node diff --git a/leetcode/0609.Find-Duplicate-File-in-System/609. Find Duplicate File in System.go b/leetcode/0609.Find-Duplicate-File-in-System/609. Find Duplicate File in System.go new file mode 100644 index 000000000..1a7852109 --- /dev/null +++ b/leetcode/0609.Find-Duplicate-File-in-System/609. Find Duplicate File in System.go @@ -0,0 +1,23 @@ +package leetcode + +import "strings" + +func findDuplicate(paths []string) [][]string { + cache := make(map[string][]string) + for _, path := range paths { + parts := strings.Split(path, " ") + dir := parts[0] + for i := 1; i < len(parts); i++ { + bracketPosition := strings.IndexByte(parts[i], '(') + content := parts[i][bracketPosition+1 : len(parts[i])-1] + cache[content] = append(cache[content], dir+"/"+parts[i][:bracketPosition]) + } + } + res := make([][]string, 0, len(cache)) + for _, group := range cache { + if len(group) >= 2 { + res = append(res, group) + } + } + return res +} diff --git a/leetcode/0609.Find-Duplicate-File-in-System/609. Find Duplicate File in System_test.go b/leetcode/0609.Find-Duplicate-File-in-System/609. Find Duplicate File in System_test.go new file mode 100644 index 000000000..f9007fee4 --- /dev/null +++ b/leetcode/0609.Find-Duplicate-File-in-System/609. Find Duplicate File in System_test.go @@ -0,0 +1,47 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question609 struct { + para609 + ans609 +} + +// para 是参数 +// one 代表第一个参数 +type para609 struct { + paths []string +} + +// ans 是答案 +// one 代表第一个答案 +type ans609 struct { + one [][]string +} + +func Test_Problem609(t *testing.T) { + + qs := []question609{ + + { + para609{[]string{"root/a 1.txt(abcd) 2.txt(efgh)", "root/c 3.txt(abcd)", "root/c/d 4.txt(efgh)", "root 4.txt(efgh)"}}, + ans609{[][]string{{"root/a/2.txt", "root/c/d/4.txt", "root/4.txt"}, {"root/a/1.txt", "root/c/3.txt"}}}, + }, + + { + para609{[]string{"root/a 1.txt(abcd) 2.txt(efgh)", "root/c 3.txt(abcd)", "root/c/d 4.txt(efgh)"}}, + ans609{[][]string{{"root/a/2.txt", "root/c/d/4.txt"}, {"root/a/1.txt", "root/c/3.txt"}}}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 609------------------------\n") + + for _, q := range qs { + _, p := q.ans609, q.para609 + fmt.Printf("【input】:%v 【output】:%v\n", p, findDuplicate(p.paths)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0609.Find-Duplicate-File-in-System/README.md b/leetcode/0609.Find-Duplicate-File-in-System/README.md new file mode 100644 index 000000000..28341709a --- /dev/null +++ b/leetcode/0609.Find-Duplicate-File-in-System/README.md @@ -0,0 +1,93 @@ +# [609. Find Duplicate File in System](https://leetcode.com/problems/find-duplicate-file-in-system/) + + +## 题目 + +Given a list `paths` of directory info, including the directory path, and all the files with contents in this directory, return *all the duplicate files in the file system in terms of their paths*. You may return the answer in **any order**. + +A group of duplicate files consists of at least two files that have the same content. + +A single directory info string in the input list has the following format: + +- `"root/d1/d2/.../dm f1.txt(f1_content) f2.txt(f2_content) ... fn.txt(fn_content)"` + +It means there are `n` files `(f1.txt, f2.txt ... fn.txt)` with content `(f1_content, f2_content ... fn_content)` respectively in the directory "`root/d1/d2/.../dm"`. Note that `n >= 1` and `m >= 0`. If `m = 0`, it means the directory is just the root directory. + +The output is a list of groups of duplicate file paths. For each group, it contains all the file paths of the files that have the same content. A file path is a string that has the following format: + +- `"directory_path/file_name.txt"` + +**Example 1:** + +``` +Input: paths = ["root/a 1.txt(abcd) 2.txt(efgh)","root/c 3.txt(abcd)","root/c/d 4.txt(efgh)","root 4.txt(efgh)"] +Output: [["root/a/2.txt","root/c/d/4.txt","root/4.txt"],["root/a/1.txt","root/c/3.txt"]] + +``` + +**Example 2:** + +``` +Input: paths = ["root/a 1.txt(abcd) 2.txt(efgh)","root/c 3.txt(abcd)","root/c/d 4.txt(efgh)"] +Output: [["root/a/2.txt","root/c/d/4.txt"],["root/a/1.txt","root/c/3.txt"]] + +``` + +**Constraints:** + +- `1 <= paths.length <= 2 * 104` +- `1 <= paths[i].length <= 3000` +- `1 <= sum(paths[i].length) <= 5 * 105` +- `paths[i]` consist of English letters, digits, `'/'`, `'.'`, `'('`, `')'`, and `' '`. +- You may assume no files or directories share the same name in the same directory. +- You may assume each given directory info represents a unique directory. A single blank space separates the directory path and file info. + +**Follow up:** + +- Imagine you are given a real file system, how will you search files? DFS or BFS? +- If the file content is very large (GB level), how will you modify your solution? +- If you can only read the file by 1kb each time, how will you modify your solution? +- What is the time complexity of your modified solution? What is the most time-consuming part and memory-consuming part of it? How to optimize? +- How to make sure the duplicated files you find are not false positive? + +## 题目大意 + +给定一个目录信息列表，包括目录路径，以及该目录中的所有包含内容的文件，您需要找到文件系统中的所有重复文件组的路径。一组重复的文件至少包括二个具有完全相同内容的文件。输入列表中的单个目录信息字符串的格式如下：`"root/d1/d2/.../dm f1.txt(f1_content) f2.txt(f2_content) ... fn.txt(fn_content)"`。这意味着有 n 个文件（`f1.txt, f2.txt ... fn.txt` 的内容分别是 `f1_content, f2_content ... fn_content`）在目录 `root/d1/d2/.../dm` 下。注意：n>=1 且 m>=0。如果 m=0，则表示该目录是根目录。该输出是重复文件路径组的列表。对于每个组，它包含具有相同内容的文件的所有文件路径。文件路径是具有下列格式的字符串：`"directory_path/file_name.txt"` + +## 解题思路 + +- 这一题算简单题，考察的是字符串基本操作与 map 的使用。首先通过字符串操作获取目录路径、文件名和文件内容。再使用 map 来寻找重复文件，key 是文件内容，value 是存储路径和文件名的列表。遍历每一个文件，并把它加入 map 中。最后遍历 map，如果一个键对应的值列表的长度大于 1，说明找到了重复文件，可以把这个列表加入到最终答案中。 +- 这道题有价值的地方在 **Follow up** 中。感兴趣的读者可以仔细想想以下几个问题： + 1. 假设您有一个真正的文件系统，您将如何搜索文件？广度搜索还是宽度搜索？ + 2. 如果文件内容非常大（GB级别），您将如何修改您的解决方案？ + 3. 如果每次只能读取 1 kb 的文件，您将如何修改解决方案？ + 4. 修改后的解决方案的时间复杂度是多少？其中最耗时的部分和消耗内存的部分是什么？如何优化？ + 5. 如何确保您发现的重复文件不是误报？ + +## 代码 + +```go +package leetcode + +import "strings" + +func findDuplicate(paths []string) [][]string { + cache := make(map[string][]string) + for _, path := range paths { + parts := strings.Split(path, " ") + dir := parts[0] + for i := 1; i < len(parts); i++ { + bracketPosition := strings.IndexByte(parts[i], '(') + content := parts[i][bracketPosition+1 : len(parts[i])-1] + cache[content] = append(cache[content], dir+"/"+parts[i][:bracketPosition]) + } + } + res := make([][]string, 0, len(cache)) + for _, group := range cache { + if len(group) >= 2 { + res = append(res, group) + } + } + return res +} +``` \ No newline at end of file diff --git a/leetcode/0611.Valid-Triangle-Number/611. Valid Triangle Number.go b/leetcode/0611.Valid-Triangle-Number/611. Valid Triangle Number.go new file mode 100644 index 000000000..69281b72f --- /dev/null +++ b/leetcode/0611.Valid-Triangle-Number/611. Valid Triangle Number.go @@ -0,0 +1,18 @@ +package leetcode + +import "sort" + +func triangleNumber(nums []int) int { + res := 0 + sort.Ints(nums) + for i := 0; i < len(nums)-2; i++ { + k := i + 2 + for j := i + 1; j < len(nums)-1 && nums[i] != 0; j++ { + for k < len(nums) && nums[i]+nums[j] > nums[k] { + k++ + } + res += k - j - 1 + } + } + return res +} diff --git a/leetcode/0611.Valid-Triangle-Number/611. Valid Triangle Number_test.go b/leetcode/0611.Valid-Triangle-Number/611. Valid Triangle Number_test.go new file mode 100644 index 000000000..c7752c1c1 --- /dev/null +++ b/leetcode/0611.Valid-Triangle-Number/611. Valid Triangle Number_test.go @@ -0,0 +1,52 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question611 struct { + para611 + ans611 +} + +// para 是参数 +// one 代表第一个参数 +type para611 struct { + nums []int +} + +// ans 是答案 +// one 代表第一个答案 +type ans611 struct { + one int +} + +func Test_Problem611(t *testing.T) { + + qs := []question611{ + + { + para611{[]int{2, 2, 3, 4}}, + ans611{3}, + }, + + { + para611{[]int{4, 2, 3, 4}}, + ans611{4}, + }, + + { + para611{[]int{0, 0}}, + ans611{0}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 611------------------------\n") + + for _, q := range qs { + _, p := q.ans611, q.para611 + fmt.Printf("【input】:%v 【output】:%v\n", p, triangleNumber(p.nums)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0611.Valid-Triangle-Number/README.md b/leetcode/0611.Valid-Triangle-Number/README.md new file mode 100644 index 000000000..a601ed595 --- /dev/null +++ b/leetcode/0611.Valid-Triangle-Number/README.md @@ -0,0 +1,37 @@ +# [611. Valid Triangle Number](https://leetcode.com/problems/valid-triangle-number/) + +## 题目 + +Given an integer array nums, return the number of triplets chosen from the array that can make triangles if we take them as side lengths of a triangle. + +## 题目大意 + +给定一个包含非负整数的数组，你的任务是统计其中可以组成三角形三条边的三元组个数。 + +## 解题思路 + +- 题意很简单，最容易想到的暴力解法是三重循环，暴力枚举，时间复杂度 O(n^3)。三重循环中最内层的循环可以优化，因为 k 和 i，j 存在关联性。第二层循环 j 从 i + 1 开始循环，k 从 j + 1 = i + 2 开始循环。循环累加 k 的值，直到 `nums[i] + nums[j] > nums[k]`，那么 `[nums[j + 1], nums[k - 1]]` 这个区间内的值都满足条件。满足条件的解个数增加 `k - j - 1` 个。j 再次递增 + 1，此时最内层的 k 不用从 j + 1 开始增加，只用从上次 k 开始增加即可。因为如果 `nums[i] + nums[j] > nums[k]`，如果这个 `nums[i] + nums[j + 1] > nums[m + 1]` 不等式成立，那么 m 一定不小于 k。所以内层循环 k 和 j 加起来的时间复杂度是 O(n)，最外层 i 的循环是 O(n)，这样优化以后，整体时间复杂度是 O(n^2)。 +- 可能有读者有疑问，三角形三条边的组成条件：任意两边之和大于第三边。`a + b > c`，`a + c > b`，`b + c > a`，此处为什么只判断了 `a + b > c` 呢？因为一开始进行了排序处理，使得 `a ≤ b ≤ c`，在这个前提下，`a + c > b`，`b + c > a` 是一定成立的。所以原问题便转化为只需关心 `a + b > c` 这一个不等式是否成立即可。此题的测试用例用有一种特殊情况，那就是其中一条边或者两条边长度为 0，那么 `a + b > c` 这个不等式一定不成立。综上，先排序预处理之后，只需要关心 `a + b > c` 这一个不等式是否成立即可。 + +## 代码 + +```go +package leetcode + +import "sort" + +func triangleNumber(nums []int) int { + res := 0 + sort.Ints(nums) + for i := 0; i < len(nums)-2; i++ { + k := i + 2 + for j := i + 1; j < len(nums)-1 && nums[i] != 0; j++ { + for k < len(nums) && nums[i]+nums[j] > nums[k] { + k++ + } + res += k - j - 1 + } + } + return res +} +``` \ No newline at end of file diff --git a/leetcode/0617.Merge-Two-Binary-Trees/617. Merge Two Binary Trees.go b/leetcode/0617.Merge-Two-Binary-Trees/617. Merge Two Binary Trees.go new file mode 100644 index 000000000..a8d8e631a --- /dev/null +++ b/leetcode/0617.Merge-Two-Binary-Trees/617. Merge Two Binary Trees.go @@ -0,0 +1,30 @@ +package leetcode + +import ( + "github.com/halfrost/LeetCode-Go/structures" +) + +// TreeNode define +type TreeNode = structures.TreeNode + +/** + * Definition for a binary tree node. + * type TreeNode struct { + * Val int + * Left *TreeNode + * Right *TreeNode + * } + */ + +func mergeTrees(root1 *TreeNode, root2 *TreeNode) *TreeNode { + if root1 == nil { + return root2 + } + if root2 == nil { + return root1 + } + root1.Val += root2.Val + root1.Left = mergeTrees(root1.Left, root2.Left) + root1.Right = mergeTrees(root1.Right, root2.Right) + return root1 +} diff --git a/leetcode/0617.Merge-Two-Binary-Trees/617. Merge Two Binary Trees_test.go b/leetcode/0617.Merge-Two-Binary-Trees/617. Merge Two Binary Trees_test.go new file mode 100644 index 000000000..249bd5d87 --- /dev/null +++ b/leetcode/0617.Merge-Two-Binary-Trees/617. Merge Two Binary Trees_test.go @@ -0,0 +1,63 @@ +package leetcode + +import ( + "fmt" + "testing" + + "github.com/halfrost/LeetCode-Go/structures" +) + +type question617 struct { + para617 + ans617 +} + +// para 是参数 +// one 代表第一个参数 +type para617 struct { + one []int + another []int +} + +// ans 是答案 +// one 代表第一个答案 +type ans617 struct { + one []int +} + +func Test_Problem617(t *testing.T) { + + qs := []question617{ + + { + para617{[]int{}, []int{}}, + ans617{[]int{}}, + }, + + { + para617{[]int{}, []int{1}}, + ans617{[]int{1}}, + }, + + { + para617{[]int{1, 3, 2, 5}, []int{2, 1, 3, structures.NULL, 4, structures.NULL, 7}}, + ans617{[]int{3, 4, 5, 5, 4, structures.NULL, 7}}, + }, + + { + para617{[]int{1}, []int{1, 2}}, + ans617{[]int{2, 2}}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 617------------------------\n") + + for _, q := range qs { + _, p := q.ans617, q.para617 + fmt.Printf("【input】:%v ", p) + root1 := structures.Ints2TreeNode(p.one) + root2 := structures.Ints2TreeNode(p.another) + fmt.Printf("【output】:%v \n", mergeTrees(root1, root2)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0617.Merge-Two-Binary-Trees/README.md b/leetcode/0617.Merge-Two-Binary-Trees/README.md new file mode 100644 index 000000000..714ecedbc --- /dev/null +++ b/leetcode/0617.Merge-Two-Binary-Trees/README.md @@ -0,0 +1,80 @@ +# [617. Merge Two Binary Trees](https://leetcode.com/problems/merge-two-binary-trees/) + + +## 题目 + +You are given two binary trees `root1` and `root2`. + +Imagine that when you put one of them to cover the other, some nodes of the two trees are overlapped while the others are not. You need to merge the two trees into a new binary tree. The merge rule is that if two nodes overlap, then sum node values up as the new value of the merged node. Otherwise, the NOT null node will be used as the node of the new tree. + +Return *the merged tree*. + +**Note:** The merging process must start from the root nodes of both trees. + +**Example 1:** + +![https://assets.leetcode.com/uploads/2021/02/05/merge.jpg](https://assets.leetcode.com/uploads/2021/02/05/merge.jpg) + +``` +Input: root1 = [1,3,2,5], root2 = [2,1,3,null,4,null,7] +Output: [3,4,5,5,4,null,7] +``` + +**Example 2:** + +``` +Input: root1 = [1], root2 = [1,2] +Output: [2,2] +``` + +**Constraints:** + +- The number of nodes in both trees is in the range `[0, 2000]`. +- `104 <= Node.val <= 104` + +## 题目大意 + +给定两个二叉树，想象当你将它们中的一个覆盖到另一个上时，两个二叉树的一些节点便会重叠。你需要将他们合并为一个新的二叉树。合并的规则是如果两个节点重叠，那么将他们的值相加作为节点合并后的新值，否则不为 NULL 的节点将直接作为新二叉树的节点。 + +## 解题思路 + +- 简单题。采用深搜的思路，分别从根节点开始同时遍历两个二叉树，并将对应的节点进行合并。两个二叉树的对应节点可能存在以下三种情况： + - 如果两个二叉树的对应节点都为空，则合并后的二叉树的对应节点也为空； + - 如果两个二叉树的对应节点只有一个为空，则合并后的二叉树的对应节点为其中的非空节点； + - 如果两个二叉树的对应节点都不为空，则合并后的二叉树的对应节点的值为两个二叉树的对应节点的值之和，此时需要显性合并两个节点。 +- 对一个节点进行合并之后，还要对该节点的左右子树分别进行合并。用递归实现即可。 + +## 代码 + +```go +package leetcode + +import ( + "github.com/halfrost/LeetCode-Go/structures" +) + +// TreeNode define +type TreeNode = structures.TreeNode + +/** + * Definition for a binary tree node. + * type TreeNode struct { + * Val int + * Left *TreeNode + * Right *TreeNode + * } + */ + +func mergeTrees(root1 *TreeNode, root2 *TreeNode) *TreeNode { + if root1 == nil { + return root2 + } + if root2 == nil { + return root1 + } + root1.Val += root2.Val + root1.Left = mergeTrees(root1.Left, root2.Left) + root1.Right = mergeTrees(root1.Right, root2.Right) + return root1 +} +``` \ No newline at end of file diff --git a/leetcode/0630.Course-Schedule-III/630. Course Schedule III.go b/leetcode/0630.Course-Schedule-III/630. Course Schedule III.go new file mode 100644 index 000000000..2d5101ddc --- /dev/null +++ b/leetcode/0630.Course-Schedule-III/630. Course Schedule III.go @@ -0,0 +1,39 @@ +package leetcode + +import ( + "container/heap" + "sort" +) + +func scheduleCourse(courses [][]int) int { + sort.Slice(courses, func(i, j int) bool { + return courses[i][1] < courses[j][1] + }) + maxHeap, time := &Schedule{}, 0 + heap.Init(maxHeap) + for _, c := range courses { + if time+c[0] <= c[1] { + time += c[0] + heap.Push(maxHeap, c[0]) + } else if (*maxHeap).Len() > 0 && (*maxHeap)[0] > c[0] { + time -= heap.Pop(maxHeap).(int) - c[0] + heap.Push(maxHeap, c[0]) + } + } + return (*maxHeap).Len() +} + +type Schedule []int + +func (s Schedule) Len() int { return len(s) } +func (s Schedule) Less(i, j int) bool { return s[i] > s[j] } +func (s Schedule) Swap(i, j int) { s[i], s[j] = s[j], s[i] } +func (s *Schedule) Pop() interface{} { + n := len(*s) + t := (*s)[n-1] + *s = (*s)[:n-1] + return t +} +func (s *Schedule) Push(x interface{}) { + *s = append(*s, x.(int)) +} diff --git a/leetcode/0630.Course-Schedule-III/630. Course Schedule III_test.go b/leetcode/0630.Course-Schedule-III/630. Course Schedule III_test.go new file mode 100644 index 000000000..fdc727628 --- /dev/null +++ b/leetcode/0630.Course-Schedule-III/630. Course Schedule III_test.go @@ -0,0 +1,42 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question630 struct { + para630 + ans630 +} + +// para 是参数 +// one 代表第一个参数 +type para630 struct { + courses [][]int +} + +// ans 是答案 +// one 代表第一个答案 +type ans630 struct { + one int +} + +func Test_Problem630(t *testing.T) { + + qs := []question630{ + + { + para630{[][]int{{100, 200}, {200, 1300}, {1000, 1250}, {2000, 3200}}}, + ans630{3}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 630------------------------\n") + + for _, q := range qs { + _, p := q.ans630, q.para630 + fmt.Printf("【input】:%v 【output】:%v\n", p, scheduleCourse(p.courses)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0630.Course-Schedule-III/README.md b/leetcode/0630.Course-Schedule-III/README.md new file mode 100644 index 000000000..442777dda --- /dev/null +++ b/leetcode/0630.Course-Schedule-III/README.md @@ -0,0 +1,96 @@ +# [630. Course Schedule III](https://leetcode.com/problems/course-schedule-iii/) + +## 题目 + +There are `n` different online courses numbered from `1` to `n`. You are given an array `courses` where `courses[i] = [durationi, lastDayi]` indicate that the `ith` course should be taken **continuously** for `durationi` days and must be finished before or on `lastDayi`. + +You will start on the `1st` day and you cannot take two or more courses simultaneously. + +Return *the maximum number of courses that you can take*. + +**Example 1:** + +``` +Input: courses = [[100,200],[200,1300],[1000,1250],[2000,3200]] +Output: 3 +Explanation: +There are totally 4 courses, but you can take 3 courses at most: +First, take the 1st course, it costs 100 days so you will finish it on the 100th day, and ready to take the next course on the 101st day. +Second, take the 3rd course, it costs 1000 days so you will finish it on the 1100th day, and ready to take the next course on the 1101st day. +Third, take the 2nd course, it costs 200 days so you will finish it on the 1300th day. +The 4th course cannot be taken now, since you will finish it on the 3300th day, which exceeds the closed date. + +``` + +**Example 2:** + +``` +Input: courses = [[1,2]] +Output: 1 + +``` + +**Example 3:** + +``` +Input: courses = [[3,2],[4,3]] +Output: 0 + +``` + +**Constraints:** + +- `1 <= courses.length <= 104` +- `1 <= durationi, lastDayi <= 104` + +## 题目大意 + +这里有 n 门不同的在线课程，他们按从 1 到 n 编号。每一门课程有一定的持续上课时间（课程时间）t 以及关闭时间第 d 天。一门课要持续学习 t 天直到第 d 天时要完成，你将会从第 1 天开始。给出 n 个在线课程用 (t, d) 对表示。你的任务是找出最多可以修几门课。 + +## 解题思路 + +- 一般选课，任务的题目会涉及排序 + 贪心。此题同样如此。最多修几门课，采用贪心的思路。先将课程结束时间从小到大排序，优先选择结束时间靠前的课程，这样留给后面课程的时间越多，便可以修更多的课。对排好序的课程从前往后选课，不断累积时间。如果选择修当前课程，但是会超时，这时改调整了。对于已经选择的课程，都加入到最大堆中，遇到需要调整时，比较当前待考虑的课程时长是否比(堆中)已经选择课中时长最长的课时长短，即堆顶的课程时长短，剔除 pop 它，再选择这门时长短的课，并加入最大堆中。并更新累积时间。一层循环扫完所有课程，最终最大堆中包含课程的数目便是最多可以修的课程数。 + +## 代码 + +```go +package leetcode + +import ( + "container/heap" + "sort" +) + +func scheduleCourse(courses [][]int) int { + sort.Slice(courses, func(i, j int) bool { + return courses[i][1] < courses[j][1] + }) + maxHeap, time := &Schedule{}, 0 + heap.Init(maxHeap) + for _, c := range courses { + if time+c[0] <= c[1] { + time += c[0] + heap.Push(maxHeap, c[0]) + } else if (*maxHeap).Len() > 0 && (*maxHeap)[0] > c[0] { + time -= heap.Pop(maxHeap).(int) - c[0] + heap.Push(maxHeap, c[0]) + } + } + return (*maxHeap).Len() +} + +type Schedule []int + +func (s Schedule) Len() int { return len(s) } +func (s Schedule) Less(i, j int) bool { return s[i] > s[j] } +func (s Schedule) Swap(i, j int) { s[i], s[j] = s[j], s[i] } +func (s *Schedule) Pop() interface{} { + n := len(*s) + t := (*s)[n-1] + *s = (*s)[:n-1] + return t +} +func (s *Schedule) Push(x interface{}) { + *s = append(*s, x.(int)) +} +``` \ No newline at end of file diff --git a/leetcode/0648.Replace-Words/648. Replace Words.go b/leetcode/0648.Replace-Words/648. Replace Words.go index d742af98f..0d26e0756 100644 --- a/leetcode/0648.Replace-Words/648. Replace Words.go +++ b/leetcode/0648.Replace-Words/648. Replace Words.go @@ -34,7 +34,7 @@ func findWord(roots map[byte][]string, word []byte) bool { return false } -//解法二 Trie +// 解法二 Trie func replaceWords1(dict []string, sentence string) string { trie := Constructor208() for _, v := range dict { diff --git a/leetcode/0653.Two-Sum-IV---Input-is-a-BST/653. Two Sum IV - Input is a BST.go b/leetcode/0653.Two-Sum-IV-Input-is-a-BST/653. Two Sum IV - Input is a BST.go similarity index 100% rename from leetcode/0653.Two-Sum-IV---Input-is-a-BST/653. Two Sum IV - Input is a BST.go rename to leetcode/0653.Two-Sum-IV-Input-is-a-BST/653. Two Sum IV - Input is a BST.go diff --git a/leetcode/0653.Two-Sum-IV---Input-is-a-BST/653. Two Sum IV - Input is a BST_test.go b/leetcode/0653.Two-Sum-IV-Input-is-a-BST/653. Two Sum IV - Input is a BST_test.go similarity index 100% rename from leetcode/0653.Two-Sum-IV---Input-is-a-BST/653. Two Sum IV - Input is a BST_test.go rename to leetcode/0653.Two-Sum-IV-Input-is-a-BST/653. Two Sum IV - Input is a BST_test.go diff --git a/leetcode/0653.Two-Sum-IV---Input-is-a-BST/README.md b/leetcode/0653.Two-Sum-IV-Input-is-a-BST/README.md similarity index 100% rename from leetcode/0653.Two-Sum-IV---Input-is-a-BST/README.md rename to leetcode/0653.Two-Sum-IV-Input-is-a-BST/README.md diff --git a/leetcode/0677.Map-Sum-Pairs/677. Map Sum Pairs.go b/leetcode/0677.Map-Sum-Pairs/677. Map Sum Pairs.go new file mode 100644 index 000000000..e5560741e --- /dev/null +++ b/leetcode/0677.Map-Sum-Pairs/677. Map Sum Pairs.go @@ -0,0 +1,43 @@ +package leetcode + +type MapSum struct { + keys map[string]int +} + +/** Initialize your data structure here. */ +func Constructor() MapSum { + return MapSum{make(map[string]int)} +} + +func (this *MapSum) Insert(key string, val int) { + this.keys[key] = val +} + +func (this *MapSum) Sum(prefix string) int { + prefixAsRunes, res := []rune(prefix), 0 + for key, val := range this.keys { + if len(key) >= len(prefix) { + shouldSum := true + for i, char := range key { + if i >= len(prefixAsRunes) { + break + } + if prefixAsRunes[i] != char { + shouldSum = false + break + } + } + if shouldSum { + res += val + } + } + } + return res +} + +/** + * Your MapSum object will be instantiated and called as such: + * obj := Constructor(); + * obj.Insert(key,val); + * param_2 := obj.Sum(prefix); + */ diff --git a/leetcode/0677.Map-Sum-Pairs/677. Map Sum Pairs_test.go b/leetcode/0677.Map-Sum-Pairs/677. Map Sum Pairs_test.go new file mode 100644 index 000000000..1be9a3e00 --- /dev/null +++ b/leetcode/0677.Map-Sum-Pairs/677. Map Sum Pairs_test.go @@ -0,0 +1,17 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +func Test_Problem677(t *testing.T) { + obj := Constructor() + fmt.Printf("obj = %v\n", obj) + obj.Insert("apple", 3) + fmt.Printf("obj = %v\n", obj) + fmt.Printf("obj.sum = %v\n", obj.Sum("ap")) + obj.Insert("app", 2) + fmt.Printf("obj = %v\n", obj) + fmt.Printf("obj.sum = %v\n", obj.Sum("ap")) +} diff --git a/leetcode/0677.Map-Sum-Pairs/README.md b/leetcode/0677.Map-Sum-Pairs/README.md new file mode 100644 index 000000000..bad5bc124 --- /dev/null +++ b/leetcode/0677.Map-Sum-Pairs/README.md @@ -0,0 +1,100 @@ +# [677. Map Sum Pairs](https://leetcode.com/problems/map-sum-pairs/) + + +## 题目 + +Design a map that allows you to do the following: + +- Maps a string key to a given value. +- Returns the sum of the values that have a key with a prefix equal to a given string. + +Implement the `MapSum` class: + +- `MapSum()` Initializes the `MapSum` object. +- `void insert(String key, int val)` Inserts the `key-val` pair into the map. If the `key` already existed, the original `key-value` pair will be overridden to the new one. +- `int sum(string prefix)` Returns the sum of all the pairs' value whose `key` starts with the `prefix`. + +**Example 1:** + +``` +Input +["MapSum", "insert", "sum", "insert", "sum"] +[[], ["apple", 3], ["ap"], ["app", 2], ["ap"]] +Output +[null, null, 3, null, 5] + +Explanation +MapSum mapSum = new MapSum(); +mapSum.insert("apple", 3); +mapSum.sum("ap"); // return 3 (apple = 3) +mapSum.insert("app", 2); +mapSum.sum("ap"); // return 5 (apple +app = 3 + 2 = 5) + +``` + +**Constraints:** + +- `1 <= key.length, prefix.length <= 50` +- `key` and `prefix` consist of only lowercase English letters. +- `1 <= val <= 1000` +- At most `50` calls will be made to `insert` and `sum`. + +## 题目大意 + +实现一个 MapSum 类，支持两个方法，insert 和 sum： + +- MapSum() 初始化 MapSum 对象 +- void insert(String key, int val) 插入 key-val 键值对，字符串表示键 key ，整数表示值 val 。如果键 key 已经存在，那么原来的键值对将被替代成新的键值对。 +- int sum(string prefix) 返回所有以该前缀 prefix 开头的键 key 的值的总和。 + +## 解题思路 + +- 简单题。用一个 map 存储数据，Insert() 方法即存储 key-value。Sum() 方法即累加满足条件前缀对应的 value。判断是否满足条件，先根据前缀长度来判断，只有长度大于等于 prefix 长度才可能满足要求。如果 key 是具有 prefix 前缀的，那么累加上这个值。最后输出总和即可。 + +## 代码 + +```go +package leetcode + +type MapSum struct { + keys map[string]int +} + +/** Initialize your data structure here. */ +func Constructor() MapSum { + return MapSum{make(map[string]int)} +} + +func (this *MapSum) Insert(key string, val int) { + this.keys[key] = val +} + +func (this *MapSum) Sum(prefix string) int { + prefixAsRunes, res := []rune(prefix), 0 + for key, val := range this.keys { + if len(key) >= len(prefix) { + shouldSum := true + for i, char := range key { + if i >= len(prefixAsRunes) { + break + } + if prefixAsRunes[i] != char { + shouldSum = false + break + } + } + if shouldSum { + res += val + } + } + } + return res +} + +/** + * Your MapSum object will be instantiated and called as such: + * obj := Constructor(); + * obj.Insert(key,val); + * param_2 := obj.Sum(prefix); + */ +``` \ No newline at end of file diff --git a/leetcode/0690.Employee-Importance/690. Employee Importance.go b/leetcode/0690.Employee-Importance/690. Employee Importance.go new file mode 100644 index 000000000..a13ace46d --- /dev/null +++ b/leetcode/0690.Employee-Importance/690. Employee Importance.go @@ -0,0 +1,26 @@ +package leetcode + +type Employee struct { + Id int + Importance int + Subordinates []int +} + +func getImportance(employees []*Employee, id int) int { + m, queue, res := map[int]*Employee{}, []int{id}, 0 + for _, e := range employees { + m[e.Id] = e + } + for len(queue) > 0 { + e := m[queue[0]] + queue = queue[1:] + if e == nil { + continue + } + res += e.Importance + for _, i := range e.Subordinates { + queue = append(queue, i) + } + } + return res +} diff --git a/leetcode/0690.Employee-Importance/690. Employee Importance_test.go b/leetcode/0690.Employee-Importance/690. Employee Importance_test.go new file mode 100644 index 000000000..401a24bb6 --- /dev/null +++ b/leetcode/0690.Employee-Importance/690. Employee Importance_test.go @@ -0,0 +1,43 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question690 struct { + para690 + ans690 +} + +// para 是参数 +// one 代表第一个参数 +type para690 struct { + employees []*Employee + id int +} + +// ans 是答案 +// one 代表第一个答案 +type ans690 struct { + one int +} + +func Test_Problem690(t *testing.T) { + + qs := []question690{ + + { + para690{[]*Employee{{1, 5, []int{2, 3}}, {2, 3, []int{}}, {3, 3, []int{}}}, 1}, + ans690{11}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 690------------------------\n") + + for _, q := range qs { + _, p := q.ans690, q.para690 + fmt.Printf("【input】:%v 【output】:%v\n", p, getImportance(p.employees, p.id)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0690.Employee-Importance/README.md b/leetcode/0690.Employee-Importance/README.md new file mode 100644 index 000000000..24ee99817 --- /dev/null +++ b/leetcode/0690.Employee-Importance/README.md @@ -0,0 +1,62 @@ +# [690. Employee Importance](https://leetcode.com/problems/employee-importance/) + +## 题目 + +You are given a data structure of employee information, which includes the employee's **unique id**, their **importance value** and their **direct** subordinates' id. + +For example, employee 1 is the leader of employee 2, and employee 2 is the leader of employee 3. They have importance value 15, 10 and 5, respectively. Then employee 1 has a data structure like [1, 15, [2]], and employee 2 has [2, 10, [3]], and employee 3 has [3, 5, []]. Note that although employee 3 is also a subordinate of employee 1, the relationship is **not direct**. + +Now given the employee information of a company, and an employee id, you need to return the total importance value of this employee and all their subordinates. + +**Example 1:** + +``` +Input: [[1, 5, [2, 3]], [2, 3, []], [3, 3, []]], 1 +Output: 11 +Explanation: +Employee 1 has importance value 5, and he has two direct subordinates: employee 2 and employee 3. They both have importance value 3. So the total importance value of employee 1 is 5 + 3 + 3 = 11. +``` + +**Note:** + +1. One employee has at most one **direct** leader and may have several subordinates. +2. The maximum number of employees won't exceed 2000. + +## 题目大意 + +给定一个保存员工信息的数据结构，它包含了员工 唯一的 id ，重要度 和 直系下属的 id 。比如，员工 1 是员工 2 的领导，员工 2 是员工 3 的领导。他们相应的重要度为 15 , 10 , 5 。那么员工 1 的数据结构是 [1, 15, [2]] ，员工 2的 数据结构是 [2, 10, [3]] ，员工 3 的数据结构是 [3, 5, []] 。注意虽然员工 3 也是员工 1 的一个下属，但是由于 并不是直系 下属，因此没有体现在员工 1 的数据结构中。现在输入一个公司的所有员工信息，以及单个员工 id ，返回这个员工和他所有下属的重要度之和。 + +## 解题思路 + +- 简单题。根据题意，DFS 或者 BFS 搜索找到所求 id 下属所有员工，累加下属员工的重要度，最后再加上这个员工本身的重要度，即为所求。 + +## 代码 + +```go +package leetcode + +type Employee struct { + Id int + Importance int + Subordinates []int +} + +func getImportance(employees []*Employee, id int) int { + m, queue, res := map[int]*Employee{}, []int{id}, 0 + for _, e := range employees { + m[e.Id] = e + } + for len(queue) > 0 { + e := m[queue[0]] + queue = queue[1:] + if e == nil { + continue + } + res += e.Importance + for _, i := range e.Subordinates { + queue = append(queue, i) + } + } + return res +} +``` \ No newline at end of file diff --git a/leetcode/0692.Top-K-Frequent-Words/692. Top K Frequent Words.go b/leetcode/0692.Top-K-Frequent-Words/692. Top K Frequent Words.go new file mode 100644 index 000000000..4b739ffb2 --- /dev/null +++ b/leetcode/0692.Top-K-Frequent-Words/692. Top K Frequent Words.go @@ -0,0 +1,50 @@ +package leetcode + +import "container/heap" + +func topKFrequent(words []string, k int) []string { + m := map[string]int{} + for _, word := range words { + m[word]++ + } + pq := &PQ{} + heap.Init(pq) + for w, c := range m { + heap.Push(pq, &wordCount{w, c}) + if pq.Len() > k { + heap.Pop(pq) + } + } + res := make([]string, k) + for i := k - 1; i >= 0; i-- { + wc := heap.Pop(pq).(*wordCount) + res[i] = wc.word + } + return res +} + +type wordCount struct { + word string + cnt int +} + +type PQ []*wordCount + +func (pq PQ) Len() int { return len(pq) } +func (pq PQ) Swap(i, j int) { pq[i], pq[j] = pq[j], pq[i] } +func (pq PQ) Less(i, j int) bool { + if pq[i].cnt == pq[j].cnt { + return pq[i].word > pq[j].word + } + return pq[i].cnt < pq[j].cnt +} +func (pq *PQ) Push(x interface{}) { + tmp := x.(*wordCount) + *pq = append(*pq, tmp) +} +func (pq *PQ) Pop() interface{} { + n := len(*pq) + tmp := (*pq)[n-1] + *pq = (*pq)[:n-1] + return tmp +} diff --git a/leetcode/0692.Top-K-Frequent-Words/692. Top K Frequent Words_test.go b/leetcode/0692.Top-K-Frequent-Words/692. Top K Frequent Words_test.go new file mode 100644 index 000000000..97221e3ef --- /dev/null +++ b/leetcode/0692.Top-K-Frequent-Words/692. Top K Frequent Words_test.go @@ -0,0 +1,48 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question692 struct { + para692 + ans692 +} + +// para 是参数 +// one 代表第一个参数 +type para692 struct { + words []string + k int +} + +// ans 是答案 +// one 代表第一个答案 +type ans692 struct { + one []string +} + +func Test_Problem692(t *testing.T) { + + qs := []question692{ + + { + para692{[]string{"i", "love", "leetcode", "i", "love", "coding"}, 2}, + ans692{[]string{"i", "love"}}, + }, + + { + para692{[]string{"the", "day", "is", "sunny", "the", "the", "the", "sunny", "is", "is"}, 4}, + ans692{[]string{"the", "is", "sunny", "day"}}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 692------------------------\n") + + for _, q := range qs { + _, p := q.ans692, q.para692 + fmt.Printf("【input】:%v 【output】:%v\n", p, topKFrequent(p.words, p.k)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0692.Top-K-Frequent-Words/README.md b/leetcode/0692.Top-K-Frequent-Words/README.md new file mode 100644 index 000000000..54a858d32 --- /dev/null +++ b/leetcode/0692.Top-K-Frequent-Words/README.md @@ -0,0 +1,98 @@ +# [692. Top K Frequent Words](https://leetcode.com/problems/top-k-frequent-words/) + + +## 题目 + +Given a non-empty list of words, return the k most frequent elements. + +Your answer should be sorted by frequency from highest to lowest. If two words have the same frequency, then the word with the lower alphabetical order comes first. + +**Example 1:** + +``` +Input: ["i", "love", "leetcode", "i", "love", "coding"], k = 2 +Output: ["i", "love"] +Explanation: "i" and "love" are the two most frequent words. + Note that "i" comes before "love" due to a lower alphabetical order. +``` + +**Example 2:** + +``` +Input: ["the", "day", "is", "sunny", "the", "the", "the", "sunny", "is", "is"], k = 4 +Output: ["the", "is", "sunny", "day"] +Explanation: "the", "is", "sunny" and "day" are the four most frequent words, + with the number of occurrence being 4, 3, 2 and 1 respectively. +``` + +**Note:** + +1. You may assume k is always valid, 1 ≤ k ≤ number of unique elements. +2. Input words contain only lowercase letters. + +**Follow up:** + +1. Try to solve it in O(n log k) time and O(n) extra space. + +## 题目大意 + +给一非空的单词列表，返回前 *k* 个出现次数最多的单词。返回的答案应该按单词出现频率由高到低排序。如果不同的单词有相同出现频率，按字母顺序排序。 + +## 解题思路 + +- 思路很简单的题。维护一个长度为 k 的最大堆，先按照频率排，如果频率相同再按照字母顺序排。最后输出依次将优先队列里面的元素 pop 出来即可。 + +## 代码 + +```go +package leetcode + +import "container/heap" + +func topKFrequent(words []string, k int) []string { + m := map[string]int{} + for _, word := range words { + m[word]++ + } + pq := &PQ{} + heap.Init(pq) + for w, c := range m { + heap.Push(pq, &wordCount{w, c}) + if pq.Len() > k { + heap.Pop(pq) + } + } + res := make([]string, k) + for i := k - 1; i >= 0; i-- { + wc := heap.Pop(pq).(*wordCount) + res[i] = wc.word + } + return res +} + +type wordCount struct { + word string + cnt int +} + +type PQ []*wordCount + +func (pq PQ) Len() int { return len(pq) } +func (pq PQ) Swap(i, j int) { pq[i], pq[j] = pq[j], pq[i] } +func (pq PQ) Less(i, j int) bool { + if pq[i].cnt == pq[j].cnt { + return pq[i].word > pq[j].word + } + return pq[i].cnt < pq[j].cnt +} +func (pq *PQ) Push(x interface{}) { + tmp := x.(*wordCount) + *pq = append(*pq, tmp) +} +func (pq *PQ) Pop() interface{} { + n := len(*pq) + tmp := (*pq)[n-1] + *pq = (*pq)[:n-1] + return tmp +} +``` \ No newline at end of file diff --git a/leetcode/0700.Search-in-a-Binary-Search-Tree/700.Search in a Binary Search Tree.go b/leetcode/0700.Search-in-a-Binary-Search-Tree/700.Search in a Binary Search Tree.go new file mode 100644 index 000000000..22c8d5a56 --- /dev/null +++ b/leetcode/0700.Search-in-a-Binary-Search-Tree/700.Search in a Binary Search Tree.go @@ -0,0 +1,30 @@ +package leetcode + +import ( + "github.com/halfrost/LeetCode-Go/structures" +) + +// TreeNode define +type TreeNode = structures.TreeNode + +/** + * Definition for a binary tree node. + * type TreeNode struct { + * Val int + * Left *TreeNode + * Right *TreeNode + * } + */ + +func searchBST(root *TreeNode, val int) *TreeNode { + if root == nil { + return nil + } + if root.Val == val { + return root + } else if root.Val < val { + return searchBST(root.Right, val) + } else { + return searchBST(root.Left, val) + } +} diff --git a/leetcode/0700.Search-in-a-Binary-Search-Tree/700.Search in a Binary Search Tree_test.go b/leetcode/0700.Search-in-a-Binary-Search-Tree/700.Search in a Binary Search Tree_test.go new file mode 100644 index 000000000..ba678bc25 --- /dev/null +++ b/leetcode/0700.Search-in-a-Binary-Search-Tree/700.Search in a Binary Search Tree_test.go @@ -0,0 +1,51 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question700 struct { + para700 + ans700 +} + +// para 是参数 +type para700 struct { + root *TreeNode + val int +} + +// ans 是答案 +type ans700 struct { + ans *TreeNode +} + +func Test_Problem700(t *testing.T) { + + qs := []question700{ + { + para700{&TreeNode{Val: 4, + Left: &TreeNode{Val: 2, Left: &TreeNode{Val: 1, Left: nil, Right: nil}, Right: &TreeNode{Val: 3, Left: nil, Right: nil}}, + Right: &TreeNode{Val: 7, Left: nil, Right: nil}}, + 2}, + ans700{&TreeNode{Val: 2, Left: &TreeNode{Val: 1, Left: nil, Right: nil}, Right: &TreeNode{Val: 3, Left: nil, Right: nil}}}, + }, + + { + para700{&TreeNode{Val: 4, + Left: &TreeNode{Val: 2, Left: &TreeNode{Val: 1, Left: nil, Right: nil}, Right: &TreeNode{Val: 3, Left: nil, Right: nil}}, + Right: &TreeNode{Val: 7, Left: nil, Right: nil}}, + 5}, + ans700{nil}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 700------------------------\n") + + for _, q := range qs { + _, p := q.ans700, q.para700 + fmt.Printf("【input】:%v 【output】:%v\n", p, searchBST(p.root, p.val)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0700.Search-in-a-Binary-Search-Tree/README.md b/leetcode/0700.Search-in-a-Binary-Search-Tree/README.md new file mode 100644 index 000000000..9079e64fc --- /dev/null +++ b/leetcode/0700.Search-in-a-Binary-Search-Tree/README.md @@ -0,0 +1,73 @@ +# [700. Search in a Binary Search Tree](https://leetcode.com/problems/search-in-a-binary-search-tree/) + +## 题目 + +You are given the root of a binary search tree (BST) and an integer val. + +Find the node in the BST that the node's value equals val and return the subtree rooted with that node. If such a node does not exist, return null. + +**Example 1**: + +![https://assets.leetcode.com/uploads/2021/01/12/tree1.jpg](https://assets.leetcode.com/uploads/2021/01/12/tree1.jpg) + + Input: root = [4,2,7,1,3], val = 2 + Output: [2,1,3] + +**Example 2**: + +![https://assets.leetcode.com/uploads/2021/01/12/tree2.jpg](https://assets.leetcode.com/uploads/2021/01/12/tree2.jpg) + + Input: root = [4,2,7,1,3], val = 5 + Output: [] + +**Constraints:** + +- The number of nodes in the tree is in the range [1, 5000]. +- 1 <= Node.val <= 10000000 +- root is a binary search tree. +- 1 <= val <= 10000000 + +## 题目大意 + +给定二叉搜索树（BST）的根节点和一个值。 你需要在BST中找到节点值等于给定值的节点。 返回以该节点为根的子树。 如果节点不存在，则返回 NULL。 + +## 解题思路 + +- 根据二叉搜索树的性质(根节点的值大于左子树所有节点的值，小于右子树所有节点的值),进行递归求解 + +## 代码 + +```go + +package leetcode + +import ( + "github.com/halfrost/LeetCode-Go/structures" +) + +// TreeNode define +type TreeNode = structures.TreeNode + +/** + * Definition for a binary tree node. + * type TreeNode struct { + * Val int + * Left *TreeNode + * Right *TreeNode + * } + */ + +func searchBST(root *TreeNode, val int) *TreeNode { + if root == nil { + return nil + } + if root.Val == val { + return root + } else if root.Val < val { + return searchBST(root.Right, val) + } else { + return searchBST(root.Left, val) + } +} + +``` \ No newline at end of file diff --git a/leetcode/0701.Insert-into-a-Binary-Search-Tree/701. Insert into a Binary Search Tree.go b/leetcode/0701.Insert-into-a-Binary-Search-Tree/701. Insert into a Binary Search Tree.go new file mode 100644 index 000000000..7333d0318 --- /dev/null +++ b/leetcode/0701.Insert-into-a-Binary-Search-Tree/701. Insert into a Binary Search Tree.go @@ -0,0 +1,30 @@ +package leetcode + +import "github.com/halfrost/LeetCode-Go/structures" + +// TreeNode define +type TreeNode = structures.TreeNode + +/** + * Definition for a binary tree node. + * type TreeNode struct { + * Val int + * Left *TreeNode + * Right *TreeNode + * } + */ +func insert(n *TreeNode, val int) *TreeNode { + if n == nil { + return &TreeNode{Val: val} + } + if n.Val < val { + n.Right = insert(n.Right, val) + } else { + n.Left = insert(n.Left, val) + } + return n +} + +func insertIntoBST(root *TreeNode, val int) *TreeNode { + return insert(root, val) +} diff --git a/leetcode/0701.Insert-into-a-Binary-Search-Tree/701. Insert into a Binary Search Tree_test.go b/leetcode/0701.Insert-into-a-Binary-Search-Tree/701. Insert into a Binary Search Tree_test.go new file mode 100644 index 000000000..d9e55f4c5 --- /dev/null +++ b/leetcode/0701.Insert-into-a-Binary-Search-Tree/701. Insert into a Binary Search Tree_test.go @@ -0,0 +1,57 @@ +package leetcode + +import ( + "fmt" + "testing" + + "github.com/halfrost/LeetCode-Go/structures" +) + +type question701 struct { + para701 + ans701 +} + +// para 是参数 +// one 代表第一个参数 +type para701 struct { + root []int + val int +} + +// ans 是答案 +// one 代表第一个答案 +type ans701 struct { + one []int +} + +func Test_Problem701(t *testing.T) { + + qs := []question701{ + + { + para701{[]int{4, 2, 7, 1, 3}, 5}, + ans701{[]int{4, 2, 7, 1, 3, 5}}, + }, + + { + para701{[]int{40, 20, 60, 10, 30, 50, 70}, 25}, + ans701{[]int{40, 20, 60, 10, 30, 50, 70, structures.NULL, structures.NULL, 25}}, + }, + + { + para701{[]int{4, 2, 7, 1, 3, structures.NULL, structures.NULL, structures.NULL, structures.NULL, structures.NULL, structures.NULL}, 5}, + ans701{[]int{4, 2, 7, 1, 3, 5}}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 701------------------------\n") + + for _, q := range qs { + _, p := q.ans701, q.para701 + fmt.Printf("【input】:%v ", p) + rootOne := structures.Ints2TreeNode(p.root) + fmt.Printf("【output】:%v \n", structures.Tree2ints(insertIntoBST(rootOne, p.val))) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0701.Insert-into-a-Binary-Search-Tree/README.md b/leetcode/0701.Insert-into-a-Binary-Search-Tree/README.md new file mode 100644 index 000000000..fc4d504c6 --- /dev/null +++ b/leetcode/0701.Insert-into-a-Binary-Search-Tree/README.md @@ -0,0 +1,88 @@ +# [701. Insert into a Binary Search Tree](https://leetcode.com/problems/insert-into-a-binary-search-tree/) + + +## 题目 + +You are given the `root` node of a binary search tree (BST) and a `value` to insert into the tree. Return *the root node of the BST after the insertion*. It is **guaranteed** that the new value does not exist in the original BST. + +**Notice** that there may exist multiple valid ways for the insertion, as long as the tree remains a BST after insertion. You can return **any of them**. + +**Example 1:** + +![https://assets.leetcode.com/uploads/2020/10/05/insertbst.jpg](https://assets.leetcode.com/uploads/2020/10/05/insertbst.jpg) + +``` +Input: root = [4,2,7,1,3], val = 5 +Output: [4,2,7,1,3,5] +Explanation: Another accepted tree is: + +``` + +![https://assets.leetcode.com/uploads/2020/10/05/bst.jpg](https://assets.leetcode.com/uploads/2020/10/05/bst.jpg) + +**Example 2:** + +``` +Input: root = [40,20,60,10,30,50,70], val = 25 +Output: [40,20,60,10,30,50,70,null,null,25] + +``` + +**Example 3:** + +``` +Input: root = [4,2,7,1,3,null,null,null,null,null,null], val = 5 +Output: [4,2,7,1,3,5] + +``` + +**Constraints:** + +- The number of nodes in the tree will be in the range `[0, 104]`. +- `108 <= Node.val <= 108` +- All the values `Node.val` are **unique**. +- `108 <= val <= 108` +- It's **guaranteed** that `val` does not exist in the original BST. + +## 题目大意 + +给定二叉搜索树（BST）的根节点和要插入树中的值，将值插入二叉搜索树。 返回插入后二叉搜索树的根节点。 输入数据 保证 ，新值和原始二叉搜索树中的任意节点值都不同。注意，可能存在多种有效的插入方式，只要树在插入后仍保持为二叉搜索树即可。 你可以返回 任意有效的结果 。 + +## 解题思路 + +- 简单题。插入节点的方法有多种，笔者这里选择一种简单的方法。从根开始遍历这个二叉树，当前节点的值比待插入节点的值小，则往右遍历；当前节点的值比待插入节点的值大，则往左遍历。最后遍历到空节点便是要插入的地方。 + +## 代码 + +```go +package leetcode + +import "github.com/halfrost/LeetCode-Go/structures" + +// TreeNode define +type TreeNode = structures.TreeNode + +/** + * Definition for a binary tree node. + * type TreeNode struct { + * Val int + * Left *TreeNode + * Right *TreeNode + * } + */ +func insert(n *TreeNode, val int) *TreeNode { + if n == nil { + return &TreeNode{Val: val} + } + if n.Val < val { + n.Right = insert(n.Right, val) + } else { + n.Left = insert(n.Left, val) + } + return n +} + +func insertIntoBST(root *TreeNode, val int) *TreeNode { + return insert(root, val) +} +``` \ No newline at end of file diff --git a/leetcode/0706.Design-HashMap/706. Design HashMap.go b/leetcode/0706.Design-HashMap/706. Design HashMap.go index acbf36fd7..2845be611 100644 --- a/leetcode/0706.Design-HashMap/706. Design HashMap.go +++ b/leetcode/0706.Design-HashMap/706. Design HashMap.go @@ -1,6 +1,6 @@ package leetcode -const Len int = 100000 +const Len int = 10000 type MyHashMap struct { content [Len]*HashNode @@ -41,9 +41,9 @@ func (N *HashNode) Remove(key int) *HashNode { return p } if N.next != nil { - return N.next.Remove(key) + N.next = N.next.Remove(key) } - return nil + return N } /** Initialize your data structure here. */ diff --git a/leetcode/0706.Design-HashMap/706. Design HashMap_test.go b/leetcode/0706.Design-HashMap/706. Design HashMap_test.go index 9ff3e200c..6d83ca0d0 100644 --- a/leetcode/0706.Design-HashMap/706. Design HashMap_test.go +++ b/leetcode/0706.Design-HashMap/706. Design HashMap_test.go @@ -13,6 +13,9 @@ func Test_Problem706(t *testing.T) { fmt.Printf("Contains 7 = %v\n", obj.Get(7)) param1 := obj.Get(100) fmt.Printf("param1 = %v\n", param1) + obj.Remove(100007) + param1 = obj.Get(7) + fmt.Printf("param1 = %v\n", param1) obj.Remove(7) param1 = obj.Get(7) fmt.Printf("param1 = %v\n", param1) diff --git a/leetcode/0707.Design-Linked-List/707. Design Linked List.go b/leetcode/0707.Design-Linked-List/707. Design Linked List.go index 788b9930d..57761f265 100644 --- a/leetcode/0707.Design-Linked-List/707. Design Linked List.go +++ b/leetcode/0707.Design-Linked-List/707. Design Linked List.go @@ -1,82 +1,97 @@ package leetcode type MyLinkedList struct { + head *Node +} + +type Node struct { Val int - Next *MyLinkedList + Next *Node + Prev *Node } /** Initialize your data structure here. */ func Constructor() MyLinkedList { - return MyLinkedList{Val: -999, Next: nil} + return MyLinkedList{} } /** Get the value of the index-th node in the linked list. If the index is invalid, return -1. */ func (this *MyLinkedList) Get(index int) int { - cur := this - for i := 0; cur != nil; i++ { - if i == index { - if cur.Val == -999 { - return -1 - } else { - return cur.Val - } - } - cur = cur.Next + curr := this.head + for i := 0; i < index && curr != nil; i++ { + curr = curr.Next + } + if curr != nil { + return curr.Val + } else { + return -1 } - return -1 } /** Add a node of value val before the first element of the linked list. After the insertion, the new node will be the first node of the linked list. */ func (this *MyLinkedList) AddAtHead(val int) { - if this.Val == -999 { - this.Val = val - } else { - tmp := &MyLinkedList{Val: this.Val, Next: this.Next} - this.Val = val - this.Next = tmp + node := &Node{Val: val} + node.Next = this.head + if this.head != nil { + this.head.Prev = node } + this.head = node } /** Append a node of value val to the last element of the linked list. */ func (this *MyLinkedList) AddAtTail(val int) { - cur := this - for cur.Next != nil { - cur = cur.Next + if this.head == nil { + this.AddAtHead(val) + return } - tmp := &MyLinkedList{Val: val, Next: nil} - cur.Next = tmp + node := &Node{Val: val} + curr := this.head + for curr != nil && curr.Next != nil { + curr = curr.Next + } + node.Prev = curr + curr.Next = node } /** Add a node of value val before the index-th node in the linked list. If index equals to the length of linked list, the node will be appended to the end of linked list. If index is greater than the length, the node will not be inserted. */ func (this *MyLinkedList) AddAtIndex(index int, val int) { - cur := this if index == 0 { this.AddAtHead(val) - return - } - for i := 0; cur != nil; i++ { - if i == index-1 { - break + } else { + node := &Node{Val: val} + curr := this.head + for i := 0; i < index-1 && curr != nil; i++ { + curr = curr.Next + } + if curr != nil { + node.Next = curr.Next + node.Prev = curr + if node.Next != nil { + node.Next.Prev = node + } + curr.Next = node } - cur = cur.Next - } - if cur != nil && cur.Val != -999 { - tmp := &MyLinkedList{Val: val, Next: cur.Next} - cur.Next = tmp } } /** Delete the index-th node in the linked list, if the index is valid. */ func (this *MyLinkedList) DeleteAtIndex(index int) { - cur := this - for i := 0; cur != nil; i++ { - if i == index-1 { - break + if index == 0 { + this.head = this.head.Next + if this.head != nil { + this.head.Prev = nil + } + } else { + curr := this.head + for i := 0; i < index-1 && curr != nil; i++ { + curr = curr.Next + } + if curr != nil && curr.Next != nil { + curr.Next = curr.Next.Next + if curr.Next != nil { + curr.Next.Prev = curr + } } - cur = cur.Next - } - if cur != nil && cur.Next != nil { - cur.Next = cur.Next.Next } } diff --git a/leetcode/0707.Design-Linked-List/707. Design Linked List_test.go b/leetcode/0707.Design-Linked-List/707. Design Linked List_test.go index 4b61e11fd..3d98de216 100644 --- a/leetcode/0707.Design-Linked-List/707. Design Linked List_test.go +++ b/leetcode/0707.Design-Linked-List/707. Design Linked List_test.go @@ -54,11 +54,10 @@ func Test_Problem707(t *testing.T) { func MList2Ints(head *MyLinkedList) []int { res := []int{} - - for head != nil { - res = append(res, head.Val) - head = head.Next + cur := head.head + for cur != nil { + res = append(res, cur.Val) + cur = cur.Next } - return res } diff --git a/leetcode/0709.To-Lower-Case/709. To Lower Case.go b/leetcode/0709.To-Lower-Case/709. To Lower Case.go new file mode 100644 index 000000000..9ade71c0e --- /dev/null +++ b/leetcode/0709.To-Lower-Case/709. To Lower Case.go @@ -0,0 +1,12 @@ +package leetcode + +func toLowerCase(s string) string { + runes := []rune(s) + diff := 'a' - 'A' + for i := 0; i < len(s); i++ { + if runes[i] >= 'A' && runes[i] <= 'Z' { + runes[i] += diff + } + } + return string(runes) +} diff --git a/leetcode/0709.To-Lower-Case/709. To Lower Case_test.go b/leetcode/0709.To-Lower-Case/709. To Lower Case_test.go new file mode 100644 index 000000000..f7bcd27fe --- /dev/null +++ b/leetcode/0709.To-Lower-Case/709. To Lower Case_test.go @@ -0,0 +1,52 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question709 struct { + para709 + ans709 +} + +// para 是参数 +// one 代表第一个参数 +type para709 struct { + one string +} + +// ans 是答案 +// one 代表第一个答案 +type ans709 struct { + one string +} + +func Test_Problem709(t *testing.T) { + + qs := []question709{ + + { + para709{"Hello"}, + ans709{"hello"}, + }, + + { + para709{"here"}, + ans709{"here"}, + }, + + { + para709{"LOVELY"}, + ans709{"lovely"}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 709------------------------\n") + + for _, q := range qs { + _, p := q.ans709, q.para709 + fmt.Printf("【input】:%v 【output】:%v\n", p, toLowerCase(p.one)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0709.To-Lower-Case/README.md b/leetcode/0709.To-Lower-Case/README.md new file mode 100644 index 000000000..062aa6051 --- /dev/null +++ b/leetcode/0709.To-Lower-Case/README.md @@ -0,0 +1,55 @@ +# [709. To Lower Case](https://leetcode.com/problems/to-lower-case/) + + +## 题目 + +Given a string `s`, return *the string after replacing every uppercase letter with the same lowercase letter*. + +**Example 1:** + +``` +Input: s = "Hello" +Output: "hello" +``` + +**Example 2:** + +``` +Input: s = "here" +Output: "here" +``` + +**Example 3:** + +``` +Input: s = "LOVELY" +Output: "lovely" +``` + +**Constraints:** + +- `1 <= s.length <= 100` +- `s` consists of printable ASCII characters. + +## 题目大意 + +给你一个字符串 s ，将该字符串中的大写字母转换成相同的小写字母，返回新的字符串。 + +## 解题思路 + +- 简单题，将字符串中的大写字母转换成小写字母。 + +## 代码 + +```go +func toLowerCase(s string) string { + runes := [] rune(s) + diff := 'a' - 'A' + for i := 0; i < len(s); i++ { + if runes[i] >= 'A' && runes[i] <= 'Z' { + runes[i] += diff + } + } + return string(runes) +} +``` \ No newline at end of file diff --git a/leetcode/0725.Split-Linked-List-in-Parts/725. Split Linked List in Parts.go b/leetcode/0725.Split-Linked-List-in-Parts/725. Split Linked List in Parts.go index 9a17de211..edfae081f 100644 --- a/leetcode/0725.Split-Linked-List-in-Parts/725. Split Linked List in Parts.go +++ b/leetcode/0725.Split-Linked-List-in-Parts/725. Split Linked List in Parts.go @@ -1,8 +1,8 @@ package leetcode -import "fmt" - import ( + "fmt" + "github.com/halfrost/LeetCode-Go/structures" ) diff --git a/leetcode/0728.Self-Dividing-Numbers/728.Self Dividing Numbers.go b/leetcode/0728.Self-Dividing-Numbers/728.Self Dividing Numbers.go new file mode 100644 index 000000000..a0f3c421f --- /dev/null +++ b/leetcode/0728.Self-Dividing-Numbers/728.Self Dividing Numbers.go @@ -0,0 +1,24 @@ +package leetcode + +func selfDividingNumbers(left int, right int) []int { + var ans []int + for num := left; num <= right; num++ { + if selfDividingNum(num) { + ans = append(ans, num) + } + } + return ans +} + +func selfDividingNum(num int) bool { + for d := num; d > 0; d = d / 10 { + reminder := d % 10 + if reminder == 0 { + return false + } + if num%reminder != 0 { + return false + } + } + return true +} diff --git a/leetcode/0728.Self-Dividing-Numbers/728.Self Dividing Numbers_test.go b/leetcode/0728.Self-Dividing-Numbers/728.Self Dividing Numbers_test.go new file mode 100644 index 000000000..a4e10d425 --- /dev/null +++ b/leetcode/0728.Self-Dividing-Numbers/728.Self Dividing Numbers_test.go @@ -0,0 +1,47 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question728 struct { + para728 + ans728 +} + +// para 是参数 +type para728 struct { + left int + right int +} + +// ans 是答案 +type ans728 struct { + ans []int +} + +func Test_Problem728(t *testing.T) { + + qs := []question728{ + + { + para728{1, 22}, + ans728{[]int{1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 15, 22}}, + }, + + { + para728{47, 85}, + ans728{[]int{48, 55, 66, 77}}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 728------------------------\n") + + for _, q := range qs { + _, p := q.ans728, q.para728 + fmt.Printf("【input】:%v ", p) + fmt.Printf("【output】:%v \n", selfDividingNumbers(p.left, p.right)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0728.Self-Dividing-Numbers/README.md b/leetcode/0728.Self-Dividing-Numbers/README.md new file mode 100644 index 000000000..323e51ef7 --- /dev/null +++ b/leetcode/0728.Self-Dividing-Numbers/README.md @@ -0,0 +1,68 @@ +# [728. Self Dividing Numbers](https://leetcode.com/problems/self-dividing-numbers/) + +## 题目 + +A self-dividing number is a number that is divisible by every digit it contains. + +- For example, 128 is a self-dividing number because 128 % 1 == 0, 128 % 2 == 0, and 128 % 8 == 0. + +A self-dividing number is not allowed to contain the digit zero. + +Given two integers left and right, return a list of all the self-dividing numbers in the range [left, right]. + +**Example 1:** + + Input: left = 1, right = 22 + Output: [1,2,3,4,5,6,7,8,9,11,12,15,22] + +**Example 2:** + + Input: left = 47, right = 85 + Output: [48,55,66,77] + +**Constraints:** + +- 1 <= left <= right <= 10000 + +## 题目大意 + +自除数是指可以被它包含的每一位数整除的数。 + +- 例如，128 是一个 自除数 ，因为 128 % 1 == 0，128 % 2 == 0，128 % 8 == 0。 + +自除数 不允许包含 0 。 + +给定两个整数 left 和 right ，返回一个列表，列表的元素是范围 [left, right] 内所有的 自除数 。 + +## 解题思路 + +- 模拟计算 + +# 代码 + +```go +package leetcode + +func selfDividingNumbers(left int, right int) []int { + var ans []int + for num := left; num <= right; num++ { + if selfDividingNum(num) { + ans = append(ans, num) + } + } + return ans +} + +func selfDividingNum(num int) bool { + for d := num; d > 0; d = d / 10 { + reminder := d % 10 + if reminder == 0 { + return false + } + if num%reminder != 0 { + return false + } + } + return true +} +``` diff --git a/leetcode/0747.Largest-Number-At-Least-Twice-of-Others/747. Largest Number At Least Twice of Others.go b/leetcode/0747.Largest-Number-At-Least-Twice-of-Others/747. Largest Number At Least Twice of Others.go new file mode 100644 index 000000000..8f68963cb --- /dev/null +++ b/leetcode/0747.Largest-Number-At-Least-Twice-of-Others/747. Largest Number At Least Twice of Others.go @@ -0,0 +1,20 @@ +package leetcode + +func dominantIndex(nums []int) int { + maxNum, flag, index := 0, false, 0 + for i, v := range nums { + if v > maxNum { + maxNum = v + index = i + } + } + for _, v := range nums { + if v != maxNum && 2*v > maxNum { + flag = true + } + } + if flag { + return -1 + } + return index +} diff --git a/leetcode/0747.Largest-Number-At-Least-Twice-of-Others/747. Largest Number At Least Twice of Others_test.go b/leetcode/0747.Largest-Number-At-Least-Twice-of-Others/747. Largest Number At Least Twice of Others_test.go new file mode 100644 index 000000000..6d658a7b8 --- /dev/null +++ b/leetcode/0747.Largest-Number-At-Least-Twice-of-Others/747. Largest Number At Least Twice of Others_test.go @@ -0,0 +1,52 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question747 struct { + para747 + ans747 +} + +// para 是参数 +// one 代表第一个参数 +type para747 struct { + nums []int +} + +// ans 是答案 +// one 代表第一个答案 +type ans747 struct { + one int +} + +func Test_Problem747(t *testing.T) { + + qs := []question747{ + + { + para747{[]int{3, 6, 1, 0}}, + ans747{1}, + }, + + { + para747{[]int{1, 2, 3, 4}}, + ans747{-1}, + }, + + { + para747{[]int{1}}, + ans747{0}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 747------------------------\n") + + for _, q := range qs { + _, p := q.ans747, q.para747 + fmt.Printf("【input】:%v 【output】:%v\n", p, dominantIndex(p.nums)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0747.Largest-Number-At-Least-Twice-of-Others/README.md b/leetcode/0747.Largest-Number-At-Least-Twice-of-Others/README.md new file mode 100644 index 000000000..9c55c6e0f --- /dev/null +++ b/leetcode/0747.Largest-Number-At-Least-Twice-of-Others/README.md @@ -0,0 +1,75 @@ +# [747. Largest Number At Least Twice of Others](https://leetcode.com/problems/largest-number-at-least-twice-of-others/) + + +## 题目 + +You are given an integer array `nums` where the largest integer is **unique**. + +Determine whether the largest element in the array is **at least twice** as much as every other number in the array. If it is, return *the **index** of the largest element, or return* `-1` *otherwise*. + +**Example 1:** + +``` +Input: nums = [3,6,1,0] +Output: 1 +Explanation: 6 is the largest integer. +For every other number in the array x, 6 is at least twice as big as x. +The index of value 6 is 1, so we return 1. + +``` + +**Example 2:** + +``` +Input: nums = [1,2,3,4] +Output: -1 +Explanation: 4 is less than twice the value of 3, so we return -1. +``` + +**Example 3:** + +``` +Input: nums = [1] +Output: 0 +Explanation: 1 is trivially at least twice the value as any other number because there are no other numbers. + +``` + +**Constraints:** + +- `1 <= nums.length <= 50` +- `0 <= nums[i] <= 100` +- The largest element in `nums` is unique. + +## 题目大意 + +给你一个整数数组 nums ，其中总是存在 唯一的 一个最大整数 。请你找出数组中的最大元素并检查它是否 至少是数组中每个其他数字的两倍 。如果是，则返回 最大元素的下标 ，否则返回 -1 。 + +## 解题思路 + +- 简单题。先扫描一遍找到最大值和下标。再扫描一遍检查最大值是否是其他数字的两倍。 + +## 代码 + +```go +package leetcode + +func dominantIndex(nums []int) int { + maxNum, flag, index := 0, false, 0 + for i, v := range nums { + if v > maxNum { + maxNum = v + index = i + } + } + for _, v := range nums { + if v != maxNum && 2*v > maxNum { + flag = true + } + } + if flag { + return -1 + } + return index +} +``` \ No newline at end of file diff --git a/leetcode/0752.Open-the-Lock/752. Open the Lock.go b/leetcode/0752.Open-the-Lock/752. Open the Lock.go new file mode 100644 index 000000000..72488e57d --- /dev/null +++ b/leetcode/0752.Open-the-Lock/752. Open the Lock.go @@ -0,0 +1,57 @@ +package leetcode + +func openLock(deadends []string, target string) int { + if target == "0000" { + return 0 + } + targetNum, visited := strToInt(target), make([]bool, 10000) + visited[0] = true + for _, deadend := range deadends { + num := strToInt(deadend) + if num == 0 { + return -1 + } + visited[num] = true + } + depth, curDepth, nextDepth := 0, []int16{0}, make([]int16, 0) + var nextNum int16 + for len(curDepth) > 0 { + nextDepth = nextDepth[0:0] + for _, curNum := range curDepth { + for incrementer := int16(1000); incrementer > 0; incrementer /= 10 { + digit := (curNum / incrementer) % 10 + if digit == 9 { + nextNum = curNum - 9*incrementer + } else { + nextNum = curNum + incrementer + } + if nextNum == targetNum { + return depth + 1 + } + if !visited[nextNum] { + visited[nextNum] = true + nextDepth = append(nextDepth, nextNum) + } + if digit == 0 { + nextNum = curNum + 9*incrementer + } else { + nextNum = curNum - incrementer + } + if nextNum == targetNum { + return depth + 1 + } + if !visited[nextNum] { + visited[nextNum] = true + nextDepth = append(nextDepth, nextNum) + } + } + } + curDepth, nextDepth = nextDepth, curDepth + depth++ + } + return -1 +} + +func strToInt(str string) int16 { + return int16(str[0]-'0')*1000 + int16(str[1]-'0')*100 + int16(str[2]-'0')*10 + int16(str[3]-'0') +} diff --git a/leetcode/0752.Open-the-Lock/752. Open the Lock_test.go b/leetcode/0752.Open-the-Lock/752. Open the Lock_test.go new file mode 100644 index 000000000..b6e7d24c9 --- /dev/null +++ b/leetcode/0752.Open-the-Lock/752. Open the Lock_test.go @@ -0,0 +1,53 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question752 struct { + para752 + ans752 +} + +// para 是参数 +// one 代表第一个参数 +type para752 struct { + deadends []string + target string +} + +// ans 是答案 +// one 代表第一个答案 +type ans752 struct { + one int +} + +func Test_Problem752(t *testing.T) { + + qs := []question752{ + + { + para752{[]string{"0201", "0101", "0102", "1212", "2002"}, "0202"}, + ans752{6}, + }, + + { + para752{[]string{"8888"}, "0009"}, + ans752{1}, + }, + + { + para752{[]string{"8887", "8889", "8878", "8898", "8788", "8988", "7888", "9888"}, "8888"}, + ans752{-1}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 752------------------------\n") + + for _, q := range qs { + _, p := q.ans752, q.para752 + fmt.Printf("【input】:%v 【output】:%v\n", p, openLock(p.deadends, p.target)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0752.Open-the-Lock/README.md b/leetcode/0752.Open-the-Lock/README.md new file mode 100644 index 000000000..132083aa0 --- /dev/null +++ b/leetcode/0752.Open-the-Lock/README.md @@ -0,0 +1,131 @@ +# [752. Open the Lock](https://leetcode.com/problems/open-the-lock/) + + +## 题目 + +You have a lock in front of you with 4 circular wheels. Each wheel has 10 slots: `'0', '1', '2', '3', '4', '5', '6', '7', '8', '9'`. The wheels can rotate freely and wrap around: for example we can turn `'9'` to be `'0'`, or `'0'` to be `'9'`. Each move consists of turning one wheel one slot. + +The lock initially starts at `'0000'`, a string representing the state of the 4 wheels. + +You are given a list of `deadends` dead ends, meaning if the lock displays any of these codes, the wheels of the lock will stop turning and you will be unable to open it. + +Given a `target` representing the value of the wheels that will unlock the lock, return the minimum total number of turns required to open the lock, or -1 if it is impossible. + +**Example 1:** + +``` +Input: deadends = ["0201","0101","0102","1212","2002"], target = "0202" +Output: 6 +Explanation: +A sequence of valid moves would be "0000" -> "1000" -> "1100" -> "1200" -> "1201" -> "1202" -> "0202". +Note that a sequence like "0000" -> "0001" -> "0002" -> "0102" -> "0202" would be invalid, +because the wheels of the lock become stuck after the display becomes the dead end "0102". + +``` + +**Example 2:** + +``` +Input: deadends = ["8888"], target = "0009" +Output: 1 +Explanation: +We can turn the last wheel in reverse to move from "0000" -> "0009". + +``` + +**Example 3:** + +``` +Input: deadends = ["8887","8889","8878","8898","8788","8988","7888","9888"], target = "8888" +Output: -1 +Explanation: +We can't reach the target without getting stuck. + +``` + +**Example 4:** + +``` +Input: deadends = ["0000"], target = "8888" +Output: -1 + +``` + +**Constraints:** + +- `1 <= deadends.length <= 500` +- `deadends[i].length == 4` +- `target.length == 4` +- target **will not be** in the list `deadends`. +- `target` and `deadends[i]` consist of digits only. + +## 题目大意 + +你有一个带有四个圆形拨轮的转盘锁。每个拨轮都有10个数字： '0', '1', '2', '3', '4', '5', '6', '7', '8', '9' 。每个拨轮可以自由旋转：例如把 '9' 变为 '0'，'0' 变为 '9' 。每次旋转都只能旋转一个拨轮的一位数字。锁的初始数字为 '0000' ，一个代表四个拨轮的数字的字符串。列表 deadends 包含了一组死亡数字，一旦拨轮的数字和列表里的任何一个元素相同，这个锁将会被永久锁定，无法再被旋转。字符串 target 代表可以解锁的数字，你需要给出解锁需要的最小旋转次数，如果无论如何不能解锁，返回 -1 。 + +## 解题思路 + +- 此题可以转化为从起始点到终点的最短路径。采用广度优先搜索。每次广搜枚举转动一次数字的状态，并且用 visited 记录是否被搜索过，如果没有被搜索过，便加入队列，下一轮继续搜索。如果搜索到了 target，便返回对应的旋转次数。如果搜索完成后，仍没有搜索到 target，说明无法解锁，返回 -1。特殊情况，如果 target 就是初始数字 0000，那么直接返回答案 0。 +- 在广搜之前，先将 deadends 放入 map 中，搜索中判断是否搜到了 deadends。如果初始数字 0000 出现在 deadends 中，可以直接返回答案 −1。 + +## 代码 + +```go +package leetcode + +func openLock(deadends []string, target string) int { + if target == "0000" { + return 0 + } + targetNum, visited := strToInt(target), make([]bool, 10000) + visited[0] = true + for _, deadend := range deadends { + num := strToInt(deadend) + if num == 0 { + return -1 + } + visited[num] = true + } + depth, curDepth, nextDepth := 0, []int16{0}, make([]int16, 0) + var nextNum int16 + for len(curDepth) > 0 { + nextDepth = nextDepth[0:0] + for _, curNum := range curDepth { + for incrementer := int16(1000); incrementer > 0; incrementer /= 10 { + digit := (curNum / incrementer) % 10 + if digit == 9 { + nextNum = curNum - 9*incrementer + } else { + nextNum = curNum + incrementer + } + if nextNum == targetNum { + return depth + 1 + } + if !visited[nextNum] { + visited[nextNum] = true + nextDepth = append(nextDepth, nextNum) + } + if digit == 0 { + nextNum = curNum + 9*incrementer + } else { + nextNum = curNum - incrementer + } + if nextNum == targetNum { + return depth + 1 + } + if !visited[nextNum] { + visited[nextNum] = true + nextDepth = append(nextDepth, nextNum) + } + } + } + curDepth, nextDepth = nextDepth, curDepth + depth++ + } + return -1 +} + +func strToInt(str string) int16 { + return int16(str[0]-'0')*1000 + int16(str[1]-'0')*100 + int16(str[2]-'0')*10 + int16(str[3]-'0') +} +``` \ No newline at end of file diff --git a/leetcode/0763.Partition-Labels/README.md b/leetcode/0763.Partition-Labels/README.md index 68ecff8a0..68d511b40 100644 --- a/leetcode/0763.Partition-Labels/README.md +++ b/leetcode/0763.Partition-Labels/README.md @@ -32,6 +32,6 @@ Note: ## 解题思路 -这一题有 2 种思路，第一种思路是先记录下每个字母的出现次数，然后对滑动窗口中的每个字母判断次数是否用尽为 0，如果这个窗口内的所有字母次数都为 0，这个窗口就是符合条件的窗口。时间复杂度为 O(n^2) +这一题有 2 种思路，第一种思路是先记录下每个字母的出现次数，然后对滑动窗口中的每个字母判断次数是否用尽为 0，如果这个窗口内的所有字母次数都为 0，这个窗口就是符合条件的窗口。时间复杂度为 O(n) 另外一种思路是记录下每个字符最后一次出现的下标，这样就不用记录次数。在每个滑动窗口中，依次判断每个字母最后一次出现的位置，如果在一个下标内，所有字母的最后一次出现的位置都包含进来了，那么这个下标就是这个满足条件的窗口大小。时间复杂度为 O(n^2) diff --git a/leetcode/0791.Custom-Sort-String/791. Custom Sort String.go b/leetcode/0791.Custom-Sort-String/791. Custom Sort String.go new file mode 100644 index 000000000..0535b0591 --- /dev/null +++ b/leetcode/0791.Custom-Sort-String/791. Custom Sort String.go @@ -0,0 +1,15 @@ +package leetcode + +import "sort" + +func customSortString(order string, str string) string { + magic := map[byte]int{} + for i := range order { + magic[order[i]] = i - 30 + } + byteSlice := []byte(str) + sort.Slice(byteSlice, func(i, j int) bool { + return magic[byteSlice[i]] < magic[byteSlice[j]] + }) + return string(byteSlice) +} diff --git a/leetcode/0791.Custom-Sort-String/791. Custom Sort String_test.go b/leetcode/0791.Custom-Sort-String/791. Custom Sort String_test.go new file mode 100644 index 000000000..c61d0da36 --- /dev/null +++ b/leetcode/0791.Custom-Sort-String/791. Custom Sort String_test.go @@ -0,0 +1,43 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question791 struct { + para791 + ans791 +} + +// para 是参数 +// one 代表第一个参数 +type para791 struct { + order string + str string +} + +// ans 是答案 +// one 代表第一个答案 +type ans791 struct { + one string +} + +func Test_Problem791(t *testing.T) { + + qs := []question791{ + + { + para791{"cba", "abcd"}, + ans791{"cbad"}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 791------------------------\n") + + for _, q := range qs { + _, p := q.ans791, q.para791 + fmt.Printf("【input】:%v 【output】:%v\n", p, customSortString(p.order, p.str)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0791.Custom-Sort-String/README.md b/leetcode/0791.Custom-Sort-String/README.md new file mode 100644 index 000000000..09c11d29f --- /dev/null +++ b/leetcode/0791.Custom-Sort-String/README.md @@ -0,0 +1,55 @@ +# [791. Custom Sort String](https://leetcode.com/problems/custom-sort-string/) + + +## 题目 + +`order` and `str` are strings composed of lowercase letters. In `order`, no letter occurs more than once. + +`order` was sorted in some custom order previously. We want to permute the characters of `str` so that they match the order that `order` was sorted. More specifically, if `x` occurs before `y` in `order`, then `x` should occur before `y` in the returned string. + +Return any permutation of `str` (as a string) that satisfies this property. + +``` +Example:Input: +order = "cba" +str = "abcd" +Output: "cbad" +Explanation: +"a", "b", "c" appear in order, so the order of "a", "b", "c" should be "c", "b", and "a". +Since "d" does not appear in order, it can be at any position in the returned string. "dcba", "cdba", "cbda" are also valid outputs. + +``` + +**Note:** + +- `order` has length at most `26`, and no character is repeated in `order`. +- `str` has length at most `200`. +- `order` and `str` consist of lowercase letters only. + +## 题目大意 + +字符串 S 和 T 只包含小写字符。在 S 中，所有字符只会出现一次。S 已经根据某种规则进行了排序。我们要根据 S 中的字符顺序对 T 进行排序。更具体地说，如果 S 中 x 在 y 之前出现，那么返回的字符串中 x 也应出现在 y 之前。返回任意一种符合条件的字符串 T。 + +## 解题思路 + +- 题目只要求 T 中包含 S 的字符串有序，所以可以先将 T 中包含 S 的字符串排好序，然后再拼接上其他字符。S 字符串最长为 26 位，先将 S 中字符的下标向左偏移 30，并将偏移后的下标值存入字典中。再把 T 字符串按照字典中下标值进行排序。S 中出现的字符对应的下标经过处理以后变成了负数，S 中未出现的字符的下标还是正数。所以经过排序以后，S 中出现的字符按照原有顺序排列在前面，S 中未出现的字符依次排在后面。 + +## 代码 + +```go +package leetcode + +import "sort" + +func customSortString(order string, str string) string { + magic := map[byte]int{} + for i := range order { + magic[order[i]] = i - 30 + } + byteSlice := []byte(str) + sort.Slice(byteSlice, func(i, j int) bool { + return magic[byteSlice[i]] < magic[byteSlice[j]] + }) + return string(byteSlice) +} +``` \ No newline at end of file diff --git a/leetcode/0792.Number-of-Matching-Subsequences/792. Number of Matching Subsequences.go b/leetcode/0792.Number-of-Matching-Subsequences/792. Number of Matching Subsequences.go new file mode 100644 index 000000000..ac40c8883 --- /dev/null +++ b/leetcode/0792.Number-of-Matching-Subsequences/792. Number of Matching Subsequences.go @@ -0,0 +1,20 @@ +package leetcode + +func numMatchingSubseq(s string, words []string) int { + hash, res := make([][]string, 26), 0 + for _, w := range words { + hash[int(w[0]-'a')] = append(hash[int(w[0]-'a')], w) + } + for _, c := range s { + words := hash[int(byte(c)-'a')] + hash[int(byte(c)-'a')] = []string{} + for _, w := range words { + if len(w) == 1 { + res += 1 + continue + } + hash[int(w[1]-'a')] = append(hash[int(w[1]-'a')], w[1:]) + } + } + return res +} diff --git a/leetcode/0792.Number-of-Matching-Subsequences/792. Number of Matching Subsequences_test.go b/leetcode/0792.Number-of-Matching-Subsequences/792. Number of Matching Subsequences_test.go new file mode 100644 index 000000000..4a1575342 --- /dev/null +++ b/leetcode/0792.Number-of-Matching-Subsequences/792. Number of Matching Subsequences_test.go @@ -0,0 +1,43 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question792 struct { + para792 + ans792 +} + +// para 是参数 +// one 代表第一个参数 +type para792 struct { + s string + words []string +} + +// ans 是答案 +// one 代表第一个答案 +type ans792 struct { + one int +} + +func Test_Problem792(t *testing.T) { + + qs := []question792{ + + { + para792{"abcde", []string{"a", "bb", "acd", "ace"}}, + ans792{3}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 792------------------------\n") + + for _, q := range qs { + _, p := q.ans792, q.para792 + fmt.Printf("【input】:%v 【output】:%v\n", p, numMatchingSubseq(p.s, p.words)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0792.Number-of-Matching-Subsequences/README.md b/leetcode/0792.Number-of-Matching-Subsequences/README.md new file mode 100644 index 000000000..8da33d3e7 --- /dev/null +++ b/leetcode/0792.Number-of-Matching-Subsequences/README.md @@ -0,0 +1,66 @@ +# [792. Number of Matching Subsequences](https://leetcode.com/problems/number-of-matching-subsequences/) + + +## 题目 + +Given a string `s` and an array of strings `words`, return *the number of* `words[i]` *that is a subsequence of* `s`. + +A **subsequence** of a string is a new string generated from the original string with some characters (can be none) deleted without changing the relative order of the remaining characters. + +- For example, `"ace"` is a subsequence of `"abcde"`. + +**Example 1:** + +``` +Input: s = "abcde", words = ["a","bb","acd","ace"] +Output: 3 +Explanation: There are three strings in words that are a subsequence of s: "a", "acd", "ace". +``` + +**Example 2:** + +``` +Input: s = "dsahjpjauf", words = ["ahjpjau","ja","ahbwzgqnuk","tnmlanowax"] +Output: 2 +``` + +**Constraints:** + +- `1 <= s.length <= 5 * 104` +- `1 <= words.length <= 5000` +- `1 <= words[i].length <= 50` +- `s` and `words[i]` consist of only lowercase English letters. + +## 题目大意 + +给定字符串 S 和单词字典 words, 求 words[i] 中是 S 的子序列的单词个数。 + +## 解题思路 + +- 如果将 words 数组内的字符串每次都在源字符串 S 中匹配，这种暴力解法超时。超时原因是对字符串 S 遍历了多次。是否有更加高效的方法呢？ +- 把 words 数组内字符串按照首字母，分到 26 个桶中。从头开始遍历一遍源字符串 S，每扫一个字母，命中 26 个桶中其中一个桶，修改这个桶中的字符串。例如：当前遍历到了 'o'，此时桶中存的数据是 'a' : ['amy','aop'], 'o': ['oqp','onwn']，那么调整 'o' 桶中的数据后，各桶的状态为，'a' : ['amy','aop'], 'q': ['qp'], 'n': ['nwn']。从头到尾扫完整个字符串 S，某个桶中的字符串被清空，说明该桶中的字符串都符合 S 的子序列。将符合子序列的字符串个数累加起来即为最终答案。 + +## 代码 + +```go +package leetcode + +func numMatchingSubseq(s string, words []string) int { + hash, res := make([][]string, 26), 0 + for _, w := range words { + hash[int(w[0]-'a')] = append(hash[int(w[0]-'a')], w) + } + for _, c := range s { + words := hash[int(byte(c)-'a')] + hash[int(byte(c)-'a')] = []string{} + for _, w := range words { + if len(w) == 1 { + res += 1 + continue + } + hash[int(w[1]-'a')] = append(hash[int(w[1]-'a')], w[1:]) + } + } + return res +} +``` \ No newline at end of file diff --git a/leetcode/0794.Valid-Tic-Tac-Toe-State/794.Valid Tic-Tac-Toe State.go b/leetcode/0794.Valid-Tic-Tac-Toe-State/794.Valid Tic-Tac-Toe State.go new file mode 100644 index 000000000..235ac8d47 --- /dev/null +++ b/leetcode/0794.Valid-Tic-Tac-Toe-State/794.Valid Tic-Tac-Toe State.go @@ -0,0 +1,40 @@ +package leetcode + +func validTicTacToe(board []string) bool { + cntX, cntO := 0, 0 + for i := range board { + for j := range board[i] { + if board[i][j] == 'X' { + cntX++ + } else if board[i][j] == 'O' { + cntO++ + } + } + } + if cntX < cntO || cntX > cntO+1 { + return false + } + if cntX == cntO { + return process(board, 'X') + } + return process(board, 'O') +} + +func process(board []string, c byte) bool { + //某一行是"ccc" + if board[0] == string([]byte{c, c, c}) || board[1] == string([]byte{c, c, c}) || board[2] == string([]byte{c, c, c}) { + return false + } + //某一列是"ccc" + if (board[0][0] == c && board[1][0] == c && board[2][0] == c) || + (board[0][1] == c && board[1][1] == c && board[2][1] == c) || + (board[0][2] == c && board[1][2] == c && board[2][2] == c) { + return false + } + //某一对角线是"ccc" + if (board[0][0] == c && board[1][1] == c && board[2][2] == c) || + (board[0][2] == c && board[1][1] == c && board[2][0] == c) { + return false + } + return true +} diff --git a/leetcode/0794.Valid-Tic-Tac-Toe-State/794.Valid Tic-Tac-Toe State_test.go b/leetcode/0794.Valid-Tic-Tac-Toe-State/794.Valid Tic-Tac-Toe State_test.go new file mode 100644 index 000000000..b324954bd --- /dev/null +++ b/leetcode/0794.Valid-Tic-Tac-Toe-State/794.Valid Tic-Tac-Toe State_test.go @@ -0,0 +1,55 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question794 struct { + para794 + ans794 +} + +// para 是参数 +type para794 struct { + board []string +} + +// ans 是答案 +type ans794 struct { + ans bool +} + +func Test_Problem794(t *testing.T) { + + qs := []question794{ + + { + para794{[]string{"O ", " ", " "}}, + ans794{false}, + }, + + { + para794{[]string{"XOX", " X ", " "}}, + ans794{false}, + }, + + { + para794{[]string{"XXX", " ", "OOO"}}, + ans794{false}, + }, + + { + para794{[]string{"XOX", "O O", "XOX"}}, + ans794{true}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 794------------------------\n") + + for _, q := range qs { + _, p := q.ans794, q.para794 + fmt.Printf("【input】:%v 【output】:%v\n", p.board, validTicTacToe(p.board)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0794.Valid-Tic-Tac-Toe-State/README.md b/leetcode/0794.Valid-Tic-Tac-Toe-State/README.md new file mode 100644 index 000000000..2965e983f --- /dev/null +++ b/leetcode/0794.Valid-Tic-Tac-Toe-State/README.md @@ -0,0 +1,119 @@ +# [794. Valid Tic-Tac-Toe State](https://leetcode.com/problems/valid-tic-tac-toe-state/) + +## 题目 + +Given a Tic-Tac-Toe board as a string array board, return true if and only if it is possible to reach this board position during the course of a valid tic-tac-toe game. + +The board is a 3 x 3 array that consists of characters ' ', 'X', and 'O'. The ' ' character represents an empty square. + +Here are the rules of Tic-Tac-Toe: + +- Players take turns placing characters into empty squares ' '. +- The first player always places 'X' characters, while the second player always places 'O' characters. +- 'X' and 'O' characters are always placed into empty squares, never filled ones. +- The game ends when there are three of the same (non-empty) character filling any row, column, or diagonal. +- The game also ends if all squares are non-empty. +- No more moves can be played if the game is over. + +**Example 1**: + +![https://assets.leetcode.com/uploads/2021/05/15/tictactoe1-grid.jpg](https://assets.leetcode.com/uploads/2021/05/15/tictactoe1-grid.jpg) + + Input: board = ["O "," "," "] + Output: false + Explanation: The first player always plays "X". + +**Example 2**: + +![https://assets.leetcode.com/uploads/2021/05/15/tictactoe2-grid.jpg](https://assets.leetcode.com/uploads/2021/05/15/tictactoe2-grid.jpg) + + Input: board = ["XOX"," X "," "] + Output: false + Explanation: Players take turns making moves. + +**Example 3**: + +![https://assets.leetcode.com/uploads/2021/05/15/tictactoe3-grid.jpg](https://assets.leetcode.com/uploads/2021/05/15/tictactoe3-grid.jpg) + + Input: board = ["XXX"," ","OOO"] + Output: false + +**Example 4**: + +![https://assets.leetcode.com/uploads/2021/05/15/tictactoe4-grid.jpg](https://assets.leetcode.com/uploads/2021/05/15/tictactoe4-grid.jpg) + + Input: board = ["XOX","O O","XOX"] + Output: true + +**Constraints:** + +- board.length == 3 +- board[i].length == 3 +- board[i][j] is either 'X', 'O', or ' '. + +## 题目大意 + +给你一个字符串数组 board 表示井字游戏的棋盘。当且仅当在井字游戏过程中，棋盘有可能达到 board 所显示的状态时，才返回 true 。 + +井字游戏的棋盘是一个 3 x 3 数组，由字符 ' '，'X' 和 'O' 组成。字符 ' ' 代表一个空位。 + +以下是井字游戏的规则： + +- 玩家轮流将字符放入空位（' '）中。 +- 玩家 1 总是放字符 'X' ，而玩家 2 总是放字符 'O' 。 +- 'X' 和 'O' 只允许放置在空位中，不允许对已放有字符的位置进行填充。 +- 当有 3 个相同（且非空）的字符填充任何行、列或对角线时，游戏结束。 +- 当所有位置非空时，也算为游戏结束。 +- 如果游戏结束，玩家不允许再放置字符。 + +## 解题思路 + +分类模拟： +- 根据题意棋盘在任意时候，要么 X 的数量比 O 的数量多 1，要么两者相等 +- X 的数量等于 O 的数量时,任何行、列或对角线都不会出现 3 个相同的 X +- X 的数量比 O 的数量多 1 时,任何行、列或对角线都不会出现 3 个相同的 O + +## 代码 + +```go +package leetcode + +func validTicTacToe(board []string) bool { + cntX, cntO := 0, 0 + for i := range board { + for j := range board[i] { + if board[i][j] == 'X' { + cntX++ + } else if board[i][j] == 'O' { + cntO++ + } + } + } + if cntX < cntO || cntX > cntO+1 { + return false + } + if cntX == cntO { + return process(board, 'X') + } + return process(board, 'O') +} + +func process(board []string, c byte) bool { + //某一行是"ccc" + if board[0] == string([]byte{c, c, c}) || board[1] == string([]byte{c, c, c}) || board[2] == string([]byte{c, c, c}) { + return false + } + //某一列是"ccc" + if (board[0][0] == c && board[1][0] == c && board[2][0] == c) || + (board[0][1] == c && board[1][1] == c && board[2][1] == c) || + (board[0][2] == c && board[1][2] == c && board[2][2] == c) { + return false + } + //某一对角线是"ccc" + if (board[0][0] == c && board[1][1] == c && board[2][2] == c) || + (board[0][2] == c && board[1][1] == c && board[2][0] == c) { + return false + } + return true +} +``` \ No newline at end of file diff --git a/leetcode/0795.Number-of-Subarrays-with-Bounded-Maximum/795. Number of Subarrays with Bounded Maximum.go b/leetcode/0795.Number-of-Subarrays-with-Bounded-Maximum/795. Number of Subarrays with Bounded Maximum.go new file mode 100644 index 000000000..f5eb5c3f7 --- /dev/null +++ b/leetcode/0795.Number-of-Subarrays-with-Bounded-Maximum/795. Number of Subarrays with Bounded Maximum.go @@ -0,0 +1,18 @@ +package leetcode + +func numSubarrayBoundedMax(nums []int, left int, right int) int { + return getAnswerPerBound(nums, right) - getAnswerPerBound(nums, left-1) +} + +func getAnswerPerBound(nums []int, bound int) int { + res, count := 0, 0 + for _, num := range nums { + if num <= bound { + count++ + } else { + count = 0 + } + res += count + } + return res +} diff --git a/leetcode/0795.Number-of-Subarrays-with-Bounded-Maximum/795. Number of Subarrays with Bounded Maximum_test.go b/leetcode/0795.Number-of-Subarrays-with-Bounded-Maximum/795. Number of Subarrays with Bounded Maximum_test.go new file mode 100644 index 000000000..5dba6f0cd --- /dev/null +++ b/leetcode/0795.Number-of-Subarrays-with-Bounded-Maximum/795. Number of Subarrays with Bounded Maximum_test.go @@ -0,0 +1,44 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question795 struct { + para795 + ans795 +} + +// para 是参数 +// one 代表第一个参数 +type para795 struct { + nums []int + left int + right int +} + +// ans 是答案 +// one 代表第一个答案 +type ans795 struct { + one int +} + +func Test_Problem795(t *testing.T) { + + qs := []question795{ + + { + para795{[]int{2, 1, 4, 3}, 2, 3}, + ans795{3}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 795------------------------\n") + + for _, q := range qs { + _, p := q.ans795, q.para795 + fmt.Printf("【input】:%v 【output】:%v\n", p, numSubarrayBoundedMax(p.nums, p.left, p.right)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0795.Number-of-Subarrays-with-Bounded-Maximum/README.md b/leetcode/0795.Number-of-Subarrays-with-Bounded-Maximum/README.md new file mode 100644 index 000000000..c69294451 --- /dev/null +++ b/leetcode/0795.Number-of-Subarrays-with-Bounded-Maximum/README.md @@ -0,0 +1,54 @@ +# [795. Number of Subarrays with Bounded Maximum](https://leetcode.com/problems/number-of-subarrays-with-bounded-maximum/) + + +## 题目 + +We are given an array `nums` of positive integers, and two positive integers `left` and `right` (`left <= right`). + +Return the number of (contiguous, non-empty) subarrays such that the value of the maximum array element in that subarray is at least `left` and at most `right`. + +``` +Example:Input: +nums = [2, 1, 4, 3] +left = 2 +right = 3 +Output: 3 +Explanation: There are three subarrays that meet the requirements: [2], [2, 1], [3]. +``` + +**Note:** + +- `left`, `right`, and `nums[i]` will be an integer in the range `[0, 109]`. +- The length of `nums` will be in the range of `[1, 50000]`. + +## 题目大意 + +给定一个元素都是正整数的数组`A` ，正整数 `L` 以及 `R` (`L <= R`)。求连续、非空且其中最大元素满足大于等于`L` 小于等于`R`的子数组个数。 + +## 解题思路 + +- 题目要求子数组最大元素在 [L,R] 区间内。假设 count(bound) 为计算所有元素都小于等于 bound 的子数组数量。那么本题所求的答案可转化为 count(R) - count(L-1)。 +- 如何统计所有元素小于 bound 的子数组数量呢？使用 count 变量记录在 bound 的左边，小于等于 bound 的连续元素数量。当找到一个这样的元素时，在此位置上结束的有效子数组的数量为 count + 1。当遇到一个元素大于 B 时，则在此位置结束的有效子数组的数量为 0。res 将每轮 count 累加，最终 res 中存的即是满足条件的所有子数组数量。 + +## 代码 + +```go +package leetcode + +func numSubarrayBoundedMax(nums []int, left int, right int) int { + return getAnswerPerBound(nums, right) - getAnswerPerBound(nums, left-1) +} + +func getAnswerPerBound(nums []int, bound int) int { + res, count := 0, 0 + for _, num := range nums { + if num <= bound { + count++ + } else { + count = 0 + } + res += count + } + return res +} +``` \ No newline at end of file diff --git a/leetcode/0807.Max-Increase-to-Keep-City-Skyline/807.Max Increase to Keep City Skyline.go b/leetcode/0807.Max-Increase-to-Keep-City-Skyline/807.Max Increase to Keep City Skyline.go new file mode 100644 index 000000000..c36831734 --- /dev/null +++ b/leetcode/0807.Max-Increase-to-Keep-City-Skyline/807.Max Increase to Keep City Skyline.go @@ -0,0 +1,39 @@ +package leetcode + +func maxIncreaseKeepingSkyline(grid [][]int) int { + n := len(grid) + topBottomSkyline := make([]int, 0, n) + leftRightSkyline := make([]int, 0, n) + for i := range grid { + cur := 0 + for _, v := range grid[i] { + if cur < v { + cur = v + } + } + leftRightSkyline = append(leftRightSkyline, cur) + } + for j := range grid { + cur := 0 + for i := 0; i < len(grid[0]); i++ { + if cur < grid[i][j] { + cur = grid[i][j] + } + } + topBottomSkyline = append(topBottomSkyline, cur) + } + var ans int + for i := range grid { + for j := 0; j < len(grid[0]); j++ { + ans += min(topBottomSkyline[j], leftRightSkyline[i]) - grid[i][j] + } + } + return ans +} + +func min(a, b int) int { + if a < b { + return a + } + return b +} diff --git a/leetcode/0807.Max-Increase-to-Keep-City-Skyline/807.Max Increase to Keep City Skyline_test.go b/leetcode/0807.Max-Increase-to-Keep-City-Skyline/807.Max Increase to Keep City Skyline_test.go new file mode 100644 index 000000000..81159a0e6 --- /dev/null +++ b/leetcode/0807.Max-Increase-to-Keep-City-Skyline/807.Max Increase to Keep City Skyline_test.go @@ -0,0 +1,45 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question807 struct { + para807 + ans807 +} + +// para 是参数 +type para807 struct { + grid [][]int +} + +// ans 是答案 +type ans807 struct { + ans int +} + +func Test_Problem807(t *testing.T) { + + qs := []question807{ + + { + para807{[][]int{{3, 0, 8, 4}, {2, 4, 5, 7}, {9, 2, 6, 3}, {0, 3, 1, 0}}}, + ans807{35}, + }, + + { + para807{[][]int{{0, 0, 0}, {0, 0, 0}, {0, 0, 0}}}, + ans807{0}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 807------------------------\n") + + for _, q := range qs { + _, p := q.ans807, q.para807 + fmt.Printf("【input】:%v 【output】:%v\n", p.grid, maxIncreaseKeepingSkyline(p.grid)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0807.Max-Increase-to-Keep-City-Skyline/README.md b/leetcode/0807.Max-Increase-to-Keep-City-Skyline/README.md new file mode 100644 index 000000000..58651c500 --- /dev/null +++ b/leetcode/0807.Max-Increase-to-Keep-City-Skyline/README.md @@ -0,0 +1,97 @@ +# [807. Max Increase to Keep City Skyline](https://leetcode.com/problems/max-increase-to-keep-city-skyline/) + +## 题目 + +There is a city composed of n x n blocks, where each block contains a single building shaped like a vertical square prism. You are given a 0-indexed n x n integer matrix grid where grid[r][c] represents the height of the building located in the block at row r and column c. + +A city's skyline is the the outer contour formed by all the building when viewing the side of the city from a distance. The skyline from each cardinal direction north, east, south, and west may be different. + +We are allowed to increase the height of any number of buildings by any amount (the amount can be different per building). The height of a 0-height building can also be increased. However, increasing the height of a building should not affect the city's skyline from any cardinal direction. + +Return the maximum total sum that the height of the buildings can be increased by without changing the city's skyline from any cardinal direction. + +**Example 1**: + +![https://assets.leetcode.com/uploads/2021/06/21/807-ex1.png](https://assets.leetcode.com/uploads/2021/06/21/807-ex1.png) + + Input: grid = [[3,0,8,4],[2,4,5,7],[9,2,6,3],[0,3,1,0]] + Output: 35 + Explanation: The building heights are shown in the center of the above image. + The skylines when viewed from each cardinal direction are drawn in red. + The grid after increasing the height of buildings without affecting skylines is: + gridNew = [ [8, 4, 8, 7], + [7, 4, 7, 7], + [9, 4, 8, 7], + [3, 3, 3, 3] ] + +**Example 2**: + + Input: grid = [[0,0,0],[0,0,0],[0,0,0]] + Output: 0 + Explanation: Increasing the height of any building will result in the skyline changing. + +**Constraints:** + +- n == grid.length +- n == grid[r].length +- 2 <= n <= 50 +- 0 <= grid[r][c] <= 100 + +## 题目大意 + +在二维数组grid中，grid[i][j]代表位于某处的建筑物的高度。 我们被允许增加任何数量（不同建筑物的数量可能不同）的建筑物的高度。 高度 0 也被认为是建筑物。 + +最后，从新数组的所有四个方向（即顶部，底部，左侧和右侧）观看的“天际线”必须与原始数组的天际线相同。 城市的天际线是从远处观看时，由所有建筑物形成的矩形的外部轮廓。 请看下面的例子。 + +建筑物高度可以增加的最大总和是多少？ + +## 解题思路 + +- 从数组竖直方向（即顶部，底部）看“天际线”计算出 topBottomSkyline +- 从数组水平方向（即左侧，右侧）看“天际线”计算出 leftRightSkyline +- 计算 grid 中每个元素与对应的 topBottomSkyline 和 leftRightSkyline 中较小值的差值 +- 统计所有差值的总和 ans 并返回 + +## 代码 + +```go +package leetcode + +func maxIncreaseKeepingSkyline(grid [][]int) int { + n := len(grid) + topBottomSkyline := make([]int, 0, n) + leftRightSkyline := make([]int, 0, n) + for i := range grid { + cur := 0 + for _, v := range grid[i] { + if cur < v { + cur = v + } + } + leftRightSkyline = append(leftRightSkyline, cur) + } + for j := range grid { + cur := 0 + for i := 0; i < len(grid[0]); i++ { + if cur < grid[i][j] { + cur = grid[i][j] + } + } + topBottomSkyline = append(topBottomSkyline, cur) + } + var ans int + for i := range grid { + for j := 0; j < len(grid[0]); j++ { + ans += min(topBottomSkyline[j], leftRightSkyline[i]) - grid[i][j] + } + } + return ans +} + +func min(a, b int) int { + if a < b { + return a + } + return b +} +``` \ No newline at end of file diff --git a/leetcode/0810.Chalkboard-XOR-Game/810. Chalkboard XOR Game.go b/leetcode/0810.Chalkboard-XOR-Game/810. Chalkboard XOR Game.go new file mode 100644 index 000000000..25c791bad --- /dev/null +++ b/leetcode/0810.Chalkboard-XOR-Game/810. Chalkboard XOR Game.go @@ -0,0 +1,12 @@ +package leetcode + +func xorGame(nums []int) bool { + if len(nums)%2 == 0 { + return true + } + xor := 0 + for _, num := range nums { + xor ^= num + } + return xor == 0 +} diff --git a/leetcode/0810.Chalkboard-XOR-Game/810. Chalkboard XOR Game_test.go b/leetcode/0810.Chalkboard-XOR-Game/810. Chalkboard XOR Game_test.go new file mode 100644 index 000000000..5c84b5e79 --- /dev/null +++ b/leetcode/0810.Chalkboard-XOR-Game/810. Chalkboard XOR Game_test.go @@ -0,0 +1,42 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question810 struct { + para810 + ans810 +} + +// para 是参数 +// one 代表第一个参数 +type para810 struct { + nums []int +} + +// ans 是答案 +// one 代表第一个答案 +type ans810 struct { + one bool +} + +func Test_Problem810(t *testing.T) { + + qs := []question810{ + + { + para810{[]int{1, 1, 2}}, + ans810{false}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 810------------------------\n") + + for _, q := range qs { + _, p := q.ans810, q.para810 + fmt.Printf("【input】:%v 【output】:%v\n", p, xorGame(p.nums)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0810.Chalkboard-XOR-Game/README.md b/leetcode/0810.Chalkboard-XOR-Game/README.md new file mode 100644 index 000000000..e44fd391e --- /dev/null +++ b/leetcode/0810.Chalkboard-XOR-Game/README.md @@ -0,0 +1,58 @@ +# [810. Chalkboard XOR Game](https://leetcode.com/problems/chalkboard-xor-game/) + + +## 题目 + +We are given non-negative integers nums[i] which are written on a chalkboard.  Alice and Bob take turns erasing exactly one number from the chalkboard, with Alice starting first.  If erasing a number causes the bitwise XOR of all the elements of the chalkboard to become 0, then that player loses.  (Also, we'll say the bitwise XOR of one element is that element itself, and the bitwise XOR of no elements is 0.) + +Also, if any player starts their turn with the bitwise XOR of all the elements of the chalkboard equal to 0, then that player wins. + +Return True if and only if Alice wins the game, assuming both players play optimally. + +``` +Example:Input: nums = [1, 1, 2] +Output: false +Explanation: +Alice has two choices: erase 1 or erase 2. +If she erases 1, the nums array becomes [1, 2]. The bitwise XOR of all the elements of the chalkboard is 1 XOR 2 = 3. Now Bob can remove any element he wants, because Alice will be the one to erase the last element and she will lose. +If Alice erases 2 first, now nums becomes [1, 1]. The bitwise XOR of all the elements of the chalkboard is 1 XOR 1 = 0. Alice will lose. +``` + +**Notes:** + +- `1 <= N <= 1000`. +- `0 <= nums[i] <= 2^16`. + +## 题目大意 + +黑板上写着一个非负整数数组 nums[i] 。Alice 和 Bob 轮流从黑板上擦掉一个数字，Alice 先手。如果擦除一个数字后，剩余的所有数字按位异或运算得出的结果等于 0 的话，当前玩家游戏失败。 (另外，如果只剩一个数字，按位异或运算得到它本身；如果无数字剩余，按位异或运算结果为 0。）并且，轮到某个玩家时，如果当前黑板上所有数字按位异或运算结果等于 0，这个玩家获胜。假设两个玩家每步都使用最优解，当且仅当 Alice 获胜时返回 true。 + +## 解题思路 + +- Alice 必胜情况之一，Alice 先手，起始数组全部元素本身异或结果就为 0 。不需要擦除数字便自动获胜。除去这个情况，还有其他情况么？由于 2 人是交替擦除数字，且每次都恰好擦掉一个数字，因此对于这两人中的任意一人，其每次在擦除数字前，黑板上剩余数字的个数的奇偶性一定都是相同的。于是奇偶性成为突破口。 +- 如果 nums 的长度是偶数，Alice 先手是否必败呢？如果必败，代表无论擦掉哪一个数字，剩余所有数字的异或结果都等于 0。利用反证法证明上述结论是错误的。首先 $num[0] \oplus num[1] \oplus num[2] \oplus \cdots \oplus num[n-1] = X ≠ 0$，初始所有元素异或结果不为 0。假设 Alice 当前擦掉第 i 个元素，0 ≤ i < n。令 $X_{n}$ 代表擦掉第 n 位元素以后剩余元素异或的结果。由证题，无论擦掉哪一个数字，剩余所有数字的异或结果都等于 0。所以 $X_{0} \oplus X_{1} \oplus X_{2} \oplus \cdots  \oplus X_{n-1} = 0$。 + + $$\begin{aligned}0 &= X_{0} \oplus  X_{1} \oplus X_{2} \oplus \cdots  \oplus X_{n-1} \\0 &= (X \oplus nums[0]) \oplus (X \oplus nums[1]) \oplus (X \oplus nums[2]) \oplus \cdots  \oplus (X \oplus nums[n-1])\\ 0 &= (X \oplus X \oplus \cdots  \oplus X) \oplus (nums[0] \oplus nums[1] \oplus nums[2] \oplus \cdots  \oplus nums[n-1])\\0 &= 0 \oplus X\\\\\Rightarrow X &= 0\\\end{aligned}$$ + + 由于 n 为偶数，所以 n 个 X 的异或结果为 0。最终推出 X = 0，很明显与前提 X ≠ 0 冲突。所以原命题，代表无论擦掉哪一个数字，剩余所有数字的异或结果都等于 0 是错误的。也就是说，当 n 为偶数时，代表无论擦掉哪一个数字，剩余所有数字的异或结果都不等于 0。即 Alice 有必胜策略。换句话说，当数组的长度是偶数时，先手 Alice 总能找到一个数字，在擦掉这个数字之后剩余的所有数字异或结果不等于 0。 + +- 综上，Alice 必胜策略有 2 种情况： + 1. 数组 nums 的全部元素初始本身异或结果就等于 0。 + 2. 数组 nums 的长度是偶数。 + +## 代码 + +```go +package leetcode + +func xorGame(nums []int) bool { + if len(nums)%2 == 0 { + return true + } + xor := 0 + for _, num := range nums { + xor ^= num + } + return xor == 0 +} +``` \ No newline at end of file diff --git a/leetcode/0816.Ambiguous-Coordinates/816. Ambiguous Coordinates.go b/leetcode/0816.Ambiguous-Coordinates/816. Ambiguous Coordinates.go new file mode 100644 index 000000000..c509719ad --- /dev/null +++ b/leetcode/0816.Ambiguous-Coordinates/816. Ambiguous Coordinates.go @@ -0,0 +1,36 @@ +package leetcode + +func ambiguousCoordinates(s string) []string { + res := []string{} + s = s[1 : len(s)-1] + for i := range s[:len(s)-1] { + a := build(s[:i+1]) + b := build(s[i+1:]) + for _, ta := range a { + for _, tb := range b { + res = append(res, "("+ta+", "+tb+")") + } + } + } + return res +} + +func build(s string) []string { + res := []string{} + if len(s) == 1 || s[0] != '0' { + res = append(res, s) + } + // 结尾带 0 的情况 + if s[len(s)-1] == '0' { + return res + } + // 切分长度大于一位且带前导 0 的情况 + if s[0] == '0' { + res = append(res, "0."+s[1:]) + return res + } + for i := range s[:len(s)-1] { + res = append(res, s[:i+1]+"."+s[i+1:]) + } + return res +} diff --git a/leetcode/0816.Ambiguous-Coordinates/816. Ambiguous Coordinates_test.go b/leetcode/0816.Ambiguous-Coordinates/816. Ambiguous Coordinates_test.go new file mode 100644 index 000000000..9764422d4 --- /dev/null +++ b/leetcode/0816.Ambiguous-Coordinates/816. Ambiguous Coordinates_test.go @@ -0,0 +1,42 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question816 struct { + para816 + ans816 +} + +// para 是参数 +// one 代表第一个参数 +type para816 struct { + one string +} + +// ans 是答案 +// one 代表第一个答案 +type ans816 struct { + one []string +} + +func Test_Problem816(t *testing.T) { + + qs := []question816{ + + { + para816{"(120123)"}, + ans816{[]string{"(1, 20123)", " (1, 2.0123)", " (1, 20.123)", " (1, 201.23)", " (1, 2012.3)", " (12, 0.123)", " (1.2, 0.123)", " (120, 123)", " (120, 1.23)", " (120, 12.3)", " (1201, 23) ", "(1201, 2.3)", " (1.201, 23)", " (1.201, 2.3) ", "(12.01, 23)", " (12.01, 2.3) ", "(120.1, 23)", " (120.1, 2.3) ", "(12012, 3)", " (1.2012, 3)", " (12.012, 3)", " (120.12, 3)", " (1201.2, 3)"}}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 816------------------------\n") + + for _, q := range qs { + _, p := q.ans816, q.para816 + fmt.Printf("【input】:%v 【output】:%v\n", p, ambiguousCoordinates(p.one)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0816.Ambiguous-Coordinates/README.md b/leetcode/0816.Ambiguous-Coordinates/README.md new file mode 100644 index 000000000..c1610fdec --- /dev/null +++ b/leetcode/0816.Ambiguous-Coordinates/README.md @@ -0,0 +1,95 @@ +# [816. Ambiguous Coordinates](https://leetcode.com/problems/ambiguous-coordinates/) + + +## 题目 + +We had some 2-dimensional coordinates, like `"(1, 3)"` or `"(2, 0.5)"`.  Then, we removed all commas, decimal points, and spaces, and ended up with the string `s`.  Return a list of strings representing all possibilities for what our original coordinates could have been. + +Our original representation never had extraneous zeroes, so we never started with numbers like "00", "0.0", "0.00", "1.0", "001", "00.01", or any other number that can be represented with less digits.  Also, a decimal point within a number never occurs without at least one digit occuring before it, so we never started with numbers like ".1". + +The final answer list can be returned in any order.  Also note that all coordinates in the final answer have exactly one space between them (occurring after the comma.) + +``` +Example 1:Input: s = "(123)" +Output: ["(1, 23)", "(12, 3)", "(1.2, 3)", "(1, 2.3)"] + +``` + +``` +Example 2:Input: s = "(00011)" +Output:  ["(0.001, 1)", "(0, 0.011)"] +Explanation: +0.0, 00, 0001 or 00.01 are not allowed. + +``` + +``` +Example 3:Input: s = "(0123)" +Output: ["(0, 123)", "(0, 12.3)", "(0, 1.23)", "(0.1, 23)", "(0.1, 2.3)", "(0.12, 3)"] + +``` + +``` +Example 4:Input: s = "(100)" +Output: [(10, 0)] +Explanation: +1.0 is not allowed. + +``` + +**Note:** + +- `4 <= s.length <= 12`. +- `s[0]` = "(", `s[s.length - 1]` = ")", and the other elements in `s` are digits. + +## 题目大意 + +我们有一些二维坐标，如 "(1, 3)" 或 "(2, 0.5)"，然后我们移除所有逗号，小数点和空格，得到一个字符串S。返回所有可能的原始字符串到一个列表中。原始的坐标表示法不会存在多余的零，所以不会出现类似于"00", "0.0", "0.00", "1.0", "001", "00.01"或一些其他更小的数来表示坐标。此外，一个小数点前至少存在一个数，所以也不会出现“.1”形式的数字。 + +最后返回的列表可以是任意顺序的。而且注意返回的两个数字中间（逗号之后）都有一个空格。 + +## 解题思路 + +- 本题没有什么算法思想，纯暴力题。先将原始字符串一分为二，分为的两个子字符串再移动坐标点，最后将每种情况组合再一次，这算完成了一次切分。将原始字符串每一位都按此规律完成切分，此题便得解。 +- 这道题有 2 处需要注意的。第一处是最终输出的字符串，请注意，**两个数字中间（逗号之后）都有一个空格**。不遵守输出格式的要求也会导致 `Wrong Answer`。另外一处是切分数字时，有 2 种违法情况，一种是带前导 0 的，另外一种是末尾带 0 的。带前导 0 的也分为 2 种情况，一种是只有一位，即只有一个 0，这种情况直接返回，因为这一个 0 怎么切分也只有一种切分方法。另外一种是长度大于 1，即 `0xxx` 这种情况。`0xxx` 这种情况只有一种切分方法，即 `0.xxx`。末尾带 0 的只有一种切分方法，即 `xxx0`，不可切分，因为 `xxx.0`，`xx.x0`，`x.xx0` 这些都是违法情况，所以末尾带 0 的也可以直接返回。具体的实现见代码和注释。 + +## 代码 + +```go +package leetcode + +func ambiguousCoordinates(s string) []string { + res := []string{} + s = s[1 : len(s)-1] + for i := range s[:len(s)-1] { + a := build(s[:i+1]) + b := build(s[i+1:]) + for _, ta := range a { + for _, tb := range b { + res = append(res, "("+ta+", "+tb+")") + } + } + } + return res +} + +func build(s string) []string { + res := []string{} + if len(s) == 1 || s[0] != '0' { + res = append(res, s) + } + // 结尾带 0 的情况 + if s[len(s)-1] == '0' { + return res + } + // 切分长度大于一位且带前导 0 的情况 + if s[0] == '0' { + res = append(res, "0."+s[1:]) + return res + } + for i := range s[:len(s)-1] { + res = append(res, s[:i+1]+"."+s[i+1:]) + } + return res +} +``` \ No newline at end of file diff --git a/leetcode/0821.Shortest-Distance-to-a-Character/821. Shortest Distance to a Character.go b/leetcode/0821.Shortest-Distance-to-a-Character/821. Shortest Distance to a Character.go index 4e7102990..88ea9ce28 100644 --- a/leetcode/0821.Shortest-Distance-to-a-Character/821. Shortest Distance to a Character.go +++ b/leetcode/0821.Shortest-Distance-to-a-Character/821. Shortest Distance to a Character.go @@ -4,7 +4,30 @@ import ( "math" ) +// 解法一 func shortestToChar(s string, c byte) []int { + n := len(s) + res := make([]int, n) + for i := range res { + res[i] = n + } + for i := 0; i < n; i++ { + if s[i] == c { + res[i] = 0 + } else if i > 0 { + res[i] = res[i-1] + 1 + } + } + for i := n - 1; i >= 0; i-- { + if i < n-1 && res[i+1]+1 < res[i] { + res[i] = res[i+1] + 1 + } + } + return res +} + +// 解法二 +func shortestToChar1(s string, c byte) []int { res := make([]int, len(s)) for i := 0; i < len(s); i++ { if s[i] == c { diff --git a/leetcode/0821.Shortest-Distance-to-a-Character/README.md b/leetcode/0821.Shortest-Distance-to-a-Character/README.md index 6a758abec..48721fa20 100644 --- a/leetcode/0821.Shortest-Distance-to-a-Character/README.md +++ b/leetcode/0821.Shortest-Distance-to-a-Character/README.md @@ -1,6 +1,5 @@ # [821. Shortest Distance to a Character](https://leetcode.com/problems/shortest-distance-to-a-character/) - ## 题目 Given a string `s` and a character `c` that occurs in `s`, return *an array of integers `answer` where* `answer.length == s.length` *and* `answer[i]` *is the shortest distance from* `s[i]` *to the character* `c` *in* `s`. @@ -31,7 +30,8 @@ Output: [3,2,1,0] ## 解题思路 -- 简单题。依次扫描字符串 S，针对每一个非字符 C 的字符，分别往左扫一次，往右扫一次，计算出距离目标字符 C 的距离，然后取左右两个距离的最小值存入最终答案数组中。 +- 解法一：从左至右更新一遍到 C 的值距离，再从右至左更新一遍到 C 的值，取两者中的最小值。 +- 解法二：依次扫描字符串 S，针对每一个非字符 C 的字符，分别往左扫一次，往右扫一次，计算出距离目标字符 C 的距离，然后取左右两个距离的最小值存入最终答案数组中。 ## 代码 @@ -42,7 +42,30 @@ import ( "math" ) +// 解法一 func shortestToChar(s string, c byte) []int { + n := len(s) + res := make([]int, n) + for i := range res { + res[i] = n + } + for i := 0; i < n; i++ { + if s[i] == c { + res[i] = 0 + } else if i > 0 { + res[i] = res[i-1] + 1 + } + } + for i := n - 1; i >= 0; i-- { + if i < n-1 && res[i+1]+1 < res[i] { + res[i] = res[i+1] + 1 + } + } + return res +} + +// 解法二 +func shortestToChar1(s string, c byte) []int { res := make([]int, len(s)) for i := 0; i < len(s); i++ { if s[i] == c { diff --git a/leetcode/0825.Friends-Of-Appropriate-Ages/825. Friends Of Appropriate Ages.go b/leetcode/0825.Friends-Of-Appropriate-Ages/825. Friends Of Appropriate Ages.go new file mode 100644 index 000000000..ebb496c68 --- /dev/null +++ b/leetcode/0825.Friends-Of-Appropriate-Ages/825. Friends Of Appropriate Ages.go @@ -0,0 +1,67 @@ +package leetcocde + +import "sort" + +// 解法一 前缀和，时间复杂度 O(n) +func numFriendRequests(ages []int) int { + count, prefixSum, res := make([]int, 121), make([]int, 121), 0 + for _, age := range ages { + count[age]++ + } + for i := 1; i < 121; i++ { + prefixSum[i] = prefixSum[i-1] + count[i] + } + for i := 15; i < 121; i++ { + if count[i] > 0 { + bound := i/2 + 8 + res += count[i] * (prefixSum[i] - prefixSum[bound-1] - 1) + } + } + return res +} + +// 解法二 双指针 + 排序，时间复杂度 O(n logn) +func numFriendRequests1(ages []int) int { + sort.Ints(ages) + left, right, res := 0, 0, 0 + for _, age := range ages { + if age < 15 { + continue + } + for ages[left]*2 <= age+14 { + left++ + } + for right+1 < len(ages) && ages[right+1] <= age { + right++ + } + res += right - left + } + return res +} + +// 解法三 暴力解法 O(n^2) +func numFriendRequests2(ages []int) int { + res, count := 0, [125]int{} + for _, x := range ages { + count[x]++ + } + for i := 1; i <= 120; i++ { + for j := 1; j <= 120; j++ { + if j > i { + continue + } + if (j-7)*2 <= i { + continue + } + if j > 100 && i < 100 { + continue + } + if i != j { + res += count[i] * count[j] + } else { + res += count[i] * (count[j] - 1) + } + } + } + return res +} diff --git a/leetcode/0825.Friends-Of-Appropriate-Ages/825. Friends Of Appropriate Ages_test.go b/leetcode/0825.Friends-Of-Appropriate-Ages/825. Friends Of Appropriate Ages_test.go new file mode 100644 index 000000000..ee891c63e --- /dev/null +++ b/leetcode/0825.Friends-Of-Appropriate-Ages/825. Friends Of Appropriate Ages_test.go @@ -0,0 +1,52 @@ +package leetcocde + +import ( + "fmt" + "testing" +) + +type question825 struct { + para825 + ans825 +} + +// para 是参数 +// one 代表第一个参数 +type para825 struct { + ages []int +} + +// ans 是答案 +// one 代表第一个答案 +type ans825 struct { + one int +} + +func Test_Problem825(t *testing.T) { + + qs := []question825{ + + { + para825{[]int{16, 16}}, + ans825{2}, + }, + + { + para825{[]int{16, 17, 18}}, + ans825{2}, + }, + + { + para825{[]int{20, 30, 100, 110, 120}}, + ans825{3}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 825------------------------\n") + + for _, q := range qs { + _, p := q.ans825, q.para825 + fmt.Printf("【input】:%v 【output】:%v\n", p, numFriendRequests(p.ages)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0825.Friends-Of-Appropriate-Ages/README.md b/leetcode/0825.Friends-Of-Appropriate-Ages/README.md new file mode 100644 index 000000000..6249cc44c --- /dev/null +++ b/leetcode/0825.Friends-Of-Appropriate-Ages/README.md @@ -0,0 +1,141 @@ +# [825. Friends Of Appropriate Ages](https://leetcode.com/problems/friends-of-appropriate-ages/) + + +## 题目 + +There are `n` persons on a social media website. You are given an integer array `ages` where `ages[i]` is the age of the `ith` person. + +A Person `x` will not send a friend request to a person `y` (`x != y`) if any of the following conditions is true: + +- `age[y] <= 0.5 * age+ 7` +- `age[y] > age[x]` +- `age[y] > 100 && age< 100` + +Otherwise, `x` will send a friend request to `y`. + +Note that if `x` sends a request to `y`, `y` will not necessarily send a request to `x`. Also, a person will not send a friend request to themself. + +Return *the total number of friend requests made*. + +**Example 1:** + +``` +Input: ages = [16,16] +Output: 2 +Explanation: 2 people friend request each other. + +``` + +**Example 2:** + +``` +Input: ages = [16,17,18] +Output: 2 +Explanation: Friend requests are made 17 -> 16, 18 -> 17. + +``` + +**Example 3:** + +``` +Input: ages = [20,30,100,110,120] +Output: 3 +Explanation: Friend requests are made 110 -> 100, 120 -> 110, 120 -> 100. + +``` + +**Constraints:** + +- `n == ages.length` +- `1 <= n <= 2 * 10^4` +- `1 <= ages[i] <= 120` + +## 题目大意 + +在社交媒体网站上有 n 个用户。给你一个整数数组 ages ，其中 ages[i] 是第 i 个用户的年龄。 + +如果下述任意一个条件为真，那么用户 x 将不会向用户 y（x != y）发送好友请求： + +- ages[y] <= 0.5 * ages[x] + 7 +- ages[y] > ages[x] +- ages[y] > 100 && ages[x] < 100 + +否则，x 将会向 y 发送一条好友请求。注意，如果 x 向 y 发送一条好友请求，y 不必也向 x 发送一条好友请求。另外，用户不会向自己发送好友请求。返回在该社交媒体网站上产生的好友请求总数。 + +## 解题思路 + +- 解法三，暴力解法。先统计 [1,120] 范围内每个年龄的人数。然后利用题目中的三个判断条件，筛选符合条件的用户对。需要注意的是，相同年龄的人可以相互发送好友请求。不同年龄的人发送好友请求是单向的，即年龄老的向年龄轻的发送好友请求，年龄轻的不会对年龄老的发送好友请求。 +- 解法二，排序 + 双指针。题目给定的 3 个条件其实是 2 个。条件 3 包含在条件 2 中。条件 1 和条件 2 组合起来是 `0.5 × ages[x]+7 < ages[y] ≤ ages[x]`。当 ages[x] 小于 15 时，这个等式无解。考虑到年龄是单调递增的，`(0.5 × ages[x]+7,ages[x]]` 这个区间左右边界也是单调递增的。于是可以用双指针维护两个边界。在区间 [left, right] 内，这些下标对应的的 y 值都满足条件。当 `ages[left] > 0.5 × ages[x]+7` 时，左指针停止右移。当 `ages[right+1] > ages[x]` 时， 右指针停止右移。在 `[left, right]` 区间内，满足条件的 y 有 `right-left+1` 个，即使得 `ages[y]` 取值在 `(0.5 × ages[x]+7,ages[x]]` 之间。依照题意，`x≠y`，即该区间右边界取不到。y 的取值个数需要再减一，减去的是取到和 x 相同的值的下标。那么每个区间能取 `right-left` 个值。累加所有满足条件的值即为好友请求总数。 +- 解法一。在解法二中，计算满足不等式 y 下标所在区间的时候，区间和区间存在重叠的情况，这些重叠情况导致了重复计算。所以这里可以优化。可以用 prefix sum 前缀和数组优化。代码见下方。 + +## 代码 + +```go +package leetcocde + +import "sort" + +// 解法一 前缀和，时间复杂度 O(n) +func numFriendRequests(ages []int) int { + count, prefixSum, res := make([]int, 121), make([]int, 121), 0 + for _, age := range ages { + count[age]++ + } + for i := 1; i < 121; i++ { + prefixSum[i] = prefixSum[i-1] + count[i] + } + for i := 15; i < 121; i++ { + if count[i] > 0 { + bound := i/2 + 8 + res += count[i] * (prefixSum[i] - prefixSum[bound-1] - 1) + } + } + return res +} + +// 解法二 双指针 + 排序，时间复杂度 O(n logn) +func numFriendRequests1(ages []int) int { + sort.Ints(ages) + left, right, res := 0, 0, 0 + for _, age := range ages { + if age < 15 { + continue + } + for ages[left]*2 <= age+14 { + left++ + } + for right+1 < len(ages) && ages[right+1] <= age { + right++ + } + res += right - left + } + return res +} + +// 解法三 暴力解法 O(n^2) +func numFriendRequests2(ages []int) int { + res, count := 0, [125]int{} + for _, x := range ages { + count[x]++ + } + for i := 1; i <= 120; i++ { + for j := 1; j <= 120; j++ { + if j > i { + continue + } + if (j-7)*2 <= i { + continue + } + if j > 100 && i < 100 { + continue + } + if i != j { + res += count[i] * count[j] + } else { + res += count[i] * (count[j] - 1) + } + } + } + return res +} +``` \ No newline at end of file diff --git a/leetcode/0842.Split-Array-into-Fibonacci-Sequence/842. Split Array into Fibonacci Sequence.go b/leetcode/0842.Split-Array-into-Fibonacci-Sequence/842. Split Array into Fibonacci Sequence.go index 78c8b9847..f6851cbab 100644 --- a/leetcode/0842.Split-Array-into-Fibonacci-Sequence/842. Split Array into Fibonacci Sequence.go +++ b/leetcode/0842.Split-Array-into-Fibonacci-Sequence/842. Split Array into Fibonacci Sequence.go @@ -32,7 +32,7 @@ func splitIntoFibonacci(S string) []int { return res } -//Propagate for rest of the string +// Propagate for rest of the string func findRecursiveCheck(S string, x1 int, x2 int, left int, res *[]int, isComplete *bool) { if x1 >= 1<<31 || x2 >= 1<<31 { // 题目要求每个数都要小于 2^31 - 1 = 2147483647，此处剪枝很关键！ return diff --git a/leetcode/0846.Hand-of-Straights/846.Hand of Straights.go b/leetcode/0846.Hand-of-Straights/846.Hand of Straights.go new file mode 100644 index 000000000..ea54dda76 --- /dev/null +++ b/leetcode/0846.Hand-of-Straights/846.Hand of Straights.go @@ -0,0 +1,23 @@ +package leetcode + +import "sort" + +func isNStraightHand(hand []int, groupSize int) bool { + mp := make(map[int]int) + for _, v := range hand { + mp[v] += 1 + } + sort.Ints(hand) + for _, num := range hand { + if mp[num] == 0 { + continue + } + for diff := 0; diff < groupSize; diff++ { + if mp[num+diff] == 0 { + return false + } + mp[num+diff] -= 1 + } + } + return true +} diff --git a/leetcode/0846.Hand-of-Straights/846.Hand of Straights_test.go b/leetcode/0846.Hand-of-Straights/846.Hand of Straights_test.go new file mode 100644 index 000000000..2a172eb0e --- /dev/null +++ b/leetcode/0846.Hand-of-Straights/846.Hand of Straights_test.go @@ -0,0 +1,46 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question846 struct { + para846 + ans846 +} + +// para 是参数 +type para846 struct { + hand []int + groupSize int +} + +// ans 是答案 +type ans846 struct { + ans bool +} + +func Test_Problem846(t *testing.T) { + + qs := []question846{ + + { + para846{[]int{1, 2, 3, 6, 2, 3, 4, 7, 8}, 3}, + ans846{true}, + }, + + { + para846{[]int{1, 2, 3, 4, 5}, 4}, + ans846{false}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 846------------------------\n") + + for _, q := range qs { + _, p := q.ans846, q.para846 + fmt.Printf("【input】:%v 【output】:%v\n", p, isNStraightHand(p.hand, p.groupSize)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0846.Hand-of-Straights/README.md b/leetcode/0846.Hand-of-Straights/README.md new file mode 100644 index 000000000..5df17ba73 --- /dev/null +++ b/leetcode/0846.Hand-of-Straights/README.md @@ -0,0 +1,68 @@ +# [846. Hand of Straights](https://leetcode.com/problems/hand-of-straights/) + +## 题目 + +Alice has some number of cards and she wants to rearrange the cards into groups so that each group is of size groupSize, and consists of groupSize consecutive cards. + +Given an integer array hand where hand[i] is the value written on the ith card and an integer groupSize, return true if she can rearrange the cards, or false otherwise. + +**Example 1**: + + Input: hand = [1,2,3,6,2,3,4,7,8], groupSize = 3 + Output: true + Explanation: Alice's hand can be rearranged as [1,2,3],[2,3,4],[6,7,8] + +**Example 2**: + + Input: hand = [1,2,3,4,5], groupSize = 4 + Output: false + Explanation: Alice's hand can not be rearranged into groups of 4. + +**Constraints:** + +- 1 <= hand.length <= 10000 +- 0 <= hand[i] <= 1000000000 +- 1 <= groupSize <= hand.length + +## 题目大意 + +Alice 手中有一把牌，她想要重新排列这些牌，分成若干组，使每一组的牌数都是 groupSize ，并且由 groupSize 张连续的牌组成。 + +给你一个整数数组 hand 其中 hand[i] 是写在第 i 张牌，和一个整数 groupSize 。如果她可能重新排列这些牌，返回 true ；否则，返回 false 。 + +## 解题思路 + +贪心算法 + +- 对hand升序排序 +- 对hand内数字进行哈希计数（key:数字，value:数量） +- 遍历hand中的数字，以数量大于1的数字作为顺子开头，寻找顺子后续元素，若无法找到完整顺子则返回false +- 所有数字都能找到完整顺子返回true + +##代码 + +```go +package leetcode + +import "sort" + +func isNStraightHand(hand []int, groupSize int) bool { + mp := make(map[int]int) + for _, v := range hand { + mp[v] += 1 + } + sort.Ints(hand) + for _, num := range hand { + if mp[num] == 0 { + continue + } + for diff := 0; diff < groupSize; diff++ { + if mp[num+diff] == 0 { + return false + } + mp[num+diff] -= 1 + } + } + return true +} +``` \ No newline at end of file diff --git a/leetcode/0859.Buddy-Strings/859.Buddy Strings.go b/leetcode/0859.Buddy-Strings/859.Buddy Strings.go new file mode 100644 index 000000000..8688f16e3 --- /dev/null +++ b/leetcode/0859.Buddy-Strings/859.Buddy Strings.go @@ -0,0 +1,30 @@ +package leetcode + +func buddyStrings(s string, goal string) bool { + if len(s) != len(goal) || len(s) <= 1 { + return false + } + mp := make(map[byte]int) + if s == goal { + for i := 0; i < len(s); i++ { + if _, ok := mp[s[i]]; ok { + return true + } + mp[s[i]]++ + } + return false + } + first, second := -1, -1 + for i := 0; i < len(s); i++ { + if s[i] != goal[i] { + if first == -1 { + first = i + } else if second == -1 { + second = i + } else { + return false + } + } + } + return second != -1 && s[first] == goal[second] && s[second] == goal[first] +} diff --git a/leetcode/0859.Buddy-Strings/859.Buddy Strings_test.go b/leetcode/0859.Buddy-Strings/859.Buddy Strings_test.go new file mode 100644 index 000000000..3085e448e --- /dev/null +++ b/leetcode/0859.Buddy-Strings/859.Buddy Strings_test.go @@ -0,0 +1,56 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question859 struct { + para859 + ans859 +} + +// para 是参数 +type para859 struct { + s string + goal string +} + +// ans 是答案 +type ans859 struct { + ans bool +} + +func Test_Problem859(t *testing.T) { + + qs := []question859{ + + { + para859{"ab", "ba"}, + ans859{true}, + }, + + { + para859{"ab", "ab"}, + ans859{false}, + }, + + { + para859{"aa", "aa"}, + ans859{true}, + }, + + { + para859{"aaaaaaabc", "aaaaaaacb"}, + ans859{true}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 859------------------------\n") + + for _, q := range qs { + _, p := q.ans859, q.para859 + fmt.Printf("【input】:%v 【output】:%v\n", p, buddyStrings(p.s, p.goal)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0859.Buddy-Strings/README.md b/leetcode/0859.Buddy-Strings/README.md new file mode 100644 index 000000000..7a7e5c650 --- /dev/null +++ b/leetcode/0859.Buddy-Strings/README.md @@ -0,0 +1,87 @@ +# [859. Buddy Strings](https://leetcode.com/problems/buddy-strings/) + +## 题目 + +Given two strings s and goal, return true if you can swap two letters in s so the result is equal to goal, otherwise, return false. + +Swapping letters is defined as taking two indices i and j (0-indexed) such that i != j and swapping the characters at s[i] and s[j]. + +For example, swapping at indices 0 and 2 in "abcd" results in "cbad". + +**Example 1**: + + Input: s = "ab", goal = "ba" + Output: true + Explanation: You can swap s[0] = 'a' and s[1] = 'b' to get "ba", which is equal to goal. + +**Example 2**: + + Input: s = "ab", goal = "ab" + Output: false + Explanation: The only letters you can swap are s[0] = 'a' and s[1] = 'b', which results in "ba" != goal. + +**Example 3**: + + Input: s = "aa", goal = "aa" + Output: true + Explanation: You can swap s[0] = 'a' and s[1] = 'a' to get "aa", which is equal to goal. + +**Example 4**: + + Input: s = "aaaaaaabc", goal = "aaaaaaacb" + Output: true + +**Constraints:** + +- 1 <= s.length, goal.length <= 2 * 10000 +- s and goal consist of lowercase letters. + +## 题目大意 + +给你两个字符串 s 和 goal ，只要我们可以通过交换 s 中的两个字母得到与 goal 相等的结果，就返回 true；否则返回 false 。 + +交换字母的定义是：取两个下标 i 和 j （下标从 0 开始）且满足 i != j ，接着交换 s[i] 和 s[j] 处的字符。 + +例如，在 "abcd" 中交换下标 0 和下标 2 的元素可以生成 "cbad" 。 + +## 解题思路 + +分为两种情况进行比较: +- s 等于 goal, s 中有重复元素就返回 true,否则返回 false +- s 不等于 goal, s 中有两个下标不同的字符与 goal 中对应下标的字符分别相等 + +## 代码 + +```go + +package leetcode + +func buddyStrings(s string, goal string) bool { + if len(s) != len(goal) || len(s) <= 1 { + return false + } + mp := make(map[byte]int) + if s == goal { + for i := 0; i < len(s); i++ { + if _, ok := mp[s[i]]; ok { + return true + } + mp[s[i]]++ + } + return false + } + first, second := -1, -1 + for i := 0; i < len(s); i++ { + if s[i] != goal[i] { + if first == -1 { + first = i + } else if second == -1 { + second = i + } else { + return false + } + } + } + return second != -1 && s[first] == goal[second] && s[second] == goal[first] +} +``` \ No newline at end of file diff --git a/leetcode/0874.Walking-Robot-Simulation/874. Walking Robot Simulation.go b/leetcode/0874.Walking-Robot-Simulation/874. Walking Robot Simulation.go new file mode 100644 index 000000000..9393000b0 --- /dev/null +++ b/leetcode/0874.Walking-Robot-Simulation/874. Walking Robot Simulation.go @@ -0,0 +1,38 @@ +package leetcode + +func robotSim(commands []int, obstacles [][]int) int { + m := make(map[[2]int]struct{}) + for _, v := range obstacles { + if len(v) != 0 { + m[[2]int{v[0], v[1]}] = struct{}{} + } + } + directX := []int{0, 1, 0, -1} + directY := []int{1, 0, -1, 0} + direct, x, y := 0, 0, 0 + result := 0 + for _, c := range commands { + if c == -2 { + direct = (direct + 3) % 4 + continue + } + if c == -1 { + direct = (direct + 1) % 4 + continue + } + for ; c > 0; c-- { + nextX := x + directX[direct] + nextY := y + directY[direct] + if _, ok := m[[2]int{nextX, nextY}]; ok { + break + } + tmpResult := nextX*nextX + nextY*nextY + if tmpResult > result { + result = tmpResult + } + x = nextX + y = nextY + } + } + return result +} diff --git a/leetcode/0874.Walking-Robot-Simulation/874. Walking Robot Simulation_test.go b/leetcode/0874.Walking-Robot-Simulation/874. Walking Robot Simulation_test.go new file mode 100644 index 000000000..2553a4099 --- /dev/null +++ b/leetcode/0874.Walking-Robot-Simulation/874. Walking Robot Simulation_test.go @@ -0,0 +1,39 @@ +package leetcode + +import "testing" + +func Test_robotSim(t *testing.T) { + type args struct { + commands []int + obstacles [][]int + } + cases := []struct { + name string + args args + want int + }{ + { + "case 1", + args{ + commands: []int{4, -1, 3}, + obstacles: [][]int{{}}, + }, + 25, + }, + { + "case 2", + args{ + commands: []int{4, -1, 4, -2, 4}, + obstacles: [][]int{{2, 4}}, + }, + 65, + }, + } + for _, tt := range cases { + t.Run(tt.name, func(t *testing.T) { + if got := robotSim(tt.args.commands, tt.args.obstacles); got != tt.want { + t.Errorf("robotSim() = %v, want %v", got, tt.want) + } + }) + } +} diff --git a/leetcode/0874.Walking-Robot-Simulation/README.md b/leetcode/0874.Walking-Robot-Simulation/README.md new file mode 100644 index 000000000..aac2857de --- /dev/null +++ b/leetcode/0874.Walking-Robot-Simulation/README.md @@ -0,0 +1,135 @@ +# [874. Walking Robot Simulation](https://leetcode.com/problems/walking-robot-simulation/) + + +## 题目 + +A robot on an infinite XY-plane starts at point `(0, 0)` and faces north. The robot can receive one of three possible types of `commands`: + +- `2`: turn left `90` degrees, +- `1`: turn right `90` degrees, or +- `1 <= k <= 9`: move forward `k` units. + +Some of the grid squares are `obstacles`. The `ith` obstacle is at grid point `obstacles[i] = (xi, yi)`. + +If the robot would try to move onto them, the robot stays on the previous grid square instead (but still continues following the rest of the route.) + +Return *the maximum Euclidean distance that the robot will be from the origin **squared** (i.e. if the distance is* `5`*, return* `25`*)*. + +**Note:** + +- North means +Y direction. +- East means +X direction. +- South means -Y direction. +- West means -X direction. + +**Example 1:** + +``` +Input: commands = [4,-1,3], obstacles = [] +Output: 25 +Explanation: The robot starts at (0, 0): +1. Move north 4 units to (0, 4). +2. Turn right. +3. Move east 3 units to (3, 4). +The furthest point away from the origin is (3, 4), which is 32 + 42 = 25 units away. + +``` + +**Example 2:** + +``` +Input: commands = [4,-1,4,-2,4], obstacles = [[2,4]] +Output: 65 +Explanation: The robot starts at (0, 0): +1. Move north 4 units to (0, 4). +2. Turn right. +3. Move east 1 unit and get blocked by the obstacle at (2, 4), robot is at (1, 4). +4. Turn left. +5. Move north 4 units to (1, 8). +The furthest point away from the origin is (1, 8), which is 12 + 82 = 65 units away. + +``` + +**Constraints:** + +- `1 <= commands.length <= 104` +- `commands[i]` is one of the values in the list `[-2,-1,1,2,3,4,5,6,7,8,9]`. +- `0 <= obstacles.length <= 104` +- `3 * 104 <= xi, yi <= 3 * 104` +- The answer is guaranteed to be less than `231`. + +## 题目大意 + +机器人在一个无限大小的 XY 网格平面上行走，从点 (0, 0) 处开始出发，面向北方。该机器人可以接收以下三种类型的命令 commands ： + +- 2 ：向左转 90 度 +- -1 ：向右转 90 度 +- 1 <= x <= 9 ：向前移动 x 个单位长度 + +在网格上有一些格子被视为障碍物 obstacles 。第 i 个障碍物位于网格点 obstacles[i] = (xi, yi) 。机器人无法走到障碍物上，它将会停留在障碍物的前一个网格方块上，但仍然可以继续尝试进行该路线的其余部分。返回从原点到机器人所有经过的路径点（坐标为整数）的最大欧式距离的平方。（即，如果距离为 5 ，则返回 25 ） + +注意： + +- 北表示 +Y 方向。 +- 东表示 +X 方向。 +- 南表示 -Y 方向。 +- 西表示 -X 方向。 + +## 解题思路 + +- 这个题的难点在于，怎么用编程语言去描述机器人的行为，可以用以下数据结构表达机器人的行为： + + ```go + direct:= 0 // direct表示机器人移动方向：0 1 2 3 4 （北东南西），默认朝北 + x, y := 0, 0 // 表示当前机器人所在横纵坐标位置，默认为(0,0) + directX := []int{0, 1, 0, -1} + directY := []int{1, 0, -1, 0} + // 组合directX directY和direct，表示机器人往某一个方向移动 + nextX := x + directX[direct] + nextY := y + directY[direct] + ``` + + 其他代码按照题意翻译即可 + +## 代码 + +```go +package leetcode + +func robotSim(commands []int, obstacles [][]int) int { + m := make(map[[2]int]struct{}) + for _, v := range obstacles { + if len(v) != 0 { + m[[2]int{v[0], v[1]}] = struct{}{} + } + } + directX := []int{0, 1, 0, -1} + directY := []int{1, 0, -1, 0} + direct, x, y := 0, 0, 0 + result := 0 + for _, c := range commands { + if c == -2 { + direct = (direct + 3) % 4 + continue + } + if c == -1 { + direct = (direct + 1) % 4 + continue + } + for ; c > 0; c-- { + nextX := x + directX[direct] + nextY := y + directY[direct] + if _, ok := m[[2]int{nextX, nextY}]; ok { + break + } + tmpResult := nextX*nextX + nextY*nextY + if tmpResult > result { + result = tmpResult + } + x = nextX + y = nextY + } + } + return result +} +``` \ No newline at end of file diff --git a/leetcode/0875.Koko-Eating-Bananas/875. Koko Eating Bananas_test.go b/leetcode/0875.Koko-Eating-Bananas/875. Koko Eating Bananas_test.go index a2a6eba65..b9fcc115e 100644 --- a/leetcode/0875.Koko-Eating-Bananas/875. Koko Eating Bananas_test.go +++ b/leetcode/0875.Koko-Eating-Bananas/875. Koko Eating Bananas_test.go @@ -41,6 +41,11 @@ func Test_Problem875(t *testing.T) { para875{[]int{30, 11, 23, 4, 20}, 6}, ans875{23}, }, + + { + para875{[]int{4, 9, 11, 17}, 8}, + ans875{6}, + }, } fmt.Printf("------------------------Leetcode Problem 875------------------------\n") diff --git a/leetcode/0877.Stone-Game/877. Stone Game.go b/leetcode/0877.Stone-Game/877. Stone Game.go new file mode 100644 index 000000000..86a89974d --- /dev/null +++ b/leetcode/0877.Stone-Game/877. Stone Game.go @@ -0,0 +1,5 @@ +package leetcode + +func stoneGame(piles []int) bool { + return true +} diff --git a/leetcode/0877.Stone-Game/877. Stone Game_test.go b/leetcode/0877.Stone-Game/877. Stone Game_test.go new file mode 100644 index 000000000..316c42c48 --- /dev/null +++ b/leetcode/0877.Stone-Game/877. Stone Game_test.go @@ -0,0 +1,42 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question877 struct { + para877 + ans877 +} + +// para 是参数 +// one 代表第一个参数 +type para877 struct { + piles []int +} + +// ans 是答案 +// one 代表第一个答案 +type ans877 struct { + one bool +} + +func Test_Problem877(t *testing.T) { + + qs := []question877{ + + { + para877{[]int{5, 3, 4, 5}}, + ans877{true}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 877------------------------\n") + + for _, q := range qs { + _, p := q.ans877, q.para877 + fmt.Printf("【input】:%v 【output】:%v\n", p, stoneGame(p.piles)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0877.Stone-Game/README.md b/leetcode/0877.Stone-Game/README.md new file mode 100644 index 000000000..6a23bfad6 --- /dev/null +++ b/leetcode/0877.Stone-Game/README.md @@ -0,0 +1,50 @@ +# [877. Stone Game](https://leetcode.com/problems/stone-game/) + +## 题目 + +Alex and Lee play a game with piles of stones.  There are an even number of piles **arranged in a row**, and each pile has a positive integer number of stones `piles[i]`. + +The objective of the game is to end with the most stones.  The total number of stones is odd, so there are no ties. + +Alex and Lee take turns, with Alex starting first.  Each turn, a player takes the entire pile of stones from either the beginning or the end of the row.  This continues until there are no more piles left, at which point the person with the most stones wins. + +Assuming Alex and Lee play optimally, return `True` if and only if Alex wins the game. + +**Example 1:** + +``` +Input: piles = [5,3,4,5] +Output: true +Explanation: +Alex starts first, and can only take the first 5 or the last 5. +Say he takes the first 5, so that the row becomes [3, 4, 5]. +If Lee takes 3, then the board is [4, 5], and Alex takes 5 to win with 10 points. +If Lee takes the last 5, then the board is [3, 4], and Alex takes 4 to win with 9 points. +This demonstrated that taking the first 5 was a winning move for Alex, so we return true. + +``` + +**Constraints:** + +- `2 <= piles.length <= 500` +- `piles.length` is even. +- `1 <= piles[i] <= 500` +- `sum(piles)` is odd. + +## 题目大意 + +亚历克斯和李用几堆石子在做游戏。偶数堆石子排成一行，每堆都有正整数颗石子 piles[i] 。游戏以谁手中的石子最多来决出胜负。石子的总数是奇数，所以没有平局。亚历克斯和李轮流进行，亚历克斯先开始。 每回合，玩家从行的开始或结束处取走整堆石头。 这种情况一直持续到没有更多的石子堆为止，此时手中石子最多的玩家获胜。假设亚历克斯和李都发挥出最佳水平，当亚历克斯赢得比赛时返回 true ，当李赢得比赛时返回 false 。 + +## 解题思路 + +- 一遇到石子问题，很容易让人联想到是否和奇偶数相关。此题指定了石子堆数一定是偶数。所以从这里为突破口试试。Alex 先拿，要么取行首下标为 0 的石子，要么取行尾下标为 n-1 的石子。假设取下标为 0 的石子，剩下的石子堆下标从 1 ~ n-1，即 Lee 只能从奇数下标的石子堆 1 或者 n-1。假设 Alex 第一次取下标为 n-1 的石子，剩下的石子堆下标从 0 ~ n-2，即 Lee 只能取偶数下标的石子堆。于是 Alex 的必胜策略是每轮取石子，取此轮奇数下标堆石子数总和，偶数下标堆石子数总和，两者大者。那么下一轮 Lee 只能取石子堆数相对少的那一堆，并且 Lee 取的石子堆下标奇偶性是完全受到上一轮 Alex 控制的。所以只要是 Alex 先手，那么每轮都可以压制 Lee，从而必胜。 + +## 代码 + +```go +package leetcode + +func stoneGame(piles []int) bool { + return true +} +``` \ No newline at end of file diff --git a/leetcode/0890.Find-and-Replace-Pattern/890. Find and Replace Pattern.go b/leetcode/0890.Find-and-Replace-Pattern/890. Find and Replace Pattern.go new file mode 100644 index 000000000..0a3300f3b --- /dev/null +++ b/leetcode/0890.Find-and-Replace-Pattern/890. Find and Replace Pattern.go @@ -0,0 +1,32 @@ +package leetcode + +func findAndReplacePattern(words []string, pattern string) []string { + res := make([]string, 0) + for _, word := range words { + if match(word, pattern) { + res = append(res, word) + } + } + return res +} + +func match(w, p string) bool { + if len(w) != len(p) { + return false + } + m, used := make(map[uint8]uint8), make(map[uint8]bool) + for i := 0; i < len(w); i++ { + if v, ok := m[p[i]]; ok { + if w[i] != v { + return false + } + } else { + if used[w[i]] { + return false + } + m[p[i]] = w[i] + used[w[i]] = true + } + } + return true +} diff --git a/leetcode/0890.Find-and-Replace-Pattern/890. Find and Replace Pattern_test.go b/leetcode/0890.Find-and-Replace-Pattern/890. Find and Replace Pattern_test.go new file mode 100644 index 000000000..3fdfd1971 --- /dev/null +++ b/leetcode/0890.Find-and-Replace-Pattern/890. Find and Replace Pattern_test.go @@ -0,0 +1,48 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question890 struct { + para890 + ans890 +} + +// para 是参数 +// one 代表第一个参数 +type para890 struct { + words []string + pattern string +} + +// ans 是答案 +// one 代表第一个答案 +type ans890 struct { + one []string +} + +func Test_Problem890(t *testing.T) { + + qs := []question890{ + + { + para890{[]string{"abc", "deq", "mee", "aqq", "dkd", "ccc"}, "abb"}, + ans890{[]string{"mee", "aqq"}}, + }, + + { + para890{[]string{"a", "b", "c"}, "a"}, + ans890{[]string{"a", "b", "c"}}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 890------------------------\n") + + for _, q := range qs { + _, p := q.ans890, q.para890 + fmt.Printf("【input】:%v 【output】:%v\n", p, findAndReplacePattern(p.words, p.pattern)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0890.Find-and-Replace-Pattern/README.md b/leetcode/0890.Find-and-Replace-Pattern/README.md new file mode 100644 index 000000000..c2cb6bb50 --- /dev/null +++ b/leetcode/0890.Find-and-Replace-Pattern/README.md @@ -0,0 +1,78 @@ +# [890. Find and Replace Pattern](https://leetcode.com/problems/find-and-replace-pattern/) + + +## 题目 + +Given a list of strings `words` and a string `pattern`, return *a list of* `words[i]` *that match* `pattern`. You may return the answer in **any order**. + +A word matches the pattern if there exists a permutation of letters `p` so that after replacing every letter `x` in the pattern with `p(x)`, we get the desired word. + +Recall that a permutation of letters is a bijection from letters to letters: every letter maps to another letter, and no two letters map to the same letter. + +**Example 1:** + +``` +Input: words = ["abc","deq","mee","aqq","dkd","ccc"], pattern = "abb" +Output: ["mee","aqq"] +Explanation: "mee" matches the pattern because there is a permutation {a -> m, b -> e, ...}. +"ccc" does not match the pattern because {a -> c, b -> c, ...} is not a permutation, since a and b map to the same letter. +``` + +**Example 2:** + +``` +Input: words = ["a","b","c"], pattern = "a" +Output: ["a","b","c"] +``` + +**Constraints:** + +- `1 <= pattern.length <= 20` +- `1 <= words.length <= 50` +- `words[i].length == pattern.length` +- `pattern` and `words[i]` are lowercase English letters. + +## 题目大意 + +你有一个单词列表 words 和一个模式  pattern，你想知道 words 中的哪些单词与模式匹配。如果存在字母的排列 p ，使得将模式中的每个字母 x 替换为 p(x) 之后，我们就得到了所需的单词，那么单词与模式是匹配的。（回想一下，字母的排列是从字母到字母的双射：每个字母映射到另一个字母，没有两个字母映射到同一个字母。）返回 words 中与给定模式匹配的单词列表。你可以按任何顺序返回答案。 + +## 解题思路 + +- 按照题目要求，分别映射两个字符串，words 字符串数组中的字符串与 pattern 字符串每个字母做映射。这里用 map 存储。题目还要求不存在 2 个字母映射到同一个字母的情况，所以再增加一个 map，用来判断当前字母是否已经被映射过了。以上 2 个条件都满足即代表模式匹配上了。最终将所有满足模式匹配的字符串输出即可。 + +## 代码 + +```go +package leetcode + +func findAndReplacePattern(words []string, pattern string) []string { + res := make([]string, 0) + for _, word := range words { + if match(word, pattern) { + res = append(res, word) + } + } + return res +} + +func match(w, p string) bool { + if len(w) != len(p) { + return false + } + m, used := make(map[uint8]uint8), make(map[uint8]bool) + for i := 0; i < len(w); i++ { + if v, ok := m[p[i]]; ok { + if w[i] != v { + return false + } + } else { + if used[w[i]] { + return false + } + m[p[i]] = w[i] + used[w[i]] = true + } + } + return true +} +``` \ No newline at end of file diff --git a/leetcode/0909.Snakes-and-Ladders/909. Snakes and Ladders.go b/leetcode/0909.Snakes-and-Ladders/909. Snakes and Ladders.go new file mode 100644 index 000000000..51c8c6be3 --- /dev/null +++ b/leetcode/0909.Snakes-and-Ladders/909. Snakes and Ladders.go @@ -0,0 +1,42 @@ +package leetcode + +type pair struct { + id, step int +} + +func snakesAndLadders(board [][]int) int { + n := len(board) + visited := make([]bool, n*n+1) + queue := []pair{{1, 0}} + for len(queue) > 0 { + p := queue[0] + queue = queue[1:] + for i := 1; i <= 6; i++ { + nxt := p.id + i + if nxt > n*n { // 超出边界 + break + } + r, c := getRowCol(nxt, n) // 得到下一步的行列 + if board[r][c] > 0 { // 存在蛇或梯子 + nxt = board[r][c] + } + if nxt == n*n { // 到达终点 + return p.step + 1 + } + if !visited[nxt] { + visited[nxt] = true + queue = append(queue, pair{nxt, p.step + 1}) // 扩展新状态 + } + } + } + return -1 +} + +func getRowCol(id, n int) (r, c int) { + r, c = (id-1)/n, (id-1)%n + if r%2 == 1 { + c = n - 1 - c + } + r = n - 1 - r + return r, c +} diff --git a/leetcode/0909.Snakes-and-Ladders/909. Snakes and Ladders_test.go b/leetcode/0909.Snakes-and-Ladders/909. Snakes and Ladders_test.go new file mode 100644 index 000000000..7d3d5ba16 --- /dev/null +++ b/leetcode/0909.Snakes-and-Ladders/909. Snakes and Ladders_test.go @@ -0,0 +1,45 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question909 struct { + para909 + ans909 +} + +// para 是参数 +// one 代表第一个参数 +type para909 struct { + one [][]int +} + +// ans 是答案 +// one 代表第一个答案 +type ans909 struct { + one int +} + +func Test_Problem909(t *testing.T) { + qs := []question909{ + { + para909{[][]int{ + {-1, -1, -1, -1, -1, -1}, + {-1, -1, -1, -1, -1, -1}, + {-1, -1, -1, -1, -1, -1}, + {-1, 35, -1, -1, 13, -1}, + {-1, -1, -1, -1, -1, -1}, + {-1, 15, -1, -1, -1, -1}, + }}, + ans909{4}, + }, + } + fmt.Printf("------------------------Leetcode Problem 909------------------------\n") + for _, q := range qs { + _, p := q.ans909, q.para909 + fmt.Printf("【input】:%v 【output】:%v\n", p, snakesAndLadders(p.one)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0909.Snakes-and-Ladders/README.md b/leetcode/0909.Snakes-and-Ladders/README.md new file mode 100644 index 000000000..43b899568 --- /dev/null +++ b/leetcode/0909.Snakes-and-Ladders/README.md @@ -0,0 +1,110 @@ +# [909. Snakes and Ladders](https://leetcode.com/problems/snakes-and-ladders/) + + +## 题目 + +On an N x N `board`, the numbers from `1` to `N*N` are written *boustrophedonically* **starting from the bottom left of the board**, and alternating direction each row.  For example, for a 6 x 6 board, the numbers are written as follows: + + +![](https://assets.leetcode.com/uploads/2018/09/23/snakes.png) + +You start on square `1` of the board (which is always in the last row and first column).  Each move, starting from square `x`, consists of the following: + +- You choose a destination square `S` with number `x+1`, `x+2`, `x+3`, `x+4`, `x+5`, or `x+6`, provided this number is `<= N*N`. + - (This choice simulates the result of a standard 6-sided die roll: ie., there are always **at most 6 destinations, regardless of the size of the board**.) +- If `S` has a snake or ladder, you move to the destination of that snake or ladder. Otherwise, you move to `S`. + +A board square on row `r` and column `c` has a "snake or ladder" if `board[r][c] != -1`.  The destination of that snake or ladder is `board[r][c]`. + +Note that you only take a snake or ladder at most once per move: if the destination to a snake or ladder is the start of another snake or ladder, you do **not** continue moving.  (For example, if the board is `[[4,-1],[-1,3]]`, and on the first move your destination square is `2`, then you finish your first move at `3`, because you do **not** continue moving to `4`.) + +Return the least number of moves required to reach square N*N.  If it is not possible, return `-1`. + +**Example 1:** + +``` +Input:[ +[-1,-1,-1,-1,-1,-1], +[-1,-1,-1,-1,-1,-1], +[-1,-1,-1,-1,-1,-1], +[-1,35,-1,-1,13,-1], +[-1,-1,-1,-1,-1,-1], +[-1,15,-1,-1,-1,-1]] +Output:4 +Explanation: +At the beginning, you start at square 1 [at row 5, column 0]. +You decide to move to square 2, and must take the ladder to square 15. +You then decide to move to square 17 (row 3, column 5), and must take the snake to square 13. +You then decide to move to square 14, and must take the ladder to square 35. +You then decide to move to square 36, ending the game. +It can be shown that you need at least 4 moves to reach the N*N-th square, so the answer is 4. + +``` + +**Note:** + +1. `2 <= board.length = board[0].length <= 20` +2. `board[i][j]` is between `1` and `N*N` or is equal to `1`. +3. The board square with number `1` has no snake or ladder. +4. The board square with number `N*N` has no snake or ladder. + +## 题目大意 + +N x N 的棋盘 board 上，按从 1 到 N*N 的数字给方格编号，编号 从左下角开始，每一行交替方向。r 行 c 列的棋盘，按前述方法编号，棋盘格中可能存在 “蛇” 或 “梯子”；如果 board[r][c] != -1，那个蛇或梯子的目的地将会是 board[r][c]。玩家从棋盘上的方格 1 （总是在最后一行、第一列）开始出发。每一回合，玩家需要从当前方格 x 开始出发，按下述要求前进：选定目标方格： + +- 选择从编号 x+1，x+2，x+3，x+4，x+5，或者 x+6 的方格中选出一个目标方格 s ，目标方格的编号 <= N*N。该选择模拟了掷骰子的情景，无论棋盘大小如何，你的目的地范围也只能处于区间 [x+1, x+6] 之间。 +- 传送玩家：如果目标方格 S 处存在蛇或梯子，那么玩家会传送到蛇或梯子的目的地。否则，玩家传送到目标方格 S。 + +注意，玩家在每回合的前进过程中最多只能爬过蛇或梯子一次：就算目的地是另一条蛇或梯子的起点，你也不会继续移动。返回达到方格 N*N 所需的最少移动次数，如果不可能，则返回 -1。 + +## 解题思路 + +- 这一题可以抽象为在有向图上求下标 1 的起点到下标 `N^2` 的终点的最短路径。用广度优先搜索。棋盘可以抽象成一个包含 `N^2` 个节点的有向图，对于每个节点 `x`，若 `x+i (1 ≤ i ≤ 6)` 上没有蛇或梯子，则连一条从 `x` 到 `x+i` 的有向边；否则记蛇梯的目的地为 `y`，连一条从 `x` 到 `y` 的有向边。然后按照最短路径的求解方式便可解题。时间复杂度 O(n^2)，空间复杂度 O(n^2)。 +- 此题棋盘上的下标是蛇形的，所以遍历下一个点的时候需要转换坐标。具体做法根据行的奇偶性，行号为偶数，下标从左往右，行号为奇数，下标从右往左。具体实现见 `getRowCol()` 函数。 + +## 代码 + +```go +package leetcode + +type pair struct { + id, step int +} + +func snakesAndLadders(board [][]int) int { + n := len(board) + visited := make([]bool, n*n+1) + queue := []pair{{1, 0}} + for len(queue) > 0 { + p := queue[0] + queue = queue[1:] + for i := 1; i <= 6; i++ { + nxt := p.id + i + if nxt > n*n { // 超出边界 + break + } + r, c := getRowCol(nxt, n) // 得到下一步的行列 + if board[r][c] > 0 { // 存在蛇或梯子 + nxt = board[r][c] + } + if nxt == n*n { // 到达终点 + return p.step + 1 + } + if !visited[nxt] { + visited[nxt] = true + queue = append(queue, pair{nxt, p.step + 1}) // 扩展新状态 + } + } + } + return -1 +} + +func getRowCol(id, n int) (r, c int) { + r, c = (id-1)/n, (id-1)%n + if r%2 == 1 { + c = n - 1 - c + } + r = n - 1 - r + return r, c +} +``` \ No newline at end of file diff --git a/leetcode/0918.Maximum-Sum-Circular-Subarray/918. Maximum Sum Circular Subarray.go b/leetcode/0918.Maximum-Sum-Circular-Subarray/918. Maximum Sum Circular Subarray.go index dd3c9a3e4..9057d97ab 100644 --- a/leetcode/0918.Maximum-Sum-Circular-Subarray/918. Maximum Sum Circular Subarray.go +++ b/leetcode/0918.Maximum-Sum-Circular-Subarray/918. Maximum Sum Circular Subarray.go @@ -2,34 +2,50 @@ package leetcode import "math" -func maxSubarraySumCircular(A []int) int { - n, sum := len(A), 0 - for _, v := range A { - sum += v - } - kad := kadane(A) - for i := 0; i < n; i++ { - A[i] = -A[i] +func maxSubarraySumCircular(nums []int) int { + var max1, max2, sum int + + // case: no circulation + max1 = int(math.Inf(-1)) + l := len(nums) + for i := 0; i < l; i++ { + sum += nums[i] + if sum > max1 { + max1 = sum + } + if sum < 1 { + sum = 0 + } } - negativeMax := kadane(A) - if sum+negativeMax <= 0 { - return kad + + // case: circling + arr_sum := 0 + for i := 0; i < l; i++ { + arr_sum += nums[i] } - return max(kad, sum+negativeMax) -} -func kadane(a []int) int { - n, MaxEndingHere, maxSoFar := len(a), a[0], math.MinInt32 - for i := 1; i < n; i++ { - MaxEndingHere = max(a[i], MaxEndingHere+a[i]) - maxSoFar = max(MaxEndingHere, maxSoFar) + sum = 0 + min_sum := 0 + for i := 1; i < l-1; i++ { + sum += nums[i] + if sum >= 0 { + sum = 0 + } + if sum < min_sum { + min_sum = sum + } } - return maxSoFar + max2 = arr_sum - min_sum + + return max(max1, max2) } -func max(a int, b int) int { - if a > b { - return a +func max(nums ...int) int { + max := int(math.Inf(-1)) + for _, num := range nums { + if num > max { + max = num + } } - return b + return max } diff --git a/leetcode/0958.Check-Completeness-of-a-Binary-Tree/0958.Check Completeness of a Binary Tree.go b/leetcode/0958.Check-Completeness-of-a-Binary-Tree/0958.Check Completeness of a Binary Tree.go new file mode 100644 index 000000000..96fb1141e --- /dev/null +++ b/leetcode/0958.Check-Completeness-of-a-Binary-Tree/0958.Check Completeness of a Binary Tree.go @@ -0,0 +1,35 @@ +package leetcode + +import ( + "github.com/halfrost/LeetCode-Go/structures" +) + +// TreeNode define +type TreeNode = structures.TreeNode + +/** + * Definition for a binary tree node. + * type TreeNode struct { + * Val int + * Left *TreeNode + * Right *TreeNode + * } + */ + +func isCompleteTree(root *TreeNode) bool { + queue, found := []*TreeNode{root}, false + for len(queue) > 0 { + node := queue[0] //取出每一层的第一个节点 + queue = queue[1:] + if node == nil { + found = true + } else { + if found { + return false // 层序遍历中，两个不为空的节点中出现一个 nil + } + //如果左孩子为nil，则append进去的node.Left为nil + queue = append(queue, node.Left, node.Right) + } + } + return true +} diff --git a/leetcode/0958.Check-Completeness-of-a-Binary-Tree/0958.Check Completeness of a Binary Tree_test.go b/leetcode/0958.Check-Completeness-of-a-Binary-Tree/0958.Check Completeness of a Binary Tree_test.go new file mode 100644 index 000000000..6eb4df6d4 --- /dev/null +++ b/leetcode/0958.Check-Completeness-of-a-Binary-Tree/0958.Check Completeness of a Binary Tree_test.go @@ -0,0 +1,51 @@ +package leetcode + +import ( + "fmt" + "testing" + + "github.com/halfrost/LeetCode-Go/structures" +) + +type question958 struct { + para958 + ans958 +} + +// para 是参数 +// one 代表第一个参数 +type para958 struct { + one []int +} + +// ans 是答案 +// one 代表第一个答案 +type ans958 struct { + one bool +} + +func Test_Problem958(t *testing.T) { + + qs := []question958{ + + { + para958{[]int{1, 2, 3, 4, 5, 6}}, + ans958{true}, + }, + + { + para958{[]int{1, 2, 3, 4, 5, structures.NULL, 7}}, + ans958{false}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 958------------------------\n") + + for _, q := range qs { + _, p := q.ans958, q.para958 + fmt.Printf("【input】:%v ", p) + root := structures.Ints2TreeNode(p.one) + fmt.Printf("【output】:%v \n", isCompleteTree(root)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0958.Check-Completeness-of-a-Binary-Tree/README.md b/leetcode/0958.Check-Completeness-of-a-Binary-Tree/README.md new file mode 100644 index 000000000..4325c36e8 --- /dev/null +++ b/leetcode/0958.Check-Completeness-of-a-Binary-Tree/README.md @@ -0,0 +1,89 @@ +# [958. Check Completeness of a Binary Tree](https://leetcode.com/problems/check-completeness-of-a-binary-tree/) + + +## 题目 + +Given the `root` of a binary tree, determine if it is a *complete binary tree*. + +In a **[complete binary tree](http://en.wikipedia.org/wiki/Binary_tree#Types_of_binary_trees)**, every level, except possibly the last, is completely filled, and all nodes in the last level are as far left as possible. It can have between `1` and `2h` nodes inclusive at the last level `h`. + +**Example 1:** + +![https://assets.leetcode.com/uploads/2018/12/15/complete-binary-tree-1.png](https://assets.leetcode.com/uploads/2018/12/15/complete-binary-tree-1.png) + +``` +Input: root = [1,2,3,4,5,6] +Output: true +Explanation: Every level before the last is full (ie. levels with node-values {1} and {2, 3}), and all nodes in the last level ({4, 5, 6}) are as far left as possible. + +``` + +**Example 2:** + +![https://assets.leetcode.com/uploads/2018/12/15/complete-binary-tree-2.png](https://assets.leetcode.com/uploads/2018/12/15/complete-binary-tree-2.png) + +``` +Input: root = [1,2,3,4,5,null,7] +Output: false +Explanation: The node with value 7 isn't as far left as possible. + +``` + +**Constraints:** + +- The number of nodes in the tree is in the range `[1, 100]`. +- `1 <= Node.val <= 1000` + +## 题目大意 + +给定一个二叉树，确定它是否是一个完全二叉树。 + +百度百科中对完全二叉树的定义如下： + +若设二叉树的深度为 h，除第 h 层外，其它各层 (1～h-1) 的结点数都达到最大个数，第 h 层所有的结点都连续集中在最左边，这就是完全二叉树。（注：第 h 层可能包含 1~ 2h 个节点。） + +## 解题思路 + +- 这一题是按层序遍历的变种题。 +- 判断每个节点的左孩子是否为空。 +- 类似的题目，第 102，107，199 题都是按层序遍历的。 + +## 代码 + +```go +package leetcode + +import ( + "github.com/halfrost/LeetCode-Go/structures" +) + +// TreeNode define +type TreeNode = structures.TreeNode + +/** + * Definition for a binary tree node. + * type TreeNode struct { + * Val int + * Left *TreeNode + * Right *TreeNode + * } + */ + +func isCompleteTree(root *TreeNode) bool { + queue, found := []*TreeNode{root}, false + for len(queue) > 0 { + node := queue[0] //取出每一层的第一个节点 + queue = queue[1:] + if node == nil { + found = true + } else { + if found { + return false // 层序遍历中，两个不为空的节点中出现一个 nil + } + //如果左孩子为nil，则append进去的node.Left为nil + queue = append(queue, node.Left, node.Right) + } + } + return true +} +``` \ No newline at end of file diff --git a/leetcode/0978.Longest-Turbulent-Subarray/978. Longest Turbulent Subarray.go b/leetcode/0978.Longest-Turbulent-Subarray/978. Longest Turbulent Subarray.go index 8a0890269..7de2db2cc 100644 --- a/leetcode/0978.Longest-Turbulent-Subarray/978. Longest Turbulent Subarray.go +++ b/leetcode/0978.Longest-Turbulent-Subarray/978. Longest Turbulent Subarray.go @@ -1,14 +1,14 @@ package leetcode // 解法一 模拟法 -func maxTurbulenceSize(A []int) int { +func maxTurbulenceSize(arr []int) int { inc, dec := 1, 1 - maxLen := min(1, len(A)) - for i := 1; i < len(A); i++ { - if A[i-1] < A[i] { + maxLen := min(1, len(arr)) + for i := 1; i < len(arr); i++ { + if arr[i-1] < arr[i] { inc = dec + 1 dec = 1 - } else if A[i-1] > A[i] { + } else if arr[i-1] > arr[i] { dec = inc + 1 inc = 1 } else { @@ -35,23 +35,21 @@ func min(a int, b int) int { } // 解法二 滑动窗口 -func maxTurbulenceSize1(A []int) int { - if len(A) == 1 { - return 1 +func maxTurbulenceSize1(arr []int) int { + var maxLength int + if len(arr) == 2 && arr[0] != arr[1] { + maxLength = 2 + } else { + maxLength = 1 } - // flag > 0 代表下一个数要大于前一个数，flag < 0 代表下一个数要小于前一个数 - res, left, right, flag, lastNum := 0, 0, 0, A[1]-A[0], A[0] - for left < len(A) { - if right < len(A)-1 && ((A[right+1] > lastNum && flag > 0) || (A[right+1] < lastNum && flag < 0) || (right == left)) { - right++ - flag = lastNum - A[right] - lastNum = A[right] - } else { - if flag != 0 { - res = max(res, right-left+1) - } - left++ + left := 0 + for right := 2; right < len(arr); right++ { + if arr[right] == arr[right-1] { + left = right + } else if (arr[right]-arr[right-1])^(arr[right-1]-arr[right-2]) >= 0 { + left = right - 1 } + maxLength = max(maxLength, right-left+1) } - return max(res, 1) + return maxLength } diff --git a/leetcode/0978.Longest-Turbulent-Subarray/README.md b/leetcode/0978.Longest-Turbulent-Subarray/README.md index 01583dee8..e38c46533 100755 --- a/leetcode/0978.Longest-Turbulent-Subarray/README.md +++ b/leetcode/0978.Longest-Turbulent-Subarray/README.md @@ -1,58 +1,58 @@ -# [978. Longest Turbulent Subarray](https://leetcode.com/problems/longest-turbulent-subarray/) - -## 题目 - -A subarray `A[i], A[i+1], ..., A[j]` of `A` is said to be *turbulent* if and only if: - -- For `i <= k < j`, `A[k] > A[k+1]` when `k` is odd, and `A[k] < A[k+1]` when `k` is even; -- **OR**, for `i <= k < j`, `A[k] > A[k+1]` when `k` is even, and `A[k] < A[k+1]` when `k` is odd. - -That is, the subarray is turbulent if the comparison sign flips between each adjacent pair of elements in the subarray. - -Return the **length** of a maximum size turbulent subarray of A. - -**Example 1:** - - Input: [9,4,2,10,7,8,8,1,9] - Output: 5 - Explanation: (A[1] > A[2] < A[3] > A[4] < A[5]) - -**Example 2:** - - Input: [4,8,12,16] - Output: 2 - -**Example 3:** - - Input: [100] - Output: 1 - -**Note:** - -1. `1 <= A.length <= 40000` -2. `0 <= A[i] <= 10^9` - - -## 题目大意 - - -当 A 的子数组 A[i], A[i+1], ..., A[j] 满足下列条件时，我们称其为湍流子数组： - -若 i <= k < j，当 k 为奇数时， A[k] > A[k+1]，且当 k 为偶数时，A[k] < A[k+1]； -或 若 i <= k < j，当 k 为偶数时，A[k] > A[k+1] ，且当 k 为奇数时， A[k] < A[k+1]。 -也就是说，如果比较符号在子数组中的每个相邻元素对之间翻转，则该子数组是湍流子数组。 - -返回 A 的最大湍流子数组的长度。 - -提示： - -- 1 <= A.length <= 40000 -- 0 <= A[i] <= 10^9 - - - -## 解题思路 - - -- 给出一个数组，要求找出“摆动数组”的最大长度。所谓“摆动数组”的意思是，元素一大一小间隔的。 -- 这一题可以用滑动窗口来解答。用一个变量记住下次出现的元素需要大于还是需要小于前一个元素。也可以用模拟的方法，用两个变量分别记录上升和下降数字的长度。一旦元素相等了，上升和下降数字长度都置为 1，其他时候按照上升和下降的关系增加队列长度即可，最后输出动态维护的最长长度。 +# [978. Longest Turbulent Subarray](https://leetcode.com/problems/longest-turbulent-subarray/) + +## 题目 + +A subarray `A[i], A[i+1], ..., A[j]` of `A` is said to be *turbulent* if and only if: + +- For `i <= k < j`, `A[k] > A[k+1]` when `k` is odd, and `A[k] < A[k+1]` when `k` is even; +- **OR**, for `i <= k < j`, `A[k] > A[k+1]` when `k` is even, and `A[k] < A[k+1]` when `k` is odd. + +That is, the subarray is turbulent if the comparison sign flips between each adjacent pair of elements in the subarray. + +Return the **length** of a maximum size turbulent subarray of A. + +**Example 1:** + + Input: [9,4,2,10,7,8,8,1,9] + Output: 5 + Explanation: (A[1] > A[2] < A[3] > A[4] < A[5]) + +**Example 2:** + + Input: [4,8,12,16] + Output: 2 + +**Example 3:** + + Input: [100] + Output: 1 + +**Note:** + +1. `1 <= A.length <= 40000` +2. `0 <= A[i] <= 10^9` + + +## 题目大意 + + +当 A 的子数组 A[i], A[i+1], ..., A[j] 满足下列条件时，我们称其为湍流子数组： + +若 i <= k < j，当 k 为奇数时， A[k] > A[k+1]，且当 k 为偶数时，A[k] < A[k+1]； +或 若 i <= k < j，当 k 为偶数时，A[k] > A[k+1] ，且当 k 为奇数时， A[k] < A[k+1]。 +也就是说，如果比较符号在子数组中的每个相邻元素对之间翻转，则该子数组是湍流子数组。 + +返回 A 的最大湍流子数组的长度。 + +提示： + +- 1 <= A.length <= 40000 +- 0 <= A[i] <= 10^9 + + + +## 解题思路 + + +- 给出一个数组，要求找出“摆动数组”的最大长度。所谓“摆动数组”的意思是，元素一大一小间隔的。 +- 这一题可以用滑动窗口来解答。用相邻元素差的乘积大于零（a ^ b >= 0 说明a b乘积大于零）来判断是否是湍流， 如果是，那么扩大窗口。否则窗口缩小为0，开始新的一个窗口。 \ No newline at end of file diff --git a/leetcode/0987.Vertical-Order-Traversal-of-a-Binary-Tree/987. Vertical Order Traversal of a Binary Tree.go b/leetcode/0987.Vertical-Order-Traversal-of-a-Binary-Tree/987. Vertical Order Traversal of a Binary Tree.go index 2e49453df..a7937eb40 100644 --- a/leetcode/0987.Vertical-Order-Traversal-of-a-Binary-Tree/987. Vertical Order Traversal of a Binary Tree.go +++ b/leetcode/0987.Vertical-Order-Traversal-of-a-Binary-Tree/987. Vertical Order Traversal of a Binary Tree.go @@ -1,6 +1,7 @@ package leetcode import ( + "math" "sort" "github.com/halfrost/LeetCode-Go/structures" @@ -23,37 +24,33 @@ type node struct { } func verticalTraversal(root *TreeNode) [][]int { - nodes := []*node{} - inorder(root, 0, 0, &nodes) - sort.Slice(nodes, func(i, j int) bool { - if nodes[i].y == nodes[j].y { - if nodes[i].x < nodes[j].x { - return true - } else if nodes[i].x > nodes[j].x { - return false - } - return nodes[i].val < nodes[j].val + var dfs func(root *TreeNode, x, y int) + var nodes []node + dfs = func(root *TreeNode, x, y int) { + if root == nil { + return } - return nodes[i].y < nodes[j].y + nodes = append(nodes, node{x, y, root.Val}) + dfs(root.Left, x+1, y-1) + dfs(root.Right, x+1, y+1) + } + dfs(root, 0, 0) + + sort.Slice(nodes, func(i, j int) bool { + a, b := nodes[i], nodes[j] + return a.y < b.y || a.y == b.y && + (a.x < b.x || a.x == b.x && a.val < b.val) }) - res, currY, currColumn := [][]int{}, nodes[0].y, []int{nodes[0].val} - for i := 1; i < len(nodes); i++ { - if currY == nodes[i].y { - currColumn = append(currColumn, nodes[i].val) + + var res [][]int + lastY := math.MinInt32 + for _, node := range nodes { + if lastY != node.y { + res = append(res, []int{node.val}) + lastY = node.y } else { - res = append(res, currColumn) - currColumn = []int{nodes[i].val} - currY = nodes[i].y + res[len(res)-1] = append(res[len(res)-1], node.val) } } - res = append(res, currColumn) return res } - -func inorder(root *TreeNode, x, y int, nodes *[]*node) { - if root != nil { - *nodes = append(*nodes, &node{x, y, root.Val}) - inorder(root.Left, x+1, y-1, nodes) - inorder(root.Right, x+1, y+1, nodes) - } -} diff --git a/leetcode/0987.Vertical-Order-Traversal-of-a-Binary-Tree/README.md b/leetcode/0987.Vertical-Order-Traversal-of-a-Binary-Tree/README.md index 3a72b7831..daa44efed 100644 --- a/leetcode/0987.Vertical-Order-Traversal-of-a-Binary-Tree/README.md +++ b/leetcode/0987.Vertical-Order-Traversal-of-a-Binary-Tree/README.md @@ -79,6 +79,7 @@ Note that the solution remains the same since 5 and 6 are in the same location a package leetcode import ( + "math" "sort" "github.com/halfrost/LeetCode-Go/structures" @@ -101,38 +102,34 @@ type node struct { } func verticalTraversal(root *TreeNode) [][]int { - nodes := []*node{} - inorder(root, 0, 0, &nodes) - sort.Slice(nodes, func(i, j int) bool { - if nodes[i].y == nodes[j].y { - if nodes[i].x < nodes[j].x { - return true - } else if nodes[i].x > nodes[j].x { - return false - } - return nodes[i].val < nodes[j].val + var dfs func(root *TreeNode, x, y int) + var nodes []node + dfs = func(root *TreeNode, x, y int) { + if root == nil { + return } - return nodes[i].y < nodes[j].y + nodes = append(nodes, node{x, y, root.Val}) + dfs(root.Left, x+1, y-1) + dfs(root.Right, x+1, y+1) + } + dfs(root, 0, 0) + + sort.Slice(nodes, func(i, j int) bool { + a, b := nodes[i], nodes[j] + return a.y < b.y || a.y == b.y && + (a.x < b.x || a.x == b.x && a.val < b.val) }) - res, currY, currColumn := [][]int{}, nodes[0].y, []int{nodes[0].val} - for i := 1; i < len(nodes); i++ { - if currY == nodes[i].y { - currColumn = append(currColumn, nodes[i].val) + + var res [][]int + lastY := math.MinInt32 + for _, node := range nodes { + if lastY != node.y { + res = append(res, []int{node.val}) + lastY = node.y } else { - res = append(res, currColumn) - currColumn = []int{nodes[i].val} - currY = nodes[i].y + res[len(res)-1] = append(res[len(res)-1], node.val) } } - res = append(res, currColumn) return res } - -func inorder(root *TreeNode, x, y int, nodes *[]*node) { - if root != nil { - *nodes = append(*nodes, &node{x, y, root.Val}) - inorder(root.Left, x+1, y-1, nodes) - inorder(root.Right, x+1, y+1, nodes) - } -} ``` \ No newline at end of file diff --git a/leetcode/0997.Find-the-Town-Judge/997.Find the Town Judge.go b/leetcode/0997.Find-the-Town-Judge/997.Find the Town Judge.go new file mode 100644 index 000000000..79351288d --- /dev/null +++ b/leetcode/0997.Find-the-Town-Judge/997.Find the Town Judge.go @@ -0,0 +1,22 @@ +package leetcode + +func findJudge(n int, trust [][]int) int { + if n == 1 && len(trust) == 0 { + return 1 + } + judges := make(map[int]int) + for _, v := range trust { + judges[v[1]] += 1 + } + for _, v := range trust { + if _, ok := judges[v[0]]; ok { + delete(judges, v[0]) + } + } + for k, v := range judges { + if v == n-1 { + return k + } + } + return -1 +} diff --git a/leetcode/0997.Find-the-Town-Judge/997.Find the Town Judge_test.go b/leetcode/0997.Find-the-Town-Judge/997.Find the Town Judge_test.go new file mode 100644 index 000000000..61b2434ff --- /dev/null +++ b/leetcode/0997.Find-the-Town-Judge/997.Find the Town Judge_test.go @@ -0,0 +1,51 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question997 struct { + para997 + ans997 +} + +// para 是参数 +type para997 struct { + n int + trust [][]int +} + +// ans 是答案 +type ans997 struct { + ans int +} + +func Test_Problem997(t *testing.T) { + + qs := []question997{ + + { + para997{2, [][]int{{1, 2}}}, + ans997{2}, + }, + + { + para997{3, [][]int{{1, 3}, {2, 3}}}, + ans997{3}, + }, + + { + para997{3, [][]int{{1, 3}, {2, 3}, {3, 1}}}, + ans997{-1}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 997------------------------\n") + + for _, q := range qs { + _, p := q.ans997, q.para997 + fmt.Printf("【input】:%v 【output】:%v\n", p, findJudge(p.n, p.trust)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/0997.Find-the-Town-Judge/README.md b/leetcode/0997.Find-the-Town-Judge/README.md new file mode 100644 index 000000000..71dc5ecfc --- /dev/null +++ b/leetcode/0997.Find-the-Town-Judge/README.md @@ -0,0 +1,87 @@ +# [997. Find the Town Judge](https://leetcode.com/problems/find-the-town-judge/) + +## 题目 + +In a town, there are n people labeled from 1 to n. There is a rumor that one of these people is secretly the town judge. + +If the town judge exists, then: + +- The town judge trusts nobody. +- Everybody (except for the town judge) trusts the town judge. +- There is exactly one person that satisfies properties 1 and 2. + +You are given an array trust where trust[i] = [ai, bi] representing that the person labeled ai trusts the person labeled bi. + +Return the label of the town judge if the town judge exists and can be identified, or return -1 otherwise. + +**Example 1**: + + Input: n = 2, trust = [[1,2]] + Output: 2 + +**Example 2**: + + Input: n = 3, trust = [[1,3],[2,3]] + Output: 3 + +**Example 3**: + + Input: n = 3, trust = [[1,3],[2,3],[3,1]] + Output: -1 + +**Constraints:** + +- 1 <= n <= 1000 +- 0 <= trust.length <= 10000 +- trust[i].length == 2 +- All the pairs of trust are unique. +- ai != bi +- 1 <= ai, bi <= n + +## 题目大意 + +小镇里有 n 个人，按从 1 到 n 的顺序编号。传言称，这些人中有一个暗地里是小镇法官。 + +如果小镇法官真的存在，那么： + +- 小镇法官不会信任任何人。 +- 每个人（除了小镇法官）都信任这位小镇法官。 +- 只有一个人同时满足属性 1 和属性 2 。 + +给你一个数组 trust ，其中 trust[i] = [ai, bi] 表示编号为 ai 的人信任编号为 bi 的人。 + +如果小镇法官存在并且可以确定他的身份，请返回该法官的编号；否则，返回 -1 。 + +## 解题思路 + +入度和出度统计 + +- 被人信任定义为入度, 信任别人定义为出度 +- 如果 1-n 之间有数字 x 的入度为 n - 1，出度为 0，则返回 x + +## 代码 + +```go +package leetcode + +func findJudge(n int, trust [][]int) int { + if n == 1 && len(trust) == 0 { + return 1 + } + judges := make(map[int]int) + for _, v := range trust { + judges[v[1]] += 1 + } + for _, v := range trust { + if _, ok := judges[v[0]]; ok { + delete(judges, v[0]) + } + } + for k, v := range judges { + if v == n-1 { + return k + } + } + return -1 +} +``` \ No newline at end of file diff --git a/leetcode/1006.Clumsy-Factorial/1006. Clumsy Factorial.go b/leetcode/1006.Clumsy-Factorial/1006. Clumsy Factorial.go index dd62b3a3b..f69cfaca2 100644 --- a/leetcode/1006.Clumsy-Factorial/1006. Clumsy Factorial.go +++ b/leetcode/1006.Clumsy-Factorial/1006. Clumsy Factorial.go @@ -1,7 +1,7 @@ package leetcode func clumsy(N int) int { - res, count, tmp, flag := 0, 1, N, true + res, count, tmp, flag := 0, 1, N, false for i := N - 1; i > 0; i-- { count = count % 4 switch count { diff --git a/leetcode/1009.Complement-of-Base-10-Integer/1009. Complement of Base 10 Integer.go b/leetcode/1009.Complement-of-Base-10-Integer/1009. Complement of Base 10 Integer.go new file mode 100644 index 000000000..19e526e39 --- /dev/null +++ b/leetcode/1009.Complement-of-Base-10-Integer/1009. Complement of Base 10 Integer.go @@ -0,0 +1,9 @@ +package leetcode + +func bitwiseComplement(n int) int { + mask := 1 + for mask < n { + mask = (mask << 1) + 1 + } + return mask ^ n +} diff --git a/leetcode/1009.Complement-of-Base-10-Integer/1009. Complement of Base 10 Integer_test.go b/leetcode/1009.Complement-of-Base-10-Integer/1009. Complement of Base 10 Integer_test.go new file mode 100644 index 000000000..90bf93447 --- /dev/null +++ b/leetcode/1009.Complement-of-Base-10-Integer/1009. Complement of Base 10 Integer_test.go @@ -0,0 +1,52 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question1009 struct { + para1009 + ans1009 +} + +// para 是参数 +// one 代表第一个参数 +type para1009 struct { + n int +} + +// ans 是答案 +// one 代表第一个答案 +type ans1009 struct { + one int +} + +func Test_Problem1009(t *testing.T) { + + qs := []question1009{ + + { + para1009{5}, + ans1009{2}, + }, + + { + para1009{7}, + ans1009{0}, + }, + + { + para1009{10}, + ans1009{5}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 1009------------------------\n") + + for _, q := range qs { + _, p := q.ans1009, q.para1009 + fmt.Printf("【input】:%v 【output】:%v\n", p, bitwiseComplement(p.n)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/1009.Complement-of-Base-10-Integer/README.md b/leetcode/1009.Complement-of-Base-10-Integer/README.md new file mode 100644 index 000000000..d8b12b302 --- /dev/null +++ b/leetcode/1009.Complement-of-Base-10-Integer/README.md @@ -0,0 +1,67 @@ +# [1009. Complement of Base 10 Integer](https://leetcode.com/problems/complement-of-base-10-integer/) + + +## 题目 + +The **complement** of an integer is the integer you get when you flip all the `0`'s to `1`'s and all the `1`'s to `0`'s in its binary representation. + +- For example, The integer `5` is `"101"` in binary and its **complement** is `"010"` which is the integer `2`. + +Given an integer `n`, return *its complement*. + +**Example 1:** + +``` +Input: n = 5 +Output: 2 +Explanation: 5 is "101" in binary, with complement "010" in binary, which is 2 in base-10. + +``` + +**Example 2:** + +``` +Input: n = 7 +Output: 0 +Explanation: 7 is "111" in binary, with complement "000" in binary, which is 0 in base-10. + +``` + +**Example 3:** + +``` +Input: n = 10 +Output: 5 +Explanation: 10 is "1010" in binary, with complement "0101" in binary, which is 5 in base-10. + +``` + +**Constraints:** + +- `0 <= n < 109` + +## 题目大意 + +每个非负整数 N 都有其二进制表示。例如， 5 可以被表示为二进制 "101"，11 可以用二进制 "1011" 表示，依此类推。注意，除 N = 0 外，任何二进制表示中都不含前导零。 + +二进制的反码表示是将每个 1 改为 0 且每个 0 变为 1。例如，二进制数 "101" 的二进制反码为 "010"。 + +给你一个十进制数 N，请你返回其二进制表示的反码所对应的十进制整数。 + +## 解题思路 + +- 简单题。求一个十进制数的反码，只需要让该数和全 1 的数进行异或计算即可。所以本题重点在如何构造 mask 上。 + +## 代码 + +```go +package leetcode + +func bitwiseComplement(n int) int { + mask := 1 + for mask < n { + mask = (mask << 1) + 1 + } + return mask ^ n +} +``` \ No newline at end of file diff --git a/leetcode/1010.Pairs-of-Songs-With-Total-Durations-Divisible-by-60/1010. Pairs of Songs With Total Durations Divisible by 60.go b/leetcode/1010.Pairs-of-Songs-With-Total-Durations-Divisible-by-60/1010. Pairs of Songs With Total Durations Divisible by 60.go new file mode 100644 index 000000000..3c6dd1afd --- /dev/null +++ b/leetcode/1010.Pairs-of-Songs-With-Total-Durations-Divisible-by-60/1010. Pairs of Songs With Total Durations Divisible by 60.go @@ -0,0 +1,16 @@ +package leetcode + +func numPairsDivisibleBy60(time []int) int { + counts := make([]int, 60) + for _, v := range time { + v %= 60 + counts[v]++ + } + res := 0 + for i := 1; i < len(counts)/2; i++ { + res += counts[i] * counts[60-i] + } + res += (counts[0] * (counts[0] - 1)) / 2 + res += (counts[30] * (counts[30] - 1)) / 2 + return res +} diff --git a/leetcode/1010.Pairs-of-Songs-With-Total-Durations-Divisible-by-60/1010. Pairs of Songs With Total Durations Divisible by 60_test.go b/leetcode/1010.Pairs-of-Songs-With-Total-Durations-Divisible-by-60/1010. Pairs of Songs With Total Durations Divisible by 60_test.go new file mode 100644 index 000000000..201e0c727 --- /dev/null +++ b/leetcode/1010.Pairs-of-Songs-With-Total-Durations-Divisible-by-60/1010. Pairs of Songs With Total Durations Divisible by 60_test.go @@ -0,0 +1,47 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question1010 struct { + para1010 + ans1010 +} + +// para 是参数 +// one 代表第一个参数 +type para1010 struct { + time []int +} + +// ans 是答案 +// one 代表第一个答案 +type ans1010 struct { + one int +} + +func Test_Problem1010(t *testing.T) { + + qs := []question1010{ + + { + para1010{[]int{30, 20, 150, 100, 40}}, + ans1010{3}, + }, + + { + para1010{[]int{60, 60, 60}}, + ans1010{3}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 1010------------------------\n") + + for _, q := range qs { + _, p := q.ans1010, q.para1010 + fmt.Printf("【input】:%v 【output】:%v\n", p, numPairsDivisibleBy60(p.time)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/1010.Pairs-of-Songs-With-Total-Durations-Divisible-by-60/README.md b/leetcode/1010.Pairs-of-Songs-With-Total-Durations-Divisible-by-60/README.md new file mode 100644 index 000000000..a49f11207 --- /dev/null +++ b/leetcode/1010.Pairs-of-Songs-With-Total-Durations-Divisible-by-60/README.md @@ -0,0 +1,63 @@ +# [1010. Pairs of Songs With Total Durations Divisible by 60](https://leetcode.com/problems/pairs-of-songs-with-total-durations-divisible-by-60/) + + +## 题目 + +You are given a list of songs where the ith song has a duration of `time[i]` seconds. + +Return *the number of pairs of songs for which their total duration in seconds is divisible by* `60`. Formally, we want the number of indices `i`, `j` such that `i < j` with `(time[i] + time[j]) % 60 == 0`. + +**Example 1:** + +``` +Input: time = [30,20,150,100,40] +Output: 3 +Explanation: Three pairs have a total duration divisible by 60: +(time[0] = 30, time[2] = 150): total duration 180 +(time[1] = 20, time[3] = 100): total duration 120 +(time[1] = 20, time[4] = 40): total duration 60 + +``` + +**Example 2:** + +``` +Input: time = [60,60,60] +Output: 3 +Explanation: All three pairs have a total duration of 120, which is divisible by 60. + +``` + +**Constraints:** + +- `1 <= time.length <= 6 * 104` +- `1 <= time[i] <= 500` + +## 题目大意 + +在歌曲列表中，第 i 首歌曲的持续时间为 time[i] 秒。 + +返回其总持续时间（以秒为单位）可被 60 整除的歌曲对的数量。形式上，我们希望下标数字 i 和 j 满足  i < j 且有 (time[i] + time[j]) % 60 == 0。 + +## 解题思路 + +- 简单题。先将数组每个元素对 60 取余，将它们都转换到 [0,59] 之间。然后在数组中找两两元素之和等于 60 的数对。可以在 0-30 之内对半查找符合条件的数对。对 0 和 30 单独计算。因为多个 0 相加，余数还为 0 。2 个 30 相加之和为 60。 + +## 代码 + +```go +func numPairsDivisibleBy60(time []int) int { + counts := make([]int, 60) + for _, v := range time { + v %= 60 + counts[v]++ + } + res := 0 + for i := 1; i < len(counts)/2; i++ { + res += counts[i] * counts[60-i] + } + res += (counts[0] * (counts[0] - 1)) / 2 + res += (counts[30] * (counts[30] - 1)) / 2 + return res +} +``` \ No newline at end of file diff --git a/leetcode/1017.Convert-to-Base--2/1017. Convert to Base -2.go b/leetcode/1017.Convert-to-Base-2/1017. Convert to Base -2.go similarity index 100% rename from leetcode/1017.Convert-to-Base--2/1017. Convert to Base -2.go rename to leetcode/1017.Convert-to-Base-2/1017. Convert to Base -2.go diff --git a/leetcode/1017.Convert-to-Base--2/1017. Convert to Base -2_test.go b/leetcode/1017.Convert-to-Base-2/1017. Convert to Base -2_test.go similarity index 100% rename from leetcode/1017.Convert-to-Base--2/1017. Convert to Base -2_test.go rename to leetcode/1017.Convert-to-Base-2/1017. Convert to Base -2_test.go diff --git a/leetcode/1017.Convert-to-Base--2/README.md b/leetcode/1017.Convert-to-Base-2/README.md similarity index 100% rename from leetcode/1017.Convert-to-Base--2/README.md rename to leetcode/1017.Convert-to-Base-2/README.md diff --git a/leetcode/1019.Next-Greater-Node-In-Linked-List/1019. Next Greater Node In Linked List.go b/leetcode/1019.Next-Greater-Node-In-Linked-List/1019. Next Greater Node In Linked List.go index 8ef54327c..a789e7748 100644 --- a/leetcode/1019.Next-Greater-Node-In-Linked-List/1019. Next Greater Node In Linked List.go +++ b/leetcode/1019.Next-Greater-Node-In-Linked-List/1019. Next Greater Node In Linked List.go @@ -14,25 +14,22 @@ type ListNode = structures.ListNode * Next *ListNode * } */ + // 解法一 单调栈 func nextLargerNodes(head *ListNode) []int { - res, indexes, nums := make([]int, 0), make([]int, 0), make([]int, 0) - p := head - for p != nil { - nums = append(nums, p.Val) - p = p.Next - } - for i := 0; i < len(nums); i++ { - res = append(res, 0) + type node struct { + index, val int } - for i := 0; i < len(nums); i++ { - num := nums[i] - for len(indexes) > 0 && nums[indexes[len(indexes)-1]] < num { - index := indexes[len(indexes)-1] - res[index] = num - indexes = indexes[:len(indexes)-1] + var monoStack []node + var res []int + for head != nil { + for len(monoStack) > 0 && monoStack[len(monoStack)-1].val < head.Val { + res[monoStack[len(monoStack)-1].index] = head.Val + monoStack = monoStack[:len(monoStack)-1] } - indexes = append(indexes, i) + monoStack = append(monoStack, node{len(res), head.Val}) + res = append(res, 0) + head = head.Next } return res } diff --git a/leetcode/1022.Sum-of-Root-To-Leaf-Binary-Numbers/1022. Sum of Root To Leaf Binary Numbers.go b/leetcode/1022.Sum-of-Root-To-Leaf-Binary-Numbers/1022. Sum of Root To Leaf Binary Numbers.go new file mode 100644 index 000000000..473564c29 --- /dev/null +++ b/leetcode/1022.Sum-of-Root-To-Leaf-Binary-Numbers/1022. Sum of Root To Leaf Binary Numbers.go @@ -0,0 +1,30 @@ +package leetcode + +import "github.com/halfrost/LeetCode-Go/structures" + +// TreeNode define +type TreeNode = structures.TreeNode + +/** + * Definition for a binary tree node. + * type TreeNode struct { + * Val int + * Left *TreeNode + * Right *TreeNode + * } + */ +func sumRootToLeaf(root *TreeNode) int { + var dfs func(*TreeNode, int) int + dfs = func(node *TreeNode, sum int) int { + if node == nil { + return 0 + } + sum = sum<<1 | node.Val + // 上一行也可以写作 sum = sum*2 + node.Val + if node.Left == nil && node.Right == nil { + return sum + } + return dfs(node.Left, sum) + dfs(node.Right, sum) + } + return dfs(root, 0) +} diff --git a/leetcode/1022.Sum-of-Root-To-Leaf-Binary-Numbers/1022. Sum of Root To Leaf Binary Numbers_test.go b/leetcode/1022.Sum-of-Root-To-Leaf-Binary-Numbers/1022. Sum of Root To Leaf Binary Numbers_test.go new file mode 100644 index 000000000..3b7ce6f92 --- /dev/null +++ b/leetcode/1022.Sum-of-Root-To-Leaf-Binary-Numbers/1022. Sum of Root To Leaf Binary Numbers_test.go @@ -0,0 +1,49 @@ +package leetcode + +import ( + "fmt" + "testing" + + "github.com/halfrost/LeetCode-Go/structures" +) + +type question1022 struct { + para1022 + ans1022 +} + +// para 是参数 +// one 代表第一个参数 +type para1022 struct { + one []int +} + +// ans 是答案 +// one 代表第一个答案 +type ans1022 struct { + one int +} + +func Test_Problem1022(t *testing.T) { + + qs := []question1022{ + { + para1022{[]int{1, 0, 1, 0, 1, 0, 1}}, + ans1022{22}, + }, + + { + para1022{[]int{0}}, + ans1022{0}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 1022------------------------\n") + + for _, q := range qs { + _, p := q.ans1022, q.para1022 + root := structures.Ints2TreeNode(p.one) + fmt.Printf("【input】:%v 【output】:%v\n", p, sumRootToLeaf(root)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/1022.Sum-of-Root-To-Leaf-Binary-Numbers/README.md b/leetcode/1022.Sum-of-Root-To-Leaf-Binary-Numbers/README.md new file mode 100644 index 000000000..83578063e --- /dev/null +++ b/leetcode/1022.Sum-of-Root-To-Leaf-Binary-Numbers/README.md @@ -0,0 +1,54 @@ +# [1022. Sum of Root To Leaf Binary Numbers](https://leetcode.com/problems/sum-of-root-to-leaf-binary-numbers/) + +## 题目 + +You are given the root of a binary tree where each node has a value 0 or 1. Each root-to-leaf path represents a binary number starting with the most significant bit. + +For example, if the path is 0 -> 1 -> 1 -> 0 -> 1, then this could represent 01101 in binary, which is 13. +For all leaves in the tree, consider the numbers represented by the path from the root to that leaf. Return the sum of these numbers. + +The test cases are generated so that the answer fits in a 32-bits integer. + +**Example 1:** + +```c +Input: root = [1,0,1,0,1,0,1] +Output: 22 +Explanation: (100) + (101) + (110) + (111) = 4 + 5 + 6 + 7 = 22 +``` + +**Example 2:** + +```c +Input: root = [0] +Output: 0 +``` + +**Constraints:** + +- The number of nodes in the tree is in the range `[1, 1000]`. + +- `Node.val` is `0` or `1`. + + +## 题目大意 + +给定一棵结点值都是`0`或`1`的二叉树，每条从根结点到叶结点的路径都代表一个从最高有效位开始的二进制数。 + +返回从根节点到所有叶结点的路径所表示的数字之和。 + + +## 解题思路 + +采用递归的方式对根结点`root`进行后序遍历（左子树-右子树-根结点）。 + +**递归函数的返回值**： + +递归遍历每个结点时，计算从根结点到当前访问结点的所表示数值`sum`都用到了上次的计算结果，所以递归函数的返回值是当前访问结点的计算结果值。 + +**递归函数的逻辑**： + +- 当前遍历结点为`nil`，表示本层递归结束了，直接`return 0`。 + +- 如果当前访问结点是叶结点，则返回从根结点到该结点所表示的数值`sum`。 +- 如果当前访问结点不是叶结点，则返回左子树和右子树所对应的结果之和。 diff --git a/leetcode/1028.Recover-a-Tree-From-Preorder-Traversal/1028. Recover a Tree From Preorder Traversal.go b/leetcode/1028.Recover-a-Tree-From-Preorder-Traversal/1028. Recover a Tree From Preorder Traversal.go index c3929f74e..f597f671c 100644 --- a/leetcode/1028.Recover-a-Tree-From-Preorder-Traversal/1028. Recover a Tree From Preorder Traversal.go +++ b/leetcode/1028.Recover-a-Tree-From-Preorder-Traversal/1028. Recover a Tree From Preorder Traversal.go @@ -2,9 +2,7 @@ package leetcode import ( "strconv" -) -import ( "github.com/halfrost/LeetCode-Go/structures" ) diff --git a/leetcode/1034.Coloring-A-Border/1034.Coloring A Border.go b/leetcode/1034.Coloring-A-Border/1034.Coloring A Border.go new file mode 100644 index 000000000..70df28edd --- /dev/null +++ b/leetcode/1034.Coloring-A-Border/1034.Coloring A Border.go @@ -0,0 +1,50 @@ +package leetcode + +type point struct { + x int + y int +} + +type gridInfo struct { + m int + n int + grid [][]int + originalColor int +} + +func colorBorder(grid [][]int, row, col, color int) [][]int { + m, n := len(grid), len(grid[0]) + dirs := []point{{1, 0}, {-1, 0}, {0, 1}, {0, -1}} + vis := make([][]bool, m) + for i := range vis { + vis[i] = make([]bool, n) + } + var borders []point + gInfo := gridInfo{ + m: m, + n: n, + grid: grid, + originalColor: grid[row][col], + } + dfs(row, col, gInfo, dirs, vis, &borders) + for _, p := range borders { + grid[p.x][p.y] = color + } + return grid +} + +func dfs(x, y int, gInfo gridInfo, dirs []point, vis [][]bool, borders *[]point) { + vis[x][y] = true + isBorder := false + for _, dir := range dirs { + nx, ny := x+dir.x, y+dir.y + if !(0 <= nx && nx < gInfo.m && 0 <= ny && ny < gInfo.n && gInfo.grid[nx][ny] == gInfo.originalColor) { + isBorder = true + } else if !vis[nx][ny] { + dfs(nx, ny, gInfo, dirs, vis, borders) + } + } + if isBorder { + *borders = append(*borders, point{x, y}) + } +} diff --git a/leetcode/1034.Coloring-A-Border/1034.Coloring A Border_test.go b/leetcode/1034.Coloring-A-Border/1034.Coloring A Border_test.go new file mode 100644 index 000000000..812a9c241 --- /dev/null +++ b/leetcode/1034.Coloring-A-Border/1034.Coloring A Border_test.go @@ -0,0 +1,53 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question1034 struct { + para1034 + ans1034 +} + +// para 是参数 +type para1034 struct { + grid [][]int + row int + col int + color int +} + +// ans 是答案 +type ans1034 struct { + ans [][]int +} + +func Test_Problem1034(t *testing.T) { + + qs := []question1034{ + + { + para1034{[][]int{{1, 1}, {1, 2}}, 0, 0, 3}, + ans1034{[][]int{{3, 3}, {3, 2}}}, + }, + + { + para1034{[][]int{{1, 2, 2}, {2, 3, 2}}, 0, 1, 3}, + ans1034{[][]int{{1, 3, 3}, {2, 3, 3}}}, + }, + + { + para1034{[][]int{{1, 1, 1}, {1, 1, 1}, {1, 1, 1}}, 1, 1, 2}, + ans1034{[][]int{{2, 2, 2}, {2, 1, 2}, {2, 2, 2}}}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 1034------------------------\n") + + for _, q := range qs { + _, p := q.ans1034, q.para1034 + fmt.Printf("【input】:%v 【output】:%v\n", p, colorBorder(p.grid, p.row, p.col, p.color)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/1034.Coloring-A-Border/README.md b/leetcode/1034.Coloring-A-Border/README.md new file mode 100644 index 000000000..6700260f9 --- /dev/null +++ b/leetcode/1034.Coloring-A-Border/README.md @@ -0,0 +1,108 @@ +# [1034. Coloring A Border](https://leetcode.com/problems/coloring-a-border/) + +## 题目 + +You are given an m x n integer matrix grid, and three integers row, col, and color. Each value in the grid represents the color of the grid square at that location. + +Two squares belong to the same connected component if they have the same color and are next to each other in any of the 4 directions. + +The border of a connected component is all the squares in the connected component that are either 4-directionally adjacent to a square not in the component, or on the boundary of the grid (the first or last row or column). + +You should color the border of the connected component that contains the square grid[row][col] with color. + +Return the final grid. + +**Example 1**: + + Input: grid = [[1,1],[1,2]], row = 0, col = 0, color = 3 + Output: [[3,3],[3,2]] + +**Example 2**: + + Input: grid = [[1,2,2],[2,3,2]], row = 0, col = 1, color = 3 + Output: [[1,3,3],[2,3,3]] + +**Example 3**: + + Input: grid = [[1,1,1],[1,1,1],[1,1,1]], row = 1, col = 1, color = 2 + Output: [[2,2,2],[2,1,2],[2,2,2]] + +**Constraints:** + +- m == grid.length +- n == grid[i].length +- 1 <= m, n <= 50 +- 1 <= grid[i][j], color <= 1000 +- 0 <= row < m +- 0 <= col < n + +## 题目大意 + +给你一个大小为 m x n 的整数矩阵 grid ，表示一个网格。另给你三个整数 row、col 和 color 。网格中的每个值表示该位置处的网格块的颜色。 + +当两个网格块的颜色相同，而且在四个方向中任意一个方向上相邻时，它们属于同一连通分量 + +边界：在连通分量的块中（前提）并且满足以下条件之一： +（1）要么上下左右存在一个块不在连通分量里面 +（2）要么这个块的位置在整个grid的边框上 + +请你使用指定颜色 color 为所有包含网格块 grid[row][col] 的连通分量的边界进行着色，并返回最终的网格 grid 。 + +## 解题思路 + +- 用 bfs 进行遍历选出边界，使用 color 给边界着色 + +## 代码 + +```go +package leetcode + +type point struct { + x int + y int +} + +type gridInfo struct { + m int + n int + grid [][]int + originalColor int +} + +func colorBorder(grid [][]int, row, col, color int) [][]int { + m, n := len(grid), len(grid[0]) + dirs := []point{{1, 0}, {-1, 0}, {0, 1}, {0, -1}} + vis := make([][]bool, m) + for i := range vis { + vis[i] = make([]bool, n) + } + var borders []point + gInfo := gridInfo{ + m: m, + n: n, + grid: grid, + originalColor: grid[row][col], + } + dfs(row, col, gInfo, dirs, vis, &borders) + for _, p := range borders { + grid[p.x][p.y] = color + } + return grid +} + +func dfs(x, y int, gInfo gridInfo, dirs []point, vis [][]bool, borders *[]point) { + vis[x][y] = true + isBorder := false + for _, dir := range dirs { + nx, ny := x+dir.x, y+dir.y + if !(0 <= nx && nx < gInfo.m && 0 <= ny && ny < gInfo.n && gInfo.grid[nx][ny] == gInfo.originalColor) { + isBorder = true + } else if !vis[nx][ny] { + dfs(nx, ny, gInfo, dirs, vis, borders) + } + } + if isBorder { + *borders = append(*borders, point{x, y}) + } +} +``` \ No newline at end of file diff --git a/leetcode/1048.Longest-String-Chain/1048. Longest String Chain.go b/leetcode/1048.Longest-String-Chain/1048. Longest String Chain.go new file mode 100644 index 000000000..b16653ba6 --- /dev/null +++ b/leetcode/1048.Longest-String-Chain/1048. Longest String Chain.go @@ -0,0 +1,49 @@ +package leetcode + +import "sort" + +func longestStrChain(words []string) int { + sort.Slice(words, func(i, j int) bool { return len(words[i]) < len(words[j]) }) + poss, res := make([]int, 16+2), 0 + for i, w := range words { + if poss[len(w)] == 0 { + poss[len(w)] = i + } + } + dp := make([]int, len(words)) + for i := len(words) - 1; i >= 0; i-- { + dp[i] = 1 + for j := poss[len(words[i])+1]; j < len(words) && len(words[j]) == len(words[i])+1; j++ { + if isPredecessor(words[j], words[i]) { + dp[i] = max(dp[i], 1+dp[j]) + } + } + res = max(res, dp[i]) + } + return res +} + +func max(a, b int) int { + if a > b { + return a + } + return b +} + +func isPredecessor(long, short string) bool { + i, j := 0, 0 + wasMismatch := false + for j < len(short) { + if long[i] != short[j] { + if wasMismatch { + return false + } + wasMismatch = true + i++ + continue + } + i++ + j++ + } + return true +} diff --git a/leetcode/1048.Longest-String-Chain/1048. Longest String Chain_test.go b/leetcode/1048.Longest-String-Chain/1048. Longest String Chain_test.go new file mode 100644 index 000000000..97c9b3b5a --- /dev/null +++ b/leetcode/1048.Longest-String-Chain/1048. Longest String Chain_test.go @@ -0,0 +1,78 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question1048 struct { + para1048 + ans1048 +} + +// para 是参数 +// one 代表第一个参数 +type para1048 struct { + words []string +} + +// ans 是答案 +// one 代表第一个答案 +type ans1048 struct { + one int +} + +func Test_Problem1048(t *testing.T) { + + qs := []question1048{ + + { + para1048{[]string{"a", "b", "ab", "bac"}}, + ans1048{2}, + }, + + { + para1048{[]string{"xbc", "pcxbcf", "xb", "cxbc", "pcxbc"}}, + ans1048{5}, + }, + + { + para1048{[]string{"a", "b", "ba", "bca", "bda", "bdca"}}, + ans1048{4}, + }, + + { + para1048{[]string{"qjcaeymang", "bqiq", "bcntqiqulagurhz", "lyctmomvis", "bdnhym", "crxrdlv", "wo", "kijftxssyqmui", "abtcrjs", "rceecupq", "crxrdclv", "tvwkxrev", "oc", "lrzzcl", "snpzuykyobci", "abbtczrjs", "rpqojpmv", + "kbfbcjxgvnb", "uqvhuucupu", "fwoquoih", "ezsuqxunx", "biq", "crxrwdclv", "qoyfqhytzxfp", "aryqceercpaupqm", "tvwxrev", "gchusjxz", "uls", "whb", "natdmc", "jvidsf", "yhyz", "smvsitdbutamn", "gcfsghusjsxiz", "ijpyhk", "tzvqwkmzxruevs", + "fwvjxaxrvmfm", "wscxklqmxhn", "velgcy", "lyctomvi", "smvsitbutam", "hfosz", "fuzubrpo", "dfdeidcepshvjn", "twqol", "rpqjpmv", "ijftxssyqmi", "dzuzsainzbsx", "qyzxfp", "tvwkmzxruev", "farfm", "bbwkizqhicip", "wqobtmamvpgluh", "rytspgy", + "uqvheuucdupuw", "jcmang", "h", "kijfhtxssyqmui", "twqgolksq", "rtkgopofnykkrl", "smvstbutam", "xkbfbbcjxgvnbq", "feyq", "oyfqhytzxfp", "velgcby", "dmnioxbf", "kbx", "zx", "wscxkqlqmxbhn", "efvcjtgoiga", "jumttwxv", "zux", "z", "smvsitbutamn", + "jftxssyqmi", "wnlhsaj", "bbwizqhcp", "yctomv", "oyqyzxfp", "wqhc", "jnnwp", "bcntqiquagurz", "qzx", "kbfbjxn", "dmnixbf", "ukqs", "fey", "ryqceecaupq", "smvlsitzdbutamn", "bdnhm", "lrhtwfosrzq", "nkptknldw", "crxrwdclvx", "abbtcwzrjs", + "uqvheuucupu", "abjbtcwbzrjs", "nkmptknldw", "wnulhsbaj", "wnlhsbaj", "wqobtmamvgluh", "jvis", "pcd", "s", "kjuannelajc", "valas", "lrrzzcl", "kjuannelajct", "snyyoc", "jwp", "vbum", "ezuunx", "bcntqiquagur", "vals", "cov", "dfdidcepshvjn", + "vvamlasl", "budnhym", "h", "fwxarvfm", "lrhwfosrz", "nkptnldw", "vjhse", "zzeb", "fubrpo", "fkla", "qjulm", "xpdcdxqia", "ucwxwdm", "jvidsfr", "exhc", "kbfbjx", "bcntqiquaur", "fwnoqjuoihe", "ezsruqxuinrpxc", "ec", "dzuzstuacinzbvsx", + "cxkqmxhn", "egpveohyvq", "bkcv", "dzuzsaizbx", "jftxssymi", "ycov", "zbvbeai", "ch", "atcrjs", "qjcemang", "tvjhsed", "vamlas", "bundnhym", "li", "wnulfhsbaj", "o", "ijhtpyhkrif", "nyoc", "ov", "ryceecupq", "wjcrjnszipc", "lrhtwfosrz", + "tbzngeqcz", "awfotfiqni", "azbw", "o", "gcfghusjsxiz", "uqvheuucdupu", "rypgy", "snpuykyobc", "ckhn", "kbfbcjxgnb", "xkeow", "jvids", "ubnsnusvgmqog", "endjbkjere", "fwarfm", "wvhb", "fwnoqtjuozihe", "jnwp", "awfotfmiyqni", "iv", "ryqceecupq", + "y", "qjuelm", "qyzxp", "vsbum", "dnh", "fam", "snpuyyobc", "wqobtmamvglu", "gjpw", "jcemang", "ukqso", "evhlfz", "nad", "bucwxwdm", "xkabfbbcjxgvnbq", "fwnoqjuozihe", "smvsitzdbutamn", "vec", "fos", "abbtcwbzrjs", "uyifxeyq", "kbfbjxgnb", + "nyyoc", "kcv", "fbundnhym", "tbzngpeqcz", "yekfvcjtgoiga", "rgjpw", "ezgvhsalfz", "yoc", "ezvhsalfz", "crxdlv", "chusjz", "fwxaxrvfm", "dzuzstuacinzbsx", "bwizqhc", "pdcdx", "dmnioxbmf", "zuunx", "oqyzxfp", "ezsruqxuinxc", "qjcaemang", "gcghusjsxiz", "nktnldw", + "qoyfqhytxzxfp", "bwqhc", "btkcvj", "qxpdcdxqia", "kijofhtxssyqmui", "rypy", "helmi", "zkrlexhxbwt", "qobtmamgu", "vhlfz", "rqjpmv", "yhy", "zzembhy", "rjpmv", "jhse", "fosz", "twol", "qbtamu", "nawxxbslyhucqxb", "dzzsaizbx", "dmnijgoxsbmf", + "ijhtpyhkr", "yp", "awfotfgmiyqni", "yctov", "hse", "azabw", "aryqceercaupqm", "fuzubrpoa", "ubnswnusvgmqog", "fafm", "i", "ezvhalfz", "aryxqceercpaupqm", "bwizqhcp", "pdcdxq", "wscxkqlqmxhn", "fuubrpo", "fwvxaxrvmfm", "abjbtcwbzrjas", "zx", + "rxmiirbxemog", "dfdeidcepshvvjqn", "az", "velc", "zkrlexnhxbwt", "nawxbslyhucqxb", "qjugelm", "ijhtpdyhkrif", "dmixbf", "gcfsghtusjsxiz", "juannlajc", "uqvheuucdupmuw", "rpqojpmgxv", "rpqojpmxv", "xppph", "kjuannellajct", "lrhfosrz", "dmnijoxsbmf", + "ckmxhn", "tvijhsed", "dzuzstuainzbsx", "exhvc", "tvwkxruev", "rxmiirbemog", "lhfosz", "fkyla", "tlwqgolksq", "velgcbpy", "bcqiqaur", "xkhfejow", "ezsuqunx", "dmnioxsbmf", "bqiqu", "ijhtpudyhkrif", "xpdcdxqi", "ckh", "nwxbslyhucqxb", "bbwkizqhcip", "pcdx", + "dzuzsuainzbsx", "xkbfbcjxgvnbq", "smvsbutm", "ezsruqxuinrxc", "smvlsitzdbutamdn", "am", "tvwkzxruev", "scxkqmxhn", "snpzuykyobc", "ekfvcjtgoiga", "fuzsubrpoa", "trtkgopofnykkrl", "oyqhytzxfp", "kbjx", "ifeyq", "vhl", "xkfeow", "ezgvhsialfz", "velgc", "hb", + "zbveai", "gcghusjxz", "twqgolkq", "btkcv", "ryqceercaupq", "bi", "vvamlas", "awfotfmiqni", "abbtcrjs", "jutkqesoh", "xkbfbcjxgvnb", "hli", "ryspgy", "endjjjbkjere", "mvsbum", "ckqmxhn", "ezsruqxunxc", "zzeby", "xhc", "ezvhlfz", "ezsruqxunx", "tzvwkmzxruev", + "hlmi", "kbbjx", "uqvhuuupu", "scxklqmxhn", "wqobtmamglu", "xpdcdxq", "qjugelym", "ifxeyq", "bcnqiquaur", "qobtmamglu", "xkabfbbcjxbgvnbq", "fuuzsubrpoa", "tvibjhsed", "oyqhyzxfp", "ijhpyhk", "c", "gcghusjxiz", "exhvoc", "awfotfini", "vhlz", "rtgopofykkrl", + "yh", "ypy", "azb", "bwiqhc", "fla", "dmnijgioxsbmf", "chusjxz", "jvjidsfr", "natddmc", "uifxeyq", "x", "tzvqwkmzxruev", "bucwxwdwm", "ckmhn", "zzemby", "rpmv", "bcntqiqulagurz", "fwoqjuoihe", "dzuzsainzbx", "zkrlehxbwt", "kv", "ucwxwm", "ubnswnusvgmdqog", + "wol", "endjjbkjere", "natyddmc", "vl", "ukqsoh", "ezuqunx", "exhvovc", "bqiqau", "bqiqaur", "zunx", "pc", "snuyyoc", "a", "lrhfosz", "kbfbjxgn", "rtgopofnykkrl", "hehszegkvse", "smvsbum", "ijhpyhkr", "ijftxssyqmui", "lyctomvis", "juanlajc", "jukqesoh", + "xptpph", "fwarvfm", "qbtmamu", "twqgolq", "aryqceercaupq", "qbtmamgu", "rtgopofykkr", "snpuyyoc", "qyzx", "fwvxaxrvfm", "juannelajc", "fwoquoihe", "nadmc", "jumttwxvx", "ijhtpyhkrf", "twqolq", "rpv", "hehszegkuvse", "ls", "tvjhse", "rxmiirbemg", + "dfdeidcepshvvjn", "dnhm", "egpeohyvq", "rgnjpw", "bbwkizqhcp", "nadc", "bcqiquaur", "xkhfeow", "smvstbutm", "ukqesoh", "yctomvi"}}, + ans1048{15}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 1048------------------------\n") + + for _, q := range qs { + _, p := q.ans1048, q.para1048 + fmt.Printf("【input】:%v 【output】:%v\n", p, longestStrChain(p.words)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/1048.Longest-String-Chain/README.md b/leetcode/1048.Longest-String-Chain/README.md new file mode 100644 index 000000000..66c079516 --- /dev/null +++ b/leetcode/1048.Longest-String-Chain/README.md @@ -0,0 +1,96 @@ +# [1048. Longest String Chain](https://leetcode.com/problems/longest-string-chain/) + + +## 题目 + +Given a list of words, each word consists of English lowercase letters. + +Let's say `word1` is a predecessor of `word2` if and only if we can add exactly one letter anywhere in `word1` to make it equal to `word2`. For example, `"abc"` is a predecessor of `"abac"`. + +A *word chain* is a sequence of words `[word_1, word_2, ..., word_k]` with `k >= 1`, where `word_1` is a predecessor of `word_2`, `word_2` is a predecessor of `word_3`, and so on. + +Return the longest possible length of a word chain with words chosen from the given list of `words`. + +**Example 1:** + +``` +Input: words = ["a","b","ba","bca","bda","bdca"] +Output: 4 +Explanation: One of the longest word chain is "a","ba","bda","bdca". +``` + +**Example 2:** + +``` +Input: words = ["xbc","pcxbcf","xb","cxbc","pcxbc"] +Output: 5 +``` + +**Constraints:** + +- `1 <= words.length <= 1000` +- `1 <= words[i].length <= 16` +- `words[i]` only consists of English lowercase letters. + +## 题目大意 + +给出一个单词列表，其中每个单词都由小写英文字母组成。如果我们可以在 word1 的任何地方添加一个字母使其变成 word2，那么我们认为 word1 是 word2 的前身。例如，"abc" 是 "abac" 的前身。词链是单词 [word_1, word_2, ..., word_k] 组成的序列，k >= 1，其中 word_1 是 word_2 的前身，word_2 是 word_3 的前身，依此类推。从给定单词列表 words 中选择单词组成词链，返回词链的最长可能长度。 + +## 解题思路 + +- 从这题的数据规模上分析，可以猜出此题是 DFS 或者 DP 的题。简单暴力的方法是以每个字符串为链条的起点开始枚举之后的字符串，两两判断能否构成满足题意的前身字符串。这种做法包含很多重叠子问题，例如 a 和 b 能构成前身字符串，以 c 为起点的字符串链条可能用到 a 和 b，以 d 为起点的字符串链条也可能用到 a 和 b。顺其自然，考虑用 DP 的思路解题。 +- 先将 words 字符串数组排序，然后用 poss 数组记录下每种长度字符串的在排序数组中的起始下标。然后逆序往前递推。因为初始条件只能得到以最长字符串为起始的字符串链长度为 1 。每选择一个起始字符串，从它的长度 + 1 的每个字符串 j 开始比较，是否能为其前身字符串。如果能构成前身字符串，那么 dp[i] = max(dp[i], 1+dp[j])。最终递推到下标为 0 的字符串。最终输出整个递推过程中的最大长度即为所求。 + +## 代码 + +```go +package leetcode + +import "sort" + +func longestStrChain(words []string) int { + sort.Slice(words, func(i, j int) bool { return len(words[i]) < len(words[j]) }) + poss, res := make([]int, 16+2), 0 + for i, w := range words { + if poss[len(w)] == 0 { + poss[len(w)] = i + } + } + dp := make([]int, len(words)) + for i := len(words) - 1; i >= 0; i-- { + dp[i] = 1 + for j := poss[len(words[i])+1]; j < len(words) && len(words[j]) == len(words[i])+1; j++ { + if isPredecessor(words[j], words[i]) { + dp[i] = max(dp[i], 1+dp[j]) + } + } + res = max(res, dp[i]) + } + return res +} + +func max(a, b int) int { + if a > b { + return a + } + return b +} + +func isPredecessor(long, short string) bool { + i, j := 0, 0 + wasMismatch := false + for j < len(short) { + if long[i] != short[j] { + if wasMismatch { + return false + } + wasMismatch = true + i++ + continue + } + i++ + j++ + } + return true +} +``` \ No newline at end of file diff --git a/leetcode/1104.Path-In-Zigzag-Labelled-Binary-Tree/1104.Path In Zigzag Labelled Binary Tree.go b/leetcode/1104.Path-In-Zigzag-Labelled-Binary-Tree/1104.Path In Zigzag Labelled Binary Tree.go new file mode 100644 index 000000000..a7e2f580e --- /dev/null +++ b/leetcode/1104.Path-In-Zigzag-Labelled-Binary-Tree/1104.Path In Zigzag Labelled Binary Tree.go @@ -0,0 +1,43 @@ +package leetcode + +func pathInZigZagTree(label int) []int { + level := getLevel(label) + ans := []int{label} + curIndex := label - (1 << level) + parent := 0 + for level >= 1 { + parent, curIndex = getParent(curIndex, level) + ans = append(ans, parent) + level-- + } + ans = reverse(ans) + return ans +} + +func getLevel(label int) int { + level := 0 + nums := 0 + for { + nums += 1 << level + if nums >= label { + return level + } + level++ + } +} + +func getParent(index int, level int) (parent int, parentIndex int) { + parentIndex = 1<<(level-1) - 1 + (index/2)*(-1) + parent = 1<<(level-1) + parentIndex + return +} + +func reverse(nums []int) []int { + left, right := 0, len(nums)-1 + for left < right { + nums[left], nums[right] = nums[right], nums[left] + left++ + right-- + } + return nums +} diff --git a/leetcode/1104.Path-In-Zigzag-Labelled-Binary-Tree/1104.Path In Zigzag Labelled Binary Tree_test.go b/leetcode/1104.Path-In-Zigzag-Labelled-Binary-Tree/1104.Path In Zigzag Labelled Binary Tree_test.go new file mode 100644 index 000000000..5bdd0cf0d --- /dev/null +++ b/leetcode/1104.Path-In-Zigzag-Labelled-Binary-Tree/1104.Path In Zigzag Labelled Binary Tree_test.go @@ -0,0 +1,45 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question1104 struct { + para1104 + ans1104 +} + +// para 是参数 +type para1104 struct { + label int +} + +// ans 是答案 +type ans1104 struct { + ans []int +} + +func Test_Problem1104(t *testing.T) { + + qs := []question1104{ + + { + para1104{14}, + ans1104{[]int{1, 3, 4, 14}}, + }, + + { + para1104{26}, + ans1104{[]int{1, 2, 6, 10, 26}}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 1104------------------------\n") + + for _, q := range qs { + _, p := q.ans1104, q.para1104 + fmt.Printf("【input】:%v 【output】:%v \n", p, pathInZigZagTree(p.label)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/1104.Path-In-Zigzag-Labelled-Binary-Tree/README.md b/leetcode/1104.Path-In-Zigzag-Labelled-Binary-Tree/README.md new file mode 100644 index 000000000..bdca7d7d0 --- /dev/null +++ b/leetcode/1104.Path-In-Zigzag-Labelled-Binary-Tree/README.md @@ -0,0 +1,92 @@ +# [1104. Path In Zigzag Labelled Binary Tree](https://leetcode.com/problems/path-in-zigzag-labelled-binary-tree/) + + +## 题目 + +In an infinite binary tree where every node has two children, the nodes are labelled in row order. + +In the odd numbered rows (ie., the first, third, fifth,...), the labelling is left to right, while in the even numbered rows (second, fourth, sixth,...), the labelling is right to left. + +![https://assets.leetcode.com/uploads/2019/06/24/tree.png](https://assets.leetcode.com/uploads/2019/06/24/tree.png) + +Given the `label` of a node in this tree, return the labels in the path from the root of the tree to the node with that `label`. + +**Example 1:** + +``` +Input: label = 14 +Output: [1,3,4,14] + +``` + +**Example 2:** + +``` +Input: label = 26 +Output: [1,2,6,10,26] + +``` + +**Constraints:** + +- `1 <= label <= 10^6` + +## 题目大意 + +在一棵无限的二叉树上，每个节点都有两个子节点，树中的节点 逐行 依次按 “之” 字形进行标记。如下图所示，在奇数行（即，第一行、第三行、第五行……）中，按从左到右的顺序进行标记；而偶数行（即，第二行、第四行、第六行……）中，按从右到左的顺序进行标记。 + +给你树上某一个节点的标号 label，请你返回从根节点到该标号为 label 节点的路径，该路径是由途经的节点标号所组成的。 + +## 解题思路 + +- 计算出 label 所在的 level 和 index。 +- 根据 index 和 level 计算出父节点的 index 和 value。 +- level 减一，循环计算出对应的父节点直到根节点。 + +## 代码 + +```go +package leetcode + +func pathInZigZagTree(label int) []int { + level := getLevel(label) + ans := []int{label} + curIndex := label - (1 << level) + parent := 0 + for level >= 1 { + parent, curIndex = getParent(curIndex, level) + ans = append(ans, parent) + level-- + } + ans = reverse(ans) + return ans +} + +func getLevel(label int) int { + level := 0 + nums := 0 + for { + nums += 1 << level + if nums >= label { + return level + } + level++ + } +} + +func getParent(index int, level int) (parent int, parentIndex int) { + parentIndex = 1<<(level-1) - 1 + (index/2)*(-1) + parent = 1<<(level-1) + parentIndex + return +} + +func reverse(nums []int) []int { + left, right := 0, len(nums)-1 + for left < right { + nums[left], nums[right] = nums[right], nums[left] + left++ + right-- + } + return nums +} +``` \ No newline at end of file diff --git a/leetcode/1178.Number-of-Valid-Words-for-Each-Puzzle/1178. Number of Valid Words for Each Puzzle.go b/leetcode/1178.Number-of-Valid-Words-for-Each-Puzzle/1178. Number of Valid Words for Each Puzzle.go index dca6fd626..8acbe9ebc 100644 --- a/leetcode/1178.Number-of-Valid-Words-for-Each-Puzzle/1178. Number of Valid Words for Each Puzzle.go +++ b/leetcode/1178.Number-of-Valid-Words-for-Each-Puzzle/1178. Number of Valid Words for Each Puzzle.go @@ -1,10 +1,10 @@ package leetcode /* - 匹配跟单词中的字母顺序，字母个数都无关，可以用bitmap压缩 - 1. 记录word中 利用map记录各种bit标示的个数 - 2. puzzles 中各个字母都不相同! 记录bitmap，然后搜索子空间中各种bit标识的个数的和 - 因为puzzles长度最长是7，所以搜索空间 2^7 +匹配跟单词中的字母顺序，字母个数都无关，可以用 bitmap 压缩 + 1. 记录 word 中 利用 map 记录各种 bit 标示的个数 + 2. puzzles 中各个字母都不相同! 记录 bitmap，然后搜索子空间中各种 bit 标识的个数的和 + 因为 puzzles 长度最长是7，所以搜索空间 2^7 */ func findNumOfValidWords(words []string, puzzles []string) []int { wordBitStatusMap, res := make(map[uint32]int, 0), []int{} @@ -14,7 +14,7 @@ func findNumOfValidWords(words []string, puzzles []string) []int { for _, p := range puzzles { var bitMap uint32 var totalNum int - bitMap |= (1 << (p[0] - 'a')) //work中要包含 p 的第一个字母 所以这个bit位上必须是1 + bitMap |= (1 << (p[0] - 'a')) //work 中要包含 p 的第一个字母 所以这个 bit 位上必须是 1 findNum([]byte(p)[1:], bitMap, &totalNum, wordBitStatusMap) res = append(res, totalNum) } @@ -29,15 +29,15 @@ func toBitMap(word []byte) uint32 { return res } -//利用dfs 搜索 pussles的子空间 +// 利用 dfs 搜索 puzzles 的子空间 func findNum(puzzles []byte, bitMap uint32, totalNum *int, m map[uint32]int) { if len(puzzles) == 0 { *totalNum = *totalNum + m[bitMap] return } - //不包含puzzles[0],即puzzles[0]对应bit是0 + //不包含 puzzles[0],即 puzzles[0] 对应 bit 是 0 findNum(puzzles[1:], bitMap, totalNum, m) - //包含puzzles[0],即puzzles[0]对应bit是1 + //包含 puzzles[0],即 puzzles[0] 对应 bit 是 1 bitMap |= (1 << (puzzles[0] - 'a')) findNum(puzzles[1:], bitMap, totalNum, m) bitMap ^= (1 << (puzzles[0] - 'a')) //异或 清零 diff --git a/leetcode/1178.Number-of-Valid-Words-for-Each-Puzzle/README.md b/leetcode/1178.Number-of-Valid-Words-for-Each-Puzzle/README.md index d0442fe25..40d69ec65 100644 --- a/leetcode/1178.Number-of-Valid-Words-for-Each-Puzzle/README.md +++ b/leetcode/1178.Number-of-Valid-Words-for-Each-Puzzle/README.md @@ -68,13 +68,14 @@ There're no valid words for "gaswxyz" cause none of the words in the list cont ## 代码 ```go + package leetcode /* - 匹配跟单词中的字母顺序，字母个数都无关，可以用bitmap压缩 - 1. 记录word中 利用map记录各种bit标示的个数 - 2. puzzles 中各个字母都不相同! 记录bitmap，然后搜索子空间中各种bit标识的个数的和 - 因为puzzles长度最长是7，所以搜索空间 2^7 + 匹配跟单词中的字母顺序，字母个数都无关，可以用 bitmap 压缩 + 1. 记录 word 中 利用 map 记录各种 bit 标示的个数 + 2. puzzles 中各个字母都不相同! 记录 bitmap，然后搜索子空间中各种 bit 标识的个数的和 + 因为 puzzles 长度最长是7，所以搜索空间 2^7 */ func findNumOfValidWords(words []string, puzzles []string) []int { wordBitStatusMap, res := make(map[uint32]int, 0), []int{} @@ -84,7 +85,7 @@ func findNumOfValidWords(words []string, puzzles []string) []int { for _, p := range puzzles { var bitMap uint32 var totalNum int - bitMap |= (1 << (p[0] - 'a')) //work中要包含 p 的第一个字母 所以这个bit位上必须是1 + bitMap |= (1 << (p[0] - 'a')) //work 中要包含 p 的第一个字母 所以这个 bit 位上必须是 1 findNum([]byte(p)[1:], bitMap, &totalNum, wordBitStatusMap) res = append(res, totalNum) } @@ -99,18 +100,20 @@ func toBitMap(word []byte) uint32 { return res } -//利用dfs 搜索 pussles的子空间 +//利用 dfs 搜索 puzzles 的子空间 func findNum(puzzles []byte, bitMap uint32, totalNum *int, m map[uint32]int) { if len(puzzles) == 0 { *totalNum = *totalNum + m[bitMap] return } - //不包含puzzles[0],即puzzles[0]对应bit是0 + //不包含 puzzles[0],即 puzzles[0] 对应 bit 是 0 findNum(puzzles[1:], bitMap, totalNum, m) - //包含puzzles[0],即puzzles[0]对应bit是1 + //包含 puzzles[0],即 puzzles[0] 对应 bit 是 1 bitMap |= (1 << (puzzles[0] - 'a')) findNum(puzzles[1:], bitMap, totalNum, m) bitMap ^= (1 << (puzzles[0] - 'a')) //异或 清零 return } + + ``` \ No newline at end of file diff --git a/leetcode/1190.Reverse-Substrings-Between-Each-Pair-of-Parentheses/1190. Reverse Substrings Between Each Pair of Parentheses.go b/leetcode/1190.Reverse-Substrings-Between-Each-Pair-of-Parentheses/1190. Reverse Substrings Between Each Pair of Parentheses.go new file mode 100644 index 000000000..fe76ab529 --- /dev/null +++ b/leetcode/1190.Reverse-Substrings-Between-Each-Pair-of-Parentheses/1190. Reverse Substrings Between Each Pair of Parentheses.go @@ -0,0 +1,24 @@ +package leetcode + +func reverseParentheses(s string) string { + pair, stack := make([]int, len(s)), []int{} + for i, b := range s { + if b == '(' { + stack = append(stack, i) + } else if b == ')' { + j := stack[len(stack)-1] + stack = stack[:len(stack)-1] + pair[i], pair[j] = j, i + } + } + res := []byte{} + for i, step := 0, 1; i < len(s); i += step { + if s[i] == '(' || s[i] == ')' { + i = pair[i] + step = -step + } else { + res = append(res, s[i]) + } + } + return string(res) +} diff --git a/leetcode/1190.Reverse-Substrings-Between-Each-Pair-of-Parentheses/1190. Reverse Substrings Between Each Pair of Parentheses_test.go b/leetcode/1190.Reverse-Substrings-Between-Each-Pair-of-Parentheses/1190. Reverse Substrings Between Each Pair of Parentheses_test.go new file mode 100644 index 000000000..cf5c51b1c --- /dev/null +++ b/leetcode/1190.Reverse-Substrings-Between-Each-Pair-of-Parentheses/1190. Reverse Substrings Between Each Pair of Parentheses_test.go @@ -0,0 +1,57 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question1190 struct { + para1190 + ans1190 +} + +// para 是参数 +// one 代表第一个参数 +type para1190 struct { + s string +} + +// ans 是答案 +// one 代表第一个答案 +type ans1190 struct { + one string +} + +func Test_Problem1190(t *testing.T) { + + qs := []question1190{ + + { + para1190{"(abcd)"}, + ans1190{"dcba"}, + }, + + { + para1190{"(u(love)i)"}, + ans1190{"iloveu"}, + }, + + { + para1190{"(ed(et(oc))el)"}, + ans1190{"leetcode"}, + }, + + { + para1190{"a(bcdefghijkl(mno)p)q"}, + ans1190{"apmnolkjihgfedcbq"}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 1190------------------------\n") + + for _, q := range qs { + _, p := q.ans1190, q.para1190 + fmt.Printf("【input】:%v 【output】:%v\n", p, reverseParentheses(p.s)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/1190.Reverse-Substrings-Between-Each-Pair-of-Parentheses/README.md b/leetcode/1190.Reverse-Substrings-Between-Each-Pair-of-Parentheses/README.md new file mode 100644 index 000000000..22bc27edd --- /dev/null +++ b/leetcode/1190.Reverse-Substrings-Between-Each-Pair-of-Parentheses/README.md @@ -0,0 +1,84 @@ +# [1190. Reverse Substrings Between Each Pair of Parentheses](https://leetcode.com/problems/reverse-substrings-between-each-pair-of-parentheses/) + + +## 题目 + +You are given a string `s` that consists of lower case English letters and brackets. + +Reverse the strings in each pair of matching parentheses, starting from the innermost one. + +Your result should **not** contain any brackets. + +**Example 1:** + +``` +Input: s = "(abcd)" +Output: "dcba" +``` + +**Example 2:** + +``` +Input: s = "(u(love)i)" +Output: "iloveu" +Explanation: The substring "love" is reversed first, then the whole string is reversed. +``` + +**Example 3:** + +``` +Input: s = "(ed(et(oc))el)" +Output: "leetcode" +Explanation: First, we reverse the substring "oc", then "etco", and finally, the whole string. +``` + +**Example 4:** + +``` +Input: s = "a(bcdefghijkl(mno)p)q" +Output: "apmnolkjihgfedcbq" +``` + +**Constraints:** + +- `0 <= s.length <= 2000` +- `s` only contains lower case English characters and parentheses. +- It's guaranteed that all parentheses are balanced. + +## 题目大意 + +给出一个字符串 s（仅含有小写英文字母和括号）。请你按照从括号内到外的顺序，逐层反转每对匹配括号中的字符串，并返回最终的结果。注意，您的结果中 不应 包含任何括号。 + +## 解题思路 + +- 本题最容易想到的思路是利用栈将每对括号里面的字符串入栈，当遇到 ")" 括号时出栈并逆序。由于用到了栈的数据结构，多层括号嵌套的问题也不用担心。这种边入栈出栈，逆序字符串的方法，时间复杂度是 O(n^2)，有没有可能进一步降低时间复杂度呢？ +- 上述解法中，存在重复遍历的情况。扫描原字符串的时候，入栈出栈已经扫描了一次，在 ")" 括号出栈时，逆序又会扫一遍已经入栈的字符串。这部分重复遍历的过程可以优化掉。第一次循环先标记出逆序区间。例如遇到 "(" 的时候，入栈并记录下它的下标，当遇到 ")" 的时候，意味着这一对括号匹配上了，所以将 ")" 的下标和之前入栈 "(" 的下标交换。此次遍历将逆序区间标记出来了。再遍历一次，根据逆序区间逆序字符串。不在逆序区间的字符串正常 append。如果在逆序区间内的，逆序遍历，添加到最终结果字符串中。这样做，时间复杂度仅为 O(n)。具体实现见下面代码。 + +## 代码 + +```go +package leetcode + +func reverseParentheses(s string) string { + pair, stack := make([]int, len(s)), []int{} + for i, b := range s { + if b == '(' { + stack = append(stack, i) + } else if b == ')' { + j := stack[len(stack)-1] + stack = stack[:len(stack)-1] + pair[i], pair[j] = j, i + } + } + res := []byte{} + for i, step := 0, 1; i < len(s); i += step { + if s[i] == '(' || s[i] == ')' { + i = pair[i] + step = -step + } else { + res = append(res, s[i]) + } + } + return string(res) +} +``` \ No newline at end of file diff --git a/leetcode/1239.Maximum-Length-of-a-Concatenated-String-with-Unique-Characters/1239. Maximum Length of a Concatenated String with Unique Characters.go b/leetcode/1239.Maximum-Length-of-a-Concatenated-String-with-Unique-Characters/1239. Maximum Length of a Concatenated String with Unique Characters.go new file mode 100644 index 000000000..f75727caf --- /dev/null +++ b/leetcode/1239.Maximum-Length-of-a-Concatenated-String-with-Unique-Characters/1239. Maximum Length of a Concatenated String with Unique Characters.go @@ -0,0 +1,38 @@ +package leetcode + +import ( + "math/bits" +) + +func maxLength(arr []string) int { + c, res := []uint32{}, 0 + for _, s := range arr { + var mask uint32 + for _, c := range s { + mask = mask | 1<<(c-'a') + } + if len(s) != bits.OnesCount32(mask) { // 如果字符串本身带有重复的字符，需要排除 + continue + } + c = append(c, mask) + } + dfs(c, 0, 0, &res) + return res +} + +func dfs(c []uint32, index int, mask uint32, res *int) { + *res = max(*res, bits.OnesCount32(mask)) + for i := index; i < len(c); i++ { + if mask&c[i] == 0 { + dfs(c, i+1, mask|c[i], res) + } + } + return +} + +func max(a, b int) int { + if a > b { + return a + } + return b +} diff --git a/leetcode/1239.Maximum-Length-of-a-Concatenated-String-with-Unique-Characters/1239. Maximum Length of a Concatenated String with Unique Characters_test.go b/leetcode/1239.Maximum-Length-of-a-Concatenated-String-with-Unique-Characters/1239. Maximum Length of a Concatenated String with Unique Characters_test.go new file mode 100644 index 000000000..8a0c00345 --- /dev/null +++ b/leetcode/1239.Maximum-Length-of-a-Concatenated-String-with-Unique-Characters/1239. Maximum Length of a Concatenated String with Unique Characters_test.go @@ -0,0 +1,52 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question1239 struct { + para1239 + ans1239 +} + +// para 是参数 +// one 代表第一个参数 +type para1239 struct { + arr []string +} + +// ans 是答案 +// one 代表第一个答案 +type ans1239 struct { + one int +} + +func Test_Problem1239(t *testing.T) { + + qs := []question1239{ + + { + para1239{[]string{"un", "iq", "ue"}}, + ans1239{4}, + }, + + { + para1239{[]string{"cha", "r", "act", "ers"}}, + ans1239{6}, + }, + + { + para1239{[]string{"abcdefghijklmnopqrstuvwxyz"}}, + ans1239{26}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 1239------------------------\n") + + for _, q := range qs { + _, p := q.ans1239, q.para1239 + fmt.Printf("【input】:%v 【output】:%v\n", p, maxLength(p.arr)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/1239.Maximum-Length-of-a-Concatenated-String-with-Unique-Characters/README.md b/leetcode/1239.Maximum-Length-of-a-Concatenated-String-with-Unique-Characters/README.md new file mode 100644 index 000000000..58cdb2e9d --- /dev/null +++ b/leetcode/1239.Maximum-Length-of-a-Concatenated-String-with-Unique-Characters/README.md @@ -0,0 +1,88 @@ +# [1239. Maximum Length of a Concatenated String with Unique Characters](https://leetcode.com/problems/maximum-length-of-a-concatenated-string-with-unique-characters/) + +## 题目 + +Given an array of strings `arr`. String `s` is a concatenation of a sub-sequence of `arr` which have **unique characters**. + +Return *the maximum possible length* of `s`. + +**Example 1:** + +``` +Input: arr = ["un","iq","ue"] +Output: 4 +Explanation: All possible concatenations are "","un","iq","ue","uniq" and "ique". +Maximum length is 4. +``` + +**Example 2:** + +``` +Input: arr = ["cha","r","act","ers"] +Output: 6 +Explanation: Possible solutions are "chaers" and "acters". +``` + +**Example 3:** + +``` +Input: arr = ["abcdefghijklmnopqrstuvwxyz"] +Output: 26 +``` + +**Constraints:** + +- `1 <= arr.length <= 16` +- `1 <= arr[i].length <= 26` +- `arr[i]` contains only lower case English letters. + +## 题目大意 + +给定一个字符串数组 arr，字符串 s 是将 arr 某一子序列字符串连接所得的字符串，如果 s 中的每一个字符都只出现过一次，那么它就是一个可行解。请返回所有可行解 s 中最长长度。 + +## 解题思路 + +- 每个字符串数组可以想象为 26 位的 0101 二进制串。出现的字符对应的位上标记为 1，没有出现的字符对应的位上标记为 0 。如果一个字符串中包含重复的字符，那么它所有 1 的个数一定不等于字符串的长度。如果 2 个字符串每个字母都只出现了一次，那么它们俩对应的二进制串 mask 相互与运算的结果一定为 0 ，即 0，1 互补了。利用这个特点，深搜所有解，保存出最长可行解的长度即可。 + +## 代码 + +```go +package leetcode + +import ( + "math/bits" +) + +func maxLength(arr []string) int { + c, res := []uint32{}, 0 + for _, s := range arr { + var mask uint32 + for _, c := range s { + mask = mask | 1<<(c-'a') + } + if len(s) != bits.OnesCount32(mask) { // 如果字符串本身带有重复的字符，需要排除 + continue + } + c = append(c, mask) + } + dfs(c, 0, 0, &res) + return res +} + +func dfs(c []uint32, index int, mask uint32, res *int) { + *res = max(*res, bits.OnesCount32(mask)) + for i := index; i < len(c); i++ { + if mask&c[i] == 0 { + dfs(c, i+1, mask|c[i], res) + } + } + return +} + +func max(a, b int) int { + if a > b { + return a + } + return b +} +``` \ No newline at end of file diff --git a/leetcode/1268.Search-Suggestions-System/1268. Search Suggestions System.go b/leetcode/1268.Search-Suggestions-System/1268. Search Suggestions System.go new file mode 100644 index 000000000..d9ba6b502 --- /dev/null +++ b/leetcode/1268.Search-Suggestions-System/1268. Search Suggestions System.go @@ -0,0 +1,22 @@ +package leetcode + +import ( + "sort" +) + +func suggestedProducts(products []string, searchWord string) [][]string { + sort.Strings(products) + searchWordBytes, result := []byte(searchWord), make([][]string, 0, len(searchWord)) + for i := 1; i <= len(searchWord); i++ { + searchWordBytes[i-1]++ + products = products[:sort.SearchStrings(products, string(searchWordBytes[:i]))] + searchWordBytes[i-1]-- + products = products[sort.SearchStrings(products, searchWord[:i]):] + if len(products) > 3 { + result = append(result, products[:3]) + } else { + result = append(result, products) + } + } + return result +} diff --git a/leetcode/1268.Search-Suggestions-System/1268. Search Suggestions System_test.go b/leetcode/1268.Search-Suggestions-System/1268. Search Suggestions System_test.go new file mode 100644 index 000000000..bc2be9a48 --- /dev/null +++ b/leetcode/1268.Search-Suggestions-System/1268. Search Suggestions System_test.go @@ -0,0 +1,70 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question1268 struct { + para1268 + ans1268 +} + +// para 是参数 +// one 代表第一个参数 +type para1268 struct { + products []string + searchWord string +} + +// ans 是答案 +// one 代表第一个答案 +type ans1268 struct { + one [][]string +} + +func Test_Problem1268(t *testing.T) { + + qs := []question1268{ + + { + para1268{[]string{"bags", "baggage", "banner", "box", "cloths"}, "bags"}, + ans1268{[][]string{ + {"baggage", "bags", "banner"}, {"baggage", "bags", "banner"}, {"baggage", "bags"}, {"bags"}, + }}, + }, + + { + para1268{[]string{"mobile", "mouse", "moneypot", "monitor", "mousepad"}, "mouse"}, + ans1268{[][]string{ + {"mobile", "moneypot", "monitor"}, + {"mobile", "moneypot", "monitor"}, + {"mouse", "mousepad"}, + {"mouse", "mousepad"}, + {"mouse", "mousepad"}, + }}, + }, + + { + para1268{[]string{"havana"}, "havana"}, + ans1268{[][]string{ + {"havana"}, {"havana"}, {"havana"}, {"havana"}, {"havana"}, {"havana"}, + }}, + }, + + { + para1268{[]string{"havana"}, "tatiana"}, + ans1268{[][]string{ + {}, {}, {}, {}, {}, {}, {}, + }}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 1268------------------------\n") + + for _, q := range qs { + _, p := q.ans1268, q.para1268 + fmt.Printf("【input】:%v 【output】:%v\n", p, suggestedProducts(p.products, p.searchWord)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/1268.Search-Suggestions-System/README.md b/leetcode/1268.Search-Suggestions-System/README.md new file mode 100644 index 000000000..769f4d7a8 --- /dev/null +++ b/leetcode/1268.Search-Suggestions-System/README.md @@ -0,0 +1,89 @@ +# [1268. Search Suggestions System](https://leetcode.com/problems/search-suggestions-system/) + +## 题目 + +Given an array of strings `products` and a string `searchWord`. We want to design a system that suggests at most three product names from `products` after each character of `searchWord` is typed. Suggested products should have common prefix with the searchWord. If there are more than three products with a common prefix return the three lexicographically minimums products. + +Return *list of lists* of the suggested `products` after each character of `searchWord` is typed. + +**Example 1:** + +``` +Input: products = ["mobile","mouse","moneypot","monitor","mousepad"], searchWord = "mouse" +Output: [ +["mobile","moneypot","monitor"], +["mobile","moneypot","monitor"], +["mouse","mousepad"], +["mouse","mousepad"], +["mouse","mousepad"] +] +Explanation: products sorted lexicographically = ["mobile","moneypot","monitor","mouse","mousepad"] +After typing m and mo all products match and we show user ["mobile","moneypot","monitor"] +After typing mou, mous and mouse the system suggests ["mouse","mousepad"] + +``` + +**Example 2:** + +``` +Input: products = ["havana"], searchWord = "havana" +Output: [["havana"],["havana"],["havana"],["havana"],["havana"],["havana"]] +``` + +**Example 3:** + +``` +Input: products = ["bags","baggage","banner","box","cloths"], searchWord = "bags" +Output: [["baggage","bags","banner"],["baggage","bags","banner"],["baggage","bags"],["bags"]] +``` + +**Example 4:** + +``` +Input: products = ["havana"], searchWord = "tatiana" +Output: [[],[],[],[],[],[],[]] +``` + +**Constraints:** + +- `1 <= products.length <= 1000` +- There are no repeated elements in `products`. +- `1 <= Σ products[i].length <= 2 * 10^4` +- All characters of `products[i]` are lower-case English letters. +- `1 <= searchWord.length <= 1000` +- All characters of `searchWord` are lower-case English letters. + +## 题目大意 + +给你一个产品数组 products 和一个字符串 searchWord ，products  数组中每个产品都是一个字符串。请你设计一个推荐系统，在依次输入单词 searchWord 的每一个字母后，推荐 products 数组中前缀与 searchWord 相同的最多三个产品。如果前缀相同的可推荐产品超过三个，请按字典序返回最小的三个。请你以二维列表的形式，返回在输入 searchWord 每个字母后相应的推荐产品的列表。 + +## 解题思路 + +- 由于题目要求返回的答案要按照字典序输出，所以先排序。有序字符串又满足了二分搜索的条件，于是可以用二分搜索。sort.SearchStrings 返回的是满足搜索条件的第一个起始下标。末尾不满足条件的字符串要切掉。所以要搜 2 次，第一次二分搜索先将不满足目标串前缀的字符串筛掉。第二次二分搜索再搜索出最终满足题意的字符串。 + +## 代码 + +```go +package leetcode + +import ( + "sort" +) + +func suggestedProducts(products []string, searchWord string) [][]string { + sort.Strings(products) + searchWordBytes, result := []byte(searchWord), make([][]string, 0, len(searchWord)) + for i := 1; i <= len(searchWord); i++ { + searchWordBytes[i-1]++ + products = products[:sort.SearchStrings(products, string(searchWordBytes[:i]))] + searchWordBytes[i-1]-- + products = products[sort.SearchStrings(products, searchWord[:i]):] + if len(products) > 3 { + result = append(result, products[:3]) + } else { + result = append(result, products) + } + } + return result +} +``` \ No newline at end of file diff --git a/leetcode/1293.Shortest-Path-in-a-Grid-with-Obstacles-Elimination/1293. Shortest Path in a Grid with Obstacles Elimination.go b/leetcode/1293.Shortest-Path-in-a-Grid-with-Obstacles-Elimination/1293. Shortest Path in a Grid with Obstacles Elimination.go new file mode 100644 index 000000000..71140a986 --- /dev/null +++ b/leetcode/1293.Shortest-Path-in-a-Grid-with-Obstacles-Elimination/1293. Shortest Path in a Grid with Obstacles Elimination.go @@ -0,0 +1,71 @@ +package leetcode + +var dir = [][]int{ + {-1, 0}, + {0, 1}, + {1, 0}, + {0, -1}, +} + +type pos struct { + x, y int + obstacle int + step int +} + +func shortestPath(grid [][]int, k int) int { + queue, m, n := []pos{}, len(grid), len(grid[0]) + visitor := make([][][]int, m) + if len(grid) == 1 && len(grid[0]) == 1 { + return 0 + } + for i := 0; i < m; i++ { + visitor[i] = make([][]int, n) + for j := 0; j < n; j++ { + visitor[i][j] = make([]int, k+1) + } + } + visitor[0][0][0] = 1 + queue = append(queue, pos{x: 0, y: 0, obstacle: 0, step: 0}) + for len(queue) > 0 { + size := len(queue) + for size > 0 { + size-- + node := queue[0] + queue = queue[1:] + for i := 0; i < len(dir); i++ { + newX := node.x + dir[i][0] + newY := node.y + dir[i][1] + if newX == m-1 && newY == n-1 { + if node.obstacle != 0 { + if node.obstacle <= k { + return node.step + 1 + } else { + continue + } + } + return node.step + 1 + } + if isInBoard(grid, newX, newY) { + if grid[newX][newY] == 1 { + if node.obstacle+1 <= k && visitor[newX][newY][node.obstacle+1] != 1 { + queue = append(queue, pos{x: newX, y: newY, obstacle: node.obstacle + 1, step: node.step + 1}) + visitor[newX][newY][node.obstacle+1] = 1 + } + } else { + if node.obstacle <= k && visitor[newX][newY][node.obstacle] != 1 { + queue = append(queue, pos{x: newX, y: newY, obstacle: node.obstacle, step: node.step + 1}) + visitor[newX][newY][node.obstacle] = 1 + } + } + + } + } + } + } + return -1 +} + +func isInBoard(board [][]int, x, y int) bool { + return x >= 0 && x < len(board) && y >= 0 && y < len(board[0]) +} diff --git a/leetcode/1293.Shortest-Path-in-a-Grid-with-Obstacles-Elimination/1293. Shortest Path in a Grid with Obstacles Elimination_test.go b/leetcode/1293.Shortest-Path-in-a-Grid-with-Obstacles-Elimination/1293. Shortest Path in a Grid with Obstacles Elimination_test.go new file mode 100644 index 000000000..c7e4c68dd --- /dev/null +++ b/leetcode/1293.Shortest-Path-in-a-Grid-with-Obstacles-Elimination/1293. Shortest Path in a Grid with Obstacles Elimination_test.go @@ -0,0 +1,73 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question1293 struct { + para1293 + ans1293 +} + +// para 是参数 +// one 代表第一个参数 +type para1293 struct { + grid [][]int + k int +} + +// ans 是答案 +// one 代表第一个答案 +type ans1293 struct { + one int +} + +func Test_Problem1293(t *testing.T) { + + qs := []question1293{ + + { + para1293{[][]int{ + {0, 0, 0}, + }, 1}, + ans1293{2}, + }, + + { + para1293{[][]int{ + {0, 1, 1}, {0, 1, 1}, {0, 0, 0}, {0, 1, 0}, {0, 1, 0}, + }, 2}, + ans1293{6}, + }, + + { + para1293{[][]int{ + {0, 0, 0}, {1, 1, 0}, {0, 0, 0}, {0, 1, 1}, {0, 0, 0}, + }, 1}, + ans1293{6}, + }, + + { + para1293{[][]int{ + {0, 1, 1}, {1, 1, 1}, {1, 0, 0}, + }, 1}, + ans1293{-1}, + }, + + { + para1293{[][]int{ + {0}, + }, 1}, + ans1293{0}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 1293------------------------\n") + + for _, q := range qs { + _, p := q.ans1293, q.para1293 + fmt.Printf("【input】:%v 【output】:%v\n", p, shortestPath(p.grid, p.k)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/1293.Shortest-Path-in-a-Grid-with-Obstacles-Elimination/README.md b/leetcode/1293.Shortest-Path-in-a-Grid-with-Obstacles-Elimination/README.md new file mode 100644 index 000000000..0ef3fc05e --- /dev/null +++ b/leetcode/1293.Shortest-Path-in-a-Grid-with-Obstacles-Elimination/README.md @@ -0,0 +1,131 @@ +# [1293. Shortest Path in a Grid with Obstacles Elimination](https://leetcode.com/problems/shortest-path-in-a-grid-with-obstacles-elimination/) + + + +## 题目 + +You are given an m x n integer matrix grid where each cell is either 0 (empty) or 1 (obstacle). You can move up, down, left, or right from and to an empty cell in one step. + +Return the minimum number of steps to walk from the upper left corner (0, 0) to the lower right corner (m - 1, n - 1) given that you can eliminate at most k obstacles. If it is not possible to find such walk return -1. + + + +Example 1: + + +![](https://assets.leetcode.com/uploads/2021/09/30/short1-grid.jpg) + + +``` +Input: grid = [[0,0,0],[1,1,0],[0,0,0],[0,1,1],[0,0,0]], k = 1 +Output: 6 +Explanation: +The shortest path without eliminating any obstacle is 10. +The shortest path with one obstacle elimination at position (3,2) is 6. Such path is (0,0) -> (0,1) -> (0,2) -> (1,2) -> (2,2) -> (3,2) -> (4,2). +``` + +Example 2: + +![](https://assets.leetcode.com/uploads/2021/09/30/short2-grid.jpg) + +``` +Input: grid = [[0,1,1],[1,1,1],[1,0,0]], k = 1 +Output: -1 +Explanation: We need to eliminate at least two obstacles to find such a walk. +``` + +Constraints: + +- m == grid.length +- n == grid[i].length +- 1 <= m, n <= 40 +- 1 <= k <= m * n +- grid[i][j] is either 0 or 1. +- grid[0][0] == grid[m - 1][n - 1] == 0 + + + +## 题目大意 + +给你一个 m * n 的网格，其中每个单元格不是 0（空）就是 1（障碍物）。每一步，您都可以在空白单元格中上、下、左、右移动。 + +如果您 最多 可以消除 k 个障碍物，请找出从左上角 (0, 0) 到右下角 (m-1, n-1) 的最短路径，并返回通过该路径所需的步数。如果找不到这样的路径，则返回 -1 。 + + +## 解题思路 + +使用 BFS 遍历棋盘。这题比普通可达性问题多了一个障碍物的限制。这个也不难。每个点往周边四个方向扩展的时候，如果遇到障碍物，先算上这个障碍物，障碍物累积总个数小于 K 的时候，从障碍物的这个格子继续开始遍历。如果没有遇到障碍物，判断当前累积障碍物个数是否已经小于 K 个，如果小于 K 便继续遍历。如果大于 K，便终止此轮遍历。 + +## 代码 + +```go +var dir = [][]int{ + {-1, 0}, + {0, 1}, + {1, 0}, + {0, -1}, +} + +type pos struct { + x, y int + obstacle int + step int +} + +func shortestPath(grid [][]int, k int) int { + queue, m, n := []pos{}, len(grid), len(grid[0]) + visitor := make([][][]int, m) + if len(grid) == 1 && len(grid[0]) == 1 { + return 0 + } + for i := 0; i < m; i++ { + visitor[i] = make([][]int, n) + for j := 0; j < n; j++ { + visitor[i][j] = make([]int, k+1) + } + } + visitor[0][0][0] = 1 + queue = append(queue, pos{x: 0, y: 0, obstacle: 0, step: 0}) + for len(queue) > 0 { + size := len(queue) + for size > 0 { + size-- + node := queue[0] + queue = queue[1:] + for i := 0; i < len(dir); i++ { + newX := node.x + dir[i][0] + newY := node.y + dir[i][1] + if newX == m-1 && newY == n-1 { + if node.obstacle != 0 { + if node.obstacle <= k { + return node.step + 1 + } else { + continue + } + } + return node.step + 1 + } + if isInBoard(grid, newX, newY) { + if grid[newX][newY] == 1 { + if node.obstacle+1 <= k && visitor[newX][newY][node.obstacle+1] != 1 { + queue = append(queue, pos{x: newX, y: newY, obstacle: node.obstacle + 1, step: node.step + 1}) + visitor[newX][newY][node.obstacle+1] = 1 + } + } else { + if node.obstacle <= k && visitor[newX][newY][node.obstacle] != 1 { + queue = append(queue, pos{x: newX, y: newY, obstacle: node.obstacle, step: node.step + 1}) + visitor[newX][newY][node.obstacle] = 1 + } + } + + } + } + } + } + return -1 +} + +func isInBoard(board [][]int, x, y int) bool { + return x >= 0 && x < len(board) && y >= 0 && y < len(board[0]) +} +``` \ No newline at end of file diff --git a/leetcode/1296.Divide-Array-in-Sets-of-K-Consecutive-Numbers/1296.Divide Array in Sets of K Consecutive Numbers.go b/leetcode/1296.Divide-Array-in-Sets-of-K-Consecutive-Numbers/1296.Divide Array in Sets of K Consecutive Numbers.go new file mode 100644 index 000000000..22663df49 --- /dev/null +++ b/leetcode/1296.Divide-Array-in-Sets-of-K-Consecutive-Numbers/1296.Divide Array in Sets of K Consecutive Numbers.go @@ -0,0 +1,23 @@ +package leetcode + +import "sort" + +func isPossibleDivide(nums []int, k int) bool { + mp := make(map[int]int) + for _, v := range nums { + mp[v] += 1 + } + sort.Ints(nums) + for _, num := range nums { + if mp[num] == 0 { + continue + } + for diff := 0; diff < k; diff++ { + if mp[num+diff] == 0 { + return false + } + mp[num+diff] -= 1 + } + } + return true +} diff --git a/leetcode/1296.Divide-Array-in-Sets-of-K-Consecutive-Numbers/1296.Divide Array in Sets of K Consecutive Numbers_test.go b/leetcode/1296.Divide-Array-in-Sets-of-K-Consecutive-Numbers/1296.Divide Array in Sets of K Consecutive Numbers_test.go new file mode 100644 index 000000000..ac0630695 --- /dev/null +++ b/leetcode/1296.Divide-Array-in-Sets-of-K-Consecutive-Numbers/1296.Divide Array in Sets of K Consecutive Numbers_test.go @@ -0,0 +1,51 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question1296 struct { + para1296 + ans1296 +} + +// para 是参数 +type para1296 struct { + nums []int + k int +} + +// ans 是答案 +type ans1296 struct { + ans bool +} + +func Test_Problem1296(t *testing.T) { + + qs := []question1296{ + + { + para1296{[]int{1, 2, 3, 3, 4, 4, 5, 6}, 4}, + ans1296{true}, + }, + + { + para1296{[]int{3, 2, 1, 2, 3, 4, 3, 4, 5, 9, 10, 11}, 3}, + ans1296{true}, + }, + + { + para1296{[]int{1, 2, 3, 4}, 3}, + ans1296{false}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 1296------------------------\n") + + for _, q := range qs { + _, p := q.ans1296, q.para1296 + fmt.Printf("【input】:%v 【output】:%v\n", p, isPossibleDivide(p.nums, p.k)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/1296.Divide-Array-in-Sets-of-K-Consecutive-Numbers/README.md b/leetcode/1296.Divide-Array-in-Sets-of-K-Consecutive-Numbers/README.md new file mode 100644 index 000000000..cd644c590 --- /dev/null +++ b/leetcode/1296.Divide-Array-in-Sets-of-K-Consecutive-Numbers/README.md @@ -0,0 +1,72 @@ +# [1296. Divide Array in Sets of K Consecutive Numbers](https://leetcode.com/problems/divide-array-in-sets-of-k-consecutive-numbers/) + +## 题目 + +Given an array of integers nums and a positive integer k, check whether it is possible to divide this array into sets of k consecutive numbers. + +Return true if it is possible. Otherwise, return false. + +**Example 1**: + + Input: nums = [1,2,3,3,4,4,5,6], k = 4 + Output: true + Explanation: Array can be divided into [1,2,3,4] and [3,4,5,6]. + +**Example 2**: + + Input: nums = [3,2,1,2,3,4,3,4,5,9,10,11], k = 3 + Output: true + Explanation: Array can be divided into [1,2,3] , [2,3,4] , [3,4,5] and [9,10,11]. + +**Example 3**: + + Input: nums = [1,2,3,4], k = 3 + Output: false + Explanation: Each array should be divided in subarrays of size 3. + +**Constraints:** + +- 1 <= k <= nums.length <= 100000 +- 1 <= nums[i] <= 1000000000 + +## 题目大意 + +给你一个整数数组 nums 和一个正整数 k，请你判断是否可以把这个数组划分成一些由 k 个连续数字组成的集合。 +如果可以，请返回 true；否则，返回 false。 + +## 解题思路 + +贪心算法 + +- 对nums升序排序 +- 对nums内数字进行哈希计数（key:数字，value:数量） +- 遍历nums中的数字，以数量大于1的数字作为连续数字开头，寻找连续数字后续元素，若无法找到 k 个连续数字则返回false +- 所有数字都能找到 k 个连续数字返回true + +##代码 + +```go +package leetcode + +import "sort" + +func isPossibleDivide(nums []int, k int) bool { + mp := make(map[int]int) + for _, v := range nums { + mp[v] += 1 + } + sort.Ints(nums) + for _, num := range nums { + if mp[num] == 0 { + continue + } + for diff := 0; diff < k; diff++ { + if mp[num+diff] == 0 { + return false + } + mp[num+diff] -= 1 + } + } + return true +} +``` diff --git a/leetcode/1305.All-Elements-in-Two-Binary-Search-Trees/1305. All Elements in Two Binary Search Trees.go b/leetcode/1305.All-Elements-in-Two-Binary-Search-Trees/1305. All Elements in Two Binary Search Trees.go index 3206a1cdb..b3c1bcb7e 100644 --- a/leetcode/1305.All-Elements-in-Two-Binary-Search-Trees/1305. All Elements in Two Binary Search Trees.go +++ b/leetcode/1305.All-Elements-in-Two-Binary-Search-Trees/1305. All Elements in Two Binary Search Trees.go @@ -2,9 +2,7 @@ package leetcode import ( "sort" -) -import ( "github.com/halfrost/LeetCode-Go/structures" ) diff --git a/leetcode/1310.XOR-Queries-of-a-Subarray/1310. XOR Queries of a Subarray.go b/leetcode/1310.XOR-Queries-of-a-Subarray/1310. XOR Queries of a Subarray.go new file mode 100644 index 000000000..e5da239c8 --- /dev/null +++ b/leetcode/1310.XOR-Queries-of-a-Subarray/1310. XOR Queries of a Subarray.go @@ -0,0 +1,17 @@ +package leetcode + +func xorQueries(arr []int, queries [][]int) []int { + xors := make([]int, len(arr)) + xors[0] = arr[0] + for i := 1; i < len(arr); i++ { + xors[i] = arr[i] ^ xors[i-1] + } + res := make([]int, len(queries)) + for i, q := range queries { + res[i] = xors[q[1]] + if q[0] > 0 { + res[i] ^= xors[q[0]-1] + } + } + return res +} diff --git a/leetcode/1310.XOR-Queries-of-a-Subarray/1310. XOR Queries of a Subarray_test.go b/leetcode/1310.XOR-Queries-of-a-Subarray/1310. XOR Queries of a Subarray_test.go new file mode 100644 index 000000000..8066c3432 --- /dev/null +++ b/leetcode/1310.XOR-Queries-of-a-Subarray/1310. XOR Queries of a Subarray_test.go @@ -0,0 +1,48 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question1310 struct { + para1310 + ans1310 +} + +// para 是参数 +// one 代表第一个参数 +type para1310 struct { + arr []int + queries [][]int +} + +// ans 是答案 +// one 代表第一个答案 +type ans1310 struct { + one []int +} + +func Test_Problem1310(t *testing.T) { + + qs := []question1310{ + + { + para1310{[]int{1, 3, 4, 8}, [][]int{{0, 1}, {1, 2}, {0, 3}, {3, 3}}}, + ans1310{[]int{2, 7, 14, 8}}, + }, + + { + para1310{[]int{4, 8, 2, 10}, [][]int{{2, 3}, {1, 3}, {0, 0}, {0, 3}}}, + ans1310{[]int{8, 0, 4, 4}}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 1310------------------------\n") + + for _, q := range qs { + _, p := q.ans1310, q.para1310 + fmt.Printf("【input】:%v 【output】:%v\n", p, xorQueries(p.arr, p.queries)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/1310.XOR-Queries-of-a-Subarray/README.md b/leetcode/1310.XOR-Queries-of-a-Subarray/README.md new file mode 100644 index 000000000..7babbbd79 --- /dev/null +++ b/leetcode/1310.XOR-Queries-of-a-Subarray/README.md @@ -0,0 +1,75 @@ +# [1310. XOR Queries of a Subarray](https://leetcode.com/problems/xor-queries-of-a-subarray/) + + +## 题目 + +Given the array `arr` of positive integers and the array `queries` where `queries[i] = [Li,Ri]`, for each query `i` compute the **XOR** of elements from `Li` to `Ri` (that is, `arr[Li]xor arr[Li+1]xor ...xor arr[Ri]`). Return an array containing the result for the given `queries`. + +**Example 1:** + +``` +Input: arr = [1,3,4,8], queries = [[0,1],[1,2],[0,3],[3,3]] +Output: [2,7,14,8] +Explanation: +The binary representation of the elements in the array are: +1 = 0001 +3 = 0011 +4 = 0100 +8 = 1000 +The XOR values for queries are: +[0,1] = 1 xor 3 = 2 +[1,2] = 3 xor 4 = 7 +[0,3] = 1 xor 3 xor 4 xor 8 = 14 +[3,3] = 8 + +``` + +**Example 2:** + +``` +Input: arr = [4,8,2,10], queries = [[2,3],[1,3],[0,0],[0,3]] +Output: [8,0,4,4] + +``` + +**Constraints:** + +- `1 <= arr.length <= 3 * 10^4` +- `1 <= arr[i] <= 10^9` +- `1 <= queries.length <= 3 * 10^4` +- `queries[i].length == 2` +- `0 <= queries[i][0] <= queries[i][1] < arr.length` + +## 题目大意 + +有一个正整数数组 arr，现给你一个对应的查询数组 queries，其中 queries[i] = [Li, Ri]。对于每个查询 i，请你计算从 Li 到 Ri 的 XOR 值（即 arr[Li] xor arr[Li+1] xor ... xor arr[Ri]）作为本次查询的结果。并返回一个包含给定查询 queries 所有结果的数组。 + +## 解题思路 + +- 此题求区间异或，很容易让人联想到区间求和。区间求和利用前缀和，可以使得 query 从 O(n) 降为 O(1)。区间异或能否也用类似前缀和的思想呢？答案是肯定的。利用异或的两个性质，x ^ x = 0，x ^ 0 = x。那么有：（由于 LaTeX 中异或符号 ^ 是特殊字符，笔者用 $\oplus$ 代替异或） + + $$\begin{aligned}Query(left,right) &=arr[left] \oplus \cdots  \oplus arr[right]\\&=(arr[0] \oplus \cdots  \oplus arr[left-1]) \oplus (arr[0] \oplus \cdots  \oplus arr[left-1]) \oplus (arr[left] \oplus \cdots  \oplus arr[right])\\ &=(arr[0] \oplus \cdots  \oplus arr[left-1]) \oplus (arr[0] \oplus \cdots  \oplus arr[right])\\ &=xors[left] \oplus xors[right+1]\\ \end{aligned}$$ + + 按照这个思路解题，便可以将 query 从 O(n) 降为 O(1)，总的时间复杂度为 O(n)。 + +## 代码 + +```go +package leetcode + +func xorQueries(arr []int, queries [][]int) []int { + xors := make([]int, len(arr)) + xors[0] = arr[0] + for i := 1; i < len(arr); i++ { + xors[i] = arr[i] ^ xors[i-1] + } + res := make([]int, len(queries)) + for i, q := range queries { + res[i] = xors[q[1]] + if q[0] > 0 { + res[i] ^= xors[q[0]-1] + } + } + return res +} +``` \ No newline at end of file diff --git a/leetcode/1383.Maximum-Performance-of-a-Team/1383. Maximum Performance of a Team.go b/leetcode/1383.Maximum-Performance-of-a-Team/1383. Maximum Performance of a Team.go new file mode 100644 index 000000000..db69d3781 --- /dev/null +++ b/leetcode/1383.Maximum-Performance-of-a-Team/1383. Maximum Performance of a Team.go @@ -0,0 +1,48 @@ +package leetcode + +import ( + "container/heap" + "sort" +) + +func maxPerformance(n int, speed []int, efficiency []int, k int) int { + indexes := make([]int, n) + for i := range indexes { + indexes[i] = i + } + sort.Slice(indexes, func(i, j int) bool { + return efficiency[indexes[i]] > efficiency[indexes[j]] + }) + ph := speedHeap{} + heap.Init(&ph) + speedSum := 0 + var max int64 + for _, index := range indexes { + if ph.Len() == k { + speedSum -= heap.Pop(&ph).(int) + } + speedSum += speed[index] + heap.Push(&ph, speed[index]) + max = Max(max, int64(speedSum)*int64(efficiency[index])) + } + return int(max % (1e9 + 7)) +} + +type speedHeap []int + +func (h speedHeap) Less(i, j int) bool { return h[i] < h[j] } +func (h speedHeap) Swap(i, j int) { h[i], h[j] = h[j], h[i] } +func (h speedHeap) Len() int { return len(h) } +func (h *speedHeap) Push(x interface{}) { *h = append(*h, x.(int)) } +func (h *speedHeap) Pop() interface{} { + res := (*h)[len(*h)-1] + *h = (*h)[:h.Len()-1] + return res +} + +func Max(a, b int64) int64 { + if a > b { + return a + } + return b +} diff --git a/leetcode/1383.Maximum-Performance-of-a-Team/1383. Maximum Performance of a Team_test.go b/leetcode/1383.Maximum-Performance-of-a-Team/1383. Maximum Performance of a Team_test.go new file mode 100644 index 000000000..0caa6af08 --- /dev/null +++ b/leetcode/1383.Maximum-Performance-of-a-Team/1383. Maximum Performance of a Team_test.go @@ -0,0 +1,55 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question1383 struct { + para1383 + ans1383 +} + +// para 是参数 +// one 代表第一个参数 +type para1383 struct { + n int + speed []int + efficiency []int + k int +} + +// ans 是答案 +// one 代表第一个答案 +type ans1383 struct { + one int +} + +func Test_Problem1383(t *testing.T) { + + qs := []question1383{ + + { + para1383{6, []int{2, 10, 3, 1, 5, 8}, []int{5, 4, 3, 9, 7, 2}, 2}, + ans1383{60}, + }, + + { + para1383{6, []int{2, 10, 3, 1, 5, 8}, []int{5, 4, 3, 9, 7, 2}, 3}, + ans1383{68}, + }, + + { + para1383{6, []int{2, 10, 3, 1, 5, 8}, []int{5, 4, 3, 9, 7, 2}, 4}, + ans1383{72}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 1383------------------------\n") + + for _, q := range qs { + _, p := q.ans1383, q.para1383 + fmt.Printf("【input】:%v 【output】:%v\n", p, maxPerformance(p.n, p.speed, p.efficiency, p.k)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/1383.Maximum-Performance-of-a-Team/README.md b/leetcode/1383.Maximum-Performance-of-a-Team/README.md new file mode 100644 index 000000000..ce941cfd2 --- /dev/null +++ b/leetcode/1383.Maximum-Performance-of-a-Team/README.md @@ -0,0 +1,105 @@ +# [1383. Maximum Performance of a Team](https://leetcode.com/problems/maximum-performance-of-a-team/) + +## 题目 + +You are given two integers `n` and `k` and two integer arrays `speed` and `efficiency` both of length `n`. There are `n` engineers numbered from `1` to `n`. `speed[i]` and `efficiency[i]` represent the speed and efficiency of the `ith` engineer respectively. + +Choose **at most** `k` different engineers out of the `n` engineers to form a team with the maximum **performance**. + +The performance of a team is the sum of their engineers' speeds multiplied by the minimum efficiency among their engineers. + +Return *the maximum performance of this team*. Since the answer can be a huge number, return it **modulo** `109 + 7`. + +**Example 1:** + +``` +Input: n = 6, speed = [2,10,3,1,5,8], efficiency = [5,4,3,9,7,2], k = 2 +Output: 60 +Explanation: +We have the maximum performance of the team by selecting engineer 2 (with speed=10 and efficiency=4) and engineer 5 (with speed=5 and efficiency=7). That is, performance = (10 + 5) * min(4, 7) = 60. +``` + +**Example 2:** + +``` +Input: n = 6, speed = [2,10,3,1,5,8], efficiency = [5,4,3,9,7,2], k = 3 +Output: 68 +Explanation: +This is the same example as the first but k = 3. We can select engineer 1, engineer 2 and engineer 5 to get the maximum performance of the team. That is, performance = (2 + 10 + 5) * min(5, 4, 7) = 68. +``` + +**Example 3:** + +``` +Input: n = 6, speed = [2,10,3,1,5,8], efficiency = [5,4,3,9,7,2], k = 4 +Output: 72 +``` + +**Constraints:** + +- `1 <= <= k <= n <= 105` +- `speed.length == n` +- `efficiency.length == n` +- `1 <= speed[i] <= 105` +- `1 <= efficiency[i] <= 108` + +## 题目大意 + +公司有编号为 1 到 n 的 n 个工程师，给你两个数组 speed 和 efficiency ，其中 speed[i] 和 efficiency[i] 分别代表第 i 位工程师的速度和效率。请你返回由最多 k 个工程师组成的 最大团队表现值 ，由于答案可能很大，请你返回结果对 10^9 + 7 取余后的结果。团队表现值 的定义为：一个团队中「所有工程师速度的和」乘以他们「效率值中的最小值」。 + +## 解题思路 + +- 题目要求返回最大团队表现值，表现值需要考虑速度的累加和，和效率的最小值。即使速度快，效率的最小值很小，总的表现值还是很小。先将效率从大到小排序。从效率高的工程师开始选起，遍历过程中维护一个大小为 k 的速度最小堆。每次遍历都计算一次团队最大表现值。扫描完成，最大团队表现值也筛选出来了。具体实现见下面的代码。 + +## 代码 + +```go +package leetcode + +import ( + "container/heap" + "sort" +) + +func maxPerformance(n int, speed []int, efficiency []int, k int) int { + indexes := make([]int, n) + for i := range indexes { + indexes[i] = i + } + sort.Slice(indexes, func(i, j int) bool { + return efficiency[indexes[i]] > efficiency[indexes[j]] + }) + ph := speedHeap{} + heap.Init(&ph) + speedSum := 0 + var max int64 + for _, index := range indexes { + if ph.Len() == k { + speedSum -= heap.Pop(&ph).(int) + } + speedSum += speed[index] + heap.Push(&ph, speed[index]) + max = Max(max, int64(speedSum)*int64(efficiency[index])) + } + return int(max % (1e9 + 7)) +} + +type speedHeap []int + +func (h speedHeap) Less(i, j int) bool { return h[i] < h[j] } +func (h speedHeap) Swap(i, j int) { h[i], h[j] = h[j], h[i] } +func (h speedHeap) Len() int { return len(h) } +func (h *speedHeap) Push(x interface{}) { *h = append(*h, x.(int)) } +func (h *speedHeap) Pop() interface{} { + res := (*h)[len(*h)-1] + *h = (*h)[:h.Len()-1] + return res +} + +func Max(a, b int64) int64 { + if a > b { + return a + } + return b +} +``` \ No newline at end of file diff --git a/leetcode/1437.Check-If-All-1s-Are-at-Least-Length-K-Places-Away/1437. Check If All 1's Are at Least Length K Places Away.go b/leetcode/1437.Check-If-All-1s-Are-at-Least-Length-K-Places-Away/1437. Check If All 1s Are at Least Length K Places Away.go similarity index 100% rename from leetcode/1437.Check-If-All-1s-Are-at-Least-Length-K-Places-Away/1437. Check If All 1's Are at Least Length K Places Away.go rename to leetcode/1437.Check-If-All-1s-Are-at-Least-Length-K-Places-Away/1437. Check If All 1s Are at Least Length K Places Away.go diff --git a/leetcode/1437.Check-If-All-1s-Are-at-Least-Length-K-Places-Away/1437. Check If All 1's Are at Least Length K Places Away_test.go b/leetcode/1437.Check-If-All-1s-Are-at-Least-Length-K-Places-Away/1437. Check If All 1s Are at Least Length K Places Away_test.go similarity index 100% rename from leetcode/1437.Check-If-All-1s-Are-at-Least-Length-K-Places-Away/1437. Check If All 1's Are at Least Length K Places Away_test.go rename to leetcode/1437.Check-If-All-1s-Are-at-Least-Length-K-Places-Away/1437. Check If All 1s Are at Least Length K Places Away_test.go diff --git a/leetcode/1442.Count-Triplets-That-Can-Form-Two-Arrays-of-Equal-XOR/1442. Count Triplets That Can Form Two Arrays of Equal XOR.go b/leetcode/1442.Count-Triplets-That-Can-Form-Two-Arrays-of-Equal-XOR/1442. Count Triplets That Can Form Two Arrays of Equal XOR.go new file mode 100644 index 000000000..19cbf203f --- /dev/null +++ b/leetcode/1442.Count-Triplets-That-Can-Form-Two-Arrays-of-Equal-XOR/1442. Count Triplets That Can Form Two Arrays of Equal XOR.go @@ -0,0 +1,21 @@ +package leetcode + +func countTriplets(arr []int) int { + prefix, num, count, total := make([]int, len(arr)), 0, 0, 0 + for i, v := range arr { + num ^= v + prefix[i] = num + } + for i := 0; i < len(prefix)-1; i++ { + for k := i + 1; k < len(prefix); k++ { + total = prefix[k] + if i > 0 { + total ^= prefix[i-1] + } + if total == 0 { + count += k - i + } + } + } + return count +} diff --git a/leetcode/1442.Count-Triplets-That-Can-Form-Two-Arrays-of-Equal-XOR/1442. Count Triplets That Can Form Two Arrays of Equal XOR_test.go b/leetcode/1442.Count-Triplets-That-Can-Form-Two-Arrays-of-Equal-XOR/1442. Count Triplets That Can Form Two Arrays of Equal XOR_test.go new file mode 100644 index 000000000..38b31020f --- /dev/null +++ b/leetcode/1442.Count-Triplets-That-Can-Form-Two-Arrays-of-Equal-XOR/1442. Count Triplets That Can Form Two Arrays of Equal XOR_test.go @@ -0,0 +1,62 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question1442 struct { + para1442 + ans1442 +} + +// para 是参数 +// one 代表第一个参数 +type para1442 struct { + arr []int +} + +// ans 是答案 +// one 代表第一个答案 +type ans1442 struct { + one int +} + +func Test_Problem1442(t *testing.T) { + + qs := []question1442{ + + { + para1442{[]int{2, 3, 1, 6, 7}}, + ans1442{4}, + }, + + { + para1442{[]int{1, 1, 1, 1, 1}}, + ans1442{10}, + }, + + { + para1442{[]int{2, 3}}, + ans1442{0}, + }, + + { + para1442{[]int{1, 3, 5, 7, 9}}, + ans1442{3}, + }, + + { + para1442{[]int{7, 11, 12, 9, 5, 2, 7, 17, 22}}, + ans1442{8}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 1442------------------------\n") + + for _, q := range qs { + _, p := q.ans1442, q.para1442 + fmt.Printf("【input】:%v 【output】:%v\n", p, countTriplets(p.arr)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/1442.Count-Triplets-That-Can-Form-Two-Arrays-of-Equal-XOR/README.md b/leetcode/1442.Count-Triplets-That-Can-Form-Two-Arrays-of-Equal-XOR/README.md new file mode 100644 index 000000000..4e45df7cf --- /dev/null +++ b/leetcode/1442.Count-Triplets-That-Can-Form-Two-Arrays-of-Equal-XOR/README.md @@ -0,0 +1,97 @@ +# [1442. Count Triplets That Can Form Two Arrays of Equal XOR](https://leetcode.com/problems/count-triplets-that-can-form-two-arrays-of-equal-xor/) + + +## 题目 + +Given an array of integers `arr`. + +We want to select three indices `i`, `j` and `k` where `(0 <= i < j <= k < arr.length)`. + +Let's define `a` and `b` as follows: + +- `a = arr[i] ^ arr[i + 1] ^ ... ^ arr[j - 1]` +- `b = arr[j] ^ arr[j + 1] ^ ... ^ arr[k]` + +Note that **^** denotes the **bitwise-xor** operation. + +Return *the number of triplets* (`i`, `j` and `k`) Where `a == b`. + +**Example 1:** + +``` +Input: arr = [2,3,1,6,7] +Output: 4 +Explanation: The triplets are (0,1,2), (0,2,2), (2,3,4) and (2,4,4) +``` + +**Example 2:** + +``` +Input: arr = [1,1,1,1,1] +Output: 10 +``` + +**Example 3:** + +``` +Input: arr = [2,3] +Output: 0 +``` + +**Example 4:** + +``` +Input: arr = [1,3,5,7,9] +Output: 3 +``` + +**Example 5:** + +``` +Input: arr = [7,11,12,9,5,2,7,17,22] +Output: 8 +``` + +**Constraints:** + +- `1 <= arr.length <= 300` +- `1 <= arr[i] <= 10^8` + +## 题目大意 + +给你一个整数数组 arr 。现需要从数组中取三个下标 i、j 和 k ，其中 (0 <= i < j <= k < arr.length) 。a 和 b 定义如下： + +- a = arr[i] ^ arr[i + 1] ^ ... ^ arr[j - 1] +- b = arr[j] ^ arr[j + 1] ^ ... ^ arr[k] + +注意：^ 表示 按位异或 操作。请返回能够令 a == b 成立的三元组 (i, j , k) 的数目。 + +## 解题思路 + +- 这一题需要用到 `x^x = 0` 这个异或特性。题目要求 `a == b`，可以等效转化为 `arr[i] ^ arr[i + 1] ^ ... ^ arr[j - 1] ^ arr[j] ^ arr[j + 1] ^ ... ^ arr[k] = 0`，这样 j 相当于可以“忽略”，专注找到所有元素异或结果为 0 的区间 [i,k] 即为答案。利用前缀和的思想，只不过此题非累加和，而是异或。又由 `x^x = 0` 这个异或特性，相同部分异或相当于消除，于是有 `prefix[i,k] = prefix[0,k] ^ prefix[0,i-1]`，找到每一个 `prefix[i,k] = 0` 的 i，k 组合，i < j <= k，那么满足条件的三元组 (i,j,k) 的个数完全取决于 j 的取值范围，(因为 i 和 k 已经固定了)，j 的取值范围为 k-i，所以累加所有满足条件的 k-i，输出即为最终答案。 + +## 代码 + +```go +package leetcode + +func countTriplets(arr []int) int { + prefix, num, count, total := make([]int, len(arr)), 0, 0, 0 + for i, v := range arr { + num ^= v + prefix[i] = num + } + for i := 0; i < len(prefix)-1; i++ { + for k := i + 1; k < len(prefix); k++ { + total = prefix[k] + if i > 0 { + total ^= prefix[i-1] + } + if total == 0 { + count += k - i + } + } + } + return count +} +``` \ No newline at end of file diff --git a/leetcode/1446.Consecutive-Characters/1446.Consecutive Characters.go b/leetcode/1446.Consecutive-Characters/1446.Consecutive Characters.go new file mode 100644 index 000000000..9da00e7c0 --- /dev/null +++ b/leetcode/1446.Consecutive-Characters/1446.Consecutive Characters.go @@ -0,0 +1,20 @@ +package leetcode + +func maxPower(s string) int { + cur, cnt, ans := s[0], 1, 1 + for i := 1; i < len(s); i++ { + if cur == s[i] { + cnt++ + } else { + if cnt > ans { + ans = cnt + } + cur = s[i] + cnt = 1 + } + } + if cnt > ans { + ans = cnt + } + return ans +} diff --git a/leetcode/1446.Consecutive-Characters/1446.Consecutive Characters_test.go b/leetcode/1446.Consecutive-Characters/1446.Consecutive Characters_test.go new file mode 100644 index 000000000..d191126ec --- /dev/null +++ b/leetcode/1446.Consecutive-Characters/1446.Consecutive Characters_test.go @@ -0,0 +1,60 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question1446 struct { + para1446 + ans1446 +} + +// para 是参数 +type para1446 struct { + s string +} + +// ans 是答案 +type ans1446 struct { + ans int +} + +func Test_Problem1446(t *testing.T) { + + qs := []question1446{ + + { + para1446{"leetcode"}, + ans1446{2}, + }, + + { + para1446{"abbcccddddeeeeedcba"}, + ans1446{5}, + }, + + { + para1446{"triplepillooooow"}, + ans1446{5}, + }, + + { + para1446{"hooraaaaaaaaaaay"}, + ans1446{11}, + }, + + { + para1446{"tourist"}, + ans1446{1}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 1446------------------------\n") + + for _, q := range qs { + _, p := q.ans1446, q.para1446 + fmt.Printf("【input】:%v 【output】:%v\n", p.s, maxPower(p.s)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/1446.Consecutive-Characters/README.md b/leetcode/1446.Consecutive-Characters/README.md new file mode 100644 index 000000000..78a6527af --- /dev/null +++ b/leetcode/1446.Consecutive-Characters/README.md @@ -0,0 +1,75 @@ +# [1446. Consecutive Characters](https://leetcode.com/problems/consecutive-characters/) + +## 题目 + +The power of the string is the maximum length of a non-empty substring that contains only one unique character. + +Given a string s, return the power of s. + +**Example 1**: + + Input: s = "leetcode" + Output: 2 + Explanation: The substring "ee" is of length 2 with the character 'e' only. + +**Example 2**: + + Input: s = "abbcccddddeeeeedcba" + Output: 5 + Explanation: The substring "eeeee" is of length 5 with the character 'e' only. + +**Example 3**: + + Input: s = "triplepillooooow" + Output: 5 + +**Example 4**: + + Input: s = "hooraaaaaaaaaaay" + Output: 11 + +**Example 5**: + + Input: s = "tourist" + Output: 1 + +**Constraints:** + +- 1 <= s.length <= 500 +- s consists of only lowercase English letters. + +## 题目大意 + +给你一个字符串 s ，字符串的「能量」定义为：只包含一种字符的最长非空子字符串的长度。 + +请你返回字符串的能量。 + +## 解题思路 + +- 顺序遍历进行统计 + +## 代码 + +```go +package leetcode + +func maxPower(s string) int { + cur, cnt, ans := s[0], 1, 1 + for i := 1; i < len(s); i++ { + if cur == s[i] { + cnt++ + } else { + if cnt > ans { + ans = cnt + } + cur = s[i] + cnt = 1 + } + } + if cnt > ans { + ans = cnt + } + return ans +} + +``` \ No newline at end of file diff --git a/leetcode/1465.Maximum-Area-of-a-Piece-of-Cake-After-Horizontal-and-Vertical-Cuts/1465. Maximum Area of a Piece of Cake After Horizontal and Vertical Cuts.go b/leetcode/1465.Maximum-Area-of-a-Piece-of-Cake-After-Horizontal-and-Vertical-Cuts/1465. Maximum Area of a Piece of Cake After Horizontal and Vertical Cuts.go new file mode 100644 index 000000000..d6a29607c --- /dev/null +++ b/leetcode/1465.Maximum-Area-of-a-Piece-of-Cake-After-Horizontal-and-Vertical-Cuts/1465. Maximum Area of a Piece of Cake After Horizontal and Vertical Cuts.go @@ -0,0 +1,26 @@ +package leetcode + +import "sort" + +func maxArea(h int, w int, horizontalCuts []int, verticalCuts []int) int { + sort.Ints(horizontalCuts) + sort.Ints(verticalCuts) + maxw, maxl := horizontalCuts[0], verticalCuts[0] + for i, c := range horizontalCuts[1:] { + if c-horizontalCuts[i] > maxw { + maxw = c - horizontalCuts[i] + } + } + if h-horizontalCuts[len(horizontalCuts)-1] > maxw { + maxw = h - horizontalCuts[len(horizontalCuts)-1] + } + for i, c := range verticalCuts[1:] { + if c-verticalCuts[i] > maxl { + maxl = c - verticalCuts[i] + } + } + if w-verticalCuts[len(verticalCuts)-1] > maxl { + maxl = w - verticalCuts[len(verticalCuts)-1] + } + return (maxw * maxl) % (1000000007) +} diff --git a/leetcode/1465.Maximum-Area-of-a-Piece-of-Cake-After-Horizontal-and-Vertical-Cuts/1465. Maximum Area of a Piece of Cake After Horizontal and Vertical Cuts_test.go b/leetcode/1465.Maximum-Area-of-a-Piece-of-Cake-After-Horizontal-and-Vertical-Cuts/1465. Maximum Area of a Piece of Cake After Horizontal and Vertical Cuts_test.go new file mode 100644 index 000000000..b6caabf3a --- /dev/null +++ b/leetcode/1465.Maximum-Area-of-a-Piece-of-Cake-After-Horizontal-and-Vertical-Cuts/1465. Maximum Area of a Piece of Cake After Horizontal and Vertical Cuts_test.go @@ -0,0 +1,55 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question1465 struct { + para1465 + ans1465 +} + +// para 是参数 +// one 代表第一个参数 +type para1465 struct { + h int + w int + horizontalCuts []int + verticalCuts []int +} + +// ans 是答案 +// one 代表第一个答案 +type ans1465 struct { + one int +} + +func Test_Problem1465(t *testing.T) { + + qs := []question1465{ + + { + para1465{5, 4, []int{1, 2, 4}, []int{1, 3}}, + ans1465{4}, + }, + + { + para1465{5, 4, []int{3, 1}, []int{1}}, + ans1465{6}, + }, + + { + para1465{5, 4, []int{3}, []int{3}}, + ans1465{9}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 1465------------------------\n") + + for _, q := range qs { + _, p := q.ans1465, q.para1465 + fmt.Printf("【input】:%v 【output】:%v \n", p, maxArea(p.h, p.w, p.horizontalCuts, p.verticalCuts)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/1465.Maximum-Area-of-a-Piece-of-Cake-After-Horizontal-and-Vertical-Cuts/README.md b/leetcode/1465.Maximum-Area-of-a-Piece-of-Cake-After-Horizontal-and-Vertical-Cuts/README.md new file mode 100644 index 000000000..8926b1776 --- /dev/null +++ b/leetcode/1465.Maximum-Area-of-a-Piece-of-Cake-After-Horizontal-and-Vertical-Cuts/README.md @@ -0,0 +1,89 @@ +# [1465. Maximum Area of a Piece of Cake After Horizontal and Vertical Cuts](https://leetcode.com/problems/maximum-area-of-a-piece-of-cake-after-horizontal-and-vertical-cuts/) + + +## 题目 + +Given a rectangular cake with height `h` and width `w`, and two arrays of integers `horizontalCuts` and `verticalCuts` where `horizontalCuts[i]` is the distance from the top of the rectangular cake to the `ith` horizontal cut and similarly, `verticalCuts[j]` is the distance from the left of the rectangular cake to the `jth` vertical cut. + +*Return the maximum area of a piece of cake after you cut at each horizontal and vertical position provided in the arrays `horizontalCuts` and `verticalCuts`.* Since the answer can be a huge number, return this modulo 10^9 + 7. + +**Example 1:** + +![https://assets.leetcode.com/uploads/2020/05/14/leetcode_max_area_2.png](https://assets.leetcode.com/uploads/2020/05/14/leetcode_max_area_2.png) + +``` +Input: h = 5, w = 4, horizontalCuts = [1,2,4], verticalCuts = [1,3] +Output: 4 +Explanation: The figure above represents the given rectangular cake. Red lines are the horizontal and vertical cuts. After you cut the cake, the green piece of cake has the maximum area. + +``` + +**Example 2:** + +![https://assets.leetcode.com/uploads/2020/05/14/leetcode_max_area_3.png](https://assets.leetcode.com/uploads/2020/05/14/leetcode_max_area_3.png) + +``` +Input: h = 5, w = 4, horizontalCuts = [3,1], verticalCuts = [1] +Output: 6 +Explanation: The figure above represents the given rectangular cake. Red lines are the horizontal and vertical cuts. After you cut the cake, the green and yellow pieces of cake have the maximum area. + +``` + +**Example 3:** + +``` +Input: h = 5, w = 4, horizontalCuts = [3], verticalCuts = [3] +Output: 9 + +``` + +**Constraints:** + +- `2 <= h, w <= 10^9` +- `1 <= horizontalCuts.length < min(h, 10^5)` +- `1 <= verticalCuts.length < min(w, 10^5)` +- `1 <= horizontalCuts[i] < h` +- `1 <= verticalCuts[i] < w` +- It is guaranteed that all elements in `horizontalCuts` are distinct. +- It is guaranteed that all elements in `verticalCuts` are distinct. + +## 题目大意 + +矩形蛋糕的高度为 h 且宽度为 w，给你两个整数数组 horizontalCuts 和 verticalCuts，其中 horizontalCuts[i] 是从矩形蛋糕顶部到第  i 个水平切口的距离，类似地， verticalCuts[j] 是从矩形蛋糕的左侧到第 j 个竖直切口的距离。请你按数组 horizontalCuts 和 verticalCuts 中提供的水平和竖直位置切割后，请你找出 面积最大 的那份蛋糕，并返回其 面积 。由于答案可能是一个很大的数字，因此需要将结果对 10^9 + 7 取余后返回。 + +## 解题思路 + +- 读完题比较容易想到解题思路。找到水平切口最大的差值和竖直切口最大的差值，这 4 条边构成的矩形即为最大矩形。不过有特殊情况需要判断，切口除了题目给的切口坐标以外，默认还有 4 个切口，即蛋糕原始的 4 条边。如下图二，最大的矩形其实在切口之外。所以找水平切口最大差值和竖直切口最大差值需要考虑到蛋糕原始的 4 条边。 + +![https://img.halfrost.com/Leetcode/leetcode_1465.png](https://img.halfrost.com/Leetcode/leetcode_1465.png) + +## 代码 + +```go +package leetcode + +import "sort" + +func maxArea(h int, w int, hcuts []int, vcuts []int) int { + sort.Ints(hcuts) + sort.Ints(vcuts) + maxw, maxl := hcuts[0], vcuts[0] + for i, c := range hcuts[1:] { + if c-hcuts[i] > maxw { + maxw = c - hcuts[i] + } + } + if h-hcuts[len(hcuts)-1] > maxw { + maxw = h - hcuts[len(hcuts)-1] + } + for i, c := range vcuts[1:] { + if c-vcuts[i] > maxl { + maxl = c - vcuts[i] + } + } + if w-vcuts[len(vcuts)-1] > maxl { + maxl = w - vcuts[len(vcuts)-1] + } + return (maxw * maxl) % (1000000007) +} +``` \ No newline at end of file diff --git a/leetcode/1482.Minimum-Number-of-Days-to-Make-m-Bouquets/1482. Minimum Number of Days to Make m Bouquets.go b/leetcode/1482.Minimum-Number-of-Days-to-Make-m-Bouquets/1482. Minimum Number of Days to Make m Bouquets.go new file mode 100644 index 000000000..759e93542 --- /dev/null +++ b/leetcode/1482.Minimum-Number-of-Days-to-Make-m-Bouquets/1482. Minimum Number of Days to Make m Bouquets.go @@ -0,0 +1,30 @@ +package leetcode + +import "sort" + +func minDays(bloomDay []int, m int, k int) int { + if m*k > len(bloomDay) { + return -1 + } + maxDay := 0 + for _, day := range bloomDay { + if day > maxDay { + maxDay = day + } + } + return sort.Search(maxDay, func(days int) bool { + flowers, bouquets := 0, 0 + for _, d := range bloomDay { + if d > days { + flowers = 0 + } else { + flowers++ + if flowers == k { + bouquets++ + flowers = 0 + } + } + } + return bouquets >= m + }) +} diff --git a/leetcode/1482.Minimum-Number-of-Days-to-Make-m-Bouquets/1482. Minimum Number of Days to Make m Bouquets_test.go b/leetcode/1482.Minimum-Number-of-Days-to-Make-m-Bouquets/1482. Minimum Number of Days to Make m Bouquets_test.go new file mode 100644 index 000000000..e505095f1 --- /dev/null +++ b/leetcode/1482.Minimum-Number-of-Days-to-Make-m-Bouquets/1482. Minimum Number of Days to Make m Bouquets_test.go @@ -0,0 +1,64 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question1482 struct { + para1482 + ans1482 +} + +// para 是参数 +// one 代表第一个参数 +type para1482 struct { + bloomDay []int + m int + k int +} + +// ans 是答案 +// one 代表第一个答案 +type ans1482 struct { + one int +} + +func Test_Problem1482(t *testing.T) { + + qs := []question1482{ + + { + para1482{[]int{1, 10, 3, 10, 2}, 3, 1}, + ans1482{3}, + }, + + { + para1482{[]int{1, 10, 3, 10, 2}, 3, 2}, + ans1482{-1}, + }, + + { + para1482{[]int{7, 7, 7, 7, 12, 7, 7}, 2, 3}, + ans1482{12}, + }, + + { + para1482{[]int{1000000000, 1000000000}, 1, 1}, + ans1482{1000000000}, + }, + + { + para1482{[]int{1, 10, 2, 9, 3, 8, 4, 7, 5, 6}, 4, 2}, + ans1482{9}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 1482------------------------\n") + + for _, q := range qs { + _, p := q.ans1482, q.para1482 + fmt.Printf("【input】:%v 【output】:%v \n", p, minDays(p.bloomDay, p.m, p.k)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/1482.Minimum-Number-of-Days-to-Make-m-Bouquets/README.md b/leetcode/1482.Minimum-Number-of-Days-to-Make-m-Bouquets/README.md new file mode 100644 index 000000000..b7d691d38 --- /dev/null +++ b/leetcode/1482.Minimum-Number-of-Days-to-Make-m-Bouquets/README.md @@ -0,0 +1,110 @@ +# [1482. Minimum Number of Days to Make m Bouquets](https://leetcode.com/problems/minimum-number-of-days-to-make-m-bouquets/) + +## 题目 + +Given an integer array `bloomDay`, an integer `m` and an integer `k`. + +We need to make `m` bouquets. To make a bouquet, you need to use `k` **adjacent flowers** from the garden. + +The garden consists of `n` flowers, the `ith` flower will bloom in the `bloomDay[i]` and then can be used in **exactly one** bouquet. + +Return *the minimum number of days* you need to wait to be able to make `m` bouquets from the garden. If it is impossible to make `m` bouquets return **-1**. + +**Example 1:** + +``` +Input: bloomDay = [1,10,3,10,2], m = 3, k = 1 +Output: 3 +Explanation: Let's see what happened in the first three days. x means flower bloomed and _ means flower didn't bloom in the garden. +We need 3 bouquets each should contain 1 flower. +After day 1: [x, _, _, _, _] // we can only make one bouquet. +After day 2: [x, _, _, _, x] // we can only make two bouquets. +After day 3: [x, _, x, _, x] // we can make 3 bouquets. The answer is 3. +``` + +**Example 2:** + +``` +Input: bloomDay = [1,10,3,10,2], m = 3, k = 2 +Output: -1 +Explanation: We need 3 bouquets each has 2 flowers, that means we need 6 flowers. We only have 5 flowers so it is impossible to get the needed bouquets and we return -1. +``` + +**Example 3:** + +``` +Input: bloomDay = [7,7,7,7,12,7,7], m = 2, k = 3 +Output: 12 +Explanation: We need 2 bouquets each should have 3 flowers. +Here's the garden after the 7 and 12 days: +After day 7: [x, x, x, x, _, x, x] +We can make one bouquet of the first three flowers that bloomed. We cannot make another bouquet from the last three flowers that bloomed because they are not adjacent. +After day 12: [x, x, x, x, x, x, x] +It is obvious that we can make two bouquets in different ways. +``` + +**Example 4:** + +``` +Input: bloomDay = [1000000000,1000000000], m = 1, k = 1 +Output: 1000000000 +Explanation: You need to wait 1000000000 days to have a flower ready for a bouquet. +``` + +**Example 5:** + +``` +Input: bloomDay = [1,10,2,9,3,8,4,7,5,6], m = 4, k = 2 +Output: 9 +``` + +**Constraints:** + +- `bloomDay.length == n` +- `1 <= n <= 10^5` +- `1 <= bloomDay[i] <= 10^9` +- `1 <= m <= 10^6` +- `1 <= k <= n` + +## 题目大意 + +给你一个整数数组 bloomDay，以及两个整数 m 和 k 。现需要制作 m 束花。制作花束时，需要使用花园中 相邻的 k 朵花 。花园中有 n 朵花，第 i 朵花会在 bloomDay[i] 时盛开，恰好 可以用于 一束 花中。请你返回从花园中摘 m 束花需要等待的最少的天数。如果不能摘到 m 束花则返回 -1 。 + +## 解题思路 + +- 本题是二分搜索提醒。题目解空间固定，答案区间一定在 [0, maxDay] 中。这是单调增且有序区间，所以可以在这个解空间内使用二分搜索。在区间 [0, maxDay] 中找到第一个能满足 m 束花的解。二分搜索判断是否为 true 的条件为：从左往右遍历数组，依次统计当前日期下，花是否开了，如果连续开花 k 朵，便为 1 束，数组遍历结束如果花束总数 ≥ k 即为答案。二分搜索会返回最小的下标，即对应满足题意的最少天数。 + +## 代码 + +```go +package leetcode + +import "sort" + +func minDays(bloomDay []int, m int, k int) int { + if m*k > len(bloomDay) { + return -1 + } + maxDay := 0 + for _, day := range bloomDay { + if day > maxDay { + maxDay = day + } + } + return sort.Search(maxDay, func(days int) bool { + flowers, bouquets := 0, 0 + for _, d := range bloomDay { + if d > days { + flowers = 0 + } else { + flowers++ + if flowers == k { + bouquets++ + flowers = 0 + } + } + } + return bouquets >= m + }) +} +``` \ No newline at end of file diff --git a/leetcode/1486.XOR-Operation-in-an-Array/1486. XOR Operation in an Array.go b/leetcode/1486.XOR-Operation-in-an-Array/1486. XOR Operation in an Array.go new file mode 100644 index 000000000..a9040341d --- /dev/null +++ b/leetcode/1486.XOR-Operation-in-an-Array/1486. XOR Operation in an Array.go @@ -0,0 +1,9 @@ +package leetcode + +func xorOperation(n int, start int) int { + res := 0 + for i := 0; i < n; i++ { + res ^= start + 2*i + } + return res +} diff --git a/leetcode/1486.XOR-Operation-in-an-Array/1486. XOR Operation in an Array_test.go b/leetcode/1486.XOR-Operation-in-an-Array/1486. XOR Operation in an Array_test.go new file mode 100644 index 000000000..e1887c155 --- /dev/null +++ b/leetcode/1486.XOR-Operation-in-an-Array/1486. XOR Operation in an Array_test.go @@ -0,0 +1,58 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question1486 struct { + para1486 + ans1486 +} + +// para 是参数 +// one 代表第一个参数 +type para1486 struct { + n int + start int +} + +// ans 是答案 +// one 代表第一个答案 +type ans1486 struct { + one int +} + +func Test_Problem1486(t *testing.T) { + + qs := []question1486{ + + { + para1486{5, 0}, + ans1486{8}, + }, + + { + para1486{4, 3}, + ans1486{8}, + }, + + { + para1486{1, 7}, + ans1486{7}, + }, + + { + para1486{10, 5}, + ans1486{2}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 1486------------------------\n") + + for _, q := range qs { + _, p := q.ans1486, q.para1486 + fmt.Printf("【input】:%v 【output】:%v \n", p, xorOperation(p.n, p.start)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/1486.XOR-Operation-in-an-Array/README.md b/leetcode/1486.XOR-Operation-in-an-Array/README.md new file mode 100644 index 000000000..3a6438de8 --- /dev/null +++ b/leetcode/1486.XOR-Operation-in-an-Array/README.md @@ -0,0 +1,69 @@ +# [1486. XOR Operation in an Array](https://leetcode.com/problems/xor-operation-in-an-array/) + + +## 题目 + +Given an integer `n` and an integer `start`. + +Define an array `nums` where `nums[i] = start + 2*i` (0-indexed) and `n == nums.length`. + +Return the bitwise XOR of all elements of `nums`. + +**Example 1:** + +``` +Input: n = 5, start = 0 +Output: 8 +Explanation:Array nums is equal to [0, 2, 4, 6, 8] where (0 ^ 2 ^ 4 ^ 6 ^ 8) = 8. +Where "^" corresponds to bitwise XOR operator. +``` + +**Example 2:** + +``` +Input: n = 4, start = 3 +Output: 8 +Explanation:Array nums is equal to [3, 5, 7, 9] where (3 ^ 5 ^ 7 ^ 9) = 8. +``` + +**Example 3:** + +``` +Input: n = 1, start = 7 +Output: 7 +``` + +**Example 4:** + +``` +Input: n = 10, start = 5 +Output: 2 +``` + +**Constraints:** + +- `1 <= n <= 1000` +- `0 <= start <= 1000` +- `n == nums.length` + +## 题目大意 + +给你两个整数，n 和 start 。数组 nums 定义为：nums[i] = start + 2*i（下标从 0 开始）且 n == nums.length 。请返回 nums 中所有元素按位异或（XOR）后得到的结果。 + +## 解题思路 + +- 简单题。按照题意，一层循环依次累积异或数组中每个元素。 + +## 代码 + +```go +package leetcode + +func xorOperation(n int, start int) int { + res := 0 + for i := 0; i < n; i++ { + res ^= start + 2*i + } + return res +} +``` \ No newline at end of file diff --git a/leetcode/1518.Water-Bottles/1518.Water Bottles.go b/leetcode/1518.Water-Bottles/1518.Water Bottles.go new file mode 100644 index 000000000..987c6b86b --- /dev/null +++ b/leetcode/1518.Water-Bottles/1518.Water Bottles.go @@ -0,0 +1,15 @@ +package leetcode + +func numWaterBottles(numBottles int, numExchange int) int { + if numBottles < numExchange { + return numBottles + } + quotient := numBottles / numExchange + reminder := numBottles % numExchange + ans := numBottles + quotient + for quotient+reminder >= numExchange { + quotient, reminder = (quotient+reminder)/numExchange, (quotient+reminder)%numExchange + ans += quotient + } + return ans +} diff --git a/leetcode/1518.Water-Bottles/1518.Water Bottles_test.go b/leetcode/1518.Water-Bottles/1518.Water Bottles_test.go new file mode 100644 index 000000000..20c2a18d7 --- /dev/null +++ b/leetcode/1518.Water-Bottles/1518.Water Bottles_test.go @@ -0,0 +1,56 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question1518 struct { + para1518 + ans1518 +} + +// para 是参数 +type para1518 struct { + numBottles int + numExchange int +} + +// ans 是答案 +type ans1518 struct { + ans int +} + +func Test_Problem1518(t *testing.T) { + + qs := []question1518{ + + { + para1518{9, 3}, + ans1518{13}, + }, + + { + para1518{15, 4}, + ans1518{19}, + }, + + { + para1518{5, 5}, + ans1518{6}, + }, + + { + para1518{2, 3}, + ans1518{2}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 1518------------------------\n") + + for _, q := range qs { + _, p := q.ans1518, q.para1518 + fmt.Printf("【input】:%v 【output】:%v\n", p, numWaterBottles(p.numBottles, p.numExchange)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/1518.Water-Bottles/README.md b/leetcode/1518.Water-Bottles/README.md new file mode 100644 index 000000000..3f05e1815 --- /dev/null +++ b/leetcode/1518.Water-Bottles/README.md @@ -0,0 +1,74 @@ +# [1518. Water Bottles](https://leetcode.com/problems/water-bottles/) + +## 题目 + +Given numBottles full water bottles, you can exchange numExchange empty water bottles for one full water bottle. + +The operation of drinking a full water bottle turns it into an empty bottle. + +Return the maximum number of water bottles you can drink. + +**Example 1**: + +![https://assets.leetcode.com/uploads/2020/07/01/sample_1_1875.png](https://assets.leetcode.com/uploads/2020/07/01/sample_1_1875.png) + + Input: numBottles = 9, numExchange = 3 + Output: 13 + Explanation: You can exchange 3 empty bottles to get 1 full water bottle. + Number of water bottles you can drink: 9 + 3 + 1 = 13. + +**Example 2**: + +![https://assets.leetcode.com/uploads/2020/07/01/sample_2_1875.png](https://assets.leetcode.com/uploads/2020/07/01/sample_2_1875.png) + + Input: numBottles = 15, numExchange = 4 + Output: 19 + Explanation: You can exchange 4 empty bottles to get 1 full water bottle. + Number of water bottles you can drink: 15 + 3 + 1 = 19. + +**Example 3**: + + Input: numBottles = 5, numExchange = 5 + Output: 6 + +**Example 4**: + + Input: numBottles = 2, numExchange = 3 + Output: 2 + +**Constraints:** + +- 1 <= numBottles <= 100 +- 2 <= numExchange <= 100 + +## 题目大意 + +小区便利店正在促销，用 numExchange 个空酒瓶可以兑换一瓶新酒。你购入了 numBottles 瓶酒。 + +如果喝掉了酒瓶中的酒，那么酒瓶就会变成空的。 + +请你计算 最多 能喝到多少瓶酒。 + +## 解题思路 + +- 模拟。首先我们一定可以喝到 numBottles 瓶酒，剩下 numBottles 个空瓶。接下来我们可以拿空瓶子换酒，每次拿出 numExchange 个瓶子换一瓶酒，然后再喝完这瓶酒，得到一个空瓶。这样模拟下去，直到所有的空瓶子小于numExchange结束。 + +## 代码 + +```go +package leetcode + +func numWaterBottles(numBottles int, numExchange int) int { + if numBottles < numExchange { + return numBottles + } + quotient := numBottles / numExchange + reminder := numBottles % numExchange + ans := numBottles + quotient + for quotient+reminder >= numExchange { + quotient, reminder = (quotient+reminder)/numExchange, (quotient+reminder)%numExchange + ans += quotient + } + return ans +} +``` \ No newline at end of file diff --git a/leetcode/1572.Matrix-Diagonal-Sum/1572.Matrix Diagonal Sum.go b/leetcode/1572.Matrix-Diagonal-Sum/1572.Matrix Diagonal Sum.go new file mode 100644 index 000000000..4f1756a33 --- /dev/null +++ b/leetcode/1572.Matrix-Diagonal-Sum/1572.Matrix Diagonal Sum.go @@ -0,0 +1,16 @@ +package leetcode + +func diagonalSum(mat [][]int) int { + n := len(mat) + ans := 0 + for pi := 0; pi < n; pi++ { + ans += mat[pi][pi] + } + for si, sj := n-1, 0; sj < n; si, sj = si-1, sj+1 { + ans += mat[si][sj] + } + if n%2 == 0 { + return ans + } + return ans - mat[n/2][n/2] +} diff --git a/leetcode/1572.Matrix-Diagonal-Sum/1572.Matrix Diagonal Sum_test.go b/leetcode/1572.Matrix-Diagonal-Sum/1572.Matrix Diagonal Sum_test.go new file mode 100644 index 000000000..c658de147 --- /dev/null +++ b/leetcode/1572.Matrix-Diagonal-Sum/1572.Matrix Diagonal Sum_test.go @@ -0,0 +1,51 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question1572 struct { + para1572 + ans1572 +} + +// para 是参数 +type para1572 struct { + mat [][]int +} + +// ans 是答案 +// one 代表第一个答案 +type ans1572 struct { + one int +} + +func Test_Problem1572(t *testing.T) { + + qs := []question1572{ + + { + para1572{[][]int{{1, 2, 3}, {4, 5, 6}, {7, 8, 9}}}, + ans1572{25}, + }, + + { + para1572{[][]int{{1, 1, 1, 1}, {1, 1, 1, 1}, {1, 1, 1, 1}, {1, 1, 1, 1}}}, + ans1572{8}, + }, + + { + para1572{[][]int{{5}}}, + ans1572{5}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 1572------------------------\n") + + for _, q := range qs { + _, p := q.ans1572, q.para1572 + fmt.Printf("【input】:%v 【output】:%v \n", p, diagonalSum(p.mat)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/1572.Matrix-Diagonal-Sum/README.md b/leetcode/1572.Matrix-Diagonal-Sum/README.md new file mode 100644 index 000000000..697aef7ee --- /dev/null +++ b/leetcode/1572.Matrix-Diagonal-Sum/README.md @@ -0,0 +1,77 @@ +# [1572. Matrix Diagonal Sum](https://leetcode.com/problems/matrix-diagonal-sum/) + + +## 题目 + +Given a square matrix `mat`, return the sum of the matrix diagonals. + +Only include the sum of all the elements on the primary diagonal and all the elements on the secondary diagonal that are not part of the primary diagonal. + +**Example 1:** + +![https://assets.leetcode.com/uploads/2020/08/14/sample_1911.png](https://assets.leetcode.com/uploads/2020/08/14/sample_1911.png) + +``` +Input: mat = [[1,2,3], +  [4,5,6], +  [7,8,9]] +Output: 25 +Explanation:Diagonals sum: 1 + 5 + 9 + 3 + 7 = 25 +Notice that element mat[1][1] = 5 is counted only once. + +``` + +**Example 2:** + +``` +Input: mat = [[1,1,1,1], +  [1,1,1,1], +  [1,1,1,1], +  [1,1,1,1]] +Output: 8 + +``` + +**Example 3:** + +``` +Input: mat = [[5]] +Output: 5 + +``` + +**Constraints:** + +- `n == mat.length == mat[i].length` +- `1 <= n <= 100` +- `1 <= mat[i][j] <= 100` + +## 题目大意 + +给你一个正方形矩阵 mat，请你返回矩阵对角线元素的和。请你返回在矩阵主对角线上的元素和副对角线上且不在主对角线上元素的和。 + +## 解题思路 + +- 简单题。根据题意，把主对角线和副对角线上的元素相加。 +- 如果正方形矩阵的长度 n 为奇数，相加的结果需要减去 mat[n/2][n/2]。 + +## 代码 + +```go +package leetcode + +func diagonalSum(mat [][]int) int { + n := len(mat) + ans := 0 + for pi := 0; pi < n; pi++ { + ans += mat[pi][pi] + } + for si, sj := n-1, 0; sj < n; si, sj = si-1, sj+1 { + ans += mat[si][sj] + } + if n%2 == 0 { + return ans + } + return ans - mat[n/2][n/2] +} +``` \ No newline at end of file diff --git a/leetcode/1576.Replace-All-s-to-Avoid-Consecutive-Repeating-Characters/1576. Replace-All-s-to-Avoid-Consecutive-Repeating-Characters.go b/leetcode/1576.Replace-All-s-to-Avoid-Consecutive-Repeating-Characters/1576. Replace-All-s-to-Avoid-Consecutive-Repeating-Characters.go new file mode 100644 index 000000000..1e1f287d0 --- /dev/null +++ b/leetcode/1576.Replace-All-s-to-Avoid-Consecutive-Repeating-Characters/1576. Replace-All-s-to-Avoid-Consecutive-Repeating-Characters.go @@ -0,0 +1,16 @@ +package leetcode + +func modifyString(s string) string { + res := []byte(s) + for i, ch := range res { + if ch == '?' { + for b := byte('a'); b <= 'z'; b++ { + if !(i > 0 && res[i-1] == b || i < len(res)-1 && res[i+1] == b) { + res[i] = b + break + } + } + } + } + return string(res) +} diff --git a/leetcode/1576.Replace-All-s-to-Avoid-Consecutive-Repeating-Characters/1576. Replace-All-s-to-Avoid-Consecutive-Repeating-Characters_test.go b/leetcode/1576.Replace-All-s-to-Avoid-Consecutive-Repeating-Characters/1576. Replace-All-s-to-Avoid-Consecutive-Repeating-Characters_test.go new file mode 100644 index 000000000..9513b182c --- /dev/null +++ b/leetcode/1576.Replace-All-s-to-Avoid-Consecutive-Repeating-Characters/1576. Replace-All-s-to-Avoid-Consecutive-Repeating-Characters_test.go @@ -0,0 +1,47 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question1576 struct { + para1576 + ans1576 +} + +// para 是参数 +// one 代表第一个参数 +type para1576 struct { + s string +} + +// ans 是答案 +// one 代表第一个答案 +type ans1576 struct { + one string +} + +func Test_Problem1576(t *testing.T) { + + qs := []question1576{ + + { + para1576{"?zs"}, + ans1576{"azs"}, + }, + + { + para1576{"ubv?w"}, + ans1576{"ubvaw"}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 1576------------------------\n") + + for _, q := range qs { + _, p := q.ans1576, q.para1576 + fmt.Printf("【input】:%v 【output】:%v \n", p, modifyString(p.s)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/1576.Replace-All-s-to-Avoid-Consecutive-Repeating-Characters/README.md b/leetcode/1576.Replace-All-s-to-Avoid-Consecutive-Repeating-Characters/README.md new file mode 100644 index 000000000..9d7a93b39 --- /dev/null +++ b/leetcode/1576.Replace-All-s-to-Avoid-Consecutive-Repeating-Characters/README.md @@ -0,0 +1,63 @@ +# [1576. Replace All ?'s to Avoid Consecutive Repeating Characters](https://leetcode.com/problems/replace-all-s-to-avoid-consecutive-repeating-characters/) + +## 题目 + +Given a string `s` containing only lowercase English letters and the `'?'` character, convert **all** the `'?'` characters into lowercase letters such that the final string does not contain any **consecutive repeating** characters. You **cannot** modify the non `'?'` characters. + +It is **guaranteed** that there are no consecutive repeating characters in the given string **except** for `'?'`. + +Return *the final string after all the conversions (possibly zero) have been made*. If there is more than one solution, return **any of them**. It can be shown that an answer is always possible with the given constraints. + +**Example 1:** + +``` +Input: s = "?zs" +Output: "azs" +Explanation: There are 25 solutions for this problem. From "azs" to "yzs", all are valid. Only "z" is an invalid modification as the string will consist of consecutive repeating characters in "zzs". + +``` + +**Example 2:** + +``` +Input: s = "ubv?w" +Output: "ubvaw" +Explanation: There are 24 solutions for this problem. Only "v" and "w" are invalid modifications as the strings will consist of consecutive repeating characters in "ubvvw" and "ubvww". + +``` + +**Constraints:** + +- `1 <= s.length <= 100` +- `s` consist of lowercase English letters and `'?'`. + +## 题目大意 + +给你一个仅包含小写英文字母和 '?' 字符的字符串 s，请你将所有的 '?' 转换为若干小写字母，使最终的字符串不包含任何 连续重复 的字符。注意：你 不能 修改非 '?' 字符。 + +题目测试用例保证 除 '?' 字符 之外，不存在连续重复的字符。在完成所有转换（可能无需转换）后返回最终的字符串。如果有多个解决方案，请返回其中任何一个。可以证明，在给定的约束条件下，答案总是存在的。 + +## 解题思路 + +- 简单题。找到源字符串中 ‘?’ 字符的位置，然后依次用 a ~ z 字符去替换，替换进去的字符不能和前后字符相同即可。 + +## 代码 + +```go +package leetcode + +func modifyString(s string) string { + res := []byte(s) + for i, ch := range res { + if ch == '?' { + for b := byte('a'); b <= 'z'; b++ { + if !(i > 0 && res[i-1] == b || i < len(res)-1 && res[i+1] == b) { + res[i] = b + break + } + } + } + } + return string(res) +} +``` \ No newline at end of file diff --git a/leetcode/1600.Throne-Inheritance/1600. Throne Inheritance.go b/leetcode/1600.Throne-Inheritance/1600. Throne Inheritance.go new file mode 100644 index 000000000..4ab87aff8 --- /dev/null +++ b/leetcode/1600.Throne-Inheritance/1600. Throne Inheritance.go @@ -0,0 +1,41 @@ +package leetcode + +type ThroneInheritance struct { + king string + edges map[string][]string + dead map[string]bool +} + +func Constructor(kingName string) (t ThroneInheritance) { + return ThroneInheritance{kingName, map[string][]string{}, map[string]bool{}} +} + +func (t *ThroneInheritance) Birth(parentName, childName string) { + t.edges[parentName] = append(t.edges[parentName], childName) +} + +func (t *ThroneInheritance) Death(name string) { + t.dead[name] = true +} + +func (t *ThroneInheritance) GetInheritanceOrder() (res []string) { + var preorder func(string) + preorder = func(name string) { + if !t.dead[name] { + res = append(res, name) + } + for _, childName := range t.edges[name] { + preorder(childName) + } + } + preorder(t.king) + return +} + +/** + * Your ThroneInheritance object will be instantiated and called as such: + * obj := Constructor(kingName); + * obj.Birth(parentName,childName); + * obj.Death(name); + * param_3 := obj.GetInheritanceOrder(); + */ diff --git a/leetcode/1600.Throne-Inheritance/1600. Throne Inheritance_test.go b/leetcode/1600.Throne-Inheritance/1600. Throne Inheritance_test.go new file mode 100644 index 000000000..2ce13f58a --- /dev/null +++ b/leetcode/1600.Throne-Inheritance/1600. Throne Inheritance_test.go @@ -0,0 +1,29 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +func Test_Problem1600(t *testing.T) { + obj := Constructor("king") + fmt.Printf("obj = %v\n", obj) + obj.Birth("king", "andy") + fmt.Printf("obj = %v\n", obj) + obj.Birth("king", "bob") + fmt.Printf("obj = %v\n", obj) + obj.Birth("king", "catherine") + fmt.Printf("obj = %v\n", obj) + obj.Birth("andy", "matthew") + fmt.Printf("obj = %v\n", obj) + obj.Birth("bob", "alex") + fmt.Printf("obj = %v\n", obj) + obj.Birth("bob", "asha") + fmt.Printf("obj = %v\n", obj) + param2 := obj.GetInheritanceOrder() + fmt.Printf("param_2 = %v obj = %v\n", param2, obj) + obj.Death("bob") + fmt.Printf("obj = %v\n", obj) + param2 = obj.GetInheritanceOrder() + fmt.Printf("param_2 = %v obj = %v\n", param2, obj) +} diff --git a/leetcode/1600.Throne-Inheritance/README.md b/leetcode/1600.Throne-Inheritance/README.md new file mode 100644 index 000000000..8e5ed385e --- /dev/null +++ b/leetcode/1600.Throne-Inheritance/README.md @@ -0,0 +1,120 @@ +# [1600. Throne Inheritance](https://leetcode.com/problems/throne-inheritance/) + + +## 题目 + +A kingdom consists of a king, his children, his grandchildren, and so on. Every once in a while, someone in the family dies or a child is born. + +The kingdom has a well-defined order of inheritance that consists of the king as the first member. Let's define the recursive function `Successor(x, curOrder)`, which given a person `x` and the inheritance order so far, returns who should be the next person after `x` in the order of inheritance. + +``` +Successor(x, curOrder): + if x has no children or all of x's children are in curOrder: + if x is the king return null + else return Successor(x's parent, curOrder) + else return x's oldest child who's not in curOrder +``` + +For example, assume we have a kingdom that consists of the king, his children Alice and Bob (Alice is older than Bob), and finally Alice's son Jack. + +1. In the beginning, `curOrder` will be `["king"]`. +2. Calling `Successor(king, curOrder)` will return Alice, so we append to `curOrder` to get `["king", "Alice"]`. +3. Calling `Successor(Alice, curOrder)` will return Jack, so we append to `curOrder` to get `["king", "Alice", "Jack"]`. +4. Calling `Successor(Jack, curOrder)` will return Bob, so we append to `curOrder` to get `["king", "Alice", "Jack", "Bob"]`. +5. Calling `Successor(Bob, curOrder)` will return `null`. Thus the order of inheritance will be `["king", "Alice", "Jack", "Bob"]`. + +Using the above function, we can always obtain a unique order of inheritance. + +Implement the `ThroneInheritance` class: + +- `ThroneInheritance(string kingName)` Initializes an object of the `ThroneInheritance` class. The name of the king is given as part of the constructor. +- `void birth(string parentName, string childName)` Indicates that `parentName` gave birth to `childName`. +- `void death(string name)` Indicates the death of `name`. The death of the person doesn't affect the `Successor` function nor the current inheritance order. You can treat it as just marking the person as dead. +- `string[] getInheritanceOrder()` Returns a list representing the current order of inheritance **excluding** dead people. + +**Example 1:** + +``` +Input +["ThroneInheritance", "birth", "birth", "birth", "birth", "birth", "birth", "getInheritanceOrder", "death", "getInheritanceOrder"] +[["king"], ["king", "andy"], ["king", "bob"], ["king", "catherine"], ["andy", "matthew"], ["bob", "alex"], ["bob", "asha"], [null], ["bob"], [null]] +Output +[null, null, null, null, null, null, null, ["king", "andy", "matthew", "bob", "alex", "asha", "catherine"], null, ["king", "andy", "matthew", "alex", "asha", "catherine"]] + +Explanation +ThroneInheritance t= new ThroneInheritance("king"); // order:king +t.birth("king", "andy"); // order: king >andy +t.birth("king", "bob"); // order: king > andy >bob +t.birth("king", "catherine"); // order: king > andy > bob >catherine +t.birth("andy", "matthew"); // order: king > andy >matthew > bob > catherine +t.birth("bob", "alex"); // order: king > andy > matthew > bob >alex > catherine +t.birth("bob", "asha"); // order: king > andy > matthew > bob > alex >asha > catherine +t.getInheritanceOrder(); // return ["king", "andy", "matthew", "bob", "alex", "asha", "catherine"] +t.death("bob"); // order: king > andy > matthew >bob > alex > asha > catherine +t.getInheritanceOrder(); // return ["king", "andy", "matthew", "alex", "asha", "catherine"] + +``` + +**Constraints:** + +- `1 <= kingName.length, parentName.length, childName.length, name.length <= 15` +- `kingName`, `parentName`, `childName`, and `name` consist of lowercase English letters only. +- All arguments `childName` and `kingName` are **distinct**. +- All `name` arguments of `death` will be passed to either the constructor or as `childName` to `birth` first. +- For each call to `birth(parentName, childName)`, it is guaranteed that `parentName` is alive. +- At most `105` calls will be made to `birth` and `death`. +- At most `10` calls will be made to `getInheritanceOrder`. + +## 题目大意 + +一个王国里住着国王、他的孩子们、他的孙子们等等。每一个时间点，这个家庭里有人出生也有人死亡。这个王国有一个明确规定的皇位继承顺序，第一继承人总是国王自己。我们定义递归函数 Successor(x, curOrder) ，给定一个人 x 和当前的继承顺序，该函数返回 x 的下一继承人。 + +## 解题思路 + +- 这道题思路不难。先将国王每个孩子按照顺序存在一个 map 中，然后每个国王的孩子还存在父子关系，同理也按顺序存在 map 中。执行 GetInheritanceOrder() 函数时，将国王的孩子按顺序遍历，如果每个孩子还有孩子，递归遍历到底。如果把继承关系看成一棵树，此题便是多叉树的先根遍历的问题。 + +## 代码 + +```go +package leetcode + +type ThroneInheritance struct { + king string + edges map[string][]string + dead map[string]bool +} + +func Constructor(kingName string) (t ThroneInheritance) { + return ThroneInheritance{kingName, map[string][]string{}, map[string]bool{}} +} + +func (t *ThroneInheritance) Birth(parentName, childName string) { + t.edges[parentName] = append(t.edges[parentName], childName) +} + +func (t *ThroneInheritance) Death(name string) { + t.dead[name] = true +} + +func (t *ThroneInheritance) GetInheritanceOrder() (res []string) { + var preorder func(string) + preorder = func(name string) { + if !t.dead[name] { + res = append(res, name) + } + for _, childName := range t.edges[name] { + preorder(childName) + } + } + preorder(t.king) + return +} + +/** + * Your ThroneInheritance object will be instantiated and called as such: + * obj := Constructor(kingName); + * obj.Birth(parentName,childName); + * obj.Death(name); + * param_3 := obj.GetInheritanceOrder(); + */ +``` \ No newline at end of file diff --git a/leetcode/1609.Even-Odd-Tree/1609.Even Odd Tree.go b/leetcode/1609.Even-Odd-Tree/1609.Even Odd Tree.go new file mode 100644 index 000000000..e48683a0b --- /dev/null +++ b/leetcode/1609.Even-Odd-Tree/1609.Even Odd Tree.go @@ -0,0 +1,72 @@ +package leetcode + +type TreeNode struct { + Val int + Left *TreeNode + Right *TreeNode +} + +func isEvenOddTree(root *TreeNode) bool { + level := 0 + queue := []*TreeNode{root} + for len(queue) != 0 { + length := len(queue) + var nums []int + for i := 0; i < length; i++ { + node := queue[i] + if node.Left != nil { + queue = append(queue, node.Left) + } + if node.Right != nil { + queue = append(queue, node.Right) + } + nums = append(nums, node.Val) + } + if level%2 == 0 { + if !even(nums) { + return false + } + } else { + if !odd(nums) { + return false + } + } + queue = queue[length:] + level++ + } + return true +} + +func odd(nums []int) bool { + cur := nums[0] + if cur%2 != 0 { + return false + } + for _, num := range nums[1:] { + if num >= cur { + return false + } + if num%2 != 0 { + return false + } + cur = num + } + return true +} + +func even(nums []int) bool { + cur := nums[0] + if cur%2 == 0 { + return false + } + for _, num := range nums[1:] { + if num <= cur { + return false + } + if num%2 == 0 { + return false + } + cur = num + } + return true +} diff --git a/leetcode/1609.Even-Odd-Tree/1609.Even Odd Tree_test.go b/leetcode/1609.Even-Odd-Tree/1609.Even Odd Tree_test.go new file mode 100644 index 000000000..6ac31fbc5 --- /dev/null +++ b/leetcode/1609.Even-Odd-Tree/1609.Even Odd Tree_test.go @@ -0,0 +1,73 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question1609 struct { + para1609 + ans1609 +} + +// para 是参数 +type para1609 struct { + root *TreeNode +} + +// ans 是答案 +type ans1609 struct { + ans bool +} + +func Test_Problem1609(t *testing.T) { + + qs := []question1609{ + + { + para1609{&TreeNode{1, + &TreeNode{10, + &TreeNode{3, &TreeNode{12, nil, nil}, &TreeNode{8, nil, nil}}, nil}, + &TreeNode{4, &TreeNode{7, &TreeNode{6, nil, nil}, nil}, &TreeNode{9, nil, &TreeNode{2, nil, nil}}}}}, + ans1609{true}, + }, + + { + para1609{&TreeNode{5, + &TreeNode{4, &TreeNode{3, nil, nil}, &TreeNode{3, nil, nil}}, + &TreeNode{2, &TreeNode{7, nil, nil}, nil}}}, + ans1609{false}, + }, + + { + para1609{&TreeNode{5, + &TreeNode{9, &TreeNode{3, nil, nil}, &TreeNode{5, nil, nil}}, + &TreeNode{1, &TreeNode{7, nil, nil}, nil}}}, + ans1609{false}, + }, + + { + para1609{&TreeNode{1, nil, nil}}, + ans1609{true}, + }, + + { + para1609{&TreeNode{11, + &TreeNode{8, + &TreeNode{1, &TreeNode{30, &TreeNode{17, nil, nil}, nil}, &TreeNode{20, nil, nil}}, + &TreeNode{3, &TreeNode{18, nil, nil}, &TreeNode{16, nil, nil}}}, + &TreeNode{6, + &TreeNode{9, &TreeNode{12, nil, nil}, &TreeNode{10, nil, nil}}, + &TreeNode{11, &TreeNode{4, nil, nil}, &TreeNode{2, nil, nil}}}}}, + ans1609{true}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 1609------------------------\n") + + for _, q := range qs { + _, p := q.ans1609, q.para1609 + fmt.Printf("【input】:%v 【output】:%v\n", p.root, isEvenOddTree(p.root)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/1609.Even-Odd-Tree/README.md b/leetcode/1609.Even-Odd-Tree/README.md new file mode 100644 index 000000000..0481d9821 --- /dev/null +++ b/leetcode/1609.Even-Odd-Tree/README.md @@ -0,0 +1,150 @@ +# [1609. Even Odd Tree](https://leetcode.com/problems/even-odd-tree/) + +## 题目 + +A binary tree is named Even-Odd if it meets the following conditions: + +- The root of the binary tree is at level index 0, its children are at level index 1, their children are at level index 2, etc. +- For every even-indexed level, all nodes at the level have odd integer values in strictly increasing order (from left to right). +- For every odd-indexed level, all nodes at the level have even integer values in strictly decreasing order (from left to right). + +Given the root of a binary tree, return true if the binary tree is Even-Odd, otherwise return false. + +**Example 1**: + +![https://assets.leetcode.com/uploads/2020/09/15/sample_1_1966.png](https://assets.leetcode.com/uploads/2020/09/15/sample_1_1966.png) + + Input: root = [1,10,4,3,null,7,9,12,8,6,null,null,2] + Output: true + Explanation: The node values on each level are: + Level 0: [1] + Level 1: [10,4] + Level 2: [3,7,9] + Level 3: [12,8,6,2] + Since levels 0 and 2 are all odd and increasing and levels 1 and 3 are all even and decreasing, the tree is Even-Odd. + +**Example 2**: + +![https://assets.leetcode.com/uploads/2020/09/15/sample_2_1966.png](https://assets.leetcode.com/uploads/2020/09/15/sample_2_1966.png) + + Input: root = [5,4,2,3,3,7] + Output: false + Explanation: The node values on each level are: + Level 0: [5] + Level 1: [4,2] + Level 2: [3,3,7] + Node values in level 2 must be in strictly increasing order, so the tree is not Even-Odd. + +**Example 3**: + +![https://assets.leetcode.com/uploads/2020/09/22/sample_1_333_1966.png](https://assets.leetcode.com/uploads/2020/09/22/sample_1_333_1966.png) + + Input: root = [5,9,1,3,5,7] + Output: false + Explanation: Node values in the level 1 should be even integers. + +**Example 4**: + + Input: root = [1] + Output: true + +**Example 5**: + + Input: root = [11,8,6,1,3,9,11,30,20,18,16,12,10,4,2,17] + Output: True + +**Constraints:** + +- The number of nodes in the tree is in the range [1, 100000]. +- 1 <= Node.val <= 1000000 + +## 题目大意 + +如果一棵二叉树满足下述几个条件，则可以称为 奇偶树 ： + +- 二叉树根节点所在层下标为 0 ，根的子节点所在层下标为 1 ，根的孙节点所在层下标为 2 ，依此类推。 +- 偶数下标 层上的所有节点的值都是 奇 整数，从左到右按顺序 严格递增 +- 奇数下标 层上的所有节点的值都是 偶 整数，从左到右按顺序 严格递减 + +给你二叉树的根节点，如果二叉树为 奇偶树 ，则返回 true ，否则返回 false 。 + +## 解题思路 + +- 广度优先遍历(分别判断奇数层和偶数层) + +## 代码 + +```go +package leetcode + +type TreeNode struct { + Val int + Left *TreeNode + Right *TreeNode +} + +func isEvenOddTree(root *TreeNode) bool { + level := 0 + queue := []*TreeNode{root} + for len(queue) != 0 { + length := len(queue) + var nums []int + for i := 0; i < length; i++ { + node := queue[i] + if node.Left != nil { + queue = append(queue, node.Left) + } + if node.Right != nil { + queue = append(queue, node.Right) + } + nums = append(nums, node.Val) + } + if level%2 == 0 { + if !even(nums) { + return false + } + } else { + if !odd(nums) { + return false + } + } + queue = queue[length:] + level++ + } + return true +} + +func odd(nums []int) bool { + cur := nums[0] + if cur%2 != 0 { + return false + } + for _, num := range nums[1:] { + if num >= cur { + return false + } + if num%2 != 0 { + return false + } + cur = num + } + return true +} + +func even(nums []int) bool { + cur := nums[0] + if cur%2 == 0 { + return false + } + for _, num := range nums[1:] { + if num <= cur { + return false + } + if num%2 == 0 { + return false + } + cur = num + } + return true +} +``` \ No newline at end of file diff --git a/leetcode/1685.Sum-of-Absolute-Differences-in-a-Sorted-Array/1685. Sum of Absolute Differences in a Sorted Array.go b/leetcode/1685.Sum-of-Absolute-Differences-in-a-Sorted-Array/1685. Sum of Absolute Differences in a Sorted Array.go index b2682093a..15656d39b 100644 --- a/leetcode/1685.Sum-of-Absolute-Differences-in-a-Sorted-Array/1685. Sum of Absolute Differences in a Sorted Array.go +++ b/leetcode/1685.Sum-of-Absolute-Differences-in-a-Sorted-Array/1685. Sum of Absolute Differences in a Sorted Array.go @@ -1,6 +1,6 @@ package leetcode -//解法一 优化版 prefixSum + sufixSum +// 解法一 优化版 prefixSum + sufixSum func getSumAbsoluteDifferences(nums []int) []int { size := len(nums) sufixSum := make([]int, size) diff --git a/leetcode/1705.Maximum-Number-of-Eaten-Apples/1705.Maximum Number of Eaten Apples.go b/leetcode/1705.Maximum-Number-of-Eaten-Apples/1705.Maximum Number of Eaten Apples.go new file mode 100644 index 000000000..a4ffd6cf3 --- /dev/null +++ b/leetcode/1705.Maximum-Number-of-Eaten-Apples/1705.Maximum Number of Eaten Apples.go @@ -0,0 +1,67 @@ +package leetcode + +import "container/heap" + +func eatenApples(apples []int, days []int) int { + h := hp{} + i := 0 + var ans int + for ; i < len(apples); i++ { + for len(h) > 0 && h[0].end <= i { + heap.Pop(&h) + } + if apples[i] > 0 { + heap.Push(&h, data{apples[i], i + days[i]}) + } + if len(h) > 0 { + minData := heap.Pop(&h).(data) + ans++ + if minData.left > 1 { + heap.Push(&h, data{minData.left - 1, minData.end}) + } + } + } + for len(h) > 0 { + for len(h) > 0 && h[0].end <= i { + heap.Pop(&h) + } + if len(h) == 0 { + break + } + minData := heap.Pop(&h).(data) + nums := min(minData.left, minData.end-i) + ans += nums + i += nums + } + return ans +} + +func min(a, b int) int { + if a < b { + return a + } + return b +} + +type data struct { + left int + end int +} + +type hp []data + +func (h hp) Len() int { return len(h) } +func (h hp) Less(i, j int) bool { return h[i].end < h[j].end } +func (h hp) Swap(i, j int) { h[i], h[j] = h[j], h[i] } + +func (h *hp) Push(x interface{}) { + *h = append(*h, x.(data)) +} + +func (h *hp) Pop() interface{} { + old := *h + n := len(old) + x := old[n-1] + *h = old[0 : n-1] + return x +} diff --git a/leetcode/1705.Maximum-Number-of-Eaten-Apples/1705.Maximum Number of Eaten Apples_test.go b/leetcode/1705.Maximum-Number-of-Eaten-Apples/1705.Maximum Number of Eaten Apples_test.go new file mode 100644 index 000000000..3b178c7a0 --- /dev/null +++ b/leetcode/1705.Maximum-Number-of-Eaten-Apples/1705.Maximum Number of Eaten Apples_test.go @@ -0,0 +1,46 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question1705 struct { + para1705 + ans1705 +} + +// para 是参数 +type para1705 struct { + apples []int + days []int +} + +// ans 是答案 +type ans1705 struct { + ans int +} + +func Test_Problem1705(t *testing.T) { + + qs := []question1705{ + + { + para1705{[]int{1, 2, 3, 5, 2}, []int{3, 2, 1, 4, 2}}, + ans1705{7}, + }, + + { + para1705{[]int{3, 0, 0, 0, 0, 2}, []int{3, 0, 0, 0, 0, 2}}, + ans1705{5}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 1705------------------------\n") + + for _, q := range qs { + _, p := q.ans1705, q.para1705 + fmt.Printf("【input】:%v 【output】:%v\n", p, eatenApples(p.apples, p.days)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/1705.Maximum-Number-of-Eaten-Apples/README.md b/leetcode/1705.Maximum-Number-of-Eaten-Apples/README.md new file mode 100644 index 000000000..b5717e75a --- /dev/null +++ b/leetcode/1705.Maximum-Number-of-Eaten-Apples/README.md @@ -0,0 +1,124 @@ +# [1705. Maximum Number of Eaten Apples](https://leetcode.com/problems/maximum-number-of-eaten-apples/) + +## 题目 + +There is a special kind of apple tree that grows apples every day for n days. On the ith day, the tree grows apples[i] apples that will rot after days[i] days, that is on day i + days[i] the apples will be rotten and cannot be eaten. On some days, the apple tree does not grow any apples, which are denoted by apples[i] == 0 and days[i] == 0. + +You decided to eat at most one apple a day (to keep the doctors away). Note that you can keep eating after the first n days. + +Given two integer arrays days and apples of length n, return the maximum number of apples you can eat. + +**Example 1**: + + Input: apples = [1,2,3,5,2], days = [3,2,1,4,2] + Output: 7 + Explanation: You can eat 7 apples: + - On the first day, you eat an apple that grew on the first day. + - On the second day, you eat an apple that grew on the second day. + - On the third day, you eat an apple that grew on the second day. After this day, the apples that grew on the third day rot. + - On the fourth to the seventh days, you eat apples that grew on the fourth day. + +**Example 2**: + + Input: apples = [3,0,0,0,0,2], days = [3,0,0,0,0,2] + Output: 5 + Explanation: You can eat 5 apples: + - On the first to the third day you eat apples that grew on the first day. + - Do nothing on the fouth and fifth days. + - On the sixth and seventh days you eat apples that grew on the sixth day. + +**Constraints:** + +- apples.length == n +- days.length == n +- 1 <= n <= 2 * 10000 +- 0 <= apples[i], days[i] <= 2 * 10000 +- days[i] = 0 if and only if apples[i] = 0. + +## 题目大意 + +有一棵特殊的苹果树，一连 n 天，每天都可以长出若干个苹果。在第 i 天，树上会长出 apples[i] 个苹果，这些苹果将会在 days[i] 天后（也就是说，第 i + days[i] 天时）腐烂，变得无法食用。也可能有那么几天，树上不会长出新的苹果，此时用 apples[i] == 0 且 days[i] == 0 表示。 + +你打算每天 最多 吃一个苹果来保证营养均衡。注意，你可以在这 n 天之后继续吃苹果。 + +给你两个长度为 n 的整数数组 days 和 apples ，返回你可以吃掉的苹果的最大数目。 + +## 解题思路 + +贪心算法和最小堆 + + - data中的end表示腐烂的日期，left表示拥有的苹果数量 + - 贪心:每天吃掉end最小但没有腐烂的苹果 + - 最小堆:构造类型为数组(数组中元素的类型为data)的最小堆 + +## 代码 + +```go +package leetcode + +import "container/heap" + +func eatenApples(apples []int, days []int) int { + h := hp{} + i := 0 + var ans int + for ; i < len(apples); i++ { + for len(h) > 0 && h[0].end <= i { + heap.Pop(&h) + } + if apples[i] > 0 { + heap.Push(&h, data{apples[i], i + days[i]}) + } + if len(h) > 0 { + minData := heap.Pop(&h).(data) + ans++ + if minData.left > 1 { + heap.Push(&h, data{minData.left - 1, minData.end}) + } + } + } + for len(h) > 0 { + for len(h) > 0 && h[0].end <= i { + heap.Pop(&h) + } + if len(h) == 0 { + break + } + minData := heap.Pop(&h).(data) + nums := min(minData.left, minData.end-i) + ans += nums + i += nums + } + return ans +} + +func min(a, b int) int { + if a < b { + return a + } + return b +} + +type data struct { + left int + end int +} + +type hp []data + +func (h hp) Len() int { return len(h) } +func (h hp) Less(i, j int) bool { return h[i].end < h[j].end } +func (h hp) Swap(i, j int) { h[i], h[j] = h[j], h[i] } + +func (h *hp) Push(x interface{}) { + *h = append(*h, x.(data)) +} + +func (h *hp) Pop() interface{} { + old := *h + n := len(old) + x := old[n-1] + *h = old[0 : n-1] + return x +} +``` \ No newline at end of file diff --git a/leetcode/1725.Number-Of-Rectangles-That-Can-Form-The-Largest-Square/1725. Number Of Rectangles That Can Form The Largest Square.go b/leetcode/1725.Number-Of-Rectangles-That-Can-Form-The-Largest-Square/1725. Number Of Rectangles That Can Form The Largest Square.go index eec17bfb8..4c7bf664b 100644 --- a/leetcode/1725.Number-Of-Rectangles-That-Can-Form-The-Largest-Square/1725. Number Of Rectangles That Can Form The Largest Square.go +++ b/leetcode/1725.Number-Of-Rectangles-That-Can-Form-The-Largest-Square/1725. Number Of Rectangles That Can Form The Largest Square.go @@ -2,7 +2,7 @@ package leetcode func countGoodRectangles(rectangles [][]int) int { minLength, count := 0, 0 - for i, _ := range rectangles { + for i := range rectangles { minSide := 0 if rectangles[i][0] <= rectangles[i][1] { minSide = rectangles[i][0] diff --git a/leetcode/1734.Decode-XORed-Permutation/1734. Decode XORed Permutation.go b/leetcode/1734.Decode-XORed-Permutation/1734. Decode XORed Permutation.go new file mode 100644 index 000000000..60f24d323 --- /dev/null +++ b/leetcode/1734.Decode-XORed-Permutation/1734. Decode XORed Permutation.go @@ -0,0 +1,17 @@ +package leetcode + +func decode(encoded []int) []int { + n, total, odd := len(encoded), 0, 0 + for i := 1; i <= n+1; i++ { + total ^= i + } + for i := 1; i < n; i += 2 { + odd ^= encoded[i] + } + perm := make([]int, n+1) + perm[0] = total ^ odd + for i, v := range encoded { + perm[i+1] = perm[i] ^ v + } + return perm +} diff --git a/leetcode/1734.Decode-XORed-Permutation/1734. Decode XORed Permutation_test.go b/leetcode/1734.Decode-XORed-Permutation/1734. Decode XORed Permutation_test.go new file mode 100644 index 000000000..837beab52 --- /dev/null +++ b/leetcode/1734.Decode-XORed-Permutation/1734. Decode XORed Permutation_test.go @@ -0,0 +1,47 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question1734 struct { + para1734 + ans1734 +} + +// para 是参数 +// one 代表第一个参数 +type para1734 struct { + encoded []int +} + +// ans 是答案 +// one 代表第一个答案 +type ans1734 struct { + one []int +} + +func Test_Problem1734(t *testing.T) { + + qs := []question1734{ + + { + para1734{[]int{3, 1}}, + ans1734{[]int{1, 2, 3}}, + }, + + { + para1734{[]int{6, 5, 4, 6}}, + ans1734{[]int{2, 4, 1, 5, 3}}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 1734------------------------\n") + + for _, q := range qs { + _, p := q.ans1734, q.para1734 + fmt.Printf("【input】:%v 【output】:%v\n", p, decode(p.encoded)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/1734.Decode-XORed-Permutation/README.md b/leetcode/1734.Decode-XORed-Permutation/README.md new file mode 100644 index 000000000..b60ab2e63 --- /dev/null +++ b/leetcode/1734.Decode-XORed-Permutation/README.md @@ -0,0 +1,71 @@ +# [1734. Decode XORed Permutation](https://leetcode.com/problems/decode-xored-permutation/) + + +## 题目 + +There is an integer array `perm` that is a permutation of the first `n` positive integers, where `n` is always **odd**. + +It was encoded into another integer array `encoded` of length `n - 1`, such that `encoded[i] = perm[i] XOR perm[i + 1]`. For example, if `perm = [1,3,2]`, then `encoded = [2,1]`. + +Given the `encoded` array, return *the original array* `perm`. It is guaranteed that the answer exists and is unique. + +**Example 1:** + +``` +Input: encoded = [3,1] +Output: [1,2,3] +Explanation: If perm = [1,2,3], then encoded = [1 XOR 2,2 XOR 3] = [3,1] + +``` + +**Example 2:** + +``` +Input: encoded = [6,5,4,6] +Output: [2,4,1,5,3] + +``` + +**Constraints:** + +- `3 <= n < 10^5` +- `n` is odd. +- `encoded.length == n - 1` + +## 题目大意 + +给你一个整数数组 perm ，它是前 n 个正整数的排列，且 n 是个奇数 。它被加密成另一个长度为 n - 1 的整数数组 encoded ，满足 encoded[i] = perm[i] XOR perm[i + 1] 。比方说，如果 perm = [1,3,2] ，那么 encoded = [2,1] 。给你 encoded 数组，请你返回原始数组 perm 。题目保证答案存在且唯一。 + +## 解题思路 + +- 这一题与第 136 题和第 137 题思路类似，借用 `x ^ x = 0` 这个性质解题。依题意，原数组 perm 是 n 个正整数，即取值在 `[1,n+1]` 区间内，但是排列顺序未知。可以考虑先将 `[1,n+1]` 区间内的所有数异或得到 total。再将 encoded 数组中奇数下标的元素异或得到 odd： + + $$\begin{aligned}odd &= encoded[1] + encoded[3] + ... + encoded[n-1]\\&= (perm[1] \,\, XOR \,\, perm[2]) + (perm[3] \,\,  XOR  \,\, perm[4]) + ... + (perm[n-1]  \,\, XOR \,\, perm[n])\end{aligned}$$ + + total 是 n 个正整数异或全集，odd 是 `n-1` 个正整数异或集。两者异或 `total ^ odd` 得到的值必定是 perm[0]，因为 `x ^ x = 0`，那么重复出现的元素被异或以后消失了。算出 perm[0] 就好办了。 + + $$\begin{aligned}encoded[0] &= perm[0] \,\, XOR \,\, perm[1]\\perm[0] \,\, XOR \,\, encoded[0] &= perm[0] \,\, XOR \,\, perm[0] \,\, XOR \,\, perm[1] = perm[1]\\perm[1] \,\, XOR \,\, encoded[1] &= perm[1] \,\, XOR \,\, perm[1] \,\, XOR \,\, perm[2] = perm[2]\\...\\perm[n-1] \,\, XOR \,\, encoded[n-1] &= perm[n-1] \,\, XOR \,\, perm[n-1] \,\, XOR \,\, perm[n] = perm[n]\\\end{aligned}$$ + + 依次类推，便可以推出原数组 perm 中的所有数。 + +## 代码 + +```go +package leetcode + +func decode(encoded []int) []int { + n, total, odd := len(encoded), 0, 0 + for i := 1; i <= n+1; i++ { + total ^= i + } + for i := 1; i < n; i += 2 { + odd ^= encoded[i] + } + perm := make([]int, n+1) + perm[0] = total ^ odd + for i, v := range encoded { + perm[i+1] = perm[i] ^ v + } + return perm +} +``` \ No newline at end of file diff --git a/leetcode/1738.Find-Kth-Largest-XOR-Coordinate-Value/1738. Find Kth Largest XOR Coordinate Value.go b/leetcode/1738.Find-Kth-Largest-XOR-Coordinate-Value/1738. Find Kth Largest XOR Coordinate Value.go new file mode 100644 index 000000000..8c5760ef4 --- /dev/null +++ b/leetcode/1738.Find-Kth-Largest-XOR-Coordinate-Value/1738. Find Kth Largest XOR Coordinate Value.go @@ -0,0 +1,36 @@ +package leetcode + +import "sort" + +// 解法一 压缩版的前缀和 +func kthLargestValue(matrix [][]int, k int) int { + if len(matrix) == 0 || len(matrix[0]) == 0 { + return 0 + } + res, prefixSum := make([]int, 0, len(matrix)*len(matrix[0])), make([]int, len(matrix[0])) + for i := range matrix { + line := 0 + for j, v := range matrix[i] { + line ^= v + prefixSum[j] ^= line + res = append(res, prefixSum[j]) + } + } + sort.Ints(res) + return res[len(res)-k] +} + +// 解法二 前缀和 +func kthLargestValue1(matrix [][]int, k int) int { + nums, prefixSum := []int{}, make([][]int, len(matrix)+1) + prefixSum[0] = make([]int, len(matrix[0])+1) + for i, row := range matrix { + prefixSum[i+1] = make([]int, len(matrix[0])+1) + for j, val := range row { + prefixSum[i+1][j+1] = prefixSum[i+1][j] ^ prefixSum[i][j+1] ^ prefixSum[i][j] ^ val + nums = append(nums, prefixSum[i+1][j+1]) + } + } + sort.Ints(nums) + return nums[len(nums)-k] +} diff --git a/leetcode/1738.Find-Kth-Largest-XOR-Coordinate-Value/1738. Find Kth Largest XOR Coordinate Value_test.go b/leetcode/1738.Find-Kth-Largest-XOR-Coordinate-Value/1738. Find Kth Largest XOR Coordinate Value_test.go new file mode 100644 index 000000000..90d199ecc --- /dev/null +++ b/leetcode/1738.Find-Kth-Largest-XOR-Coordinate-Value/1738. Find Kth Largest XOR Coordinate Value_test.go @@ -0,0 +1,58 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question1738 struct { + para1738 + ans1738 +} + +// para 是参数 +// one 代表第一个参数 +type para1738 struct { + matrix [][]int + k int +} + +// ans 是答案 +// one 代表第一个答案 +type ans1738 struct { + one int +} + +func Test_Problem1738(t *testing.T) { + + qs := []question1738{ + + { + para1738{[][]int{{5, 2}, {1, 6}}, 1}, + ans1738{7}, + }, + + { + para1738{[][]int{{5, 2}, {1, 6}}, 2}, + ans1738{5}, + }, + + { + para1738{[][]int{{5, 2}, {1, 6}}, 3}, + ans1738{4}, + }, + + { + para1738{[][]int{{5, 2}, {1, 6}}, 4}, + ans1738{0}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 1738------------------------\n") + + for _, q := range qs { + _, p := q.ans1738, q.para1738 + fmt.Printf("【input】:%v 【output】:%v\n", p, kthLargestValue(p.matrix, p.k)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/1738.Find-Kth-Largest-XOR-Coordinate-Value/README.md b/leetcode/1738.Find-Kth-Largest-XOR-Coordinate-Value/README.md new file mode 100644 index 000000000..a264778a4 --- /dev/null +++ b/leetcode/1738.Find-Kth-Largest-XOR-Coordinate-Value/README.md @@ -0,0 +1,111 @@ +# [1738. Find Kth Largest XOR Coordinate Value](https://leetcode.com/problems/find-kth-largest-xor-coordinate-value/) + + +## 题目 + +You are given a 2D `matrix` of size `m x n`, consisting of non-negative integers. You are also given an integer `k`. + +The **value** of coordinate `(a, b)` of the matrix is the XOR of all `matrix[i][j]` where `0 <= i <= a < m` and `0 <= j <= b < n` **(0-indexed)**. + +Find the `kth` largest value **(1-indexed)** of all the coordinates of `matrix`. + +**Example 1:** + +``` +Input: matrix = [[5,2],[1,6]], k = 1 +Output: 7 +Explanation: The value of coordinate (0,1) is 5 XOR 2 = 7, which is the largest value. +``` + +**Example 2:** + +``` +Input: matrix = [[5,2],[1,6]], k = 2 +Output: 5 +Explanation:The value of coordinate (0,0) is 5 = 5, which is the 2nd largest value. +``` + +**Example 3:** + +``` +Input: matrix = [[5,2],[1,6]], k = 3 +Output: 4 +Explanation: The value of coordinate (1,0) is 5 XOR 1 = 4, which is the 3rd largest value. +``` + +**Example 4:** + +``` +Input: matrix = [[5,2],[1,6]], k = 4 +Output: 0 +Explanation: The value of coordinate (1,1) is 5 XOR 2 XOR 1 XOR 6 = 0, which is the 4th largest value. +``` + +**Constraints:** + +- `m == matrix.length` +- `n == matrix[i].length` +- `1 <= m, n <= 1000` +- `0 <= matrix[i][j] <= 10^6` +- `1 <= k <= m * n` + +## 题目大意 + +给你一个二维矩阵 matrix 和一个整数 k ，矩阵大小为 m x n 由非负整数组成。矩阵中坐标 (a, b) 的 值 可由对所有满足 0 <= i <= a < m 且 0 <= j <= b < n 的元素 matrix[i][j]（下标从 0 开始计数）执行异或运算得到。请你找出 matrix 的所有坐标中第 k 大的值（k 的值从 1 开始计数）。 + +## 解题思路 + +- 区间异或结果类比于区间二维前缀和。只不过需要注意 x^x = 0 这一性质。举例： + + ![](https://img.halfrost.com/Leetcode/leetcode_1738_0_.png) + + 通过简单推理，可以得出区间二维前缀和 preSum 的递推式。具体代码见解法二。 + +- 上面的解法中，preSum 用二维数组计算的。能否再优化空间复杂度，降低成 O(n)？答案是可以的。通过观察可以发现。preSum 可以按照一行一行来生成。先生成 preSum 前一行，下一行生成过程中会用到前一行的信息，异或计算以后，可以覆盖原数据(前一行的信息)，对之后的计算没有影响。这个优化空间复杂度的方法和优化 DP 空间复杂度是完全一样的思路和方法。 + + ![](https://img.halfrost.com/Leetcode/leetcode_1738_1_.png) + + 具体代码见解法一。 + +- 计算出了 preSum，还需要考虑如何输出第 k 大的值。有 3 种做法，第一种是排序，第二种是优先队列，第三种是第 215 题中的 O(n) 的 partition 方法。时间复杂度最低的当然是 O(n)。但是经过实际测试，runtime 最优的是排序的方法。所以笔者以下两种方法均采用了排序的方法。 + +## 代码 + +```go +package leetcode + +import "sort" + +// 解法一 压缩版的前缀和 +func kthLargestValue(matrix [][]int, k int) int { + if len(matrix) == 0 || len(matrix[0]) == 0 { + return 0 + } + res, prefixSum := make([]int, 0, len(matrix)*len(matrix[0])), make([]int, len(matrix[0])) + for i := range matrix { + line := 0 + for j, v := range matrix[i] { + line ^= v + prefixSum[j] ^= line + res = append(res, prefixSum[j]) + } + } + sort.Ints(res) + return res[len(res)-k] +} + +// 解法二 前缀和 +func kthLargestValue1(matrix [][]int, k int) int { + nums, prefixSum := []int{}, make([][]int, len(matrix)+1) + prefixSum[0] = make([]int, len(matrix[0])+1) + for i, row := range matrix { + prefixSum[i+1] = make([]int, len(matrix[0])+1) + for j, val := range row { + prefixSum[i+1][j+1] = prefixSum[i+1][j] ^ prefixSum[i][j+1] ^ prefixSum[i][j] ^ val + nums = append(nums, prefixSum[i+1][j+1]) + } + } + sort.Ints(nums) + return nums[len(nums)-k] +} +``` \ No newline at end of file diff --git a/leetcode/1744.Can-You-Eat-Your-Favorite-Candy-on-Your-Favorite-Day/1744. Can You Eat Your Favorite Candy on Your Favorite Day.go b/leetcode/1744.Can-You-Eat-Your-Favorite-Candy-on-Your-Favorite-Day/1744. Can You Eat Your Favorite Candy on Your Favorite Day.go new file mode 100644 index 000000000..ce89feb07 --- /dev/null +++ b/leetcode/1744.Can-You-Eat-Your-Favorite-Candy-on-Your-Favorite-Day/1744. Can You Eat Your Favorite Candy on Your Favorite Day.go @@ -0,0 +1,23 @@ +package leetcode + +func canEat(candiesCount []int, queries [][]int) []bool { + n := len(candiesCount) + prefixSum := make([]int, n) + prefixSum[0] = candiesCount[0] + for i := 1; i < n; i++ { + prefixSum[i] = prefixSum[i-1] + candiesCount[i] + } + res := make([]bool, len(queries)) + for i, q := range queries { + favoriteType, favoriteDay, dailyCap := q[0], q[1], q[2] + x1 := favoriteDay + 1 + y1 := (favoriteDay + 1) * dailyCap + x2 := 1 + if favoriteType > 0 { + x2 = prefixSum[favoriteType-1] + 1 + } + y2 := prefixSum[favoriteType] + res[i] = !(x1 > y2 || y1 < x2) + } + return res +} diff --git a/leetcode/1744.Can-You-Eat-Your-Favorite-Candy-on-Your-Favorite-Day/1744. Can You Eat Your Favorite Candy on Your Favorite Day_test.go b/leetcode/1744.Can-You-Eat-Your-Favorite-Candy-on-Your-Favorite-Day/1744. Can You Eat Your Favorite Candy on Your Favorite Day_test.go new file mode 100644 index 000000000..73a486bcd --- /dev/null +++ b/leetcode/1744.Can-You-Eat-Your-Favorite-Candy-on-Your-Favorite-Day/1744. Can You Eat Your Favorite Candy on Your Favorite Day_test.go @@ -0,0 +1,48 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question1744 struct { + para1744 + ans1744 +} + +// para 是参数 +// one 代表第一个参数 +type para1744 struct { + candiesCount []int + queries [][]int +} + +// ans 是答案 +// one 代表第一个答案 +type ans1744 struct { + one []bool +} + +func Test_Problem1744(t *testing.T) { + + qs := []question1744{ + + { + para1744{[]int{7, 4, 5, 3, 8}, [][]int{{0, 2, 2}, {4, 2, 4}, {2, 13, 1000000000}}}, + ans1744{[]bool{true, false, true}}, + }, + + { + para1744{[]int{5, 2, 6, 4, 1}, [][]int{{3, 1, 2}, {4, 10, 3}, {3, 10, 100}, {4, 100, 30}, {1, 3, 1}}}, + ans1744{[]bool{false, true, true, false, false}}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 1744------------------------\n") + + for _, q := range qs { + _, p := q.ans1744, q.para1744 + fmt.Printf("【input】:%v 【output】:%v\n", p, canEat(p.candiesCount, p.queries)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/1744.Can-You-Eat-Your-Favorite-Candy-on-Your-Favorite-Day/README.md b/leetcode/1744.Can-You-Eat-Your-Favorite-Candy-on-Your-Favorite-Day/README.md new file mode 100644 index 000000000..bb06c20a2 --- /dev/null +++ b/leetcode/1744.Can-You-Eat-Your-Favorite-Candy-on-Your-Favorite-Day/README.md @@ -0,0 +1,88 @@ +# [1744. Can You Eat Your Favorite Candy on Your Favorite Day?](https://leetcode.com/problems/can-you-eat-your-favorite-candy-on-your-favorite-day/) + +## 题目 + +You are given a **(0-indexed)** array of positive integers `candiesCount` where `candiesCount[i]` represents the number of candies of the `ith` type you have. You are also given a 2D array `queries` where `queries[i] = [favoriteTypei, favoriteDayi, dailyCapi]`. + +You play a game with the following rules: + +- You start eating candies on day **`0`**. +- You **cannot** eat **any** candy of type `i` unless you have eaten **all** candies of type `i - 1`. +- You must eat **at least** **one** candy per day until you have eaten all the candies. + +Construct a boolean array `answer` such that `answer.length == queries.length` and `answer[i]` is `true` if you can eat a candy of type `favoriteTypei` on day `favoriteDayi` without eating **more than** `dailyCapi` candies on **any** day, and `false` otherwise. Note that you can eat different types of candy on the same day, provided that you follow rule 2. + +Return *the constructed array* `answer`. + +**Example 1:** + +``` +Input: candiesCount = [7,4,5,3,8], queries = [[0,2,2],[4,2,4],[2,13,1000000000]] +Output: [true,false,true] +Explanation: +1- If you eat 2 candies (type 0) on day 0 and 2 candies (type 0) on day 1, you will eat a candy of type 0 on day 2. +2- You can eat at most 4 candies each day. + If you eat 4 candies every day, you will eat 4 candies (type 0) on day 0 and 4 candies (type 0 and type 1) on day 1. + On day 2, you can only eat 4 candies (type 1 and type 2), so you cannot eat a candy of type 4 on day 2. +3- If you eat 1 candy each day, you will eat a candy of type 2 on day 13. +``` + +**Example 2:** + +``` +Input: candiesCount = [5,2,6,4,1], queries = [[3,1,2],[4,10,3],[3,10,100],[4,100,30],[1,3,1]] +Output: [false,true,true,false,false] +``` + +**Constraints:** + +- `1 <= candiesCount.length <= 105` +- `1 <= candiesCount[i] <= 105` +- `1 <= queries.length <= 105` +- `queries[i].length == 3` +- `0 <= favoriteTypei < candiesCount.length` +- `0 <= favoriteDayi <= 109` +- `1 <= dailyCapi <= 109` + +## 题目大意 + +给你一个下标从 0 开始的正整数数组 candiesCount ，其中 candiesCount[i] 表示你拥有的第 i 类糖果的数目。同时给你一个二维数组 queries ，其中 queries[i] = [favoriteTypei, favoriteDayi, dailyCapi] 。你按照如下规则进行一场游戏： + +- 你从第 0 天开始吃糖果。 +- 你在吃完 所有 第 i - 1 类糖果之前，不能 吃任何一颗第 i 类糖果。 +- 在吃完所有糖果之前，你必须每天 至少 吃 一颗 糖果。 + +请你构建一个布尔型数组 answer ，满足 answer.length == queries.length 。answer[i] 为 true 的条件是：在每天吃 不超过 dailyCapi 颗糖果的前提下，你可以在第 favoriteDayi 天吃到第 favoriteTypei 类糖果；否则 answer[i] 为 false 。注意，只要满足上面 3 条规则中的第二条规则，你就可以在同一天吃不同类型的糖果。请你返回得到的数组 answer 。 + +## 解题思路 + +- 每天吃糖个数的下限是 1 颗，上限是 dailyCap。针对每一个 query 查询在第 i 天能否吃到 i 类型的糖果，要想吃到 i 类型的糖果，必须吃完 i-1 类型的糖果。意味着在 [favoriteDayi + 1, (favoriteDayi+1)×dailyCapi] 区间内能否包含一颗第 favoriteTypei 类型的糖果。如果能包含则输出 true，不能包含则输出 false。吃的糖果数是累积的，所以这里利用前缀和计算出累积吃糖果数所在区间 [sum[favoriteTypei−1]+1, sum[favoriteTypei]]。最后判断 query 区间和累积吃糖果数的区间是否有重叠即可。如果重叠即输出 true。 +- 判断两个区间是否重合，情况有好几种：内包含，全包含，半包含等等。没有交集的情况比较少，所以可以用排除法。对于区间 [x1, y1] 以及 [x2, y2]，它们没有交集当且仅当 x1 > y2 或者 y1 < x2。 + +## 代码 + +```go +package leetcode + +func canEat(candiesCount []int, queries [][]int) []bool { + n := len(candiesCount) + prefixSum := make([]int, n) + prefixSum[0] = candiesCount[0] + for i := 1; i < n; i++ { + prefixSum[i] = prefixSum[i-1] + candiesCount[i] + } + res := make([]bool, len(queries)) + for i, q := range queries { + favoriteType, favoriteDay, dailyCap := q[0], q[1], q[2] + x1 := favoriteDay + 1 + y1 := (favoriteDay + 1) * dailyCap + x2 := 1 + if favoriteType > 0 { + x2 = prefixSum[favoriteType-1] + 1 + } + y2 := prefixSum[favoriteType] + res[i] = !(x1 > y2 || y1 < x2) + } + return res +} +``` \ No newline at end of file diff --git a/leetcode/1763.Longest-Nice-Substring/1763. Longest Nice Substring.go b/leetcode/1763.Longest-Nice-Substring/1763. Longest Nice Substring.go new file mode 100644 index 000000000..9219ed23a --- /dev/null +++ b/leetcode/1763.Longest-Nice-Substring/1763. Longest Nice Substring.go @@ -0,0 +1,82 @@ +package leetcode + +import "unicode" + +// 解法一 分治，时间复杂度 O(n) +func longestNiceSubstring(s string) string { + if len(s) < 2 { + return "" + } + + chars := map[rune]int{} + for _, r := range s { + chars[r]++ + } + + for i := 0; i < len(s); i++ { + r := rune(s[i]) + _, u := chars[unicode.ToUpper(r)] + _, l := chars[unicode.ToLower(r)] + if u && l { + continue + } + left := longestNiceSubstring(s[:i]) + right := longestNiceSubstring(s[i+1:]) + if len(left) >= len(right) { + return left + } else { + return right + } + } + return s +} + +// 解法二 用二进制表示状态 +func longestNiceSubstring1(s string) (ans string) { + for i := range s { + lower, upper := 0, 0 + for j := i; j < len(s); j++ { + if unicode.IsLower(rune(s[j])) { + lower |= 1 << (s[j] - 'a') + } else { + upper |= 1 << (s[j] - 'A') + } + if lower == upper && j-i+1 > len(ans) { + ans = s[i : j+1] + } + } + } + return +} + +// 解法三 暴力枚举，时间复杂度 O(n^2) +func longestNiceSubstring2(s string) string { + res := "" + for i := 0; i < len(s); i++ { + m := map[byte]int{} + m[s[i]]++ + for j := i + 1; j < len(s); j++ { + m[s[j]]++ + if checkNiceString(m) && (j-i+1 > len(res)) { + res = s[i : j+1] + } + } + } + return res +} + +func checkNiceString(m map[byte]int) bool { + for k := range m { + if k >= 97 && k <= 122 { + if _, ok := m[k-32]; !ok { + return false + } + } + if k >= 65 && k <= 90 { + if _, ok := m[k+32]; !ok { + return false + } + } + } + return true +} diff --git a/leetcode/1763.Longest-Nice-Substring/1763. Longest Nice Substring_test.go b/leetcode/1763.Longest-Nice-Substring/1763. Longest Nice Substring_test.go new file mode 100644 index 000000000..08d550a30 --- /dev/null +++ b/leetcode/1763.Longest-Nice-Substring/1763. Longest Nice Substring_test.go @@ -0,0 +1,52 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question1763 struct { + para1763 + ans1763 +} + +// para 是参数 +// one 代表第一个参数 +type para1763 struct { + s string +} + +// ans 是答案 +// one 代表第一个答案 +type ans1763 struct { + one string +} + +func Test_Problem1763(t *testing.T) { + + qs := []question1763{ + + { + para1763{"YazaAay"}, + ans1763{"aAa"}, + }, + + { + para1763{"Bb"}, + ans1763{"Bb"}, + }, + + { + para1763{"c"}, + ans1763{""}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 1763------------------------\n") + + for _, q := range qs { + _, p := q.ans1763, q.para1763 + fmt.Printf("【input】:%v 【output】:%v\n", p, longestNiceSubstring(p.s)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/1763.Longest-Nice-Substring/README.md b/leetcode/1763.Longest-Nice-Substring/README.md new file mode 100644 index 000000000..05dd0bac4 --- /dev/null +++ b/leetcode/1763.Longest-Nice-Substring/README.md @@ -0,0 +1,140 @@ +# [1763. Longest Nice Substring](https://leetcode.com/problems/longest-nice-substring/) + + +## 题目 + +A string `s` is **nice** if, for every letter of the alphabet that `s` contains, it appears **both** in uppercase and lowercase. For example, `"abABB"` is nice because `'A'` and `'a'` appear, and `'B'` and `'b'` appear. However, `"abA"` is not because `'b'` appears, but `'B'` does not. + +Given a string `s`, return *the longest **substring** of `s` that is **nice**. If there are multiple, return the substring of the **earliest** occurrence. If there are none, return an empty string*. + +**Example 1:** + +``` +Input: s = "YazaAay" +Output: "aAa" +Explanation:"aAa" is a nice string because 'A/a' is the only letter of the alphabet in s, and both 'A' and 'a' appear. +"aAa" is the longest nice substring. + +``` + +**Example 2:** + +``` +Input: s = "Bb" +Output: "Bb" +Explanation: "Bb" is a nice string because both 'B' and 'b' appear. The whole string is a substring. + +``` + +**Example 3:** + +``` +Input: s = "c" +Output: "" +Explanation: There are no nice substrings. + +``` + +**Constraints:** + +- `1 <= s.length <= 100` +- `s` consists of uppercase and lowercase English letters. + +## 题目大意 + +当一个字符串 s 包含的每一种字母的大写和小写形式 同时 出现在 s 中，就称这个字符串 s 是 美好 字符串。比方说，"abABB" 是美好字符串，因为 'A' 和 'a' 同时出现了，且 'B' 和 'b' 也同时出现了。然而，"abA" 不是美好字符串因为 'b' 出现了，而 'B' 没有出现。 + +给你一个字符串 s ，请你返回 s 最长的 美好子字符串 。如果有多个答案，请你返回 最早 出现的一个。如果不存在美好子字符串，请你返回一个空字符串。 + +## 解题思路 + +- 解法一，暴力解法。枚举每一段字符串，判断这个子字符串内是否满足美好字符串的定义，即字母的大小写是否同时出现。 +- 解法二，这个解法是解法一的小幅优化版，利用二进制记录状态。先构造二进制状态串，再利用直接比较这个二进制串。 +- 解法三，分治。以 `i` 为分割点依次切开字符串。左右两个字符串分别判断是否满足美好字符串的定义。左右分开的字符串还可以继续划分。直至分到一个字母为止。在这个过程中记录最早出现的字符串。 + +## 代码 + +```go +package leetcode + +import "unicode" + +// 解法一 分治，时间复杂度 O(n) +func longestNiceSubstring(s string) string { + if len(s) < 2 { + return "" + } + + chars := map[rune]int{} + for _, r := range s { + chars[r]++ + } + + for i := 0; i < len(s); i++ { + r := rune(s[i]) + _, u := chars[unicode.ToUpper(r)] + _, l := chars[unicode.ToLower(r)] + if u && l { + continue + } + left := longestNiceSubstring(s[:i]) + right := longestNiceSubstring(s[i+1:]) + if len(left) >= len(right) { + return left + } else { + return right + } + } + return s +} + +// 解法二 用二进制表示状态 +func longestNiceSubstring1(s string) (ans string) { + for i := range s { + lower, upper := 0, 0 + for j := i; j < len(s); j++ { + if unicode.IsLower(rune(s[j])) { + lower |= 1 << (s[j] - 'a') + } else { + upper |= 1 << (s[j] - 'A') + } + if lower == upper && j-i+1 > len(ans) { + ans = s[i : j+1] + } + } + } + return +} + +// 解法三 暴力枚举，时间复杂度 O(n^2) +func longestNiceSubstring2(s string) string { + res := "" + for i := 0; i < len(s); i++ { + m := map[byte]int{} + m[s[i]]++ + for j := i + 1; j < len(s); j++ { + m[s[j]]++ + if checkNiceString(m) && (j-i+1 > len(res)) { + res = s[i : j+1] + } + } + } + return res +} + +func checkNiceString(m map[byte]int) bool { + for k := range m { + if k >= 97 && k <= 122 { + if _, ok := m[k-32]; !ok { + return false + } + } + if k >= 65 && k <= 90 { + if _, ok := m[k+32]; !ok { + return false + } + } + } + return true +} +``` \ No newline at end of file diff --git a/leetcode/1791.Find-Center-of-Star-Graph/1791.Find Center of Star Graph.go b/leetcode/1791.Find-Center-of-Star-Graph/1791.Find Center of Star Graph.go new file mode 100644 index 000000000..6f39e98f9 --- /dev/null +++ b/leetcode/1791.Find-Center-of-Star-Graph/1791.Find Center of Star Graph.go @@ -0,0 +1,8 @@ +package leetcode + +func findCenter(edges [][]int) int { + if edges[0][0] == edges[1][0] || edges[0][0] == edges[1][1] { + return edges[0][0] + } + return edges[0][1] +} diff --git a/leetcode/1791.Find-Center-of-Star-Graph/1791.Find Center of Star Graph_test.go b/leetcode/1791.Find-Center-of-Star-Graph/1791.Find Center of Star Graph_test.go new file mode 100644 index 000000000..e1ade4d8e --- /dev/null +++ b/leetcode/1791.Find-Center-of-Star-Graph/1791.Find Center of Star Graph_test.go @@ -0,0 +1,46 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question1791 struct { + para1791 + ans1791 +} + +// para 是参数 +type para1791 struct { + edges [][]int +} + +// ans 是答案 +type ans1791 struct { + ans int +} + +func Test_Problem1791(t *testing.T) { + + qs := []question1791{ + + { + para1791{[][]int{{1, 2}, {2, 3}, {4, 2}}}, + ans1791{2}, + }, + + { + para1791{[][]int{{1, 2}, {5, 1}, {1, 3}, {1, 4}}}, + ans1791{1}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 1791------------------------\n") + + for _, q := range qs { + _, p := q.ans1791, q.para1791 + fmt.Printf("【input】:%v ", p.edges) + fmt.Printf("【output】:%v \n", findCenter(p.edges)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/1791.Find-Center-of-Star-Graph/README.md b/leetcode/1791.Find-Center-of-Star-Graph/README.md new file mode 100644 index 000000000..7c3a049fa --- /dev/null +++ b/leetcode/1791.Find-Center-of-Star-Graph/README.md @@ -0,0 +1,52 @@ +# [1791.Find Center of Star Graph](https://leetcode.com/problems/find-center-of-star-graph/) + +## 题目 + +There is an undirected star graph consisting of n nodes labeled from 1 to n. A star graph is a graph where there is one center node and exactly n - 1 edges that connect the center node with every other node. + +You are given a 2D integer array edges where each edges[i] = [ui, vi] indicates that there is an edge between the nodes ui and vi. Return the center of the given star graph. + +**Example 1:** + +![https://assets.leetcode.com/uploads/2021/02/24/star_graph.png:w](https://assets.leetcode.com/uploads/2021/02/24/star_graph.png) + + Input: edges = [[1,2],[2,3],[4,2]] + Output: 2 + Explanation: As shown in the figure above, node 2 is connected to every other node, so 2 is the center. + +**Example 2:** + + Input: edges = [[1,2],[5,1],[1,3],[1,4]] + Output: 1 + +**Constraints:** + +- 3 <= n <= 100000 +- edges.length == n - 1 +- edges[i].length == 2 +- 1 <= ui, vi <= n +- ui != vi +- The given edges represent a valid star graph. + +## 题目大意 + +有一个无向的 星型 图，由 n 个编号从 1 到 n 的节点组成。星型图有一个 中心 节点，并且恰有 n - 1 条边将中心节点与其他每个节点连接起来。 + +给你一个二维整数数组 edges ，其中 edges[i] = [ui, vi] 表示在节点 ui 和 vi 之间存在一条边。请你找出并返回 edges 所表示星型图的中心节点。 + +## 解题思路 + +- 求出edges中前两个元素的共同值，即是中心节点 + +## 代码 + +```go +package leetcode + +func findCenter(edges [][]int) int { + if edges[0][0] == edges[1][0] || edges[0][0] == edges[1][1] { + return edges[0][0] + } + return edges[0][1] +} +``` diff --git a/leetcode/1816.Truncate-Sentence/1816.Truncate Sentence.go b/leetcode/1816.Truncate-Sentence/1816.Truncate Sentence.go new file mode 100644 index 000000000..99d917314 --- /dev/null +++ b/leetcode/1816.Truncate-Sentence/1816.Truncate Sentence.go @@ -0,0 +1,18 @@ +package leetcode + +func truncateSentence(s string, k int) string { + end := 0 + for i := range s { + if k > 0 && s[i] == ' ' { + k-- + } + if k == 0 { + end = i + break + } + } + if end == 0 { + return s + } + return s[:end] +} diff --git a/leetcode/1816.Truncate-Sentence/1816.Truncate Sentence_test.go b/leetcode/1816.Truncate-Sentence/1816.Truncate Sentence_test.go new file mode 100644 index 000000000..2d277bbfa --- /dev/null +++ b/leetcode/1816.Truncate-Sentence/1816.Truncate Sentence_test.go @@ -0,0 +1,51 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question1816 struct { + para1816 + ans1816 +} + +// para 是参数 +type para1816 struct { + s string + k int +} + +// ans 是答案 +type ans1816 struct { + ans string +} + +func Test_Problem1816(t *testing.T) { + + qs := []question1816{ + + { + para1816{"Hello how are you Contestant", 4}, + ans1816{"Hello how are you"}, + }, + + { + para1816{"What is the solution to this problem", 4}, + ans1816{"What is the solution"}, + }, + + { + para1816{"chopper is not a tanuki", 5}, + ans1816{"chopper is not a tanuki"}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 1816------------------------\n") + + for _, q := range qs { + _, p := q.ans1816, q.para1816 + fmt.Printf("【input】:%v 【output】:%v\n", p, truncateSentence(p.s, p.k)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/1816.Truncate-Sentence/README.md b/leetcode/1816.Truncate-Sentence/README.md new file mode 100644 index 000000000..ebd9b5877 --- /dev/null +++ b/leetcode/1816.Truncate-Sentence/README.md @@ -0,0 +1,76 @@ +# [1816. Truncate Sentence](https://leetcode.com/problems/truncate-sentence/) + +## 题目 + +A sentence is a list of words that are separated by a single space with no leading or trailing spaces. Each of the words consists of only uppercase and lowercase English letters (no punctuation). + +- For example, "Hello World", "HELLO", and "hello world hello world" are all sentences. + +You are given a sentence s and an integer k. You want to truncate s such that it contains only the first k words. Return s after truncating it. + +**Example 1**: + + Input: s = "Hello how are you Contestant", k = 4 + Output: "Hello how are you" + Explanation: + The words in s are ["Hello", "how" "are", "you", "Contestant"]. + The first 4 words are ["Hello", "how", "are", "you"]. + Hence, you should return "Hello how are you". + +**Example 2**: + + Input: s = "What is the solution to this problem", k = 4 + Output: "What is the solution" + Explanation: + The words in s are ["What", "is" "the", "solution", "to", "this", "problem"]. + The first 4 words are ["What", "is", "the", "solution"]. + Hence, you should return "What is the solution". + +**Example 3**: + + Input: s = "chopper is not a tanuki", k = 5 + Output: "chopper is not a tanuki" + +**Constraints:** + +- 1 <= s.length <= 500 +- k is in the range [1, the number of words in s]. +- s consist of only lowercase and uppercase English letters and spaces. +- The words in s are separated by a single space. +- There are no leading or trailing spaces. + +## 题目大意 + +句子 是一个单词列表，列表中的单词之间用单个空格隔开，且不存在前导或尾随空格。每个单词仅由大小写英文字母组成（不含标点符号）。 + +- 例如，"Hello World"、"HELLO" 和 "hello world hello world" 都是句子。 + +给你一个句子 s 和一个整数 k ，请你将 s 截断使截断后的句子仅含前 k 个单词。返回截断 s 后得到的句子。 + +## 解题思路 + +- 遍历字符串 s，找到最后一个空格的下标 end +- 如果 end 为 0，直接返回 s,否则返回 s[:end] + +## 代码 + +```go +package leetcode + +func truncateSentence(s string, k int) string { + end := 0 + for i := range s { + if k > 0 && s[i] == ' ' { + k-- + } + if k == 0 { + end = i + break + } + } + if end == 0 { + return s + } + return s[:end] +} +``` \ No newline at end of file diff --git a/leetcode/1818.Minimum-Absolute-Sum-Difference/1818. Minimum Absolute Sum Difference.go b/leetcode/1818.Minimum-Absolute-Sum-Difference/1818. Minimum Absolute Sum Difference.go new file mode 100644 index 000000000..dec40606d --- /dev/null +++ b/leetcode/1818.Minimum-Absolute-Sum-Difference/1818. Minimum Absolute Sum Difference.go @@ -0,0 +1,38 @@ +package leetcode + +func minAbsoluteSumDiff(nums1 []int, nums2 []int) int { + diff := 0 + maxDiff := 0 + for i, n2 := range nums2 { + d := abs(nums1[i] - n2) + diff += d + if maxDiff < d { + t := 100001 + for _, n1 := range nums1 { + maxDiff = max(maxDiff, d-min(t, abs(n1-n2))) + } + } + } + return (diff - maxDiff) % (1e9 + 7) +} + +func max(a, b int) int { + if a > b { + return a + } + return b +} + +func abs(a int) int { + if a > 0 { + return a + } + return -a +} + +func min(a, b int) int { + if a > b { + return b + } + return a +} diff --git a/leetcode/1818.Minimum-Absolute-Sum-Difference/1818. Minimum Absolute Sum Difference_test.go b/leetcode/1818.Minimum-Absolute-Sum-Difference/1818. Minimum Absolute Sum Difference_test.go new file mode 100644 index 000000000..9c9b36cf1 --- /dev/null +++ b/leetcode/1818.Minimum-Absolute-Sum-Difference/1818. Minimum Absolute Sum Difference_test.go @@ -0,0 +1,53 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question1818 struct { + para1818 + ans1818 +} + +// para 是参数 +// one 代表第一个参数 +type para1818 struct { + nums1 []int + nums2 []int +} + +// ans 是答案 +// one 代表第一个答案 +type ans1818 struct { + one int +} + +func Test_Problem1818(t *testing.T) { + + qs := []question1818{ + + { + para1818{[]int{1, 7, 5}, []int{2, 3, 5}}, + ans1818{3}, + }, + + { + para1818{[]int{2, 4, 6, 8, 10}, []int{2, 4, 6, 8, 10}}, + ans1818{0}, + }, + + { + para1818{[]int{1, 10, 4, 4, 2, 7}, []int{9, 3, 5, 1, 7, 4}}, + ans1818{20}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 1818------------------------\n") + + for _, q := range qs { + _, p := q.ans1818, q.para1818 + fmt.Printf("【input】:%v 【output】:%v\n", p, minAbsoluteSumDiff(p.nums1, p.nums2)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/1818.Minimum-Absolute-Sum-Difference/README.md b/leetcode/1818.Minimum-Absolute-Sum-Difference/README.md new file mode 100644 index 000000000..d66650997 --- /dev/null +++ b/leetcode/1818.Minimum-Absolute-Sum-Difference/README.md @@ -0,0 +1,117 @@ +# [1818. Minimum Absolute Sum Difference](https://leetcode.com/problems/minimum-absolute-sum-difference/) + +## 题目 + +You are given two positive integer arrays `nums1` and `nums2`, both of length `n`. + +The **absolute sum difference** of arrays `nums1` and `nums2` is defined as the **sum** of `|nums1[i] - nums2[i]|` for each `0 <= i < n` (**0-indexed**). + +You can replace **at most one** element of `nums1` with **any** other element in `nums1` to **minimize** the absolute sum difference. + +Return the *minimum absolute sum difference **after** replacing at most one ****element in the array `nums1`.* Since the answer may be large, return it **modulo** `109 + 7`. + +`|x|` is defined as: + +- `x` if `x >= 0`, or +- `x` if `x < 0`. + +**Example 1:** + +``` +Input: nums1 = [1,7,5], nums2 = [2,3,5] +Output: 3 +Explanation:There are two possible optimal solutions: +- Replace the second element with the first: [1,7,5] => [1,1,5], or +- Replace the second element with the third: [1,7,5] => [1,5,5]. +Both will yield an absolute sum difference of|1-2| + (|1-3| or |5-3|) + |5-5| =3. + +``` + +**Example 2:** + +``` +Input: nums1 = [2,4,6,8,10], nums2 = [2,4,6,8,10] +Output: 0 +Explanation:nums1 is equal to nums2 so no replacement is needed. This will result in an +absolute sum difference of 0. + +``` + +**Example 3:** + +``` +Input: nums1 = [1,10,4,4,2,7], nums2 = [9,3,5,1,7,4] +Output: 20 +Explanation:Replace the first element with the second: [1,10,4,4,2,7] => [10,10,4,4,2,7]. +This yields an absolute sum difference of|10-9| + |10-3| + |4-5| + |4-1| + |2-7| + |7-4| = 20 +``` + +**Constraints:** + +- `n == nums1.length` +- `n == nums2.length` +- `1 <= n <= 10^5` +- `1 <= nums1[i], nums2[i] <= 10^5` + +## 题目大意 + +给你两个正整数数组 nums1 和 nums2 ，数组的长度都是 n 。数组 nums1 和 nums2 的 绝对差值和 定义为所有 |nums1[i] - nums2[i]|（0 <= i < n）的 总和（下标从 0 开始）。你可以选用 nums1 中的 任意一个 元素来替换 nums1 中的 至多 一个元素，以 最小化 绝对差值和。在替换数组 nums1 中最多一个元素 之后 ，返回最小绝对差值和。因为答案可能很大，所以需要对 10^9 + 7 取余 后返回。 + +## 解题思路 + +- 如果不改变任何元素，绝对差值和为 + +$$\sum \left | nums1[i] - nums2[i] \right |$$ + +- 如果改变一个元素后，那么绝对差值和为 + +$$\begin{aligned}&\sum \left | nums1[i] - nums2[i] \right | - \left ( \left | nums1[i] - nums2[i] \right | - \left | nums1[j] - nums2[i] \right |\right )\\= &\sum \left | nums1[i] - nums2[i] \right | - \Delta \end{aligned}$$ + +题目要求返回最小绝对差值和，即求 + +$$\Delta $$ + +的最大值。暴力枚举 nums1 和 nums2 中两两差值，找到 maxdiff。 + +## 代码 + +```go +package leetcode + +func minAbsoluteSumDiff(nums1 []int, nums2 []int) int { + diff := 0 + maxDiff := 0 + for i, n2 := range nums2 { + d := abs(nums1[i] - n2) + diff += d + if maxDiff < d { + t := 100001 + for _, n1 := range nums1 { + maxDiff = max(maxDiff, d-min(t, abs(n1-n2))) + } + } + } + return (diff - maxDiff) % (1e9 + 7) +} + +func max(a, b int) int { + if a > b { + return a + } + return b +} + +func abs(a int) int { + if a > 0 { + return a + } + return -a +} + +func min(a, b int) int { + if a > b { + return b + } + return a +} +``` \ No newline at end of file diff --git a/leetcode/1846.Maximum-Element-After-Decreasing-and-Rearranging/1846. Maximum Element After Decreasing and Rearranging.go b/leetcode/1846.Maximum-Element-After-Decreasing-and-Rearranging/1846. Maximum Element After Decreasing and Rearranging.go new file mode 100644 index 000000000..1fde93aba --- /dev/null +++ b/leetcode/1846.Maximum-Element-After-Decreasing-and-Rearranging/1846. Maximum Element After Decreasing and Rearranging.go @@ -0,0 +1,25 @@ +package leetcode + +func maximumElementAfterDecrementingAndRearranging(arr []int) int { + n := len(arr) + count := make([]int, n+1) + for _, v := range arr { + count[min(v, n)]++ + } + miss := 0 + for _, c := range count[1:] { + if c == 0 { + miss++ + } else { + miss -= min(c-1, miss) + } + } + return n - miss +} + +func min(a, b int) int { + if a < b { + return a + } + return b +} diff --git a/leetcode/1846.Maximum-Element-After-Decreasing-and-Rearranging/1846. Maximum Element After Decreasing and Rearranging_test.go b/leetcode/1846.Maximum-Element-After-Decreasing-and-Rearranging/1846. Maximum Element After Decreasing and Rearranging_test.go new file mode 100644 index 000000000..b4198e574 --- /dev/null +++ b/leetcode/1846.Maximum-Element-After-Decreasing-and-Rearranging/1846. Maximum Element After Decreasing and Rearranging_test.go @@ -0,0 +1,52 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question1846 struct { + para1846 + ans1846 +} + +// para 是参数 +// one 代表第一个参数 +type para1846 struct { + arr []int +} + +// ans 是答案 +// one 代表第一个答案 +type ans1846 struct { + one int +} + +func Test_Problem1846(t *testing.T) { + + qs := []question1846{ + + { + para1846{[]int{2, 2, 1, 2, 1}}, + ans1846{2}, + }, + + { + para1846{[]int{100, 1, 1000}}, + ans1846{3}, + }, + + { + para1846{[]int{1, 2, 3, 4, 5}}, + ans1846{5}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 1846------------------------\n") + + for _, q := range qs { + _, p := q.ans1846, q.para1846 + fmt.Printf("【input】:%v 【output】:%v\n", p, maximumElementAfterDecrementingAndRearranging(p.arr)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/1846.Maximum-Element-After-Decreasing-and-Rearranging/README.md b/leetcode/1846.Maximum-Element-After-Decreasing-and-Rearranging/README.md new file mode 100644 index 000000000..2196f6bb4 --- /dev/null +++ b/leetcode/1846.Maximum-Element-After-Decreasing-and-Rearranging/README.md @@ -0,0 +1,103 @@ +# [1846. Maximum Element After Decreasing and Rearranging](https://leetcode.com/problems/maximum-element-after-decreasing-and-rearranging/) + + +## 题目 + +You are given an array of positive integers `arr`. Perform some operations (possibly none) on `arr` so that it satisfies these conditions: + +- The value of the **first** element in `arr` must be `1`. +- The absolute difference between any 2 adjacent elements must be **less than or equal to** `1`. In other words, `abs(arr[i] - arr[i - 1]) <= 1` for each `i` where `1 <= i < arr.length` (**0-indexed**). `abs(x)` is the absolute value of `x`. + +There are 2 types of operations that you can perform any number of times: + +- **Decrease** the value of any element of `arr` to a **smaller positive integer**. +- **Rearrange** the elements of `arr` to be in any order. + +Return *the **maximum** possible value of an element in* `arr` *after performing the operations to satisfy the conditions*. + +**Example 1:** + +``` +Input: arr = [2,2,1,2,1] +Output: 2 +Explanation: +We can satisfy the conditions by rearrangingarr so it becomes[1,2,2,2,1]. +The largest element inarr is 2. + +``` + +**Example 2:** + +``` +Input: arr = [100,1,1000] +Output: 3 +Explanation: +One possible way to satisfy the conditions is by doing the following: +1. Rearrangearr so it becomes[1,100,1000]. +2. Decrease the value of the second element to 2. +3. Decrease the value of the third element to 3. +Nowarr = [1,2,3], whichsatisfies the conditions. +The largest element inarr is 3. +``` + +**Example 3:** + +``` +Input: arr = [1,2,3,4,5] +Output: 5 +Explanation: The array already satisfies the conditions, and the largest element is 5. + +``` + +**Constraints:** + +- `1 <= arr.length <= 10^5` +- `1 <= arr[i] <= 10^9` + +## 题目大意 + +给你一个正整数数组 arr 。请你对 arr 执行一些操作（也可以不进行任何操作），使得数组满足以下条件： + +- arr 中 第一个 元素必须为 1 。 +- 任意相邻两个元素的差的绝对值 小于等于 1 ，也就是说，对于任意的 1 <= i < arr.length （数组下标从 0 开始），都满足 abs(arr[i] - arr[i - 1]) <= 1 。abs(x) 为 x 的绝对值。 + +你可以执行以下 2 种操作任意次： + +- 减小 arr 中任意元素的值，使其变为一个 更小的正整数 。 +- 重新排列 arr 中的元素，你可以以任意顺序重新排列。 + +请你返回执行以上操作后，在满足前文所述的条件下，arr 中可能的 最大值 。 + +## 解题思路 + +- 正整数数组 arr 第一个元素必须为 1，且两两元素绝对值小于等于 1，那么 arr 最大值肯定不大于 n。采用贪心的策略，先统计所有元素出现的次数，大于 n 的元素出现次数都累加到 n 上。然后从 1 扫描到 n，遇到“空隙”（出现次数为 0 的元素），便将最近一个出现次数大于 1 的元素“挪”过来填补“空隙”。题目所求最大值出现在，“填补空隙”之后，数组从左往右连续的最右端。 + +## 代码 + +```go +package leetcode + +func maximumElementAfterDecrementingAndRearranging(arr []int) int { + n := len(arr) + count := make([]int, n+1) + for _, v := range arr { + count[min(v, n)]++ + } + miss := 0 + for _, c := range count[1:] { + if c == 0 { + miss++ + } else { + miss -= min(c-1, miss) + } + } + return n - miss +} + +func min(a, b int) int { + if a < b { + return a + } + return b +} +``` \ No newline at end of file diff --git a/leetcode/1877.Minimize-Maximum-Pair-Sum-in-Array/1877. Minimize Maximum Pair Sum in Array.go b/leetcode/1877.Minimize-Maximum-Pair-Sum-in-Array/1877. Minimize Maximum Pair Sum in Array.go new file mode 100644 index 000000000..3d74fe3a1 --- /dev/null +++ b/leetcode/1877.Minimize-Maximum-Pair-Sum-in-Array/1877. Minimize Maximum Pair Sum in Array.go @@ -0,0 +1,19 @@ +package leetcode + +import "sort" + +func minPairSum(nums []int) int { + sort.Ints(nums) + n, res := len(nums), 0 + for i, val := range nums[:n/2] { + res = max(res, val+nums[n-1-i]) + } + return res +} + +func max(a, b int) int { + if a > b { + return a + } + return b +} diff --git a/leetcode/1877.Minimize-Maximum-Pair-Sum-in-Array/1877. Minimize Maximum Pair Sum in Array_test.go b/leetcode/1877.Minimize-Maximum-Pair-Sum-in-Array/1877. Minimize Maximum Pair Sum in Array_test.go new file mode 100644 index 000000000..c07aba6e9 --- /dev/null +++ b/leetcode/1877.Minimize-Maximum-Pair-Sum-in-Array/1877. Minimize Maximum Pair Sum in Array_test.go @@ -0,0 +1,62 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question1877 struct { + para1877 + ans1877 +} + +// para 是参数 +// one 代表第一个参数 +type para1877 struct { + nums []int +} + +// ans 是答案 +// one 代表第一个答案 +type ans1877 struct { + one int +} + +func Test_Problem1877(t *testing.T) { + + qs := []question1877{ + + { + para1877{[]int{2, 2, 1, 2, 1}}, + ans1877{3}, + }, + + { + para1877{[]int{100, 1, 1000}}, + ans1877{1001}, + }, + + { + para1877{[]int{1, 2, 3, 4, 5}}, + ans1877{6}, + }, + + { + para1877{[]int{3, 5, 2, 3}}, + ans1877{7}, + }, + + { + para1877{[]int{3, 5, 4, 2, 4, 6}}, + ans1877{8}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 1877------------------------\n") + + for _, q := range qs { + _, p := q.ans1877, q.para1877 + fmt.Printf("【input】:%v 【output】:%v\n", p, minPairSum(p.nums)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/1877.Minimize-Maximum-Pair-Sum-in-Array/README.md b/leetcode/1877.Minimize-Maximum-Pair-Sum-in-Array/README.md new file mode 100644 index 000000000..17ff53013 --- /dev/null +++ b/leetcode/1877.Minimize-Maximum-Pair-Sum-in-Array/README.md @@ -0,0 +1,81 @@ +# [1877. Minimize Maximum Pair Sum in Array](https://leetcode.com/problems/minimize-maximum-pair-sum-in-array/) + + +## 题目 + +The **pair sum** of a pair `(a,b)` is equal to `a + b`. The **maximum pair sum** is the largest **pair sum** in a list of pairs. + +- For example, if we have pairs `(1,5)`, `(2,3)`, and `(4,4)`, the **maximum pair sum** would be `max(1+5, 2+3, 4+4) = max(6, 5, 8) = 8`. + +Given an array `nums` of **even** length `n`, pair up the elements of `nums` into `n / 2` pairs such that: + +- Each element of `nums` is in **exactly one** pair, and +- The **maximum pair sum** is **minimized**. + +Return *the minimized **maximum pair sum** after optimally pairing up the elements*. + +**Example 1:** + +``` +Input: nums = [3,5,2,3] +Output: 7 +Explanation: The elements can be paired up into pairs (3,3) and (5,2). +The maximum pair sum is max(3+3, 5+2) = max(6, 7) = 7. +``` + +**Example 2:** + +``` +Input: nums = [3,5,4,2,4,6] +Output: 8 +Explanation: The elements can be paired up into pairs (3,5), (4,4), and (6,2). +The maximum pair sum is max(3+5, 4+4, 6+2) = max(8, 8, 8) = 8. +``` + +**Constraints:** + +- `n == nums.length` +- `2 <= n <= 105` +- `n` is **even**. +- `1 <= nums[i] <= 105` + +## 题目大意 + +一个数对 (a,b) 的 **数对和** 等于 a + b 。**最大数对和** 是一个数对数组中最大的 数对和 。 + +- 比方说，如果我们有数对 (1,5) ，(2,3) 和 (4,4)，**最大数对和** 为 max(1+5, 2+3, 4+4) = max(6, 5, 8) = 8 。 + +给你一个长度为 **偶数** n 的数组 nums ，请你将 nums 中的元素分成 n / 2 个数对，使得： + +- nums 中每个元素 **恰好** 在 一个 数对中，且 +- **最大数对和** 的值 **最小** 。 + +请你在最优数对划分的方案下，返回最小的 最大数对和 。 + +## 解题思路 + +- 要想最大数对和最小，那么最大的元素一定只能和最小的元素组合在一起，不然一定不是最小。当最大元素和最小元素组合在一起了，剩下的次最大元素也应该和次最小元素组合在一起。按照这个思路，先将数组从小到大排序，然后依次取出首尾元素，两两组合在一起。输出这些数对的最大值即为所求。 + +## 代码 + +```go +package leetcode + +import "sort" + +func minPairSum(nums []int) int { + sort.Ints(nums) + n, res := len(nums), 0 + for i, val := range nums[:n/2] { + res = max(res, val+nums[n-1-i]) + } + return res +} + +func max(a, b int) int { + if a > b { + return a + } + return b +} +``` \ No newline at end of file diff --git a/leetcode/1984.Minimum-Difference-Between-Highest-and-Lowest-of-K-Scores/1984.Minimum Difference Between Highest and Lowest of K Scores.go b/leetcode/1984.Minimum-Difference-Between-Highest-and-Lowest-of-K-Scores/1984.Minimum Difference Between Highest and Lowest of K Scores.go new file mode 100644 index 000000000..b4b381488 --- /dev/null +++ b/leetcode/1984.Minimum-Difference-Between-Highest-and-Lowest-of-K-Scores/1984.Minimum Difference Between Highest and Lowest of K Scores.go @@ -0,0 +1,18 @@ +package leetcode + +import "sort" + +func minimumDifference(nums []int, k int) int { + sort.Ints(nums) + minDiff := 100000 + 1 + for i := 0; i < len(nums); i++ { + if i+k-1 >= len(nums) { + break + } + diff := nums[i+k-1] - nums[i] + if diff < minDiff { + minDiff = diff + } + } + return minDiff +} diff --git a/leetcode/1984.Minimum-Difference-Between-Highest-and-Lowest-of-K-Scores/1984.Minimum Difference Between Highest and Lowest of K Scores_test.go b/leetcode/1984.Minimum-Difference-Between-Highest-and-Lowest-of-K-Scores/1984.Minimum Difference Between Highest and Lowest of K Scores_test.go new file mode 100644 index 000000000..90997ca78 --- /dev/null +++ b/leetcode/1984.Minimum-Difference-Between-Highest-and-Lowest-of-K-Scores/1984.Minimum Difference Between Highest and Lowest of K Scores_test.go @@ -0,0 +1,47 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question1984 struct { + para1984 + ans1984 +} + +// para 是参数 +type para1984 struct { + nums []int + k int +} + +// ans 是答案 +type ans1984 struct { + ans int +} + +func Test_Problem1984(t *testing.T) { + + qs := []question1984{ + + { + para1984{[]int{90}, 1}, + ans1984{0}, + }, + + { + para1984{[]int{9, 4, 1, 7}, 2}, + ans1984{2}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 1984------------------------\n") + + for _, q := range qs { + _, p := q.ans1984, q.para1984 + fmt.Printf("【input】:%v ", p) + fmt.Printf("【output】:%v \n", minimumDifference(p.nums, p.k)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/1984.Minimum-Difference-Between-Highest-and-Lowest-of-K-Scores/README.md b/leetcode/1984.Minimum-Difference-Between-Highest-and-Lowest-of-K-Scores/README.md new file mode 100644 index 000000000..fe7146c04 --- /dev/null +++ b/leetcode/1984.Minimum-Difference-Between-Highest-and-Lowest-of-K-Scores/README.md @@ -0,0 +1,71 @@ +# [1984. Minimum Difference Between Highest and Lowest of K Scores](https://leetcode.com/problems/minimum-difference-between-highest-and-lowest-of-k-scores/) + +## 题目 + +You are given a 0-indexed integer array nums, where nums[i] represents the score of the ith student. You are also given an integer k. + +Pick the scores of any k students from the array so that the difference between the highest and the lowest of the k scores is minimized. + +Return the minimum possible difference. + +**Example 1:** + + Input: nums = [90], k = 1 + Output: 0 + Explanation: There is one way to pick score(s) of one student: + - [90]. The difference between the highest and lowest score is 90 - 90 = 0. + The minimum possible difference is 0. + +**Example 2:** + + Input: nums = [9,4,1,7], k = 2 + Output: 2 + Explanation: There are six ways to pick score(s) of two students: + - [9,4,1,7]. The difference between the highest and lowest score is 9 - 4 = 5. + - [9,4,1,7]. The difference between the highest and lowest score is 9 - 1 = 8. + - [9,4,1,7]. The difference between the highest and lowest score is 9 - 7 = 2. + - [9,4,1,7]. The difference between the highest and lowest score is 4 - 1 = 3. + - [9,4,1,7]. The difference between the highest and lowest score is 7 - 4 = 3. + - [9,4,1,7]. The difference between the highest and lowest score is 7 - 1 = 6. + The minimum possible difference is 2. + +**Constraints:** + +- 1 <= k <= nums.length <= 1000 +- 0 <= nums[i] <= 100000 + +## 题目大意 + +给你一个下标从 0 开始的整数数组 nums ，其中 nums[i] 表示第 i 名学生的分数。另给你一个整数 k 。 + +从数组中选出任意 k 名学生的分数，使这 k 个分数间最高分和最低分的差值达到最小化 。 + +返回可能的最小差值 。 + +## 解题思路 + +- nums 排序 +- 求出nums[i+k-1] - nums[i]中的最小差值 + +## 代码 + +```go +package leetcode + +import "sort" + +func minimumDifference(nums []int, k int) int { + sort.Ints(nums) + minDiff := 100000 + 1 + for i := 0; i < len(nums); i++ { + if i+k-1 >= len(nums) { + break + } + diff := nums[i+k-1] - nums[i] + if diff < minDiff { + minDiff = diff + } + } + return minDiff +} +``` \ No newline at end of file diff --git a/leetcode/2021.Brightest-Position-on-Street/2021. Brightest Position on Street.go b/leetcode/2021.Brightest-Position-on-Street/2021. Brightest Position on Street.go new file mode 100644 index 000000000..c667e2465 --- /dev/null +++ b/leetcode/2021.Brightest-Position-on-Street/2021. Brightest Position on Street.go @@ -0,0 +1,33 @@ +package leetcode + +import ( + "sort" +) + +type lightItem struct { + index int + sign int +} + +func brightestPosition(lights [][]int) int { + lightMap, lightItems := map[int]int{}, []lightItem{} + for _, light := range lights { + lightMap[light[0]-light[1]] += 1 + lightMap[light[0]+light[1]+1] -= 1 + } + for k, v := range lightMap { + lightItems = append(lightItems, lightItem{index: k, sign: v}) + } + sort.SliceStable(lightItems, func(i, j int) bool { + return lightItems[i].index < lightItems[j].index + }) + res, border, tmp := 0, 0, 0 + for _, v := range lightItems { + tmp += v.sign + if border < tmp { + res = v.index + border = tmp + } + } + return res +} diff --git a/leetcode/2021.Brightest-Position-on-Street/2021. Brightest Position on Street_test.go b/leetcode/2021.Brightest-Position-on-Street/2021. Brightest Position on Street_test.go new file mode 100644 index 000000000..5247fbf6e --- /dev/null +++ b/leetcode/2021.Brightest-Position-on-Street/2021. Brightest Position on Street_test.go @@ -0,0 +1,56 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question2021 struct { + para2021 + ans2021 +} + +// para 是参数 +type para2021 struct { + lights [][]int +} + +// ans 是答案 +type ans2021 struct { + ans int +} + +func Test_Problem2021(t *testing.T) { + + qs := []question2021{ + + { + para2021{[][]int{{-3, 2}, {1, 2}, {3, 3}}}, + ans2021{-1}, + }, + + { + para2021{[][]int{{1, 0}, {0, 1}}}, + ans2021{1}, + }, + + { + para2021{[][]int{{1, 2}}}, + ans2021{-1}, + }, + + { + para2021{[][]int{{1, 1}, {2, 4}, {-1, 0}, {-3, 5}, {1, 2}}}, + ans2021{-1}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 2021------------------------\n") + + for _, q := range qs { + _, p := q.ans2021, q.para2021 + fmt.Printf("【input】:%v ", p) + fmt.Printf("【output】:%v \n", brightestPosition(p.lights)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/2021.Brightest-Position-on-Street/README.md b/leetcode/2021.Brightest-Position-on-Street/README.md new file mode 100644 index 000000000..3456fc7a0 --- /dev/null +++ b/leetcode/2021.Brightest-Position-on-Street/README.md @@ -0,0 +1,109 @@ +# [2021. Brightest Position on Street](https://leetcode.com/problems/brightest-position-on-street/) + + +## 题目 + +A perfectly straight street is represented by a number line. The street has street lamp(s) on it and is represented by a 2D integer array `lights`. Each `lights[i] = [positioni, rangei]` indicates that there is a street lamp at position `positioni` that lights up the area from `[positioni - rangei, positioni + rangei]` (**inclusive**). + +The **brightness** of a position `p` is defined as the number of street lamp that light up the position `p`. + +Given `lights`, return *the **brightest** position on the street. If there are multiple brightest positions, return the **smallest** one.* + +**Example 1:** + +![https://assets.leetcode.com/uploads/2021/09/28/image-20210928155140-1.png](https://assets.leetcode.com/uploads/2021/09/28/image-20210928155140-1.png) + +``` +Input: lights = [[-3,2],[1,2],[3,3]] +Output: -1 +Explanation: +The first street lamp lights up the area from [(-3) - 2, (-3) + 2] = [-5, -1]. +The second street lamp lights up the area from [1 - 2, 1 + 2] = [-1, 3]. +The third street lamp lights up the area from [3 - 3, 3 + 3] = [0, 6]. + +Position -1 has a brightness of 2, illuminated by the first and second street light. +Positions 0, 1, 2, and 3 have a brightness of 2, illuminated by the second and third street light. +Out of all these positions, -1 is the smallest, so return it. + +``` + +**Example 2:** + +``` +Input: lights = [[1,0],[0,1]] +Output: 1 +Explanation: +The first street lamp lights up the area from [1 - 0, 1 + 0] = [1, 1]. +The second street lamp lights up the area from [0 - 1, 0 + 1] = [-1, 1]. + +Position 1 has a brightness of 2, illuminated by the first and second street light. +Return 1 because it is the brightest position on the street. + +``` + +**Example 3:** + +``` +Input: lights = [[1,2]] +Output: -1 +Explanation: +The first street lamp lights up the area from [1 - 2, 1 + 2] = [-1, 3]. + +Positions -1, 0, 1, 2, and 3 have a brightness of 1, illuminated by the first street light. +Out of all these positions, -1 is the smallest, so return it. + +``` + +**Constraints:** + +- `1 <= lights.length <= 105` +- `lights[i].length == 2` +- `108 <= positioni <= 108` +- `0 <= rangei <= 108` + +## 题目大意 + +一条完全笔直的街道由一条数字线表示。街道上有路灯，由二维数据表示。每个 `lights[i] = [positioni, rangei]` 表示位置 `i` 处有一盏路灯，灯可以照亮从 `[positioni - rangei, positioni + rangei]` （含）的区域。 位置 `p` 的亮度定义为点亮位置 `p` 的路灯数量。 给定路灯，返回街道上最亮的位置。如果有多个最亮的位置，则返回最小的一个。 + +## 解题思路 + +- 先将每个路灯的起始和终点位置计算出来。这样我们得到了一堆坐标点。假设灯照亮的范围是 [A, B]，那么在坐标轴上 A 坐标点处 + 1， B + 1 坐标点处 -1 。这样处理的含义是：坐标点 A 可以被一盏灯照亮，所以它照亮次数加一，坐标点 B + 1 出了灯照亮的范围了，所以照亮次数减一。那么从坐标轴坐标开始扫一遍，每次遇到 + 1 的时候就 + 1，遇到 - 1 的地方就 - 1。如此可以算出某个坐标点处，可以被灯照亮的总次数。 +- 需要注意的点是，题目给的测试数据可能会有单点照亮的情况，即某一盏灯只照亮一个坐标点，灯照范围为 0。同一个坐标点也可能是多个灯的起点。用一个 map 去重坐标点即可。 + +## 代码 + +```go +package leetcode + +import ( + "sort" +) + +type lightItem struct { + index int + sign int +} + +func brightestPosition(lights [][]int) int { + lightMap, lightItems := map[int]int{}, []lightItem{} + for _, light := range lights { + lightMap[light[0]-light[1]] += 1 + lightMap[light[0]+light[1]+1] -= 1 + } + for k, v := range lightMap { + lightItems = append(lightItems, lightItem{index: k, sign: v}) + } + sort.SliceStable(lightItems, func(i, j int) bool { + return lightItems[i].index < lightItems[j].index + }) + res, border, tmp := 0, 0, 0 + for _, v := range lightItems { + tmp += v.sign + if border < tmp { + res = v.index + border = tmp + } + } + return res +} +``` \ No newline at end of file diff --git a/leetcode/2022.Convert-1D-Array-Into-2D-Array/2022. Convert 1D Array Into 2D Array.go b/leetcode/2022.Convert-1D-Array-Into-2D-Array/2022. Convert 1D Array Into 2D Array.go new file mode 100644 index 000000000..28dd363b8 --- /dev/null +++ b/leetcode/2022.Convert-1D-Array-Into-2D-Array/2022. Convert 1D Array Into 2D Array.go @@ -0,0 +1,12 @@ +package leetcode + +func construct2DArray(original []int, m int, n int) [][]int { + if m*n != len(original) { + return [][]int{} + } + res := make([][]int, m) + for i := 0; i < m; i++ { + res[i] = original[n*i : n*(i+1)] + } + return res +} diff --git a/leetcode/2022.Convert-1D-Array-Into-2D-Array/2022. Convert 1D Array Into 2D Array_test.go b/leetcode/2022.Convert-1D-Array-Into-2D-Array/2022. Convert 1D Array Into 2D Array_test.go new file mode 100644 index 000000000..39f540d38 --- /dev/null +++ b/leetcode/2022.Convert-1D-Array-Into-2D-Array/2022. Convert 1D Array Into 2D Array_test.go @@ -0,0 +1,64 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question2022 struct { + para2022 + ans2022 +} + +// para 是参数 +// one 代表第一个参数 +type para2022 struct { + original []int + m int + n int +} + +// ans 是答案 +// one 代表第一个答案 +type ans2022 struct { + one [][]int +} + +func Test_Problem2022(t *testing.T) { + + qs := []question2022{ + + { + para2022{[]int{1, 2, 3, 4}, 2, 2}, + ans2022{[][]int{{1, 2}, {3, 4}}}, + }, + + { + para2022{[]int{1, 2, 3}, 1, 3}, + ans2022{[][]int{{1, 2, 3}}}, + }, + + { + para2022{[]int{1, 2}, 1, 1}, + ans2022{[][]int{{}}}, + }, + + { + para2022{[]int{3}, 1, 2}, + ans2022{[][]int{{3}}}, + }, + + { + para2022{[]int{1, 1, 1, 1}, 4, 1}, + ans2022{[][]int{{1, 1, 1, 1}}}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 2022------------------------\n") + + for _, q := range qs { + _, p := q.ans2022, q.para2022 + fmt.Printf("【input】:%v 【output】:%v\n", p, construct2DArray(p.original, p.m, p.n)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/2022.Convert-1D-Array-Into-2D-Array/README.md b/leetcode/2022.Convert-1D-Array-Into-2D-Array/README.md new file mode 100644 index 000000000..83899096d --- /dev/null +++ b/leetcode/2022.Convert-1D-Array-Into-2D-Array/README.md @@ -0,0 +1,77 @@ +# [2022. Convert 1D Array Into 2D Array](https://leetcode.com/problems/convert-1d-array-into-2d-array/) + +## 题目 + +You are given a **0-indexed** 1-dimensional (1D) integer array `original`, and two integers, `m` and `n`. You are tasked with creating a 2-dimensional (2D) array with `m` rows and `n` columns using **all** the elements from `original`. + +The elements from indices `0` to `n - 1` (**inclusive**) of `original` should form the first row of the constructed 2D array, the elements from indices `n` to `2 * n - 1` (**inclusive**) should form the second row of the constructed 2D array, and so on. + +Return *an* `m x n` *2D array constructed according to the above procedure, or an empty 2D array if it is impossible*. + +**Example 1:** + +![https://assets.leetcode.com/uploads/2021/08/26/image-20210826114243-1.png](https://assets.leetcode.com/uploads/2021/08/26/image-20210826114243-1.png) + +``` +Input: original = [1,2,3,4], m = 2, n = 2 +Output: [[1,2],[3,4]] +Explanation: The constructed 2D array should contain 2 rows and 2 columns. +The first group of n=2 elements in original, [1,2], becomes the first row in the constructed 2D array. +The second group of n=2 elements in original, [3,4], becomes the second row in the constructed 2D array. + +``` + +**Example 2:** + +``` +Input: original = [1,2,3], m = 1, n = 3 +Output: [[1,2,3]] +Explanation: The constructed 2D array should contain 1 row and 3 columns. +Put all three elements in original into the first row of the constructed 2D array. + +``` + +**Example 3:** + +``` +Input: original = [1,2], m = 1, n = 1 +Output: [] +Explanation: There are 2 elements in original. +It is impossible to fit 2 elements in a 1x1 2D array, so return an empty 2D array. + +``` + +**Constraints:** + +- `1 <= original.length <= 5 * 104` +- `1 <= original[i] <= 105` +- `1 <= m, n <= 4 * 104` + +## 题目大意 + +给你一个下标从 0 开始的一维整数数组 original 和两个整数 m 和  n 。你需要使用 original 中 所有 元素创建一个 m 行 n 列的二维数组。 + +original 中下标从 0 到 n - 1 （都 包含 ）的元素构成二维数组的第一行，下标从 n 到 2 * n - 1 （都 包含 ）的元素构成二维数组的第二行，依此类推。 + +请你根据上述过程返回一个 m x n 的二维数组。如果无法构成这样的二维数组，请你返回一个空的二维数组。 + +## 解题思路 + +- 简单题。从一维数组 original 中依次取出每行 n 个元素，顺序放到 m 行中。此题中，如果 m*n 大于或者小于 original 的长度，都输出空数组。 + +## 代码 + +```go +package leetcode + +func construct2DArray(original []int, m int, n int) [][]int { + if m*n != len(original) { + return [][]int{} + } + res := make([][]int, m) + for i := 0; i < m; i++ { + res[i] = original[n*i : n*(i+1)] + } + return res +} +``` \ No newline at end of file diff --git a/leetcode/2037.Minimum-Number-of-Moves-to-Seat-Everyone/2037.Minimum Number of Moves to Seat Everyone.go b/leetcode/2037.Minimum-Number-of-Moves-to-Seat-Everyone/2037.Minimum Number of Moves to Seat Everyone.go new file mode 100644 index 000000000..89cae6ff4 --- /dev/null +++ b/leetcode/2037.Minimum-Number-of-Moves-to-Seat-Everyone/2037.Minimum Number of Moves to Seat Everyone.go @@ -0,0 +1,21 @@ +package leetcode + +import "sort" + +func minMovesToSeat(seats []int, students []int) int { + sort.Ints(seats) + sort.Ints(students) + n := len(students) + moves := 0 + for i := 0; i < n; i++ { + moves += abs(seats[i], students[i]) + } + return moves +} + +func abs(a, b int) int { + if a > b { + return a - b + } + return b - a +} diff --git a/leetcode/2037.Minimum-Number-of-Moves-to-Seat-Everyone/2037.Minimum Number of Moves to Seat Everyone_test.go b/leetcode/2037.Minimum-Number-of-Moves-to-Seat-Everyone/2037.Minimum Number of Moves to Seat Everyone_test.go new file mode 100644 index 000000000..17239790e --- /dev/null +++ b/leetcode/2037.Minimum-Number-of-Moves-to-Seat-Everyone/2037.Minimum Number of Moves to Seat Everyone_test.go @@ -0,0 +1,52 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question2037 struct { + para2037 + ans2037 +} + +// para 是参数 +type para2037 struct { + seats []int + students []int +} + +// ans 是答案 +type ans2037 struct { + ans int +} + +func Test_Problem2037(t *testing.T) { + + qs := []question2037{ + + { + para2037{[]int{3, 1, 5}, []int{2, 7, 4}}, + ans2037{4}, + }, + + { + para2037{[]int{4, 1, 5, 9}, []int{1, 3, 2, 6}}, + ans2037{7}, + }, + + { + para2037{[]int{2, 2, 6, 6}, []int{1, 3, 2, 6}}, + ans2037{4}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 2037------------------------\n") + + for _, q := range qs { + _, p := q.ans2037, q.para2037 + fmt.Printf("【input】:%v ", p) + fmt.Printf("【output】:%v \n", minMovesToSeat(p.seats, p.students)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/2037.Minimum-Number-of-Moves-to-Seat-Everyone/README.md b/leetcode/2037.Minimum-Number-of-Moves-to-Seat-Everyone/README.md new file mode 100644 index 000000000..beec7e76c --- /dev/null +++ b/leetcode/2037.Minimum-Number-of-Moves-to-Seat-Everyone/README.md @@ -0,0 +1,94 @@ +# [2037. Minimum Number of Moves to Seat Everyone](https://leetcode.com/problems/minimum-number-of-moves-to-seat-everyone/) + +## 题目 + +There are n seats and n students in a room. You are given an array seats of length n, where seats[i] is the position of the ith seat. You are also given the array students of length n, where students[j] is the position of the jth student. + +You may perform the following move any number of times: + +- Increase or decrease the position of the ith student by 1 (i.e., moving the ith student from position x to x + 1 or x - 1) + +Return the minimum number of moves required to move each student to a seat such that no two students are in the same seat. + +Note that there may be multiple seats or students in the same position at the beginning. + +**Example 1:** + + Input: seats = [3,1,5], students = [2,7,4] + Output: 4 + Explanation: The students are moved as follows: + - The first student is moved from from position 2 to position 1 using 1 move. + - The second student is moved from from position 7 to position 5 using 2 moves. + - The third student is moved from from position 4 to position 3 using 1 move. + In total, 1 + 2 + 1 = 4 moves were used. + +**Example 2:** + + Input: seats = [4,1,5,9], students = [1,3,2,6] + Output: 7 + Explanation: The students are moved as follows: + - The first student is not moved. + - The second student is moved from from position 3 to position 4 using 1 move. + - The third student is moved from from position 2 to position 5 using 3 moves. + - The fourth student is moved from from position 6 to position 9 using 3 moves. + In total, 0 + 1 + 3 + 3 = 7 moves were used. + +**Example 3:** + + Input: seats = [2,2,6,6], students = [1,3,2,6] + Output: 4 + Explanation: Note that there are two seats at position 2 and two seats at position 6. + The students are moved as follows: + - The first student is moved from from position 1 to position 2 using 1 move. + - The second student is moved from from position 3 to position 6 using 3 moves. + - The third student is not moved. + - The fourth student is not moved. + In total, 1 + 3 + 0 + 0 = 4 moves were used. + +**Constraints:** + +- n == seats.length == students.length +- 1 <= n <= 100 +- 1 <= seats[i], students[j] <= 100 + +## 题目大意 + +一个房间里有 n 个座位和 n 名学生，房间用一个数轴表示。给你一个长度为 n 的数组 seats，其中 seats[i] 是第 i 个座位的位置。同时给你一个长度为 n 的数组 students ，其中 students[j] 是第 j 位学生的位置。 + +你可以执行以下操作任意次： + +增加或者减少第 i 位学生的位置，每次变化量为 1（也就是将第 i 位学生从位置 x 移动到 x + 1或者 x - 1） + +请你返回使所有学生都有座位坐的最少移动次数，并确保没有两位学生的座位相同。 + +请注意，初始时有可能有多个座位或者多位学生在 同一位置。 + +## 解题思路 + +- 排序+模拟计算 + +# 代码 + +```go +package leetcode + +import "sort" + +func minMovesToSeat(seats []int, students []int) int { + sort.Ints(seats) + sort.Ints(students) + n := len(students) + moves := 0 + for i := 0; i < n; i++ { + moves += abs(seats[i], students[i]) + } + return moves +} + +func abs(a, b int) int { + if a > b { + return a - b + } + return b - a +} +``` \ No newline at end of file diff --git a/leetcode/2038.Remove-Colored-Pieces-if-Both-Neighbors-are-the-Same-Color/2038.Remove Colored Pieces if Both Neighbors are the Same Color.go b/leetcode/2038.Remove-Colored-Pieces-if-Both-Neighbors-are-the-Same-Color/2038.Remove Colored Pieces if Both Neighbors are the Same Color.go new file mode 100644 index 000000000..8962f957a --- /dev/null +++ b/leetcode/2038.Remove-Colored-Pieces-if-Both-Neighbors-are-the-Same-Color/2038.Remove Colored Pieces if Both Neighbors are the Same Color.go @@ -0,0 +1,25 @@ +package leetcode + +func winnerOfGame(colors string) bool { + As, Bs := 0, 0 + Acont, Bcont := 0, 0 + for _, color := range colors { + if color == 'A' { + Acont += 1 + Bcont = 0 + } else { + Bcont += 1 + Acont = 0 + } + if Acont >= 3 { + As += Acont - 2 + } + if Bcont >= 3 { + Bs += Bcont - 2 + } + } + if As > Bs { + return true + } + return false +} diff --git a/leetcode/2038.Remove-Colored-Pieces-if-Both-Neighbors-are-the-Same-Color/2038.Remove Colored Pieces if Both Neighbors are the Same Color_test.go b/leetcode/2038.Remove-Colored-Pieces-if-Both-Neighbors-are-the-Same-Color/2038.Remove Colored Pieces if Both Neighbors are the Same Color_test.go new file mode 100644 index 000000000..567eea1fe --- /dev/null +++ b/leetcode/2038.Remove-Colored-Pieces-if-Both-Neighbors-are-the-Same-Color/2038.Remove Colored Pieces if Both Neighbors are the Same Color_test.go @@ -0,0 +1,51 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question2038 struct { + para2038 + ans2038 +} + +// para 是参数 +type para2038 struct { + colors string +} + +// ans 是答案 +type ans2038 struct { + ans bool +} + +func Test_Problem2038(t *testing.T) { + + qs := []question2038{ + + { + para2038{"AAABABB"}, + ans2038{true}, + }, + + { + para2038{"AA"}, + ans2038{false}, + }, + + { + para2038{"ABBBBBBBAAA"}, + ans2038{false}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 2038------------------------\n") + + for _, q := range qs { + _, p := q.ans2038, q.para2038 + fmt.Printf("【input】:%v ", p.colors) + fmt.Printf("【output】:%v \n", winnerOfGame(p.colors)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/2038.Remove-Colored-Pieces-if-Both-Neighbors-are-the-Same-Color/README.md b/leetcode/2038.Remove-Colored-Pieces-if-Both-Neighbors-are-the-Same-Color/README.md new file mode 100644 index 000000000..fdf3e5525 --- /dev/null +++ b/leetcode/2038.Remove-Colored-Pieces-if-Both-Neighbors-are-the-Same-Color/README.md @@ -0,0 +1,105 @@ +# [2038. Remove Colored Pieces if Both Neighbors are the Same Color](https://leetcode.com/problems/remove-colored-pieces-if-both-neighbors-are-the-same-color/) + +## 题目 + +There are n pieces arranged in a line, and each piece is colored either by 'A' or by 'B'. You are given a string colors of length n where colors[i] is the color of the ith piece. + +Alice and Bob are playing a game where they take alternating turns removing pieces from the line. In this game, Alice moves first. + +- Alice is only allowed to remove a piece colored 'A' if both its neighbors are also colored 'A'. She is not allowed to remove pieces that are colored 'B'. +- Bob is only allowed to remove a piece colored 'B' if both its neighbors are also colored 'B'. He is not allowed to remove pieces that are colored 'A'. +- Alice and Bob cannot remove pieces from the edge of the line. +- If a player cannot make a move on their turn, that player loses and the other player wins. + +Assuming Alice and Bob play optimally, return true if Alice wins, or return false if Bob wins. + +**Example 1:** + + Input: colors = "AAABABB" + Output: true + Explanation: + AAABABB -> AABABB + Alice moves first. + She removes the second 'A' from the left since that is the only 'A' whose neighbors are both 'A'. + + Now it's Bob's turn. + Bob cannot make a move on his turn since there are no 'B's whose neighbors are both 'B'. + Thus, Alice wins, so return true. + +**Example 2:** + + Input: colors = "AA" + Output: false + Explanation: + Alice has her turn first. + There are only two 'A's and both are on the edge of the line, so she cannot move on her turn. + Thus, Bob wins, so return false. + +**Example 3:** + + Input: colors = "ABBBBBBBAAA" + Output: false + Explanation: + ABBBBBBBAAA -> ABBBBBBBAA + Alice moves first. + Her only option is to remove the second to last 'A' from the right. + + ABBBBBBBAA -> ABBBBBBAA + Next is Bob's turn. + He has many options for which 'B' piece to remove. He can pick any. + + On Alice's second turn, she has no more pieces that she can remove. + Thus, Bob wins, so return false. + +**Constraints:** + +- 1 <= colors.length <= 100000 +- colors consists of only the letters 'A' and 'B' + +## 题目大意 + +总共有 n 个颜色片段排成一列，每个颜色片段要么是 'A' 要么是 'B' 。给你一个长度为 n 的字符串 colors ，其中 colors[i] 表示第 i 个颜色片段的颜色。 + +Alice 和 Bob 在玩一个游戏，他们轮流从这个字符串中删除颜色。Alice 先手。 + +- 如果一个颜色片段为 'A' 且相邻两个颜色都是颜色 'A'，那么 Alice 可以删除该颜色片段。Alice不可以删除任何颜色 'B' 片段。 +- 如果一个颜色片段为 'B'且相邻两个颜色都是颜色 'B' ，那么 Bob 可以删除该颜色片段。Bob 不可以删除任何颜色 'A' 片段。 +- Alice 和 Bob 不能从字符串两端删除颜色片段。 +- 如果其中一人无法继续操作，则该玩家 输掉游戏且另一玩家 获胜。 + +假设 Alice 和 Bob 都采用最优策略，如果 Alice 获胜，请返回true，否则 Bob 获胜，返回false。 + +## 解题思路 + +- 统计 Alice 和 Bob 分别可以操作的次数记为 As，Bs +- 因为 Alice 先手，所以只要 As 大于 Bs，Alice 获胜返回 true，否则 Bob 获胜返回 false + +# 代码 + +```go +package leetcode + +func winnerOfGame(colors string) bool { + As, Bs := 0, 0 + Acont, Bcont := 0, 0 + for _, color := range colors { + if color == 'A' { + Acont += 1 + Bcont = 0 + } else { + Bcont += 1 + Acont = 0 + } + if Acont >= 3 { + As += Acont - 2 + } + if Bcont >= 3 { + Bs += Bcont - 2 + } + } + if As > Bs { + return true + } + return false +} +``` \ No newline at end of file diff --git a/leetcode/2043.Simple-Bank-System/2043.Simple Bank System.go b/leetcode/2043.Simple-Bank-System/2043.Simple Bank System.go new file mode 100644 index 000000000..025ce2480 --- /dev/null +++ b/leetcode/2043.Simple-Bank-System/2043.Simple Bank System.go @@ -0,0 +1,44 @@ +package leetcode + +type Bank struct { + accounts []int64 + n int +} + +func Constructor(balance []int64) Bank { + return Bank{ + accounts: balance, + n: len(balance), + } +} + +func (this *Bank) Transfer(account1 int, account2 int, money int64) bool { + if account1 > this.n || account2 > this.n { + return false + } + if this.accounts[account1-1] < money { + return false + } + this.accounts[account1-1] -= money + this.accounts[account2-1] += money + return true +} + +func (this *Bank) Deposit(account int, money int64) bool { + if account > this.n { + return false + } + this.accounts[account-1] += money + return true +} + +func (this *Bank) Withdraw(account int, money int64) bool { + if account > this.n { + return false + } + if this.accounts[account-1] < money { + return false + } + this.accounts[account-1] -= money + return true +} diff --git a/leetcode/2043.Simple-Bank-System/2043.Simple Bank System_test.go b/leetcode/2043.Simple-Bank-System/2043.Simple Bank System_test.go new file mode 100644 index 000000000..96908986c --- /dev/null +++ b/leetcode/2043.Simple-Bank-System/2043.Simple Bank System_test.go @@ -0,0 +1,62 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question2043 struct { + para2043 + ans2043 +} + +// para 是参数 +type para2043 struct { + ops []string + para [][]int64 +} + +// ans 是答案 +type ans2043 struct { + ans []bool +} + +func Test_Problem2043(t *testing.T) { + + qs := []question2043{ + + { + para2043{ + []string{"Bank", "withdraw", "transfer", "deposit", "transfer", "withdraw"}, + [][]int64{{10, 100, 20, 50, 30}, {3, 10}, {5, 1, 20}, {5, 20}, {3, 4, 15}, {10, 50}}}, + ans2043{[]bool{true, true, true, false, false}}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 2043------------------------\n") + + for _, q := range qs { + var b Bank + var res []bool + _, p := q.ans2043, q.para2043 + for i, op := range p.ops { + if op == "Bank" { + b = Constructor(q.para[i]) + } else if op == "withdraw" { + isSuccess := b.Withdraw(int(p.para[i][0]), p.para[i][1]) + res = append(res, isSuccess) + } else if op == "transfer" { + isSuccess := b.Transfer(int(p.para[i][0]), int(p.para[i][0]), p.para[i][2]) + res = append(res, isSuccess) + } else if op == "deposit" { + isSuccess := b.Deposit(int(p.para[i][0]), p.para[i][1]) + res = append(res, isSuccess) + } else { + fmt.Println("unknown operation") + } + } + fmt.Printf("【input】:%v \n", p) + fmt.Printf("【output】:%v \n", res) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/2043.Simple-Bank-System/README.md b/leetcode/2043.Simple-Bank-System/README.md new file mode 100644 index 000000000..abae43d3b --- /dev/null +++ b/leetcode/2043.Simple-Bank-System/README.md @@ -0,0 +1,113 @@ +# [2043. Simple Bank System](https://leetcode.com/problems/simple-bank-system/) + +## 题目 + +You have been tasked with writing a program for a popular bank that will automate all its incoming transactions (transfer, deposit, and withdraw). The bank has n accounts numbered from 1 to n. The initial balance of each account is stored in a 0-indexed integer array balance, with the (i + 1)th account having an initial balance of balance[i]. + +Execute all the valid transactions. A transaction is valid if: + +- The given account number(s) are between 1 and n, and +- The amount of money withdrawn or transferred from is less than or equal to the balance of the account. + +Implement the Bank class: + +- Bank(long[] balance) Initializes the object with the 0-indexed integer array balance. +- boolean transfer(int account1, int account2, long money) Transfers money dollars from the account numbered account1 to the account numbered account2. Return true if the transaction was successful, false otherwise. +- boolean deposit(int account, long money) Deposit money dollars into the account numbered account. Return true if the transaction was successful, false otherwise. +- boolean withdraw(int account, long money) Withdraw money dollars from the account numbered account. Return true if the transaction was successful, false otherwise. + +**Example 1:** + + Input + ["Bank", "withdraw", "transfer", "deposit", "transfer", "withdraw"] + [[[10, 100, 20, 50, 30]], [3, 10], [5, 1, 20], [5, 20], [3, 4, 15], [10, 50]] + Output + [null, true, true, true, false, false] + + Explanation + Bank bank = new Bank([10, 100, 20, 50, 30]); + bank.withdraw(3, 10); // return true, account 3 has a balance of $20, so it is valid to withdraw $10. + // Account 3 has $20 - $10 = $10. + bank.transfer(5, 1, 20); // return true, account 5 has a balance of $30, so it is valid to transfer $20. + // Account 5 has $30 - $20 = $10, and account 1 has $10 + $20 = $30. + bank.deposit(5, 20); // return true, it is valid to deposit $20 to account 5. + // Account 5 has $10 + $20 = $30. + bank.transfer(3, 4, 15); // return false, the current balance of account 3 is $10, + // so it is invalid to transfer $15 from it. + bank.withdraw(10, 50); // return false, it is invalid because account 10 does not exist. + +**Constraints:** + +- n == balance.length +- 1 <= n, account, account1, account2 <= 100000 +- 0 <= balance[i], money <= 1000000000000 +- At most 104 calls will be made to each function transfer, deposit, withdraw. + +## 题目大意 + +你的任务是为一个很受欢迎的银行设计一款程序，以自动化执行所有传入的交易（转账，存款和取款）。银行共有 n 个账户，编号从 1 到 n 。每个账号的初始余额存储在一个下标从 0 开始的整数数组 balance 中，其中第 (i + 1) 个账户的初始余额是 balance[i] 。 + +请你执行所有 有效的 交易。如果满足下面全部条件，则交易 有效 ： + +- 指定的账户数量在 1 和 n 之间，且 +- 取款或者转账需要的钱的总数 小于或者等于 账户余额。 + +实现 Bank 类： + +- Bank(long[] balance) 使用下标从 0 开始的整数数组 balance 初始化该对象。 +- boolean transfer(int account1, int account2, long money) 从编号为 account1 的账户向编号为 account2 的账户转帐 money 美元。如果交易成功，返回 true ，否则，返回 false 。 +- boolean deposit(int account, long money) 向编号为 account 的账户存款 money 美元。如果交易成功，返回 true ；否则，返回 false 。 +- boolean withdraw(int account, long money) 从编号为 account 的账户取款 money 美元。如果交易成功，返回 true ；否则，返回 false 。 + +## 解题思路 + + 根据题意进行简单模拟 + +# 代码 + +```go +package leetcode + +type Bank struct { + accounts []int64 + n int +} + +func Constructor(balance []int64) Bank { + return Bank{ + accounts: balance, + n: len(balance), + } +} + +func (this *Bank) Transfer(account1 int, account2 int, money int64) bool { + if account1 > this.n || account2 > this.n { + return false + } + if this.accounts[account1-1] < money { + return false + } + this.accounts[account1-1] -= money + this.accounts[account2-1] += money + return true +} + +func (this *Bank) Deposit(account int, money int64) bool { + if account > this.n { + return false + } + this.accounts[account-1] += money + return true +} + +func (this *Bank) Withdraw(account int, money int64) bool { + if account > this.n { + return false + } + if this.accounts[account-1] < money { + return false + } + this.accounts[account-1] -= money + return true +} +``` \ No newline at end of file diff --git a/leetcode/2096.Step-By-Step-Directions-From-a-Binary-Tree-Node-to-Another/2096. Step-By-Step Directions From a Binary Tree Node to Another.go b/leetcode/2096.Step-By-Step-Directions-From-a-Binary-Tree-Node-to-Another/2096. Step-By-Step Directions From a Binary Tree Node to Another.go new file mode 100644 index 000000000..cd4f10897 --- /dev/null +++ b/leetcode/2096.Step-By-Step-Directions-From-a-Binary-Tree-Node-to-Another/2096. Step-By-Step Directions From a Binary Tree Node to Another.go @@ -0,0 +1,77 @@ +package leetcode + +import ( + "github.com/halfrost/LeetCode-Go/structures" +) + +// TreeNode define +type TreeNode = structures.TreeNode + +/** + * Definition for a binary tree node. + * type TreeNode struct { + * Val int + * Left *TreeNode + * Right *TreeNode + * } + */ + +func getDirections(root *TreeNode, startValue int, destValue int) string { + sPath, dPath := make([]byte, 0), make([]byte, 0) + findPath(root, startValue, &sPath) + findPath(root, destValue, &dPath) + size, i := min(len(sPath), len(dPath)), 0 + for i < size { + if sPath[len(sPath)-1-i] == dPath[len(dPath)-1-i] { + i++ + } else { + break + } + } + sPath = sPath[:len(sPath)-i] + replace(sPath) + dPath = dPath[:len(dPath)-i] + reverse(dPath) + sPath = append(sPath, dPath...) + return string(sPath) +} + +func findPath(root *TreeNode, value int, path *[]byte) bool { + if root.Val == value { + return true + } + + if root.Left != nil && findPath(root.Left, value, path) { + *path = append(*path, 'L') + return true + } + + if root.Right != nil && findPath(root.Right, value, path) { + *path = append(*path, 'R') + return true + } + + return false +} + +func reverse(path []byte) { + left, right := 0, len(path)-1 + for left < right { + path[left], path[right] = path[right], path[left] + left++ + right-- + } +} + +func replace(path []byte) { + for i := 0; i < len(path); i++ { + path[i] = 'U' + } +} + +func min(i, j int) int { + if i < j { + return i + } + return j +} diff --git a/leetcode/2096.Step-By-Step-Directions-From-a-Binary-Tree-Node-to-Another/2096. Step-By-Step Directions From a Binary Tree Node to Another_test.go b/leetcode/2096.Step-By-Step-Directions-From-a-Binary-Tree-Node-to-Another/2096. Step-By-Step Directions From a Binary Tree Node to Another_test.go new file mode 100644 index 000000000..e30610185 --- /dev/null +++ b/leetcode/2096.Step-By-Step-Directions-From-a-Binary-Tree-Node-to-Another/2096. Step-By-Step Directions From a Binary Tree Node to Another_test.go @@ -0,0 +1,68 @@ +package leetcode + +import ( + "fmt" + "testing" + + "github.com/halfrost/LeetCode-Go/structures" +) + +type question2096 struct { + para2096 + ans2096 +} + +// para 是参数 +// one 代表第一个参数 +type para2096 struct { + one []int + startValue int + destValue int +} + +// ans 是答案 +// one 代表第一个答案 +type ans2096 struct { + one string +} + +func Test_Problem2096(t *testing.T) { + + qs := []question2096{ + + { + para2096{[]int{5, 1, 2, 3, structures.NULL, 6, 4}, 3, 6}, + ans2096{"UURL"}, + }, + + { + para2096{[]int{2, 1}, 2, 1}, + ans2096{"L"}, + }, + + { + para2096{[]int{1, 2}, 2, 1}, + ans2096{"U"}, + }, + + { + para2096{[]int{3, 1, 2}, 2, 1}, + ans2096{"UL"}, + }, + + { + para2096{[]int{7, 8, 3, 1, structures.NULL, 4, 5, 6, structures.NULL, structures.NULL, structures.NULL, structures.NULL, structures.NULL, structures.NULL, 2}, 7, 5}, + ans2096{"RR"}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 2096------------------------\n") + + for _, q := range qs { + _, p := q.ans2096, q.para2096 + fmt.Printf("【input】:%v ", p) + root := structures.Ints2TreeNode(p.one) + fmt.Printf("【output】:%v \n", getDirections(root, p.startValue, p.destValue)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/2096.Step-By-Step-Directions-From-a-Binary-Tree-Node-to-Another/README.md b/leetcode/2096.Step-By-Step-Directions-From-a-Binary-Tree-Node-to-Another/README.md new file mode 100644 index 000000000..409608c8c --- /dev/null +++ b/leetcode/2096.Step-By-Step-Directions-From-a-Binary-Tree-Node-to-Another/README.md @@ -0,0 +1,145 @@ +# [2096. Step-By-Step Directions From a Binary Tree Node to Another](https://leetcode.com/problems/step-by-step-directions-from-a-binary-tree-node-to-another/) + + +## 题目 + +You are given the `root` of a **binary tree** with `n` nodes. Each node is uniquely assigned a value from `1` to `n`. You are also given an integer `startValue` representing the value of the start node `s`, and a different integer `destValue` representing the value of the destination node `t`. + +Find the **shortest path** starting from node `s` and ending at node `t`. Generate step-by-step directions of such path as a string consisting of only the **uppercase** letters `'L'`, `'R'`, and `'U'`. Each letter indicates a specific direction: + +- `'L'` means to go from a node to its **left child** node. +- `'R'` means to go from a node to its **right child** node. +- `'U'` means to go from a node to its **parent** node. + +Return *the step-by-step directions of the **shortest path** from node* `s` *to node* `t`. + +**Example 1:** + +![https://assets.leetcode.com/uploads/2021/11/15/eg1.png](https://assets.leetcode.com/uploads/2021/11/15/eg1.png) + +``` +Input: root = [5,1,2,3,null,6,4], startValue = 3, destValue = 6 +Output: "UURL" +Explanation: The shortest path is: 3 → 1 → 5 → 2 → 6. + +``` + +**Example 2:** + +![https://assets.leetcode.com/uploads/2021/11/15/eg2.png](https://assets.leetcode.com/uploads/2021/11/15/eg2.png) + +``` +Input: root = [2,1], startValue = 2, destValue = 1 +Output: "L" +Explanation: The shortest path is: 2 → 1. + +``` + +**Constraints:** + +- The number of nodes in the tree is `n`. +- `2 <= n <= 105` +- `1 <= Node.val <= n` +- All the values in the tree are **unique**. +- `1 <= startValue, destValue <= n` +- `startValue != destValue` + +## 题目大意 + +给你一棵 二叉树 的根节点 root ，这棵二叉树总共有 n 个节点。每个节点的值为 1 到 n 中的一个整数，且互不相同。给你一个整数 startValue ，表示起点节点 s 的值，和另一个不同的整数 destValue ，表示终点节点 t 的值。 + +请找到从节点 s 到节点 t 的 最短路径 ，并以字符串的形式返回每一步的方向。每一步用 大写 字母 'L' ，'R' 和 'U' 分别表示一种方向： + +- 'L' 表示从一个节点前往它的 左孩子 节点。 +- 'R' 表示从一个节点前往它的 右孩子 节点。 +- 'U' 表示从一个节点前往它的 父 节点。 + +请你返回从 s 到 t 最短路径 每一步的方向。 + +## 解题思路 + +- 二叉树中一个节点到另一个节点的最短路径一定可以分为两个部分（可能为空）：从起点节点向上到两个节点的**最近公共祖先**，再从最近公共祖先向下到达终点节点。 +- 首先需要找到起点 s 与公共祖先的节点之间的 path1，公共祖先节点与终点 t 的 path2。再删掉 2 个 path 的公共前缀。如果起点 s 和终点 t 在不同的分支上，不存在公共前缀。如果他们在相同的分支上，那么最终答案要去掉这个公共前缀。 +- 删除掉公共前缀以后，需要再整理一下最终答案的输出格式。由于题目要求，起点到公共祖先节点需要输出 U，所以把这段 path1 全部改成 U，然后再拼接上 path2 字符串，即可得到的字符串即为待求 ss 到 tt 每一步的最短路径。 + +## 代码 + +```go +package leetcode + +import ( + "github.com/halfrost/LeetCode-Go/structures" +) + +// TreeNode define +type TreeNode = structures.TreeNode + +/** + * Definition for a binary tree node. + * type TreeNode struct { + * Val int + * Left *TreeNode + * Right *TreeNode + * } + */ + +func getDirections(root *TreeNode, startValue int, destValue int) string { + sPath, dPath := make([]byte, 0), make([]byte, 0) + findPath(root, startValue, &sPath) + findPath(root, destValue, &dPath) + size, i := min(len(sPath), len(dPath)), 0 + for i < size { + if sPath[len(sPath)-1-i] == dPath[len(dPath)-1-i] { + i++ + } else { + break + } + } + sPath = sPath[:len(sPath)-i] + replace(sPath) + dPath = dPath[:len(dPath)-i] + reverse(dPath) + sPath = append(sPath, dPath...) + return string(sPath) +} + +func findPath(root *TreeNode, value int, path *[]byte) bool { + if root.Val == value { + return true + } + + if root.Left != nil && findPath(root.Left, value, path) { + *path = append(*path, 'L') + return true + } + + if root.Right != nil && findPath(root.Right, value, path) { + *path = append(*path, 'R') + return true + } + + return false +} + +func reverse(path []byte) { + left, right := 0, len(path)-1 + for left < right { + path[left], path[right] = path[right], path[left] + left++ + right-- + } +} + +func replace(path []byte) { + for i := 0; i < len(path); i++ { + path[i] = 'U' + } +} + +func min(i, j int) int { + if i < j { + return i + } + return j +} +``` \ No newline at end of file diff --git a/leetcode/2164.Sort-Even-and-Odd-Indices-Independently/2164. Sort Even and Odd Indices Independently.go b/leetcode/2164.Sort-Even-and-Odd-Indices-Independently/2164. Sort Even and Odd Indices Independently.go new file mode 100644 index 000000000..fa5fd49d9 --- /dev/null +++ b/leetcode/2164.Sort-Even-and-Odd-Indices-Independently/2164. Sort Even and Odd Indices Independently.go @@ -0,0 +1,30 @@ +package leetcode + +import ( + "sort" +) + +func sortEvenOdd(nums []int) []int { + odd, even, res := []int{}, []int{}, []int{} + for index, v := range nums { + if index%2 == 0 { + even = append(even, v) + } else { + odd = append(odd, v) + } + } + sort.Ints(even) + sort.Sort(sort.Reverse(sort.IntSlice(odd))) + + indexO, indexE := 0, 0 + for i := 0; i < len(nums); i++ { + if i%2 == 0 { + res = append(res, even[indexE]) + indexE++ + } else { + res = append(res, odd[indexO]) + indexO++ + } + } + return res +} diff --git a/leetcode/2164.Sort-Even-and-Odd-Indices-Independently/2164. Sort Even and Odd Indices Independently_test.go b/leetcode/2164.Sort-Even-and-Odd-Indices-Independently/2164. Sort Even and Odd Indices Independently_test.go new file mode 100644 index 000000000..77933ad14 --- /dev/null +++ b/leetcode/2164.Sort-Even-and-Odd-Indices-Independently/2164. Sort Even and Odd Indices Independently_test.go @@ -0,0 +1,46 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question2164 struct { + para2164 + ans2164 +} + +// para 是参数 +// one 代表第一个参数 +type para2164 struct { + nums []int +} + +// ans 是答案 +// one 代表第一个答案 +type ans2164 struct { + one []int +} + +func Test_Problem1(t *testing.T) { + + qs := []question2164{ + { + para2164{[]int{4, 1, 2, 3}}, + ans2164{[]int{2, 3, 4, 1}}, + }, + + { + para2164{[]int{2, 1}}, + ans2164{[]int{2, 1}}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 2164------------------------\n") + + for _, q := range qs { + _, p := q.ans2164, q.para2164 + fmt.Printf("【input】:%v 【output】:%v\n", p, sortEvenOdd(p.nums)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/2164.Sort-Even-and-Odd-Indices-Independently/README.md b/leetcode/2164.Sort-Even-and-Odd-Indices-Independently/README.md new file mode 100644 index 000000000..a8e650740 --- /dev/null +++ b/leetcode/2164.Sort-Even-and-Odd-Indices-Independently/README.md @@ -0,0 +1,93 @@ +# [2164. Sort Even and Odd Indices Independently](https://leetcode.com/problems/sort-even-and-odd-indices-independently/) + + +## 题目 + +You are given a **0-indexed** integer array `nums`. Rearrange the values of `nums` according to the following rules: + +1. Sort the values at **odd indices** of `nums` in **non-increasing** order. + - For example, if `nums = [4,**1**,2,**3**]` before this step, it becomes `[4,**3**,2,**1**]` after. The values at odd indices `1` and `3` are sorted in non-increasing order. +2. Sort the values at **even indices** of `nums` in **non-decreasing** order. + - For example, if `nums = [**4**,1,**2**,3]` before this step, it becomes `[**2**,1,**4**,3]` after. The values at even indices `0` and `2` are sorted in non-decreasing order. + +Return *the array formed after rearranging the values of* `nums`. + +**Example 1:** + +``` +Input: nums = [4,1,2,3] +Output: [2,3,4,1] +Explanation: +First, we sort the values present at odd indices (1 and 3) in non-increasing order. +So, nums changes from [4,1,2,3] to [4,3,2,1]. +Next, we sort the values present at even indices (0 and 2) in non-decreasing order. +So, nums changes from [4,1,2,3] to [2,3,4,1]. +Thus, the array formed after rearranging the values is [2,3,4,1]. + +``` + +**Example 2:** + +``` +Input: nums = [2,1] +Output: [2,1] +Explanation: +Since there is exactly one odd index and one even index, no rearrangement of values takes place. +The resultant array formed is [2,1], which is the same as the initial array. + +``` + +**Constraints:** + +- `1 <= nums.length <= 100` +- `1 <= nums[i] <= 100` + +## 题目大意 + +给你一个下标从 0 开始的整数数组 nums 。根据下述规则重排 nums 中的值： + +1. 按 非递增 顺序排列 nums 奇数下标 上的所有值。 +举个例子，如果排序前 nums = [4,1,2,3] ，对奇数下标的值排序后变为 [4,3,2,1] 。奇数下标 1 和 3 的值按照非递增顺序重排。 +2. 按 非递减 顺序排列 nums 偶数下标 上的所有值。 +举个例子，如果排序前 nums = [4,1,2,3] ，对偶数下标的值排序后变为 [2,1,4,3] 。偶数下标 0 和 2 的值按照非递减顺序重排。 + +返回重排 nums 的值之后形成的数组。 + +## 解题思路 + +- 简单题。分别将奇数和偶数位上的数字排序，奇数位的数从大到小，偶数位的数从小到大。最后将他们组合成一个数组。 + +## 代码 + +```go +package leetcode + +import ( + "sort" +) + +func sortEvenOdd(nums []int) []int { + odd, even, res := []int{}, []int{}, []int{} + for index, v := range nums { + if index%2 == 0 { + even = append(even, v) + } else { + odd = append(odd, v) + } + } + sort.Ints(even) + sort.Sort(sort.Reverse(sort.IntSlice(odd))) + + indexO, indexE := 0, 0 + for i := 0; i < len(nums); i++ { + if i%2 == 0 { + res = append(res, even[indexE]) + indexE++ + } else { + res = append(res, odd[indexO]) + indexO++ + } + } + return res +} +``` \ No newline at end of file diff --git a/leetcode/2165.Smallest-Value-of-the-Rearranged-Number/2165. Smallest Value of the Rearranged Number.go b/leetcode/2165.Smallest-Value-of-the-Rearranged-Number/2165. Smallest Value of the Rearranged Number.go new file mode 100644 index 000000000..1ca93c413 --- /dev/null +++ b/leetcode/2165.Smallest-Value-of-the-Rearranged-Number/2165. Smallest Value of the Rearranged Number.go @@ -0,0 +1,51 @@ +package leetcode + +import "sort" + +func smallestNumber(num int64) int64 { + pos := true + if num < 0 { + pos = false + num *= -1 + } + nums, m, res := []int{}, map[int]int{}, 0 + for num != 0 { + tmp := int(num % 10) + m[tmp]++ + num = num / 10 + } + + for k := range m { + nums = append(nums, k) + } + if pos { + sort.Ints(nums) + } else { + sort.Sort(sort.Reverse(sort.IntSlice(nums))) + } + + if nums[0] == 0 && len(nums) > 1 { + res += nums[1] + m[nums[1]]-- + } + + for _, v := range nums { + if res != 0 { + for j := m[v]; j > 0; j-- { + res = res * 10 + res += v + } + } else { + res += v + tmp := m[v] - 1 + for j := tmp; j > 0; j-- { + res = res * 10 + res += v + } + } + } + if !pos { + return -1 * int64(res) + } + return int64(res) +} diff --git a/leetcode/2165.Smallest-Value-of-the-Rearranged-Number/2165. Smallest Value of the Rearranged Number_test.go b/leetcode/2165.Smallest-Value-of-the-Rearranged-Number/2165. Smallest Value of the Rearranged Number_test.go new file mode 100644 index 000000000..657fe30c4 --- /dev/null +++ b/leetcode/2165.Smallest-Value-of-the-Rearranged-Number/2165. Smallest Value of the Rearranged Number_test.go @@ -0,0 +1,52 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question2165 struct { + para2165 + ans2165 +} + +// para 是参数 +// one 代表第一个参数 +type para2165 struct { + nums int64 +} + +// ans 是答案 +// one 代表第一个答案 +type ans2165 struct { + one int64 +} + +func Test_Problem1(t *testing.T) { + + qs := []question2165{ + + { + para2165{310}, + ans2165{103}, + }, + + { + para2165{5059}, + ans2165{5059}, + }, + + { + para2165{-7605}, + ans2165{-7650}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 2165------------------------\n") + + for _, q := range qs { + _, p := q.ans2165, q.para2165 + fmt.Printf("【input】:%v 【output】:%v\n", p, smallestNumber(p.nums)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/2165.Smallest-Value-of-the-Rearranged-Number/README.md b/leetcode/2165.Smallest-Value-of-the-Rearranged-Number/README.md new file mode 100644 index 000000000..8561bf22e --- /dev/null +++ b/leetcode/2165.Smallest-Value-of-the-Rearranged-Number/README.md @@ -0,0 +1,101 @@ +# [2165. Smallest Value of the Rearranged Number](https://leetcode.com/problems/smallest-value-of-the-rearranged-number/) + + +## 题目 + +You are given an integer `num.` **Rearrange** the digits of `num` such that its value is **minimized** and it does not contain **any** leading zeros. + +Return *the rearranged number with minimal value*. + +Note that the sign of the number does not change after rearranging the digits. + +**Example 1:** + +``` +Input: num = 310 +Output: 103 +Explanation: The possible arrangements for the digits of 310 are 013, 031, 103, 130, 301, 310. +The arrangement with the smallest value that does not contain any leading zeros is 103. + +``` + +**Example 2:** + +``` +Input: num = -7605 +Output: -7650 +Explanation: Some possible arrangements for the digits of -7605 are -7650, -6705, -5076, -0567. +The arrangement with the smallest value that does not contain any leading zeros is -7650. + +``` + +**Constraints:** + +- `10^15 <= num <= 10^15` + +## 题目大意 + +给你一个整数 num 。重排 num 中的各位数字，使其值 最小化 且不含 任何 前导零。 + +返回不含前导零且值最小的重排数字。注意，重排各位数字后，num 的符号不会改变。 + +## 解题思路 + +- 先将每个数字出现次数统计出来。然后将数字大小从小到大排序。如果原数是正数，当出现有数字 0 的情况的时候，需先将第二小的数字排列到第一个，再把 0 排列完。再继续排列第二小，第三小。。。 +- 如果原数是负数。那么就逆序排列，即先排列最大的数字，然后次大的数字，直到排列最小的数字。因为数字越大，对应的这个数的负数就越小。 + +## 代码 + +```go +package leetcode + +import "sort" + +func smallestNumber(num int64) int64 { + pos := true + if num < 0 { + pos = false + num *= -1 + } + nums, m, res := []int{}, map[int]int{}, 0 + for num != 0 { + tmp := int(num % 10) + m[tmp]++ + num = num / 10 + } + + for k := range m { + nums = append(nums, k) + } + if pos { + sort.Ints(nums) + } else { + sort.Sort(sort.Reverse(sort.IntSlice(nums))) + } + + if nums[0] == 0 && len(nums) > 1 { + res += nums[1] + m[nums[1]]-- + } + + for _, v := range nums { + if res != 0 { + for j := m[v]; j > 0; j-- { + res = res * 10 + res += v + } + } else { + res += v + tmp := m[v] - 1 + for j := tmp; j > 0; j-- { + res = res * 10 + res += v + } + } + } + if !pos { + return -1 * int64(res) + } + return int64(res) +} +``` \ No newline at end of file diff --git a/leetcode/2166.Design-Bitset/2166. Design Bitset.go b/leetcode/2166.Design-Bitset/2166. Design Bitset.go new file mode 100644 index 000000000..27d7bb0af --- /dev/null +++ b/leetcode/2166.Design-Bitset/2166. Design Bitset.go @@ -0,0 +1,72 @@ +package leetcode + +type Bitset struct { + set []byte + flipped []byte + oneCount int + size int +} + +func Constructor(size int) Bitset { + set := make([]byte, size) + flipped := make([]byte, size) + for i := 0; i < size; i++ { + set[i] = byte('0') + flipped[i] = byte('1') + } + return Bitset{ + set: set, + flipped: flipped, + oneCount: 0, + size: size, + } +} + +func (this *Bitset) Fix(idx int) { + if this.set[idx] == byte('0') { + this.set[idx] = byte('1') + this.flipped[idx] = byte('0') + this.oneCount++ + } +} + +func (this *Bitset) Unfix(idx int) { + if this.set[idx] == byte('1') { + this.set[idx] = byte('0') + this.flipped[idx] = byte('1') + this.oneCount-- + } +} + +func (this *Bitset) Flip() { + this.set, this.flipped = this.flipped, this.set + this.oneCount = this.size - this.oneCount +} + +func (this *Bitset) All() bool { + return this.oneCount == this.size +} + +func (this *Bitset) One() bool { + return this.oneCount != 0 +} + +func (this *Bitset) Count() int { + return this.oneCount +} + +func (this *Bitset) ToString() string { + return string(this.set) +} + +/** + * Your Bitset object will be instantiated and called as such: + * obj := Constructor(size); + * obj.Fix(idx); + * obj.Unfix(idx); + * obj.Flip(); + * param_4 := obj.All(); + * param_5 := obj.One(); + * param_6 := obj.Count(); + * param_7 := obj.ToString(); + */ diff --git a/leetcode/2166.Design-Bitset/2166. Design Bitset_test.go b/leetcode/2166.Design-Bitset/2166. Design Bitset_test.go new file mode 100644 index 000000000..48ee6ec0a --- /dev/null +++ b/leetcode/2166.Design-Bitset/2166. Design Bitset_test.go @@ -0,0 +1,31 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +func Test_Problem2166(t *testing.T) { + obj := Constructor(5) + fmt.Printf("obj = %v\n", obj) + + obj.Fix(3) + fmt.Printf("obj = %v\n", obj) + obj.Fix(1) + fmt.Printf("obj = %v\n", obj) + obj.Flip() + fmt.Printf("obj = %v\n", obj) + + fmt.Printf("all = %v\n", obj.All()) + obj.Unfix(0) + fmt.Printf("obj = %v\n", obj) + obj.Flip() + fmt.Printf("obj = %v\n", obj) + + fmt.Printf("one = %v\n", obj.One()) + obj.Unfix(0) + fmt.Printf("obj = %v\n", obj) + + fmt.Printf("count = %v\n", obj.Count()) + fmt.Printf("toString = %v\n", obj.ToString()) +} diff --git a/leetcode/2166.Design-Bitset/README.md b/leetcode/2166.Design-Bitset/README.md new file mode 100644 index 000000000..916bbf5ed --- /dev/null +++ b/leetcode/2166.Design-Bitset/README.md @@ -0,0 +1,156 @@ +# [2166. Design Bitset](https://leetcode.com/problems/design-bitset/) + + +## 题目 + +A **Bitset** is a data structure that compactly stores bits. + +Implement the `Bitset` class: + +- `Bitset(int size)` Initializes the Bitset with `size` bits, all of which are `0`. +- `void fix(int idx)` Updates the value of the bit at the index `idx` to `1`. If the value was already `1`, no change occurs. +- `void unfix(int idx)` Updates the value of the bit at the index `idx` to `0`. If the value was already `0`, no change occurs. +- `void flip()` Flips the values of each bit in the Bitset. In other words, all bits with value `0` will now have value `1` and vice versa. +- `boolean all()` Checks if the value of **each** bit in the Bitset is `1`. Returns `true` if it satisfies the condition, `false` otherwise. +- `boolean one()` Checks if there is **at least one** bit in the Bitset with value `1`. Returns `true` if it satisfies the condition, `false` otherwise. +- `int count()` Returns the **total number** of bits in the Bitset which have value `1`. +- `String toString()` Returns the current composition of the Bitset. Note that in the resultant string, the character at the `ith` index should coincide with the value at the `ith` bit of the Bitset. + +**Example 1:** + +``` +Input +["Bitset", "fix", "fix", "flip", "all", "unfix", "flip", "one", "unfix", "count", "toString"] +[[5], [3], [1], [], [], [0], [], [], [0], [], []] +Output +[null, null, null, null, false, null, null, true, null, 2, "01010"] + +Explanation +Bitset bs = new Bitset(5); // bitset = "00000". +bs.fix(3); // the value at idx = 3 is updated to 1, so bitset = "00010". +bs.fix(1); // the value at idx = 1 is updated to 1, so bitset = "01010". +bs.flip(); // the value of each bit is flipped, so bitset = "10101". +bs.all(); // return False, as not all values of the bitset are 1. +bs.unfix(0); // the value at idx = 0 is updated to 0, so bitset = "00101". +bs.flip(); // the value of each bit is flipped, so bitset = "11010". +bs.one(); // return True, as there is at least 1 index with value 1. +bs.unfix(0); // the value at idx = 0 is updated to 0, so bitset = "01010". +bs.count(); // return 2, as there are 2 bits with value 1. +bs.toString(); // return "01010", which is the composition of bitset. + +``` + +**Constraints:** + +- `1 <= size <= 10^5` +- `0 <= idx <= size - 1` +- At most `10^5` calls will be made **in total** to `fix`, `unfix`, `flip`, `all`, `one`, `count`, and `toString`. +- At least one call will be made to `all`, `one`, `count`, or `toString`. +- At most `5` calls will be made to `toString`. + +## 题目大意 + +位集 Bitset 是一种能以紧凑形式存储位的数据结构。 + +请你实现 Bitset 类。 + +- Bitset(int size) 用 size 个位初始化 Bitset ，所有位都是 0 。 +- void fix(int idx) 将下标为 idx 的位上的值更新为 1 。如果值已经是 1 ，则不会发生任何改变。 +- void unfix(int idx) 将下标为 idx 的位上的值更新为 0 。如果值已经是 0 ，则不会发生任何改变。 +- void flip() 翻转 Bitset 中每一位上的值。换句话说，所有值为 0 的位将会变成 1 ，反之亦然。 +- boolean all() 检查 Bitset 中 每一位 的值是否都是 1 。如果满足此条件，返回 true ；否则，返回 false 。 +- boolean one() 检查 Bitset 中 是否 至少一位 的值是 1 。如果满足此条件，返回 true ；否则，返回 false 。 +- int count() 返回 Bitset 中值为 1 的位的 总数 。 +- String toString() 返回 Bitset 的当前组成情况。注意，在结果字符串中，第 i 个下标处的字符应该与 Bitset 中的第 i 位一致。 + +提示： + +- 1 <= size <= 10^5 +- 0 <= idx <= size - 1 +- 至多调用 fix、unfix、flip、all、one、count 和 toString 方法 总共 10^5 次 +- 至少调用 all、one、count 或 toString 方法一次 +- 至多调用 toString 方法 5 次 + +## 解题思路 + +- 题目中给出了 size 大小，10^5 位二进制。所以不能用 int64 数据类型。 +- 用数组模拟二进制位的一系列操作。flip 操作并不需要每次去翻转，偶数次翻转等于没有翻转，奇数次翻转记下标记，同时更新 1 的个数。这次懒操作在调用 fix 和 unfix 时，更新到原来数组中。 +- fix 和 unfix 根据懒数组中的标记对应更新二进制位。同时更新 1 的个数。 +- all，one，count 都是判断 1 的个数。toString 输出即可。 + +## 代码 + +```go +package leetcode + +type Bitset struct { + set []byte + flipped []byte + oneCount int + size int +} + +func Constructor(size int) Bitset { + set := make([]byte, size) + flipped := make([]byte, size) + for i := 0; i < size; i++ { + set[i] = byte('0') + flipped[i] = byte('1') + } + return Bitset{ + set: set, + flipped: flipped, + oneCount: 0, + size: size, + } +} + +func (this *Bitset) Fix(idx int) { + if this.set[idx] == byte('0') { + this.set[idx] = byte('1') + this.flipped[idx] = byte('0') + this.oneCount++ + } +} + +func (this *Bitset) Unfix(idx int) { + if this.set[idx] == byte('1') { + this.set[idx] = byte('0') + this.flipped[idx] = byte('1') + this.oneCount-- + } +} + +func (this *Bitset) Flip() { + this.set, this.flipped = this.flipped, this.set + this.oneCount = this.size - this.oneCount +} + +func (this *Bitset) All() bool { + return this.oneCount == this.size +} + +func (this *Bitset) One() bool { + return this.oneCount != 0 +} + +func (this *Bitset) Count() int { + return this.oneCount +} + +func (this *Bitset) ToString() string { + return string(this.set) +} + +/** + * Your Bitset object will be instantiated and called as such: + * obj := Constructor(size); + * obj.Fix(idx); + * obj.Unfix(idx); + * obj.Flip(); + * param_4 := obj.All(); + * param_5 := obj.One(); + * param_6 := obj.Count(); + * param_7 := obj.ToString(); + */ +``` \ No newline at end of file diff --git a/leetcode/2167.Minimum-Time-to-Remove-All-Cars-Containing-Illegal-Goods/2167. Minimum Time to Remove All Cars Containing Illegal Goods.go b/leetcode/2167.Minimum-Time-to-Remove-All-Cars-Containing-Illegal-Goods/2167. Minimum Time to Remove All Cars Containing Illegal Goods.go new file mode 100644 index 000000000..72335ded0 --- /dev/null +++ b/leetcode/2167.Minimum-Time-to-Remove-All-Cars-Containing-Illegal-Goods/2167. Minimum Time to Remove All Cars Containing Illegal Goods.go @@ -0,0 +1,48 @@ +package leetcode + +import "runtime/debug" + +// 解法一 DP +func minimumTime(s string) int { + suffixSum, prefixSum, res := make([]int, len(s)+1), make([]int, len(s)+1), 0 + for i := len(s) - 1; i >= 0; i-- { + if s[i] == '0' { + suffixSum[i] = suffixSum[i+1] + } else { + suffixSum[i] = min(suffixSum[i+1]+2, len(s)-i) + } + } + res = suffixSum[0] + if s[0] == '1' { + prefixSum[0] = 1 + } + for i := 1; i < len(s); i++ { + if s[i] == '0' { + prefixSum[i] = prefixSum[i-1] + } else { + prefixSum[i] = min(prefixSum[i-1]+2, i+1) + } + res = min(res, prefixSum[i]+suffixSum[i+1]) + } + return res +} + +func init() { debug.SetGCPercent(-1) } + +// 解法二 小幅优化时间和空间复杂度 +func minimumTime1(s string) int { + res, count := len(s), 0 + for i := 0; i < len(s); i++ { + count = min(count+int(s[i]-'0')*2, i+1) + res = min(res, count+len(s)-i-1) + } + return res +} + +func min(a, b int) int { + if a < b { + return a + } else { + return b + } +} diff --git a/leetcode/2167.Minimum-Time-to-Remove-All-Cars-Containing-Illegal-Goods/2167. Minimum Time to Remove All Cars Containing Illegal Goods_test.go b/leetcode/2167.Minimum-Time-to-Remove-All-Cars-Containing-Illegal-Goods/2167. Minimum Time to Remove All Cars Containing Illegal Goods_test.go new file mode 100644 index 000000000..c3d59064a --- /dev/null +++ b/leetcode/2167.Minimum-Time-to-Remove-All-Cars-Containing-Illegal-Goods/2167. Minimum Time to Remove All Cars Containing Illegal Goods_test.go @@ -0,0 +1,57 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question2167 struct { + para2167 + ans2167 +} + +// para 是参数 +// one 代表第一个参数 +type para2167 struct { + s string +} + +// ans 是答案 +// one 代表第一个答案 +type ans2167 struct { + one int +} + +func Test_Problem2167(t *testing.T) { + + qs := []question2167{ + + { + para2167{"1100101"}, + ans2167{5}, + }, + + { + para2167{"0010"}, + ans2167{2}, + }, + + { + para2167{"1100111101"}, + ans2167{8}, + }, + + { + para2167{"1001010101"}, + ans2167{8}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 2167------------------------\n") + + for _, q := range qs { + _, p := q.ans2167, q.para2167 + fmt.Printf("【input】:%v 【output】:%v\n", p, minimumTime(p.s)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/2167.Minimum-Time-to-Remove-All-Cars-Containing-Illegal-Goods/README.md b/leetcode/2167.Minimum-Time-to-Remove-All-Cars-Containing-Illegal-Goods/README.md new file mode 100644 index 000000000..258e5b9a9 --- /dev/null +++ b/leetcode/2167.Minimum-Time-to-Remove-All-Cars-Containing-Illegal-Goods/README.md @@ -0,0 +1,145 @@ +# [2167. Minimum Time to Remove All Cars Containing Illegal Goods](https://leetcode.com/problems/minimum-time-to-remove-all-cars-containing-illegal-goods/) + + +## 题目 + +You are given a **0-indexed** binary string `s` which represents a sequence of train cars. `s[i] = '0'` denotes that the `ith` car does **not** contain illegal goods and `s[i] = '1'` denotes that the `ith` car does contain illegal goods. + +As the train conductor, you would like to get rid of all the cars containing illegal goods. You can do any of the following three operations **any** number of times: + +1. Remove a train car from the **left** end (i.e., remove `s[0]`) which takes 1 unit of time. +2. Remove a train car from the **right** end (i.e., remove `s[s.length - 1]`) which takes 1 unit of time. +3. Remove a train car from **anywhere** in the sequence which takes 2 units of time. + +Return *the **minimum** time to remove all the cars containing illegal goods*. + +Note that an empty sequence of cars is considered to have no cars containing illegal goods. + +**Example 1:** + +``` +Input: s = "1100101" +Output: 5 +Explanation: +One way to remove all the cars containing illegal goods from the sequence is to +- remove a car from the left end 2 times. Time taken is 2 * 1 = 2. +- remove a car from the right end. Time taken is 1. +- remove the car containing illegal goods found in the middle. Time taken is 2. +This obtains a total time of 2 + 1 + 2 = 5. + +An alternative way is to +- remove a car from the left end 2 times. Time taken is 2 * 1 = 2. +- remove a car from the right end 3 times. Time taken is 3 * 1 = 3. +This also obtains a total time of 2 + 3 = 5. + +5 is the minimum time taken to remove all the cars containing illegal goods. +There are no other ways to remove them with less time. + +``` + +**Example 2:** + +``` +Input: s = "0010" +Output: 2 +Explanation: +One way to remove all the cars containing illegal goods from the sequence is to +- remove a car from the left end 3 times. Time taken is 3 * 1 = 3. +This obtains a total time of 3. + +Another way to remove all the cars containing illegal goods from the sequence is to +- remove the car containing illegal goods found in the middle. Time taken is 2. +This obtains a total time of 2. + +Another way to remove all the cars containing illegal goods from the sequence is to +- remove a car from the right end 2 times. Time taken is 2 * 1 = 2. +This obtains a total time of 2. + +2 is the minimum time taken to remove all the cars containing illegal goods. +There are no other ways to remove them with less time. +``` + +**Constraints:** + +- `1 <= s.length <= 2 * 10^5` +- `s[i]` is either `'0'` or `'1'`. + +## 题目大意 + +给你一个下标从 0 开始的二进制字符串 s ，表示一个列车车厢序列。s[i] = '0' 表示第 i 节车厢 不 含违禁货物，而 s[i] = '1' 表示第 i 节车厢含违禁货物。 + +作为列车长，你需要清理掉所有载有违禁货物的车厢。你可以不限次数执行下述三种操作中的任意一个： + +1. 从列车 左 端移除一节车厢（即移除 s[0]），用去 1 单位时间。 +2. 从列车 右 端移除一节车厢（即移除 s[s.length - 1]），用去 1 单位时间。 +3. 从列车车厢序列的 任意位置 移除一节车厢，用去 2 单位时间。 + +返回移除所有载有违禁货物车厢所需要的 最少 单位时间数。注意，空的列车车厢序列视为没有车厢含违禁货物。 + +## 解题思路 + +- 这道题求最少单位时间数，最少时间数一定是尽量少使用 2 个单位时间的操作，多用 1 个时间的操作。从列车两头移除车厢，只需要移除和旁边车厢的金属连接处即可。由于列车位于两边，所以与其他车厢的金属连接处只有 1 个，故只需要 1 个单位时间；当车厢在中间，该车厢与两边的车厢有 2 个金属连接处，移除它需要断开与两边车厢的连接。所以需要 2 个单位时间。 +- 断开中间一节车厢以后，列车会被断成 2 部分。2 部分列车分别有 2 个头 2 个尾。举例：`1100111101`，如果把它从第 5 节开始断开，剩下的列车为 `11001 (1)` 和 `1101`。剩下的 1 都位于 2 边，移除他们都只需要 1 个单位时间。那么移除所有违禁品最少时间是 2 * 1 + 1 * 6 = 8。 +- 左半部分，定义 prefixSum[i] 表示移除前 i 节车厢所花费的最少时间。状态转移方程为： + + $prefixSum[i] =\left\{\begin{matrix}prefixSum[i-1],s[i]=0\\ min(prefixSum[i-1]+2, i+1), s[i]=1\end{matrix}\right.$ + +- 同理，右半部分定义 suffixSum[i] 表示移除后 i 节车厢所花费的最少时间。状态转移方程为： + + $suffixSum[i] =\left\{\begin{matrix} suffixSum[i+1],s[i]=0\\ min(suffixSum[i+1]+2, n-i), s[i]=1\end{matrix}\right.$ + +- 最后一层循环枚举 prefixSum[i] + suffixSum[i+1] 的最小值即为答案。 +- 这一题在解法一的基础上还可以再简化。当 s[i] = 1 时，prefixSum 和 suffixSum 是两种计算方法。我们可以假设中间断开的部分在 prefixSum 中。于是可以合并上面两个状态转移方程。简化以后的代码见解法二。 + +## 代码 + +```go +package leetcode + +import "runtime/debug" + +// 解法一 DP +func minimumTime(s string) int { + suffixSum, prefixSum, res := make([]int, len(s)+1), make([]int, len(s)+1), 0 + for i := len(s) - 1; i >= 0; i-- { + if s[i] == '0' { + suffixSum[i] = suffixSum[i+1] + } else { + suffixSum[i] = min(suffixSum[i+1]+2, len(s)-i) + } + } + res = suffixSum[0] + if s[0] == '1' { + prefixSum[0] = 1 + } + for i := 1; i < len(s); i++ { + if s[i] == '0' { + prefixSum[i] = prefixSum[i-1] + } else { + prefixSum[i] = min(prefixSum[i-1]+2, i+1) + } + res = min(res, prefixSum[i]+suffixSum[i+1]) + } + return res +} + +func init() { debug.SetGCPercent(-1) } + +// 解法二 小幅优化时间和空间复杂度 +func minimumTime1(s string) int { + res, count := len(s), 0 + for i := 0; i < len(s); i++ { + count = min(count+int(s[i]-'0')*2, i+1) + res = min(res, count+len(s)-i-1) + } + return res +} + +func min(a, b int) int { + if a < b { + return a + } else { + return b + } +} +``` \ No newline at end of file diff --git a/leetcode/2169.Count-Operations-to-Obtain-Zero/2169. Count Operations to Obtain Zero.go b/leetcode/2169.Count-Operations-to-Obtain-Zero/2169. Count Operations to Obtain Zero.go new file mode 100644 index 000000000..040ac3705 --- /dev/null +++ b/leetcode/2169.Count-Operations-to-Obtain-Zero/2169. Count Operations to Obtain Zero.go @@ -0,0 +1,14 @@ +package leetcode + +func countOperations(num1 int, num2 int) int { + res := 0 + for num1 != 0 && num2 != 0 { + if num1 >= num2 { + num1 -= num2 + } else { + num2 -= num1 + } + res++ + } + return res +} diff --git a/leetcode/2169.Count-Operations-to-Obtain-Zero/2169. Count Operations to Obtain Zero_test.go b/leetcode/2169.Count-Operations-to-Obtain-Zero/2169. Count Operations to Obtain Zero_test.go new file mode 100644 index 000000000..69d21f8a8 --- /dev/null +++ b/leetcode/2169.Count-Operations-to-Obtain-Zero/2169. Count Operations to Obtain Zero_test.go @@ -0,0 +1,48 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question2169 struct { + para2169 + ans2169 +} + +// para 是参数 +// one 代表第一个参数 +type para2169 struct { + num1 int + num2 int +} + +// ans 是答案 +// one 代表第一个答案 +type ans2169 struct { + one int +} + +func Test_Problem2169(t *testing.T) { + + qs := []question2169{ + + { + para2169{2, 3}, + ans2169{3}, + }, + + { + para2169{10, 10}, + ans2169{1}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 2169------------------------\n") + + for _, q := range qs { + _, p := q.ans2169, q.para2169 + fmt.Printf("【input】:%v 【output】:%v\n", p, countOperations(p.num1, p.num2)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/2169.Count-Operations-to-Obtain-Zero/README.md b/leetcode/2169.Count-Operations-to-Obtain-Zero/README.md new file mode 100644 index 000000000..10878ea04 --- /dev/null +++ b/leetcode/2169.Count-Operations-to-Obtain-Zero/README.md @@ -0,0 +1,73 @@ +# [2169. Count Operations to Obtain Zero](https://leetcode.com/problems/count-operations-to-obtain-zero/) + + +## 题目 + +You are given two **non-negative** integers `num1` and `num2`. + +In one **operation**, if `num1 >= num2`, you must subtract `num2` from `num1`, otherwise subtract `num1` from `num2`. + +- For example, if `num1 = 5` and `num2 = 4`, subtract `num2` from `num1`, thus obtaining `num1 = 1` and `num2 = 4`. However, if `num1 = 4` and `num2 = 5`, after one operation, `num1 = 4` and `num2 = 1`. + +Return *the **number of operations** required to make either* `num1 = 0` *or* `num2 = 0`. + +**Example 1:** + +``` +Input: num1 = 2, num2 = 3 +Output: 3 +Explanation: +- Operation 1: num1 = 2, num2 = 3. Since num1 < num2, we subtract num1 from num2 and get num1 = 2, num2 = 3 - 2 = 1. +- Operation 2: num1 = 2, num2 = 1. Since num1 > num2, we subtract num2 from num1. +- Operation 3: num1 = 1, num2 = 1. Since num1 == num2, we subtract num2 from num1. +Now num1 = 0 and num2 = 1. Since num1 == 0, we do not need to perform any further operations. +So the total number of operations required is 3. + +``` + +**Example 2:** + +``` +Input: num1 = 10, num2 = 10 +Output: 1 +Explanation: +- Operation 1: num1 = 10, num2 = 10. Since num1 == num2, we subtract num2 from num1 and get num1 = 10 - 10 = 0. +Now num1 = 0 and num2 = 10. Since num1 == 0, we are done. +So the total number of operations required is 1. + +``` + +**Constraints:** + +- `0 <= num1, num2 <= 10^5` + +## 题目大意 + +给你两个 非负 整数 num1 和 num2 。每一步 操作 中，如果 num1 >= num2 ，你必须用 num1 减 num2 ；否则，你必须用 num2 减 num1 。 + +- 例如，num1 = 5 且 num2 = 4 ，应该用 num1 减 num2 ，因此，得到 num1 = 1 和 num2 = 4 。然而，如果 num1 = 4且 num2 = 5 ，一步操作后，得到 num1 = 4 和 num2 = 1 。 + +返回使 num1 = 0 或 num2 = 0 的 操作数 。 + +## 解题思路 + +- 简单题，按照题意模拟，每次两个数字相减，便累加操作次数。当某个数字变为 0 时，输出操作次数。 + +## 代码 + +```go +package leetcode + +func countOperations(num1 int, num2 int) int { + res := 0 + for num1 != 0 && num2 != 0 { + if num1 >= num2 { + num1 -= num2 + } else { + num2 -= num1 + } + res++ + } + return res +} +``` \ No newline at end of file diff --git a/leetcode/2170.Minimum-Operations-to-Make-the-Array-Alternating/2170. Minimum Operations to Make the Array Alternating.go b/leetcode/2170.Minimum-Operations-to-Make-the-Array-Alternating/2170. Minimum Operations to Make the Array Alternating.go new file mode 100644 index 000000000..d5d156ffb --- /dev/null +++ b/leetcode/2170.Minimum-Operations-to-Make-the-Array-Alternating/2170. Minimum Operations to Make the Array Alternating.go @@ -0,0 +1,60 @@ +package leetcode + +import ( + "sort" +) + +type node struct { + value int + count int +} + +func minimumOperations(nums []int) int { + if len(nums) == 1 { + return 0 + } + res, odd, even, oddMap, evenMap := 0, []node{}, []node{}, map[int]int{}, map[int]int{} + + for i := 0; i < len(nums); i += 2 { + evenMap[nums[i]]++ + } + for k, v := range evenMap { + even = append(even, node{value: k, count: v}) + } + sort.Slice(even, func(i, j int) bool { + return even[i].count > even[j].count + }) + + for i := 1; i < len(nums); i += 2 { + oddMap[nums[i]]++ + } + for k, v := range oddMap { + odd = append(odd, node{value: k, count: v}) + } + sort.Slice(odd, func(i, j int) bool { + return odd[i].count > odd[j].count + }) + + if even[0].value == odd[0].value { + if len(even) == 1 && len(odd) != 1 { + res = len(nums) - even[0].count - odd[1].count + } else if len(odd) == 1 && len(even) != 1 { + res = len(nums) - odd[0].count - even[1].count + } else if len(odd) == 1 && len(even) == 1 { + res = len(nums) / 2 + } else { + // both != 1 + res = min(len(nums)-odd[0].count-even[1].count, len(nums)-odd[1].count-even[0].count) + } + } else { + res = len(nums) - even[0].count - odd[0].count + } + return res +} + +func min(a, b int) int { + if a > b { + return b + } + return a +} diff --git a/leetcode/2170.Minimum-Operations-to-Make-the-Array-Alternating/2170. Minimum Operations to Make the Array Alternating_test.go b/leetcode/2170.Minimum-Operations-to-Make-the-Array-Alternating/2170. Minimum Operations to Make the Array Alternating_test.go new file mode 100644 index 000000000..c792e89e4 --- /dev/null +++ b/leetcode/2170.Minimum-Operations-to-Make-the-Array-Alternating/2170. Minimum Operations to Make the Array Alternating_test.go @@ -0,0 +1,57 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question2170 struct { + para2170 + ans2170 +} + +// para 是参数 +// one 代表第一个参数 +type para2170 struct { + nums []int +} + +// ans 是答案 +// one 代表第一个答案 +type ans2170 struct { + one int +} + +func Test_Problem1(t *testing.T) { + + qs := []question2170{ + + { + para2170{[]int{1}}, + ans2170{0}, + }, + + { + para2170{[]int{3, 1, 3, 2, 4, 3}}, + ans2170{3}, + }, + + { + para2170{[]int{1, 2, 2, 2, 2}}, + ans2170{2}, + }, + + { + para2170{[]int{69, 91, 47, 74, 75, 94, 22, 100, 43, 50, 82, 47, 40, 51, 90, 27, 98, 85, 47, 14, 55, 82, 52, 9, 65, 90, 86, 45, 52, 52, 95, 40, 85, 3, 46, 77, 16, 59, 32, 22, 41, 87, 89, 78, 59, 78, 34, 26, 71, 9, 82, 68, 80, 74, 100, 6, 10, 53, 84, 80, 7, 87, 3, 82, 26, 26, 14, 37, 26, 58, 96, 73, 41, 2, 79, 43, 56, 74, 30, 71, 6, 100, 72, 93, 83, 40, 28, 79, 24}}, + ans2170{84}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 2170------------------------\n") + + for _, q := range qs { + _, p := q.ans2170, q.para2170 + fmt.Printf("【input】:%v 【output】:%v\n", p, minimumOperations(p.nums)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/2170.Minimum-Operations-to-Make-the-Array-Alternating/README.md b/leetcode/2170.Minimum-Operations-to-Make-the-Array-Alternating/README.md new file mode 100644 index 000000000..305d79ce6 --- /dev/null +++ b/leetcode/2170.Minimum-Operations-to-Make-the-Array-Alternating/README.md @@ -0,0 +1,130 @@ +# [2170. Minimum Operations to Make the Array Alternating](https://leetcode.com/problems/minimum-operations-to-make-the-array-alternating/) + + +## 题目 + +You are given a **0-indexed** array `nums` consisting of `n` positive integers. + +The array `nums` is called **alternating** if: + +- `nums[i - 2] == nums[i]`, where `2 <= i <= n - 1`. +- `nums[i - 1] != nums[i]`, where `1 <= i <= n - 1`. + +In one **operation**, you can choose an index `i` and **change** `nums[i]` into **any** positive integer. + +Return *the **minimum number of operations** required to make the array alternating*. + +**Example 1:** + +``` +Input: nums = [3,1,3,2,4,3] +Output: 3 +Explanation: +One way to make the array alternating is by converting it to [3,1,3,1,3,1]. +The number of operations required in this case is 3. +It can be proven that it is not possible to make the array alternating in less than 3 operations. + +``` + +**Example 2:** + +``` +Input: nums = [1,2,2,2,2] +Output: 2 +Explanation: +One way to make the array alternating is by converting it to [1,2,1,2,1]. +The number of operations required in this case is 2. +Note that the array cannot be converted to [2,2,2,2,2] because in this case nums[0] == nums[1] which violates the conditions of an alternating array. + +``` + +**Constraints:** + +- `1 <= nums.length <= 10^5` +- `1 <= nums[i] <= 10^5` + +## 题目大意 + +给你一个下标从 0 开始的数组 nums ，该数组由 n 个正整数组成。 + +如果满足下述条件，则数组 nums 是一个 交替数组 ： + +- nums[i - 2] == nums[i] ，其中 2 <= i <= n - 1 。 +- nums[i - 1] != nums[i] ，其中 1 <= i <= n - 1 。 + +在一步 操作 中，你可以选择下标 i 并将 nums[i] 更改 为 任一 正整数。返回使数组变成交替数组的 最少操作数 。 + +**提示：** + +- `1 <= nums.length <= 10^5` +- `1 <= nums[i] <= 10^5` + +## 解题思路 + +- 题目要求最少操作数，即留下出现频次最多的数字，剩下的数字都替换成这个数字。先将每个数字出现的频次统计出来，然后按照频次从大到小排序。优先选择出现频次高的数字。 +- 有几种“特殊”情况需要处理：当奇数下标的数字频次最大的数字和偶数下标的数字频次最大的数字相同（数字相同，频次不同），这时应选取频次大的数字留下；当数字相同，频次也相同，这时要看奇数下标和偶数下标的数字分别有几个。 如果其中一个只有一种数字，那么另外一组数字则需都变成该组频次第二大的数字，例如奇数下标的数字全是 1，频次是 3，偶数下标的数字是 1，最大频次是 2。第二频次的数字是 9，频次是 1 。那么这种情况下，选择奇数下标的数字 1，和偶数下标数字 9 。将偶数下标不是 9 的数字改变成 9 ；更近一步，如果奇数下标和偶数下标都只有一个数字，频次相同，那么只能改变奇数下标或者偶数下标的所有数字。 + +## 代码 + +```go +package leetcode + +import ( + "sort" +) + +type node struct { + value int + count int +} + +func minimumOperations(nums []int) int { + if len(nums) == 1 { + return 0 + } + res, odd, even, oddMap, evenMap := 0, []node{}, []node{}, map[int]int{}, map[int]int{} + + for i := 0; i < len(nums); i += 2 { + evenMap[nums[i]]++ + } + for k, v := range evenMap { + even = append(even, node{value: k, count: v}) + } + sort.Slice(even, func(i, j int) bool { + return even[i].count > even[j].count + }) + + for i := 1; i < len(nums); i += 2 { + oddMap[nums[i]]++ + } + for k, v := range oddMap { + odd = append(odd, node{value: k, count: v}) + } + sort.Slice(odd, func(i, j int) bool { + return odd[i].count > odd[j].count + }) + + if even[0].value == odd[0].value { + if len(even) == 1 && len(odd) != 1 { + res = len(nums) - even[0].count - odd[1].count + } else if len(odd) == 1 && len(even) != 1 { + res = len(nums) - odd[0].count - even[1].count + } else if len(odd) == 1 && len(even) == 1 { + res = len(nums) / 2 + } else { + // both != 1 + res = min(len(nums)-odd[0].count-even[1].count, len(nums)-odd[1].count-even[0].count) + } + } else { + res = len(nums) - even[0].count - odd[0].count + } + return res +} + +func min(a, b int) int { + if a > b { + return b + } + return a +} +``` \ No newline at end of file diff --git a/leetcode/2171.Removing-Minimum-Number-of-Magic-Beans/2171. Removing Minimum Number of Magic Beans.go b/leetcode/2171.Removing-Minimum-Number-of-Magic-Beans/2171. Removing Minimum Number of Magic Beans.go new file mode 100644 index 000000000..c4032a1d2 --- /dev/null +++ b/leetcode/2171.Removing-Minimum-Number-of-Magic-Beans/2171. Removing Minimum Number of Magic Beans.go @@ -0,0 +1,20 @@ +package leetcode + +import "sort" + +func minimumRemoval(beans []int) int64 { + sort.Ints(beans) + sum, mx := 0, 0 + for i, v := range beans { + sum += v + mx = max(mx, (len(beans)-i)*v) + } + return int64(sum - mx) +} + +func max(a, b int) int { + if b > a { + return b + } + return a +} diff --git a/leetcode/2171.Removing-Minimum-Number-of-Magic-Beans/2171. Removing Minimum Number of Magic Beans_test.go b/leetcode/2171.Removing-Minimum-Number-of-Magic-Beans/2171. Removing Minimum Number of Magic Beans_test.go new file mode 100644 index 000000000..068733524 --- /dev/null +++ b/leetcode/2171.Removing-Minimum-Number-of-Magic-Beans/2171. Removing Minimum Number of Magic Beans_test.go @@ -0,0 +1,47 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question2170 struct { + para2170 + ans2170 +} + +// para 是参数 +// one 代表第一个参数 +type para2170 struct { + beans []int +} + +// ans 是答案 +// one 代表第一个答案 +type ans2170 struct { + one int +} + +func Test_Problem1(t *testing.T) { + + qs := []question2170{ + + { + para2170{[]int{4, 1, 6, 5}}, + ans2170{4}, + }, + + { + para2170{[]int{2, 10, 3, 2}}, + ans2170{7}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 2170------------------------\n") + + for _, q := range qs { + _, p := q.ans2170, q.para2170 + fmt.Printf("【input】:%v 【output】:%v\n", p, minimumRemoval(p.beans)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/2171.Removing-Minimum-Number-of-Magic-Beans/README.md b/leetcode/2171.Removing-Minimum-Number-of-Magic-Beans/README.md new file mode 100644 index 000000000..0234821dc --- /dev/null +++ b/leetcode/2171.Removing-Minimum-Number-of-Magic-Beans/README.md @@ -0,0 +1,90 @@ +# [2171. Removing Minimum Number of Magic Beans](https://leetcode.com/problems/removing-minimum-number-of-magic-beans/) + + +## 题目 + +You are given an array of **positive** integers `beans`, where each integer represents the number of magic beans found in a particular magic bag. + +**Remove** any number of beans (**possibly none**) from each bag such that the number of beans in each remaining **non-empty** bag (still containing **at least one** bean) is **equal**. Once a bean has been removed from a bag, you are **not** allowed to return it to any of the bags. + +Return *the **minimum** number of magic beans that you have to remove*. + +**Example 1:** + +``` +Input: beans = [4,1,6,5] +Output: 4 +Explanation: +- We remove 1 bean from the bag with only 1 bean. + This results in the remaining bags: [4,0,6,5] +- Then we remove 2 beans from the bag with 6 beans. + This results in the remaining bags: [4,0,4,5] +- Then we remove 1 bean from the bag with 5 beans. + This results in the remaining bags: [4,0,4,4] +We removed a total of 1 + 2 + 1 = 4 beans to make the remaining non-empty bags have an equal number of beans. +There are no other solutions that remove 4 beans or fewer. + +``` + +**Example 2:** + +``` +Input: beans = [2,10,3,2] +Output: 7 +Explanation: +- We remove 2 beans from one of the bags with 2 beans. + This results in the remaining bags: [0,10,3,2] +- Then we remove 2 beans from the other bag with 2 beans. + This results in the remaining bags: [0,10,3,0] +- Then we remove 3 beans from the bag with 3 beans. + This results in the remaining bags: [0,10,0,0] +We removed a total of 2 + 2 + 3 = 7 beans to make the remaining non-empty bags have an equal number of beans. +There are no other solutions that removes 7 beans or fewer. + +``` + +**Constraints:** + +- `1 <= beans.length <= 10^5` +- `1 <= beans[i] <= 10^5` + +## 题目大意 + +给你一个 正 整数数组 beans ，其中每个整数表示一个袋子里装的魔法豆的数目。 + +请你从每个袋子中 拿出 一些豆子（也可以 不拿出），使得剩下的 非空 袋子中（即 至少 还有 一颗 魔法豆的袋子）魔法豆的数目 相等 。一旦魔法豆从袋子中取出，你不能将它放到任何其他的袋子中。请你返回你需要拿出魔法豆的 最少数目。 + +**提示：** + +- `1 <= beans.length <= 10^5` +- `1 <= beans[i] <= 10^5` + +## 解题思路 + +- 这一题没有特别巧妙的方法。最初思路来源于暴力解法。从第一个袋子开始，依次以每个袋子中的豆子为基准，改变其他袋子里面的豆子数，使得其他袋子里面的豆子都和基准袋子中豆子一样多。 +- 如果从下标为 0 扫到下标 n-1 ，这中间会有大量重复计算。有些计算区间和的操作，反复计算了很多遍，导致算法不高效。由于移除豆子数量多少和基准袋豆子数量强相关，所以先排序。如果袋子内豆子数目小于基准袋的豆子，`0 ≤ j < i`，那么这些袋子内的豆子数量会归零。需要移除 `beans[0] + beans[1] + ... + beans[i-1]` 个豆子；如果袋子内豆子数目大于等于基准袋的豆子，`j ≥ i` ，那么这些袋子内的豆子需要调整为 `beans[i]` 个。需要移除 `(beans[i] - beans[i]) + (beans[i+1] - beans[i]) + (beans[i+2] - beans[i]) + ... + (beans[n-1] - beans[i]) = beans[i]+ ... + beans[n-1] - (n-i) * beans[i]` 个豆子。将这 2 种情况综合起来，那么总共需要移除 `sum(beans) - (N - i) * beans[i]` 个豆子。综上，先排序，然后从小到大扫一遍数组，动态维护最少移除豆子的个数即可。 + +## 代码 + +```go +package leetcode + +import "sort" + +func minimumRemoval(beans []int) int64 { + sort.Ints(beans) + sum, mx := 0, 0 + for i, v := range beans { + sum += v + mx = max(mx, (len(beans)-i)*v) + } + return int64(sum - mx) +} + +func max(a, b int) int { + if b > a { + return b + } + return a +} +``` \ No newline at end of file diff --git a/leetcode/2180.Count-Integers-With-Even-Digit-Sum/2180. Count Integers With Even Digit Sum.go b/leetcode/2180.Count-Integers-With-Even-Digit-Sum/2180. Count Integers With Even Digit Sum.go new file mode 100644 index 000000000..d942429c6 --- /dev/null +++ b/leetcode/2180.Count-Integers-With-Even-Digit-Sum/2180. Count Integers With Even Digit Sum.go @@ -0,0 +1,21 @@ +package leetcode + +func countEven(num int) int { + count := 0 + for i := 1; i <= num; i++ { + if addSum(i)%2 == 0 { + count++ + } + } + return count +} + +func addSum(num int) int { + sum := 0 + tmp := num + for tmp != 0 { + sum += tmp % 10 + tmp = tmp / 10 + } + return sum +} diff --git a/leetcode/2180.Count-Integers-With-Even-Digit-Sum/2180. Count Integers With Even Digit Sum_test.go b/leetcode/2180.Count-Integers-With-Even-Digit-Sum/2180. Count Integers With Even Digit Sum_test.go new file mode 100644 index 000000000..684e23100 --- /dev/null +++ b/leetcode/2180.Count-Integers-With-Even-Digit-Sum/2180. Count Integers With Even Digit Sum_test.go @@ -0,0 +1,46 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question2180 struct { + para2180 + ans2180 +} + +// para 是参数 +// one 代表第一个参数 +type para2180 struct { + target int +} + +// ans 是答案 +// one 代表第一个答案 +type ans2180 struct { + one int +} + +func Test_Problem1(t *testing.T) { + + qs := []question2180{ + { + para2180{4}, + ans2180{2}, + }, + + { + para2180{30}, + ans2180{14}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 2180------------------------\n") + + for _, q := range qs { + _, p := q.ans2180, q.para2180 + fmt.Printf("【input】:%v 【output】:%v\n", p, countEven(p.target)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/2180.Count-Integers-With-Even-Digit-Sum/README.md b/leetcode/2180.Count-Integers-With-Even-Digit-Sum/README.md new file mode 100644 index 000000000..15b2a5410 --- /dev/null +++ b/leetcode/2180.Count-Integers-With-Even-Digit-Sum/README.md @@ -0,0 +1,69 @@ +# [2180. Count Integers With Even Digit Sum](https://leetcode.com/problems/count-integers-with-even-digit-sum/) + + +## 题目 + +Given a positive integer `num`, return *the number of positive integers **less than or equal to*** `num` *whose digit sums are **even***. + +The **digit sum** of a positive integer is the sum of all its digits. + +**Example 1:** + +``` +Input: num = 4 +Output: 2 +Explanation: +The only integers less than or equal to 4 whose digit sums are even are 2 and 4. + +``` + +**Example 2:** + +``` +Input: num = 30 +Output: 14 +Explanation: +The 14 integers less than or equal to 30 whose digit sums are even are +2, 4, 6, 8, 11, 13, 15, 17, 19, 20, 22, 24, 26, and 28. + +``` + +**Constraints:** + +- `1 <= num <= 1000` + +## 题目大意 + +给你一个正整数 num ，请你统计并返回 小于或等于 num 且各位数字之和为 偶数 的正整数的数目。 + +正整数的 各位数字之和 是其所有位上的对应数字相加的结果。 + +## 解题思路 + +- 简单题。依照题意，计算每个数的各位数字之和，如何和为偶数，则统计结果加一。最后输出统计结果即可。 + +## 代码 + +```go +package leetcode + +func countEven(num int) int { + count := 0 + for i := 1; i <= num; i++ { + if addSum(i)%2 == 0 { + count++ + } + } + return count +} + +func addSum(num int) int { + sum := 0 + tmp := num + for tmp != 0 { + sum += tmp % 10 + tmp = tmp / 10 + } + return sum +} +``` \ No newline at end of file diff --git a/leetcode/2181.Merge-Nodes-in-Between-Zeros/2181. Merge Nodes in Between Zeros.go b/leetcode/2181.Merge-Nodes-in-Between-Zeros/2181. Merge Nodes in Between Zeros.go new file mode 100644 index 000000000..be7ef2c6a --- /dev/null +++ b/leetcode/2181.Merge-Nodes-in-Between-Zeros/2181. Merge Nodes in Between Zeros.go @@ -0,0 +1,36 @@ +package leetcode + +import ( + "github.com/halfrost/LeetCode-Go/structures" +) + +// ListNode define +type ListNode = structures.ListNode + +/** + * Definition for singly-linked list. + * type ListNode struct { + * Val int + * Next *ListNode + * } + */ +func mergeNodes(head *ListNode) *ListNode { + res := &ListNode{} + h := res + if head.Next == nil { + return &structures.ListNode{} + } + cur := head + sum := 0 + for cur.Next != nil { + if cur.Next.Val != 0 { + sum += cur.Next.Val + } else { + h.Next = &ListNode{Val: sum, Next: nil} + h = h.Next + sum = 0 + } + cur = cur.Next + } + return res.Next +} diff --git a/leetcode/2181.Merge-Nodes-in-Between-Zeros/2181. Merge Nodes in Between Zeros_test.go b/leetcode/2181.Merge-Nodes-in-Between-Zeros/2181. Merge Nodes in Between Zeros_test.go new file mode 100644 index 000000000..44a308c12 --- /dev/null +++ b/leetcode/2181.Merge-Nodes-in-Between-Zeros/2181. Merge Nodes in Between Zeros_test.go @@ -0,0 +1,67 @@ +package leetcode + +import ( + "fmt" + "testing" + + "github.com/halfrost/LeetCode-Go/structures" +) + +type question2181 struct { + para2181 + ans2181 +} + +// para 是参数 +// one 代表第一个参数 +type para2181 struct { + one []int +} + +// ans 是答案 +// one 代表第一个答案 +type ans2181 struct { + one []int +} + +func Test_Problem2181(t *testing.T) { + + qs := []question2181{ + + { + para2181{[]int{0, 3, 1, 0, 4, 5, 2, 0}}, + ans2181{[]int{4, 11}}, + }, + + { + para2181{[]int{0, 1, 0, 3, 0, 2, 2, 0}}, + ans2181{[]int{1, 3, 4}}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 2181------------------------\n") + + for _, q := range qs { + _, p := q.ans2181, q.para2181 + fmt.Printf("【input】:%v 【output】:%v\n", p, structures.List2Ints(mergeNodes(structures.Ints2List(p.one)))) + } + fmt.Printf("\n\n\n") +} + +func removeElements(head *ListNode, val int) *ListNode { + if head == nil { + return head + } + newHead := &ListNode{Val: 0, Next: head} + pre := newHead + cur := head + for cur != nil { + if cur.Val == val { + pre.Next = cur.Next + } else { + pre = cur + } + cur = cur.Next + } + return newHead.Next +} diff --git a/leetcode/2181.Merge-Nodes-in-Between-Zeros/README.md b/leetcode/2181.Merge-Nodes-in-Between-Zeros/README.md new file mode 100644 index 000000000..6aba3609f --- /dev/null +++ b/leetcode/2181.Merge-Nodes-in-Between-Zeros/README.md @@ -0,0 +1,96 @@ +# [2181. Merge Nodes in Between Zeros](https://leetcode.com/problems/merge-nodes-in-between-zeros/) + +## 题目 + +You are given the `head` of a linked list, which contains a series of integers **separated** by `0`'s. The **beginning** and **end** of the linked list will have `Node.val == 0`. + +For **every** two consecutive `0`'s, **merge** all the nodes lying in between them into a single node whose value is the **sum** of all the merged nodes. The modified list should not contain any `0`'s. + +Return *the* `head` *of the modified linked list*. + +**Example 1:** + +![https://assets.leetcode.com/uploads/2022/02/02/ex1-1.png](https://assets.leetcode.com/uploads/2022/02/02/ex1-1.png) + +``` +Input: head = [0,3,1,0,4,5,2,0] +Output: [4,11] +Explanation: +The above figure represents the given linked list. The modified list contains +- The sum of the nodes marked in green: 3 + 1 = 4. +- The sum of the nodes marked in red: 4 + 5 + 2 = 11. + +``` + +**Example 2:** + +![https://assets.leetcode.com/uploads/2022/02/02/ex2-1.png](https://assets.leetcode.com/uploads/2022/02/02/ex2-1.png) + +``` +Input: head = [0,1,0,3,0,2,2,0] +Output: [1,3,4] +Explanation: +The above figure represents the given linked list. The modified list contains +- The sum of the nodes marked in green: 1 = 1. +- The sum of the nodes marked in red: 3 = 3. +- The sum of the nodes marked in yellow: 2 + 2 = 4. + +``` + +**Constraints:** + +- The number of nodes in the list is in the range `[3, 2 * 10^5]`. +- `0 <= Node.val <= 1000` +- There are **no** two consecutive nodes with `Node.val == 0`. +- The **beginning** and **end** of the linked list have `Node.val == 0`. + +## 题目大意 + +给你一个链表的头节点 head ，该链表包含由 0 分隔开的一连串整数。链表的 开端 和 末尾 的节点都满足 Node.val == 0 。对于每两个相邻的 0 ，请你将它们之间的所有节点合并成一个节点，其值是所有已合并节点的值之和。然后将所有 0 移除，修改后的链表不应该含有任何 0 。 + +返回修改后链表的头节点 head 。 + +## 解题思路 + +- 简单题。合并链表中两个值为 0 的节点。从头开始遍历链表，遇到节点值不为 0 的节点便累加；遇到节点值为 0 的节点，将累加值转换成结果链表要输出的节点值，然后继续遍历。 + +## 代码 + +```go +package leetcode + +import ( + "github.com/halfrost/LeetCode-Go/structures" +) + +// ListNode define +type ListNode = structures.ListNode + +/** + * Definition for singly-linked list. + * type ListNode struct { + * Val int + * Next *ListNode + * } + */ +func mergeNodes(head *ListNode) *ListNode { + res := &ListNode{} + h := res + if head.Next == nil { + return &structures.ListNode{} + } + cur := head + sum := 0 + for cur.Next != nil { + if cur.Next.Val != 0 { + sum += cur.Next.Val + } else { + h.Next = &ListNode{Val: sum, Next: nil} + h = h.Next + sum = 0 + } + cur = cur.Next + } + return res.Next +} +``` \ No newline at end of file diff --git a/leetcode/2182.Construct-String-With-Repeat-Limit/2182. Construct String With Repeat Limit.go b/leetcode/2182.Construct-String-With-Repeat-Limit/2182. Construct String With Repeat Limit.go new file mode 100644 index 000000000..9baa17c4f --- /dev/null +++ b/leetcode/2182.Construct-String-With-Repeat-Limit/2182. Construct String With Repeat Limit.go @@ -0,0 +1,37 @@ +package leetcode + +func repeatLimitedString(s string, repeatLimit int) string { + cnt := make([]int, 26) + for _, c := range s { + cnt[int(c-'a')]++ + } + var ns []byte + for i := 25; i >= 0; { + k := i - 1 + for cnt[i] > 0 { + for j := 0; j < min(cnt[i], repeatLimit); j++ { + ns = append(ns, byte(i)+'a') + } + cnt[i] -= repeatLimit + if cnt[i] > 0 { + for ; k >= 0 && cnt[k] == 0; k-- { + } + if k < 0 { + break + } else { + ns = append(ns, byte(k)+'a') + cnt[k]-- + } + } + } + i = k + } + return string(ns) +} +func min(a, b int) int { + if a < b { + return a + } else { + return b + } +} diff --git a/leetcode/2182.Construct-String-With-Repeat-Limit/2182. Construct String With Repeat Limit_test.go b/leetcode/2182.Construct-String-With-Repeat-Limit/2182. Construct String With Repeat Limit_test.go new file mode 100644 index 000000000..ac01fb982 --- /dev/null +++ b/leetcode/2182.Construct-String-With-Repeat-Limit/2182. Construct String With Repeat Limit_test.go @@ -0,0 +1,48 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question2182 struct { + para2182 + ans2182 +} + +// para 是参数 +// one 代表第一个参数 +type para2182 struct { + one string + limit int +} + +// ans 是答案 +// one 代表第一个答案 +type ans2182 struct { + one string +} + +func Test_Problem2182(t *testing.T) { + + qs := []question2182{ + + { + para2182{"cczazcc", 3}, + ans2182{"zzcccac"}, + }, + + { + para2182{"aababab", 2}, + ans2182{"bbabaa"}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 2182------------------------\n") + + for _, q := range qs { + _, p := q.ans2182, q.para2182 + fmt.Printf("【input】:%v 【output】:%v\n", p, repeatLimitedString(p.one, p.limit)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/2182.Construct-String-With-Repeat-Limit/README.md b/leetcode/2182.Construct-String-With-Repeat-Limit/README.md new file mode 100644 index 000000000..68500ed18 --- /dev/null +++ b/leetcode/2182.Construct-String-With-Repeat-Limit/README.md @@ -0,0 +1,98 @@ +# [2182. Construct String With Repeat Limit](https://leetcode.com/problems/construct-string-with-repeat-limit/) + + +## 题目 + +You are given a string `s` and an integer `repeatLimit`. Construct a new string `repeatLimitedString` using the characters of `s` such that no letter appears **more than** `repeatLimit` times **in a row**. You do **not** have to use all characters from `s`. + +Return *the **lexicographically largest*** `repeatLimitedString` *possible*. + +A string `a` is **lexicographically larger** than a string `b` if in the first position where `a` and `b` differ, string `a` has a letter that appears later in the alphabet than the corresponding letter in `b`. If the first `min(a.length, b.length)` characters do not differ, then the longer string is the lexicographically larger one. + +**Example 1:** + +``` +Input: s = "cczazcc", repeatLimit = 3 +Output: "zzcccac" +Explanation: We use all of the characters from s to construct the repeatLimitedString "zzcccac". +The letter 'a' appears at most 1 time in a row. +The letter 'c' appears at most 3 times in a row. +The letter 'z' appears at most 2 times in a row. +Hence, no letter appears more than repeatLimit times in a row and the string is a valid repeatLimitedString. +The string is the lexicographically largest repeatLimitedString possible so we return "zzcccac". +Note that the string "zzcccca" is lexicographically larger but the letter 'c' appears more than 3 times in a row, so it is not a valid repeatLimitedString. + +``` + +**Example 2:** + +``` +Input: s = "aababab", repeatLimit = 2 +Output: "bbabaa" +Explanation: We use only some of the characters from s to construct the repeatLimitedString "bbabaa". +The letter 'a' appears at most 2 times in a row. +The letter 'b' appears at most 2 times in a row. +Hence, no letter appears more than repeatLimit times in a row and the string is a valid repeatLimitedString. +The string is the lexicographically largest repeatLimitedString possible so we return "bbabaa". +Note that the string "bbabaaa" is lexicographically larger but the letter 'a' appears more than 2 times in a row, so it is not a valid repeatLimitedString. + +``` + +**Constraints:** + +- `1 <= repeatLimit <= s.length <= 10^5` +- `s` consists of lowercase English letters. + +## 题目大意 + +给你一个字符串 s 和一个整数 repeatLimit ，用 s 中的字符构造一个新字符串 repeatLimitedString ，使任何字母 连续 出现的次数都不超过 repeatLimit 次。你不必使用 s 中的全部字符。 + +返回 字典序最大的 repeatLimitedString 。 + +如果在字符串 a 和 b 不同的第一个位置，字符串 a 中的字母在字母表中出现时间比字符串 b 对应的字母晚，则认为字符串 a 比字符串 b 字典序更大 。如果字符串中前 min(a.length, b.length) 个字符都相同，那么较长的字符串字典序更大。 + +## 解题思路 + +- 利用贪心的思想，由于题意要求返回字典序最大的字符串，所以先从字典序最大的字母开始选起。然后选择当前字典序最大的字母个数和 limit 的最小值。如果当前字典序最大的字母比较多，多于 limit，不能一直选择它。选完 limit 个以后，需要选一个字典序次大的字母，选完这个字母以后再次选择字典序最大的字母。因为 limit 限制字母不能连续多于 limit 个。如此循环，直到所有的字母都选完。这样的策略排列出来的字母串为最大字典序。 + +## 代码 + +```go +package leetcode + +func repeatLimitedString(s string, repeatLimit int) string { + cnt := make([]int, 26) + for _, c := range s { + cnt[int(c-'a')]++ + } + var ns []byte + for i := 25; i >= 0; { + k := i - 1 + for cnt[i] > 0 { + for j := 0; j < min(cnt[i], repeatLimit); j++ { + ns = append(ns, byte(i)+'a') + } + cnt[i] -= repeatLimit + if cnt[i] > 0 { + for ; k >= 0 && cnt[k] == 0; k-- { + } + if k < 0 { + break + } else { + ns = append(ns, byte(k)+'a') + cnt[k]-- + } + } + } + i = k + } + return string(ns) +} +func min(a, b int) int { + if a < b { + return a + } else { + return b + } +} +``` \ No newline at end of file diff --git a/leetcode/2183.Count-Array-Pairs-Divisible-by-K/2183. Count Array Pairs Divisible by K.go b/leetcode/2183.Count-Array-Pairs-Divisible-by-K/2183. Count Array Pairs Divisible by K.go new file mode 100644 index 000000000..62c22397f --- /dev/null +++ b/leetcode/2183.Count-Array-Pairs-Divisible-by-K/2183. Count Array Pairs Divisible by K.go @@ -0,0 +1,32 @@ +package leetcode + +import "math" + +func countPairs(nums []int, k int) int64 { + n := int(math.Sqrt(float64(k))) + gcds, res := make(map[int]int, n), 0 + for _, num := range nums { + gcds[gcd(num, k)]++ + } + + for a, n1 := range gcds { + for b, n2 := range gcds { + if a > b || (a*b)%k != 0 { + continue + } + if a != b { + res += n1 * n2 + } else { // a == b + res += n1 * (n1 - 1) / 2 + } + } + } + return int64(res) +} + +func gcd(a, b int) int { + for a%b != 0 { + a, b = b, a%b + } + return b +} diff --git a/leetcode/2183.Count-Array-Pairs-Divisible-by-K/2183. Count Array Pairs Divisible by K_test.go b/leetcode/2183.Count-Array-Pairs-Divisible-by-K/2183. Count Array Pairs Divisible by K_test.go new file mode 100644 index 000000000..487dd70cd --- /dev/null +++ b/leetcode/2183.Count-Array-Pairs-Divisible-by-K/2183. Count Array Pairs Divisible by K_test.go @@ -0,0 +1,48 @@ +package leetcode + +import ( + "fmt" + "testing" +) + +type question2182 struct { + para2182 + ans2182 +} + +// para 是参数 +// one 代表第一个参数 +type para2182 struct { + nums []int + k int +} + +// ans 是答案 +// one 代表第一个答案 +type ans2182 struct { + one int64 +} + +func Test_Problem2182(t *testing.T) { + + qs := []question2182{ + + { + para2182{[]int{1, 2, 3, 4, 5}, 2}, + ans2182{7}, + }, + + { + para2182{[]int{1, 2, 3, 4}, 5}, + ans2182{0}, + }, + } + + fmt.Printf("------------------------Leetcode Problem 2183------------------------\n") + + for _, q := range qs { + _, p := q.ans2182, q.para2182 + fmt.Printf("【input】:%v 【output】:%v\n", p, countPairs(p.nums, p.k)) + } + fmt.Printf("\n\n\n") +} diff --git a/leetcode/2183.Count-Array-Pairs-Divisible-by-K/README.md b/leetcode/2183.Count-Array-Pairs-Divisible-by-K/README.md new file mode 100644 index 000000000..f7bec80a3 --- /dev/null +++ b/leetcode/2183.Count-Array-Pairs-Divisible-by-K/README.md @@ -0,0 +1,85 @@ +# [2183. Count Array Pairs Divisible by K](https://leetcode.com/problems/count-array-pairs-divisible-by-k/) + + +## 题目 + +Given a **0-indexed** integer array `nums` of length `n` and an integer `k`, return *the **number of pairs*** `(i, j)` *such that:* + +- `0 <= i < j <= n - 1` *and* +- `nums[i] * nums[j]` *is divisible by* `k`. + +**Example 1:** + +``` +Input: nums = [1,2,3,4,5], k = 2 +Output: 7 +Explanation: +The 7 pairs of indices whose corresponding products are divisible by 2 are +(0, 1), (0, 3), (1, 2), (1, 3), (1, 4), (2, 3), and (3, 4). +Their products are 2, 4, 6, 8, 10, 12, and 20 respectively. +Other pairs such as (0, 2) and (2, 4) have products 3 and 15 respectively, which are not divisible by 2. + +``` + +**Example 2:** + +``` +Input: nums = [1,2,3,4], k = 5 +Output: 0 +Explanation: There does not exist any pair of indices whose corresponding product is divisible by 5. + +``` + +**Constraints:** + +- `1 <= nums.length <= 10^5` +- `1 <= nums[i], k <= 10^5` + +## 题目大意 + +给你一个下标从 0 开始、长度为 n 的整数数组 nums 和一个整数 k ，返回满足下述条件的下标对 (i, j) 的数目： + +- 0 <= i < j <= n - 1 且 +- nums[i] * nums[j] 能被 k 整除。 + +## 解题思路 + +- 先找出 num 中每个元素与 k 的最大公约数。并统计这些公约数出现的频次，将数据保存在 map 中。在计算过程中，循环可以只需算到 ${O(\sqrt {k})}$ , 因为每一个 gcd[i] 一定是 k 的因数，而它出现的频次不会超过 ${O(\sqrt {k})}$。简单证明一下：假设因子 v 和 k/v 这两个因数为 k 的因子。v 和 k/v 必至少有 1 个小于等于 $\sqrt {k}$。所以 k 的因子也不会超过 2 * $\sqrt {k}$ = ${O(\sqrt {k})}$ 个。 +- 算出上述的 map 以后，2 层循环暴力遍历 key 值，如果 a * b 能被 k 整除，并且 a 和 b 不相同，那么 a 和 b 对应的 value 值相乘即为满足条件的下标对数；如果 a 和 b 相同，那么下标对数为 $C_{n}^{2}$。最后累加结果即可。 + +## 代码 + +```go +package leetcode + +import "math" + +func countPairs(nums []int, k int) int64 { + n := int(math.Sqrt(float64(k))) + gcds, res := make(map[int]int, n), 0 + for _, num := range nums { + gcds[gcd(num, k)]++ + } + + for a, n1 := range gcds { + for b, n2 := range gcds { + if a > b || (a*b)%k != 0 { + continue + } + if a != b { + res += n1 * n2 + } else { // a == b + res += n1 * (n1 - 1) / 2 + } + } + } + return int64(res) +} + +func gcd(a, b int) int { + for a%b != 0 { + a, b = b, a%b + } + return b +} +``` \ No newline at end of file diff --git a/note/time_complexity.md b/note/time_complexity.md index acf62fc2d..174aad59f 100644 --- a/note/time_complexity.md +++ b/note/time_complexity.md @@ -47,19 +47,13 @@ bool isPrime (int n){ } ``` -上面这段代码的时间复杂度是 O(sqrt(n)) 而不是 O(n) +上面这段代码的时间复杂度是 O(sqrt(n)) 而不是 O(n)。 -再举一个例子，有一个字符串数组，将数组中的每一个字符串按照字母序排序，之后再降整个字符串数组按照字典序排序。两步操作的整体时间复杂度是多少呢？ +再举一个例子，有一个字符串数组，将数组中的每一个字符串按照字母序排序，之后再将整个字符串数组按照字典序排序。两步操作的整体时间复杂度是多少呢？ -如果回答是 O(n*nlog n + nlog n) = O(n^2log n)，这个答案是错误的。 +如果回答是 O(n*nlog n + nlog n) = O(n^2log n)，这个答案是错误的。字符串的长度和数组的长度是没有关系的，所以这两个变量应该单独计算。假设最长的字符串长度为 s，数组中有 n 个字符串。对每个字符串排序的时间复杂度是 O(slog s)，将数组中每个字符串都按照字母序排序的时间复杂度是 O(n * slog s)。 -字符串的长度和数组的长度是没有关系的，所以这两个变量应该单独计算。 - -假设最长的字符串长度为 s，数组中有 n 个字符串。对每个字符串排序的时间复杂度是 O(slog s)，将数组中每个字符串都按照字母序排序的时间复杂度是 O(n * slog s)。 - -将整个字符串数组按照字典序排序的时间复杂度是 O(s * nlog n)。排序算法中的 O(nlog n) 是比较的次数，由于比较的是整型数字，所以每次比较是 O(1)。但是字符串按照字典序比较，时间复杂度是 O(s)。所以字符串数组按照字典序排序的时间复杂度是 O(s * nlog n) - -所以整体复杂度是 O(n * slog s) + O(s * nlog n) = O(n\*slog s + s\*nlogn) = O(n\*s\*(log s + log n)) +将整个字符串数组按照字典序排序的时间复杂度是 O(s * nlog n)。排序算法中的 O(nlog n) 是比较的次数，由于比较的是整型数字，所以每次比较是 O(1)。但是字符串按照字典序比较，时间复杂度是 O(s)。所以字符串数组按照字典序排序的时间复杂度是 O(s * nlog n)。所以整体复杂度是 O(n * slog s) + O(s * nlog n) = O(n\*slog s + s\*nlogn) = O(n\*s\*(log s + log n)) ## 二. 空间复杂度 @@ -105,7 +99,7 @@ int binarySearch(int arr[], int l, int r, int target){ return mid; else if (arr[mid]>target) return binarySearch(arr,l,mid-1,target); - eles + else return binarySearch(arr,mid+1,r,target); } @@ -130,4 +124,4 @@ int f(int n){ 上述这次递归调用的次数为 2^0^ + 2^1^ + 2^2^ + …… + 2^n^ = 2^n+1^ - 1 = O(2^n) -> 关于更加复杂的递归的复杂度分析，请参考，主定理。主定理中针对各种复杂情况都给出了正确的结论。 \ No newline at end of file +> 关于更加复杂的递归的复杂度分析，请参考，主定理。主定理中针对各种复杂情况都给出了正确的结论。 diff --git a/structures/Heap_test.go b/structures/Heap_test.go index 8e6a30c40..af8291f52 100644 --- a/structures/Heap_test.go +++ b/structures/Heap_test.go @@ -20,7 +20,7 @@ func Test_intHeap(t *testing.T) { begin, end := 0, 10 for i := begin; i < end; i++ { heap.Push(ih, i) - ast.Equal(0, (*ih)[0], "插入 %d 后的最小值却是 %d，ih=%v", i, (*ih)[0], (*ih)) + ast.Equal(0, (*ih)[0], "插入 %d 后的最小值却是 %d, ih=%v", i, (*ih)[0], (*ih)) } for i := begin; i < end; i++ { diff --git a/structures/TreeNode.go b/structures/TreeNode.go index f6edb9c4b..99060be17 100644 --- a/structures/TreeNode.go +++ b/structures/TreeNode.go @@ -2,6 +2,7 @@ package structures import ( "fmt" + "strconv" ) // TreeNode is tree's node @@ -218,7 +219,7 @@ func Tree2ints(tn *TreeNode) []int { return res[:i] } -// T2s convert *TreeNode to []int +// T2s converts *TreeNode to []int func T2s(head *TreeNode, array *[]int) { fmt.Printf("运行到这里了 head = %v array = %v\n", head, array) // fmt.Printf("****array = %v\n", array) @@ -231,3 +232,83 @@ func T2s(head *TreeNode, array *[]int) { T2s(head.Right, array) } } + +// Strings2TreeNode converts []string to *TreeNode +func Strings2TreeNode(strs []string) *TreeNode { + n := len(strs) + if n == 0 { + return nil + } + x, _ := strconv.Atoi(strs[0]) + root := &TreeNode{Val: x} + queue := make([]*TreeNode, 1, n<<1) + queue[0] = root + i := 1 + for i < n { + node := queue[0] + queue = queue[1:] + if i < n && strs[i] != "null" { + x, _ = strconv.Atoi(strs[i]) + node.Left = &TreeNode{Val: x} + queue = append(queue, node.Left) + } + i++ + if i < n && strs[i] != "null" { + x, _ = strconv.Atoi(strs[i]) + node.Right = &TreeNode{Val: x} + queue = append(queue, node.Right) + } + i++ + } + return root +} + +// Tree2LevelOrderStrings converts *TreeNode into []string by level order traversal. +func Tree2LevelOrderStrings(root *TreeNode) []string { + var ans []string + if root == nil { + return ans + } + queue := []*TreeNode{root} + var level int + for level = 0; len(queue) > 0; level++ { + size := len(queue) + for i := 0; i < size; i++ { + node := queue[i] + if node == nil { + ans = append(ans, "null") + } else { + ans = append(ans, strconv.Itoa(node.Val)) + if node.Left != nil || node.Right != nil { + queue = append(queue, node.Left, node.Right) + } + } + } + queue = queue[size:] + } + level-- + return ans +} + +// Tree2PreOrderStrings converts *TreeNode into []string by preorder traversal. +func Tree2PreOrderStrings(root *TreeNode) []string { + var ans []string + if root == nil { + return ans + } + stack := []*TreeNode{root} + node := root + for len(stack) > 0 { + if node == nil { + ans = append(ans, "null") + } + for node != nil { + ans = append(ans, strconv.Itoa(node.Val)) + stack = append(stack, node) + node = node.Left + } + node = stack[len(stack)-1].Right + stack = stack[:len(stack)-1] + } + return ans +} diff --git a/structures/go.mod b/structures/go.mod new file mode 100644 index 000000000..53c9843a0 --- /dev/null +++ b/structures/go.mod @@ -0,0 +1,11 @@ +module github.com/halfrost/LeetCode-Go/structures + +go 1.19 + +require github.com/stretchr/testify v1.8.0 + +require ( + github.com/davecgh/go-spew v1.1.1 // indirect + github.com/pmezard/go-difflib v1.0.0 // indirect + gopkg.in/yaml.v3 v3.0.1 // indirect +) diff --git a/structures/go.sum b/structures/go.sum new file mode 100644 index 000000000..51648299d --- /dev/null +++ b/structures/go.sum @@ -0,0 +1,15 @@ +github.com/davecgh/go-spew v1.1.0/go.mod h1:J7Y8YcW2NihsgmVo/mv3lAwl/skON4iLHjSsI+c5H38= +github.com/davecgh/go-spew v1.1.1 h1:vj9j/u1bqnvCEfJOwUhtlOARqs3+rkHYY13jYWTU97c= +github.com/davecgh/go-spew v1.1.1/go.mod h1:J7Y8YcW2NihsgmVo/mv3lAwl/skON4iLHjSsI+c5H38= +github.com/pmezard/go-difflib v1.0.0 h1:4DBwDE0NGyQoBHbLQYPwSUPoCMWR5BEzIk/f1lZbAQM= +github.com/pmezard/go-difflib v1.0.0/go.mod h1:iKH77koFhYxTK1pcRnkKkqfTogsbg7gZNVY4sRDYZ/4= +github.com/stretchr/objx v0.1.0/go.mod h1:HFkY916IF+rwdDfMAkV7OtwuqBVzrE8GR6GFx+wExME= +github.com/stretchr/objx v0.4.0/go.mod h1:YvHI0jy2hoMjB+UWwv71VJQ9isScKT/TqJzVSSt89Yw= +github.com/stretchr/testify v1.7.1/go.mod h1:6Fq8oRcR53rry900zMqJjRRixrwX3KX962/h/Wwjteg= +github.com/stretchr/testify v1.8.0 h1:pSgiaMZlXftHpm5L7V1+rVB+AZJydKsMxsQBIJw4PKk= +github.com/stretchr/testify v1.8.0/go.mod h1:yNjHg4UonilssWZ8iaSj1OCr/vHnekPRkoO+kdMU+MU= +gopkg.in/check.v1 v0.0.0-20161208181325-20d25e280405 h1:yhCVgyC4o1eVCa2tZl7eS0r+SDo693bJlVdllGtEeKM= +gopkg.in/check.v1 v0.0.0-20161208181325-20d25e280405/go.mod h1:Co6ibVJAznAaIkqp8huTwlJQCZ016jof/cbN4VW5Yz0= +gopkg.in/yaml.v3 v3.0.0-20200313102051-9f266ea9e77c/go.mod h1:K4uyk7z7BCEPqu6E+C64Yfv1cQ7kz7rIZviUmN+EgEM= +gopkg.in/yaml.v3 v3.0.1 h1:fxVm/GzAzEWqLHuvctI91KS9hhNmmWOoWu0XTYJS7CA= +gopkg.in/yaml.v3 v3.0.1/go.mod h1:K4uyk7z7BCEPqu6E+C64Yfv1cQ7kz7rIZviUmN+EgEM= diff --git a/template/CLRUCache.go b/template/CLRUCache.go index 03b5115c6..9738fb86e 100644 --- a/template/CLRUCache.go +++ b/template/CLRUCache.go @@ -132,7 +132,7 @@ func (c *CLRUCache) worker() { for { select { case el, ok := <-c.movePairs: - if ok == false { + if !ok { goto clean } if c.doMove(el) && c.list.Len() > c.cap { diff --git a/template/go.mod b/template/go.mod new file mode 100644 index 000000000..6ef287eab --- /dev/null +++ b/template/go.mod @@ -0,0 +1,11 @@ +module github.com/halfrost/LeetCode-Go/template + +go 1.19 + +require github.com/stretchr/testify v1.8.0 + +require ( + github.com/davecgh/go-spew v1.1.1 // indirect + github.com/pmezard/go-difflib v1.0.0 // indirect + gopkg.in/yaml.v3 v3.0.1 // indirect +) diff --git a/template/go.sum b/template/go.sum new file mode 100644 index 000000000..51648299d --- /dev/null +++ b/template/go.sum @@ -0,0 +1,15 @@ +github.com/davecgh/go-spew v1.1.0/go.mod h1:J7Y8YcW2NihsgmVo/mv3lAwl/skON4iLHjSsI+c5H38= +github.com/davecgh/go-spew v1.1.1 h1:vj9j/u1bqnvCEfJOwUhtlOARqs3+rkHYY13jYWTU97c= +github.com/davecgh/go-spew v1.1.1/go.mod h1:J7Y8YcW2NihsgmVo/mv3lAwl/skON4iLHjSsI+c5H38= +github.com/pmezard/go-difflib v1.0.0 h1:4DBwDE0NGyQoBHbLQYPwSUPoCMWR5BEzIk/f1lZbAQM= +github.com/pmezard/go-difflib v1.0.0/go.mod h1:iKH77koFhYxTK1pcRnkKkqfTogsbg7gZNVY4sRDYZ/4= +github.com/stretchr/objx v0.1.0/go.mod h1:HFkY916IF+rwdDfMAkV7OtwuqBVzrE8GR6GFx+wExME= +github.com/stretchr/objx v0.4.0/go.mod h1:YvHI0jy2hoMjB+UWwv71VJQ9isScKT/TqJzVSSt89Yw= +github.com/stretchr/testify v1.7.1/go.mod h1:6Fq8oRcR53rry900zMqJjRRixrwX3KX962/h/Wwjteg= +github.com/stretchr/testify v1.8.0 h1:pSgiaMZlXftHpm5L7V1+rVB+AZJydKsMxsQBIJw4PKk= +github.com/stretchr/testify v1.8.0/go.mod h1:yNjHg4UonilssWZ8iaSj1OCr/vHnekPRkoO+kdMU+MU= +gopkg.in/check.v1 v0.0.0-20161208181325-20d25e280405 h1:yhCVgyC4o1eVCa2tZl7eS0r+SDo693bJlVdllGtEeKM= +gopkg.in/check.v1 v0.0.0-20161208181325-20d25e280405/go.mod h1:Co6ibVJAznAaIkqp8huTwlJQCZ016jof/cbN4VW5Yz0= +gopkg.in/yaml.v3 v3.0.0-20200313102051-9f266ea9e77c/go.mod h1:K4uyk7z7BCEPqu6E+C64Yfv1cQ7kz7rIZviUmN+EgEM= +gopkg.in/yaml.v3 v3.0.1 h1:fxVm/GzAzEWqLHuvctI91KS9hhNmmWOoWu0XTYJS7CA= +gopkg.in/yaml.v3 v3.0.1/go.mod h1:K4uyk7z7BCEPqu6E+C64Yfv1cQ7kz7rIZviUmN+EgEM= diff --git a/website/config.toml b/website/config.toml index ffb851146..52297f0ba 100644 --- a/website/config.toml +++ b/website/config.toml @@ -80,7 +80,7 @@ disablePathToLower = true # (Optional, default true) Controls table of contents visibility on right side of pages. # Start and end levels can be controlled with markup.tableOfContents setting. # You can also specify this parameter per page in front matter. - BookToC = false + BookToC = true # (Optional, default none) Set the path to a logo for the book. If the logo is # /static/logo.png then the path would be logo.png @@ -98,10 +98,17 @@ disablePathToLower = true # Used for 'Last Modified' and 'Edit this page' links. BookRepo = 'https://github.com/halfrost/LeetCode-Go' + # Specifies commit portion of the link to the page's last modified commit hash for 'doc' page + # type. + # Required if 'BookRepo' param is set. + # Value used to construct a URL consisting of BookRepo/BookCommitPath/ + # Github uses 'commit', Bitbucket uses 'commits' + BookCommitPath = 'commit' + # Enable "Edit this page" links for 'doc' page type. # Disabled by default. Uncomment to enable. Requires 'BookRepo' param. # Path must point to 'content' directory of repo. - BookEditPath = 'tree/master/website/content' + BookEditPath = 'tree/master/website/' # Configure the date format used on the pages # - In git information diff --git a/website/content/ChapterFour/0001~0099/0003.Longest-Substring-Without-Repeating-Characters.md b/website/content/ChapterFour/0001~0099/0003.Longest-Substring-Without-Repeating-Characters.md index d5406effe..f86f9d4d4 100644 --- a/website/content/ChapterFour/0001~0099/0003.Longest-Substring-Without-Repeating-Characters.md +++ b/website/content/ChapterFour/0001~0099/0003.Longest-Substring-Without-Repeating-Characters.md @@ -63,7 +63,7 @@ func lengthOfLongestSubstring(s string) int { var bitSet [256]bool result, left, right := 0, 0, 0 for left < len(s) { - // 右侧字符对应的 bitSet 被标记 true，说明此字符在 X 位置重复，需要左侧向前移动，直到将X标记为 false + // 右侧字符对应的 bitSet 被标记 true，说明此字符在 X 位置重复，需要左侧向前移动，直到将 X 标记为 false if bitSet[s[right]] { bitSet[s[left]] = false left++ @@ -82,19 +82,20 @@ func lengthOfLongestSubstring(s string) int { } // 解法二 滑动窗口 -func lengthOfLongestSubstring_(s string) int { +func lengthOfLongestSubstring1(s string) int { if len(s) == 0 { return 0 } - var freq [256]int + var freq [127]int result, left, right := 0, 0, -1 for left < len(s) { - if right+1 < len(s) && freq[s[right+1]-'a'] == 0 { - freq[s[right+1]-'a']++ + if right+1 < len(s) && freq[s[right+1]] == 0 { + freq[s[right+1]]++ right++ + } else { - freq[s[left]-'a']-- + freq[s[left]]-- left++ } result = max(result, right-left+1) @@ -102,6 +103,21 @@ func lengthOfLongestSubstring_(s string) int { return result } +// 解法三 滑动窗口-哈希桶 +func lengthOfLongestSubstring2(s string) int { + right, left, res := 0, 0, 0 + indexes := make(map[byte]int, len(s)) + for left < len(s) { + if idx, ok := indexes[s[left]]; ok && idx >= right { + right = idx + 1 + } + indexes[s[left]] = left + left++ + res = max(res, left-right) + } + return res +} + func max(a int, b int) int { if a > b { return a @@ -109,7 +125,6 @@ func max(a int, b int) int { return b } - ``` diff --git a/website/content/ChapterFour/0001~0099/0005.Longest-Palindromic-Substring.md b/website/content/ChapterFour/0001~0099/0005.Longest-Palindromic-Substring.md index c89528653..1adffa4b2 100644 --- a/website/content/ChapterFour/0001~0099/0005.Longest-Palindromic-Substring.md +++ b/website/content/ChapterFour/0001~0099/0005.Longest-Palindromic-Substring.md @@ -61,7 +61,7 @@ Output: "a" ![https://img.halfrost.com/Leetcode/leetcode_5_2.png](https://img.halfrost.com/Leetcode/leetcode_5_2.png) -- 核心部分是如何通过左边已经扫描过的数据推出右边下一次要扩散的中心。这里定义下一次要扩散的中心下标是 `i`。如果 `i` 比 `maxRight` 要小，只能继续中心扩散。如果 `i` 比 `maxRight` 大，这是又分为 3 种情况。三种情况见上图。将上述 3 种情况总结起来，就是 ：`dp[i] = min(maxRight-i, dp[2*center-i])`，其中，`mirror` 相对于 `center` 是和 `i` 中心对称的，所以它的下标可以计算出来是 `2*center-i`。更新完 `dp[i]` 以后，就要进行中心扩散了。中心扩散以后动态维护最长回文串并相应的更新 `center`，`maxRight`，并且记录下原始字符串的起始位置 `begin` 和 `maxLen`。 +- 核心部分是如何通过左边已经扫描过的数据推出右边下一次要扩散的中心。这里定义下一次要扩散的中心下标是 `i`。如果 `i` 比 `maxRight` 要大，只能继续中心扩散。如果 `i` 比 `maxRight` 小，这时又分为 3 种情况。三种情况见上图。将上述 3 种情况总结起来，就是 ：`dp[i] = min(maxRight-i, dp[2*center-i])`，其中，`mirror` 相对于 `center` 是和 `i` 中心对称的，所以它的下标可以计算出来是 `2*center-i`。更新完 `dp[i]` 以后，就要进行中心扩散了。中心扩散以后动态维护最长回文串并相应的更新 `center`，`maxRight`，并且记录下原始字符串的起始位置 `begin` 和 `maxLen`。 ## 代码 diff --git a/website/content/ChapterFour/0001~0099/0013.Roman-to-Integer.md b/website/content/ChapterFour/0001~0099/0013.Roman-to-Integer.md index 2eb6ff751..ae95445d3 100644 --- a/website/content/ChapterFour/0001~0099/0013.Roman-to-Integer.md +++ b/website/content/ChapterFour/0001~0099/0013.Roman-to-Integer.md @@ -135,5 +135,5 @@ func romanToInt(s string) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0001~0099/0014.Longest-Common-Prefix.md b/website/content/ChapterFour/0001~0099/0014.Longest-Common-Prefix.md new file mode 100644 index 000000000..c6354e451 --- /dev/null +++ b/website/content/ChapterFour/0001~0099/0014.Longest-Common-Prefix.md @@ -0,0 +1,65 @@ +# [14. Longest Common Prefix](https://leetcode.com/problems/longest-common-prefix/) + +## 题目 + +Write a function to find the longest common prefix string amongst an array of strings. + +If there is no common prefix, return an empty string "". + +**Example 1**: + + Input: strs = ["flower","flow","flight"] + Output: "fl" + +**Example 2**: + + Input: strs = ["dog","racecar","car"] + Output: "" + Explanation: There is no common prefix among the input strings. + +**Constraints:** + +- 1 <= strs.length <= 200 +- 0 <= strs[i].length <= 200 +- strs[i] consists of only lower-case English letters. + +## 题目大意 + +编写一个函数来查找字符串数组中的最长公共前缀。 + +如果不存在公共前缀，返回空字符串 ""。 + +## 解题思路 + +- 对 strs 按照字符串长度进行升序排序，求出 strs 中长度最小字符串的长度 minLen +- 逐个比较长度最小字符串与其它字符串中的字符，如果不相等就返回 commonPrefix,否则就把该字符加入 commonPrefix + +## 代码 + +```go + +package leetcode + +func longestCommonPrefix(strs []string) string { + prefix := strs[0] + + for i := 1; i < len(strs); i++ { + for j := 0; j < len(prefix); j++ { + if len(strs[i]) <= j || strs[i][j] != prefix[j] { + prefix = prefix[0:j] + break + } + } + } + + return prefix +} + +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0001~0099/0015.3Sum.md b/website/content/ChapterFour/0001~0099/0015.3Sum.md index 6de469825..48d53acb3 100644 --- a/website/content/ChapterFour/0001~0099/0015.3Sum.md +++ b/website/content/ChapterFour/0001~0099/0015.3Sum.md @@ -120,6 +120,6 @@ func threeSum1(nums []int) [][]int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0001~0099/0016.3Sum-Closest.md b/website/content/ChapterFour/0001~0099/0016.3Sum-Closest.md index 447778b9b..c98e985ad 100644 --- a/website/content/ChapterFour/0001~0099/0016.3Sum-Closest.md +++ b/website/content/ChapterFour/0001~0099/0016.3Sum-Closest.md @@ -44,6 +44,9 @@ func threeSumClosest(nums []int, target int) int { if n > 2 { sort.Ints(nums) for i := 0; i < n-2; i++ { + if i > 0 && nums[i] == nums[i-1] { + continue + } for j, k := i+1, n-1; j < k; { sum := nums[i] + nums[j] + nums[k] if abs(sum-target) < diff { diff --git a/website/content/ChapterFour/0001~0099/0018.4Sum.md b/website/content/ChapterFour/0001~0099/0018.4Sum.md index 801861542..672e26be7 100644 --- a/website/content/ChapterFour/0001~0099/0018.4Sum.md +++ b/website/content/ChapterFour/0001~0099/0018.4Sum.md @@ -44,7 +44,92 @@ package leetcode import "sort" -func fourSum(nums []int, target int) [][]int { +// 解法一 双指针 +func fourSum(nums []int, target int) (quadruplets [][]int) { + sort.Ints(nums) + n := len(nums) + for i := 0; i < n-3 && nums[i]+nums[i+1]+nums[i+2]+nums[i+3] <= target; i++ { + if i > 0 && nums[i] == nums[i-1] || nums[i]+nums[n-3]+nums[n-2]+nums[n-1] < target { + continue + } + for j := i + 1; j < n-2 && nums[i]+nums[j]+nums[j+1]+nums[j+2] <= target; j++ { + if j > i+1 && nums[j] == nums[j-1] || nums[i]+nums[j]+nums[n-2]+nums[n-1] < target { + continue + } + for left, right := j+1, n-1; left < right; { + if sum := nums[i] + nums[j] + nums[left] + nums[right]; sum == target { + quadruplets = append(quadruplets, []int{nums[i], nums[j], nums[left], nums[right]}) + for left++; left < right && nums[left] == nums[left-1]; left++ { + } + for right--; left < right && nums[right] == nums[right+1]; right-- { + } + } else if sum < target { + left++ + } else { + right-- + } + } + } + } + return +} + +// 解法二 kSum +func fourSum1(nums []int, target int) [][]int { + res, cur := make([][]int, 0), make([]int, 0) + sort.Ints(nums) + kSum(nums, 0, len(nums)-1, target, 4, cur, &res) + return res +} + +func kSum(nums []int, left, right int, target int, k int, cur []int, res *[][]int) { + if right-left+1 < k || k < 2 || target < nums[left]*k || target > nums[right]*k { + return + } + if k == 2 { + // 2 sum + twoSum(nums, left, right, target, cur, res) + } else { + for i := left; i < len(nums); i++ { + if i == left || (i > left && nums[i-1] != nums[i]) { + next := make([]int, len(cur)) + copy(next, cur) + next = append(next, nums[i]) + kSum(nums, i+1, len(nums)-1, target-nums[i], k-1, next, res) + } + } + } + +} + +func twoSum(nums []int, left, right int, target int, cur []int, res *[][]int) { + for left < right { + sum := nums[left] + nums[right] + if sum == target { + cur = append(cur, nums[left], nums[right]) + temp := make([]int, len(cur)) + copy(temp, cur) + *res = append(*res, temp) + // reset cur to previous state + cur = cur[:len(cur)-2] + left++ + right-- + for left < right && nums[left] == nums[left-1] { + left++ + } + for left < right && nums[right] == nums[right+1] { + right-- + } + } else if sum < target { + left++ + } else { + right-- + } + } +} + +// 解法三 +func fourSum2(nums []int, target int) [][]int { res := [][]int{} counter := map[int]int{} for _, value := range nums { diff --git a/website/content/ChapterFour/0001~0099/0019.Remove-Nth-Node-From-End-of-List.md b/website/content/ChapterFour/0001~0099/0019.Remove-Nth-Node-From-End-of-List.md index e752190ac..0a511762f 100644 --- a/website/content/ChapterFour/0001~0099/0019.Remove-Nth-Node-From-End-of-List.md +++ b/website/content/ChapterFour/0001~0099/0019.Remove-Nth-Node-From-End-of-List.md @@ -52,11 +52,10 @@ Output: [1] ## 代码 ```go - package leetcode import ( - "github.com/halfrost/LeetCode-Go/structures" + "github.com/halfrost/leetcode-go/structures" ) // ListNode define @@ -72,31 +71,18 @@ type ListNode = structures.ListNode // 解法一 func removeNthFromEnd(head *ListNode, n int) *ListNode { - if head == nil { - return nil - } - var fast, slow *ListNode - fast = head - slow = head - step := 0 - for i := 0; i < n; i++ { - // n maybe much larger than length of linklist - if fast.Next == nil && step < n-1 { - return head + dummyHead := &ListNode{Next: head} + preSlow, slow, fast := dummyHead, head, head + for fast != nil { + if n <= 0 { + preSlow = slow + slow = slow.Next } + n-- fast = fast.Next - step++ - } - if fast == nil { - head = head.Next - return head } - for fast.Next != nil { - fast = fast.Next - slow = slow.Next - } - slow.Next = slow.Next.Next - return head + preSlow.Next = slow.Next + return dummyHead.Next } // 解法二 @@ -136,9 +122,6 @@ func removeNthFromEnd1(head *ListNode, n int) *ListNode { } return head } - - - ``` diff --git a/website/content/ChapterFour/0001~0099/0024.Swap-Nodes-in-Pairs.md b/website/content/ChapterFour/0001~0099/0024.Swap-Nodes-in-Pairs.md index 3283b4a9f..460110543 100644 --- a/website/content/ChapterFour/0001~0099/0024.Swap-Nodes-in-Pairs.md +++ b/website/content/ChapterFour/0001~0099/0024.Swap-Nodes-in-Pairs.md @@ -30,6 +30,13 @@ Given 1->2->3->4, you should return the list as 2->1->4->3. package leetcode +import ( + "github.com/halfrost/leetcode-go/structures" +) + +// ListNode define +type ListNode = structures.ListNode + /** * Definition for singly-linked list. * type ListNode struct { @@ -39,35 +46,15 @@ package leetcode */ func swapPairs(head *ListNode) *ListNode { - if head == nil || head.Next == nil { - return head + dummy := &ListNode{Next: head} + for pt := dummy; pt != nil && pt.Next != nil && pt.Next.Next != nil; { + pt, pt.Next, pt.Next.Next, pt.Next.Next.Next = pt.Next, pt.Next.Next, pt.Next.Next.Next, pt.Next } - s := head.Next - var behind *ListNode - for head.Next != nil { - headNext := head.Next - if behind != nil && behind.Next != nil { - behind.Next = headNext - } - var next *ListNode - if head.Next.Next != nil { - next = head.Next.Next - } - if head.Next.Next != nil { - head.Next = next - } else { - head.Next = nil - } - headNext.Next = head - behind = head - if head.Next != nil { - head = next - } - } - return s + return dummy.Next } + ``` diff --git a/website/content/ChapterFour/0001~0099/0027.Remove-Element.md b/website/content/ChapterFour/0001~0099/0027.Remove-Element.md index 7f77f8207..ef1a75df3 100644 --- a/website/content/ChapterFour/0001~0099/0027.Remove-Element.md +++ b/website/content/ChapterFour/0001~0099/0027.Remove-Element.md @@ -94,5 +94,5 @@ func removeElement(nums []int, val int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0001~0099/0028.Implement-strStr.md b/website/content/ChapterFour/0001~0099/0028.Find-the-Index-of-the-First-Occurrence-in-a-String.md similarity index 92% rename from website/content/ChapterFour/0001~0099/0028.Implement-strStr.md rename to website/content/ChapterFour/0001~0099/0028.Find-the-Index-of-the-First-Occurrence-in-a-String.md index b7c44e241..ee3577638 100644 --- a/website/content/ChapterFour/0001~0099/0028.Implement-strStr.md +++ b/website/content/ChapterFour/0001~0099/0028.Find-the-Index-of-the-First-Occurrence-in-a-String.md @@ -1,4 +1,4 @@ -# [28. Implement strStr()](https://leetcode.com/problems/implement-strstr/) +# [28. Find the Index of the First Occurrence in a String](https://leetcode.com/problems/find-the-index-of-the-first-occurrence-in-a-string/) ## 题目 diff --git a/website/content/ChapterFour/0001~0099/0029.Divide-Two-Integers.md b/website/content/ChapterFour/0001~0099/0029.Divide-Two-Integers.md index aa5672d1c..72f2e1062 100755 --- a/website/content/ChapterFour/0001~0099/0029.Divide-Two-Integers.md +++ b/website/content/ChapterFour/0001~0099/0029.Divide-Two-Integers.md @@ -150,6 +150,6 @@ func divide1(divided int, divisor int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0001~0099/0031.Next-Permutation.md b/website/content/ChapterFour/0001~0099/0031.Next-Permutation.md index 38f4b44c2..4689e75ba 100644 --- a/website/content/ChapterFour/0001~0099/0031.Next-Permutation.md +++ b/website/content/ChapterFour/0001~0099/0031.Next-Permutation.md @@ -57,6 +57,7 @@ Output: [1] ```go package leetcode +// 解法一 func nextPermutation(nums []int) { i, j := 0, 0 for i = len(nums) - 2; i >= 0; i-- { @@ -86,6 +87,47 @@ func reverse(nums *[]int, i, j int) { func swap(nums *[]int, i, j int) { (*nums)[i], (*nums)[j] = (*nums)[j], (*nums)[i] } + +// 解法二 +// [2,(3),6,5,4,1] -> 2,(4),6,5,(3),1 -> 2,4, 1,3,5,6 +func nextPermutation1(nums []int) { + var n = len(nums) + var pIdx = checkPermutationPossibility(nums) + if pIdx == -1 { + reverse(&nums, 0, n-1) + return + } + + var rp = len(nums) - 1 + // start from right most to leftward,find the first number which is larger than PIVOT + for rp > 0 { + if nums[rp] > nums[pIdx] { + swap(&nums, pIdx, rp) + break + } else { + rp-- + } + } + // Finally, Reverse all elements which are right from pivot + reverse(&nums, pIdx+1, n-1) +} + +// checkPermutationPossibility returns 1st occurrence Index where +// value is in decreasing order(from right to left) +// returns -1 if not found(it's already in its last permutation) +func checkPermutationPossibility(nums []int) (idx int) { + // search right to left for 1st number(from right) that is not in increasing order + var rp = len(nums) - 1 + for rp > 0 { + if nums[rp-1] < nums[rp] { + idx = rp - 1 + return idx + } + rp-- + } + return -1 +} + ``` diff --git a/website/content/ChapterFour/0001~0099/0040.Combination-Sum-II.md b/website/content/ChapterFour/0001~0099/0040.Combination-Sum-II.md index 4a0185edb..aa46f3f10 100755 --- a/website/content/ChapterFour/0001~0099/0040.Combination-Sum-II.md +++ b/website/content/ChapterFour/0001~0099/0040.Combination-Sum-II.md @@ -45,7 +45,7 @@ candidates 中的每个数字在每个组合中只能使用一次。 ## 解题思路 - 题目要求出总和为 sum 的所有组合，组合需要去重。这一题是第 39 题的加强版，第 39 题中元素可以重复利用(重复元素可无限次使用)，这一题中元素只能有限次数的利用，因为存在重复元素，并且每个元素只能用一次(重复元素只能使用有限次) -- 这一题和第 47 题类似，只不过元素可以反复使用。 +- 这一题和第 47 题类似。 ## 代码 diff --git a/website/content/ChapterFour/0001~0099/0048.Rotate-Image.md b/website/content/ChapterFour/0001~0099/0048.Rotate-Image.md index 3354ad476..4e7a4e0ce 100755 --- a/website/content/ChapterFour/0001~0099/0048.Rotate-Image.md +++ b/website/content/ChapterFour/0001~0099/0048.Rotate-Image.md @@ -97,34 +97,67 @@ You have to rotate the image **[in-place](https://en.wikipedia.org/wiki/In-plac ## 代码 ```go - package leetcode +// 解法一 func rotate(matrix [][]int) { - row := len(matrix) - if row <= 0 { - return - } - column := len(matrix[0]) + length := len(matrix) // rotate by diagonal 对角线变换 - for i := 0; i < row; i++ { - for j := i + 1; j < column; j++ { - tmp := matrix[i][j] - matrix[i][j] = matrix[j][i] - matrix[j][i] = tmp + for i := 0; i < length; i++ { + for j := i + 1; j < length; j++ { + matrix[i][j], matrix[j][i] = matrix[j][i], matrix[i][j] } } // rotate by vertical centerline 竖直轴对称翻转 - halfColumn := column / 2 - for i := 0; i < row; i++ { - for j := 0; j < halfColumn; j++ { - tmp := matrix[i][j] - matrix[i][j] = matrix[i][column-j-1] - matrix[i][column-j-1] = tmp + for i := 0; i < length; i++ { + for j := 0; j < length/2; j++ { + matrix[i][j], matrix[i][length-j-1] = matrix[i][length-j-1], matrix[i][j] } } } +// 解法二 +func rotate1(matrix [][]int) { + n := len(matrix) + if n == 1 { + return + } + /* rotate clock-wise = 1. transpose matrix => 2. reverse(matrix[i]) + + 1 2 3 4 1 5 9 13 13 9 5 1 + 5 6 7 8 => 2 6 10 14 => 14 10 6 2 + 9 10 11 12 3 7 11 15 15 11 7 3 + 13 14 15 16 4 8 12 16 16 12 8 4 + + */ + + for i := 0; i < n; i++ { + // transpose, i=rows, j=columns + // j = i+1, coz diagonal elements didn't change in a square matrix + for j := i + 1; j < n; j++ { + swap(matrix, i, j) + } + // reverse each row of the image + matrix[i] = reverse(matrix[i]) + } +} + +// swap changes original slice's i,j position +func swap(nums [][]int, i, j int) { + nums[i][j], nums[j][i] = nums[j][i], nums[i][j] +} + +// reverses a row of image, matrix[i] +func reverse(nums []int) []int { + var lp, rp = 0, len(nums) - 1 + + for lp < rp { + nums[lp], nums[rp] = nums[rp], nums[lp] + lp++ + rp-- + } + return nums +} ``` diff --git a/website/content/ChapterFour/0001~0099/0051.N-Queens.md b/website/content/ChapterFour/0001~0099/0051.N-Queens.md index d2d8dbe87..eacce3135 100755 --- a/website/content/ChapterFour/0001~0099/0051.N-Queens.md +++ b/website/content/ChapterFour/0001~0099/0051.N-Queens.md @@ -40,6 +40,7 @@ Each solution contains a distinct board configuration of the *n*-queens' placem - 利用 col 数组记录列信息，col 有 `n` 列。用 dia1，dia2 记录从左下到右上的对角线，从左上到右下的对角线的信息，dia1 和 dia2 分别都有 `2*n-1` 个。 - dia1 对角线的规律是 `i + j 是定值`，例如[0,0]，为 0；[1,0]、[0,1] 为 1；[2,0]、[1,1]、[0,2] 为 2； - dia2 对角线的规律是 `i - j 是定值`，例如[0,7]，为 -7；[0,6]、[1,7] 为 -6；[0,5]、[1,6]、[2,7] 为 -5；为了使他们从 0 开始，i - j + n - 1 偏移到 0 开始，所以 dia2 的规律是 `i - j + n - 1 为定值`。 +- 还有一个位运算的方法，每行只能选一个位置放皇后，那么对每行遍历可能放皇后的位置。如何高效判断哪些点不能放皇后呢？这里的做法毕竟巧妙，把所有之前选过的点按照顺序存下来，然后根据之前选的点到当前行的距离，就可以快速判断是不是会有冲突。举个例子: 假如在 4 皇后问题中，如果第一二行已经选择了位置 [1, 3]，那么在第三行选择时，首先不能再选 1, 3 列了，而对于第三行， 1 距离长度为2，所以它会影响到 -1, 3 两个列。同理，3 在第二行，距离第三行为 1，所以 3 会影响到列 2, 4。由上面的结果，我们知道 -1, 4 超出边界了不用去管，别的不能选的点是 1, 2, 3，所以第三行就只能选 0。在代码实现中，可以在每次遍历前根据之前选择的情况生成一个 occupied 用来记录当前这一行，已经被选了的和由于之前皇后攻击范围所以不能选的位置，然后只选择合法的位置进入到下一层递归。另外就是预处理了一个皇后放不同位置的字符串，这样这些字符串在返回结果的时候是可以在内存中复用的，省一点内存。 ## 代码 @@ -94,42 +95,48 @@ func generateBoard(n int, row *[]int) []string { return board } -// 解法二 二进制操作法 -// class Solution -// { -// int n; -// string getNq(int p) -// { -// string s(n, '.'); -// s[p] = 'Q'; -// return s; -// } -// void nQueens(int p, int l, int m, int r, vector> &res) -// { -// static vector ans; -// if (p >= n) -// { -// res.push_back(ans); -// return ; -// } -// int mask = l | m | r; -// for (int i = 0, b = 1; i < n; ++ i, b <<= 1) -// if (!(mask & b)) -// { -// ans.push_back(getNq(i)); -// nQueens(p + 1, (l | b) >> 1, m | b, (r | b) << 1, res); -// ans.pop_back(); -// } -// } -// public: -// vector > solveNQueens(int n) -// { -// this->n = n; -// vector> res; -// nQueens(0, 0, 0, 0, res); -// return res; -// } -// }; +// 解法二 二进制操作法 Signed-off-by: Hanlin Shi shihanlin9@gmail.com +func solveNQueens2(n int) (res [][]string) { + placements := make([]string, n) + for i := range placements { + buf := make([]byte, n) + for j := range placements { + if i == j { + buf[j] = 'Q' + } else { + buf[j] = '.' + } + } + placements[i] = string(buf) + } + var construct func(prev []int) + construct = func(prev []int) { + if len(prev) == n { + plan := make([]string, n) + for i := 0; i < n; i++ { + plan[i] = placements[prev[i]] + } + res = append(res, plan) + return + } + occupied := 0 + for i := range prev { + dist := len(prev) - i + bit := 1 << prev[i] + occupied |= bit | bit<>dist + } + prev = append(prev, -1) + for i := 0; i < n; i++ { + if (occupied>>i)&1 != 0 { + continue + } + prev[len(prev)-1] = i + construct(prev) + } + } + construct(make([]int, 0, n)) + return +} ``` diff --git a/website/content/ChapterFour/0001~0099/0057.Insert-Interval.md b/website/content/ChapterFour/0001~0099/0057.Insert-Interval.md index 9aef7db19..f5eb6964e 100644 --- a/website/content/ChapterFour/0001~0099/0057.Insert-Interval.md +++ b/website/content/ChapterFour/0001~0099/0057.Insert-Interval.md @@ -78,5 +78,5 @@ func insert(intervals []Interval, newInterval Interval) []Interval { ---------------------------------------------- diff --git a/website/content/ChapterFour/0001~0099/0058.Length-of-Last-Word.md b/website/content/ChapterFour/0001~0099/0058.Length-of-Last-Word.md new file mode 100644 index 000000000..3d25cf40d --- /dev/null +++ b/website/content/ChapterFour/0001~0099/0058.Length-of-Last-Word.md @@ -0,0 +1,77 @@ +# [58. Length of Last Word](https://leetcode.com/problems/length-of-last-word/) + + +## 题目 + +Given a string `s` consisting of some words separated by some number of spaces, return *the length of the **last** word in the string.* + +A **word** is a maximal substring consisting of non-space characters only. + +**Example 1:** + +``` +Input: s = "Hello World" +Output: 5 +Explanation: The last word is "World" with length 5. + +``` + +**Example 2:** + +``` +Input: s = " fly me to the moon " +Output: 4 +Explanation: The last word is "moon" with length 4. + +``` + +**Example 3:** + +``` +Input: s = "luffy is still joyboy" +Output: 6 +Explanation: The last word is "joyboy" with length 6. + +``` + +**Constraints:** + +- `1 <= s.length <= 104` +- `s` consists of only English letters and spaces `' '`. +- There will be at least one word in `s`. + +## 题目大意 + +给你一个字符串 `s`，由若干单词组成，单词前后用一些空格字符隔开。返回字符串中最后一个单词的长度。**单词** 是指仅由字母组成、不包含任何空格字符的最大子字符串。 + +## 解题思路 + +- 先从后过滤掉空格找到单词尾部，再从尾部向前遍历，找到单词头部，最后两者相减，即为单词的长度。 + +## 代码 + +```go +package leetcode + +func lengthOfLastWord(s string) int { + last := len(s) - 1 + for last >= 0 && s[last] == ' ' { + last-- + } + if last < 0 { + return 0 + } + first := last + for first >= 0 && s[first] != ' ' { + first-- + } + return last - first +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0001~0099/0059.Spiral-Matrix-II.md b/website/content/ChapterFour/0001~0099/0059.Spiral-Matrix-II.md index f9d5f999e..7d6df02a0 100755 --- a/website/content/ChapterFour/0001~0099/0059.Spiral-Matrix-II.md +++ b/website/content/ChapterFour/0001~0099/0059.Spiral-Matrix-II.md @@ -96,6 +96,6 @@ func generateMatrix(n int) [][]int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0001~0099/0062.Unique-Paths.md b/website/content/ChapterFour/0001~0099/0062.Unique-Paths.md index e2023e499..fcd62db98 100755 --- a/website/content/ChapterFour/0001~0099/0062.Unique-Paths.md +++ b/website/content/ChapterFour/0001~0099/0062.Unique-Paths.md @@ -52,14 +52,12 @@ func uniquePaths(m int, n int) int { for i := 0; i < n; i++ { dp[i] = make([]int, m) } - for i := 0; i < m; i++ { - dp[0][i] = 1 - } for i := 0; i < n; i++ { - dp[i][0] = 1 - } - for i := 1; i < n; i++ { - for j := 1; j < m; j++ { + for j := 0; j < m; j++ { + if i == 0 || j == 0 { + dp[i][j] = 1 + continue + } dp[i][j] = dp[i-1][j] + dp[i][j-1] } } diff --git a/website/content/ChapterFour/0001~0099/0064.Minimum-Path-Sum.md b/website/content/ChapterFour/0001~0099/0064.Minimum-Path-Sum.md index e0fcb0935..5f833d874 100755 --- a/website/content/ChapterFour/0001~0099/0064.Minimum-Path-Sum.md +++ b/website/content/ChapterFour/0001~0099/0064.Minimum-Path-Sum.md @@ -96,5 +96,5 @@ func minPathSum1(grid [][]int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0001~0099/0065.Valid-Number.md b/website/content/ChapterFour/0001~0099/0065.Valid-Number.md new file mode 100644 index 000000000..024f13106 --- /dev/null +++ b/website/content/ChapterFour/0001~0099/0065.Valid-Number.md @@ -0,0 +1,85 @@ +# [65. Valid Number](https://leetcode.com/problems/valid-number/) + + +## 题目 + +A **valid number** can be split up into these components (in order): + + 1. A **decimal number** or an integer. + 2. (Optional) An 'e' or 'E', followed by an **integer.** + +A **decimal number** can be split up into these components (in order): + + 1. (Optional) A sign character (either '+' or '-'). + 2. One of the following formats: + 1. One or more digits, followed by a dot '.'. + 2. One or more digits, followed by a dot '.', followed by one or more digits. + 3. A dot '.', followed by one or more digits. + +An **integer** can be split up into these components (in order): + + 1. (Optional) A sign character (either '+' or '-'). + 2. One or more digits. + +For example, all the following are valid numbers: `["2", "0089", "-0.1", "+3.14", "4.", "-.9", "2e10", "-90E3", "3e+7", "+6e-1", "53.5e93", "-123.456e789"]`, while the following are not valid numbers: `["abc", "1a", "1e", "e3", "99e2.5", "--6", "-+3", "95a54e53"].` + +Given a string s, return true if s is a **valid number.** + +**Example:** + + Input: s = "0" + Output: true + + Input: s = "e" + Output: false + +## 题目大意 + +给定一个字符串S，请根据以上的规则判断该字符串是否是一个有效的数字字符串。 + + +## 解题思路 + +- 用三个变量分别标记是否出现过数字、是否出现过'.'和 是否出现过 'e/E' +- 从左到右依次遍历字符串中的每一个元素 + - 如果是数字，则标记数字出现过 + - 如果是 '.', 则需要 '.'没有出现过，并且 'e/E' 没有出现过，才会进行标记 + - 如果是 'e/E', 则需要 'e/E'没有出现过，并且前面出现过数字，才会进行标记 + - 如果是 '+/-', 则需要是第一个字符，或者前一个字符是 'e/E'，才会进行标记，并重置数字出现的标识 + - 最后返回时，需要字符串中至少出现过数字，避免下列case: s == '.' or 'e/E' or '+/e' and etc... + +## 代码 + +```go + +package leetcode + +func isNumber(s string) bool { + numFlag, dotFlag, eFlag := false, false, false + for i := 0; i < len(s); i++ { + if '0' <= s[i] && s[i] <= '9' { + numFlag = true + } else if s[i] == '.' && !dotFlag && !eFlag { + dotFlag = true + } else if (s[i] == 'e' || s[i] == 'E') && !eFlag && numFlag { + eFlag = true + numFlag = false // reJudge integer after 'e' or 'E' + } else if (s[i] == '+' || s[i] == '-') && (i == 0 || s[i-1] == 'e' || s[i-1] == 'E') { + continue + } else { + return false + } + } + // avoid case: s == '.' or 'e/E' or '+/-' and etc... + // string s must have num + return numFlag +} + +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0001~0099/0066.Plus-One.md b/website/content/ChapterFour/0001~0099/0066.Plus-One.md index 115a610cb..37761b545 100755 --- a/website/content/ChapterFour/0001~0099/0066.Plus-One.md +++ b/website/content/ChapterFour/0001~0099/0066.Plus-One.md @@ -63,6 +63,6 @@ func plusOne(digits []int) []int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0001~0099/0069.Sqrtx.md b/website/content/ChapterFour/0001~0099/0069.Sqrtx.md index acc9ddcbe..fc0aba54a 100755 --- a/website/content/ChapterFour/0001~0099/0069.Sqrtx.md +++ b/website/content/ChapterFour/0001~0099/0069.Sqrtx.md @@ -42,24 +42,18 @@ Since the return type is an integer, the decimal digits are truncated and only package leetcode -// 解法一 二分 +// 解法一 二分, 找到最后一个满足 n^2 <= x 的整数n func mySqrt(x int) int { - if x == 0 { - return 0 - } - left, right, res := 1, x, 0 - for left <= right { - mid := left + ((right - left) >> 1) - if mid < x/mid { - left = mid + 1 - res = mid - } else if mid == x/mid { - return mid + l, r := 0, x + for l < r { + mid := (l + r + 1) / 2 + if mid*mid > x { + r = mid - 1 } else { - right = mid - 1 + l = mid } } - return res + return l } // 解法二 牛顿迭代法 https://en.wikipedia.org/wiki/Integer_square_root diff --git a/website/content/ChapterFour/0001~0099/0075.Sort-Colors.md b/website/content/ChapterFour/0001~0099/0075.Sort-Colors.md index f6248f14a..7a980a932 100644 --- a/website/content/ChapterFour/0001~0099/0075.Sort-Colors.md +++ b/website/content/ChapterFour/0001~0099/0075.Sort-Colors.md @@ -43,28 +43,16 @@ First, iterate the array counting number of 0's, 1's, and 2's, then overwrite ar package leetcode func sortColors(nums []int) { - if len(nums) == 0 { - return - } - - r := 0 - w := 0 - b := 0 // label the end of different colors; - for _, num := range nums { - if num == 0 { - nums[b] = 2 - b++ - nums[w] = 1 - w++ - nums[r] = 0 - r++ - } else if num == 1 { - nums[b] = 2 - b++ - nums[w] = 1 - w++ - } else if num == 2 { - b++ + zero, one := 0, 0 + for i, n := range nums { + nums[i] = 2 + if n <= 1 { + nums[one] = 1 + one++ + } + if n == 0 { + nums[zero] = 0 + zero++ } } } diff --git a/website/content/ChapterFour/0001~0099/0080.Remove-Duplicates-from-Sorted-Array-II.md b/website/content/ChapterFour/0001~0099/0080.Remove-Duplicates-from-Sorted-Array-II.md index 4bec75291..84a5e631a 100644 --- a/website/content/ChapterFour/0001~0099/0080.Remove-Duplicates-from-Sorted-Array-II.md +++ b/website/content/ChapterFour/0001~0099/0080.Remove-Duplicates-from-Sorted-Array-II.md @@ -2,9 +2,11 @@ ## 题目 -Given a sorted array nums, remove the duplicates in-place such that duplicates appeared at most twice and return the new length. +Given a sorted array nums, remove the duplicates in-place such that duplicates appeared at most twice and return the new +length. -Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory. +Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra +memory. **Example 1**: @@ -34,7 +36,8 @@ It doesn't matter what values are set beyond the returned length. Confused why the returned value is an integer but your answer is an array? -Note that the input array is passed in by reference, which means modification to the input array will be known to the caller as well. +Note that the input array is passed in by reference, which means modification to the input array will be known to the +caller as well. Internally you can think of this: @@ -57,9 +60,9 @@ for (int i = 0; i < len; i++) { ## 解题思路 -这道题和第 26 题很像。是第 26 题的加强版。这道题和第 283 题，第 27 题基本一致，283 题是删除 0，27 题是删除指定元素，这一题是删除重复元素，实质是一样的。 - -这里数组的删除并不是真的删除，只是将删除的元素移动到数组后面的空间内，然后返回数组实际剩余的元素个数，OJ 最终判断题目的时候会读取数组剩余个数的元素进行输出。 +- 问题提示有序数组，一般最容易想到使用双指针的解法，双指针的关键点：移动两个指针的条件。 +- 在该题中移动的条件：快指针从头遍历数组，慢指针指向修改后的数组的末端，当慢指针指向倒数第二个数与快指针指向的数不相等时，才移动慢指针，同时赋值慢指针。 +- 处理边界条件：当数组小于两个元素时，不做处理。 ## 代码 @@ -67,38 +70,15 @@ for (int i = 0; i < len; i++) { package leetcode -func removeDuplicates80(nums []int) int { - if len(nums) == 0 { - return 0 - } - last, finder := 0, 0 - for last < len(nums)-1 { - startFinder := -1 - for nums[finder] == nums[last] { - if startFinder == -1 || startFinder > finder { - startFinder = finder - } - if finder == len(nums)-1 { - break - } - finder++ - } - if finder-startFinder >= 2 && nums[finder-1] == nums[last] && nums[finder] != nums[last] { - nums[last+1] = nums[finder-1] - nums[last+2] = nums[finder] - last += 2 - } else { - nums[last+1] = nums[finder] - last++ - } - if finder == len(nums)-1 { - if nums[finder] != nums[last-1] { - nums[last] = nums[finder] - } - return last + 1 +func removeDuplicates(nums []int) int { + slow := 0 + for fast, v := range nums { + if fast < 2 || nums[slow-2] != v { + nums[slow] = v + slow++ } } - return last + 1 + return slow } diff --git a/website/content/ChapterFour/0001~0099/0084.Largest-Rectangle-in-Histogram.md b/website/content/ChapterFour/0001~0099/0084.Largest-Rectangle-in-Histogram.md index 5937127d3..c2c9e289c 100644 --- a/website/content/ChapterFour/0001~0099/0084.Largest-Rectangle-in-Histogram.md +++ b/website/content/ChapterFour/0001~0099/0084.Largest-Rectangle-in-Histogram.md @@ -41,37 +41,38 @@ Output: 10 package leetcode -import "fmt" - func largestRectangleArea(heights []int) int { - maxArea, stack, height := 0, []int{}, 0 - for i := 0; i <= len(heights); i++ { - if i == len(heights) { - height = 0 - } else { - height = heights[i] + maxArea := 0 + n := len(heights) + 2 + // Add a sentry at the beginning and the end + getHeight := func(i int) int { + if i == 0 || n-1 == i { + return 0 } - if len(stack) == 0 || height >= heights[stack[len(stack)-1]] { - stack = append(stack, i) - } else { - tmp := stack[len(stack)-1] - fmt.Printf("1. tmp = %v stack = %v\n", tmp, stack) - stack = stack[:len(stack)-1] - length := 0 - if len(stack) == 0 { - length = i - } else { - length = i - 1 - stack[len(stack)-1] - fmt.Printf("2. length = %v stack = %v i = %v\n", length, stack, i) - } - maxArea = max(maxArea, heights[tmp]*length) - fmt.Printf("3. maxArea = %v heights[tmp]*length = %v\n", maxArea, heights[tmp]*length) - i-- + return heights[i-1] + } + st := make([]int, 0, n/2) + for i := 0; i < n; i++ { + for len(st) > 0 && getHeight(st[len(st)-1]) > getHeight(i) { + // pop stack + idx := st[len(st)-1] + st = st[:len(st)-1] + maxArea = max(maxArea, getHeight(idx)*(i-st[len(st)-1]-1)) } + // push stack + st = append(st, i) } return maxArea } +func max(a int, b int) int { + if a > b { + return a + } + return b +} + + ``` diff --git a/website/content/ChapterFour/0001~0099/0091.Decode-Ways.md b/website/content/ChapterFour/0001~0099/0091.Decode-Ways.md index 6bb4b168e..7ac985062 100755 --- a/website/content/ChapterFour/0001~0099/0091.Decode-Ways.md +++ b/website/content/ChapterFour/0001~0099/0091.Decode-Ways.md @@ -51,32 +51,19 @@ Given a **non-empty** string containing only digits, determine the total numbe package leetcode -import ( - "strconv" -) - func numDecodings(s string) int { - if len(s) == 0 { - return 0 - } - dp := make([]int, len(s)+1) + n := len(s) + dp := make([]int, n+1) dp[0] = 1 - if s[:1] == "0" { - dp[1] = 0 - } else { - dp[1] = 1 - } - for i := 2; i <= len(s); i++ { - lastNum, _ := strconv.Atoi(s[i-1 : i]) - if lastNum >= 1 && lastNum <= 9 { + for i := 1; i <= n; i++ { + if s[i-1] != '0' { dp[i] += dp[i-1] } - lastNum, _ = strconv.Atoi(s[i-2 : i]) - if lastNum >= 10 && lastNum <= 26 { + if i > 1 && s[i-2] != '0' && (s[i-2]-'0')*10+(s[i-1]-'0') <= 26 { dp[i] += dp[i-2] } } - return dp[len(s)] + return dp[n] } ``` diff --git a/website/content/ChapterFour/0001~0099/0096.Unique-Binary-Search-Trees.md b/website/content/ChapterFour/0001~0099/0096.Unique-Binary-Search-Trees.md index 688a3d0ae..f98628afc 100755 --- a/website/content/ChapterFour/0001~0099/0096.Unique-Binary-Search-Trees.md +++ b/website/content/ChapterFour/0001~0099/0096.Unique-Binary-Search-Trees.md @@ -56,5 +56,5 @@ func numTrees(n int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0001~0099/0097.Interleaving-String.md b/website/content/ChapterFour/0001~0099/0097.Interleaving-String.md new file mode 100644 index 000000000..2b6daae8c --- /dev/null +++ b/website/content/ChapterFour/0001~0099/0097.Interleaving-String.md @@ -0,0 +1,111 @@ +# [97. Interleaving String](https://leetcode.com/problems/interleaving-string/) + + +## 题目 + +Given strings `s1`, `s2`, and `s3`, find whether `s3` is formed by an **interleaving** of `s1` and `s2`. + +An **interleaving** of two strings `s` and `t` is a configuration where they are divided into **non-empty** substrings such that: + +- `s = s1 + s2 + ... + sn` +- `t = t1 + t2 + ... + tm` +- `|n - m| <= 1` +- The **interleaving** is `s1 + t1 + s2 + t2 + s3 + t3 + ...` or `t1 + s1 + t2 + s2 + t3 + s3 + ...` + +**Note:** `a + b` is the concatenation of strings `a` and `b`. + +**Example 1:** + +![https://assets.leetcode.com/uploads/2020/09/02/interleave.jpg](https://assets.leetcode.com/uploads/2020/09/02/interleave.jpg) + +``` +Input: s1 = "aabcc", s2 = "dbbca", s3 = "aadbbcbcac" +Output: true + +``` + +**Example 2:** + +``` +Input: s1 = "aabcc", s2 = "dbbca", s3 = "aadbbbaccc" +Output: false + +``` + +**Example 3:** + +``` +Input: s1 = "", s2 = "", s3 = "" +Output: true + +``` + +**Constraints:** + +- `0 <= s1.length, s2.length <= 100` +- `0 <= s3.length <= 200` +- `s1`, `s2`, and `s3` consist of lowercase English letters. + +**Follow up:** Could you solve it using only `O(s2.length)` additional memory space? + +## 题目大意 + +给定三个字符串 s1、s2、s3，请你帮忙验证 s3 是否是由 s1 和 s2 交错 组成的。两个字符串 s 和 t 交错 的定义与过程如下，其中每个字符串都会被分割成若干 非空 子字符串： + +- s = s1 + s2 + ... + sn +- t = t1 + t2 + ... + tm +- |n - m| <= 1 +- 交错 是 s1 + t1 + s2 + t2 + s3 + t3 + ... 或者 t1 + s1 + t2 + s2 + t3 + s3 + ... + +提示：a + b 意味着字符串 a 和 b 连接。 + +## 解题思路 + +- 深搜或者广搜暴力解题。笔者用深搜实现的。记录 s1 和 s2 串当前比较的位置 p1 和 p2。如果 s3[p1+p2] 的位置上等于 s1[p1] 或者 s2[p2] 代表能匹配上，那么继续往后移动 p1 和 p2 相应的位置。因为是交错字符串，所以判断匹配的位置是 s3[p1+p2] 的位置。如果仅仅这么写，会超时，s1 和 s2 两个字符串重复交叉判断的位置太多了。需要加上记忆化搜索。可以用 visited[i][j] 这样的二维数组来记录是否搜索过了。笔者为了压缩空间，将 i 和 j 编码压缩到一维数组了。i * len(s3) + j 是唯一下标，所以可以用这种方式存储是否搜索过。具体代码见下面的实现。 + +## 代码 + +```go +package leetcode + +func isInterleave(s1 string, s2 string, s3 string) bool { + if len(s1)+len(s2) != len(s3) { + return false + } + visited := make(map[int]bool) + return dfs(s1, s2, s3, 0, 0, visited) +} + +func dfs(s1, s2, s3 string, p1, p2 int, visited map[int]bool) bool { + if p1+p2 == len(s3) { + return true + } + if _, ok := visited[(p1*len(s3))+p2]; ok { + return false + } + visited[(p1*len(s3))+p2] = true + var match1, match2 bool + if p1 < len(s1) && s3[p1+p2] == s1[p1] { + match1 = true + } + if p2 < len(s2) && s3[p1+p2] == s2[p2] { + match2 = true + } + if match1 && match2 { + return dfs(s1, s2, s3, p1+1, p2, visited) || dfs(s1, s2, s3, p1, p2+1, visited) + } else if match1 { + return dfs(s1, s2, s3, p1+1, p2, visited) + } else if match2 { + return dfs(s1, s2, s3, p1, p2+1, visited) + } else { + return false + } +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0001~0099/0098.Validate-Binary-Search-Tree.md b/website/content/ChapterFour/0001~0099/0098.Validate-Binary-Search-Tree.md index 7c1247151..ffc988c57 100755 --- a/website/content/ChapterFour/0001~0099/0098.Validate-Binary-Search-Tree.md +++ b/website/content/ChapterFour/0001~0099/0098.Validate-Binary-Search-Tree.md @@ -101,6 +101,6 @@ func inOrder(root *TreeNode, arr *[]int) { ---------------------------------------------- diff --git a/website/content/ChapterFour/0100~0199/0101.Symmetric-Tree.md b/website/content/ChapterFour/0100~0199/0101.Symmetric-Tree.md index 1c23821cb..2b9de1e98 100644 --- a/website/content/ChapterFour/0100~0199/0101.Symmetric-Tree.md +++ b/website/content/ChapterFour/0100~0199/0101.Symmetric-Tree.md @@ -54,7 +54,7 @@ Bonus points if you could solve it both recursively and iteratively. package leetcode import ( - "github.com/halfrost/LeetCode-Go/structures" + "github.com/halfrost/leetcode-go/structures" ) // TreeNode define @@ -71,20 +71,20 @@ type TreeNode = structures.TreeNode // 解法一 dfs func isSymmetric(root *TreeNode) bool { - return root == nil || dfs(root.Left, root.Right) + if root == nil { + return true + } + return isMirror(root.Left, root.Right) } -func dfs(rootLeft, rootRight *TreeNode) bool { - if rootLeft == nil && rootRight == nil { +func isMirror(left *TreeNode, right *TreeNode) bool { + if left == nil && right == nil { return true } - if rootLeft == nil || rootRight == nil { + if left == nil || right == nil { return false } - if rootLeft.Val != rootRight.Val { - return false - } - return dfs(rootLeft.Left, rootRight.Right) && dfs(rootLeft.Right, rootRight.Left) + return (left.Val == right.Val) && isMirror(left.Left, right.Right) && isMirror(left.Right, right.Left) } // 解法二 @@ -119,6 +119,7 @@ func invertTree(root *TreeNode) *TreeNode { } + ``` diff --git a/website/content/ChapterFour/0100~0199/0102.Binary-Tree-Level-Order-Traversal.md b/website/content/ChapterFour/0100~0199/0102.Binary-Tree-Level-Order-Traversal.md index 226aafe4d..68f93c42a 100644 --- a/website/content/ChapterFour/0100~0199/0102.Binary-Tree-Level-Order-Traversal.md +++ b/website/content/ChapterFour/0100~0199/0102.Binary-Tree-Level-Order-Traversal.md @@ -51,7 +51,7 @@ return its level order traversal as: package leetcode import ( - "github.com/halfrost/LeetCode-Go/structures" + "github.com/halfrost/leetcode-go/structures" ) // TreeNode define diff --git a/website/content/ChapterFour/0100~0199/0103.Binary-Tree-Zigzag-Level-Order-Traversal.md b/website/content/ChapterFour/0100~0199/0103.Binary-Tree-Zigzag-Level-Order-Traversal.md index 9553543e8..0afad6242 100644 --- a/website/content/ChapterFour/0100~0199/0103.Binary-Tree-Zigzag-Level-Order-Traversal.md +++ b/website/content/ChapterFour/0100~0199/0103.Binary-Tree-Zigzag-Level-Order-Traversal.md @@ -49,7 +49,7 @@ return its zigzag level order traversal as: package leetcode import ( - "github.com/halfrost/LeetCode-Go/structures" + "github.com/halfrost/leetcode-go/structures" ) // TreeNode define diff --git a/website/content/ChapterFour/0100~0199/0105.Construct-Binary-Tree-from-Preorder-and-Inorder-Traversal.md b/website/content/ChapterFour/0100~0199/0105.Construct-Binary-Tree-from-Preorder-and-Inorder-Traversal.md index 5de3c4e43..556a6da65 100755 --- a/website/content/ChapterFour/0100~0199/0105.Construct-Binary-Tree-from-Preorder-and-Inorder-Traversal.md +++ b/website/content/ChapterFour/0100~0199/0105.Construct-Binary-Tree-from-Preorder-and-Inorder-Traversal.md @@ -42,6 +42,13 @@ Return the following binary tree: package leetcode +import ( + "github.com/halfrost/leetcode-go/structures" +) + +// TreeNode define +type TreeNode = structures.TreeNode + /** * Definition for a binary tree node. * type TreeNode struct { @@ -50,7 +57,24 @@ package leetcode * Right *TreeNode * } */ + +// 解法一, 直接传入需要的 slice 范围作为输入, 可以避免申请对应 inorder 索引的内存, 内存使用(leetcode test case) 4.7MB -> 4.3MB. func buildTree(preorder []int, inorder []int) *TreeNode { + if len(preorder) == 0 { + return nil + } + root := &TreeNode{Val: preorder[0]} + for pos, node := range inorder { + if node == root.Val { + root.Left = buildTree(preorder[1:pos+1], inorder[:pos]) + root.Right = buildTree(preorder[pos+1:], inorder[pos+1:]) + } + } + return root +} + +// 解法二 +func buildTree1(preorder []int, inorder []int) *TreeNode { inPos := make(map[int]int) for i := 0; i < len(inorder); i++ { inPos[inorder[i]] = i @@ -70,6 +94,7 @@ func buildPreIn2TreeDFS(pre []int, preStart int, preEnd int, inStart int, inPos return root } + ``` diff --git a/website/content/ChapterFour/0100~0199/0106.Construct-Binary-Tree-from-Inorder-and-Postorder-Traversal.md b/website/content/ChapterFour/0100~0199/0106.Construct-Binary-Tree-from-Inorder-and-Postorder-Traversal.md index 77b102d56..fe051ed8c 100755 --- a/website/content/ChapterFour/0100~0199/0106.Construct-Binary-Tree-from-Inorder-and-Postorder-Traversal.md +++ b/website/content/ChapterFour/0100~0199/0106.Construct-Binary-Tree-from-Inorder-and-Postorder-Traversal.md @@ -40,6 +40,13 @@ Return the following binary tree: package leetcode +import ( + "github.com/halfrost/leetcode-go/structures" +) + +// TreeNode define +type TreeNode = structures.TreeNode + /** * Definition for a binary tree node. * type TreeNode struct { @@ -48,7 +55,26 @@ package leetcode * Right *TreeNode * } */ -func buildTree106(inorder []int, postorder []int) *TreeNode { + +// 解法一, 直接传入需要的 slice 范围作为输入, 可以避免申请对应 inorder 索引的内存, 内存使用(leetcode test case) 4.7MB -> 4.3MB. +func buildTree(inorder []int, postorder []int) *TreeNode { + postorderLen := len(postorder) + if len(inorder) == 0 { + return nil + } + root := &TreeNode{Val: postorder[postorderLen-1]} + postorder = postorder[:postorderLen-1] + for pos, node := range inorder { + if node == root.Val { + root.Left = buildTree(inorder[:pos], postorder[:len(inorder[:pos])]) + root.Right = buildTree(inorder[pos+1:], postorder[len(inorder[:pos]):]) + } + } + return root +} + +// 解法二 +func buildTree1(inorder []int, postorder []int) *TreeNode { inPos := make(map[int]int) for i := 0; i < len(inorder); i++ { inPos[inorder[i]] = i @@ -68,6 +94,7 @@ func buildInPos2TreeDFS(post []int, postStart int, postEnd int, inStart int, inP return root } + ``` diff --git a/website/content/ChapterFour/0100~0199/0115.Distinct-Subsequences.md b/website/content/ChapterFour/0100~0199/0115.Distinct-Subsequences.md index cb88a997b..b3baae4d5 100644 --- a/website/content/ChapterFour/0100~0199/0115.Distinct-Subsequences.md +++ b/website/content/ChapterFour/0100~0199/0115.Distinct-Subsequences.md @@ -104,5 +104,5 @@ func numDistinct1(s, t string) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0100~0199/0116.Populating-Next-Right-Pointers-in-Each-Node.md b/website/content/ChapterFour/0100~0199/0116.Populating-Next-Right-Pointers-in-Each-Node.md new file mode 100644 index 000000000..95b54ea29 --- /dev/null +++ b/website/content/ChapterFour/0100~0199/0116.Populating-Next-Right-Pointers-in-Each-Node.md @@ -0,0 +1,125 @@ +# [116. Populating Next Right Pointers in Each Node](https://leetcode.com/problems/populating-next-right-pointers-in-each-node/) + + +## 题目 + +You are given a **perfect binary tree** where all leaves are on the same level, and every parent has two children. The binary tree has the following definition: + +``` +struct Node { + int val; + Node *left; + Node *right; + Node *next; +} + +``` + +Populate each next pointer to point to its next right node. If there is no next right node, the next pointer should be set to `NULL`. + +Initially, all next pointers are set to `NULL`. + +**Follow up:** + +- You may only use constant extra space. +- Recursive approach is fine, you may assume implicit stack space does not count as extra space for this problem. + +**Example 1:** + +![https://assets.leetcode.com/uploads/2019/02/14/116_sample.png](https://assets.leetcode.com/uploads/2019/02/14/116_sample.png) + +``` +Input: root = [1,2,3,4,5,6,7] +Output: [1,#,2,3,#,4,5,6,7,#] +Explanation:Given the above perfect binary tree (Figure A), your function should populate each next pointer to point to its next right node, just like in Figure B. The serialized output is in level order as connected by the next pointers, with '#' signifying the end of each level. + +``` + +**Constraints:** + +- The number of nodes in the given tree is less than `4096`. +- `1000 <= node.val <= 1000` + +## 题目大意 + +给定一个 完美二叉树 ，其所有叶子节点都在同一层，每个父节点都有两个子节点。二叉树定义如下： + +```jsx +struct Node { + int val; + Node *left; + Node *right; + Node *next; +} + +``` + +填充它的每个 next 指针，让这个指针指向其下一个右侧节点。如果找不到下一个右侧节点，则将 next 指针设置为 NULL。初始状态下，所有 next 指针都被设置为 NULL。 + +## 解题思路 + +- 本质上是二叉树的层序遍历，基于广度优先搜索，将每层的节点放入队列，并遍历队列进行连接。 + +## 代码 + +```go +package leetcode + +type Node struct { + Val int + Left *Node + Right *Node + Next *Node +} + +//解法一：迭代 +func connect(root *Node) *Node { + if root == nil { + return root + } + q := []*Node{root} + for len(q) > 0 { + var p []*Node + // 遍历这一层的所有节点 + for i, node := range q { + if i+1 < len(q) { + node.Next = q[i+1] + } + if node.Left != nil { + p = append(p, node.Left) + } + if node.Right != nil { + p = append(p, node.Right) + } + } + q = p + } + return root +} + +// 解法二 递归 +func connect2(root *Node) *Node { + if root == nil { + return nil + } + connectTwoNode(root.Left, root.Right) + return root +} + +func connectTwoNode(node1, node2 *Node) { + if node1 == nil || node2 == nil { + return + } + node1.Next = node2 + connectTwoNode(node1.Left, node1.Right) + connectTwoNode(node2.Left, node2.Right) + connectTwoNode(node1.Right, node2.Left) +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0100~0199/0118.Pascals-Triangle.md b/website/content/ChapterFour/0100~0199/0118.Pascals-Triangle.md index 60efaae97..9dee8ab67 100644 --- a/website/content/ChapterFour/0100~0199/0118.Pascals-Triangle.md +++ b/website/content/ChapterFour/0100~0199/0118.Pascals-Triangle.md @@ -62,6 +62,6 @@ func generate(numRows int) [][]int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0100~0199/0128.Longest-Consecutive-Sequence.md b/website/content/ChapterFour/0100~0199/0128.Longest-Consecutive-Sequence.md index ef76f90d5..fddce0f06 100755 --- a/website/content/ChapterFour/0100~0199/0128.Longest-Consecutive-Sequence.md +++ b/website/content/ChapterFour/0100~0199/0128.Longest-Consecutive-Sequence.md @@ -37,7 +37,7 @@ Your algorithm should run in O(*n*) complexity. package leetcode import ( - "github.com/halfrost/LeetCode-Go/template" + "github.com/halfrost/leetcode-go/template" ) // 解法一 map，时间复杂度 O(n) diff --git a/website/content/ChapterFour/0100~0199/0129.Sum-Root-to-Leaf-Numbers.md b/website/content/ChapterFour/0100~0199/0129.Sum-Root-to-Leaf-Numbers.md index b1a0636d5..312f4a066 100755 --- a/website/content/ChapterFour/0100~0199/0129.Sum-Root-to-Leaf-Numbers.md +++ b/website/content/ChapterFour/0100~0199/0129.Sum-Root-to-Leaf-Numbers.md @@ -45,7 +45,7 @@ Find the total sum of all root-to-leaf numbers. ## 解题思路 -- 这一题是第 257 题的变形题，第 257 题要求输出每条从根节点到叶子节点的路径，这一题变成了把每一个从根节点到叶子节点的数字都串联起来，再累加每条路径，求出最后的总和。实际做题思路基本没变 +- 这一题是第 257 题的变形题，第 257 题要求输出每条从根节点到叶子节点的路径，这一题变成了把每一个从根节点到叶子节点的数字都串联起来，再累加每条路径，求出最后的总和。实际做题思路基本没变。运用前序遍历的思想，当从根节点出发一直加到叶子节点，每个叶子节点汇总一次。 ## 代码 @@ -55,9 +55,12 @@ Find the total sum of all root-to-leaf numbers. package leetcode import ( - "strconv" + "github.com/halfrost/leetcode-go/structures" ) +// TreeNode define +type TreeNode = structures.TreeNode + /** * Definition for a binary tree node. * type TreeNode struct { @@ -66,32 +69,24 @@ import ( * Right *TreeNode * } */ + func sumNumbers(root *TreeNode) int { - res, nums := 0, binaryTreeNums(root) - for _, n := range nums { - num, _ := strconv.Atoi(n) - res += num - } + res := 0 + dfs(root,0,&res) return res } -func binaryTreeNums(root *TreeNode) []string { - if root == nil { - return []string{} +func dfs(root *TreeNode,sum int,res *int) { + if root == nil{ + return } - res := []string{} - if root.Left == nil && root.Right == nil { - return []string{strconv.Itoa(root.Val)} + sum = sum*10 + root.Val + if root.Left == nil && root.Right == nil{ + *res += sum + return } - tmpLeft := binaryTreeNums(root.Left) - for i := 0; i < len(tmpLeft); i++ { - res = append(res, strconv.Itoa(root.Val)+tmpLeft[i]) - } - tmpRight := binaryTreeNums(root.Right) - for i := 0; i < len(tmpRight); i++ { - res = append(res, strconv.Itoa(root.Val)+tmpRight[i]) - } - return res + dfs(root.Left,sum,res) + dfs(root.Right,sum,res) } ``` diff --git a/website/content/ChapterFour/0100~0199/0130.Surrounded-Regions.md b/website/content/ChapterFour/0100~0199/0130.Surrounded-Regions.md index 3211fb082..279e9551b 100755 --- a/website/content/ChapterFour/0100~0199/0130.Surrounded-Regions.md +++ b/website/content/ChapterFour/0100~0199/0130.Surrounded-Regions.md @@ -46,7 +46,7 @@ Surrounded regions shouldn’t be on the border, which means that any `'O'` on package leetcode import ( - "github.com/halfrost/LeetCode-Go/template" + "github.com/halfrost/leetcode-go/template" ) // 解法一 并查集 diff --git a/website/content/ChapterFour/0100~0199/0131.Palindrome-Partitioning.md b/website/content/ChapterFour/0100~0199/0131.Palindrome-Partitioning.md index a619e00b4..eb77f95c5 100755 --- a/website/content/ChapterFour/0100~0199/0131.Palindrome-Partitioning.md +++ b/website/content/ChapterFour/0100~0199/0131.Palindrome-Partitioning.md @@ -124,5 +124,5 @@ func isPal(str string, s, e int) bool { ---------------------------------------------- diff --git a/website/content/ChapterFour/0100~0199/0135.Candy.md b/website/content/ChapterFour/0100~0199/0135.Candy.md new file mode 100644 index 000000000..d2df666b9 --- /dev/null +++ b/website/content/ChapterFour/0100~0199/0135.Candy.md @@ -0,0 +1,81 @@ +# [135. Candy](https://leetcode.com/problems/candy/) + + +## 题目 + +There are `n` children standing in a line. Each child is assigned a rating value given in the integer array `ratings`. + +You are giving candies to these children subjected to the following requirements: + +- Each child must have at least one candy. +- Children with a higher rating get more candies than their neighbors. + +Return *the minimum number of candies you need to have to distribute the candies to the children*. + +**Example 1:** + +``` +Input: ratings = [1,0,2] +Output: 5 +Explanation: You can allocate to the first, second and third child with 2, 1, 2 candies respectively. +``` + +**Example 2:** + +``` +Input: ratings = [1,2,2] +Output: 4 +Explanation: You can allocate to the first, second and third child with 1, 2, 1 candies respectively. +The third child gets 1 candy because it satisfies the above two conditions. +``` + +**Constraints:** + +- `n == ratings.length` +- `1 <= n <= 2 * 10^4` +- `0 <= ratings[i] <= 2 * 10^4` + +## 题目大意 + +老师想给孩子们分发糖果，有 N 个孩子站成了一条直线，老师会根据每个孩子的表现，预先给他们评分。你需要按照以下要求，帮助老师给这些孩子分发糖果： + +- 每个孩子至少分配到 1 个糖果。 +- 评分更高的孩子必须比他两侧的邻位孩子获得更多的糖果。 + +那么这样下来，老师至少需要准备多少颗糖果呢？ + +## 解题思路 + +- 本题的突破口在于，评分更高的孩子必须比他两侧的邻位孩子获得更多的糖果，这句话。这个规则可以理解为 2 条规则，想象成按身高排队，站在下标为 0 的地方往后“看”，评分高即为个子高的，应该比前面个子矮(评分低)的分到糖果多；站在下标为 n - 1 的地方往后“看”，评分高即为个子高的，同样应该比前面个子矮(评分低)的分到糖果多。你可能会有疑问，规则都是一样的，为什么会出现至少需要多少糖果呢？因为可能出现评分一样高的同学。扫描数组两次，处理出每一个学生分别满足左规则或右规则时，最少需要被分得的糖果数量。每个人最终分得的糖果数量即为这两个数量的最大值。两次遍历结束，将所有糖果累加起来即为至少需要准备的糖果数。由于每个人至少分配到 1 个糖果，所以每个人糖果数再加一。 + +## 代码 + +```go +package leetcode + +func candy(ratings []int) int { + candies := make([]int, len(ratings)) + for i := 1; i < len(ratings); i++ { + if ratings[i] > ratings[i-1] { + candies[i] += candies[i-1] + 1 + } + } + for i := len(ratings) - 2; i >= 0; i-- { + if ratings[i] > ratings[i+1] && candies[i] <= candies[i+1] { + candies[i] = candies[i+1] + 1 + } + } + total := 0 + for _, candy := range candies { + total += candy + 1 + } + return total +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0100~0199/0136.Single-Number.md b/website/content/ChapterFour/0100~0199/0136.Single-Number.md index 02b2b4b41..a5801d4e1 100755 --- a/website/content/ChapterFour/0100~0199/0136.Single-Number.md +++ b/website/content/ChapterFour/0100~0199/0136.Single-Number.md @@ -26,7 +26,7 @@ Your algorithm should have a linear runtime complexity. Could you implement it w ## 解题思路 - 题目要求不能使用辅助空间，并且时间复杂度只能是线性的。 -- 题目为什么要强调有一个数字出现一次，其他的出现两次？我们想到了异或运算的性质：任何一个数字异或它自己都等于0。也就是说，如果我们从头到尾依次异或数组中的每一个数字，那么最终的结果刚好是那个只出现依次的数字，因为那些出现两次的数字全部在异或中抵消掉了。于是最终做法是从头到尾依次异或数组中的每一个数字，那么最终得到的结果就是两个只出现一次的数字的异或结果。因为其他数字都出现了两次，在异或中全部抵消掉了。**利用的性质是 x^x = 0**。 +- 题目为什么要强调有一个数字出现一次，其他的出现两次？我们想到了异或运算的性质：任何一个数字异或它自己都等于0。也就是说，如果我们从头到尾依次异或数组中的每一个数字，那么最终的结果刚好是那个只出现一次的数字，因为那些出现两次的数字全部在异或中抵消掉了。于是最终做法是从头到尾依次异或数组中的每一个数字，那么最终得到的结果就是两个只出现一次的数字的异或结果。因为其他数字都出现了两次，在异或中全部抵消掉了。**利用的性质是 x^x = 0**。 ## 代码 @@ -48,6 +48,6 @@ func singleNumber(nums []int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0100~0199/0137.Single-Number-II.md b/website/content/ChapterFour/0100~0199/0137.Single-Number-II.md index 172739cff..9cbca6720 100755 --- a/website/content/ChapterFour/0100~0199/0137.Single-Number-II.md +++ b/website/content/ChapterFour/0100~0199/0137.Single-Number-II.md @@ -30,9 +30,9 @@ Your algorithm should have a linear runtime complexity. Could you implement it w ## 解题思路 - 这一题是第 136 题的加强版。这类题也可以扩展，在数组中每个元素都出现 5 次，找出只出现 1 次的数。 -- 本题中要求找出只出现 1 次的数，出现 3 次的数都要被消除。第 136 题是消除出现 2 次的数。这一题也会相当相同的解法，出现 3 次的数也要被消除。定义状态，00、10、01，这 3 个状态。当一个数出现 3 次，那么它每个位置上的 1 出现的次数肯定是 3 的倍数，所以当 1 出现 3 次以后，就归零清除。如何能做到这点呢？仿造`三进制(00，10，01)` 就可以做到。 +- 本题中要求找出只出现 1 次的数，出现 3 次的数都要被消除。第 136 题是消除出现 2 次的数。这一题也会相当相同的解法，出现 3 次的数也要被消除。定义状态，00、10、01，这 3 个状态。当一个数出现 3 次，那么它每个位置上的 1 出现的次数肯定是 3 的倍数，所以当 1 出现 3 次以后，就归零清除。如何能做到这点呢？仿造`三进制(00，01，10)` 就可以做到。 - 变量 ones 中记录遍历中每个位上出现 1 的个数。将它与 A[i] 进行异或，目的是： - - 每位上两者都是 1 的，表示历史统计结果 ones 出现1次、A[i]中又出现1次，则是出现 2 次，需要进位到 twos 变量中。 + - 每位上两者都是 1 的，表示历史统计结果 ones 出现1次、A[i]中又出现 1 次，则是出现 2 次，需要进位到 twos 变量中。 - 每位上两者分别为 0、1 的，加入到 ones 统计结果中。 - 最后还要 & ^twos ，是为了能做到三进制，出现 3 次就清零。例如 ones = x，那么 twos = 0，当 twos = x，那么 ones = 0； - 变量 twos 中记录遍历中每个位上出现 1 ，2次 的个数。与 A[i] 进行异或的目的和上述描述相同，不再赘述。 @@ -41,6 +41,31 @@ Your algorithm should have a linear runtime complexity. Could you implement it w > 在 golang 中没有 Java 中的 ~ 位操作运算符，Java 中的 ~ 运算符代表按位取反。这个操作就想当于 golang 中的 ^ 运算符当做一元运算符使用的效果。 +|(twos,ones)|xi|(twos'',ones')|ones'| +|:----:|:----:|:----:|:----:| +|00|0|00|0| +|00|1|01|1| +|01|0|01|1| +|01|1|10|0| +|10|0|10|0| +|10|1|00|0| + +- 第一步，先将 ones -> ones'。通过观察可以看出 ones = (ones ^ nums[i]) & ^twos + +|(twos,ones')|xi|twos'| +|:----:|:----:|:----:| +|00|0|0| +|01|1|0| +|01|0|0| +|00|1|1| +|10|0|1| +|10|1|0| + + +- 第二步，再将 twos -> twos'。这一步需要用到前一步的 ones。通过观察可以看出 twos = (twos ^ nums[i]) & ^ones。 + +-------------------------- + 这一题还可以继续扩展，在数组中每个元素都出现 5 次，找出只出现 1 次的数。那该怎么做呢？思路还是一样的，模拟一个五进制，5 次就会消除。代码如下： // 解法一 diff --git a/website/content/ChapterFour/0100~0199/0141.Linked-List-Cycle.md b/website/content/ChapterFour/0100~0199/0141.Linked-List-Cycle.md index 248a7b62c..96c3310bd 100644 --- a/website/content/ChapterFour/0100~0199/0141.Linked-List-Cycle.md +++ b/website/content/ChapterFour/0100~0199/0141.Linked-List-Cycle.md @@ -23,19 +23,25 @@ Can you solve it without using extra space? package leetcode +import ( + "github.com/halfrost/leetcode-go/structures" +) + +// ListNode define +type ListNode = structures.ListNode + /** * Definition for singly-linked list. - * struct ListNode { - * int val; - * ListNode *next; - * ListNode(int x) : val(x), next(NULL) {} - * }; + * type ListNode struct { + * Val int + * Next *ListNode + * } */ func hasCycle(head *ListNode) bool { fast := head slow := head - for slow != nil && fast != nil && fast.Next != nil { + for fast != nil && fast.Next != nil { fast = fast.Next.Next slow = slow.Next if fast == slow { @@ -45,6 +51,7 @@ func hasCycle(head *ListNode) bool { return false } + ``` diff --git a/website/content/ChapterFour/0100~0199/0143.Reorder-List.md b/website/content/ChapterFour/0100~0199/0143.Reorder-List.md index bd9b24690..4e835246c 100644 --- a/website/content/ChapterFour/0100~0199/0143.Reorder-List.md +++ b/website/content/ChapterFour/0100~0199/0143.Reorder-List.md @@ -35,7 +35,7 @@ Given 1->2->3->4->5, reorder it to 1->5->2->4->3. 更好的做法是结合之前几道题的操作：链表逆序，找中间结点。 -先找到链表的中间结点，然后利用逆序区间的操作，如 [第 92 题](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode/0092.Reverse-Linked-List-II) 里的 reverseBetween() 操作，只不过这里的反转区间是从中点一直到末尾。最后利用 2 个指针，一个指向头结点，一个指向中间结点，开始拼接最终的结果。这种做法的时间复杂度是 O(n)，空间复杂度是 O(1)。 +先找到链表的中间结点，然后利用逆序区间的操作，如 [第 92 题](https://github.com/halfrost/leetcode-go/tree/master/leetcode/0092.Reverse-Linked-List-II) 里的 reverseBetween() 操作，只不过这里的反转区间是从中点一直到末尾。最后利用 2 个指针，一个指向头结点，一个指向中间结点，开始拼接最终的结果。这种做法的时间复杂度是 O(n)，空间复杂度是 O(1)。 ## 代码 diff --git a/website/content/ChapterFour/0100~0199/0150.Evaluate-Reverse-Polish-Notation.md b/website/content/ChapterFour/0100~0199/0150.Evaluate-Reverse-Polish-Notation.md index 9b06aa859..0e4614d5a 100644 --- a/website/content/ChapterFour/0100~0199/0150.Evaluate-Reverse-Polish-Notation.md +++ b/website/content/ChapterFour/0100~0199/0150.Evaluate-Reverse-Polish-Notation.md @@ -66,46 +66,23 @@ import ( ) func evalRPN(tokens []string) int { - if len(tokens) == 1 { - i, _ := strconv.Atoi(tokens[0]) - return i - } - stack, top := []int{}, 0 - for _, v := range tokens { - switch v { - case "+": - { - sum := stack[top-2] + stack[top-1] - stack = stack[:top-2] - stack = append(stack, sum) - top-- - } - case "-": - { - sub := stack[top-2] - stack[top-1] - stack = stack[:top-2] - stack = append(stack, sub) - top-- - } - case "*": - { - mul := stack[top-2] * stack[top-1] - stack = stack[:top-2] - stack = append(stack, mul) - top-- - } - case "/": - { - div := stack[top-2] / stack[top-1] - stack = stack[:top-2] - stack = append(stack, div) - top-- - } - default: - { - i, _ := strconv.Atoi(v) - stack = append(stack, i) - top++ + stack := make([]int, 0, len(tokens)) + for _, token := range tokens { + v, err := strconv.Atoi(token) + if err == nil { + stack = append(stack, v) + } else { + num1, num2 := stack[len(stack)-2], stack[len(stack)-1] + stack = stack[:len(stack)-2] + switch token { + case "+": + stack = append(stack, num1+num2) + case "-": + stack = append(stack, num1-num2) + case "*": + stack = append(stack, num1*num2) + case "/": + stack = append(stack, num1/num2) } } } diff --git a/website/content/ChapterFour/0100~0199/0168.Excel-Sheet-Column-Title.md b/website/content/ChapterFour/0100~0199/0168.Excel-Sheet-Column-Title.md index 6c62c3584..6cfe377e7 100644 --- a/website/content/ChapterFour/0100~0199/0168.Excel-Sheet-Column-Title.md +++ b/website/content/ChapterFour/0100~0199/0168.Excel-Sheet-Column-Title.md @@ -7,7 +7,7 @@ Given a positive integer, return its corresponding column title as appear in an For example: ``` - 1 -> A + 1 -> A 2 -> B 3 -> C ... diff --git a/website/content/ChapterFour/0100~0199/0173.Binary-Search-Tree-Iterator.md b/website/content/ChapterFour/0100~0199/0173.Binary-Search-Tree-Iterator.md index eb4b039c7..559f61217 100755 --- a/website/content/ChapterFour/0100~0199/0173.Binary-Search-Tree-Iterator.md +++ b/website/content/ChapterFour/0100~0199/0173.Binary-Search-Tree-Iterator.md @@ -47,7 +47,7 @@ package leetcode import ( "container/heap" - "github.com/halfrost/LeetCode-Go/structures" + "github.com/halfrost/leetcode-go/structures" ) // TreeNode define diff --git a/website/content/ChapterFour/0100~0199/0199.Binary-Tree-Right-Side-View.md b/website/content/ChapterFour/0100~0199/0199.Binary-Tree-Right-Side-View.md index 8f0e72c17..70be59786 100644 --- a/website/content/ChapterFour/0100~0199/0199.Binary-Tree-Right-Side-View.md +++ b/website/content/ChapterFour/0100~0199/0199.Binary-Tree-Right-Side-View.md @@ -50,33 +50,23 @@ package leetcode * } */ func rightSideView(root *TreeNode) []int { + res := []int{} if root == nil { - return []int{} + return res } - queue := []*TreeNode{} - queue = append(queue, root) - curNum, nextLevelNum, res, tmp := 1, 0, []int{}, []int{} - for len(queue) != 0 { - if curNum > 0 { - node := queue[0] - if node.Left != nil { - queue = append(queue, node.Left) - nextLevelNum++ + queue := []*TreeNode{root} + for len(queue) > 0 { + n := len(queue) + for i := 0; i < n; i++ { + if queue[i].Left != nil { + queue = append(queue, queue[i].Left) } - if node.Right != nil { - queue = append(queue, node.Right) - nextLevelNum++ + if queue[i].Right != nil { + queue = append(queue, queue[i].Right) } - curNum-- - tmp = append(tmp, node.Val) - queue = queue[1:] - } - if curNum == 0 { - res = append(res, tmp[len(tmp)-1]) - curNum = nextLevelNum - nextLevelNum = 0 - tmp = []int{} } + res = append(res, queue[n-1].Val) + queue = queue[n:] } return res } diff --git a/website/content/ChapterFour/0200~0299/0202.Happy-Number.md b/website/content/ChapterFour/0200~0299/0202.Happy-Number.md index 90def17b8..db82ed58e 100644 --- a/website/content/ChapterFour/0200~0299/0202.Happy-Number.md +++ b/website/content/ChapterFour/0200~0299/0202.Happy-Number.md @@ -37,29 +37,28 @@ Explanation: package leetcode func isHappy(n int) bool { - if n == 0 { - return false - } - res := 0 - num := n record := map[int]int{} - for { - for num != 0 { - res += (num % 10) * (num % 10) - num = num / 10 - } - if _, ok := record[res]; !ok { - if res == 1 { - return true + for n != 1 { + record[n] = n + n = getSquareOfDigits(n) + for _, previous := range record { + if n == previous { + return false } - record[res] = res - num = res - res = 0 - continue - } else { - return false } } + return true +} + +func getSquareOfDigits(n int) int { + squareOfDigits := 0 + temporary := n + for temporary != 0 { + remainder := temporary % 10 + squareOfDigits += remainder * remainder + temporary /= 10 + } + return squareOfDigits } ``` diff --git a/website/content/ChapterFour/0200~0299/0209.Minimum-Size-Subarray-Sum.md b/website/content/ChapterFour/0200~0299/0209.Minimum-Size-Subarray-Sum.md index 446bca925..806093aee 100644 --- a/website/content/ChapterFour/0200~0299/0209.Minimum-Size-Subarray-Sum.md +++ b/website/content/ChapterFour/0200~0299/0209.Minimum-Size-Subarray-Sum.md @@ -34,30 +34,29 @@ If you have figured out the O(n) solution, try coding another solution of which package leetcode -func minSubArrayLen(s int, nums []int) int { - n := len(nums) - if n == 0 { - return 0 - } - left, right, res, sum := 0, -1, n+1, 0 - for left < n { - if (right+1) < n && sum < s { - right++ - sum += nums[right] - } else { +func minSubArrayLen(target int, nums []int) int { + left, sum, res := 0, 0, len(nums)+1 + for right, v := range nums { + sum += v + for sum >= target { + res = min(res, right-left+1) sum -= nums[left] left++ } - if sum >= s { - res = min(res, right-left+1) - } } - if res == n+1 { + if res == len(nums)+1 { return 0 } return res } +func min(a int, b int) int { + if a > b { + return b + } + return a +} + ``` diff --git a/website/content/ChapterFour/0200~0299/0212.Word-Search-II.md b/website/content/ChapterFour/0200~0299/0212.Word-Search-II.md index 8966a46b9..69511f5f4 100755 --- a/website/content/ChapterFour/0200~0299/0212.Word-Search-II.md +++ b/website/content/ChapterFour/0200~0299/0212.Word-Search-II.md @@ -54,6 +54,52 @@ func findWords(board [][]byte, words []string) []string { return res } +// these is 79 solution +var dir = [][]int{ + {-1, 0}, + {0, 1}, + {1, 0}, + {0, -1}, +} + +func exist(board [][]byte, word string) bool { + visited := make([][]bool, len(board)) + for i := 0; i < len(visited); i++ { + visited[i] = make([]bool, len(board[0])) + } + for i, v := range board { + for j := range v { + if searchWord(board, visited, word, 0, i, j) { + return true + } + } + } + return false +} + +func isInBoard(board [][]byte, x, y int) bool { + return x >= 0 && x < len(board) && y >= 0 && y < len(board[0]) +} + +func searchWord(board [][]byte, visited [][]bool, word string, index, x, y int) bool { + if index == len(word)-1 { + return board[x][y] == word[index] + } + if board[x][y] == word[index] { + visited[x][y] = true + for i := 0; i < 4; i++ { + nx := x + dir[i][0] + ny := y + dir[i][1] + if isInBoard(board, nx, ny) && !visited[nx][ny] && searchWord(board, visited, word, index+1, nx, ny) { + return true + } + } + visited[x][y] = false + } + return false +} + + ``` diff --git a/website/content/ChapterFour/0200~0299/0215.Kth-Largest-Element-in-an-Array.md b/website/content/ChapterFour/0200~0299/0215.Kth-Largest-Element-in-an-Array.md index 0ea6345ab..0213a51c2 100644 --- a/website/content/ChapterFour/0200~0299/0215.Kth-Largest-Element-in-an-Array.md +++ b/website/content/ChapterFour/0200~0299/0215.Kth-Largest-Element-in-an-Array.md @@ -33,8 +33,8 @@ You may assume k is always valid, 1 ≤ k ≤ array's length. ## 解题思路 -在快排的 partition 操作中，每次 partition 操作结束都会返回一个点，这个标定点的下标和最终排序之后有序数组中这个元素所在的下标是一致的。利用这个特性，我们可以不断的划分数组区间，最终找到第 K 大的元素。执行一次 partition 操作以后，如果这个元素的下标比 K 小，那么接着就在后边的区间继续执行 partition 操作；如果这个元素的下标比 K 大，那么就在左边的区间继续执行 partition 操作；如果相等就直接输出这个下标对应的数组元素即可。 - +- 在快速选择 quickselect 的 partition 操作中，每次 partition 操作结束都会返回一个点，这个标定点的下标和最终排序之后有序数组中这个元素所在的下标是一致的。利用这个特性，我们可以不断的划分数组区间，最终找到第 K 大的元素。执行一次 partition 操作以后，如果这个元素的下标比 K 小，那么接着就在后边的区间继续执行 partition 操作；如果这个元素的下标比 K 大，那么就在左边的区间继续执行 partition 操作；如果相等就直接输出这个下标对应的数组元素即可。 +- 快速选择 quickselect 的思路实现的算法时间复杂度为 O(n)，空间复杂度为 O(logn)。由于证明过程很繁琐，所以不再这里展开讲。具体证明可以参考《算法导论》第 9 章第 2 小节。 ## 代码 @@ -43,7 +43,10 @@ You may assume k is always valid, 1 ≤ k ≤ array's length. package leetcode -import "sort" +import ( + "math/rand" + "sort" +) // 解法一 排序，排序的方法反而速度是最快的 func findKthLargest1(nums []int, k int) int { @@ -52,40 +55,66 @@ func findKthLargest1(nums []int, k int) int { } // 解法二 这个方法的理论依据是 partition 得到的点的下标就是最终排序之后的下标，根据这个下标，我们可以判断第 K 大的数在哪里 +// 时间复杂度 O(n)，空间复杂度 O(log n)，最坏时间复杂度为 O(n^2)，空间复杂度 O(n) func findKthLargest(nums []int, k int) int { - if len(nums) == 0 { - return 0 - } - return selection(nums, 0, len(nums)-1, len(nums)-k) + m := len(nums) - k + 1 // mth smallest, from 1..len(nums) + return selectSmallest(nums, 0, len(nums)-1, m) } -func selection(arr []int, l, r, k int) int { - if l == r { - return arr[l] +func selectSmallest(nums []int, l, r, i int) int { + if l >= r { + return nums[l] + } + q := partition(nums, l, r) + k := q - l + 1 + if k == i { + return nums[q] } - p := partition164(arr, l, r) - if k == p { - return arr[p] - } else if k < p { - return selection(arr, l, p-1, k) + if i < k { + return selectSmallest(nums, l, q-1, i) } else { - return selection(arr, p+1, r, k) + return selectSmallest(nums, q+1, r, i-k) } } -func partition164(a []int, lo, hi int) int { - pivot := a[hi] - i := lo - 1 - for j := lo; j < hi; j++ { - if a[j] < pivot { +func partition(nums []int, l, r int) int { + k := l + rand.Intn(r-l+1) // 此处为优化，使得时间复杂度期望降为 O(n)，最坏时间复杂度为 O(n^2) + nums[k], nums[r] = nums[r], nums[k] + i := l - 1 + // nums[l..i] <= nums[r] + // nums[i+1..j-1] > nums[r] + for j := l; j < r; j++ { + if nums[j] <= nums[r] { i++ - a[j], a[i] = a[i], a[j] + nums[i], nums[j] = nums[j], nums[i] } } - a[i+1], a[hi] = a[hi], a[i+1] + nums[i+1], nums[r] = nums[r], nums[i+1] return i + 1 } +// 扩展题 剑指 Offer 40. 最小的 k 个数 +func getLeastNumbers(arr []int, k int) []int { + return selectSmallest1(arr, 0, len(arr)-1, k)[:k] +} + +// 和 selectSmallest 实现完全一致，只是返回值不用再截取了，直接返回 nums 即可 +func selectSmallest1(nums []int, l, r, i int) []int { + if l >= r { + return nums + } + q := partition(nums, l, r) + k := q - l + 1 + if k == i { + return nums + } + if i < k { + return selectSmallest1(nums, l, q-1, i) + } else { + return selectSmallest1(nums, q+1, r, i-k) + } +} + ``` diff --git a/website/content/ChapterFour/0200~0299/0218.The-Skyline-Problem.md b/website/content/ChapterFour/0200~0299/0218.The-Skyline-Problem.md index d3afdcab6..e563455f6 100755 --- a/website/content/ChapterFour/0200~0299/0218.The-Skyline-Problem.md +++ b/website/content/ChapterFour/0200~0299/0218.The-Skyline-Problem.md @@ -84,7 +84,7 @@ package leetcode import ( "sort" - "github.com/halfrost/LeetCode-Go/template" + "github.com/halfrost/leetcode-go/template" ) // 解法一 树状数组，时间复杂度 O(n log n) @@ -162,7 +162,7 @@ func (bit *BinaryIndexedTree) Query(index int) int { return sum } -// 解法三 线段树 Segment Tree，时间复杂度 O(n log n) +// 解法二 线段树 Segment Tree，时间复杂度 O(n log n) func getSkyline1(buildings [][]int) [][]int { st, ans, lastHeight, check := template.SegmentTree{}, [][]int{}, 0, false posMap, pos := discretization218(buildings) diff --git a/website/content/ChapterFour/0200~0299/0234.Palindrome-Linked-List.md b/website/content/ChapterFour/0200~0299/0234.Palindrome-Linked-List.md index 8f4095184..2870f9571 100644 --- a/website/content/ChapterFour/0200~0299/0234.Palindrome-Linked-List.md +++ b/website/content/ChapterFour/0200~0299/0234.Palindrome-Linked-List.md @@ -40,6 +40,13 @@ Could you do it in O(n) time and O(1) space? package leetcode +import ( + "github.com/halfrost/leetcode-go/structures" +) + +// ListNode define +type ListNode = structures.ListNode + /** * Definition for singly-linked list. * type ListNode struct { @@ -48,8 +55,26 @@ package leetcode * } */ +// 解法一 +func isPalindrome(head *ListNode) bool { + slice := []int{} + for head != nil { + slice = append(slice, head.Val) + head = head.Next + } + for i, j := 0, len(slice)-1; i < j; { + if slice[i] != slice[j] { + return false + } + i++ + j-- + } + return true +} + +// 解法二 // 此题和 143 题 Reorder List 思路基本一致 -func isPalindrome234(head *ListNode) bool { +func isPalindrome1(head *ListNode) bool { if head == nil || head.Next == nil { return true } @@ -61,7 +86,6 @@ func isPalindrome234(head *ListNode) bool { p1 = p1.Next p2 = p2.Next.Next } - // 反转链表后半部分 1->2->3->4->5->6 to 1->2->3->6->5->4 preMiddle := p1 preCurrent := p1.Next @@ -71,7 +95,6 @@ func isPalindrome234(head *ListNode) bool { current.Next = preMiddle.Next preMiddle.Next = current } - // 扫描表，判断是否是回文 p1 = head p2 = preMiddle.Next @@ -92,19 +115,16 @@ func isPalindrome234(head *ListNode) bool { return false } } - return res } // L2ss define func L2ss(head *ListNode) []int { res := []int{} - for head != nil { res = append(res, head.Val) head = head.Next } - return res } diff --git a/website/content/ChapterFour/0200~0299/0237.Delete-Node-in-a-Linked-List.md b/website/content/ChapterFour/0200~0299/0237.Delete-Node-in-a-Linked-List.md index e7a23da54..e8690ff52 100644 --- a/website/content/ChapterFour/0200~0299/0237.Delete-Node-in-a-Linked-List.md +++ b/website/content/ChapterFour/0200~0299/0237.Delete-Node-in-a-Linked-List.md @@ -1,39 +1,64 @@ # [237. Delete Node in a Linked List](https://leetcode.com/problems/delete-node-in-a-linked-list/) + ## 题目 -Write a function to delete a node (except the tail) in a singly linked list, given only access to that node. +Write a function to **delete a node** in a singly-linked list. You will **not** be given access to the `head` of the list, instead you will be given access to **the node to be deleted** directly. -Given linked list -- head = [4,5,1,9], which looks like following: +It is **guaranteed** that the node to be deleted is **not a tail node** in the list. -![](https://assets.leetcode.com/uploads/2018/12/28/237_example.png) +**Example 1:** -**Example 1**: +![https://assets.leetcode.com/uploads/2020/09/01/node1.jpg](https://assets.leetcode.com/uploads/2020/09/01/node1.jpg) ``` - Input: head = [4,5,1,9], node = 5 Output: [4,1,9] -Explanation: You are given the second node with value 5, the linked list should become 4 -> 1 -> 9 after calling your function. +Explanation:You are given the second node with value 5, the linked list should become 4 -> 1 -> 9 after calling your function. ``` -**Example 2**: +**Example 2:** -``` +![https://assets.leetcode.com/uploads/2020/09/01/node2.jpg](https://assets.leetcode.com/uploads/2020/09/01/node2.jpg) +``` Input: head = [4,5,1,9], node = 1 Output: [4,5,9] -Explanation: You are given the third node with value 1, the linked list should become 4 -> 5 -> 9 after calling your function. +Explanation:You are given the third node with value 1, the linked list should become 4 -> 5 -> 9 after calling your function. + +``` + +**Example 3:** + +``` +Input: head = [1,2,3,4], node = 3 +Output: [1,2,4] ``` -**Note**: +**Example 4:** -- The linked list will have at least two elements. -- All of the nodes' values will be unique. -- The given node will not be the tail and it will always be a valid node of the linked list. -- Do not return anything from your function. +``` +Input: head = [0,1], node = 0 +Output: [1] + +``` + +**Example 5:** + +``` +Input: head = [-3,5,-99], node = -3 +Output: [5,-99] + +``` + +**Constraints:** + +- The number of the nodes in the given list is in the range `[2, 1000]`. +- `1000 <= Node.val <= 1000` +- The value of each node in the list is **unique**. +- The `node` to be deleted is **in the list** and is **not a tail** node ## 题目大意 @@ -46,9 +71,15 @@ Explanation: You are given the third node with value 1, the linked list should b ## 代码 ```go - package leetcode +import ( + "github.com/halfrost/leetcode-go/structures" +) + +// ListNode define +type ListNode = structures.ListNode + /** * Definition for singly-linked list. * type ListNode struct { @@ -57,18 +88,9 @@ package leetcode * } */ func deleteNode(node *ListNode) { - if node == nil { - return - } - cur := node - for cur.Next.Next != nil { - cur.Val = cur.Next.Val - cur = cur.Next - } - cur.Val = cur.Next.Val - cur.Next = nil + node.Val = node.Next.Val + node.Next = node.Next.Next } - ``` diff --git a/website/content/ChapterFour/0200~0299/0242.Valid-Anagram.md b/website/content/ChapterFour/0200~0299/0242.Valid-Anagram.md index 9e99ce872..15f171934 100644 --- a/website/content/ChapterFour/0200~0299/0242.Valid-Anagram.md +++ b/website/content/ChapterFour/0200~0299/0242.Valid-Anagram.md @@ -72,47 +72,21 @@ func isAnagram(s string, t string) bool { // 解法二 func isAnagram1(s string, t string) bool { - if s == "" && t == "" { - return true + hash := map[rune]int{} + for _, value := range s { + hash[value]++ } - if s == "" || t == "" { - return false + for _, value := range t { + hash[value]-- } - sBytes := []byte(s) - tBytes := []byte(t) - if len(sBytes) != len(tBytes) { - return false - } - quickSortByte(sBytes, 0, len(sBytes)-1) - quickSortByte(tBytes, 0, len(tBytes)-1) - - for i := 0; i < len(sBytes); i++ { - if sBytes[i] != tBytes[i] { + for _, value := range hash { + if value != 0 { return false } } return true } -func partitionByte(a []byte, lo, hi int) int { - pivot := a[hi] - i := lo - 1 - for j := lo; j < hi; j++ { - if a[j] > pivot { - i++ - a[j], a[i] = a[i], a[j] - } - } - a[i+1], a[hi] = a[hi], a[i+1] - return i + 1 -} -func quickSortByte(a []byte, lo, hi int) { - if lo >= hi { - return - } - p := partitionByte(a, lo, hi) - quickSortByte(a, lo, p-1) - quickSortByte(a, p+1, hi) -} + ``` diff --git a/website/content/ChapterFour/0200~0299/0263.Ugly-Number.md b/website/content/ChapterFour/0200~0299/0263.Ugly-Number.md index dad2d3c25..5d2ad1e10 100644 --- a/website/content/ChapterFour/0200~0299/0263.Ugly-Number.md +++ b/website/content/ChapterFour/0200~0299/0263.Ugly-Number.md @@ -58,14 +58,17 @@ Explanation: 14 is not ugly since it includes another prime factor 7. package leetcode func isUgly(num int) bool { - for i := 2; i < 6 && num > 0; i++ { - for num%i == 0 { - num /= i + if num > 0 { + for _, i := range []int{2, 3, 5} { + for num%i == 0 { + num /= i + } } } return num == 1 } + ``` diff --git a/website/content/ChapterFour/0200~0299/0275.H-Index-II.md b/website/content/ChapterFour/0200~0299/0275.H-Index-II.md index a29f7133c..2ab6406b6 100755 --- a/website/content/ChapterFour/0200~0299/0275.H-Index-II.md +++ b/website/content/ChapterFour/0200~0299/0275.H-Index-II.md @@ -74,5 +74,5 @@ func hIndex275(citations []int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0200~0299/0278.First-Bad-Version.md b/website/content/ChapterFour/0200~0299/0278.First-Bad-Version.md new file mode 100644 index 000000000..36fd27b46 --- /dev/null +++ b/website/content/ChapterFour/0200~0299/0278.First-Bad-Version.md @@ -0,0 +1,69 @@ +# [278. First Bad Version](https://leetcode.com/problems/first-bad-version/) + +## 题目 + +You are a product manager and currently leading a team to develop a new product. Unfortunately, the latest version of your product fails the quality check. Since each version is developed based on the previous version, all the versions after a bad version are also bad. + +Suppose you have `n` versions `[1, 2, ..., n]` and you want to find out the first bad one, which causes all the following ones to be bad. + +You are given an API `bool isBadVersion(version)` which returns whether `version` is bad. Implement a function to find the first bad version. You should minimize the number of calls to the API. + +**Example 1:** + +``` +Input: n = 5, bad = 4 +Output: 4 +Explanation: +call isBadVersion(3) -> false +call isBadVersion(5) -> true +call isBadVersion(4) -> true +Then 4 is the first bad version. + +``` + +**Example 2:** + +``` +Input: n = 1, bad = 1 +Output: 1 + +``` + +**Constraints:** + +- `1 <= bad <= n <= 231 - 1` + +## 题目大意 + +你是产品经理，目前正在带领一个团队开发新的产品。不幸的是，你的产品的最新版本没有通过质量检测。由于每个版本都是基于之前的版本开发的，所以错误的版本之后的所有版本都是错的。假设你有 n 个版本 [1, 2, ..., n]，你想找出导致之后所有版本出错的第一个错误的版本。你可以通过调用 bool isBadVersion(version) 接口来判断版本号 version 是否在单元测试中出错。实现一个函数来查找第一个错误的版本。你应该尽量减少对调用 API 的次数。 + +## 解题思路 + +- 我们知道开发产品迭代的版本，如果当一个版本为正确版本，则该版本之前的所有版本均为正确版本；当一个版本为错误版本，则该版本之后的所有版本均为错误版本。利用这个性质就可以进行二分查找。利用二分搜索，也可以满足减少对调用 API 的次数的要求。时间复杂度：O(logn)，其中 n 是给定版本的数量。空间复杂度：O(1)。 + +## 代码 + +```go +package leetcode + +import "sort" + +/** + * Forward declaration of isBadVersion API. + * @param version your guess about first bad version + * @return true if current version is bad + * false if current version is good + * func isBadVersion(version int) bool; + */ + +func firstBadVersion(n int) int { + return sort.Search(n, func(version int) bool { return isBadVersion(version) }) +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0200~0299/0279.Perfect-Squares.md b/website/content/ChapterFour/0200~0299/0279.Perfect-Squares.md new file mode 100644 index 000000000..6ef4ffcc9 --- /dev/null +++ b/website/content/ChapterFour/0200~0299/0279.Perfect-Squares.md @@ -0,0 +1,85 @@ +# [279. Perfect Squares](https://leetcode.com/problems/perfect-squares/) + + +## 题目 + +Given an integer `n`, return *the least number of perfect square numbers that sum to* `n`. + +A **perfect square** is an integer that is the square of an integer; in other words, it is the product of some integer with itself. For example, `1`, `4`, `9`, and `16` are perfect squares while `3` and `11` are not. + +**Example 1:** + +``` +Input: n = 12 +Output: 3 +Explanation: 12 = 4 + 4 + 4. +``` + +**Example 2:** + +``` +Input: n = 13 +Output: 2 +Explanation: 13 = 4 + 9. +``` + +**Constraints:** + +- `1 <= n <= 104` + +## 题目大意 + +给定正整数 n，找到若干个完全平方数（比如 1, 4, 9, 16, ...）使得它们的和等于 n。你需要让组成和的完全平方数的个数最少。给你一个整数 n ，返回和为 n 的完全平方数的 最少数量 。 + +完全平方数 是一个整数，其值等于另一个整数的平方；换句话说，其值等于一个整数自乘的积。例如，1、4、9 和 16 都是完全平方数，而 3 和 11 不是。 + +## 解题思路 + +- 由拉格朗日的四平方定理可得，每个自然数都可以表示为四个整数平方之和。 其中四个数字是整数。四平方和定理证明了任意一个正整数都可以被表示为至多四个正整数的平方和。这给出了本题的答案的上界。 +- 四平方和定理可以推出三平方和推论：当且仅当 {{< katex >}} n \neq 4^{k} \times (8*m + 7){{< /katex >}} 时，n 可以被表示为至多三个正整数的平方和。所以当 {{< katex >}} n = 4^{k} * (8*m + 7){{< /katex >}} 时，n 只能被表示为四个正整数的平方和。此时我们可以直接返回 4。 +- 当 {{< katex >}} n \neq 4^{k} \times (8*m + 7){{< /katex >}} 时，需要判断 n 到底可以分解成几个完全平方数之和。答案肯定是 1，2，3 中的一个。题目要求我们求最小的，所以从 1 开始一个个判断是否满足。如果答案为 1，代表 n 为完全平方数，这很好判断。如果答案为 2，代表 {{< katex >}} n = a^{2} + b^{2} {{< /katex >}}，枚举 {{< katex >}} 1 \leqslant a \leqslant \sqrt{n} {{< /katex >}}，判断 {{< katex >}} n - a^{2} {{< /katex >}} 是否为完全平方数。当 1 和 2 都排除了，剩下的答案只能为 3 了。 + +## 代码 + +```go +package leetcode + +import "math" + +func numSquares(n int) int { + if isPerfectSquare(n) { + return 1 + } + if checkAnswer4(n) { + return 4 + } + for i := 1; i*i <= n; i++ { + j := n - i*i + if isPerfectSquare(j) { + return 2 + } + } + return 3 +} + +// 判断是否为完全平方数 +func isPerfectSquare(n int) bool { + sq := int(math.Floor(math.Sqrt(float64(n)))) + return sq*sq == n +} + +// 判断是否能表示为 4^k*(8m+7) +func checkAnswer4(x int) bool { + for x%4 == 0 { + x /= 4 + } + return x%8 == 7 +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0200~0299/0283.Move-Zeroes.md b/website/content/ChapterFour/0200~0299/0283.Move-Zeroes.md index 7548b275a..16c37efae 100644 --- a/website/content/ChapterFour/0200~0299/0283.Move-Zeroes.md +++ b/website/content/ChapterFour/0200~0299/0283.Move-Zeroes.md @@ -44,10 +44,8 @@ func moveZeroes(nums []int) { if nums[i] != 0 { if i != j { nums[i], nums[j] = nums[j], nums[i] - j++ - } else { - j++ - } + } + j++ } } } @@ -57,6 +55,6 @@ func moveZeroes(nums []int) { ---------------------------------------------- diff --git a/website/content/ChapterFour/0200~0299/0297.Serialize-and-Deserialize-Binary-Tree.md b/website/content/ChapterFour/0200~0299/0297.Serialize-and-Deserialize-Binary-Tree.md index 50edf2014..dc86b67fa 100644 --- a/website/content/ChapterFour/0200~0299/0297.Serialize-and-Deserialize-Binary-Tree.md +++ b/website/content/ChapterFour/0200~0299/0297.Serialize-and-Deserialize-Binary-Tree.md @@ -62,7 +62,7 @@ import ( "strconv" "strings" - "github.com/halfrost/LeetCode-Go/structures" + "github.com/halfrost/leetcode-go/structures" ) type TreeNode = structures.TreeNode @@ -116,5 +116,5 @@ func (this *Codec) deserializeHelper() *TreeNode { ---------------------------------------------- diff --git a/website/content/ChapterFour/0200~0299/0299.Bulls-and-Cows.md b/website/content/ChapterFour/0200~0299/0299.Bulls-and-Cows.md new file mode 100644 index 000000000..10b6261d4 --- /dev/null +++ b/website/content/ChapterFour/0200~0299/0299.Bulls-and-Cows.md @@ -0,0 +1,121 @@ +# [299. Bulls and Cows](https://leetcode.com/problems/bulls-and-cows/) + + +## 题目 + +You are playing the Bulls and Cows game with your friend. + +You write down a secret number and ask your friend to guess what the number is. When your friend makes a guess, you provide a hint with the following info: + +The number of "bulls", which are digits in the guess that are in the correct position. +The number of "cows", which are digits in the guess that are in your secret number but are located in the wrong position. Specifically, the non-bull digits in the guess that could be rearranged such that they become bulls. +Given the secret number secret and your friend's guess guess, return the hint for your friend's guess. + +The hint should be formatted as "xAyB", where x is the number of bulls and y is the number of cows. Note that both secret and guess may contain duplicate digits. + +**Example 1:** + +``` +Input: secret = "1807", guess = "7810" +Output: "1A3B" +Explanation: Bulls are connected with a '|' and cows are underlined: +"1807" + | +"7810" +``` + +**Example 2:** + +``` +Input: secret = "1123", guess = "0111" +Output: "1A1B" +Explanation: Bulls are connected with a '|' and cows are underlined: +"1123" "1123" + | or | +"0111" "0111" +Note that only one of the two unmatched 1s is counted as a cow since the non-bull digits can only be rearranged to allow one 1 to be a bull. +``` + +**Example 3:** + +``` +Input: secret = "1", guess = "0" +Output: "0A0B" +``` + +**Example 4:** + +``` +Input: secret = "1", guess = "1" +Output: "1A0B" +``` + +**Constraints:** + +- 1 <= secret.length, guess.length <= 1000 +- secret.length == guess.length +- secret and guess consist of digits only. + +## 题目大意 + +你在和朋友一起玩 猜数字（Bulls and Cows）游戏，该游戏规则如下： + +写出一个秘密数字，并请朋友猜这个数字是多少。朋友每猜测一次，你就会给他一个包含下述信息的提示： + +猜测数字中有多少位属于数字和确切位置都猜对了（称为 "Bulls", 公牛）， +有多少位属于数字猜对了但是位置不对（称为 "Cows", 奶牛）。也就是说，这次猜测中有多少位非公牛数字可以通过重新排列转换成公牛数字。 +给你一个秘密数字secret 和朋友猜测的数字guess ，请你返回对朋友这次猜测的提示。 + +提示的格式为 "xAyB" ，x 是公牛个数， y 是奶牛个数，A 表示公牛，B表示奶牛。 + +请注意秘密数字和朋友猜测的数字都可能含有重复数字。 + +## 解题思路 + +- 计算下标一致并且对应下标的元素一致的个数，即 x +- secret 和 guess 分别去除 x 个公牛的元素,剩下 secret 和 guess 求共同的元素个数就是 y +- 把 x， y 转换成字符串，分别与 "A" 和 "B" 进行拼接返回结果 + +## 代码 + +```go + +package leetcode + +import "strconv" + +func getHint(secret string, guess string) string { + cntA, cntB := 0, 0 + mpS := make(map[byte]int) + var strG []byte + n := len(secret) + var ans string + for i := 0; i < n; i++ { + if secret[i] == guess[i] { + cntA++ + } else { + mpS[secret[i]] += 1 + strG = append(strG, guess[i]) + } + } + for _, v := range strG { + if _, ok := mpS[v]; ok { + if mpS[v] > 1 { + mpS[v] -= 1 + } else { + delete(mpS, v) + } + cntB++ + } + } + ans += strconv.Itoa(cntA) + "A" + strconv.Itoa(cntB) + "B" + return ans +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0300~0399/0300.Longest-Increasing-Subsequence.md b/website/content/ChapterFour/0300~0399/0300.Longest-Increasing-Subsequence.md index 17132f4da..3692985ac 100755 --- a/website/content/ChapterFour/0300~0399/0300.Longest-Increasing-Subsequence.md +++ b/website/content/ChapterFour/0300~0399/0300.Longest-Increasing-Subsequence.md @@ -82,6 +82,6 @@ func lengthOfLIS1(nums []int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0300~0399/0301.Remove-Invalid-Parentheses.md b/website/content/ChapterFour/0300~0399/0301.Remove-Invalid-Parentheses.md new file mode 100644 index 000000000..db483d160 --- /dev/null +++ b/website/content/ChapterFour/0300~0399/0301.Remove-Invalid-Parentheses.md @@ -0,0 +1,138 @@ +# [301. Remove Invalid Parentheses](https://leetcode.com/problems/remove-invalid-parentheses/) + + +## 题目 + +Given a string s that contains parentheses and letters, remove the minimum number of invalid parentheses to make the input string valid. + +Return all the possible results. You may return the answer in any order. + +**Example 1:** + + Input: s = "()())()" + Output: ["(())()","()()()"] + +**Example 2:** + + Input: s = "(a)())()" + Output: ["(a())()","(a)()()"] + +**Example 3:** + + Input: s = ")(" + Output: [""] + +**Constraints:** + +- 1 <= s.length <= 25 +- s consists of lowercase English letters and parentheses '(' and ')'. +- There will be at most 20 parentheses in s. + +## 题目大意 + +给你一个由若干括号和字母组成的字符串 s ，删除最小数量的无效括号，使得输入的字符串有效。 + +返回所有可能的结果。答案可以按 任意顺序 返回。 + +说明: + +- 1 <= s.length <= 25 +- s 由小写英文字母以及括号 '(' 和 ')' 组成 +- s 中至多含 20 个括号 + + +## 解题思路 + +回溯和剪枝 +- 计算最大得分数maxScore，合法字符串的长度length，左括号和右括号的移除次数lmoves,rmoves +- 加一个左括号的得分加1；加一个右括号的得分减1 +- 对于一个合法的字符串，左括号等于右括号，得分最终为0； +- 搜索过程中出现以下任何一种情况都直接返回 + - 得分值为负数 + - 得分大于最大得分数 + - 得分小于0 + - lmoves小于0 + - rmoves小于0 + +## 代码 + +```go + +package leetcode + +var ( + res []string + mp map[string]int + n int + length int + maxScore int + str string +) + +func removeInvalidParentheses(s string) []string { + lmoves, rmoves, lcnt, rcnt := 0, 0, 0, 0 + for _, v := range s { + if v == '(' { + lmoves++ + lcnt++ + } else if v == ')' { + if lmoves != 0 { + lmoves-- + } else { + rmoves++ + } + rcnt++ + } + } + n = len(s) + length = n - lmoves - rmoves + res = []string{} + mp = make(map[string]int) + maxScore = min(lcnt, rcnt) + str = s + backtrace(0, "", lmoves, rmoves, 0) + return res +} + +func backtrace(i int, cur string, lmoves int, rmoves int, score int) { + if lmoves < 0 || rmoves < 0 || score < 0 || score > maxScore { + return + } + if lmoves == 0 && rmoves == 0 { + if len(cur) == length { + if _, ok := mp[cur]; !ok { + res = append(res, cur) + mp[cur] = 1 + } + return + } + } + if i == n { + return + } + if str[i] == '(' { + backtrace(i+1, cur+string('('), lmoves, rmoves, score+1) + backtrace(i+1, cur, lmoves-1, rmoves, score) + } else if str[i] == ')' { + backtrace(i+1, cur+string(')'), lmoves, rmoves, score-1) + backtrace(i+1, cur, lmoves, rmoves-1, score) + } else { + backtrace(i+1, cur+string(str[i]), lmoves, rmoves, score) + } +} + +func min(a, b int) int { + if a < b { + return a + } + return b +} + +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0300~0399/0303.Range-Sum-Query-Immutable.md b/website/content/ChapterFour/0300~0399/0303.Range-Sum-Query-Immutable.md index 5c92392a9..8b49288ba 100755 --- a/website/content/ChapterFour/0300~0399/0303.Range-Sum-Query-Immutable.md +++ b/website/content/ChapterFour/0300~0399/0303.Range-Sum-Query-Immutable.md @@ -54,7 +54,7 @@ sumRange(0, 5) -> -3 package leetcode import ( - "github.com/halfrost/LeetCode-Go/template" + "github.com/halfrost/leetcode-go/template" ) //解法一 线段树，sumRange 时间复杂度 O(1) @@ -112,6 +112,6 @@ func (ma *NumArray) SumRange(i int, j int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0300~0399/0304.Range-Sum-Query-2D-Immutable.md b/website/content/ChapterFour/0300~0399/0304.Range-Sum-Query-2D-Immutable.md index 0f289fa6d..c70fa06cf 100644 --- a/website/content/ChapterFour/0300~0399/0304.Range-Sum-Query-2D-Immutable.md +++ b/website/content/ChapterFour/0300~0399/0304.Range-Sum-Query-2D-Immutable.md @@ -5,7 +5,7 @@ Given a 2D matrix matrix, find the sum of the elements inside the rectangle defined by its upper left corner (row1, col1) and lower right corner (row2, col2). -![https://leetcode.com/static/images/courses/range_sum_query_2d.png](https://leetcode.com/static/images/courses/range_sum_query_2d.png) +![https://leetcode.com/static/images/courses/range_sum_query_2d.png](https://assets.leetcode.com/uploads/2021/03/14/sum-grid.jpg) The above rectangle (with the red border) is defined by (row1, col1) = **(2, 1)** and (row2, col2) = **(4, 3)**, which contains sum = **8**. diff --git a/website/content/ChapterFour/0300~0399/0307.Range-Sum-Query-Mutable.md b/website/content/ChapterFour/0300~0399/0307.Range-Sum-Query-Mutable.md index 99db86f66..50b02e262 100755 --- a/website/content/ChapterFour/0300~0399/0307.Range-Sum-Query-Mutable.md +++ b/website/content/ChapterFour/0300~0399/0307.Range-Sum-Query-Mutable.md @@ -57,7 +57,7 @@ sumRange(0, 2) -> 8 package leetcode -import "github.com/halfrost/LeetCode-Go/template" +import "github.com/halfrost/leetcode-go/template" // NumArray define type NumArray struct { diff --git a/website/content/ChapterFour/0300~0399/0315.Count-of-Smaller-Numbers-After-Self.md b/website/content/ChapterFour/0300~0399/0315.Count-of-Smaller-Numbers-After-Self.md index 5988c80d2..ac37bace0 100755 --- a/website/content/ChapterFour/0300~0399/0315.Count-of-Smaller-Numbers-After-Self.md +++ b/website/content/ChapterFour/0300~0399/0315.Count-of-Smaller-Numbers-After-Self.md @@ -52,7 +52,7 @@ package leetcode import ( "sort" - "github.com/halfrost/LeetCode-Go/template" + "github.com/halfrost/leetcode-go/template" ) // 解法一 线段树 diff --git a/website/content/ChapterFour/0300~0399/0318.Maximum-Product-of-Word-Lengths.md b/website/content/ChapterFour/0300~0399/0318.Maximum-Product-of-Word-Lengths.md index 00e0b4dc9..436375e9b 100755 --- a/website/content/ChapterFour/0300~0399/0318.Maximum-Product-of-Word-Lengths.md +++ b/website/content/ChapterFour/0300~0399/0318.Maximum-Product-of-Word-Lengths.md @@ -80,5 +80,5 @@ func maxProduct318(words []string) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0300~0399/0319.Bulb-Switcher.md b/website/content/ChapterFour/0300~0399/0319.Bulb-Switcher.md new file mode 100644 index 000000000..5a4e16e1e --- /dev/null +++ b/website/content/ChapterFour/0300~0399/0319.Bulb-Switcher.md @@ -0,0 +1,65 @@ +# [319. Bulb Switcher](https://leetcode.com/problems/bulb-switcher/) + + +## 题目 + +There are n bulbs that are initially off. You first turn on all the bulbs, then you turn off every second bulb. + +On the third round, you toggle every third bulb (turning on if it's off or turning off if it's on). For the ith round, you toggle every i bulb. For the nth round, you only toggle the last bulb. + +Return the number of bulbs that are on after n rounds. + +**Example 1:** + + Input: n = 3 + Output: 1 + Explanation: At first, the three bulbs are [off, off, off]. + After the first round, the three bulbs are [on, on, on]. + After the second round, the three bulbs are [on, off, on]. + After the third round, the three bulbs are [on, off, off]. + So you should return 1 because there is only one bulb is on. + +**Example 2:** + + Input: n = 0 + Output: 0 + +**Example 3:** + + Input: n = 1 + Output: 1 + +## 题目大意 + +初始时有 n 个灯泡处于关闭状态。第一轮，你将会打开所有灯泡。接下来的第二轮，你将会每两个灯泡关闭一个。 + +第三轮，你每三个灯泡就切换一个灯泡的开关（即，打开变关闭，关闭变打开）。第 i 轮，你每 i 个灯泡就切换一个灯泡的开关。直到第 n 轮，你只需要切换最后一个灯泡的开关。 + +找出并返回 n 轮后有多少个亮着的灯泡。 + +## 解题思路 + +- 计算 1 到 n 中有奇数个约数的个数 +- 1 到 n 中的某个数 x 有奇数个约数,也即 x 是完全平方数 +- 计算 1 到 n 中完全平方数的个数 sqrt(n) + +## 代码 + +```go + +package leetcode + +import "math" + +func bulbSwitch(n int) int { + return int(math.Sqrt(float64(n))) +} + +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0300~0399/0322.Coin-Change.md b/website/content/ChapterFour/0300~0399/0322.Coin-Change.md index fb1838d75..a1bd78323 100755 --- a/website/content/ChapterFour/0300~0399/0322.Coin-Change.md +++ b/website/content/ChapterFour/0300~0399/0322.Coin-Change.md @@ -63,6 +63,6 @@ func coinChange(coins []int, amount int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0300~0399/0327.Count-of-Range-Sum.md b/website/content/ChapterFour/0300~0399/0327.Count-of-Range-Sum.md index 4fc79c875..6b57a221f 100755 --- a/website/content/ChapterFour/0300~0399/0327.Count-of-Range-Sum.md +++ b/website/content/ChapterFour/0300~0399/0327.Count-of-Range-Sum.md @@ -88,7 +88,7 @@ package leetcode import ( "sort" - "github.com/halfrost/LeetCode-Go/template" + "github.com/halfrost/leetcode-go/template" ) // 解法一 线段树，时间复杂度 O(n log n) diff --git a/website/content/ChapterFour/0300~0399/0328.Odd-Even-Linked-List.md b/website/content/ChapterFour/0300~0399/0328.Odd-Even-Linked-List.md index 53b921534..dcf9585a7 100644 --- a/website/content/ChapterFour/0300~0399/0328.Odd-Even-Linked-List.md +++ b/website/content/ChapterFour/0300~0399/0328.Odd-Even-Linked-List.md @@ -35,7 +35,7 @@ Output: 2->3->6->7->1->5->4->NULL ## 解题思路 -这道题思路也是一样的，分别把奇数和偶数都放在 2 个链表中，最后首尾拼接就是答案。 +这道题思路也是一样的，分别把奇数节点和偶数节点都放在 2 个链表中，最后首尾拼接就是答案。 ## 代码 diff --git a/website/content/ChapterFour/0300~0399/0345.Reverse-Vowels-of-a-String.md b/website/content/ChapterFour/0300~0399/0345.Reverse-Vowels-of-a-String.md index 7e812f36e..1c87310a9 100644 --- a/website/content/ChapterFour/0300~0399/0345.Reverse-Vowels-of-a-String.md +++ b/website/content/ChapterFour/0300~0399/0345.Reverse-Vowels-of-a-String.md @@ -37,35 +37,30 @@ Output: "leotcede" ## 代码 ```go - package leetcode func reverseVowels(s string) string { b := []byte(s) for i, j := 0, len(b)-1; i < j; { - if isVowels(b[i]) && isVowels(b[j]) { - b[i], b[j] = b[j], b[i] - i++ - j-- - } else if isVowels(b[i]) && !isVowels(b[j]) { - j-- - } else if !isVowels(b[i]) && isVowels(b[j]) { - i++ - } else { + if !isVowel(b[i]) { i++ + continue + } + if !isVowel(b[j]) { j-- + continue } + b[i], b[j] = b[j], b[i] + i++ + j-- } return string(b) } -func isVowels(s byte) bool { - if s == 'a' || s == 'e' || s == 'i' || s == 'o' || s == 'u' || s == 'A' || s == 'E' || s == 'I' || s == 'O' || s == 'U' { - return true - } - return false +func isVowel(s byte) bool { + return s == 'a' || s == 'e' || s == 'i' || s == 'o' || s == 'u' || s == 'A' || + s == 'E' || s == 'I' || s == 'O' || s == 'U' } - ``` diff --git a/website/content/ChapterFour/0300~0399/0350.Intersection-of-Two-Arrays-II.md b/website/content/ChapterFour/0300~0399/0350.Intersection-of-Two-Arrays-II.md index dcfe10b53..b3b3c30b0 100644 --- a/website/content/ChapterFour/0300~0399/0350.Intersection-of-Two-Arrays-II.md +++ b/website/content/ChapterFour/0300~0399/0350.Intersection-of-Two-Arrays-II.md @@ -75,5 +75,5 @@ func intersect(nums1 []int, nums2 []int) []int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0300~0399/0352.Data-Stream-as-Disjoint-Intervals.md b/website/content/ChapterFour/0300~0399/0352.Data-Stream-as-Disjoint-Intervals.md new file mode 100644 index 000000000..14899590d --- /dev/null +++ b/website/content/ChapterFour/0300~0399/0352.Data-Stream-as-Disjoint-Intervals.md @@ -0,0 +1,115 @@ +# [352. Data Stream as Disjoint Intervals](https://leetcode.com/problems/data-stream-as-disjoint-intervals/) + + +## 题目 + +Given a data stream input of non-negative integers a1, a2, ..., an, summarize the numbers seen so far as a list of disjoint intervals. + +Implement the SummaryRanges class: + + - SummaryRanges() Initializes the object with an empty stream. + - void addNum(int val) Adds the integer val to the stream. + - int[][] getIntervals() Returns a summary of the integers in the stream currently as a list of disjoint intervals [starti, endi]. + +**Example 1:** + + Input + ["SummaryRanges", "addNum", "getIntervals", "addNum", "getIntervals", "addNum", "getIntervals", "addNum", "getIntervals", "addNum", "getIntervals"] + [[], [1], [], [3], [], [7], [], [2], [], [6], []] + Output + [null, null, [[1, 1]], null, [[1, 1], [3, 3]], null, [[1, 1], [3, 3], [7, 7]], null, [[1, 3], [7, 7]], null, [[1, 3], [6, 7]]] + + Explanation + SummaryRanges summaryRanges = new SummaryRanges(); + summaryRanges.addNum(1); // arr = [1] + summaryRanges.getIntervals(); // return [[1, 1]] + summaryRanges.addNum(3); // arr = [1, 3] + summaryRanges.getIntervals(); // return [[1, 1], [3, 3]] + summaryRanges.addNum(7); // arr = [1, 3, 7] + summaryRanges.getIntervals(); // return [[1, 1], [3, 3], [7, 7]] + summaryRanges.addNum(2); // arr = [1, 2, 3, 7] + summaryRanges.getIntervals(); // return [[1, 3], [7, 7]] + summaryRanges.addNum(6); // arr = [1, 2, 3, 6, 7] + summaryRanges.getIntervals(); // return [[1, 3], [6, 7]] + +**Constraints** + + - 0 <= val <= 10000 + - At most 3 * 10000 calls will be made to addNum and getIntervals. + +## 题目大意 + +给你一个由非负整数a1, a2, ..., an 组成的数据流输入，请你将到目前为止看到的数字总结为不相交的区间列表。 + +实现 SummaryRanges 类： + + - SummaryRanges() 使用一个空数据流初始化对象。 + - void addNum(int val) 向数据流中加入整数 val 。 + - int[][] getIntervals() 以不相交区间[starti, endi] 的列表形式返回对数据流中整数的总结 + +## 解题思路 + +- 使用字典过滤掉重复的数字 +- 把过滤后的数字放到nums中,并进行排序 +- 使用nums构建不重复的区间 + +## 代码 + +```go +package leetcode + +import "sort" + +type SummaryRanges struct { + nums []int + mp map[int]int +} + +func Constructor() SummaryRanges { + return SummaryRanges{ + nums: []int{}, + mp : map[int]int{}, + } +} + +func (this *SummaryRanges) AddNum(val int) { + if _, ok := this.mp[val]; !ok { + this.mp[val] = 1 + this.nums = append(this.nums, val) + } + sort.Ints(this.nums) +} + +func (this *SummaryRanges) GetIntervals() [][]int { + n := len(this.nums) + var ans [][]int + if n == 0 { + return ans + } + if n == 1 { + ans = append(ans, []int{this.nums[0], this.nums[0]}) + return ans + } + start, end := this.nums[0], this.nums[0] + ans = append(ans, []int{start, end}) + index := 0 + for i := 1; i < n; i++ { + if this.nums[i] == end + 1 { + end = this.nums[i] + ans[index][1] = end + } else { + start, end = this.nums[i], this.nums[i] + ans = append(ans, []int{start, end}) + index++ + } + } + return ans +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0300~0399/0354.Russian-Doll-Envelopes.md b/website/content/ChapterFour/0300~0399/0354.Russian-Doll-Envelopes.md index f6388e0f0..af4abd4a2 100755 --- a/website/content/ChapterFour/0300~0399/0354.Russian-Doll-Envelopes.md +++ b/website/content/ChapterFour/0300~0399/0354.Russian-Doll-Envelopes.md @@ -84,6 +84,6 @@ func maxEnvelopes(envelopes [][]int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0300~0399/0373.Find-K-Pairs-with-Smallest-Sums.md b/website/content/ChapterFour/0300~0399/0373.Find-K-Pairs-with-Smallest-Sums.md index 8a9fd12f0..ff62bbf4f 100755 --- a/website/content/ChapterFour/0300~0399/0373.Find-K-Pairs-with-Smallest-Sums.md +++ b/website/content/ChapterFour/0300~0399/0373.Find-K-Pairs-with-Smallest-Sums.md @@ -129,5 +129,5 @@ func kSmallestPairs1(nums1 []int, nums2 []int, k int) [][]int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0300~0399/0374.Guess-Number-Higher-or-Lower.md b/website/content/ChapterFour/0300~0399/0374.Guess-Number-Higher-or-Lower.md new file mode 100644 index 000000000..a904fadd8 --- /dev/null +++ b/website/content/ChapterFour/0300~0399/0374.Guess-Number-Higher-or-Lower.md @@ -0,0 +1,101 @@ +# [374. Guess Number Higher or Lower](https://leetcode.com/problems/guess-number-higher-or-lower/) + +## 题目 + +We are playing the Guess Game. The game is as follows: + +I pick a number from `1` to `n`. You have to guess which number I picked. + +Every time you guess wrong, I will tell you whether the number I picked is higher or lower than your guess. + +You call a pre-defined API `int guess(int num)`, which returns 3 possible results: + +- `1`: The number I picked is lower than your guess (i.e. `pick < num`). +- `1`: The number I picked is higher than your guess (i.e. `pick > num`). +- `0`: The number I picked is equal to your guess (i.e. `pick == num`). + +Return *the number that I picked*. + +**Example 1:** + +``` +Input: n = 10, pick = 6 +Output: 6 +``` + +**Example 2:** + +``` +Input: n = 1, pick = 1 +Output: 1 +``` + +**Example 3:** + +``` +Input: n = 2, pick = 1 +Output: 1 +``` + +**Example 4:** + +``` +Input: n = 2, pick = 2 +Output: 2 +``` + +**Constraints:** + +- `1 <= n <= 231 - 1` +- `1 <= pick <= n` + +## 题目大意 + +猜数字游戏的规则如下： + +- 每轮游戏，我都会从 1 到 n 随机选择一个数字。 请你猜选出的是哪个数字。 +- 如果你猜错了，我会告诉你，你猜测的数字比我选出的数字是大了还是小了。 + +你可以通过调用一个预先定义好的接口 int guess(int num) 来获取猜测结果，返回值一共有 3 种可能的情况（-1，1 或 0）： + +- 1：我选出的数字比你猜的数字小 pick < num +- 1：我选出的数字比你猜的数字大 pick > num +- 0：我选出的数字和你猜的数字一样。恭喜！你猜对了！pick == num + +返回我选出的数字。 + +## 解题思路 + +- 这一题是简单题，和小时候玩的猜大猜小的游戏一样。思路很简单，二分查找即可。这一题和第 278 题类似。 + +## 代码 + +```go +package leetcode + +import "sort" + +/** + * Forward declaration of guess API. + * @param num your guess + * @return -1 if num is lower than the guess number + * 1 if num is higher than the guess number + * otherwise return 0 + * func guess(num int) int; + */ + +func guessNumber(n int) int { + return sort.Search(n, func(x int) bool { return guess(x) <= 0 }) +} + +func guess(num int) int { + return 0 +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0300~0399/0376.Wiggle-Subsequence.md b/website/content/ChapterFour/0300~0399/0376.Wiggle-Subsequence.md index e959f6fa7..bc9b7c693 100644 --- a/website/content/ChapterFour/0300~0399/0376.Wiggle-Subsequence.md +++ b/website/content/ChapterFour/0300~0399/0376.Wiggle-Subsequence.md @@ -78,6 +78,6 @@ func wiggleMaxLength(nums []int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0300~0399/0378.Kth-Smallest-Element-in-a-Sorted-Matrix.md b/website/content/ChapterFour/0300~0399/0378.Kth-Smallest-Element-in-a-Sorted-Matrix.md index d16137872..e0b264fbc 100755 --- a/website/content/ChapterFour/0300~0399/0378.Kth-Smallest-Element-in-a-Sorted-Matrix.md +++ b/website/content/ChapterFour/0300~0399/0378.Kth-Smallest-Element-in-a-Sorted-Matrix.md @@ -138,5 +138,5 @@ func (p *pq) Pop() interface{} { ---------------------------------------------- diff --git a/website/content/ChapterFour/0300~0399/0382.Linked-List-Random-Node.md b/website/content/ChapterFour/0300~0399/0382.Linked-List-Random-Node.md new file mode 100644 index 000000000..449c5aaa8 --- /dev/null +++ b/website/content/ChapterFour/0300~0399/0382.Linked-List-Random-Node.md @@ -0,0 +1,112 @@ +# [382. Linked List Random Node](https://leetcode.com/problems/linked-list-random-node/) + + +## 题目 + +Given a singly linked list, return a random node's value from the linked list. Each node must have the **same probability** of being chosen. + +Implement the `Solution` class: + +- `Solution(ListNode head)` Initializes the object with the integer array nums. +- `int getRandom()` Chooses a node randomly from the list and returns its value. All the nodes of the list should be equally likely to be choosen. + +**Example 1:** + +![https://assets.leetcode.com/uploads/2021/03/16/getrand-linked-list.jpg](https://assets.leetcode.com/uploads/2021/03/16/getrand-linked-list.jpg) + +``` +Input +["Solution", "getRandom", "getRandom", "getRandom", "getRandom", "getRandom"] +[[[1, 2, 3]], [], [], [], [], []] +Output +[null, 1, 3, 2, 2, 3] + +Explanation +Solution solution = new Solution([1, 2, 3]); +solution.getRandom(); // return 1 +solution.getRandom(); // return 3 +solution.getRandom(); // return 2 +solution.getRandom(); // return 2 +solution.getRandom(); // return 3 +// getRandom() should return either 1, 2, or 3 randomly. Each element should have equal probability of returning. + +``` + +**Constraints:** + +- The number of nodes in the linked list will be in the range `[1, 104]`. +- `-10^4 <= Node.val <= 10^4` +- At most `10^4` calls will be made to `getRandom`. + +**Follow up:** + +- What if the linked list is extremely large and its length is unknown to you? +- Could you solve this efficiently without using extra space? + +## 题目大意 + +给定一个单链表，随机选择链表的一个节点，并返回相应的节点值。保证每个节点被选的概率一样。 + +进阶: 如果链表十分大且长度未知，如何解决这个问题？你能否使用常数级空间复杂度实现？ + +## 解题思路 + +- rand.Float64() 可以返回 [0.0,1.0) 之间的随机数。利用这个函数完成我们的随机化取节点的过程。 + +## 代码 + +```go +package leetcode + +import ( + "math/rand" + + "github.com/halfrost/leetcode-go/structures" +) + +// ListNode define +type ListNode = structures.ListNode + +/** + * Definition for singly-linked list. + * type ListNode struct { + * Val int + * Next *ListNode + * } + */ +type Solution struct { + head *ListNode +} + +/** @param head The linked list's head. + Note that the head is guaranteed to be not null, so it contains at least one node. */ +func Constructor(head *ListNode) Solution { + return Solution{head: head} +} + +/** Returns a random node's value. */ +func (this *Solution) GetRandom() int { + scope, selectPoint, curr := 1, 0, this.head + for curr != nil { + if rand.Float64() < 1.0/float64(scope) { + selectPoint = curr.Val + } + scope += 1 + curr = curr.Next + } + return selectPoint +} + +/** + * Your Solution object will be instantiated and called as such: + * obj := Constructor(head); + * param_1 := obj.GetRandom(); + */ +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0300~0399/0383.Ransom-Note.md b/website/content/ChapterFour/0300~0399/0383.Ransom-Note.md new file mode 100644 index 000000000..ef5603c7c --- /dev/null +++ b/website/content/ChapterFour/0300~0399/0383.Ransom-Note.md @@ -0,0 +1,71 @@ +# [383. Ransom Note](https://leetcode.com/problems/ransom-note/) + +## 题目 + +Given two stings ransomNote and magazine, return true if ransomNote can be constructed from magazine and false otherwise. + +Each letter in magazine can only be used once in ransomNote. + +**Example 1**: + + Input: ransomNote = "a", magazine = "b" + Output: false + +**Example 2**: + + Input: ransomNote = "aa", magazine = "ab" + Output: false + +**Example 3**: + + Input: ransomNote = "aa", magazine = "aab" + Output: true + +**Constraints:** + +- 1 <= ransomNote.length, magazine.length <= 100000 +- ransomNote and magazine consist of lowercase English letters. + +## 题目大意 + +为了不在赎金信中暴露字迹，从杂志上搜索各个需要的字母，组成单词来表达意思。 + +给你一个赎金信 (ransomNote) 字符串和一个杂志(magazine)字符串，判断 ransomNote 能不能由 magazines 里面的字符构成。 + +如果可以构成，返回 true ；否则返回 false 。 + +magazine 中的每个字符只能在 ransomNote 中使用一次。 + +## 解题思路 + +- ransomNote 和 magazine 都是由小写字母组成，所以用数组进行简单的字符统计 + +## 代码 + +````go +package leetcode + +func canConstruct(ransomNote string, magazine string) bool { + if len(ransomNote) > len(magazine) { + return false + } + var cnt [26]int + for _, v := range magazine { + cnt[v-'a']++ + } + for _, v := range ransomNote { + cnt[v-'a']-- + if cnt[v-'a'] < 0 { + return false + } + } + return true +} +```` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0300~0399/0384.Shuffle-an-Array.md b/website/content/ChapterFour/0300~0399/0384.Shuffle-an-Array.md new file mode 100644 index 000000000..908f9049c --- /dev/null +++ b/website/content/ChapterFour/0300~0399/0384.Shuffle-an-Array.md @@ -0,0 +1,89 @@ +# [384.Shuffle an Array](https://leetcode.com/problems/shuffle-an-array/) + +## 题目 + +Given an integer array nums, design an algorithm to randomly shuffle the array. All permutations of the array should be equally likely as a result of the shuffling. + +Implement the Solution class: + +- Solution(int[] nums) Initializes the object with the integer array nums. +- int[] reset() Resets the array to its original configuration and returns it. +- int[] shuffle() Returns a random shuffling of the array. + +**Example 1**: + + Input + ["Solution", "shuffle", "reset", "shuffle"] + [[[1, 2, 3]], [], [], []] + Output + [null, [3, 1, 2], [1, 2, 3], [1, 3, 2]] + + Explanation + Solution solution = new Solution([1, 2, 3]); + solution.shuffle(); // Shuffle the array [1,2,3] and return its result. + // Any permutation of [1,2,3] must be equally likely to be returned. + // Example: return [3, 1, 2] + solution.reset(); // Resets the array back to its original configuration [1,2,3]. Return [1, 2, 3] + solution.shuffle(); // Returns the random shuffling of array [1,2,3]. Example: return [1, 3, 2] + +**Constraints:** + +- 1 <= nums.length <= 200 +- -1000000 <= nums[i] <= 1000000 +- All the elements of nums are unique. +- At most 5 * 10000 calls in total will be made to reset and shuffle. + +## 题目大意 + +给你一个整数数组 nums ，设计算法来打乱一个没有重复元素的数组。 + +实现 Solution class: + +- Solution(int[] nums) 使用整数数组 nums 初始化对象 +- int[] reset() 重设数组到它的初始状态并返回 +- int[] shuffle() 返回数组随机打乱后的结果 + +## 解题思路 + +- 使用 rand.Shuffle 进行数组随机打乱 + +## 代码 + +```go + +package leetcode + +import "math/rand" + +type Solution struct { + nums []int +} + +func Constructor(nums []int) Solution { + return Solution{ + nums: nums, + } +} + +/** Resets the array to its original configuration and return it. */ +func (this *Solution) Reset() []int { + return this.nums +} + +/** Returns a random shuffling of the array. */ +func (this *Solution) Shuffle() []int { + arr := make([]int, len(this.nums)) + copy(arr, this.nums) + rand.Shuffle(len(arr), func(i, j int) { + arr[i], arr[j] = arr[j], arr[i] + }) + return arr +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0300~0399/0385.Mini-Parser.md b/website/content/ChapterFour/0300~0399/0385.Mini-Parser.md index 869839bfd..eff5eb9d9 100755 --- a/website/content/ChapterFour/0300~0399/0385.Mini-Parser.md +++ b/website/content/ChapterFour/0300~0399/0385.Mini-Parser.md @@ -177,6 +177,6 @@ func deserialize(s string) *NestedInteger { ---------------------------------------------- diff --git a/website/content/ChapterFour/0300~0399/0389.Find-the-Difference.md b/website/content/ChapterFour/0300~0399/0389.Find-the-Difference.md index 0a326d51f..d21ed2376 100755 --- a/website/content/ChapterFour/0300~0399/0389.Find-the-Difference.md +++ b/website/content/ChapterFour/0300~0399/0389.Find-the-Difference.md @@ -51,5 +51,5 @@ func findTheDifference(s string, t string) byte { ---------------------------------------------- diff --git a/website/content/ChapterFour/0300~0399/0390.Elimination-Game.md b/website/content/ChapterFour/0300~0399/0390.Elimination-Game.md new file mode 100644 index 000000000..d90aca5b9 --- /dev/null +++ b/website/content/ChapterFour/0300~0399/0390.Elimination-Game.md @@ -0,0 +1,81 @@ +# [390. Elimination Game](https://leetcode.com/problems/elimination-game/) + + +## 题目 + +You have a list `arr` of all integers in the range `[1, n]` sorted in a strictly increasing order. Apply the following algorithm on `arr`: + +- Starting from left to right, remove the first number and every other number afterward until you reach the end of the list. +- Repeat the previous step again, but this time from right to left, remove the rightmost number and every other number from the remaining numbers. +- Keep repeating the steps again, alternating left to right and right to left, until a single number remains. + +Given the integer `n`, return *the last number that remains in* `arr`. + +**Example 1:** + +``` +Input: n = 9 +Output: 6 +Explanation: +arr = [1, 2,3, 4,5, 6,7, 8,9] +arr = [2,4, 6,8] +arr = [2, 6] +arr = [6] + +``` + +**Example 2:** + +``` +Input: n = 1 +Output: 1 + +``` + +**Constraints:** + +- `1 <= n <= 109` + +## 题目大意 + +列表 arr 由在范围 [1, n] 中的所有整数组成，并按严格递增排序。请你对 arr 应用下述算法： + +- 从左到右，删除第一个数字，然后每隔一个数字删除一个，直到到达列表末尾。 +- 重复上面的步骤，但这次是从右到左。也就是，删除最右侧的数字，然后剩下的数字每隔一个删除一个。 +- 不断重复这两步，从左到右和从右到左交替进行，直到只剩下一个数字。 + +给你整数 n ，返回 arr 最后剩下的数字。 + +## 解题思路 + +- 模拟题。按照题意，第一轮从左往右删除数字，第二轮从右往左删除数字。题目要求最后剩下的数字，模拟过程中不需要真的删除元素。只需要标记起始元素，该轮步长和方向即可。最后总元素只剩下一个即为所求。 + +## 代码 + +```go +package leetcode + +func lastRemaining(n int) int { + start, dir, step := 1, true, 1 + for n > 1 { + if dir { // 正向 + start += step + } else { // 反向 + if n%2 == 1 { + start += step + } + } + dir = !dir + n >>= 1 + step <<= 1 + } + return start +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0300~0399/0391.Perfect-Rectangle.md b/website/content/ChapterFour/0300~0399/0391.Perfect-Rectangle.md new file mode 100644 index 000000000..3028424f4 --- /dev/null +++ b/website/content/ChapterFour/0300~0399/0391.Perfect-Rectangle.md @@ -0,0 +1,121 @@ +# [391. Perfect Rectangle](https://leetcode.com/problems/perfect-rectangle/) + +## 题目 + +Given an array rectangles where rectangles[i] = [xi, yi, ai, bi] represents an axis-aligned rectangle. The bottom-left point of the rectangle is (xi, yi) and the top-right point of it is (ai, bi). + +Return true if all the rectangles together form an exact cover of a rectangular region. + +**Example1:** + +![https://assets.leetcode.com/uploads/2021/03/27/perectrec1-plane.jpg](https://assets.leetcode.com/uploads/2021/03/27/perectrec1-plane.jpg) + + Input: rectangles = [[1,1,3,3],[3,1,4,2],[3,2,4,4],[1,3,2,4],[2,3,3,4]] + Output: true + Explanation: All 5 rectangles together form an exact cover of a rectangular region. + +**Example2:** + +![https://assets.leetcode.com/uploads/2021/03/27/perfectrec2-plane.jpg](https://assets.leetcode.com/uploads/2021/03/27/perfectrec2-plane.jpg) + + Input: rectangles = [[1,1,2,3],[1,3,2,4],[3,1,4,2],[3,2,4,4]] + Output: false + Explanation: Because there is a gap between the two rectangular regions. + +**Example3:** + +![https://assets.leetcode.com/uploads/2021/03/27/perfectrec3-plane.jpg](https://assets.leetcode.com/uploads/2021/03/27/perfectrec3-plane.jpg) + + Input: rectangles = [[1,1,3,3],[3,1,4,2],[1,3,2,4],[3,2,4,4]] + Output: false + Explanation: Because there is a gap in the top center. + +**Example4:** + +![https://assets.leetcode.com/uploads/2021/03/27/perfecrrec4-plane.jpg](https://assets.leetcode.com/uploads/2021/03/27/perfecrrec4-plane.jpg) + + Input: rectangles = [[1,1,3,3],[3,1,4,2],[1,3,2,4],[2,2,4,4]] + Output: false + Explanation: Because two of the rectangles overlap with each other. + +**Constraints:** + +- 1 <= rectangles.length <= 2 * 10000 +- rectangles[i].length == 4 +- -100000 <= xi, yi, ai, bi <= 100000 + +## 题目大意 + +给你一个数组 rectangles ，其中 rectangles[i] = [xi, yi, ai, bi] 表示一个坐标轴平行的矩形。这个矩形的左下顶点是 (xi, yi) ，右上顶点是 (ai, bi) 。 + +如果所有矩形一起精确覆盖了某个矩形区域，则返回 true ；否则，返回 false 。 + +## 解题思路 + +- 矩形区域的面积等于所有矩形的面积之和并且满足矩形区域四角的顶点只能出现一次，且其余顶点的出现次数只能是两次或四次则返回 true,否则返回 false + +## 代码 + +```go + +package leetcode + +type point struct { + x int + y int +} + +func isRectangleCover(rectangles [][]int) bool { + minX, minY, maxA, maxB := rectangles[0][0], rectangles[0][1], rectangles[0][2], rectangles[0][3] + area := 0 + cnt := make(map[point]int) + for _, v := range rectangles { + x, y, a, b := v[0], v[1], v[2], v[3] + area += (a - x) * (b - y) + minX = min(minX, x) + minY = min(minY, y) + maxA = max(maxA, a) + maxB = max(maxB, b) + cnt[point{x, y}]++ + cnt[point{a, b}]++ + cnt[point{x, b}]++ + cnt[point{a, y}]++ + } + if area != (maxA - minX) * (maxB - minY) || + cnt[point{minX, minY}] != 1 || cnt[point{maxA, maxB}] != 1 || + cnt[point{minX, maxB}] != 1 || cnt[point{maxA, minY}] != 1 { + return false + } + delete(cnt, point{minX, minY}) + delete(cnt, point{maxA, maxB}) + delete(cnt, point{minX, maxB}) + delete(cnt, point{maxA, minY}) + for _, v := range cnt { + if v != 2 && v != 4 { + return false + } + } + return true +} + +func min(a, b int) int { + if a < b { + return a + } + return b +} + +func max(a, b int) int { + if a > b { + return a + } + return b +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0300~0399/0392.Is-Subsequence.md b/website/content/ChapterFour/0300~0399/0392.Is-Subsequence.md index ff476a02b..459d38068 100755 --- a/website/content/ChapterFour/0300~0399/0392.Is-Subsequence.md +++ b/website/content/ChapterFour/0300~0399/0392.Is-Subsequence.md @@ -82,6 +82,6 @@ func isSubsequence1(s string, t string) bool { ---------------------------------------------- diff --git a/website/content/ChapterFour/0300~0399/0395.Longest-Substring-with-At-Least-K-Repeating-Characters.md b/website/content/ChapterFour/0300~0399/0395.Longest-Substring-with-At-Least-K-Repeating-Characters.md index 190d81d1d..5c3966441 100644 --- a/website/content/ChapterFour/0300~0399/0395.Longest-Substring-with-At-Least-K-Repeating-Characters.md +++ b/website/content/ChapterFour/0300~0399/0395.Longest-Substring-with-At-Least-K-Repeating-Characters.md @@ -115,5 +115,5 @@ func longestSubstring1(s string, k int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0300~0399/0396.Rotate-Function.md b/website/content/ChapterFour/0300~0399/0396.Rotate-Function.md new file mode 100644 index 000000000..95a661c99 --- /dev/null +++ b/website/content/ChapterFour/0300~0399/0396.Rotate-Function.md @@ -0,0 +1,117 @@ +# [396. Rotate Function](https://leetcode.com/problems/rotate-function/) + +## 题目 + +You are given an integer array `nums` of length `n`. + +Assume `arrk` to be an array obtained by rotating `nums` by `k` positions clock-wise. We define the **rotation function** `F` on `nums` as follow: + +- `F(k) = 0 * arrk[0] + 1 * arrk[1] + ... + (n - 1) * arrk[n - 1]`. + +Return the maximum value of `F(0), F(1), ..., F(n-1)`. + +The test cases are generated so that the answer fits in a **32-bit** integer. + +**Example 1:** + +```c +Input: nums = [4,3,2,6] +Output: 26 +Explanation: +F(0) = (0 * 4) + (1 * 3) + (2 * 2) + (3 * 6) = 0 + 3 + 4 + 18 = 25 +F(1) = (0 * 6) + (1 * 4) + (2 * 3) + (3 * 2) = 0 + 4 + 6 + 6 = 16 +F(2) = (0 * 2) + (1 * 6) + (2 * 4) + (3 * 3) = 0 + 6 + 8 + 9 = 23 +F(3) = (0 * 3) + (1 * 2) + (2 * 6) + (3 * 4) = 0 + 2 + 12 + 12 = 26 +So the maximum value of F(0), F(1), F(2), F(3) is F(3) = 26. +``` + +**Example 2:** + +```c +Input: nums = [100] +Output: 0 +``` + +**Constraints:** + +- `n == nums.length` +- `1 <= n <= 105` +- `-100 <= nums[i] <= 100` + +## 题目大意 + +给定一个长度为`n`的整数数组`nums`，设`arrk`是数组`nums`顺时针旋转`k`个位置后的数组。 + +定义`nums`的旋转函数`F`为： + +- `F(k) = 0 * arrk[0] + 1 * arrk[1] + ... + (n - 1) * arrk[n - 1]` + +返回`F(0), F(1), ..., F(n-1)`中的最大值。 + +## 解题思路 + +**抽象化观察：** + +```c +nums = [A0, A1, A2, A3] + +sum = A0 + A1 + A2+ A3 +F(0) = 0*A0 +0*A0 + 1*A1 + 2*A2 + 3*A3 + +F(1) = 0*A3 + 1*A0 + 2*A1 + 3*A2 + = F(0) + (A0 + A1 + A2) - 3*A3 + = F(0) + (sum-A3) - 3*A3 + = F(0) + sum - 4*A3 + +F(2) = 0*A2 + 1*A3 + 2*A0 + 3*A1 + = F(1) + A3 + A0 + A1 - 3*A2 + = F(1) + sum - 4*A2 + +F(3) = 0*A1 + 1*A2 + 2*A3 + 3*A0 + = F(2) + A2 + A3 + A0 - 3*A1 + = F(2) + sum - 4*A1 + +// 记sum为nums数组中所有元素和 +// 可以猜测当0 ≤ i < n时存在公式: +F(i) = F(i-1) + sum - n * A(n-i) +``` + +**数学归纳法证明迭代公式：** + +根据题目中给定的旋转函数公式可得已知条件： + +- `F(0) = 0×nums[0] + 1×nums[1] + ... + (n−1)×nums[n−1]`； + +- `F(1) = 1×nums[0] + 2×nums[1] + ... + 0×nums[n-1]`。 + +令数组`nums`中所有元素和为`sum`，用数学归纳法验证：当`1 ≤ k < n`时，`F(k) = F(k-1) + sum - n×nums[n-k]`成立。 + +**归纳奠基**：证明`k=1`时命题成立。 + +```c +F(1) = 1×nums[0] + 2×nums[1] + ... + 0×nums[n-1] + = F(0) + sum - n×nums[n-1] +``` + +**归纳假设**：假设`F(k) = F(k-1) + sum - n×nums[n-k]`成立。 + +**归纳递推**：由归纳假设推出`F(k+1) = F(k) + sum - n×nums[n-(k+1)]`成立，则假设的递推公式成立。 + +```c +F(k+1) = (k+1)×nums[0] + k×nums[1] + ... + 0×nums[n-1] + = F(k) + sum - n×nums[n-(k+1)] +``` + +因此可以得到递推公式： + +- 当`n = 0`时，`F(0) = 0×nums[0] + 1×nums[1] + ... + (n−1)×nums[n−1]` +- 当`1 ≤ k < n`时，`F(k) = F(k-1) + sum - n×nums[n-k]`成立。 + +循环遍历`0 ≤ k < n`，计算出不同的`F(k)`并不断更新最大值，就能求出`F(0), F(1), ..., F(n-1)`中的最大值。 + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0300~0399/0397.Integer-Replacement.md b/website/content/ChapterFour/0300~0399/0397.Integer-Replacement.md index 57a91ef22..92179b94a 100755 --- a/website/content/ChapterFour/0300~0399/0397.Integer-Replacement.md +++ b/website/content/ChapterFour/0300~0399/0397.Integer-Replacement.md @@ -88,6 +88,6 @@ func integerReplacement(n int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0300~0399/0399.Evaluate-Division.md b/website/content/ChapterFour/0300~0399/0399.Evaluate-Division.md index efe0faef5..b1d2a5988 100755 --- a/website/content/ChapterFour/0300~0399/0399.Evaluate-Division.md +++ b/website/content/ChapterFour/0300~0399/0399.Evaluate-Division.md @@ -120,5 +120,5 @@ func calcEquation(equations [][]string, values []float64, queries [][]string) [] ---------------------------------------------- diff --git a/website/content/ChapterFour/0400~0499/0400.Nth-Digit.md b/website/content/ChapterFour/0400~0499/0400.Nth-Digit.md new file mode 100644 index 000000000..543559ac1 --- /dev/null +++ b/website/content/ChapterFour/0400~0499/0400.Nth-Digit.md @@ -0,0 +1,74 @@ +# [400. Nth Digit](https://leetcode.com/problems/nth-digit/) + +## 题目 + +Given an integer n, return the nth digit of the infinite integer sequence [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, ...]. + +**Example 1**: + + Input: n = 3 + Output: 3 + +**Example 2**: + + Input: n = 11 + Output: 0 + Explanation: The 11th digit of the sequence 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, ... is a 0, which is part of the number 10. + +**Constraints:** + +- 1 <= n <= int(math.Pow(2, 31)) - 1 + +## 题目大意 + +给你一个整数 n ，请你在无限的整数序列 [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, ...] 中找出并返回第 n 位数字。 + +## 解题思路 + +- bits = 1 的时候有 1,2,3,4,5,6,7,8,9 这 9 个数; 9 = math.Pow10(bits - 1) * bits +- bits = 2 的时候有 10-99 这 90 个数; 90 = math.Pow10(bits - 1) * bits +- n 不断减去 bits 从 1 开始的数字总数,求出 n 所在的数字是几位数即 bits +- 计算 n 所在的数字 num，等于初始值加上 (n - 1) / bits +- 计算 n 所在这个数字的第几位 digitIdx 等于 (n - 1) % bits +- 计算出 digitIdx 位的数字 + + ### 以11 为例: + 11 - 9 = 2 + + (2 - 1) / 2 = 0 + + (2 - 1) % 2 = 1 + + 也就是说第 11 位数字是位数是 2 的第一个数字的第二位，即是 0 + +## 代码 + +```go + +package leetcode + +import "math" + +func findNthDigit(n int) int { + if n <= 9 { + return n + } + bits := 1 + for n > 9*int(math.Pow10(bits-1))*bits { + n -= 9 * int(math.Pow10(bits-1)) * bits + bits++ + } + idx := n - 1 + start := int(math.Pow10(bits - 1)) + num := start + idx/bits + digitIdx := idx % bits + return num / int(math.Pow10(bits-digitIdx-1)) % 10 +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0400~0499/0401.Binary-Watch.md b/website/content/ChapterFour/0400~0499/0401.Binary-Watch.md index 462679a61..07ebddf69 100755 --- a/website/content/ChapterFour/0400~0499/0401.Binary-Watch.md +++ b/website/content/ChapterFour/0400~0499/0401.Binary-Watch.md @@ -51,30 +51,67 @@ import ( "strconv" ) +// 解法一 +func readBinaryWatch(num int) []string { + memo := make([]int, 60) + // count the number of 1 in a binary number + count := func(n int) int { + if memo[n] != 0 { + return memo[n] + } + originN, res := n, 0 + for n != 0 { + n = n & (n - 1) + res++ + } + memo[originN] = res + return res + } + // fmtMinute format minute 0:1 -> 0:01 + fmtMinute := func(m int) string { + if m < 10 { + return "0" + strconv.Itoa(m) + } + return strconv.Itoa(m) + } + + var res []string + // traverse 0:00 -> 12:00 + for i := 0; i < 12; i++ { + for j := 0; j < 60; j++ { + if count(i)+count(j) == num { + res = append(res, strconv.Itoa(i)+":"+fmtMinute(j)) + } + } + } + return res +} + +// 解法二 打表 var ( hour = []string{"1", "2", "4", "8"} minute = []string{"01", "02", "04", "08", "16", "32"} hourMap = map[int][]string{ - 0: []string{"0"}, - 1: []string{"1", "2", "4", "8"}, - 2: []string{"3", "5", "9", "6", "10"}, - 3: []string{"7", "11"}, + 0: {"0"}, + 1: {"1", "2", "4", "8"}, + 2: {"3", "5", "9", "6", "10"}, + 3: {"7", "11"}, } minuteMap = map[int][]string{ - 0: []string{"00"}, - 1: []string{"01", "02", "04", "08", "16", "32"}, - 2: []string{"03", "05", "09", "17", "33", "06", "10", "18", "34", "12", "20", "36", "24", "40", "48"}, - 3: []string{"07", "11", "19", "35", "13", "21", "37", "25", "41", "49", "14", "22", "38", "26", "42", "50", "28", "44", "52", "56"}, - 4: []string{"15", "23", "39", "27", "43", "51", "29", "45", "53", "57", "30", "46", "54", "58"}, - 5: []string{"31", "47", "55", "59"}, + 0: {"00"}, + 1: {"01", "02", "04", "08", "16", "32"}, + 2: {"03", "05", "09", "17", "33", "06", "10", "18", "34", "12", "20", "36", "24", "40", "48"}, + 3: {"07", "11", "19", "35", "13", "21", "37", "25", "41", "49", "14", "22", "38", "26", "42", "50", "28", "44", "52", "56"}, + 4: {"15", "23", "39", "27", "43", "51", "29", "45", "53", "57", "30", "46", "54", "58"}, + 5: {"31", "47", "55", "59"}, } ) -func readBinaryWatch(num int) []string { +func readBinaryWatch1(num int) []string { + var res []string if num > 8 { - return []string{} + return res } - res := []string{} for i := 0; i <= num; i++ { for j := 0; j < len(hourMap[i]); j++ { for k := 0; k < len(minuteMap[num-i]); k++ { @@ -135,11 +172,12 @@ func findReadBinaryWatchHour(target, index int, c []int, res *[]string) { } } + ``` ---------------------------------------------- diff --git a/website/content/ChapterFour/0400~0499/0412.Fizz-Buzz.md b/website/content/ChapterFour/0400~0499/0412.Fizz-Buzz.md index 9ed37c0d0..72ab8c7c3 100644 --- a/website/content/ChapterFour/0400~0499/0412.Fizz-Buzz.md +++ b/website/content/ChapterFour/0400~0499/0412.Fizz-Buzz.md @@ -50,18 +50,16 @@ package leetcode import "strconv" func fizzBuzz(n int) []string { - if n < 0 { - return []string{} - } solution := make([]string, n) for i := 1; i <= n; i++ { - if i%3 == 0 && i%5 == 0 { - solution[i-1] = "FizzBuzz" - } else if i%3 == 0 { - solution[i-1] = "Fizz" - } else if i%5 == 0 { - solution[i-1] = "Buzz" - } else { + solution[i-1] = "" + if i%3 == 0 { + solution[i-1] += "Fizz" + } + if i%5 == 0 { + solution[i-1] += "Buzz" + } + if solution[i-1] == "" { solution[i-1] = strconv.Itoa(i) } } diff --git a/website/content/ChapterFour/0400~0499/0417.Pacific-Atlantic-Water-Flow.md b/website/content/ChapterFour/0400~0499/0417.Pacific-Atlantic-Water-Flow.md index a4072e31d..c19fb8751 100644 --- a/website/content/ChapterFour/0400~0499/0417.Pacific-Atlantic-Water-Flow.md +++ b/website/content/ChapterFour/0400~0499/0417.Pacific-Atlantic-Water-Flow.md @@ -95,5 +95,5 @@ func dfs(matrix [][]int, row, col int, visited *[][]bool, height int) { ---------------------------------------------- diff --git a/website/content/ChapterFour/0400~0499/0419.Battleships-in-a-Board.md b/website/content/ChapterFour/0400~0499/0419.Battleships-in-a-Board.md new file mode 100644 index 000000000..505b3ab0a --- /dev/null +++ b/website/content/ChapterFour/0400~0499/0419.Battleships-in-a-Board.md @@ -0,0 +1,58 @@ +# [419. Battleships in a Board](https://leetcode.com/problems/battleships-in-a-board/) + +## 题目 + +Given an `m x n` matrix `board` where each cell is a battleship `'X'` or empty `'.'`, return the number of the **battleships** on `board`. + +**Battleships** can only be placed horizontally or vertically on `board`. In other words, they can only be made of the shape `1 x k` (`1` row, `k` columns) or `k x 1` (`k` rows, `1` column), where `k` can be of any size. At least one horizontal or vertical cell separates between two battleships (i.e., there are no adjacent battleships). + +**Example 1:** + +![img](https://assets.leetcode.com/uploads/2021/04/10/battelship-grid.jpg) + +```c +Input: board = [["X",".",".","X"],[".",".",".","X"],[".",".",".","X"]] +Output: 2 +``` + +**Example 2:** + +```c +Input: board = [["."]] +Output: 0 +``` + +**Constraints:** + +- `m == board.length` +- `n == board[i].length` +- `1 <= m, n <= 200` +- `board[i][j] is either '.' or 'X'`. + +**Follow up:** Could you do it in one-pass, using only `O(1)` extra memory and without modifying the values `board`? + +## 题目大意 + +给定一个大小为`m × n`的矩阵 称之为甲板，矩阵单元格中的`'X'`表示战舰，`'.'`表示空位。 + +战舰只能水平或竖直摆放在甲板上（换句话说，可以理解为联通的同一行`'X'`或同一列`'X'`只算作一个“战舰群”），任意俩个“战舰群”间都是不相邻的。返回甲板上“战舰群”的数量。 + +## 解题思路 + +题目进阶要求一次扫描算法，空间复杂度为`O(1)`，且不能修改矩阵中的值。 + +因为题目中给定的两个“战舰群”间至少有一个水平或垂直的空位分隔，所以可以通过枚举每个战舰的左上顶点即可统计“战舰群”的个数。 + +假设当前遍历到矩阵中`'X'`的位置为`(i, j)`，即 `board[i][j]='X'`。如果当前战舰属于一个新的“战舰群”，则需要满足以下条件： + +- 当前位置的上方位为空，即 `board[i-1][j]='.'`； +- 当前位置的左方位为空，即 `board[i][j-1]='.'`； + +统计出所有左方位和上方位为空的战舰个数，即可得到“战舰群”的数量。 + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0400~0499/0421.Maximum-XOR-of-Two-Numbers-in-an-Array.md b/website/content/ChapterFour/0400~0499/0421.Maximum-XOR-of-Two-Numbers-in-an-Array.md index 05db370e2..7abc8d853 100755 --- a/website/content/ChapterFour/0400~0499/0421.Maximum-XOR-of-Two-Numbers-in-an-Array.md +++ b/website/content/ChapterFour/0400~0499/0421.Maximum-XOR-of-Two-Numbers-in-an-Array.md @@ -101,6 +101,6 @@ func findMaximumXOR1(nums []int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0400~0499/0424.Longest-Repeating-Character-Replacement.md b/website/content/ChapterFour/0400~0499/0424.Longest-Repeating-Character-Replacement.md index 6846fd35d..d9cc7cbe1 100644 --- a/website/content/ChapterFour/0400~0499/0424.Longest-Repeating-Character-Replacement.md +++ b/website/content/ChapterFour/0400~0499/0424.Longest-Repeating-Character-Replacement.md @@ -88,5 +88,5 @@ func max(a int, b int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0400~0499/0429.N-ary-Tree-Level-Order-Traversal.md b/website/content/ChapterFour/0400~0499/0429.N-ary-Tree-Level-Order-Traversal.md new file mode 100644 index 000000000..ac4fe90a2 --- /dev/null +++ b/website/content/ChapterFour/0400~0499/0429.N-ary-Tree-Level-Order-Traversal.md @@ -0,0 +1,92 @@ +# [429.N-ary Tree Level Order Traversal](https://leetcode.com/problems/n-ary-tree-level-order-traversal/) + + +## 题目 + +Given an n-ary tree, return the *level order* traversal of its nodes' values. + +*Nary-Tree input serialization is represented in their level order traversal, each group of children is separated by the null value (See examples).* + +**Example 1:** + +![https://assets.leetcode.com/uploads/2018/10/12/narytreeexample.png](https://assets.leetcode.com/uploads/2018/10/12/narytreeexample.png) + +``` +Input: root = [1,null,3,2,4,null,5,6] +Output: [[1],[3,2,4],[5,6]] + +``` + +**Example 2:** + +![https://assets.leetcode.com/uploads/2019/11/08/sample_4_964.png](https://assets.leetcode.com/uploads/2019/11/08/sample_4_964.png) + +``` +Input: root = [1,null,2,3,4,5,null,null,6,7,null,8,null,9,10,null,null,11,null,12,null,13,null,null,14] +Output: [[1],[2,3,4,5],[6,7,8,9,10],[11,12,13],[14]] + +``` + +**Constraints:** + +- The height of the n-ary tree is less than or equal to `1000` +- The total number of nodes is between `[0, 104]` + +## 题目大意 + +给定一个 N 叉树，返回其节点值的层序遍历。（即从左到右，逐层遍历）。树的序列化输入是用层序遍历，每组子节点都由 null 值分隔（参见示例）。 + +## 解题思路 + +- 这是 n 叉树的系列题，第 589 题也是这一系列的题目。这一题思路不难，既然是层序遍历，用 BFS 解答。 + +## 代码 + +```go +package leetcode + +/** + * Definition for a Node. + * type Node struct { + * Val int + * Children []*Node + * } + */ + +type Node struct { + Val int + Children []*Node +} + +func levelOrder(root *Node) [][]int { + var res [][]int + var temp []int + if root == nil { + return res + } + queue := []*Node{root, nil} + for len(queue) > 1 { + node := queue[0] + queue = queue[1:] + if node == nil { + queue = append(queue, nil) + res = append(res, temp) + temp = []int{} + } else { + temp = append(temp, node.Val) + if len(node.Children) > 0 { + queue = append(queue, node.Children...) + } + } + } + res = append(res, temp) + return res +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0400~0499/0433.Minimum-Genetic-Mutation.md b/website/content/ChapterFour/0400~0499/0433.Minimum-Genetic-Mutation.md index 2f6b2fd59..566f2afde 100755 --- a/website/content/ChapterFour/0400~0499/0433.Minimum-Genetic-Mutation.md +++ b/website/content/ChapterFour/0400~0499/0433.Minimum-Genetic-Mutation.md @@ -185,6 +185,6 @@ func convert(gene string) uint32 { ---------------------------------------------- diff --git a/website/content/ChapterFour/0400~0499/0434.Number-of-Segments-in-a-String.md b/website/content/ChapterFour/0400~0499/0434.Number-of-Segments-in-a-String.md new file mode 100644 index 000000000..71d45b7d7 --- /dev/null +++ b/website/content/ChapterFour/0400~0499/0434.Number-of-Segments-in-a-String.md @@ -0,0 +1,77 @@ +# [434. Number of Segments in a String](https://leetcode.com/problems/number-of-segments-in-a-string/) + + +## 题目 + +You are given a string s, return the number of segments in the string. + +A segment is defined to be a contiguous sequence of non-space characters. + +**Example 1:** + + Input: s = "Hello, my name is John" + Output: 5 + Explanation: The five segments are ["Hello,", "my", "name", "is", "John"] + +**Example 2:** + + Input: s = "Hello" + Output: 1 + +**Example 3:** + + Input: s = "love live! mu'sic forever" + Output: 4 + +**Example 4:** + + Input: s = "" + Output: 0 + +**Constraints** + + - 0 <= s.length <= 300 + - s consists of lower-case and upper-case English letters, digits or one of the following characters "!@#$%^&*()_+-=',.:". + - The only space character in s is ' '. + +## 题目大意 + +统计字符串中的单词个数，这里的单词指的是连续的不是空格的字符。 + +请注意，你可以假定字符串里不包括任何不可打印的字符。 + +## 解题思路 + +- 以空格为分割计算元素个数 + +## 代码 + +```go + +package leetcode + +func countSegments(s string) int { + segments := false + cnt := 0 + for _, v := range s { + if v == ' ' && segments { + segments = false + cnt += 1 + } else if v != ' ' { + segments = true + } + } + if segments { + cnt++ + } + return cnt +} + +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0400~0499/0435.Non-overlapping-Intervals.md b/website/content/ChapterFour/0400~0499/0435.Non-overlapping-Intervals.md index 9ab19644c..17d409ac3 100755 --- a/website/content/ChapterFour/0400~0499/0435.Non-overlapping-Intervals.md +++ b/website/content/ChapterFour/0400~0499/0435.Non-overlapping-Intervals.md @@ -137,6 +137,6 @@ func eraseOverlapIntervals1(intervals [][]int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0400~0499/0437.Path-Sum-III.md b/website/content/ChapterFour/0400~0499/0437.Path-Sum-III.md index e05fc8550..cf8405325 100755 --- a/website/content/ChapterFour/0400~0499/0437.Path-Sum-III.md +++ b/website/content/ChapterFour/0400~0499/0437.Path-Sum-III.md @@ -3,32 +3,34 @@ ## 题目 -You are given a binary tree in which each node contains an integer value. +Given the `root` of a binary tree and an integer `targetSum`, return *the number of paths where the sum of the values along the path equals* `targetSum`. -Find the number of paths that sum to a given value. +The path does not need to start or end at the root or a leaf, but it must go downwards (i.e., traveling only from parent nodes to child nodes). -The path does not need to start or end at the root or a leaf, but it must go downwards (traveling only from parent nodes to child nodes). +**Example 1:** -The tree has no more than 1,000 nodes and the values are in the range -1,000,000 to 1,000,000. +![https://assets.leetcode.com/uploads/2021/04/09/pathsum3-1-tree.jpg](https://assets.leetcode.com/uploads/2021/04/09/pathsum3-1-tree.jpg) -**Example**: +``` +Input: root = [10,5,-3,3,2,null,11,3,-2,null,1], targetSum = 8 +Output: 3 +Explanation: The paths that sum to 8 are shown. + +``` + +**Example 2:** + +``` +Input: root = [5,4,8,11,null,13,4,7,2,null,null,5,1], targetSum = 22 +Output: 3 + +``` - root = [10,5,-3,3,2,null,11,3,-2,null,1], sum = 8 - - 10 - / \ - 5 -3 - / \ \ - 3 2 11 - / \ \ - 3 -2 1 - - Return 3. The paths that sum to 8 are: - - 1. 5 -> 3 - 2. 5 -> 2 -> 1 - 3. -3 -> 11 +**Constraints:** +- The number of nodes in the tree is in the range `[0, 1000]`. +- `109 <= Node.val <= 109` +- `1000 <= targetSum <= 1000` ## 题目大意 @@ -50,6 +52,13 @@ The tree has no more than 1,000 nodes and the values are in the range -1,000,000 package leetcode +import ( + "github.com/halfrost/leetcode-go/structures" +) + +// TreeNode define +type TreeNode = structures.TreeNode + /** * Definition for a binary tree node. * type TreeNode struct { @@ -58,6 +67,31 @@ package leetcode * Right *TreeNode * } */ + +// 解法一 带缓存 dfs +func pathSum(root *TreeNode, targetSum int) int { + prefixSum := make(map[int]int) + prefixSum[0] = 1 + return dfs(root, prefixSum, 0, targetSum) +} + +func dfs(root *TreeNode, prefixSum map[int]int, cur, sum int) int { + if root == nil { + return 0 + } + cur += root.Val + cnt := 0 + if v, ok := prefixSum[cur-sum]; ok { + cnt = v + } + prefixSum[cur]++ + cnt += dfs(root.Left, prefixSum, cur, sum) + cnt += dfs(root.Right, prefixSum, cur, sum) + prefixSum[cur]-- + return cnt +} + +// 解法二 func pathSumIII(root *TreeNode, sum int) int { if root == nil { return 0 @@ -82,6 +116,7 @@ func findPath437(root *TreeNode, sum int) int { return res } + ``` diff --git a/website/content/ChapterFour/0400~0499/0445.Add-Two-Numbers-II.md b/website/content/ChapterFour/0400~0499/0445.Add-Two-Numbers-II.md index 9d167693c..a4156c6fb 100644 --- a/website/content/ChapterFour/0400~0499/0445.Add-Two-Numbers-II.md +++ b/website/content/ChapterFour/0400~0499/0445.Add-Two-Numbers-II.md @@ -32,6 +32,22 @@ Output: 7 -> 8 -> 0 -> 7 package leetcode +/** + * Definition for singly-linked list. + * type ListNode struct { + * Val int + * Next *ListNode + * } + */ +package leetcode + +import ( + "github.com/halfrost/leetcode-go/structures" +) + +// ListNode define +type ListNode = structures.ListNode + /** * Definition for singly-linked list. * type ListNode struct { @@ -93,6 +109,75 @@ func getLength(l *ListNode) int { return count } +func addTwoNumbers1(l1 *ListNode, l2 *ListNode) *ListNode { + reservedL1 := reverseList(l1) + reservedL2 := reverseList(l2) + + dummyHead := &ListNode{} + head := dummyHead + carry := 0 + for reservedL1 != nil || reservedL2 != nil || carry > 0 { + val := carry + if reservedL1 != nil { + val = reservedL1.Val + val + reservedL1 = reservedL1.Next + } + if reservedL2 != nil { + val = reservedL2.Val + val + reservedL2 = reservedL2.Next + } + carry = val / 10 + head.Next = &ListNode{Val: val % 10} + head = head.Next + } + return reverseList(dummyHead.Next) +} + +func reverseList(head *ListNode) *ListNode { + var prev *ListNode + for head != nil { + tmp := head.Next + head.Next = prev + + prev = head + head = tmp + } + return prev +} + +func addTwoNumbers(l1 *ListNode, l2 *ListNode) *ListNode { + stack1 := pushStack(l1) + stack2 := pushStack(l2) + + dummyHead := &ListNode{} + head := dummyHead + carry := 0 + for len(stack1) > 0 || len(stack2) > 0 || carry > 0 { + val := carry + if len(stack1) > 0 { + val = val + stack1[len(stack1)-1] + stack1 = stack1[:len(stack1)-1] + } + if len(stack2) > 0 { + val = val + stack2[len(stack2)-1] + stack2 = stack2[:len(stack2)-1] + } + carry = val / 10 + tmp := head.Next + head.Next = &ListNode{Val: val % 10, Next: tmp} + } + return dummyHead.Next +} + +func pushStack(l *ListNode) []int { + var stack []int + for l != nil { + stack = append(stack, l.Val) + l = l.Next + } + return stack +} + ``` diff --git a/website/content/ChapterFour/0400~0499/0454.4Sum-II.md b/website/content/ChapterFour/0400~0499/0454.4Sum-II.md index 5b97f45b8..bccad3d5a 100644 --- a/website/content/ChapterFour/0400~0499/0454.4Sum-II.md +++ b/website/content/ChapterFour/0400~0499/0454.4Sum-II.md @@ -23,7 +23,7 @@ Explanation: The two tuples are: 1. (0, 0, 0, 1) -> A[0] + B[0] + C[0] + D[1] = 1 + (-2) + (-1) + 2 = 0 2. (1, 1, 0, 0) -> A[1] + B[1] + C[0] + D[0] = 2 + (-1) + (-1) + 0 = 0 -3. + ``` diff --git a/website/content/ChapterFour/0400~0499/0457.Circular-Array-Loop.md b/website/content/ChapterFour/0400~0499/0457.Circular-Array-Loop.md index e665c389c..d43a50e6e 100755 --- a/website/content/ChapterFour/0400~0499/0457.Circular-Array-Loop.md +++ b/website/content/ChapterFour/0400~0499/0457.Circular-Array-Loop.md @@ -107,5 +107,5 @@ func getNextIndex(nums []int, index int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0400~0499/0458.Poor-Pigs.md b/website/content/ChapterFour/0400~0499/0458.Poor-Pigs.md new file mode 100644 index 000000000..dcccfda06 --- /dev/null +++ b/website/content/ChapterFour/0400~0499/0458.Poor-Pigs.md @@ -0,0 +1,84 @@ +# [458. Poor Pigs](https://leetcode.com/problems/poor-pigs/) + +## 题目 + +There are buckets buckets of liquid, where exactly one of the buckets is poisonous. To figure out which one is poisonous, you feed some number of (poor) pigs the liquid to see whether they will die or not. Unfortunately, you only have minutesToTest minutes to determine which bucket is poisonous. + +You can feed the pigs according to these steps: + +- Choose some live pigs to feed. +- For each pig, choose which buckets to feed it. The pig will consume all the chosen buckets simultaneously and will take no time. +- Wait for minutesToDie minutes. You may not feed any other pigs during this time. +- After minutesToDie minutes have passed, any pigs that have been fed the poisonous bucket will die, and all others will survive. +- Repeat this process until you run out of time. + +Given buckets, minutesToDie, and minutesToTest, return the minimum number of pigs needed to figure out which bucket is poisonous within the allotted time. + +**Example 1**: + + Input: buckets = 1000, minutesToDie = 15, minutesToTest = 60 + Output: 5 + +**Example 2**: + + Input: buckets = 4, minutesToDie = 15, minutesToTest = 15 + Output: 2 + +**Example 3**: + + Input: buckets = 4, minutesToDie = 15, minutesToTest = 30 + Output: 2 + +**Constraints:** + +- 1 <= buckets <= 1000 +- 1 <= minutesToDie <= minutesToTest <= 100 + +## 题目大意 + +有 buckets 桶液体，其中 正好 有一桶含有毒药，其余装的都是水。它们从外观看起来都一样。为了弄清楚哪只水桶含有毒药，你可以喂一些猪喝，通过观察猪是否会死进行判断。不幸的是，你只有 minutesToTest 分钟时间来确定哪桶液体是有毒的。 + +喂猪的规则如下： + +- 选择若干活猪进行喂养 +- 可以允许小猪同时饮用任意数量的桶中的水，并且该过程不需要时间。 +- 小猪喝完水后，必须有 minutesToDie 分钟的冷却时间。在这段时间里，你只能观察，而不允许继续喂猪。 +- 过了 minutesToDie 分钟后，所有喝到毒药的猪都会死去，其他所有猪都会活下来。 +- 重复这一过程，直到时间用完。 + +给你桶的数目 buckets ，minutesToDie 和 minutesToTest ，返回在规定时间内判断哪个桶有毒所需的 最小 猪数。 + +## 解题思路 + +使用数学方法,以 minutesToDie=15, minutesToTest=60, 1 只小猪为例,可以测试 5 只桶 + +- 0-15 小猪吃第一个桶中的液体,如果死去，则第一个桶有毒,否则继续测试 +- 15-30 小猪吃第二个桶中的液体，如果死去，则第二个桶有毒,否则继续测试 +- 30-45 小猪吃第三个桶中的液体，如果死去，则第三个桶有毒,否则继续测试 +- 45-60 小猪吃第四个桶中的液体，如果死去，则第四个桶有毒 +- 如果最后小猪没有死去，则第五个桶有毒 + +所以一只小猪在 minutesToDie 和 minutesToTest 时间一定的情况下可以最多判断 base = minutesToTest / minutesToDie + 1 个桶 + +假设小猪的数量是 num,那么 pow(base, num) >= buckets,根据对数运算规则，两边分别取对数得到: num >= Log10(buckets) / Log10(base) + +## 代码 + +```go + +package leetcode + +import "math" + +func poorPigs(buckets int, minutesToDie int, minutesToTest int) int { + base := minutesToTest/minutesToDie + 1 + return int(math.Ceil(math.Log10(float64(buckets)) / math.Log10(float64(base)))) +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0400~0499/0460.LFU-Cache.md b/website/content/ChapterFour/0400~0499/0460.LFU-Cache.md index dfbde2437..5692cc711 100644 --- a/website/content/ChapterFour/0400~0499/0460.LFU-Cache.md +++ b/website/content/ChapterFour/0400~0499/0460.LFU-Cache.md @@ -144,6 +144,6 @@ func (this *LFUCache) Put(key int, value int) { ---------------------------------------------- diff --git a/website/content/ChapterFour/0400~0499/0461.Hamming-Distance.md b/website/content/ChapterFour/0400~0499/0461.Hamming-Distance.md index 9335d7750..c36e66eb7 100755 --- a/website/content/ChapterFour/0400~0499/0461.Hamming-Distance.md +++ b/website/content/ChapterFour/0400~0499/0461.Hamming-Distance.md @@ -56,5 +56,5 @@ func hammingDistance(x int, y int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0400~0499/0462.Minimum-Moves-to-Equal-Array-Elements-II.md b/website/content/ChapterFour/0400~0499/0462.Minimum-Moves-to-Equal-Array-Elements-II.md new file mode 100644 index 000000000..c43b0bdeb --- /dev/null +++ b/website/content/ChapterFour/0400~0499/0462.Minimum-Moves-to-Equal-Array-Elements-II.md @@ -0,0 +1,73 @@ +# [462. Minimum Moves to Equal Array Elements II](https://leetcode.com/problems/minimum-moves-to-equal-array-elements-ii/) + + +## 题目 + +Given an integer array `nums` of size `n`, return *the minimum number of moves required to make all array elements equal*. + +In one move, you can increment or decrement an element of the array by `1`. + +**Example 1:** + +``` +Input: nums = [1,2,3] +Output: 2 +Explanation: +Only two moves are needed (remember each move increments or decrements one element): +[1,2,3] => [2,2,3] => [2,2,2] +``` + +**Example 2:** + +``` +Input: nums = [1,10,2,9] +Output: 16 +``` + +**Constraints:** + +- `n == nums.length` +- `1 <= nums.length <= 10^5` +- `109 <= nums[i] <= 10^9` + +## 题目大意 + +给定一个非空整数数组，找到使所有数组元素相等所需的最小移动数，其中每次移动可将选定的一个元素加 1 或减 1。 您可以假设数组的长度最多为10000。 + +## 解题思路 + +- 这题抽象成数学问题是，如果我们把数组 a 中的每个数看成水平轴上的一个点，那么根据上面的移动次数公式，我们需要找到在水平轴上找到一个点 x，使得这 N 个点到 x 的距离之和最小。有 2 个点值得我们考虑，一个是中位数，另外一个是平均值。举个简单的例子，[1,0,0,8,6] 这组数据，中位数是 1，平均值是 3 。分别计算移动的步数，按照中位数对齐是 14，按照平均值对齐是 16 。所以选择中位数。 +- 此题可以用数学证明，证明出，按照平均值移动的步数 ≥ 按照中位数移动的步数。具体证明笔者这里不证明了，感兴趣的同学可以自己证明试试。 + +## 代码 + +```go +package leetcode + +import ( + "math" + "sort" +) + +func minMoves2(nums []int) int { + if len(nums) == 0 { + return 0 + } + moves, mid := 0, len(nums)/2 + sort.Ints(nums) + for i := range nums { + if i == mid { + continue + } + moves += int(math.Abs(float64(nums[mid] - nums[i]))) + } + return moves +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0400~0499/0463.Island-Perimeter.md b/website/content/ChapterFour/0400~0499/0463.Island-Perimeter.md index e0e60da7c..3ac220658 100755 --- a/website/content/ChapterFour/0400~0499/0463.Island-Perimeter.md +++ b/website/content/ChapterFour/0400~0499/0463.Island-Perimeter.md @@ -73,6 +73,6 @@ func islandPerimeter(grid [][]int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0400~0499/0470.Implement-Rand10-Using-Rand7.md b/website/content/ChapterFour/0400~0499/0470.Implement-Rand10-Using-Rand7.md index f36524a18..3e3ac3826 100755 --- a/website/content/ChapterFour/0400~0499/0470.Implement-Rand10-Using-Rand7.md +++ b/website/content/ChapterFour/0400~0499/0470.Implement-Rand10-Using-Rand7.md @@ -103,5 +103,5 @@ func rand101() int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0400~0499/0473.Matchsticks-to-Square.md b/website/content/ChapterFour/0400~0499/0473.Matchsticks-to-Square.md new file mode 100644 index 000000000..5ac15f049 --- /dev/null +++ b/website/content/ChapterFour/0400~0499/0473.Matchsticks-to-Square.md @@ -0,0 +1,101 @@ +# [473. Matchsticks to Square](https://leetcode.com/problems/matchsticks-to-square/) + + +## 题目 + +You are given an integer array `matchsticks` where `matchsticks[i]` is the length of the `ith` matchstick. You want to use **all the matchsticks** to make one square. You **should not break** any stick, but you can link them up, and each matchstick must be used **exactly one time**. + +Return `true` if you can make this square and `false` otherwise. + +**Example 1:** + +![https://assets.leetcode.com/uploads/2021/04/09/matchsticks1-grid.jpg](https://assets.leetcode.com/uploads/2021/04/09/matchsticks1-grid.jpg) + +``` +Input: matchsticks = [1,1,2,2,2] +Output: true +Explanation: You can form a square with length 2, one side of the square came two sticks with length 1. +``` + +**Example 2:** + +``` +Input: matchsticks = [3,3,3,3,4] +Output: false +Explanation: You cannot find a way to form a square with all the matchsticks. +``` + +**Constraints:** + +- `1 <= matchsticks.length <= 15` +- `0 <= matchsticks[i] <= 109` + +## 题目大意 + +现在已知小女孩有多少根火柴，请找出一种能使用所有火柴拼成一个正方形的方法。不能折断火柴，可以把火柴连接起来，并且每根火柴都要用到。输入为小女孩拥有火柴的数目，每根火柴用其长度表示。输出即为是否能用所有的火柴拼成正方形。 + +## 解题思路 + +- 将火柴拼成一个正方形，可以将它们分成四组，每一根火柴恰好属于其中的一组；并且每一组火柴的长度之和都相同，等于所有火柴长度之和的四分之一。 +- 考虑暴力解法，使用深度优先搜索枚举出所有的分组情况，并对于每一种情况，判断是否满足上述的两个条件(每根火柴属于其中一组，每组火柴长度之和相同)。依次对每一根火柴进行搜索，当搜索到第 i 根火柴时，可以考虑把它放到四组中的任意一种。对于每一种放置方法，继续对第 i + 1 根火柴进行深搜。当我们搜索完全部的 N 根火柴后，再判断每一组火柴的长度之和是否都相同。 + +## 代码 + +```go +package leetcode + +import "sort" + +func makesquare(matchsticks []int) bool { + if len(matchsticks) < 4 { + return false + } + total := 0 + for _, v := range matchsticks { + total += v + } + if total%4 != 0 { + return false + } + sort.Slice(matchsticks, func(i, j int) bool { + return matchsticks[i] > matchsticks[j] + }) + visited := make([]bool, 16) + return dfs(matchsticks, 0, 0, 0, total, &visited) +} + +func dfs(matchsticks []int, cur, group, sum, total int, visited *[]bool) bool { + if group == 4 { + return true + } + if sum > total/4 { + return false + } + if sum == total/4 { + return dfs(matchsticks, 0, group+1, 0, total, visited) + } + last := -1 + for i := cur; i < len(matchsticks); i++ { + if (*visited)[i] { + continue + } + if last == matchsticks[i] { + continue + } + (*visited)[i] = true + last = matchsticks[i] + if dfs(matchsticks, i+1, group, sum+matchsticks[i], total, visited) { + return true + } + (*visited)[i] = false + } + return false +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0400~0499/0474.Ones-and-Zeroes.md b/website/content/ChapterFour/0400~0499/0474.Ones-and-Zeroes.md index 8fefe5c88..7cd4969c7 100755 --- a/website/content/ChapterFour/0400~0499/0474.Ones-and-Zeroes.md +++ b/website/content/ChapterFour/0400~0499/0474.Ones-and-Zeroes.md @@ -80,6 +80,6 @@ func findMaxForm(strs []string, m int, n int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0400~0499/0483.Smallest-Good-Base.md b/website/content/ChapterFour/0400~0499/0483.Smallest-Good-Base.md index 88e4c378e..817478cec 100755 --- a/website/content/ChapterFour/0400~0499/0483.Smallest-Good-Base.md +++ b/website/content/ChapterFour/0400~0499/0483.Smallest-Good-Base.md @@ -104,37 +104,27 @@ package leetcode import ( "math" + "math/bits" "strconv" ) func smallestGoodBase(n string) string { - num, _ := strconv.ParseUint(n, 10, 64) - for bit := uint64(math.Log2(float64(num))); bit >= 1; bit-- { - low, high := uint64(2), uint64(math.Pow(float64(num), 1.0/float64(bit))) - for low < high { - mid := uint64(low + (high-low)>>1) - sum := findBase(mid, bit) - if sum == num { - return strconv.FormatUint(mid, 10) - } else if sum > num { - high = mid - 1 - } else { - low = mid + 1 - } + nVal, _ := strconv.Atoi(n) + mMax := bits.Len(uint(nVal)) - 1 + for m := mMax; m > 1; m-- { + k := int(math.Pow(float64(nVal), 1/float64(m))) + mul, sum := 1, 1 + for i := 0; i < m; i++ { + mul *= k + sum += mul + } + if sum == nVal { + return strconv.Itoa(k) } } - return strconv.FormatUint(num-1, 10) + return strconv.Itoa(nVal - 1) } -// 计算 k^m + k^(m-1) + ... + k + 1 -func findBase(mid, bit uint64) uint64 { - sum, base := uint64(1), uint64(1) - for i := uint64(1); i <= bit; i++ { - base *= mid - sum += base - } - return sum -} ``` diff --git a/website/content/ChapterFour/0400~0499/0485.Max-Consecutive-Ones.md b/website/content/ChapterFour/0400~0499/0485.Max-Consecutive-Ones.md index afc46ab33..dce4ba166 100644 --- a/website/content/ChapterFour/0400~0499/0485.Max-Consecutive-Ones.md +++ b/website/content/ChapterFour/0400~0499/0485.Max-Consecutive-Ones.md @@ -62,5 +62,5 @@ func findMaxConsecutiveOnes(nums []int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0400~0499/0488.Zuma-Game.md b/website/content/ChapterFour/0400~0499/0488.Zuma-Game.md new file mode 100644 index 000000000..3b17baa76 --- /dev/null +++ b/website/content/ChapterFour/0400~0499/0488.Zuma-Game.md @@ -0,0 +1,148 @@ +# [488. Zuma Game](https://leetcode.com/problems/zuma-game/) + + +## 题目 + +You are playing a variation of the game Zuma. + +In this variation of Zuma, there is a single row of colored balls on a board, where each ball can be colored red 'R', yellow 'Y', blue 'B', green 'G', or white 'W'. You also have several colored balls in your hand. + +Your goal is to clear all of the balls from the board. On each turn: + +Pick any ball from your hand and insert it in between two balls in the row or on either end of the row. +If there is a group of three or more consecutive balls of the same color, remove the group of balls from the board. +If this removal causes more groups of three or more of the same color to form, then continue removing each group until there are none left. +If there are no more balls on the board, then you win the game. +Repeat this process until you either win or do not have any more balls in your hand. +Given a string board, representing the row of balls on the board, and a string hand, representing the balls in your hand, return the minimum number of balls you have to insert to clear all the balls from the board. If you cannot clear all the balls from the board using the balls in your hand, return -1. + +**Example 1**: + +``` +Input: board = "WRRBBW", hand = "RB" +Output: -1 +Explanation: It is impossible to clear all the balls. The best you can do is: +- Insert 'R' so the board becomes WRRRBBW. WRRRBBW -> WBBW. +- Insert 'B' so the board becomes WBBBW. WBBBW -> WW. +There are still balls remaining on the board, and you are out of balls to insert. +``` + +**Example 2**: +``` +Input: board = "WWRRBBWW", hand = "WRBRW" +Output: 2 +Explanation: To make the board empty: +- Insert 'R' so the board becomes WWRRRBBWW. WWRRRBBWW -> WWBBWW. +- Insert 'B' so the board becomes WWBBBWW. WWBBBWW -> WWWW -> empty. +2 balls from your hand were needed to clear the board. +``` + +**Example 3**: +``` +Input: board = "G", hand = "GGGGG" +Output: 2 +Explanation: To make the board empty: +- Insert 'G' so the board becomes GG. +- Insert 'G' so the board becomes GGG. GGG -> empty. +2 balls from your hand were needed to clear the board. +``` + +**Example 4**: +``` +Input: board = "RBYYBBRRB", hand = "YRBGB" +Output: 3 +Explanation: To make the board empty: +- Insert 'Y' so the board becomes RBYYYBBRRB. RBYYYBBRRB -> RBBBRRB -> RRRB -> B. +- Insert 'B' so the board becomes BB. +- Insert 'B' so the board becomes BBB. BBB -> empty. +3 balls from your hand were needed to clear the board. +``` + +**Constraints**: + +- 1 <= board.length <= 16 +- 1 <= hand.length <= 5 +- board and hand consist of the characters 'R', 'Y', 'B', 'G', and 'W'. +- The initial row of balls on the board will not have any groups of three or more consecutive balls of the same color. + +## 题目大意 + +你正在参与祖玛游戏的一个变种。 + +在这个祖玛游戏变体中，桌面上有 一排 彩球，每个球的颜色可能是：红色 'R'、黄色 'Y'、蓝色 'B'、绿色 'G' 或白色 'W' 。你的手中也有一些彩球。 + +你的目标是 清空 桌面上所有的球。每一回合： + +从你手上的彩球中选出 任意一颗 ，然后将其插入桌面上那一排球中：两球之间或这一排球的任一端。 +接着，如果有出现 三个或者三个以上 且 颜色相同 的球相连的话，就把它们移除掉。 +如果这种移除操作同样导致出现三个或者三个以上且颜色相同的球相连，则可以继续移除这些球，直到不再满足移除条件。 +如果桌面上所有球都被移除，则认为你赢得本场游戏。 +重复这个过程，直到你赢了游戏或者手中没有更多的球。 +给你一个字符串 board ，表示桌面上最开始的那排球。另给你一个字符串 hand ，表示手里的彩球。请你按上述操作步骤移除掉桌上所有球，计算并返回所需的 最少 球数。如果不能移除桌上所有的球，返回 -1 。 + +## 解题思路 + +- 使用广度优先搜索和剪枝 + +## 代码 + +```go + +package leetcode + +func findMinStep(board string, hand string) int { + q := [][]string{{board, hand}} + mp := make(map[string]bool) + minStep := 0 + for len(q) > 0 { + length := len(q) + minStep++ + for length > 0 { + length-- + cur := q[0] + q = q[1:] + curB, curH := cur[0], cur[1] + for i := 0; i < len(curB); i++ { + for j := 0; j < len(curH); j++ { + curB2 := del3(curB[0:i] + string(curH[j]) + curB[i:]) + curH2 := curH[0:j] + curH[j+1:] + if len(curB2) == 0 { + return minStep + } + if _, ok := mp[curB2+curH2]; ok { + continue + } + mp[curB2+curH2] = true + q = append(q, []string{curB2, curH2}) + } + } + } + } + return -1 +} + +func del3(str string) string { + cnt := 1 + for i := 1; i < len(str); i++ { + if str[i] == str[i-1] { + cnt++ + } else { + if cnt >= 3 { + return del3(str[0:i-cnt] + str[i:]) + } + cnt = 1 + } + } + if cnt >= 3 { + return str[0 : len(str)-cnt] + } + return str +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0400~0499/0491.Increasing-Subsequences.md b/website/content/ChapterFour/0400~0499/0491.Non-decreasing-Subsequences.md similarity index 93% rename from website/content/ChapterFour/0400~0499/0491.Increasing-Subsequences.md rename to website/content/ChapterFour/0400~0499/0491.Non-decreasing-Subsequences.md index a7271f6a5..e18e428c3 100755 --- a/website/content/ChapterFour/0400~0499/0491.Increasing-Subsequences.md +++ b/website/content/ChapterFour/0400~0499/0491.Non-decreasing-Subsequences.md @@ -1,4 +1,4 @@ -# [491. Increasing Subsequences](https://leetcode.com/problems/increasing-subsequences/) +# [491. Non-decreasing Subsequences](https://leetcode.com/problems/non-decreasing-subsequences/) ## 题目 @@ -86,6 +86,6 @@ func generateIncSubsets(nums []int, current int, c []int, res *[][]int) { ---------------------------------------------- diff --git a/website/content/ChapterFour/0400~0499/0492.Construct-the-Rectangle.md b/website/content/ChapterFour/0400~0499/0492.Construct-the-Rectangle.md new file mode 100644 index 000000000..5e02ec17e --- /dev/null +++ b/website/content/ChapterFour/0400~0499/0492.Construct-the-Rectangle.md @@ -0,0 +1,79 @@ +# [492. Construct the Rectangle](https://leetcode.com/problems/construct-the-rectangle/) + + +## 题目 + +A web developer needs to know how to design a web page's size. +So, given a specific rectangular web page’s area, your job by now is to design a rectangular web page, +whose length L and width W satisfy the following requirements: + + The area of the rectangular web page you designed must equal to the given target area. + The width W should not be larger than the length L, which means L >= W. + The difference between length L and width W should be as small as possible. + Return an array [L, W] where L and W are the length and width of the web page you designed in sequence. + +**Example 1:** + + Input: area = 4 + Output: [2,2] + Explanation: The target area is 4, and all the possible ways to construct it are [1,4], [2,2], [4,1]. + But according to requirement 2, [1,4] is illegal; according to requirement 3, [4,1] is not optimal compared to [2,2]. So the length L is 2, and the width W is 2. + +**Example 2:** + + Input: area = 37 + Output: [37,1] + +**Example 3:** + + Input: area = 122122 + Output: [427,286] + +**Constraints** + + - 1 <= area <= 10000000 + +## 题目大意 + +作为一位 web 开发者， 懂得怎样去规划一个页面的尺寸是很重要的。 现给定一个具体的矩形页面面积，你的任务是设计一个长度为 L 和宽度为 W 且满足以下要求的矩形的页面。要求： + +1. 你设计的矩形页面必须等于给定的目标面积。 +2. 宽度 W 不应大于长度 L，换言之，要求 L >= W 。 +3. 长度 L 和宽度 W 之间的差距应当尽可能小。 + +你需要按顺序输出你设计的页面的长度 L 和宽度 W。 + +## 解题思路 + +- 令 W 等于根号 area +- 在 W 大于等于 1 的情况下,判断 area%W 是否等于 0,如果不相等 W 就减 1 继续循环,如果相等就返回 [area/W, W] + +## 代码 + +```go + +package leetcode + +import "math" + +func constructRectangle(area int) []int { + ans := make([]int, 2) + W := int(math.Sqrt(float64(area))) + for W >= 1 { + if area%W == 0 { + ans[0], ans[1] = area/W, W + break + } + W -= 1 + } + return ans +} + +`` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0400~0499/0493.Reverse-Pairs.md b/website/content/ChapterFour/0400~0499/0493.Reverse-Pairs.md index 14256f760..0e53ce7d5 100755 --- a/website/content/ChapterFour/0400~0499/0493.Reverse-Pairs.md +++ b/website/content/ChapterFour/0400~0499/0493.Reverse-Pairs.md @@ -52,7 +52,7 @@ package leetcode import ( "sort" - "github.com/halfrost/LeetCode-Go/template" + "github.com/halfrost/leetcode-go/template" ) // 解法一 归并排序 mergesort，时间复杂度 O(n log n) @@ -158,6 +158,6 @@ func reversePairs2(nums []int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0400~0499/0494.Target-Sum.md b/website/content/ChapterFour/0400~0499/0494.Target-Sum.md index 4dfd11e87..e104ed18a 100644 --- a/website/content/ChapterFour/0400~0499/0494.Target-Sum.md +++ b/website/content/ChapterFour/0400~0499/0494.Target-Sum.md @@ -42,7 +42,7 @@ There are 5 ways to assign symbols to make the sum of nums be target 3. ## 解题思路 - 给出一个数组，要求在这个数组里面的每个元素前面加上 + 或者 - 号，最终总和等于 S。问有多少种不同的方法。 -- 这一题可以用 DP 和 DFS 解答。DFS 方法就不比较暴力简单了。见代码。这里分析一下 DP 的做法。题目要求在数组元素前加上 + 或者 - 号，其实相当于把数组分成了 2 组，一组全部都加 + 号，一组都加 - 号。记 + 号的一组 P ，记 - 号的一组 N，那么可以推出以下的关系。 +- 这一题可以用 DP 和 DFS 解答。DFS 方法就比较暴力简单了。见代码。这里分析一下 DP 的做法。题目要求在数组元素前加上 + 或者 - 号，其实相当于把数组分成了 2 组，一组全部都加 + 号，一组都加 - 号。记 + 号的一组 P ，记 - 号的一组 N，那么可以推出以下的关系。 ```go sum(P) - sum(N) = target @@ -111,5 +111,5 @@ func dfsFindTargetSumWays(nums []int, index int, curSum int, S int, res *int, su ---------------------------------------------- diff --git a/website/content/ChapterFour/0400~0499/0495.Teemo-Attacking.md b/website/content/ChapterFour/0400~0499/0495.Teemo-Attacking.md new file mode 100644 index 000000000..b575de2cb --- /dev/null +++ b/website/content/ChapterFour/0400~0499/0495.Teemo-Attacking.md @@ -0,0 +1,92 @@ +# [495. Teemo Attacking](https://leetcode.com/problems/teemo-attacking/) + + +## 题目 + +Our hero Teemo is attacking an enemy Ashe with poison attacks! When Teemo attacks Ashe, Ashe gets poisoned for a exactly duration seconds. + +More formally, an attack at second t will mean Ashe is poisoned during the inclusive time interval [t, t + duration - 1]. + +If Teemo attacks again before the poison effect ends, the timer for it is reset, and the poison effect will end duration seconds after the new attack. + +You are given a non-decreasing integer array timeSeries, where timeSeries[i] denotes that Teemo attacks Ashe at second timeSeries[i], and an integer duration. + +Return the total number of seconds that Ashe is poisoned. + +**Example 1**: +``` +Input: timeSeries = [1,4], duration = 2 +Output: 4 +Explanation: Teemo's attacks on Ashe go as follows: +- At second 1, Teemo attacks, and Ashe is poisoned for seconds 1 and 2. +- At second 4, Teemo attacks, and Ashe is poisoned for seconds 4 and 5. +Ashe is poisoned for seconds 1, 2, 4, and 5, which is 4 seconds in total. +``` + +**Example 2**: +``` +Input: timeSeries = [1,2], duration = 2 +Output: 3 +Explanation: Teemo's attacks on Ashe go as follows: +- At second 1, Teemo attacks, and Ashe is poisoned for seconds 1 and 2. +- At second 2 however, Teemo attacks again and resets the poison timer. Ashe is poisoned for seconds 2 and 3. +Ashe is poisoned for seconds 1, 2, and 3, which is 3 seconds in total. +``` + +**Constraints**: + +- 1 <= timeSeries.length <= 10000 +- 0 <= timeSeries[i], duration <= 10000000 +- timeSeries is sorted in non-decreasing order. + +## 题目大意 + +在《英雄联盟》的世界中，有一个叫 “提莫” 的英雄。他的攻击可以让敌方英雄艾希（编者注：寒冰射手）进入中毒状态。 + +当提莫攻击艾希，艾希的中毒状态正好持续duration 秒。 + +正式地讲，提莫在t发起发起攻击意味着艾希在时间区间 [t, t + duration - 1]（含 t 和 t + duration - 1）处于中毒状态。 + +如果提莫在中毒影响结束前再次攻击，中毒状态计时器将会重置，在新的攻击之后，中毒影响将会在duration秒后结束。 + +给你一个非递减的整数数组timeSeries，其中timeSeries[i]表示提莫在timeSeries[i]秒时对艾希发起攻击，以及一个表示中毒持续时间的整数duration 。 + +返回艾希处于中毒状态的总秒数。 + +## 解题思路 + +- i 从 1 开始计数，令 t 等于 timeSeries[i - 1] +- 比较 end(t + duration - 1) 和 timeSeries[i] 的大小， + - 如果 end 小于 timeSeries[i],ans+=duration + - 否则 ans += timeSeries[i] - t +- ans += duration 并返回 ans + +## 代码 + +```go + +package leetcode + +func findPoisonedDuration(timeSeries []int, duration int) int { + var ans int + for i := 1; i < len(timeSeries); i++ { + t := timeSeries[i-1] + end := t + duration - 1 + if end < timeSeries[i] { + ans += duration + } else { + ans += timeSeries[i] - t + } + } + ans += duration + return ans +} + +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0400~0499/0496.Next-Greater-Element-I.md b/website/content/ChapterFour/0400~0499/0496.Next-Greater-Element-I.md index 59678c7d2..1075380ba 100644 --- a/website/content/ChapterFour/0400~0499/0496.Next-Greater-Element-I.md +++ b/website/content/ChapterFour/0400~0499/0496.Next-Greater-Element-I.md @@ -82,6 +82,6 @@ func nextGreaterElement(nums1 []int, nums2 []int) []int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0400~0499/0498.Diagonal-Traverse.md b/website/content/ChapterFour/0400~0499/0498.Diagonal-Traverse.md index 674ddc2cf..454f91cfe 100755 --- a/website/content/ChapterFour/0400~0499/0498.Diagonal-Traverse.md +++ b/website/content/ChapterFour/0400~0499/0498.Diagonal-Traverse.md @@ -37,6 +37,13 @@ The total number of elements of the given matrix will not exceed 10,000. - 给出一个二维数组，要求按照如图的方式遍历整个数组。 - 这一题用模拟的方式就可以解出来。需要注意的是边界条件：比如二维数组为空，二维数组退化为一行或者一列，退化为一个元素。具体例子见测试用例。 +- 解题关键是在判断下一个位置，将矩阵想像成一个X,Y坐标轴。那么可分为以下几种情况， + 1、斜角向右上遍历时， + 当右上角在坐标轴内， 正常计算 即， x+1(X轴向右移动)， y-1(Y轴向上移动) + 当右上角在坐标轴外，那么当前位置只能在 第一行X坐标轴 ，或者 最后一列Y坐标轴 ， 即判断该两种情况下�应该X坐标往右，或者 Y坐标往上 + 2、同理 斜角向下遍历时 + 当左下角在坐标轴内，正常计算 即， x-1(X轴向右移动)， y+1(Y轴向下移动) + 当左下角在坐标轴外，那么当前位置只能在 第一列Y坐标轴，或者 最后一行X坐标轴， 即判断该两种情况下�应该X坐标往左，或者 Y坐标往下 ## 代码 diff --git a/website/content/ChapterFour/0500~0599/0503.Next-Greater-Element-II.md b/website/content/ChapterFour/0500~0599/0503.Next-Greater-Element-II.md index 2974c302d..69675aa8d 100644 --- a/website/content/ChapterFour/0500~0599/0503.Next-Greater-Element-II.md +++ b/website/content/ChapterFour/0500~0599/0503.Next-Greater-Element-II.md @@ -81,5 +81,5 @@ func nextGreaterElements1(nums []int) []int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0500~0599/0504.Base-7.md b/website/content/ChapterFour/0500~0599/0504.Base-7.md new file mode 100644 index 000000000..30b82e50e --- /dev/null +++ b/website/content/ChapterFour/0500~0599/0504.Base-7.md @@ -0,0 +1,67 @@ +# [504. Base 7](https://leetcode.com/problems/base-7/) + +## 题目 + +Given an integer num, return a string of its base 7 representation. + +**Example 1:** + + Input: num = 100 + Output: "202" + +**Example 2:** + + Input: num = -7 + Output: "-10" + +**Constraints:** + +- -10000000 <= num <= 10000000 + +## 题目大意 + +给定一个整数 num，将其转化为 7 进制，并以字符串形式输出。 + +## 解题思路 + + num反复除以7，然后倒排余数 + +# 代码 + +```go +package leetcode + +import "strconv" + +func convertToBase7(num int) string { + if num == 0 { + return "0" + } + negative := false + if num < 0 { + negative = true + num = -num + } + var ans string + var nums []int + for num != 0 { + remainder := num % 7 + nums = append(nums, remainder) + num = num / 7 + } + if negative { + ans += "-" + } + for i := len(nums) - 1; i >= 0; i-- { + ans += strconv.Itoa(nums[i]) + } + return ans +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0500~0599/0506.Relative-Ranks.md b/website/content/ChapterFour/0500~0599/0506.Relative-Ranks.md new file mode 100644 index 000000000..0e1522f5f --- /dev/null +++ b/website/content/ChapterFour/0500~0599/0506.Relative-Ranks.md @@ -0,0 +1,91 @@ +# [506. Relative Ranks](https://leetcode.com/problems/relative-ranks/) + +## 题目 + +You are given an integer array score of size n, where score[i] is the score of the ith athlete in a competition. All the scores are guaranteed to be unique. + +The athletes are placed based on their scores, where the 1st place athlete has the highest score, the 2nd place athlete has the 2nd highest score, and so on. The placement of each athlete determines their rank: + +- The 1st place athlete's rank is "Gold Medal". +- The 2nd place athlete's rank is "Silver Medal". +- The 3rd place athlete's rank is "Bronze Medal". +- For the 4th place to the nth place athlete, their rank is their placement number (i.e., the xth place athlete's rank is "x"). + +Return an array answer of size n where answer[i] is the rank of the ith athlete. + +**Example 1**: + + Input: score = [5,4,3,2,1] + Output: ["Gold Medal","Silver Medal","Bronze Medal","4","5"] + Explanation: The placements are [1st, 2nd, 3rd, 4th, 5th]. + +**Example 2**: + + Input: score = [10,3,8,9,4] + Output: ["Gold Medal","5","Bronze Medal","Silver Medal","4"] + Explanation: The placements are [1st, 5th, 3rd, 2nd, 4th]. + +**Constraints:** + +- n == score.length +- 1 <= n <= 10000 +- 0 <= score[i] <= 1000000 +- All the values in score are unique. + +## 题目大意 + +给你一个长度为 n 的整数数组 score ，其中 score[i] 是第 i 位运动员在比赛中的得分。所有得分都 互不相同 。 + +运动员将根据得分 决定名次 ，其中名次第 1 的运动员得分最高，名次第 2 的运动员得分第 2 高，依此类推。运动员的名次决定了他们的获奖情况： + +- 名次第 1 的运动员获金牌 "Gold Medal" 。 +- 名次第 2 的运动员获银牌 "Silver Medal" 。 +- 名次第 3 的运动员获铜牌 "Bronze Medal" 。 +- 从名次第 4 到第 n 的运动员，只能获得他们的名次编号（即，名次第 x 的运动员获得编号 "x"）。 + +使用长度为 n 的数组 answer 返回获奖，其中 answer[i] 是第 i 位运动员的获奖情况。 + +## 解题思路 + +- 用 map 记录原来 score 中元素对应的坐标，然后对 score 进行排序，对排序后的元素我们通过 map 就可以知道它排的名次了 + +## 代码 + +```go +package leetcode + +import ( + "sort" + "strconv" +) + +func findRelativeRanks(score []int) []string { + mp := make(map[int]int) + for i, v := range score { + mp[v] = i + } + sort.Slice(score, func(i, j int) bool { + return score[i] > score[j] + }) + ans := make([]string, len(score)) + for i, v := range score { + if i == 0 { + ans[mp[v]] = "Gold Medal" + } else if i == 1 { + ans[mp[v]] = "Silver Medal" + } else if i == 2 { + ans[mp[v]] = "Bronze Medal" + } else { + ans[mp[v]] = strconv.Itoa(i + 1) + } + } + return ans +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0500~0599/0507.Perfect-Number.md b/website/content/ChapterFour/0500~0599/0507.Perfect-Number.md index fe2293ae5..d48f8bd18 100644 --- a/website/content/ChapterFour/0500~0599/0507.Perfect-Number.md +++ b/website/content/ChapterFour/0500~0599/0507.Perfect-Number.md @@ -66,6 +66,6 @@ func checkPerfectNumber_(num int) bool { ---------------------------------------------- diff --git a/website/content/ChapterFour/0500~0599/0515.Find-Largest-Value-in-Each-Tree-Row.md b/website/content/ChapterFour/0500~0599/0515.Find-Largest-Value-in-Each-Tree-Row.md index 406372790..063e06f5e 100755 --- a/website/content/ChapterFour/0500~0599/0515.Find-Largest-Value-in-Each-Tree-Row.md +++ b/website/content/ChapterFour/0500~0599/0515.Find-Largest-Value-in-Each-Tree-Row.md @@ -90,11 +90,33 @@ func largestValues1(root *TreeNode) []int { return res } +// 解法三 深度遍历二叉树 +func largestValues3(root *TreeNode) []int { + var res []int + var dfs func(root *TreeNode, level int) + dfs = func(root *TreeNode, level int) { + if root == nil { + return + } + if len(res) == level { + res = append(res, root.Val) + } + if res[level] < root.Val { + res[level] = root.Val + } + + dfs(root.Right, level+1) + dfs(root.Left, level+1) + } + dfs(root, 0) + return res +} + ``` ---------------------------------------------- diff --git a/website/content/ChapterFour/0500~0599/0518.Coin-Change-II.md b/website/content/ChapterFour/0500~0599/0518.Coin-Change-II.md new file mode 100644 index 000000000..5fc89a1cd --- /dev/null +++ b/website/content/ChapterFour/0500~0599/0518.Coin-Change-II.md @@ -0,0 +1,80 @@ +# [518. Coin Change II](https://leetcode.com/problems/coin-change-ii/) + + +## 题目 + +You are given an integer array `coins` representing coins of different denominations and an integer `amount` representing a total amount of money. + +Return *the number of combinations that make up that amount*. If that amount of money cannot be made up by any combination of the coins, return `0`. + +You may assume that you have an infinite number of each kind of coin. + +The answer is **guaranteed** to fit into a signed **32-bit** integer. + +**Example 1:** + +``` +Input: amount = 5, coins = [1,2,5] +Output: 4 +Explanation: there are four ways to make up the amount: +5=5 +5=2+2+1 +5=2+1+1+1 +5=1+1+1+1+1 +``` + +**Example 2:** + +``` +Input: amount = 3, coins = [2] +Output: 0 +Explanation: the amount of 3 cannot be made up just with coins of 2. +``` + +**Example 3:** + +``` +Input: amount = 10, coins = [10] +Output: 1 +``` + +**Constraints:** + +- `1 <= coins.length <= 300` +- `1 <= coins[i] <= 5000` +- All the values of `coins` are **unique**. +- `0 <= amount <= 5000` + +## 题目大意 + +给你一个整数数组 coins 表示不同面额的硬币，另给一个整数 amount 表示总金额。请你计算并返回可以凑成总金额的硬币组合数。如果任何硬币组合都无法凑出总金额，返回 0 。假设每一种面额的硬币有无限个。题目数据保证结果符合 32 位带符号整数。 + +## 解题思路 + +- 此题虽然名字叫 Coin Change，但是不是经典的背包九讲问题。题目中 coins 的每个元素可以选取多次，且不考虑选取元素的顺序，因此这道题实际需要计算的是选取硬币的组合数。定义 dp[i] 表示金额之和等于 i 的硬币组合数，目标求 dp[amount]。初始边界条件为 dp[0] = 1，即不取任何硬币，就这一种取法，金额为 0 。状态转移方程 dp[i] += dp[i-coin]，coin 为当前枚举的 coin。 +- 可能有读者会有疑惑，上述做法会不会出现重复计算。答案是不会。外层循环是遍历数组 coins 的值，内层循环是遍历不同的金额之和，在计算 dp[i] 的值时，可以确保金额之和等于 i 的硬币面额的顺序，由于顺序确定，因此不会重复计算不同的排列。 +- 和此题完全一致的解题思路的题有，第 377 题和第 494 题。 + +## 代码 + +```go +package leetcode + +func change(amount int, coins []int) int { + dp := make([]int, amount+1) + dp[0] = 1 + for _, coin := range coins { + for i := coin; i <= amount; i++ { + dp[i] += dp[i-coin] + } + } + return dp[amount] +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0500~0599/0519.Random-Flip-Matrix.md b/website/content/ChapterFour/0500~0599/0519.Random-Flip-Matrix.md new file mode 100644 index 000000000..d72da22bb --- /dev/null +++ b/website/content/ChapterFour/0500~0599/0519.Random-Flip-Matrix.md @@ -0,0 +1,105 @@ +# [519. Random Flip Matrix](https://leetcode.com/problems/random-flip-matrix/) + +## 题目 + +There is an m x n binary grid matrix with all the values set 0 initially. Design an algorithm to randomly pick an index (i, j) where matrix[i][j] == 0 and flips it to 1. All the indices (i, j) where matrix[i][j] == 0 should be equally likely to be returned. + +Optimize your algorithm to minimize the number of calls made to the built-in random function of your language and optimize the time and space complexity. + +Implement the Solution class: + +- Solution(int m, int n) Initializes the object with the size of the binary matrix m and n. +- int[] flip() Returns a random index [i, j] of the matrix where matrix[i][j] == 0 and flips it to 1. +- void reset() Resets all the values of the matrix to be 0. + +**Example 1**: + + Input + ["Solution", "flip", "flip", "flip", "reset", "flip"] + [[3, 1], [], [], [], [], []] + Output + [null, [1, 0], [2, 0], [0, 0], null, [2, 0]] + + Explanation + Solution solution = new Solution(3, 1); + solution.flip(); // return [1, 0], [0,0], [1,0], and [2,0] should be equally likely to be returned. + solution.flip(); // return [2, 0], Since [1,0] was returned, [2,0] and [0,0] + solution.flip(); // return [0, 0], Based on the previously returned indices, only [0,0] can be returned. + solution.reset(); // All the values are reset to 0 and can be returned. + solution.flip(); // return [2, 0], [0,0], [1,0], and [2,0] should be equally likely to be returned. + +**Constraints:** + +- 1 <= m, n <= 10000 +- There will be at least one free cell for each call to flip. +- At most 1000 calls will be made to flip and reset. + +## 题目大意 + +给你一个 m x n 的二元矩阵 matrix ，且所有值被初始化为 0 。请你设计一个算法，随机选取一个满足 matrix[i][j] == 0 的下标 (i, j) ，并将它的值变为 1 。所有满足 matrix[i][j] == 0 的下标 (i, j) 被选取的概率应当均等。 + +尽量最少调用内置的随机函数，并且优化时间和空间复杂度。 + +实现 Solution 类： + +- Solution(int m, int n) 使用二元矩阵的大小 m 和 n 初始化该对象 +- int[] flip() 返回一个满足 matrix[i][j] == 0 的随机下标 [i, j] ，并将其对应格子中的值变为 1 +- void reset() 将矩阵中所有的值重置为 0 + +## 解题思路 + +- 二维矩阵利用哈希表转换为一维,每次随机选择一维中的任意一个元素，然后与最后一个元素交换，一维元素的总个数减一 +- 哈希表中默认的映射为x->x, 然后将不满足这个映射的特殊键值对存入哈希表 + +## 代码 + +```go +package leetcode + +import "math/rand" + +type Solution struct { + r int + c int + total int + mp map[int]int +} + +func Constructor(m int, n int) Solution { + return Solution{ + r: m, + c: n, + total: m * n, + mp: map[int]int{}, + } +} + +func (this *Solution) Flip() []int { + k := rand.Intn(this.total) + val := k + if v, ok := this.mp[k]; ok { + val = v + } + if _, ok := this.mp[this.total-1]; ok { + this.mp[k] = this.mp[this.total-1] + } else { + this.mp[k] = this.total - 1 + } + delete(this.mp, this.total - 1) + this.total-- + newR, newC := val/this.c, val%this.c + return []int{newR, newC} +} + +func (this *Solution) Reset() { + this.total = this.r * this.c + this.mp = map[int]int{} +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0500~0599/0520.Detect-Capital.md b/website/content/ChapterFour/0500~0599/0520.Detect-Capital.md new file mode 100644 index 000000000..33791a2ec --- /dev/null +++ b/website/content/ChapterFour/0500~0599/0520.Detect-Capital.md @@ -0,0 +1,75 @@ +# [520. Detect Capital](https://leetcode.com/problems/detect-capital/) + + +## 题目 + +We define the usage of capitals in a word to be right when one of the following cases holds: + +All letters in this word are capitals, like "USA". + +All letters in this word are not capitals, like "leetcode". + +Only the first letter in this word is capital, like "Google". + +Given a string word, return true if the usage of capitals in it is right. + +**Example 1:** + +``` +Input: word = "USA" +Output: true +``` + +**Example 2:** + +``` +Input: word = "FlaG" +Output: false +``` + +**Constraints:** + +- 1 <= word.length <= 100 +- word consists of lowercase and uppercase English letters. + +## 题目大意 + +我们定义，在以下情况时，单词的大写用法是正确的： + +全部字母都是大写，比如 "USA" 。 +单词中所有字母都不是大写，比如 "leetcode" 。 +如果单词不只含有一个字母，只有首字母大写，比如"Google" 。 + +给你一个字符串 word 。如果大写用法正确，返回 true ；否则，返回 false 。 + +## 解题思路 + +- 把 word 分别转换为全部小写 wLower，全部大写 wUpper，首字母大写的字符串 wCaptial +- 判断 word 是否等于 wLower, wUpper, wCaptial 中的一个，如果是返回 true，否则返回 false + +## 代码 + +```go + +package leetcode + +import "strings" + +func detectCapitalUse(word string) bool { + wLower := strings.ToLower(word) + wUpper := strings.ToUpper(word) + wCaptial := strings.ToUpper(string(word[0])) + strings.ToLower(string(word[1:])) + if wCaptial == word || wLower == word || wUpper == word { + return true + } + return false +} + +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0500~0599/0523.Continuous-Subarray-Sum.md b/website/content/ChapterFour/0500~0599/0523.Continuous-Subarray-Sum.md new file mode 100644 index 000000000..671295e2a --- /dev/null +++ b/website/content/ChapterFour/0500~0599/0523.Continuous-Subarray-Sum.md @@ -0,0 +1,82 @@ +# [523. Continuous Subarray Sum](https://leetcode.com/problems/continuous-subarray-sum/) + + +## 题目 + +Given an integer array `nums` and an integer `k`, return `true` *if* `nums` *has a continuous subarray of size **at least two** whose elements sum up to a multiple of* `k`*, or* `false` *otherwise*. + +An integer `x` is a multiple of `k` if there exists an integer `n` such that `x = n * k`. `0` is **always** a multiple of `k`. + +**Example 1:** + +``` +Input: nums = [23,2,4,6,7], k = 6 +Output: true +Explanation: [2, 4] is a continuous subarray of size 2 whose elements sum up to 6. +``` + +**Example 2:** + +``` +Input: nums = [23,2,6,4,7], k = 6 +Output: true +Explanation: [23, 2, 6, 4, 7] is an continuous subarray of size 5 whose elements sum up to 42. +42 is a multiple of 6 because 42 = 7 * 6 and 7 is an integer. +``` + +**Example 3:** + +``` +Input: nums = [23,2,6,4,7], k = 13 +Output: false +``` + +**Constraints:** + +- `1 <= nums.length <= 105` +- `0 <= nums[i] <= 109` +- `0 <= sum(nums[i]) <= 231 - 1` +- `1 <= k <= 231 - 1` + +## 题目大意 + +给你一个整数数组 nums 和一个整数 k ，编写一个函数来判断该数组是否含有同时满足下述条件的连续子数组： + +- 子数组大小至少为 2 ，且 +- 子数组元素总和为 k 的倍数。 + +如果存在，返回 true ；否则，返回 false 。如果存在一个整数 n ，令整数 x 符合 x = n * k ，则称 x 是 k 的一个倍数。 + +## 解题思路 + +- 简单题。题目只要求是否存在，不要求找出所有解。用一个变量 sum 记录累加和。子数组的元素和可以用前缀和相减得到，例如 [i,j] 区间内的元素和，可以由 prefixSum[j] - prefixSum[i] 得到。当 prefixSums[j]−prefixSums[i] 为 k 的倍数时，prefixSums[i] 和 prefixSums[j] 除以 k 的余数相同。因此只需要计算每个下标对应的前缀和除以 k 的余数即可，使用 map 存储每个余数第一次出现的下标即可。在 map 中如果存在相同余数的 key，代表当前下标和 map 中这个 key 记录的下标可以满足总和为 k 的倍数这一条件。再判断一下能否满足大小至少为 2 的条件即可。用 2 个下标相减，长度大于等于 2 即满足条件，可以输出 true。 + +## 代码 + +```go +package leetcode + +func checkSubarraySum(nums []int, k int) bool { + m := make(map[int]int) + m[0] = -1 + sum := 0 + for i, n := range nums { + sum += n + if r, ok := m[sum%k]; ok { + if i-2 >= r { + return true + } + } else { + m[sum%k] = i + } + } + return false +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0500~0599/0524.Longest-Word-in-Dictionary-through-Deleting.md b/website/content/ChapterFour/0500~0599/0524.Longest-Word-in-Dictionary-through-Deleting.md index 1bd98aec7..51d40043e 100644 --- a/website/content/ChapterFour/0500~0599/0524.Longest-Word-in-Dictionary-through-Deleting.md +++ b/website/content/ChapterFour/0500~0599/0524.Longest-Word-in-Dictionary-through-Deleting.md @@ -78,6 +78,6 @@ func findLongestWord(s string, d []string) string { ---------------------------------------------- diff --git a/website/content/ChapterFour/0500~0599/0525.Contiguous-Array.md b/website/content/ChapterFour/0500~0599/0525.Contiguous-Array.md new file mode 100644 index 000000000..412f71fad --- /dev/null +++ b/website/content/ChapterFour/0500~0599/0525.Contiguous-Array.md @@ -0,0 +1,74 @@ +# [525. Contiguous Array](https://leetcode.com/problems/contiguous-array/) + + +## 题目 + +Given a binary array `nums`, return *the maximum length of a contiguous subarray with an equal number of* `0` *and* `1`. + +**Example 1:** + +``` +Input: nums = [0,1] +Output: 2 +Explanation: [0, 1] is the longest contiguous subarray with an equal number of 0 and 1. +``` + +**Example 2:** + +``` +Input: nums = [0,1,0] +Output: 2 +Explanation: [0, 1] (or [1, 0]) is a longest contiguous subarray with equal number of 0 and 1. +``` + +**Constraints:** + +- `1 <= nums.length <= 105` +- `nums[i]` is either `0` or `1`. + +## 题目大意 + +给定一个二进制数组 nums , 找到含有相同数量的 0 和 1 的最长连续子数组，并返回该子数组的长度。 + +## 解题思路 + +- 0 和 1 的数量相同可以转化为两者数量相差为 0，如果将 0 看作为 -1，那么原题转化为求最长连续子数组，其元素和为 0 。又变成了区间内求和的问题，自然而然转换为前缀和来处理。假设连续子数组是 [i,j] 区间，这个区间内元素和为 0 意味着 prefixSum[j] - prefixSum[i] = 0，也就是 prefixSum[i] = prefixSum[j]。不断累加前缀和，将每个前缀和存入 map 中。一旦某个 key 存在了，代表之前某个下标的前缀和和当前下标构成的区间，这段区间内的元素和为 0 。这个区间是所求。扫完整个数组，扫描过程中动态更新最大区间长度，扫描完成便可得到最大区间长度，即最长连续子数组。 + +## 代码 + +```go +package leetcode + +func findMaxLength(nums []int) int { + dict := map[int]int{} + dict[0] = -1 + count, res := 0, 0 + for i := 0; i < len(nums); i++ { + if nums[i] == 0 { + count-- + } else { + count++ + } + if idx, ok := dict[count]; ok { + res = max(res, i-idx) + } else { + dict[count] = i + } + } + return res +} + +func max(a, b int) int { + if a > b { + return a + } + return b +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0500~0599/0526.Beautiful-Arrangement.md b/website/content/ChapterFour/0500~0599/0526.Beautiful-Arrangement.md index 4c91731a8..f3188ead0 100755 --- a/website/content/ChapterFour/0500~0599/0526.Beautiful-Arrangement.md +++ b/website/content/ChapterFour/0500~0599/0526.Beautiful-Arrangement.md @@ -112,6 +112,6 @@ func checkDivisible(num, d int) bool { ---------------------------------------------- diff --git a/website/content/ChapterFour/0500~0599/0529.Minesweeper.md b/website/content/ChapterFour/0500~0599/0529.Minesweeper.md index 1593ad8b4..88540208a 100644 --- a/website/content/ChapterFour/0500~0599/0529.Minesweeper.md +++ b/website/content/ChapterFour/0500~0599/0529.Minesweeper.md @@ -103,45 +103,35 @@ func updateBoard(board [][]byte, click []int) [][]byte { board[click[0]][click[1]] = 'X' return board } - mineMap := make([][]int, len(board)) - for i := range board { - mineMap[i] = make([]int, len(board[i])) - } - for i := range board { - for j := range board[i] { - if board[i][j] == 'M' { - mineMap[i][j] = -1 - for _, d := range dir8 { - nx, ny := i+d[0], j+d[1] - if isInBoard(board, nx, ny) && mineMap[nx][ny] >= 0 { - mineMap[nx][ny]++ - } - } - } - } - } - mineSweeper(click[0], click[1], board, mineMap, dir8) + dfs(board, click[0], click[1]) return board } -func mineSweeper(x, y int, board [][]byte, mineMap [][]int, dir8 [][]int) { - if board[x][y] != 'M' && board[x][y] != 'E' { +func dfs(board [][]byte, x, y int) { + cnt := 0 + for i := 0; i < 8; i++ { + nx, ny := x+dir8[i][0], y+dir8[i][1] + if isInBoard(board, nx, ny) && board[nx][ny] == 'M' { + cnt++ + + } + } + if cnt > 0 { + board[x][y] = byte(cnt + '0') return } - if mineMap[x][y] == -1 { - board[x][y] = 'X' - } else if mineMap[x][y] > 0 { - board[x][y] = '0' + byte(mineMap[x][y]) - } else { - board[x][y] = 'B' - for _, d := range dir8 { - nx, ny := x+d[0], y+d[1] - if isInBoard(board, nx, ny) && mineMap[nx][ny] >= 0 { - mineSweeper(nx, ny, board, mineMap, dir8) - } + board[x][y] = 'B' + for i := 0; i < 8; i++ { + nx, ny := x+dir8[i][0], y+dir8[i][1] + if isInBoard(board, nx, ny) && board[nx][ny] != 'B' { + dfs(board, nx, ny) } } } + +func isInBoard(board [][]byte, x, y int) bool { + return x >= 0 && x < len(board) && y >= 0 && y < len(board[0]) +} ``` diff --git a/website/content/ChapterFour/0500~0599/0530.Minimum-Absolute-Difference-in-BST.md b/website/content/ChapterFour/0500~0599/0530.Minimum-Absolute-Difference-in-BST.md index 45eecdd00..5dcd943f9 100644 --- a/website/content/ChapterFour/0500~0599/0530.Minimum-Absolute-Difference-in-BST.md +++ b/website/content/ChapterFour/0500~0599/0530.Minimum-Absolute-Difference-in-BST.md @@ -45,7 +45,7 @@ package leetcode import ( "math" - "github.com/halfrost/LeetCode-Go/structures" + "github.com/halfrost/leetcode-go/structures" ) // TreeNode define diff --git a/website/content/ChapterFour/0500~0599/0538.Convert-BST-to-Greater-Tree.md b/website/content/ChapterFour/0500~0599/0538.Convert-BST-to-Greater-Tree.md index b90804b18..c69654019 100644 --- a/website/content/ChapterFour/0500~0599/0538.Convert-BST-to-Greater-Tree.md +++ b/website/content/ChapterFour/0500~0599/0538.Convert-BST-to-Greater-Tree.md @@ -70,7 +70,7 @@ Output: [7,9,4,10] package leetcode import ( - "github.com/halfrost/LeetCode-Go/structures" + "github.com/halfrost/leetcode-go/structures" ) // TreeNode define @@ -109,5 +109,5 @@ func dfs538(root *TreeNode, sum *int) { ---------------------------------------------- diff --git a/website/content/ChapterFour/0500~0599/0540.Single-Element-in-a-Sorted-Array.md b/website/content/ChapterFour/0500~0599/0540.Single-Element-in-a-Sorted-Array.md new file mode 100644 index 000000000..b092e6466 --- /dev/null +++ b/website/content/ChapterFour/0500~0599/0540.Single-Element-in-a-Sorted-Array.md @@ -0,0 +1,71 @@ +# [540. Single Element in a Sorted Array](https://leetcode.com/problems/single-element-in-a-sorted-array/) + +## 题目 + +You are given a sorted array consisting of only integers where every element appears exactly twice, except for one element which appears exactly once. + +Return the single element that appears only once. + +Your solution must run in O(log n) time and O(1) space. + +**Example 1:** + + Input: nums = [1,1,2,3,3,4,4,8,8] + Output: 2 + +**Example 2:** + + Input: nums = [3,3,7,7,10,11,11] + Output: 10 + +**Constraints:** + +- 1 <= nums.length <= 100000 +- 0 <= nums[i] <= 100000 + +## 题目大意 + +给你一个仅由整数组成的有序数组，其中每个元素都会出现两次，唯有一个数只会出现一次。 + +请你找出并返回只出现一次的那个数。 + +你设计的解决方案必须满足 O(log n) 时间复杂度和 O(1) 空间复杂度。 + +## 解题思路 + + 假设下标idx是单独的数字,idx左边的偶数下标x有nums[x] == nums[x + 1], + idx右边的奇数下标y有nums[y] == nums[y + 1],可以根据此特性用二分查找idx对应的值 + +## 代码 + +```go +package leetcode + +func singleNonDuplicate(nums []int) int { + left, right := 0, len(nums)-1 + for left < right { + mid := (left + right) / 2 + if mid%2 == 0 { + if nums[mid] == nums[mid+1] { + left = mid + 1 + } else { + right = mid + } + } else { + if nums[mid] == nums[mid-1] { + left = mid + 1 + } else { + right = mid + } + } + } + return nums[left] +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0500~0599/0541.Reverse-String-II.md b/website/content/ChapterFour/0500~0599/0541.Reverse-String-II.md index 48133a06a..ad726de6d 100755 --- a/website/content/ChapterFour/0500~0599/0541.Reverse-String-II.md +++ b/website/content/ChapterFour/0500~0599/0541.Reverse-String-II.md @@ -53,11 +53,23 @@ func reverseStr(s string, k int) string { return s } +func revers(s string) string { + bytes := []byte(s) + i, j := 0, len(bytes)-1 + for i < j { + bytes[i], bytes[j] = bytes[j], bytes[i] + i++ + j-- + } + return string(bytes) +} + + ``` ---------------------------------------------- diff --git a/website/content/ChapterFour/0500~0599/0542.01-Matrix.md b/website/content/ChapterFour/0500~0599/0542.01-Matrix.md index 96e596296..09f41a810 100755 --- a/website/content/ChapterFour/0500~0599/0542.01-Matrix.md +++ b/website/content/ChapterFour/0500~0599/0542.01-Matrix.md @@ -205,5 +205,5 @@ func updateMatrixDP(matrix [][]int) [][]int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0500~0599/0543.Diameter-of-Binary-Tree.md b/website/content/ChapterFour/0500~0599/0543.Diameter-of-Binary-Tree.md new file mode 100644 index 000000000..ced821989 --- /dev/null +++ b/website/content/ChapterFour/0500~0599/0543.Diameter-of-Binary-Tree.md @@ -0,0 +1,94 @@ +# [543. Diameter of Binary Tree](https://leetcode.com/problems/diameter-of-binary-tree/) + + +## 题目 + +Given the `root` of a binary tree, return *the length of the **diameter** of the tree*. + +The **diameter** of a binary tree is the **length** of the longest path between any two nodes in a tree. This path may or may not pass through the `root`. + +The **length** of a path between two nodes is represented by the number of edges between them. + +**Example 1:** + +![https://assets.leetcode.com/uploads/2021/03/06/diamtree.jpg](https://assets.leetcode.com/uploads/2021/03/06/diamtree.jpg) + +``` +Input: root = [1,2,3,4,5] +Output: 3 +Explanation: 3 is the length of the path [4,2,1,3] or [5,2,1,3]. + +``` + +**Example 2:** + +``` +Input: root = [1,2] +Output: 1 + +``` + +**Constraints:** + +- The number of nodes in the tree is in the range `[1, 104]`. +- `100 <= Node.val <= 100` + +## 题目大意 + +给定一棵二叉树，你需要计算它的直径长度。一棵二叉树的直径长度是任意两个结点路径长度中的最大值。这条路径可能穿过也可能不穿过根结点。 + +## 解题思路 + +- 简单题。遍历每个节点的左子树和右子树，累加从左子树到右子树的最大长度。遍历每个节点时，动态更新这个最大长度即可。 + +## 代码 + +```go +package leetcode + +import ( + "github.com/halfrost/leetcode-go/structures" +) + +// TreeNode define +type TreeNode = structures.TreeNode + +/** + * Definition for a binary tree node. + * type TreeNode struct { + * Val int + * Left *TreeNode + * Right *TreeNode + * } + */ + +func diameterOfBinaryTree(root *TreeNode) int { + result := 0 + checkDiameter(root, &result) + return result +} + +func checkDiameter(root *TreeNode, result *int) int { + if root == nil { + return 0 + } + left := checkDiameter(root.Left, result) + right := checkDiameter(root.Right, result) + *result = max(*result, left+right) + return max(left, right) + 1 +} + +func max(a int, b int) int { + if a > b { + return a + } + return b +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0500~0599/0547.Number-of-Provinces.md b/website/content/ChapterFour/0500~0599/0547.Number-of-Provinces.md index 1515667ca..60011312f 100755 --- a/website/content/ChapterFour/0500~0599/0547.Number-of-Provinces.md +++ b/website/content/ChapterFour/0500~0599/0547.Number-of-Provinces.md @@ -61,7 +61,7 @@ Given a **N*N** matrix **M** representing the friend relationship between st package leetcode import ( - "github.com/halfrost/LeetCode-Go/template" + "github.com/halfrost/leetcode-go/template" ) // 解法一 并查集 @@ -113,6 +113,6 @@ func dfs547(M [][]int, cur int, visited []bool) { ---------------------------------------------- diff --git a/website/content/ChapterFour/0500~0599/0551.Student-Attendance-Record-I.md b/website/content/ChapterFour/0500~0599/0551.Student-Attendance-Record-I.md new file mode 100644 index 000000000..6d5a09651 --- /dev/null +++ b/website/content/ChapterFour/0500~0599/0551.Student-Attendance-Record-I.md @@ -0,0 +1,93 @@ +# [551. Student Attendance Record I](https://leetcode.com/problems/student-attendance-record-i/) + +## 题目 + +You are given a string `s` representing an attendance record for a student where each character signifies whether the student was absent, late, or present on that day. The record only contains the following three characters: + +- `'A'`: Absent. +- `'L'`: Late. +- `'P'`: Present. + +The student is eligible for an attendance award if they meet **both** of the following criteria: + +- The student was absent (`'A'`) for **strictly** fewer than 2 days **total**. +- The student was **never** late (`'L'`) for 3 or more **consecutive** days. + +Return `true` *if the student is eligible for an attendance award, or* `false` *otherwise*. + +**Example 1:** + +``` +Input: s = "PPALLP" +Output: true +Explanation: The student has fewer than 2 absences and was never late 3 or more consecutive days. + +``` + +**Example 2:** + +``` +Input: s = "PPALLL" +Output: false +Explanation: The student was late 3 consecutive days in the last 3 days, so is not eligible for the award. + +``` + +**Constraints:** + +- `1 <= s.length <= 1000` +- `s[i]` is either `'A'`, `'L'`, or `'P'`. + +## 题目大意 + +给你一个字符串 s 表示一个学生的出勤记录，其中的每个字符用来标记当天的出勤情况（缺勤、迟到、到场）。记录中只含下面三种字符： + +- 'A'：Absent，缺勤 +- 'L'：Late，迟到 +- 'P'：Present，到场 + +如果学生能够 同时 满足下面两个条件，则可以获得出勤奖励： + +- 按 总出勤 计，学生缺勤（'A'）严格 少于两天。 +- 学生 不会 存在 连续 3 天或 连续 3 天以上的迟到（'L'）记录。 + +如果学生可以获得出勤奖励，返回 true ；否则，返回 false 。 + +## 解题思路 + +- 遍历字符串 s 求出 'A' 的总数量和连续 'L' 的最大数量。 +- 比较 'A' 的数量是否小于 2 并且 'L' 的连续最大数量是否小于 3。 + +## 代码 + +```go +package leetcode + +func checkRecord(s string) bool { + numsA, maxL, numsL := 0, 0, 0 + for _, v := range s { + if v == 'L' { + numsL++ + } else { + if numsL > maxL { + maxL = numsL + } + numsL = 0 + if v == 'A' { + numsA++ + } + } + } + if numsL > maxL { + maxL = numsL + } + return numsA < 2 && maxL < 3 +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0500~0599/0554.Brick-Wall.md b/website/content/ChapterFour/0500~0599/0554.Brick-Wall.md new file mode 100644 index 000000000..88f47f615 --- /dev/null +++ b/website/content/ChapterFour/0500~0599/0554.Brick-Wall.md @@ -0,0 +1,75 @@ +# [554. Brick Wall](https://leetcode.com/problems/brick-wall/) + +## 题目 + +There is a rectangular brick wall in front of you with `n` rows of bricks. The `ith` row has some number of bricks each of the same height (i.e., one unit) but they can be of different widths. The total width of each row is the same. + +Draw a vertical line from the top to the bottom and cross the least bricks. If your line goes through the edge of a brick, then the brick is not considered as crossed. You cannot draw a line just along one of the two vertical edges of the wall, in which case the line will obviously cross no bricks. + +Given the 2D array `wall` that contains the information about the wall, return *the minimum number of crossed bricks after drawing such a vertical line*. + +**Example 1:** + +![https://assets.leetcode.com/uploads/2021/04/24/cutwall-grid.jpg](https://assets.leetcode.com/uploads/2021/04/24/cutwall-grid.jpg) + +``` +Input: wall = [[1,2,2,1],[3,1,2],[1,3,2],[2,4],[3,1,2],[1,3,1,1]] +Output: 2 + +``` + +**Example 2:** + +``` +Input: wall = [[1],[1],[1]] +Output: 3 + +``` + +**Constraints:** + +- `n == wall.length` +- `1 <= n <= 10^4` +- `1 <= wall[i].length <= 10^4` +- `1 <= sum(wall[i].length) <= 2 * 10^4` +- `sum(wall[i])` is the same for each row `i`. +- `1 <= wall[i][j] <= 2^31 - 1` + +## 题目大意 + +你的面前有一堵矩形的、由 n 行砖块组成的砖墙。这些砖块高度相同（也就是一个单位高）但是宽度不同。每一行砖块的宽度之和应该相等。你现在要画一条 自顶向下 的、穿过 最少 砖块的垂线。如果你画的线只是从砖块的边缘经过，就不算穿过这块砖。你不能沿着墙的两个垂直边缘之一画线，这样显然是没有穿过一块砖的。给你一个二维数组 wall ，该数组包含这堵墙的相关信息。其中，wall[i] 是一个代表从左至右每块砖的宽度的数组。你需要找出怎样画才能使这条线 穿过的砖块数量最少 ，并且返回 穿过的砖块数量 。 + +## 解题思路 + +- 既然穿过砖块中缝不算穿过砖块，那么穿过最少砖块数量一定是穿过很多中缝。按行遍历每一行的砖块，累加每行砖块宽度，将每行砖块“缝”的坐标存在 map 中。最后取出 map 中出现频次最高的缝，即为铅垂线要穿过的地方。墙高减去缝出现的频次，剩下的即为穿过砖块的数量。 + +## 代码 + +```go +package leetcode + +func leastBricks(wall [][]int) int { + m := make(map[int]int) + for _, row := range wall { + sum := 0 + for i := 0; i < len(row)-1; i++ { + sum += row[i] + m[sum]++ + } + } + max := 0 + for _, v := range m { + if v > max { + max = v + } + } + return len(wall) - max +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0500~0599/0557.Reverse-Words-in-a-String-III.md b/website/content/ChapterFour/0500~0599/0557.Reverse-Words-in-a-String-III.md index d0ab404c2..0f277d761 100755 --- a/website/content/ChapterFour/0500~0599/0557.Reverse-Words-in-a-String-III.md +++ b/website/content/ChapterFour/0500~0599/0557.Reverse-Words-in-a-String-III.md @@ -59,6 +59,6 @@ func revers(s string) string { ---------------------------------------------- diff --git a/website/content/ChapterFour/0500~0599/0559.Maximum-Depth-of-N-ary-Tree.md b/website/content/ChapterFour/0500~0599/0559.Maximum-Depth-of-N-ary-Tree.md new file mode 100644 index 000000000..fec8b6e83 --- /dev/null +++ b/website/content/ChapterFour/0500~0599/0559.Maximum-Depth-of-N-ary-Tree.md @@ -0,0 +1,85 @@ +# [559. Maximum Depth of N-ary Tree](https://leetcode.com/problems/maximum-depth-of-n-ary-tree/) + +## 题目 + +Given a n-ary tree, find its maximum depth. + +The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node. + +Nary-Tree input serialization is represented in their level order traversal, each group of children is separated by the null value (See examples). + +**Example 1**: + +![https://assets.leetcode.com/uploads/2018/10/12/narytreeexample.png](https://assets.leetcode.com/uploads/2018/10/12/narytreeexample.png) + + Input: root = [1,null,3,2,4,null,5,6] + Output: 3 + +**Example 2**: + +![https://assets.leetcode.com/uploads/2019/11/08/sample_4_964.png](https://assets.leetcode.com/uploads/2019/11/08/sample_4_964.png) + + Input: root = [1,null,2,3,4,5,null,null,6,7,null,8,null,9,10,null,null,11,null,12,null,13,null,null,14] + Output: 5 + +**Constraints:** + +- The total number of nodes is in the range [0, 10000]. +- The depth of the n-ary tree is less than or equal to 1000. + +## 题目大意 + +给定一个 N 叉树，找到其最大深度。 + +最大深度是指从根节点到最远叶子节点的最长路径上的节点总数。 + +N 叉树输入按层序遍历序列化表示，每组子节点由空值分隔（请参见示例）。 + +## 解题思路 + +- 使用广度优先遍历 + +## 代码 + +```go + +package leetcode + +type Node struct { + Val int + Children []*Node +} + +func maxDepth(root *Node) int { + if root == nil { + return 0 + } + return 1 + bfs(root) +} + +func bfs(root *Node) int { + var q []*Node + var depth int + q = append(q, root.Children...) + for len(q) != 0 { + depth++ + length := len(q) + for length != 0 { + ele := q[0] + q = q[1:] + length-- + if ele != nil && len(ele.Children) != 0 { + q = append(q, ele.Children...) + } + } + } + return depth +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0500~0599/0560.Subarray-Sum-Equals-K.md b/website/content/ChapterFour/0500~0599/0560.Subarray-Sum-Equals-K.md new file mode 100644 index 000000000..024667f09 --- /dev/null +++ b/website/content/ChapterFour/0500~0599/0560.Subarray-Sum-Equals-K.md @@ -0,0 +1,65 @@ +# [560. Subarray Sum Equals K](https://leetcode.com/problems/subarray-sum-equals-k/) + + +## 题目 + +Given an array of integers `nums` and an integer `k`, return *the total number of continuous subarrays whose sum equals to `k`*. + +**Example 1:** + +``` +Input: nums = [1,1,1], k = 2 +Output: 2 + +``` + +**Example 2:** + +``` +Input: nums = [1,2,3], k = 3 +Output: 2 + +``` + +**Constraints:** + +- `1 <= nums.length <= 2 * 104` +- `-1000 <= nums[i] <= 1000` +- `-10^7 <= k <= 10^7` + +## 题目大意 + +给你一个整数数组 `nums` 和一个整数 `k` ，请你统计并返回该数组中和为 `k` ****的连续子数组的个数。 + +## 解题思路 + +- 此题不能使用滑动窗口来解。因为 `nums[i]` 可能为负数。 +- 前缀和的思路可以解答此题，但是时间复杂度有点高了，`O(n^2)`。考虑优化时间复杂度。 +- 题目要求找到连续区间和为 `k` 的子区间总数，即区间 `[i,j]` 内的和为 K ⇒ `prefixSum[j] - prefixSum[i-1] == k`。所以 `prefixSum[j] == k - prefixSum[i-1]` 。这样转换以后，题目就转换成类似 A + B = K 的问题了。LeetCode 第一题的优化思路拿来用。用 map 存储累加过的结果。如此优化以后，时间复杂度 `O(n)`。 + +## 代码 + +```go +package leetcode + +func subarraySum(nums []int, k int) int { + count, pre := 0, 0 + m := map[int]int{} + m[0] = 1 + for i := 0; i < len(nums); i++ { + pre += nums[i] + if _, ok := m[pre-k]; ok { + count += m[pre-k] + } + m[pre] += 1 + } + return count +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0500~0599/0561.Array-Partition-I.md b/website/content/ChapterFour/0500~0599/0561.Array-Partition.md similarity index 95% rename from website/content/ChapterFour/0500~0599/0561.Array-Partition-I.md rename to website/content/ChapterFour/0500~0599/0561.Array-Partition.md index cb8dc31ea..04b71df09 100644 --- a/website/content/ChapterFour/0500~0599/0561.Array-Partition-I.md +++ b/website/content/ChapterFour/0500~0599/0561.Array-Partition.md @@ -1,4 +1,4 @@ -# [561. Array Partition I](https://leetcode.com/problems/array-partition-i/) +# [561. Array Partition](https://leetcode.com/problems/array-partition/) ## 题目 @@ -60,6 +60,6 @@ func arrayPairSum(nums []int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0500~0599/0563.Binary-Tree-Tilt.md b/website/content/ChapterFour/0500~0599/0563.Binary-Tree-Tilt.md index 83b5be1b5..dfe47b0de 100755 --- a/website/content/ChapterFour/0500~0599/0563.Binary-Tree-Tilt.md +++ b/website/content/ChapterFour/0500~0599/0563.Binary-Tree-Tilt.md @@ -85,6 +85,6 @@ func findTiltDFS(root *TreeNode, sum *int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0500~0599/0575.Distribute-Candies.md b/website/content/ChapterFour/0500~0599/0575.Distribute-Candies.md index 8702b393b..cdbf391ed 100755 --- a/website/content/ChapterFour/0500~0599/0575.Distribute-Candies.md +++ b/website/content/ChapterFour/0500~0599/0575.Distribute-Candies.md @@ -62,5 +62,5 @@ func distributeCandies(candies []int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0500~0599/0576.Out-of-Boundary-Paths.md b/website/content/ChapterFour/0500~0599/0576.Out-of-Boundary-Paths.md new file mode 100644 index 000000000..c58ba3fd3 --- /dev/null +++ b/website/content/ChapterFour/0500~0599/0576.Out-of-Boundary-Paths.md @@ -0,0 +1,96 @@ +# [576. Out of Boundary Paths](https://leetcode.com/problems/out-of-boundary-paths/) + + +## 题目 + +There is an `m x n` grid with a ball. The ball is initially at the position `[startRow, startColumn]`. You are allowed to move the ball to one of the four adjacent four cells in the grid (possibly out of the grid crossing the grid boundary). You can apply **at most** `maxMove` moves to the ball. + +Given the five integers `m`, `n`, `maxMove`, `startRow`, `startColumn`, return the number of paths to move the ball out of the grid boundary. Since the answer can be very large, return it **modulo** `109 + 7`. + +**Example 1:** + +![https://assets.leetcode.com/uploads/2021/04/28/out_of_boundary_paths_1.png](https://assets.leetcode.com/uploads/2021/04/28/out_of_boundary_paths_1.png) + +``` +Input: m = 2, n = 2, maxMove = 2, startRow = 0, startColumn = 0 +Output: 6 +``` + +**Example 2:** + +![https://assets.leetcode.com/uploads/2021/04/28/out_of_boundary_paths_2.png](https://assets.leetcode.com/uploads/2021/04/28/out_of_boundary_paths_2.png) + +``` +Input: m = 1, n = 3, maxMove = 3, startRow = 0, startColumn = 1 +Output: 12 +``` + +**Constraints:** + +- `1 <= m, n <= 50` +- `0 <= maxMove <= 50` +- `0 <= startRow <= m` +- `0 <= startColumn <= n` + +## 题目大意 + +给定一个 m × n 的网格和一个球。球的起始坐标为 (i,j) ，你可以将球移到相邻的单元格内，或者往上、下、左、右四个方向上移动使球穿过网格边界。但是，你最多可以移动 N 次。找出可以将球移出边界的路径数量。答案可能非常大，返回 结果 mod 109 + 7 的值。 + +## 解题思路 + +- 单纯暴力的思路，在球的每个方向都遍历一步，直到移动步数用完。这样暴力搜索，解空间是 4^n 。优化思路便是增加记忆化。用三维数组记录位置坐标和步数，对应的出边界的路径数量。加上记忆化以后的深搜解法 runtime beats 100% 了。 + +## 代码 + +```go +package leetcode + +var dir = [][]int{ + {-1, 0}, + {0, 1}, + {1, 0}, + {0, -1}, +} + +func findPaths(m int, n int, maxMove int, startRow int, startColumn int) int { + visited := make([][][]int, m) + for i := range visited { + visited[i] = make([][]int, n) + for j := range visited[i] { + visited[i][j] = make([]int, maxMove+1) + for l := range visited[i][j] { + visited[i][j][l] = -1 + } + } + } + return dfs(startRow, startColumn, maxMove, m, n, visited) +} + +func dfs(x, y, maxMove, m, n int, visited [][][]int) int { + if x < 0 || x >= m || y < 0 || y >= n { + return 1 + } + if maxMove == 0 { + visited[x][y][maxMove] = 0 + return 0 + } + if visited[x][y][maxMove] >= 0 { + return visited[x][y][maxMove] + } + res := 0 + for i := 0; i < 4; i++ { + nx := x + dir[i][0] + ny := y + dir[i][1] + res += (dfs(nx, ny, maxMove-1, m, n, visited) % 1000000007) + } + visited[x][y][maxMove] = res % 1000000007 + return visited[x][y][maxMove] +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0500~0599/0581.Shortest-Unsorted-Continuous-Subarray.md b/website/content/ChapterFour/0500~0599/0581.Shortest-Unsorted-Continuous-Subarray.md index 1dc5a8f6f..88bece34b 100644 --- a/website/content/ChapterFour/0500~0599/0581.Shortest-Unsorted-Continuous-Subarray.md +++ b/website/content/ChapterFour/0500~0599/0581.Shortest-Unsorted-Continuous-Subarray.md @@ -109,6 +109,6 @@ func min(a, b int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0500~0599/0583.Delete-Operation-for-Two-Strings.md b/website/content/ChapterFour/0500~0599/0583.Delete-Operation-for-Two-Strings.md new file mode 100644 index 000000000..98678815b --- /dev/null +++ b/website/content/ChapterFour/0500~0599/0583.Delete-Operation-for-Two-Strings.md @@ -0,0 +1,85 @@ +# [583. Delete Operation for Two Strings](https://leetcode.com/problems/delete-operation-for-two-strings/) + + +## 题目 + +Given two strings `word1` and `word2`, return *the minimum number of **steps** required to make* `word1` *and* `word2` *the same*. + +In one **step**, you can delete exactly one character in either string. + +**Example 1:** + +``` +Input: word1 = "sea", word2 = "eat" +Output: 2 +Explanation: You need one step to make "sea" to "ea" and another step to make "eat" to "ea". +``` + +**Example 2:** + +``` +Input: word1 = "leetcode", word2 = "etco" +Output: 4 +``` + +**Constraints:** + +- `1 <= word1.length, word2.length <= 500` +- `word1` and `word2` consist of only lowercase English letters. + +## 题目大意 + +给定两个单词 word1 和 word2，找到使得 word1 和 word2 相同所需的最小步数，每步可以删除任意一个字符串中的一个字符。 + +## 解题思路 + +- 从题目数据量级判断，此题一定是 O(n^2) 动态规划题。定义 `dp[i][j]` 表示 `word1[:i]` 与 `word2[:j]` 匹配所删除的最少步数。如果 `word1[:i-1]` 与 `word2[:j-1]` 匹配，那么 `dp[i][j] = dp[i-1][j-1]`。如果 `word1[:i-1]` 与 `word2[:j-1]` 不匹配，那么需要考虑删除一次，所以 `dp[i][j] = 1 + min(dp[i][j-1], dp[i-1][j])`。所以动态转移方程是： + + {{< katex display >}} + dp[i][j] = \left\{\begin{matrix}dp[i-1][j-1]&, word1[i-1] == word2[j-1]\\ 1 + min(dp[i][j-1], dp[i-1][j])&, word1[i-1] \neq word2[j-1]\\\end{matrix}\right. + {{< /katex >}} + + 最终答案存储在 `dp[len(word1)][len(word2)]` 中。 + +## 代码 + +```go +package leetcode + +func minDistance(word1 string, word2 string) int { + dp := make([][]int, len(word1)+1) + for i := 0; i < len(word1)+1; i++ { + dp[i] = make([]int, len(word2)+1) + } + for i := 0; i < len(word1)+1; i++ { + dp[i][0] = i + } + for i := 0; i < len(word2)+1; i++ { + dp[0][i] = i + } + for i := 1; i < len(word1)+1; i++ { + for j := 1; j < len(word2)+1; j++ { + if word1[i-1] == word2[j-1] { + dp[i][j] = dp[i-1][j-1] + } else { + dp[i][j] = 1 + min(dp[i][j-1], dp[i-1][j]) + } + } + } + return dp[len(word1)][len(word2)] +} + +func min(x, y int) int { + if x < y { + return x + } + return y +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0500~0599/0589.N-ary-Tree-Preorder-Traversal.md b/website/content/ChapterFour/0500~0599/0589.N-ary-Tree-Preorder-Traversal.md index 65c487f0e..0bef5c6a2 100644 --- a/website/content/ChapterFour/0500~0599/0589.N-ary-Tree-Preorder-Traversal.md +++ b/website/content/ChapterFour/0500~0599/0589.N-ary-Tree-Preorder-Traversal.md @@ -92,6 +92,6 @@ func preorderdfs(root *Node, res *[]int) { ---------------------------------------------- diff --git a/website/content/ChapterFour/0600~0699/0605.Can-Place-Flowers.md b/website/content/ChapterFour/0600~0699/0605.Can-Place-Flowers.md index c3a3123aa..fe4ee14a7 100644 --- a/website/content/ChapterFour/0600~0699/0605.Can-Place-Flowers.md +++ b/website/content/ChapterFour/0600~0699/0605.Can-Place-Flowers.md @@ -63,5 +63,5 @@ func canPlaceFlowers(flowerbed []int, n int) bool { ---------------------------------------------- diff --git a/website/content/ChapterFour/0600~0699/0609.Find-Duplicate-File-in-System.md b/website/content/ChapterFour/0600~0699/0609.Find-Duplicate-File-in-System.md new file mode 100644 index 000000000..0e7cc04ab --- /dev/null +++ b/website/content/ChapterFour/0600~0699/0609.Find-Duplicate-File-in-System.md @@ -0,0 +1,100 @@ +# [609. Find Duplicate File in System](https://leetcode.com/problems/find-duplicate-file-in-system/) + + +## 题目 + +Given a list `paths` of directory info, including the directory path, and all the files with contents in this directory, return *all the duplicate files in the file system in terms of their paths*. You may return the answer in **any order**. + +A group of duplicate files consists of at least two files that have the same content. + +A single directory info string in the input list has the following format: + +- `"root/d1/d2/.../dm f1.txt(f1_content) f2.txt(f2_content) ... fn.txt(fn_content)"` + +It means there are `n` files `(f1.txt, f2.txt ... fn.txt)` with content `(f1_content, f2_content ... fn_content)` respectively in the directory "`root/d1/d2/.../dm"`. Note that `n >= 1` and `m >= 0`. If `m = 0`, it means the directory is just the root directory. + +The output is a list of groups of duplicate file paths. For each group, it contains all the file paths of the files that have the same content. A file path is a string that has the following format: + +- `"directory_path/file_name.txt"` + +**Example 1:** + +``` +Input: paths = ["root/a 1.txt(abcd) 2.txt(efgh)","root/c 3.txt(abcd)","root/c/d 4.txt(efgh)","root 4.txt(efgh)"] +Output: [["root/a/2.txt","root/c/d/4.txt","root/4.txt"],["root/a/1.txt","root/c/3.txt"]] + +``` + +**Example 2:** + +``` +Input: paths = ["root/a 1.txt(abcd) 2.txt(efgh)","root/c 3.txt(abcd)","root/c/d 4.txt(efgh)"] +Output: [["root/a/2.txt","root/c/d/4.txt"],["root/a/1.txt","root/c/3.txt"]] + +``` + +**Constraints:** + +- `1 <= paths.length <= 2 * 104` +- `1 <= paths[i].length <= 3000` +- `1 <= sum(paths[i].length) <= 5 * 105` +- `paths[i]` consist of English letters, digits, `'/'`, `'.'`, `'('`, `')'`, and `' '`. +- You may assume no files or directories share the same name in the same directory. +- You may assume each given directory info represents a unique directory. A single blank space separates the directory path and file info. + +**Follow up:** + +- Imagine you are given a real file system, how will you search files? DFS or BFS? +- If the file content is very large (GB level), how will you modify your solution? +- If you can only read the file by 1kb each time, how will you modify your solution? +- What is the time complexity of your modified solution? What is the most time-consuming part and memory-consuming part of it? How to optimize? +- How to make sure the duplicated files you find are not false positive? + +## 题目大意 + +给定一个目录信息列表，包括目录路径，以及该目录中的所有包含内容的文件，您需要找到文件系统中的所有重复文件组的路径。一组重复的文件至少包括二个具有完全相同内容的文件。输入列表中的单个目录信息字符串的格式如下：`"root/d1/d2/.../dm f1.txt(f1_content) f2.txt(f2_content) ... fn.txt(fn_content)"`。这意味着有 n 个文件（`f1.txt, f2.txt ... fn.txt` 的内容分别是 `f1_content, f2_content ... fn_content`）在目录 `root/d1/d2/.../dm` 下。注意：n>=1 且 m>=0。如果 m=0，则表示该目录是根目录。该输出是重复文件路径组的列表。对于每个组，它包含具有相同内容的文件的所有文件路径。文件路径是具有下列格式的字符串：`"directory_path/file_name.txt"` + +## 解题思路 + +- 这一题算简单题，考察的是字符串基本操作与 map 的使用。首先通过字符串操作获取目录路径、文件名和文件内容。再使用 map 来寻找重复文件，key 是文件内容，value 是存储路径和文件名的列表。遍历每一个文件，并把它加入 map 中。最后遍历 map，如果一个键对应的值列表的长度大于 1，说明找到了重复文件，可以把这个列表加入到最终答案中。 +- 这道题有价值的地方在 **Follow up** 中。感兴趣的读者可以仔细想想以下几个问题： + 1. 假设您有一个真正的文件系统，您将如何搜索文件？广度搜索还是宽度搜索？ + 2. 如果文件内容非常大（GB级别），您将如何修改您的解决方案？ + 3. 如果每次只能读取 1 kb 的文件，您将如何修改解决方案？ + 4. 修改后的解决方案的时间复杂度是多少？其中最耗时的部分和消耗内存的部分是什么？如何优化？ + 5. 如何确保您发现的重复文件不是误报？ + +## 代码 + +```go +package leetcode + +import "strings" + +func findDuplicate(paths []string) [][]string { + cache := make(map[string][]string) + for _, path := range paths { + parts := strings.Split(path, " ") + dir := parts[0] + for i := 1; i < len(parts); i++ { + bracketPosition := strings.IndexByte(parts[i], '(') + content := parts[i][bracketPosition+1 : len(parts[i])-1] + cache[content] = append(cache[content], dir+"/"+parts[i][:bracketPosition]) + } + } + res := make([][]string, 0, len(cache)) + for _, group := range cache { + if len(group) >= 2 { + res = append(res, group) + } + } + return res +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0600~0699/0611.Valid-Triangle-Number.md b/website/content/ChapterFour/0600~0699/0611.Valid-Triangle-Number.md new file mode 100644 index 000000000..417b341fd --- /dev/null +++ b/website/content/ChapterFour/0600~0699/0611.Valid-Triangle-Number.md @@ -0,0 +1,44 @@ +# [611. Valid Triangle Number](https://leetcode.com/problems/valid-triangle-number/) + +## 题目 + +Given an integer array nums, return the number of triplets chosen from the array that can make triangles if we take them as side lengths of a triangle. + +## 题目大意 + +给定一个包含非负整数的数组，你的任务是统计其中可以组成三角形三条边的三元组个数。 + +## 解题思路 + +- 题意很简单，最容易想到的暴力解法是三重循环，暴力枚举，时间复杂度 O(n^3)。三重循环中最内层的循环可以优化，因为 k 和 i，j 存在关联性。第二层循环 j 从 i + 1 开始循环，k 从 j + 1 = i + 2 开始循环。循环累加 k 的值，直到 `nums[i] + nums[j] > nums[k]`，那么 `[nums[j + 1], nums[k - 1]]` 这个区间内的值都满足条件。满足条件的解个数增加 `k - j - 1` 个。j 再次递增 + 1，此时最内层的 k 不用从 j + 1 开始增加，只用从上次 k 开始增加即可。因为如果 `nums[i] + nums[j] > nums[k]`，如果这个 `nums[i] + nums[j + 1] > nums[m + 1]` 不等式成立，那么 m 一定不小于 k。所以内层循环 k 和 j 加起来的时间复杂度是 O(n)，最外层 i 的循环是 O(n)，这样优化以后，整体时间复杂度是 O(n^2)。 +- 可能有读者有疑问，三角形三条边的组成条件：任意两边之和大于第三边。`a + b > c`，`a + c > b`，`b + c > a`，此处为什么只判断了 `a + b > c` 呢？因为一开始进行了排序处理，使得 `a ≤ b ≤ c`，在这个前提下，`a + c > b`，`b + c > a` 是一定成立的。所以原问题便转化为只需关心 `a + b > c` 这一个不等式是否成立即可。此题的测试用例用有一种特殊情况，那就是其中一条边或者两条边长度为 0，那么 `a + b > c` 这个不等式一定不成立。综上，先排序预处理之后，只需要关心 `a + b > c` 这一个不等式是否成立即可。 + +## 代码 + +```go +package leetcode + +import "sort" + +func triangleNumber(nums []int) int { + res := 0 + sort.Ints(nums) + for i := 0; i < len(nums)-2; i++ { + k := i + 2 + for j := i + 1; j < len(nums)-1 && nums[i] != 0; j++ { + for k < len(nums) && nums[i]+nums[j] > nums[k] { + k++ + } + res += k - j - 1 + } + } + return res +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0600~0699/0617.Merge-Two-Binary-Trees.md b/website/content/ChapterFour/0600~0699/0617.Merge-Two-Binary-Trees.md new file mode 100644 index 000000000..8e535838c --- /dev/null +++ b/website/content/ChapterFour/0600~0699/0617.Merge-Two-Binary-Trees.md @@ -0,0 +1,87 @@ +# [617. Merge Two Binary Trees](https://leetcode.com/problems/merge-two-binary-trees/) + + +## 题目 + +You are given two binary trees `root1` and `root2`. + +Imagine that when you put one of them to cover the other, some nodes of the two trees are overlapped while the others are not. You need to merge the two trees into a new binary tree. The merge rule is that if two nodes overlap, then sum node values up as the new value of the merged node. Otherwise, the NOT null node will be used as the node of the new tree. + +Return *the merged tree*. + +**Note:** The merging process must start from the root nodes of both trees. + +**Example 1:** + +![https://assets.leetcode.com/uploads/2021/02/05/merge.jpg](https://assets.leetcode.com/uploads/2021/02/05/merge.jpg) + +``` +Input: root1 = [1,3,2,5], root2 = [2,1,3,null,4,null,7] +Output: [3,4,5,5,4,null,7] +``` + +**Example 2:** + +``` +Input: root1 = [1], root2 = [1,2] +Output: [2,2] +``` + +**Constraints:** + +- The number of nodes in both trees is in the range `[0, 2000]`. +- `104 <= Node.val <= 104` + +## 题目大意 + +给定两个二叉树，想象当你将它们中的一个覆盖到另一个上时，两个二叉树的一些节点便会重叠。你需要将他们合并为一个新的二叉树。合并的规则是如果两个节点重叠，那么将他们的值相加作为节点合并后的新值，否则不为 NULL 的节点将直接作为新二叉树的节点。 + +## 解题思路 + +- 简单题。采用深搜的思路，分别从根节点开始同时遍历两个二叉树，并将对应的节点进行合并。两个二叉树的对应节点可能存在以下三种情况： + - 如果两个二叉树的对应节点都为空，则合并后的二叉树的对应节点也为空； + - 如果两个二叉树的对应节点只有一个为空，则合并后的二叉树的对应节点为其中的非空节点； + - 如果两个二叉树的对应节点都不为空，则合并后的二叉树的对应节点的值为两个二叉树的对应节点的值之和，此时需要显性合并两个节点。 +- 对一个节点进行合并之后，还要对该节点的左右子树分别进行合并。用递归实现即可。 + +## 代码 + +```go +package leetcode + +import ( + "github.com/halfrost/leetcode-go/structures" +) + +// TreeNode define +type TreeNode = structures.TreeNode + +/** + * Definition for a binary tree node. + * type TreeNode struct { + * Val int + * Left *TreeNode + * Right *TreeNode + * } + */ + +func mergeTrees(root1 *TreeNode, root2 *TreeNode) *TreeNode { + if root1 == nil { + return root2 + } + if root2 == nil { + return root1 + } + root1.Val += root2.Val + root1.Left = mergeTrees(root1.Left, root2.Left) + root1.Right = mergeTrees(root1.Right, root2.Right) + return root1 +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0600~0699/0622.Design-Circular-Queue.md b/website/content/ChapterFour/0600~0699/0622.Design-Circular-Queue.md index f9fa7a79f..54dfe8f24 100644 --- a/website/content/ChapterFour/0600~0699/0622.Design-Circular-Queue.md +++ b/website/content/ChapterFour/0600~0699/0622.Design-Circular-Queue.md @@ -149,6 +149,6 @@ func (this *MyCircularQueue) IsFull() bool { ---------------------------------------------- diff --git a/website/content/ChapterFour/0600~0699/0623.Add-One-Row-to-Tree.md b/website/content/ChapterFour/0600~0699/0623.Add-One-Row-to-Tree.md index f99f04af1..356232ccb 100644 --- a/website/content/ChapterFour/0600~0699/0623.Add-One-Row-to-Tree.md +++ b/website/content/ChapterFour/0600~0699/0623.Add-One-Row-to-Tree.md @@ -68,7 +68,7 @@ v = 1d = 3Output: package leetcode import ( - "github.com/halfrost/LeetCode-Go/structures" + "github.com/halfrost/leetcode-go/structures" ) // TreeNode define diff --git a/website/content/ChapterFour/0600~0699/0628.Maximum-Product-of-Three-Numbers.md b/website/content/ChapterFour/0600~0699/0628.Maximum-Product-of-Three-Numbers.md index db97a3919..8eedbe1ea 100755 --- a/website/content/ChapterFour/0600~0699/0628.Maximum-Product-of-Three-Numbers.md +++ b/website/content/ChapterFour/0600~0699/0628.Maximum-Product-of-Three-Numbers.md @@ -106,5 +106,5 @@ func maximumProduct1(nums []int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0600~0699/0630.Course-Schedule-III.md b/website/content/ChapterFour/0600~0699/0630.Course-Schedule-III.md new file mode 100644 index 000000000..2179af424 --- /dev/null +++ b/website/content/ChapterFour/0600~0699/0630.Course-Schedule-III.md @@ -0,0 +1,103 @@ +# [630. Course Schedule III](https://leetcode.com/problems/course-schedule-iii/) + +## 题目 + +There are `n` different online courses numbered from `1` to `n`. You are given an array `courses` where `courses[i] = [durationi, lastDayi]` indicate that the `ith` course should be taken **continuously** for `durationi` days and must be finished before or on `lastDayi`. + +You will start on the `1st` day and you cannot take two or more courses simultaneously. + +Return *the maximum number of courses that you can take*. + +**Example 1:** + +``` +Input: courses = [[100,200],[200,1300],[1000,1250],[2000,3200]] +Output: 3 +Explanation: +There are totally 4 courses, but you can take 3 courses at most: +First, take the 1st course, it costs 100 days so you will finish it on the 100th day, and ready to take the next course on the 101st day. +Second, take the 3rd course, it costs 1000 days so you will finish it on the 1100th day, and ready to take the next course on the 1101st day. +Third, take the 2nd course, it costs 200 days so you will finish it on the 1300th day. +The 4th course cannot be taken now, since you will finish it on the 3300th day, which exceeds the closed date. + +``` + +**Example 2:** + +``` +Input: courses = [[1,2]] +Output: 1 + +``` + +**Example 3:** + +``` +Input: courses = [[3,2],[4,3]] +Output: 0 + +``` + +**Constraints:** + +- `1 <= courses.length <= 104` +- `1 <= durationi, lastDayi <= 104` + +## 题目大意 + +这里有 n 门不同的在线课程，他们按从 1 到 n 编号。每一门课程有一定的持续上课时间（课程时间）t 以及关闭时间第 d 天。一门课要持续学习 t 天直到第 d 天时要完成，你将会从第 1 天开始。给出 n 个在线课程用 (t, d) 对表示。你的任务是找出最多可以修几门课。 + +## 解题思路 + +- 一般选课，任务的题目会涉及排序 + 贪心。此题同样如此。最多修几门课，采用贪心的思路。先将课程结束时间从小到大排序，优先选择结束时间靠前的课程，这样留给后面课程的时间越多，便可以修更多的课。对排好序的课程从前往后选课，不断累积时间。如果选择修当前课程，但是会超时，这时改调整了。对于已经选择的课程，都加入到最大堆中，遇到需要调整时，比较当前待考虑的课程时长是否比(堆中)已经选择课中时长最长的课时长短，即堆顶的课程时长短，剔除 pop 它，再选择这门时长短的课，并加入最大堆中。并更新累积时间。一层循环扫完所有课程，最终最大堆中包含课程的数目便是最多可以修的课程数。 + +## 代码 + +```go +package leetcode + +import ( + "container/heap" + "sort" +) + +func scheduleCourse(courses [][]int) int { + sort.Slice(courses, func(i, j int) bool { + return courses[i][1] < courses[j][1] + }) + maxHeap, time := &Schedule{}, 0 + heap.Init(maxHeap) + for _, c := range courses { + if time+c[0] <= c[1] { + time += c[0] + heap.Push(maxHeap, c[0]) + } else if (*maxHeap).Len() > 0 && (*maxHeap)[0] > c[0] { + time -= heap.Pop(maxHeap).(int) - c[0] + heap.Push(maxHeap, c[0]) + } + } + return (*maxHeap).Len() +} + +type Schedule []int + +func (s Schedule) Len() int { return len(s) } +func (s Schedule) Less(i, j int) bool { return s[i] > s[j] } +func (s Schedule) Swap(i, j int) { s[i], s[j] = s[j], s[i] } +func (s *Schedule) Pop() interface{} { + n := len(*s) + t := (*s)[n-1] + *s = (*s)[:n-1] + return t +} +func (s *Schedule) Push(x interface{}) { + *s = append(*s, x.(int)) +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0600~0699/0632.Smallest-Range-Covering-Elements-from-K-Lists.md b/website/content/ChapterFour/0600~0699/0632.Smallest-Range-Covering-Elements-from-K-Lists.md index ec1310e4a..def61bb38 100755 --- a/website/content/ChapterFour/0600~0699/0632.Smallest-Range-Covering-Elements-from-K-Lists.md +++ b/website/content/ChapterFour/0600~0699/0632.Smallest-Range-Covering-Elements-from-K-Lists.md @@ -115,6 +115,6 @@ func (p SortByVal) Less(i, j int) bool { ---------------------------------------------- diff --git a/website/content/ChapterFour/0600~0699/0669.Trim-a-Binary-Search-Tree.md b/website/content/ChapterFour/0600~0699/0669.Trim-a-Binary-Search-Tree.md index d140542bc..12b162fbc 100644 --- a/website/content/ChapterFour/0600~0699/0669.Trim-a-Binary-Search-Tree.md +++ b/website/content/ChapterFour/0600~0699/0669.Trim-a-Binary-Search-Tree.md @@ -68,7 +68,7 @@ Output: [2] package leetcode import ( - "github.com/halfrost/LeetCode-Go/structures" + "github.com/halfrost/leetcode-go/structures" ) // TreeNode define diff --git a/website/content/ChapterFour/0600~0699/0676.Implement-Magic-Dictionary.md b/website/content/ChapterFour/0600~0699/0676.Implement-Magic-Dictionary.md index c0d96e1a9..74961388c 100755 --- a/website/content/ChapterFour/0600~0699/0676.Implement-Magic-Dictionary.md +++ b/website/content/ChapterFour/0600~0699/0676.Implement-Magic-Dictionary.md @@ -90,5 +90,5 @@ func (this *MagicDictionary) Search(word string) bool { ---------------------------------------------- diff --git a/website/content/ChapterFour/0600~0699/0677.Map-Sum-Pairs.md b/website/content/ChapterFour/0600~0699/0677.Map-Sum-Pairs.md new file mode 100644 index 000000000..2fa80a36b --- /dev/null +++ b/website/content/ChapterFour/0600~0699/0677.Map-Sum-Pairs.md @@ -0,0 +1,107 @@ +# [677. Map Sum Pairs](https://leetcode.com/problems/map-sum-pairs/) + + +## 题目 + +Design a map that allows you to do the following: + +- Maps a string key to a given value. +- Returns the sum of the values that have a key with a prefix equal to a given string. + +Implement the `MapSum` class: + +- `MapSum()` Initializes the `MapSum` object. +- `void insert(String key, int val)` Inserts the `key-val` pair into the map. If the `key` already existed, the original `key-value` pair will be overridden to the new one. +- `int sum(string prefix)` Returns the sum of all the pairs' value whose `key` starts with the `prefix`. + +**Example 1:** + +``` +Input +["MapSum", "insert", "sum", "insert", "sum"] +[[], ["apple", 3], ["ap"], ["app", 2], ["ap"]] +Output +[null, null, 3, null, 5] + +Explanation +MapSum mapSum = new MapSum(); +mapSum.insert("apple", 3); +mapSum.sum("ap"); // return 3 (apple = 3) +mapSum.insert("app", 2); +mapSum.sum("ap"); // return 5 (apple +app = 3 + 2 = 5) + +``` + +**Constraints:** + +- `1 <= key.length, prefix.length <= 50` +- `key` and `prefix` consist of only lowercase English letters. +- `1 <= val <= 1000` +- At most `50` calls will be made to `insert` and `sum`. + +## 题目大意 + +实现一个 MapSum 类，支持两个方法，insert 和 sum： + +- MapSum() 初始化 MapSum 对象 +- void insert(String key, int val) 插入 key-val 键值对，字符串表示键 key ，整数表示值 val 。如果键 key 已经存在，那么原来的键值对将被替代成新的键值对。 +- int sum(string prefix) 返回所有以该前缀 prefix 开头的键 key 的值的总和。 + +## 解题思路 + +- 简单题。用一个 map 存储数据，Insert() 方法即存储 key-value。Sum() 方法即累加满足条件前缀对应的 value。判断是否满足条件，先根据前缀长度来判断，只有长度大于等于 prefix 长度才可能满足要求。如果 key 是具有 prefix 前缀的，那么累加上这个值。最后输出总和即可。 + +## 代码 + +```go +package leetcode + +type MapSum struct { + keys map[string]int +} + +/** Initialize your data structure here. */ +func Constructor() MapSum { + return MapSum{make(map[string]int)} +} + +func (this *MapSum) Insert(key string, val int) { + this.keys[key] = val +} + +func (this *MapSum) Sum(prefix string) int { + prefixAsRunes, res := []rune(prefix), 0 + for key, val := range this.keys { + if len(key) >= len(prefix) { + shouldSum := true + for i, char := range key { + if i >= len(prefixAsRunes) { + break + } + if prefixAsRunes[i] != char { + shouldSum = false + break + } + } + if shouldSum { + res += val + } + } + } + return res +} + +/** + * Your MapSum object will be instantiated and called as such: + * obj := Constructor(); + * obj.Insert(key,val); + * param_2 := obj.Sum(prefix); + */ +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0600~0699/0682.Baseball-Game.md b/website/content/ChapterFour/0600~0699/0682.Baseball-Game.md index a85678d4e..17efc69b7 100644 --- a/website/content/ChapterFour/0600~0699/0682.Baseball-Game.md +++ b/website/content/ChapterFour/0600~0699/0682.Baseball-Game.md @@ -108,6 +108,6 @@ func calPoints(ops []string) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0600~0699/0684.Redundant-Connection.md b/website/content/ChapterFour/0600~0699/0684.Redundant-Connection.md index 6f48fee39..4fff04a31 100755 --- a/website/content/ChapterFour/0600~0699/0684.Redundant-Connection.md +++ b/website/content/ChapterFour/0600~0699/0684.Redundant-Connection.md @@ -62,7 +62,7 @@ Return an edge that can be removed so that the resulting graph is a tree of N no package leetcode import ( - "github.com/halfrost/LeetCode-Go/template" + "github.com/halfrost/leetcode-go/template" ) func findRedundantConnection(edges [][]int) []int { diff --git a/website/content/ChapterFour/0600~0699/0685.Redundant-Connection-II.md b/website/content/ChapterFour/0600~0699/0685.Redundant-Connection-II.md index b6befebfe..f24a372a4 100755 --- a/website/content/ChapterFour/0600~0699/0685.Redundant-Connection-II.md +++ b/website/content/ChapterFour/0600~0699/0685.Redundant-Connection-II.md @@ -113,5 +113,5 @@ func findRoot(parent *[]int, k int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0600~0699/0690.Employee-Importance.md b/website/content/ChapterFour/0600~0699/0690.Employee-Importance.md new file mode 100644 index 000000000..df80e9bc7 --- /dev/null +++ b/website/content/ChapterFour/0600~0699/0690.Employee-Importance.md @@ -0,0 +1,69 @@ +# [690. Employee Importance](https://leetcode.com/problems/employee-importance/) + +## 题目 + +You are given a data structure of employee information, which includes the employee's **unique id**, their **importance value** and their **direct** subordinates' id. + +For example, employee 1 is the leader of employee 2, and employee 2 is the leader of employee 3. They have importance value 15, 10 and 5, respectively. Then employee 1 has a data structure like [1, 15, [2]], and employee 2 has [2, 10, [3]], and employee 3 has [3, 5, []]. Note that although employee 3 is also a subordinate of employee 1, the relationship is **not direct**. + +Now given the employee information of a company, and an employee id, you need to return the total importance value of this employee and all their subordinates. + +**Example 1:** + +``` +Input: [[1, 5, [2, 3]], [2, 3, []], [3, 3, []]], 1 +Output: 11 +Explanation: +Employee 1 has importance value 5, and he has two direct subordinates: employee 2 and employee 3. They both have importance value 3. So the total importance value of employee 1 is 5 + 3 + 3 = 11. +``` + +**Note:** + +1. One employee has at most one **direct** leader and may have several subordinates. +2. The maximum number of employees won't exceed 2000. + +## 题目大意 + +给定一个保存员工信息的数据结构，它包含了员工 唯一的 id ，重要度 和 直系下属的 id 。比如，员工 1 是员工 2 的领导，员工 2 是员工 3 的领导。他们相应的重要度为 15 , 10 , 5 。那么员工 1 的数据结构是 [1, 15, [2]] ，员工 2的 数据结构是 [2, 10, [3]] ，员工 3 的数据结构是 [3, 5, []] 。注意虽然员工 3 也是员工 1 的一个下属，但是由于 并不是直系 下属，因此没有体现在员工 1 的数据结构中。现在输入一个公司的所有员工信息，以及单个员工 id ，返回这个员工和他所有下属的重要度之和。 + +## 解题思路 + +- 简单题。根据题意，DFS 或者 BFS 搜索找到所求 id 下属所有员工，累加下属员工的重要度，最后再加上这个员工本身的重要度，即为所求。 + +## 代码 + +```go +package leetcode + +type Employee struct { + Id int + Importance int + Subordinates []int +} + +func getImportance(employees []*Employee, id int) int { + m, queue, res := map[int]*Employee{}, []int{id}, 0 + for _, e := range employees { + m[e.Id] = e + } + for len(queue) > 0 { + e := m[queue[0]] + queue = queue[1:] + if e == nil { + continue + } + res += e.Importance + for _, i := range e.Subordinates { + queue = append(queue, i) + } + } + return res +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0600~0699/0692.Top-K-Frequent-Words.md b/website/content/ChapterFour/0600~0699/0692.Top-K-Frequent-Words.md new file mode 100644 index 000000000..1d8f09791 --- /dev/null +++ b/website/content/ChapterFour/0600~0699/0692.Top-K-Frequent-Words.md @@ -0,0 +1,105 @@ +# [692. Top K Frequent Words](https://leetcode.com/problems/top-k-frequent-words/) + + +## 题目 + +Given a non-empty list of words, return the k most frequent elements. + +Your answer should be sorted by frequency from highest to lowest. If two words have the same frequency, then the word with the lower alphabetical order comes first. + +**Example 1:** + +``` +Input: ["i", "love", "leetcode", "i", "love", "coding"], k = 2 +Output: ["i", "love"] +Explanation: "i" and "love" are the two most frequent words. + Note that "i" comes before "love" due to a lower alphabetical order. +``` + +**Example 2:** + +``` +Input: ["the", "day", "is", "sunny", "the", "the", "the", "sunny", "is", "is"], k = 4 +Output: ["the", "is", "sunny", "day"] +Explanation: "the", "is", "sunny" and "day" are the four most frequent words, + with the number of occurrence being 4, 3, 2 and 1 respectively. +``` + +**Note:** + +1. You may assume k is always valid, 1 ≤ k ≤ number of unique elements. +2. Input words contain only lowercase letters. + +**Follow up:** + +1. Try to solve it in O(n log k) time and O(n) extra space. + +## 题目大意 + +给一非空的单词列表，返回前 *k* 个出现次数最多的单词。返回的答案应该按单词出现频率由高到低排序。如果不同的单词有相同出现频率，按字母顺序排序。 + +## 解题思路 + +- 思路很简单的题。维护一个长度为 k 的最大堆，先按照频率排，如果频率相同再按照字母顺序排。最后输出依次将优先队列里面的元素 pop 出来即可。 + +## 代码 + +```go +package leetcode + +import "container/heap" + +func topKFrequent(words []string, k int) []string { + m := map[string]int{} + for _, word := range words { + m[word]++ + } + pq := &PQ{} + heap.Init(pq) + for w, c := range m { + heap.Push(pq, &wordCount{w, c}) + if pq.Len() > k { + heap.Pop(pq) + } + } + res := make([]string, k) + for i := k - 1; i >= 0; i-- { + wc := heap.Pop(pq).(*wordCount) + res[i] = wc.word + } + return res +} + +type wordCount struct { + word string + cnt int +} + +type PQ []*wordCount + +func (pq PQ) Len() int { return len(pq) } +func (pq PQ) Swap(i, j int) { pq[i], pq[j] = pq[j], pq[i] } +func (pq PQ) Less(i, j int) bool { + if pq[i].cnt == pq[j].cnt { + return pq[i].word > pq[j].word + } + return pq[i].cnt < pq[j].cnt +} +func (pq *PQ) Push(x interface{}) { + tmp := x.(*wordCount) + *pq = append(*pq, tmp) +} +func (pq *PQ) Pop() interface{} { + n := len(*pq) + tmp := (*pq)[n-1] + *pq = (*pq)[:n-1] + return tmp +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0600~0699/0693.Binary-Number-with-Alternating-Bits.md b/website/content/ChapterFour/0600~0699/0693.Binary-Number-with-Alternating-Bits.md index e363ecde0..b77b30872 100755 --- a/website/content/ChapterFour/0600~0699/0693.Binary-Number-with-Alternating-Bits.md +++ b/website/content/ChapterFour/0600~0699/0693.Binary-Number-with-Alternating-Bits.md @@ -82,6 +82,6 @@ func hasAlternatingBits1(n int) bool { ---------------------------------------------- diff --git a/website/content/ChapterFour/0600~0699/0695.Max-Area-of-Island.md b/website/content/ChapterFour/0600~0699/0695.Max-Area-of-Island.md index 7ea96495a..05c391e04 100644 --- a/website/content/ChapterFour/0600~0699/0695.Max-Area-of-Island.md +++ b/website/content/ChapterFour/0600~0699/0695.Max-Area-of-Island.md @@ -45,6 +45,14 @@ Given the above grid, return`0`. ## 代码 ```go + +var dir = [][]int{ + {-1, 0}, + {0, 1}, + {1, 0}, + {0, -1}, +} + func maxAreaOfIsland(grid [][]int) int { res := 0 for i, row := range grid { @@ -61,6 +69,10 @@ func maxAreaOfIsland(grid [][]int) int { return res } +func isInGrid(grid [][]int, x, y int) bool { + return x >= 0 && x < len(grid) && y >= 0 && y < len(grid[0]) +} + func areaOfIsland(grid [][]int, x, y int) int { if !isInGrid(grid, x, y) || grid[x][y] == 0 { return 0 @@ -74,6 +86,7 @@ func areaOfIsland(grid [][]int, x, y int) int { } return total } + ``` diff --git a/website/content/ChapterFour/0600~0699/0699.Falling-Squares.md b/website/content/ChapterFour/0600~0699/0699.Falling-Squares.md index 6ea24b3e0..83772c54a 100755 --- a/website/content/ChapterFour/0600~0699/0699.Falling-Squares.md +++ b/website/content/ChapterFour/0600~0699/0699.Falling-Squares.md @@ -108,7 +108,7 @@ package leetcode import ( "sort" - "github.com/halfrost/LeetCode-Go/template" + "github.com/halfrost/leetcode-go/template" ) func fallingSquares(positions [][]int) []int { @@ -148,5 +148,5 @@ func discretization(positions [][]int) map[int]int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0700~0799/0700.Search-in-a-Binary-Search-Tree.md b/website/content/ChapterFour/0700~0799/0700.Search-in-a-Binary-Search-Tree.md new file mode 100644 index 000000000..dd0072acb --- /dev/null +++ b/website/content/ChapterFour/0700~0799/0700.Search-in-a-Binary-Search-Tree.md @@ -0,0 +1,80 @@ +# [700. Search in a Binary Search Tree](https://leetcode.com/problems/search-in-a-binary-search-tree/) + +## 题目 + +You are given the root of a binary search tree (BST) and an integer val. + +Find the node in the BST that the node's value equals val and return the subtree rooted with that node. If such a node does not exist, return null. + +**Example 1**: + +![https://assets.leetcode.com/uploads/2021/01/12/tree1.jpg](https://assets.leetcode.com/uploads/2021/01/12/tree1.jpg) + + Input: root = [4,2,7,1,3], val = 2 + Output: [2,1,3] + +**Example 2**: + +![https://assets.leetcode.com/uploads/2021/01/12/tree2.jpg](https://assets.leetcode.com/uploads/2021/01/12/tree2.jpg) + + Input: root = [4,2,7,1,3], val = 5 + Output: [] + +**Constraints:** + +- The number of nodes in the tree is in the range [1, 5000]. +- 1 <= Node.val <= 10000000 +- root is a binary search tree. +- 1 <= val <= 10000000 + +## 题目大意 + +给定二叉搜索树（BST）的根节点和一个值。 你需要在BST中找到节点值等于给定值的节点。 返回以该节点为根的子树。 如果节点不存在，则返回 NULL。 + +## 解题思路 + +- 根据二叉搜索树的性质(根节点的值大于左子树所有节点的值，小于右子树所有节点的值),进行递归求解 + +## 代码 + +```go + +package leetcode + +import ( + "github.com/halfrost/leetcode-go/structures" +) + +// TreeNode define +type TreeNode = structures.TreeNode + +/** + * Definition for a binary tree node. + * type TreeNode struct { + * Val int + * Left *TreeNode + * Right *TreeNode + * } + */ + +func searchBST(root *TreeNode, val int) *TreeNode { + if root == nil { + return nil + } + if root.Val == val { + return root + } else if root.Val < val { + return searchBST(root.Right, val) + } else { + return searchBST(root.Left, val) + } +} + +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0700~0799/0701.Insert-into-a-Binary-Search-Tree.md b/website/content/ChapterFour/0700~0799/0701.Insert-into-a-Binary-Search-Tree.md new file mode 100644 index 000000000..bbfc43a22 --- /dev/null +++ b/website/content/ChapterFour/0700~0799/0701.Insert-into-a-Binary-Search-Tree.md @@ -0,0 +1,95 @@ +# [701. Insert into a Binary Search Tree](https://leetcode.com/problems/insert-into-a-binary-search-tree/) + + +## 题目 + +You are given the `root` node of a binary search tree (BST) and a `value` to insert into the tree. Return *the root node of the BST after the insertion*. It is **guaranteed** that the new value does not exist in the original BST. + +**Notice** that there may exist multiple valid ways for the insertion, as long as the tree remains a BST after insertion. You can return **any of them**. + +**Example 1:** + +![https://assets.leetcode.com/uploads/2020/10/05/insertbst.jpg](https://assets.leetcode.com/uploads/2020/10/05/insertbst.jpg) + +``` +Input: root = [4,2,7,1,3], val = 5 +Output: [4,2,7,1,3,5] +Explanation: Another accepted tree is: + +``` + +![https://assets.leetcode.com/uploads/2020/10/05/bst.jpg](https://assets.leetcode.com/uploads/2020/10/05/bst.jpg) + +**Example 2:** + +``` +Input: root = [40,20,60,10,30,50,70], val = 25 +Output: [40,20,60,10,30,50,70,null,null,25] + +``` + +**Example 3:** + +``` +Input: root = [4,2,7,1,3,null,null,null,null,null,null], val = 5 +Output: [4,2,7,1,3,5] + +``` + +**Constraints:** + +- The number of nodes in the tree will be in the range `[0, 104]`. +- `108 <= Node.val <= 108` +- All the values `Node.val` are **unique**. +- `108 <= val <= 108` +- It's **guaranteed** that `val` does not exist in the original BST. + +## 题目大意 + +给定二叉搜索树（BST）的根节点和要插入树中的值，将值插入二叉搜索树。 返回插入后二叉搜索树的根节点。 输入数据 保证 ，新值和原始二叉搜索树中的任意节点值都不同。注意，可能存在多种有效的插入方式，只要树在插入后仍保持为二叉搜索树即可。 你可以返回 任意有效的结果 。 + +## 解题思路 + +- 简单题。插入节点的方法有多种，笔者这里选择一种简单的方法。从根开始遍历这个二叉树，当前节点的值比待插入节点的值小，则往右遍历；当前节点的值比待插入节点的值大，则往左遍历。最后遍历到空节点便是要插入的地方。 + +## 代码 + +```go +package leetcode + +import "github.com/halfrost/leetcode-go/structures" + +// TreeNode define +type TreeNode = structures.TreeNode + +/** + * Definition for a binary tree node. + * type TreeNode struct { + * Val int + * Left *TreeNode + * Right *TreeNode + * } + */ +func insert(n *TreeNode, val int) *TreeNode { + if n == nil { + return &TreeNode{Val: val} + } + if n.Val < val { + n.Right = insert(n.Right, val) + } else { + n.Left = insert(n.Left, val) + } + return n +} + +func insertIntoBST(root *TreeNode, val int) *TreeNode { + return insert(root, val) +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0700~0799/0703.Kth-Largest-Element-in-a-Stream.md b/website/content/ChapterFour/0700~0799/0703.Kth-Largest-Element-in-a-Stream.md index c55105bf7..0cce2cbfa 100644 --- a/website/content/ChapterFour/0700~0799/0703.Kth-Largest-Element-in-a-Stream.md +++ b/website/content/ChapterFour/0700~0799/0703.Kth-Largest-Element-in-a-Stream.md @@ -95,6 +95,6 @@ func (kl *KthLargest) Add(val int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0700~0799/0706.Design-HashMap.md b/website/content/ChapterFour/0700~0799/0706.Design-HashMap.md index e941b88e0..e6b441607 100755 --- a/website/content/ChapterFour/0700~0799/0706.Design-HashMap.md +++ b/website/content/ChapterFour/0700~0799/0706.Design-HashMap.md @@ -98,9 +98,9 @@ func (N *HashNode) Remove(key int) *HashNode { return p } if N.next != nil { - return N.next.Remove(key) + N.next = N.next.Remove(key) } - return nil + return N } /** Initialize your data structure here. */ diff --git a/website/content/ChapterFour/0700~0799/0707.Design-Linked-List.md b/website/content/ChapterFour/0700~0799/0707.Design-Linked-List.md index c42b34267..93aaf77b9 100644 --- a/website/content/ChapterFour/0700~0799/0707.Design-Linked-List.md +++ b/website/content/ChapterFour/0700~0799/0707.Design-Linked-List.md @@ -48,82 +48,97 @@ linkedList.get(1); // returns 3 package leetcode type MyLinkedList struct { + head *Node +} + +type Node struct { Val int - Next *MyLinkedList + Next *Node + Prev *Node } /** Initialize your data structure here. */ func Constructor() MyLinkedList { - return MyLinkedList{Val: -999, Next: nil} + return MyLinkedList{} } /** Get the value of the index-th node in the linked list. If the index is invalid, return -1. */ func (this *MyLinkedList) Get(index int) int { - cur := this - for i := 0; cur != nil; i++ { - if i == index { - if cur.Val == -999 { - return -1 - } else { - return cur.Val - } - } - cur = cur.Next + curr := this.head + for i := 0; i < index && curr != nil; i++ { + curr = curr.Next + } + if curr != nil { + return curr.Val + } else { + return -1 } - return -1 } /** Add a node of value val before the first element of the linked list. After the insertion, the new node will be the first node of the linked list. */ func (this *MyLinkedList) AddAtHead(val int) { - if this.Val == -999 { - this.Val = val - } else { - tmp := &MyLinkedList{Val: this.Val, Next: this.Next} - this.Val = val - this.Next = tmp + node := &Node{Val: val} + node.Next = this.head + if this.head != nil { + this.head.Prev = node } + this.head = node } /** Append a node of value val to the last element of the linked list. */ func (this *MyLinkedList) AddAtTail(val int) { - cur := this - for cur.Next != nil { - cur = cur.Next + if this.head == nil { + this.AddAtHead(val) + return } - tmp := &MyLinkedList{Val: val, Next: nil} - cur.Next = tmp + node := &Node{Val: val} + curr := this.head + for curr != nil && curr.Next != nil { + curr = curr.Next + } + node.Prev = curr + curr.Next = node } /** Add a node of value val before the index-th node in the linked list. If index equals to the length of linked list, the node will be appended to the end of linked list. If index is greater than the length, the node will not be inserted. */ func (this *MyLinkedList) AddAtIndex(index int, val int) { - cur := this if index == 0 { this.AddAtHead(val) - return - } - for i := 0; cur != nil; i++ { - if i == index-1 { - break + } else { + node := &Node{Val: val} + curr := this.head + for i := 0; i < index-1 && curr != nil; i++ { + curr = curr.Next + } + if curr != nil { + node.Next = curr.Next + node.Prev = curr + if node.Next != nil { + node.Next.Prev = node + } + curr.Next = node } - cur = cur.Next - } - if cur != nil && cur.Val != -999 { - tmp := &MyLinkedList{Val: val, Next: cur.Next} - cur.Next = tmp } } /** Delete the index-th node in the linked list, if the index is valid. */ func (this *MyLinkedList) DeleteAtIndex(index int) { - cur := this - for i := 0; cur != nil; i++ { - if i == index-1 { - break + if index == 0 { + this.head = this.head.Next + if this.head != nil { + this.head.Prev = nil + } + } else { + curr := this.head + for i := 0; i < index-1 && curr != nil; i++ { + curr = curr.Next + } + if curr != nil && curr.Next != nil { + curr.Next = curr.Next.Next + if curr.Next != nil { + curr.Next.Prev = curr + } } - cur = cur.Next - } - if cur != nil && cur.Next != nil { - cur.Next = cur.Next.Next } } @@ -137,11 +152,12 @@ func (this *MyLinkedList) DeleteAtIndex(index int) { * obj.DeleteAtIndex(index); */ + ``` ---------------------------------------------- diff --git a/website/content/ChapterFour/0700~0799/0709.To-Lower-Case.md b/website/content/ChapterFour/0700~0799/0709.To-Lower-Case.md new file mode 100644 index 000000000..b88578cf6 --- /dev/null +++ b/website/content/ChapterFour/0700~0799/0709.To-Lower-Case.md @@ -0,0 +1,62 @@ +# [709. To Lower Case](https://leetcode.com/problems/to-lower-case/) + + +## 题目 + +Given a string `s`, return *the string after replacing every uppercase letter with the same lowercase letter*. + +**Example 1:** + +``` +Input: s = "Hello" +Output: "hello" +``` + +**Example 2:** + +``` +Input: s = "here" +Output: "here" +``` + +**Example 3:** + +``` +Input: s = "LOVELY" +Output: "lovely" +``` + +**Constraints:** + +- `1 <= s.length <= 100` +- `s` consists of printable ASCII characters. + +## 题目大意 + +给你一个字符串 s ，将该字符串中的大写字母转换成相同的小写字母，返回新的字符串。 + +## 解题思路 + +- 简单题，将字符串中的大写字母转换成小写字母。 + +## 代码 + +```go +func toLowerCase(s string) string { + runes := [] rune(s) + diff := 'a' - 'A' + for i := 0; i < len(s); i++ { + if runes[i] >= 'A' && runes[i] <= 'Z' { + runes[i] += diff + } + } + return string(runes) +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0700~0799/0710.Random-Pick-with-Blacklist.md b/website/content/ChapterFour/0700~0799/0710.Random-Pick-with-Blacklist.md index f80540875..d0e9356c8 100644 --- a/website/content/ChapterFour/0700~0799/0710.Random-Pick-with-Blacklist.md +++ b/website/content/ChapterFour/0700~0799/0710.Random-Pick-with-Blacklist.md @@ -147,6 +147,6 @@ func (this *Solution) Pick() int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0700~0799/0721.Accounts-Merge.md b/website/content/ChapterFour/0700~0799/0721.Accounts-Merge.md index dfe1190cb..a7cb56781 100755 --- a/website/content/ChapterFour/0700~0799/0721.Accounts-Merge.md +++ b/website/content/ChapterFour/0700~0799/0721.Accounts-Merge.md @@ -58,7 +58,7 @@ package leetcode import ( "sort" - "github.com/halfrost/LeetCode-Go/template" + "github.com/halfrost/leetcode-go/template" ) // 解法一 并查集优化搜索解法 diff --git a/website/content/ChapterFour/0700~0799/0726.Number-of-Atoms.md b/website/content/ChapterFour/0700~0799/0726.Number-of-Atoms.md index 3cbf7a4f7..da6ec1a93 100755 --- a/website/content/ChapterFour/0700~0799/0726.Number-of-Atoms.md +++ b/website/content/ChapterFour/0700~0799/0726.Number-of-Atoms.md @@ -189,5 +189,5 @@ func isLowerLetter(v byte) bool { ---------------------------------------------- diff --git a/website/content/ChapterFour/0700~0799/0728.Self-Dividing-Numbers.md b/website/content/ChapterFour/0700~0799/0728.Self-Dividing-Numbers.md new file mode 100644 index 000000000..0a7871712 --- /dev/null +++ b/website/content/ChapterFour/0700~0799/0728.Self-Dividing-Numbers.md @@ -0,0 +1,75 @@ +# [728. Self Dividing Numbers](https://leetcode.com/problems/self-dividing-numbers/) + +## 题目 + +A self-dividing number is a number that is divisible by every digit it contains. + +- For example, 128 is a self-dividing number because 128 % 1 == 0, 128 % 2 == 0, and 128 % 8 == 0. + +A self-dividing number is not allowed to contain the digit zero. + +Given two integers left and right, return a list of all the self-dividing numbers in the range [left, right]. + +**Example 1:** + + Input: left = 1, right = 22 + Output: [1,2,3,4,5,6,7,8,9,11,12,15,22] + +**Example 2:** + + Input: left = 47, right = 85 + Output: [48,55,66,77] + +**Constraints:** + +- 1 <= left <= right <= 10000 + +## 题目大意 + +自除数是指可以被它包含的每一位数整除的数。 + +- 例如，128 是一个 自除数 ，因为 128 % 1 == 0，128 % 2 == 0，128 % 8 == 0。 + +自除数 不允许包含 0 。 + +给定两个整数 left 和 right ，返回一个列表，列表的元素是范围 [left, right] 内所有的 自除数 。 + +## 解题思路 + +- 模拟计算 + +# 代码 + +```go +package leetcode + +func selfDividingNumbers(left int, right int) []int { + var ans []int + for num := left; num <= right; num++ { + if selfDividingNum(num) { + ans = append(ans, num) + } + } + return ans +} + +func selfDividingNum(num int) bool { + for d := num; d > 0; d = d / 10 { + reminder := d % 10 + if reminder == 0 { + return false + } + if num%reminder != 0 { + return false + } + } + return true +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0700~0799/0729.My-Calendar-I.md b/website/content/ChapterFour/0700~0799/0729.My-Calendar-I.md index 6c7cf30b3..0579c76da 100755 --- a/website/content/ChapterFour/0700~0799/0729.My-Calendar-I.md +++ b/website/content/ChapterFour/0700~0799/0729.My-Calendar-I.md @@ -182,6 +182,6 @@ func (this *MyCalendar) Book(start int, end int) bool { ---------------------------------------------- diff --git a/website/content/ChapterFour/0700~0799/0746.Min-Cost-Climbing-Stairs.md b/website/content/ChapterFour/0700~0799/0746.Min-Cost-Climbing-Stairs.md index 94bfac521..b4f00e291 100755 --- a/website/content/ChapterFour/0700~0799/0746.Min-Cost-Climbing-Stairs.md +++ b/website/content/ChapterFour/0700~0799/0746.Min-Cost-Climbing-Stairs.md @@ -74,5 +74,5 @@ func minCostClimbingStairs1(cost []int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0700~0799/0747.Largest-Number-At-Least-Twice-of-Others.md b/website/content/ChapterFour/0700~0799/0747.Largest-Number-At-Least-Twice-of-Others.md new file mode 100644 index 000000000..759e8cb7f --- /dev/null +++ b/website/content/ChapterFour/0700~0799/0747.Largest-Number-At-Least-Twice-of-Others.md @@ -0,0 +1,82 @@ +# [747. Largest Number At Least Twice of Others](https://leetcode.com/problems/largest-number-at-least-twice-of-others/) + + +## 题目 + +You are given an integer array `nums` where the largest integer is **unique**. + +Determine whether the largest element in the array is **at least twice** as much as every other number in the array. If it is, return *the **index** of the largest element, or return* `-1` *otherwise*. + +**Example 1:** + +``` +Input: nums = [3,6,1,0] +Output: 1 +Explanation: 6 is the largest integer. +For every other number in the array x, 6 is at least twice as big as x. +The index of value 6 is 1, so we return 1. + +``` + +**Example 2:** + +``` +Input: nums = [1,2,3,4] +Output: -1 +Explanation: 4 is less than twice the value of 3, so we return -1. +``` + +**Example 3:** + +``` +Input: nums = [1] +Output: 0 +Explanation: 1 is trivially at least twice the value as any other number because there are no other numbers. + +``` + +**Constraints:** + +- `1 <= nums.length <= 50` +- `0 <= nums[i] <= 100` +- The largest element in `nums` is unique. + +## 题目大意 + +给你一个整数数组 nums ，其中总是存在 唯一的 一个最大整数 。请你找出数组中的最大元素并检查它是否 至少是数组中每个其他数字的两倍 。如果是，则返回 最大元素的下标 ，否则返回 -1 。 + +## 解题思路 + +- 简单题。先扫描一遍找到最大值和下标。再扫描一遍检查最大值是否是其他数字的两倍。 + +## 代码 + +```go +package leetcode + +func dominantIndex(nums []int) int { + maxNum, flag, index := 0, false, 0 + for i, v := range nums { + if v > maxNum { + maxNum = v + index = i + } + } + for _, v := range nums { + if v != maxNum && 2*v > maxNum { + flag = true + } + } + if flag { + return -1 + } + return index +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0700~0799/0748.Shortest-Completing-Word.md b/website/content/ChapterFour/0700~0799/0748.Shortest-Completing-Word.md index 5bf3a79db..54e53357a 100755 --- a/website/content/ChapterFour/0700~0799/0748.Shortest-Completing-Word.md +++ b/website/content/ChapterFour/0700~0799/0748.Shortest-Completing-Word.md @@ -104,6 +104,6 @@ func match(lp [26]int, w string) bool { ---------------------------------------------- diff --git a/website/content/ChapterFour/0700~0799/0752.Open-the-Lock.md b/website/content/ChapterFour/0700~0799/0752.Open-the-Lock.md new file mode 100644 index 000000000..3c442ae7f --- /dev/null +++ b/website/content/ChapterFour/0700~0799/0752.Open-the-Lock.md @@ -0,0 +1,138 @@ +# [752. Open the Lock](https://leetcode.com/problems/open-the-lock/) + + +## 题目 + +You have a lock in front of you with 4 circular wheels. Each wheel has 10 slots: `'0', '1', '2', '3', '4', '5', '6', '7', '8', '9'`. The wheels can rotate freely and wrap around: for example we can turn `'9'` to be `'0'`, or `'0'` to be `'9'`. Each move consists of turning one wheel one slot. + +The lock initially starts at `'0000'`, a string representing the state of the 4 wheels. + +You are given a list of `deadends` dead ends, meaning if the lock displays any of these codes, the wheels of the lock will stop turning and you will be unable to open it. + +Given a `target` representing the value of the wheels that will unlock the lock, return the minimum total number of turns required to open the lock, or -1 if it is impossible. + +**Example 1:** + +``` +Input: deadends = ["0201","0101","0102","1212","2002"], target = "0202" +Output: 6 +Explanation: +A sequence of valid moves would be "0000" -> "1000" -> "1100" -> "1200" -> "1201" -> "1202" -> "0202". +Note that a sequence like "0000" -> "0001" -> "0002" -> "0102" -> "0202" would be invalid, +because the wheels of the lock become stuck after the display becomes the dead end "0102". + +``` + +**Example 2:** + +``` +Input: deadends = ["8888"], target = "0009" +Output: 1 +Explanation: +We can turn the last wheel in reverse to move from "0000" -> "0009". + +``` + +**Example 3:** + +``` +Input: deadends = ["8887","8889","8878","8898","8788","8988","7888","9888"], target = "8888" +Output: -1 +Explanation: +We can't reach the target without getting stuck. + +``` + +**Example 4:** + +``` +Input: deadends = ["0000"], target = "8888" +Output: -1 + +``` + +**Constraints:** + +- `1 <= deadends.length <= 500` +- `deadends[i].length == 4` +- `target.length == 4` +- target **will not be** in the list `deadends`. +- `target` and `deadends[i]` consist of digits only. + +## 题目大意 + +你有一个带有四个圆形拨轮的转盘锁。每个拨轮都有10个数字： '0', '1', '2', '3', '4', '5', '6', '7', '8', '9' 。每个拨轮可以自由旋转：例如把 '9' 变为 '0'，'0' 变为 '9' 。每次旋转都只能旋转一个拨轮的一位数字。锁的初始数字为 '0000' ，一个代表四个拨轮的数字的字符串。列表 deadends 包含了一组死亡数字，一旦拨轮的数字和列表里的任何一个元素相同，这个锁将会被永久锁定，无法再被旋转。字符串 target 代表可以解锁的数字，你需要给出解锁需要的最小旋转次数，如果无论如何不能解锁，返回 -1 。 + +## 解题思路 + +- 此题可以转化为从起始点到终点的最短路径。采用广度优先搜索。每次广搜枚举转动一次数字的状态，并且用 visited 记录是否被搜索过，如果没有被搜索过，便加入队列，下一轮继续搜索。如果搜索到了 target，便返回对应的旋转次数。如果搜索完成后，仍没有搜索到 target，说明无法解锁，返回 -1。特殊情况，如果 target 就是初始数字 0000，那么直接返回答案 0。 +- 在广搜之前，先将 deadends 放入 map 中，搜索中判断是否搜到了 deadends。如果初始数字 0000 出现在 deadends 中，可以直接返回答案 −1。 + +## 代码 + +```go +package leetcode + +func openLock(deadends []string, target string) int { + if target == "0000" { + return 0 + } + targetNum, visited := strToInt(target), make([]bool, 10000) + visited[0] = true + for _, deadend := range deadends { + num := strToInt(deadend) + if num == 0 { + return -1 + } + visited[num] = true + } + depth, curDepth, nextDepth := 0, []int16{0}, make([]int16, 0) + var nextNum int16 + for len(curDepth) > 0 { + nextDepth = nextDepth[0:0] + for _, curNum := range curDepth { + for incrementer := int16(1000); incrementer > 0; incrementer /= 10 { + digit := (curNum / incrementer) % 10 + if digit == 9 { + nextNum = curNum - 9*incrementer + } else { + nextNum = curNum + incrementer + } + if nextNum == targetNum { + return depth + 1 + } + if !visited[nextNum] { + visited[nextNum] = true + nextDepth = append(nextDepth, nextNum) + } + if digit == 0 { + nextNum = curNum + 9*incrementer + } else { + nextNum = curNum - incrementer + } + if nextNum == targetNum { + return depth + 1 + } + if !visited[nextNum] { + visited[nextNum] = true + nextDepth = append(nextDepth, nextNum) + } + } + } + curDepth, nextDepth = nextDepth, curDepth + depth++ + } + return -1 +} + +func strToInt(str string) int16 { + return int16(str[0]-'0')*1000 + int16(str[1]-'0')*100 + int16(str[2]-'0')*10 + int16(str[3]-'0') +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0700~0799/0753.Cracking-the-Safe.md b/website/content/ChapterFour/0700~0799/0753.Cracking-the-Safe.md index 12f1d6ebf..3a919ce78 100644 --- a/website/content/ChapterFour/0700~0799/0753.Cracking-the-Safe.md +++ b/website/content/ChapterFour/0700~0799/0753.Cracking-the-Safe.md @@ -94,6 +94,6 @@ func dfsCrackSafe(depth, n, k int, str *[]byte, visit *map[string]bool) bool { ---------------------------------------------- diff --git a/website/content/ChapterFour/0700~0799/0763.Partition-Labels.md b/website/content/ChapterFour/0700~0799/0763.Partition-Labels.md index caac72ef1..68b1b7b24 100644 --- a/website/content/ChapterFour/0700~0799/0763.Partition-Labels.md +++ b/website/content/ChapterFour/0700~0799/0763.Partition-Labels.md @@ -34,7 +34,7 @@ A partition like "ababcbacadefegde", "hijhklij" is incorrect, because it splits ## 解题思路 -这一题有 2 种思路，第一种思路是先记录下每个字母的出现次数，然后对滑动窗口中的每个字母判断次数是否用尽为 0，如果这个窗口内的所有字母次数都为 0，这个窗口就是符合条件的窗口。时间复杂度为 O(n^2) +这一题有 2 种思路，第一种思路是先记录下每个字母的出现次数，然后对滑动窗口中的每个字母判断次数是否用尽为 0，如果这个窗口内的所有字母次数都为 0，这个窗口就是符合条件的窗口。时间复杂度为 O(n) 另外一种思路是记录下每个字符最后一次出现的下标，这样就不用记录次数。在每个滑动窗口中，依次判断每个字母最后一次出现的位置，如果在一个下标内，所有字母的最后一次出现的位置都包含进来了，那么这个下标就是这个满足条件的窗口大小。时间复杂度为 O(n^2) diff --git a/website/content/ChapterFour/0700~0799/0765.Couples-Holding-Hands.md b/website/content/ChapterFour/0700~0799/0765.Couples-Holding-Hands.md index 87fe36c4e..988f3eaea 100755 --- a/website/content/ChapterFour/0700~0799/0765.Couples-Holding-Hands.md +++ b/website/content/ChapterFour/0700~0799/0765.Couples-Holding-Hands.md @@ -70,7 +70,7 @@ N 对情侣坐在连续排列的 2N 个座位上，想要牵到对方的手。 package leetcode import ( - "github.com/halfrost/LeetCode-Go/template" + "github.com/halfrost/leetcode-go/template" ) func minSwapsCouples(row []int) int { diff --git a/website/content/ChapterFour/0700~0799/0778.Swim-in-Rising-Water.md b/website/content/ChapterFour/0700~0799/0778.Swim-in-Rising-Water.md index 6a2780a29..6ac095ff3 100755 --- a/website/content/ChapterFour/0700~0799/0778.Swim-in-Rising-Water.md +++ b/website/content/ChapterFour/0700~0799/0778.Swim-in-Rising-Water.md @@ -65,7 +65,7 @@ You start at the top left square `(0, 0)`. What is the least time until you can package leetcode import ( - "github.com/halfrost/LeetCode-Go/template" + "github.com/halfrost/leetcode-go/template" ) // 解法一 DFS + 二分 diff --git a/website/content/ChapterFour/0700~0799/0783.Minimum-Distance-Between-BST-Nodes.md b/website/content/ChapterFour/0700~0799/0783.Minimum-Distance-Between-BST-Nodes.md index 4093810d2..ae6f93087 100644 --- a/website/content/ChapterFour/0700~0799/0783.Minimum-Distance-Between-BST-Nodes.md +++ b/website/content/ChapterFour/0700~0799/0783.Minimum-Distance-Between-BST-Nodes.md @@ -46,7 +46,7 @@ package leetcode import ( "math" - "github.com/halfrost/LeetCode-Go/structures" + "github.com/halfrost/leetcode-go/structures" ) // TreeNode define diff --git a/website/content/ChapterFour/0700~0799/0786.K-th-Smallest-Prime-Fraction.md b/website/content/ChapterFour/0700~0799/0786.K-th-Smallest-Prime-Fraction.md index b0747026c..ac61759e4 100755 --- a/website/content/ChapterFour/0700~0799/0786.K-th-Smallest-Prime-Fraction.md +++ b/website/content/ChapterFour/0700~0799/0786.K-th-Smallest-Prime-Fraction.md @@ -122,5 +122,5 @@ func (a SortByFraction) Less(i, j int) bool { ---------------------------------------------- diff --git a/website/content/ChapterFour/0700~0799/0791.Custom-Sort-String.md b/website/content/ChapterFour/0700~0799/0791.Custom-Sort-String.md new file mode 100644 index 000000000..80de5408e --- /dev/null +++ b/website/content/ChapterFour/0700~0799/0791.Custom-Sort-String.md @@ -0,0 +1,62 @@ +# [791. Custom Sort String](https://leetcode.com/problems/custom-sort-string/) + + +## 题目 + +`order` and `str` are strings composed of lowercase letters. In `order`, no letter occurs more than once. + +`order` was sorted in some custom order previously. We want to permute the characters of `str` so that they match the order that `order` was sorted. More specifically, if `x` occurs before `y` in `order`, then `x` should occur before `y` in the returned string. + +Return any permutation of `str` (as a string) that satisfies this property. + +``` +Example:Input: +order = "cba" +str = "abcd" +Output: "cbad" +Explanation: +"a", "b", "c" appear in order, so the order of "a", "b", "c" should be "c", "b", and "a". +Since "d" does not appear in order, it can be at any position in the returned string. "dcba", "cdba", "cbda" are also valid outputs. + +``` + +**Note:** + +- `order` has length at most `26`, and no character is repeated in `order`. +- `str` has length at most `200`. +- `order` and `str` consist of lowercase letters only. + +## 题目大意 + +字符串 S 和 T 只包含小写字符。在 S 中，所有字符只会出现一次。S 已经根据某种规则进行了排序。我们要根据 S 中的字符顺序对 T 进行排序。更具体地说，如果 S 中 x 在 y 之前出现，那么返回的字符串中 x 也应出现在 y 之前。返回任意一种符合条件的字符串 T。 + +## 解题思路 + +- 题目只要求 T 中包含 S 的字符串有序，所以可以先将 T 中包含 S 的字符串排好序，然后再拼接上其他字符。S 字符串最长为 26 位，先将 S 中字符的下标向左偏移 30，并将偏移后的下标值存入字典中。再把 T 字符串按照字典中下标值进行排序。S 中出现的字符对应的下标经过处理以后变成了负数，S 中未出现的字符的下标还是正数。所以经过排序以后，S 中出现的字符按照原有顺序排列在前面，S 中未出现的字符依次排在后面。 + +## 代码 + +```go +package leetcode + +import "sort" + +func customSortString(order string, str string) string { + magic := map[byte]int{} + for i := range order { + magic[order[i]] = i - 30 + } + byteSlice := []byte(str) + sort.Slice(byteSlice, func(i, j int) bool { + return magic[byteSlice[i]] < magic[byteSlice[j]] + }) + return string(byteSlice) +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0700~0799/0792.Number-of-Matching-Subsequences.md b/website/content/ChapterFour/0700~0799/0792.Number-of-Matching-Subsequences.md new file mode 100644 index 000000000..9f773b9e2 --- /dev/null +++ b/website/content/ChapterFour/0700~0799/0792.Number-of-Matching-Subsequences.md @@ -0,0 +1,73 @@ +# [792. Number of Matching Subsequences](https://leetcode.com/problems/number-of-matching-subsequences/) + + +## 题目 + +Given a string `s` and an array of strings `words`, return *the number of* `words[i]` *that is a subsequence of* `s`. + +A **subsequence** of a string is a new string generated from the original string with some characters (can be none) deleted without changing the relative order of the remaining characters. + +- For example, `"ace"` is a subsequence of `"abcde"`. + +**Example 1:** + +``` +Input: s = "abcde", words = ["a","bb","acd","ace"] +Output: 3 +Explanation: There are three strings in words that are a subsequence of s: "a", "acd", "ace". +``` + +**Example 2:** + +``` +Input: s = "dsahjpjauf", words = ["ahjpjau","ja","ahbwzgqnuk","tnmlanowax"] +Output: 2 +``` + +**Constraints:** + +- `1 <= s.length <= 5 * 104` +- `1 <= words.length <= 5000` +- `1 <= words[i].length <= 50` +- `s` and `words[i]` consist of only lowercase English letters. + +## 题目大意 + +给定字符串 S 和单词字典 words, 求 words[i] 中是 S 的子序列的单词个数。 + +## 解题思路 + +- 如果将 words 数组内的字符串每次都在源字符串 S 中匹配，这种暴力解法超时。超时原因是对字符串 S 遍历了多次。是否有更加高效的方法呢？ +- 把 words 数组内字符串按照首字母，分到 26 个桶中。从头开始遍历一遍源字符串 S，每扫一个字母，命中 26 个桶中其中一个桶，修改这个桶中的字符串。例如：当前遍历到了 'o'，此时桶中存的数据是 'a' : ['amy','aop'], 'o': ['oqp','onwn']，那么调整 'o' 桶中的数据后，各桶的状态为，'a' : ['amy','aop'], 'q': ['qp'], 'n': ['nwn']。从头到尾扫完整个字符串 S，某个桶中的字符串被清空，说明该桶中的字符串都符合 S 的子序列。将符合子序列的字符串个数累加起来即为最终答案。 + +## 代码 + +```go +package leetcode + +func numMatchingSubseq(s string, words []string) int { + hash, res := make([][]string, 26), 0 + for _, w := range words { + hash[int(w[0]-'a')] = append(hash[int(w[0]-'a')], w) + } + for _, c := range s { + words := hash[int(byte(c)-'a')] + hash[int(byte(c)-'a')] = []string{} + for _, w := range words { + if len(w) == 1 { + res += 1 + continue + } + hash[int(w[1]-'a')] = append(hash[int(w[1]-'a')], w[1:]) + } + } + return res +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0700~0799/0793.Preimage-Size-of-Factorial-Zeroes-Function.md b/website/content/ChapterFour/0700~0799/0793.Preimage-Size-of-Factorial-Zeroes-Function.md index 3208a8aea..deca87330 100755 --- a/website/content/ChapterFour/0700~0799/0793.Preimage-Size-of-Factorial-Zeroes-Function.md +++ b/website/content/ChapterFour/0700~0799/0793.Preimage-Size-of-Factorial-Zeroes-Function.md @@ -103,6 +103,6 @@ func preimageSizeFZF1(K int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0700~0799/0794.Valid-Tic-Tac-Toe-State.md b/website/content/ChapterFour/0700~0799/0794.Valid-Tic-Tac-Toe-State.md new file mode 100644 index 000000000..6bc24866a --- /dev/null +++ b/website/content/ChapterFour/0700~0799/0794.Valid-Tic-Tac-Toe-State.md @@ -0,0 +1,126 @@ +# [794. Valid Tic-Tac-Toe State](https://leetcode.com/problems/valid-tic-tac-toe-state/) + +## 题目 + +Given a Tic-Tac-Toe board as a string array board, return true if and only if it is possible to reach this board position during the course of a valid tic-tac-toe game. + +The board is a 3 x 3 array that consists of characters ' ', 'X', and 'O'. The ' ' character represents an empty square. + +Here are the rules of Tic-Tac-Toe: + +- Players take turns placing characters into empty squares ' '. +- The first player always places 'X' characters, while the second player always places 'O' characters. +- 'X' and 'O' characters are always placed into empty squares, never filled ones. +- The game ends when there are three of the same (non-empty) character filling any row, column, or diagonal. +- The game also ends if all squares are non-empty. +- No more moves can be played if the game is over. + +**Example 1**: + +![https://assets.leetcode.com/uploads/2021/05/15/tictactoe1-grid.jpg](https://assets.leetcode.com/uploads/2021/05/15/tictactoe1-grid.jpg) + + Input: board = ["O "," "," "] + Output: false + Explanation: The first player always plays "X". + +**Example 2**: + +![https://assets.leetcode.com/uploads/2021/05/15/tictactoe2-grid.jpg](https://assets.leetcode.com/uploads/2021/05/15/tictactoe2-grid.jpg) + + Input: board = ["XOX"," X "," "] + Output: false + Explanation: Players take turns making moves. + +**Example 3**: + +![https://assets.leetcode.com/uploads/2021/05/15/tictactoe3-grid.jpg](https://assets.leetcode.com/uploads/2021/05/15/tictactoe3-grid.jpg) + + Input: board = ["XXX"," ","OOO"] + Output: false + +**Example 4**: + +![https://assets.leetcode.com/uploads/2021/05/15/tictactoe4-grid.jpg](https://assets.leetcode.com/uploads/2021/05/15/tictactoe4-grid.jpg) + + Input: board = ["XOX","O O","XOX"] + Output: true + +**Constraints:** + +- board.length == 3 +- board[i].length == 3 +- board[i][j] is either 'X', 'O', or ' '. + +## 题目大意 + +给你一个字符串数组 board 表示井字游戏的棋盘。当且仅当在井字游戏过程中，棋盘有可能达到 board 所显示的状态时，才返回 true 。 + +井字游戏的棋盘是一个 3 x 3 数组，由字符 ' '，'X' 和 'O' 组成。字符 ' ' 代表一个空位。 + +以下是井字游戏的规则： + +- 玩家轮流将字符放入空位（' '）中。 +- 玩家 1 总是放字符 'X' ，而玩家 2 总是放字符 'O' 。 +- 'X' 和 'O' 只允许放置在空位中，不允许对已放有字符的位置进行填充。 +- 当有 3 个相同（且非空）的字符填充任何行、列或对角线时，游戏结束。 +- 当所有位置非空时，也算为游戏结束。 +- 如果游戏结束，玩家不允许再放置字符。 + +## 解题思路 + +分类模拟： +- 根据题意棋盘在任意时候，要么 X 的数量比 O 的数量多 1，要么两者相等 +- X 的数量等于 O 的数量时,任何行、列或对角线都不会出现 3 个相同的 X +- X 的数量比 O 的数量多 1 时,任何行、列或对角线都不会出现 3 个相同的 O + +## 代码 + +```go +package leetcode + +func validTicTacToe(board []string) bool { + cntX, cntO := 0, 0 + for i := range board { + for j := range board[i] { + if board[i][j] == 'X' { + cntX++ + } else if board[i][j] == 'O' { + cntO++ + } + } + } + if cntX < cntO || cntX > cntO+1 { + return false + } + if cntX == cntO { + return process(board, 'X') + } + return process(board, 'O') +} + +func process(board []string, c byte) bool { + //某一行是"ccc" + if board[0] == string([]byte{c, c, c}) || board[1] == string([]byte{c, c, c}) || board[2] == string([]byte{c, c, c}) { + return false + } + //某一列是"ccc" + if (board[0][0] == c && board[1][0] == c && board[2][0] == c) || + (board[0][1] == c && board[1][1] == c && board[2][1] == c) || + (board[0][2] == c && board[1][2] == c && board[2][2] == c) { + return false + } + //某一对角线是"ccc" + if (board[0][0] == c && board[1][1] == c && board[2][2] == c) || + (board[0][2] == c && board[1][1] == c && board[2][0] == c) { + return false + } + return true +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0700~0799/0795.Number-of-Subarrays-with-Bounded-Maximum.md b/website/content/ChapterFour/0700~0799/0795.Number-of-Subarrays-with-Bounded-Maximum.md new file mode 100644 index 000000000..3b206fcca --- /dev/null +++ b/website/content/ChapterFour/0700~0799/0795.Number-of-Subarrays-with-Bounded-Maximum.md @@ -0,0 +1,61 @@ +# [795. Number of Subarrays with Bounded Maximum](https://leetcode.com/problems/number-of-subarrays-with-bounded-maximum/) + + +## 题目 + +We are given an array `nums` of positive integers, and two positive integers `left` and `right` (`left <= right`). + +Return the number of (contiguous, non-empty) subarrays such that the value of the maximum array element in that subarray is at least `left` and at most `right`. + +``` +Example:Input: +nums = [2, 1, 4, 3] +left = 2 +right = 3 +Output: 3 +Explanation: There are three subarrays that meet the requirements: [2], [2, 1], [3]. +``` + +**Note:** + +- `left`, `right`, and `nums[i]` will be an integer in the range `[0, 109]`. +- The length of `nums` will be in the range of `[1, 50000]`. + +## 题目大意 + +给定一个元素都是正整数的数组`A` ，正整数 `L` 以及 `R` (`L <= R`)。求连续、非空且其中最大元素满足大于等于`L` 小于等于`R`的子数组个数。 + +## 解题思路 + +- 题目要求子数组最大元素在 [L,R] 区间内。假设 count(bound) 为计算所有元素都小于等于 bound 的子数组数量。那么本题所求的答案可转化为 count(R) - count(L-1)。 +- 如何统计所有元素小于 bound 的子数组数量呢？使用 count 变量记录在 bound 的左边，小于等于 bound 的连续元素数量。当找到一个这样的元素时，在此位置上结束的有效子数组的数量为 count + 1。当遇到一个元素大于 B 时，则在此位置结束的有效子数组的数量为 0。res 将每轮 count 累加，最终 res 中存的即是满足条件的所有子数组数量。 + +## 代码 + +```go +package leetcode + +func numSubarrayBoundedMax(nums []int, left int, right int) int { + return getAnswerPerBound(nums, right) - getAnswerPerBound(nums, left-1) +} + +func getAnswerPerBound(nums []int, bound int) int { + res, count := 0, 0 + for _, num := range nums { + if num <= bound { + count++ + } else { + count = 0 + } + res += count + } + return res +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0800~0899/0802.Find-Eventual-Safe-States.md b/website/content/ChapterFour/0800~0899/0802.Find-Eventual-Safe-States.md index 740545078..1a3d0cd79 100644 --- a/website/content/ChapterFour/0800~0899/0802.Find-Eventual-Safe-States.md +++ b/website/content/ChapterFour/0800~0899/0802.Find-Eventual-Safe-States.md @@ -75,6 +75,6 @@ func dfsEventualSafeNodes(graph [][]int, idx int, color []int) bool { ---------------------------------------------- diff --git a/website/content/ChapterFour/0800~0899/0803.Bricks-Falling-When-Hit.md b/website/content/ChapterFour/0800~0899/0803.Bricks-Falling-When-Hit.md index 81657194e..f05f3978f 100755 --- a/website/content/ChapterFour/0800~0899/0803.Bricks-Falling-When-Hit.md +++ b/website/content/ChapterFour/0800~0899/0803.Bricks-Falling-When-Hit.md @@ -65,7 +65,7 @@ Return an array representing the number of bricks that will drop after each eras package leetcode import ( - "github.com/halfrost/LeetCode-Go/template" + "github.com/halfrost/leetcode-go/template" ) func hitBricks(grid [][]int, hits [][]int) []int { @@ -128,5 +128,5 @@ func getUnionFindFromGrid(grid [][]int, x, y int, uf template.UnionFindCount) { ---------------------------------------------- diff --git a/website/content/ChapterFour/0800~0899/0807.Max-Increase-to-Keep-City-Skyline.md b/website/content/ChapterFour/0800~0899/0807.Max-Increase-to-Keep-City-Skyline.md new file mode 100644 index 000000000..cb19b053a --- /dev/null +++ b/website/content/ChapterFour/0800~0899/0807.Max-Increase-to-Keep-City-Skyline.md @@ -0,0 +1,104 @@ +# [807. Max Increase to Keep City Skyline](https://leetcode.com/problems/max-increase-to-keep-city-skyline/) + +## 题目 + +There is a city composed of n x n blocks, where each block contains a single building shaped like a vertical square prism. You are given a 0-indexed n x n integer matrix grid where grid[r][c] represents the height of the building located in the block at row r and column c. + +A city's skyline is the the outer contour formed by all the building when viewing the side of the city from a distance. The skyline from each cardinal direction north, east, south, and west may be different. + +We are allowed to increase the height of any number of buildings by any amount (the amount can be different per building). The height of a 0-height building can also be increased. However, increasing the height of a building should not affect the city's skyline from any cardinal direction. + +Return the maximum total sum that the height of the buildings can be increased by without changing the city's skyline from any cardinal direction. + +**Example 1**: + +![https://assets.leetcode.com/uploads/2021/06/21/807-ex1.png](https://assets.leetcode.com/uploads/2021/06/21/807-ex1.png) + + Input: grid = [[3,0,8,4],[2,4,5,7],[9,2,6,3],[0,3,1,0]] + Output: 35 + Explanation: The building heights are shown in the center of the above image. + The skylines when viewed from each cardinal direction are drawn in red. + The grid after increasing the height of buildings without affecting skylines is: + gridNew = [ [8, 4, 8, 7], + [7, 4, 7, 7], + [9, 4, 8, 7], + [3, 3, 3, 3] ] + +**Example 2**: + + Input: grid = [[0,0,0],[0,0,0],[0,0,0]] + Output: 0 + Explanation: Increasing the height of any building will result in the skyline changing. + +**Constraints:** + +- n == grid.length +- n == grid[r].length +- 2 <= n <= 50 +- 0 <= grid[r][c] <= 100 + +## 题目大意 + +在二维数组grid中，grid[i][j]代表位于某处的建筑物的高度。 我们被允许增加任何数量（不同建筑物的数量可能不同）的建筑物的高度。 高度 0 也被认为是建筑物。 + +最后，从新数组的所有四个方向（即顶部，底部，左侧和右侧）观看的“天际线”必须与原始数组的天际线相同。 城市的天际线是从远处观看时，由所有建筑物形成的矩形的外部轮廓。 请看下面的例子。 + +建筑物高度可以增加的最大总和是多少？ + +## 解题思路 + +- 从数组竖直方向（即顶部，底部）看“天际线”计算出 topBottomSkyline +- 从数组水平方向（即左侧，右侧）看“天际线”计算出 leftRightSkyline +- 计算 grid 中每个元素与对应的 topBottomSkyline 和 leftRightSkyline 中较小值的差值 +- 统计所有差值的总和 ans 并返回 + +## 代码 + +```go +package leetcode + +func maxIncreaseKeepingSkyline(grid [][]int) int { + n := len(grid) + topBottomSkyline := make([]int, 0, n) + leftRightSkyline := make([]int, 0, n) + for i := range grid { + cur := 0 + for _, v := range grid[i] { + if cur < v { + cur = v + } + } + leftRightSkyline = append(leftRightSkyline, cur) + } + for j := range grid { + cur := 0 + for i := 0; i < len(grid[0]); i++ { + if cur < grid[i][j] { + cur = grid[i][j] + } + } + topBottomSkyline = append(topBottomSkyline, cur) + } + var ans int + for i := range grid { + for j := 0; j < len(grid[0]); j++ { + ans += min(topBottomSkyline[j], leftRightSkyline[i]) - grid[i][j] + } + } + return ans +} + +func min(a, b int) int { + if a < b { + return a + } + return b +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0800~0899/0810.Chalkboard-XOR-Game.md b/website/content/ChapterFour/0800~0899/0810.Chalkboard-XOR-Game.md new file mode 100644 index 000000000..2c2d62d0f --- /dev/null +++ b/website/content/ChapterFour/0800~0899/0810.Chalkboard-XOR-Game.md @@ -0,0 +1,67 @@ +# [810. Chalkboard XOR Game](https://leetcode.com/problems/chalkboard-xor-game/) + + +## 题目 + +We are given non-negative integers nums[i] which are written on a chalkboard.  Alice and Bob take turns erasing exactly one number from the chalkboard, with Alice starting first.  If erasing a number causes the bitwise XOR of all the elements of the chalkboard to become 0, then that player loses.  (Also, we'll say the bitwise XOR of one element is that element itself, and the bitwise XOR of no elements is 0.) + +Also, if any player starts their turn with the bitwise XOR of all the elements of the chalkboard equal to 0, then that player wins. + +Return True if and only if Alice wins the game, assuming both players play optimally. + +``` +Example:Input: nums = [1, 1, 2] +Output: false +Explanation: +Alice has two choices: erase 1 or erase 2. +If she erases 1, the nums array becomes [1, 2]. The bitwise XOR of all the elements of the chalkboard is 1 XOR 2 = 3. Now Bob can remove any element he wants, because Alice will be the one to erase the last element and she will lose. +If Alice erases 2 first, now nums becomes [1, 1]. The bitwise XOR of all the elements of the chalkboard is 1 XOR 1 = 0. Alice will lose. +``` + +**Notes:** + +- `1 <= N <= 1000`. +- `0 <= nums[i] <= 2^16`. + +## 题目大意 + +黑板上写着一个非负整数数组 nums[i] 。Alice 和 Bob 轮流从黑板上擦掉一个数字，Alice 先手。如果擦除一个数字后，剩余的所有数字按位异或运算得出的结果等于 0 的话，当前玩家游戏失败。 (另外，如果只剩一个数字，按位异或运算得到它本身；如果无数字剩余，按位异或运算结果为 0。）并且，轮到某个玩家时，如果当前黑板上所有数字按位异或运算结果等于 0，这个玩家获胜。假设两个玩家每步都使用最优解，当且仅当 Alice 获胜时返回 true。 + +## 解题思路 + +- Alice 必胜情况之一，Alice 先手，起始数组全部元素本身异或结果就为 0 。不需要擦除数字便自动获胜。除去这个情况，还有其他情况么？由于 2 人是交替擦除数字，且每次都恰好擦掉一个数字，因此对于这两人中的任意一人，其每次在擦除数字前，黑板上剩余数字的个数的奇偶性一定都是相同的。于是奇偶性成为突破口。 +- 如果 nums 的长度是偶数，Alice 先手是否必败呢？如果必败，代表无论擦掉哪一个数字，剩余所有数字的异或结果都等于 0。利用反证法证明上述结论是错误的。首先 {{< katex >}} num[0] \oplus num[1] \oplus num[2] \oplus \cdots  \oplus num[n-1] = X ≠ 0 {{< /katex >}} ，初始所有元素异或结果不为 0。假设 Alice 当前擦掉第 i 个元素，0 ≤ i < n。令 {{< katex >}}X_{n}{{< /katex >}} 代表擦掉第 n 位元素以后剩余元素异或的结果。由证题，无论擦掉哪一个数字，剩余所有数字的异或结果都等于 0。所以 {{< katex >}} X_{0} \oplus X_{1} \oplus X_{2} \oplus \cdots  \oplus X_{n-1} = 0{{< /katex >}} 。 + + {{< katex display >}} + \begin{aligned}0 &= X_{0} \oplus  X_{1} \oplus X_{2} \oplus \cdots  \oplus X_{n-1} \\0 &= (X \oplus nums[0]) \oplus (X \oplus nums[1]) \oplus (X \oplus nums[2]) \oplus \cdots  \oplus (X \oplus nums[n-1])\\ 0 &= (X \oplus X \oplus \cdots  \oplus X) \oplus (nums[0] \oplus nums[1] \oplus nums[2] \oplus \cdots  \oplus nums[n-1])\\0 &= 0 \oplus X\\\\\Rightarrow X &= 0\\\end{aligned} + {{< /katex >}} + + 由于 n 为偶数，所以 n 个 X 的异或结果为 0。最终推出 X = 0，很明显与前提 X ≠ 0 冲突。所以原命题，代表无论擦掉哪一个数字，剩余所有数字的异或结果都等于 0 是错误的。也就是说，当 n 为偶数时，代表无论擦掉哪一个数字，剩余所有数字的异或结果都不等于 0。即 Alice 有必胜策略。换句话说，当数组的长度是偶数时，先手 Alice 总能找到一个数字，在擦掉这个数字之后剩余的所有数字异或结果不等于 0。 + +- 综上，Alice 必胜策略有 2 种情况： + 1. 数组 nums 的全部元素初始本身异或结果就等于 0。 + 2. 数组 nums 的长度是偶数。 + +## 代码 + +```go +package leetcode + +func xorGame(nums []int) bool { + if len(nums)%2 == 0 { + return true + } + xor := 0 + for _, num := range nums { + xor ^= num + } + return xor == 0 +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0800~0899/0811.Subdomain-Visit-Count.md b/website/content/ChapterFour/0800~0899/0811.Subdomain-Visit-Count.md index c3a9ac906..12232f80e 100755 --- a/website/content/ChapterFour/0800~0899/0811.Subdomain-Visit-Count.md +++ b/website/content/ChapterFour/0800~0899/0811.Subdomain-Visit-Count.md @@ -145,6 +145,6 @@ func splitDomain(domain string, domains map[string]int) { ---------------------------------------------- diff --git a/website/content/ChapterFour/0800~0899/0815.Bus-Routes.md b/website/content/ChapterFour/0800~0899/0815.Bus-Routes.md index 844c5540b..29ab7cfa8 100755 --- a/website/content/ChapterFour/0800~0899/0815.Bus-Routes.md +++ b/website/content/ChapterFour/0800~0899/0815.Bus-Routes.md @@ -91,5 +91,5 @@ func numBusesToDestination(routes [][]int, S int, T int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0800~0899/0816.Ambiguous-Coordinates.md b/website/content/ChapterFour/0800~0899/0816.Ambiguous-Coordinates.md new file mode 100644 index 000000000..3c10a9ec1 --- /dev/null +++ b/website/content/ChapterFour/0800~0899/0816.Ambiguous-Coordinates.md @@ -0,0 +1,102 @@ +# [816. Ambiguous Coordinates](https://leetcode.com/problems/ambiguous-coordinates/) + + +## 题目 + +We had some 2-dimensional coordinates, like `"(1, 3)"` or `"(2, 0.5)"`.  Then, we removed all commas, decimal points, and spaces, and ended up with the string `s`.  Return a list of strings representing all possibilities for what our original coordinates could have been. + +Our original representation never had extraneous zeroes, so we never started with numbers like "00", "0.0", "0.00", "1.0", "001", "00.01", or any other number that can be represented with less digits.  Also, a decimal point within a number never occurs without at least one digit occuring before it, so we never started with numbers like ".1". + +The final answer list can be returned in any order.  Also note that all coordinates in the final answer have exactly one space between them (occurring after the comma.) + +``` +Example 1:Input: s = "(123)" +Output: ["(1, 23)", "(12, 3)", "(1.2, 3)", "(1, 2.3)"] + +``` + +``` +Example 2:Input: s = "(00011)" +Output:  ["(0.001, 1)", "(0, 0.011)"] +Explanation: +0.0, 00, 0001 or 00.01 are not allowed. + +``` + +``` +Example 3:Input: s = "(0123)" +Output: ["(0, 123)", "(0, 12.3)", "(0, 1.23)", "(0.1, 23)", "(0.1, 2.3)", "(0.12, 3)"] + +``` + +``` +Example 4:Input: s = "(100)" +Output: [(10, 0)] +Explanation: +1.0 is not allowed. + +``` + +**Note:** + +- `4 <= s.length <= 12`. +- `s[0]` = "(", `s[s.length - 1]` = ")", and the other elements in `s` are digits. + +## 题目大意 + +我们有一些二维坐标，如 "(1, 3)" 或 "(2, 0.5)"，然后我们移除所有逗号，小数点和空格，得到一个字符串S。返回所有可能的原始字符串到一个列表中。原始的坐标表示法不会存在多余的零，所以不会出现类似于"00", "0.0", "0.00", "1.0", "001", "00.01"或一些其他更小的数来表示坐标。此外，一个小数点前至少存在一个数，所以也不会出现“.1”形式的数字。 + +最后返回的列表可以是任意顺序的。而且注意返回的两个数字中间（逗号之后）都有一个空格。 + +## 解题思路 + +- 本题没有什么算法思想，纯暴力题。先将原始字符串一分为二，分为的两个子字符串再移动坐标点，最后将每种情况组合再一次，这算完成了一次切分。将原始字符串每一位都按此规律完成切分，此题便得解。 +- 这道题有 2 处需要注意的。第一处是最终输出的字符串，请注意，**两个数字中间（逗号之后）都有一个空格**。不遵守输出格式的要求也会导致 `Wrong Answer`。另外一处是切分数字时，有 2 种违法情况，一种是带前导 0 的，另外一种是末尾带 0 的。带前导 0 的也分为 2 种情况，一种是只有一位，即只有一个 0，这种情况直接返回，因为这一个 0 怎么切分也只有一种切分方法。另外一种是长度大于 1，即 `0xxx` 这种情况。`0xxx` 这种情况只有一种切分方法，即 `0.xxx`。末尾带 0 的只有一种切分方法，即 `xxx0`，不可切分，因为 `xxx.0`，`xx.x0`，`x.xx0` 这些都是违法情况，所以末尾带 0 的也可以直接返回。具体的实现见代码和注释。 + +## 代码 + +```go +package leetcode + +func ambiguousCoordinates(s string) []string { + res := []string{} + s = s[1 : len(s)-1] + for i := range s[:len(s)-1] { + a := build(s[:i+1]) + b := build(s[i+1:]) + for _, ta := range a { + for _, tb := range b { + res = append(res, "("+ta+", "+tb+")") + } + } + } + return res +} + +func build(s string) []string { + res := []string{} + if len(s) == 1 || s[0] != '0' { + res = append(res, s) + } + // 结尾带 0 的情况 + if s[len(s)-1] == '0' { + return res + } + // 切分长度大于一位且带前导 0 的情况 + if s[0] == '0' { + res = append(res, "0."+s[1:]) + return res + } + for i := range s[:len(s)-1] { + res = append(res, s[:i+1]+"."+s[i+1:]) + } + return res +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0800~0899/0817.Linked-List-Components.md b/website/content/ChapterFour/0800~0899/0817.Linked-List-Components.md index 1442d1286..9527d1750 100644 --- a/website/content/ChapterFour/0800~0899/0817.Linked-List-Components.md +++ b/website/content/ChapterFour/0800~0899/0817.Linked-List-Components.md @@ -111,6 +111,6 @@ func toMap(G []int) map[int]int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0800~0899/0821.Shortest-Distance-to-a-Character.md b/website/content/ChapterFour/0800~0899/0821.Shortest-Distance-to-a-Character.md index c3100c678..1f88563da 100644 --- a/website/content/ChapterFour/0800~0899/0821.Shortest-Distance-to-a-Character.md +++ b/website/content/ChapterFour/0800~0899/0821.Shortest-Distance-to-a-Character.md @@ -31,18 +31,43 @@ Output: [3,2,1,0] ## 解题思路 -- 简单题。依次扫描字符串 S，针对每一个非字符 C 的字符，分别往左扫一次，往右扫一次，计算出距离目标字符 C 的距离，然后取左右两个距离的最小值存入最终答案数组中。 +- 解法一：从左至右更新一遍到 C 的值距离，再从右至左更新一遍到 C 的值，取两者中的最小值。 +- 解法二：依次扫描字符串 S，针对每一个非字符 C 的字符，分别往左扫一次，往右扫一次，计算出距离目标字符 C 的距离，然后取左右两个距离的最小值存入最终答案数组中。 ## 代码 ```go + package leetcode import ( "math" ) +// 解法一 func shortestToChar(s string, c byte) []int { + n := len(s) + res := make([]int, n) + for i := range res { + res[i] = n + } + for i := 0; i < n; i++ { + if s[i] == c { + res[i] = 0 + } else if i > 0 { + res[i] = res[i-1] + 1 + } + } + for i := n - 1; i >= 0; i-- { + if i < n-1 && res[i+1]+1 < res[i] { + res[i] = res[i+1] + 1 + } + } + return res +} + +// 解法二 +func shortestToChar1(s string, c byte) []int { res := make([]int, len(s)) for i := 0; i < len(s); i++ { if s[i] == c { @@ -73,6 +98,7 @@ func min(a, b int) int { } return a } + ``` diff --git a/website/content/ChapterFour/0800~0899/0823.Binary-Trees-With-Factors.md b/website/content/ChapterFour/0800~0899/0823.Binary-Trees-With-Factors.md index 7c116146f..d58e146da 100644 --- a/website/content/ChapterFour/0800~0899/0823.Binary-Trees-With-Factors.md +++ b/website/content/ChapterFour/0800~0899/0823.Binary-Trees-With-Factors.md @@ -39,7 +39,9 @@ Explanation: We can make these trees: [2], [4], [5], [10], [4, 2, 2], [10, 2, 5] - 首先想到的是暴力解法，先排序，然后遍历所有节点，枚举两两乘积为第三个节点值的组合。然后枚举这些组合并构成树。这里计数的时候要注意，左右孩子如果不是对称的，左右子树相互对调又是一组解。但是这个方法超时了。原因是，暴力枚举了很多次重复的节点和组合。优化这里的方法就是把已经计算过的节点放入 `map` 中。这里有 2 层 `map`，第一层 `map` 记忆化的是两两乘积的组合，将父亲节点作为 `key`，左右 2 个孩子作为 `value`。第二层 `map` 记忆化的是以 `root` 为根节点此时二叉树的种类数，`key` 是 `root`，`value` 存的是种类数。这样优化以后，DFS 暴力解法可以 runtime beats 100%。 - 另外一种解法是 DP。定义 `dp[i]` 代表以 `i` 为根节点的树的种类数。dp[i] 初始都是 1，因为所有节点自身可以形成为自身单个节点为 `root` 的树。同样需要先排序。状态转移方程是： - $$dp[i] = \sum_{j}} + dp[i] = \sum_{j}} 最后将 `dp[]` 数组中所有结果累加取模即为最终结果，时间复杂度 O(n^2)，空间复杂度 O(n)。 @@ -122,5 +124,5 @@ func numFactoredBinaryTrees1(arr []int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0800~0899/0825.Friends-Of-Appropriate-Ages.md b/website/content/ChapterFour/0800~0899/0825.Friends-Of-Appropriate-Ages.md new file mode 100644 index 000000000..4f278efa1 --- /dev/null +++ b/website/content/ChapterFour/0800~0899/0825.Friends-Of-Appropriate-Ages.md @@ -0,0 +1,148 @@ +# [825. Friends Of Appropriate Ages](https://leetcode.com/problems/friends-of-appropriate-ages/) + + +## 题目 + +There are `n` persons on a social media website. You are given an integer array `ages` where `ages[i]` is the age of the `ith` person. + +A Person `x` will not send a friend request to a person `y` (`x != y`) if any of the following conditions is true: + +- `age[y] <= 0.5 * age+ 7` +- `age[y] > age[x]` +- `age[y] > 100 && age< 100` + +Otherwise, `x` will send a friend request to `y`. + +Note that if `x` sends a request to `y`, `y` will not necessarily send a request to `x`. Also, a person will not send a friend request to themself. + +Return *the total number of friend requests made*. + +**Example 1:** + +``` +Input: ages = [16,16] +Output: 2 +Explanation: 2 people friend request each other. + +``` + +**Example 2:** + +``` +Input: ages = [16,17,18] +Output: 2 +Explanation: Friend requests are made 17 -> 16, 18 -> 17. + +``` + +**Example 3:** + +``` +Input: ages = [20,30,100,110,120] +Output: 3 +Explanation: Friend requests are made 110 -> 100, 120 -> 110, 120 -> 100. + +``` + +**Constraints:** + +- `n == ages.length` +- `1 <= n <= 2 * 10^4` +- `1 <= ages[i] <= 120` + +## 题目大意 + +在社交媒体网站上有 n 个用户。给你一个整数数组 ages ，其中 ages[i] 是第 i 个用户的年龄。 + +如果下述任意一个条件为真，那么用户 x 将不会向用户 y（x != y）发送好友请求： + +- ages[y] <= 0.5 * ages[x] + 7 +- ages[y] > ages[x] +- ages[y] > 100 && ages[x] < 100 + +否则，x 将会向 y 发送一条好友请求。注意，如果 x 向 y 发送一条好友请求，y 不必也向 x 发送一条好友请求。另外，用户不会向自己发送好友请求。返回在该社交媒体网站上产生的好友请求总数。 + +## 解题思路 + +- 解法三，暴力解法。先统计 [1,120] 范围内每个年龄的人数。然后利用题目中的三个判断条件，筛选符合条件的用户对。需要注意的是，相同年龄的人可以相互发送好友请求。不同年龄的人发送好友请求是单向的，即年龄老的向年龄轻的发送好友请求，年龄轻的不会对年龄老的发送好友请求。 +- 解法二，排序 + 双指针。题目给定的 3 个条件其实是 2 个。条件 3 包含在条件 2 中。条件 1 和条件 2 组合起来是 `0.5 × ages[x]+7 < ages[y] ≤ ages[x]`。当 ages[x] 小于 15 时，这个等式无解。考虑到年龄是单调递增的，`(0.5 × ages[x]+7,ages[x]]` 这个区间左右边界也是单调递增的。于是可以用双指针维护两个边界。在区间 [left, right] 内，这些下标对应的的 y 值都满足条件。当 `ages[left] > 0.5 × ages[x]+7` 时，左指针停止右移。当 `ages[right+1] > ages[x]` 时， 右指针停止右移。在 `[left, right]` 区间内，满足条件的 y 有 `right-left+1` 个，即使得 `ages[y]` 取值在 `(0.5 × ages[x]+7,ages[x]]` 之间。依照题意，`x≠y`，即该区间右边界取不到。y 的取值个数需要再减一，减去的是取到和 x 相同的值的下标。那么每个区间能取 `right-left` 个值。累加所有满足条件的值即为好友请求总数。 +- 解法一。在解法二中，计算满足不等式 y 下标所在区间的时候，区间和区间存在重叠的情况，这些重叠情况导致了重复计算。所以这里可以优化。可以用 prefix sum 前缀和数组优化。代码见下方。 + +## 代码 + +```go +package leetcocde + +import "sort" + +// 解法一 前缀和，时间复杂度 O(n) +func numFriendRequests(ages []int) int { + count, prefixSum, res := make([]int, 121), make([]int, 121), 0 + for _, age := range ages { + count[age]++ + } + for i := 1; i < 121; i++ { + prefixSum[i] = prefixSum[i-1] + count[i] + } + for i := 15; i < 121; i++ { + if count[i] > 0 { + bound := i/2 + 8 + res += count[i] * (prefixSum[i] - prefixSum[bound-1] - 1) + } + } + return res +} + +// 解法二 双指针 + 排序，时间复杂度 O(n logn) +func numFriendRequests1(ages []int) int { + sort.Ints(ages) + left, right, res := 0, 0, 0 + for _, age := range ages { + if age < 15 { + continue + } + for ages[left]*2 <= age+14 { + left++ + } + for right+1 < len(ages) && ages[right+1] <= age { + right++ + } + res += right - left + } + return res +} + +// 解法三 暴力解法 O(n^2) +func numFriendRequests2(ages []int) int { + res, count := 0, [125]int{} + for _, x := range ages { + count[x]++ + } + for i := 1; i <= 120; i++ { + for j := 1; j <= 120; j++ { + if j > i { + continue + } + if (j-7)*2 <= i { + continue + } + if j > 100 && i < 100 { + continue + } + if i != j { + res += count[i] * count[j] + } else { + res += count[i] * (count[j] - 1) + } + } + } + return res +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0800~0899/0826.Most-Profit-Assigning-Work.md b/website/content/ChapterFour/0800~0899/0826.Most-Profit-Assigning-Work.md index e28937383..fa7464dbd 100644 --- a/website/content/ChapterFour/0800~0899/0826.Most-Profit-Assigning-Work.md +++ b/website/content/ChapterFour/0800~0899/0826.Most-Profit-Assigning-Work.md @@ -109,6 +109,6 @@ func maxProfitAssignment(difficulty []int, profit []int, worker []int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0800~0899/0839.Similar-String-Groups.md b/website/content/ChapterFour/0800~0899/0839.Similar-String-Groups.md index ed2f22420..c369de1d9 100755 --- a/website/content/ChapterFour/0800~0899/0839.Similar-String-Groups.md +++ b/website/content/ChapterFour/0800~0899/0839.Similar-String-Groups.md @@ -66,7 +66,7 @@ We are given a list `A` of strings. Every string in `A` is an anagram of eve package leetcode import ( - "github.com/halfrost/LeetCode-Go/template" + "github.com/halfrost/leetcode-go/template" ) func numSimilarGroups(A []string) int { diff --git a/website/content/ChapterFour/0800~0899/0845.Longest-Mountain-in-Array.md b/website/content/ChapterFour/0800~0899/0845.Longest-Mountain-in-Array.md index d0270ed58..8854bef47 100644 --- a/website/content/ChapterFour/0800~0899/0845.Longest-Mountain-in-Array.md +++ b/website/content/ChapterFour/0800~0899/0845.Longest-Mountain-in-Array.md @@ -94,5 +94,5 @@ func longestMountain(A []int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0800~0899/0846.Hand-of-Straights.md b/website/content/ChapterFour/0800~0899/0846.Hand-of-Straights.md new file mode 100644 index 000000000..f26eb6cc6 --- /dev/null +++ b/website/content/ChapterFour/0800~0899/0846.Hand-of-Straights.md @@ -0,0 +1,75 @@ +# [846. Hand of Straights](https://leetcode.com/problems/hand-of-straights/) + +## 题目 + +Alice has some number of cards and she wants to rearrange the cards into groups so that each group is of size groupSize, and consists of groupSize consecutive cards. + +Given an integer array hand where hand[i] is the value written on the ith card and an integer groupSize, return true if she can rearrange the cards, or false otherwise. + +**Example 1**: + + Input: hand = [1,2,3,6,2,3,4,7,8], groupSize = 3 + Output: true + Explanation: Alice's hand can be rearranged as [1,2,3],[2,3,4],[6,7,8] + +**Example 2**: + + Input: hand = [1,2,3,4,5], groupSize = 4 + Output: false + Explanation: Alice's hand can not be rearranged into groups of 4. + +**Constraints:** + +- 1 <= hand.length <= 10000 +- 0 <= hand[i] <= 1000000000 +- 1 <= groupSize <= hand.length + +## 题目大意 + +Alice 手中有一把牌，她想要重新排列这些牌，分成若干组，使每一组的牌数都是 groupSize ，并且由 groupSize 张连续的牌组成。 + +给你一个整数数组 hand 其中 hand[i] 是写在第 i 张牌，和一个整数 groupSize 。如果她可能重新排列这些牌，返回 true ；否则，返回 false 。 + +## 解题思路 + +贪心算法 + +- 对hand升序排序 +- 对hand内数字进行哈希计数（key:数字，value:数量） +- 遍历hand中的数字，以数量大于1的数字作为顺子开头，寻找顺子后续元素，若无法找到完整顺子则返回false +- 所有数字都能找到完整顺子返回true + +##代码 + +```go +package leetcode + +import "sort" + +func isNStraightHand(hand []int, groupSize int) bool { + mp := make(map[int]int) + for _, v := range hand { + mp[v] += 1 + } + sort.Ints(hand) + for _, num := range hand { + if mp[num] == 0 { + continue + } + for diff := 0; diff < groupSize; diff++ { + if mp[num+diff] == 0 { + return false + } + mp[num+diff] -= 1 + } + } + return true +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0800~0899/0850.Rectangle-Area-II.md b/website/content/ChapterFour/0800~0899/0850.Rectangle-Area-II.md index 965f4da01..b16e51fe7 100755 --- a/website/content/ChapterFour/0800~0899/0850.Rectangle-Area-II.md +++ b/website/content/ChapterFour/0800~0899/0850.Rectangle-Area-II.md @@ -295,6 +295,6 @@ func (sat *SegmentAreaTree) updateInTree(treeIndex, left, right, updateLeft, upd ---------------------------------------------- diff --git a/website/content/ChapterFour/0800~0899/0856.Score-of-Parentheses.md b/website/content/ChapterFour/0800~0899/0856.Score-of-Parentheses.md index 1b7546caf..d94ee68f1 100644 --- a/website/content/ChapterFour/0800~0899/0856.Score-of-Parentheses.md +++ b/website/content/ChapterFour/0800~0899/0856.Score-of-Parentheses.md @@ -105,5 +105,5 @@ func scoreOfParentheses(S string) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0800~0899/0859.Buddy-Strings.md b/website/content/ChapterFour/0800~0899/0859.Buddy-Strings.md new file mode 100644 index 000000000..9c8ddd17f --- /dev/null +++ b/website/content/ChapterFour/0800~0899/0859.Buddy-Strings.md @@ -0,0 +1,94 @@ +# [859. Buddy Strings](https://leetcode.com/problems/buddy-strings/) + +## 题目 + +Given two strings s and goal, return true if you can swap two letters in s so the result is equal to goal, otherwise, return false. + +Swapping letters is defined as taking two indices i and j (0-indexed) such that i != j and swapping the characters at s[i] and s[j]. + +For example, swapping at indices 0 and 2 in "abcd" results in "cbad". + +**Example 1**: + + Input: s = "ab", goal = "ba" + Output: true + Explanation: You can swap s[0] = 'a' and s[1] = 'b' to get "ba", which is equal to goal. + +**Example 2**: + + Input: s = "ab", goal = "ab" + Output: false + Explanation: The only letters you can swap are s[0] = 'a' and s[1] = 'b', which results in "ba" != goal. + +**Example 3**: + + Input: s = "aa", goal = "aa" + Output: true + Explanation: You can swap s[0] = 'a' and s[1] = 'a' to get "aa", which is equal to goal. + +**Example 4**: + + Input: s = "aaaaaaabc", goal = "aaaaaaacb" + Output: true + +**Constraints:** + +- 1 <= s.length, goal.length <= 2 * 10000 +- s and goal consist of lowercase letters. + +## 题目大意 + +给你两个字符串 s 和 goal ，只要我们可以通过交换 s 中的两个字母得到与 goal 相等的结果，就返回 true；否则返回 false 。 + +交换字母的定义是：取两个下标 i 和 j （下标从 0 开始）且满足 i != j ，接着交换 s[i] 和 s[j] 处的字符。 + +例如，在 "abcd" 中交换下标 0 和下标 2 的元素可以生成 "cbad" 。 + +## 解题思路 + +分为两种情况进行比较: +- s 等于 goal, s 中有重复元素就返回 true,否则返回 false +- s 不等于 goal, s 中有两个下标不同的字符与 goal 中对应下标的字符分别相等 + +## 代码 + +```go + +package leetcode + +func buddyStrings(s string, goal string) bool { + if len(s) != len(goal) || len(s) <= 1 { + return false + } + mp := make(map[byte]int) + if s == goal { + for i := 0; i < len(s); i++ { + if _, ok := mp[s[i]]; ok { + return true + } + mp[s[i]]++ + } + return false + } + first, second := -1, -1 + for i := 0; i < len(s); i++ { + if s[i] != goal[i] { + if first == -1 { + first = i + } else if second == -1 { + second = i + } else { + return false + } + } + } + return second != -1 && s[first] == goal[second] && s[second] == goal[first] +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0800~0899/0862.Shortest-Subarray-with-Sum-at-Least-K.md b/website/content/ChapterFour/0800~0899/0862.Shortest-Subarray-with-Sum-at-Least-K.md index a1079dfda..0f0090725 100644 --- a/website/content/ChapterFour/0800~0899/0862.Shortest-Subarray-with-Sum-at-Least-K.md +++ b/website/content/ChapterFour/0800~0899/0862.Shortest-Subarray-with-Sum-at-Least-K.md @@ -92,6 +92,6 @@ func shortestSubarray(A []int, K int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0800~0899/0872.Leaf-Similar-Trees.md b/website/content/ChapterFour/0800~0899/0872.Leaf-Similar-Trees.md index ef245b90e..04f5b7f27 100644 --- a/website/content/ChapterFour/0800~0899/0872.Leaf-Similar-Trees.md +++ b/website/content/ChapterFour/0800~0899/0872.Leaf-Similar-Trees.md @@ -65,5 +65,5 @@ func dfsLeaf(root *TreeNode, leaf *[]int) { ---------------------------------------------- diff --git a/website/content/ChapterFour/0800~0899/0874.Walking-Robot-Simulation.md b/website/content/ChapterFour/0800~0899/0874.Walking-Robot-Simulation.md new file mode 100644 index 000000000..61df07cec --- /dev/null +++ b/website/content/ChapterFour/0800~0899/0874.Walking-Robot-Simulation.md @@ -0,0 +1,142 @@ +# [874. Walking Robot Simulation](https://leetcode.com/problems/walking-robot-simulation/) + + +## 题目 + +A robot on an infinite XY-plane starts at point `(0, 0)` and faces north. The robot can receive one of three possible types of `commands`: + +- `2`: turn left `90` degrees, +- `1`: turn right `90` degrees, or +- `1 <= k <= 9`: move forward `k` units. + +Some of the grid squares are `obstacles`. The `ith` obstacle is at grid point `obstacles[i] = (xi, yi)`. + +If the robot would try to move onto them, the robot stays on the previous grid square instead (but still continues following the rest of the route.) + +Return *the maximum Euclidean distance that the robot will be from the origin **squared** (i.e. if the distance is* `5`*, return* `25`*)*. + +**Note:** + +- North means +Y direction. +- East means +X direction. +- South means -Y direction. +- West means -X direction. + +**Example 1:** + +``` +Input: commands = [4,-1,3], obstacles = [] +Output: 25 +Explanation: The robot starts at (0, 0): +1. Move north 4 units to (0, 4). +2. Turn right. +3. Move east 3 units to (3, 4). +The furthest point away from the origin is (3, 4), which is 32 + 42 = 25 units away. + +``` + +**Example 2:** + +``` +Input: commands = [4,-1,4,-2,4], obstacles = [[2,4]] +Output: 65 +Explanation: The robot starts at (0, 0): +1. Move north 4 units to (0, 4). +2. Turn right. +3. Move east 1 unit and get blocked by the obstacle at (2, 4), robot is at (1, 4). +4. Turn left. +5. Move north 4 units to (1, 8). +The furthest point away from the origin is (1, 8), which is 12 + 82 = 65 units away. + +``` + +**Constraints:** + +- `1 <= commands.length <= 104` +- `commands[i]` is one of the values in the list `[-2,-1,1,2,3,4,5,6,7,8,9]`. +- `0 <= obstacles.length <= 104` +- `3 * 104 <= xi, yi <= 3 * 104` +- The answer is guaranteed to be less than `231`. + +## 题目大意 + +机器人在一个无限大小的 XY 网格平面上行走，从点 (0, 0) 处开始出发，面向北方。该机器人可以接收以下三种类型的命令 commands ： + +- 2 ：向左转 90 度 +- -1 ：向右转 90 度 +- 1 <= x <= 9 ：向前移动 x 个单位长度 + +在网格上有一些格子被视为障碍物 obstacles 。第 i 个障碍物位于网格点 obstacles[i] = (xi, yi) 。机器人无法走到障碍物上，它将会停留在障碍物的前一个网格方块上，但仍然可以继续尝试进行该路线的其余部分。返回从原点到机器人所有经过的路径点（坐标为整数）的最大欧式距离的平方。（即，如果距离为 5 ，则返回 25 ） + +注意： + +- 北表示 +Y 方向。 +- 东表示 +X 方向。 +- 南表示 -Y 方向。 +- 西表示 -X 方向。 + +## 解题思路 + +- 这个题的难点在于，怎么用编程语言去描述机器人的行为，可以用以下数据结构表达机器人的行为： + + ```go + direct:= 0 // direct表示机器人移动方向：0 1 2 3 4 （北东南西），默认朝北 + x, y := 0, 0 // 表示当前机器人所在横纵坐标位置，默认为(0,0) + directX := []int{0, 1, 0, -1} + directY := []int{1, 0, -1, 0} + // 组合directX directY和direct，表示机器人往某一个方向移动 + nextX := x + directX[direct] + nextY := y + directY[direct] + ``` + + 其他代码按照题意翻译即可 + +## 代码 + +```go +package leetcode + +func robotSim(commands []int, obstacles [][]int) int { + m := make(map[[2]int]struct{}) + for _, v := range obstacles { + if len(v) != 0 { + m[[2]int{v[0], v[1]}] = struct{}{} + } + } + directX := []int{0, 1, 0, -1} + directY := []int{1, 0, -1, 0} + direct, x, y := 0, 0, 0 + result := 0 + for _, c := range commands { + if c == -2 { + direct = (direct + 3) % 4 + continue + } + if c == -1 { + direct = (direct + 1) % 4 + continue + } + for ; c > 0; c-- { + nextX := x + directX[direct] + nextY := y + directY[direct] + if _, ok := m[[2]int{nextX, nextY}]; ok { + break + } + tmpResult := nextX*nextX + nextY*nextY + if tmpResult > result { + result = tmpResult + } + x = nextX + y = nextY + } + } + return result +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0800~0899/0875.Koko-Eating-Bananas.md b/website/content/ChapterFour/0800~0899/0875.Koko-Eating-Bananas.md index 0eeb2e409..734bf16d3 100755 --- a/website/content/ChapterFour/0800~0899/0875.Koko-Eating-Bananas.md +++ b/website/content/ChapterFour/0800~0899/0875.Koko-Eating-Bananas.md @@ -103,6 +103,6 @@ func maxInArr(xs []int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0800~0899/0876.Middle-of-the-Linked-List.md b/website/content/ChapterFour/0800~0899/0876.Middle-of-the-Linked-List.md index fb584c8d6..264d75801 100644 --- a/website/content/ChapterFour/0800~0899/0876.Middle-of-the-Linked-List.md +++ b/website/content/ChapterFour/0800~0899/0876.Middle-of-the-Linked-List.md @@ -85,5 +85,5 @@ func middleNode(head *ListNode) *ListNode { ---------------------------------------------- diff --git a/website/content/ChapterFour/0800~0899/0877.Stone-Game.md b/website/content/ChapterFour/0800~0899/0877.Stone-Game.md new file mode 100644 index 000000000..104eedb8f --- /dev/null +++ b/website/content/ChapterFour/0800~0899/0877.Stone-Game.md @@ -0,0 +1,57 @@ +# [877. Stone Game](https://leetcode.com/problems/stone-game/) + +## 题目 + +Alex and Lee play a game with piles of stones.  There are an even number of piles **arranged in a row**, and each pile has a positive integer number of stones `piles[i]`. + +The objective of the game is to end with the most stones.  The total number of stones is odd, so there are no ties. + +Alex and Lee take turns, with Alex starting first.  Each turn, a player takes the entire pile of stones from either the beginning or the end of the row.  This continues until there are no more piles left, at which point the person with the most stones wins. + +Assuming Alex and Lee play optimally, return `True` if and only if Alex wins the game. + +**Example 1:** + +``` +Input: piles = [5,3,4,5] +Output: true +Explanation: +Alex starts first, and can only take the first 5 or the last 5. +Say he takes the first 5, so that the row becomes [3, 4, 5]. +If Lee takes 3, then the board is [4, 5], and Alex takes 5 to win with 10 points. +If Lee takes the last 5, then the board is [3, 4], and Alex takes 4 to win with 9 points. +This demonstrated that taking the first 5 was a winning move for Alex, so we return true. + +``` + +**Constraints:** + +- `2 <= piles.length <= 500` +- `piles.length` is even. +- `1 <= piles[i] <= 500` +- `sum(piles)` is odd. + +## 题目大意 + +亚历克斯和李用几堆石子在做游戏。偶数堆石子排成一行，每堆都有正整数颗石子 piles[i] 。游戏以谁手中的石子最多来决出胜负。石子的总数是奇数，所以没有平局。亚历克斯和李轮流进行，亚历克斯先开始。 每回合，玩家从行的开始或结束处取走整堆石头。 这种情况一直持续到没有更多的石子堆为止，此时手中石子最多的玩家获胜。假设亚历克斯和李都发挥出最佳水平，当亚历克斯赢得比赛时返回 true ，当李赢得比赛时返回 false 。 + +## 解题思路 + +- 一遇到石子问题，很容易让人联想到是否和奇偶数相关。此题指定了石子堆数一定是偶数。所以从这里为突破口试试。Alex 先拿，要么取行首下标为 0 的石子，要么取行尾下标为 n-1 的石子。假设取下标为 0 的石子，剩下的石子堆下标从 1 ~ n-1，即 Lee 只能从奇数下标的石子堆 1 或者 n-1。假设 Alex 第一次取下标为 n-1 的石子，剩下的石子堆下标从 0 ~ n-2，即 Lee 只能取偶数下标的石子堆。于是 Alex 的必胜策略是每轮取石子，取此轮奇数下标堆石子数总和，偶数下标堆石子数总和，两者大者。那么下一轮 Lee 只能取石子堆数相对少的那一堆，并且 Lee 取的石子堆下标奇偶性是完全受到上一轮 Alex 控制的。所以只要是 Alex 先手，那么每轮都可以压制 Lee，从而必胜。 + +## 代码 + +```go +package leetcode + +func stoneGame(piles []int) bool { + return true +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0800~0899/0878.Nth-Magical-Number.md b/website/content/ChapterFour/0800~0899/0878.Nth-Magical-Number.md index ae40b10b2..18bad9d0e 100755 --- a/website/content/ChapterFour/0800~0899/0878.Nth-Magical-Number.md +++ b/website/content/ChapterFour/0800~0899/0878.Nth-Magical-Number.md @@ -83,6 +83,6 @@ func calNthMagicalCount(num, a, b int64) int64 { ---------------------------------------------- diff --git a/website/content/ChapterFour/0800~0899/0888.Fair-Candy-Swap.md b/website/content/ChapterFour/0800~0899/0888.Fair-Candy-Swap.md index 4c5a9e213..f47316529 100644 --- a/website/content/ChapterFour/0800~0899/0888.Fair-Candy-Swap.md +++ b/website/content/ChapterFour/0800~0899/0888.Fair-Candy-Swap.md @@ -113,5 +113,5 @@ func max(a, b int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0800~0899/0890.Find-and-Replace-Pattern.md b/website/content/ChapterFour/0800~0899/0890.Find-and-Replace-Pattern.md new file mode 100644 index 000000000..1931ae16a --- /dev/null +++ b/website/content/ChapterFour/0800~0899/0890.Find-and-Replace-Pattern.md @@ -0,0 +1,85 @@ +# [890. Find and Replace Pattern](https://leetcode.com/problems/find-and-replace-pattern/) + + +## 题目 + +Given a list of strings `words` and a string `pattern`, return *a list of* `words[i]` *that match* `pattern`. You may return the answer in **any order**. + +A word matches the pattern if there exists a permutation of letters `p` so that after replacing every letter `x` in the pattern with `p(x)`, we get the desired word. + +Recall that a permutation of letters is a bijection from letters to letters: every letter maps to another letter, and no two letters map to the same letter. + +**Example 1:** + +``` +Input: words = ["abc","deq","mee","aqq","dkd","ccc"], pattern = "abb" +Output: ["mee","aqq"] +Explanation: "mee" matches the pattern because there is a permutation {a -> m, b -> e, ...}. +"ccc" does not match the pattern because {a -> c, b -> c, ...} is not a permutation, since a and b map to the same letter. +``` + +**Example 2:** + +``` +Input: words = ["a","b","c"], pattern = "a" +Output: ["a","b","c"] +``` + +**Constraints:** + +- `1 <= pattern.length <= 20` +- `1 <= words.length <= 50` +- `words[i].length == pattern.length` +- `pattern` and `words[i]` are lowercase English letters. + +## 题目大意 + +你有一个单词列表 words 和一个模式  pattern，你想知道 words 中的哪些单词与模式匹配。如果存在字母的排列 p ，使得将模式中的每个字母 x 替换为 p(x) 之后，我们就得到了所需的单词，那么单词与模式是匹配的。（回想一下，字母的排列是从字母到字母的双射：每个字母映射到另一个字母，没有两个字母映射到同一个字母。）返回 words 中与给定模式匹配的单词列表。你可以按任何顺序返回答案。 + +## 解题思路 + +- 按照题目要求，分别映射两个字符串，words 字符串数组中的字符串与 pattern 字符串每个字母做映射。这里用 map 存储。题目还要求不存在 2 个字母映射到同一个字母的情况，所以再增加一个 map，用来判断当前字母是否已经被映射过了。以上 2 个条件都满足即代表模式匹配上了。最终将所有满足模式匹配的字符串输出即可。 + +## 代码 + +```go +package leetcode + +func findAndReplacePattern(words []string, pattern string) []string { + res := make([]string, 0) + for _, word := range words { + if match(word, pattern) { + res = append(res, word) + } + } + return res +} + +func match(w, p string) bool { + if len(w) != len(p) { + return false + } + m, used := make(map[uint8]uint8), make(map[uint8]bool) + for i := 0; i < len(w); i++ { + if v, ok := m[p[i]]; ok { + if w[i] != v { + return false + } + } else { + if used[w[i]] { + return false + } + m[p[i]] = w[i] + used[w[i]] = true + } + } + return true +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0800~0899/0891.Sum-of-Subsequence-Widths.md b/website/content/ChapterFour/0800~0899/0891.Sum-of-Subsequence-Widths.md index 7a75c0429..a0baf573d 100644 --- a/website/content/ChapterFour/0800~0899/0891.Sum-of-Subsequence-Widths.md +++ b/website/content/ChapterFour/0800~0899/0891.Sum-of-Subsequence-Widths.md @@ -70,6 +70,6 @@ func sumSubseqWidths(A []int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0900~0999/0907.Sum-of-Subarray-Minimums.md b/website/content/ChapterFour/0900~0999/0907.Sum-of-Subarray-Minimums.md index abf0341bb..1fd0096d1 100644 --- a/website/content/ChapterFour/0900~0999/0907.Sum-of-Subarray-Minimums.md +++ b/website/content/ChapterFour/0900~0999/0907.Sum-of-Subarray-Minimums.md @@ -127,5 +127,5 @@ func sumSubarrayMins2(A []int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0900~0999/0909.Snakes-and-Ladders.md b/website/content/ChapterFour/0900~0999/0909.Snakes-and-Ladders.md new file mode 100644 index 000000000..ebba1cb5d --- /dev/null +++ b/website/content/ChapterFour/0900~0999/0909.Snakes-and-Ladders.md @@ -0,0 +1,117 @@ +# [909. Snakes and Ladders](https://leetcode.com/problems/snakes-and-ladders/) + + +## 题目 + +On an N x N `board`, the numbers from `1` to `N*N` are written *boustrophedonically* **starting from the bottom left of the board**, and alternating direction each row.  For example, for a 6 x 6 board, the numbers are written as follows: + + +![](https://assets.leetcode.com/uploads/2018/09/23/snakes.png) + +You start on square `1` of the board (which is always in the last row and first column).  Each move, starting from square `x`, consists of the following: + +- You choose a destination square `S` with number `x+1`, `x+2`, `x+3`, `x+4`, `x+5`, or `x+6`, provided this number is `<= N*N`. + - (This choice simulates the result of a standard 6-sided die roll: ie., there are always **at most 6 destinations, regardless of the size of the board**.) +- If `S` has a snake or ladder, you move to the destination of that snake or ladder. Otherwise, you move to `S`. + +A board square on row `r` and column `c` has a "snake or ladder" if `board[r][c] != -1`.  The destination of that snake or ladder is `board[r][c]`. + +Note that you only take a snake or ladder at most once per move: if the destination to a snake or ladder is the start of another snake or ladder, you do **not** continue moving.  (For example, if the board is `[[4,-1],[-1,3]]`, and on the first move your destination square is `2`, then you finish your first move at `3`, because you do **not** continue moving to `4`.) + +Return the least number of moves required to reach square N*N.  If it is not possible, return `-1`. + +**Example 1:** + +``` +Input:[ +[-1,-1,-1,-1,-1,-1], +[-1,-1,-1,-1,-1,-1], +[-1,-1,-1,-1,-1,-1], +[-1,35,-1,-1,13,-1], +[-1,-1,-1,-1,-1,-1], +[-1,15,-1,-1,-1,-1]] +Output:4 +Explanation: +At the beginning, you start at square 1 [at row 5, column 0]. +You decide to move to square 2, and must take the ladder to square 15. +You then decide to move to square 17 (row 3, column 5), and must take the snake to square 13. +You then decide to move to square 14, and must take the ladder to square 35. +You then decide to move to square 36, ending the game. +It can be shown that you need at least 4 moves to reach the N*N-th square, so the answer is 4. + +``` + +**Note:** + +1. `2 <= board.length = board[0].length <= 20` +2. `board[i][j]` is between `1` and `N*N` or is equal to `1`. +3. The board square with number `1` has no snake or ladder. +4. The board square with number `N*N` has no snake or ladder. + +## 题目大意 + +N x N 的棋盘 board 上，按从 1 到 N*N 的数字给方格编号，编号 从左下角开始，每一行交替方向。r 行 c 列的棋盘，按前述方法编号，棋盘格中可能存在 “蛇” 或 “梯子”；如果 board[r][c] != -1，那个蛇或梯子的目的地将会是 board[r][c]。玩家从棋盘上的方格 1 （总是在最后一行、第一列）开始出发。每一回合，玩家需要从当前方格 x 开始出发，按下述要求前进：选定目标方格： + +- 选择从编号 x+1，x+2，x+3，x+4，x+5，或者 x+6 的方格中选出一个目标方格 s ，目标方格的编号 <= N*N。该选择模拟了掷骰子的情景，无论棋盘大小如何，你的目的地范围也只能处于区间 [x+1, x+6] 之间。 +- 传送玩家：如果目标方格 S 处存在蛇或梯子，那么玩家会传送到蛇或梯子的目的地。否则，玩家传送到目标方格 S。 + +注意，玩家在每回合的前进过程中最多只能爬过蛇或梯子一次：就算目的地是另一条蛇或梯子的起点，你也不会继续移动。返回达到方格 N*N 所需的最少移动次数，如果不可能，则返回 -1。 + +## 解题思路 + +- 这一题可以抽象为在有向图上求下标 1 的起点到下标 `N^2` 的终点的最短路径。用广度优先搜索。棋盘可以抽象成一个包含 `N^2` 个节点的有向图，对于每个节点 `x`，若 `x+i (1 ≤ i ≤ 6)` 上没有蛇或梯子，则连一条从 `x` 到 `x+i` 的有向边；否则记蛇梯的目的地为 `y`，连一条从 `x` 到 `y` 的有向边。然后按照最短路径的求解方式便可解题。时间复杂度 O(n^2)，空间复杂度 O(n^2)。 +- 此题棋盘上的下标是蛇形的，所以遍历下一个点的时候需要转换坐标。具体做法根据行的奇偶性，行号为偶数，下标从左往右，行号为奇数，下标从右往左。具体实现见 `getRowCol()` 函数。 + +## 代码 + +```go +package leetcode + +type pair struct { + id, step int +} + +func snakesAndLadders(board [][]int) int { + n := len(board) + visited := make([]bool, n*n+1) + queue := []pair{{1, 0}} + for len(queue) > 0 { + p := queue[0] + queue = queue[1:] + for i := 1; i <= 6; i++ { + nxt := p.id + i + if nxt > n*n { // 超出边界 + break + } + r, c := getRowCol(nxt, n) // 得到下一步的行列 + if board[r][c] > 0 { // 存在蛇或梯子 + nxt = board[r][c] + } + if nxt == n*n { // 到达终点 + return p.step + 1 + } + if !visited[nxt] { + visited[nxt] = true + queue = append(queue, pair{nxt, p.step + 1}) // 扩展新状态 + } + } + } + return -1 +} + +func getRowCol(id, n int) (r, c int) { + r, c = (id-1)/n, (id-1)%n + if r%2 == 1 { + c = n - 1 - c + } + r = n - 1 - r + return r, c +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0900~0999/0910.Smallest-Range-II.md b/website/content/ChapterFour/0900~0999/0910.Smallest-Range-II.md index 69ca991fb..1f9f33035 100644 --- a/website/content/ChapterFour/0900~0999/0910.Smallest-Range-II.md +++ b/website/content/ChapterFour/0900~0999/0910.Smallest-Range-II.md @@ -84,6 +84,6 @@ func min(a, b int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0900~0999/0918.Maximum-Sum-Circular-Subarray.md b/website/content/ChapterFour/0900~0999/0918.Maximum-Sum-Circular-Subarray.md index 24ae69763..955a68679 100755 --- a/website/content/ChapterFour/0900~0999/0918.Maximum-Sum-Circular-Subarray.md +++ b/website/content/ChapterFour/0900~0999/0918.Maximum-Sum-Circular-Subarray.md @@ -73,31 +73,55 @@ package leetcode import "math" -func maxSubarraySumCircular(A []int) int { - n, sum := len(A), 0 - for _, v := range A { - sum += v +func maxSubarraySumCircular(nums []int) int { + var max1, max2, sum int + + // case: no circulation + max1 = int(math.Inf(-1)) + l := len(nums) + for i := 0; i < l; i++ { + sum += nums[i] + if sum > max1 { + max1 = sum + } + if sum < 1 { + sum = 0 + } } - kad := kadane(A) - for i := 0; i < n; i++ { - A[i] = -A[i] + + // case: circling + arr_sum := 0 + for i := 0; i < l; i++ { + arr_sum += nums[i] } - negativeMax := kadane(A) - if sum+negativeMax <= 0 { - return kad + + sum = 0 + min_sum := 0 + for i := 1; i < l-1; i++ { + sum += nums[i] + if sum >= 0 { + sum = 0 + } + if sum < min_sum { + min_sum = sum + } } - return max(kad, sum+negativeMax) + max2 = arr_sum - min_sum + + return max(max1, max2) } -func kadane(a []int) int { - n, MaxEndingHere, maxSoFar := len(a), a[0], math.MinInt32 - for i := 1; i < n; i++ { - MaxEndingHere = max(a[i], MaxEndingHere+a[i]) - maxSoFar = max(MaxEndingHere, maxSoFar) +func max(nums ...int) int { + max := int(math.Inf(-1)) + for _, num := range nums { + if num > max { + max = num + } } - return maxSoFar + return max } + ``` diff --git a/website/content/ChapterFour/0900~0999/0924.Minimize-Malware-Spread.md b/website/content/ChapterFour/0900~0999/0924.Minimize-Malware-Spread.md index 8b4cf9351..b5835a932 100755 --- a/website/content/ChapterFour/0900~0999/0924.Minimize-Malware-Spread.md +++ b/website/content/ChapterFour/0900~0999/0924.Minimize-Malware-Spread.md @@ -67,7 +67,7 @@ package leetcode import ( "math" - "github.com/halfrost/LeetCode-Go/template" + "github.com/halfrost/leetcode-go/template" ) func minMalwareSpread(graph [][]int, initial []int) int { diff --git a/website/content/ChapterFour/0900~0999/0928.Minimize-Malware-Spread-II.md b/website/content/ChapterFour/0900~0999/0928.Minimize-Malware-Spread-II.md index 16819d5e9..ad047b303 100755 --- a/website/content/ChapterFour/0900~0999/0928.Minimize-Malware-Spread-II.md +++ b/website/content/ChapterFour/0900~0999/0928.Minimize-Malware-Spread-II.md @@ -70,7 +70,7 @@ package leetcode import ( "math" - "github.com/halfrost/LeetCode-Go/template" + "github.com/halfrost/leetcode-go/template" ) func minMalwareSpread2(graph [][]int, initial []int) int { diff --git a/website/content/ChapterFour/0900~0999/0938.Range-Sum-of-BST.md b/website/content/ChapterFour/0900~0999/0938.Range-Sum-of-BST.md index 861607673..a0c1644ec 100644 --- a/website/content/ChapterFour/0900~0999/0938.Range-Sum-of-BST.md +++ b/website/content/ChapterFour/0900~0999/0938.Range-Sum-of-BST.md @@ -46,7 +46,7 @@ Output: 23 package leetcode import ( - "github.com/halfrost/LeetCode-Go/structures" + "github.com/halfrost/leetcode-go/structures" ) // TreeNode define diff --git a/website/content/ChapterFour/0900~0999/0947.Most-Stones-Removed-with-Same-Row-or-Column.md b/website/content/ChapterFour/0900~0999/0947.Most-Stones-Removed-with-Same-Row-or-Column.md index 215f957ed..e19800760 100755 --- a/website/content/ChapterFour/0900~0999/0947.Most-Stones-Removed-with-Same-Row-or-Column.md +++ b/website/content/ChapterFour/0900~0999/0947.Most-Stones-Removed-with-Same-Row-or-Column.md @@ -55,7 +55,7 @@ What is the largest possible number of moves we can make? package leetcode import ( - "github.com/halfrost/LeetCode-Go/template" + "github.com/halfrost/leetcode-go/template" ) func removeStones(stones [][]int) int { diff --git a/website/content/ChapterFour/0900~0999/0952.Largest-Component-Size-by-Common-Factor.md b/website/content/ChapterFour/0900~0999/0952.Largest-Component-Size-by-Common-Factor.md index 48a6fda39..f40b90a1c 100755 --- a/website/content/ChapterFour/0900~0999/0952.Largest-Component-Size-by-Common-Factor.md +++ b/website/content/ChapterFour/0900~0999/0952.Largest-Component-Size-by-Common-Factor.md @@ -63,7 +63,7 @@ Return the size of the largest connected component in the graph. package leetcode import ( - "github.com/halfrost/LeetCode-Go/template" + "github.com/halfrost/leetcode-go/template" ) // 解法一 并查集 UnionFind diff --git a/website/content/ChapterFour/0900~0999/0953.Verifying-an-Alien-Dictionary.md b/website/content/ChapterFour/0900~0999/0953.Verifying-an-Alien-Dictionary.md index 5d922cbab..f50c0855a 100755 --- a/website/content/ChapterFour/0900~0999/0953.Verifying-an-Alien-Dictionary.md +++ b/website/content/ChapterFour/0900~0999/0953.Verifying-an-Alien-Dictionary.md @@ -84,5 +84,5 @@ func isAlienSorted(words []string, order string) bool { ---------------------------------------------- diff --git a/website/content/ChapterFour/0900~0999/0958.Check-Completeness-of-a-Binary-Tree.md b/website/content/ChapterFour/0900~0999/0958.Check-Completeness-of-a-Binary-Tree.md new file mode 100644 index 000000000..d9a30b23b --- /dev/null +++ b/website/content/ChapterFour/0900~0999/0958.Check-Completeness-of-a-Binary-Tree.md @@ -0,0 +1,96 @@ +# [958. Check Completeness of a Binary Tree](https://leetcode.com/problems/check-completeness-of-a-binary-tree/) + + +## 题目 + +Given the `root` of a binary tree, determine if it is a *complete binary tree*. + +In a **[complete binary tree](http://en.wikipedia.org/wiki/Binary_tree#Types_of_binary_trees)**, every level, except possibly the last, is completely filled, and all nodes in the last level are as far left as possible. It can have between `1` and `2h` nodes inclusive at the last level `h`. + +**Example 1:** + +![https://assets.leetcode.com/uploads/2018/12/15/complete-binary-tree-1.png](https://assets.leetcode.com/uploads/2018/12/15/complete-binary-tree-1.png) + +``` +Input: root = [1,2,3,4,5,6] +Output: true +Explanation: Every level before the last is full (ie. levels with node-values {1} and {2, 3}), and all nodes in the last level ({4, 5, 6}) are as far left as possible. + +``` + +**Example 2:** + +![https://assets.leetcode.com/uploads/2018/12/15/complete-binary-tree-2.png](https://assets.leetcode.com/uploads/2018/12/15/complete-binary-tree-2.png) + +``` +Input: root = [1,2,3,4,5,null,7] +Output: false +Explanation: The node with value 7 isn't as far left as possible. + +``` + +**Constraints:** + +- The number of nodes in the tree is in the range `[1, 100]`. +- `1 <= Node.val <= 1000` + +## 题目大意 + +给定一个二叉树，确定它是否是一个完全二叉树。 + +百度百科中对完全二叉树的定义如下： + +若设二叉树的深度为 h，除第 h 层外，其它各层 (1～h-1) 的结点数都达到最大个数，第 h 层所有的结点都连续集中在最左边，这就是完全二叉树。（注：第 h 层可能包含 1~ 2h 个节点。） + +## 解题思路 + +- 这一题是按层序遍历的变种题。 +- 判断每个节点的左孩子是否为空。 +- 类似的题目，第 102，107，199 题都是按层序遍历的。 + +## 代码 + +```go +package leetcode + +import ( + "github.com/halfrost/leetcode-go/structures" +) + +// TreeNode define +type TreeNode = structures.TreeNode + +/** + * Definition for a binary tree node. + * type TreeNode struct { + * Val int + * Left *TreeNode + * Right *TreeNode + * } + */ + +func isCompleteTree(root *TreeNode) bool { + queue, found := []*TreeNode{root}, false + for len(queue) > 0 { + node := queue[0] //取出每一层的第一个节点 + queue = queue[1:] + if node == nil { + found = true + } else { + if found { + return false // 层序遍历中，两个不为空的节点中出现一个 nil + } + //如果左孩子为nil，则append进去的node.Left为nil + queue = append(queue, node.Left, node.Right) + } + } + return true +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0900~0999/0959.Regions-Cut-By-Slashes.md b/website/content/ChapterFour/0900~0999/0959.Regions-Cut-By-Slashes.md index 5b6f13145..1aba869f9 100755 --- a/website/content/ChapterFour/0900~0999/0959.Regions-Cut-By-Slashes.md +++ b/website/content/ChapterFour/0900~0999/0959.Regions-Cut-By-Slashes.md @@ -105,7 +105,7 @@ Return the number of regions. package leetcode import ( - "github.com/halfrost/LeetCode-Go/template" + "github.com/halfrost/leetcode-go/template" ) func regionsBySlashes(grid []string) int { @@ -152,6 +152,6 @@ func getFaceIdx(size, i, j, k int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/0900~0999/0971.Flip-Binary-Tree-To-Match-Preorder-Traversal.md b/website/content/ChapterFour/0900~0999/0971.Flip-Binary-Tree-To-Match-Preorder-Traversal.md index 41795741e..5433a7ae8 100644 --- a/website/content/ChapterFour/0900~0999/0971.Flip-Binary-Tree-To-Match-Preorder-Traversal.md +++ b/website/content/ChapterFour/0900~0999/0971.Flip-Binary-Tree-To-Match-Preorder-Traversal.md @@ -66,7 +66,7 @@ Explanation: The tree's pre-order traversal already matches voyage, so no nodes package leetcode import ( - "github.com/halfrost/LeetCode-Go/structures" + "github.com/halfrost/leetcode-go/structures" ) // TreeNode define diff --git a/website/content/ChapterFour/0900~0999/0978.Longest-Turbulent-Subarray.md b/website/content/ChapterFour/0900~0999/0978.Longest-Turbulent-Subarray.md index bb760b0c0..58ff3044d 100755 --- a/website/content/ChapterFour/0900~0999/0978.Longest-Turbulent-Subarray.md +++ b/website/content/ChapterFour/0900~0999/0978.Longest-Turbulent-Subarray.md @@ -55,8 +55,7 @@ Return the **length** of a maximum size turbulent subarray of A. - 给出一个数组，要求找出“摆动数组”的最大长度。所谓“摆动数组”的意思是，元素一大一小间隔的。 -- 这一题可以用滑动窗口来解答。用一个变量记住下次出现的元素需要大于还是需要小于前一个元素。也可以用模拟的方法，用两个变量分别记录上升和下降数字的长度。一旦元素相等了，上升和下降数字长度都置为 1，其他时候按照上升和下降的关系增加队列长度即可，最后输出动态维护的最长长度。 - +- 这一题可以用滑动窗口来解答。用相邻元素差的乘积大于零（a ^ b >= 0 说明a b乘积大于零）来判断是否是湍流， 如果是，那么扩大窗口。否则窗口缩小为0，开始新的一个窗口。 ## 代码 @@ -65,14 +64,14 @@ Return the **length** of a maximum size turbulent subarray of A. package leetcode // 解法一 模拟法 -func maxTurbulenceSize(A []int) int { +func maxTurbulenceSize(arr []int) int { inc, dec := 1, 1 - maxLen := min(1, len(A)) - for i := 1; i < len(A); i++ { - if A[i-1] < A[i] { + maxLen := min(1, len(arr)) + for i := 1; i < len(arr); i++ { + if arr[i-1] < arr[i] { inc = dec + 1 dec = 1 - } else if A[i-1] > A[i] { + } else if arr[i-1] > arr[i] { dec = inc + 1 inc = 1 } else { @@ -85,25 +84,23 @@ func maxTurbulenceSize(A []int) int { } // 解法二 滑动窗口 -func maxTurbulenceSize1(A []int) int { - if len(A) == 1 { - return 1 +func maxTurbulenceSize1(arr []int) int { + var maxLength int + if len(arr) == 2 && arr[0] != arr[1] { + maxLength = 2 + } else { + maxLength = 1 } - // flag > 0 代表下一个数要大于前一个数，flag < 0 代表下一个数要小于前一个数 - res, left, right, flag, lastNum := 0, 0, 0, A[1]-A[0], A[0] - for left < len(A) { - if right < len(A)-1 && ((A[right+1] > lastNum && flag > 0) || (A[right+1] < lastNum && flag < 0) || (right == left)) { - right++ - flag = lastNum - A[right] - lastNum = A[right] - } else { - if flag != 0 { - res = max(res, right-left+1) - } - left++ + left := 0 + for right := 2; right < len(arr); right++ { + if arr[right] == arr[right-1] { + left = right + } else if (arr[right]-arr[right-1])^(arr[right-1]-arr[right-2]) >= 0 { + left = right - 1 } + maxLength = max(maxLength, right-left+1) } - return max(res, 1) + return maxLength } ``` diff --git a/website/content/ChapterFour/0900~0999/0987.Vertical-Order-Traversal-of-a-Binary-Tree.md b/website/content/ChapterFour/0900~0999/0987.Vertical-Order-Traversal-of-a-Binary-Tree.md index 9f6cd9321..aba6488b5 100644 --- a/website/content/ChapterFour/0900~0999/0987.Vertical-Order-Traversal-of-a-Binary-Tree.md +++ b/website/content/ChapterFour/0900~0999/0987.Vertical-Order-Traversal-of-a-Binary-Tree.md @@ -79,9 +79,10 @@ Note that the solution remains the same since 5 and 6 are in the same location a package leetcode import ( + "math" "sort" - "github.com/halfrost/LeetCode-Go/structures" + "github.com/halfrost/leetcode-go/structures" ) // TreeNode define @@ -101,40 +102,37 @@ type node struct { } func verticalTraversal(root *TreeNode) [][]int { - nodes := []*node{} - inorder(root, 0, 0, &nodes) - sort.Slice(nodes, func(i, j int) bool { - if nodes[i].y == nodes[j].y { - if nodes[i].x < nodes[j].x { - return true - } else if nodes[i].x > nodes[j].x { - return false - } - return nodes[i].val < nodes[j].val + var dfs func(root *TreeNode, x, y int) + var nodes []node + dfs = func(root *TreeNode, x, y int) { + if root == nil { + return } - return nodes[i].y < nodes[j].y + nodes = append(nodes, node{x, y, root.Val}) + dfs(root.Left, x+1, y-1) + dfs(root.Right, x+1, y+1) + } + dfs(root, 0, 0) + + sort.Slice(nodes, func(i, j int) bool { + a, b := nodes[i], nodes[j] + return a.y < b.y || a.y == b.y && + (a.x < b.x || a.x == b.x && a.val < b.val) }) - res, currY, currColumn := [][]int{}, nodes[0].y, []int{nodes[0].val} - for i := 1; i < len(nodes); i++ { - if currY == nodes[i].y { - currColumn = append(currColumn, nodes[i].val) + + var res [][]int + lastY := math.MinInt32 + for _, node := range nodes { + if lastY != node.y { + res = append(res, []int{node.val}) + lastY = node.y } else { - res = append(res, currColumn) - currColumn = []int{nodes[i].val} - currY = nodes[i].y + res[len(res)-1] = append(res[len(res)-1], node.val) } } - res = append(res, currColumn) return res } -func inorder(root *TreeNode, x, y int, nodes *[]*node) { - if root != nil { - *nodes = append(*nodes, &node{x, y, root.Val}) - inorder(root.Left, x+1, y-1, nodes) - inorder(root.Right, x+1, y+1, nodes) - } -} ``` diff --git a/website/content/ChapterFour/0900~0999/0990.Satisfiability-of-Equality-Equations.md b/website/content/ChapterFour/0900~0999/0990.Satisfiability-of-Equality-Equations.md index a2a795e97..bca338729 100755 --- a/website/content/ChapterFour/0900~0999/0990.Satisfiability-of-Equality-Equations.md +++ b/website/content/ChapterFour/0900~0999/0990.Satisfiability-of-Equality-Equations.md @@ -72,7 +72,7 @@ Return `true` if and only if it is possible to assign integers to variable nam package leetcode import ( - "github.com/halfrost/LeetCode-Go/template" + "github.com/halfrost/leetcode-go/template" ) func equationsPossible(equations []string) bool { diff --git a/website/content/ChapterFour/0900~0999/0996.Number-of-Squareful-Arrays.md b/website/content/ChapterFour/0900~0999/0996.Number-of-Squareful-Arrays.md index a003aafaf..c305fa181 100755 --- a/website/content/ChapterFour/0900~0999/0996.Number-of-Squareful-Arrays.md +++ b/website/content/ChapterFour/0900~0999/0996.Number-of-Squareful-Arrays.md @@ -110,5 +110,5 @@ func checkSquare(num int) bool { ---------------------------------------------- diff --git a/website/content/ChapterFour/0900~0999/0997.Find-the-Town-Judge.md b/website/content/ChapterFour/0900~0999/0997.Find-the-Town-Judge.md new file mode 100644 index 000000000..495f18cad --- /dev/null +++ b/website/content/ChapterFour/0900~0999/0997.Find-the-Town-Judge.md @@ -0,0 +1,94 @@ +# [997. Find the Town Judge](https://leetcode.com/problems/find-the-town-judge/) + +## 题目 + +In a town, there are n people labeled from 1 to n. There is a rumor that one of these people is secretly the town judge. + +If the town judge exists, then: + +- The town judge trusts nobody. +- Everybody (except for the town judge) trusts the town judge. +- There is exactly one person that satisfies properties 1 and 2. + +You are given an array trust where trust[i] = [ai, bi] representing that the person labeled ai trusts the person labeled bi. + +Return the label of the town judge if the town judge exists and can be identified, or return -1 otherwise. + +**Example 1**: + + Input: n = 2, trust = [[1,2]] + Output: 2 + +**Example 2**: + + Input: n = 3, trust = [[1,3],[2,3]] + Output: 3 + +**Example 3**: + + Input: n = 3, trust = [[1,3],[2,3],[3,1]] + Output: -1 + +**Constraints:** + +- 1 <= n <= 1000 +- 0 <= trust.length <= 10000 +- trust[i].length == 2 +- All the pairs of trust are unique. +- ai != bi +- 1 <= ai, bi <= n + +## 题目大意 + +小镇里有 n 个人，按从 1 到 n 的顺序编号。传言称，这些人中有一个暗地里是小镇法官。 + +如果小镇法官真的存在，那么： + +- 小镇法官不会信任任何人。 +- 每个人（除了小镇法官）都信任这位小镇法官。 +- 只有一个人同时满足属性 1 和属性 2 。 + +给你一个数组 trust ，其中 trust[i] = [ai, bi] 表示编号为 ai 的人信任编号为 bi 的人。 + +如果小镇法官存在并且可以确定他的身份，请返回该法官的编号；否则，返回 -1 。 + +## 解题思路 + +入度和出度统计 + +- 被人信任定义为入度, 信任别人定义为出度 +- 如果 1-n 之间有数字 x 的入度为 n - 1，出度为 0，则返回 x + +## 代码 + +```go +package leetcode + +func findJudge(n int, trust [][]int) int { + if n == 1 && len(trust) == 0 { + return 1 + } + judges := make(map[int]int) + for _, v := range trust { + judges[v[1]] += 1 + } + for _, v := range trust { + if _, ok := judges[v[0]]; ok { + delete(judges, v[0]) + } + } + for k, v := range judges { + if v == n-1 { + return k + } + } + return -1 +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/0900~0999/0999.Available-Captures-for-Rook.md b/website/content/ChapterFour/0900~0999/0999.Available-Captures-for-Rook.md index 1831514c0..8797ca961 100644 --- a/website/content/ChapterFour/0900~0999/0999.Available-Captures-for-Rook.md +++ b/website/content/ChapterFour/0900~0999/0999.Available-Captures-for-Rook.md @@ -101,6 +101,6 @@ func caputure(board [][]byte, x, y int, bx, by int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/1000~1099/1004.Max-Consecutive-Ones-III.md b/website/content/ChapterFour/1000~1099/1004.Max-Consecutive-Ones-III.md index c7c40384d..8731490ef 100644 --- a/website/content/ChapterFour/1000~1099/1004.Max-Consecutive-Ones-III.md +++ b/website/content/ChapterFour/1000~1099/1004.Max-Consecutive-Ones-III.md @@ -77,6 +77,13 @@ func longestOnes(A []int, K int) int { return res } +func max(a int, b int) int { + if a > b { + return a + } + return b +} + ``` diff --git a/website/content/ChapterFour/1000~1099/1006.Clumsy-Factorial.md b/website/content/ChapterFour/1000~1099/1006.Clumsy-Factorial.md index 5824903f6..737ec2205 100644 --- a/website/content/ChapterFour/1000~1099/1006.Clumsy-Factorial.md +++ b/website/content/ChapterFour/1000~1099/1006.Clumsy-Factorial.md @@ -48,7 +48,7 @@ Explanation:12 = 10 * 9 / 8 + 7 - 6 * 5 / 4 + 3 - 2 * 1 package leetcode func clumsy(N int) int { - res, count, tmp, flag := 0, 1, N, true + res, count, tmp, flag := 0, 1, N, false for i := N - 1; i > 0; i-- { count = count % 4 switch count { @@ -78,5 +78,5 @@ func clumsy(N int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/1000~1099/1009.Complement-of-Base-10-Integer.md b/website/content/ChapterFour/1000~1099/1009.Complement-of-Base-10-Integer.md new file mode 100644 index 000000000..b448d6c2b --- /dev/null +++ b/website/content/ChapterFour/1000~1099/1009.Complement-of-Base-10-Integer.md @@ -0,0 +1,74 @@ +# [1009. Complement of Base 10 Integer](https://leetcode.com/problems/complement-of-base-10-integer/) + + +## 题目 + +The **complement** of an integer is the integer you get when you flip all the `0`'s to `1`'s and all the `1`'s to `0`'s in its binary representation. + +- For example, The integer `5` is `"101"` in binary and its **complement** is `"010"` which is the integer `2`. + +Given an integer `n`, return *its complement*. + +**Example 1:** + +``` +Input: n = 5 +Output: 2 +Explanation: 5 is "101" in binary, with complement "010" in binary, which is 2 in base-10. + +``` + +**Example 2:** + +``` +Input: n = 7 +Output: 0 +Explanation: 7 is "111" in binary, with complement "000" in binary, which is 0 in base-10. + +``` + +**Example 3:** + +``` +Input: n = 10 +Output: 5 +Explanation: 10 is "1010" in binary, with complement "0101" in binary, which is 5 in base-10. + +``` + +**Constraints:** + +- `0 <= n < 109` + +## 题目大意 + +每个非负整数 N 都有其二进制表示。例如， 5 可以被表示为二进制 "101"，11 可以用二进制 "1011" 表示，依此类推。注意，除 N = 0 外，任何二进制表示中都不含前导零。 + +二进制的反码表示是将每个 1 改为 0 且每个 0 变为 1。例如，二进制数 "101" 的二进制反码为 "010"。 + +给你一个十进制数 N，请你返回其二进制表示的反码所对应的十进制整数。 + +## 解题思路 + +- 简单题。求一个十进制数的反码，只需要让该数和全 1 的数进行异或计算即可。所以本题重点在如何构造 mask 上。 + +## 代码 + +```go +package leetcode + +func bitwiseComplement(n int) int { + mask := 1 + for mask < n { + mask = (mask << 1) + 1 + } + return mask ^ n +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/1000~1099/1010.Pairs-of-Songs-With-Total-Durations-Divisible-by-60.md b/website/content/ChapterFour/1000~1099/1010.Pairs-of-Songs-With-Total-Durations-Divisible-by-60.md new file mode 100644 index 000000000..b8edb0ebb --- /dev/null +++ b/website/content/ChapterFour/1000~1099/1010.Pairs-of-Songs-With-Total-Durations-Divisible-by-60.md @@ -0,0 +1,70 @@ +# [1010. Pairs of Songs With Total Durations Divisible by 60](https://leetcode.com/problems/pairs-of-songs-with-total-durations-divisible-by-60/) + + +## 题目 + +You are given a list of songs where the ith song has a duration of `time[i]` seconds. + +Return *the number of pairs of songs for which their total duration in seconds is divisible by* `60`. Formally, we want the number of indices `i`, `j` such that `i < j` with `(time[i] + time[j]) % 60 == 0`. + +**Example 1:** + +``` +Input: time = [30,20,150,100,40] +Output: 3 +Explanation: Three pairs have a total duration divisible by 60: +(time[0] = 30, time[2] = 150): total duration 180 +(time[1] = 20, time[3] = 100): total duration 120 +(time[1] = 20, time[4] = 40): total duration 60 + +``` + +**Example 2:** + +``` +Input: time = [60,60,60] +Output: 3 +Explanation: All three pairs have a total duration of 120, which is divisible by 60. + +``` + +**Constraints:** + +- `1 <= time.length <= 6 * 104` +- `1 <= time[i] <= 500` + +## 题目大意 + +在歌曲列表中，第 i 首歌曲的持续时间为 time[i] 秒。 + +返回其总持续时间（以秒为单位）可被 60 整除的歌曲对的数量。形式上，我们希望下标数字 i 和 j 满足  i < j 且有 (time[i] + time[j]) % 60 == 0。 + +## 解题思路 + +- 简单题。先将数组每个元素对 60 取余，将它们都转换到 [0,59] 之间。然后在数组中找两两元素之和等于 60 的数对。可以在 0-30 之内对半查找符合条件的数对。对 0 和 30 单独计算。因为多个 0 相加，余数还为 0 。2 个 30 相加之和为 60。 + +## 代码 + +```go +func numPairsDivisibleBy60(time []int) int { + counts := make([]int, 60) + for _, v := range time { + v %= 60 + counts[v]++ + } + res := 0 + for i := 1; i < len(counts)/2; i++ { + res += counts[i] * counts[60-i] + } + res += (counts[0] * (counts[0] - 1)) / 2 + res += (counts[30] * (counts[30] - 1)) / 2 + return res +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/1000~1099/1011.Capacity-To-Ship-Packages-Within-D-Days.md b/website/content/ChapterFour/1000~1099/1011.Capacity-To-Ship-Packages-Within-D-Days.md index 8cd28a6c3..c812630ac 100755 --- a/website/content/ChapterFour/1000~1099/1011.Capacity-To-Ship-Packages-Within-D-Days.md +++ b/website/content/ChapterFour/1000~1099/1011.Capacity-To-Ship-Packages-Within-D-Days.md @@ -117,6 +117,6 @@ func calSum(mid, m int, nums []int) bool { ---------------------------------------------- diff --git a/website/content/ChapterFour/1000~1099/1019.Next-Greater-Node-In-Linked-List.md b/website/content/ChapterFour/1000~1099/1019.Next-Greater-Node-In-Linked-List.md index d54c4e035..a4f1ec424 100644 --- a/website/content/ChapterFour/1000~1099/1019.Next-Greater-Node-In-Linked-List.md +++ b/website/content/ChapterFour/1000~1099/1019.Next-Greater-Node-In-Linked-List.md @@ -70,29 +70,27 @@ package leetcode * Next *ListNode * } */ + // 解法一 单调栈 func nextLargerNodes(head *ListNode) []int { - res, indexes, nums := make([]int, 0), make([]int, 0), make([]int, 0) - p := head - for p != nil { - nums = append(nums, p.Val) - p = p.Next - } - for i := 0; i < len(nums); i++ { - res = append(res, 0) + type node struct { + index, val int } - for i := 0; i < len(nums); i++ { - num := nums[i] - for len(indexes) > 0 && nums[indexes[len(indexes)-1]] < num { - index := indexes[len(indexes)-1] - res[index] = num - indexes = indexes[:len(indexes)-1] + var monoStack []node + var res []int + for head != nil { + for len(monoStack) > 0 && monoStack[len(monoStack)-1].val < head.Val { + res[monoStack[len(monoStack)-1].index] = head.Val + monoStack = monoStack[:len(monoStack)-1] } - indexes = append(indexes, i) + monoStack = append(monoStack, node{len(res), head.Val}) + res = append(res, 0) + head = head.Next } return res } + ``` diff --git a/website/content/ChapterFour/1000~1099/1021.Remove-Outermost-Parentheses.md b/website/content/ChapterFour/1000~1099/1021.Remove-Outermost-Parentheses.md index d6ffcbd0a..7742aec2c 100644 --- a/website/content/ChapterFour/1000~1099/1021.Remove-Outermost-Parentheses.md +++ b/website/content/ChapterFour/1000~1099/1021.Remove-Outermost-Parentheses.md @@ -126,5 +126,5 @@ func removeOuterParentheses1(S string) string { ---------------------------------------------- diff --git a/website/content/ChapterFour/1000~1099/1022.Sum-of-Root-To-Leaf-Binary-Numbers.md b/website/content/ChapterFour/1000~1099/1022.Sum-of-Root-To-Leaf-Binary-Numbers.md new file mode 100644 index 000000000..299a22219 --- /dev/null +++ b/website/content/ChapterFour/1000~1099/1022.Sum-of-Root-To-Leaf-Binary-Numbers.md @@ -0,0 +1,61 @@ +# [1022. Sum of Root To Leaf Binary Numbers](https://leetcode.com/problems/sum-of-root-to-leaf-binary-numbers/) + +## 题目 + +You are given the root of a binary tree where each node has a value 0 or 1. Each root-to-leaf path represents a binary number starting with the most significant bit. + +For example, if the path is 0 -> 1 -> 1 -> 0 -> 1, then this could represent 01101 in binary, which is 13. +For all leaves in the tree, consider the numbers represented by the path from the root to that leaf. Return the sum of these numbers. + +The test cases are generated so that the answer fits in a 32-bits integer. + +**Example 1:** + +```c +Input: root = [1,0,1,0,1,0,1] +Output: 22 +Explanation: (100) + (101) + (110) + (111) = 4 + 5 + 6 + 7 = 22 +``` + +**Example 2:** + +```c +Input: root = [0] +Output: 0 +``` + +**Constraints:** + +- The number of nodes in the tree is in the range `[1, 1000]`. + +- `Node.val` is `0` or `1`. + + +## 题目大意 + +给定一棵结点值都是`0`或`1`的二叉树，每条从根结点到叶结点的路径都代表一个从最高有效位开始的二进制数。 + +返回从根节点到所有叶结点的路径所表示的数字之和。 + + +## 解题思路 + +采用递归的方式对根结点`root`进行后序遍历（左子树-右子树-根结点）。 + +**递归函数的返回值**： + +递归遍历每个结点时，计算从根结点到当前访问结点的所表示数值`sum`都用到了上次的计算结果，所以递归函数的返回值是当前访问结点的计算结果值。 + +**递归函数的逻辑**： + +- 当前遍历结点为`nil`，表示本层递归结束了，直接`return 0`。 + +- 如果当前访问结点是叶结点，则返回从根结点到该结点所表示的数值`sum`。 +- 如果当前访问结点不是叶结点，则返回左子树和右子树所对应的结果之和。 + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/1000~1099/1025.Divisor-Game.md b/website/content/ChapterFour/1000~1099/1025.Divisor-Game.md index 2183178d7..868900959 100755 --- a/website/content/ChapterFour/1000~1099/1025.Divisor-Game.md +++ b/website/content/ChapterFour/1000~1099/1025.Divisor-Game.md @@ -64,6 +64,6 @@ func divisorGame(N int) bool { ---------------------------------------------- diff --git a/website/content/ChapterFour/1000~1099/1030.Matrix-Cells-in-Distance-Order.md b/website/content/ChapterFour/1000~1099/1030.Matrix-Cells-in-Distance-Order.md index f71f5f8a7..a54d2fddd 100755 --- a/website/content/ChapterFour/1000~1099/1030.Matrix-Cells-in-Distance-Order.md +++ b/website/content/ChapterFour/1000~1099/1030.Matrix-Cells-in-Distance-Order.md @@ -87,5 +87,5 @@ func allCellsDistOrder(R int, C int, r0 int, c0 int) [][]int { ---------------------------------------------- diff --git a/website/content/ChapterFour/1000~1099/1034.Coloring-A-Border.md b/website/content/ChapterFour/1000~1099/1034.Coloring-A-Border.md new file mode 100644 index 000000000..cfcb67675 --- /dev/null +++ b/website/content/ChapterFour/1000~1099/1034.Coloring-A-Border.md @@ -0,0 +1,115 @@ +# [1034. Coloring A Border](https://leetcode.com/problems/coloring-a-border/) + +## 题目 + +You are given an m x n integer matrix grid, and three integers row, col, and color. Each value in the grid represents the color of the grid square at that location. + +Two squares belong to the same connected component if they have the same color and are next to each other in any of the 4 directions. + +The border of a connected component is all the squares in the connected component that are either 4-directionally adjacent to a square not in the component, or on the boundary of the grid (the first or last row or column). + +You should color the border of the connected component that contains the square grid[row][col] with color. + +Return the final grid. + +**Example 1**: + + Input: grid = [[1,1],[1,2]], row = 0, col = 0, color = 3 + Output: [[3,3],[3,2]] + +**Example 2**: + + Input: grid = [[1,2,2],[2,3,2]], row = 0, col = 1, color = 3 + Output: [[1,3,3],[2,3,3]] + +**Example 3**: + + Input: grid = [[1,1,1],[1,1,1],[1,1,1]], row = 1, col = 1, color = 2 + Output: [[2,2,2],[2,1,2],[2,2,2]] + +**Constraints:** + +- m == grid.length +- n == grid[i].length +- 1 <= m, n <= 50 +- 1 <= grid[i][j], color <= 1000 +- 0 <= row < m +- 0 <= col < n + +## 题目大意 + +给你一个大小为 m x n 的整数矩阵 grid ，表示一个网格。另给你三个整数 row、col 和 color 。网格中的每个值表示该位置处的网格块的颜色。 + +当两个网格块的颜色相同，而且在四个方向中任意一个方向上相邻时，它们属于同一连通分量 + +边界：在连通分量的块中（前提）并且满足以下条件之一： +（1）要么上下左右存在一个块不在连通分量里面 +（2）要么这个块的位置在整个grid的边框上 + +请你使用指定颜色 color 为所有包含网格块 grid[row][col] 的连通分量的边界进行着色，并返回最终的网格 grid 。 + +## 解题思路 + +- 用 bfs 进行遍历选出边界，使用 color 给边界着色 + +## 代码 + +```go +package leetcode + +type point struct { + x int + y int +} + +type gridInfo struct { + m int + n int + grid [][]int + originalColor int +} + +func colorBorder(grid [][]int, row, col, color int) [][]int { + m, n := len(grid), len(grid[0]) + dirs := []point{{1, 0}, {-1, 0}, {0, 1}, {0, -1}} + vis := make([][]bool, m) + for i := range vis { + vis[i] = make([]bool, n) + } + var borders []point + gInfo := gridInfo{ + m: m, + n: n, + grid: grid, + originalColor: grid[row][col], + } + dfs(row, col, gInfo, dirs, vis, &borders) + for _, p := range borders { + grid[p.x][p.y] = color + } + return grid +} + +func dfs(x, y int, gInfo gridInfo, dirs []point, vis [][]bool, borders *[]point) { + vis[x][y] = true + isBorder := false + for _, dir := range dirs { + nx, ny := x+dir.x, y+dir.y + if !(0 <= nx && nx < gInfo.m && 0 <= ny && ny < gInfo.n && gInfo.grid[nx][ny] == gInfo.originalColor) { + isBorder = true + } else if !vis[nx][ny] { + dfs(nx, ny, gInfo, dirs, vis, borders) + } + } + if isBorder { + *borders = append(*borders, point{x, y}) + } +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/1000~1099/1037.Valid-Boomerang.md b/website/content/ChapterFour/1000~1099/1037.Valid-Boomerang.md index eb1940040..d01462887 100644 --- a/website/content/ChapterFour/1000~1099/1037.Valid-Boomerang.md +++ b/website/content/ChapterFour/1000~1099/1037.Valid-Boomerang.md @@ -51,6 +51,6 @@ func isBoomerang(points [][]int) bool { ---------------------------------------------- diff --git a/website/content/ChapterFour/1000~1099/1038.Binary-Search-Tree-to-Greater-Sum-Tree.md b/website/content/ChapterFour/1000~1099/1038.Binary-Search-Tree-to-Greater-Sum-Tree.md index 68d9737ef..31c0a5142 100644 --- a/website/content/ChapterFour/1000~1099/1038.Binary-Search-Tree-to-Greater-Sum-Tree.md +++ b/website/content/ChapterFour/1000~1099/1038.Binary-Search-Tree-to-Greater-Sum-Tree.md @@ -71,7 +71,7 @@ Output: [7,9,4,10] package leetcode import ( - "github.com/halfrost/LeetCode-Go/structures" + "github.com/halfrost/leetcode-go/structures" ) // TreeNode define diff --git a/website/content/ChapterFour/1000~1099/1047.Remove-All-Adjacent-Duplicates-In-String.md b/website/content/ChapterFour/1000~1099/1047.Remove-All-Adjacent-Duplicates-In-String.md index 22e3764f6..5508dc6ff 100644 --- a/website/content/ChapterFour/1000~1099/1047.Remove-All-Adjacent-Duplicates-In-String.md +++ b/website/content/ChapterFour/1000~1099/1047.Remove-All-Adjacent-Duplicates-In-String.md @@ -60,5 +60,5 @@ func removeDuplicates1047(S string) string { ---------------------------------------------- diff --git a/website/content/ChapterFour/1000~1099/1048.Longest-String-Chain.md b/website/content/ChapterFour/1000~1099/1048.Longest-String-Chain.md new file mode 100644 index 000000000..703bf3794 --- /dev/null +++ b/website/content/ChapterFour/1000~1099/1048.Longest-String-Chain.md @@ -0,0 +1,103 @@ +# [1048. Longest String Chain](https://leetcode.com/problems/longest-string-chain/) + + +## 题目 + +Given a list of words, each word consists of English lowercase letters. + +Let's say `word1` is a predecessor of `word2` if and only if we can add exactly one letter anywhere in `word1` to make it equal to `word2`. For example, `"abc"` is a predecessor of `"abac"`. + +A *word chain* is a sequence of words `[word_1, word_2, ..., word_k]` with `k >= 1`, where `word_1` is a predecessor of `word_2`, `word_2` is a predecessor of `word_3`, and so on. + +Return the longest possible length of a word chain with words chosen from the given list of `words`. + +**Example 1:** + +``` +Input: words = ["a","b","ba","bca","bda","bdca"] +Output: 4 +Explanation: One of the longest word chain is "a","ba","bda","bdca". +``` + +**Example 2:** + +``` +Input: words = ["xbc","pcxbcf","xb","cxbc","pcxbc"] +Output: 5 +``` + +**Constraints:** + +- `1 <= words.length <= 1000` +- `1 <= words[i].length <= 16` +- `words[i]` only consists of English lowercase letters. + +## 题目大意 + +给出一个单词列表，其中每个单词都由小写英文字母组成。如果我们可以在 word1 的任何地方添加一个字母使其变成 word2，那么我们认为 word1 是 word2 的前身。例如，"abc" 是 "abac" 的前身。词链是单词 [word_1, word_2, ..., word_k] 组成的序列，k >= 1，其中 word_1 是 word_2 的前身，word_2 是 word_3 的前身，依此类推。从给定单词列表 words 中选择单词组成词链，返回词链的最长可能长度。 + +## 解题思路 + +- 从这题的数据规模上分析，可以猜出此题是 DFS 或者 DP 的题。简单暴力的方法是以每个字符串为链条的起点开始枚举之后的字符串，两两判断能否构成满足题意的前身字符串。这种做法包含很多重叠子问题，例如 a 和 b 能构成前身字符串，以 c 为起点的字符串链条可能用到 a 和 b，以 d 为起点的字符串链条也可能用到 a 和 b。顺其自然，考虑用 DP 的思路解题。 +- 先将 words 字符串数组排序，然后用 poss 数组记录下每种长度字符串的在排序数组中的起始下标。然后逆序往前递推。因为初始条件只能得到以最长字符串为起始的字符串链长度为 1 。每选择一个起始字符串，从它的长度 + 1 的每个字符串 j 开始比较，是否能为其前身字符串。如果能构成前身字符串，那么 dp[i] = max(dp[i], 1+dp[j])。最终递推到下标为 0 的字符串。最终输出整个递推过程中的最大长度即为所求。 + +## 代码 + +```go +package leetcode + +import "sort" + +func longestStrChain(words []string) int { + sort.Slice(words, func(i, j int) bool { return len(words[i]) < len(words[j]) }) + poss, res := make([]int, 16+2), 0 + for i, w := range words { + if poss[len(w)] == 0 { + poss[len(w)] = i + } + } + dp := make([]int, len(words)) + for i := len(words) - 1; i >= 0; i-- { + dp[i] = 1 + for j := poss[len(words[i])+1]; j < len(words) && len(words[j]) == len(words[i])+1; j++ { + if isPredecessor(words[j], words[i]) { + dp[i] = max(dp[i], 1+dp[j]) + } + } + res = max(res, dp[i]) + } + return res +} + +func max(a, b int) int { + if a > b { + return a + } + return b +} + +func isPredecessor(long, short string) bool { + i, j := 0, 0 + wasMismatch := false + for j < len(short) { + if long[i] != short[j] { + if wasMismatch { + return false + } + wasMismatch = true + i++ + continue + } + i++ + j++ + } + return true +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/1000~1099/1049.Last-Stone-Weight-II.md b/website/content/ChapterFour/1000~1099/1049.Last-Stone-Weight-II.md index 5cb48f000..4645224f1 100755 --- a/website/content/ChapterFour/1000~1099/1049.Last-Stone-Weight-II.md +++ b/website/content/ChapterFour/1000~1099/1049.Last-Stone-Weight-II.md @@ -81,6 +81,6 @@ func lastStoneWeightII(stones []int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/1000~1099/1093.Statistics-from-a-Large-Sample.md b/website/content/ChapterFour/1000~1099/1093.Statistics-from-a-Large-Sample.md index 32b84b815..39779662f 100755 --- a/website/content/ChapterFour/1000~1099/1093.Statistics-from-a-Large-Sample.md +++ b/website/content/ChapterFour/1000~1099/1093.Statistics-from-a-Large-Sample.md @@ -101,5 +101,5 @@ func sampleStats(count []int) []float64 { ---------------------------------------------- diff --git a/website/content/ChapterFour/1100~1199/1104.Path-In-Zigzag-Labelled-Binary-Tree.md b/website/content/ChapterFour/1100~1199/1104.Path-In-Zigzag-Labelled-Binary-Tree.md new file mode 100644 index 000000000..05076ee8d --- /dev/null +++ b/website/content/ChapterFour/1100~1199/1104.Path-In-Zigzag-Labelled-Binary-Tree.md @@ -0,0 +1,99 @@ +# [1104. Path In Zigzag Labelled Binary Tree](https://leetcode.com/problems/path-in-zigzag-labelled-binary-tree/) + + +## 题目 + +In an infinite binary tree where every node has two children, the nodes are labelled in row order. + +In the odd numbered rows (ie., the first, third, fifth,...), the labelling is left to right, while in the even numbered rows (second, fourth, sixth,...), the labelling is right to left. + +![https://assets.leetcode.com/uploads/2019/06/24/tree.png](https://assets.leetcode.com/uploads/2019/06/24/tree.png) + +Given the `label` of a node in this tree, return the labels in the path from the root of the tree to the node with that `label`. + +**Example 1:** + +``` +Input: label = 14 +Output: [1,3,4,14] + +``` + +**Example 2:** + +``` +Input: label = 26 +Output: [1,2,6,10,26] + +``` + +**Constraints:** + +- `1 <= label <= 10^6` + +## 题目大意 + +在一棵无限的二叉树上，每个节点都有两个子节点，树中的节点 逐行 依次按 “之” 字形进行标记。如下图所示，在奇数行（即，第一行、第三行、第五行……）中，按从左到右的顺序进行标记；而偶数行（即，第二行、第四行、第六行……）中，按从右到左的顺序进行标记。 + +给你树上某一个节点的标号 label，请你返回从根节点到该标号为 label 节点的路径，该路径是由途经的节点标号所组成的。 + +## 解题思路 + +- 计算出 label 所在的 level 和 index。 +- 根据 index 和 level 计算出父节点的 index 和 value。 +- level 减一，循环计算出对应的父节点直到根节点。 + +## 代码 + +```go +package leetcode + +func pathInZigZagTree(label int) []int { + level := getLevel(label) + ans := []int{label} + curIndex := label - (1 << level) + parent := 0 + for level >= 1 { + parent, curIndex = getParent(curIndex, level) + ans = append(ans, parent) + level-- + } + ans = reverse(ans) + return ans +} + +func getLevel(label int) int { + level := 0 + nums := 0 + for { + nums += 1 << level + if nums >= label { + return level + } + level++ + } +} + +func getParent(index int, level int) (parent int, parentIndex int) { + parentIndex = 1<<(level-1) - 1 + (index/2)*(-1) + parent = 1<<(level-1) + parentIndex + return +} + +func reverse(nums []int) []int { + left, right := 0, len(nums)-1 + for left < right { + nums[left], nums[right] = nums[right], nums[left] + left++ + right-- + } + return nums +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/1100~1199/1105.Filling-Bookcase-Shelves.md b/website/content/ChapterFour/1100~1199/1105.Filling-Bookcase-Shelves.md index f7a5f422a..8a914c8d0 100755 --- a/website/content/ChapterFour/1100~1199/1105.Filling-Bookcase-Shelves.md +++ b/website/content/ChapterFour/1100~1199/1105.Filling-Bookcase-Shelves.md @@ -70,6 +70,6 @@ func minHeightShelves(books [][]int, shelfWidth int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/1100~1199/1178.Number-of-Valid-Words-for-Each-Puzzle.md b/website/content/ChapterFour/1100~1199/1178.Number-of-Valid-Words-for-Each-Puzzle.md index 0e065a56e..bf708bb7d 100644 --- a/website/content/ChapterFour/1100~1199/1178.Number-of-Valid-Words-for-Each-Puzzle.md +++ b/website/content/ChapterFour/1100~1199/1178.Number-of-Valid-Words-for-Each-Puzzle.md @@ -68,13 +68,14 @@ There're no valid words for "gaswxyz" cause none of the words in the list cont ## 代码 ```go + package leetcode /* - 匹配跟单词中的字母顺序，字母个数都无关，可以用bitmap压缩 - 1. 记录word中 利用map记录各种bit标示的个数 - 2. puzzles 中各个字母都不相同! 记录bitmap，然后搜索子空间中各种bit标识的个数的和 - 因为puzzles长度最长是7，所以搜索空间 2^7 + 匹配跟单词中的字母顺序，字母个数都无关，可以用 bitmap 压缩 + 1. 记录 word 中 利用 map 记录各种 bit 标示的个数 + 2. puzzles 中各个字母都不相同! 记录 bitmap，然后搜索子空间中各种 bit 标识的个数的和 + 因为 puzzles 长度最长是7，所以搜索空间 2^7 */ func findNumOfValidWords(words []string, puzzles []string) []int { wordBitStatusMap, res := make(map[uint32]int, 0), []int{} @@ -84,7 +85,7 @@ func findNumOfValidWords(words []string, puzzles []string) []int { for _, p := range puzzles { var bitMap uint32 var totalNum int - bitMap |= (1 << (p[0] - 'a')) //work中要包含 p 的第一个字母 所以这个bit位上必须是1 + bitMap |= (1 << (p[0] - 'a')) //work 中要包含 p 的第一个字母 所以这个 bit 位上必须是 1 findNum([]byte(p)[1:], bitMap, &totalNum, wordBitStatusMap) res = append(res, totalNum) } @@ -99,20 +100,22 @@ func toBitMap(word []byte) uint32 { return res } -//利用dfs 搜索 pussles的子空间 +//利用 dfs 搜索 puzzles 的子空间 func findNum(puzzles []byte, bitMap uint32, totalNum *int, m map[uint32]int) { if len(puzzles) == 0 { *totalNum = *totalNum + m[bitMap] return } - //不包含puzzles[0],即puzzles[0]对应bit是0 + //不包含 puzzles[0],即 puzzles[0] 对应 bit 是 0 findNum(puzzles[1:], bitMap, totalNum, m) - //包含puzzles[0],即puzzles[0]对应bit是1 + //包含 puzzles[0],即 puzzles[0] 对应 bit 是 1 bitMap |= (1 << (puzzles[0] - 'a')) findNum(puzzles[1:], bitMap, totalNum, m) bitMap ^= (1 << (puzzles[0] - 'a')) //异或 清零 return } + + ``` diff --git a/website/content/ChapterFour/1100~1199/1189.Maximum-Number-of-Balloons.md b/website/content/ChapterFour/1100~1199/1189.Maximum-Number-of-Balloons.md index 22cf634d1..ed9b096d8 100755 --- a/website/content/ChapterFour/1100~1199/1189.Maximum-Number-of-Balloons.md +++ b/website/content/ChapterFour/1100~1199/1189.Maximum-Number-of-Balloons.md @@ -73,5 +73,5 @@ func maxNumberOfBalloons(text string) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/1100~1199/1190.Reverse-Substrings-Between-Each-Pair-of-Parentheses.md b/website/content/ChapterFour/1100~1199/1190.Reverse-Substrings-Between-Each-Pair-of-Parentheses.md new file mode 100644 index 000000000..0e9fdafc6 --- /dev/null +++ b/website/content/ChapterFour/1100~1199/1190.Reverse-Substrings-Between-Each-Pair-of-Parentheses.md @@ -0,0 +1,91 @@ +# [1190. Reverse Substrings Between Each Pair of Parentheses](https://leetcode.com/problems/reverse-substrings-between-each-pair-of-parentheses/) + + +## 题目 + +You are given a string `s` that consists of lower case English letters and brackets. + +Reverse the strings in each pair of matching parentheses, starting from the innermost one. + +Your result should **not** contain any brackets. + +**Example 1:** + +``` +Input: s = "(abcd)" +Output: "dcba" +``` + +**Example 2:** + +``` +Input: s = "(u(love)i)" +Output: "iloveu" +Explanation: The substring "love" is reversed first, then the whole string is reversed. +``` + +**Example 3:** + +``` +Input: s = "(ed(et(oc))el)" +Output: "leetcode" +Explanation: First, we reverse the substring "oc", then "etco", and finally, the whole string. +``` + +**Example 4:** + +``` +Input: s = "a(bcdefghijkl(mno)p)q" +Output: "apmnolkjihgfedcbq" +``` + +**Constraints:** + +- `0 <= s.length <= 2000` +- `s` only contains lower case English characters and parentheses. +- It's guaranteed that all parentheses are balanced. + +## 题目大意 + +给出一个字符串 s（仅含有小写英文字母和括号）。请你按照从括号内到外的顺序，逐层反转每对匹配括号中的字符串，并返回最终的结果。注意，您的结果中 不应 包含任何括号。 + +## 解题思路 + +- 本题最容易想到的思路是利用栈将每对括号里面的字符串入栈，当遇到 ")" 括号时出栈并逆序。由于用到了栈的数据结构，多层括号嵌套的问题也不用担心。这种边入栈出栈，逆序字符串的方法，时间复杂度是 O(n^2)，有没有可能进一步降低时间复杂度呢？ +- 上述解法中，存在重复遍历的情况。扫描原字符串的时候，入栈出栈已经扫描了一次，在 ")" 括号出栈时，逆序又会扫一遍已经入栈的字符串。这部分重复遍历的过程可以优化掉。第一次循环先标记出逆序区间。例如遇到 "(" 的时候，入栈并记录下它的下标，当遇到 ")" 的时候，意味着这一对括号匹配上了，所以将 ")" 的下标和之前入栈 "(" 的下标交换。此次遍历将逆序区间标记出来了。再遍历一次，根据逆序区间逆序字符串。不在逆序区间的字符串正常 append。如果在逆序区间内的，逆序遍历，添加到最终结果字符串中。这样做，时间复杂度仅为 O(n)。具体实现见下面代码。 + +## 代码 + +```go +package leetcode + +func reverseParentheses(s string) string { + pair, stack := make([]int, len(s)), []int{} + for i, b := range s { + if b == '(' { + stack = append(stack, i) + } else if b == ')' { + j := stack[len(stack)-1] + stack = stack[:len(stack)-1] + pair[i], pair[j] = j, i + } + } + res := []byte{} + for i, step := 0, 1; i < len(s); i += step { + if s[i] == '(' || s[i] == ')' { + i = pair[i] + step = -step + } else { + res = append(res, s[i]) + } + } + return string(res) +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/1200~1299/1200.Minimum-Absolute-Difference.md b/website/content/ChapterFour/1200~1299/1200.Minimum-Absolute-Difference.md index f23995fbd..cfc42996d 100755 --- a/website/content/ChapterFour/1200~1299/1200.Minimum-Absolute-Difference.md +++ b/website/content/ChapterFour/1200~1299/1200.Minimum-Absolute-Difference.md @@ -79,6 +79,6 @@ func minimumAbsDifference(arr []int) [][]int { ---------------------------------------------- diff --git a/website/content/ChapterFour/1200~1299/1202.Smallest-String-With-Swaps.md b/website/content/ChapterFour/1200~1299/1202.Smallest-String-With-Swaps.md index 32b06cb98..da9f6cc3b 100755 --- a/website/content/ChapterFour/1200~1299/1202.Smallest-String-With-Swaps.md +++ b/website/content/ChapterFour/1200~1299/1202.Smallest-String-With-Swaps.md @@ -72,7 +72,7 @@ package leetcode import ( "sort" - "github.com/halfrost/LeetCode-Go/template" + "github.com/halfrost/leetcode-go/template" ) func smallestStringWithSwaps(s string, pairs [][]int) string { diff --git a/website/content/ChapterFour/1200~1299/1235.Maximum-Profit-in-Job-Scheduling.md b/website/content/ChapterFour/1200~1299/1235.Maximum-Profit-in-Job-Scheduling.md index 29a1644b0..ca4826f49 100755 --- a/website/content/ChapterFour/1200~1299/1235.Maximum-Profit-in-Job-Scheduling.md +++ b/website/content/ChapterFour/1200~1299/1235.Maximum-Profit-in-Job-Scheduling.md @@ -121,5 +121,5 @@ func (s sortJobs) Swap(i, j int) { ---------------------------------------------- diff --git a/website/content/ChapterFour/1200~1299/1239.Maximum-Length-of-a-Concatenated-String-with-Unique-Characters.md b/website/content/ChapterFour/1200~1299/1239.Maximum-Length-of-a-Concatenated-String-with-Unique-Characters.md new file mode 100644 index 000000000..86d530b44 --- /dev/null +++ b/website/content/ChapterFour/1200~1299/1239.Maximum-Length-of-a-Concatenated-String-with-Unique-Characters.md @@ -0,0 +1,95 @@ +# [1239. Maximum Length of a Concatenated String with Unique Characters](https://leetcode.com/problems/maximum-length-of-a-concatenated-string-with-unique-characters/) + +## 题目 + +Given an array of strings `arr`. String `s` is a concatenation of a sub-sequence of `arr` which have **unique characters**. + +Return *the maximum possible length* of `s`. + +**Example 1:** + +``` +Input: arr = ["un","iq","ue"] +Output: 4 +Explanation: All possible concatenations are "","un","iq","ue","uniq" and "ique". +Maximum length is 4. +``` + +**Example 2:** + +``` +Input: arr = ["cha","r","act","ers"] +Output: 6 +Explanation: Possible solutions are "chaers" and "acters". +``` + +**Example 3:** + +``` +Input: arr = ["abcdefghijklmnopqrstuvwxyz"] +Output: 26 +``` + +**Constraints:** + +- `1 <= arr.length <= 16` +- `1 <= arr[i].length <= 26` +- `arr[i]` contains only lower case English letters. + +## 题目大意 + +给定一个字符串数组 arr，字符串 s 是将 arr 某一子序列字符串连接所得的字符串，如果 s 中的每一个字符都只出现过一次，那么它就是一个可行解。请返回所有可行解 s 中最长长度。 + +## 解题思路 + +- 每个字符串数组可以想象为 26 位的 0101 二进制串。出现的字符对应的位上标记为 1，没有出现的字符对应的位上标记为 0 。如果一个字符串中包含重复的字符，那么它所有 1 的个数一定不等于字符串的长度。如果 2 个字符串每个字母都只出现了一次，那么它们俩对应的二进制串 mask 相互与运算的结果一定为 0 ，即 0，1 互补了。利用这个特点，深搜所有解，保存出最长可行解的长度即可。 + +## 代码 + +```go +package leetcode + +import ( + "math/bits" +) + +func maxLength(arr []string) int { + c, res := []uint32{}, 0 + for _, s := range arr { + var mask uint32 + for _, c := range s { + mask = mask | 1<<(c-'a') + } + if len(s) != bits.OnesCount32(mask) { // 如果字符串本身带有重复的字符，需要排除 + continue + } + c = append(c, mask) + } + dfs(c, 0, 0, &res) + return res +} + +func dfs(c []uint32, index int, mask uint32, res *int) { + *res = max(*res, bits.OnesCount32(mask)) + for i := index; i < len(c); i++ { + if mask&c[i] == 0 { + dfs(c, i+1, mask|c[i], res) + } + } + return +} + +func max(a, b int) int { + if a > b { + return a + } + return b +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/1200~1299/1249.Minimum-Remove-to-Make-Valid-Parentheses.md b/website/content/ChapterFour/1200~1299/1249.Minimum-Remove-to-Make-Valid-Parentheses.md index 95889e348..c1936b889 100644 --- a/website/content/ChapterFour/1200~1299/1249.Minimum-Remove-to-Make-Valid-Parentheses.md +++ b/website/content/ChapterFour/1200~1299/1249.Minimum-Remove-to-Make-Valid-Parentheses.md @@ -97,6 +97,6 @@ func minRemoveToMakeValid(s string) string { ---------------------------------------------- diff --git a/website/content/ChapterFour/1200~1299/1266.Minimum-Time-Visiting-All-Points.md b/website/content/ChapterFour/1200~1299/1266.Minimum-Time-Visiting-All-Points.md index 252a9822b..5b20c53a1 100755 --- a/website/content/ChapterFour/1200~1299/1266.Minimum-Time-Visiting-All-Points.md +++ b/website/content/ChapterFour/1200~1299/1266.Minimum-Time-Visiting-All-Points.md @@ -78,5 +78,5 @@ func minTimeToVisitAllPoints(points [][]int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/1200~1299/1268.Search-Suggestions-System.md b/website/content/ChapterFour/1200~1299/1268.Search-Suggestions-System.md new file mode 100644 index 000000000..759f58221 --- /dev/null +++ b/website/content/ChapterFour/1200~1299/1268.Search-Suggestions-System.md @@ -0,0 +1,96 @@ +# [1268. Search Suggestions System](https://leetcode.com/problems/search-suggestions-system/) + +## 题目 + +Given an array of strings `products` and a string `searchWord`. We want to design a system that suggests at most three product names from `products` after each character of `searchWord` is typed. Suggested products should have common prefix with the searchWord. If there are more than three products with a common prefix return the three lexicographically minimums products. + +Return *list of lists* of the suggested `products` after each character of `searchWord` is typed. + +**Example 1:** + +``` +Input: products = ["mobile","mouse","moneypot","monitor","mousepad"], searchWord = "mouse" +Output: [ +["mobile","moneypot","monitor"], +["mobile","moneypot","monitor"], +["mouse","mousepad"], +["mouse","mousepad"], +["mouse","mousepad"] +] +Explanation: products sorted lexicographically = ["mobile","moneypot","monitor","mouse","mousepad"] +After typing m and mo all products match and we show user ["mobile","moneypot","monitor"] +After typing mou, mous and mouse the system suggests ["mouse","mousepad"] + +``` + +**Example 2:** + +``` +Input: products = ["havana"], searchWord = "havana" +Output: [["havana"],["havana"],["havana"],["havana"],["havana"],["havana"]] +``` + +**Example 3:** + +``` +Input: products = ["bags","baggage","banner","box","cloths"], searchWord = "bags" +Output: [["baggage","bags","banner"],["baggage","bags","banner"],["baggage","bags"],["bags"]] +``` + +**Example 4:** + +``` +Input: products = ["havana"], searchWord = "tatiana" +Output: [[],[],[],[],[],[],[]] +``` + +**Constraints:** + +- `1 <= products.length <= 1000` +- There are no repeated elements in `products`. +- `1 <= Σ products[i].length <= 2 * 10^4` +- All characters of `products[i]` are lower-case English letters. +- `1 <= searchWord.length <= 1000` +- All characters of `searchWord` are lower-case English letters. + +## 题目大意 + +给你一个产品数组 products 和一个字符串 searchWord ，products  数组中每个产品都是一个字符串。请你设计一个推荐系统，在依次输入单词 searchWord 的每一个字母后，推荐 products 数组中前缀与 searchWord 相同的最多三个产品。如果前缀相同的可推荐产品超过三个，请按字典序返回最小的三个。请你以二维列表的形式，返回在输入 searchWord 每个字母后相应的推荐产品的列表。 + +## 解题思路 + +- 由于题目要求返回的答案要按照字典序输出，所以先排序。有序字符串又满足了二分搜索的条件，于是可以用二分搜索。sort.SearchStrings 返回的是满足搜索条件的第一个起始下标。末尾不满足条件的字符串要切掉。所以要搜 2 次，第一次二分搜索先将不满足目标串前缀的字符串筛掉。第二次二分搜索再搜索出最终满足题意的字符串。 + +## 代码 + +```go +package leetcode + +import ( + "sort" +) + +func suggestedProducts(products []string, searchWord string) [][]string { + sort.Strings(products) + searchWordBytes, result := []byte(searchWord), make([][]string, 0, len(searchWord)) + for i := 1; i <= len(searchWord); i++ { + searchWordBytes[i-1]++ + products = products[:sort.SearchStrings(products, string(searchWordBytes[:i]))] + searchWordBytes[i-1]-- + products = products[sort.SearchStrings(products, searchWord[:i]):] + if len(products) > 3 { + result = append(result, products[:3]) + } else { + result = append(result, products) + } + } + return result +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/1200~1299/1275.Find-Winner-on-a-Tic-Tac-Toe-Game.md b/website/content/ChapterFour/1200~1299/1275.Find-Winner-on-a-Tic-Tac-Toe-Game.md index d7721e9e0..eda51cd07 100644 --- a/website/content/ChapterFour/1200~1299/1275.Find-Winner-on-a-Tic-Tac-Toe-Game.md +++ b/website/content/ChapterFour/1200~1299/1275.Find-Winner-on-a-Tic-Tac-Toe-Game.md @@ -156,6 +156,6 @@ func tictactoe(moves [][]int) string { ---------------------------------------------- diff --git a/website/content/ChapterFour/1200~1299/1290.Convert-Binary-Number-in-a-Linked-List-to-Integer.md b/website/content/ChapterFour/1200~1299/1290.Convert-Binary-Number-in-a-Linked-List-to-Integer.md index 41633eae2..af3a2ca0a 100644 --- a/website/content/ChapterFour/1200~1299/1290.Convert-Binary-Number-in-a-Linked-List-to-Integer.md +++ b/website/content/ChapterFour/1200~1299/1290.Convert-Binary-Number-in-a-Linked-List-to-Integer.md @@ -84,5 +84,5 @@ func getDecimalValue(head *ListNode) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/1200~1299/1293.Shortest-Path-in-a-Grid-with-Obstacles-Elimination.md b/website/content/ChapterFour/1200~1299/1293.Shortest-Path-in-a-Grid-with-Obstacles-Elimination.md new file mode 100644 index 000000000..f4cebe1fa --- /dev/null +++ b/website/content/ChapterFour/1200~1299/1293.Shortest-Path-in-a-Grid-with-Obstacles-Elimination.md @@ -0,0 +1,138 @@ +# [1293. Shortest Path in a Grid with Obstacles Elimination](https://leetcode.com/problems/shortest-path-in-a-grid-with-obstacles-elimination/) + + + +## 题目 + +You are given an m x n integer matrix grid where each cell is either 0 (empty) or 1 (obstacle). You can move up, down, left, or right from and to an empty cell in one step. + +Return the minimum number of steps to walk from the upper left corner (0, 0) to the lower right corner (m - 1, n - 1) given that you can eliminate at most k obstacles. If it is not possible to find such walk return -1. + + + +Example 1: + + +![](https://assets.leetcode.com/uploads/2021/09/30/short1-grid.jpg) + + +``` +Input: grid = [[0,0,0],[1,1,0],[0,0,0],[0,1,1],[0,0,0]], k = 1 +Output: 6 +Explanation: +The shortest path without eliminating any obstacle is 10. +The shortest path with one obstacle elimination at position (3,2) is 6. Such path is (0,0) -> (0,1) -> (0,2) -> (1,2) -> (2,2) -> (3,2) -> (4,2). +``` + +Example 2: + +![](https://assets.leetcode.com/uploads/2021/09/30/short2-grid.jpg) + +``` +Input: grid = [[0,1,1],[1,1,1],[1,0,0]], k = 1 +Output: -1 +Explanation: We need to eliminate at least two obstacles to find such a walk. +``` + +Constraints: + +- m == grid.length +- n == grid[i].length +- 1 <= m, n <= 40 +- 1 <= k <= m * n +- grid[i][j] is either 0 or 1. +- grid[0][0] == grid[m - 1][n - 1] == 0 + + + +## 题目大意 + +给你一个 m * n 的网格，其中每个单元格不是 0（空）就是 1（障碍物）。每一步，您都可以在空白单元格中上、下、左、右移动。 + +如果您 最多 可以消除 k 个障碍物，请找出从左上角 (0, 0) 到右下角 (m-1, n-1) 的最短路径，并返回通过该路径所需的步数。如果找不到这样的路径，则返回 -1 。 + + +## 解题思路 + +使用 BFS 遍历棋盘。这题比普通可达性问题多了一个障碍物的限制。这个也不难。每个点往周边四个方向扩展的时候，如果遇到障碍物，先算上这个障碍物，障碍物累积总个数小于 K 的时候，从障碍物的这个格子继续开始遍历。如果没有遇到障碍物，判断当前累积障碍物个数是否已经小于 K 个，如果小于 K 便继续遍历。如果大于 K，便终止此轮遍历。 + +## 代码 + +```go +var dir = [][]int{ + {-1, 0}, + {0, 1}, + {1, 0}, + {0, -1}, +} + +type pos struct { + x, y int + obstacle int + step int +} + +func shortestPath(grid [][]int, k int) int { + queue, m, n := []pos{}, len(grid), len(grid[0]) + visitor := make([][][]int, m) + if len(grid) == 1 && len(grid[0]) == 1 { + return 0 + } + for i := 0; i < m; i++ { + visitor[i] = make([][]int, n) + for j := 0; j < n; j++ { + visitor[i][j] = make([]int, k+1) + } + } + visitor[0][0][0] = 1 + queue = append(queue, pos{x: 0, y: 0, obstacle: 0, step: 0}) + for len(queue) > 0 { + size := len(queue) + for size > 0 { + size-- + node := queue[0] + queue = queue[1:] + for i := 0; i < len(dir); i++ { + newX := node.x + dir[i][0] + newY := node.y + dir[i][1] + if newX == m-1 && newY == n-1 { + if node.obstacle != 0 { + if node.obstacle <= k { + return node.step + 1 + } else { + continue + } + } + return node.step + 1 + } + if isInBoard(grid, newX, newY) { + if grid[newX][newY] == 1 { + if node.obstacle+1 <= k && visitor[newX][newY][node.obstacle+1] != 1 { + queue = append(queue, pos{x: newX, y: newY, obstacle: node.obstacle + 1, step: node.step + 1}) + visitor[newX][newY][node.obstacle+1] = 1 + } + } else { + if node.obstacle <= k && visitor[newX][newY][node.obstacle] != 1 { + queue = append(queue, pos{x: newX, y: newY, obstacle: node.obstacle, step: node.step + 1}) + visitor[newX][newY][node.obstacle] = 1 + } + } + + } + } + } + } + return -1 +} + +func isInBoard(board [][]int, x, y int) bool { + return x >= 0 && x < len(board) && y >= 0 && y < len(board[0]) +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/1200~1299/1295.Find-Numbers-with-Even-Number-of-Digits.md b/website/content/ChapterFour/1200~1299/1295.Find-Numbers-with-Even-Number-of-Digits.md index 17d3b6ba1..afb613611 100644 --- a/website/content/ChapterFour/1200~1299/1295.Find-Numbers-with-Even-Number-of-Digits.md +++ b/website/content/ChapterFour/1200~1299/1295.Find-Numbers-with-Even-Number-of-Digits.md @@ -65,6 +65,6 @@ func findNumbers(nums []int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/1200~1299/1296.Divide-Array-in-Sets-of-K-Consecutive-Numbers.md b/website/content/ChapterFour/1200~1299/1296.Divide-Array-in-Sets-of-K-Consecutive-Numbers.md new file mode 100644 index 000000000..ea345986c --- /dev/null +++ b/website/content/ChapterFour/1200~1299/1296.Divide-Array-in-Sets-of-K-Consecutive-Numbers.md @@ -0,0 +1,79 @@ +# [1296. Divide Array in Sets of K Consecutive Numbers](https://leetcode.com/problems/divide-array-in-sets-of-k-consecutive-numbers/) + +## 题目 + +Given an array of integers nums and a positive integer k, check whether it is possible to divide this array into sets of k consecutive numbers. + +Return true if it is possible. Otherwise, return false. + +**Example 1**: + + Input: nums = [1,2,3,3,4,4,5,6], k = 4 + Output: true + Explanation: Array can be divided into [1,2,3,4] and [3,4,5,6]. + +**Example 2**: + + Input: nums = [3,2,1,2,3,4,3,4,5,9,10,11], k = 3 + Output: true + Explanation: Array can be divided into [1,2,3] , [2,3,4] , [3,4,5] and [9,10,11]. + +**Example 3**: + + Input: nums = [1,2,3,4], k = 3 + Output: false + Explanation: Each array should be divided in subarrays of size 3. + +**Constraints:** + +- 1 <= k <= nums.length <= 100000 +- 1 <= nums[i] <= 1000000000 + +## 题目大意 + +给你一个整数数组 nums 和一个正整数 k，请你判断是否可以把这个数组划分成一些由 k 个连续数字组成的集合。 +如果可以，请返回 true；否则，返回 false。 + +## 解题思路 + +贪心算法 + +- 对nums升序排序 +- 对nums内数字进行哈希计数（key:数字，value:数量） +- 遍历nums中的数字，以数量大于1的数字作为连续数字开头，寻找连续数字后续元素，若无法找到 k 个连续数字则返回false +- 所有数字都能找到 k 个连续数字返回true + +##代码 + +```go +package leetcode + +import "sort" + +func isPossibleDivide(nums []int, k int) bool { + mp := make(map[int]int) + for _, v := range nums { + mp[v] += 1 + } + sort.Ints(nums) + for _, num := range nums { + if mp[num] == 0 { + continue + } + for diff := 0; diff < k; diff++ { + if mp[num+diff] == 0 { + return false + } + mp[num+diff] -= 1 + } + } + return true +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/1200~1299/1299.Replace-Elements-with-Greatest-Element-on-Right-Side.md b/website/content/ChapterFour/1200~1299/1299.Replace-Elements-with-Greatest-Element-on-Right-Side.md index 2bbb88acb..ea964e728 100644 --- a/website/content/ChapterFour/1200~1299/1299.Replace-Elements-with-Greatest-Element-on-Right-Side.md +++ b/website/content/ChapterFour/1200~1299/1299.Replace-Elements-with-Greatest-Element-on-Right-Side.md @@ -53,6 +53,6 @@ func replaceElements(arr []int) []int { ---------------------------------------------- diff --git a/website/content/ChapterFour/1300~1399/1306.Jump-Game-III.md b/website/content/ChapterFour/1300~1399/1306.Jump-Game-III.md index cddd5cd09..e34767f0e 100644 --- a/website/content/ChapterFour/1300~1399/1306.Jump-Game-III.md +++ b/website/content/ChapterFour/1300~1399/1306.Jump-Game-III.md @@ -83,5 +83,5 @@ func canReach(arr []int, start int) bool { ---------------------------------------------- diff --git a/website/content/ChapterFour/1300~1399/1310.XOR-Queries-of-a-Subarray.md b/website/content/ChapterFour/1300~1399/1310.XOR-Queries-of-a-Subarray.md new file mode 100644 index 000000000..4c90917b3 --- /dev/null +++ b/website/content/ChapterFour/1300~1399/1310.XOR-Queries-of-a-Subarray.md @@ -0,0 +1,84 @@ +# [1310. XOR Queries of a Subarray](https://leetcode.com/problems/xor-queries-of-a-subarray/) + + +## 题目 + +Given the array `arr` of positive integers and the array `queries` where `queries[i] = [Li,Ri]`, for each query `i` compute the **XOR** of elements from `Li` to `Ri` (that is, `arr[Li]xor arr[Li+1]xor ...xor arr[Ri]`). Return an array containing the result for the given `queries`. + +**Example 1:** + +``` +Input: arr = [1,3,4,8], queries = [[0,1],[1,2],[0,3],[3,3]] +Output: [2,7,14,8] +Explanation: +The binary representation of the elements in the array are: +1 = 0001 +3 = 0011 +4 = 0100 +8 = 1000 +The XOR values for queries are: +[0,1] = 1 xor 3 = 2 +[1,2] = 3 xor 4 = 7 +[0,3] = 1 xor 3 xor 4 xor 8 = 14 +[3,3] = 8 + +``` + +**Example 2:** + +``` +Input: arr = [4,8,2,10], queries = [[2,3],[1,3],[0,0],[0,3]] +Output: [8,0,4,4] + +``` + +**Constraints:** + +- `1 <= arr.length <= 3 * 10^4` +- `1 <= arr[i] <= 10^9` +- `1 <= queries.length <= 3 * 10^4` +- `queries[i].length == 2` +- `0 <= queries[i][0] <= queries[i][1] < arr.length` + +## 题目大意 + +有一个正整数数组 arr，现给你一个对应的查询数组 queries，其中 queries[i] = [Li, Ri]。对于每个查询 i，请你计算从 Li 到 Ri 的 XOR 值（即 arr[Li] xor arr[Li+1] xor ... xor arr[Ri]）作为本次查询的结果。并返回一个包含给定查询 queries 所有结果的数组。 + +## 解题思路 + +- 此题求区间异或，很容易让人联想到区间求和。区间求和利用前缀和，可以使得 query 从 O(n) 降为 O(1)。区间异或能否也用类似前缀和的思想呢？答案是肯定的。利用异或的两个性质，x ^ x = 0，x ^ 0 = x。那么有：（由于 LaTeX 中异或符号 ^ 是特殊字符，笔者用 {{< katex >}} \oplus {{< /katex >}} 代替异或） + + {{< katex display >}} + \begin{aligned}Query(left,right) &=arr[left] \oplus \cdots  \oplus arr[right]\\&=(arr[0] \oplus \cdots  \oplus arr[left-1]) \oplus (arr[0] \oplus \cdots  \oplus arr[left-1]) \oplus (arr[left] \oplus \cdots  \oplus arr[right])\\ &=(arr[0] \oplus \cdots  \oplus arr[left-1]) \oplus (arr[0] \oplus \cdots  \oplus arr[right])\\ &=xors[left] \oplus xors[right+1]\\ \end{aligned} + {{< /katex >}} + + 按照这个思路解题，便可以将 query 从 O(n) 降为 O(1)，总的时间复杂度为 O(n)。 + +## 代码 + +```go +package leetcode + +func xorQueries(arr []int, queries [][]int) []int { + xors := make([]int, len(arr)) + xors[0] = arr[0] + for i := 1; i < len(arr); i++ { + xors[i] = arr[i] ^ xors[i-1] + } + res := make([]int, len(queries)) + for i, q := range queries { + res[i] = xors[q[1]] + if q[0] > 0 { + res[i] ^= xors[q[0]-1] + } + } + return res +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/1300~1399/1313.Decompress-Run-Length-Encoded-List.md b/website/content/ChapterFour/1300~1399/1313.Decompress-Run-Length-Encoded-List.md index afdb5f772..4d56280fb 100644 --- a/website/content/ChapterFour/1300~1399/1313.Decompress-Run-Length-Encoded-List.md +++ b/website/content/ChapterFour/1300~1399/1313.Decompress-Run-Length-Encoded-List.md @@ -62,6 +62,6 @@ func decompressRLElist(nums []int) []int { ---------------------------------------------- diff --git a/website/content/ChapterFour/1300~1399/1319.Number-of-Operations-to-Make-Network-Connected.md b/website/content/ChapterFour/1300~1399/1319.Number-of-Operations-to-Make-Network-Connected.md index 2982a1237..2adf943ce 100644 --- a/website/content/ChapterFour/1300~1399/1319.Number-of-Operations-to-Make-Network-Connected.md +++ b/website/content/ChapterFour/1300~1399/1319.Number-of-Operations-to-Make-Network-Connected.md @@ -66,7 +66,7 @@ Output: 0 package leetcode import ( - "github.com/halfrost/LeetCode-Go/template" + "github.com/halfrost/leetcode-go/template" ) func makeConnected(n int, connections [][]int) int { diff --git a/website/content/ChapterFour/1300~1399/1380.Lucky-Numbers-in-a-Matrix.md b/website/content/ChapterFour/1300~1399/1380.Lucky-Numbers-in-a-Matrix.md index 6e48e4865..e17321058 100644 --- a/website/content/ChapterFour/1300~1399/1380.Lucky-Numbers-in-a-Matrix.md +++ b/website/content/ChapterFour/1300~1399/1380.Lucky-Numbers-in-a-Matrix.md @@ -90,5 +90,5 @@ func luckyNumbers(matrix [][]int) []int { ---------------------------------------------- diff --git a/website/content/ChapterFour/1300~1399/1383.Maximum-Performance-of-a-Team.md b/website/content/ChapterFour/1300~1399/1383.Maximum-Performance-of-a-Team.md new file mode 100644 index 000000000..d4a3be6d2 --- /dev/null +++ b/website/content/ChapterFour/1300~1399/1383.Maximum-Performance-of-a-Team.md @@ -0,0 +1,112 @@ +# [1383. Maximum Performance of a Team](https://leetcode.com/problems/maximum-performance-of-a-team/) + +## 题目 + +You are given two integers `n` and `k` and two integer arrays `speed` and `efficiency` both of length `n`. There are `n` engineers numbered from `1` to `n`. `speed[i]` and `efficiency[i]` represent the speed and efficiency of the `ith` engineer respectively. + +Choose **at most** `k` different engineers out of the `n` engineers to form a team with the maximum **performance**. + +The performance of a team is the sum of their engineers' speeds multiplied by the minimum efficiency among their engineers. + +Return *the maximum performance of this team*. Since the answer can be a huge number, return it **modulo** `109 + 7`. + +**Example 1:** + +``` +Input: n = 6, speed = [2,10,3,1,5,8], efficiency = [5,4,3,9,7,2], k = 2 +Output: 60 +Explanation: +We have the maximum performance of the team by selecting engineer 2 (with speed=10 and efficiency=4) and engineer 5 (with speed=5 and efficiency=7). That is, performance = (10 + 5) * min(4, 7) = 60. +``` + +**Example 2:** + +``` +Input: n = 6, speed = [2,10,3,1,5,8], efficiency = [5,4,3,9,7,2], k = 3 +Output: 68 +Explanation: +This is the same example as the first but k = 3. We can select engineer 1, engineer 2 and engineer 5 to get the maximum performance of the team. That is, performance = (2 + 10 + 5) * min(5, 4, 7) = 68. +``` + +**Example 3:** + +``` +Input: n = 6, speed = [2,10,3,1,5,8], efficiency = [5,4,3,9,7,2], k = 4 +Output: 72 +``` + +**Constraints:** + +- `1 <= <= k <= n <= 105` +- `speed.length == n` +- `efficiency.length == n` +- `1 <= speed[i] <= 105` +- `1 <= efficiency[i] <= 108` + +## 题目大意 + +公司有编号为 1 到 n 的 n 个工程师，给你两个数组 speed 和 efficiency ，其中 speed[i] 和 efficiency[i] 分别代表第 i 位工程师的速度和效率。请你返回由最多 k 个工程师组成的 最大团队表现值 ，由于答案可能很大，请你返回结果对 10^9 + 7 取余后的结果。团队表现值 的定义为：一个团队中「所有工程师速度的和」乘以他们「效率值中的最小值」。 + +## 解题思路 + +- 题目要求返回最大团队表现值，表现值需要考虑速度的累加和，和效率的最小值。即使速度快，效率的最小值很小，总的表现值还是很小。先将效率从大到小排序。从效率高的工程师开始选起，遍历过程中维护一个大小为 k 的速度最小堆。每次遍历都计算一次团队最大表现值。扫描完成，最大团队表现值也筛选出来了。具体实现见下面的代码。 + +## 代码 + +```go +package leetcode + +import ( + "container/heap" + "sort" +) + +func maxPerformance(n int, speed []int, efficiency []int, k int) int { + indexes := make([]int, n) + for i := range indexes { + indexes[i] = i + } + sort.Slice(indexes, func(i, j int) bool { + return efficiency[indexes[i]] > efficiency[indexes[j]] + }) + ph := speedHeap{} + heap.Init(&ph) + speedSum := 0 + var max int64 + for _, index := range indexes { + if ph.Len() == k { + speedSum -= heap.Pop(&ph).(int) + } + speedSum += speed[index] + heap.Push(&ph, speed[index]) + max = Max(max, int64(speedSum)*int64(efficiency[index])) + } + return int(max % (1e9 + 7)) +} + +type speedHeap []int + +func (h speedHeap) Less(i, j int) bool { return h[i] < h[j] } +func (h speedHeap) Swap(i, j int) { h[i], h[j] = h[j], h[i] } +func (h speedHeap) Len() int { return len(h) } +func (h *speedHeap) Push(x interface{}) { *h = append(*h, x.(int)) } +func (h *speedHeap) Pop() interface{} { + res := (*h)[len(*h)-1] + *h = (*h)[:h.Len()-1] + return res +} + +func Max(a, b int64) int64 { + if a > b { + return a + } + return b +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/1300~1399/1385.Find-the-Distance-Value-Between-Two-Arrays.md b/website/content/ChapterFour/1300~1399/1385.Find-the-Distance-Value-Between-Two-Arrays.md index 9d0a25fa4..02541558a 100644 --- a/website/content/ChapterFour/1300~1399/1385.Find-the-Distance-Value-Between-Two-Arrays.md +++ b/website/content/ChapterFour/1300~1399/1385.Find-the-Distance-Value-Between-Two-Arrays.md @@ -100,6 +100,6 @@ func abs(a int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/1400~1499/1439.Find-the-Kth-Smallest-Sum-of-a-Matrix-With-Sorted-Rows.md b/website/content/ChapterFour/1400~1499/1439.Find-the-Kth-Smallest-Sum-of-a-Matrix-With-Sorted-Rows.md index 61dc1c504..574a8f3a3 100644 --- a/website/content/ChapterFour/1400~1499/1439.Find-the-Kth-Smallest-Sum-of-a-Matrix-With-Sorted-Rows.md +++ b/website/content/ChapterFour/1400~1499/1439.Find-the-Kth-Smallest-Sum-of-a-Matrix-With-Sorted-Rows.md @@ -147,5 +147,5 @@ func (pq *priorityQueue) Push(i interface{}) { ---------------------------------------------- diff --git a/website/content/ChapterFour/1400~1499/1442.Count-Triplets-That-Can-Form-Two-Arrays-of-Equal-XOR.md b/website/content/ChapterFour/1400~1499/1442.Count-Triplets-That-Can-Form-Two-Arrays-of-Equal-XOR.md new file mode 100644 index 000000000..e8fcfcce1 --- /dev/null +++ b/website/content/ChapterFour/1400~1499/1442.Count-Triplets-That-Can-Form-Two-Arrays-of-Equal-XOR.md @@ -0,0 +1,104 @@ +# [1442. Count Triplets That Can Form Two Arrays of Equal XOR](https://leetcode.com/problems/count-triplets-that-can-form-two-arrays-of-equal-xor/) + + +## 题目 + +Given an array of integers `arr`. + +We want to select three indices `i`, `j` and `k` where `(0 <= i < j <= k < arr.length)`. + +Let's define `a` and `b` as follows: + +- `a = arr[i] ^ arr[i + 1] ^ ... ^ arr[j - 1]` +- `b = arr[j] ^ arr[j + 1] ^ ... ^ arr[k]` + +Note that **^** denotes the **bitwise-xor** operation. + +Return *the number of triplets* (`i`, `j` and `k`) Where `a == b`. + +**Example 1:** + +``` +Input: arr = [2,3,1,6,7] +Output: 4 +Explanation: The triplets are (0,1,2), (0,2,2), (2,3,4) and (2,4,4) +``` + +**Example 2:** + +``` +Input: arr = [1,1,1,1,1] +Output: 10 +``` + +**Example 3:** + +``` +Input: arr = [2,3] +Output: 0 +``` + +**Example 4:** + +``` +Input: arr = [1,3,5,7,9] +Output: 3 +``` + +**Example 5:** + +``` +Input: arr = [7,11,12,9,5,2,7,17,22] +Output: 8 +``` + +**Constraints:** + +- `1 <= arr.length <= 300` +- `1 <= arr[i] <= 10^8` + +## 题目大意 + +给你一个整数数组 arr 。现需要从数组中取三个下标 i、j 和 k ，其中 (0 <= i < j <= k < arr.length) 。a 和 b 定义如下： + +- a = arr[i] ^ arr[i + 1] ^ ... ^ arr[j - 1] +- b = arr[j] ^ arr[j + 1] ^ ... ^ arr[k] + +注意：^ 表示 按位异或 操作。请返回能够令 a == b 成立的三元组 (i, j , k) 的数目。 + +## 解题思路 + +- 这一题需要用到 `x^x = 0` 这个异或特性。题目要求 `a == b`，可以等效转化为 `arr[i] ^ arr[i + 1] ^ ... ^ arr[j - 1] ^ arr[j] ^ arr[j + 1] ^ ... ^ arr[k] = 0`，这样 j 相当于可以“忽略”，专注找到所有元素异或结果为 0 的区间 [i,k] 即为答案。利用前缀和的思想，只不过此题非累加和，而是异或。又由 `x^x = 0` 这个异或特性，相同部分异或相当于消除，于是有 `prefix[i,k] = prefix[0,k] ^ prefix[0,i-1]`，找到每一个 `prefix[i,k] = 0` 的 i，k 组合，i < j <= k，那么满足条件的三元组 (i,j,k) 的个数完全取决于 j 的取值范围，(因为 i 和 k 已经固定了)，j 的取值范围为 k-i，所以累加所有满足条件的 k-i，输出即为最终答案。 + +## 代码 + +```go +package leetcode + +func countTriplets(arr []int) int { + prefix, num, count, total := make([]int, len(arr)), 0, 0, 0 + for i, v := range arr { + num ^= v + prefix[i] = num + } + for i := 0; i < len(prefix)-1; i++ { + for k := i + 1; k < len(prefix); k++ { + total = prefix[k] + if i > 0 { + total ^= prefix[i-1] + } + if total == 0 { + count += k - i + } + } + } + return count +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/1400~1499/1446.Consecutive-Characters.md b/website/content/ChapterFour/1400~1499/1446.Consecutive-Characters.md new file mode 100644 index 000000000..1d1beb7ff --- /dev/null +++ b/website/content/ChapterFour/1400~1499/1446.Consecutive-Characters.md @@ -0,0 +1,82 @@ +# [1446. Consecutive Characters](https://leetcode.com/problems/consecutive-characters/) + +## 题目 + +The power of the string is the maximum length of a non-empty substring that contains only one unique character. + +Given a string s, return the power of s. + +**Example 1**: + + Input: s = "leetcode" + Output: 2 + Explanation: The substring "ee" is of length 2 with the character 'e' only. + +**Example 2**: + + Input: s = "abbcccddddeeeeedcba" + Output: 5 + Explanation: The substring "eeeee" is of length 5 with the character 'e' only. + +**Example 3**: + + Input: s = "triplepillooooow" + Output: 5 + +**Example 4**: + + Input: s = "hooraaaaaaaaaaay" + Output: 11 + +**Example 5**: + + Input: s = "tourist" + Output: 1 + +**Constraints:** + +- 1 <= s.length <= 500 +- s consists of only lowercase English letters. + +## 题目大意 + +给你一个字符串 s ，字符串的「能量」定义为：只包含一种字符的最长非空子字符串的长度。 + +请你返回字符串的能量。 + +## 解题思路 + +- 顺序遍历进行统计 + +## 代码 + +```go +package leetcode + +func maxPower(s string) int { + cur, cnt, ans := s[0], 1, 1 + for i := 1; i < len(s); i++ { + if cur == s[i] { + cnt++ + } else { + if cnt > ans { + ans = cnt + } + cur = s[i] + cnt = 1 + } + } + if cnt > ans { + ans = cnt + } + return ans +} + +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/1400~1499/1455.Check-If-a-Word-Occurs-As-a-Prefix-of-Any-Word-in-a-Sentence.md b/website/content/ChapterFour/1400~1499/1455.Check-If-a-Word-Occurs-As-a-Prefix-of-Any-Word-in-a-Sentence.md index 8a031d749..3bba6e43b 100644 --- a/website/content/ChapterFour/1400~1499/1455.Check-If-a-Word-Occurs-As-a-Prefix-of-Any-Word-in-a-Sentence.md +++ b/website/content/ChapterFour/1400~1499/1455.Check-If-a-Word-Occurs-As-a-Prefix-of-Any-Word-in-a-Sentence.md @@ -100,6 +100,6 @@ func isPrefixOfWord(sentence string, searchWord string) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/1400~1499/1464.Maximum-Product-of-Two-Elements-in-an-Array.md b/website/content/ChapterFour/1400~1499/1464.Maximum-Product-of-Two-Elements-in-an-Array.md index 8f75c287b..d318eb25b 100644 --- a/website/content/ChapterFour/1400~1499/1464.Maximum-Product-of-Two-Elements-in-an-Array.md +++ b/website/content/ChapterFour/1400~1499/1464.Maximum-Product-of-Two-Elements-in-an-Array.md @@ -69,5 +69,5 @@ func maxProduct(nums []int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/1400~1499/1465.Maximum-Area-of-a-Piece-of-Cake-After-Horizontal-and-Vertical-Cuts.md b/website/content/ChapterFour/1400~1499/1465.Maximum-Area-of-a-Piece-of-Cake-After-Horizontal-and-Vertical-Cuts.md new file mode 100644 index 000000000..9a4a4bf64 --- /dev/null +++ b/website/content/ChapterFour/1400~1499/1465.Maximum-Area-of-a-Piece-of-Cake-After-Horizontal-and-Vertical-Cuts.md @@ -0,0 +1,96 @@ +# [1465. Maximum Area of a Piece of Cake After Horizontal and Vertical Cuts](https://leetcode.com/problems/maximum-area-of-a-piece-of-cake-after-horizontal-and-vertical-cuts/) + + +## 题目 + +Given a rectangular cake with height `h` and width `w`, and two arrays of integers `horizontalCuts` and `verticalCuts` where `horizontalCuts[i]` is the distance from the top of the rectangular cake to the `ith` horizontal cut and similarly, `verticalCuts[j]` is the distance from the left of the rectangular cake to the `jth` vertical cut. + +*Return the maximum area of a piece of cake after you cut at each horizontal and vertical position provided in the arrays `horizontalCuts` and `verticalCuts`.* Since the answer can be a huge number, return this modulo 10^9 + 7. + +**Example 1:** + +![https://assets.leetcode.com/uploads/2020/05/14/leetcode_max_area_2.png](https://assets.leetcode.com/uploads/2020/05/14/leetcode_max_area_2.png) + +``` +Input: h = 5, w = 4, horizontalCuts = [1,2,4], verticalCuts = [1,3] +Output: 4 +Explanation: The figure above represents the given rectangular cake. Red lines are the horizontal and vertical cuts. After you cut the cake, the green piece of cake has the maximum area. + +``` + +**Example 2:** + +![https://assets.leetcode.com/uploads/2020/05/14/leetcode_max_area_3.png](https://assets.leetcode.com/uploads/2020/05/14/leetcode_max_area_3.png) + +``` +Input: h = 5, w = 4, horizontalCuts = [3,1], verticalCuts = [1] +Output: 6 +Explanation: The figure above represents the given rectangular cake. Red lines are the horizontal and vertical cuts. After you cut the cake, the green and yellow pieces of cake have the maximum area. + +``` + +**Example 3:** + +``` +Input: h = 5, w = 4, horizontalCuts = [3], verticalCuts = [3] +Output: 9 + +``` + +**Constraints:** + +- `2 <= h, w <= 10^9` +- `1 <= horizontalCuts.length < min(h, 10^5)` +- `1 <= verticalCuts.length < min(w, 10^5)` +- `1 <= horizontalCuts[i] < h` +- `1 <= verticalCuts[i] < w` +- It is guaranteed that all elements in `horizontalCuts` are distinct. +- It is guaranteed that all elements in `verticalCuts` are distinct. + +## 题目大意 + +矩形蛋糕的高度为 h 且宽度为 w，给你两个整数数组 horizontalCuts 和 verticalCuts，其中 horizontalCuts[i] 是从矩形蛋糕顶部到第  i 个水平切口的距离，类似地， verticalCuts[j] 是从矩形蛋糕的左侧到第 j 个竖直切口的距离。请你按数组 horizontalCuts 和 verticalCuts 中提供的水平和竖直位置切割后，请你找出 面积最大 的那份蛋糕，并返回其 面积 。由于答案可能是一个很大的数字，因此需要将结果对 10^9 + 7 取余后返回。 + +## 解题思路 + +- 读完题比较容易想到解题思路。找到水平切口最大的差值和竖直切口最大的差值，这 4 条边构成的矩形即为最大矩形。不过有特殊情况需要判断，切口除了题目给的切口坐标以外，默认还有 4 个切口，即蛋糕原始的 4 条边。如下图二，最大的矩形其实在切口之外。所以找水平切口最大差值和竖直切口最大差值需要考虑到蛋糕原始的 4 条边。 + +![https://img.halfrost.com/Leetcode/leetcode_1465.png](https://img.halfrost.com/Leetcode/leetcode_1465.png) + +## 代码 + +```go +package leetcode + +import "sort" + +func maxArea(h int, w int, hcuts []int, vcuts []int) int { + sort.Ints(hcuts) + sort.Ints(vcuts) + maxw, maxl := hcuts[0], vcuts[0] + for i, c := range hcuts[1:] { + if c-hcuts[i] > maxw { + maxw = c - hcuts[i] + } + } + if h-hcuts[len(hcuts)-1] > maxw { + maxw = h - hcuts[len(hcuts)-1] + } + for i, c := range vcuts[1:] { + if c-vcuts[i] > maxl { + maxl = c - vcuts[i] + } + } + if w-vcuts[len(vcuts)-1] > maxl { + maxl = w - vcuts[len(vcuts)-1] + } + return (maxw * maxl) % (1000000007) +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/1400~1499/1470.Shuffle-the-Array.md b/website/content/ChapterFour/1400~1499/1470.Shuffle-the-Array.md index f010ba9f2..fc653d637 100644 --- a/website/content/ChapterFour/1400~1499/1470.Shuffle-the-Array.md +++ b/website/content/ChapterFour/1400~1499/1470.Shuffle-the-Array.md @@ -66,6 +66,6 @@ func shuffle(nums []int, n int) []int { ---------------------------------------------- diff --git a/website/content/ChapterFour/1400~1499/1480.Running-Sum-of-1d-Array.md b/website/content/ChapterFour/1400~1499/1480.Running-Sum-of-1d-Array.md index f3bde0702..6398e56a0 100644 --- a/website/content/ChapterFour/1400~1499/1480.Running-Sum-of-1d-Array.md +++ b/website/content/ChapterFour/1400~1499/1480.Running-Sum-of-1d-Array.md @@ -67,5 +67,5 @@ func runningSum(nums []int) []int { ---------------------------------------------- diff --git a/website/content/ChapterFour/1400~1499/1482.Minimum-Number-of-Days-to-Make-m-Bouquets.md b/website/content/ChapterFour/1400~1499/1482.Minimum-Number-of-Days-to-Make-m-Bouquets.md new file mode 100644 index 000000000..92c3ba07c --- /dev/null +++ b/website/content/ChapterFour/1400~1499/1482.Minimum-Number-of-Days-to-Make-m-Bouquets.md @@ -0,0 +1,117 @@ +# [1482. Minimum Number of Days to Make m Bouquets](https://leetcode.com/problems/minimum-number-of-days-to-make-m-bouquets/) + +## 题目 + +Given an integer array `bloomDay`, an integer `m` and an integer `k`. + +We need to make `m` bouquets. To make a bouquet, you need to use `k` **adjacent flowers** from the garden. + +The garden consists of `n` flowers, the `ith` flower will bloom in the `bloomDay[i]` and then can be used in **exactly one** bouquet. + +Return *the minimum number of days* you need to wait to be able to make `m` bouquets from the garden. If it is impossible to make `m` bouquets return **-1**. + +**Example 1:** + +``` +Input: bloomDay = [1,10,3,10,2], m = 3, k = 1 +Output: 3 +Explanation: Let's see what happened in the first three days. x means flower bloomed and _ means flower didn't bloom in the garden. +We need 3 bouquets each should contain 1 flower. +After day 1: [x, _, _, _, _] // we can only make one bouquet. +After day 2: [x, _, _, _, x] // we can only make two bouquets. +After day 3: [x, _, x, _, x] // we can make 3 bouquets. The answer is 3. +``` + +**Example 2:** + +``` +Input: bloomDay = [1,10,3,10,2], m = 3, k = 2 +Output: -1 +Explanation: We need 3 bouquets each has 2 flowers, that means we need 6 flowers. We only have 5 flowers so it is impossible to get the needed bouquets and we return -1. +``` + +**Example 3:** + +``` +Input: bloomDay = [7,7,7,7,12,7,7], m = 2, k = 3 +Output: 12 +Explanation: We need 2 bouquets each should have 3 flowers. +Here's the garden after the 7 and 12 days: +After day 7: [x, x, x, x, _, x, x] +We can make one bouquet of the first three flowers that bloomed. We cannot make another bouquet from the last three flowers that bloomed because they are not adjacent. +After day 12: [x, x, x, x, x, x, x] +It is obvious that we can make two bouquets in different ways. +``` + +**Example 4:** + +``` +Input: bloomDay = [1000000000,1000000000], m = 1, k = 1 +Output: 1000000000 +Explanation: You need to wait 1000000000 days to have a flower ready for a bouquet. +``` + +**Example 5:** + +``` +Input: bloomDay = [1,10,2,9,3,8,4,7,5,6], m = 4, k = 2 +Output: 9 +``` + +**Constraints:** + +- `bloomDay.length == n` +- `1 <= n <= 10^5` +- `1 <= bloomDay[i] <= 10^9` +- `1 <= m <= 10^6` +- `1 <= k <= n` + +## 题目大意 + +给你一个整数数组 bloomDay，以及两个整数 m 和 k 。现需要制作 m 束花。制作花束时，需要使用花园中 相邻的 k 朵花 。花园中有 n 朵花，第 i 朵花会在 bloomDay[i] 时盛开，恰好 可以用于 一束 花中。请你返回从花园中摘 m 束花需要等待的最少的天数。如果不能摘到 m 束花则返回 -1 。 + +## 解题思路 + +- 本题是二分搜索提醒。题目解空间固定，答案区间一定在 [0, maxDay] 中。这是单调增且有序区间，所以可以在这个解空间内使用二分搜索。在区间 [0, maxDay] 中找到第一个能满足 m 束花的解。二分搜索判断是否为 true 的条件为：从左往右遍历数组，依次统计当前日期下，花是否开了，如果连续开花 k 朵，便为 1 束，数组遍历结束如果花束总数 ≥ k 即为答案。二分搜索会返回最小的下标，即对应满足题意的最少天数。 + +## 代码 + +```go +package leetcode + +import "sort" + +func minDays(bloomDay []int, m int, k int) int { + if m*k > len(bloomDay) { + return -1 + } + maxDay := 0 + for _, day := range bloomDay { + if day > maxDay { + maxDay = day + } + } + return sort.Search(maxDay, func(days int) bool { + flowers, bouquets := 0, 0 + for _, d := range bloomDay { + if d > days { + flowers = 0 + } else { + flowers++ + if flowers == k { + bouquets++ + flowers = 0 + } + } + } + return bouquets >= m + }) +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/1400~1499/1486.XOR-Operation-in-an-Array.md b/website/content/ChapterFour/1400~1499/1486.XOR-Operation-in-an-Array.md new file mode 100644 index 000000000..5536755fb --- /dev/null +++ b/website/content/ChapterFour/1400~1499/1486.XOR-Operation-in-an-Array.md @@ -0,0 +1,76 @@ +# [1486. XOR Operation in an Array](https://leetcode.com/problems/xor-operation-in-an-array/) + + +## 题目 + +Given an integer `n` and an integer `start`. + +Define an array `nums` where `nums[i] = start + 2*i` (0-indexed) and `n == nums.length`. + +Return the bitwise XOR of all elements of `nums`. + +**Example 1:** + +``` +Input: n = 5, start = 0 +Output: 8 +Explanation:Array nums is equal to [0, 2, 4, 6, 8] where (0 ^ 2 ^ 4 ^ 6 ^ 8) = 8. +Where "^" corresponds to bitwise XOR operator. +``` + +**Example 2:** + +``` +Input: n = 4, start = 3 +Output: 8 +Explanation:Array nums is equal to [3, 5, 7, 9] where (3 ^ 5 ^ 7 ^ 9) = 8. +``` + +**Example 3:** + +``` +Input: n = 1, start = 7 +Output: 7 +``` + +**Example 4:** + +``` +Input: n = 10, start = 5 +Output: 2 +``` + +**Constraints:** + +- `1 <= n <= 1000` +- `0 <= start <= 1000` +- `n == nums.length` + +## 题目大意 + +给你两个整数，n 和 start 。数组 nums 定义为：nums[i] = start + 2*i（下标从 0 开始）且 n == nums.length 。请返回 nums 中所有元素按位异或（XOR）后得到的结果。 + +## 解题思路 + +- 简单题。按照题意，一层循环依次累积异或数组中每个元素。 + +## 代码 + +```go +package leetcode + +func xorOperation(n int, start int) int { + res := 0 + for i := 0; i < n; i++ { + res ^= start + 2*i + } + return res +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/1500~1599/1512.Number-of-Good-Pairs.md b/website/content/ChapterFour/1500~1599/1512.Number-of-Good-Pairs.md index 327a4e922..009b74b35 100644 --- a/website/content/ChapterFour/1500~1599/1512.Number-of-Good-Pairs.md +++ b/website/content/ChapterFour/1500~1599/1512.Number-of-Good-Pairs.md @@ -69,6 +69,6 @@ func numIdenticalPairs(nums []int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/1500~1599/1518.Water-Bottles.md b/website/content/ChapterFour/1500~1599/1518.Water-Bottles.md new file mode 100644 index 000000000..e7817708c --- /dev/null +++ b/website/content/ChapterFour/1500~1599/1518.Water-Bottles.md @@ -0,0 +1,81 @@ +# [1518. Water Bottles](https://leetcode.com/problems/water-bottles/) + +## 题目 + +Given numBottles full water bottles, you can exchange numExchange empty water bottles for one full water bottle. + +The operation of drinking a full water bottle turns it into an empty bottle. + +Return the maximum number of water bottles you can drink. + +**Example 1**: + +![https://assets.leetcode.com/uploads/2020/07/01/sample_1_1875.png](https://assets.leetcode.com/uploads/2020/07/01/sample_1_1875.png) + + Input: numBottles = 9, numExchange = 3 + Output: 13 + Explanation: You can exchange 3 empty bottles to get 1 full water bottle. + Number of water bottles you can drink: 9 + 3 + 1 = 13. + +**Example 2**: + +![https://assets.leetcode.com/uploads/2020/07/01/sample_2_1875.png](https://assets.leetcode.com/uploads/2020/07/01/sample_2_1875.png) + + Input: numBottles = 15, numExchange = 4 + Output: 19 + Explanation: You can exchange 4 empty bottles to get 1 full water bottle. + Number of water bottles you can drink: 15 + 3 + 1 = 19. + +**Example 3**: + + Input: numBottles = 5, numExchange = 5 + Output: 6 + +**Example 4**: + + Input: numBottles = 2, numExchange = 3 + Output: 2 + +**Constraints:** + +- 1 <= numBottles <= 100 +- 2 <= numExchange <= 100 + +## 题目大意 + +小区便利店正在促销，用 numExchange 个空酒瓶可以兑换一瓶新酒。你购入了 numBottles 瓶酒。 + +如果喝掉了酒瓶中的酒，那么酒瓶就会变成空的。 + +请你计算 最多 能喝到多少瓶酒。 + +## 解题思路 + +- 模拟。首先我们一定可以喝到 numBottles 瓶酒，剩下 numBottles 个空瓶。接下来我们可以拿空瓶子换酒，每次拿出 numExchange 个瓶子换一瓶酒，然后再喝完这瓶酒，得到一个空瓶。这样模拟下去，直到所有的空瓶子小于numExchange结束。 + +## 代码 + +```go +package leetcode + +func numWaterBottles(numBottles int, numExchange int) int { + if numBottles < numExchange { + return numBottles + } + quotient := numBottles / numExchange + reminder := numBottles % numExchange + ans := numBottles + quotient + for quotient+reminder >= numExchange { + quotient, reminder = (quotient+reminder)/numExchange, (quotient+reminder)%numExchange + ans += quotient + } + return ans +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/1500~1599/1539.Kth-Missing-Positive-Number.md b/website/content/ChapterFour/1500~1599/1539.Kth-Missing-Positive-Number.md index 737f3163c..c22e07e0c 100644 --- a/website/content/ChapterFour/1500~1599/1539.Kth-Missing-Positive-Number.md +++ b/website/content/ChapterFour/1500~1599/1539.Kth-Missing-Positive-Number.md @@ -65,6 +65,6 @@ func findKthPositive(arr []int, k int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/1500~1599/1551.Minimum-Operations-to-Make-Array-Equal.md b/website/content/ChapterFour/1500~1599/1551.Minimum-Operations-to-Make-Array-Equal.md index 88b649a9c..74ef1db9e 100644 --- a/website/content/ChapterFour/1500~1599/1551.Minimum-Operations-to-Make-Array-Equal.md +++ b/website/content/ChapterFour/1500~1599/1551.Minimum-Operations-to-Make-Array-Equal.md @@ -65,5 +65,5 @@ func minOperations(n int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/1500~1599/1572.Matrix-Diagonal-Sum.md b/website/content/ChapterFour/1500~1599/1572.Matrix-Diagonal-Sum.md new file mode 100644 index 000000000..c0fe7ee41 --- /dev/null +++ b/website/content/ChapterFour/1500~1599/1572.Matrix-Diagonal-Sum.md @@ -0,0 +1,84 @@ +# [1572. Matrix Diagonal Sum](https://leetcode.com/problems/matrix-diagonal-sum/) + + +## 题目 + +Given a square matrix `mat`, return the sum of the matrix diagonals. + +Only include the sum of all the elements on the primary diagonal and all the elements on the secondary diagonal that are not part of the primary diagonal. + +**Example 1:** + +![https://assets.leetcode.com/uploads/2020/08/14/sample_1911.png](https://assets.leetcode.com/uploads/2020/08/14/sample_1911.png) + +``` +Input: mat = [[1,2,3], +  [4,5,6], +  [7,8,9]] +Output: 25 +Explanation:Diagonals sum: 1 + 5 + 9 + 3 + 7 = 25 +Notice that element mat[1][1] = 5 is counted only once. + +``` + +**Example 2:** + +``` +Input: mat = [[1,1,1,1], +  [1,1,1,1], +  [1,1,1,1], +  [1,1,1,1]] +Output: 8 + +``` + +**Example 3:** + +``` +Input: mat = [[5]] +Output: 5 + +``` + +**Constraints:** + +- `n == mat.length == mat[i].length` +- `1 <= n <= 100` +- `1 <= mat[i][j] <= 100` + +## 题目大意 + +给你一个正方形矩阵 mat，请你返回矩阵对角线元素的和。请你返回在矩阵主对角线上的元素和副对角线上且不在主对角线上元素的和。 + +## 解题思路 + +- 简单题。根据题意，把主对角线和副对角线上的元素相加。 +- 如果正方形矩阵的长度 n 为奇数，相加的结果需要减去 mat[n/2][n/2]。 + +## 代码 + +```go +package leetcode + +func diagonalSum(mat [][]int) int { + n := len(mat) + ans := 0 + for pi := 0; pi < n; pi++ { + ans += mat[pi][pi] + } + for si, sj := n-1, 0; sj < n; si, sj = si-1, sj+1 { + ans += mat[si][sj] + } + if n%2 == 0 { + return ans + } + return ans - mat[n/2][n/2] +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/1500~1599/1573.Number-of-Ways-to-Split-a-String.md b/website/content/ChapterFour/1500~1599/1573.Number-of-Ways-to-Split-a-String.md index 85065f971..916d942a9 100644 --- a/website/content/ChapterFour/1500~1599/1573.Number-of-Ways-to-Split-a-String.md +++ b/website/content/ChapterFour/1500~1599/1573.Number-of-Ways-to-Split-a-String.md @@ -110,6 +110,6 @@ func numWays(s string) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/1500~1599/1576.Replace-All-s-to-Avoid-Consecutive-Repeating-Characters.md b/website/content/ChapterFour/1500~1599/1576.Replace-All-s-to-Avoid-Consecutive-Repeating-Characters.md new file mode 100644 index 000000000..7d57d2b0a --- /dev/null +++ b/website/content/ChapterFour/1500~1599/1576.Replace-All-s-to-Avoid-Consecutive-Repeating-Characters.md @@ -0,0 +1,70 @@ +# [1576. Replace All ?'s to Avoid Consecutive Repeating Characters](https://leetcode.com/problems/replace-all-s-to-avoid-consecutive-repeating-characters/) + +## 题目 + +Given a string `s` containing only lowercase English letters and the `'?'` character, convert **all** the `'?'` characters into lowercase letters such that the final string does not contain any **consecutive repeating** characters. You **cannot** modify the non `'?'` characters. + +It is **guaranteed** that there are no consecutive repeating characters in the given string **except** for `'?'`. + +Return *the final string after all the conversions (possibly zero) have been made*. If there is more than one solution, return **any of them**. It can be shown that an answer is always possible with the given constraints. + +**Example 1:** + +``` +Input: s = "?zs" +Output: "azs" +Explanation: There are 25 solutions for this problem. From "azs" to "yzs", all are valid. Only "z" is an invalid modification as the string will consist of consecutive repeating characters in "zzs". + +``` + +**Example 2:** + +``` +Input: s = "ubv?w" +Output: "ubvaw" +Explanation: There are 24 solutions for this problem. Only "v" and "w" are invalid modifications as the strings will consist of consecutive repeating characters in "ubvvw" and "ubvww". + +``` + +**Constraints:** + +- `1 <= s.length <= 100` +- `s` consist of lowercase English letters and `'?'`. + +## 题目大意 + +给你一个仅包含小写英文字母和 '?' 字符的字符串 s，请你将所有的 '?' 转换为若干小写字母，使最终的字符串不包含任何 连续重复 的字符。注意：你 不能 修改非 '?' 字符。 + +题目测试用例保证 除 '?' 字符 之外，不存在连续重复的字符。在完成所有转换（可能无需转换）后返回最终的字符串。如果有多个解决方案，请返回其中任何一个。可以证明，在给定的约束条件下，答案总是存在的。 + +## 解题思路 + +- 简单题。找到源字符串中 ‘?’ 字符的位置，然后依次用 a ~ z 字符去替换，替换进去的字符不能和前后字符相同即可。 + +## 代码 + +```go +package leetcode + +func modifyString(s string) string { + res := []byte(s) + for i, ch := range res { + if ch == '?' { + for b := byte('a'); b <= 'z'; b++ { + if !(i > 0 && res[i-1] == b || i < len(res)-1 && res[i+1] == b) { + res[i] = b + break + } + } + } + } + return string(res) +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/1500~1599/1579.Remove-Max-Number-of-Edges-to-Keep-Graph-Fully-Traversable.md b/website/content/ChapterFour/1500~1599/1579.Remove-Max-Number-of-Edges-to-Keep-Graph-Fully-Traversable.md index 594743b73..8806ed95d 100644 --- a/website/content/ChapterFour/1500~1599/1579.Remove-Max-Number-of-Edges-to-Keep-Graph-Fully-Traversable.md +++ b/website/content/ChapterFour/1500~1599/1579.Remove-Max-Number-of-Edges-to-Keep-Graph-Fully-Traversable.md @@ -73,7 +73,7 @@ Alice 和 Bob 共有一个无向图，其中包含 n 个节点和 3  种类型 package leetcode import ( - "github.com/halfrost/LeetCode-Go/template" + "github.com/halfrost/leetcode-go/template" ) func maxNumEdgesToRemove(n int, edges [][]int) int { @@ -105,6 +105,6 @@ func maxNumEdgesToRemove(n int, edges [][]int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/1600~1699/1600.Throne-Inheritance.md b/website/content/ChapterFour/1600~1699/1600.Throne-Inheritance.md new file mode 100644 index 000000000..c20245511 --- /dev/null +++ b/website/content/ChapterFour/1600~1699/1600.Throne-Inheritance.md @@ -0,0 +1,127 @@ +# [1600. Throne Inheritance](https://leetcode.com/problems/throne-inheritance/) + + +## 题目 + +A kingdom consists of a king, his children, his grandchildren, and so on. Every once in a while, someone in the family dies or a child is born. + +The kingdom has a well-defined order of inheritance that consists of the king as the first member. Let's define the recursive function `Successor(x, curOrder)`, which given a person `x` and the inheritance order so far, returns who should be the next person after `x` in the order of inheritance. + +``` +Successor(x, curOrder): + if x has no children or all of x's children are in curOrder: + if x is the king return null + else return Successor(x's parent, curOrder) + else return x's oldest child who's not in curOrder +``` + +For example, assume we have a kingdom that consists of the king, his children Alice and Bob (Alice is older than Bob), and finally Alice's son Jack. + +1. In the beginning, `curOrder` will be `["king"]`. +2. Calling `Successor(king, curOrder)` will return Alice, so we append to `curOrder` to get `["king", "Alice"]`. +3. Calling `Successor(Alice, curOrder)` will return Jack, so we append to `curOrder` to get `["king", "Alice", "Jack"]`. +4. Calling `Successor(Jack, curOrder)` will return Bob, so we append to `curOrder` to get `["king", "Alice", "Jack", "Bob"]`. +5. Calling `Successor(Bob, curOrder)` will return `null`. Thus the order of inheritance will be `["king", "Alice", "Jack", "Bob"]`. + +Using the above function, we can always obtain a unique order of inheritance. + +Implement the `ThroneInheritance` class: + +- `ThroneInheritance(string kingName)` Initializes an object of the `ThroneInheritance` class. The name of the king is given as part of the constructor. +- `void birth(string parentName, string childName)` Indicates that `parentName` gave birth to `childName`. +- `void death(string name)` Indicates the death of `name`. The death of the person doesn't affect the `Successor` function nor the current inheritance order. You can treat it as just marking the person as dead. +- `string[] getInheritanceOrder()` Returns a list representing the current order of inheritance **excluding** dead people. + +**Example 1:** + +``` +Input +["ThroneInheritance", "birth", "birth", "birth", "birth", "birth", "birth", "getInheritanceOrder", "death", "getInheritanceOrder"] +[["king"], ["king", "andy"], ["king", "bob"], ["king", "catherine"], ["andy", "matthew"], ["bob", "alex"], ["bob", "asha"], [null], ["bob"], [null]] +Output +[null, null, null, null, null, null, null, ["king", "andy", "matthew", "bob", "alex", "asha", "catherine"], null, ["king", "andy", "matthew", "alex", "asha", "catherine"]] + +Explanation +ThroneInheritance t= new ThroneInheritance("king"); // order:king +t.birth("king", "andy"); // order: king >andy +t.birth("king", "bob"); // order: king > andy >bob +t.birth("king", "catherine"); // order: king > andy > bob >catherine +t.birth("andy", "matthew"); // order: king > andy >matthew > bob > catherine +t.birth("bob", "alex"); // order: king > andy > matthew > bob >alex > catherine +t.birth("bob", "asha"); // order: king > andy > matthew > bob > alex >asha > catherine +t.getInheritanceOrder(); // return ["king", "andy", "matthew", "bob", "alex", "asha", "catherine"] +t.death("bob"); // order: king > andy > matthew >bob > alex > asha > catherine +t.getInheritanceOrder(); // return ["king", "andy", "matthew", "alex", "asha", "catherine"] + +``` + +**Constraints:** + +- `1 <= kingName.length, parentName.length, childName.length, name.length <= 15` +- `kingName`, `parentName`, `childName`, and `name` consist of lowercase English letters only. +- All arguments `childName` and `kingName` are **distinct**. +- All `name` arguments of `death` will be passed to either the constructor or as `childName` to `birth` first. +- For each call to `birth(parentName, childName)`, it is guaranteed that `parentName` is alive. +- At most `105` calls will be made to `birth` and `death`. +- At most `10` calls will be made to `getInheritanceOrder`. + +## 题目大意 + +一个王国里住着国王、他的孩子们、他的孙子们等等。每一个时间点，这个家庭里有人出生也有人死亡。这个王国有一个明确规定的皇位继承顺序，第一继承人总是国王自己。我们定义递归函数 Successor(x, curOrder) ，给定一个人 x 和当前的继承顺序，该函数返回 x 的下一继承人。 + +## 解题思路 + +- 这道题思路不难。先将国王每个孩子按照顺序存在一个 map 中，然后每个国王的孩子还存在父子关系，同理也按顺序存在 map 中。执行 GetInheritanceOrder() 函数时，将国王的孩子按顺序遍历，如果每个孩子还有孩子，递归遍历到底。如果把继承关系看成一棵树，此题便是多叉树的先根遍历的问题。 + +## 代码 + +```go +package leetcode + +type ThroneInheritance struct { + king string + edges map[string][]string + dead map[string]bool +} + +func Constructor(kingName string) (t ThroneInheritance) { + return ThroneInheritance{kingName, map[string][]string{}, map[string]bool{}} +} + +func (t *ThroneInheritance) Birth(parentName, childName string) { + t.edges[parentName] = append(t.edges[parentName], childName) +} + +func (t *ThroneInheritance) Death(name string) { + t.dead[name] = true +} + +func (t *ThroneInheritance) GetInheritanceOrder() (res []string) { + var preorder func(string) + preorder = func(name string) { + if !t.dead[name] { + res = append(res, name) + } + for _, childName := range t.edges[name] { + preorder(childName) + } + } + preorder(t.king) + return +} + +/** + * Your ThroneInheritance object will be instantiated and called as such: + * obj := Constructor(kingName); + * obj.Birth(parentName,childName); + * obj.Death(name); + * param_3 := obj.GetInheritanceOrder(); + */ +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/1600~1699/1603.Design-Parking-System.md b/website/content/ChapterFour/1600~1699/1603.Design-Parking-System.md index 8cbb81739..274894e60 100644 --- a/website/content/ChapterFour/1600~1699/1603.Design-Parking-System.md +++ b/website/content/ChapterFour/1600~1699/1603.Design-Parking-System.md @@ -105,6 +105,6 @@ func (this *ParkingSystem) AddCar(carType int) bool { ---------------------------------------------- diff --git a/website/content/ChapterFour/1600~1699/1608.Special-Array-With-X-Elements-Greater-Than-or-Equal-X.md b/website/content/ChapterFour/1600~1699/1608.Special-Array-With-X-Elements-Greater-Than-or-Equal-X.md index ac9a93658..447f61cc5 100644 --- a/website/content/ChapterFour/1600~1699/1608.Special-Array-With-X-Elements-Greater-Than-or-Equal-X.md +++ b/website/content/ChapterFour/1600~1699/1608.Special-Array-With-X-Elements-Greater-Than-or-Equal-X.md @@ -83,5 +83,5 @@ func specialArray(nums []int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/1600~1699/1609.Even-Odd-Tree.md b/website/content/ChapterFour/1600~1699/1609.Even-Odd-Tree.md new file mode 100644 index 000000000..66be442a9 --- /dev/null +++ b/website/content/ChapterFour/1600~1699/1609.Even-Odd-Tree.md @@ -0,0 +1,157 @@ +# [1609. Even Odd Tree](https://leetcode.com/problems/even-odd-tree/) + +## 题目 + +A binary tree is named Even-Odd if it meets the following conditions: + +- The root of the binary tree is at level index 0, its children are at level index 1, their children are at level index 2, etc. +- For every even-indexed level, all nodes at the level have odd integer values in strictly increasing order (from left to right). +- For every odd-indexed level, all nodes at the level have even integer values in strictly decreasing order (from left to right). + +Given the root of a binary tree, return true if the binary tree is Even-Odd, otherwise return false. + +**Example 1**: + +![https://assets.leetcode.com/uploads/2020/09/15/sample_1_1966.png](https://assets.leetcode.com/uploads/2020/09/15/sample_1_1966.png) + + Input: root = [1,10,4,3,null,7,9,12,8,6,null,null,2] + Output: true + Explanation: The node values on each level are: + Level 0: [1] + Level 1: [10,4] + Level 2: [3,7,9] + Level 3: [12,8,6,2] + Since levels 0 and 2 are all odd and increasing and levels 1 and 3 are all even and decreasing, the tree is Even-Odd. + +**Example 2**: + +![https://assets.leetcode.com/uploads/2020/09/15/sample_2_1966.png](https://assets.leetcode.com/uploads/2020/09/15/sample_2_1966.png) + + Input: root = [5,4,2,3,3,7] + Output: false + Explanation: The node values on each level are: + Level 0: [5] + Level 1: [4,2] + Level 2: [3,3,7] + Node values in level 2 must be in strictly increasing order, so the tree is not Even-Odd. + +**Example 3**: + +![https://assets.leetcode.com/uploads/2020/09/22/sample_1_333_1966.png](https://assets.leetcode.com/uploads/2020/09/22/sample_1_333_1966.png) + + Input: root = [5,9,1,3,5,7] + Output: false + Explanation: Node values in the level 1 should be even integers. + +**Example 4**: + + Input: root = [1] + Output: true + +**Example 5**: + + Input: root = [11,8,6,1,3,9,11,30,20,18,16,12,10,4,2,17] + Output: True + +**Constraints:** + +- The number of nodes in the tree is in the range [1, 100000]. +- 1 <= Node.val <= 1000000 + +## 题目大意 + +如果一棵二叉树满足下述几个条件，则可以称为 奇偶树 ： + +- 二叉树根节点所在层下标为 0 ，根的子节点所在层下标为 1 ，根的孙节点所在层下标为 2 ，依此类推。 +- 偶数下标 层上的所有节点的值都是 奇 整数，从左到右按顺序 严格递增 +- 奇数下标 层上的所有节点的值都是 偶 整数，从左到右按顺序 严格递减 + +给你二叉树的根节点，如果二叉树为 奇偶树 ，则返回 true ，否则返回 false 。 + +## 解题思路 + +- 广度优先遍历(分别判断奇数层和偶数层) + +## 代码 + +```go +package leetcode + +type TreeNode struct { + Val int + Left *TreeNode + Right *TreeNode +} + +func isEvenOddTree(root *TreeNode) bool { + level := 0 + queue := []*TreeNode{root} + for len(queue) != 0 { + length := len(queue) + var nums []int + for i := 0; i < length; i++ { + node := queue[i] + if node.Left != nil { + queue = append(queue, node.Left) + } + if node.Right != nil { + queue = append(queue, node.Right) + } + nums = append(nums, node.Val) + } + if level%2 == 0 { + if !even(nums) { + return false + } + } else { + if !odd(nums) { + return false + } + } + queue = queue[length:] + level++ + } + return true +} + +func odd(nums []int) bool { + cur := nums[0] + if cur%2 != 0 { + return false + } + for _, num := range nums[1:] { + if num >= cur { + return false + } + if num%2 != 0 { + return false + } + cur = num + } + return true +} + +func even(nums []int) bool { + cur := nums[0] + if cur%2 == 0 { + return false + } + for _, num := range nums[1:] { + if num <= cur { + return false + } + if num%2 == 0 { + return false + } + cur = num + } + return true +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/1600~1699/1614.Maximum-Nesting-Depth-of-the-Parentheses.md b/website/content/ChapterFour/1600~1699/1614.Maximum-Nesting-Depth-of-the-Parentheses.md index 4c24ceb5b..6800959bc 100644 --- a/website/content/ChapterFour/1600~1699/1614.Maximum-Nesting-Depth-of-the-Parentheses.md +++ b/website/content/ChapterFour/1600~1699/1614.Maximum-Nesting-Depth-of-the-Parentheses.md @@ -104,6 +104,6 @@ func max(a, b int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/1600~1699/1631.Path-With-Minimum-Effort.md b/website/content/ChapterFour/1600~1699/1631.Path-With-Minimum-Effort.md index 0fa9e2f09..e219d8c62 100644 --- a/website/content/ChapterFour/1600~1699/1631.Path-With-Minimum-Effort.md +++ b/website/content/ChapterFour/1600~1699/1631.Path-With-Minimum-Effort.md @@ -64,7 +64,7 @@ package leetcode import ( "sort" - "github.com/halfrost/LeetCode-Go/template" + "github.com/halfrost/leetcode-go/template" ) var dir = [4][2]int{ diff --git a/website/content/ChapterFour/1600~1699/1649.Create-Sorted-Array-through-Instructions.md b/website/content/ChapterFour/1600~1699/1649.Create-Sorted-Array-through-Instructions.md index fa098714b..cdd804681 100644 --- a/website/content/ChapterFour/1600~1699/1649.Create-Sorted-Array-through-Instructions.md +++ b/website/content/ChapterFour/1600~1699/1649.Create-Sorted-Array-through-Instructions.md @@ -85,7 +85,7 @@ package leetcode import ( "sort" - "github.com/halfrost/LeetCode-Go/template" + "github.com/halfrost/leetcode-go/template" ) // 解法一 树状数组 Binary Indexed Tree diff --git a/website/content/ChapterFour/1700~1799/1704.Determine-if-String-Halves-Are-Alike.md b/website/content/ChapterFour/1700~1799/1704.Determine-if-String-Halves-Are-Alike.md index a506dcbb7..e3e454298 100644 --- a/website/content/ChapterFour/1700~1799/1704.Determine-if-String-Halves-Are-Alike.md +++ b/website/content/ChapterFour/1700~1799/1704.Determine-if-String-Halves-Are-Alike.md @@ -78,5 +78,5 @@ func numVowels(x string) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/1700~1799/1705.Maximum-Number-of-Eaten-Apples.md b/website/content/ChapterFour/1700~1799/1705.Maximum-Number-of-Eaten-Apples.md new file mode 100644 index 000000000..fb4094c33 --- /dev/null +++ b/website/content/ChapterFour/1700~1799/1705.Maximum-Number-of-Eaten-Apples.md @@ -0,0 +1,131 @@ +# [1705. Maximum Number of Eaten Apples](https://leetcode.com/problems/maximum-number-of-eaten-apples/) + +## 题目 + +There is a special kind of apple tree that grows apples every day for n days. On the ith day, the tree grows apples[i] apples that will rot after days[i] days, that is on day i + days[i] the apples will be rotten and cannot be eaten. On some days, the apple tree does not grow any apples, which are denoted by apples[i] == 0 and days[i] == 0. + +You decided to eat at most one apple a day (to keep the doctors away). Note that you can keep eating after the first n days. + +Given two integer arrays days and apples of length n, return the maximum number of apples you can eat. + +**Example 1**: + + Input: apples = [1,2,3,5,2], days = [3,2,1,4,2] + Output: 7 + Explanation: You can eat 7 apples: + - On the first day, you eat an apple that grew on the first day. + - On the second day, you eat an apple that grew on the second day. + - On the third day, you eat an apple that grew on the second day. After this day, the apples that grew on the third day rot. + - On the fourth to the seventh days, you eat apples that grew on the fourth day. + +**Example 2**: + + Input: apples = [3,0,0,0,0,2], days = [3,0,0,0,0,2] + Output: 5 + Explanation: You can eat 5 apples: + - On the first to the third day you eat apples that grew on the first day. + - Do nothing on the fouth and fifth days. + - On the sixth and seventh days you eat apples that grew on the sixth day. + +**Constraints:** + +- apples.length == n +- days.length == n +- 1 <= n <= 2 * 10000 +- 0 <= apples[i], days[i] <= 2 * 10000 +- days[i] = 0 if and only if apples[i] = 0. + +## 题目大意 + +有一棵特殊的苹果树，一连 n 天，每天都可以长出若干个苹果。在第 i 天，树上会长出 apples[i] 个苹果，这些苹果将会在 days[i] 天后（也就是说，第 i + days[i] 天时）腐烂，变得无法食用。也可能有那么几天，树上不会长出新的苹果，此时用 apples[i] == 0 且 days[i] == 0 表示。 + +你打算每天 最多 吃一个苹果来保证营养均衡。注意，你可以在这 n 天之后继续吃苹果。 + +给你两个长度为 n 的整数数组 days 和 apples ，返回你可以吃掉的苹果的最大数目。 + +## 解题思路 + +贪心算法和最小堆 + + - data中的end表示腐烂的日期，left表示拥有的苹果数量 + - 贪心:每天吃掉end最小但没有腐烂的苹果 + - 最小堆:构造类型为数组(数组中元素的类型为data)的最小堆 + +## 代码 + +```go +package leetcode + +import "container/heap" + +func eatenApples(apples []int, days []int) int { + h := hp{} + i := 0 + var ans int + for ; i < len(apples); i++ { + for len(h) > 0 && h[0].end <= i { + heap.Pop(&h) + } + if apples[i] > 0 { + heap.Push(&h, data{apples[i], i + days[i]}) + } + if len(h) > 0 { + minData := heap.Pop(&h).(data) + ans++ + if minData.left > 1 { + heap.Push(&h, data{minData.left - 1, minData.end}) + } + } + } + for len(h) > 0 { + for len(h) > 0 && h[0].end <= i { + heap.Pop(&h) + } + if len(h) == 0 { + break + } + minData := heap.Pop(&h).(data) + nums := min(minData.left, minData.end-i) + ans += nums + i += nums + } + return ans +} + +func min(a, b int) int { + if a < b { + return a + } + return b +} + +type data struct { + left int + end int +} + +type hp []data + +func (h hp) Len() int { return len(h) } +func (h hp) Less(i, j int) bool { return h[i].end < h[j].end } +func (h hp) Swap(i, j int) { h[i], h[j] = h[j], h[i] } + +func (h *hp) Push(x interface{}) { + *h = append(*h, x.(data)) +} + +func (h *hp) Pop() interface{} { + old := *h + n := len(old) + x := old[n-1] + *h = old[0 : n-1] + return x +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/1700~1799/1710.Maximum-Units-on-a-Truck.md b/website/content/ChapterFour/1700~1799/1710.Maximum-Units-on-a-Truck.md index 8d7933546..2b311d0c0 100644 --- a/website/content/ChapterFour/1700~1799/1710.Maximum-Units-on-a-Truck.md +++ b/website/content/ChapterFour/1700~1799/1710.Maximum-Units-on-a-Truck.md @@ -79,6 +79,6 @@ func maximumUnits(boxTypes [][]int, truckSize int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/1700~1799/1721.Swapping-Nodes-in-a-Linked-List.md b/website/content/ChapterFour/1700~1799/1721.Swapping-Nodes-in-a-Linked-List.md index 96f76e0d7..70e7b2412 100644 --- a/website/content/ChapterFour/1700~1799/1721.Swapping-Nodes-in-a-Linked-List.md +++ b/website/content/ChapterFour/1700~1799/1721.Swapping-Nodes-in-a-Linked-List.md @@ -64,7 +64,7 @@ Output: [1,2,3] package leetcode import ( - "github.com/halfrost/LeetCode-Go/structures" + "github.com/halfrost/leetcode-go/structures" ) // ListNode define diff --git a/website/content/ChapterFour/1700~1799/1732.Find-the-Highest-Altitude.md b/website/content/ChapterFour/1700~1799/1732.Find-the-Highest-Altitude.md index 2534015d5..7ff314990 100644 --- a/website/content/ChapterFour/1700~1799/1732.Find-the-Highest-Altitude.md +++ b/website/content/ChapterFour/1700~1799/1732.Find-the-Highest-Altitude.md @@ -58,5 +58,5 @@ func largestAltitude(gain []int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/1700~1799/1734.Decode-XORed-Permutation.md b/website/content/ChapterFour/1700~1799/1734.Decode-XORed-Permutation.md new file mode 100644 index 000000000..eef845b91 --- /dev/null +++ b/website/content/ChapterFour/1700~1799/1734.Decode-XORed-Permutation.md @@ -0,0 +1,82 @@ +# [1734. Decode XORed Permutation](https://leetcode.com/problems/decode-xored-permutation/) + + +## 题目 + +There is an integer array `perm` that is a permutation of the first `n` positive integers, where `n` is always **odd**. + +It was encoded into another integer array `encoded` of length `n - 1`, such that `encoded[i] = perm[i] XOR perm[i + 1]`. For example, if `perm = [1,3,2]`, then `encoded = [2,1]`. + +Given the `encoded` array, return *the original array* `perm`. It is guaranteed that the answer exists and is unique. + +**Example 1:** + +``` +Input: encoded = [3,1] +Output: [1,2,3] +Explanation: If perm = [1,2,3], then encoded = [1 XOR 2,2 XOR 3] = [3,1] + +``` + +**Example 2:** + +``` +Input: encoded = [6,5,4,6] +Output: [2,4,1,5,3] + +``` + +**Constraints:** + +- `3 <= n < 10^5` +- `n` is odd. +- `encoded.length == n - 1` + +## 题目大意 + +给你一个整数数组 perm ，它是前 n 个正整数的排列，且 n 是个奇数 。它被加密成另一个长度为 n - 1 的整数数组 encoded ，满足 encoded[i] = perm[i] XOR perm[i + 1] 。比方说，如果 perm = [1,3,2] ，那么 encoded = [2,1] 。给你 encoded 数组，请你返回原始数组 perm 。题目保证答案存在且唯一。 + +## 解题思路 + +- 这一题与第 136 题和第 137 题思路类似，借用 `x ^ x = 0` 这个性质解题。依题意，原数组 perm 是 n 个正整数，即取值在 `[1,n+1]` 区间内，但是排列顺序未知。可以考虑先将 `[1,n+1]` 区间内的所有数异或得到 total。再将 encoded 数组中奇数下标的元素异或得到 odd： + + {{< katex display >}} + \begin{aligned}odd &= encoded[1] + encoded[3] + ... + encoded[n-1]\\&= (perm[1] \,\, XOR \,\, perm[2]) + (perm[3] \,\,  XOR  \,\, perm[4]) + ... + (perm[n-1]  \,\, XOR \,\, perm[n])\end{aligned} + {{< /katex >}} + + total 是 n 个正整数异或全集，odd 是 `n-1` 个正整数异或集。两者异或 `total ^ odd` 得到的值必定是 perm[0]，因为 `x ^ x = 0`，那么重复出现的元素被异或以后消失了。算出 perm[0] 就好办了。 + + {{< katex display >}} + \begin{aligned}encoded[0] &= perm[0] \,\, XOR \,\, perm[1]\\perm[0] \,\, XOR \,\, encoded[0] &= perm[0] \,\, XOR \,\, perm[0] \,\, XOR \,\, perm[1] = perm[1]\\perm[1] \,\, XOR \,\, encoded[1] &= perm[1] \,\, XOR \,\, perm[1] \,\, XOR \,\, perm[2] = perm[2]\\...\\perm[n-1] \,\, XOR \,\, encoded[n-1] &= perm[n-1] \,\, XOR \,\, perm[n-1] \,\, XOR \,\, perm[n] = perm[n]\\\end{aligned} + {{< /katex >}} + + 依次类推，便可以推出原数组 perm 中的所有数。 + +## 代码 + +```go +package leetcode + +func decode(encoded []int) []int { + n, total, odd := len(encoded), 0, 0 + for i := 1; i <= n+1; i++ { + total ^= i + } + for i := 1; i < n; i += 2 { + odd ^= encoded[i] + } + perm := make([]int, n+1) + perm[0] = total ^ odd + for i, v := range encoded { + perm[i+1] = perm[i] ^ v + } + return perm +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/1700~1799/1736.Latest-Time-by-Replacing-Hidden-Digits.md b/website/content/ChapterFour/1700~1799/1736.Latest-Time-by-Replacing-Hidden-Digits.md index 060275793..c8d3cf920 100644 --- a/website/content/ChapterFour/1700~1799/1736.Latest-Time-by-Replacing-Hidden-Digits.md +++ b/website/content/ChapterFour/1700~1799/1736.Latest-Time-by-Replacing-Hidden-Digits.md @@ -77,6 +77,6 @@ func maximumTime(time string) string { ---------------------------------------------- diff --git a/website/content/ChapterFour/1700~1799/1738.Find-Kth-Largest-XOR-Coordinate-Value.md b/website/content/ChapterFour/1700~1799/1738.Find-Kth-Largest-XOR-Coordinate-Value.md new file mode 100644 index 000000000..c5d0cc20b --- /dev/null +++ b/website/content/ChapterFour/1700~1799/1738.Find-Kth-Largest-XOR-Coordinate-Value.md @@ -0,0 +1,118 @@ +# [1738. Find Kth Largest XOR Coordinate Value](https://leetcode.com/problems/find-kth-largest-xor-coordinate-value/) + + +## 题目 + +You are given a 2D `matrix` of size `m x n`, consisting of non-negative integers. You are also given an integer `k`. + +The **value** of coordinate `(a, b)` of the matrix is the XOR of all `matrix[i][j]` where `0 <= i <= a < m` and `0 <= j <= b < n` **(0-indexed)**. + +Find the `kth` largest value **(1-indexed)** of all the coordinates of `matrix`. + +**Example 1:** + +``` +Input: matrix = [[5,2],[1,6]], k = 1 +Output: 7 +Explanation: The value of coordinate (0,1) is 5 XOR 2 = 7, which is the largest value. +``` + +**Example 2:** + +``` +Input: matrix = [[5,2],[1,6]], k = 2 +Output: 5 +Explanation:The value of coordinate (0,0) is 5 = 5, which is the 2nd largest value. +``` + +**Example 3:** + +``` +Input: matrix = [[5,2],[1,6]], k = 3 +Output: 4 +Explanation: The value of coordinate (1,0) is 5 XOR 1 = 4, which is the 3rd largest value. +``` + +**Example 4:** + +``` +Input: matrix = [[5,2],[1,6]], k = 4 +Output: 0 +Explanation: The value of coordinate (1,1) is 5 XOR 2 XOR 1 XOR 6 = 0, which is the 4th largest value. +``` + +**Constraints:** + +- `m == matrix.length` +- `n == matrix[i].length` +- `1 <= m, n <= 1000` +- `0 <= matrix[i][j] <= 10^6` +- `1 <= k <= m * n` + +## 题目大意 + +给你一个二维矩阵 matrix 和一个整数 k ，矩阵大小为 m x n 由非负整数组成。矩阵中坐标 (a, b) 的 值 可由对所有满足 0 <= i <= a < m 且 0 <= j <= b < n 的元素 matrix[i][j]（下标从 0 开始计数）执行异或运算得到。请你找出 matrix 的所有坐标中第 k 大的值（k 的值从 1 开始计数）。 + +## 解题思路 + +- 区间异或结果类比于区间二维前缀和。只不过需要注意 x^x = 0 这一性质。举例： + + ![](https://img.halfrost.com/Leetcode/leetcode_1738_0_.png) + + 通过简单推理，可以得出区间二维前缀和 preSum 的递推式。具体代码见解法二。 + +- 上面的解法中，preSum 用二维数组计算的。能否再优化空间复杂度，降低成 O(n)？答案是可以的。通过观察可以发现。preSum 可以按照一行一行来生成。先生成 preSum 前一行，下一行生成过程中会用到前一行的信息，异或计算以后，可以覆盖原数据(前一行的信息)，对之后的计算没有影响。这个优化空间复杂度的方法和优化 DP 空间复杂度是完全一样的思路和方法。 + + ![](https://img.halfrost.com/Leetcode/leetcode_1738_1_.png) + + 具体代码见解法一。 + +- 计算出了 preSum，还需要考虑如何输出第 k 大的值。有 3 种做法，第一种是排序，第二种是优先队列，第三种是第 215 题中的 O(n) 的 partition 方法。时间复杂度最低的当然是 O(n)。但是经过实际测试，runtime 最优的是排序的方法。所以笔者以下两种方法均采用了排序的方法。 + +## 代码 + +```go +package leetcode + +import "sort" + +// 解法一 压缩版的前缀和 +func kthLargestValue(matrix [][]int, k int) int { + if len(matrix) == 0 || len(matrix[0]) == 0 { + return 0 + } + res, prefixSum := make([]int, 0, len(matrix)*len(matrix[0])), make([]int, len(matrix[0])) + for i := range matrix { + line := 0 + for j, v := range matrix[i] { + line ^= v + prefixSum[j] ^= line + res = append(res, prefixSum[j]) + } + } + sort.Ints(res) + return res[len(res)-k] +} + +// 解法二 前缀和 +func kthLargestValue1(matrix [][]int, k int) int { + nums, prefixSum := []int{}, make([][]int, len(matrix)+1) + prefixSum[0] = make([]int, len(matrix[0])+1) + for i, row := range matrix { + prefixSum[i+1] = make([]int, len(matrix[0])+1) + for j, val := range row { + prefixSum[i+1][j+1] = prefixSum[i+1][j] ^ prefixSum[i][j+1] ^ prefixSum[i][j] ^ val + nums = append(nums, prefixSum[i+1][j+1]) + } + } + sort.Ints(nums) + return nums[len(nums)-k] +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/1700~1799/1742.Maximum-Number-of-Balls-in-a-Box.md b/website/content/ChapterFour/1700~1799/1742.Maximum-Number-of-Balls-in-a-Box.md index 9e06e974e..188f72959 100644 --- a/website/content/ChapterFour/1700~1799/1742.Maximum-Number-of-Balls-in-a-Box.md +++ b/website/content/ChapterFour/1700~1799/1742.Maximum-Number-of-Balls-in-a-Box.md @@ -83,6 +83,6 @@ func countBalls(lowLimit int, highLimit int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/1700~1799/1744.Can-You-Eat-Your-Favorite-Candy-on-Your-Favorite-Day.md b/website/content/ChapterFour/1700~1799/1744.Can-You-Eat-Your-Favorite-Candy-on-Your-Favorite-Day.md new file mode 100644 index 000000000..1be8f7864 --- /dev/null +++ b/website/content/ChapterFour/1700~1799/1744.Can-You-Eat-Your-Favorite-Candy-on-Your-Favorite-Day.md @@ -0,0 +1,95 @@ +# [1744. Can You Eat Your Favorite Candy on Your Favorite Day?](https://leetcode.com/problems/can-you-eat-your-favorite-candy-on-your-favorite-day/) + +## 题目 + +You are given a **(0-indexed)** array of positive integers `candiesCount` where `candiesCount[i]` represents the number of candies of the `ith` type you have. You are also given a 2D array `queries` where `queries[i] = [favoriteTypei, favoriteDayi, dailyCapi]`. + +You play a game with the following rules: + +- You start eating candies on day **`0`**. +- You **cannot** eat **any** candy of type `i` unless you have eaten **all** candies of type `i - 1`. +- You must eat **at least** **one** candy per day until you have eaten all the candies. + +Construct a boolean array `answer` such that `answer.length == queries.length` and `answer[i]` is `true` if you can eat a candy of type `favoriteTypei` on day `favoriteDayi` without eating **more than** `dailyCapi` candies on **any** day, and `false` otherwise. Note that you can eat different types of candy on the same day, provided that you follow rule 2. + +Return *the constructed array* `answer`. + +**Example 1:** + +``` +Input: candiesCount = [7,4,5,3,8], queries = [[0,2,2],[4,2,4],[2,13,1000000000]] +Output: [true,false,true] +Explanation: +1- If you eat 2 candies (type 0) on day 0 and 2 candies (type 0) on day 1, you will eat a candy of type 0 on day 2. +2- You can eat at most 4 candies each day. + If you eat 4 candies every day, you will eat 4 candies (type 0) on day 0 and 4 candies (type 0 and type 1) on day 1. + On day 2, you can only eat 4 candies (type 1 and type 2), so you cannot eat a candy of type 4 on day 2. +3- If you eat 1 candy each day, you will eat a candy of type 2 on day 13. +``` + +**Example 2:** + +``` +Input: candiesCount = [5,2,6,4,1], queries = [[3,1,2],[4,10,3],[3,10,100],[4,100,30],[1,3,1]] +Output: [false,true,true,false,false] +``` + +**Constraints:** + +- `1 <= candiesCount.length <= 105` +- `1 <= candiesCount[i] <= 105` +- `1 <= queries.length <= 105` +- `queries[i].length == 3` +- `0 <= favoriteTypei < candiesCount.length` +- `0 <= favoriteDayi <= 109` +- `1 <= dailyCapi <= 109` + +## 题目大意 + +给你一个下标从 0 开始的正整数数组 candiesCount ，其中 candiesCount[i] 表示你拥有的第 i 类糖果的数目。同时给你一个二维数组 queries ，其中 queries[i] = [favoriteTypei, favoriteDayi, dailyCapi] 。你按照如下规则进行一场游戏： + +- 你从第 0 天开始吃糖果。 +- 你在吃完 所有 第 i - 1 类糖果之前，不能 吃任何一颗第 i 类糖果。 +- 在吃完所有糖果之前，你必须每天 至少 吃 一颗 糖果。 + +请你构建一个布尔型数组 answer ，满足 answer.length == queries.length 。answer[i] 为 true 的条件是：在每天吃 不超过 dailyCapi 颗糖果的前提下，你可以在第 favoriteDayi 天吃到第 favoriteTypei 类糖果；否则 answer[i] 为 false 。注意，只要满足上面 3 条规则中的第二条规则，你就可以在同一天吃不同类型的糖果。请你返回得到的数组 answer 。 + +## 解题思路 + +- 每天吃糖个数的下限是 1 颗，上限是 dailyCap。针对每一个 query 查询在第 i 天能否吃到 i 类型的糖果，要想吃到 i 类型的糖果，必须吃完 i-1 类型的糖果。意味着在 [favoriteDayi + 1, (favoriteDayi+1)×dailyCapi] 区间内能否包含一颗第 favoriteTypei 类型的糖果。如果能包含则输出 true，不能包含则输出 false。吃的糖果数是累积的，所以这里利用前缀和计算出累积吃糖果数所在区间 [sum[favoriteTypei−1]+1, sum[favoriteTypei]]。最后判断 query 区间和累积吃糖果数的区间是否有重叠即可。如果重叠即输出 true。 +- 判断两个区间是否重合，情况有好几种：内包含，全包含，半包含等等。没有交集的情况比较少，所以可以用排除法。对于区间 [x1, y1] 以及 [x2, y2]，它们没有交集当且仅当 x1 > y2 或者 y1 < x2。 + +## 代码 + +```go +package leetcode + +func canEat(candiesCount []int, queries [][]int) []bool { + n := len(candiesCount) + prefixSum := make([]int, n) + prefixSum[0] = candiesCount[0] + for i := 1; i < n; i++ { + prefixSum[i] = prefixSum[i-1] + candiesCount[i] + } + res := make([]bool, len(queries)) + for i, q := range queries { + favoriteType, favoriteDay, dailyCap := q[0], q[1], q[2] + x1 := favoriteDay + 1 + y1 := (favoriteDay + 1) * dailyCap + x2 := 1 + if favoriteType > 0 { + x2 = prefixSum[favoriteType-1] + 1 + } + y2 := prefixSum[favoriteType] + res[i] = !(x1 > y2 || y1 < x2) + } + return res +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/1700~1799/1748.Sum-of-Unique-Elements.md b/website/content/ChapterFour/1700~1799/1748.Sum-of-Unique-Elements.md index 3f285687b..27fade95e 100644 --- a/website/content/ChapterFour/1700~1799/1748.Sum-of-Unique-Elements.md +++ b/website/content/ChapterFour/1700~1799/1748.Sum-of-Unique-Elements.md @@ -69,6 +69,6 @@ func sumOfUnique(nums []int) int { ---------------------------------------------- diff --git a/website/content/ChapterFour/1700~1799/1758.Minimum-Changes-To-Make-Alternating-Binary-String.md b/website/content/ChapterFour/1700~1799/1758.Minimum-Changes-To-Make-Alternating-Binary-String.md index 71215f25a..7e06a4478 100644 --- a/website/content/ChapterFour/1700~1799/1758.Minimum-Changes-To-Make-Alternating-Binary-String.md +++ b/website/content/ChapterFour/1700~1799/1758.Minimum-Changes-To-Make-Alternating-Binary-String.md @@ -70,7 +70,8 @@ func min(a, b int) int { ``` - ---------------------------------------------- + diff --git a/website/content/ChapterFour/1700~1799/1763.Longest-Nice-Substring.md b/website/content/ChapterFour/1700~1799/1763.Longest-Nice-Substring.md new file mode 100644 index 000000000..4b574b199 --- /dev/null +++ b/website/content/ChapterFour/1700~1799/1763.Longest-Nice-Substring.md @@ -0,0 +1,147 @@ +# [1763. Longest Nice Substring](https://leetcode.com/problems/longest-nice-substring/) + + +## 题目 + +A string `s` is **nice** if, for every letter of the alphabet that `s` contains, it appears **both** in uppercase and lowercase. For example, `"abABB"` is nice because `'A'` and `'a'` appear, and `'B'` and `'b'` appear. However, `"abA"` is not because `'b'` appears, but `'B'` does not. + +Given a string `s`, return *the longest **substring** of `s` that is **nice**. If there are multiple, return the substring of the **earliest** occurrence. If there are none, return an empty string*. + +**Example 1:** + +``` +Input: s = "YazaAay" +Output: "aAa" +Explanation:"aAa" is a nice string because 'A/a' is the only letter of the alphabet in s, and both 'A' and 'a' appear. +"aAa" is the longest nice substring. + +``` + +**Example 2:** + +``` +Input: s = "Bb" +Output: "Bb" +Explanation: "Bb" is a nice string because both 'B' and 'b' appear. The whole string is a substring. + +``` + +**Example 3:** + +``` +Input: s = "c" +Output: "" +Explanation: There are no nice substrings. + +``` + +**Constraints:** + +- `1 <= s.length <= 100` +- `s` consists of uppercase and lowercase English letters. + +## 题目大意 + +当一个字符串 s 包含的每一种字母的大写和小写形式 同时 出现在 s 中，就称这个字符串 s 是 美好 字符串。比方说，"abABB" 是美好字符串，因为 'A' 和 'a' 同时出现了，且 'B' 和 'b' 也同时出现了。然而，"abA" 不是美好字符串因为 'b' 出现了，而 'B' 没有出现。 + +给你一个字符串 s ，请你返回 s 最长的 美好子字符串 。如果有多个答案，请你返回 最早 出现的一个。如果不存在美好子字符串，请你返回一个空字符串。 + +## 解题思路 + +- 解法一，暴力解法。枚举每一段字符串，判断这个子字符串内是否满足美好字符串的定义，即字母的大小写是否同时出现。 +- 解法二，这个解法是解法一的小幅优化版，利用二进制记录状态。先构造二进制状态串，再利用直接比较这个二进制串。 +- 解法三，分治。以 `i` 为分割点依次切开字符串。左右两个字符串分别判断是否满足美好字符串的定义。左右分开的字符串还可以继续划分。直至分到一个字母为止。在这个过程中记录最早出现的字符串。 + +## 代码 + +```go +package leetcode + +import "unicode" + +// 解法一 分治，时间复杂度 O(n) +func longestNiceSubstring(s string) string { + if len(s) < 2 { + return "" + } + + chars := map[rune]int{} + for _, r := range s { + chars[r]++ + } + + for i := 0; i < len(s); i++ { + r := rune(s[i]) + _, u := chars[unicode.ToUpper(r)] + _, l := chars[unicode.ToLower(r)] + if u && l { + continue + } + left := longestNiceSubstring(s[:i]) + right := longestNiceSubstring(s[i+1:]) + if len(left) >= len(right) { + return left + } else { + return right + } + } + return s +} + +// 解法二 用二进制表示状态 +func longestNiceSubstring1(s string) (ans string) { + for i := range s { + lower, upper := 0, 0 + for j := i; j < len(s); j++ { + if unicode.IsLower(rune(s[j])) { + lower |= 1 << (s[j] - 'a') + } else { + upper |= 1 << (s[j] - 'A') + } + if lower == upper && j-i+1 > len(ans) { + ans = s[i : j+1] + } + } + } + return +} + +// 解法三 暴力枚举，时间复杂度 O(n^2) +func longestNiceSubstring2(s string) string { + res := "" + for i := 0; i < len(s); i++ { + m := map[byte]int{} + m[s[i]]++ + for j := i + 1; j < len(s); j++ { + m[s[j]]++ + if checkNiceString(m) && (j-i+1 > len(res)) { + res = s[i : j+1] + } + } + } + return res +} + +func checkNiceString(m map[byte]int) bool { + for k := range m { + if k >= 97 && k <= 122 { + if _, ok := m[k-32]; !ok { + return false + } + } + if k >= 65 && k <= 90 { + if _, ok := m[k+32]; !ok { + return false + } + } + } + return true +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/1700~1799/1791.Find-Center-of-Star-Graph.md b/website/content/ChapterFour/1700~1799/1791.Find-Center-of-Star-Graph.md new file mode 100644 index 000000000..6e91c8abc --- /dev/null +++ b/website/content/ChapterFour/1700~1799/1791.Find-Center-of-Star-Graph.md @@ -0,0 +1,59 @@ +# [1791.Find Center of Star Graph](https://leetcode.com/problems/find-center-of-star-graph/) + +## 题目 + +There is an undirected star graph consisting of n nodes labeled from 1 to n. A star graph is a graph where there is one center node and exactly n - 1 edges that connect the center node with every other node. + +You are given a 2D integer array edges where each edges[i] = [ui, vi] indicates that there is an edge between the nodes ui and vi. Return the center of the given star graph. + +**Example 1:** + +![https://assets.leetcode.com/uploads/2021/02/24/star_graph.png:w](https://assets.leetcode.com/uploads/2021/02/24/star_graph.png) + + Input: edges = [[1,2],[2,3],[4,2]] + Output: 2 + Explanation: As shown in the figure above, node 2 is connected to every other node, so 2 is the center. + +**Example 2:** + + Input: edges = [[1,2],[5,1],[1,3],[1,4]] + Output: 1 + +**Constraints:** + +- 3 <= n <= 100000 +- edges.length == n - 1 +- edges[i].length == 2 +- 1 <= ui, vi <= n +- ui != vi +- The given edges represent a valid star graph. + +## 题目大意 + +有一个无向的 星型 图，由 n 个编号从 1 到 n 的节点组成。星型图有一个 中心 节点，并且恰有 n - 1 条边将中心节点与其他每个节点连接起来。 + +给你一个二维整数数组 edges ，其中 edges[i] = [ui, vi] 表示在节点 ui 和 vi 之间存在一条边。请你找出并返回 edges 所表示星型图的中心节点。 + +## 解题思路 + +- 求出edges中前两个元素的共同值，即是中心节点 + +## 代码 + +```go +package leetcode + +func findCenter(edges [][]int) int { + if edges[0][0] == edges[1][0] || edges[0][0] == edges[1][1] { + return edges[0][0] + } + return edges[0][1] +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/1800~1899/1816.Truncate-Sentence.md b/website/content/ChapterFour/1800~1899/1816.Truncate-Sentence.md new file mode 100644 index 000000000..74b52d890 --- /dev/null +++ b/website/content/ChapterFour/1800~1899/1816.Truncate-Sentence.md @@ -0,0 +1,83 @@ +# [1816. Truncate Sentence](https://leetcode.com/problems/truncate-sentence/) + +## 题目 + +A sentence is a list of words that are separated by a single space with no leading or trailing spaces. Each of the words consists of only uppercase and lowercase English letters (no punctuation). + +- For example, "Hello World", "HELLO", and "hello world hello world" are all sentences. + +You are given a sentence s and an integer k. You want to truncate s such that it contains only the first k words. Return s after truncating it. + +**Example 1**: + + Input: s = "Hello how are you Contestant", k = 4 + Output: "Hello how are you" + Explanation: + The words in s are ["Hello", "how" "are", "you", "Contestant"]. + The first 4 words are ["Hello", "how", "are", "you"]. + Hence, you should return "Hello how are you". + +**Example 2**: + + Input: s = "What is the solution to this problem", k = 4 + Output: "What is the solution" + Explanation: + The words in s are ["What", "is" "the", "solution", "to", "this", "problem"]. + The first 4 words are ["What", "is", "the", "solution"]. + Hence, you should return "What is the solution". + +**Example 3**: + + Input: s = "chopper is not a tanuki", k = 5 + Output: "chopper is not a tanuki" + +**Constraints:** + +- 1 <= s.length <= 500 +- k is in the range [1, the number of words in s]. +- s consist of only lowercase and uppercase English letters and spaces. +- The words in s are separated by a single space. +- There are no leading or trailing spaces. + +## 题目大意 + +句子 是一个单词列表，列表中的单词之间用单个空格隔开，且不存在前导或尾随空格。每个单词仅由大小写英文字母组成（不含标点符号）。 + +- 例如，"Hello World"、"HELLO" 和 "hello world hello world" 都是句子。 + +给你一个句子 s 和一个整数 k ，请你将 s 截断使截断后的句子仅含前 k 个单词。返回截断 s 后得到的句子。 + +## 解题思路 + +- 遍历字符串 s，找到最后一个空格的下标 end +- 如果 end 为 0，直接返回 s,否则返回 s[:end] + +## 代码 + +```go +package leetcode + +func truncateSentence(s string, k int) string { + end := 0 + for i := range s { + if k > 0 && s[i] == ' ' { + k-- + } + if k == 0 { + end = i + break + } + } + if end == 0 { + return s + } + return s[:end] +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/1800~1899/1818.Minimum-Absolute-Sum-Difference.md b/website/content/ChapterFour/1800~1899/1818.Minimum-Absolute-Sum-Difference.md new file mode 100644 index 000000000..204e09c1a --- /dev/null +++ b/website/content/ChapterFour/1800~1899/1818.Minimum-Absolute-Sum-Difference.md @@ -0,0 +1,115 @@ +# [1818. Minimum Absolute Sum Difference](https://leetcode.com/problems/minimum-absolute-sum-difference/) + +## 题目 + +You are given two positive integer arrays `nums1` and `nums2`, both of length `n`. + +The **absolute sum difference** of arrays `nums1` and `nums2` is defined as the **sum** of `|nums1[i] - nums2[i]|` for each `0 <= i < n` (**0-indexed**). + +You can replace **at most one** element of `nums1` with **any** other element in `nums1` to **minimize** the absolute sum difference. + +Return the *minimum absolute sum difference **after** replacing at most one ****element in the array `nums1`.* Since the answer may be large, return it **modulo** `109 + 7`. + +`|x|` is defined as: + +- `x` if `x >= 0`, or +- `x` if `x < 0`. + +**Example 1:** + +``` +Input: nums1 = [1,7,5], nums2 = [2,3,5] +Output: 3 +Explanation:There are two possible optimal solutions: +- Replace the second element with the first: [1,7,5] => [1,1,5], or +- Replace the second element with the third: [1,7,5] => [1,5,5]. +Both will yield an absolute sum difference of|1-2| + (|1-3| or |5-3|) + |5-5| =3. + +``` + +**Example 2:** + +``` +Input: nums1 = [2,4,6,8,10], nums2 = [2,4,6,8,10] +Output: 0 +Explanation:nums1 is equal to nums2 so no replacement is needed. This will result in an +absolute sum difference of 0. + +``` + +**Example 3:** + +``` +Input: nums1 = [1,10,4,4,2,7], nums2 = [9,3,5,1,7,4] +Output: 20 +Explanation:Replace the first element with the second: [1,10,4,4,2,7] => [10,10,4,4,2,7]. +This yields an absolute sum difference of|10-9| + |10-3| + |4-5| + |4-1| + |2-7| + |7-4| = 20 +``` + +**Constraints:** + +- `n == nums1.length` +- `n == nums2.length` +- `1 <= n <= 10^5` +- `1 <= nums1[i], nums2[i] <= 10^5` + +## 题目大意 + +给你两个正整数数组 nums1 和 nums2 ，数组的长度都是 n 。数组 nums1 和 nums2 的 绝对差值和 定义为所有 |nums1[i] - nums2[i]|（0 <= i < n）的 总和（下标从 0 开始）。你可以选用 nums1 中的 任意一个 元素来替换 nums1 中的 至多 一个元素，以 最小化 绝对差值和。在替换数组 nums1 中最多一个元素 之后 ，返回最小绝对差值和。因为答案可能很大，所以需要对 10^9 + 7 取余 后返回。 + +## 解题思路 + +- 如果不改变任何元素，绝对差值和为 {{< katex >}} \sum \left | nums1[i] - nums2[i] \right | {{< /katex >}}。如果改变一个元素后，那么绝对差值和为 + {{< katex display>}} \begin{aligned}&\sum \left | nums1[i] - nums2[i] \right | - \left ( \left | nums1[i] - nums2[i] \right | - \left | nums1[j] - nums2[i] \right |\right )\\= &\sum \left | nums1[i] - nums2[i] \right | - \Delta \end{aligned} {{< /katex >}} + + 题目要求返回最小绝对差值和，即求 {{< katex >}}\Delta {{< /katex >}} 的最大值。暴力枚举 nums1 和 nums2 中两两差值，找到 maxdiff，即 {{< katex >}}\Delta {{< /katex >}} 的最大值，此题得到解。 + +## 代码 + +```go +package leetcode + +func minAbsoluteSumDiff(nums1 []int, nums2 []int) int { + diff := 0 + maxDiff := 0 + for i, n2 := range nums2 { + d := abs(nums1[i] - n2) + diff += d + if maxDiff < d { + t := 100001 + for _, n1 := range nums1 { + maxDiff = max(maxDiff, d-min(t, abs(n1-n2))) + } + } + } + return (diff - maxDiff) % (1e9 + 7) +} + +func max(a, b int) int { + if a > b { + return a + } + return b +} + +func abs(a int) int { + if a > 0 { + return a + } + return -a +} + +func min(a, b int) int { + if a > b { + return b + } + return a +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/1800~1899/1846.Maximum-Element-After-Decreasing-and-Rearranging.md b/website/content/ChapterFour/1800~1899/1846.Maximum-Element-After-Decreasing-and-Rearranging.md new file mode 100644 index 000000000..8b68e57ac --- /dev/null +++ b/website/content/ChapterFour/1800~1899/1846.Maximum-Element-After-Decreasing-and-Rearranging.md @@ -0,0 +1,110 @@ +# [1846. Maximum Element After Decreasing and Rearranging](https://leetcode.com/problems/maximum-element-after-decreasing-and-rearranging/) + + +## 题目 + +You are given an array of positive integers `arr`. Perform some operations (possibly none) on `arr` so that it satisfies these conditions: + +- The value of the **first** element in `arr` must be `1`. +- The absolute difference between any 2 adjacent elements must be **less than or equal to** `1`. In other words, `abs(arr[i] - arr[i - 1]) <= 1` for each `i` where `1 <= i < arr.length` (**0-indexed**). `abs(x)` is the absolute value of `x`. + +There are 2 types of operations that you can perform any number of times: + +- **Decrease** the value of any element of `arr` to a **smaller positive integer**. +- **Rearrange** the elements of `arr` to be in any order. + +Return *the **maximum** possible value of an element in* `arr` *after performing the operations to satisfy the conditions*. + +**Example 1:** + +``` +Input: arr = [2,2,1,2,1] +Output: 2 +Explanation: +We can satisfy the conditions by rearrangingarr so it becomes[1,2,2,2,1]. +The largest element inarr is 2. + +``` + +**Example 2:** + +``` +Input: arr = [100,1,1000] +Output: 3 +Explanation: +One possible way to satisfy the conditions is by doing the following: +1. Rearrangearr so it becomes[1,100,1000]. +2. Decrease the value of the second element to 2. +3. Decrease the value of the third element to 3. +Nowarr = [1,2,3], whichsatisfies the conditions. +The largest element inarr is 3. +``` + +**Example 3:** + +``` +Input: arr = [1,2,3,4,5] +Output: 5 +Explanation: The array already satisfies the conditions, and the largest element is 5. + +``` + +**Constraints:** + +- `1 <= arr.length <= 10^5` +- `1 <= arr[i] <= 10^9` + +## 题目大意 + +给你一个正整数数组 arr 。请你对 arr 执行一些操作（也可以不进行任何操作），使得数组满足以下条件： + +- arr 中 第一个 元素必须为 1 。 +- 任意相邻两个元素的差的绝对值 小于等于 1 ，也就是说，对于任意的 1 <= i < arr.length （数组下标从 0 开始），都满足 abs(arr[i] - arr[i - 1]) <= 1 。abs(x) 为 x 的绝对值。 + +你可以执行以下 2 种操作任意次： + +- 减小 arr 中任意元素的值，使其变为一个 更小的正整数 。 +- 重新排列 arr 中的元素，你可以以任意顺序重新排列。 + +请你返回执行以上操作后，在满足前文所述的条件下，arr 中可能的 最大值 。 + +## 解题思路 + +- 正整数数组 arr 第一个元素必须为 1，且两两元素绝对值小于等于 1，那么 arr 最大值肯定不大于 n。采用贪心的策略，先统计所有元素出现的次数，大于 n 的元素出现次数都累加到 n 上。然后从 1 扫描到 n，遇到“空隙”（出现次数为 0 的元素），便将最近一个出现次数大于 1 的元素“挪”过来填补“空隙”。题目所求最大值出现在，“填补空隙”之后，数组从左往右连续的最右端。 + +## 代码 + +```go +package leetcode + +func maximumElementAfterDecrementingAndRearranging(arr []int) int { + n := len(arr) + count := make([]int, n+1) + for _, v := range arr { + count[min(v, n)]++ + } + miss := 0 + for _, c := range count[1:] { + if c == 0 { + miss++ + } else { + miss -= min(c-1, miss) + } + } + return n - miss +} + +func min(a, b int) int { + if a < b { + return a + } + return b +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/1800~1899/1877.Minimize-Maximum-Pair-Sum-in-Array.md b/website/content/ChapterFour/1800~1899/1877.Minimize-Maximum-Pair-Sum-in-Array.md new file mode 100644 index 000000000..26bc64c66 --- /dev/null +++ b/website/content/ChapterFour/1800~1899/1877.Minimize-Maximum-Pair-Sum-in-Array.md @@ -0,0 +1,87 @@ +# [1877. Minimize Maximum Pair Sum in Array](https://leetcode.com/problems/minimize-maximum-pair-sum-in-array/) + + +## 题目 + +The **pair sum** of a pair `(a,b)` is equal to `a + b`. The **maximum pair sum** is the largest **pair sum** in a list of pairs. + +- For example, if we have pairs `(1,5)`, `(2,3)`, and `(4,4)`, the **maximum pair sum** would be `max(1+5, 2+3, 4+4) = max(6, 5, 8) = 8`. + +Given an array `nums` of **even** length `n`, pair up the elements of `nums` into `n / 2` pairs such that: + +- Each element of `nums` is in **exactly one** pair, and +- The **maximum pair sum** is **minimized**. + +Return *the minimized **maximum pair sum** after optimally pairing up the elements*. + +**Example 1:** + +``` +Input: nums = [3,5,2,3] +Output: 7 +Explanation: The elements can be paired up into pairs (3,3) and (5,2). +The maximum pair sum is max(3+3, 5+2) = max(6, 7) = 7. +``` + +**Example 2:** + +``` +Input: nums = [3,5,4,2,4,6] +Output: 8 +Explanation: The elements can be paired up into pairs (3,5), (4,4), and (6,2). +The maximum pair sum is max(3+5, 4+4, 6+2) = max(8, 8, 8) = 8. +``` + +**Constraints:** + +- `n == nums.length` +- `2 <= n <= 105` +- `n` is **even**. +- `1 <= nums[i] <= 105` + +## 题目大意 + +一个数对 (a,b) 的 **数对和** 等于 a + b 。**最大数对和** 是一个数对数组中最大的 数对和 。 + +- 比方说，如果我们有数对 (1,5) ，(2,3) 和 (4,4)，**最大数对和** 为 max(1+5, 2+3, 4+4) = max(6, 5, 8) = 8 。 + +给你一个长度为 **偶数** n 的数组 nums ，请你将 nums 中的元素分成 n / 2 个数对，使得： + +- nums 中每个元素 **恰好** 在 一个 数对中，且 +- **最大数对和** 的值 **最小** 。 + +请你在最优数对划分的方案下，返回最小的 最大数对和 。 + +## 解题思路 + +- 要想最大数对和最小，那么最大的元素一定只能和最小的元素组合在一起，不然一定不是最小。当最大元素和最小元素组合在一起了，剩下的次最大元素也应该和次最小元素组合在一起。按照这个思路，先将数组从小到大排序，然后依次取出首尾元素，两两组合在一起。输出这些数对的最大值即为所求。 + +## 代码 + +```go +package leetcode + +import "sort" + +func minPairSum(nums []int) int { + sort.Ints(nums) + n, res := len(nums), 0 + for i, val := range nums[:n/2] { + res = max(res, val+nums[n-1-i]) + } + return res +} + +func max(a, b int) int { + if a > b { + return a + } + return b +} +``` + +---------------------------------------------- + diff --git a/website/content/ChapterFour/1800~1899/_index.md b/website/content/ChapterFour/1800~1899/_index.md new file mode 100644 index 000000000..e954f0877 --- /dev/null +++ b/website/content/ChapterFour/1800~1899/_index.md @@ -0,0 +1,4 @@ +--- +bookCollapseSection: true +weight: 20 +--- diff --git a/website/content/ChapterFour/1900~1999/1984.Minimum-Difference-Between-Highest-and-Lowest-of-K-Scores.md b/website/content/ChapterFour/1900~1999/1984.Minimum-Difference-Between-Highest-and-Lowest-of-K-Scores.md new file mode 100644 index 000000000..31ce16d63 --- /dev/null +++ b/website/content/ChapterFour/1900~1999/1984.Minimum-Difference-Between-Highest-and-Lowest-of-K-Scores.md @@ -0,0 +1,78 @@ +# [1984. Minimum Difference Between Highest and Lowest of K Scores](https://leetcode.com/problems/minimum-difference-between-highest-and-lowest-of-k-scores/) + +## 题目 + +You are given a 0-indexed integer array nums, where nums[i] represents the score of the ith student. You are also given an integer k. + +Pick the scores of any k students from the array so that the difference between the highest and the lowest of the k scores is minimized. + +Return the minimum possible difference. + +**Example 1:** + + Input: nums = [90], k = 1 + Output: 0 + Explanation: There is one way to pick score(s) of one student: + - [90]. The difference between the highest and lowest score is 90 - 90 = 0. + The minimum possible difference is 0. + +**Example 2:** + + Input: nums = [9,4,1,7], k = 2 + Output: 2 + Explanation: There are six ways to pick score(s) of two students: + - [9,4,1,7]. The difference between the highest and lowest score is 9 - 4 = 5. + - [9,4,1,7]. The difference between the highest and lowest score is 9 - 1 = 8. + - [9,4,1,7]. The difference between the highest and lowest score is 9 - 7 = 2. + - [9,4,1,7]. The difference between the highest and lowest score is 4 - 1 = 3. + - [9,4,1,7]. The difference between the highest and lowest score is 7 - 4 = 3. + - [9,4,1,7]. The difference between the highest and lowest score is 7 - 1 = 6. + The minimum possible difference is 2. + +**Constraints:** + +- 1 <= k <= nums.length <= 1000 +- 0 <= nums[i] <= 100000 + +## 题目大意 + +给你一个下标从 0 开始的整数数组 nums ，其中 nums[i] 表示第 i 名学生的分数。另给你一个整数 k 。 + +从数组中选出任意 k 名学生的分数，使这 k 个分数间最高分和最低分的差值达到最小化 。 + +返回可能的最小差值 。 + +## 解题思路 + +- nums 排序 +- 求出nums[i+k-1] - nums[i]中的最小差值 + +## 代码 + +```go +package leetcode + +import "sort" + +func minimumDifference(nums []int, k int) int { + sort.Ints(nums) + minDiff := 100000 + 1 + for i := 0; i < len(nums); i++ { + if i+k-1 >= len(nums) { + break + } + diff := nums[i+k-1] - nums[i] + if diff < minDiff { + minDiff = diff + } + } + return minDiff +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/1900~1999/_index.md b/website/content/ChapterFour/1900~1999/_index.md new file mode 100644 index 000000000..e954f0877 --- /dev/null +++ b/website/content/ChapterFour/1900~1999/_index.md @@ -0,0 +1,4 @@ +--- +bookCollapseSection: true +weight: 20 +--- diff --git a/website/content/ChapterFour/2000~2099/2021.Brightest-Position-on-Street.md b/website/content/ChapterFour/2000~2099/2021.Brightest-Position-on-Street.md new file mode 100644 index 000000000..d223af086 --- /dev/null +++ b/website/content/ChapterFour/2000~2099/2021.Brightest-Position-on-Street.md @@ -0,0 +1,116 @@ +# [2021. Brightest Position on Street](https://leetcode.com/problems/brightest-position-on-street/) + + +## 题目 + +A perfectly straight street is represented by a number line. The street has street lamp(s) on it and is represented by a 2D integer array `lights`. Each `lights[i] = [positioni, rangei]` indicates that there is a street lamp at position `positioni` that lights up the area from `[positioni - rangei, positioni + rangei]` (**inclusive**). + +The **brightness** of a position `p` is defined as the number of street lamp that light up the position `p`. + +Given `lights`, return *the **brightest** position on the street. If there are multiple brightest positions, return the **smallest** one.* + +**Example 1:** + +![https://assets.leetcode.com/uploads/2021/09/28/image-20210928155140-1.png](https://assets.leetcode.com/uploads/2021/09/28/image-20210928155140-1.png) + +``` +Input: lights = [[-3,2],[1,2],[3,3]] +Output: -1 +Explanation: +The first street lamp lights up the area from [(-3) - 2, (-3) + 2] = [-5, -1]. +The second street lamp lights up the area from [1 - 2, 1 + 2] = [-1, 3]. +The third street lamp lights up the area from [3 - 3, 3 + 3] = [0, 6]. + +Position -1 has a brightness of 2, illuminated by the first and second street light. +Positions 0, 1, 2, and 3 have a brightness of 2, illuminated by the second and third street light. +Out of all these positions, -1 is the smallest, so return it. + +``` + +**Example 2:** + +``` +Input: lights = [[1,0],[0,1]] +Output: 1 +Explanation: +The first street lamp lights up the area from [1 - 0, 1 + 0] = [1, 1]. +The second street lamp lights up the area from [0 - 1, 0 + 1] = [-1, 1]. + +Position 1 has a brightness of 2, illuminated by the first and second street light. +Return 1 because it is the brightest position on the street. + +``` + +**Example 3:** + +``` +Input: lights = [[1,2]] +Output: -1 +Explanation: +The first street lamp lights up the area from [1 - 2, 1 + 2] = [-1, 3]. + +Positions -1, 0, 1, 2, and 3 have a brightness of 1, illuminated by the first street light. +Out of all these positions, -1 is the smallest, so return it. + +``` + +**Constraints:** + +- `1 <= lights.length <= 105` +- `lights[i].length == 2` +- `108 <= positioni <= 108` +- `0 <= rangei <= 108` + +## 题目大意 + +一条完全笔直的街道由一条数字线表示。街道上有路灯，由二维数据表示。每个 `lights[i] = [positioni, rangei]` 表示位置 `i` 处有一盏路灯，灯可以照亮从 `[positioni - rangei, positioni + rangei]` （含）的区域。 位置 `p` 的亮度定义为点亮位置 `p` 的路灯数量。 给定路灯，返回街道上最亮的位置。如果有多个最亮的位置，则返回最小的一个。 + +## 解题思路 + +- 先将每个路灯的起始和终点位置计算出来。这样我们得到了一堆坐标点。假设灯照亮的范围是 [A, B]，那么在坐标轴上 A 坐标点处 + 1， B + 1 坐标点处 -1 。这样处理的含义是：坐标点 A 可以被一盏灯照亮，所以它照亮次数加一，坐标点 B + 1 出了灯照亮的范围了，所以照亮次数减一。那么从坐标轴坐标开始扫一遍，每次遇到 + 1 的时候就 + 1，遇到 - 1 的地方就 - 1。如此可以算出某个坐标点处，可以被灯照亮的总次数。 +- 需要注意的点是，题目给的测试数据可能会有单点照亮的情况，即某一盏灯只照亮一个坐标点，灯照范围为 0。同一个坐标点也可能是多个灯的起点。用一个 map 去重坐标点即可。 + +## 代码 + +```go +package leetcode + +import ( + "sort" +) + +type lightItem struct { + index int + sign int +} + +func brightestPosition(lights [][]int) int { + lightMap, lightItems := map[int]int{}, []lightItem{} + for _, light := range lights { + lightMap[light[0]-light[1]] += 1 + lightMap[light[0]+light[1]+1] -= 1 + } + for k, v := range lightMap { + lightItems = append(lightItems, lightItem{index: k, sign: v}) + } + sort.SliceStable(lightItems, func(i, j int) bool { + return lightItems[i].index < lightItems[j].index + }) + res, border, tmp := 0, 0, 0 + for _, v := range lightItems { + tmp += v.sign + if border < tmp { + res = v.index + border = tmp + } + } + return res +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/2000~2099/2022.Convert-1D-Array-Into-2D-Array.md b/website/content/ChapterFour/2000~2099/2022.Convert-1D-Array-Into-2D-Array.md new file mode 100644 index 000000000..29646b4a0 --- /dev/null +++ b/website/content/ChapterFour/2000~2099/2022.Convert-1D-Array-Into-2D-Array.md @@ -0,0 +1,84 @@ +# [2022. Convert 1D Array Into 2D Array](https://leetcode.com/problems/convert-1d-array-into-2d-array/) + +## 题目 + +You are given a **0-indexed** 1-dimensional (1D) integer array `original`, and two integers, `m` and `n`. You are tasked with creating a 2-dimensional (2D) array with `m` rows and `n` columns using **all** the elements from `original`. + +The elements from indices `0` to `n - 1` (**inclusive**) of `original` should form the first row of the constructed 2D array, the elements from indices `n` to `2 * n - 1` (**inclusive**) should form the second row of the constructed 2D array, and so on. + +Return *an* `m x n` *2D array constructed according to the above procedure, or an empty 2D array if it is impossible*. + +**Example 1:** + +![https://assets.leetcode.com/uploads/2021/08/26/image-20210826114243-1.png](https://assets.leetcode.com/uploads/2021/08/26/image-20210826114243-1.png) + +``` +Input: original = [1,2,3,4], m = 2, n = 2 +Output: [[1,2],[3,4]] +Explanation: The constructed 2D array should contain 2 rows and 2 columns. +The first group of n=2 elements in original, [1,2], becomes the first row in the constructed 2D array. +The second group of n=2 elements in original, [3,4], becomes the second row in the constructed 2D array. + +``` + +**Example 2:** + +``` +Input: original = [1,2,3], m = 1, n = 3 +Output: [[1,2,3]] +Explanation: The constructed 2D array should contain 1 row and 3 columns. +Put all three elements in original into the first row of the constructed 2D array. + +``` + +**Example 3:** + +``` +Input: original = [1,2], m = 1, n = 1 +Output: [] +Explanation: There are 2 elements in original. +It is impossible to fit 2 elements in a 1x1 2D array, so return an empty 2D array. + +``` + +**Constraints:** + +- `1 <= original.length <= 5 * 104` +- `1 <= original[i] <= 105` +- `1 <= m, n <= 4 * 104` + +## 题目大意 + +给你一个下标从 0 开始的一维整数数组 original 和两个整数 m 和  n 。你需要使用 original 中 所有 元素创建一个 m 行 n 列的二维数组。 + +original 中下标从 0 到 n - 1 （都 包含 ）的元素构成二维数组的第一行，下标从 n 到 2 * n - 1 （都 包含 ）的元素构成二维数组的第二行，依此类推。 + +请你根据上述过程返回一个 m x n 的二维数组。如果无法构成这样的二维数组，请你返回一个空的二维数组。 + +## 解题思路 + +- 简单题。从一维数组 original 中依次取出每行 n 个元素，顺序放到 m 行中。此题中，如果 m*n 大于或者小于 original 的长度，都输出空数组。 + +## 代码 + +```go +package leetcode + +func construct2DArray(original []int, m int, n int) [][]int { + if m*n != len(original) { + return [][]int{} + } + res := make([][]int, m) + for i := 0; i < m; i++ { + res[i] = original[n*i : n*(i+1)] + } + return res +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/2000~2099/2037.Minimum-Number-of-Moves-to-Seat-Everyone.md b/website/content/ChapterFour/2000~2099/2037.Minimum-Number-of-Moves-to-Seat-Everyone.md new file mode 100644 index 000000000..8f7878c44 --- /dev/null +++ b/website/content/ChapterFour/2000~2099/2037.Minimum-Number-of-Moves-to-Seat-Everyone.md @@ -0,0 +1,101 @@ +# [2037. Minimum Number of Moves to Seat Everyone](https://leetcode.com/problems/minimum-number-of-moves-to-seat-everyone/) + +## 题目 + +There are n seats and n students in a room. You are given an array seats of length n, where seats[i] is the position of the ith seat. You are also given the array students of length n, where students[j] is the position of the jth student. + +You may perform the following move any number of times: + +- Increase or decrease the position of the ith student by 1 (i.e., moving the ith student from position x to x + 1 or x - 1) + +Return the minimum number of moves required to move each student to a seat such that no two students are in the same seat. + +Note that there may be multiple seats or students in the same position at the beginning. + +**Example 1:** + + Input: seats = [3,1,5], students = [2,7,4] + Output: 4 + Explanation: The students are moved as follows: + - The first student is moved from from position 2 to position 1 using 1 move. + - The second student is moved from from position 7 to position 5 using 2 moves. + - The third student is moved from from position 4 to position 3 using 1 move. + In total, 1 + 2 + 1 = 4 moves were used. + +**Example 2:** + + Input: seats = [4,1,5,9], students = [1,3,2,6] + Output: 7 + Explanation: The students are moved as follows: + - The first student is not moved. + - The second student is moved from from position 3 to position 4 using 1 move. + - The third student is moved from from position 2 to position 5 using 3 moves. + - The fourth student is moved from from position 6 to position 9 using 3 moves. + In total, 0 + 1 + 3 + 3 = 7 moves were used. + +**Example 3:** + + Input: seats = [2,2,6,6], students = [1,3,2,6] + Output: 4 + Explanation: Note that there are two seats at position 2 and two seats at position 6. + The students are moved as follows: + - The first student is moved from from position 1 to position 2 using 1 move. + - The second student is moved from from position 3 to position 6 using 3 moves. + - The third student is not moved. + - The fourth student is not moved. + In total, 1 + 3 + 0 + 0 = 4 moves were used. + +**Constraints:** + +- n == seats.length == students.length +- 1 <= n <= 100 +- 1 <= seats[i], students[j] <= 100 + +## 题目大意 + +一个房间里有 n 个座位和 n 名学生，房间用一个数轴表示。给你一个长度为 n 的数组 seats，其中 seats[i] 是第 i 个座位的位置。同时给你一个长度为 n 的数组 students ，其中 students[j] 是第 j 位学生的位置。 + +你可以执行以下操作任意次： + +增加或者减少第 i 位学生的位置，每次变化量为 1（也就是将第 i 位学生从位置 x 移动到 x + 1或者 x - 1） + +请你返回使所有学生都有座位坐的最少移动次数，并确保没有两位学生的座位相同。 + +请注意，初始时有可能有多个座位或者多位学生在 同一位置。 + +## 解题思路 + +- 排序+模拟计算 + +# 代码 + +```go +package leetcode + +import "sort" + +func minMovesToSeat(seats []int, students []int) int { + sort.Ints(seats) + sort.Ints(students) + n := len(students) + moves := 0 + for i := 0; i < n; i++ { + moves += abs(seats[i], students[i]) + } + return moves +} + +func abs(a, b int) int { + if a > b { + return a - b + } + return b - a +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/2000~2099/2038.Remove-Colored-Pieces-if-Both-Neighbors-are-the-Same-Color.md b/website/content/ChapterFour/2000~2099/2038.Remove-Colored-Pieces-if-Both-Neighbors-are-the-Same-Color.md new file mode 100644 index 000000000..09091fcc8 --- /dev/null +++ b/website/content/ChapterFour/2000~2099/2038.Remove-Colored-Pieces-if-Both-Neighbors-are-the-Same-Color.md @@ -0,0 +1,112 @@ +# [2038. Remove Colored Pieces if Both Neighbors are the Same Color](https://leetcode.com/problems/remove-colored-pieces-if-both-neighbors-are-the-same-color/) + +## 题目 + +There are n pieces arranged in a line, and each piece is colored either by 'A' or by 'B'. You are given a string colors of length n where colors[i] is the color of the ith piece. + +Alice and Bob are playing a game where they take alternating turns removing pieces from the line. In this game, Alice moves first. + +- Alice is only allowed to remove a piece colored 'A' if both its neighbors are also colored 'A'. She is not allowed to remove pieces that are colored 'B'. +- Bob is only allowed to remove a piece colored 'B' if both its neighbors are also colored 'B'. He is not allowed to remove pieces that are colored 'A'. +- Alice and Bob cannot remove pieces from the edge of the line. +- If a player cannot make a move on their turn, that player loses and the other player wins. + +Assuming Alice and Bob play optimally, return true if Alice wins, or return false if Bob wins. + +**Example 1:** + + Input: colors = "AAABABB" + Output: true + Explanation: + AAABABB -> AABABB + Alice moves first. + She removes the second 'A' from the left since that is the only 'A' whose neighbors are both 'A'. + + Now it's Bob's turn. + Bob cannot make a move on his turn since there are no 'B's whose neighbors are both 'B'. + Thus, Alice wins, so return true. + +**Example 2:** + + Input: colors = "AA" + Output: false + Explanation: + Alice has her turn first. + There are only two 'A's and both are on the edge of the line, so she cannot move on her turn. + Thus, Bob wins, so return false. + +**Example 3:** + + Input: colors = "ABBBBBBBAAA" + Output: false + Explanation: + ABBBBBBBAAA -> ABBBBBBBAA + Alice moves first. + Her only option is to remove the second to last 'A' from the right. + + ABBBBBBBAA -> ABBBBBBAA + Next is Bob's turn. + He has many options for which 'B' piece to remove. He can pick any. + + On Alice's second turn, she has no more pieces that she can remove. + Thus, Bob wins, so return false. + +**Constraints:** + +- 1 <= colors.length <= 100000 +- colors consists of only the letters 'A' and 'B' + +## 题目大意 + +总共有 n 个颜色片段排成一列，每个颜色片段要么是 'A' 要么是 'B' 。给你一个长度为 n 的字符串 colors ，其中 colors[i] 表示第 i 个颜色片段的颜色。 + +Alice 和 Bob 在玩一个游戏，他们轮流从这个字符串中删除颜色。Alice 先手。 + +- 如果一个颜色片段为 'A' 且相邻两个颜色都是颜色 'A'，那么 Alice 可以删除该颜色片段。Alice不可以删除任何颜色 'B' 片段。 +- 如果一个颜色片段为 'B'且相邻两个颜色都是颜色 'B' ，那么 Bob 可以删除该颜色片段。Bob 不可以删除任何颜色 'A' 片段。 +- Alice 和 Bob 不能从字符串两端删除颜色片段。 +- 如果其中一人无法继续操作，则该玩家 输掉游戏且另一玩家 获胜。 + +假设 Alice 和 Bob 都采用最优策略，如果 Alice 获胜，请返回true，否则 Bob 获胜，返回false。 + +## 解题思路 + +- 统计 Alice 和 Bob 分别可以操作的次数记为 As，Bs +- 因为 Alice 先手，所以只要 As 大于 Bs，Alice 获胜返回 true，否则 Bob 获胜返回 false + +# 代码 + +```go +package leetcode + +func winnerOfGame(colors string) bool { + As, Bs := 0, 0 + Acont, Bcont := 0, 0 + for _, color := range colors { + if color == 'A' { + Acont += 1 + Bcont = 0 + } else { + Bcont += 1 + Acont = 0 + } + if Acont >= 3 { + As += Acont - 2 + } + if Bcont >= 3 { + Bs += Bcont - 2 + } + } + if As > Bs { + return true + } + return false +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/2000~2099/2043.Simple-Bank-System.md b/website/content/ChapterFour/2000~2099/2043.Simple-Bank-System.md new file mode 100644 index 000000000..b756eb8e0 --- /dev/null +++ b/website/content/ChapterFour/2000~2099/2043.Simple-Bank-System.md @@ -0,0 +1,120 @@ +# [2043. Simple Bank System](https://leetcode.com/problems/simple-bank-system/) + +## 题目 + +You have been tasked with writing a program for a popular bank that will automate all its incoming transactions (transfer, deposit, and withdraw). The bank has n accounts numbered from 1 to n. The initial balance of each account is stored in a 0-indexed integer array balance, with the (i + 1)th account having an initial balance of balance[i]. + +Execute all the valid transactions. A transaction is valid if: + +- The given account number(s) are between 1 and n, and +- The amount of money withdrawn or transferred from is less than or equal to the balance of the account. + +Implement the Bank class: + +- Bank(long[] balance) Initializes the object with the 0-indexed integer array balance. +- boolean transfer(int account1, int account2, long money) Transfers money dollars from the account numbered account1 to the account numbered account2. Return true if the transaction was successful, false otherwise. +- boolean deposit(int account, long money) Deposit money dollars into the account numbered account. Return true if the transaction was successful, false otherwise. +- boolean withdraw(int account, long money) Withdraw money dollars from the account numbered account. Return true if the transaction was successful, false otherwise. + +**Example 1:** + + Input + ["Bank", "withdraw", "transfer", "deposit", "transfer", "withdraw"] + [[[10, 100, 20, 50, 30]], [3, 10], [5, 1, 20], [5, 20], [3, 4, 15], [10, 50]] + Output + [null, true, true, true, false, false] + + Explanation + Bank bank = new Bank([10, 100, 20, 50, 30]); + bank.withdraw(3, 10); // return true, account 3 has a balance of $20, so it is valid to withdraw $10. + // Account 3 has $20 - $10 = $10. + bank.transfer(5, 1, 20); // return true, account 5 has a balance of $30, so it is valid to transfer $20. + // Account 5 has $30 - $20 = $10, and account 1 has $10 + $20 = $30. + bank.deposit(5, 20); // return true, it is valid to deposit $20 to account 5. + // Account 5 has $10 + $20 = $30. + bank.transfer(3, 4, 15); // return false, the current balance of account 3 is $10, + // so it is invalid to transfer $15 from it. + bank.withdraw(10, 50); // return false, it is invalid because account 10 does not exist. + +**Constraints:** + +- n == balance.length +- 1 <= n, account, account1, account2 <= 100000 +- 0 <= balance[i], money <= 1000000000000 +- At most 104 calls will be made to each function transfer, deposit, withdraw. + +## 题目大意 + +你的任务是为一个很受欢迎的银行设计一款程序，以自动化执行所有传入的交易（转账，存款和取款）。银行共有 n 个账户，编号从 1 到 n 。每个账号的初始余额存储在一个下标从 0 开始的整数数组 balance 中，其中第 (i + 1) 个账户的初始余额是 balance[i] 。 + +请你执行所有 有效的 交易。如果满足下面全部条件，则交易 有效 ： + +- 指定的账户数量在 1 和 n 之间，且 +- 取款或者转账需要的钱的总数 小于或者等于 账户余额。 + +实现 Bank 类： + +- Bank(long[] balance) 使用下标从 0 开始的整数数组 balance 初始化该对象。 +- boolean transfer(int account1, int account2, long money) 从编号为 account1 的账户向编号为 account2 的账户转帐 money 美元。如果交易成功，返回 true ，否则，返回 false 。 +- boolean deposit(int account, long money) 向编号为 account 的账户存款 money 美元。如果交易成功，返回 true ；否则，返回 false 。 +- boolean withdraw(int account, long money) 从编号为 account 的账户取款 money 美元。如果交易成功，返回 true ；否则，返回 false 。 + +## 解题思路 + + 根据题意进行简单模拟 + +# 代码 + +```go +package leetcode + +type Bank struct { + accounts []int64 + n int +} + +func Constructor(balance []int64) Bank { + return Bank{ + accounts: balance, + n: len(balance), + } +} + +func (this *Bank) Transfer(account1 int, account2 int, money int64) bool { + if account1 > this.n || account2 > this.n { + return false + } + if this.accounts[account1-1] < money { + return false + } + this.accounts[account1-1] -= money + this.accounts[account2-1] += money + return true +} + +func (this *Bank) Deposit(account int, money int64) bool { + if account > this.n { + return false + } + this.accounts[account-1] += money + return true +} + +func (this *Bank) Withdraw(account int, money int64) bool { + if account > this.n { + return false + } + if this.accounts[account-1] < money { + return false + } + this.accounts[account-1] -= money + return true +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/2000~2099/2096.Step-By-Step-Directions-From-a-Binary-Tree-Node-to-Another.md b/website/content/ChapterFour/2000~2099/2096.Step-By-Step-Directions-From-a-Binary-Tree-Node-to-Another.md new file mode 100644 index 000000000..65dcf54fb --- /dev/null +++ b/website/content/ChapterFour/2000~2099/2096.Step-By-Step-Directions-From-a-Binary-Tree-Node-to-Another.md @@ -0,0 +1,152 @@ +# [2096. Step-By-Step Directions From a Binary Tree Node to Another](https://leetcode.com/problems/step-by-step-directions-from-a-binary-tree-node-to-another/) + + +## 题目 + +You are given the `root` of a **binary tree** with `n` nodes. Each node is uniquely assigned a value from `1` to `n`. You are also given an integer `startValue` representing the value of the start node `s`, and a different integer `destValue` representing the value of the destination node `t`. + +Find the **shortest path** starting from node `s` and ending at node `t`. Generate step-by-step directions of such path as a string consisting of only the **uppercase** letters `'L'`, `'R'`, and `'U'`. Each letter indicates a specific direction: + +- `'L'` means to go from a node to its **left child** node. +- `'R'` means to go from a node to its **right child** node. +- `'U'` means to go from a node to its **parent** node. + +Return *the step-by-step directions of the **shortest path** from node* `s` *to node* `t`. + +**Example 1:** + +![https://assets.leetcode.com/uploads/2021/11/15/eg1.png](https://assets.leetcode.com/uploads/2021/11/15/eg1.png) + +``` +Input: root = [5,1,2,3,null,6,4], startValue = 3, destValue = 6 +Output: "UURL" +Explanation: The shortest path is: 3 → 1 → 5 → 2 → 6. + +``` + +**Example 2:** + +![https://assets.leetcode.com/uploads/2021/11/15/eg2.png](https://assets.leetcode.com/uploads/2021/11/15/eg2.png) + +``` +Input: root = [2,1], startValue = 2, destValue = 1 +Output: "L" +Explanation: The shortest path is: 2 → 1. + +``` + +**Constraints:** + +- The number of nodes in the tree is `n`. +- `2 <= n <= 105` +- `1 <= Node.val <= n` +- All the values in the tree are **unique**. +- `1 <= startValue, destValue <= n` +- `startValue != destValue` + +## 题目大意 + +给你一棵 二叉树 的根节点 root ，这棵二叉树总共有 n 个节点。每个节点的值为 1 到 n 中的一个整数，且互不相同。给你一个整数 startValue ，表示起点节点 s 的值，和另一个不同的整数 destValue ，表示终点节点 t 的值。 + +请找到从节点 s 到节点 t 的 最短路径 ，并以字符串的形式返回每一步的方向。每一步用 大写 字母 'L' ，'R' 和 'U' 分别表示一种方向： + +- 'L' 表示从一个节点前往它的 左孩子 节点。 +- 'R' 表示从一个节点前往它的 右孩子 节点。 +- 'U' 表示从一个节点前往它的 父 节点。 + +请你返回从 s 到 t 最短路径 每一步的方向。 + +## 解题思路 + +- 二叉树中一个节点到另一个节点的最短路径一定可以分为两个部分（可能为空）：从起点节点向上到两个节点的**最近公共祖先**，再从最近公共祖先向下到达终点节点。 +- 首先需要找到起点 s 与公共祖先的节点之间的 path1，公共祖先节点与终点 t 的 path2。再删掉 2 个 path 的公共前缀。如果起点 s 和终点 t 在不同的分支上，不存在公共前缀。如果他们在相同的分支上，那么最终答案要去掉这个公共前缀。 +- 删除掉公共前缀以后，需要再整理一下最终答案的输出格式。由于题目要求，起点到公共祖先节点需要输出 U，所以把这段 path1 全部改成 U，然后再拼接上 path2 字符串，即可得到的字符串即为待求 ss 到 tt 每一步的最短路径。 + +## 代码 + +```go +package leetcode + +import ( + "github.com/halfrost/leetcode-go/structures" +) + +// TreeNode define +type TreeNode = structures.TreeNode + +/** + * Definition for a binary tree node. + * type TreeNode struct { + * Val int + * Left *TreeNode + * Right *TreeNode + * } + */ + +func getDirections(root *TreeNode, startValue int, destValue int) string { + sPath, dPath := make([]byte, 0), make([]byte, 0) + findPath(root, startValue, &sPath) + findPath(root, destValue, &dPath) + size, i := min(len(sPath), len(dPath)), 0 + for i < size { + if sPath[len(sPath)-1-i] == dPath[len(dPath)-1-i] { + i++ + } else { + break + } + } + sPath = sPath[:len(sPath)-i] + replace(sPath) + dPath = dPath[:len(dPath)-i] + reverse(dPath) + sPath = append(sPath, dPath...) + return string(sPath) +} + +func findPath(root *TreeNode, value int, path *[]byte) bool { + if root.Val == value { + return true + } + + if root.Left != nil && findPath(root.Left, value, path) { + *path = append(*path, 'L') + return true + } + + if root.Right != nil && findPath(root.Right, value, path) { + *path = append(*path, 'R') + return true + } + + return false +} + +func reverse(path []byte) { + left, right := 0, len(path)-1 + for left < right { + path[left], path[right] = path[right], path[left] + left++ + right-- + } +} + +func replace(path []byte) { + for i := 0; i < len(path); i++ { + path[i] = 'U' + } +} + +func min(i, j int) int { + if i < j { + return i + } + return j +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/2000~2099/_index.md b/website/content/ChapterFour/2000~2099/_index.md new file mode 100644 index 000000000..e954f0877 --- /dev/null +++ b/website/content/ChapterFour/2000~2099/_index.md @@ -0,0 +1,4 @@ +--- +bookCollapseSection: true +weight: 20 +--- diff --git a/website/content/ChapterFour/2100~2199/2164.Sort-Even-and-Odd-Indices-Independently.md b/website/content/ChapterFour/2100~2199/2164.Sort-Even-and-Odd-Indices-Independently.md new file mode 100644 index 000000000..bb3a1e28c --- /dev/null +++ b/website/content/ChapterFour/2100~2199/2164.Sort-Even-and-Odd-Indices-Independently.md @@ -0,0 +1,100 @@ +# [2164. Sort Even and Odd Indices Independently](https://leetcode.com/problems/sort-even-and-odd-indices-independently/) + + +## 题目 + +You are given a **0-indexed** integer array `nums`. Rearrange the values of `nums` according to the following rules: + +1. Sort the values at **odd indices** of `nums` in **non-increasing** order. + - For example, if `nums = [4,**1**,2,**3**]` before this step, it becomes `[4,**3**,2,**1**]` after. The values at odd indices `1` and `3` are sorted in non-increasing order. +2. Sort the values at **even indices** of `nums` in **non-decreasing** order. + - For example, if `nums = [**4**,1,**2**,3]` before this step, it becomes `[**2**,1,**4**,3]` after. The values at even indices `0` and `2` are sorted in non-decreasing order. + +Return *the array formed after rearranging the values of* `nums`. + +**Example 1:** + +``` +Input: nums = [4,1,2,3] +Output: [2,3,4,1] +Explanation: +First, we sort the values present at odd indices (1 and 3) in non-increasing order. +So, nums changes from [4,1,2,3] to [4,3,2,1]. +Next, we sort the values present at even indices (0 and 2) in non-decreasing order. +So, nums changes from [4,1,2,3] to [2,3,4,1]. +Thus, the array formed after rearranging the values is [2,3,4,1]. + +``` + +**Example 2:** + +``` +Input: nums = [2,1] +Output: [2,1] +Explanation: +Since there is exactly one odd index and one even index, no rearrangement of values takes place. +The resultant array formed is [2,1], which is the same as the initial array. + +``` + +**Constraints:** + +- `1 <= nums.length <= 100` +- `1 <= nums[i] <= 100` + +## 题目大意 + +给你一个下标从 0 开始的整数数组 nums 。根据下述规则重排 nums 中的值： + +1. 按 非递增 顺序排列 nums 奇数下标 上的所有值。 +举个例子，如果排序前 nums = [4,1,2,3] ，对奇数下标的值排序后变为 [4,3,2,1] 。奇数下标 1 和 3 的值按照非递增顺序重排。 +2. 按 非递减 顺序排列 nums 偶数下标 上的所有值。 +举个例子，如果排序前 nums = [4,1,2,3] ，对偶数下标的值排序后变为 [2,1,4,3] 。偶数下标 0 和 2 的值按照非递减顺序重排。 + +返回重排 nums 的值之后形成的数组。 + +## 解题思路 + +- 简单题。分别将奇数和偶数位上的数字排序，奇数位的数从大到小，偶数位的数从小到大。最后将他们组合成一个数组。 + +## 代码 + +```go +package leetcode + +import ( + "sort" +) + +func sortEvenOdd(nums []int) []int { + odd, even, res := []int{}, []int{}, []int{} + for index, v := range nums { + if index%2 == 0 { + even = append(even, v) + } else { + odd = append(odd, v) + } + } + sort.Ints(even) + sort.Sort(sort.Reverse(sort.IntSlice(odd))) + + indexO, indexE := 0, 0 + for i := 0; i < len(nums); i++ { + if i%2 == 0 { + res = append(res, even[indexE]) + indexE++ + } else { + res = append(res, odd[indexO]) + indexO++ + } + } + return res +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/2100~2199/2165.Smallest-Value-of-the-Rearranged-Number.md b/website/content/ChapterFour/2100~2199/2165.Smallest-Value-of-the-Rearranged-Number.md new file mode 100644 index 000000000..d2ce438b0 --- /dev/null +++ b/website/content/ChapterFour/2100~2199/2165.Smallest-Value-of-the-Rearranged-Number.md @@ -0,0 +1,108 @@ +# [2165. Smallest Value of the Rearranged Number](https://leetcode.com/problems/smallest-value-of-the-rearranged-number/) + + +## 题目 + +You are given an integer `num.` **Rearrange** the digits of `num` such that its value is **minimized** and it does not contain **any** leading zeros. + +Return *the rearranged number with minimal value*. + +Note that the sign of the number does not change after rearranging the digits. + +**Example 1:** + +``` +Input: num = 310 +Output: 103 +Explanation: The possible arrangements for the digits of 310 are 013, 031, 103, 130, 301, 310. +The arrangement with the smallest value that does not contain any leading zeros is 103. + +``` + +**Example 2:** + +``` +Input: num = -7605 +Output: -7650 +Explanation: Some possible arrangements for the digits of -7605 are -7650, -6705, -5076, -0567. +The arrangement with the smallest value that does not contain any leading zeros is -7650. + +``` + +**Constraints:** + +- `10^15 <= num <= 10^15` + +## 题目大意 + +给你一个整数 num 。重排 num 中的各位数字，使其值 最小化 且不含 任何 前导零。 + +返回不含前导零且值最小的重排数字。注意，重排各位数字后，num 的符号不会改变。 + +## 解题思路 + +- 先将每个数字出现次数统计出来。然后将数字大小从小到大排序。如果原数是正数，当出现有数字 0 的情况的时候，需先将第二小的数字排列到第一个，再把 0 排列完。再继续排列第二小，第三小。。。 +- 如果原数是负数。那么就逆序排列，即先排列最大的数字，然后次大的数字，直到排列最小的数字。因为数字越大，对应的这个数的负数就越小。 + +## 代码 + +```go +package leetcode + +import "sort" + +func smallestNumber(num int64) int64 { + pos := true + if num < 0 { + pos = false + num *= -1 + } + nums, m, res := []int{}, map[int]int{}, 0 + for num != 0 { + tmp := int(num % 10) + m[tmp]++ + num = num / 10 + } + + for k := range m { + nums = append(nums, k) + } + if pos { + sort.Ints(nums) + } else { + sort.Sort(sort.Reverse(sort.IntSlice(nums))) + } + + if nums[0] == 0 && len(nums) > 1 { + res += nums[1] + m[nums[1]]-- + } + + for _, v := range nums { + if res != 0 { + for j := m[v]; j > 0; j-- { + res = res * 10 + res += v + } + } else { + res += v + tmp := m[v] - 1 + for j := tmp; j > 0; j-- { + res = res * 10 + res += v + } + } + } + if !pos { + return -1 * int64(res) + } + return int64(res) +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/2100~2199/2166.Design-Bitset.md b/website/content/ChapterFour/2100~2199/2166.Design-Bitset.md new file mode 100644 index 000000000..8fbc2a786 --- /dev/null +++ b/website/content/ChapterFour/2100~2199/2166.Design-Bitset.md @@ -0,0 +1,163 @@ +# [2166. Design Bitset](https://leetcode.com/problems/design-bitset/) + + +## 题目 + +A **Bitset** is a data structure that compactly stores bits. + +Implement the `Bitset` class: + +- `Bitset(int size)` Initializes the Bitset with `size` bits, all of which are `0`. +- `void fix(int idx)` Updates the value of the bit at the index `idx` to `1`. If the value was already `1`, no change occurs. +- `void unfix(int idx)` Updates the value of the bit at the index `idx` to `0`. If the value was already `0`, no change occurs. +- `void flip()` Flips the values of each bit in the Bitset. In other words, all bits with value `0` will now have value `1` and vice versa. +- `boolean all()` Checks if the value of **each** bit in the Bitset is `1`. Returns `true` if it satisfies the condition, `false` otherwise. +- `boolean one()` Checks if there is **at least one** bit in the Bitset with value `1`. Returns `true` if it satisfies the condition, `false` otherwise. +- `int count()` Returns the **total number** of bits in the Bitset which have value `1`. +- `String toString()` Returns the current composition of the Bitset. Note that in the resultant string, the character at the `ith` index should coincide with the value at the `ith` bit of the Bitset. + +**Example 1:** + +``` +Input +["Bitset", "fix", "fix", "flip", "all", "unfix", "flip", "one", "unfix", "count", "toString"] +[[5], [3], [1], [], [], [0], [], [], [0], [], []] +Output +[null, null, null, null, false, null, null, true, null, 2, "01010"] + +Explanation +Bitset bs = new Bitset(5); // bitset = "00000". +bs.fix(3); // the value at idx = 3 is updated to 1, so bitset = "00010". +bs.fix(1); // the value at idx = 1 is updated to 1, so bitset = "01010". +bs.flip(); // the value of each bit is flipped, so bitset = "10101". +bs.all(); // return False, as not all values of the bitset are 1. +bs.unfix(0); // the value at idx = 0 is updated to 0, so bitset = "00101". +bs.flip(); // the value of each bit is flipped, so bitset = "11010". +bs.one(); // return True, as there is at least 1 index with value 1. +bs.unfix(0); // the value at idx = 0 is updated to 0, so bitset = "01010". +bs.count(); // return 2, as there are 2 bits with value 1. +bs.toString(); // return "01010", which is the composition of bitset. + +``` + +**Constraints:** + +- `1 <= size <= 10^5` +- `0 <= idx <= size - 1` +- At most `10^5` calls will be made **in total** to `fix`, `unfix`, `flip`, `all`, `one`, `count`, and `toString`. +- At least one call will be made to `all`, `one`, `count`, or `toString`. +- At most `5` calls will be made to `toString`. + +## 题目大意 + +位集 Bitset 是一种能以紧凑形式存储位的数据结构。 + +请你实现 Bitset 类。 + +- Bitset(int size) 用 size 个位初始化 Bitset ，所有位都是 0 。 +- void fix(int idx) 将下标为 idx 的位上的值更新为 1 。如果值已经是 1 ，则不会发生任何改变。 +- void unfix(int idx) 将下标为 idx 的位上的值更新为 0 。如果值已经是 0 ，则不会发生任何改变。 +- void flip() 翻转 Bitset 中每一位上的值。换句话说，所有值为 0 的位将会变成 1 ，反之亦然。 +- boolean all() 检查 Bitset 中 每一位 的值是否都是 1 。如果满足此条件，返回 true ；否则，返回 false 。 +- boolean one() 检查 Bitset 中 是否 至少一位 的值是 1 。如果满足此条件，返回 true ；否则，返回 false 。 +- int count() 返回 Bitset 中值为 1 的位的 总数 。 +- String toString() 返回 Bitset 的当前组成情况。注意，在结果字符串中，第 i 个下标处的字符应该与 Bitset 中的第 i 位一致。 + +提示： + +- 1 <= size <= 10^5 +- 0 <= idx <= size - 1 +- 至多调用 fix、unfix、flip、all、one、count 和 toString 方法 总共 10^5 次 +- 至少调用 all、one、count 或 toString 方法一次 +- 至多调用 toString 方法 5 次 + +## 解题思路 + +- 题目中给出了 size 大小，10^5 位二进制。所以不能用 int64 数据类型。 +- 用数组模拟二进制位的一系列操作。flip 操作并不需要每次去翻转，偶数次翻转等于没有翻转，奇数次翻转记下标记，同时更新 1 的个数。这次懒操作在调用 fix 和 unfix 时，更新到原来数组中。 +- fix 和 unfix 根据懒数组中的标记对应更新二进制位。同时更新 1 的个数。 +- all，one，count 都是判断 1 的个数。toString 输出即可。 + +## 代码 + +```go +package leetcode + +type Bitset struct { + set []byte + flipped []byte + oneCount int + size int +} + +func Constructor(size int) Bitset { + set := make([]byte, size) + flipped := make([]byte, size) + for i := 0; i < size; i++ { + set[i] = byte('0') + flipped[i] = byte('1') + } + return Bitset{ + set: set, + flipped: flipped, + oneCount: 0, + size: size, + } +} + +func (this *Bitset) Fix(idx int) { + if this.set[idx] == byte('0') { + this.set[idx] = byte('1') + this.flipped[idx] = byte('0') + this.oneCount++ + } +} + +func (this *Bitset) Unfix(idx int) { + if this.set[idx] == byte('1') { + this.set[idx] = byte('0') + this.flipped[idx] = byte('1') + this.oneCount-- + } +} + +func (this *Bitset) Flip() { + this.set, this.flipped = this.flipped, this.set + this.oneCount = this.size - this.oneCount +} + +func (this *Bitset) All() bool { + return this.oneCount == this.size +} + +func (this *Bitset) One() bool { + return this.oneCount != 0 +} + +func (this *Bitset) Count() int { + return this.oneCount +} + +func (this *Bitset) ToString() string { + return string(this.set) +} + +/** + * Your Bitset object will be instantiated and called as such: + * obj := Constructor(size); + * obj.Fix(idx); + * obj.Unfix(idx); + * obj.Flip(); + * param_4 := obj.All(); + * param_5 := obj.One(); + * param_6 := obj.Count(); + * param_7 := obj.ToString(); + */ +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/2100~2199/2167.Minimum-Time-to-Remove-All-Cars-Containing-Illegal-Goods.md b/website/content/ChapterFour/2100~2199/2167.Minimum-Time-to-Remove-All-Cars-Containing-Illegal-Goods.md new file mode 100644 index 000000000..867f7fc8e --- /dev/null +++ b/website/content/ChapterFour/2100~2199/2167.Minimum-Time-to-Remove-All-Cars-Containing-Illegal-Goods.md @@ -0,0 +1,156 @@ +# [2167. Minimum Time to Remove All Cars Containing Illegal Goods](https://leetcode.com/problems/minimum-time-to-remove-all-cars-containing-illegal-goods/) + + +## 题目 + +You are given a **0-indexed** binary string `s` which represents a sequence of train cars. `s[i] = '0'` denotes that the `ith` car does **not** contain illegal goods and `s[i] = '1'` denotes that the `ith` car does contain illegal goods. + +As the train conductor, you would like to get rid of all the cars containing illegal goods. You can do any of the following three operations **any** number of times: + +1. Remove a train car from the **left** end (i.e., remove `s[0]`) which takes 1 unit of time. +2. Remove a train car from the **right** end (i.e., remove `s[s.length - 1]`) which takes 1 unit of time. +3. Remove a train car from **anywhere** in the sequence which takes 2 units of time. + +Return *the **minimum** time to remove all the cars containing illegal goods*. + +Note that an empty sequence of cars is considered to have no cars containing illegal goods. + +**Example 1:** + +``` +Input: s = "1100101" +Output: 5 +Explanation: +One way to remove all the cars containing illegal goods from the sequence is to +- remove a car from the left end 2 times. Time taken is 2 * 1 = 2. +- remove a car from the right end. Time taken is 1. +- remove the car containing illegal goods found in the middle. Time taken is 2. +This obtains a total time of 2 + 1 + 2 = 5. + +An alternative way is to +- remove a car from the left end 2 times. Time taken is 2 * 1 = 2. +- remove a car from the right end 3 times. Time taken is 3 * 1 = 3. +This also obtains a total time of 2 + 3 = 5. + +5 is the minimum time taken to remove all the cars containing illegal goods. +There are no other ways to remove them with less time. + +``` + +**Example 2:** + +``` +Input: s = "0010" +Output: 2 +Explanation: +One way to remove all the cars containing illegal goods from the sequence is to +- remove a car from the left end 3 times. Time taken is 3 * 1 = 3. +This obtains a total time of 3. + +Another way to remove all the cars containing illegal goods from the sequence is to +- remove the car containing illegal goods found in the middle. Time taken is 2. +This obtains a total time of 2. + +Another way to remove all the cars containing illegal goods from the sequence is to +- remove a car from the right end 2 times. Time taken is 2 * 1 = 2. +This obtains a total time of 2. + +2 is the minimum time taken to remove all the cars containing illegal goods. +There are no other ways to remove them with less time. +``` + +**Constraints:** + +- `1 <= s.length <= 2 * 10^5` +- `s[i]` is either `'0'` or `'1'`. + +## 题目大意 + +给你一个下标从 0 开始的二进制字符串 s ，表示一个列车车厢序列。s[i] = '0' 表示第 i 节车厢 不 含违禁货物，而 s[i] = '1' 表示第 i 节车厢含违禁货物。 + +作为列车长，你需要清理掉所有载有违禁货物的车厢。你可以不限次数执行下述三种操作中的任意一个： + +1. 从列车 左 端移除一节车厢（即移除 s[0]），用去 1 单位时间。 +2. 从列车 右 端移除一节车厢（即移除 s[s.length - 1]），用去 1 单位时间。 +3. 从列车车厢序列的 任意位置 移除一节车厢，用去 2 单位时间。 + +返回移除所有载有违禁货物车厢所需要的 最少 单位时间数。注意，空的列车车厢序列视为没有车厢含违禁货物。 + +## 解题思路 + +- 这道题求最少单位时间数，最少时间数一定是尽量少使用 2 个单位时间的操作，多用 1 个时间的操作。从列车两头移除车厢，只需要移除和旁边车厢的金属连接处即可。由于列车位于两边，所以与其他车厢的金属连接处只有 1 个，故只需要 1 个单位时间；当车厢在中间，该车厢与两边的车厢有 2 个金属连接处，移除它需要断开与两边车厢的连接。所以需要 2 个单位时间。 +- 断开中间一节车厢以后，列车会被断成 2 部分。2 部分列车分别有 2 个头 2 个尾。举例：`1100111101`，如果把它从第 5 节开始断开，剩下的列车为 `11001 (1)` 和 `1101`。剩下的 1 都位于 2 边，移除他们都只需要 1 个单位时间。那么移除所有违禁品最少时间是 2 * 1 + 1 * 6 = 8。 +- 左半部分，定义 prefixSum[i] 表示移除前 i 节车厢所花费的最少时间。状态转移方程为： + + {{< katex display >}} + prefixSum[i] =\left\{\begin{matrix}prefixSum[i-1],s[i]=0\\ min(prefixSum[i-1]+2, i+1), s[i]=1\end{matrix}\right. + {{< /katex >}} + +- 同理，右半部分定义 suffixSum[i] 表示移除后 i 节车厢所花费的最少时间。状态转移方程为： + + {{< katex display >}} + suffixSum[i] =\left\{\begin{matrix} suffixSum[i+1],s[i]=0\\ min(suffixSum[i+1]+2, n-i), s[i]=1\end{matrix}\right. + {{< /katex >}} + +- 最后一层循环枚举 prefixSum[i] + suffixSum[i+1] 的最小值即为答案。 +- 这一题在解法一的基础上还可以再简化。当 s[i] = 1 时，prefixSum 和 suffixSum 是两种计算方法。我们可以假设中间断开的部分在 prefixSum 中。于是可以合并上面两个状态转移方程。简化以后的代码见解法二。 + +## 代码 + +```go +package leetcode + +import "runtime/debug" + +// 解法一 DP +func minimumTime(s string) int { + suffixSum, prefixSum, res := make([]int, len(s)+1), make([]int, len(s)+1), 0 + for i := len(s) - 1; i >= 0; i-- { + if s[i] == '0' { + suffixSum[i] = suffixSum[i+1] + } else { + suffixSum[i] = min(suffixSum[i+1]+2, len(s)-i) + } + } + res = suffixSum[0] + if s[0] == '1' { + prefixSum[0] = 1 + } + for i := 1; i < len(s); i++ { + if s[i] == '0' { + prefixSum[i] = prefixSum[i-1] + } else { + prefixSum[i] = min(prefixSum[i-1]+2, i+1) + } + res = min(res, prefixSum[i]+suffixSum[i+1]) + } + return res +} + +func init() { debug.SetGCPercent(-1) } + +// 解法二 小幅优化时间和空间复杂度 +func minimumTime1(s string) int { + res, count := len(s), 0 + for i := 0; i < len(s); i++ { + count = min(count+int(s[i]-'0')*2, i+1) + res = min(res, count+len(s)-i-1) + } + return res +} + +func min(a, b int) int { + if a < b { + return a + } else { + return b + } +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/2100~2199/2169.Count-Operations-to-Obtain-Zero.md b/website/content/ChapterFour/2100~2199/2169.Count-Operations-to-Obtain-Zero.md new file mode 100644 index 000000000..588a18794 --- /dev/null +++ b/website/content/ChapterFour/2100~2199/2169.Count-Operations-to-Obtain-Zero.md @@ -0,0 +1,80 @@ +# [2169. Count Operations to Obtain Zero](https://leetcode.com/problems/count-operations-to-obtain-zero/) + + +## 题目 + +You are given two **non-negative** integers `num1` and `num2`. + +In one **operation**, if `num1 >= num2`, you must subtract `num2` from `num1`, otherwise subtract `num1` from `num2`. + +- For example, if `num1 = 5` and `num2 = 4`, subtract `num2` from `num1`, thus obtaining `num1 = 1` and `num2 = 4`. However, if `num1 = 4` and `num2 = 5`, after one operation, `num1 = 4` and `num2 = 1`. + +Return *the **number of operations** required to make either* `num1 = 0` *or* `num2 = 0`. + +**Example 1:** + +``` +Input: num1 = 2, num2 = 3 +Output: 3 +Explanation: +- Operation 1: num1 = 2, num2 = 3. Since num1 < num2, we subtract num1 from num2 and get num1 = 2, num2 = 3 - 2 = 1. +- Operation 2: num1 = 2, num2 = 1. Since num1 > num2, we subtract num2 from num1. +- Operation 3: num1 = 1, num2 = 1. Since num1 == num2, we subtract num2 from num1. +Now num1 = 0 and num2 = 1. Since num1 == 0, we do not need to perform any further operations. +So the total number of operations required is 3. + +``` + +**Example 2:** + +``` +Input: num1 = 10, num2 = 10 +Output: 1 +Explanation: +- Operation 1: num1 = 10, num2 = 10. Since num1 == num2, we subtract num2 from num1 and get num1 = 10 - 10 = 0. +Now num1 = 0 and num2 = 10. Since num1 == 0, we are done. +So the total number of operations required is 1. + +``` + +**Constraints:** + +- `0 <= num1, num2 <= 10^5` + +## 题目大意 + +给你两个 非负 整数 num1 和 num2 。每一步 操作 中，如果 num1 >= num2 ，你必须用 num1 减 num2 ；否则，你必须用 num2 减 num1 。 + +- 例如，num1 = 5 且 num2 = 4 ，应该用 num1 减 num2 ，因此，得到 num1 = 1 和 num2 = 4 。然而，如果 num1 = 4且 num2 = 5 ，一步操作后，得到 num1 = 4 和 num2 = 1 。 + +返回使 num1 = 0 或 num2 = 0 的 操作数 。 + +## 解题思路 + +- 简单题，按照题意模拟，每次两个数字相减，便累加操作次数。当某个数字变为 0 时，输出操作次数。 + +## 代码 + +```go +package leetcode + +func countOperations(num1 int, num2 int) int { + res := 0 + for num1 != 0 && num2 != 0 { + if num1 >= num2 { + num1 -= num2 + } else { + num2 -= num1 + } + res++ + } + return res +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/2100~2199/2170.Minimum-Operations-to-Make-the-Array-Alternating.md b/website/content/ChapterFour/2100~2199/2170.Minimum-Operations-to-Make-the-Array-Alternating.md new file mode 100644 index 000000000..e41c64ec8 --- /dev/null +++ b/website/content/ChapterFour/2100~2199/2170.Minimum-Operations-to-Make-the-Array-Alternating.md @@ -0,0 +1,137 @@ +# [2170. Minimum Operations to Make the Array Alternating](https://leetcode.com/problems/minimum-operations-to-make-the-array-alternating/) + + +## 题目 + +You are given a **0-indexed** array `nums` consisting of `n` positive integers. + +The array `nums` is called **alternating** if: + +- `nums[i - 2] == nums[i]`, where `2 <= i <= n - 1`. +- `nums[i - 1] != nums[i]`, where `1 <= i <= n - 1`. + +In one **operation**, you can choose an index `i` and **change** `nums[i]` into **any** positive integer. + +Return *the **minimum number of operations** required to make the array alternating*. + +**Example 1:** + +``` +Input: nums = [3,1,3,2,4,3] +Output: 3 +Explanation: +One way to make the array alternating is by converting it to [3,1,3,1,3,1]. +The number of operations required in this case is 3. +It can be proven that it is not possible to make the array alternating in less than 3 operations. + +``` + +**Example 2:** + +``` +Input: nums = [1,2,2,2,2] +Output: 2 +Explanation: +One way to make the array alternating is by converting it to [1,2,1,2,1]. +The number of operations required in this case is 2. +Note that the array cannot be converted to [2,2,2,2,2] because in this case nums[0] == nums[1] which violates the conditions of an alternating array. + +``` + +**Constraints:** + +- `1 <= nums.length <= 10^5` +- `1 <= nums[i] <= 10^5` + +## 题目大意 + +给你一个下标从 0 开始的数组 nums ，该数组由 n 个正整数组成。 + +如果满足下述条件，则数组 nums 是一个 交替数组 ： + +- nums[i - 2] == nums[i] ，其中 2 <= i <= n - 1 。 +- nums[i - 1] != nums[i] ，其中 1 <= i <= n - 1 。 + +在一步 操作 中，你可以选择下标 i 并将 nums[i] 更改 为 任一 正整数。返回使数组变成交替数组的 最少操作数 。 + +**提示：** + +- `1 <= nums.length <= 10^5` +- `1 <= nums[i] <= 10^5` + +## 解题思路 + +- 题目要求最少操作数，即留下出现频次最多的数字，剩下的数字都替换成这个数字。先将每个数字出现的频次统计出来，然后按照频次从大到小排序。优先选择出现频次高的数字。 +- 有几种“特殊”情况需要处理：当奇数下标的数字频次最大的数字和偶数下标的数字频次最大的数字相同（数字相同，频次不同），这时应选取频次大的数字留下；当数字相同，频次也相同，这时要看奇数下标和偶数下标的数字分别有几个。 如果其中一个只有一种数字，那么另外一组数字则需都变成该组频次第二大的数字，例如奇数下标的数字全是 1，频次是 3，偶数下标的数字是 1，最大频次是 2。第二频次的数字是 9，频次是 1 。那么这种情况下，选择奇数下标的数字 1，和偶数下标数字 9 。将偶数下标不是 9 的数字改变成 9 ；更近一步，如果奇数下标和偶数下标都只有一个数字，频次相同，那么只能改变奇数下标或者偶数下标的所有数字。 + +## 代码 + +```go +package leetcode + +import ( + "sort" +) + +type node struct { + value int + count int +} + +func minimumOperations(nums []int) int { + if len(nums) == 1 { + return 0 + } + res, odd, even, oddMap, evenMap := 0, []node{}, []node{}, map[int]int{}, map[int]int{} + + for i := 0; i < len(nums); i += 2 { + evenMap[nums[i]]++ + } + for k, v := range evenMap { + even = append(even, node{value: k, count: v}) + } + sort.Slice(even, func(i, j int) bool { + return even[i].count > even[j].count + }) + + for i := 1; i < len(nums); i += 2 { + oddMap[nums[i]]++ + } + for k, v := range oddMap { + odd = append(odd, node{value: k, count: v}) + } + sort.Slice(odd, func(i, j int) bool { + return odd[i].count > odd[j].count + }) + + if even[0].value == odd[0].value { + if len(even) == 1 && len(odd) != 1 { + res = len(nums) - even[0].count - odd[1].count + } else if len(odd) == 1 && len(even) != 1 { + res = len(nums) - odd[0].count - even[1].count + } else if len(odd) == 1 && len(even) == 1 { + res = len(nums) / 2 + } else { + // both != 1 + res = min(len(nums)-odd[0].count-even[1].count, len(nums)-odd[1].count-even[0].count) + } + } else { + res = len(nums) - even[0].count - odd[0].count + } + return res +} + +func min(a, b int) int { + if a > b { + return b + } + return a +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/2100~2199/2171.Removing-Minimum-Number-of-Magic-Beans.md b/website/content/ChapterFour/2100~2199/2171.Removing-Minimum-Number-of-Magic-Beans.md new file mode 100644 index 000000000..410c13c7c --- /dev/null +++ b/website/content/ChapterFour/2100~2199/2171.Removing-Minimum-Number-of-Magic-Beans.md @@ -0,0 +1,97 @@ +# [2171. Removing Minimum Number of Magic Beans](https://leetcode.com/problems/removing-minimum-number-of-magic-beans/) + + +## 题目 + +You are given an array of **positive** integers `beans`, where each integer represents the number of magic beans found in a particular magic bag. + +**Remove** any number of beans (**possibly none**) from each bag such that the number of beans in each remaining **non-empty** bag (still containing **at least one** bean) is **equal**. Once a bean has been removed from a bag, you are **not** allowed to return it to any of the bags. + +Return *the **minimum** number of magic beans that you have to remove*. + +**Example 1:** + +``` +Input: beans = [4,1,6,5] +Output: 4 +Explanation: +- We remove 1 bean from the bag with only 1 bean. + This results in the remaining bags: [4,0,6,5] +- Then we remove 2 beans from the bag with 6 beans. + This results in the remaining bags: [4,0,4,5] +- Then we remove 1 bean from the bag with 5 beans. + This results in the remaining bags: [4,0,4,4] +We removed a total of 1 + 2 + 1 = 4 beans to make the remaining non-empty bags have an equal number of beans. +There are no other solutions that remove 4 beans or fewer. + +``` + +**Example 2:** + +``` +Input: beans = [2,10,3,2] +Output: 7 +Explanation: +- We remove 2 beans from one of the bags with 2 beans. + This results in the remaining bags: [0,10,3,2] +- Then we remove 2 beans from the other bag with 2 beans. + This results in the remaining bags: [0,10,3,0] +- Then we remove 3 beans from the bag with 3 beans. + This results in the remaining bags: [0,10,0,0] +We removed a total of 2 + 2 + 3 = 7 beans to make the remaining non-empty bags have an equal number of beans. +There are no other solutions that removes 7 beans or fewer. + +``` + +**Constraints:** + +- `1 <= beans.length <= 10^5` +- `1 <= beans[i] <= 10^5` + +## 题目大意 + +给你一个 正 整数数组 beans ，其中每个整数表示一个袋子里装的魔法豆的数目。 + +请你从每个袋子中 拿出 一些豆子（也可以 不拿出），使得剩下的 非空 袋子中（即 至少 还有 一颗 魔法豆的袋子）魔法豆的数目 相等 。一旦魔法豆从袋子中取出，你不能将它放到任何其他的袋子中。请你返回你需要拿出魔法豆的 最少数目。 + +**提示：** + +- `1 <= beans.length <= 10^5` +- `1 <= beans[i] <= 10^5` + +## 解题思路 + +- 这一题没有特别巧妙的方法。最初思路来源于暴力解法。从第一个袋子开始，依次以每个袋子中的豆子为基准，改变其他袋子里面的豆子数，使得其他袋子里面的豆子都和基准袋子中豆子一样多。 +- 如果从下标为 0 扫到下标 n-1 ，这中间会有大量重复计算。有些计算区间和的操作，反复计算了很多遍，导致算法不高效。由于移除豆子数量多少和基准袋豆子数量强相关，所以先排序。如果袋子内豆子数目小于基准袋的豆子，`0 ≤ j < i`，那么这些袋子内的豆子数量会归零。需要移除 `beans[0] + beans[1] + ... + beans[i-1]` 个豆子；如果袋子内豆子数目大于等于基准袋的豆子，`j ≥ i` ，那么这些袋子内的豆子需要调整为 `beans[i]` 个。需要移除 `(beans[i] - beans[i]) + (beans[i+1] - beans[i]) + (beans[i+2] - beans[i]) + ... + (beans[n-1] - beans[i]) = beans[i]+ ... + beans[n-1] - (n-i) * beans[i]` 个豆子。将这 2 种情况综合起来，那么总共需要移除 `sum(beans) - (N - i) * beans[i]` 个豆子。综上，先排序，然后从小到大扫一遍数组，动态维护最少移除豆子的个数即可。 + +## 代码 + +```go +package leetcode + +import "sort" + +func minimumRemoval(beans []int) int64 { + sort.Ints(beans) + sum, mx := 0, 0 + for i, v := range beans { + sum += v + mx = max(mx, (len(beans)-i)*v) + } + return int64(sum - mx) +} + +func max(a, b int) int { + if b > a { + return b + } + return a +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/2100~2199/2180.Count-Integers-With-Even-Digit-Sum.md b/website/content/ChapterFour/2100~2199/2180.Count-Integers-With-Even-Digit-Sum.md new file mode 100644 index 000000000..4685d7d37 --- /dev/null +++ b/website/content/ChapterFour/2100~2199/2180.Count-Integers-With-Even-Digit-Sum.md @@ -0,0 +1,76 @@ +# [2180. Count Integers With Even Digit Sum](https://leetcode.com/problems/count-integers-with-even-digit-sum/) + + +## 题目 + +Given a positive integer `num`, return *the number of positive integers **less than or equal to*** `num` *whose digit sums are **even***. + +The **digit sum** of a positive integer is the sum of all its digits. + +**Example 1:** + +``` +Input: num = 4 +Output: 2 +Explanation: +The only integers less than or equal to 4 whose digit sums are even are 2 and 4. + +``` + +**Example 2:** + +``` +Input: num = 30 +Output: 14 +Explanation: +The 14 integers less than or equal to 30 whose digit sums are even are +2, 4, 6, 8, 11, 13, 15, 17, 19, 20, 22, 24, 26, and 28. + +``` + +**Constraints:** + +- `1 <= num <= 1000` + +## 题目大意 + +给你一个正整数 num ，请你统计并返回 小于或等于 num 且各位数字之和为 偶数 的正整数的数目。 + +正整数的 各位数字之和 是其所有位上的对应数字相加的结果。 + +## 解题思路 + +- 简单题。依照题意，计算每个数的各位数字之和，如何和为偶数，则统计结果加一。最后输出统计结果即可。 + +## 代码 + +```go +package leetcode + +func countEven(num int) int { + count := 0 + for i := 1; i <= num; i++ { + if addSum(i)%2 == 0 { + count++ + } + } + return count +} + +func addSum(num int) int { + sum := 0 + tmp := num + for tmp != 0 { + sum += tmp % 10 + tmp = tmp / 10 + } + return sum +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/2100~2199/2181.Merge-Nodes-in-Between-Zeros.md b/website/content/ChapterFour/2100~2199/2181.Merge-Nodes-in-Between-Zeros.md new file mode 100644 index 000000000..35ef63ea0 --- /dev/null +++ b/website/content/ChapterFour/2100~2199/2181.Merge-Nodes-in-Between-Zeros.md @@ -0,0 +1,103 @@ +# [2181. Merge Nodes in Between Zeros](https://leetcode.com/problems/merge-nodes-in-between-zeros/) + +## 题目 + +You are given the `head` of a linked list, which contains a series of integers **separated** by `0`'s. The **beginning** and **end** of the linked list will have `Node.val == 0`. + +For **every** two consecutive `0`'s, **merge** all the nodes lying in between them into a single node whose value is the **sum** of all the merged nodes. The modified list should not contain any `0`'s. + +Return *the* `head` *of the modified linked list*. + +**Example 1:** + +![https://assets.leetcode.com/uploads/2022/02/02/ex1-1.png](https://assets.leetcode.com/uploads/2022/02/02/ex1-1.png) + +``` +Input: head = [0,3,1,0,4,5,2,0] +Output: [4,11] +Explanation: +The above figure represents the given linked list. The modified list contains +- The sum of the nodes marked in green: 3 + 1 = 4. +- The sum of the nodes marked in red: 4 + 5 + 2 = 11. + +``` + +**Example 2:** + +![https://assets.leetcode.com/uploads/2022/02/02/ex2-1.png](https://assets.leetcode.com/uploads/2022/02/02/ex2-1.png) + +``` +Input: head = [0,1,0,3,0,2,2,0] +Output: [1,3,4] +Explanation: +The above figure represents the given linked list. The modified list contains +- The sum of the nodes marked in green: 1 = 1. +- The sum of the nodes marked in red: 3 = 3. +- The sum of the nodes marked in yellow: 2 + 2 = 4. + +``` + +**Constraints:** + +- The number of nodes in the list is in the range `[3, 2 * 10^5]`. +- `0 <= Node.val <= 1000` +- There are **no** two consecutive nodes with `Node.val == 0`. +- The **beginning** and **end** of the linked list have `Node.val == 0`. + +## 题目大意 + +给你一个链表的头节点 head ，该链表包含由 0 分隔开的一连串整数。链表的 开端 和 末尾 的节点都满足 Node.val == 0 。对于每两个相邻的 0 ，请你将它们之间的所有节点合并成一个节点，其值是所有已合并节点的值之和。然后将所有 0 移除，修改后的链表不应该含有任何 0 。 + +返回修改后链表的头节点 head 。 + +## 解题思路 + +- 简单题。合并链表中两个值为 0 的节点。从头开始遍历链表，遇到节点值不为 0 的节点便累加；遇到节点值为 0 的节点，将累加值转换成结果链表要输出的节点值，然后继续遍历。 + +## 代码 + +```go +package leetcode + +import ( + "github.com/halfrost/leetcode-go/structures" +) + +// ListNode define +type ListNode = structures.ListNode + +/** + * Definition for singly-linked list. + * type ListNode struct { + * Val int + * Next *ListNode + * } + */ +func mergeNodes(head *ListNode) *ListNode { + res := &ListNode{} + h := res + if head.Next == nil { + return &structures.ListNode{} + } + cur := head + sum := 0 + for cur.Next != nil { + if cur.Next.Val != 0 { + sum += cur.Next.Val + } else { + h.Next = &ListNode{Val: sum, Next: nil} + h = h.Next + sum = 0 + } + cur = cur.Next + } + return res.Next +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/2100~2199/2182.Construct-String-With-Repeat-Limit.md b/website/content/ChapterFour/2100~2199/2182.Construct-String-With-Repeat-Limit.md new file mode 100644 index 000000000..0507b90ee --- /dev/null +++ b/website/content/ChapterFour/2100~2199/2182.Construct-String-With-Repeat-Limit.md @@ -0,0 +1,105 @@ +# [2182. Construct String With Repeat Limit](https://leetcode.com/problems/construct-string-with-repeat-limit/) + + +## 题目 + +You are given a string `s` and an integer `repeatLimit`. Construct a new string `repeatLimitedString` using the characters of `s` such that no letter appears **more than** `repeatLimit` times **in a row**. You do **not** have to use all characters from `s`. + +Return *the **lexicographically largest*** `repeatLimitedString` *possible*. + +A string `a` is **lexicographically larger** than a string `b` if in the first position where `a` and `b` differ, string `a` has a letter that appears later in the alphabet than the corresponding letter in `b`. If the first `min(a.length, b.length)` characters do not differ, then the longer string is the lexicographically larger one. + +**Example 1:** + +``` +Input: s = "cczazcc", repeatLimit = 3 +Output: "zzcccac" +Explanation: We use all of the characters from s to construct the repeatLimitedString "zzcccac". +The letter 'a' appears at most 1 time in a row. +The letter 'c' appears at most 3 times in a row. +The letter 'z' appears at most 2 times in a row. +Hence, no letter appears more than repeatLimit times in a row and the string is a valid repeatLimitedString. +The string is the lexicographically largest repeatLimitedString possible so we return "zzcccac". +Note that the string "zzcccca" is lexicographically larger but the letter 'c' appears more than 3 times in a row, so it is not a valid repeatLimitedString. + +``` + +**Example 2:** + +``` +Input: s = "aababab", repeatLimit = 2 +Output: "bbabaa" +Explanation: We use only some of the characters from s to construct the repeatLimitedString "bbabaa". +The letter 'a' appears at most 2 times in a row. +The letter 'b' appears at most 2 times in a row. +Hence, no letter appears more than repeatLimit times in a row and the string is a valid repeatLimitedString. +The string is the lexicographically largest repeatLimitedString possible so we return "bbabaa". +Note that the string "bbabaaa" is lexicographically larger but the letter 'a' appears more than 2 times in a row, so it is not a valid repeatLimitedString. + +``` + +**Constraints:** + +- `1 <= repeatLimit <= s.length <= 10^5` +- `s` consists of lowercase English letters. + +## 题目大意 + +给你一个字符串 s 和一个整数 repeatLimit ，用 s 中的字符构造一个新字符串 repeatLimitedString ，使任何字母 连续 出现的次数都不超过 repeatLimit 次。你不必使用 s 中的全部字符。 + +返回 字典序最大的 repeatLimitedString 。 + +如果在字符串 a 和 b 不同的第一个位置，字符串 a 中的字母在字母表中出现时间比字符串 b 对应的字母晚，则认为字符串 a 比字符串 b 字典序更大 。如果字符串中前 min(a.length, b.length) 个字符都相同，那么较长的字符串字典序更大。 + +## 解题思路 + +- 利用贪心的思想，由于题意要求返回字典序最大的字符串，所以先从字典序最大的字母开始选起。然后选择当前字典序最大的字母个数和 limit 的最小值。如果当前字典序最大的字母比较多，多于 limit，不能一直选择它。选完 limit 个以后，需要选一个字典序次大的字母，选完这个字母以后再次选择字典序最大的字母。因为 limit 限制字母不能连续多于 limit 个。如此循环，直到所有的字母都选完。这样的策略排列出来的字母串为最大字典序。 + +## 代码 + +```go +package leetcode + +func repeatLimitedString(s string, repeatLimit int) string { + cnt := make([]int, 26) + for _, c := range s { + cnt[int(c-'a')]++ + } + var ns []byte + for i := 25; i >= 0; { + k := i - 1 + for cnt[i] > 0 { + for j := 0; j < min(cnt[i], repeatLimit); j++ { + ns = append(ns, byte(i)+'a') + } + cnt[i] -= repeatLimit + if cnt[i] > 0 { + for ; k >= 0 && cnt[k] == 0; k-- { + } + if k < 0 { + break + } else { + ns = append(ns, byte(k)+'a') + cnt[k]-- + } + } + } + i = k + } + return string(ns) +} +func min(a, b int) int { + if a < b { + return a + } else { + return b + } +} +``` + + +---------------------------------------------- + diff --git a/website/content/ChapterFour/2100~2199/2183.Count-Array-Pairs-Divisible-by-K.md b/website/content/ChapterFour/2100~2199/2183.Count-Array-Pairs-Divisible-by-K.md new file mode 100644 index 000000000..71d925113 --- /dev/null +++ b/website/content/ChapterFour/2100~2199/2183.Count-Array-Pairs-Divisible-by-K.md @@ -0,0 +1,90 @@ +# [2183. Count Array Pairs Divisible by K](https://leetcode.com/problems/count-array-pairs-divisible-by-k/) + + +## 题目 + +Given a **0-indexed** integer array `nums` of length `n` and an integer `k`, return *the **number of pairs*** `(i, j)` *such that:* + +- `0 <= i < j <= n - 1` *and* +- `nums[i] * nums[j]` *is divisible by* `k`. + +**Example 1:** + +``` +Input: nums = [1,2,3,4,5], k = 2 +Output: 7 +Explanation: +The 7 pairs of indices whose corresponding products are divisible by 2 are +(0, 1), (0, 3), (1, 2), (1, 3), (1, 4), (2, 3), and (3, 4). +Their products are 2, 4, 6, 8, 10, 12, and 20 respectively. +Other pairs such as (0, 2) and (2, 4) have products 3 and 15 respectively, which are not divisible by 2. + +``` + +**Example 2:** + +``` +Input: nums = [1,2,3,4], k = 5 +Output: 0 +Explanation: There does not exist any pair of indices whose corresponding product is divisible by 5. + +``` + +**Constraints:** + +- `1 <= nums.length <= 10^5` +- `1 <= nums[i], k <= 10^5` + +## 题目大意 + +给你一个下标从 0 开始、长度为 n 的整数数组 nums 和一个整数 k ，返回满足下述条件的下标对 (i, j) 的数目： + +- 0 <= i < j <= n - 1 且 +- nums[i] * nums[j] 能被 k 整除。 + +## 解题思路 + +- 先找出 num 中每个元素与 k 的最大公约数。并统计这些公约数出现的频次，将数据保存在 map 中。在计算过程中，循环可以只需算到 {{< katex >}}{O(\sqrt {k})}{{< /katex >}} , 因为每一个 gcd[i] 一定是 k 的因数，而它出现的频次不会超过 {{< katex >}}{O(\sqrt {k})}{{< /katex >}}。简单证明一下：假设因子 v 和 k/v 这两个因数为 k 的因子。v 和 k/v 必至少有 1 个小于等于 {{< katex >}}\sqrt {k}{{< /katex >}}。所以 k 的因子也不会超过 2 * {{< katex >}}\sqrt {k}{{< /katex >}} = {{< katex >}}{O(\sqrt {k})}{{< /katex >}} 个。 +- 算出上述的 map 以后，2 层循环暴力遍历 key 值，如果 a * b 能被 k 整除，并且 a 和 b 不相同，那么 a 和 b 对应的 value 值相乘即为满足条件的下标对数；如果 a 和 b 相同，那么下标对数为 {{< katex >}}C_{n}^{2}{{< /katex >}}。最后累加结果即可。 + +## 代码 + +```go +package leetcode + +import "math" + +func countPairs(nums []int, k int) int64 { + n := int(math.Sqrt(float64(k))) + gcds, res := make(map[int]int, n), 0 + for _, num := range nums { + gcds[gcd(num, k)]++ + } + + for a, n1 := range gcds { + for b, n2 := range gcds { + if a > b || (a*b)%k != 0 { + continue + } + if a != b { + res += n1 * n2 + } else { // a == b + res += n1 * (n1 - 1) / 2 + } + } + } + return int64(res) +} + +func gcd(a, b int) int { + for a%b != 0 { + a, b = b, a%b + } + return b +} +``` + + +---------------------------------------------- +

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+ diff --git a/website/content/ChapterFour/2100~2199/_index.md b/website/content/ChapterFour/2100~2199/_index.md new file mode 100644 index 000000000..e954f0877 --- /dev/null +++ b/website/content/ChapterFour/2100~2199/_index.md @@ -0,0 +1,4 @@ +--- +bookCollapseSection: true +weight: 20 +--- diff --git a/website/content/ChapterFour/2200~2299/_index.md b/website/content/ChapterFour/2200~2299/_index.md new file mode 100644 index 000000000..e954f0877 --- /dev/null +++ b/website/content/ChapterFour/2200~2299/_index.md @@ -0,0 +1,4 @@ +--- +bookCollapseSection: true +weight: 20 +--- diff --git a/website/content/ChapterOne/Algorithm.md b/website/content/ChapterOne/Algorithm.md index c43698381..45b4f74ff 100644 --- a/website/content/ChapterOne/Algorithm.md +++ b/website/content/ChapterOne/Algorithm.md @@ -23,12 +23,12 @@ weight: 2 |数论||1. 最大公约数
2. 最小公倍数
3. 分解质因数
4. 素数判定
5. 进制转换
6. 高精度计算
7. 整除问题
8. 同余问题
9. 欧拉函数
10. 扩展欧几里得
11. 置换群
12. 母函数
13. 离散变换
14. 康托展开
15. 矩阵
16. 向量
17. 线性方程组
18. 线性规划
|| |几何||1. 凸包 - Gift wrapping
2. 凸包 - Graham scan
3. 线段问题
4. 多边形和多面体相关问题
|| |NP 完全|1. 计算模型
2. P 类与 NP 类问题
3. NP 完全问题
4. NP 完全问题的近似算法
|1. 随机存取机 RAM
2. 随机存取存储程序机 RASP
3. 图灵机
4. 非确定性图灵机
5. P 类与 NP 类语言
6. 多项式时间验证
7. 多项式时间变换
8. Cook定理
9. 合取范式的可满足性问题 CNF-SAT
10. 3 元合取范式的可满足性问题 3-SAT
11. 团问题 CLIQUE
12. 顶点覆盖问题 VERTEX-COVER
13. 子集和问题 SUBSET-SUM
14. 哈密顿回路问题 HAM-CYCLE
15. 旅行售货员问题 TSP
16. 顶点覆盖问题的近似算法
17. 旅行售货员问题近似算法
18. 具有三角不等式性质的旅行售货员问题
19. 一般的旅行售货员问题
20. 集合覆盖问题的近似算法
21. 子集和问题的近似算法
22. 子集和问题的指数时间算法
23. 子集和问题的多项式时间近似格式
|| -|位运算| 位操作包括：
1. 取反（NOT）
2. 按位或（OR）
3. 按位异或（XOR）
4. 按位与（AND）
5. 移位: 是一个二元运算符，用来将一个二进制数中的每一位全部都向一个方向移动指定位，溢出的部分将被舍弃，而空缺的部分填入一定的值。
| 1.数字范围按位与
2.UTF-8 编码验证
3.数字转换为十六进制数
4.找出最长的超赞子字符串
5.数组异或操作
6.幂集
7.位1的个数
8.二进制表示中质数个计算置位
9.子数组异或查询
| [力扣：位运算](https://leetcode-cn.com/tag/bit-manipulation/) +|位运算| 位操作包括：
1. 取反（NOT）
2. 按位或（OR）
3. 按位异或（XOR）
4. 按位与（AND）
5. 移位: 是一个二元运算符，用来将一个二进制数中的每一位全部都向一个方向移动指定位，溢出的部分将被舍弃，而空缺的部分填入一定的值。
| 1.数字范围按位与
2.UTF-8 编码验证
3.数字转换为十六进制数
4.找出最长的超赞子字符串
5.数组异或操作
6.幂集
7.位1的个数
8.二进制表示中质数个计算置位
9.子数组异或查询
| [力扣：位运算](https://leetcode-cn.com/tag/bit-manipulation/)| |------------|------------------------------------------------------------------|-----------------------------------------------------------------|--------------------| ---------------------------------------------- diff --git a/website/content/ChapterOne/Time_Complexity.md b/website/content/ChapterOne/Time_Complexity.md new file mode 100644 index 000000000..b68708bb2 --- /dev/null +++ b/website/content/ChapterOne/Time_Complexity.md @@ -0,0 +1,139 @@ +--- +title: 1.3 时间复杂度 +type: docs +weight: 3 +--- + +# 时间复杂度和空间复杂度 + + +## 一. 时间复杂度数据规模 + +1s 内能解决问题的数据规模：10^6 ~ 10^7 + +- O(n^2) 算法可以处理 10^4 级别的数据规模(保守估计，处理 1000 级别的问题肯定没问题) +- O(n) 算法可以处理 10^8 级别的数据规模(保守估计，处理 10^7 级别的问题肯定没问题) +- O(nlog n) 算法可以处理 10^7 级别的数据规模(保守估计，处理 10^6 级别的问题肯定没问题) + +| | 数据规模|时间复杂度 | 算法举例| +|:------:|:------:|:------:|:------:| +|1|10|O(n!)|permutation 排列| +|2|20~30|O(2^n)|combination 组合| +|3|50|O(n^4)|DFS 搜索、DP 动态规划| +|4|100|O(n^3)|任意两点最短路径、DP 动态规划| +|5|1000|O(n^2)|稠密图、DP 动态规划| +|6|10^6|O(nlog n)|排序，堆，递归与分治| +|7|10^7|O(n)|DP 动态规划、图遍历、拓扑排序、树遍历| +|8|10^9|O(sqrt(n))|筛素数、求平方根| +|9|10^10|O(log n)|二分搜索| +|10|+∞|O(1)|数学相关算法| +|------------------------------|------------------------------|------------------------------------------------------------------|------------------------------------------------------------------| + + +一些具有迷惑性的例子： + +```c +void hello (int n){ + for( int sz = 1 ; sz < n ; sz += sz ) + for( int i = 1 ; i < n ; i ++ ) + cout << "Hello" << endl; +} +``` + +上面这段代码的时间复杂度是 O(nlog n) 而不是 O(n^2) + +```c +bool isPrime (int n){ + if (num <= 1) return false; + for( int x = 2 ; x * x <= n ; x ++ ) + if( n % x == 0 ) + return false; + return true; +} +``` + +上面这段代码的时间复杂度是 O(sqrt(n)) 而不是 O(n)。 + +再举一个例子，有一个字符串数组，将数组中的每一个字符串按照字母序排序，之后再将整个字符串数组按照字典序排序。两步操作的整体时间复杂度是多少呢？ + +如果回答是 O(n*nlog n + nlog n) = O(n^2log n)，这个答案是错误的。字符串的长度和数组的长度是没有关系的，所以这两个变量应该单独计算。假设最长的字符串长度为 s，数组中有 n 个字符串。对每个字符串排序的时间复杂度是 O(slog s)，将数组中每个字符串都按照字母序排序的时间复杂度是 O(n * slog s)。 + +将整个字符串数组按照字典序排序的时间复杂度是 O(s * nlog n)。排序算法中的 O(nlog n) 是比较的次数，由于比较的是整型数字，所以每次比较是 O(1)。但是字符串按照字典序比较，时间复杂度是 O(s)。所以字符串数组按照字典序排序的时间复杂度是 O(s * nlog n)。所以整体复杂度是 O(n * slog s) + O(s * nlog n) = O(n\*slog s + s\*nlogn) = O(n\*s\*(log s + log n)) = O(n\*s\*log(n\*s)）。 + +## 二. 空间复杂度 + +递归调用是有空间代价的，递归算法需要保存递归栈信息，所以花费的空间复杂度会比非递归算法要高。 + +```c +int sum( int n ){ + assert( n >= 0 ) + int ret = 0; + for ( int i = 0 ; i <= n ; i ++ ) + ret += i; + return ret; +} +``` + +上面算法的时间复杂度为 O(n)，空间复杂度 O(1)。 + +```c +int sum( int n ){ + assert( n >= 0 ) + if ( n == 0 ) + return 0; + return n + sum( n - 1 ); +} +``` + +上面算法的时间复杂度为 O(n)，空间复杂度 O(n)。 + +## 三. 递归的时间复杂度 + +### 1. 只有一次递归调用 + +如果递归函数中，只进行了一次递归调用，且递归深度为 depth，在每个递归函数中，时间复杂度为 T，那么总体的时间复杂度为 O(T * depth) + +举个例子： + +```c +int binarySearch(int arr[], int l, int r, int target){ + if( l > r ) + return -1; + int mid = l + ( r - l ) / 2; // 防溢出 + if(arr[mid] == target) + return mid; + else if (arr[mid] > target) + return binarySearch(arr,l,mid-1,target); + else + return binarySearch(arr,mid+1,r,target); +} + +``` + +在二分查找的递归实现中，只递归调用了自身。递归深度是 log n ，每次递归里面的复杂度是 O(1) 的，所以二分查找的递归实现的时间复杂度为 O(log n) 的。 + + +### 2. 只有多次递归调用 + +针对多次递归调用的情况，就需要看它的计算调用的次数了。通常可以画一颗递归树来看。举例： + +```c +int f(int n){ + assert( n >= 0 ); + if( n == 0 ) + return 1; + return f( n - 1 ) + f ( n - 1 ); +} +``` + +上述这次递归调用的次数为 2^0^ + 2^1^ + 2^2^ + …… + 2^n^ = 2^n+1^ - 1 = O(2^n) + + +> 关于更加复杂的递归的复杂度分析，请参考主定理。主定理中针对各种复杂情况都给出了正确的结论。 + + +---------------------------------------------- + diff --git a/website/content/ChapterOne/_index.md b/website/content/ChapterOne/_index.md index 48ff3ac10..6d535294a 100644 --- a/website/content/ChapterOne/_index.md +++ b/website/content/ChapterOne/_index.md @@ -35,7 +35,7 @@ weight: 1 ## 关于作者 -笔者是一个刚刚入行一年半的 gopher 新人，还请各位大佬多多指点小弟我。大学参加了 3 年 ACM-ICPC，但是由于资质不高，没有拿到一块金牌。所以在算法方面，我对自己的评价算是新手吧。参加 ACM-ICPC 最大的收获是训练了思维能力，这种能力也会运用到生活中。其次是认识了很多国内很聪明的选手，看到了自己和他们的差距。最后，就是那 200 多页，有些自己都没有完全理解的，打印的密密麻麻的[算法模板](https://github.com/halfrost/LeetCode-Go/releases/tag/Special)。知识学会了，终身都是自己的，没有学会，那些知识都是身外之物。 +笔者是一个刚刚入行一年半的 gopher 新人，还请各位大佬多多指点小弟我。大学参加了 3 年 ACM-ICPC，但是由于资质不高，没有拿到一块金牌。所以在算法方面，我对自己的评价算是新手吧。参加 ACM-ICPC 最大的收获是训练了思维能力，这种能力也会运用到生活中。其次是认识了很多国内很聪明的选手，看到了自己和他们的差距。最后，就是那 200 多页，有些自己都没有完全理解的，打印的密密麻麻的[算法模板](https://github.com/halfrost/leetcode-go/releases/tag/Special)。知识学会了，终身都是自己的，没有学会，那些知识都是身外之物。 笔者从 2019 年 3 月 25 号开始刷题，到 2020 年 3 月 25 号，整整一年的时间。原计划是每天一题。实际上每天有时候不止一题，最终完成了 600+： @@ -49,7 +49,7 @@ weight: 1 ## 关于书中的代码 -代码都放在 [github repo](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode) 中，按题号可以搜索到题目。 +代码都放在 [github repo](https://github.com/halfrost/leetcode-go/tree/master/leetcode) 中，按题号可以搜索到题目。 本书题目的代码都已经 beats 100% 了。没有 beats 100% 题解就没有放到本书中了。那些题目笔者会继续优化到 100% 再放进来。 有可能读者会问，为何要追求 beats 100%。笔者认为优化到 beats 100% 才算是把这题做出感觉了。有好几道 Hard 题，笔者都用暴力解法 AC 了，然后只 beats 了 5%。这题就如同没做一样。而且面试中如果给了这样的答案，面试官也不会满意，“还有没有更优解？”。如果通过自己的思考能给出更优解，面试官会更满意一些。 diff --git a/website/content/ChapterThree/Segment_Tree.md b/website/content/ChapterThree/Segment_Tree.md index c0fc16a99..162d7e6b6 100644 --- a/website/content/ChapterThree/Segment_Tree.md +++ b/website/content/ChapterThree/Segment_Tree.md @@ -373,13 +373,13 @@ Range Sum Query 问题专门处理查询范围内的元素总和。这个问题 -### 2. 单点更新: +### 2. 单点更新 - [HDU 1166 敌兵布阵](http://acm.hdu.edu.cn/showproblem.php?pid=1166) update:单点增减 query:区间求和 - [HDU 1754 I Hate It](http://acm.hdu.edu.cn/showproblem.php?pid=1754) update:单点替换 query:区间最值 - [HDU 1394 Minimum Inversion Number](http://acm.hdu.edu.cn/showproblem.php?pid=1394) update:单点增减 query:区间求和 - [HDU 2795 Billboard](http://acm.hdu.edu.cn/showproblem.php?pid=2795) query:区间求最大值的位子(直接把update的操作在query里做了) -### 3. 区间更新: +### 3. 区间更新 - [HDU 1698 Just a Hook](http://acm.hdu.edu.cn/showproblem.php?pid=1698) update:成段替换 (由于只query一次总区间,所以可以直接输出 1 结点的信息) - [POJ 3468 A Simple Problem with Integers](http://poj.org/problem?id=3468) update:成段增减 query:区间求和 diff --git a/website/content/ChapterTwo/Array.md b/website/content/ChapterTwo/Array.md index 85cf49579..1ef86606b 100644 --- a/website/content/ChapterTwo/Array.md +++ b/website/content/ChapterTwo/Array.md @@ -8,172 +8,422 @@ weight: 1 | No. | Title | Solution | Difficulty | TimeComplexity | SpaceComplexity |Favorite| Acceptance | |:--------:|:------- | :--------: | :----------: | :----: | :-----: | :-----: |:-----: | -|0001|Two Sum|[Go]({{< relref "/ChapterFour/0001~0099/0001.Two-Sum.md" >}})|Easy| O(n)| O(n)||46.8%| -|0004|Median of Two Sorted Arrays|[Go]({{< relref "/ChapterFour/0001~0099/0004.Median-of-Two-Sorted-Arrays.md" >}})|Hard||||31.5%| -|0011|Container With Most Water|[Go]({{< relref "/ChapterFour/0001~0099/0011.Container-With-Most-Water.md" >}})|Medium| O(n)| O(1)||52.9%| -|0015|3Sum|[Go]({{< relref "/ChapterFour/0001~0099/0015.3Sum.md" >}})|Medium| O(n^2)| O(n)|❤️|28.4%| -|0016|3Sum Closest|[Go]({{< relref "/ChapterFour/0001~0099/0016.3Sum-Closest.md" >}})|Medium| O(n^2)| O(1)|❤️|46.4%| -|0018|4Sum|[Go]({{< relref "/ChapterFour/0001~0099/0018.4Sum.md" >}})|Medium| O(n^3)| O(n^2)|❤️|35.2%| -|0026|Remove Duplicates from Sorted Array|[Go]({{< relref "/ChapterFour/0001~0099/0026.Remove-Duplicates-from-Sorted-Array.md" >}})|Easy| O(n)| O(1)||46.9%| -|0027|Remove Element|[Go]({{< relref "/ChapterFour/0001~0099/0027.Remove-Element.md" >}})|Easy| O(n)| O(1)||49.6%| -|0031|Next Permutation|[Go]({{< relref "/ChapterFour/0001~0099/0031.Next-Permutation.md" >}})|Medium||||33.9%| -|0033|Search in Rotated Sorted Array|[Go]({{< relref "/ChapterFour/0001~0099/0033.Search-in-Rotated-Sorted-Array.md" >}})|Medium||||36.2%| -|0034|Find First and Last Position of Element in Sorted Array|[Go]({{< relref "/ChapterFour/0001~0099/0034.Find-First-and-Last-Position-of-Element-in-Sorted-Array.md" >}})|Medium||||37.6%| -|0035|Search Insert Position|[Go]({{< relref "/ChapterFour/0001~0099/0035.Search-Insert-Position.md" >}})|Easy||||42.9%| -|0039|Combination Sum|[Go]({{< relref "/ChapterFour/0001~0099/0039.Combination-Sum.md" >}})|Medium| O(n log n)| O(n)||59.9%| -|0040|Combination Sum II|[Go]({{< relref "/ChapterFour/0001~0099/0040.Combination-Sum-II.md" >}})|Medium| O(n log n)| O(n)||50.5%| -|0041|First Missing Positive|[Go]({{< relref "/ChapterFour/0001~0099/0041.First-Missing-Positive.md" >}})|Hard| O(n)| O(n)||34.1%| -|0042|Trapping Rain Water|[Go]({{< relref "/ChapterFour/0001~0099/0042.Trapping-Rain-Water.md" >}})|Hard| O(n)| O(1)|❤️|51.8%| -|0045|Jump Game II|[Go]({{< relref "/ChapterFour/0001~0099/0045.Jump-Game-II.md" >}})|Medium||||31.8%| -|0048|Rotate Image|[Go]({{< relref "/ChapterFour/0001~0099/0048.Rotate-Image.md" >}})|Medium| O(n)| O(1)||61.2%| -|0053|Maximum Subarray|[Go]({{< relref "/ChapterFour/0001~0099/0053.Maximum-Subarray.md" >}})|Easy| O(n)| O(n)||47.9%| -|0054|Spiral Matrix|[Go]({{< relref "/ChapterFour/0001~0099/0054.Spiral-Matrix.md" >}})|Medium| O(n)| O(n^2)||36.7%| -|0055|Jump Game|[Go]({{< relref "/ChapterFour/0001~0099/0055.Jump-Game.md" >}})|Medium||||35.3%| -|0056|Merge Intervals|[Go]({{< relref "/ChapterFour/0001~0099/0056.Merge-Intervals.md" >}})|Medium| O(n log n)| O(1)||41.5%| -|0057|Insert Interval|[Go]({{< relref "/ChapterFour/0001~0099/0057.Insert-Interval.md" >}})|Medium| O(n)| O(1)||35.4%| -|0059|Spiral Matrix II|[Go]({{< relref "/ChapterFour/0001~0099/0059.Spiral-Matrix-II.md" >}})|Medium| O(n)| O(n^2)||58.4%| -|0062|Unique Paths|[Go]({{< relref "/ChapterFour/0001~0099/0062.Unique-Paths.md" >}})|Medium| O(n^2)| O(n^2)||56.5%| -|0063|Unique Paths II|[Go]({{< relref "/ChapterFour/0001~0099/0063.Unique-Paths-II.md" >}})|Medium| O(n^2)| O(n^2)||35.4%| -|0064|Minimum Path Sum|[Go]({{< relref "/ChapterFour/0001~0099/0064.Minimum-Path-Sum.md" >}})|Medium| O(n^2)| O(n^2)||56.6%| -|0066|Plus One|[Go]({{< relref "/ChapterFour/0001~0099/0066.Plus-One.md" >}})|Easy||||42.2%| -|0073|Set Matrix Zeroes|[Go]({{< relref "/ChapterFour/0001~0099/0073.Set-Matrix-Zeroes.md" >}})|Medium||||44.7%| -|0074|Search a 2D Matrix|[Go]({{< relref "/ChapterFour/0001~0099/0074.Search-a-2D-Matrix.md" >}})|Medium||||38.3%| -|0075|Sort Colors|[Go]({{< relref "/ChapterFour/0001~0099/0075.Sort-Colors.md" >}})|Medium| O(n)| O(1)|❤️|50.0%| -|0078|Subsets|[Go]({{< relref "/ChapterFour/0001~0099/0078.Subsets.md" >}})|Medium| O(n^2)| O(n)|❤️|65.8%| -|0079|Word Search|[Go]({{< relref "/ChapterFour/0001~0099/0079.Word-Search.md" >}})|Medium| O(n^2)| O(n^2)|❤️|37.3%| -|0080|Remove Duplicates from Sorted Array II|[Go]({{< relref "/ChapterFour/0001~0099/0080.Remove-Duplicates-from-Sorted-Array-II.md" >}})|Medium| O(n)| O(1||46.5%| -|0081|Search in Rotated Sorted Array II|[Go]({{< relref "/ChapterFour/0001~0099/0081.Search-in-Rotated-Sorted-Array-II.md" >}})|Medium||||33.7%| -|0084|Largest Rectangle in Histogram|[Go]({{< relref "/ChapterFour/0001~0099/0084.Largest-Rectangle-in-Histogram.md" >}})|Hard| O(n)| O(n)|❤️|37.5%| -|0088|Merge Sorted Array|[Go]({{< relref "/ChapterFour/0001~0099/0088.Merge-Sorted-Array.md" >}})|Easy| O(n)| O(1)|❤️|40.9%| -|0090|Subsets II|[Go]({{< relref "/ChapterFour/0001~0099/0090.Subsets-II.md" >}})|Medium| O(n^2)| O(n)|❤️|49.3%| -|0105|Construct Binary Tree from Preorder and Inorder Traversal|[Go]({{< relref "/ChapterFour/0100~0199/0105.Construct-Binary-Tree-from-Preorder-and-Inorder-Traversal.md" >}})|Medium||||52.6%| -|0106|Construct Binary Tree from Inorder and Postorder Traversal|[Go]({{< relref "/ChapterFour/0100~0199/0106.Construct-Binary-Tree-from-Inorder-and-Postorder-Traversal.md" >}})|Medium||||50.3%| -|0118|Pascal's Triangle|[Go]({{< relref "/ChapterFour/0100~0199/0118.Pascals-Triangle.md" >}})|Easy||||55.7%| -|0119|Pascal's Triangle II|[Go]({{< relref "/ChapterFour/0100~0199/0119.Pascals-Triangle-II.md" >}})|Easy||||52.7%| -|0120|Triangle|[Go]({{< relref "/ChapterFour/0100~0199/0120.Triangle.md" >}})|Medium| O(n^2)| O(n)||46.9%| -|0121|Best Time to Buy and Sell Stock|[Go]({{< relref "/ChapterFour/0100~0199/0121.Best-Time-to-Buy-and-Sell-Stock.md" >}})|Easy| O(n)| O(1)||51.9%| -|0122|Best Time to Buy and Sell Stock II|[Go]({{< relref "/ChapterFour/0100~0199/0122.Best-Time-to-Buy-and-Sell-Stock-II.md" >}})|Easy| O(n)| O(1)||58.9%| -|0126|Word Ladder II|[Go]({{< relref "/ChapterFour/0100~0199/0126.Word-Ladder-II.md" >}})|Hard| O(n)| O(n^2)|❤️|23.9%| -|0128|Longest Consecutive Sequence|[Go]({{< relref "/ChapterFour/0100~0199/0128.Longest-Consecutive-Sequence.md" >}})|Hard||||46.6%| -|0152|Maximum Product Subarray|[Go]({{< relref "/ChapterFour/0100~0199/0152.Maximum-Product-Subarray.md" >}})|Medium| O(n)| O(1)||32.9%| -|0153|Find Minimum in Rotated Sorted Array|[Go]({{< relref "/ChapterFour/0100~0199/0153.Find-Minimum-in-Rotated-Sorted-Array.md" >}})|Medium||||46.5%| -|0154|Find Minimum in Rotated Sorted Array II|[Go]({{< relref "/ChapterFour/0100~0199/0154.Find-Minimum-in-Rotated-Sorted-Array-II.md" >}})|Hard||||42.2%| -|0162|Find Peak Element|[Go]({{< relref "/ChapterFour/0100~0199/0162.Find-Peak-Element.md" >}})|Medium||||44.1%| -|0167|Two Sum II - Input array is sorted|[Go]({{< relref "/ChapterFour/0100~0199/0167.Two-Sum-II-Input-array-is-sorted.md" >}})|Easy| O(n)| O(1)||55.8%| -|0169|Majority Element|[Go]({{< relref "/ChapterFour/0100~0199/0169.Majority-Element.md" >}})|Easy||||60.3%| -|0189|Rotate Array|[Go]({{< relref "/ChapterFour/0100~0199/0189.Rotate-Array.md" >}})|Medium||||36.8%| -|0209|Minimum Size Subarray Sum|[Go]({{< relref "/ChapterFour/0200~0299/0209.Minimum-Size-Subarray-Sum.md" >}})|Medium| O(n)| O(1)||39.9%| -|0216|Combination Sum III|[Go]({{< relref "/ChapterFour/0200~0299/0216.Combination-Sum-III.md" >}})|Medium| O(n)| O(1)|❤️|60.8%| -|0217|Contains Duplicate|[Go]({{< relref "/ChapterFour/0200~0299/0217.Contains-Duplicate.md" >}})|Easy| O(n)| O(n)||57.0%| -|0219|Contains Duplicate II|[Go]({{< relref "/ChapterFour/0200~0299/0219.Contains-Duplicate-II.md" >}})|Easy| O(n)| O(n)||38.9%| -|0228|Summary Ranges|[Go]({{< relref "/ChapterFour/0200~0299/0228.Summary-Ranges.md" >}})|Easy||||42.8%| -|0229|Majority Element II|[Go]({{< relref "/ChapterFour/0200~0299/0229.Majority-Element-II.md" >}})|Medium||||39.1%| -|0268|Missing Number|[Go]({{< relref "/ChapterFour/0200~0299/0268.Missing-Number.md" >}})|Easy||||55.4%| -|0283|Move Zeroes|[Go]({{< relref "/ChapterFour/0200~0299/0283.Move-Zeroes.md" >}})|Easy| O(n)| O(1)||58.7%| -|0287|Find the Duplicate Number|[Go]({{< relref "/ChapterFour/0200~0299/0287.Find-the-Duplicate-Number.md" >}})|Medium| O(n)| O(1)|❤️|58.0%| -|0414|Third Maximum Number|[Go]({{< relref "/ChapterFour/0400~0499/0414.Third-Maximum-Number.md" >}})|Easy||||30.8%| -|0448|Find All Numbers Disappeared in an Array|[Go]({{< relref "/ChapterFour/0400~0499/0448.Find-All-Numbers-Disappeared-in-an-Array.md" >}})|Easy||||56.3%| -|0457|Circular Array Loop|[Go]({{< relref "/ChapterFour/0400~0499/0457.Circular-Array-Loop.md" >}})|Medium||||30.4%| -|0485|Max Consecutive Ones|[Go]({{< relref "/ChapterFour/0400~0499/0485.Max-Consecutive-Ones.md" >}})|Easy||||52.7%| -|0509|Fibonacci Number|[Go]({{< relref "/ChapterFour/0500~0599/0509.Fibonacci-Number.md" >}})|Easy||||67.9%| -|0532|K-diff Pairs in an Array|[Go]({{< relref "/ChapterFour/0500~0599/0532.K-diff-Pairs-in-an-Array.md" >}})|Medium| O(n)| O(n)||35.6%| -|0561|Array Partition I|[Go]({{< relref "/ChapterFour/0500~0599/0561.Array-Partition-I.md" >}})|Easy||||73.6%| -|0566|Reshape the Matrix|[Go]({{< relref "/ChapterFour/0500~0599/0566.Reshape-the-Matrix.md" >}})|Easy| O(n^2)| O(n^2)||61.1%| -|0581|Shortest Unsorted Continuous Subarray|[Go]({{< relref "/ChapterFour/0500~0599/0581.Shortest-Unsorted-Continuous-Subarray.md" >}})|Medium||||33.0%| -|0605|Can Place Flowers|[Go]({{< relref "/ChapterFour/0600~0699/0605.Can-Place-Flowers.md" >}})|Easy||||31.7%| -|0628|Maximum Product of Three Numbers|[Go]({{< relref "/ChapterFour/0600~0699/0628.Maximum-Product-of-Three-Numbers.md" >}})|Easy| O(n)| O(1)||46.8%| -|0643|Maximum Average Subarray I|[Go]({{< relref "/ChapterFour/0600~0699/0643.Maximum-Average-Subarray-I.md" >}})|Easy||||42.1%| -|0661|Image Smoother|[Go]({{< relref "/ChapterFour/0600~0699/0661.Image-Smoother.md" >}})|Easy||||52.4%| -|0665|Non-decreasing Array|[Go]({{< relref "/ChapterFour/0600~0699/0665.Non-decreasing-Array.md" >}})|Medium||||19.9%| -|0667|Beautiful Arrangement II|[Go]({{< relref "/ChapterFour/0600~0699/0667.Beautiful-Arrangement-II.md" >}})|Medium||||59.0%| -|0674|Longest Continuous Increasing Subsequence|[Go]({{< relref "/ChapterFour/0600~0699/0674.Longest-Continuous-Increasing-Subsequence.md" >}})|Easy||||46.0%| -|0695|Max Area of Island|[Go]({{< relref "/ChapterFour/0600~0699/0695.Max-Area-of-Island.md" >}})|Medium||||65.3%| -|0697|Degree of an Array|[Go]({{< relref "/ChapterFour/0600~0699/0697.Degree-of-an-Array.md" >}})|Easy||||54.5%| -|0713|Subarray Product Less Than K|[Go]({{< relref "/ChapterFour/0700~0799/0713.Subarray-Product-Less-Than-K.md" >}})|Medium| O(n)| O(1)||40.6%| -|0714|Best Time to Buy and Sell Stock with Transaction Fee|[Go]({{< relref "/ChapterFour/0700~0799/0714.Best-Time-to-Buy-and-Sell-Stock-with-Transaction-Fee.md" >}})|Medium| O(n)| O(1)||58.2%| -|0717|1-bit and 2-bit Characters|[Go]({{< relref "/ChapterFour/0700~0799/0717.1-bit-and-2-bit-Characters.md" >}})|Easy||||46.8%| -|0718|Maximum Length of Repeated Subarray|[Go]({{< relref "/ChapterFour/0700~0799/0718.Maximum-Length-of-Repeated-Subarray.md" >}})|Medium||||50.6%| -|0719|Find K-th Smallest Pair Distance|[Go]({{< relref "/ChapterFour/0700~0799/0719.Find-K-th-Smallest-Pair-Distance.md" >}})|Hard||||32.7%| -|0724|Find Pivot Index|[Go]({{< relref "/ChapterFour/0700~0799/0724.Find-Pivot-Index.md" >}})|Easy||||46.4%| -|0729|My Calendar I|[Go]({{< relref "/ChapterFour/0700~0799/0729.My-Calendar-I.md" >}})|Medium||||53.7%| -|0746|Min Cost Climbing Stairs|[Go]({{< relref "/ChapterFour/0700~0799/0746.Min-Cost-Climbing-Stairs.md" >}})|Easy| O(n)| O(1)||51.2%| -|0766|Toeplitz Matrix|[Go]({{< relref "/ChapterFour/0700~0799/0766.Toeplitz-Matrix.md" >}})|Easy| O(n)| O(1)||66.0%| -|0775|Global and Local Inversions|[Go]({{< relref "/ChapterFour/0700~0799/0775.Global-and-Local-Inversions.md" >}})|Medium||||46.2%| -|0830|Positions of Large Groups|[Go]({{< relref "/ChapterFour/0800~0899/0830.Positions-of-Large-Groups.md" >}})|Easy||||50.5%| -|0832|Flipping an Image|[Go]({{< relref "/ChapterFour/0800~0899/0832.Flipping-an-Image.md" >}})|Easy||||78.4%| -|0867|Transpose Matrix|[Go]({{< relref "/ChapterFour/0800~0899/0867.Transpose-Matrix.md" >}})|Easy| O(n)| O(1)||61.9%| -|0870|Advantage Shuffle|[Go]({{< relref "/ChapterFour/0800~0899/0870.Advantage-Shuffle.md" >}})|Medium||||50.8%| -|0888|Fair Candy Swap|[Go]({{< relref "/ChapterFour/0800~0899/0888.Fair-Candy-Swap.md" >}})|Easy||||59.2%| -|0891|Sum of Subsequence Widths|[Go]({{< relref "/ChapterFour/0800~0899/0891.Sum-of-Subsequence-Widths.md" >}})|Hard| O(n log n)| O(1)||33.2%| -|0896|Monotonic Array|[Go]({{< relref "/ChapterFour/0800~0899/0896.Monotonic-Array.md" >}})|Easy||||57.9%| -|0907|Sum of Subarray Minimums|[Go]({{< relref "/ChapterFour/0900~0999/0907.Sum-of-Subarray-Minimums.md" >}})|Medium| O(n)| O(n)|❤️|33.1%| -|0914|X of a Kind in a Deck of Cards|[Go]({{< relref "/ChapterFour/0900~0999/0914.X-of-a-Kind-in-a-Deck-of-Cards.md" >}})|Easy||||33.9%| -|0918|Maximum Sum Circular Subarray|[Go]({{< relref "/ChapterFour/0900~0999/0918.Maximum-Sum-Circular-Subarray.md" >}})|Medium||||34.4%| +|0001|Two Sum|[Go]({{< relref "/ChapterFour/0001~0099/0001.Two-Sum.md" >}})|Easy| O(n)| O(n)||49.7%| +|0004|Median of Two Sorted Arrays|[Go]({{< relref "/ChapterFour/0001~0099/0004.Median-of-Two-Sorted-Arrays.md" >}})|Hard||||36.2%| +|0011|Container With Most Water|[Go]({{< relref "/ChapterFour/0001~0099/0011.Container-With-Most-Water.md" >}})|Medium| O(n)| O(1)||54.0%| +|0015|3Sum|[Go]({{< relref "/ChapterFour/0001~0099/0015.3Sum.md" >}})|Medium| O(n^2)| O(n)|❤️|32.6%| +|0016|3Sum Closest|[Go]({{< relref "/ChapterFour/0001~0099/0016.3Sum-Closest.md" >}})|Medium| O(n^2)| O(1)|❤️|45.7%| +|0018|4Sum|[Go]({{< relref "/ChapterFour/0001~0099/0018.4Sum.md" >}})|Medium| O(n^3)| O(n^2)|❤️|35.9%| +|0026|Remove Duplicates from Sorted Array|[Go]({{< relref "/ChapterFour/0001~0099/0026.Remove-Duplicates-from-Sorted-Array.md" >}})|Easy| O(n)| O(1)||51.6%| +|0027|Remove Element|[Go]({{< relref "/ChapterFour/0001~0099/0027.Remove-Element.md" >}})|Easy| O(n)| O(1)||53.0%| +|0031|Next Permutation|[Go]({{< relref "/ChapterFour/0001~0099/0031.Next-Permutation.md" >}})|Medium||||37.6%| +|0033|Search in Rotated Sorted Array|[Go]({{< relref "/ChapterFour/0001~0099/0033.Search-in-Rotated-Sorted-Array.md" >}})|Medium||||39.0%| +|0034|Find First and Last Position of Element in Sorted Array|[Go]({{< relref "/ChapterFour/0001~0099/0034.Find-First-and-Last-Position-of-Element-in-Sorted-Array.md" >}})|Medium||||41.9%| +|0035|Search Insert Position|[Go]({{< relref "/ChapterFour/0001~0099/0035.Search-Insert-Position.md" >}})|Easy||||43.4%| +|0036|Valid Sudoku|[Go]({{< relref "/ChapterFour/0001~0099/0036.Valid-Sudoku.md" >}})|Medium||||58.1%| +|0037|Sudoku Solver|[Go]({{< relref "/ChapterFour/0001~0099/0037.Sudoku-Solver.md" >}})|Hard||||57.7%| +|0039|Combination Sum|[Go]({{< relref "/ChapterFour/0001~0099/0039.Combination-Sum.md" >}})|Medium| O(n log n)| O(n)||68.6%| +|0040|Combination Sum II|[Go]({{< relref "/ChapterFour/0001~0099/0040.Combination-Sum-II.md" >}})|Medium| O(n log n)| O(n)||53.4%| +|0041|First Missing Positive|[Go]({{< relref "/ChapterFour/0001~0099/0041.First-Missing-Positive.md" >}})|Hard| O(n)| O(n)||36.7%| +|0042|Trapping Rain Water|[Go]({{< relref "/ChapterFour/0001~0099/0042.Trapping-Rain-Water.md" >}})|Hard| O(n)| O(1)|❤️|59.3%| +|0045|Jump Game II|[Go]({{< relref "/ChapterFour/0001~0099/0045.Jump-Game-II.md" >}})|Medium||||39.8%| +|0046|Permutations|[Go]({{< relref "/ChapterFour/0001~0099/0046.Permutations.md" >}})|Medium||||75.7%| +|0047|Permutations II|[Go]({{< relref "/ChapterFour/0001~0099/0047.Permutations-II.md" >}})|Medium||||57.4%| +|0048|Rotate Image|[Go]({{< relref "/ChapterFour/0001~0099/0048.Rotate-Image.md" >}})|Medium| O(n)| O(1)||71.0%| +|0049|Group Anagrams|[Go]({{< relref "/ChapterFour/0001~0099/0049.Group-Anagrams.md" >}})|Medium||||66.8%| +|0051|N-Queens|[Go]({{< relref "/ChapterFour/0001~0099/0051.N-Queens.md" >}})|Hard||||64.2%| +|0053|Maximum Subarray|[Go]({{< relref "/ChapterFour/0001~0099/0053.Maximum-Subarray.md" >}})|Medium| O(n)| O(n)||50.2%| +|0054|Spiral Matrix|[Go]({{< relref "/ChapterFour/0001~0099/0054.Spiral-Matrix.md" >}})|Medium| O(n)| O(n^2)||45.0%| +|0055|Jump Game|[Go]({{< relref "/ChapterFour/0001~0099/0055.Jump-Game.md" >}})|Medium||||38.9%| +|0056|Merge Intervals|[Go]({{< relref "/ChapterFour/0001~0099/0056.Merge-Intervals.md" >}})|Medium| O(n log n)| O(1)||46.2%| +|0057|Insert Interval|[Go]({{< relref "/ChapterFour/0001~0099/0057.Insert-Interval.md" >}})|Medium| O(n)| O(1)||39.0%| +|0059|Spiral Matrix II|[Go]({{< relref "/ChapterFour/0001~0099/0059.Spiral-Matrix-II.md" >}})|Medium| O(n)| O(n^2)||67.4%| +|0063|Unique Paths II|[Go]({{< relref "/ChapterFour/0001~0099/0063.Unique-Paths-II.md" >}})|Medium| O(n^2)| O(n^2)||39.4%| +|0064|Minimum Path Sum|[Go]({{< relref "/ChapterFour/0001~0099/0064.Minimum-Path-Sum.md" >}})|Medium| O(n^2)| O(n^2)||62.0%| +|0066|Plus One|[Go]({{< relref "/ChapterFour/0001~0099/0066.Plus-One.md" >}})|Easy||||43.7%| +|0073|Set Matrix Zeroes|[Go]({{< relref "/ChapterFour/0001~0099/0073.Set-Matrix-Zeroes.md" >}})|Medium||||51.3%| +|0074|Search a 2D Matrix|[Go]({{< relref "/ChapterFour/0001~0099/0074.Search-a-2D-Matrix.md" >}})|Medium||||47.7%| +|0075|Sort Colors|[Go]({{< relref "/ChapterFour/0001~0099/0075.Sort-Colors.md" >}})|Medium| O(n)| O(1)|❤️|58.6%| +|0078|Subsets|[Go]({{< relref "/ChapterFour/0001~0099/0078.Subsets.md" >}})|Medium| O(n^2)| O(n)|❤️|74.9%| +|0079|Word Search|[Go]({{< relref "/ChapterFour/0001~0099/0079.Word-Search.md" >}})|Medium| O(n^2)| O(n^2)|❤️|40.2%| +|0080|Remove Duplicates from Sorted Array II|[Go]({{< relref "/ChapterFour/0001~0099/0080.Remove-Duplicates-from-Sorted-Array-II.md" >}})|Medium| O(n)| O(1||52.3%| +|0081|Search in Rotated Sorted Array II|[Go]({{< relref "/ChapterFour/0001~0099/0081.Search-in-Rotated-Sorted-Array-II.md" >}})|Medium||||35.7%| +|0084|Largest Rectangle in Histogram|[Go]({{< relref "/ChapterFour/0001~0099/0084.Largest-Rectangle-in-Histogram.md" >}})|Hard| O(n)| O(n)|❤️|42.6%| +|0088|Merge Sorted Array|[Go]({{< relref "/ChapterFour/0001~0099/0088.Merge-Sorted-Array.md" >}})|Easy| O(n)| O(1)|❤️|46.6%| +|0090|Subsets II|[Go]({{< relref "/ChapterFour/0001~0099/0090.Subsets-II.md" >}})|Medium| O(n^2)| O(n)|❤️|55.9%| +|0105|Construct Binary Tree from Preorder and Inorder Traversal|[Go]({{< relref "/ChapterFour/0100~0199/0105.Construct-Binary-Tree-from-Preorder-and-Inorder-Traversal.md" >}})|Medium||||61.6%| +|0106|Construct Binary Tree from Inorder and Postorder Traversal|[Go]({{< relref "/ChapterFour/0100~0199/0106.Construct-Binary-Tree-from-Inorder-and-Postorder-Traversal.md" >}})|Medium||||60.0%| +|0108|Convert Sorted Array to Binary Search Tree|[Go]({{< relref "/ChapterFour/0100~0199/0108.Convert-Sorted-Array-to-Binary-Search-Tree.md" >}})|Easy||||69.9%| +|0118|Pascal's Triangle|[Go]({{< relref "/ChapterFour/0100~0199/0118.Pascals-Triangle.md" >}})|Easy||||70.8%| +|0119|Pascal's Triangle II|[Go]({{< relref "/ChapterFour/0100~0199/0119.Pascals-Triangle-II.md" >}})|Easy||||60.8%| +|0120|Triangle|[Go]({{< relref "/ChapterFour/0100~0199/0120.Triangle.md" >}})|Medium| O(n^2)| O(n)||54.5%| +|0121|Best Time to Buy and Sell Stock|[Go]({{< relref "/ChapterFour/0100~0199/0121.Best-Time-to-Buy-and-Sell-Stock.md" >}})|Easy| O(n)| O(1)||54.3%| +|0122|Best Time to Buy and Sell Stock II|[Go]({{< relref "/ChapterFour/0100~0199/0122.Best-Time-to-Buy-and-Sell-Stock-II.md" >}})|Medium| O(n)| O(1)||63.9%| +|0128|Longest Consecutive Sequence|[Go]({{< relref "/ChapterFour/0100~0199/0128.Longest-Consecutive-Sequence.md" >}})|Medium||||48.5%| +|0130|Surrounded Regions|[Go]({{< relref "/ChapterFour/0100~0199/0130.Surrounded-Regions.md" >}})|Medium||||36.8%| +|0135|Candy|[Go]({{< relref "/ChapterFour/0100~0199/0135.Candy.md" >}})|Hard||||41.0%| +|0136|Single Number|[Go]({{< relref "/ChapterFour/0100~0199/0136.Single-Number.md" >}})|Easy||||70.7%| +|0137|Single Number II|[Go]({{< relref "/ChapterFour/0100~0199/0137.Single-Number-II.md" >}})|Medium||||58.5%| +|0150|Evaluate Reverse Polish Notation|[Go]({{< relref "/ChapterFour/0100~0199/0150.Evaluate-Reverse-Polish-Notation.md" >}})|Medium||||45.8%| +|0152|Maximum Product Subarray|[Go]({{< relref "/ChapterFour/0100~0199/0152.Maximum-Product-Subarray.md" >}})|Medium| O(n)| O(1)||34.9%| +|0153|Find Minimum in Rotated Sorted Array|[Go]({{< relref "/ChapterFour/0100~0199/0153.Find-Minimum-in-Rotated-Sorted-Array.md" >}})|Medium||||48.9%| +|0154|Find Minimum in Rotated Sorted Array II|[Go]({{< relref "/ChapterFour/0100~0199/0154.Find-Minimum-in-Rotated-Sorted-Array-II.md" >}})|Hard||||43.5%| +|0162|Find Peak Element|[Go]({{< relref "/ChapterFour/0100~0199/0162.Find-Peak-Element.md" >}})|Medium||||46.0%| +|0164|Maximum Gap|[Go]({{< relref "/ChapterFour/0100~0199/0164.Maximum-Gap.md" >}})|Hard||||43.4%| +|0167|Two Sum II - Input Array Is Sorted|[Go]({{< relref "/ChapterFour/0100~0199/0167.Two-Sum-II-Input-Array-Is-Sorted.md" >}})|Medium| O(n)| O(1)||60.0%| +|0169|Majority Element|[Go]({{< relref "/ChapterFour/0100~0199/0169.Majority-Element.md" >}})|Easy||||63.9%| +|0174|Dungeon Game|[Go]({{< relref "/ChapterFour/0100~0199/0174.Dungeon-Game.md" >}})|Hard||||37.5%| +|0179|Largest Number|[Go]({{< relref "/ChapterFour/0100~0199/0179.Largest-Number.md" >}})|Medium||||34.6%| +|0189|Rotate Array|[Go]({{< relref "/ChapterFour/0100~0199/0189.Rotate-Array.md" >}})|Medium||||39.4%| +|0198|House Robber|[Go]({{< relref "/ChapterFour/0100~0199/0198.House-Robber.md" >}})|Medium||||49.4%| +|0200|Number of Islands|[Go]({{< relref "/ChapterFour/0200~0299/0200.Number-of-Islands.md" >}})|Medium||||57.0%| +|0204|Count Primes|[Go]({{< relref "/ChapterFour/0200~0299/0204.Count-Primes.md" >}})|Medium||||33.1%| +|0209|Minimum Size Subarray Sum|[Go]({{< relref "/ChapterFour/0200~0299/0209.Minimum-Size-Subarray-Sum.md" >}})|Medium| O(n)| O(1)||45.0%| +|0212|Word Search II|[Go]({{< relref "/ChapterFour/0200~0299/0212.Word-Search-II.md" >}})|Hard||||36.4%| +|0213|House Robber II|[Go]({{< relref "/ChapterFour/0200~0299/0213.House-Robber-II.md" >}})|Medium||||41.0%| +|0215|Kth Largest Element in an Array|[Go]({{< relref "/ChapterFour/0200~0299/0215.Kth-Largest-Element-in-an-Array.md" >}})|Medium||||66.2%| +|0216|Combination Sum III|[Go]({{< relref "/ChapterFour/0200~0299/0216.Combination-Sum-III.md" >}})|Medium| O(n)| O(1)|❤️|67.6%| +|0217|Contains Duplicate|[Go]({{< relref "/ChapterFour/0200~0299/0217.Contains-Duplicate.md" >}})|Easy| O(n)| O(n)||61.4%| +|0218|The Skyline Problem|[Go]({{< relref "/ChapterFour/0200~0299/0218.The-Skyline-Problem.md" >}})|Hard||||41.9%| +|0219|Contains Duplicate II|[Go]({{< relref "/ChapterFour/0200~0299/0219.Contains-Duplicate-II.md" >}})|Easy| O(n)| O(n)||42.6%| +|0220|Contains Duplicate III|[Go]({{< relref "/ChapterFour/0200~0299/0220.Contains-Duplicate-III.md" >}})|Hard||||22.1%| +|0228|Summary Ranges|[Go]({{< relref "/ChapterFour/0200~0299/0228.Summary-Ranges.md" >}})|Easy||||47.2%| +|0229|Majority Element II|[Go]({{< relref "/ChapterFour/0200~0299/0229.Majority-Element-II.md" >}})|Medium||||45.1%| +|0239|Sliding Window Maximum|[Go]({{< relref "/ChapterFour/0200~0299/0239.Sliding-Window-Maximum.md" >}})|Hard||||46.3%| +|0240|Search a 2D Matrix II|[Go]({{< relref "/ChapterFour/0200~0299/0240.Search-a-2D-Matrix-II.md" >}})|Medium||||51.0%| +|0260|Single Number III|[Go]({{< relref "/ChapterFour/0200~0299/0260.Single-Number-III.md" >}})|Medium||||67.7%| +|0268|Missing Number|[Go]({{< relref "/ChapterFour/0200~0299/0268.Missing-Number.md" >}})|Easy||||62.6%| +|0274|H-Index|[Go]({{< relref "/ChapterFour/0200~0299/0274.H-Index.md" >}})|Medium||||38.3%| +|0275|H-Index II|[Go]({{< relref "/ChapterFour/0200~0299/0275.H-Index-II.md" >}})|Medium||||37.5%| +|0283|Move Zeroes|[Go]({{< relref "/ChapterFour/0200~0299/0283.Move-Zeroes.md" >}})|Easy| O(n)| O(1)||61.4%| +|0284|Peeking Iterator|[Go]({{< relref "/ChapterFour/0200~0299/0284.Peeking-Iterator.md" >}})|Medium||||58.7%| +|0287|Find the Duplicate Number|[Go]({{< relref "/ChapterFour/0200~0299/0287.Find-the-Duplicate-Number.md" >}})|Medium| O(n)| O(1)|❤️|59.1%| +|0300|Longest Increasing Subsequence|[Go]({{< relref "/ChapterFour/0300~0399/0300.Longest-Increasing-Subsequence.md" >}})|Medium||||52.2%| +|0303|Range Sum Query - Immutable|[Go]({{< relref "/ChapterFour/0300~0399/0303.Range-Sum-Query-Immutable.md" >}})|Easy||||59.5%| +|0304|Range Sum Query 2D - Immutable|[Go]({{< relref "/ChapterFour/0300~0399/0304.Range-Sum-Query-2D-Immutable.md" >}})|Medium||||52.9%| +|0307|Range Sum Query - Mutable|[Go]({{< relref "/ChapterFour/0300~0399/0307.Range-Sum-Query-Mutable.md" >}})|Medium||||40.7%| +|0309|Best Time to Buy and Sell Stock with Cooldown|[Go]({{< relref "/ChapterFour/0300~0399/0309.Best-Time-to-Buy-and-Sell-Stock-with-Cooldown.md" >}})|Medium||||56.2%| +|0315|Count of Smaller Numbers After Self|[Go]({{< relref "/ChapterFour/0300~0399/0315.Count-of-Smaller-Numbers-After-Self.md" >}})|Hard||||42.6%| +|0318|Maximum Product of Word Lengths|[Go]({{< relref "/ChapterFour/0300~0399/0318.Maximum-Product-of-Word-Lengths.md" >}})|Medium||||59.9%| +|0322|Coin Change|[Go]({{< relref "/ChapterFour/0300~0399/0322.Coin-Change.md" >}})|Medium||||42.1%| +|0324|Wiggle Sort II|[Go]({{< relref "/ChapterFour/0300~0399/0324.Wiggle-Sort-II.md" >}})|Medium||||33.3%| +|0327|Count of Range Sum|[Go]({{< relref "/ChapterFour/0300~0399/0327.Count-of-Range-Sum.md" >}})|Hard||||35.8%| +|0329|Longest Increasing Path in a Matrix|[Go]({{< relref "/ChapterFour/0300~0399/0329.Longest-Increasing-Path-in-a-Matrix.md" >}})|Hard||||52.4%| +|0347|Top K Frequent Elements|[Go]({{< relref "/ChapterFour/0300~0399/0347.Top-K-Frequent-Elements.md" >}})|Medium||||64.2%| +|0349|Intersection of Two Arrays|[Go]({{< relref "/ChapterFour/0300~0399/0349.Intersection-of-Two-Arrays.md" >}})|Easy||||70.9%| +|0350|Intersection of Two Arrays II|[Go]({{< relref "/ChapterFour/0300~0399/0350.Intersection-of-Two-Arrays-II.md" >}})|Easy||||56.0%| +|0354|Russian Doll Envelopes|[Go]({{< relref "/ChapterFour/0300~0399/0354.Russian-Doll-Envelopes.md" >}})|Hard||||37.9%| +|0368|Largest Divisible Subset|[Go]({{< relref "/ChapterFour/0300~0399/0368.Largest-Divisible-Subset.md" >}})|Medium||||41.6%| +|0373|Find K Pairs with Smallest Sums|[Go]({{< relref "/ChapterFour/0300~0399/0373.Find-K-Pairs-with-Smallest-Sums.md" >}})|Medium||||38.3%| +|0376|Wiggle Subsequence|[Go]({{< relref "/ChapterFour/0300~0399/0376.Wiggle-Subsequence.md" >}})|Medium||||48.3%| +|0377|Combination Sum IV|[Go]({{< relref "/ChapterFour/0300~0399/0377.Combination-Sum-IV.md" >}})|Medium||||52.2%| +|0378|Kth Smallest Element in a Sorted Matrix|[Go]({{< relref "/ChapterFour/0300~0399/0378.Kth-Smallest-Element-in-a-Sorted-Matrix.md" >}})|Medium||||61.8%| +|0384|Shuffle an Array|[Go]({{< relref "/ChapterFour/0300~0399/0384.Shuffle-an-Array.md" >}})|Medium||||57.8%| +|0391|Perfect Rectangle|[Go]({{< relref "/ChapterFour/0300~0399/0391.Perfect-Rectangle.md" >}})|Hard||||32.8%| +|0393|UTF-8 Validation|[Go]({{< relref "/ChapterFour/0300~0399/0393.UTF-8-Validation.md" >}})|Medium||||45.1%| +|0396|Rotate Function|[Go]({{< relref "/ChapterFour/0300~0399/0396.Rotate-Function.md" >}})|Medium||||41.1%| +|0399|Evaluate Division|[Go]({{< relref "/ChapterFour/0300~0399/0399.Evaluate-Division.md" >}})|Medium||||59.7%| +|0410|Split Array Largest Sum|[Go]({{< relref "/ChapterFour/0400~0499/0410.Split-Array-Largest-Sum.md" >}})|Hard||||53.5%| +|0413|Arithmetic Slices|[Go]({{< relref "/ChapterFour/0400~0499/0413.Arithmetic-Slices.md" >}})|Medium||||65.1%| +|0414|Third Maximum Number|[Go]({{< relref "/ChapterFour/0400~0499/0414.Third-Maximum-Number.md" >}})|Easy||||33.2%| +|0416|Partition Equal Subset Sum|[Go]({{< relref "/ChapterFour/0400~0499/0416.Partition-Equal-Subset-Sum.md" >}})|Medium||||46.3%| +|0417|Pacific Atlantic Water Flow|[Go]({{< relref "/ChapterFour/0400~0499/0417.Pacific-Atlantic-Water-Flow.md" >}})|Medium||||54.4%| +|0419|Battleships in a Board|[Go]({{< relref "/ChapterFour/0400~0499/0419.Battleships-in-a-Board.md" >}})|Medium||||74.8%| +|0421|Maximum XOR of Two Numbers in an Array|[Go]({{< relref "/ChapterFour/0400~0499/0421.Maximum-XOR-of-Two-Numbers-in-an-Array.md" >}})|Medium||||54.0%| +|0435|Non-overlapping Intervals|[Go]({{< relref "/ChapterFour/0400~0499/0435.Non-overlapping-Intervals.md" >}})|Medium||||50.3%| +|0436|Find Right Interval|[Go]({{< relref "/ChapterFour/0400~0499/0436.Find-Right-Interval.md" >}})|Medium||||50.8%| +|0447|Number of Boomerangs|[Go]({{< relref "/ChapterFour/0400~0499/0447.Number-of-Boomerangs.md" >}})|Medium||||54.9%| +|0448|Find All Numbers Disappeared in an Array|[Go]({{< relref "/ChapterFour/0400~0499/0448.Find-All-Numbers-Disappeared-in-an-Array.md" >}})|Easy||||59.9%| +|0453|Minimum Moves to Equal Array Elements|[Go]({{< relref "/ChapterFour/0400~0499/0453.Minimum-Moves-to-Equal-Array-Elements.md" >}})|Medium||||56.0%| +|0454|4Sum II|[Go]({{< relref "/ChapterFour/0400~0499/0454.4Sum-II.md" >}})|Medium||||57.2%| +|0455|Assign Cookies|[Go]({{< relref "/ChapterFour/0400~0499/0455.Assign-Cookies.md" >}})|Easy||||49.9%| +|0456|132 Pattern|[Go]({{< relref "/ChapterFour/0400~0499/0456.132-Pattern.md" >}})|Medium||||32.4%| +|0457|Circular Array Loop|[Go]({{< relref "/ChapterFour/0400~0499/0457.Circular-Array-Loop.md" >}})|Medium||||32.6%| +|0462|Minimum Moves to Equal Array Elements II|[Go]({{< relref "/ChapterFour/0400~0499/0462.Minimum-Moves-to-Equal-Array-Elements-II.md" >}})|Medium||||60.0%| +|0463|Island Perimeter|[Go]({{< relref "/ChapterFour/0400~0499/0463.Island-Perimeter.md" >}})|Easy||||69.7%| +|0473|Matchsticks to Square|[Go]({{< relref "/ChapterFour/0400~0499/0473.Matchsticks-to-Square.md" >}})|Medium||||40.2%| +|0474|Ones and Zeroes|[Go]({{< relref "/ChapterFour/0400~0499/0474.Ones-and-Zeroes.md" >}})|Medium||||46.8%| +|0475|Heaters|[Go]({{< relref "/ChapterFour/0400~0499/0475.Heaters.md" >}})|Medium||||36.5%| +|0477|Total Hamming Distance|[Go]({{< relref "/ChapterFour/0400~0499/0477.Total-Hamming-Distance.md" >}})|Medium||||52.2%| +|0480|Sliding Window Median|[Go]({{< relref "/ChapterFour/0400~0499/0480.Sliding-Window-Median.md" >}})|Hard||||41.1%| +|0485|Max Consecutive Ones|[Go]({{< relref "/ChapterFour/0400~0499/0485.Max-Consecutive-Ones.md" >}})|Easy||||56.6%| +|0491|Non-decreasing Subsequences|[Go]({{< relref "/ChapterFour/0400~0499/0491.Non-decreasing-Subsequences.md" >}})|Medium||||60.2%| +|0493|Reverse Pairs|[Go]({{< relref "/ChapterFour/0400~0499/0493.Reverse-Pairs.md" >}})|Hard||||30.9%| +|0494|Target Sum|[Go]({{< relref "/ChapterFour/0400~0499/0494.Target-Sum.md" >}})|Medium||||45.7%| +|0495|Teemo Attacking|[Go]({{< relref "/ChapterFour/0400~0499/0495.Teemo-Attacking.md" >}})|Easy||||56.8%| +|0496|Next Greater Element I|[Go]({{< relref "/ChapterFour/0400~0499/0496.Next-Greater-Element-I.md" >}})|Easy||||71.4%| +|0497|Random Point in Non-overlapping Rectangles|[Go]({{< relref "/ChapterFour/0400~0499/0497.Random-Point-in-Non-overlapping-Rectangles.md" >}})|Medium||||39.4%| +|0498|Diagonal Traverse|[Go]({{< relref "/ChapterFour/0400~0499/0498.Diagonal-Traverse.md" >}})|Medium||||58.3%| +|0500|Keyboard Row|[Go]({{< relref "/ChapterFour/0500~0599/0500.Keyboard-Row.md" >}})|Easy||||69.6%| +|0503|Next Greater Element II|[Go]({{< relref "/ChapterFour/0500~0599/0503.Next-Greater-Element-II.md" >}})|Medium||||63.2%| +|0506|Relative Ranks|[Go]({{< relref "/ChapterFour/0500~0599/0506.Relative-Ranks.md" >}})|Easy||||60.6%| +|0518|Coin Change II|[Go]({{< relref "/ChapterFour/0500~0599/0518.Coin-Change-II.md" >}})|Medium||||60.6%| +|0523|Continuous Subarray Sum|[Go]({{< relref "/ChapterFour/0500~0599/0523.Continuous-Subarray-Sum.md" >}})|Medium||||28.5%| +|0524|Longest Word in Dictionary through Deleting|[Go]({{< relref "/ChapterFour/0500~0599/0524.Longest-Word-in-Dictionary-through-Deleting.md" >}})|Medium||||51.0%| +|0525|Contiguous Array|[Go]({{< relref "/ChapterFour/0500~0599/0525.Contiguous-Array.md" >}})|Medium||||46.8%| +|0526|Beautiful Arrangement|[Go]({{< relref "/ChapterFour/0500~0599/0526.Beautiful-Arrangement.md" >}})|Medium||||64.4%| +|0528|Random Pick with Weight|[Go]({{< relref "/ChapterFour/0500~0599/0528.Random-Pick-with-Weight.md" >}})|Medium||||46.1%| +|0529|Minesweeper|[Go]({{< relref "/ChapterFour/0500~0599/0529.Minesweeper.md" >}})|Medium||||65.7%| +|0532|K-diff Pairs in an Array|[Go]({{< relref "/ChapterFour/0500~0599/0532.K-diff-Pairs-in-an-Array.md" >}})|Medium| O(n)| O(n)||41.2%| +|0540|Single Element in a Sorted Array|[Go]({{< relref "/ChapterFour/0500~0599/0540.Single-Element-in-a-Sorted-Array.md" >}})|Medium||||59.1%| +|0542|01 Matrix|[Go]({{< relref "/ChapterFour/0500~0599/0542.01-Matrix.md" >}})|Medium||||44.8%| +|0554|Brick Wall|[Go]({{< relref "/ChapterFour/0500~0599/0554.Brick-Wall.md" >}})|Medium||||53.6%| +|0560|Subarray Sum Equals K|[Go]({{< relref "/ChapterFour/0500~0599/0560.Subarray-Sum-Equals-K.md" >}})|Medium||||43.7%| +|0561|Array Partition|[Go]({{< relref "/ChapterFour/0500~0599/0561.Array-Partition.md" >}})|Easy||||77.2%| +|0566|Reshape the Matrix|[Go]({{< relref "/ChapterFour/0500~0599/0566.Reshape-the-Matrix.md" >}})|Easy| O(n^2)| O(n^2)||62.9%| +|0575|Distribute Candies|[Go]({{< relref "/ChapterFour/0500~0599/0575.Distribute-Candies.md" >}})|Easy||||66.5%| +|0581|Shortest Unsorted Continuous Subarray|[Go]({{< relref "/ChapterFour/0500~0599/0581.Shortest-Unsorted-Continuous-Subarray.md" >}})|Medium||||36.4%| +|0594|Longest Harmonious Subsequence|[Go]({{< relref "/ChapterFour/0500~0599/0594.Longest-Harmonious-Subsequence.md" >}})|Easy||||53.5%| +|0598|Range Addition II|[Go]({{< relref "/ChapterFour/0500~0599/0598.Range-Addition-II.md" >}})|Easy||||55.3%| +|0599|Minimum Index Sum of Two Lists|[Go]({{< relref "/ChapterFour/0500~0599/0599.Minimum-Index-Sum-of-Two-Lists.md" >}})|Easy||||53.4%| +|0605|Can Place Flowers|[Go]({{< relref "/ChapterFour/0600~0699/0605.Can-Place-Flowers.md" >}})|Easy||||32.8%| +|0609|Find Duplicate File in System|[Go]({{< relref "/ChapterFour/0600~0699/0609.Find-Duplicate-File-in-System.md" >}})|Medium||||67.7%| +|0611|Valid Triangle Number|[Go]({{< relref "/ChapterFour/0600~0699/0611.Valid-Triangle-Number.md" >}})|Medium||||50.6%| +|0622|Design Circular Queue|[Go]({{< relref "/ChapterFour/0600~0699/0622.Design-Circular-Queue.md" >}})|Medium||||51.5%| +|0628|Maximum Product of Three Numbers|[Go]({{< relref "/ChapterFour/0600~0699/0628.Maximum-Product-of-Three-Numbers.md" >}})|Easy| O(n)| O(1)||45.9%| +|0630|Course Schedule III|[Go]({{< relref "/ChapterFour/0600~0699/0630.Course-Schedule-III.md" >}})|Hard||||40.1%| +|0632|Smallest Range Covering Elements from K Lists|[Go]({{< relref "/ChapterFour/0600~0699/0632.Smallest-Range-Covering-Elements-from-K-Lists.md" >}})|Hard||||61.0%| +|0636|Exclusive Time of Functions|[Go]({{< relref "/ChapterFour/0600~0699/0636.Exclusive-Time-of-Functions.md" >}})|Medium||||61.2%| +|0638|Shopping Offers|[Go]({{< relref "/ChapterFour/0600~0699/0638.Shopping-Offers.md" >}})|Medium||||53.3%| +|0643|Maximum Average Subarray I|[Go]({{< relref "/ChapterFour/0600~0699/0643.Maximum-Average-Subarray-I.md" >}})|Easy||||43.7%| +|0645|Set Mismatch|[Go]({{< relref "/ChapterFour/0600~0699/0645.Set-Mismatch.md" >}})|Easy||||42.7%| +|0648|Replace Words|[Go]({{< relref "/ChapterFour/0600~0699/0648.Replace-Words.md" >}})|Medium||||62.7%| +|0658|Find K Closest Elements|[Go]({{< relref "/ChapterFour/0600~0699/0658.Find-K-Closest-Elements.md" >}})|Medium||||46.8%| +|0661|Image Smoother|[Go]({{< relref "/ChapterFour/0600~0699/0661.Image-Smoother.md" >}})|Easy||||55.4%| +|0665|Non-decreasing Array|[Go]({{< relref "/ChapterFour/0600~0699/0665.Non-decreasing-Array.md" >}})|Medium||||24.3%| +|0667|Beautiful Arrangement II|[Go]({{< relref "/ChapterFour/0600~0699/0667.Beautiful-Arrangement-II.md" >}})|Medium||||59.8%| +|0674|Longest Continuous Increasing Subsequence|[Go]({{< relref "/ChapterFour/0600~0699/0674.Longest-Continuous-Increasing-Subsequence.md" >}})|Easy||||49.3%| +|0682|Baseball Game|[Go]({{< relref "/ChapterFour/0600~0699/0682.Baseball-Game.md" >}})|Easy||||74.3%| +|0695|Max Area of Island|[Go]({{< relref "/ChapterFour/0600~0699/0695.Max-Area-of-Island.md" >}})|Medium||||71.8%| +|0697|Degree of an Array|[Go]({{< relref "/ChapterFour/0600~0699/0697.Degree-of-an-Array.md" >}})|Easy||||56.0%| +|0699|Falling Squares|[Go]({{< relref "/ChapterFour/0600~0699/0699.Falling-Squares.md" >}})|Hard||||44.7%| +|0704|Binary Search|[Go]({{< relref "/ChapterFour/0700~0799/0704.Binary-Search.md" >}})|Easy||||56.1%| +|0705|Design HashSet|[Go]({{< relref "/ChapterFour/0700~0799/0705.Design-HashSet.md" >}})|Easy||||65.6%| +|0706|Design HashMap|[Go]({{< relref "/ChapterFour/0700~0799/0706.Design-HashMap.md" >}})|Easy||||64.7%| +|0710|Random Pick with Blacklist|[Go]({{< relref "/ChapterFour/0700~0799/0710.Random-Pick-with-Blacklist.md" >}})|Hard||||33.5%| +|0713|Subarray Product Less Than K|[Go]({{< relref "/ChapterFour/0700~0799/0713.Subarray-Product-Less-Than-K.md" >}})|Medium| O(n)| O(1)||45.8%| +|0714|Best Time to Buy and Sell Stock with Transaction Fee|[Go]({{< relref "/ChapterFour/0700~0799/0714.Best-Time-to-Buy-and-Sell-Stock-with-Transaction-Fee.md" >}})|Medium| O(n)| O(1)||65.2%| +|0717|1-bit and 2-bit Characters|[Go]({{< relref "/ChapterFour/0700~0799/0717.1-bit-and-2-bit-Characters.md" >}})|Easy||||45.7%| +|0718|Maximum Length of Repeated Subarray|[Go]({{< relref "/ChapterFour/0700~0799/0718.Maximum-Length-of-Repeated-Subarray.md" >}})|Medium||||51.3%| +|0719|Find K-th Smallest Pair Distance|[Go]({{< relref "/ChapterFour/0700~0799/0719.Find-K-th-Smallest-Pair-Distance.md" >}})|Hard||||36.7%| +|0720|Longest Word in Dictionary|[Go]({{< relref "/ChapterFour/0700~0799/0720.Longest-Word-in-Dictionary.md" >}})|Medium||||52.0%| +|0721|Accounts Merge|[Go]({{< relref "/ChapterFour/0700~0799/0721.Accounts-Merge.md" >}})|Medium||||56.3%| +|0724|Find Pivot Index|[Go]({{< relref "/ChapterFour/0700~0799/0724.Find-Pivot-Index.md" >}})|Easy||||54.7%| +|0733|Flood Fill|[Go]({{< relref "/ChapterFour/0700~0799/0733.Flood-Fill.md" >}})|Easy||||62.0%| +|0735|Asteroid Collision|[Go]({{< relref "/ChapterFour/0700~0799/0735.Asteroid-Collision.md" >}})|Medium||||44.4%| +|0739|Daily Temperatures|[Go]({{< relref "/ChapterFour/0700~0799/0739.Daily-Temperatures.md" >}})|Medium||||66.3%| +|0744|Find Smallest Letter Greater Than Target|[Go]({{< relref "/ChapterFour/0700~0799/0744.Find-Smallest-Letter-Greater-Than-Target.md" >}})|Easy||||45.8%| +|0746|Min Cost Climbing Stairs|[Go]({{< relref "/ChapterFour/0700~0799/0746.Min-Cost-Climbing-Stairs.md" >}})|Easy| O(n)| O(1)||63.2%| +|0747|Largest Number At Least Twice of Others|[Go]({{< relref "/ChapterFour/0700~0799/0747.Largest-Number-At-Least-Twice-of-Others.md" >}})|Easy||||47.1%| +|0748|Shortest Completing Word|[Go]({{< relref "/ChapterFour/0700~0799/0748.Shortest-Completing-Word.md" >}})|Easy||||59.3%| +|0752|Open the Lock|[Go]({{< relref "/ChapterFour/0700~0799/0752.Open-the-Lock.md" >}})|Medium||||55.6%| +|0766|Toeplitz Matrix|[Go]({{< relref "/ChapterFour/0700~0799/0766.Toeplitz-Matrix.md" >}})|Easy| O(n)| O(1)||68.6%| +|0775|Global and Local Inversions|[Go]({{< relref "/ChapterFour/0700~0799/0775.Global-and-Local-Inversions.md" >}})|Medium||||43.3%| +|0778|Swim in Rising Water|[Go]({{< relref "/ChapterFour/0700~0799/0778.Swim-in-Rising-Water.md" >}})|Hard||||59.8%| +|0781|Rabbits in Forest|[Go]({{< relref "/ChapterFour/0700~0799/0781.Rabbits-in-Forest.md" >}})|Medium||||54.7%| +|0786|K-th Smallest Prime Fraction|[Go]({{< relref "/ChapterFour/0700~0799/0786.K-th-Smallest-Prime-Fraction.md" >}})|Medium||||51.7%| +|0794|Valid Tic-Tac-Toe State|[Go]({{< relref "/ChapterFour/0700~0799/0794.Valid-Tic-Tac-Toe-State.md" >}})|Medium||||35.1%| +|0795|Number of Subarrays with Bounded Maximum|[Go]({{< relref "/ChapterFour/0700~0799/0795.Number-of-Subarrays-with-Bounded-Maximum.md" >}})|Medium||||52.8%| +|0803|Bricks Falling When Hit|[Go]({{< relref "/ChapterFour/0800~0899/0803.Bricks-Falling-When-Hit.md" >}})|Hard||||34.4%| +|0807|Max Increase to Keep City Skyline|[Go]({{< relref "/ChapterFour/0800~0899/0807.Max-Increase-to-Keep-City-Skyline.md" >}})|Medium||||85.9%| +|0810|Chalkboard XOR Game|[Go]({{< relref "/ChapterFour/0800~0899/0810.Chalkboard-XOR-Game.md" >}})|Hard||||55.8%| +|0811|Subdomain Visit Count|[Go]({{< relref "/ChapterFour/0800~0899/0811.Subdomain-Visit-Count.md" >}})|Medium||||75.5%| +|0812|Largest Triangle Area|[Go]({{< relref "/ChapterFour/0800~0899/0812.Largest-Triangle-Area.md" >}})|Easy||||59.9%| +|0815|Bus Routes|[Go]({{< relref "/ChapterFour/0800~0899/0815.Bus-Routes.md" >}})|Hard||||45.6%| +|0817|Linked List Components|[Go]({{< relref "/ChapterFour/0800~0899/0817.Linked-List-Components.md" >}})|Medium||||57.7%| +|0820|Short Encoding of Words|[Go]({{< relref "/ChapterFour/0800~0899/0820.Short-Encoding-of-Words.md" >}})|Medium||||60.6%| +|0821|Shortest Distance to a Character|[Go]({{< relref "/ChapterFour/0800~0899/0821.Shortest-Distance-to-a-Character.md" >}})|Easy||||71.3%| +|0823|Binary Trees With Factors|[Go]({{< relref "/ChapterFour/0800~0899/0823.Binary-Trees-With-Factors.md" >}})|Medium||||49.7%| +|0825|Friends Of Appropriate Ages|[Go]({{< relref "/ChapterFour/0800~0899/0825.Friends-Of-Appropriate-Ages.md" >}})|Medium||||46.3%| +|0826|Most Profit Assigning Work|[Go]({{< relref "/ChapterFour/0800~0899/0826.Most-Profit-Assigning-Work.md" >}})|Medium||||44.9%| +|0832|Flipping an Image|[Go]({{< relref "/ChapterFour/0800~0899/0832.Flipping-an-Image.md" >}})|Easy||||80.8%| +|0839|Similar String Groups|[Go]({{< relref "/ChapterFour/0800~0899/0839.Similar-String-Groups.md" >}})|Hard||||48.0%| +|0845|Longest Mountain in Array|[Go]({{< relref "/ChapterFour/0800~0899/0845.Longest-Mountain-in-Array.md" >}})|Medium||||40.2%| +|0846|Hand of Straights|[Go]({{< relref "/ChapterFour/0800~0899/0846.Hand-of-Straights.md" >}})|Medium||||56.2%| +|0850|Rectangle Area II|[Go]({{< relref "/ChapterFour/0800~0899/0850.Rectangle-Area-II.md" >}})|Hard||||53.9%| +|0851|Loud and Rich|[Go]({{< relref "/ChapterFour/0800~0899/0851.Loud-and-Rich.md" >}})|Medium||||58.4%| +|0852|Peak Index in a Mountain Array|[Go]({{< relref "/ChapterFour/0800~0899/0852.Peak-Index-in-a-Mountain-Array.md" >}})|Medium||||69.0%| +|0853|Car Fleet|[Go]({{< relref "/ChapterFour/0800~0899/0853.Car-Fleet.md" >}})|Medium||||50.3%| +|0862|Shortest Subarray with Sum at Least K|[Go]({{< relref "/ChapterFour/0800~0899/0862.Shortest-Subarray-with-Sum-at-Least-K.md" >}})|Hard||||26.0%| +|0864|Shortest Path to Get All Keys|[Go]({{< relref "/ChapterFour/0800~0899/0864.Shortest-Path-to-Get-All-Keys.md" >}})|Hard||||45.6%| +|0867|Transpose Matrix|[Go]({{< relref "/ChapterFour/0800~0899/0867.Transpose-Matrix.md" >}})|Easy| O(n)| O(1)||64.3%| +|0870|Advantage Shuffle|[Go]({{< relref "/ChapterFour/0800~0899/0870.Advantage-Shuffle.md" >}})|Medium||||51.9%| +|0874|Walking Robot Simulation|[Go]({{< relref "/ChapterFour/0800~0899/0874.Walking-Robot-Simulation.md" >}})|Medium||||39.0%| +|0875|Koko Eating Bananas|[Go]({{< relref "/ChapterFour/0800~0899/0875.Koko-Eating-Bananas.md" >}})|Medium||||52.1%| +|0877|Stone Game|[Go]({{< relref "/ChapterFour/0800~0899/0877.Stone-Game.md" >}})|Medium||||69.7%| +|0881|Boats to Save People|[Go]({{< relref "/ChapterFour/0800~0899/0881.Boats-to-Save-People.md" >}})|Medium||||55.8%| +|0885|Spiral Matrix III|[Go]({{< relref "/ChapterFour/0800~0899/0885.Spiral-Matrix-III.md" >}})|Medium||||73.5%| +|0888|Fair Candy Swap|[Go]({{< relref "/ChapterFour/0800~0899/0888.Fair-Candy-Swap.md" >}})|Easy||||60.7%| +|0890|Find and Replace Pattern|[Go]({{< relref "/ChapterFour/0800~0899/0890.Find-and-Replace-Pattern.md" >}})|Medium||||77.6%| +|0891|Sum of Subsequence Widths|[Go]({{< relref "/ChapterFour/0800~0899/0891.Sum-of-Subsequence-Widths.md" >}})|Hard| O(n log n)| O(1)||36.7%| +|0892|Surface Area of 3D Shapes|[Go]({{< relref "/ChapterFour/0800~0899/0892.Surface-Area-of-3D-Shapes.md" >}})|Easy||||64.0%| +|0896|Monotonic Array|[Go]({{< relref "/ChapterFour/0800~0899/0896.Monotonic-Array.md" >}})|Easy||||58.4%| +|0898|Bitwise ORs of Subarrays|[Go]({{< relref "/ChapterFour/0800~0899/0898.Bitwise-ORs-of-Subarrays.md" >}})|Medium||||37.2%| +|0904|Fruit Into Baskets|[Go]({{< relref "/ChapterFour/0900~0999/0904.Fruit-Into-Baskets.md" >}})|Medium||||43.7%| +|0907|Sum of Subarray Minimums|[Go]({{< relref "/ChapterFour/0900~0999/0907.Sum-of-Subarray-Minimums.md" >}})|Medium| O(n)| O(n)|❤️|35.8%| +|0909|Snakes and Ladders|[Go]({{< relref "/ChapterFour/0900~0999/0909.Snakes-and-Ladders.md" >}})|Medium||||45.1%| +|0910|Smallest Range II|[Go]({{< relref "/ChapterFour/0900~0999/0910.Smallest-Range-II.md" >}})|Medium||||35.2%| +|0911|Online Election|[Go]({{< relref "/ChapterFour/0900~0999/0911.Online-Election.md" >}})|Medium||||52.2%| +|0914|X of a Kind in a Deck of Cards|[Go]({{< relref "/ChapterFour/0900~0999/0914.X-of-a-Kind-in-a-Deck-of-Cards.md" >}})|Easy||||31.2%| +|0916|Word Subsets|[Go]({{< relref "/ChapterFour/0900~0999/0916.Word-Subsets.md" >}})|Medium||||53.7%| +|0918|Maximum Sum Circular Subarray|[Go]({{< relref "/ChapterFour/0900~0999/0918.Maximum-Sum-Circular-Subarray.md" >}})|Medium||||43.0%| |0922|Sort Array By Parity II|[Go]({{< relref "/ChapterFour/0900~0999/0922.Sort-Array-By-Parity-II.md" >}})|Easy| O(n)| O(1)||70.7%| -|0969|Pancake Sorting|[Go]({{< relref "/ChapterFour/0900~0999/0969.Pancake-Sorting.md" >}})|Medium| O(n)| O(1)|❤️|68.8%| -|0977|Squares of a Sorted Array|[Go]({{< relref "/ChapterFour/0900~0999/0977.Squares-of-a-Sorted-Array.md" >}})|Easy| O(n)| O(1)||71.8%| -|0978|Longest Turbulent Subarray|[Go]({{< relref "/ChapterFour/0900~0999/0978.Longest-Turbulent-Subarray.md" >}})|Medium||||46.7%| -|0985|Sum of Even Numbers After Queries|[Go]({{< relref "/ChapterFour/0900~0999/0985.Sum-of-Even-Numbers-After-Queries.md" >}})|Easy||||60.6%| -|0989|Add to Array-Form of Integer|[Go]({{< relref "/ChapterFour/0900~0999/0989.Add-to-Array-Form-of-Integer.md" >}})|Easy||||44.9%| -|0999|Available Captures for Rook|[Go]({{< relref "/ChapterFour/0900~0999/0999.Available-Captures-for-Rook.md" >}})|Easy||||67.7%| -|1002|Find Common Characters|[Go]({{< relref "/ChapterFour/1000~1099/1002.Find-Common-Characters.md" >}})|Easy||||68.7%| -|1011|Capacity To Ship Packages Within D Days|[Go]({{< relref "/ChapterFour/1000~1099/1011.Capacity-To-Ship-Packages-Within-D-Days.md" >}})|Medium||||60.0%| -|1018|Binary Prefix Divisible By 5|[Go]({{< relref "/ChapterFour/1000~1099/1018.Binary-Prefix-Divisible-By-5.md" >}})|Easy||||47.7%| -|1040|Moving Stones Until Consecutive II|[Go]({{< relref "/ChapterFour/1000~1099/1040.Moving-Stones-Until-Consecutive-II.md" >}})|Medium||||54.3%| -|1051|Height Checker|[Go]({{< relref "/ChapterFour/1000~1099/1051.Height-Checker.md" >}})|Easy||||72.4%| -|1052|Grumpy Bookstore Owner|[Go]({{< relref "/ChapterFour/1000~1099/1052.Grumpy-Bookstore-Owner.md" >}})|Medium||||56.0%| -|1074|Number of Submatrices That Sum to Target|[Go]({{< relref "/ChapterFour/1000~1099/1074.Number-of-Submatrices-That-Sum-to-Target.md" >}})|Hard||||64.9%| +|0923|3Sum With Multiplicity|[Go]({{< relref "/ChapterFour/0900~0999/0923.3Sum-With-Multiplicity.md" >}})|Medium||||45.3%| +|0924|Minimize Malware Spread|[Go]({{< relref "/ChapterFour/0900~0999/0924.Minimize-Malware-Spread.md" >}})|Hard||||42.1%| +|0927|Three Equal Parts|[Go]({{< relref "/ChapterFour/0900~0999/0927.Three-Equal-Parts.md" >}})|Hard||||39.6%| +|0928|Minimize Malware Spread II|[Go]({{< relref "/ChapterFour/0900~0999/0928.Minimize-Malware-Spread-II.md" >}})|Hard||||42.8%| +|0930|Binary Subarrays With Sum|[Go]({{< relref "/ChapterFour/0900~0999/0930.Binary-Subarrays-With-Sum.md" >}})|Medium||||52.2%| +|0942|DI String Match|[Go]({{< relref "/ChapterFour/0900~0999/0942.DI-String-Match.md" >}})|Easy||||77.3%| +|0946|Validate Stack Sequences|[Go]({{< relref "/ChapterFour/0900~0999/0946.Validate-Stack-Sequences.md" >}})|Medium||||67.7%| +|0952|Largest Component Size by Common Factor|[Go]({{< relref "/ChapterFour/0900~0999/0952.Largest-Component-Size-by-Common-Factor.md" >}})|Hard||||40.0%| +|0953|Verifying an Alien Dictionary|[Go]({{< relref "/ChapterFour/0900~0999/0953.Verifying-an-Alien-Dictionary.md" >}})|Easy||||54.5%| +|0961|N-Repeated Element in Size 2N Array|[Go]({{< relref "/ChapterFour/0900~0999/0961.N-Repeated-Element-in-Size-2N-Array.md" >}})|Easy||||76.1%| +|0966|Vowel Spellchecker|[Go]({{< relref "/ChapterFour/0900~0999/0966.Vowel-Spellchecker.md" >}})|Medium||||51.4%| +|0969|Pancake Sorting|[Go]({{< relref "/ChapterFour/0900~0999/0969.Pancake-Sorting.md" >}})|Medium| O(n)| O(1)|❤️|70.1%| +|0973|K Closest Points to Origin|[Go]({{< relref "/ChapterFour/0900~0999/0973.K-Closest-Points-to-Origin.md" >}})|Medium||||65.7%| +|0976|Largest Perimeter Triangle|[Go]({{< relref "/ChapterFour/0900~0999/0976.Largest-Perimeter-Triangle.md" >}})|Easy||||54.7%| +|0977|Squares of a Sorted Array|[Go]({{< relref "/ChapterFour/0900~0999/0977.Squares-of-a-Sorted-Array.md" >}})|Easy| O(n)| O(1)||71.9%| +|0978|Longest Turbulent Subarray|[Go]({{< relref "/ChapterFour/0900~0999/0978.Longest-Turbulent-Subarray.md" >}})|Medium||||47.2%| +|0980|Unique Paths III|[Go]({{< relref "/ChapterFour/0900~0999/0980.Unique-Paths-III.md" >}})|Hard||||81.7%| +|0985|Sum of Even Numbers After Queries|[Go]({{< relref "/ChapterFour/0900~0999/0985.Sum-of-Even-Numbers-After-Queries.md" >}})|Medium||||68.1%| +|0986|Interval List Intersections|[Go]({{< relref "/ChapterFour/0900~0999/0986.Interval-List-Intersections.md" >}})|Medium||||71.3%| +|0989|Add to Array-Form of Integer|[Go]({{< relref "/ChapterFour/0900~0999/0989.Add-to-Array-Form-of-Integer.md" >}})|Easy||||47.1%| +|0990|Satisfiability of Equality Equations|[Go]({{< relref "/ChapterFour/0900~0999/0990.Satisfiability-of-Equality-Equations.md" >}})|Medium||||50.5%| +|0992|Subarrays with K Different Integers|[Go]({{< relref "/ChapterFour/0900~0999/0992.Subarrays-with-K-Different-Integers.md" >}})|Hard||||54.6%| +|0995|Minimum Number of K Consecutive Bit Flips|[Go]({{< relref "/ChapterFour/0900~0999/0995.Minimum-Number-of-K-Consecutive-Bit-Flips.md" >}})|Hard||||51.2%| +|0996|Number of Squareful Arrays|[Go]({{< relref "/ChapterFour/0900~0999/0996.Number-of-Squareful-Arrays.md" >}})|Hard||||49.2%| +|0997|Find the Town Judge|[Go]({{< relref "/ChapterFour/0900~0999/0997.Find-the-Town-Judge.md" >}})|Easy||||49.5%| +|0999|Available Captures for Rook|[Go]({{< relref "/ChapterFour/0900~0999/0999.Available-Captures-for-Rook.md" >}})|Easy||||68.2%| +|1002|Find Common Characters|[Go]({{< relref "/ChapterFour/1000~1099/1002.Find-Common-Characters.md" >}})|Easy||||68.5%| +|1004|Max Consecutive Ones III|[Go]({{< relref "/ChapterFour/1000~1099/1004.Max-Consecutive-Ones-III.md" >}})|Medium||||63.2%| +|1005|Maximize Sum Of Array After K Negations|[Go]({{< relref "/ChapterFour/1000~1099/1005.Maximize-Sum-Of-Array-After-K-Negations.md" >}})|Easy||||50.8%| +|1010|Pairs of Songs With Total Durations Divisible by 60|[Go]({{< relref "/ChapterFour/1000~1099/1010.Pairs-of-Songs-With-Total-Durations-Divisible-by-60.md" >}})|Medium||||52.8%| +|1011|Capacity To Ship Packages Within D Days|[Go]({{< relref "/ChapterFour/1000~1099/1011.Capacity-To-Ship-Packages-Within-D-Days.md" >}})|Medium||||67.7%| +|1018|Binary Prefix Divisible By 5|[Go]({{< relref "/ChapterFour/1000~1099/1018.Binary-Prefix-Divisible-By-5.md" >}})|Easy||||46.9%| +|1019|Next Greater Node In Linked List|[Go]({{< relref "/ChapterFour/1000~1099/1019.Next-Greater-Node-In-Linked-List.md" >}})|Medium||||59.9%| +|1020|Number of Enclaves|[Go]({{< relref "/ChapterFour/1000~1099/1020.Number-of-Enclaves.md" >}})|Medium||||65.6%| +|1030|Matrix Cells in Distance Order|[Go]({{< relref "/ChapterFour/1000~1099/1030.Matrix-Cells-in-Distance-Order.md" >}})|Easy||||69.7%| +|1034|Coloring A Border|[Go]({{< relref "/ChapterFour/1000~1099/1034.Coloring-A-Border.md" >}})|Medium||||49.2%| +|1037|Valid Boomerang|[Go]({{< relref "/ChapterFour/1000~1099/1037.Valid-Boomerang.md" >}})|Easy||||37.0%| +|1040|Moving Stones Until Consecutive II|[Go]({{< relref "/ChapterFour/1000~1099/1040.Moving-Stones-Until-Consecutive-II.md" >}})|Medium||||55.9%| +|1048|Longest String Chain|[Go]({{< relref "/ChapterFour/1000~1099/1048.Longest-String-Chain.md" >}})|Medium||||59.3%| +|1049|Last Stone Weight II|[Go]({{< relref "/ChapterFour/1000~1099/1049.Last-Stone-Weight-II.md" >}})|Medium||||53.2%| +|1051|Height Checker|[Go]({{< relref "/ChapterFour/1000~1099/1051.Height-Checker.md" >}})|Easy||||75.6%| +|1052|Grumpy Bookstore Owner|[Go]({{< relref "/ChapterFour/1000~1099/1052.Grumpy-Bookstore-Owner.md" >}})|Medium||||57.1%| +|1054|Distant Barcodes|[Go]({{< relref "/ChapterFour/1000~1099/1054.Distant-Barcodes.md" >}})|Medium||||45.9%| +|1073|Adding Two Negabinary Numbers|[Go]({{< relref "/ChapterFour/1000~1099/1073.Adding-Two-Negabinary-Numbers.md" >}})|Medium||||36.5%| +|1074|Number of Submatrices That Sum to Target|[Go]({{< relref "/ChapterFour/1000~1099/1074.Number-of-Submatrices-That-Sum-to-Target.md" >}})|Hard||||69.5%| |1089|Duplicate Zeros|[Go]({{< relref "/ChapterFour/1000~1099/1089.Duplicate-Zeros.md" >}})|Easy||||51.5%| -|1122|Relative Sort Array|[Go]({{< relref "/ChapterFour/1100~1199/1122.Relative-Sort-Array.md" >}})|Easy||||68.1%| -|1128|Number of Equivalent Domino Pairs|[Go]({{< relref "/ChapterFour/1100~1199/1128.Number-of-Equivalent-Domino-Pairs.md" >}})|Easy||||46.3%| -|1157|Online Majority Element In Subarray|[Go]({{< relref "/ChapterFour/1100~1199/1157.Online-Majority-Element-In-Subarray.md" >}})|Hard||||41.0%| -|1160|Find Words That Can Be Formed by Characters|[Go]({{< relref "/ChapterFour/1100~1199/1160.Find-Words-That-Can-Be-Formed-by-Characters.md" >}})|Easy||||67.9%| -|1170|Compare Strings by Frequency of the Smallest Character|[Go]({{< relref "/ChapterFour/1100~1199/1170.Compare-Strings-by-Frequency-of-the-Smallest-Character.md" >}})|Medium||||60.4%| -|1184|Distance Between Bus Stops|[Go]({{< relref "/ChapterFour/1100~1199/1184.Distance-Between-Bus-Stops.md" >}})|Easy||||53.9%| -|1185|Day of the Week|[Go]({{< relref "/ChapterFour/1100~1199/1185.Day-of-the-Week.md" >}})|Easy||||61.0%| -|1200|Minimum Absolute Difference|[Go]({{< relref "/ChapterFour/1200~1299/1200.Minimum-Absolute-Difference.md" >}})|Easy||||67.1%| -|1202|Smallest String With Swaps|[Go]({{< relref "/ChapterFour/1200~1299/1202.Smallest-String-With-Swaps.md" >}})|Medium||||49.1%| -|1208|Get Equal Substrings Within Budget|[Go]({{< relref "/ChapterFour/1200~1299/1208.Get-Equal-Substrings-Within-Budget.md" >}})|Medium||||44.4%| -|1217|Minimum Cost to Move Chips to The Same Position|[Go]({{< relref "/ChapterFour/1200~1299/1217.Minimum-Cost-to-Move-Chips-to-The-Same-Position.md" >}})|Easy||||70.9%| -|1232|Check If It Is a Straight Line|[Go]({{< relref "/ChapterFour/1200~1299/1232.Check-If-It-Is-a-Straight-Line.md" >}})|Easy||||43.1%| -|1252|Cells with Odd Values in a Matrix|[Go]({{< relref "/ChapterFour/1200~1299/1252.Cells-with-Odd-Values-in-a-Matrix.md" >}})|Easy||||78.6%| -|1260|Shift 2D Grid|[Go]({{< relref "/ChapterFour/1200~1299/1260.Shift-2D-Grid.md" >}})|Easy||||61.8%| -|1266|Minimum Time Visiting All Points|[Go]({{< relref "/ChapterFour/1200~1299/1266.Minimum-Time-Visiting-All-Points.md" >}})|Easy||||79.3%| -|1275|Find Winner on a Tic Tac Toe Game|[Go]({{< relref "/ChapterFour/1200~1299/1275.Find-Winner-on-a-Tic-Tac-Toe-Game.md" >}})|Easy||||52.9%| -|1287|Element Appearing More Than 25% In Sorted Array|[Go]({{< relref "/ChapterFour/1200~1299/1287.Element-Appearing-More-Than-25-In-Sorted-Array.md" >}})|Easy||||60.3%| -|1295|Find Numbers with Even Number of Digits|[Go]({{< relref "/ChapterFour/1200~1299/1295.Find-Numbers-with-Even-Number-of-Digits.md" >}})|Easy||||78.7%| -|1299|Replace Elements with Greatest Element on Right Side|[Go]({{< relref "/ChapterFour/1200~1299/1299.Replace-Elements-with-Greatest-Element-on-Right-Side.md" >}})|Easy||||74.6%| -|1300|Sum of Mutated Array Closest to Target|[Go]({{< relref "/ChapterFour/1300~1399/1300.Sum-of-Mutated-Array-Closest-to-Target.md" >}})|Medium||||43.0%| -|1304|Find N Unique Integers Sum up to Zero|[Go]({{< relref "/ChapterFour/1300~1399/1304.Find-N-Unique-Integers-Sum-up-to-Zero.md" >}})|Easy||||76.7%| -|1313|Decompress Run-Length Encoded List|[Go]({{< relref "/ChapterFour/1300~1399/1313.Decompress-Run-Length-Encoded-List.md" >}})|Easy||||85.4%| -|1329|Sort the Matrix Diagonally|[Go]({{< relref "/ChapterFour/1300~1399/1329.Sort-the-Matrix-Diagonally.md" >}})|Medium||||81.6%| -|1337|The K Weakest Rows in a Matrix|[Go]({{< relref "/ChapterFour/1300~1399/1337.The-K-Weakest-Rows-in-a-Matrix.md" >}})|Easy||||72.0%| -|1380|Lucky Numbers in a Matrix|[Go]({{< relref "/ChapterFour/1300~1399/1380.Lucky-Numbers-in-a-Matrix.md" >}})|Easy||||70.4%| -|1385|Find the Distance Value Between Two Arrays|[Go]({{< relref "/ChapterFour/1300~1399/1385.Find-the-Distance-Value-Between-Two-Arrays.md" >}})|Easy||||66.5%| -|1389|Create Target Array in the Given Order|[Go]({{< relref "/ChapterFour/1300~1399/1389.Create-Target-Array-in-the-Given-Order.md" >}})|Easy||||84.9%| -|1423|Maximum Points You Can Obtain from Cards|[Go]({{< relref "/ChapterFour/1400~1499/1423.Maximum-Points-You-Can-Obtain-from-Cards.md" >}})|Medium||||47.0%| -|1437|Check If All 1's Are at Least Length K Places Away|[Go]({{< relref "/ChapterFour/1400~1499/1437.Check-If-All-1s-Are-at-Least-Length-K-Places-Away.md" >}})|Easy||||61.8%| -|1438|Longest Continuous Subarray With Absolute Diff Less Than or Equal to Limit|[Go]({{< relref "/ChapterFour/1400~1499/1438.Longest-Continuous-Subarray-With-Absolute-Diff-Less-Than-or-Equal-to-Limit.md" >}})|Medium||||44.5%| -|1464|Maximum Product of Two Elements in an Array|[Go]({{< relref "/ChapterFour/1400~1499/1464.Maximum-Product-of-Two-Elements-in-an-Array.md" >}})|Easy||||77.1%| -|1470|Shuffle the Array|[Go]({{< relref "/ChapterFour/1400~1499/1470.Shuffle-the-Array.md" >}})|Easy||||88.1%| -|1480|Running Sum of 1d Array|[Go]({{< relref "/ChapterFour/1400~1499/1480.Running-Sum-of-1d-Array.md" >}})|Easy||||88.5%| -|1512|Number of Good Pairs|[Go]({{< relref "/ChapterFour/1500~1599/1512.Number-of-Good-Pairs.md" >}})|Easy||||87.6%| -|1539|Kth Missing Positive Number|[Go]({{< relref "/ChapterFour/1500~1599/1539.Kth-Missing-Positive-Number.md" >}})|Easy||||54.8%| -|1608|Special Array With X Elements Greater Than or Equal X|[Go]({{< relref "/ChapterFour/1600~1699/1608.Special-Array-With-X-Elements-Greater-Than-or-Equal-X.md" >}})|Easy||||61.4%| -|1619|Mean of Array After Removing Some Elements|[Go]({{< relref "/ChapterFour/1600~1699/1619.Mean-of-Array-After-Removing-Some-Elements.md" >}})|Easy||||64.5%| +|1091|Shortest Path in Binary Matrix|[Go]({{< relref "/ChapterFour/1000~1099/1091.Shortest-Path-in-Binary-Matrix.md" >}})|Medium||||44.7%| +|1093|Statistics from a Large Sample|[Go]({{< relref "/ChapterFour/1000~1099/1093.Statistics-from-a-Large-Sample.md" >}})|Medium||||43.5%| +|1105|Filling Bookcase Shelves|[Go]({{< relref "/ChapterFour/1100~1199/1105.Filling-Bookcase-Shelves.md" >}})|Medium||||59.3%| +|1122|Relative Sort Array|[Go]({{< relref "/ChapterFour/1100~1199/1122.Relative-Sort-Array.md" >}})|Easy||||68.6%| +|1128|Number of Equivalent Domino Pairs|[Go]({{< relref "/ChapterFour/1100~1199/1128.Number-of-Equivalent-Domino-Pairs.md" >}})|Easy||||47.1%| +|1157|Online Majority Element In Subarray|[Go]({{< relref "/ChapterFour/1100~1199/1157.Online-Majority-Element-In-Subarray.md" >}})|Hard||||41.8%| +|1160|Find Words That Can Be Formed by Characters|[Go]({{< relref "/ChapterFour/1100~1199/1160.Find-Words-That-Can-Be-Formed-by-Characters.md" >}})|Easy||||67.5%| +|1170|Compare Strings by Frequency of the Smallest Character|[Go]({{< relref "/ChapterFour/1100~1199/1170.Compare-Strings-by-Frequency-of-the-Smallest-Character.md" >}})|Medium||||61.5%| +|1178|Number of Valid Words for Each Puzzle|[Go]({{< relref "/ChapterFour/1100~1199/1178.Number-of-Valid-Words-for-Each-Puzzle.md" >}})|Hard||||46.3%| +|1184|Distance Between Bus Stops|[Go]({{< relref "/ChapterFour/1100~1199/1184.Distance-Between-Bus-Stops.md" >}})|Easy||||54.0%| +|1200|Minimum Absolute Difference|[Go]({{< relref "/ChapterFour/1200~1299/1200.Minimum-Absolute-Difference.md" >}})|Easy||||69.6%| +|1207|Unique Number of Occurrences|[Go]({{< relref "/ChapterFour/1200~1299/1207.Unique-Number-of-Occurrences.md" >}})|Easy||||73.5%| +|1217|Minimum Cost to Move Chips to The Same Position|[Go]({{< relref "/ChapterFour/1200~1299/1217.Minimum-Cost-to-Move-Chips-to-The-Same-Position.md" >}})|Easy||||71.9%| +|1232|Check If It Is a Straight Line|[Go]({{< relref "/ChapterFour/1200~1299/1232.Check-If-It-Is-a-Straight-Line.md" >}})|Easy||||40.3%| +|1235|Maximum Profit in Job Scheduling|[Go]({{< relref "/ChapterFour/1200~1299/1235.Maximum-Profit-in-Job-Scheduling.md" >}})|Hard||||53.4%| +|1239|Maximum Length of a Concatenated String with Unique Characters|[Go]({{< relref "/ChapterFour/1200~1299/1239.Maximum-Length-of-a-Concatenated-String-with-Unique-Characters.md" >}})|Medium||||52.2%| +|1252|Cells with Odd Values in a Matrix|[Go]({{< relref "/ChapterFour/1200~1299/1252.Cells-with-Odd-Values-in-a-Matrix.md" >}})|Easy||||78.5%| +|1254|Number of Closed Islands|[Go]({{< relref "/ChapterFour/1200~1299/1254.Number-of-Closed-Islands.md" >}})|Medium||||66.9%| +|1260|Shift 2D Grid|[Go]({{< relref "/ChapterFour/1200~1299/1260.Shift-2D-Grid.md" >}})|Easy||||67.8%| +|1266|Minimum Time Visiting All Points|[Go]({{< relref "/ChapterFour/1200~1299/1266.Minimum-Time-Visiting-All-Points.md" >}})|Easy||||79.1%| +|1268|Search Suggestions System|[Go]({{< relref "/ChapterFour/1200~1299/1268.Search-Suggestions-System.md" >}})|Medium||||66.2%| +|1275|Find Winner on a Tic Tac Toe Game|[Go]({{< relref "/ChapterFour/1200~1299/1275.Find-Winner-on-a-Tic-Tac-Toe-Game.md" >}})|Easy||||54.2%| +|1283|Find the Smallest Divisor Given a Threshold|[Go]({{< relref "/ChapterFour/1200~1299/1283.Find-the-Smallest-Divisor-Given-a-Threshold.md" >}})|Medium||||56.2%| +|1287|Element Appearing More Than 25% In Sorted Array|[Go]({{< relref "/ChapterFour/1200~1299/1287.Element-Appearing-More-Than-25-In-Sorted-Array.md" >}})|Easy||||59.4%| +|1293|Shortest Path in a Grid with Obstacles Elimination|[Go]({{< relref "/ChapterFour/1200~1299/1293.Shortest-Path-in-a-Grid-with-Obstacles-Elimination.md" >}})|Hard||||45.3%| +|1295|Find Numbers with Even Number of Digits|[Go]({{< relref "/ChapterFour/1200~1299/1295.Find-Numbers-with-Even-Number-of-Digits.md" >}})|Easy||||77.0%| +|1296|Divide Array in Sets of K Consecutive Numbers|[Go]({{< relref "/ChapterFour/1200~1299/1296.Divide-Array-in-Sets-of-K-Consecutive-Numbers.md" >}})|Medium||||56.5%| +|1299|Replace Elements with Greatest Element on Right Side|[Go]({{< relref "/ChapterFour/1200~1299/1299.Replace-Elements-with-Greatest-Element-on-Right-Side.md" >}})|Easy||||73.3%| +|1300|Sum of Mutated Array Closest to Target|[Go]({{< relref "/ChapterFour/1300~1399/1300.Sum-of-Mutated-Array-Closest-to-Target.md" >}})|Medium||||43.6%| +|1304|Find N Unique Integers Sum up to Zero|[Go]({{< relref "/ChapterFour/1300~1399/1304.Find-N-Unique-Integers-Sum-up-to-Zero.md" >}})|Easy||||76.9%| +|1306|Jump Game III|[Go]({{< relref "/ChapterFour/1300~1399/1306.Jump-Game-III.md" >}})|Medium||||63.5%| +|1310|XOR Queries of a Subarray|[Go]({{< relref "/ChapterFour/1300~1399/1310.XOR-Queries-of-a-Subarray.md" >}})|Medium||||72.3%| +|1313|Decompress Run-Length Encoded List|[Go]({{< relref "/ChapterFour/1300~1399/1313.Decompress-Run-Length-Encoded-List.md" >}})|Easy||||85.8%| +|1329|Sort the Matrix Diagonally|[Go]({{< relref "/ChapterFour/1300~1399/1329.Sort-the-Matrix-Diagonally.md" >}})|Medium||||83.3%| +|1337|The K Weakest Rows in a Matrix|[Go]({{< relref "/ChapterFour/1300~1399/1337.The-K-Weakest-Rows-in-a-Matrix.md" >}})|Easy||||72.1%| +|1353|Maximum Number of Events That Can Be Attended|[Go]({{< relref "/ChapterFour/1300~1399/1353.Maximum-Number-of-Events-That-Can-Be-Attended.md" >}})|Medium||||32.5%| +|1380|Lucky Numbers in a Matrix|[Go]({{< relref "/ChapterFour/1300~1399/1380.Lucky-Numbers-in-a-Matrix.md" >}})|Easy||||70.7%| +|1383|Maximum Performance of a Team|[Go]({{< relref "/ChapterFour/1300~1399/1383.Maximum-Performance-of-a-Team.md" >}})|Hard||||48.5%| +|1385|Find the Distance Value Between Two Arrays|[Go]({{< relref "/ChapterFour/1300~1399/1385.Find-the-Distance-Value-Between-Two-Arrays.md" >}})|Easy||||66.6%| +|1389|Create Target Array in the Given Order|[Go]({{< relref "/ChapterFour/1300~1399/1389.Create-Target-Array-in-the-Given-Order.md" >}})|Easy||||85.8%| +|1423|Maximum Points You Can Obtain from Cards|[Go]({{< relref "/ChapterFour/1400~1499/1423.Maximum-Points-You-Can-Obtain-from-Cards.md" >}})|Medium||||52.2%| +|1437|Check If All 1's Are at Least Length K Places Away|[Go]({{< relref "/ChapterFour/1400~1499/1437.Check-If-All-1s-Are-at-Least-Length-K-Places-Away.md" >}})|Easy||||58.7%| +|1438|Longest Continuous Subarray With Absolute Diff Less Than or Equal to Limit|[Go]({{< relref "/ChapterFour/1400~1499/1438.Longest-Continuous-Subarray-With-Absolute-Diff-Less-Than-or-Equal-to-Limit.md" >}})|Medium||||48.3%| +|1439|Find the Kth Smallest Sum of a Matrix With Sorted Rows|[Go]({{< relref "/ChapterFour/1400~1499/1439.Find-the-Kth-Smallest-Sum-of-a-Matrix-With-Sorted-Rows.md" >}})|Hard||||61.4%| +|1442|Count Triplets That Can Form Two Arrays of Equal XOR|[Go]({{< relref "/ChapterFour/1400~1499/1442.Count-Triplets-That-Can-Form-Two-Arrays-of-Equal-XOR.md" >}})|Medium||||76.1%| +|1463|Cherry Pickup II|[Go]({{< relref "/ChapterFour/1400~1499/1463.Cherry-Pickup-II.md" >}})|Hard||||69.5%| +|1464|Maximum Product of Two Elements in an Array|[Go]({{< relref "/ChapterFour/1400~1499/1464.Maximum-Product-of-Two-Elements-in-an-Array.md" >}})|Easy||||80.0%| +|1465|Maximum Area of a Piece of Cake After Horizontal and Vertical Cuts|[Go]({{< relref "/ChapterFour/1400~1499/1465.Maximum-Area-of-a-Piece-of-Cake-After-Horizontal-and-Vertical-Cuts.md" >}})|Medium||||40.9%| +|1470|Shuffle the Array|[Go]({{< relref "/ChapterFour/1400~1499/1470.Shuffle-the-Array.md" >}})|Easy||||89.0%| +|1480|Running Sum of 1d Array|[Go]({{< relref "/ChapterFour/1400~1499/1480.Running-Sum-of-1d-Array.md" >}})|Easy||||87.4%| +|1482|Minimum Number of Days to Make m Bouquets|[Go]({{< relref "/ChapterFour/1400~1499/1482.Minimum-Number-of-Days-to-Make-m-Bouquets.md" >}})|Medium||||54.0%| +|1512|Number of Good Pairs|[Go]({{< relref "/ChapterFour/1500~1599/1512.Number-of-Good-Pairs.md" >}})|Easy||||88.2%| +|1539|Kth Missing Positive Number|[Go]({{< relref "/ChapterFour/1500~1599/1539.Kth-Missing-Positive-Number.md" >}})|Easy||||58.6%| +|1572|Matrix Diagonal Sum|[Go]({{< relref "/ChapterFour/1500~1599/1572.Matrix-Diagonal-Sum.md" >}})|Easy||||80.3%| +|1608|Special Array With X Elements Greater Than or Equal X|[Go]({{< relref "/ChapterFour/1600~1699/1608.Special-Array-With-X-Elements-Greater-Than-or-Equal-X.md" >}})|Easy||||60.5%| +|1619|Mean of Array After Removing Some Elements|[Go]({{< relref "/ChapterFour/1600~1699/1619.Mean-of-Array-After-Removing-Some-Elements.md" >}})|Easy||||65.8%| |1629|Slowest Key|[Go]({{< relref "/ChapterFour/1600~1699/1629.Slowest-Key.md" >}})|Easy||||59.2%| -|1636|Sort Array by Increasing Frequency|[Go]({{< relref "/ChapterFour/1600~1699/1636.Sort-Array-by-Increasing-Frequency.md" >}})|Easy||||67.0%| -|1640|Check Array Formation Through Concatenation|[Go]({{< relref "/ChapterFour/1600~1699/1640.Check-Array-Formation-Through-Concatenation.md" >}})|Easy||||59.7%| -|1646|Get Maximum in Generated Array|[Go]({{< relref "/ChapterFour/1600~1699/1646.Get-Maximum-in-Generated-Array.md" >}})|Easy||||53.1%| -|1652|Defuse the Bomb|[Go]({{< relref "/ChapterFour/1600~1699/1652.Defuse-the-Bomb.md" >}})|Easy||||61.6%| -|1656|Design an Ordered Stream|[Go]({{< relref "/ChapterFour/1600~1699/1656.Design-an-Ordered-Stream.md" >}})|Easy||||81.9%| -|1672|Richest Customer Wealth|[Go]({{< relref "/ChapterFour/1600~1699/1672.Richest-Customer-Wealth.md" >}})|Easy||||88.2%| -|1700|Number of Students Unable to Eat Lunch|[Go]({{< relref "/ChapterFour/1700~1799/1700.Number-of-Students-Unable-to-Eat-Lunch.md" >}})|Easy||||67.6%| -|1732|Find the Highest Altitude|[Go]({{< relref "/ChapterFour/1700~1799/1732.Find-the-Highest-Altitude.md" >}})|Easy||||79.7%| -|1742|Maximum Number of Balls in a Box|[Go]({{< relref "/ChapterFour/1700~1799/1742.Maximum-Number-of-Balls-in-a-Box.md" >}})|Easy||||73.5%| -|1748|Sum of Unique Elements|[Go]({{< relref "/ChapterFour/1700~1799/1748.Sum-of-Unique-Elements.md" >}})|Easy||||74.7%| -|1752|Check if Array Is Sorted and Rotated|[Go]({{< relref "/ChapterFour/1700~1799/1752.Check-if-Array-Is-Sorted-and-Rotated.md" >}})|Easy||||60.0%| -|1758|Minimum Changes To Make Alternating Binary String|[Go]({{< relref "/ChapterFour/1700~1799/1758.Minimum-Changes-To-Make-Alternating-Binary-String.md" >}})|Easy||||58.0%| +|1631|Path With Minimum Effort|[Go]({{< relref "/ChapterFour/1600~1699/1631.Path-With-Minimum-Effort.md" >}})|Medium||||55.7%| +|1636|Sort Array by Increasing Frequency|[Go]({{< relref "/ChapterFour/1600~1699/1636.Sort-Array-by-Increasing-Frequency.md" >}})|Easy||||69.5%| +|1640|Check Array Formation Through Concatenation|[Go]({{< relref "/ChapterFour/1600~1699/1640.Check-Array-Formation-Through-Concatenation.md" >}})|Easy||||56.2%| +|1642|Furthest Building You Can Reach|[Go]({{< relref "/ChapterFour/1600~1699/1642.Furthest-Building-You-Can-Reach.md" >}})|Medium||||48.3%| +|1646|Get Maximum in Generated Array|[Go]({{< relref "/ChapterFour/1600~1699/1646.Get-Maximum-in-Generated-Array.md" >}})|Easy||||50.2%| +|1648|Sell Diminishing-Valued Colored Balls|[Go]({{< relref "/ChapterFour/1600~1699/1648.Sell-Diminishing-Valued-Colored-Balls.md" >}})|Medium||||30.4%| +|1649|Create Sorted Array through Instructions|[Go]({{< relref "/ChapterFour/1600~1699/1649.Create-Sorted-Array-through-Instructions.md" >}})|Hard||||37.5%| +|1652|Defuse the Bomb|[Go]({{< relref "/ChapterFour/1600~1699/1652.Defuse-the-Bomb.md" >}})|Easy||||62.4%| +|1654|Minimum Jumps to Reach Home|[Go]({{< relref "/ChapterFour/1600~1699/1654.Minimum-Jumps-to-Reach-Home.md" >}})|Medium||||29.1%| +|1655|Distribute Repeating Integers|[Go]({{< relref "/ChapterFour/1600~1699/1655.Distribute-Repeating-Integers.md" >}})|Hard||||39.3%| +|1656|Design an Ordered Stream|[Go]({{< relref "/ChapterFour/1600~1699/1656.Design-an-Ordered-Stream.md" >}})|Easy||||85.2%| +|1658|Minimum Operations to Reduce X to Zero|[Go]({{< relref "/ChapterFour/1600~1699/1658.Minimum-Operations-to-Reduce-X-to-Zero.md" >}})|Medium||||37.6%| +|1662|Check If Two String Arrays are Equivalent|[Go]({{< relref "/ChapterFour/1600~1699/1662.Check-If-Two-String-Arrays-are-Equivalent.md" >}})|Easy||||83.5%| +|1664|Ways to Make a Fair Array|[Go]({{< relref "/ChapterFour/1600~1699/1664.Ways-to-Make-a-Fair-Array.md" >}})|Medium||||63.3%| +|1665|Minimum Initial Energy to Finish Tasks|[Go]({{< relref "/ChapterFour/1600~1699/1665.Minimum-Initial-Energy-to-Finish-Tasks.md" >}})|Hard||||56.4%| +|1670|Design Front Middle Back Queue|[Go]({{< relref "/ChapterFour/1600~1699/1670.Design-Front-Middle-Back-Queue.md" >}})|Medium||||57.2%| +|1672|Richest Customer Wealth|[Go]({{< relref "/ChapterFour/1600~1699/1672.Richest-Customer-Wealth.md" >}})|Easy||||87.9%| +|1673|Find the Most Competitive Subsequence|[Go]({{< relref "/ChapterFour/1600~1699/1673.Find-the-Most-Competitive-Subsequence.md" >}})|Medium||||49.3%| +|1674|Minimum Moves to Make Array Complementary|[Go]({{< relref "/ChapterFour/1600~1699/1674.Minimum-Moves-to-Make-Array-Complementary.md" >}})|Medium||||38.7%| +|1675|Minimize Deviation in Array|[Go]({{< relref "/ChapterFour/1600~1699/1675.Minimize-Deviation-in-Array.md" >}})|Hard||||54.6%| +|1679|Max Number of K-Sum Pairs|[Go]({{< relref "/ChapterFour/1600~1699/1679.Max-Number-of-K-Sum-Pairs.md" >}})|Medium||||57.3%| +|1681|Minimum Incompatibility|[Go]({{< relref "/ChapterFour/1600~1699/1681.Minimum-Incompatibility.md" >}})|Hard||||37.8%| +|1684|Count the Number of Consistent Strings|[Go]({{< relref "/ChapterFour/1600~1699/1684.Count-the-Number-of-Consistent-Strings.md" >}})|Easy||||82.3%| +|1685|Sum of Absolute Differences in a Sorted Array|[Go]({{< relref "/ChapterFour/1600~1699/1685.Sum-of-Absolute-Differences-in-a-Sorted-Array.md" >}})|Medium||||63.5%| +|1690|Stone Game VII|[Go]({{< relref "/ChapterFour/1600~1699/1690.Stone-Game-VII.md" >}})|Medium||||58.1%| +|1691|Maximum Height by Stacking Cuboids|[Go]({{< relref "/ChapterFour/1600~1699/1691.Maximum-Height-by-Stacking-Cuboids.md" >}})|Hard||||54.6%| +|1695|Maximum Erasure Value|[Go]({{< relref "/ChapterFour/1600~1699/1695.Maximum-Erasure-Value.md" >}})|Medium||||57.6%| +|1696|Jump Game VI|[Go]({{< relref "/ChapterFour/1600~1699/1696.Jump-Game-VI.md" >}})|Medium||||46.1%| +|1700|Number of Students Unable to Eat Lunch|[Go]({{< relref "/ChapterFour/1700~1799/1700.Number-of-Students-Unable-to-Eat-Lunch.md" >}})|Easy||||68.8%| +|1705|Maximum Number of Eaten Apples|[Go]({{< relref "/ChapterFour/1700~1799/1705.Maximum-Number-of-Eaten-Apples.md" >}})|Medium||||38.0%| +|1710|Maximum Units on a Truck|[Go]({{< relref "/ChapterFour/1700~1799/1710.Maximum-Units-on-a-Truck.md" >}})|Easy||||73.8%| +|1720|Decode XORed Array|[Go]({{< relref "/ChapterFour/1700~1799/1720.Decode-XORed-Array.md" >}})|Easy||||85.8%| +|1725|Number Of Rectangles That Can Form The Largest Square|[Go]({{< relref "/ChapterFour/1700~1799/1725.Number-Of-Rectangles-That-Can-Form-The-Largest-Square.md" >}})|Easy||||78.6%| +|1732|Find the Highest Altitude|[Go]({{< relref "/ChapterFour/1700~1799/1732.Find-the-Highest-Altitude.md" >}})|Easy||||78.9%| +|1734|Decode XORed Permutation|[Go]({{< relref "/ChapterFour/1700~1799/1734.Decode-XORed-Permutation.md" >}})|Medium||||63.0%| +|1738|Find Kth Largest XOR Coordinate Value|[Go]({{< relref "/ChapterFour/1700~1799/1738.Find-Kth-Largest-XOR-Coordinate-Value.md" >}})|Medium||||61.0%| +|1744|Can You Eat Your Favorite Candy on Your Favorite Day?|[Go]({{< relref "/ChapterFour/1700~1799/1744.Can-You-Eat-Your-Favorite-Candy-on-Your-Favorite-Day.md" >}})|Medium||||33.1%| +|1748|Sum of Unique Elements|[Go]({{< relref "/ChapterFour/1700~1799/1748.Sum-of-Unique-Elements.md" >}})|Easy||||76.3%| +|1752|Check if Array Is Sorted and Rotated|[Go]({{< relref "/ChapterFour/1700~1799/1752.Check-if-Array-Is-Sorted-and-Rotated.md" >}})|Easy||||50.1%| +|1816|Truncate Sentence|[Go]({{< relref "/ChapterFour/1800~1899/1816.Truncate-Sentence.md" >}})|Easy||||83.1%| +|1818|Minimum Absolute Sum Difference|[Go]({{< relref "/ChapterFour/1800~1899/1818.Minimum-Absolute-Sum-Difference.md" >}})|Medium||||30.4%| +|1846|Maximum Element After Decreasing and Rearranging|[Go]({{< relref "/ChapterFour/1800~1899/1846.Maximum-Element-After-Decreasing-and-Rearranging.md" >}})|Medium||||58.9%| +|1877|Minimize Maximum Pair Sum in Array|[Go]({{< relref "/ChapterFour/1800~1899/1877.Minimize-Maximum-Pair-Sum-in-Array.md" >}})|Medium||||79.9%| +|1984|Minimum Difference Between Highest and Lowest of K Scores|[Go]({{< relref "/ChapterFour/1900~1999/1984.Minimum-Difference-Between-Highest-and-Lowest-of-K-Scores.md" >}})|Easy||||54.5%| +|2021|Brightest Position on Street|[Go]({{< relref "/ChapterFour/2000~2099/2021.Brightest-Position-on-Street.md" >}})|Medium||||62.1%| +|2022|Convert 1D Array Into 2D Array|[Go]({{< relref "/ChapterFour/2000~2099/2022.Convert-1D-Array-Into-2D-Array.md" >}})|Easy||||59.1%| +|2037|Minimum Number of Moves to Seat Everyone|[Go]({{< relref "/ChapterFour/2000~2099/2037.Minimum-Number-of-Moves-to-Seat-Everyone.md" >}})|Easy||||82.1%| +|2043|Simple Bank System|[Go]({{< relref "/ChapterFour/2000~2099/2043.Simple-Bank-System.md" >}})|Medium||||65.2%| +|2164|Sort Even and Odd Indices Independently|[Go]({{< relref "/ChapterFour/2100~2199/2164.Sort-Even-and-Odd-Indices-Independently.md" >}})|Easy||||64.9%| +|2166|Design Bitset|[Go]({{< relref "/ChapterFour/2100~2199/2166.Design-Bitset.md" >}})|Medium||||31.8%| +|2170|Minimum Operations to Make the Array Alternating|[Go]({{< relref "/ChapterFour/2100~2199/2170.Minimum-Operations-to-Make-the-Array-Alternating.md" >}})|Medium||||33.2%| +|2171|Removing Minimum Number of Magic Beans|[Go]({{< relref "/ChapterFour/2100~2199/2171.Removing-Minimum-Number-of-Magic-Beans.md" >}})|Medium||||42.1%| +|2183|Count Array Pairs Divisible by K|[Go]({{< relref "/ChapterFour/2100~2199/2183.Count-Array-Pairs-Divisible-by-K.md" >}})|Hard||||28.3%| |------------|-------------------------------------------------------|-------| ----------------| ---------------|-------------|-------------|-------------| diff --git a/website/content/ChapterTwo/Backtracking.md b/website/content/ChapterTwo/Backtracking.md index 72cf31da0..fd1b61831 100644 --- a/website/content/ChapterTwo/Backtracking.md +++ b/website/content/ChapterTwo/Backtracking.md @@ -100,41 +100,45 @@ func updateMatrix_BFS(matrix [][]int) [][]int { | No. | Title | Solution | Difficulty | TimeComplexity | SpaceComplexity |Favorite| Acceptance | |:--------:|:------- | :--------: | :----------: | :----: | :-----: | :-----: |:-----: | -|0017|Letter Combinations of a Phone Number|[Go]({{< relref "/ChapterFour/0001~0099/0017.Letter-Combinations-of-a-Phone-Number.md" >}})|Medium| O(log n)| O(1)||50.0%| -|0022|Generate Parentheses|[Go]({{< relref "/ChapterFour/0001~0099/0022.Generate-Parentheses.md" >}})|Medium| O(log n)| O(1)||65.9%| -|0037|Sudoku Solver|[Go]({{< relref "/ChapterFour/0001~0099/0037.Sudoku-Solver.md" >}})|Hard| O(n^2)| O(n^2)|❤️|47.3%| -|0039|Combination Sum|[Go]({{< relref "/ChapterFour/0001~0099/0039.Combination-Sum.md" >}})|Medium| O(n log n)| O(n)||59.9%| -|0040|Combination Sum II|[Go]({{< relref "/ChapterFour/0001~0099/0040.Combination-Sum-II.md" >}})|Medium| O(n log n)| O(n)||50.5%| -|0046|Permutations|[Go]({{< relref "/ChapterFour/0001~0099/0046.Permutations.md" >}})|Medium| O(n)| O(n)|❤️|67.3%| -|0047|Permutations II|[Go]({{< relref "/ChapterFour/0001~0099/0047.Permutations-II.md" >}})|Medium| O(n^2)| O(n)|❤️|50.0%| -|0051|N-Queens|[Go]({{< relref "/ChapterFour/0001~0099/0051.N-Queens.md" >}})|Hard| O(n!)| O(n)|❤️|50.4%| -|0052|N-Queens II|[Go]({{< relref "/ChapterFour/0001~0099/0052.N-Queens-II.md" >}})|Hard| O(n!)| O(n)|❤️|60.8%| -|0060|Permutation Sequence|[Go]({{< relref "/ChapterFour/0001~0099/0060.Permutation-Sequence.md" >}})|Hard| O(n log n)| O(1)||39.7%| -|0077|Combinations|[Go]({{< relref "/ChapterFour/0001~0099/0077.Combinations.md" >}})|Medium| O(n)| O(n)|❤️|58.2%| -|0078|Subsets|[Go]({{< relref "/ChapterFour/0001~0099/0078.Subsets.md" >}})|Medium| O(n^2)| O(n)|❤️|65.8%| -|0079|Word Search|[Go]({{< relref "/ChapterFour/0001~0099/0079.Word-Search.md" >}})|Medium| O(n^2)| O(n^2)|❤️|37.3%| -|0089|Gray Code|[Go]({{< relref "/ChapterFour/0001~0099/0089.Gray-Code.md" >}})|Medium| O(n)| O(1)||50.8%| -|0090|Subsets II|[Go]({{< relref "/ChapterFour/0001~0099/0090.Subsets-II.md" >}})|Medium| O(n^2)| O(n)|❤️|49.3%| -|0093|Restore IP Addresses|[Go]({{< relref "/ChapterFour/0001~0099/0093.Restore-IP-Addresses.md" >}})|Medium| O(n)| O(n)|❤️|38.0%| -|0126|Word Ladder II|[Go]({{< relref "/ChapterFour/0100~0199/0126.Word-Ladder-II.md" >}})|Hard| O(n)| O(n^2)|❤️|23.9%| -|0131|Palindrome Partitioning|[Go]({{< relref "/ChapterFour/0100~0199/0131.Palindrome-Partitioning.md" >}})|Medium| O(n)| O(n^2)|❤️|52.9%| -|0211|Design Add and Search Words Data Structure|[Go]({{< relref "/ChapterFour/0200~0299/0211.Design-Add-and-Search-Words-Data-Structure.md" >}})|Medium| O(n)| O(n)|❤️|40.7%| -|0212|Word Search II|[Go]({{< relref "/ChapterFour/0200~0299/0212.Word-Search-II.md" >}})|Hard| O(n^2)| O(n^2)|❤️|37.6%| -|0216|Combination Sum III|[Go]({{< relref "/ChapterFour/0200~0299/0216.Combination-Sum-III.md" >}})|Medium| O(n)| O(1)|❤️|60.8%| -|0306|Additive Number|[Go]({{< relref "/ChapterFour/0300~0399/0306.Additive-Number.md" >}})|Medium| O(n^2)| O(1)|❤️|29.8%| -|0357|Count Numbers with Unique Digits|[Go]({{< relref "/ChapterFour/0300~0399/0357.Count-Numbers-with-Unique-Digits.md" >}})|Medium| O(1)| O(1)||49.0%| -|0401|Binary Watch|[Go]({{< relref "/ChapterFour/0400~0499/0401.Binary-Watch.md" >}})|Easy| O(1)| O(1)||48.7%| -|0526|Beautiful Arrangement|[Go]({{< relref "/ChapterFour/0500~0599/0526.Beautiful-Arrangement.md" >}})|Medium| O(n^2)| O(1)|❤️|62.2%| -|0784|Letter Case Permutation|[Go]({{< relref "/ChapterFour/0700~0799/0784.Letter-Case-Permutation.md" >}})|Medium| O(n)| O(n)||68.9%| -|0842|Split Array into Fibonacci Sequence|[Go]({{< relref "/ChapterFour/0800~0899/0842.Split-Array-into-Fibonacci-Sequence.md" >}})|Medium| O(n^2)| O(1)|❤️|37.0%| -|0980|Unique Paths III|[Go]({{< relref "/ChapterFour/0900~0999/0980.Unique-Paths-III.md" >}})|Hard| O(n log n)| O(n)||77.1%| -|0996|Number of Squareful Arrays|[Go]({{< relref "/ChapterFour/0900~0999/0996.Number-of-Squareful-Arrays.md" >}})|Hard| O(n log n)| O(n) ||48.6%| +|0017|Letter Combinations of a Phone Number|[Go]({{< relref "/ChapterFour/0001~0099/0017.Letter-Combinations-of-a-Phone-Number.md" >}})|Medium| O(log n)| O(1)||56.6%| +|0022|Generate Parentheses|[Go]({{< relref "/ChapterFour/0001~0099/0022.Generate-Parentheses.md" >}})|Medium| O(log n)| O(1)||72.5%| +|0037|Sudoku Solver|[Go]({{< relref "/ChapterFour/0001~0099/0037.Sudoku-Solver.md" >}})|Hard| O(n^2)| O(n^2)|❤️|57.7%| +|0039|Combination Sum|[Go]({{< relref "/ChapterFour/0001~0099/0039.Combination-Sum.md" >}})|Medium| O(n log n)| O(n)||68.6%| +|0040|Combination Sum II|[Go]({{< relref "/ChapterFour/0001~0099/0040.Combination-Sum-II.md" >}})|Medium| O(n log n)| O(n)||53.4%| +|0046|Permutations|[Go]({{< relref "/ChapterFour/0001~0099/0046.Permutations.md" >}})|Medium| O(n)| O(n)|❤️|75.7%| +|0047|Permutations II|[Go]({{< relref "/ChapterFour/0001~0099/0047.Permutations-II.md" >}})|Medium| O(n^2)| O(n)|❤️|57.4%| +|0051|N-Queens|[Go]({{< relref "/ChapterFour/0001~0099/0051.N-Queens.md" >}})|Hard| O(n!)| O(n)|❤️|64.2%| +|0052|N-Queens II|[Go]({{< relref "/ChapterFour/0001~0099/0052.N-Queens-II.md" >}})|Hard| O(n!)| O(n)|❤️|71.6%| +|0077|Combinations|[Go]({{< relref "/ChapterFour/0001~0099/0077.Combinations.md" >}})|Medium| O(n)| O(n)|❤️|67.0%| +|0078|Subsets|[Go]({{< relref "/ChapterFour/0001~0099/0078.Subsets.md" >}})|Medium| O(n^2)| O(n)|❤️|74.9%| +|0079|Word Search|[Go]({{< relref "/ChapterFour/0001~0099/0079.Word-Search.md" >}})|Medium| O(n^2)| O(n^2)|❤️|40.2%| +|0089|Gray Code|[Go]({{< relref "/ChapterFour/0001~0099/0089.Gray-Code.md" >}})|Medium| O(n)| O(1)||57.2%| +|0090|Subsets II|[Go]({{< relref "/ChapterFour/0001~0099/0090.Subsets-II.md" >}})|Medium| O(n^2)| O(n)|❤️|55.9%| +|0093|Restore IP Addresses|[Go]({{< relref "/ChapterFour/0001~0099/0093.Restore-IP-Addresses.md" >}})|Medium| O(n)| O(n)|❤️|47.4%| +|0095|Unique Binary Search Trees II|[Go]({{< relref "/ChapterFour/0001~0099/0095.Unique-Binary-Search-Trees-II.md" >}})|Medium||||52.4%| +|0113|Path Sum II|[Go]({{< relref "/ChapterFour/0100~0199/0113.Path-Sum-II.md" >}})|Medium||||57.1%| +|0126|Word Ladder II|[Go]({{< relref "/ChapterFour/0100~0199/0126.Word-Ladder-II.md" >}})|Hard| O(n)| O(n^2)|❤️|27.5%| +|0131|Palindrome Partitioning|[Go]({{< relref "/ChapterFour/0100~0199/0131.Palindrome-Partitioning.md" >}})|Medium| O(n)| O(n^2)|❤️|64.9%| +|0212|Word Search II|[Go]({{< relref "/ChapterFour/0200~0299/0212.Word-Search-II.md" >}})|Hard| O(n^2)| O(n^2)|❤️|36.4%| +|0216|Combination Sum III|[Go]({{< relref "/ChapterFour/0200~0299/0216.Combination-Sum-III.md" >}})|Medium| O(n)| O(1)|❤️|67.6%| +|0257|Binary Tree Paths|[Go]({{< relref "/ChapterFour/0200~0299/0257.Binary-Tree-Paths.md" >}})|Easy||||61.4%| +|0301|Remove Invalid Parentheses|[Go]({{< relref "/ChapterFour/0300~0399/0301.Remove-Invalid-Parentheses.md" >}})|Hard||||47.2%| +|0306|Additive Number|[Go]({{< relref "/ChapterFour/0300~0399/0306.Additive-Number.md" >}})|Medium| O(n^2)| O(1)|❤️|31.1%| +|0357|Count Numbers with Unique Digits|[Go]({{< relref "/ChapterFour/0300~0399/0357.Count-Numbers-with-Unique-Digits.md" >}})|Medium| O(1)| O(1)||51.9%| +|0401|Binary Watch|[Go]({{< relref "/ChapterFour/0400~0499/0401.Binary-Watch.md" >}})|Easy| O(1)| O(1)||52.3%| +|0473|Matchsticks to Square|[Go]({{< relref "/ChapterFour/0400~0499/0473.Matchsticks-to-Square.md" >}})|Medium||||40.2%| +|0491|Non-decreasing Subsequences|[Go]({{< relref "/ChapterFour/0400~0499/0491.Non-decreasing-Subsequences.md" >}})|Medium||||60.2%| +|0494|Target Sum|[Go]({{< relref "/ChapterFour/0400~0499/0494.Target-Sum.md" >}})|Medium||||45.7%| +|0526|Beautiful Arrangement|[Go]({{< relref "/ChapterFour/0500~0599/0526.Beautiful-Arrangement.md" >}})|Medium| O(n^2)| O(1)|❤️|64.4%| +|0638|Shopping Offers|[Go]({{< relref "/ChapterFour/0600~0699/0638.Shopping-Offers.md" >}})|Medium||||53.3%| +|0784|Letter Case Permutation|[Go]({{< relref "/ChapterFour/0700~0799/0784.Letter-Case-Permutation.md" >}})|Medium| O(n)| O(n)||73.8%| +|0816|Ambiguous Coordinates|[Go]({{< relref "/ChapterFour/0800~0899/0816.Ambiguous-Coordinates.md" >}})|Medium||||56.4%| +|0842|Split Array into Fibonacci Sequence|[Go]({{< relref "/ChapterFour/0800~0899/0842.Split-Array-into-Fibonacci-Sequence.md" >}})|Medium| O(n^2)| O(1)|❤️|38.4%| +|0980|Unique Paths III|[Go]({{< relref "/ChapterFour/0900~0999/0980.Unique-Paths-III.md" >}})|Hard| O(n log n)| O(n)||81.7%| +|0996|Number of Squareful Arrays|[Go]({{< relref "/ChapterFour/0900~0999/0996.Number-of-Squareful-Arrays.md" >}})|Hard| O(n log n)| O(n) ||49.2%| |1079|Letter Tile Possibilities|[Go]({{< relref "/ChapterFour/1000~1099/1079.Letter-Tile-Possibilities.md" >}})|Medium| O(n^2)| O(1)|❤️|76.0%| -|1641|Count Sorted Vowel Strings|[Go]({{< relref "/ChapterFour/1600~1699/1641.Count-Sorted-Vowel-Strings.md" >}})|Medium||||75.4%| -|1655|Distribute Repeating Integers|[Go]({{< relref "/ChapterFour/1600~1699/1655.Distribute-Repeating-Integers.md" >}})|Hard||||40.0%| -|1659|Maximize Grid Happiness|[Go]({{< relref "/ChapterFour/1600~1699/1659.Maximize-Grid-Happiness.md" >}})|Hard||||35.6%| -|1681|Minimum Incompatibility|[Go]({{< relref "/ChapterFour/1600~1699/1681.Minimum-Incompatibility.md" >}})|Hard||||35.9%| -|1688|Count of Matches in Tournament|[Go]({{< relref "/ChapterFour/1600~1699/1688.Count-of-Matches-in-Tournament.md" >}})|Easy||||81.5%| +|1239|Maximum Length of a Concatenated String with Unique Characters|[Go]({{< relref "/ChapterFour/1200~1299/1239.Maximum-Length-of-a-Concatenated-String-with-Unique-Characters.md" >}})|Medium||||52.2%| +|1655|Distribute Repeating Integers|[Go]({{< relref "/ChapterFour/1600~1699/1655.Distribute-Repeating-Integers.md" >}})|Hard||||39.3%| |------------|-------------------------------------------------------|-------| ----------------| ---------------|-------------|-------------|-------------| diff --git a/website/content/ChapterTwo/Binary_Indexed_Tree.md b/website/content/ChapterTwo/Binary_Indexed_Tree.md index ce441cf31..6a988987e 100644 --- a/website/content/ChapterTwo/Binary_Indexed_Tree.md +++ b/website/content/ChapterTwo/Binary_Indexed_Tree.md @@ -10,18 +10,16 @@ weight: 19 | No. | Title | Solution | Difficulty | TimeComplexity | SpaceComplexity |Favorite| Acceptance | |:--------:|:------- | :--------: | :----------: | :----: | :-----: | :-----: |:-----: | -|0218|The Skyline Problem|[Go]({{< relref "/ChapterFour/0200~0299/0218.The-Skyline-Problem.md" >}})|Hard||||36.7%| -|0307|Range Sum Query - Mutable|[Go]({{< relref "/ChapterFour/0300~0399/0307.Range-Sum-Query-Mutable.md" >}})|Medium||||37.1%| -|0315|Count of Smaller Numbers After Self|[Go]({{< relref "/ChapterFour/0300~0399/0315.Count-of-Smaller-Numbers-After-Self.md" >}})|Hard||||42.4%| -|0327|Count of Range Sum|[Go]({{< relref "/ChapterFour/0300~0399/0327.Count-of-Range-Sum.md" >}})|Hard||||36.4%| -|0493|Reverse Pairs|[Go]({{< relref "/ChapterFour/0400~0499/0493.Reverse-Pairs.md" >}})|Hard||||27.3%| -|1649|Create Sorted Array through Instructions|[Go]({{< relref "/ChapterFour/1600~1699/1649.Create-Sorted-Array-through-Instructions.md" >}})|Hard||||36.7%| +|0218|The Skyline Problem|[Go]({{< relref "/ChapterFour/0200~0299/0218.The-Skyline-Problem.md" >}})|Hard||||41.9%| +|0307|Range Sum Query - Mutable|[Go]({{< relref "/ChapterFour/0300~0399/0307.Range-Sum-Query-Mutable.md" >}})|Medium||||40.7%| +|0315|Count of Smaller Numbers After Self|[Go]({{< relref "/ChapterFour/0300~0399/0315.Count-of-Smaller-Numbers-After-Self.md" >}})|Hard||||42.6%| +|0327|Count of Range Sum|[Go]({{< relref "/ChapterFour/0300~0399/0327.Count-of-Range-Sum.md" >}})|Hard||||35.8%| +|0493|Reverse Pairs|[Go]({{< relref "/ChapterFour/0400~0499/0493.Reverse-Pairs.md" >}})|Hard||||30.9%| +|1157|Online Majority Element In Subarray|[Go]({{< relref "/ChapterFour/1100~1199/1157.Online-Majority-Element-In-Subarray.md" >}})|Hard||||41.8%| +|1649|Create Sorted Array through Instructions|[Go]({{< relref "/ChapterFour/1600~1699/1649.Create-Sorted-Array-through-Instructions.md" >}})|Hard||||37.5%| |------------|-------------------------------------------------------|-------| ----------------| ---------------|-------------|-------------|-------------| - - - ----------------------------------------------

⬅️上一页

diff --git a/website/content/ChapterTwo/Binary_Search.md b/website/content/ChapterTwo/Binary_Search.md index 744f8d25b..bbfa80272 100644 --- a/website/content/ChapterTwo/Binary_Search.md +++ b/website/content/ChapterTwo/Binary_Search.md @@ -131,75 +131,90 @@ func peakIndexInMountainArray(A []int) int { | No. | Title | Solution | Difficulty | TimeComplexity | SpaceComplexity |Favorite| Acceptance | |:--------:|:------- | :--------: | :----------: | :----: | :-----: | :-----: |:-----: | -|0004|Median of Two Sorted Arrays|[Go]({{< relref "/ChapterFour/0001~0099/0004.Median-of-Two-Sorted-Arrays.md" >}})|Hard||||31.5%| -|0029|Divide Two Integers|[Go]({{< relref "/ChapterFour/0001~0099/0029.Divide-Two-Integers.md" >}})|Medium||||16.9%| -|0033|Search in Rotated Sorted Array|[Go]({{< relref "/ChapterFour/0001~0099/0033.Search-in-Rotated-Sorted-Array.md" >}})|Medium||||36.2%| -|0034|Find First and Last Position of Element in Sorted Array|[Go]({{< relref "/ChapterFour/0001~0099/0034.Find-First-and-Last-Position-of-Element-in-Sorted-Array.md" >}})|Medium||||37.6%| -|0035|Search Insert Position|[Go]({{< relref "/ChapterFour/0001~0099/0035.Search-Insert-Position.md" >}})|Easy||||42.9%| -|0050|Pow(x, n)|[Go]({{< relref "/ChapterFour/0001~0099/0050.Powx-n.md" >}})|Medium| O(log n)| O(1)||31.1%| -|0069|Sqrt(x)|[Go]({{< relref "/ChapterFour/0001~0099/0069.Sqrtx.md" >}})|Easy| O(log n)| O(1)||35.5%| -|0074|Search a 2D Matrix|[Go]({{< relref "/ChapterFour/0001~0099/0074.Search-a-2D-Matrix.md" >}})|Medium||||38.3%| -|0081|Search in Rotated Sorted Array II|[Go]({{< relref "/ChapterFour/0001~0099/0081.Search-in-Rotated-Sorted-Array-II.md" >}})|Medium||||33.7%| -|0153|Find Minimum in Rotated Sorted Array|[Go]({{< relref "/ChapterFour/0100~0199/0153.Find-Minimum-in-Rotated-Sorted-Array.md" >}})|Medium||||46.5%| -|0154|Find Minimum in Rotated Sorted Array II|[Go]({{< relref "/ChapterFour/0100~0199/0154.Find-Minimum-in-Rotated-Sorted-Array-II.md" >}})|Hard||||42.2%| -|0162|Find Peak Element|[Go]({{< relref "/ChapterFour/0100~0199/0162.Find-Peak-Element.md" >}})|Medium||||44.1%| -|0167|Two Sum II - Input array is sorted|[Go]({{< relref "/ChapterFour/0100~0199/0167.Two-Sum-II-Input-array-is-sorted.md" >}})|Easy| O(n)| O(1)||55.8%| -|0174|Dungeon Game|[Go]({{< relref "/ChapterFour/0100~0199/0174.Dungeon-Game.md" >}})|Hard||||33.5%| -|0209|Minimum Size Subarray Sum|[Go]({{< relref "/ChapterFour/0200~0299/0209.Minimum-Size-Subarray-Sum.md" >}})|Medium| O(n)| O(1)||39.9%| -|0222|Count Complete Tree Nodes|[Go]({{< relref "/ChapterFour/0200~0299/0222.Count-Complete-Tree-Nodes.md" >}})|Medium| O(n)| O(1)||49.9%| -|0230|Kth Smallest Element in a BST|[Go]({{< relref "/ChapterFour/0200~0299/0230.Kth-Smallest-Element-in-a-BST.md" >}})|Medium| O(n)| O(1)||63.1%| -|0240|Search a 2D Matrix II|[Go]({{< relref "/ChapterFour/0200~0299/0240.Search-a-2D-Matrix-II.md" >}})|Medium||||45.5%| -|0275|H-Index II|[Go]({{< relref "/ChapterFour/0200~0299/0275.H-Index-II.md" >}})|Medium||||36.4%| -|0287|Find the Duplicate Number|[Go]({{< relref "/ChapterFour/0200~0299/0287.Find-the-Duplicate-Number.md" >}})|Medium| O(n)| O(1)|❤️|58.0%| -|0300|Longest Increasing Subsequence|[Go]({{< relref "/ChapterFour/0300~0399/0300.Longest-Increasing-Subsequence.md" >}})|Medium| O(n log n)| O(n)||44.7%| -|0315|Count of Smaller Numbers After Self|[Go]({{< relref "/ChapterFour/0300~0399/0315.Count-of-Smaller-Numbers-After-Self.md" >}})|Hard||||42.4%| -|0327|Count of Range Sum|[Go]({{< relref "/ChapterFour/0300~0399/0327.Count-of-Range-Sum.md" >}})|Hard||||36.4%| -|0349|Intersection of Two Arrays|[Go]({{< relref "/ChapterFour/0300~0399/0349.Intersection-of-Two-Arrays.md" >}})|Easy| O(n)| O(n) ||65.5%| -|0350|Intersection of Two Arrays II|[Go]({{< relref "/ChapterFour/0300~0399/0350.Intersection-of-Two-Arrays-II.md" >}})|Easy| O(n)| O(n) ||52.2%| -|0354|Russian Doll Envelopes|[Go]({{< relref "/ChapterFour/0300~0399/0354.Russian-Doll-Envelopes.md" >}})|Hard||||37.8%| -|0367|Valid Perfect Square|[Go]({{< relref "/ChapterFour/0300~0399/0367.Valid-Perfect-Square.md" >}})|Easy||||42.3%| -|0378|Kth Smallest Element in a Sorted Matrix|[Go]({{< relref "/ChapterFour/0300~0399/0378.Kth-Smallest-Element-in-a-Sorted-Matrix.md" >}})|Medium||||56.6%| -|0392|Is Subsequence|[Go]({{< relref "/ChapterFour/0300~0399/0392.Is-Subsequence.md" >}})|Easy| O(n)| O(1)||49.6%| -|0410|Split Array Largest Sum|[Go]({{< relref "/ChapterFour/0400~0499/0410.Split-Array-Largest-Sum.md" >}})|Hard||||46.8%| -|0436|Find Right Interval|[Go]({{< relref "/ChapterFour/0400~0499/0436.Find-Right-Interval.md" >}})|Medium||||48.6%| -|0441|Arranging Coins|[Go]({{< relref "/ChapterFour/0400~0499/0441.Arranging-Coins.md" >}})|Easy||||42.7%| -|0454|4Sum II|[Go]({{< relref "/ChapterFour/0400~0499/0454.4Sum-II.md" >}})|Medium| O(n^2)| O(n) ||54.7%| -|0475|Heaters|[Go]({{< relref "/ChapterFour/0400~0499/0475.Heaters.md" >}})|Medium||||33.8%| -|0483|Smallest Good Base|[Go]({{< relref "/ChapterFour/0400~0499/0483.Smallest-Good-Base.md" >}})|Hard||||36.4%| -|0493|Reverse Pairs|[Go]({{< relref "/ChapterFour/0400~0499/0493.Reverse-Pairs.md" >}})|Hard||||27.3%| -|0497|Random Point in Non-overlapping Rectangles|[Go]({{< relref "/ChapterFour/0400~0499/0497.Random-Point-in-Non-overlapping-Rectangles.md" >}})|Medium||||39.1%| -|0528|Random Pick with Weight|[Go]({{< relref "/ChapterFour/0500~0599/0528.Random-Pick-with-Weight.md" >}})|Medium||||44.8%| -|0658|Find K Closest Elements|[Go]({{< relref "/ChapterFour/0600~0699/0658.Find-K-Closest-Elements.md" >}})|Medium||||42.4%| -|0668|Kth Smallest Number in Multiplication Table|[Go]({{< relref "/ChapterFour/0600~0699/0668.Kth-Smallest-Number-in-Multiplication-Table.md" >}})|Hard||||48.0%| -|0704|Binary Search|[Go]({{< relref "/ChapterFour/0700~0799/0704.Binary-Search.md" >}})|Easy||||54.4%| -|0710|Random Pick with Blacklist|[Go]({{< relref "/ChapterFour/0700~0799/0710.Random-Pick-with-Blacklist.md" >}})|Hard| O(n)| O(n) ||33.1%| -|0718|Maximum Length of Repeated Subarray|[Go]({{< relref "/ChapterFour/0700~0799/0718.Maximum-Length-of-Repeated-Subarray.md" >}})|Medium||||50.6%| -|0719|Find K-th Smallest Pair Distance|[Go]({{< relref "/ChapterFour/0700~0799/0719.Find-K-th-Smallest-Pair-Distance.md" >}})|Hard||||32.7%| -|0744|Find Smallest Letter Greater Than Target|[Go]({{< relref "/ChapterFour/0700~0799/0744.Find-Smallest-Letter-Greater-Than-Target.md" >}})|Easy||||45.6%| -|0778|Swim in Rising Water|[Go]({{< relref "/ChapterFour/0700~0799/0778.Swim-in-Rising-Water.md" >}})|Hard||||55.1%| -|0786|K-th Smallest Prime Fraction|[Go]({{< relref "/ChapterFour/0700~0799/0786.K-th-Smallest-Prime-Fraction.md" >}})|Hard||||43.7%| -|0793|Preimage Size of Factorial Zeroes Function|[Go]({{< relref "/ChapterFour/0700~0799/0793.Preimage-Size-of-Factorial-Zeroes-Function.md" >}})|Hard||||40.7%| -|0852|Peak Index in a Mountain Array|[Go]({{< relref "/ChapterFour/0800~0899/0852.Peak-Index-in-a-Mountain-Array.md" >}})|Easy||||71.8%| -|0862|Shortest Subarray with Sum at Least K|[Go]({{< relref "/ChapterFour/0800~0899/0862.Shortest-Subarray-with-Sum-at-Least-K.md" >}})|Hard||||25.3%| -|0875|Koko Eating Bananas|[Go]({{< relref "/ChapterFour/0800~0899/0875.Koko-Eating-Bananas.md" >}})|Medium||||53.5%| -|0878|Nth Magical Number|[Go]({{< relref "/ChapterFour/0800~0899/0878.Nth-Magical-Number.md" >}})|Hard||||28.9%| -|0887|Super Egg Drop|[Go]({{< relref "/ChapterFour/0800~0899/0887.Super-Egg-Drop.md" >}})|Hard||||27.0%| -|0911|Online Election|[Go]({{< relref "/ChapterFour/0900~0999/0911.Online-Election.md" >}})|Medium||||51.5%| -|0927|Three Equal Parts|[Go]({{< relref "/ChapterFour/0900~0999/0927.Three-Equal-Parts.md" >}})|Hard||||34.7%| -|0981|Time Based Key-Value Store|[Go]({{< relref "/ChapterFour/0900~0999/0981.Time-Based-Key-Value-Store.md" >}})|Medium||||54.3%| -|1011|Capacity To Ship Packages Within D Days|[Go]({{< relref "/ChapterFour/1000~1099/1011.Capacity-To-Ship-Packages-Within-D-Days.md" >}})|Medium||||60.0%| -|1111|Maximum Nesting Depth of Two Valid Parentheses Strings|[Go]({{< relref "/ChapterFour/1100~1199/1111.Maximum-Nesting-Depth-of-Two-Valid-Parentheses-Strings.md" >}})|Medium||||72.8%| -|1157|Online Majority Element In Subarray|[Go]({{< relref "/ChapterFour/1100~1199/1157.Online-Majority-Element-In-Subarray.md" >}})|Hard||||41.0%| -|1170|Compare Strings by Frequency of the Smallest Character|[Go]({{< relref "/ChapterFour/1100~1199/1170.Compare-Strings-by-Frequency-of-the-Smallest-Character.md" >}})|Medium||||60.4%| -|1201|Ugly Number III|[Go]({{< relref "/ChapterFour/1200~1299/1201.Ugly-Number-III.md" >}})|Medium||||26.5%| -|1235|Maximum Profit in Job Scheduling|[Go]({{< relref "/ChapterFour/1200~1299/1235.Maximum-Profit-in-Job-Scheduling.md" >}})|Hard||||47.8%| -|1283|Find the Smallest Divisor Given a Threshold|[Go]({{< relref "/ChapterFour/1200~1299/1283.Find-the-Smallest-Divisor-Given-a-Threshold.md" >}})|Medium||||50.0%| -|1300|Sum of Mutated Array Closest to Target|[Go]({{< relref "/ChapterFour/1300~1399/1300.Sum-of-Mutated-Array-Closest-to-Target.md" >}})|Medium||||43.0%| -|1337|The K Weakest Rows in a Matrix|[Go]({{< relref "/ChapterFour/1300~1399/1337.The-K-Weakest-Rows-in-a-Matrix.md" >}})|Easy||||72.0%| -|1631|Path With Minimum Effort|[Go]({{< relref "/ChapterFour/1600~1699/1631.Path-With-Minimum-Effort.md" >}})|Medium||||50.0%| -|1642|Furthest Building You Can Reach|[Go]({{< relref "/ChapterFour/1600~1699/1642.Furthest-Building-You-Can-Reach.md" >}})|Medium||||47.3%| -|1649|Create Sorted Array through Instructions|[Go]({{< relref "/ChapterFour/1600~1699/1649.Create-Sorted-Array-through-Instructions.md" >}})|Hard||||36.7%| -|1658|Minimum Operations to Reduce X to Zero|[Go]({{< relref "/ChapterFour/1600~1699/1658.Minimum-Operations-to-Reduce-X-to-Zero.md" >}})|Medium||||33.3%| +|0004|Median of Two Sorted Arrays|[Go]({{< relref "/ChapterFour/0001~0099/0004.Median-of-Two-Sorted-Arrays.md" >}})|Hard||||36.2%| +|0033|Search in Rotated Sorted Array|[Go]({{< relref "/ChapterFour/0001~0099/0033.Search-in-Rotated-Sorted-Array.md" >}})|Medium||||39.0%| +|0034|Find First and Last Position of Element in Sorted Array|[Go]({{< relref "/ChapterFour/0001~0099/0034.Find-First-and-Last-Position-of-Element-in-Sorted-Array.md" >}})|Medium||||41.9%| +|0035|Search Insert Position|[Go]({{< relref "/ChapterFour/0001~0099/0035.Search-Insert-Position.md" >}})|Easy||||43.4%| +|0069|Sqrt(x)|[Go]({{< relref "/ChapterFour/0001~0099/0069.Sqrtx.md" >}})|Easy| O(log n)| O(1)||37.4%| +|0074|Search a 2D Matrix|[Go]({{< relref "/ChapterFour/0001~0099/0074.Search-a-2D-Matrix.md" >}})|Medium||||47.7%| +|0081|Search in Rotated Sorted Array II|[Go]({{< relref "/ChapterFour/0001~0099/0081.Search-in-Rotated-Sorted-Array-II.md" >}})|Medium||||35.7%| +|0153|Find Minimum in Rotated Sorted Array|[Go]({{< relref "/ChapterFour/0100~0199/0153.Find-Minimum-in-Rotated-Sorted-Array.md" >}})|Medium||||48.9%| +|0154|Find Minimum in Rotated Sorted Array II|[Go]({{< relref "/ChapterFour/0100~0199/0154.Find-Minimum-in-Rotated-Sorted-Array-II.md" >}})|Hard||||43.5%| +|0162|Find Peak Element|[Go]({{< relref "/ChapterFour/0100~0199/0162.Find-Peak-Element.md" >}})|Medium||||46.0%| +|0167|Two Sum II - Input Array Is Sorted|[Go]({{< relref "/ChapterFour/0100~0199/0167.Two-Sum-II-Input-Array-Is-Sorted.md" >}})|Medium| O(n)| O(1)||60.0%| +|0209|Minimum Size Subarray Sum|[Go]({{< relref "/ChapterFour/0200~0299/0209.Minimum-Size-Subarray-Sum.md" >}})|Medium| O(n)| O(1)||45.0%| +|0222|Count Complete Tree Nodes|[Go]({{< relref "/ChapterFour/0200~0299/0222.Count-Complete-Tree-Nodes.md" >}})|Medium| O(n)| O(1)||60.6%| +|0240|Search a 2D Matrix II|[Go]({{< relref "/ChapterFour/0200~0299/0240.Search-a-2D-Matrix-II.md" >}})|Medium||||51.0%| +|0268|Missing Number|[Go]({{< relref "/ChapterFour/0200~0299/0268.Missing-Number.md" >}})|Easy||||62.6%| +|0275|H-Index II|[Go]({{< relref "/ChapterFour/0200~0299/0275.H-Index-II.md" >}})|Medium||||37.5%| +|0278|First Bad Version|[Go]({{< relref "/ChapterFour/0200~0299/0278.First-Bad-Version.md" >}})|Easy||||43.3%| +|0287|Find the Duplicate Number|[Go]({{< relref "/ChapterFour/0200~0299/0287.Find-the-Duplicate-Number.md" >}})|Medium| O(n)| O(1)|❤️|59.1%| +|0300|Longest Increasing Subsequence|[Go]({{< relref "/ChapterFour/0300~0399/0300.Longest-Increasing-Subsequence.md" >}})|Medium| O(n log n)| O(n)||52.2%| +|0315|Count of Smaller Numbers After Self|[Go]({{< relref "/ChapterFour/0300~0399/0315.Count-of-Smaller-Numbers-After-Self.md" >}})|Hard||||42.6%| +|0327|Count of Range Sum|[Go]({{< relref "/ChapterFour/0300~0399/0327.Count-of-Range-Sum.md" >}})|Hard||||35.8%| +|0349|Intersection of Two Arrays|[Go]({{< relref "/ChapterFour/0300~0399/0349.Intersection-of-Two-Arrays.md" >}})|Easy| O(n)| O(n) ||70.9%| +|0350|Intersection of Two Arrays II|[Go]({{< relref "/ChapterFour/0300~0399/0350.Intersection-of-Two-Arrays-II.md" >}})|Easy| O(n)| O(n) ||56.0%| +|0352|Data Stream as Disjoint Intervals|[Go]({{< relref "/ChapterFour/0300~0399/0352.Data-Stream-as-Disjoint-Intervals.md" >}})|Hard||||59.7%| +|0354|Russian Doll Envelopes|[Go]({{< relref "/ChapterFour/0300~0399/0354.Russian-Doll-Envelopes.md" >}})|Hard||||37.9%| +|0367|Valid Perfect Square|[Go]({{< relref "/ChapterFour/0300~0399/0367.Valid-Perfect-Square.md" >}})|Easy||||43.3%| +|0374|Guess Number Higher or Lower|[Go]({{< relref "/ChapterFour/0300~0399/0374.Guess-Number-Higher-or-Lower.md" >}})|Easy||||51.9%| +|0378|Kth Smallest Element in a Sorted Matrix|[Go]({{< relref "/ChapterFour/0300~0399/0378.Kth-Smallest-Element-in-a-Sorted-Matrix.md" >}})|Medium||||61.8%| +|0400|Nth Digit|[Go]({{< relref "/ChapterFour/0400~0499/0400.Nth-Digit.md" >}})|Medium||||34.1%| +|0410|Split Array Largest Sum|[Go]({{< relref "/ChapterFour/0400~0499/0410.Split-Array-Largest-Sum.md" >}})|Hard||||53.5%| +|0436|Find Right Interval|[Go]({{< relref "/ChapterFour/0400~0499/0436.Find-Right-Interval.md" >}})|Medium||||50.8%| +|0441|Arranging Coins|[Go]({{< relref "/ChapterFour/0400~0499/0441.Arranging-Coins.md" >}})|Easy||||46.2%| +|0456|132 Pattern|[Go]({{< relref "/ChapterFour/0400~0499/0456.132-Pattern.md" >}})|Medium||||32.4%| +|0475|Heaters|[Go]({{< relref "/ChapterFour/0400~0499/0475.Heaters.md" >}})|Medium||||36.5%| +|0483|Smallest Good Base|[Go]({{< relref "/ChapterFour/0400~0499/0483.Smallest-Good-Base.md" >}})|Hard||||38.8%| +|0493|Reverse Pairs|[Go]({{< relref "/ChapterFour/0400~0499/0493.Reverse-Pairs.md" >}})|Hard||||30.9%| +|0497|Random Point in Non-overlapping Rectangles|[Go]({{< relref "/ChapterFour/0400~0499/0497.Random-Point-in-Non-overlapping-Rectangles.md" >}})|Medium||||39.4%| +|0528|Random Pick with Weight|[Go]({{< relref "/ChapterFour/0500~0599/0528.Random-Pick-with-Weight.md" >}})|Medium||||46.1%| +|0532|K-diff Pairs in an Array|[Go]({{< relref "/ChapterFour/0500~0599/0532.K-diff-Pairs-in-an-Array.md" >}})|Medium||||41.2%| +|0540|Single Element in a Sorted Array|[Go]({{< relref "/ChapterFour/0500~0599/0540.Single-Element-in-a-Sorted-Array.md" >}})|Medium||||59.1%| +|0611|Valid Triangle Number|[Go]({{< relref "/ChapterFour/0600~0699/0611.Valid-Triangle-Number.md" >}})|Medium||||50.6%| +|0633|Sum of Square Numbers|[Go]({{< relref "/ChapterFour/0600~0699/0633.Sum-of-Square-Numbers.md" >}})|Medium||||34.4%| +|0658|Find K Closest Elements|[Go]({{< relref "/ChapterFour/0600~0699/0658.Find-K-Closest-Elements.md" >}})|Medium||||46.8%| +|0668|Kth Smallest Number in Multiplication Table|[Go]({{< relref "/ChapterFour/0600~0699/0668.Kth-Smallest-Number-in-Multiplication-Table.md" >}})|Hard||||51.4%| +|0704|Binary Search|[Go]({{< relref "/ChapterFour/0700~0799/0704.Binary-Search.md" >}})|Easy||||56.1%| +|0710|Random Pick with Blacklist|[Go]({{< relref "/ChapterFour/0700~0799/0710.Random-Pick-with-Blacklist.md" >}})|Hard| O(n)| O(n) ||33.5%| +|0718|Maximum Length of Repeated Subarray|[Go]({{< relref "/ChapterFour/0700~0799/0718.Maximum-Length-of-Repeated-Subarray.md" >}})|Medium||||51.3%| +|0719|Find K-th Smallest Pair Distance|[Go]({{< relref "/ChapterFour/0700~0799/0719.Find-K-th-Smallest-Pair-Distance.md" >}})|Hard||||36.7%| +|0729|My Calendar I|[Go]({{< relref "/ChapterFour/0700~0799/0729.My-Calendar-I.md" >}})|Medium||||56.8%| +|0732|My Calendar III|[Go]({{< relref "/ChapterFour/0700~0799/0732.My-Calendar-III.md" >}})|Hard||||71.5%| +|0744|Find Smallest Letter Greater Than Target|[Go]({{< relref "/ChapterFour/0700~0799/0744.Find-Smallest-Letter-Greater-Than-Target.md" >}})|Easy||||45.8%| +|0778|Swim in Rising Water|[Go]({{< relref "/ChapterFour/0700~0799/0778.Swim-in-Rising-Water.md" >}})|Hard||||59.8%| +|0786|K-th Smallest Prime Fraction|[Go]({{< relref "/ChapterFour/0700~0799/0786.K-th-Smallest-Prime-Fraction.md" >}})|Medium||||51.7%| +|0793|Preimage Size of Factorial Zeroes Function|[Go]({{< relref "/ChapterFour/0700~0799/0793.Preimage-Size-of-Factorial-Zeroes-Function.md" >}})|Hard||||43.2%| +|0825|Friends Of Appropriate Ages|[Go]({{< relref "/ChapterFour/0800~0899/0825.Friends-Of-Appropriate-Ages.md" >}})|Medium||||46.3%| +|0826|Most Profit Assigning Work|[Go]({{< relref "/ChapterFour/0800~0899/0826.Most-Profit-Assigning-Work.md" >}})|Medium||||44.9%| +|0852|Peak Index in a Mountain Array|[Go]({{< relref "/ChapterFour/0800~0899/0852.Peak-Index-in-a-Mountain-Array.md" >}})|Medium||||69.0%| +|0862|Shortest Subarray with Sum at Least K|[Go]({{< relref "/ChapterFour/0800~0899/0862.Shortest-Subarray-with-Sum-at-Least-K.md" >}})|Hard||||26.0%| +|0875|Koko Eating Bananas|[Go]({{< relref "/ChapterFour/0800~0899/0875.Koko-Eating-Bananas.md" >}})|Medium||||52.1%| +|0878|Nth Magical Number|[Go]({{< relref "/ChapterFour/0800~0899/0878.Nth-Magical-Number.md" >}})|Hard||||35.4%| +|0887|Super Egg Drop|[Go]({{< relref "/ChapterFour/0800~0899/0887.Super-Egg-Drop.md" >}})|Hard||||27.1%| +|0888|Fair Candy Swap|[Go]({{< relref "/ChapterFour/0800~0899/0888.Fair-Candy-Swap.md" >}})|Easy||||60.7%| +|0911|Online Election|[Go]({{< relref "/ChapterFour/0900~0999/0911.Online-Election.md" >}})|Medium||||52.2%| +|0981|Time Based Key-Value Store|[Go]({{< relref "/ChapterFour/0900~0999/0981.Time-Based-Key-Value-Store.md" >}})|Medium||||52.2%| +|1004|Max Consecutive Ones III|[Go]({{< relref "/ChapterFour/1000~1099/1004.Max-Consecutive-Ones-III.md" >}})|Medium||||63.2%| +|1011|Capacity To Ship Packages Within D Days|[Go]({{< relref "/ChapterFour/1000~1099/1011.Capacity-To-Ship-Packages-Within-D-Days.md" >}})|Medium||||67.7%| +|1157|Online Majority Element In Subarray|[Go]({{< relref "/ChapterFour/1100~1199/1157.Online-Majority-Element-In-Subarray.md" >}})|Hard||||41.8%| +|1170|Compare Strings by Frequency of the Smallest Character|[Go]({{< relref "/ChapterFour/1100~1199/1170.Compare-Strings-by-Frequency-of-the-Smallest-Character.md" >}})|Medium||||61.5%| +|1201|Ugly Number III|[Go]({{< relref "/ChapterFour/1200~1299/1201.Ugly-Number-III.md" >}})|Medium||||28.9%| +|1208|Get Equal Substrings Within Budget|[Go]({{< relref "/ChapterFour/1200~1299/1208.Get-Equal-Substrings-Within-Budget.md" >}})|Medium||||48.6%| +|1235|Maximum Profit in Job Scheduling|[Go]({{< relref "/ChapterFour/1200~1299/1235.Maximum-Profit-in-Job-Scheduling.md" >}})|Hard||||53.4%| +|1283|Find the Smallest Divisor Given a Threshold|[Go]({{< relref "/ChapterFour/1200~1299/1283.Find-the-Smallest-Divisor-Given-a-Threshold.md" >}})|Medium||||56.2%| +|1300|Sum of Mutated Array Closest to Target|[Go]({{< relref "/ChapterFour/1300~1399/1300.Sum-of-Mutated-Array-Closest-to-Target.md" >}})|Medium||||43.6%| +|1337|The K Weakest Rows in a Matrix|[Go]({{< relref "/ChapterFour/1300~1399/1337.The-K-Weakest-Rows-in-a-Matrix.md" >}})|Easy||||72.1%| +|1385|Find the Distance Value Between Two Arrays|[Go]({{< relref "/ChapterFour/1300~1399/1385.Find-the-Distance-Value-Between-Two-Arrays.md" >}})|Easy||||66.6%| +|1439|Find the Kth Smallest Sum of a Matrix With Sorted Rows|[Go]({{< relref "/ChapterFour/1400~1499/1439.Find-the-Kth-Smallest-Sum-of-a-Matrix-With-Sorted-Rows.md" >}})|Hard||||61.4%| +|1482|Minimum Number of Days to Make m Bouquets|[Go]({{< relref "/ChapterFour/1400~1499/1482.Minimum-Number-of-Days-to-Make-m-Bouquets.md" >}})|Medium||||54.0%| +|1539|Kth Missing Positive Number|[Go]({{< relref "/ChapterFour/1500~1599/1539.Kth-Missing-Positive-Number.md" >}})|Easy||||58.6%| +|1608|Special Array With X Elements Greater Than or Equal X|[Go]({{< relref "/ChapterFour/1600~1699/1608.Special-Array-With-X-Elements-Greater-Than-or-Equal-X.md" >}})|Easy||||60.5%| +|1631|Path With Minimum Effort|[Go]({{< relref "/ChapterFour/1600~1699/1631.Path-With-Minimum-Effort.md" >}})|Medium||||55.7%| +|1648|Sell Diminishing-Valued Colored Balls|[Go]({{< relref "/ChapterFour/1600~1699/1648.Sell-Diminishing-Valued-Colored-Balls.md" >}})|Medium||||30.4%| +|1649|Create Sorted Array through Instructions|[Go]({{< relref "/ChapterFour/1600~1699/1649.Create-Sorted-Array-through-Instructions.md" >}})|Hard||||37.5%| +|1658|Minimum Operations to Reduce X to Zero|[Go]({{< relref "/ChapterFour/1600~1699/1658.Minimum-Operations-to-Reduce-X-to-Zero.md" >}})|Medium||||37.6%| +|1818|Minimum Absolute Sum Difference|[Go]({{< relref "/ChapterFour/1800~1899/1818.Minimum-Absolute-Sum-Difference.md" >}})|Medium||||30.4%| |------------|-------------------------------------------------------|-------| ----------------| ---------------|-------------|-------------|-------------| diff --git a/website/content/ChapterTwo/Bit_Manipulation.md b/website/content/ChapterTwo/Bit_Manipulation.md index 5ecaeccac..e1c9ac95d 100644 --- a/website/content/ChapterTwo/Bit_Manipulation.md +++ b/website/content/ChapterTwo/Bit_Manipulation.md @@ -44,44 +44,70 @@ X & ~X = 0 | No. | Title | Solution | Difficulty | TimeComplexity | SpaceComplexity |Favorite| Acceptance | |:--------:|:------- | :--------: | :----------: | :----: | :-----: | :-----: |:-----: | -|0078|Subsets|[Go]({{< relref "/ChapterFour/0001~0099/0078.Subsets.md" >}})|Medium| O(n^2)| O(n)|❤️|65.8%| -|0136|Single Number|[Go]({{< relref "/ChapterFour/0100~0199/0136.Single-Number.md" >}})|Easy| O(n)| O(1)||66.8%| -|0137|Single Number II|[Go]({{< relref "/ChapterFour/0100~0199/0137.Single-Number-II.md" >}})|Medium| O(n)| O(1)|❤️|54.2%| -|0169|Majority Element|[Go]({{< relref "/ChapterFour/0100~0199/0169.Majority-Element.md" >}})|Easy| O(n)| O(1)|❤️|60.3%| -|0187|Repeated DNA Sequences|[Go]({{< relref "/ChapterFour/0100~0199/0187.Repeated-DNA-Sequences.md" >}})|Medium| O(n)| O(1)||41.8%| -|0190|Reverse Bits|[Go]({{< relref "/ChapterFour/0100~0199/0190.Reverse-Bits.md" >}})|Easy| O(n)| O(1)|❤️|42.8%| -|0191|Number of 1 Bits|[Go]({{< relref "/ChapterFour/0100~0199/0191.Number-of-1-Bits.md" >}})|Easy| O(n)| O(1)||54.5%| -|0201|Bitwise AND of Numbers Range|[Go]({{< relref "/ChapterFour/0200~0299/0201.Bitwise-AND-of-Numbers-Range.md" >}})|Medium| O(n)| O(1)|❤️|39.7%| -|0231|Power of Two|[Go]({{< relref "/ChapterFour/0200~0299/0231.Power-of-Two.md" >}})|Easy| O(1)| O(1)||43.8%| -|0260|Single Number III|[Go]({{< relref "/ChapterFour/0200~0299/0260.Single-Number-III.md" >}})|Medium| O(n)| O(1)|❤️|65.5%| -|0268|Missing Number|[Go]({{< relref "/ChapterFour/0200~0299/0268.Missing-Number.md" >}})|Easy| O(n)| O(1)||55.4%| -|0318|Maximum Product of Word Lengths|[Go]({{< relref "/ChapterFour/0300~0399/0318.Maximum-Product-of-Word-Lengths.md" >}})|Medium| O(n)| O(1)||52.6%| -|0338|Counting Bits|[Go]({{< relref "/ChapterFour/0300~0399/0338.Counting-Bits.md" >}})|Medium| O(n)| O(n)||70.7%| -|0342|Power of Four|[Go]({{< relref "/ChapterFour/0300~0399/0342.Power-of-Four.md" >}})|Easy| O(n)| O(1)||41.9%| -|0371|Sum of Two Integers|[Go]({{< relref "/ChapterFour/0300~0399/0371.Sum-of-Two-Integers.md" >}})|Medium| O(n)| O(1)||50.6%| -|0389|Find the Difference|[Go]({{< relref "/ChapterFour/0300~0399/0389.Find-the-Difference.md" >}})|Easy| O(n)| O(1)||58.0%| -|0393|UTF-8 Validation|[Go]({{< relref "/ChapterFour/0300~0399/0393.UTF-8-Validation.md" >}})|Medium| O(n)| O(1)||38.2%| -|0397|Integer Replacement|[Go]({{< relref "/ChapterFour/0300~0399/0397.Integer-Replacement.md" >}})|Medium| O(n)| O(1)||33.6%| -|0401|Binary Watch|[Go]({{< relref "/ChapterFour/0400~0499/0401.Binary-Watch.md" >}})|Easy| O(1)| O(1)||48.7%| -|0405|Convert a Number to Hexadecimal|[Go]({{< relref "/ChapterFour/0400~0499/0405.Convert-a-Number-to-Hexadecimal.md" >}})|Easy| O(n)| O(1)||44.6%| -|0421|Maximum XOR of Two Numbers in an Array|[Go]({{< relref "/ChapterFour/0400~0499/0421.Maximum-XOR-of-Two-Numbers-in-an-Array.md" >}})|Medium| O(n)| O(1)|❤️|54.4%| -|0461|Hamming Distance|[Go]({{< relref "/ChapterFour/0400~0499/0461.Hamming-Distance.md" >}})|Easy| O(n)| O(1)||73.3%| -|0476|Number Complement|[Go]({{< relref "/ChapterFour/0400~0499/0476.Number-Complement.md" >}})|Easy| O(n)| O(1)||65.2%| -|0477|Total Hamming Distance|[Go]({{< relref "/ChapterFour/0400~0499/0477.Total-Hamming-Distance.md" >}})|Medium| O(n)| O(1)||50.7%| -|0693|Binary Number with Alternating Bits|[Go]({{< relref "/ChapterFour/0600~0699/0693.Binary-Number-with-Alternating-Bits.md" >}})|Easy| O(n)| O(1)|❤️|60.0%| -|0756|Pyramid Transition Matrix|[Go]({{< relref "/ChapterFour/0700~0799/0756.Pyramid-Transition-Matrix.md" >}})|Medium| O(n log n)| O(n)||55.7%| -|0762|Prime Number of Set Bits in Binary Representation|[Go]({{< relref "/ChapterFour/0700~0799/0762.Prime-Number-of-Set-Bits-in-Binary-Representation.md" >}})|Easy| O(n)| O(1)||64.7%| -|0784|Letter Case Permutation|[Go]({{< relref "/ChapterFour/0700~0799/0784.Letter-Case-Permutation.md" >}})|Medium| O(n)| O(1)||68.9%| -|0898|Bitwise ORs of Subarrays|[Go]({{< relref "/ChapterFour/0800~0899/0898.Bitwise-ORs-of-Subarrays.md" >}})|Medium| O(n)| O(1)||34.5%| -|1178|Number of Valid Words for Each Puzzle|[Go]({{< relref "/ChapterFour/1100~1199/1178.Number-of-Valid-Words-for-Each-Puzzle.md" >}})|Hard||||39.8%| -|1290|Convert Binary Number in a Linked List to Integer|[Go]({{< relref "/ChapterFour/1200~1299/1290.Convert-Binary-Number-in-a-Linked-List-to-Integer.md" >}})|Easy||||81.7%| -|1461|Check If a String Contains All Binary Codes of Size K|[Go]({{< relref "/ChapterFour/1400~1499/1461.Check-If-a-String-Contains-All-Binary-Codes-of-Size-K.md" >}})|Medium||||54.2%| -|1720|Decode XORed Array|[Go]({{< relref "/ChapterFour/1700~1799/1720.Decode-XORed-Array.md" >}})|Easy||||85.1%| +|0029|Divide Two Integers|[Go]({{< relref "/ChapterFour/0001~0099/0029.Divide-Two-Integers.md" >}})|Medium||||17.2%| +|0067|Add Binary|[Go]({{< relref "/ChapterFour/0001~0099/0067.Add-Binary.md" >}})|Easy||||52.4%| +|0078|Subsets|[Go]({{< relref "/ChapterFour/0001~0099/0078.Subsets.md" >}})|Medium| O(n^2)| O(n)|❤️|74.9%| +|0089|Gray Code|[Go]({{< relref "/ChapterFour/0001~0099/0089.Gray-Code.md" >}})|Medium||||57.2%| +|0090|Subsets II|[Go]({{< relref "/ChapterFour/0001~0099/0090.Subsets-II.md" >}})|Medium||||55.9%| +|0136|Single Number|[Go]({{< relref "/ChapterFour/0100~0199/0136.Single-Number.md" >}})|Easy| O(n)| O(1)||70.7%| +|0137|Single Number II|[Go]({{< relref "/ChapterFour/0100~0199/0137.Single-Number-II.md" >}})|Medium| O(n)| O(1)|❤️|58.5%| +|0187|Repeated DNA Sequences|[Go]({{< relref "/ChapterFour/0100~0199/0187.Repeated-DNA-Sequences.md" >}})|Medium| O(n)| O(1)||47.0%| +|0190|Reverse Bits|[Go]({{< relref "/ChapterFour/0100~0199/0190.Reverse-Bits.md" >}})|Easy| O(n)| O(1)|❤️|54.0%| +|0191|Number of 1 Bits|[Go]({{< relref "/ChapterFour/0100~0199/0191.Number-of-1-Bits.md" >}})|Easy| O(n)| O(1)||66.6%| +|0201|Bitwise AND of Numbers Range|[Go]({{< relref "/ChapterFour/0200~0299/0201.Bitwise-AND-of-Numbers-Range.md" >}})|Medium| O(n)| O(1)|❤️|42.5%| +|0231|Power of Two|[Go]({{< relref "/ChapterFour/0200~0299/0231.Power-of-Two.md" >}})|Easy| O(1)| O(1)||46.0%| +|0260|Single Number III|[Go]({{< relref "/ChapterFour/0200~0299/0260.Single-Number-III.md" >}})|Medium| O(n)| O(1)|❤️|67.7%| +|0268|Missing Number|[Go]({{< relref "/ChapterFour/0200~0299/0268.Missing-Number.md" >}})|Easy| O(n)| O(1)||62.6%| +|0287|Find the Duplicate Number|[Go]({{< relref "/ChapterFour/0200~0299/0287.Find-the-Duplicate-Number.md" >}})|Medium||||59.1%| +|0318|Maximum Product of Word Lengths|[Go]({{< relref "/ChapterFour/0300~0399/0318.Maximum-Product-of-Word-Lengths.md" >}})|Medium| O(n)| O(1)||59.9%| +|0338|Counting Bits|[Go]({{< relref "/ChapterFour/0300~0399/0338.Counting-Bits.md" >}})|Easy| O(n)| O(n)||75.8%| +|0342|Power of Four|[Go]({{< relref "/ChapterFour/0300~0399/0342.Power-of-Four.md" >}})|Easy| O(n)| O(1)||46.2%| +|0371|Sum of Two Integers|[Go]({{< relref "/ChapterFour/0300~0399/0371.Sum-of-Two-Integers.md" >}})|Medium| O(n)| O(1)||50.7%| +|0389|Find the Difference|[Go]({{< relref "/ChapterFour/0300~0399/0389.Find-the-Difference.md" >}})|Easy| O(n)| O(1)||59.9%| +|0393|UTF-8 Validation|[Go]({{< relref "/ChapterFour/0300~0399/0393.UTF-8-Validation.md" >}})|Medium| O(n)| O(1)||45.1%| +|0397|Integer Replacement|[Go]({{< relref "/ChapterFour/0300~0399/0397.Integer-Replacement.md" >}})|Medium| O(n)| O(1)||35.2%| +|0401|Binary Watch|[Go]({{< relref "/ChapterFour/0400~0499/0401.Binary-Watch.md" >}})|Easy| O(1)| O(1)||52.3%| +|0405|Convert a Number to Hexadecimal|[Go]({{< relref "/ChapterFour/0400~0499/0405.Convert-a-Number-to-Hexadecimal.md" >}})|Easy| O(n)| O(1)||46.8%| +|0421|Maximum XOR of Two Numbers in an Array|[Go]({{< relref "/ChapterFour/0400~0499/0421.Maximum-XOR-of-Two-Numbers-in-an-Array.md" >}})|Medium| O(n)| O(1)|❤️|54.0%| +|0461|Hamming Distance|[Go]({{< relref "/ChapterFour/0400~0499/0461.Hamming-Distance.md" >}})|Easy| O(n)| O(1)||75.0%| +|0473|Matchsticks to Square|[Go]({{< relref "/ChapterFour/0400~0499/0473.Matchsticks-to-Square.md" >}})|Medium||||40.2%| +|0476|Number Complement|[Go]({{< relref "/ChapterFour/0400~0499/0476.Number-Complement.md" >}})|Easy| O(n)| O(1)||67.4%| +|0477|Total Hamming Distance|[Go]({{< relref "/ChapterFour/0400~0499/0477.Total-Hamming-Distance.md" >}})|Medium| O(n)| O(1)||52.2%| +|0491|Non-decreasing Subsequences|[Go]({{< relref "/ChapterFour/0400~0499/0491.Non-decreasing-Subsequences.md" >}})|Medium||||60.2%| +|0526|Beautiful Arrangement|[Go]({{< relref "/ChapterFour/0500~0599/0526.Beautiful-Arrangement.md" >}})|Medium||||64.4%| +|0638|Shopping Offers|[Go]({{< relref "/ChapterFour/0600~0699/0638.Shopping-Offers.md" >}})|Medium||||53.3%| +|0645|Set Mismatch|[Go]({{< relref "/ChapterFour/0600~0699/0645.Set-Mismatch.md" >}})|Easy||||42.7%| +|0693|Binary Number with Alternating Bits|[Go]({{< relref "/ChapterFour/0600~0699/0693.Binary-Number-with-Alternating-Bits.md" >}})|Easy| O(n)| O(1)|❤️|61.6%| +|0756|Pyramid Transition Matrix|[Go]({{< relref "/ChapterFour/0700~0799/0756.Pyramid-Transition-Matrix.md" >}})|Medium| O(n log n)| O(n)||52.7%| +|0762|Prime Number of Set Bits in Binary Representation|[Go]({{< relref "/ChapterFour/0700~0799/0762.Prime-Number-of-Set-Bits-in-Binary-Representation.md" >}})|Easy| O(n)| O(1)||68.0%| +|0784|Letter Case Permutation|[Go]({{< relref "/ChapterFour/0700~0799/0784.Letter-Case-Permutation.md" >}})|Medium| O(n)| O(1)||73.8%| +|0810|Chalkboard XOR Game|[Go]({{< relref "/ChapterFour/0800~0899/0810.Chalkboard-XOR-Game.md" >}})|Hard||||55.8%| +|0864|Shortest Path to Get All Keys|[Go]({{< relref "/ChapterFour/0800~0899/0864.Shortest-Path-to-Get-All-Keys.md" >}})|Hard||||45.6%| +|0898|Bitwise ORs of Subarrays|[Go]({{< relref "/ChapterFour/0800~0899/0898.Bitwise-ORs-of-Subarrays.md" >}})|Medium| O(n)| O(1)||37.2%| +|0980|Unique Paths III|[Go]({{< relref "/ChapterFour/0900~0999/0980.Unique-Paths-III.md" >}})|Hard||||81.7%| +|0995|Minimum Number of K Consecutive Bit Flips|[Go]({{< relref "/ChapterFour/0900~0999/0995.Minimum-Number-of-K-Consecutive-Bit-Flips.md" >}})|Hard||||51.2%| +|0996|Number of Squareful Arrays|[Go]({{< relref "/ChapterFour/0900~0999/0996.Number-of-Squareful-Arrays.md" >}})|Hard||||49.2%| +|1009|Complement of Base 10 Integer|[Go]({{< relref "/ChapterFour/1000~1099/1009.Complement-of-Base-10-Integer.md" >}})|Easy||||61.5%| +|1178|Number of Valid Words for Each Puzzle|[Go]({{< relref "/ChapterFour/1100~1199/1178.Number-of-Valid-Words-for-Each-Puzzle.md" >}})|Hard||||46.3%| +|1239|Maximum Length of a Concatenated String with Unique Characters|[Go]({{< relref "/ChapterFour/1200~1299/1239.Maximum-Length-of-a-Concatenated-String-with-Unique-Characters.md" >}})|Medium||||52.2%| +|1310|XOR Queries of a Subarray|[Go]({{< relref "/ChapterFour/1300~1399/1310.XOR-Queries-of-a-Subarray.md" >}})|Medium||||72.3%| +|1442|Count Triplets That Can Form Two Arrays of Equal XOR|[Go]({{< relref "/ChapterFour/1400~1499/1442.Count-Triplets-That-Can-Form-Two-Arrays-of-Equal-XOR.md" >}})|Medium||||76.1%| +|1461|Check If a String Contains All Binary Codes of Size K|[Go]({{< relref "/ChapterFour/1400~1499/1461.Check-If-a-String-Contains-All-Binary-Codes-of-Size-K.md" >}})|Medium||||56.6%| +|1486|XOR Operation in an Array|[Go]({{< relref "/ChapterFour/1400~1499/1486.XOR-Operation-in-an-Array.md" >}})|Easy||||84.6%| +|1655|Distribute Repeating Integers|[Go]({{< relref "/ChapterFour/1600~1699/1655.Distribute-Repeating-Integers.md" >}})|Hard||||39.3%| +|1659|Maximize Grid Happiness|[Go]({{< relref "/ChapterFour/1600~1699/1659.Maximize-Grid-Happiness.md" >}})|Hard||||38.8%| +|1680|Concatenation of Consecutive Binary Numbers|[Go]({{< relref "/ChapterFour/1600~1699/1680.Concatenation-of-Consecutive-Binary-Numbers.md" >}})|Medium||||57.0%| +|1681|Minimum Incompatibility|[Go]({{< relref "/ChapterFour/1600~1699/1681.Minimum-Incompatibility.md" >}})|Hard||||37.8%| +|1684|Count the Number of Consistent Strings|[Go]({{< relref "/ChapterFour/1600~1699/1684.Count-the-Number-of-Consistent-Strings.md" >}})|Easy||||82.3%| +|1720|Decode XORed Array|[Go]({{< relref "/ChapterFour/1700~1799/1720.Decode-XORed-Array.md" >}})|Easy||||85.8%| +|1734|Decode XORed Permutation|[Go]({{< relref "/ChapterFour/1700~1799/1734.Decode-XORed-Permutation.md" >}})|Medium||||63.0%| +|1738|Find Kth Largest XOR Coordinate Value|[Go]({{< relref "/ChapterFour/1700~1799/1738.Find-Kth-Largest-XOR-Coordinate-Value.md" >}})|Medium||||61.0%| +|1763|Longest Nice Substring|[Go]({{< relref "/ChapterFour/1700~1799/1763.Longest-Nice-Substring.md" >}})|Easy||||61.5%| |------------|-------------------------------------------------------|-------| ----------------| ---------------|-------------|-------------|-------------| ---------------------------------------------- diff --git a/website/content/ChapterTwo/Breadth_First_Search.md b/website/content/ChapterTwo/Breadth_First_Search.md index 665dc3ad8..631b6dff9 100644 --- a/website/content/ChapterTwo/Breadth_First_Search.md +++ b/website/content/ChapterTwo/Breadth_First_Search.md @@ -9,33 +9,86 @@ weight: 10 | No. | Title | Solution | Difficulty | TimeComplexity | SpaceComplexity |Favorite| Acceptance | |:--------:|:------- | :--------: | :----------: | :----: | :-----: | :-----: |:-----: | -|0101|Symmetric Tree|[Go]({{< relref "/ChapterFour/0100~0199/0101.Symmetric-Tree.md" >}})|Easy| O(n)| O(1)||48.6%| -|0102|Binary Tree Level Order Traversal|[Go]({{< relref "/ChapterFour/0100~0199/0102.Binary-Tree-Level-Order-Traversal.md" >}})|Medium| O(n)| O(1)||57.1%| -|0103|Binary Tree Zigzag Level Order Traversal|[Go]({{< relref "/ChapterFour/0100~0199/0103.Binary-Tree-Zigzag-Level-Order-Traversal.md" >}})|Medium| O(n)| O(n)||50.6%| -|0107|Binary Tree Level Order Traversal II|[Go]({{< relref "/ChapterFour/0100~0199/0107.Binary-Tree-Level-Order-Traversal-II.md" >}})|Medium| O(n)| O(1)||55.6%| -|0111|Minimum Depth of Binary Tree|[Go]({{< relref "/ChapterFour/0100~0199/0111.Minimum-Depth-of-Binary-Tree.md" >}})|Easy| O(n)| O(1)||39.9%| -|0126|Word Ladder II|[Go]({{< relref "/ChapterFour/0100~0199/0126.Word-Ladder-II.md" >}})|Hard| O(n)| O(n^2)|❤️|23.9%| -|0127|Word Ladder|[Go]({{< relref "/ChapterFour/0100~0199/0127.Word-Ladder.md" >}})|Hard| O(n)| O(n)||32.3%| -|0130|Surrounded Regions|[Go]({{< relref "/ChapterFour/0100~0199/0130.Surrounded-Regions.md" >}})|Medium||||29.9%| -|0199|Binary Tree Right Side View|[Go]({{< relref "/ChapterFour/0100~0199/0199.Binary-Tree-Right-Side-View.md" >}})|Medium| O(n)| O(1)||56.7%| -|0200|Number of Islands|[Go]({{< relref "/ChapterFour/0200~0299/0200.Number-of-Islands.md" >}})|Medium| O(n^2)| O(n^2)||49.7%| -|0207|Course Schedule|[Go]({{< relref "/ChapterFour/0200~0299/0207.Course-Schedule.md" >}})|Medium| O(n^2)| O(n^2)||44.4%| -|0210|Course Schedule II|[Go]({{< relref "/ChapterFour/0200~0299/0210.Course-Schedule-II.md" >}})|Medium| O(n^2)| O(n^2)||43.1%| -|0417|Pacific Atlantic Water Flow|[Go]({{< relref "/ChapterFour/0400~0499/0417.Pacific-Atlantic-Water-Flow.md" >}})|Medium||||44.2%| -|0513|Find Bottom Left Tree Value|[Go]({{< relref "/ChapterFour/0500~0599/0513.Find-Bottom-Left-Tree-Value.md" >}})|Medium||||62.9%| -|0515|Find Largest Value in Each Tree Row|[Go]({{< relref "/ChapterFour/0500~0599/0515.Find-Largest-Value-in-Each-Tree-Row.md" >}})|Medium| O(n)| O(n)||62.5%| -|0529|Minesweeper|[Go]({{< relref "/ChapterFour/0500~0599/0529.Minesweeper.md" >}})|Medium||||61.6%| -|0542|01 Matrix|[Go]({{< relref "/ChapterFour/0500~0599/0542.01-Matrix.md" >}})|Medium| O(n)| O(1)||41.2%| -|0785|Is Graph Bipartite?|[Go]({{< relref "/ChapterFour/0700~0799/0785.Is-Graph-Bipartite.md" >}})|Medium||||48.8%| -|0815|Bus Routes|[Go]({{< relref "/ChapterFour/0800~0899/0815.Bus-Routes.md" >}})|Hard||||43.6%| -|0863|All Nodes Distance K in Binary Tree|[Go]({{< relref "/ChapterFour/0800~0899/0863.All-Nodes-Distance-K-in-Binary-Tree.md" >}})|Medium||||58.3%| -|0864|Shortest Path to Get All Keys|[Go]({{< relref "/ChapterFour/0800~0899/0864.Shortest-Path-to-Get-All-Keys.md" >}})|Hard||||42.5%| -|0987|Vertical Order Traversal of a Binary Tree|[Go]({{< relref "/ChapterFour/0900~0999/0987.Vertical-Order-Traversal-of-a-Binary-Tree.md" >}})|Hard||||39.1%| -|0993|Cousins in Binary Tree|[Go]({{< relref "/ChapterFour/0900~0999/0993.Cousins-in-Binary-Tree.md" >}})|Easy| O(n)| O(1)||52.3%| -|1091|Shortest Path in Binary Matrix|[Go]({{< relref "/ChapterFour/1000~1099/1091.Shortest-Path-in-Binary-Matrix.md" >}})|Medium||||40.2%| -|1306|Jump Game III|[Go]({{< relref "/ChapterFour/1300~1399/1306.Jump-Game-III.md" >}})|Medium||||62.1%| -|1319|Number of Operations to Make Network Connected|[Go]({{< relref "/ChapterFour/1300~1399/1319.Number-of-Operations-to-Make-Network-Connected.md" >}})|Medium||||55.6%| -|1654|Minimum Jumps to Reach Home|[Go]({{< relref "/ChapterFour/1600~1699/1654.Minimum-Jumps-to-Reach-Home.md" >}})|Medium||||24.9%| +|0100|Same Tree|[Go]({{< relref "/ChapterFour/0100~0199/0100.Same-Tree.md" >}})|Easy||||58.2%| +|0101|Symmetric Tree|[Go]({{< relref "/ChapterFour/0100~0199/0101.Symmetric-Tree.md" >}})|Easy| O(n)| O(1)||54.3%| +|0102|Binary Tree Level Order Traversal|[Go]({{< relref "/ChapterFour/0100~0199/0102.Binary-Tree-Level-Order-Traversal.md" >}})|Medium| O(n)| O(1)||64.4%| +|0103|Binary Tree Zigzag Level Order Traversal|[Go]({{< relref "/ChapterFour/0100~0199/0103.Binary-Tree-Zigzag-Level-Order-Traversal.md" >}})|Medium| O(n)| O(n)||56.9%| +|0104|Maximum Depth of Binary Tree|[Go]({{< relref "/ChapterFour/0100~0199/0104.Maximum-Depth-of-Binary-Tree.md" >}})|Easy||||73.9%| +|0107|Binary Tree Level Order Traversal II|[Go]({{< relref "/ChapterFour/0100~0199/0107.Binary-Tree-Level-Order-Traversal-II.md" >}})|Medium| O(n)| O(1)||61.2%| +|0111|Minimum Depth of Binary Tree|[Go]({{< relref "/ChapterFour/0100~0199/0111.Minimum-Depth-of-Binary-Tree.md" >}})|Easy| O(n)| O(1)||44.5%| +|0112|Path Sum|[Go]({{< relref "/ChapterFour/0100~0199/0112.Path-Sum.md" >}})|Easy||||48.3%| +|0116|Populating Next Right Pointers in Each Node|[Go]({{< relref "/ChapterFour/0100~0199/0116.Populating-Next-Right-Pointers-in-Each-Node.md" >}})|Medium||||60.4%| +|0126|Word Ladder II|[Go]({{< relref "/ChapterFour/0100~0199/0126.Word-Ladder-II.md" >}})|Hard| O(n)| O(n^2)|❤️|27.5%| +|0127|Word Ladder|[Go]({{< relref "/ChapterFour/0100~0199/0127.Word-Ladder.md" >}})|Hard| O(n)| O(n)||37.2%| +|0130|Surrounded Regions|[Go]({{< relref "/ChapterFour/0100~0199/0130.Surrounded-Regions.md" >}})|Medium||||36.8%| +|0199|Binary Tree Right Side View|[Go]({{< relref "/ChapterFour/0100~0199/0199.Binary-Tree-Right-Side-View.md" >}})|Medium| O(n)| O(1)||61.6%| +|0200|Number of Islands|[Go]({{< relref "/ChapterFour/0200~0299/0200.Number-of-Islands.md" >}})|Medium| O(n^2)| O(n^2)||57.0%| +|0207|Course Schedule|[Go]({{< relref "/ChapterFour/0200~0299/0207.Course-Schedule.md" >}})|Medium| O(n^2)| O(n^2)||45.4%| +|0210|Course Schedule II|[Go]({{< relref "/ChapterFour/0200~0299/0210.Course-Schedule-II.md" >}})|Medium| O(n^2)| O(n^2)||48.5%| +|0226|Invert Binary Tree|[Go]({{< relref "/ChapterFour/0200~0299/0226.Invert-Binary-Tree.md" >}})|Easy||||74.7%| +|0279|Perfect Squares|[Go]({{< relref "/ChapterFour/0200~0299/0279.Perfect-Squares.md" >}})|Medium||||52.7%| +|0297|Serialize and Deserialize Binary Tree|[Go]({{< relref "/ChapterFour/0200~0299/0297.Serialize-and-Deserialize-Binary-Tree.md" >}})|Hard||||55.4%| +|0301|Remove Invalid Parentheses|[Go]({{< relref "/ChapterFour/0300~0399/0301.Remove-Invalid-Parentheses.md" >}})|Hard||||47.2%| +|0322|Coin Change|[Go]({{< relref "/ChapterFour/0300~0399/0322.Coin-Change.md" >}})|Medium||||42.1%| +|0329|Longest Increasing Path in a Matrix|[Go]({{< relref "/ChapterFour/0300~0399/0329.Longest-Increasing-Path-in-a-Matrix.md" >}})|Hard||||52.4%| +|0399|Evaluate Division|[Go]({{< relref "/ChapterFour/0300~0399/0399.Evaluate-Division.md" >}})|Medium||||59.7%| +|0404|Sum of Left Leaves|[Go]({{< relref "/ChapterFour/0400~0499/0404.Sum-of-Left-Leaves.md" >}})|Easy||||56.7%| +|0417|Pacific Atlantic Water Flow|[Go]({{< relref "/ChapterFour/0400~0499/0417.Pacific-Atlantic-Water-Flow.md" >}})|Medium||||54.4%| +|0429|N-ary Tree Level Order Traversal|[Go]({{< relref "/ChapterFour/0400~0499/0429.N-ary-Tree-Level-Order-Traversal.md" >}})|Medium||||70.7%| +|0433|Minimum Genetic Mutation|[Go]({{< relref "/ChapterFour/0400~0499/0433.Minimum-Genetic-Mutation.md" >}})|Medium||||52.4%| +|0463|Island Perimeter|[Go]({{< relref "/ChapterFour/0400~0499/0463.Island-Perimeter.md" >}})|Easy||||69.7%| +|0488|Zuma Game|[Go]({{< relref "/ChapterFour/0400~0499/0488.Zuma-Game.md" >}})|Hard||||33.9%| +|0513|Find Bottom Left Tree Value|[Go]({{< relref "/ChapterFour/0500~0599/0513.Find-Bottom-Left-Tree-Value.md" >}})|Medium||||66.9%| +|0515|Find Largest Value in Each Tree Row|[Go]({{< relref "/ChapterFour/0500~0599/0515.Find-Largest-Value-in-Each-Tree-Row.md" >}})|Medium| O(n)| O(n)||64.6%| +|0529|Minesweeper|[Go]({{< relref "/ChapterFour/0500~0599/0529.Minesweeper.md" >}})|Medium||||65.7%| +|0530|Minimum Absolute Difference in BST|[Go]({{< relref "/ChapterFour/0500~0599/0530.Minimum-Absolute-Difference-in-BST.md" >}})|Easy||||57.3%| +|0542|01 Matrix|[Go]({{< relref "/ChapterFour/0500~0599/0542.01-Matrix.md" >}})|Medium| O(n)| O(1)||44.8%| +|0547|Number of Provinces|[Go]({{< relref "/ChapterFour/0500~0599/0547.Number-of-Provinces.md" >}})|Medium||||63.8%| +|0559|Maximum Depth of N-ary Tree|[Go]({{< relref "/ChapterFour/0500~0599/0559.Maximum-Depth-of-N-ary-Tree.md" >}})|Easy||||71.7%| +|0617|Merge Two Binary Trees|[Go]({{< relref "/ChapterFour/0600~0699/0617.Merge-Two-Binary-Trees.md" >}})|Easy||||78.7%| +|0623|Add One Row to Tree|[Go]({{< relref "/ChapterFour/0600~0699/0623.Add-One-Row-to-Tree.md" >}})|Medium||||59.5%| +|0637|Average of Levels in Binary Tree|[Go]({{< relref "/ChapterFour/0600~0699/0637.Average-of-Levels-in-Binary-Tree.md" >}})|Easy||||71.7%| +|0653|Two Sum IV - Input is a BST|[Go]({{< relref "/ChapterFour/0600~0699/0653.Two-Sum-IV-Input-is-a-BST.md" >}})|Easy||||61.0%| +|0662|Maximum Width of Binary Tree|[Go]({{< relref "/ChapterFour/0600~0699/0662.Maximum-Width-of-Binary-Tree.md" >}})|Medium||||40.7%| +|0684|Redundant Connection|[Go]({{< relref "/ChapterFour/0600~0699/0684.Redundant-Connection.md" >}})|Medium||||62.2%| +|0685|Redundant Connection II|[Go]({{< relref "/ChapterFour/0600~0699/0685.Redundant-Connection-II.md" >}})|Hard||||34.1%| +|0690|Employee Importance|[Go]({{< relref "/ChapterFour/0600~0699/0690.Employee-Importance.md" >}})|Medium||||65.6%| +|0695|Max Area of Island|[Go]({{< relref "/ChapterFour/0600~0699/0695.Max-Area-of-Island.md" >}})|Medium||||71.8%| +|0721|Accounts Merge|[Go]({{< relref "/ChapterFour/0700~0799/0721.Accounts-Merge.md" >}})|Medium||||56.3%| +|0733|Flood Fill|[Go]({{< relref "/ChapterFour/0700~0799/0733.Flood-Fill.md" >}})|Easy||||62.0%| +|0752|Open the Lock|[Go]({{< relref "/ChapterFour/0700~0799/0752.Open-the-Lock.md" >}})|Medium||||55.6%| +|0756|Pyramid Transition Matrix|[Go]({{< relref "/ChapterFour/0700~0799/0756.Pyramid-Transition-Matrix.md" >}})|Medium||||52.7%| +|0765|Couples Holding Hands|[Go]({{< relref "/ChapterFour/0700~0799/0765.Couples-Holding-Hands.md" >}})|Hard||||56.6%| +|0778|Swim in Rising Water|[Go]({{< relref "/ChapterFour/0700~0799/0778.Swim-in-Rising-Water.md" >}})|Hard||||59.8%| +|0783|Minimum Distance Between BST Nodes|[Go]({{< relref "/ChapterFour/0700~0799/0783.Minimum-Distance-Between-BST-Nodes.md" >}})|Easy||||59.3%| +|0785|Is Graph Bipartite?|[Go]({{< relref "/ChapterFour/0700~0799/0785.Is-Graph-Bipartite.md" >}})|Medium||||53.1%| +|0802|Find Eventual Safe States|[Go]({{< relref "/ChapterFour/0800~0899/0802.Find-Eventual-Safe-States.md" >}})|Medium||||56.6%| +|0815|Bus Routes|[Go]({{< relref "/ChapterFour/0800~0899/0815.Bus-Routes.md" >}})|Hard||||45.6%| +|0839|Similar String Groups|[Go]({{< relref "/ChapterFour/0800~0899/0839.Similar-String-Groups.md" >}})|Hard||||48.0%| +|0841|Keys and Rooms|[Go]({{< relref "/ChapterFour/0800~0899/0841.Keys-and-Rooms.md" >}})|Medium||||71.5%| +|0863|All Nodes Distance K in Binary Tree|[Go]({{< relref "/ChapterFour/0800~0899/0863.All-Nodes-Distance-K-in-Binary-Tree.md" >}})|Medium||||62.3%| +|0864|Shortest Path to Get All Keys|[Go]({{< relref "/ChapterFour/0800~0899/0864.Shortest-Path-to-Get-All-Keys.md" >}})|Hard||||45.6%| +|0909|Snakes and Ladders|[Go]({{< relref "/ChapterFour/0900~0999/0909.Snakes-and-Ladders.md" >}})|Medium||||45.1%| +|0924|Minimize Malware Spread|[Go]({{< relref "/ChapterFour/0900~0999/0924.Minimize-Malware-Spread.md" >}})|Hard||||42.1%| +|0928|Minimize Malware Spread II|[Go]({{< relref "/ChapterFour/0900~0999/0928.Minimize-Malware-Spread-II.md" >}})|Hard||||42.8%| +|0958|Check Completeness of a Binary Tree|[Go]({{< relref "/ChapterFour/0900~0999/0958.Check-Completeness-of-a-Binary-Tree.md" >}})|Medium||||56.2%| +|0959|Regions Cut By Slashes|[Go]({{< relref "/ChapterFour/0900~0999/0959.Regions-Cut-By-Slashes.md" >}})|Medium||||69.1%| +|0987|Vertical Order Traversal of a Binary Tree|[Go]({{< relref "/ChapterFour/0900~0999/0987.Vertical-Order-Traversal-of-a-Binary-Tree.md" >}})|Hard||||45.1%| +|0993|Cousins in Binary Tree|[Go]({{< relref "/ChapterFour/0900~0999/0993.Cousins-in-Binary-Tree.md" >}})|Easy| O(n)| O(1)||54.6%| +|1020|Number of Enclaves|[Go]({{< relref "/ChapterFour/1000~1099/1020.Number-of-Enclaves.md" >}})|Medium||||65.6%| +|1034|Coloring A Border|[Go]({{< relref "/ChapterFour/1000~1099/1034.Coloring-A-Border.md" >}})|Medium||||49.2%| +|1091|Shortest Path in Binary Matrix|[Go]({{< relref "/ChapterFour/1000~1099/1091.Shortest-Path-in-Binary-Matrix.md" >}})|Medium||||44.7%| +|1123|Lowest Common Ancestor of Deepest Leaves|[Go]({{< relref "/ChapterFour/1100~1199/1123.Lowest-Common-Ancestor-of-Deepest-Leaves.md" >}})|Medium||||70.9%| +|1202|Smallest String With Swaps|[Go]({{< relref "/ChapterFour/1200~1299/1202.Smallest-String-With-Swaps.md" >}})|Medium||||57.7%| +|1203|Sort Items by Groups Respecting Dependencies|[Go]({{< relref "/ChapterFour/1200~1299/1203.Sort-Items-by-Groups-Respecting-Dependencies.md" >}})|Hard||||51.2%| +|1254|Number of Closed Islands|[Go]({{< relref "/ChapterFour/1200~1299/1254.Number-of-Closed-Islands.md" >}})|Medium||||66.9%| +|1293|Shortest Path in a Grid with Obstacles Elimination|[Go]({{< relref "/ChapterFour/1200~1299/1293.Shortest-Path-in-a-Grid-with-Obstacles-Elimination.md" >}})|Hard||||45.3%| +|1302|Deepest Leaves Sum|[Go]({{< relref "/ChapterFour/1300~1399/1302.Deepest-Leaves-Sum.md" >}})|Medium||||86.6%| +|1306|Jump Game III|[Go]({{< relref "/ChapterFour/1300~1399/1306.Jump-Game-III.md" >}})|Medium||||63.5%| +|1319|Number of Operations to Make Network Connected|[Go]({{< relref "/ChapterFour/1300~1399/1319.Number-of-Operations-to-Make-Network-Connected.md" >}})|Medium||||62.1%| +|1609|Even Odd Tree|[Go]({{< relref "/ChapterFour/1600~1699/1609.Even-Odd-Tree.md" >}})|Medium||||54.4%| +|1631|Path With Minimum Effort|[Go]({{< relref "/ChapterFour/1600~1699/1631.Path-With-Minimum-Effort.md" >}})|Medium||||55.7%| +|1654|Minimum Jumps to Reach Home|[Go]({{< relref "/ChapterFour/1600~1699/1654.Minimum-Jumps-to-Reach-Home.md" >}})|Medium||||29.1%| |------------|-------------------------------------------------------|-------| ----------------| ---------------|-------------|-------------|-------------| diff --git a/website/content/ChapterTwo/Depth_First_Search.md b/website/content/ChapterTwo/Depth_First_Search.md index 7117203fa..ac15634e1 100644 --- a/website/content/ChapterTwo/Depth_First_Search.md +++ b/website/content/ChapterTwo/Depth_First_Search.md @@ -9,86 +9,113 @@ weight: 9 | No. | Title | Solution | Difficulty | TimeComplexity | SpaceComplexity |Favorite| Acceptance | |:--------:|:------- | :--------: | :----------: | :----: | :-----: | :-----: |:-----: | -|0017|Letter Combinations of a Phone Number|[Go]({{< relref "/ChapterFour/0001~0099/0017.Letter-Combinations-of-a-Phone-Number.md" >}})|Medium||||50.0%| -|0098|Validate Binary Search Tree|[Go]({{< relref "/ChapterFour/0001~0099/0098.Validate-Binary-Search-Tree.md" >}})|Medium| O(n)| O(1)||29.0%| -|0099|Recover Binary Search Tree|[Go]({{< relref "/ChapterFour/0001~0099/0099.Recover-Binary-Search-Tree.md" >}})|Hard| O(n)| O(1)||42.9%| -|0100|Same Tree|[Go]({{< relref "/ChapterFour/0100~0199/0100.Same-Tree.md" >}})|Easy| O(n)| O(1)||54.3%| -|0101|Symmetric Tree|[Go]({{< relref "/ChapterFour/0100~0199/0101.Symmetric-Tree.md" >}})|Easy| O(n)| O(1)||48.6%| -|0104|Maximum Depth of Binary Tree|[Go]({{< relref "/ChapterFour/0100~0199/0104.Maximum-Depth-of-Binary-Tree.md" >}})|Easy| O(n)| O(1)||68.5%| -|0105|Construct Binary Tree from Preorder and Inorder Traversal|[Go]({{< relref "/ChapterFour/0100~0199/0105.Construct-Binary-Tree-from-Preorder-and-Inorder-Traversal.md" >}})|Medium||||52.6%| -|0106|Construct Binary Tree from Inorder and Postorder Traversal|[Go]({{< relref "/ChapterFour/0100~0199/0106.Construct-Binary-Tree-from-Inorder-and-Postorder-Traversal.md" >}})|Medium||||50.3%| -|0108|Convert Sorted Array to Binary Search Tree|[Go]({{< relref "/ChapterFour/0100~0199/0108.Convert-Sorted-Array-to-Binary-Search-Tree.md" >}})|Easy| O(n)| O(1)||61.1%| -|0109|Convert Sorted List to Binary Search Tree|[Go]({{< relref "/ChapterFour/0100~0199/0109.Convert-Sorted-List-to-Binary-Search-Tree.md" >}})|Medium| O(log n)| O(n)||50.8%| -|0110|Balanced Binary Tree|[Go]({{< relref "/ChapterFour/0100~0199/0110.Balanced-Binary-Tree.md" >}})|Easy| O(n)| O(1)||44.9%| -|0111|Minimum Depth of Binary Tree|[Go]({{< relref "/ChapterFour/0100~0199/0111.Minimum-Depth-of-Binary-Tree.md" >}})|Easy| O(n)| O(1)||39.9%| -|0112|Path Sum|[Go]({{< relref "/ChapterFour/0100~0199/0112.Path-Sum.md" >}})|Easy| O(n)| O(1)||42.8%| -|0113|Path Sum II|[Go]({{< relref "/ChapterFour/0100~0199/0113.Path-Sum-II.md" >}})|Medium| O(n)| O(1)||49.7%| -|0114|Flatten Binary Tree to Linked List|[Go]({{< relref "/ChapterFour/0100~0199/0114.Flatten-Binary-Tree-to-Linked-List.md" >}})|Medium| O(n)| O(1)||52.6%| -|0124|Binary Tree Maximum Path Sum|[Go]({{< relref "/ChapterFour/0100~0199/0124.Binary-Tree-Maximum-Path-Sum.md" >}})|Hard| O(n)| O(1)||35.7%| -|0129|Sum Root to Leaf Numbers|[Go]({{< relref "/ChapterFour/0100~0199/0129.Sum-Root-to-Leaf-Numbers.md" >}})|Medium| O(n)| O(1)||51.5%| -|0130|Surrounded Regions|[Go]({{< relref "/ChapterFour/0100~0199/0130.Surrounded-Regions.md" >}})|Medium||||29.9%| -|0131|Palindrome Partitioning|[Go]({{< relref "/ChapterFour/0100~0199/0131.Palindrome-Partitioning.md" >}})|Medium||||52.9%| -|0199|Binary Tree Right Side View|[Go]({{< relref "/ChapterFour/0100~0199/0199.Binary-Tree-Right-Side-View.md" >}})|Medium| O(n)| O(1)||56.7%| -|0200|Number of Islands|[Go]({{< relref "/ChapterFour/0200~0299/0200.Number-of-Islands.md" >}})|Medium| O(n^2)| O(n^2)||49.7%| -|0207|Course Schedule|[Go]({{< relref "/ChapterFour/0200~0299/0207.Course-Schedule.md" >}})|Medium| O(n^2)| O(n^2)||44.4%| -|0210|Course Schedule II|[Go]({{< relref "/ChapterFour/0200~0299/0210.Course-Schedule-II.md" >}})|Medium| O(n^2)| O(n^2)||43.1%| -|0211|Design Add and Search Words Data Structure|[Go]({{< relref "/ChapterFour/0200~0299/0211.Design-Add-and-Search-Words-Data-Structure.md" >}})|Medium||||40.7%| -|0257|Binary Tree Paths|[Go]({{< relref "/ChapterFour/0200~0299/0257.Binary-Tree-Paths.md" >}})|Easy| O(n)| O(1)||54.3%| -|0329|Longest Increasing Path in a Matrix|[Go]({{< relref "/ChapterFour/0300~0399/0329.Longest-Increasing-Path-in-a-Matrix.md" >}})|Hard||||46.4%| -|0337|House Robber III|[Go]({{< relref "/ChapterFour/0300~0399/0337.House-Robber-III.md" >}})|Medium||||52.0%| -|0394|Decode String|[Go]({{< relref "/ChapterFour/0300~0399/0394.Decode-String.md" >}})|Medium| O(n)| O(n)||53.1%| -|0417|Pacific Atlantic Water Flow|[Go]({{< relref "/ChapterFour/0400~0499/0417.Pacific-Atlantic-Water-Flow.md" >}})|Medium||||44.2%| -|0491|Increasing Subsequences|[Go]({{< relref "/ChapterFour/0400~0499/0491.Increasing-Subsequences.md" >}})|Medium||||47.9%| -|0494|Target Sum|[Go]({{< relref "/ChapterFour/0400~0499/0494.Target-Sum.md" >}})|Medium||||45.6%| -|0513|Find Bottom Left Tree Value|[Go]({{< relref "/ChapterFour/0500~0599/0513.Find-Bottom-Left-Tree-Value.md" >}})|Medium||||62.9%| -|0515|Find Largest Value in Each Tree Row|[Go]({{< relref "/ChapterFour/0500~0599/0515.Find-Largest-Value-in-Each-Tree-Row.md" >}})|Medium| O(n)| O(n)||62.5%| -|0526|Beautiful Arrangement|[Go]({{< relref "/ChapterFour/0500~0599/0526.Beautiful-Arrangement.md" >}})|Medium||||62.2%| -|0529|Minesweeper|[Go]({{< relref "/ChapterFour/0500~0599/0529.Minesweeper.md" >}})|Medium||||61.6%| -|0538|Convert BST to Greater Tree|[Go]({{< relref "/ChapterFour/0500~0599/0538.Convert-BST-to-Greater-Tree.md" >}})|Medium||||60.0%| -|0542|01 Matrix|[Go]({{< relref "/ChapterFour/0500~0599/0542.01-Matrix.md" >}})|Medium| O(n)| O(1)||41.2%| -|0547|Number of Provinces|[Go]({{< relref "/ChapterFour/0500~0599/0547.Number-of-Provinces.md" >}})|Medium||||60.9%| -|0563|Binary Tree Tilt|[Go]({{< relref "/ChapterFour/0500~0599/0563.Binary-Tree-Tilt.md" >}})|Easy||||53.4%| -|0638|Shopping Offers|[Go]({{< relref "/ChapterFour/0600~0699/0638.Shopping-Offers.md" >}})|Medium||||53.3%| -|0685|Redundant Connection II|[Go]({{< relref "/ChapterFour/0600~0699/0685.Redundant-Connection-II.md" >}})|Hard||||33.2%| -|0695|Max Area of Island|[Go]({{< relref "/ChapterFour/0600~0699/0695.Max-Area-of-Island.md" >}})|Medium||||65.3%| -|0721|Accounts Merge|[Go]({{< relref "/ChapterFour/0700~0799/0721.Accounts-Merge.md" >}})|Medium||||52.5%| -|0733|Flood Fill|[Go]({{< relref "/ChapterFour/0700~0799/0733.Flood-Fill.md" >}})|Easy||||56.0%| -|0753|Cracking the Safe|[Go]({{< relref "/ChapterFour/0700~0799/0753.Cracking-the-Safe.md" >}})|Hard||||52.7%| -|0756|Pyramid Transition Matrix|[Go]({{< relref "/ChapterFour/0700~0799/0756.Pyramid-Transition-Matrix.md" >}})|Medium||||55.7%| -|0778|Swim in Rising Water|[Go]({{< relref "/ChapterFour/0700~0799/0778.Swim-in-Rising-Water.md" >}})|Hard||||55.1%| -|0783|Minimum Distance Between BST Nodes|[Go]({{< relref "/ChapterFour/0700~0799/0783.Minimum-Distance-Between-BST-Nodes.md" >}})|Easy||||54.3%| -|0785|Is Graph Bipartite?|[Go]({{< relref "/ChapterFour/0700~0799/0785.Is-Graph-Bipartite.md" >}})|Medium||||48.8%| -|0802|Find Eventual Safe States|[Go]({{< relref "/ChapterFour/0800~0899/0802.Find-Eventual-Safe-States.md" >}})|Medium||||50.1%| -|0834|Sum of Distances in Tree|[Go]({{< relref "/ChapterFour/0800~0899/0834.Sum-of-Distances-in-Tree.md" >}})|Hard||||46.8%| -|0839|Similar String Groups|[Go]({{< relref "/ChapterFour/0800~0899/0839.Similar-String-Groups.md" >}})|Hard||||41.8%| -|0841|Keys and Rooms|[Go]({{< relref "/ChapterFour/0800~0899/0841.Keys-and-Rooms.md" >}})|Medium||||66.5%| -|0851|Loud and Rich|[Go]({{< relref "/ChapterFour/0800~0899/0851.Loud-and-Rich.md" >}})|Medium||||52.9%| -|0863|All Nodes Distance K in Binary Tree|[Go]({{< relref "/ChapterFour/0800~0899/0863.All-Nodes-Distance-K-in-Binary-Tree.md" >}})|Medium||||58.3%| -|0872|Leaf-Similar Trees|[Go]({{< relref "/ChapterFour/0800~0899/0872.Leaf-Similar-Trees.md" >}})|Easy||||64.5%| -|0897|Increasing Order Search Tree|[Go]({{< relref "/ChapterFour/0800~0899/0897.Increasing-Order-Search-Tree.md" >}})|Easy||||74.7%| -|0924|Minimize Malware Spread|[Go]({{< relref "/ChapterFour/0900~0999/0924.Minimize-Malware-Spread.md" >}})|Hard||||41.9%| -|0928|Minimize Malware Spread II|[Go]({{< relref "/ChapterFour/0900~0999/0928.Minimize-Malware-Spread-II.md" >}})|Hard||||41.5%| -|0938|Range Sum of BST|[Go]({{< relref "/ChapterFour/0900~0999/0938.Range-Sum-of-BST.md" >}})|Easy||||83.3%| -|0947|Most Stones Removed with Same Row or Column|[Go]({{< relref "/ChapterFour/0900~0999/0947.Most-Stones-Removed-with-Same-Row-or-Column.md" >}})|Medium||||55.7%| -|0959|Regions Cut By Slashes|[Go]({{< relref "/ChapterFour/0900~0999/0959.Regions-Cut-By-Slashes.md" >}})|Medium||||67.2%| -|0968|Binary Tree Cameras|[Go]({{< relref "/ChapterFour/0900~0999/0968.Binary-Tree-Cameras.md" >}})|Hard||||39.0%| -|0971|Flip Binary Tree To Match Preorder Traversal|[Go]({{< relref "/ChapterFour/0900~0999/0971.Flip-Binary-Tree-To-Match-Preorder-Traversal.md" >}})|Medium||||50.1%| -|0979|Distribute Coins in Binary Tree|[Go]({{< relref "/ChapterFour/0900~0999/0979.Distribute-Coins-in-Binary-Tree.md" >}})|Medium||||70.0%| -|0980|Unique Paths III|[Go]({{< relref "/ChapterFour/0900~0999/0980.Unique-Paths-III.md" >}})|Hard| O(n log n)| O(n)||77.1%| -|0987|Vertical Order Traversal of a Binary Tree|[Go]({{< relref "/ChapterFour/0900~0999/0987.Vertical-Order-Traversal-of-a-Binary-Tree.md" >}})|Hard||||39.1%| -|1020|Number of Enclaves|[Go]({{< relref "/ChapterFour/1000~1099/1020.Number-of-Enclaves.md" >}})|Medium||||59.3%| -|1026|Maximum Difference Between Node and Ancestor|[Go]({{< relref "/ChapterFour/1000~1099/1026.Maximum-Difference-Between-Node-and-Ancestor.md" >}})|Medium||||69.8%| -|1028|Recover a Tree From Preorder Traversal|[Go]({{< relref "/ChapterFour/1000~1099/1028.Recover-a-Tree-From-Preorder-Traversal.md" >}})|Hard||||71.1%| -|1038|Binary Search Tree to Greater Sum Tree|[Go]({{< relref "/ChapterFour/1000~1099/1038.Binary-Search-Tree-to-Greater-Sum-Tree.md" >}})|Medium||||82.7%| -|1110|Delete Nodes And Return Forest|[Go]({{< relref "/ChapterFour/1100~1199/1110.Delete-Nodes-And-Return-Forest.md" >}})|Medium||||67.9%| -|1123|Lowest Common Ancestor of Deepest Leaves|[Go]({{< relref "/ChapterFour/1100~1199/1123.Lowest-Common-Ancestor-of-Deepest-Leaves.md" >}})|Medium||||68.1%| -|1145|Binary Tree Coloring Game|[Go]({{< relref "/ChapterFour/1100~1199/1145.Binary-Tree-Coloring-Game.md" >}})|Medium||||51.2%| -|1203|Sort Items by Groups Respecting Dependencies|[Go]({{< relref "/ChapterFour/1200~1299/1203.Sort-Items-by-Groups-Respecting-Dependencies.md" >}})|Hard||||48.4%| -|1254|Number of Closed Islands|[Go]({{< relref "/ChapterFour/1200~1299/1254.Number-of-Closed-Islands.md" >}})|Medium||||62.0%| -|1302|Deepest Leaves Sum|[Go]({{< relref "/ChapterFour/1300~1399/1302.Deepest-Leaves-Sum.md" >}})|Medium||||85.4%| -|1306|Jump Game III|[Go]({{< relref "/ChapterFour/1300~1399/1306.Jump-Game-III.md" >}})|Medium||||62.1%| -|1319|Number of Operations to Make Network Connected|[Go]({{< relref "/ChapterFour/1300~1399/1319.Number-of-Operations-to-Make-Network-Connected.md" >}})|Medium||||55.6%| -|1631|Path With Minimum Effort|[Go]({{< relref "/ChapterFour/1600~1699/1631.Path-With-Minimum-Effort.md" >}})|Medium||||50.0%| +|0094|Binary Tree Inorder Traversal|[Go]({{< relref "/ChapterFour/0001~0099/0094.Binary-Tree-Inorder-Traversal.md" >}})|Easy||||73.8%| +|0098|Validate Binary Search Tree|[Go]({{< relref "/ChapterFour/0001~0099/0098.Validate-Binary-Search-Tree.md" >}})|Medium| O(n)| O(1)||32.0%| +|0099|Recover Binary Search Tree|[Go]({{< relref "/ChapterFour/0001~0099/0099.Recover-Binary-Search-Tree.md" >}})|Medium| O(n)| O(1)||51.0%| +|0100|Same Tree|[Go]({{< relref "/ChapterFour/0100~0199/0100.Same-Tree.md" >}})|Easy| O(n)| O(1)||58.2%| +|0101|Symmetric Tree|[Go]({{< relref "/ChapterFour/0100~0199/0101.Symmetric-Tree.md" >}})|Easy| O(n)| O(1)||54.3%| +|0104|Maximum Depth of Binary Tree|[Go]({{< relref "/ChapterFour/0100~0199/0104.Maximum-Depth-of-Binary-Tree.md" >}})|Easy| O(n)| O(1)||73.9%| +|0110|Balanced Binary Tree|[Go]({{< relref "/ChapterFour/0100~0199/0110.Balanced-Binary-Tree.md" >}})|Easy| O(n)| O(1)||49.1%| +|0111|Minimum Depth of Binary Tree|[Go]({{< relref "/ChapterFour/0100~0199/0111.Minimum-Depth-of-Binary-Tree.md" >}})|Easy| O(n)| O(1)||44.5%| +|0112|Path Sum|[Go]({{< relref "/ChapterFour/0100~0199/0112.Path-Sum.md" >}})|Easy| O(n)| O(1)||48.3%| +|0113|Path Sum II|[Go]({{< relref "/ChapterFour/0100~0199/0113.Path-Sum-II.md" >}})|Medium| O(n)| O(1)||57.1%| +|0114|Flatten Binary Tree to Linked List|[Go]({{< relref "/ChapterFour/0100~0199/0114.Flatten-Binary-Tree-to-Linked-List.md" >}})|Medium| O(n)| O(1)||61.8%| +|0116|Populating Next Right Pointers in Each Node|[Go]({{< relref "/ChapterFour/0100~0199/0116.Populating-Next-Right-Pointers-in-Each-Node.md" >}})|Medium||||60.4%| +|0124|Binary Tree Maximum Path Sum|[Go]({{< relref "/ChapterFour/0100~0199/0124.Binary-Tree-Maximum-Path-Sum.md" >}})|Hard| O(n)| O(1)||39.2%| +|0129|Sum Root to Leaf Numbers|[Go]({{< relref "/ChapterFour/0100~0199/0129.Sum-Root-to-Leaf-Numbers.md" >}})|Medium| O(n)| O(1)||61.0%| +|0130|Surrounded Regions|[Go]({{< relref "/ChapterFour/0100~0199/0130.Surrounded-Regions.md" >}})|Medium||||36.8%| +|0144|Binary Tree Preorder Traversal|[Go]({{< relref "/ChapterFour/0100~0199/0144.Binary-Tree-Preorder-Traversal.md" >}})|Easy||||66.9%| +|0145|Binary Tree Postorder Traversal|[Go]({{< relref "/ChapterFour/0100~0199/0145.Binary-Tree-Postorder-Traversal.md" >}})|Easy||||68.0%| +|0199|Binary Tree Right Side View|[Go]({{< relref "/ChapterFour/0100~0199/0199.Binary-Tree-Right-Side-View.md" >}})|Medium| O(n)| O(1)||61.6%| +|0200|Number of Islands|[Go]({{< relref "/ChapterFour/0200~0299/0200.Number-of-Islands.md" >}})|Medium| O(n^2)| O(n^2)||57.0%| +|0207|Course Schedule|[Go]({{< relref "/ChapterFour/0200~0299/0207.Course-Schedule.md" >}})|Medium| O(n^2)| O(n^2)||45.4%| +|0210|Course Schedule II|[Go]({{< relref "/ChapterFour/0200~0299/0210.Course-Schedule-II.md" >}})|Medium| O(n^2)| O(n^2)||48.5%| +|0211|Design Add and Search Words Data Structure|[Go]({{< relref "/ChapterFour/0200~0299/0211.Design-Add-and-Search-Words-Data-Structure.md" >}})|Medium||||44.0%| +|0222|Count Complete Tree Nodes|[Go]({{< relref "/ChapterFour/0200~0299/0222.Count-Complete-Tree-Nodes.md" >}})|Medium||||60.6%| +|0226|Invert Binary Tree|[Go]({{< relref "/ChapterFour/0200~0299/0226.Invert-Binary-Tree.md" >}})|Easy||||74.7%| +|0230|Kth Smallest Element in a BST|[Go]({{< relref "/ChapterFour/0200~0299/0230.Kth-Smallest-Element-in-a-BST.md" >}})|Medium||||70.2%| +|0235|Lowest Common Ancestor of a Binary Search Tree|[Go]({{< relref "/ChapterFour/0200~0299/0235.Lowest-Common-Ancestor-of-a-Binary-Search-Tree.md" >}})|Medium||||61.6%| +|0236|Lowest Common Ancestor of a Binary Tree|[Go]({{< relref "/ChapterFour/0200~0299/0236.Lowest-Common-Ancestor-of-a-Binary-Tree.md" >}})|Medium||||58.8%| +|0257|Binary Tree Paths|[Go]({{< relref "/ChapterFour/0200~0299/0257.Binary-Tree-Paths.md" >}})|Easy| O(n)| O(1)||61.4%| +|0297|Serialize and Deserialize Binary Tree|[Go]({{< relref "/ChapterFour/0200~0299/0297.Serialize-and-Deserialize-Binary-Tree.md" >}})|Hard||||55.4%| +|0329|Longest Increasing Path in a Matrix|[Go]({{< relref "/ChapterFour/0300~0399/0329.Longest-Increasing-Path-in-a-Matrix.md" >}})|Hard||||52.4%| +|0337|House Robber III|[Go]({{< relref "/ChapterFour/0300~0399/0337.House-Robber-III.md" >}})|Medium||||53.9%| +|0341|Flatten Nested List Iterator|[Go]({{< relref "/ChapterFour/0300~0399/0341.Flatten-Nested-List-Iterator.md" >}})|Medium||||61.8%| +|0385|Mini Parser|[Go]({{< relref "/ChapterFour/0300~0399/0385.Mini-Parser.md" >}})|Medium||||36.9%| +|0386|Lexicographical Numbers|[Go]({{< relref "/ChapterFour/0300~0399/0386.Lexicographical-Numbers.md" >}})|Medium||||61.6%| +|0399|Evaluate Division|[Go]({{< relref "/ChapterFour/0300~0399/0399.Evaluate-Division.md" >}})|Medium||||59.7%| +|0404|Sum of Left Leaves|[Go]({{< relref "/ChapterFour/0400~0499/0404.Sum-of-Left-Leaves.md" >}})|Easy||||56.7%| +|0417|Pacific Atlantic Water Flow|[Go]({{< relref "/ChapterFour/0400~0499/0417.Pacific-Atlantic-Water-Flow.md" >}})|Medium||||54.4%| +|0419|Battleships in a Board|[Go]({{< relref "/ChapterFour/0400~0499/0419.Battleships-in-a-Board.md" >}})|Medium||||74.8%| +|0437|Path Sum III|[Go]({{< relref "/ChapterFour/0400~0499/0437.Path-Sum-III.md" >}})|Medium||||48.0%| +|0463|Island Perimeter|[Go]({{< relref "/ChapterFour/0400~0499/0463.Island-Perimeter.md" >}})|Easy||||69.7%| +|0508|Most Frequent Subtree Sum|[Go]({{< relref "/ChapterFour/0500~0599/0508.Most-Frequent-Subtree-Sum.md" >}})|Medium||||64.9%| +|0513|Find Bottom Left Tree Value|[Go]({{< relref "/ChapterFour/0500~0599/0513.Find-Bottom-Left-Tree-Value.md" >}})|Medium||||66.9%| +|0515|Find Largest Value in Each Tree Row|[Go]({{< relref "/ChapterFour/0500~0599/0515.Find-Largest-Value-in-Each-Tree-Row.md" >}})|Medium| O(n)| O(n)||64.6%| +|0529|Minesweeper|[Go]({{< relref "/ChapterFour/0500~0599/0529.Minesweeper.md" >}})|Medium||||65.7%| +|0530|Minimum Absolute Difference in BST|[Go]({{< relref "/ChapterFour/0500~0599/0530.Minimum-Absolute-Difference-in-BST.md" >}})|Easy||||57.3%| +|0538|Convert BST to Greater Tree|[Go]({{< relref "/ChapterFour/0500~0599/0538.Convert-BST-to-Greater-Tree.md" >}})|Medium||||67.8%| +|0543|Diameter of Binary Tree|[Go]({{< relref "/ChapterFour/0500~0599/0543.Diameter-of-Binary-Tree.md" >}})|Easy||||56.8%| +|0547|Number of Provinces|[Go]({{< relref "/ChapterFour/0500~0599/0547.Number-of-Provinces.md" >}})|Medium||||63.8%| +|0559|Maximum Depth of N-ary Tree|[Go]({{< relref "/ChapterFour/0500~0599/0559.Maximum-Depth-of-N-ary-Tree.md" >}})|Easy||||71.7%| +|0563|Binary Tree Tilt|[Go]({{< relref "/ChapterFour/0500~0599/0563.Binary-Tree-Tilt.md" >}})|Easy||||60.1%| +|0572|Subtree of Another Tree|[Go]({{< relref "/ChapterFour/0500~0599/0572.Subtree-of-Another-Tree.md" >}})|Easy||||46.4%| +|0589|N-ary Tree Preorder Traversal|[Go]({{< relref "/ChapterFour/0500~0599/0589.N-ary-Tree-Preorder-Traversal.md" >}})|Easy||||75.8%| +|0617|Merge Two Binary Trees|[Go]({{< relref "/ChapterFour/0600~0699/0617.Merge-Two-Binary-Trees.md" >}})|Easy||||78.7%| +|0623|Add One Row to Tree|[Go]({{< relref "/ChapterFour/0600~0699/0623.Add-One-Row-to-Tree.md" >}})|Medium||||59.5%| +|0637|Average of Levels in Binary Tree|[Go]({{< relref "/ChapterFour/0600~0699/0637.Average-of-Levels-in-Binary-Tree.md" >}})|Easy||||71.7%| +|0653|Two Sum IV - Input is a BST|[Go]({{< relref "/ChapterFour/0600~0699/0653.Two-Sum-IV-Input-is-a-BST.md" >}})|Easy||||61.0%| +|0662|Maximum Width of Binary Tree|[Go]({{< relref "/ChapterFour/0600~0699/0662.Maximum-Width-of-Binary-Tree.md" >}})|Medium||||40.7%| +|0669|Trim a Binary Search Tree|[Go]({{< relref "/ChapterFour/0600~0699/0669.Trim-a-Binary-Search-Tree.md" >}})|Medium||||66.4%| +|0684|Redundant Connection|[Go]({{< relref "/ChapterFour/0600~0699/0684.Redundant-Connection.md" >}})|Medium||||62.2%| +|0685|Redundant Connection II|[Go]({{< relref "/ChapterFour/0600~0699/0685.Redundant-Connection-II.md" >}})|Hard||||34.1%| +|0690|Employee Importance|[Go]({{< relref "/ChapterFour/0600~0699/0690.Employee-Importance.md" >}})|Medium||||65.6%| +|0695|Max Area of Island|[Go]({{< relref "/ChapterFour/0600~0699/0695.Max-Area-of-Island.md" >}})|Medium||||71.8%| +|0721|Accounts Merge|[Go]({{< relref "/ChapterFour/0700~0799/0721.Accounts-Merge.md" >}})|Medium||||56.3%| +|0733|Flood Fill|[Go]({{< relref "/ChapterFour/0700~0799/0733.Flood-Fill.md" >}})|Easy||||62.0%| +|0753|Cracking the Safe|[Go]({{< relref "/ChapterFour/0700~0799/0753.Cracking-the-Safe.md" >}})|Hard||||55.8%| +|0756|Pyramid Transition Matrix|[Go]({{< relref "/ChapterFour/0700~0799/0756.Pyramid-Transition-Matrix.md" >}})|Medium||||52.7%| +|0765|Couples Holding Hands|[Go]({{< relref "/ChapterFour/0700~0799/0765.Couples-Holding-Hands.md" >}})|Hard||||56.6%| +|0778|Swim in Rising Water|[Go]({{< relref "/ChapterFour/0700~0799/0778.Swim-in-Rising-Water.md" >}})|Hard||||59.8%| +|0783|Minimum Distance Between BST Nodes|[Go]({{< relref "/ChapterFour/0700~0799/0783.Minimum-Distance-Between-BST-Nodes.md" >}})|Easy||||59.3%| +|0785|Is Graph Bipartite?|[Go]({{< relref "/ChapterFour/0700~0799/0785.Is-Graph-Bipartite.md" >}})|Medium||||53.1%| +|0802|Find Eventual Safe States|[Go]({{< relref "/ChapterFour/0800~0899/0802.Find-Eventual-Safe-States.md" >}})|Medium||||56.6%| +|0834|Sum of Distances in Tree|[Go]({{< relref "/ChapterFour/0800~0899/0834.Sum-of-Distances-in-Tree.md" >}})|Hard||||59.1%| +|0839|Similar String Groups|[Go]({{< relref "/ChapterFour/0800~0899/0839.Similar-String-Groups.md" >}})|Hard||||48.0%| +|0841|Keys and Rooms|[Go]({{< relref "/ChapterFour/0800~0899/0841.Keys-and-Rooms.md" >}})|Medium||||71.5%| +|0851|Loud and Rich|[Go]({{< relref "/ChapterFour/0800~0899/0851.Loud-and-Rich.md" >}})|Medium||||58.4%| +|0863|All Nodes Distance K in Binary Tree|[Go]({{< relref "/ChapterFour/0800~0899/0863.All-Nodes-Distance-K-in-Binary-Tree.md" >}})|Medium||||62.3%| +|0872|Leaf-Similar Trees|[Go]({{< relref "/ChapterFour/0800~0899/0872.Leaf-Similar-Trees.md" >}})|Easy||||67.6%| +|0897|Increasing Order Search Tree|[Go]({{< relref "/ChapterFour/0800~0899/0897.Increasing-Order-Search-Tree.md" >}})|Easy||||78.4%| +|0924|Minimize Malware Spread|[Go]({{< relref "/ChapterFour/0900~0999/0924.Minimize-Malware-Spread.md" >}})|Hard||||42.1%| +|0928|Minimize Malware Spread II|[Go]({{< relref "/ChapterFour/0900~0999/0928.Minimize-Malware-Spread-II.md" >}})|Hard||||42.8%| +|0938|Range Sum of BST|[Go]({{< relref "/ChapterFour/0900~0999/0938.Range-Sum-of-BST.md" >}})|Easy||||85.9%| +|0947|Most Stones Removed with Same Row or Column|[Go]({{< relref "/ChapterFour/0900~0999/0947.Most-Stones-Removed-with-Same-Row-or-Column.md" >}})|Medium||||58.9%| +|0959|Regions Cut By Slashes|[Go]({{< relref "/ChapterFour/0900~0999/0959.Regions-Cut-By-Slashes.md" >}})|Medium||||69.1%| +|0968|Binary Tree Cameras|[Go]({{< relref "/ChapterFour/0900~0999/0968.Binary-Tree-Cameras.md" >}})|Hard||||46.6%| +|0971|Flip Binary Tree To Match Preorder Traversal|[Go]({{< relref "/ChapterFour/0900~0999/0971.Flip-Binary-Tree-To-Match-Preorder-Traversal.md" >}})|Medium||||50.0%| +|0979|Distribute Coins in Binary Tree|[Go]({{< relref "/ChapterFour/0900~0999/0979.Distribute-Coins-in-Binary-Tree.md" >}})|Medium||||72.2%| +|0987|Vertical Order Traversal of a Binary Tree|[Go]({{< relref "/ChapterFour/0900~0999/0987.Vertical-Order-Traversal-of-a-Binary-Tree.md" >}})|Hard||||45.1%| +|0993|Cousins in Binary Tree|[Go]({{< relref "/ChapterFour/0900~0999/0993.Cousins-in-Binary-Tree.md" >}})|Easy||||54.6%| +|1020|Number of Enclaves|[Go]({{< relref "/ChapterFour/1000~1099/1020.Number-of-Enclaves.md" >}})|Medium||||65.6%| +|1022|Sum of Root To Leaf Binary Numbers|[Go]({{< relref "/ChapterFour/1000~1099/1022.Sum-of-Root-To-Leaf-Binary-Numbers.md" >}})|Easy||||73.5%| +|1026|Maximum Difference Between Node and Ancestor|[Go]({{< relref "/ChapterFour/1000~1099/1026.Maximum-Difference-Between-Node-and-Ancestor.md" >}})|Medium||||75.8%| +|1028|Recover a Tree From Preorder Traversal|[Go]({{< relref "/ChapterFour/1000~1099/1028.Recover-a-Tree-From-Preorder-Traversal.md" >}})|Hard||||73.3%| +|1034|Coloring A Border|[Go]({{< relref "/ChapterFour/1000~1099/1034.Coloring-A-Border.md" >}})|Medium||||49.2%| +|1038|Binary Search Tree to Greater Sum Tree|[Go]({{< relref "/ChapterFour/1000~1099/1038.Binary-Search-Tree-to-Greater-Sum-Tree.md" >}})|Medium||||85.5%| +|1110|Delete Nodes And Return Forest|[Go]({{< relref "/ChapterFour/1100~1199/1110.Delete-Nodes-And-Return-Forest.md" >}})|Medium||||69.3%| +|1123|Lowest Common Ancestor of Deepest Leaves|[Go]({{< relref "/ChapterFour/1100~1199/1123.Lowest-Common-Ancestor-of-Deepest-Leaves.md" >}})|Medium||||70.9%| +|1145|Binary Tree Coloring Game|[Go]({{< relref "/ChapterFour/1100~1199/1145.Binary-Tree-Coloring-Game.md" >}})|Medium||||51.7%| +|1202|Smallest String With Swaps|[Go]({{< relref "/ChapterFour/1200~1299/1202.Smallest-String-With-Swaps.md" >}})|Medium||||57.7%| +|1203|Sort Items by Groups Respecting Dependencies|[Go]({{< relref "/ChapterFour/1200~1299/1203.Sort-Items-by-Groups-Respecting-Dependencies.md" >}})|Hard||||51.2%| +|1254|Number of Closed Islands|[Go]({{< relref "/ChapterFour/1200~1299/1254.Number-of-Closed-Islands.md" >}})|Medium||||66.9%| +|1302|Deepest Leaves Sum|[Go]({{< relref "/ChapterFour/1300~1399/1302.Deepest-Leaves-Sum.md" >}})|Medium||||86.6%| +|1305|All Elements in Two Binary Search Trees|[Go]({{< relref "/ChapterFour/1300~1399/1305.All-Elements-in-Two-Binary-Search-Trees.md" >}})|Medium||||79.8%| +|1306|Jump Game III|[Go]({{< relref "/ChapterFour/1300~1399/1306.Jump-Game-III.md" >}})|Medium||||63.5%| +|1319|Number of Operations to Make Network Connected|[Go]({{< relref "/ChapterFour/1300~1399/1319.Number-of-Operations-to-Make-Network-Connected.md" >}})|Medium||||62.1%| +|1600|Throne Inheritance|[Go]({{< relref "/ChapterFour/1600~1699/1600.Throne-Inheritance.md" >}})|Medium||||63.6%| +|1631|Path With Minimum Effort|[Go]({{< relref "/ChapterFour/1600~1699/1631.Path-With-Minimum-Effort.md" >}})|Medium||||55.7%| +|2096|Step-By-Step Directions From a Binary Tree Node to Another|[Go]({{< relref "/ChapterFour/2000~2099/2096.Step-By-Step-Directions-From-a-Binary-Tree-Node-to-Another.md" >}})|Medium||||48.5%| |------------|-------------------------------------------------------|-------| ----------------| ---------------|-------------|-------------|-------------| diff --git a/website/content/ChapterTwo/Dynamic_Programming.md b/website/content/ChapterTwo/Dynamic_Programming.md index 1df6f8a1c..79c094207 100644 --- a/website/content/ChapterTwo/Dynamic_Programming.md +++ b/website/content/ChapterTwo/Dynamic_Programming.md @@ -9,71 +9,104 @@ weight: 7 | No. | Title | Solution | Difficulty | TimeComplexity | SpaceComplexity |Favorite| Acceptance | |:--------:|:------- | :--------: | :----------: | :----: | :-----: | :-----: |:-----: | -|0005|Longest Palindromic Substring|[Go]({{< relref "/ChapterFour/0001~0099/0005.Longest-Palindromic-Substring.md" >}})|Medium||||30.7%| -|0032|Longest Valid Parentheses|[Go]({{< relref "/ChapterFour/0001~0099/0032.Longest-Valid-Parentheses.md" >}})|Hard||||29.9%| -|0042|Trapping Rain Water|[Go]({{< relref "/ChapterFour/0001~0099/0042.Trapping-Rain-Water.md" >}})|Hard||||51.8%| -|0053|Maximum Subarray|[Go]({{< relref "/ChapterFour/0001~0099/0053.Maximum-Subarray.md" >}})|Easy| O(n)| O(n)||47.9%| -|0062|Unique Paths|[Go]({{< relref "/ChapterFour/0001~0099/0062.Unique-Paths.md" >}})|Medium| O(n^2)| O(n^2)||56.5%| -|0063|Unique Paths II|[Go]({{< relref "/ChapterFour/0001~0099/0063.Unique-Paths-II.md" >}})|Medium| O(n^2)| O(n^2)||35.4%| -|0064|Minimum Path Sum|[Go]({{< relref "/ChapterFour/0001~0099/0064.Minimum-Path-Sum.md" >}})|Medium| O(n^2)| O(n^2)||56.6%| -|0070|Climbing Stairs|[Go]({{< relref "/ChapterFour/0001~0099/0070.Climbing-Stairs.md" >}})|Easy| O(n)| O(n)||48.8%| -|0091|Decode Ways|[Go]({{< relref "/ChapterFour/0001~0099/0091.Decode-Ways.md" >}})|Medium| O(n)| O(n)||27.0%| -|0095|Unique Binary Search Trees II|[Go]({{< relref "/ChapterFour/0001~0099/0095.Unique-Binary-Search-Trees-II.md" >}})|Medium||||43.2%| -|0096|Unique Binary Search Trees|[Go]({{< relref "/ChapterFour/0001~0099/0096.Unique-Binary-Search-Trees.md" >}})|Medium| O(n)| O(n)||54.8%| -|0115|Distinct Subsequences|[Go]({{< relref "/ChapterFour/0100~0199/0115.Distinct-Subsequences.md" >}})|Hard||||40.1%| -|0120|Triangle|[Go]({{< relref "/ChapterFour/0100~0199/0120.Triangle.md" >}})|Medium| O(n^2)| O(n)||46.9%| -|0121|Best Time to Buy and Sell Stock|[Go]({{< relref "/ChapterFour/0100~0199/0121.Best-Time-to-Buy-and-Sell-Stock.md" >}})|Easy| O(n)| O(1)||51.9%| -|0131|Palindrome Partitioning|[Go]({{< relref "/ChapterFour/0100~0199/0131.Palindrome-Partitioning.md" >}})|Medium||||52.9%| -|0152|Maximum Product Subarray|[Go]({{< relref "/ChapterFour/0100~0199/0152.Maximum-Product-Subarray.md" >}})|Medium| O(n)| O(1)||32.9%| -|0174|Dungeon Game|[Go]({{< relref "/ChapterFour/0100~0199/0174.Dungeon-Game.md" >}})|Hard||||33.5%| -|0198|House Robber|[Go]({{< relref "/ChapterFour/0100~0199/0198.House-Robber.md" >}})|Medium| O(n)| O(n)||43.2%| -|0213|House Robber II|[Go]({{< relref "/ChapterFour/0200~0299/0213.House-Robber-II.md" >}})|Medium| O(n)| O(n)||37.7%| -|0264|Ugly Number II|[Go]({{< relref "/ChapterFour/0200~0299/0264.Ugly-Number-II.md" >}})|Medium||||43.1%| -|0300|Longest Increasing Subsequence|[Go]({{< relref "/ChapterFour/0300~0399/0300.Longest-Increasing-Subsequence.md" >}})|Medium| O(n log n)| O(n)||44.7%| -|0303|Range Sum Query - Immutable|[Go]({{< relref "/ChapterFour/0300~0399/0303.Range-Sum-Query-Immutable.md" >}})|Easy||||48.5%| -|0304|Range Sum Query 2D - Immutable|[Go]({{< relref "/ChapterFour/0300~0399/0304.Range-Sum-Query-2D-Immutable.md" >}})|Medium||||41.4%| -|0309|Best Time to Buy and Sell Stock with Cooldown|[Go]({{< relref "/ChapterFour/0300~0399/0309.Best-Time-to-Buy-and-Sell-Stock-with-Cooldown.md" >}})|Medium| O(n)| O(n)||48.5%| -|0322|Coin Change|[Go]({{< relref "/ChapterFour/0300~0399/0322.Coin-Change.md" >}})|Medium| O(n)| O(n)||37.8%| -|0337|House Robber III|[Go]({{< relref "/ChapterFour/0300~0399/0337.House-Robber-III.md" >}})|Medium||||52.0%| -|0338|Counting Bits|[Go]({{< relref "/ChapterFour/0300~0399/0338.Counting-Bits.md" >}})|Medium| O(n)| O(n)||70.7%| -|0343|Integer Break|[Go]({{< relref "/ChapterFour/0300~0399/0343.Integer-Break.md" >}})|Medium| O(n^2)| O(n)||51.4%| -|0354|Russian Doll Envelopes|[Go]({{< relref "/ChapterFour/0300~0399/0354.Russian-Doll-Envelopes.md" >}})|Hard||||37.8%| -|0357|Count Numbers with Unique Digits|[Go]({{< relref "/ChapterFour/0300~0399/0357.Count-Numbers-with-Unique-Digits.md" >}})|Medium| O(1)| O(1)||49.0%| -|0368|Largest Divisible Subset|[Go]({{< relref "/ChapterFour/0300~0399/0368.Largest-Divisible-Subset.md" >}})|Medium||||38.5%| -|0376|Wiggle Subsequence|[Go]({{< relref "/ChapterFour/0300~0399/0376.Wiggle-Subsequence.md" >}})|Medium||||42.3%| -|0377|Combination Sum IV|[Go]({{< relref "/ChapterFour/0300~0399/0377.Combination-Sum-IV.md" >}})|Medium||||47.1%| -|0392|Is Subsequence|[Go]({{< relref "/ChapterFour/0300~0399/0392.Is-Subsequence.md" >}})|Easy| O(n)| O(1)||49.6%| -|0410|Split Array Largest Sum|[Go]({{< relref "/ChapterFour/0400~0499/0410.Split-Array-Largest-Sum.md" >}})|Hard||||46.8%| -|0413|Arithmetic Slices|[Go]({{< relref "/ChapterFour/0400~0499/0413.Arithmetic-Slices.md" >}})|Medium||||60.1%| -|0416|Partition Equal Subset Sum|[Go]({{< relref "/ChapterFour/0400~0499/0416.Partition-Equal-Subset-Sum.md" >}})|Medium| O(n^2)| O(n)||45.0%| -|0474|Ones and Zeroes|[Go]({{< relref "/ChapterFour/0400~0499/0474.Ones-and-Zeroes.md" >}})|Medium||||43.5%| -|0494|Target Sum|[Go]({{< relref "/ChapterFour/0400~0499/0494.Target-Sum.md" >}})|Medium||||45.6%| +|0005|Longest Palindromic Substring|[Go]({{< relref "/ChapterFour/0001~0099/0005.Longest-Palindromic-Substring.md" >}})|Medium||||32.4%| +|0022|Generate Parentheses|[Go]({{< relref "/ChapterFour/0001~0099/0022.Generate-Parentheses.md" >}})|Medium||||72.5%| +|0032|Longest Valid Parentheses|[Go]({{< relref "/ChapterFour/0001~0099/0032.Longest-Valid-Parentheses.md" >}})|Hard||||32.8%| +|0042|Trapping Rain Water|[Go]({{< relref "/ChapterFour/0001~0099/0042.Trapping-Rain-Water.md" >}})|Hard||||59.3%| +|0045|Jump Game II|[Go]({{< relref "/ChapterFour/0001~0099/0045.Jump-Game-II.md" >}})|Medium||||39.8%| +|0053|Maximum Subarray|[Go]({{< relref "/ChapterFour/0001~0099/0053.Maximum-Subarray.md" >}})|Medium| O(n)| O(n)||50.2%| +|0055|Jump Game|[Go]({{< relref "/ChapterFour/0001~0099/0055.Jump-Game.md" >}})|Medium||||38.9%| +|0062|Unique Paths|[Go]({{< relref "/ChapterFour/0001~0099/0062.Unique-Paths.md" >}})|Medium| O(n^2)| O(n^2)||62.7%| +|0063|Unique Paths II|[Go]({{< relref "/ChapterFour/0001~0099/0063.Unique-Paths-II.md" >}})|Medium| O(n^2)| O(n^2)||39.4%| +|0064|Minimum Path Sum|[Go]({{< relref "/ChapterFour/0001~0099/0064.Minimum-Path-Sum.md" >}})|Medium| O(n^2)| O(n^2)||62.0%| +|0070|Climbing Stairs|[Go]({{< relref "/ChapterFour/0001~0099/0070.Climbing-Stairs.md" >}})|Easy| O(n)| O(n)||52.2%| +|0091|Decode Ways|[Go]({{< relref "/ChapterFour/0001~0099/0091.Decode-Ways.md" >}})|Medium| O(n)| O(n)||32.7%| +|0095|Unique Binary Search Trees II|[Go]({{< relref "/ChapterFour/0001~0099/0095.Unique-Binary-Search-Trees-II.md" >}})|Medium||||52.4%| +|0096|Unique Binary Search Trees|[Go]({{< relref "/ChapterFour/0001~0099/0096.Unique-Binary-Search-Trees.md" >}})|Medium| O(n)| O(n)||59.7%| +|0097|Interleaving String|[Go]({{< relref "/ChapterFour/0001~0099/0097.Interleaving-String.md" >}})|Medium||||37.3%| +|0115|Distinct Subsequences|[Go]({{< relref "/ChapterFour/0100~0199/0115.Distinct-Subsequences.md" >}})|Hard||||44.5%| +|0118|Pascal's Triangle|[Go]({{< relref "/ChapterFour/0100~0199/0118.Pascals-Triangle.md" >}})|Easy||||70.8%| +|0119|Pascal's Triangle II|[Go]({{< relref "/ChapterFour/0100~0199/0119.Pascals-Triangle-II.md" >}})|Easy||||60.8%| +|0120|Triangle|[Go]({{< relref "/ChapterFour/0100~0199/0120.Triangle.md" >}})|Medium| O(n^2)| O(n)||54.5%| +|0121|Best Time to Buy and Sell Stock|[Go]({{< relref "/ChapterFour/0100~0199/0121.Best-Time-to-Buy-and-Sell-Stock.md" >}})|Easy| O(n)| O(1)||54.3%| +|0122|Best Time to Buy and Sell Stock II|[Go]({{< relref "/ChapterFour/0100~0199/0122.Best-Time-to-Buy-and-Sell-Stock-II.md" >}})|Medium||||63.9%| +|0124|Binary Tree Maximum Path Sum|[Go]({{< relref "/ChapterFour/0100~0199/0124.Binary-Tree-Maximum-Path-Sum.md" >}})|Hard||||39.2%| +|0131|Palindrome Partitioning|[Go]({{< relref "/ChapterFour/0100~0199/0131.Palindrome-Partitioning.md" >}})|Medium||||64.9%| +|0152|Maximum Product Subarray|[Go]({{< relref "/ChapterFour/0100~0199/0152.Maximum-Product-Subarray.md" >}})|Medium| O(n)| O(1)||34.9%| +|0174|Dungeon Game|[Go]({{< relref "/ChapterFour/0100~0199/0174.Dungeon-Game.md" >}})|Hard||||37.5%| +|0198|House Robber|[Go]({{< relref "/ChapterFour/0100~0199/0198.House-Robber.md" >}})|Medium| O(n)| O(n)||49.4%| +|0213|House Robber II|[Go]({{< relref "/ChapterFour/0200~0299/0213.House-Robber-II.md" >}})|Medium| O(n)| O(n)||41.0%| +|0264|Ugly Number II|[Go]({{< relref "/ChapterFour/0200~0299/0264.Ugly-Number-II.md" >}})|Medium||||46.2%| +|0279|Perfect Squares|[Go]({{< relref "/ChapterFour/0200~0299/0279.Perfect-Squares.md" >}})|Medium||||52.7%| +|0300|Longest Increasing Subsequence|[Go]({{< relref "/ChapterFour/0300~0399/0300.Longest-Increasing-Subsequence.md" >}})|Medium| O(n log n)| O(n)||52.2%| +|0309|Best Time to Buy and Sell Stock with Cooldown|[Go]({{< relref "/ChapterFour/0300~0399/0309.Best-Time-to-Buy-and-Sell-Stock-with-Cooldown.md" >}})|Medium| O(n)| O(n)||56.2%| +|0322|Coin Change|[Go]({{< relref "/ChapterFour/0300~0399/0322.Coin-Change.md" >}})|Medium| O(n)| O(n)||42.1%| +|0329|Longest Increasing Path in a Matrix|[Go]({{< relref "/ChapterFour/0300~0399/0329.Longest-Increasing-Path-in-a-Matrix.md" >}})|Hard||||52.4%| +|0337|House Robber III|[Go]({{< relref "/ChapterFour/0300~0399/0337.House-Robber-III.md" >}})|Medium||||53.9%| +|0338|Counting Bits|[Go]({{< relref "/ChapterFour/0300~0399/0338.Counting-Bits.md" >}})|Easy| O(n)| O(n)||75.8%| +|0343|Integer Break|[Go]({{< relref "/ChapterFour/0300~0399/0343.Integer-Break.md" >}})|Medium| O(n^2)| O(n)||56.1%| +|0354|Russian Doll Envelopes|[Go]({{< relref "/ChapterFour/0300~0399/0354.Russian-Doll-Envelopes.md" >}})|Hard||||37.9%| +|0357|Count Numbers with Unique Digits|[Go]({{< relref "/ChapterFour/0300~0399/0357.Count-Numbers-with-Unique-Digits.md" >}})|Medium| O(1)| O(1)||51.9%| +|0368|Largest Divisible Subset|[Go]({{< relref "/ChapterFour/0300~0399/0368.Largest-Divisible-Subset.md" >}})|Medium||||41.6%| +|0376|Wiggle Subsequence|[Go]({{< relref "/ChapterFour/0300~0399/0376.Wiggle-Subsequence.md" >}})|Medium||||48.3%| +|0377|Combination Sum IV|[Go]({{< relref "/ChapterFour/0300~0399/0377.Combination-Sum-IV.md" >}})|Medium||||52.2%| +|0392|Is Subsequence|[Go]({{< relref "/ChapterFour/0300~0399/0392.Is-Subsequence.md" >}})|Easy| O(n)| O(1)||47.5%| +|0396|Rotate Function|[Go]({{< relref "/ChapterFour/0300~0399/0396.Rotate-Function.md" >}})|Medium||||41.1%| +|0397|Integer Replacement|[Go]({{< relref "/ChapterFour/0300~0399/0397.Integer-Replacement.md" >}})|Medium||||35.2%| +|0410|Split Array Largest Sum|[Go]({{< relref "/ChapterFour/0400~0499/0410.Split-Array-Largest-Sum.md" >}})|Hard||||53.5%| +|0413|Arithmetic Slices|[Go]({{< relref "/ChapterFour/0400~0499/0413.Arithmetic-Slices.md" >}})|Medium||||65.1%| +|0416|Partition Equal Subset Sum|[Go]({{< relref "/ChapterFour/0400~0499/0416.Partition-Equal-Subset-Sum.md" >}})|Medium| O(n^2)| O(n)||46.3%| +|0435|Non-overlapping Intervals|[Go]({{< relref "/ChapterFour/0400~0499/0435.Non-overlapping-Intervals.md" >}})|Medium||||50.3%| +|0458|Poor Pigs|[Go]({{< relref "/ChapterFour/0400~0499/0458.Poor-Pigs.md" >}})|Hard||||62.8%| +|0473|Matchsticks to Square|[Go]({{< relref "/ChapterFour/0400~0499/0473.Matchsticks-to-Square.md" >}})|Medium||||40.2%| +|0474|Ones and Zeroes|[Go]({{< relref "/ChapterFour/0400~0499/0474.Ones-and-Zeroes.md" >}})|Medium||||46.8%| +|0488|Zuma Game|[Go]({{< relref "/ChapterFour/0400~0499/0488.Zuma-Game.md" >}})|Hard||||33.9%| +|0494|Target Sum|[Go]({{< relref "/ChapterFour/0400~0499/0494.Target-Sum.md" >}})|Medium||||45.7%| +|0509|Fibonacci Number|[Go]({{< relref "/ChapterFour/0500~0599/0509.Fibonacci-Number.md" >}})|Easy||||69.8%| +|0518|Coin Change II|[Go]({{< relref "/ChapterFour/0500~0599/0518.Coin-Change-II.md" >}})|Medium||||60.6%| +|0526|Beautiful Arrangement|[Go]({{< relref "/ChapterFour/0500~0599/0526.Beautiful-Arrangement.md" >}})|Medium||||64.4%| +|0542|01 Matrix|[Go]({{< relref "/ChapterFour/0500~0599/0542.01-Matrix.md" >}})|Medium||||44.8%| +|0576|Out of Boundary Paths|[Go]({{< relref "/ChapterFour/0500~0599/0576.Out-of-Boundary-Paths.md" >}})|Medium||||44.3%| +|0583|Delete Operation for Two Strings|[Go]({{< relref "/ChapterFour/0500~0599/0583.Delete-Operation-for-Two-Strings.md" >}})|Medium||||59.8%| |0638|Shopping Offers|[Go]({{< relref "/ChapterFour/0600~0699/0638.Shopping-Offers.md" >}})|Medium||||53.3%| -|0647|Palindromic Substrings|[Go]({{< relref "/ChapterFour/0600~0699/0647.Palindromic-Substrings.md" >}})|Medium||||62.8%| -|0714|Best Time to Buy and Sell Stock with Transaction Fee|[Go]({{< relref "/ChapterFour/0700~0799/0714.Best-Time-to-Buy-and-Sell-Stock-with-Transaction-Fee.md" >}})|Medium| O(n)| O(1)||58.2%| -|0718|Maximum Length of Repeated Subarray|[Go]({{< relref "/ChapterFour/0700~0799/0718.Maximum-Length-of-Repeated-Subarray.md" >}})|Medium||||50.6%| -|0746|Min Cost Climbing Stairs|[Go]({{< relref "/ChapterFour/0700~0799/0746.Min-Cost-Climbing-Stairs.md" >}})|Easy| O(n)| O(1)||51.2%| -|0838|Push Dominoes|[Go]({{< relref "/ChapterFour/0800~0899/0838.Push-Dominoes.md" >}})|Medium| O(n)| O(n)||50.1%| -|0887|Super Egg Drop|[Go]({{< relref "/ChapterFour/0800~0899/0887.Super-Egg-Drop.md" >}})|Hard||||27.0%| -|0898|Bitwise ORs of Subarrays|[Go]({{< relref "/ChapterFour/0800~0899/0898.Bitwise-ORs-of-Subarrays.md" >}})|Medium||||34.5%| -|0920|Number of Music Playlists|[Go]({{< relref "/ChapterFour/0900~0999/0920.Number-of-Music-Playlists.md" >}})|Hard||||48.2%| -|0968|Binary Tree Cameras|[Go]({{< relref "/ChapterFour/0900~0999/0968.Binary-Tree-Cameras.md" >}})|Hard||||39.0%| -|0978|Longest Turbulent Subarray|[Go]({{< relref "/ChapterFour/0900~0999/0978.Longest-Turbulent-Subarray.md" >}})|Medium||||46.7%| -|1025|Divisor Game|[Go]({{< relref "/ChapterFour/1000~1099/1025.Divisor-Game.md" >}})|Easy| O(1)| O(1)||66.1%| -|1049|Last Stone Weight II|[Go]({{< relref "/ChapterFour/1000~1099/1049.Last-Stone-Weight-II.md" >}})|Medium||||46.2%| -|1074|Number of Submatrices That Sum to Target|[Go]({{< relref "/ChapterFour/1000~1099/1074.Number-of-Submatrices-That-Sum-to-Target.md" >}})|Hard||||64.9%| -|1105|Filling Bookcase Shelves|[Go]({{< relref "/ChapterFour/1100~1199/1105.Filling-Bookcase-Shelves.md" >}})|Medium||||57.5%| -|1143|Longest Common Subsequence|[Go]({{< relref "/ChapterFour/1100~1199/1143.Longest-Common-Subsequence.md" >}})|Medium||||58.7%| -|1235|Maximum Profit in Job Scheduling|[Go]({{< relref "/ChapterFour/1200~1299/1235.Maximum-Profit-in-Job-Scheduling.md" >}})|Hard||||47.8%| -|1423|Maximum Points You Can Obtain from Cards|[Go]({{< relref "/ChapterFour/1400~1499/1423.Maximum-Points-You-Can-Obtain-from-Cards.md" >}})|Medium||||47.0%| -|1463|Cherry Pickup II|[Go]({{< relref "/ChapterFour/1400~1499/1463.Cherry-Pickup-II.md" >}})|Hard||||68.8%| -|1641|Count Sorted Vowel Strings|[Go]({{< relref "/ChapterFour/1600~1699/1641.Count-Sorted-Vowel-Strings.md" >}})|Medium||||75.4%| -|1654|Minimum Jumps to Reach Home|[Go]({{< relref "/ChapterFour/1600~1699/1654.Minimum-Jumps-to-Reach-Home.md" >}})|Medium||||24.9%| -|1655|Distribute Repeating Integers|[Go]({{< relref "/ChapterFour/1600~1699/1655.Distribute-Repeating-Integers.md" >}})|Hard||||40.0%| -|1659|Maximize Grid Happiness|[Go]({{< relref "/ChapterFour/1600~1699/1659.Maximize-Grid-Happiness.md" >}})|Hard||||35.6%| -|1664|Ways to Make a Fair Array|[Go]({{< relref "/ChapterFour/1600~1699/1664.Ways-to-Make-a-Fair-Array.md" >}})|Medium||||62.0%| -|1690|Stone Game VII|[Go]({{< relref "/ChapterFour/1600~1699/1690.Stone-Game-VII.md" >}})|Medium||||49.2%| -|1691|Maximum Height by Stacking Cuboids|[Go]({{< relref "/ChapterFour/1600~1699/1691.Maximum-Height-by-Stacking-Cuboids.md" >}})|Hard||||50.5%| +|0647|Palindromic Substrings|[Go]({{< relref "/ChapterFour/0600~0699/0647.Palindromic-Substrings.md" >}})|Medium||||66.9%| +|0714|Best Time to Buy and Sell Stock with Transaction Fee|[Go]({{< relref "/ChapterFour/0700~0799/0714.Best-Time-to-Buy-and-Sell-Stock-with-Transaction-Fee.md" >}})|Medium| O(n)| O(1)||65.2%| +|0718|Maximum Length of Repeated Subarray|[Go]({{< relref "/ChapterFour/0700~0799/0718.Maximum-Length-of-Repeated-Subarray.md" >}})|Medium||||51.3%| +|0746|Min Cost Climbing Stairs|[Go]({{< relref "/ChapterFour/0700~0799/0746.Min-Cost-Climbing-Stairs.md" >}})|Easy| O(n)| O(1)||63.2%| +|0823|Binary Trees With Factors|[Go]({{< relref "/ChapterFour/0800~0899/0823.Binary-Trees-With-Factors.md" >}})|Medium||||49.7%| +|0828|Count Unique Characters of All Substrings of a Given String|[Go]({{< relref "/ChapterFour/0800~0899/0828.Count-Unique-Characters-of-All-Substrings-of-a-Given-String.md" >}})|Hard||||51.6%| +|0834|Sum of Distances in Tree|[Go]({{< relref "/ChapterFour/0800~0899/0834.Sum-of-Distances-in-Tree.md" >}})|Hard||||59.1%| +|0838|Push Dominoes|[Go]({{< relref "/ChapterFour/0800~0899/0838.Push-Dominoes.md" >}})|Medium| O(n)| O(n)||57.0%| +|0845|Longest Mountain in Array|[Go]({{< relref "/ChapterFour/0800~0899/0845.Longest-Mountain-in-Array.md" >}})|Medium||||40.2%| +|0877|Stone Game|[Go]({{< relref "/ChapterFour/0800~0899/0877.Stone-Game.md" >}})|Medium||||69.7%| +|0887|Super Egg Drop|[Go]({{< relref "/ChapterFour/0800~0899/0887.Super-Egg-Drop.md" >}})|Hard||||27.1%| +|0898|Bitwise ORs of Subarrays|[Go]({{< relref "/ChapterFour/0800~0899/0898.Bitwise-ORs-of-Subarrays.md" >}})|Medium||||37.2%| +|0907|Sum of Subarray Minimums|[Go]({{< relref "/ChapterFour/0900~0999/0907.Sum-of-Subarray-Minimums.md" >}})|Medium||||35.8%| +|0918|Maximum Sum Circular Subarray|[Go]({{< relref "/ChapterFour/0900~0999/0918.Maximum-Sum-Circular-Subarray.md" >}})|Medium||||43.0%| +|0920|Number of Music Playlists|[Go]({{< relref "/ChapterFour/0900~0999/0920.Number-of-Music-Playlists.md" >}})|Hard||||50.7%| +|0968|Binary Tree Cameras|[Go]({{< relref "/ChapterFour/0900~0999/0968.Binary-Tree-Cameras.md" >}})|Hard||||46.6%| +|0978|Longest Turbulent Subarray|[Go]({{< relref "/ChapterFour/0900~0999/0978.Longest-Turbulent-Subarray.md" >}})|Medium||||47.2%| +|0996|Number of Squareful Arrays|[Go]({{< relref "/ChapterFour/0900~0999/0996.Number-of-Squareful-Arrays.md" >}})|Hard||||49.2%| +|1025|Divisor Game|[Go]({{< relref "/ChapterFour/1000~1099/1025.Divisor-Game.md" >}})|Easy| O(1)| O(1)||67.6%| +|1048|Longest String Chain|[Go]({{< relref "/ChapterFour/1000~1099/1048.Longest-String-Chain.md" >}})|Medium||||59.3%| +|1049|Last Stone Weight II|[Go]({{< relref "/ChapterFour/1000~1099/1049.Last-Stone-Weight-II.md" >}})|Medium||||53.2%| +|1105|Filling Bookcase Shelves|[Go]({{< relref "/ChapterFour/1100~1199/1105.Filling-Bookcase-Shelves.md" >}})|Medium||||59.3%| +|1137|N-th Tribonacci Number|[Go]({{< relref "/ChapterFour/1100~1199/1137.N-th-Tribonacci-Number.md" >}})|Easy||||63.7%| +|1143|Longest Common Subsequence|[Go]({{< relref "/ChapterFour/1100~1199/1143.Longest-Common-Subsequence.md" >}})|Medium||||58.4%| +|1235|Maximum Profit in Job Scheduling|[Go]({{< relref "/ChapterFour/1200~1299/1235.Maximum-Profit-in-Job-Scheduling.md" >}})|Hard||||53.4%| +|1463|Cherry Pickup II|[Go]({{< relref "/ChapterFour/1400~1499/1463.Cherry-Pickup-II.md" >}})|Hard||||69.5%| +|1641|Count Sorted Vowel Strings|[Go]({{< relref "/ChapterFour/1600~1699/1641.Count-Sorted-Vowel-Strings.md" >}})|Medium||||77.4%| +|1646|Get Maximum in Generated Array|[Go]({{< relref "/ChapterFour/1600~1699/1646.Get-Maximum-in-Generated-Array.md" >}})|Easy||||50.2%| +|1653|Minimum Deletions to Make String Balanced|[Go]({{< relref "/ChapterFour/1600~1699/1653.Minimum-Deletions-to-Make-String-Balanced.md" >}})|Medium||||58.9%| +|1654|Minimum Jumps to Reach Home|[Go]({{< relref "/ChapterFour/1600~1699/1654.Minimum-Jumps-to-Reach-Home.md" >}})|Medium||||29.1%| +|1655|Distribute Repeating Integers|[Go]({{< relref "/ChapterFour/1600~1699/1655.Distribute-Repeating-Integers.md" >}})|Hard||||39.3%| +|1659|Maximize Grid Happiness|[Go]({{< relref "/ChapterFour/1600~1699/1659.Maximize-Grid-Happiness.md" >}})|Hard||||38.8%| +|1664|Ways to Make a Fair Array|[Go]({{< relref "/ChapterFour/1600~1699/1664.Ways-to-Make-a-Fair-Array.md" >}})|Medium||||63.3%| +|1681|Minimum Incompatibility|[Go]({{< relref "/ChapterFour/1600~1699/1681.Minimum-Incompatibility.md" >}})|Hard||||37.8%| +|1690|Stone Game VII|[Go]({{< relref "/ChapterFour/1600~1699/1690.Stone-Game-VII.md" >}})|Medium||||58.1%| +|1691|Maximum Height by Stacking Cuboids|[Go]({{< relref "/ChapterFour/1600~1699/1691.Maximum-Height-by-Stacking-Cuboids.md" >}})|Hard||||54.6%| +|1696|Jump Game VI|[Go]({{< relref "/ChapterFour/1600~1699/1696.Jump-Game-VI.md" >}})|Medium||||46.1%| +|2167|Minimum Time to Remove All Cars Containing Illegal Goods|[Go]({{< relref "/ChapterFour/2100~2199/2167.Minimum-Time-to-Remove-All-Cars-Containing-Illegal-Goods.md" >}})|Hard||||40.8%| |------------|-------------------------------------------------------|-------| ----------------| ---------------|-------------|-------------|-------------| diff --git a/website/content/ChapterTwo/Hash_Table.md b/website/content/ChapterTwo/Hash_Table.md index f8237bbb6..d0dc53572 100644 --- a/website/content/ChapterTwo/Hash_Table.md +++ b/website/content/ChapterTwo/Hash_Table.md @@ -9,84 +9,172 @@ weight: 13 | No. | Title | Solution | Difficulty | TimeComplexity | SpaceComplexity |Favorite| Acceptance | |:--------:|:------- | :--------: | :----------: | :----: | :-----: | :-----: |:-----: | -|0001|Two Sum|[Go]({{< relref "/ChapterFour/0001~0099/0001.Two-Sum.md" >}})|Easy| O(n)| O(n)||46.8%| -|0003|Longest Substring Without Repeating Characters|[Go]({{< relref "/ChapterFour/0001~0099/0003.Longest-Substring-Without-Repeating-Characters.md" >}})|Medium| O(n)| O(1)|❤️|31.6%| -|0018|4Sum|[Go]({{< relref "/ChapterFour/0001~0099/0018.4Sum.md" >}})|Medium| O(n^3)| O(n^2)|❤️|35.2%| -|0030|Substring with Concatenation of All Words|[Go]({{< relref "/ChapterFour/0001~0099/0030.Substring-with-Concatenation-of-All-Words.md" >}})|Hard| O(n)| O(n)|❤️|26.4%| -|0036|Valid Sudoku|[Go]({{< relref "/ChapterFour/0001~0099/0036.Valid-Sudoku.md" >}})|Medium| O(n^2)| O(n^2)||51.0%| -|0037|Sudoku Solver|[Go]({{< relref "/ChapterFour/0001~0099/0037.Sudoku-Solver.md" >}})|Hard| O(n^2)| O(n^2)|❤️|47.3%| -|0049|Group Anagrams|[Go]({{< relref "/ChapterFour/0001~0099/0049.Group-Anagrams.md" >}})|Medium| O(n log n)| O(n)||59.9%| -|0076|Minimum Window Substring|[Go]({{< relref "/ChapterFour/0001~0099/0076.Minimum-Window-Substring.md" >}})|Hard| O(n)| O(n)|❤️|36.3%| -|0094|Binary Tree Inorder Traversal|[Go]({{< relref "/ChapterFour/0001~0099/0094.Binary-Tree-Inorder-Traversal.md" >}})|Medium| O(n)| O(1)||66.5%| -|0136|Single Number|[Go]({{< relref "/ChapterFour/0100~0199/0136.Single-Number.md" >}})|Easy||||66.8%| -|0138|Copy List with Random Pointer|[Go]({{< relref "/ChapterFour/0100~0199/0138.Copy-List-with-Random-Pointer.md" >}})|Medium| O(n)| O(1)||41.7%| -|0187|Repeated DNA Sequences|[Go]({{< relref "/ChapterFour/0100~0199/0187.Repeated-DNA-Sequences.md" >}})|Medium||||41.8%| -|0202|Happy Number|[Go]({{< relref "/ChapterFour/0200~0299/0202.Happy-Number.md" >}})|Easy| O(log n)| O(1)||51.4%| -|0204|Count Primes|[Go]({{< relref "/ChapterFour/0200~0299/0204.Count-Primes.md" >}})|Easy||||32.4%| -|0205|Isomorphic Strings|[Go]({{< relref "/ChapterFour/0200~0299/0205.Isomorphic-Strings.md" >}})|Easy| O(log n)| O(n)||40.7%| -|0217|Contains Duplicate|[Go]({{< relref "/ChapterFour/0200~0299/0217.Contains-Duplicate.md" >}})|Easy| O(n)| O(n)||57.0%| -|0219|Contains Duplicate II|[Go]({{< relref "/ChapterFour/0200~0299/0219.Contains-Duplicate-II.md" >}})|Easy| O(n)| O(n)||38.9%| -|0242|Valid Anagram|[Go]({{< relref "/ChapterFour/0200~0299/0242.Valid-Anagram.md" >}})|Easy| O(n)| O(n) ||59.0%| -|0274|H-Index|[Go]({{< relref "/ChapterFour/0200~0299/0274.H-Index.md" >}})|Medium| O(n)| O(n) ||36.5%| -|0290|Word Pattern|[Go]({{< relref "/ChapterFour/0200~0299/0290.Word-Pattern.md" >}})|Easy| O(n)| O(n) ||38.5%| -|0347|Top K Frequent Elements|[Go]({{< relref "/ChapterFour/0300~0399/0347.Top-K-Frequent-Elements.md" >}})|Medium| O(n)| O(n) ||62.7%| -|0349|Intersection of Two Arrays|[Go]({{< relref "/ChapterFour/0300~0399/0349.Intersection-of-Two-Arrays.md" >}})|Easy| O(n)| O(n) ||65.5%| -|0350|Intersection of Two Arrays II|[Go]({{< relref "/ChapterFour/0300~0399/0350.Intersection-of-Two-Arrays-II.md" >}})|Easy| O(n)| O(n) ||52.2%| -|0387|First Unique Character in a String|[Go]({{< relref "/ChapterFour/0300~0399/0387.First-Unique-Character-in-a-String.md" >}})|Easy||||54.1%| -|0389|Find the Difference|[Go]({{< relref "/ChapterFour/0300~0399/0389.Find-the-Difference.md" >}})|Easy||||58.0%| -|0409|Longest Palindrome|[Go]({{< relref "/ChapterFour/0400~0499/0409.Longest-Palindrome.md" >}})|Easy||||52.3%| -|0438|Find All Anagrams in a String|[Go]({{< relref "/ChapterFour/0400~0499/0438.Find-All-Anagrams-in-a-String.md" >}})|Medium| O(n)| O(1) ||45.3%| -|0447|Number of Boomerangs|[Go]({{< relref "/ChapterFour/0400~0499/0447.Number-of-Boomerangs.md" >}})|Medium| O(n)| O(1) ||52.6%| -|0451|Sort Characters By Frequency|[Go]({{< relref "/ChapterFour/0400~0499/0451.Sort-Characters-By-Frequency.md" >}})|Medium| O(n log n)| O(1) ||64.7%| -|0454|4Sum II|[Go]({{< relref "/ChapterFour/0400~0499/0454.4Sum-II.md" >}})|Medium| O(n^2)| O(n) ||54.7%| -|0463|Island Perimeter|[Go]({{< relref "/ChapterFour/0400~0499/0463.Island-Perimeter.md" >}})|Easy||||66.9%| -|0500|Keyboard Row|[Go]({{< relref "/ChapterFour/0500~0599/0500.Keyboard-Row.md" >}})|Easy||||66.0%| -|0508|Most Frequent Subtree Sum|[Go]({{< relref "/ChapterFour/0500~0599/0508.Most-Frequent-Subtree-Sum.md" >}})|Medium||||59.3%| -|0535|Encode and Decode TinyURL|[Go]({{< relref "/ChapterFour/0500~0599/0535.Encode-and-Decode-TinyURL.md" >}})|Medium||||82.4%| -|0575|Distribute Candies|[Go]({{< relref "/ChapterFour/0500~0599/0575.Distribute-Candies.md" >}})|Easy||||64.4%| -|0594|Longest Harmonious Subsequence|[Go]({{< relref "/ChapterFour/0500~0599/0594.Longest-Harmonious-Subsequence.md" >}})|Easy||||51.3%| -|0599|Minimum Index Sum of Two Lists|[Go]({{< relref "/ChapterFour/0500~0599/0599.Minimum-Index-Sum-of-Two-Lists.md" >}})|Easy||||52.0%| -|0632|Smallest Range Covering Elements from K Lists|[Go]({{< relref "/ChapterFour/0600~0699/0632.Smallest-Range-Covering-Elements-from-K-Lists.md" >}})|Hard||||54.7%| -|0645|Set Mismatch|[Go]({{< relref "/ChapterFour/0600~0699/0645.Set-Mismatch.md" >}})|Easy||||41.0%| -|0648|Replace Words|[Go]({{< relref "/ChapterFour/0600~0699/0648.Replace-Words.md" >}})|Medium| O(n)| O(n) ||59.2%| -|0676|Implement Magic Dictionary|[Go]({{< relref "/ChapterFour/0600~0699/0676.Implement-Magic-Dictionary.md" >}})|Medium| O(n)| O(n) ||55.4%| -|0705|Design HashSet|[Go]({{< relref "/ChapterFour/0700~0799/0705.Design-HashSet.md" >}})|Easy||||64.5%| -|0706|Design HashMap|[Go]({{< relref "/ChapterFour/0700~0799/0706.Design-HashMap.md" >}})|Easy||||64.0%| -|0710|Random Pick with Blacklist|[Go]({{< relref "/ChapterFour/0700~0799/0710.Random-Pick-with-Blacklist.md" >}})|Hard| O(n)| O(n) ||33.1%| -|0718|Maximum Length of Repeated Subarray|[Go]({{< relref "/ChapterFour/0700~0799/0718.Maximum-Length-of-Repeated-Subarray.md" >}})|Medium||||50.6%| -|0720|Longest Word in Dictionary|[Go]({{< relref "/ChapterFour/0700~0799/0720.Longest-Word-in-Dictionary.md" >}})|Easy| O(n)| O(n) ||49.6%| -|0726|Number of Atoms|[Go]({{< relref "/ChapterFour/0700~0799/0726.Number-of-Atoms.md" >}})|Hard| O(n)| O(n) |❤️|51.0%| -|0739|Daily Temperatures|[Go]({{< relref "/ChapterFour/0700~0799/0739.Daily-Temperatures.md" >}})|Medium| O(n)| O(n) ||64.9%| -|0748|Shortest Completing Word|[Go]({{< relref "/ChapterFour/0700~0799/0748.Shortest-Completing-Word.md" >}})|Easy||||57.7%| -|0771|Jewels and Stones|[Go]({{< relref "/ChapterFour/0700~0799/0771.Jewels-and-Stones.md" >}})|Easy||||87.0%| -|0781|Rabbits in Forest|[Go]({{< relref "/ChapterFour/0700~0799/0781.Rabbits-in-Forest.md" >}})|Medium||||55.8%| -|0811|Subdomain Visit Count|[Go]({{< relref "/ChapterFour/0800~0899/0811.Subdomain-Visit-Count.md" >}})|Easy||||71.8%| -|0884|Uncommon Words from Two Sentences|[Go]({{< relref "/ChapterFour/0800~0899/0884.Uncommon-Words-from-Two-Sentences.md" >}})|Easy||||64.3%| -|0895|Maximum Frequency Stack|[Go]({{< relref "/ChapterFour/0800~0899/0895.Maximum-Frequency-Stack.md" >}})|Hard| O(n)| O(n) ||63.3%| -|0930|Binary Subarrays With Sum|[Go]({{< relref "/ChapterFour/0900~0999/0930.Binary-Subarrays-With-Sum.md" >}})|Medium| O(n)| O(n) |❤️|44.9%| -|0953|Verifying an Alien Dictionary|[Go]({{< relref "/ChapterFour/0900~0999/0953.Verifying-an-Alien-Dictionary.md" >}})|Easy||||52.5%| -|0961|N-Repeated Element in Size 2N Array|[Go]({{< relref "/ChapterFour/0900~0999/0961.N-Repeated-Element-in-Size-2N-Array.md" >}})|Easy||||74.7%| -|0966|Vowel Spellchecker|[Go]({{< relref "/ChapterFour/0900~0999/0966.Vowel-Spellchecker.md" >}})|Medium||||51.9%| -|0970|Powerful Integers|[Go]({{< relref "/ChapterFour/0900~0999/0970.Powerful-Integers.md" >}})|Medium||||40.1%| -|0981|Time Based Key-Value Store|[Go]({{< relref "/ChapterFour/0900~0999/0981.Time-Based-Key-Value-Store.md" >}})|Medium||||54.3%| -|0987|Vertical Order Traversal of a Binary Tree|[Go]({{< relref "/ChapterFour/0900~0999/0987.Vertical-Order-Traversal-of-a-Binary-Tree.md" >}})|Hard||||39.1%| -|0992|Subarrays with K Different Integers|[Go]({{< relref "/ChapterFour/0900~0999/0992.Subarrays-with-K-Different-Integers.md" >}})|Hard| O(n)| O(n) |❤️|50.9%| -|1002|Find Common Characters|[Go]({{< relref "/ChapterFour/1000~1099/1002.Find-Common-Characters.md" >}})|Easy||||68.7%| -|1078|Occurrences After Bigram|[Go]({{< relref "/ChapterFour/1000~1099/1078.Occurrences-After-Bigram.md" >}})|Easy||||65.0%| -|1160|Find Words That Can Be Formed by Characters|[Go]({{< relref "/ChapterFour/1100~1199/1160.Find-Words-That-Can-Be-Formed-by-Characters.md" >}})|Easy||||67.9%| -|1178|Number of Valid Words for Each Puzzle|[Go]({{< relref "/ChapterFour/1100~1199/1178.Number-of-Valid-Words-for-Each-Puzzle.md" >}})|Hard||||39.8%| -|1189|Maximum Number of Balloons|[Go]({{< relref "/ChapterFour/1100~1199/1189.Maximum-Number-of-Balloons.md" >}})|Easy||||62.2%| -|1207|Unique Number of Occurrences|[Go]({{< relref "/ChapterFour/1200~1299/1207.Unique-Number-of-Occurrences.md" >}})|Easy||||72.0%| -|1512|Number of Good Pairs|[Go]({{< relref "/ChapterFour/1500~1599/1512.Number-of-Good-Pairs.md" >}})|Easy||||87.6%| -|1539|Kth Missing Positive Number|[Go]({{< relref "/ChapterFour/1500~1599/1539.Kth-Missing-Positive-Number.md" >}})|Easy||||54.8%| -|1640|Check Array Formation Through Concatenation|[Go]({{< relref "/ChapterFour/1600~1699/1640.Check-Array-Formation-Through-Concatenation.md" >}})|Easy||||59.7%| -|1679|Max Number of K-Sum Pairs|[Go]({{< relref "/ChapterFour/1600~1699/1679.Max-Number-of-K-Sum-Pairs.md" >}})|Medium||||53.7%| -|1748|Sum of Unique Elements|[Go]({{< relref "/ChapterFour/1700~1799/1748.Sum-of-Unique-Elements.md" >}})|Easy||||74.7%| +|0001|Two Sum|[Go]({{< relref "/ChapterFour/0001~0099/0001.Two-Sum.md" >}})|Easy| O(n)| O(n)||49.7%| +|0003|Longest Substring Without Repeating Characters|[Go]({{< relref "/ChapterFour/0001~0099/0003.Longest-Substring-Without-Repeating-Characters.md" >}})|Medium| O(n)| O(1)|❤️|33.8%| +|0012|Integer to Roman|[Go]({{< relref "/ChapterFour/0001~0099/0012.Integer-to-Roman.md" >}})|Medium||||62.0%| +|0013|Roman to Integer|[Go]({{< relref "/ChapterFour/0001~0099/0013.Roman-to-Integer.md" >}})|Easy||||58.6%| +|0017|Letter Combinations of a Phone Number|[Go]({{< relref "/ChapterFour/0001~0099/0017.Letter-Combinations-of-a-Phone-Number.md" >}})|Medium||||56.6%| +|0030|Substring with Concatenation of All Words|[Go]({{< relref "/ChapterFour/0001~0099/0030.Substring-with-Concatenation-of-All-Words.md" >}})|Hard| O(n)| O(n)|❤️|31.2%| +|0036|Valid Sudoku|[Go]({{< relref "/ChapterFour/0001~0099/0036.Valid-Sudoku.md" >}})|Medium| O(n^2)| O(n^2)||58.1%| +|0037|Sudoku Solver|[Go]({{< relref "/ChapterFour/0001~0099/0037.Sudoku-Solver.md" >}})|Hard| O(n^2)| O(n^2)|❤️|57.7%| +|0041|First Missing Positive|[Go]({{< relref "/ChapterFour/0001~0099/0041.First-Missing-Positive.md" >}})|Hard||||36.7%| +|0049|Group Anagrams|[Go]({{< relref "/ChapterFour/0001~0099/0049.Group-Anagrams.md" >}})|Medium| O(n log n)| O(n)||66.8%| +|0073|Set Matrix Zeroes|[Go]({{< relref "/ChapterFour/0001~0099/0073.Set-Matrix-Zeroes.md" >}})|Medium||||51.3%| +|0076|Minimum Window Substring|[Go]({{< relref "/ChapterFour/0001~0099/0076.Minimum-Window-Substring.md" >}})|Hard| O(n)| O(n)|❤️|40.9%| +|0105|Construct Binary Tree from Preorder and Inorder Traversal|[Go]({{< relref "/ChapterFour/0100~0199/0105.Construct-Binary-Tree-from-Preorder-and-Inorder-Traversal.md" >}})|Medium||||61.6%| +|0106|Construct Binary Tree from Inorder and Postorder Traversal|[Go]({{< relref "/ChapterFour/0100~0199/0106.Construct-Binary-Tree-from-Inorder-and-Postorder-Traversal.md" >}})|Medium||||60.0%| +|0126|Word Ladder II|[Go]({{< relref "/ChapterFour/0100~0199/0126.Word-Ladder-II.md" >}})|Hard||||27.5%| +|0127|Word Ladder|[Go]({{< relref "/ChapterFour/0100~0199/0127.Word-Ladder.md" >}})|Hard||||37.2%| +|0128|Longest Consecutive Sequence|[Go]({{< relref "/ChapterFour/0100~0199/0128.Longest-Consecutive-Sequence.md" >}})|Medium||||48.5%| +|0138|Copy List with Random Pointer|[Go]({{< relref "/ChapterFour/0100~0199/0138.Copy-List-with-Random-Pointer.md" >}})|Medium| O(n)| O(1)||51.4%| +|0141|Linked List Cycle|[Go]({{< relref "/ChapterFour/0100~0199/0141.Linked-List-Cycle.md" >}})|Easy||||47.5%| +|0142|Linked List Cycle II|[Go]({{< relref "/ChapterFour/0100~0199/0142.Linked-List-Cycle-II.md" >}})|Medium||||48.8%| +|0146|LRU Cache|[Go]({{< relref "/ChapterFour/0100~0199/0146.LRU-Cache.md" >}})|Medium||||40.7%| +|0160|Intersection of Two Linked Lists|[Go]({{< relref "/ChapterFour/0100~0199/0160.Intersection-of-Two-Linked-Lists.md" >}})|Easy||||54.4%| +|0169|Majority Element|[Go]({{< relref "/ChapterFour/0100~0199/0169.Majority-Element.md" >}})|Easy||||63.9%| +|0187|Repeated DNA Sequences|[Go]({{< relref "/ChapterFour/0100~0199/0187.Repeated-DNA-Sequences.md" >}})|Medium||||47.0%| +|0202|Happy Number|[Go]({{< relref "/ChapterFour/0200~0299/0202.Happy-Number.md" >}})|Easy| O(log n)| O(1)||54.8%| +|0205|Isomorphic Strings|[Go]({{< relref "/ChapterFour/0200~0299/0205.Isomorphic-Strings.md" >}})|Easy| O(log n)| O(n)||42.9%| +|0208|Implement Trie (Prefix Tree)|[Go]({{< relref "/ChapterFour/0200~0299/0208.Implement-Trie-Prefix-Tree.md" >}})|Medium||||62.8%| +|0217|Contains Duplicate|[Go]({{< relref "/ChapterFour/0200~0299/0217.Contains-Duplicate.md" >}})|Easy| O(n)| O(n)||61.4%| +|0219|Contains Duplicate II|[Go]({{< relref "/ChapterFour/0200~0299/0219.Contains-Duplicate-II.md" >}})|Easy| O(n)| O(n)||42.6%| +|0229|Majority Element II|[Go]({{< relref "/ChapterFour/0200~0299/0229.Majority-Element-II.md" >}})|Medium||||45.1%| +|0242|Valid Anagram|[Go]({{< relref "/ChapterFour/0200~0299/0242.Valid-Anagram.md" >}})|Easy| O(n)| O(n) ||63.1%| +|0264|Ugly Number II|[Go]({{< relref "/ChapterFour/0200~0299/0264.Ugly-Number-II.md" >}})|Medium||||46.2%| +|0268|Missing Number|[Go]({{< relref "/ChapterFour/0200~0299/0268.Missing-Number.md" >}})|Easy||||62.6%| +|0290|Word Pattern|[Go]({{< relref "/ChapterFour/0200~0299/0290.Word-Pattern.md" >}})|Easy| O(n)| O(n) ||41.7%| +|0299|Bulls and Cows|[Go]({{< relref "/ChapterFour/0200~0299/0299.Bulls-and-Cows.md" >}})|Medium||||49.4%| +|0347|Top K Frequent Elements|[Go]({{< relref "/ChapterFour/0300~0399/0347.Top-K-Frequent-Elements.md" >}})|Medium| O(n)| O(n) ||64.2%| +|0349|Intersection of Two Arrays|[Go]({{< relref "/ChapterFour/0300~0399/0349.Intersection-of-Two-Arrays.md" >}})|Easy| O(n)| O(n) ||70.9%| +|0350|Intersection of Two Arrays II|[Go]({{< relref "/ChapterFour/0300~0399/0350.Intersection-of-Two-Arrays-II.md" >}})|Easy| O(n)| O(n) ||56.0%| +|0383|Ransom Note|[Go]({{< relref "/ChapterFour/0300~0399/0383.Ransom-Note.md" >}})|Easy||||58.3%| +|0387|First Unique Character in a String|[Go]({{< relref "/ChapterFour/0300~0399/0387.First-Unique-Character-in-a-String.md" >}})|Easy||||59.6%| +|0389|Find the Difference|[Go]({{< relref "/ChapterFour/0300~0399/0389.Find-the-Difference.md" >}})|Easy||||59.9%| +|0395|Longest Substring with At Least K Repeating Characters|[Go]({{< relref "/ChapterFour/0300~0399/0395.Longest-Substring-with-At-Least-K-Repeating-Characters.md" >}})|Medium||||44.8%| +|0409|Longest Palindrome|[Go]({{< relref "/ChapterFour/0400~0499/0409.Longest-Palindrome.md" >}})|Easy||||54.2%| +|0421|Maximum XOR of Two Numbers in an Array|[Go]({{< relref "/ChapterFour/0400~0499/0421.Maximum-XOR-of-Two-Numbers-in-an-Array.md" >}})|Medium||||54.0%| +|0423|Reconstruct Original Digits from English|[Go]({{< relref "/ChapterFour/0400~0499/0423.Reconstruct-Original-Digits-from-English.md" >}})|Medium||||51.2%| +|0424|Longest Repeating Character Replacement|[Go]({{< relref "/ChapterFour/0400~0499/0424.Longest-Repeating-Character-Replacement.md" >}})|Medium||||52.0%| +|0433|Minimum Genetic Mutation|[Go]({{< relref "/ChapterFour/0400~0499/0433.Minimum-Genetic-Mutation.md" >}})|Medium||||52.4%| +|0438|Find All Anagrams in a String|[Go]({{< relref "/ChapterFour/0400~0499/0438.Find-All-Anagrams-in-a-String.md" >}})|Medium| O(n)| O(1) ||50.2%| +|0447|Number of Boomerangs|[Go]({{< relref "/ChapterFour/0400~0499/0447.Number-of-Boomerangs.md" >}})|Medium| O(n)| O(1) ||54.9%| +|0448|Find All Numbers Disappeared in an Array|[Go]({{< relref "/ChapterFour/0400~0499/0448.Find-All-Numbers-Disappeared-in-an-Array.md" >}})|Easy||||59.9%| +|0451|Sort Characters By Frequency|[Go]({{< relref "/ChapterFour/0400~0499/0451.Sort-Characters-By-Frequency.md" >}})|Medium| O(n log n)| O(1) ||70.1%| +|0454|4Sum II|[Go]({{< relref "/ChapterFour/0400~0499/0454.4Sum-II.md" >}})|Medium| O(n^2)| O(n) ||57.2%| +|0457|Circular Array Loop|[Go]({{< relref "/ChapterFour/0400~0499/0457.Circular-Array-Loop.md" >}})|Medium||||32.6%| +|0460|LFU Cache|[Go]({{< relref "/ChapterFour/0400~0499/0460.LFU-Cache.md" >}})|Hard||||43.0%| +|0480|Sliding Window Median|[Go]({{< relref "/ChapterFour/0400~0499/0480.Sliding-Window-Median.md" >}})|Hard||||41.1%| +|0491|Non-decreasing Subsequences|[Go]({{< relref "/ChapterFour/0400~0499/0491.Non-decreasing-Subsequences.md" >}})|Medium||||60.2%| +|0496|Next Greater Element I|[Go]({{< relref "/ChapterFour/0400~0499/0496.Next-Greater-Element-I.md" >}})|Easy||||71.4%| +|0500|Keyboard Row|[Go]({{< relref "/ChapterFour/0500~0599/0500.Keyboard-Row.md" >}})|Easy||||69.6%| +|0508|Most Frequent Subtree Sum|[Go]({{< relref "/ChapterFour/0500~0599/0508.Most-Frequent-Subtree-Sum.md" >}})|Medium||||64.9%| +|0519|Random Flip Matrix|[Go]({{< relref "/ChapterFour/0500~0599/0519.Random-Flip-Matrix.md" >}})|Medium||||40.0%| +|0523|Continuous Subarray Sum|[Go]({{< relref "/ChapterFour/0500~0599/0523.Continuous-Subarray-Sum.md" >}})|Medium||||28.5%| +|0525|Contiguous Array|[Go]({{< relref "/ChapterFour/0500~0599/0525.Contiguous-Array.md" >}})|Medium||||46.8%| +|0532|K-diff Pairs in an Array|[Go]({{< relref "/ChapterFour/0500~0599/0532.K-diff-Pairs-in-an-Array.md" >}})|Medium||||41.2%| +|0535|Encode and Decode TinyURL|[Go]({{< relref "/ChapterFour/0500~0599/0535.Encode-and-Decode-TinyURL.md" >}})|Medium||||86.0%| +|0554|Brick Wall|[Go]({{< relref "/ChapterFour/0500~0599/0554.Brick-Wall.md" >}})|Medium||||53.6%| +|0560|Subarray Sum Equals K|[Go]({{< relref "/ChapterFour/0500~0599/0560.Subarray-Sum-Equals-K.md" >}})|Medium||||43.7%| +|0567|Permutation in String|[Go]({{< relref "/ChapterFour/0500~0599/0567.Permutation-in-String.md" >}})|Medium||||44.3%| +|0575|Distribute Candies|[Go]({{< relref "/ChapterFour/0500~0599/0575.Distribute-Candies.md" >}})|Easy||||66.5%| +|0594|Longest Harmonious Subsequence|[Go]({{< relref "/ChapterFour/0500~0599/0594.Longest-Harmonious-Subsequence.md" >}})|Easy||||53.5%| +|0599|Minimum Index Sum of Two Lists|[Go]({{< relref "/ChapterFour/0500~0599/0599.Minimum-Index-Sum-of-Two-Lists.md" >}})|Easy||||53.4%| +|0609|Find Duplicate File in System|[Go]({{< relref "/ChapterFour/0600~0699/0609.Find-Duplicate-File-in-System.md" >}})|Medium||||67.7%| +|0632|Smallest Range Covering Elements from K Lists|[Go]({{< relref "/ChapterFour/0600~0699/0632.Smallest-Range-Covering-Elements-from-K-Lists.md" >}})|Hard||||61.0%| +|0645|Set Mismatch|[Go]({{< relref "/ChapterFour/0600~0699/0645.Set-Mismatch.md" >}})|Easy||||42.7%| +|0648|Replace Words|[Go]({{< relref "/ChapterFour/0600~0699/0648.Replace-Words.md" >}})|Medium| O(n)| O(n) ||62.7%| +|0653|Two Sum IV - Input is a BST|[Go]({{< relref "/ChapterFour/0600~0699/0653.Two-Sum-IV-Input-is-a-BST.md" >}})|Easy||||61.0%| +|0676|Implement Magic Dictionary|[Go]({{< relref "/ChapterFour/0600~0699/0676.Implement-Magic-Dictionary.md" >}})|Medium| O(n)| O(n) ||56.9%| +|0677|Map Sum Pairs|[Go]({{< relref "/ChapterFour/0600~0699/0677.Map-Sum-Pairs.md" >}})|Medium||||56.8%| +|0690|Employee Importance|[Go]({{< relref "/ChapterFour/0600~0699/0690.Employee-Importance.md" >}})|Medium||||65.6%| +|0692|Top K Frequent Words|[Go]({{< relref "/ChapterFour/0600~0699/0692.Top-K-Frequent-Words.md" >}})|Medium||||57.2%| +|0697|Degree of an Array|[Go]({{< relref "/ChapterFour/0600~0699/0697.Degree-of-an-Array.md" >}})|Easy||||56.0%| +|0705|Design HashSet|[Go]({{< relref "/ChapterFour/0700~0799/0705.Design-HashSet.md" >}})|Easy||||65.6%| +|0706|Design HashMap|[Go]({{< relref "/ChapterFour/0700~0799/0706.Design-HashMap.md" >}})|Easy||||64.7%| +|0710|Random Pick with Blacklist|[Go]({{< relref "/ChapterFour/0700~0799/0710.Random-Pick-with-Blacklist.md" >}})|Hard| O(n)| O(n) ||33.5%| +|0720|Longest Word in Dictionary|[Go]({{< relref "/ChapterFour/0700~0799/0720.Longest-Word-in-Dictionary.md" >}})|Medium| O(n)| O(n) ||52.0%| +|0726|Number of Atoms|[Go]({{< relref "/ChapterFour/0700~0799/0726.Number-of-Atoms.md" >}})|Hard| O(n)| O(n) |❤️|52.2%| +|0745|Prefix and Suffix Search|[Go]({{< relref "/ChapterFour/0700~0799/0745.Prefix-and-Suffix-Search.md" >}})|Hard||||41.2%| +|0748|Shortest Completing Word|[Go]({{< relref "/ChapterFour/0700~0799/0748.Shortest-Completing-Word.md" >}})|Easy||||59.3%| +|0752|Open the Lock|[Go]({{< relref "/ChapterFour/0700~0799/0752.Open-the-Lock.md" >}})|Medium||||55.6%| +|0763|Partition Labels|[Go]({{< relref "/ChapterFour/0700~0799/0763.Partition-Labels.md" >}})|Medium||||79.7%| +|0767|Reorganize String|[Go]({{< relref "/ChapterFour/0700~0799/0767.Reorganize-String.md" >}})|Medium||||52.9%| +|0771|Jewels and Stones|[Go]({{< relref "/ChapterFour/0700~0799/0771.Jewels-and-Stones.md" >}})|Easy||||88.2%| +|0781|Rabbits in Forest|[Go]({{< relref "/ChapterFour/0700~0799/0781.Rabbits-in-Forest.md" >}})|Medium||||54.7%| +|0791|Custom Sort String|[Go]({{< relref "/ChapterFour/0700~0799/0791.Custom-Sort-String.md" >}})|Medium||||69.1%| +|0792|Number of Matching Subsequences|[Go]({{< relref "/ChapterFour/0700~0799/0792.Number-of-Matching-Subsequences.md" >}})|Medium||||51.6%| +|0811|Subdomain Visit Count|[Go]({{< relref "/ChapterFour/0800~0899/0811.Subdomain-Visit-Count.md" >}})|Medium||||75.5%| +|0815|Bus Routes|[Go]({{< relref "/ChapterFour/0800~0899/0815.Bus-Routes.md" >}})|Hard||||45.6%| +|0817|Linked List Components|[Go]({{< relref "/ChapterFour/0800~0899/0817.Linked-List-Components.md" >}})|Medium||||57.7%| +|0819|Most Common Word|[Go]({{< relref "/ChapterFour/0800~0899/0819.Most-Common-Word.md" >}})|Easy||||44.7%| +|0820|Short Encoding of Words|[Go]({{< relref "/ChapterFour/0800~0899/0820.Short-Encoding-of-Words.md" >}})|Medium||||60.6%| +|0823|Binary Trees With Factors|[Go]({{< relref "/ChapterFour/0800~0899/0823.Binary-Trees-With-Factors.md" >}})|Medium||||49.7%| +|0828|Count Unique Characters of All Substrings of a Given String|[Go]({{< relref "/ChapterFour/0800~0899/0828.Count-Unique-Characters-of-All-Substrings-of-a-Given-String.md" >}})|Hard||||51.6%| +|0846|Hand of Straights|[Go]({{< relref "/ChapterFour/0800~0899/0846.Hand-of-Straights.md" >}})|Medium||||56.2%| +|0859|Buddy Strings|[Go]({{< relref "/ChapterFour/0800~0899/0859.Buddy-Strings.md" >}})|Easy||||29.2%| +|0884|Uncommon Words from Two Sentences|[Go]({{< relref "/ChapterFour/0800~0899/0884.Uncommon-Words-from-Two-Sentences.md" >}})|Easy||||66.4%| +|0888|Fair Candy Swap|[Go]({{< relref "/ChapterFour/0800~0899/0888.Fair-Candy-Swap.md" >}})|Easy||||60.7%| +|0890|Find and Replace Pattern|[Go]({{< relref "/ChapterFour/0800~0899/0890.Find-and-Replace-Pattern.md" >}})|Medium||||77.6%| +|0895|Maximum Frequency Stack|[Go]({{< relref "/ChapterFour/0800~0899/0895.Maximum-Frequency-Stack.md" >}})|Hard| O(n)| O(n) ||66.6%| +|0904|Fruit Into Baskets|[Go]({{< relref "/ChapterFour/0900~0999/0904.Fruit-Into-Baskets.md" >}})|Medium||||43.7%| +|0911|Online Election|[Go]({{< relref "/ChapterFour/0900~0999/0911.Online-Election.md" >}})|Medium||||52.2%| +|0914|X of a Kind in a Deck of Cards|[Go]({{< relref "/ChapterFour/0900~0999/0914.X-of-a-Kind-in-a-Deck-of-Cards.md" >}})|Easy||||31.2%| +|0916|Word Subsets|[Go]({{< relref "/ChapterFour/0900~0999/0916.Word-Subsets.md" >}})|Medium||||53.7%| +|0923|3Sum With Multiplicity|[Go]({{< relref "/ChapterFour/0900~0999/0923.3Sum-With-Multiplicity.md" >}})|Medium||||45.3%| +|0930|Binary Subarrays With Sum|[Go]({{< relref "/ChapterFour/0900~0999/0930.Binary-Subarrays-With-Sum.md" >}})|Medium| O(n)| O(n) |❤️|52.2%| +|0953|Verifying an Alien Dictionary|[Go]({{< relref "/ChapterFour/0900~0999/0953.Verifying-an-Alien-Dictionary.md" >}})|Easy||||54.5%| +|0961|N-Repeated Element in Size 2N Array|[Go]({{< relref "/ChapterFour/0900~0999/0961.N-Repeated-Element-in-Size-2N-Array.md" >}})|Easy||||76.1%| +|0966|Vowel Spellchecker|[Go]({{< relref "/ChapterFour/0900~0999/0966.Vowel-Spellchecker.md" >}})|Medium||||51.4%| +|0970|Powerful Integers|[Go]({{< relref "/ChapterFour/0900~0999/0970.Powerful-Integers.md" >}})|Medium||||43.6%| +|0981|Time Based Key-Value Store|[Go]({{< relref "/ChapterFour/0900~0999/0981.Time-Based-Key-Value-Store.md" >}})|Medium||||52.2%| +|0987|Vertical Order Traversal of a Binary Tree|[Go]({{< relref "/ChapterFour/0900~0999/0987.Vertical-Order-Traversal-of-a-Binary-Tree.md" >}})|Hard||||45.1%| +|0992|Subarrays with K Different Integers|[Go]({{< relref "/ChapterFour/0900~0999/0992.Subarrays-with-K-Different-Integers.md" >}})|Hard| O(n)| O(n) |❤️|54.6%| +|0997|Find the Town Judge|[Go]({{< relref "/ChapterFour/0900~0999/0997.Find-the-Town-Judge.md" >}})|Easy||||49.5%| +|1002|Find Common Characters|[Go]({{< relref "/ChapterFour/1000~1099/1002.Find-Common-Characters.md" >}})|Easy||||68.5%| +|1010|Pairs of Songs With Total Durations Divisible by 60|[Go]({{< relref "/ChapterFour/1000~1099/1010.Pairs-of-Songs-With-Total-Durations-Divisible-by-60.md" >}})|Medium||||52.8%| +|1048|Longest String Chain|[Go]({{< relref "/ChapterFour/1000~1099/1048.Longest-String-Chain.md" >}})|Medium||||59.3%| +|1054|Distant Barcodes|[Go]({{< relref "/ChapterFour/1000~1099/1054.Distant-Barcodes.md" >}})|Medium||||45.9%| +|1074|Number of Submatrices That Sum to Target|[Go]({{< relref "/ChapterFour/1000~1099/1074.Number-of-Submatrices-That-Sum-to-Target.md" >}})|Hard||||69.5%| +|1079|Letter Tile Possibilities|[Go]({{< relref "/ChapterFour/1000~1099/1079.Letter-Tile-Possibilities.md" >}})|Medium||||76.0%| +|1122|Relative Sort Array|[Go]({{< relref "/ChapterFour/1100~1199/1122.Relative-Sort-Array.md" >}})|Easy||||68.6%| +|1123|Lowest Common Ancestor of Deepest Leaves|[Go]({{< relref "/ChapterFour/1100~1199/1123.Lowest-Common-Ancestor-of-Deepest-Leaves.md" >}})|Medium||||70.9%| +|1128|Number of Equivalent Domino Pairs|[Go]({{< relref "/ChapterFour/1100~1199/1128.Number-of-Equivalent-Domino-Pairs.md" >}})|Easy||||47.1%| +|1160|Find Words That Can Be Formed by Characters|[Go]({{< relref "/ChapterFour/1100~1199/1160.Find-Words-That-Can-Be-Formed-by-Characters.md" >}})|Easy||||67.5%| +|1170|Compare Strings by Frequency of the Smallest Character|[Go]({{< relref "/ChapterFour/1100~1199/1170.Compare-Strings-by-Frequency-of-the-Smallest-Character.md" >}})|Medium||||61.5%| +|1171|Remove Zero Sum Consecutive Nodes from Linked List|[Go]({{< relref "/ChapterFour/1100~1199/1171.Remove-Zero-Sum-Consecutive-Nodes-from-Linked-List.md" >}})|Medium||||43.2%| +|1178|Number of Valid Words for Each Puzzle|[Go]({{< relref "/ChapterFour/1100~1199/1178.Number-of-Valid-Words-for-Each-Puzzle.md" >}})|Hard||||46.3%| +|1189|Maximum Number of Balloons|[Go]({{< relref "/ChapterFour/1100~1199/1189.Maximum-Number-of-Balloons.md" >}})|Easy||||61.0%| +|1202|Smallest String With Swaps|[Go]({{< relref "/ChapterFour/1200~1299/1202.Smallest-String-With-Swaps.md" >}})|Medium||||57.7%| +|1207|Unique Number of Occurrences|[Go]({{< relref "/ChapterFour/1200~1299/1207.Unique-Number-of-Occurrences.md" >}})|Easy||||73.5%| +|1275|Find Winner on a Tic Tac Toe Game|[Go]({{< relref "/ChapterFour/1200~1299/1275.Find-Winner-on-a-Tic-Tac-Toe-Game.md" >}})|Easy||||54.2%| +|1296|Divide Array in Sets of K Consecutive Numbers|[Go]({{< relref "/ChapterFour/1200~1299/1296.Divide-Array-in-Sets-of-K-Consecutive-Numbers.md" >}})|Medium||||56.5%| +|1396|Design Underground System|[Go]({{< relref "/ChapterFour/1300~1399/1396.Design-Underground-System.md" >}})|Medium||||73.6%| +|1442|Count Triplets That Can Form Two Arrays of Equal XOR|[Go]({{< relref "/ChapterFour/1400~1499/1442.Count-Triplets-That-Can-Form-Two-Arrays-of-Equal-XOR.md" >}})|Medium||||76.1%| +|1461|Check If a String Contains All Binary Codes of Size K|[Go]({{< relref "/ChapterFour/1400~1499/1461.Check-If-a-String-Contains-All-Binary-Codes-of-Size-K.md" >}})|Medium||||56.6%| +|1512|Number of Good Pairs|[Go]({{< relref "/ChapterFour/1500~1599/1512.Number-of-Good-Pairs.md" >}})|Easy||||88.2%| +|1600|Throne Inheritance|[Go]({{< relref "/ChapterFour/1600~1699/1600.Throne-Inheritance.md" >}})|Medium||||63.6%| +|1624|Largest Substring Between Two Equal Characters|[Go]({{< relref "/ChapterFour/1600~1699/1624.Largest-Substring-Between-Two-Equal-Characters.md" >}})|Easy||||59.1%| +|1636|Sort Array by Increasing Frequency|[Go]({{< relref "/ChapterFour/1600~1699/1636.Sort-Array-by-Increasing-Frequency.md" >}})|Easy||||69.5%| +|1640|Check Array Formation Through Concatenation|[Go]({{< relref "/ChapterFour/1600~1699/1640.Check-Array-Formation-Through-Concatenation.md" >}})|Easy||||56.2%| +|1647|Minimum Deletions to Make Character Frequencies Unique|[Go]({{< relref "/ChapterFour/1600~1699/1647.Minimum-Deletions-to-Make-Character-Frequencies-Unique.md" >}})|Medium||||59.1%| +|1656|Design an Ordered Stream|[Go]({{< relref "/ChapterFour/1600~1699/1656.Design-an-Ordered-Stream.md" >}})|Easy||||85.2%| +|1657|Determine if Two Strings Are Close|[Go]({{< relref "/ChapterFour/1600~1699/1657.Determine-if-Two-Strings-Are-Close.md" >}})|Medium||||56.3%| +|1658|Minimum Operations to Reduce X to Zero|[Go]({{< relref "/ChapterFour/1600~1699/1658.Minimum-Operations-to-Reduce-X-to-Zero.md" >}})|Medium||||37.6%| +|1674|Minimum Moves to Make Array Complementary|[Go]({{< relref "/ChapterFour/1600~1699/1674.Minimum-Moves-to-Make-Array-Complementary.md" >}})|Medium||||38.7%| +|1679|Max Number of K-Sum Pairs|[Go]({{< relref "/ChapterFour/1600~1699/1679.Max-Number-of-K-Sum-Pairs.md" >}})|Medium||||57.3%| +|1684|Count the Number of Consistent Strings|[Go]({{< relref "/ChapterFour/1600~1699/1684.Count-the-Number-of-Consistent-Strings.md" >}})|Easy||||82.3%| +|1695|Maximum Erasure Value|[Go]({{< relref "/ChapterFour/1600~1699/1695.Maximum-Erasure-Value.md" >}})|Medium||||57.6%| +|1742|Maximum Number of Balls in a Box|[Go]({{< relref "/ChapterFour/1700~1799/1742.Maximum-Number-of-Balls-in-a-Box.md" >}})|Easy||||73.6%| +|1748|Sum of Unique Elements|[Go]({{< relref "/ChapterFour/1700~1799/1748.Sum-of-Unique-Elements.md" >}})|Easy||||76.3%| +|1763|Longest Nice Substring|[Go]({{< relref "/ChapterFour/1700~1799/1763.Longest-Nice-Substring.md" >}})|Easy||||61.5%| +|2043|Simple Bank System|[Go]({{< relref "/ChapterFour/2000~2099/2043.Simple-Bank-System.md" >}})|Medium||||65.2%| +|2166|Design Bitset|[Go]({{< relref "/ChapterFour/2100~2199/2166.Design-Bitset.md" >}})|Medium||||31.8%| +|2170|Minimum Operations to Make the Array Alternating|[Go]({{< relref "/ChapterFour/2100~2199/2170.Minimum-Operations-to-Make-the-Array-Alternating.md" >}})|Medium||||33.2%| |------------|-------------------------------------------------------|-------| ----------------| ---------------|-------------|-------------|-------------| ---------------------------------------------- diff --git a/website/content/ChapterTwo/Linked_List.md b/website/content/ChapterTwo/Linked_List.md index 05452e2be..aa72c67ec 100644 --- a/website/content/ChapterTwo/Linked_List.md +++ b/website/content/ChapterTwo/Linked_List.md @@ -23,41 +23,50 @@ weight: 4 | No. | Title | Solution | Difficulty | TimeComplexity | SpaceComplexity |Favorite| Acceptance | |:--------:|:------- | :--------: | :----------: | :----: | :-----: | :-----: |:-----: | -|0002|Add Two Numbers|[Go]({{< relref "/ChapterFour/0001~0099/0002.Add-Two-Numbers.md" >}})|Medium| O(n)| O(1)||35.8%| -|0019|Remove Nth Node From End of List|[Go]({{< relref "/ChapterFour/0001~0099/0019.Remove-Nth-Node-From-End-of-List.md" >}})|Medium| O(n)| O(1)||36.2%| -|0021|Merge Two Sorted Lists|[Go]({{< relref "/ChapterFour/0001~0099/0021.Merge-Two-Sorted-Lists.md" >}})|Easy| O(log n)| O(1)||56.5%| -|0023|Merge k Sorted Lists|[Go]({{< relref "/ChapterFour/0001~0099/0023.Merge-k-Sorted-Lists.md" >}})|Hard| O(log n)| O(1)|❤️|43.2%| -|0024|Swap Nodes in Pairs|[Go]({{< relref "/ChapterFour/0001~0099/0024.Swap-Nodes-in-Pairs.md" >}})|Medium| O(n)| O(1)||53.7%| -|0025|Reverse Nodes in k-Group|[Go]({{< relref "/ChapterFour/0001~0099/0025.Reverse-Nodes-in-k-Group.md" >}})|Hard| O(log n)| O(1)|❤️|45.6%| -|0061|Rotate List|[Go]({{< relref "/ChapterFour/0001~0099/0061.Rotate-List.md" >}})|Medium| O(n)| O(1)||32.0%| -|0082|Remove Duplicates from Sorted List II|[Go]({{< relref "/ChapterFour/0001~0099/0082.Remove-Duplicates-from-Sorted-List-II.md" >}})|Medium| O(n)| O(1)||39.6%| -|0083|Remove Duplicates from Sorted List|[Go]({{< relref "/ChapterFour/0001~0099/0083.Remove-Duplicates-from-Sorted-List.md" >}})|Easy| O(n)| O(1)||46.8%| -|0086|Partition List|[Go]({{< relref "/ChapterFour/0001~0099/0086.Partition-List.md" >}})|Medium| O(n)| O(1)|❤️|44.9%| -|0092|Reverse Linked List II|[Go]({{< relref "/ChapterFour/0001~0099/0092.Reverse-Linked-List-II.md" >}})|Medium| O(n)| O(1)|❤️|40.9%| -|0109|Convert Sorted List to Binary Search Tree|[Go]({{< relref "/ChapterFour/0100~0199/0109.Convert-Sorted-List-to-Binary-Search-Tree.md" >}})|Medium| O(log n)| O(n)||50.8%| -|0138|Copy List with Random Pointer|[Go]({{< relref "/ChapterFour/0100~0199/0138.Copy-List-with-Random-Pointer.md" >}})|Medium||||41.7%| -|0141|Linked List Cycle|[Go]({{< relref "/ChapterFour/0100~0199/0141.Linked-List-Cycle.md" >}})|Easy| O(n)| O(1)|❤️|43.2%| -|0142|Linked List Cycle II|[Go]({{< relref "/ChapterFour/0100~0199/0142.Linked-List-Cycle-II.md" >}})|Medium| O(n)| O(1)|❤️|40.1%| -|0143|Reorder List|[Go]({{< relref "/ChapterFour/0100~0199/0143.Reorder-List.md" >}})|Medium| O(n)| O(1)|❤️|41.3%| -|0147|Insertion Sort List|[Go]({{< relref "/ChapterFour/0100~0199/0147.Insertion-Sort-List.md" >}})|Medium| O(n)| O(1)|❤️|44.8%| -|0148|Sort List|[Go]({{< relref "/ChapterFour/0100~0199/0148.Sort-List.md" >}})|Medium| O(n log n)| O(n)|❤️|46.9%| -|0160|Intersection of Two Linked Lists|[Go]({{< relref "/ChapterFour/0100~0199/0160.Intersection-of-Two-Linked-Lists.md" >}})|Easy| O(n)| O(1)|❤️|44.8%| -|0203|Remove Linked List Elements|[Go]({{< relref "/ChapterFour/0200~0299/0203.Remove-Linked-List-Elements.md" >}})|Easy| O(n)| O(1)||39.6%| -|0206|Reverse Linked List|[Go]({{< relref "/ChapterFour/0200~0299/0206.Reverse-Linked-List.md" >}})|Easy| O(n)| O(1)||65.9%| -|0234|Palindrome Linked List|[Go]({{< relref "/ChapterFour/0200~0299/0234.Palindrome-Linked-List.md" >}})|Easy| O(n)| O(1)||42.2%| -|0237|Delete Node in a Linked List|[Go]({{< relref "/ChapterFour/0200~0299/0237.Delete-Node-in-a-Linked-List.md" >}})|Easy| O(n)| O(1)||67.7%| -|0328|Odd Even Linked List|[Go]({{< relref "/ChapterFour/0300~0399/0328.Odd-Even-Linked-List.md" >}})|Medium| O(n)| O(1)||57.3%| -|0445|Add Two Numbers II|[Go]({{< relref "/ChapterFour/0400~0499/0445.Add-Two-Numbers-II.md" >}})|Medium| O(n)| O(n)||56.7%| -|0707|Design Linked List|[Go]({{< relref "/ChapterFour/0700~0799/0707.Design-Linked-List.md" >}})|Medium| O(n)| O(1)||26.1%| -|0725|Split Linked List in Parts|[Go]({{< relref "/ChapterFour/0700~0799/0725.Split-Linked-List-in-Parts.md" >}})|Medium| O(n)| O(1)||53.2%| -|0817|Linked List Components|[Go]({{< relref "/ChapterFour/0800~0899/0817.Linked-List-Components.md" >}})|Medium| O(n)| O(1)||57.8%| -|0876|Middle of the Linked List|[Go]({{< relref "/ChapterFour/0800~0899/0876.Middle-of-the-Linked-List.md" >}})|Easy| O(n)| O(1)|❤️|69.3%| -|1019|Next Greater Node In Linked List|[Go]({{< relref "/ChapterFour/1000~1099/1019.Next-Greater-Node-In-Linked-List.md" >}})|Medium| O(n)| O(1)||58.3%| -|1171|Remove Zero Sum Consecutive Nodes from Linked List|[Go]({{< relref "/ChapterFour/1100~1199/1171.Remove-Zero-Sum-Consecutive-Nodes-from-Linked-List.md" >}})|Medium||||41.5%| -|1290|Convert Binary Number in a Linked List to Integer|[Go]({{< relref "/ChapterFour/1200~1299/1290.Convert-Binary-Number-in-a-Linked-List-to-Integer.md" >}})|Easy||||81.7%| -|1669|Merge In Between Linked Lists|[Go]({{< relref "/ChapterFour/1600~1699/1669.Merge-In-Between-Linked-Lists.md" >}})|Medium||||75.5%| -|1670|Design Front Middle Back Queue|[Go]({{< relref "/ChapterFour/1600~1699/1670.Design-Front-Middle-Back-Queue.md" >}})|Medium||||54.1%| -|1721|Swapping Nodes in a Linked List|[Go]({{< relref "/ChapterFour/1700~1799/1721.Swapping-Nodes-in-a-Linked-List.md" >}})|Medium||||67.3%| +|0002|Add Two Numbers|[Go]({{< relref "/ChapterFour/0001~0099/0002.Add-Two-Numbers.md" >}})|Medium| O(n)| O(1)||40.4%| +|0019|Remove Nth Node From End of List|[Go]({{< relref "/ChapterFour/0001~0099/0019.Remove-Nth-Node-From-End-of-List.md" >}})|Medium| O(n)| O(1)||41.1%| +|0021|Merge Two Sorted Lists|[Go]({{< relref "/ChapterFour/0001~0099/0021.Merge-Two-Sorted-Lists.md" >}})|Easy| O(log n)| O(1)||62.5%| +|0023|Merge k Sorted Lists|[Go]({{< relref "/ChapterFour/0001~0099/0023.Merge-k-Sorted-Lists.md" >}})|Hard| O(log n)| O(1)|❤️|49.8%| +|0024|Swap Nodes in Pairs|[Go]({{< relref "/ChapterFour/0001~0099/0024.Swap-Nodes-in-Pairs.md" >}})|Medium| O(n)| O(1)||61.3%| +|0025|Reverse Nodes in k-Group|[Go]({{< relref "/ChapterFour/0001~0099/0025.Reverse-Nodes-in-k-Group.md" >}})|Hard| O(log n)| O(1)|❤️|54.7%| +|0061|Rotate List|[Go]({{< relref "/ChapterFour/0001~0099/0061.Rotate-List.md" >}})|Medium| O(n)| O(1)||36.1%| +|0082|Remove Duplicates from Sorted List II|[Go]({{< relref "/ChapterFour/0001~0099/0082.Remove-Duplicates-from-Sorted-List-II.md" >}})|Medium| O(n)| O(1)||45.9%| +|0083|Remove Duplicates from Sorted List|[Go]({{< relref "/ChapterFour/0001~0099/0083.Remove-Duplicates-from-Sorted-List.md" >}})|Easy| O(n)| O(1)||50.6%| +|0086|Partition List|[Go]({{< relref "/ChapterFour/0001~0099/0086.Partition-List.md" >}})|Medium| O(n)| O(1)|❤️|52.0%| +|0092|Reverse Linked List II|[Go]({{< relref "/ChapterFour/0001~0099/0092.Reverse-Linked-List-II.md" >}})|Medium| O(n)| O(1)|❤️|45.4%| +|0109|Convert Sorted List to Binary Search Tree|[Go]({{< relref "/ChapterFour/0100~0199/0109.Convert-Sorted-List-to-Binary-Search-Tree.md" >}})|Medium| O(log n)| O(n)||60.2%| +|0114|Flatten Binary Tree to Linked List|[Go]({{< relref "/ChapterFour/0100~0199/0114.Flatten-Binary-Tree-to-Linked-List.md" >}})|Medium||||61.8%| +|0116|Populating Next Right Pointers in Each Node|[Go]({{< relref "/ChapterFour/0100~0199/0116.Populating-Next-Right-Pointers-in-Each-Node.md" >}})|Medium||||60.4%| +|0138|Copy List with Random Pointer|[Go]({{< relref "/ChapterFour/0100~0199/0138.Copy-List-with-Random-Pointer.md" >}})|Medium||||51.4%| +|0141|Linked List Cycle|[Go]({{< relref "/ChapterFour/0100~0199/0141.Linked-List-Cycle.md" >}})|Easy| O(n)| O(1)|❤️|47.5%| +|0142|Linked List Cycle II|[Go]({{< relref "/ChapterFour/0100~0199/0142.Linked-List-Cycle-II.md" >}})|Medium| O(n)| O(1)|❤️|48.8%| +|0143|Reorder List|[Go]({{< relref "/ChapterFour/0100~0199/0143.Reorder-List.md" >}})|Medium| O(n)| O(1)|❤️|52.6%| +|0146|LRU Cache|[Go]({{< relref "/ChapterFour/0100~0199/0146.LRU-Cache.md" >}})|Medium||||40.7%| +|0147|Insertion Sort List|[Go]({{< relref "/ChapterFour/0100~0199/0147.Insertion-Sort-List.md" >}})|Medium| O(n)| O(1)|❤️|51.1%| +|0148|Sort List|[Go]({{< relref "/ChapterFour/0100~0199/0148.Sort-List.md" >}})|Medium| O(n log n)| O(n)|❤️|55.1%| +|0160|Intersection of Two Linked Lists|[Go]({{< relref "/ChapterFour/0100~0199/0160.Intersection-of-Two-Linked-Lists.md" >}})|Easy| O(n)| O(1)|❤️|54.4%| +|0203|Remove Linked List Elements|[Go]({{< relref "/ChapterFour/0200~0299/0203.Remove-Linked-List-Elements.md" >}})|Easy| O(n)| O(1)||46.0%| +|0206|Reverse Linked List|[Go]({{< relref "/ChapterFour/0200~0299/0206.Reverse-Linked-List.md" >}})|Easy| O(n)| O(1)||73.6%| +|0234|Palindrome Linked List|[Go]({{< relref "/ChapterFour/0200~0299/0234.Palindrome-Linked-List.md" >}})|Easy| O(n)| O(1)||50.2%| +|0237|Delete Node in a Linked List|[Go]({{< relref "/ChapterFour/0200~0299/0237.Delete-Node-in-a-Linked-List.md" >}})|Medium| O(n)| O(1)||76.0%| +|0328|Odd Even Linked List|[Go]({{< relref "/ChapterFour/0300~0399/0328.Odd-Even-Linked-List.md" >}})|Medium| O(n)| O(1)||61.3%| +|0382|Linked List Random Node|[Go]({{< relref "/ChapterFour/0300~0399/0382.Linked-List-Random-Node.md" >}})|Medium||||62.8%| +|0445|Add Two Numbers II|[Go]({{< relref "/ChapterFour/0400~0499/0445.Add-Two-Numbers-II.md" >}})|Medium| O(n)| O(n)||59.6%| +|0460|LFU Cache|[Go]({{< relref "/ChapterFour/0400~0499/0460.LFU-Cache.md" >}})|Hard||||43.0%| +|0622|Design Circular Queue|[Go]({{< relref "/ChapterFour/0600~0699/0622.Design-Circular-Queue.md" >}})|Medium||||51.5%| +|0705|Design HashSet|[Go]({{< relref "/ChapterFour/0700~0799/0705.Design-HashSet.md" >}})|Easy||||65.6%| +|0706|Design HashMap|[Go]({{< relref "/ChapterFour/0700~0799/0706.Design-HashMap.md" >}})|Easy||||64.7%| +|0707|Design Linked List|[Go]({{< relref "/ChapterFour/0700~0799/0707.Design-Linked-List.md" >}})|Medium| O(n)| O(1)||27.7%| +|0725|Split Linked List in Parts|[Go]({{< relref "/ChapterFour/0700~0799/0725.Split-Linked-List-in-Parts.md" >}})|Medium| O(n)| O(1)||57.2%| +|0817|Linked List Components|[Go]({{< relref "/ChapterFour/0800~0899/0817.Linked-List-Components.md" >}})|Medium| O(n)| O(1)||57.7%| +|0876|Middle of the Linked List|[Go]({{< relref "/ChapterFour/0800~0899/0876.Middle-of-the-Linked-List.md" >}})|Easy| O(n)| O(1)|❤️|75.7%| +|1019|Next Greater Node In Linked List|[Go]({{< relref "/ChapterFour/1000~1099/1019.Next-Greater-Node-In-Linked-List.md" >}})|Medium| O(n)| O(1)||59.9%| +|1171|Remove Zero Sum Consecutive Nodes from Linked List|[Go]({{< relref "/ChapterFour/1100~1199/1171.Remove-Zero-Sum-Consecutive-Nodes-from-Linked-List.md" >}})|Medium||||43.2%| +|1290|Convert Binary Number in a Linked List to Integer|[Go]({{< relref "/ChapterFour/1200~1299/1290.Convert-Binary-Number-in-a-Linked-List-to-Integer.md" >}})|Easy||||82.1%| +|1669|Merge In Between Linked Lists|[Go]({{< relref "/ChapterFour/1600~1699/1669.Merge-In-Between-Linked-Lists.md" >}})|Medium||||73.7%| +|1670|Design Front Middle Back Queue|[Go]({{< relref "/ChapterFour/1600~1699/1670.Design-Front-Middle-Back-Queue.md" >}})|Medium||||57.2%| +|1721|Swapping Nodes in a Linked List|[Go]({{< relref "/ChapterFour/1700~1799/1721.Swapping-Nodes-in-a-Linked-List.md" >}})|Medium||||67.1%| +|2181|Merge Nodes in Between Zeros|[Go]({{< relref "/ChapterFour/2100~2199/2181.Merge-Nodes-in-Between-Zeros.md" >}})|Medium||||86.3%| |------------|-------------------------------------------------------|-------| ----------------| ---------------|-------------|-------------|-------------| diff --git a/website/content/ChapterTwo/Math.md b/website/content/ChapterTwo/Math.md index 78a94d33b..20e6ba342 100644 --- a/website/content/ChapterTwo/Math.md +++ b/website/content/ChapterTwo/Math.md @@ -9,92 +9,147 @@ weight: 12 | No. | Title | Solution | Difficulty | TimeComplexity | SpaceComplexity |Favorite| Acceptance | |:--------:|:------- | :--------: | :----------: | :----: | :-----: | :-----: |:-----: | -|0002|Add Two Numbers|[Go]({{< relref "/ChapterFour/0001~0099/0002.Add-Two-Numbers.md" >}})|Medium| O(n)| O(1)||35.8%| -|0007|Reverse Integer|[Go]({{< relref "/ChapterFour/0001~0099/0007.Reverse-Integer.md" >}})|Easy||||26.0%| -|0008|String to Integer (atoi)|[Go]({{< relref "/ChapterFour/0001~0099/0008.String-to-Integer-atoi.md" >}})|Medium||||15.8%| -|0009|Palindrome Number|[Go]({{< relref "/ChapterFour/0001~0099/0009.Palindrome-Number.md" >}})|Easy||||50.2%| -|0012|Integer to Roman|[Go]({{< relref "/ChapterFour/0001~0099/0012.Integer-to-Roman.md" >}})|Medium||||57.2%| -|0013|Roman to Integer|[Go]({{< relref "/ChapterFour/0001~0099/0013.Roman-to-Integer.md" >}})|Easy||||57.1%| -|0029|Divide Two Integers|[Go]({{< relref "/ChapterFour/0001~0099/0029.Divide-Two-Integers.md" >}})|Medium||||16.9%| -|0043|Multiply Strings|[Go]({{< relref "/ChapterFour/0001~0099/0043.Multiply-Strings.md" >}})|Medium||||35.2%| -|0050|Pow(x, n)|[Go]({{< relref "/ChapterFour/0001~0099/0050.Powx-n.md" >}})|Medium| O(log n)| O(1)||31.1%| -|0060|Permutation Sequence|[Go]({{< relref "/ChapterFour/0001~0099/0060.Permutation-Sequence.md" >}})|Hard| O(n log n)| O(1)||39.7%| -|0067|Add Binary|[Go]({{< relref "/ChapterFour/0001~0099/0067.Add-Binary.md" >}})|Easy||||47.4%| -|0069|Sqrt(x)|[Go]({{< relref "/ChapterFour/0001~0099/0069.Sqrtx.md" >}})|Easy| O(log n)| O(1)||35.5%| -|0168|Excel Sheet Column Title|[Go]({{< relref "/ChapterFour/0100~0199/0168.Excel-Sheet-Column-Title.md" >}})|Easy||||32.0%| -|0171|Excel Sheet Column Number|[Go]({{< relref "/ChapterFour/0100~0199/0171.Excel-Sheet-Column-Number.md" >}})|Easy||||57.2%| -|0172|Factorial Trailing Zeroes|[Go]({{< relref "/ChapterFour/0100~0199/0172.Factorial-Trailing-Zeroes.md" >}})|Easy||||38.9%| -|0202|Happy Number|[Go]({{< relref "/ChapterFour/0200~0299/0202.Happy-Number.md" >}})|Easy| O(log n)| O(1)||51.4%| -|0204|Count Primes|[Go]({{< relref "/ChapterFour/0200~0299/0204.Count-Primes.md" >}})|Easy||||32.4%| -|0223|Rectangle Area|[Go]({{< relref "/ChapterFour/0200~0299/0223.Rectangle-Area.md" >}})|Medium||||38.4%| -|0224|Basic Calculator|[Go]({{< relref "/ChapterFour/0200~0299/0224.Basic-Calculator.md" >}})|Hard| O(n)| O(n)||38.3%| -|0231|Power of Two|[Go]({{< relref "/ChapterFour/0200~0299/0231.Power-of-Two.md" >}})|Easy| O(1)| O(1)||43.8%| -|0258|Add Digits|[Go]({{< relref "/ChapterFour/0200~0299/0258.Add-Digits.md" >}})|Easy||||58.8%| -|0263|Ugly Number|[Go]({{< relref "/ChapterFour/0200~0299/0263.Ugly-Number.md" >}})|Easy| O(log n)| O(1)||41.7%| -|0264|Ugly Number II|[Go]({{< relref "/ChapterFour/0200~0299/0264.Ugly-Number-II.md" >}})|Medium||||43.1%| -|0268|Missing Number|[Go]({{< relref "/ChapterFour/0200~0299/0268.Missing-Number.md" >}})|Easy||||55.4%| -|0326|Power of Three|[Go]({{< relref "/ChapterFour/0300~0399/0326.Power-of-Three.md" >}})|Easy| O(1)| O(1)||42.3%| -|0343|Integer Break|[Go]({{< relref "/ChapterFour/0300~0399/0343.Integer-Break.md" >}})|Medium| O(n^2)| O(n)||51.4%| -|0357|Count Numbers with Unique Digits|[Go]({{< relref "/ChapterFour/0300~0399/0357.Count-Numbers-with-Unique-Digits.md" >}})|Medium| O(1)| O(1)||49.0%| -|0367|Valid Perfect Square|[Go]({{< relref "/ChapterFour/0300~0399/0367.Valid-Perfect-Square.md" >}})|Easy||||42.3%| -|0368|Largest Divisible Subset|[Go]({{< relref "/ChapterFour/0300~0399/0368.Largest-Divisible-Subset.md" >}})|Medium||||38.5%| -|0372|Super Pow|[Go]({{< relref "/ChapterFour/0300~0399/0372.Super-Pow.md" >}})|Medium||||36.8%| -|0397|Integer Replacement|[Go]({{< relref "/ChapterFour/0300~0399/0397.Integer-Replacement.md" >}})|Medium||||33.6%| -|0413|Arithmetic Slices|[Go]({{< relref "/ChapterFour/0400~0499/0413.Arithmetic-Slices.md" >}})|Medium||||60.1%| -|0423|Reconstruct Original Digits from English|[Go]({{< relref "/ChapterFour/0400~0499/0423.Reconstruct-Original-Digits-from-English.md" >}})|Medium||||50.9%| -|0441|Arranging Coins|[Go]({{< relref "/ChapterFour/0400~0499/0441.Arranging-Coins.md" >}})|Easy||||42.7%| -|0447|Number of Boomerangs|[Go]({{< relref "/ChapterFour/0400~0499/0447.Number-of-Boomerangs.md" >}})|Medium||||52.6%| -|0453|Minimum Moves to Equal Array Elements|[Go]({{< relref "/ChapterFour/0400~0499/0453.Minimum-Moves-to-Equal-Array-Elements.md" >}})|Easy||||51.1%| -|0478|Generate Random Point in a Circle|[Go]({{< relref "/ChapterFour/0400~0499/0478.Generate-Random-Point-in-a-Circle.md" >}})|Medium||||39.1%| -|0483|Smallest Good Base|[Go]({{< relref "/ChapterFour/0400~0499/0483.Smallest-Good-Base.md" >}})|Hard||||36.4%| -|0507|Perfect Number|[Go]({{< relref "/ChapterFour/0500~0599/0507.Perfect-Number.md" >}})|Easy||||36.4%| -|0535|Encode and Decode TinyURL|[Go]({{< relref "/ChapterFour/0500~0599/0535.Encode-and-Decode-TinyURL.md" >}})|Medium||||82.4%| -|0537|Complex Number Multiplication|[Go]({{< relref "/ChapterFour/0500~0599/0537.Complex-Number-Multiplication.md" >}})|Medium||||68.4%| -|0598|Range Addition II|[Go]({{< relref "/ChapterFour/0500~0599/0598.Range-Addition-II.md" >}})|Easy||||50.3%| -|0628|Maximum Product of Three Numbers|[Go]({{< relref "/ChapterFour/0600~0699/0628.Maximum-Product-of-Three-Numbers.md" >}})|Easy| O(n)| O(1)||46.8%| -|0633|Sum of Square Numbers|[Go]({{< relref "/ChapterFour/0600~0699/0633.Sum-of-Square-Numbers.md" >}})|Medium||||32.7%| -|0645|Set Mismatch|[Go]({{< relref "/ChapterFour/0600~0699/0645.Set-Mismatch.md" >}})|Easy||||41.0%| -|0753|Cracking the Safe|[Go]({{< relref "/ChapterFour/0700~0799/0753.Cracking-the-Safe.md" >}})|Hard||||52.7%| -|0775|Global and Local Inversions|[Go]({{< relref "/ChapterFour/0700~0799/0775.Global-and-Local-Inversions.md" >}})|Medium||||46.2%| -|0781|Rabbits in Forest|[Go]({{< relref "/ChapterFour/0700~0799/0781.Rabbits-in-Forest.md" >}})|Medium||||55.8%| -|0812|Largest Triangle Area|[Go]({{< relref "/ChapterFour/0800~0899/0812.Largest-Triangle-Area.md" >}})|Easy||||59.1%| -|0836|Rectangle Overlap|[Go]({{< relref "/ChapterFour/0800~0899/0836.Rectangle-Overlap.md" >}})|Easy||||43.5%| -|0869|Reordered Power of 2|[Go]({{< relref "/ChapterFour/0800~0899/0869.Reordered-Power-of-2.md" >}})|Medium||||61.2%| -|0878|Nth Magical Number|[Go]({{< relref "/ChapterFour/0800~0899/0878.Nth-Magical-Number.md" >}})|Hard||||28.9%| -|0885|Spiral Matrix III|[Go]({{< relref "/ChapterFour/0800~0899/0885.Spiral-Matrix-III.md" >}})|Medium| O(n^2)| O(1)||71.1%| -|0887|Super Egg Drop|[Go]({{< relref "/ChapterFour/0800~0899/0887.Super-Egg-Drop.md" >}})|Hard||||27.0%| -|0891|Sum of Subsequence Widths|[Go]({{< relref "/ChapterFour/0800~0899/0891.Sum-of-Subsequence-Widths.md" >}})|Hard| O(n log n)| O(1)||33.2%| -|0892|Surface Area of 3D Shapes|[Go]({{< relref "/ChapterFour/0800~0899/0892.Surface-Area-of-3D-Shapes.md" >}})|Easy||||60.0%| -|0910|Smallest Range II|[Go]({{< relref "/ChapterFour/0900~0999/0910.Smallest-Range-II.md" >}})|Medium||||31.2%| -|0914|X of a Kind in a Deck of Cards|[Go]({{< relref "/ChapterFour/0900~0999/0914.X-of-a-Kind-in-a-Deck-of-Cards.md" >}})|Easy||||33.9%| -|0927|Three Equal Parts|[Go]({{< relref "/ChapterFour/0900~0999/0927.Three-Equal-Parts.md" >}})|Hard||||34.7%| -|0942|DI String Match|[Go]({{< relref "/ChapterFour/0900~0999/0942.DI-String-Match.md" >}})|Easy| O(n)| O(1)||73.8%| -|0949|Largest Time for Given Digits|[Go]({{< relref "/ChapterFour/0900~0999/0949.Largest-Time-for-Given-Digits.md" >}})|Medium||||36.2%| -|0952|Largest Component Size by Common Factor|[Go]({{< relref "/ChapterFour/0900~0999/0952.Largest-Component-Size-by-Common-Factor.md" >}})|Hard||||36.5%| -|0970|Powerful Integers|[Go]({{< relref "/ChapterFour/0900~0999/0970.Powerful-Integers.md" >}})|Medium||||40.1%| -|0976|Largest Perimeter Triangle|[Go]({{< relref "/ChapterFour/0900~0999/0976.Largest-Perimeter-Triangle.md" >}})|Easy| O(n log n)| O(log n) ||59.4%| -|0991|Broken Calculator|[Go]({{< relref "/ChapterFour/0900~0999/0991.Broken-Calculator.md" >}})|Medium||||49.7%| -|0996|Number of Squareful Arrays|[Go]({{< relref "/ChapterFour/0900~0999/0996.Number-of-Squareful-Arrays.md" >}})|Hard| O(n log n)| O(n) ||48.6%| -|1006|Clumsy Factorial|[Go]({{< relref "/ChapterFour/1000~1099/1006.Clumsy-Factorial.md" >}})|Medium||||53.7%| -|1017|Convert to Base -2|[Go]({{< relref "/ChapterFour/1000~1099/1017.Convert-to-Base-2.md" >}})|Medium||||59.2%| -|1025|Divisor Game|[Go]({{< relref "/ChapterFour/1000~1099/1025.Divisor-Game.md" >}})|Easy| O(1)| O(1)||66.1%| -|1037|Valid Boomerang|[Go]({{< relref "/ChapterFour/1000~1099/1037.Valid-Boomerang.md" >}})|Easy||||37.5%| -|1073|Adding Two Negabinary Numbers|[Go]({{< relref "/ChapterFour/1000~1099/1073.Adding-Two-Negabinary-Numbers.md" >}})|Medium||||34.8%| -|1093|Statistics from a Large Sample|[Go]({{< relref "/ChapterFour/1000~1099/1093.Statistics-from-a-Large-Sample.md" >}})|Medium||||48.6%| -|1154|Day of the Year|[Go]({{< relref "/ChapterFour/1100~1199/1154.Day-of-the-Year.md" >}})|Easy||||49.1%| -|1175|Prime Arrangements|[Go]({{< relref "/ChapterFour/1100~1199/1175.Prime-Arrangements.md" >}})|Easy||||51.8%| -|1201|Ugly Number III|[Go]({{< relref "/ChapterFour/1200~1299/1201.Ugly-Number-III.md" >}})|Medium||||26.5%| -|1217|Minimum Cost to Move Chips to The Same Position|[Go]({{< relref "/ChapterFour/1200~1299/1217.Minimum-Cost-to-Move-Chips-to-The-Same-Position.md" >}})|Easy||||70.9%| -|1232|Check If It Is a Straight Line|[Go]({{< relref "/ChapterFour/1200~1299/1232.Check-If-It-Is-a-Straight-Line.md" >}})|Easy||||43.1%| -|1281|Subtract the Product and Sum of Digits of an Integer|[Go]({{< relref "/ChapterFour/1200~1299/1281.Subtract-the-Product-and-Sum-of-Digits-of-an-Integer.md" >}})|Easy||||85.6%| -|1317|Convert Integer to the Sum of Two No-Zero Integers|[Go]({{< relref "/ChapterFour/1300~1399/1317.Convert-Integer-to-the-Sum-of-Two-No-Zero-Integers.md" >}})|Easy||||56.9%| -|1512|Number of Good Pairs|[Go]({{< relref "/ChapterFour/1500~1599/1512.Number-of-Good-Pairs.md" >}})|Easy||||87.6%| -|1551|Minimum Operations to Make Array Equal|[Go]({{< relref "/ChapterFour/1500~1599/1551.Minimum-Operations-to-Make-Array-Equal.md" >}})|Medium||||80.8%| -|1641|Count Sorted Vowel Strings|[Go]({{< relref "/ChapterFour/1600~1699/1641.Count-Sorted-Vowel-Strings.md" >}})|Medium||||75.4%| -|1648|Sell Diminishing-Valued Colored Balls|[Go]({{< relref "/ChapterFour/1600~1699/1648.Sell-Diminishing-Valued-Colored-Balls.md" >}})|Medium||||30.7%| -|1680|Concatenation of Consecutive Binary Numbers|[Go]({{< relref "/ChapterFour/1600~1699/1680.Concatenation-of-Consecutive-Binary-Numbers.md" >}})|Medium||||52.3%| -|1685|Sum of Absolute Differences in a Sorted Array|[Go]({{< relref "/ChapterFour/1600~1699/1685.Sum-of-Absolute-Differences-in-a-Sorted-Array.md" >}})|Medium||||63.2%| -|1716|Calculate Money in Leetcode Bank|[Go]({{< relref "/ChapterFour/1700~1799/1716.Calculate-Money-in-Leetcode-Bank.md" >}})|Easy||||64.6%| +|0002|Add Two Numbers|[Go]({{< relref "/ChapterFour/0001~0099/0002.Add-Two-Numbers.md" >}})|Medium| O(n)| O(1)||40.4%| +|0007|Reverse Integer|[Go]({{< relref "/ChapterFour/0001~0099/0007.Reverse-Integer.md" >}})|Medium||||27.5%| +|0009|Palindrome Number|[Go]({{< relref "/ChapterFour/0001~0099/0009.Palindrome-Number.md" >}})|Easy||||53.5%| +|0012|Integer to Roman|[Go]({{< relref "/ChapterFour/0001~0099/0012.Integer-to-Roman.md" >}})|Medium||||62.0%| +|0013|Roman to Integer|[Go]({{< relref "/ChapterFour/0001~0099/0013.Roman-to-Integer.md" >}})|Easy||||58.6%| +|0029|Divide Two Integers|[Go]({{< relref "/ChapterFour/0001~0099/0029.Divide-Two-Integers.md" >}})|Medium||||17.2%| +|0043|Multiply Strings|[Go]({{< relref "/ChapterFour/0001~0099/0043.Multiply-Strings.md" >}})|Medium||||39.2%| +|0048|Rotate Image|[Go]({{< relref "/ChapterFour/0001~0099/0048.Rotate-Image.md" >}})|Medium||||71.0%| +|0050|Pow(x, n)|[Go]({{< relref "/ChapterFour/0001~0099/0050.Powx-n.md" >}})|Medium| O(log n)| O(1)||33.0%| +|0060|Permutation Sequence|[Go]({{< relref "/ChapterFour/0001~0099/0060.Permutation-Sequence.md" >}})|Hard| O(n log n)| O(1)||44.4%| +|0062|Unique Paths|[Go]({{< relref "/ChapterFour/0001~0099/0062.Unique-Paths.md" >}})|Medium||||62.7%| +|0066|Plus One|[Go]({{< relref "/ChapterFour/0001~0099/0066.Plus-One.md" >}})|Easy||||43.7%| +|0067|Add Binary|[Go]({{< relref "/ChapterFour/0001~0099/0067.Add-Binary.md" >}})|Easy||||52.4%| +|0069|Sqrt(x)|[Go]({{< relref "/ChapterFour/0001~0099/0069.Sqrtx.md" >}})|Easy| O(log n)| O(1)||37.4%| +|0070|Climbing Stairs|[Go]({{< relref "/ChapterFour/0001~0099/0070.Climbing-Stairs.md" >}})|Easy||||52.2%| +|0089|Gray Code|[Go]({{< relref "/ChapterFour/0001~0099/0089.Gray-Code.md" >}})|Medium||||57.2%| +|0096|Unique Binary Search Trees|[Go]({{< relref "/ChapterFour/0001~0099/0096.Unique-Binary-Search-Trees.md" >}})|Medium||||59.7%| +|0150|Evaluate Reverse Polish Notation|[Go]({{< relref "/ChapterFour/0100~0199/0150.Evaluate-Reverse-Polish-Notation.md" >}})|Medium||||45.8%| +|0168|Excel Sheet Column Title|[Go]({{< relref "/ChapterFour/0100~0199/0168.Excel-Sheet-Column-Title.md" >}})|Easy||||35.5%| +|0171|Excel Sheet Column Number|[Go]({{< relref "/ChapterFour/0100~0199/0171.Excel-Sheet-Column-Number.md" >}})|Easy||||62.1%| +|0172|Factorial Trailing Zeroes|[Go]({{< relref "/ChapterFour/0100~0199/0172.Factorial-Trailing-Zeroes.md" >}})|Medium||||42.2%| +|0189|Rotate Array|[Go]({{< relref "/ChapterFour/0100~0199/0189.Rotate-Array.md" >}})|Medium||||39.4%| +|0202|Happy Number|[Go]({{< relref "/ChapterFour/0200~0299/0202.Happy-Number.md" >}})|Easy| O(log n)| O(1)||54.8%| +|0204|Count Primes|[Go]({{< relref "/ChapterFour/0200~0299/0204.Count-Primes.md" >}})|Medium||||33.1%| +|0223|Rectangle Area|[Go]({{< relref "/ChapterFour/0200~0299/0223.Rectangle-Area.md" >}})|Medium||||45.1%| +|0224|Basic Calculator|[Go]({{< relref "/ChapterFour/0200~0299/0224.Basic-Calculator.md" >}})|Hard| O(n)| O(n)||42.4%| +|0227|Basic Calculator II|[Go]({{< relref "/ChapterFour/0200~0299/0227.Basic-Calculator-II.md" >}})|Medium||||42.4%| +|0231|Power of Two|[Go]({{< relref "/ChapterFour/0200~0299/0231.Power-of-Two.md" >}})|Easy| O(1)| O(1)||46.0%| +|0258|Add Digits|[Go]({{< relref "/ChapterFour/0200~0299/0258.Add-Digits.md" >}})|Easy||||64.0%| +|0263|Ugly Number|[Go]({{< relref "/ChapterFour/0200~0299/0263.Ugly-Number.md" >}})|Easy| O(log n)| O(1)||42.3%| +|0264|Ugly Number II|[Go]({{< relref "/ChapterFour/0200~0299/0264.Ugly-Number-II.md" >}})|Medium||||46.2%| +|0268|Missing Number|[Go]({{< relref "/ChapterFour/0200~0299/0268.Missing-Number.md" >}})|Easy||||62.6%| +|0279|Perfect Squares|[Go]({{< relref "/ChapterFour/0200~0299/0279.Perfect-Squares.md" >}})|Medium||||52.7%| +|0319|Bulb Switcher|[Go]({{< relref "/ChapterFour/0300~0399/0319.Bulb-Switcher.md" >}})|Medium||||48.3%| +|0326|Power of Three|[Go]({{< relref "/ChapterFour/0300~0399/0326.Power-of-Three.md" >}})|Easy| O(1)| O(1)||45.5%| +|0342|Power of Four|[Go]({{< relref "/ChapterFour/0300~0399/0342.Power-of-Four.md" >}})|Easy||||46.2%| +|0343|Integer Break|[Go]({{< relref "/ChapterFour/0300~0399/0343.Integer-Break.md" >}})|Medium| O(n^2)| O(n)||56.1%| +|0357|Count Numbers with Unique Digits|[Go]({{< relref "/ChapterFour/0300~0399/0357.Count-Numbers-with-Unique-Digits.md" >}})|Medium| O(1)| O(1)||51.9%| +|0367|Valid Perfect Square|[Go]({{< relref "/ChapterFour/0300~0399/0367.Valid-Perfect-Square.md" >}})|Easy||||43.3%| +|0368|Largest Divisible Subset|[Go]({{< relref "/ChapterFour/0300~0399/0368.Largest-Divisible-Subset.md" >}})|Medium||||41.6%| +|0371|Sum of Two Integers|[Go]({{< relref "/ChapterFour/0300~0399/0371.Sum-of-Two-Integers.md" >}})|Medium||||50.7%| +|0372|Super Pow|[Go]({{< relref "/ChapterFour/0300~0399/0372.Super-Pow.md" >}})|Medium||||36.3%| +|0382|Linked List Random Node|[Go]({{< relref "/ChapterFour/0300~0399/0382.Linked-List-Random-Node.md" >}})|Medium||||62.8%| +|0384|Shuffle an Array|[Go]({{< relref "/ChapterFour/0300~0399/0384.Shuffle-an-Array.md" >}})|Medium||||57.8%| +|0390|Elimination Game|[Go]({{< relref "/ChapterFour/0300~0399/0390.Elimination-Game.md" >}})|Medium||||46.1%| +|0396|Rotate Function|[Go]({{< relref "/ChapterFour/0300~0399/0396.Rotate-Function.md" >}})|Medium||||41.1%| +|0400|Nth Digit|[Go]({{< relref "/ChapterFour/0400~0499/0400.Nth-Digit.md" >}})|Medium||||34.1%| +|0405|Convert a Number to Hexadecimal|[Go]({{< relref "/ChapterFour/0400~0499/0405.Convert-a-Number-to-Hexadecimal.md" >}})|Easy||||46.8%| +|0412|Fizz Buzz|[Go]({{< relref "/ChapterFour/0400~0499/0412.Fizz-Buzz.md" >}})|Easy||||70.0%| +|0423|Reconstruct Original Digits from English|[Go]({{< relref "/ChapterFour/0400~0499/0423.Reconstruct-Original-Digits-from-English.md" >}})|Medium||||51.2%| +|0441|Arranging Coins|[Go]({{< relref "/ChapterFour/0400~0499/0441.Arranging-Coins.md" >}})|Easy||||46.2%| +|0445|Add Two Numbers II|[Go]({{< relref "/ChapterFour/0400~0499/0445.Add-Two-Numbers-II.md" >}})|Medium||||59.6%| +|0447|Number of Boomerangs|[Go]({{< relref "/ChapterFour/0400~0499/0447.Number-of-Boomerangs.md" >}})|Medium||||54.9%| +|0453|Minimum Moves to Equal Array Elements|[Go]({{< relref "/ChapterFour/0400~0499/0453.Minimum-Moves-to-Equal-Array-Elements.md" >}})|Medium||||56.0%| +|0458|Poor Pigs|[Go]({{< relref "/ChapterFour/0400~0499/0458.Poor-Pigs.md" >}})|Hard||||62.8%| +|0462|Minimum Moves to Equal Array Elements II|[Go]({{< relref "/ChapterFour/0400~0499/0462.Minimum-Moves-to-Equal-Array-Elements-II.md" >}})|Medium||||60.0%| +|0470|Implement Rand10() Using Rand7()|[Go]({{< relref "/ChapterFour/0400~0499/0470.Implement-Rand10-Using-Rand7.md" >}})|Medium||||46.4%| +|0477|Total Hamming Distance|[Go]({{< relref "/ChapterFour/0400~0499/0477.Total-Hamming-Distance.md" >}})|Medium||||52.2%| +|0478|Generate Random Point in a Circle|[Go]({{< relref "/ChapterFour/0400~0499/0478.Generate-Random-Point-in-a-Circle.md" >}})|Medium||||39.6%| +|0483|Smallest Good Base|[Go]({{< relref "/ChapterFour/0400~0499/0483.Smallest-Good-Base.md" >}})|Hard||||38.8%| +|0492|Construct the Rectangle|[Go]({{< relref "/ChapterFour/0400~0499/0492.Construct-the-Rectangle.md" >}})|Easy||||54.8%| +|0497|Random Point in Non-overlapping Rectangles|[Go]({{< relref "/ChapterFour/0400~0499/0497.Random-Point-in-Non-overlapping-Rectangles.md" >}})|Medium||||39.4%| +|0504|Base 7|[Go]({{< relref "/ChapterFour/0500~0599/0504.Base-7.md" >}})|Easy||||48.5%| +|0507|Perfect Number|[Go]({{< relref "/ChapterFour/0500~0599/0507.Perfect-Number.md" >}})|Easy||||37.7%| +|0509|Fibonacci Number|[Go]({{< relref "/ChapterFour/0500~0599/0509.Fibonacci-Number.md" >}})|Easy||||69.8%| +|0519|Random Flip Matrix|[Go]({{< relref "/ChapterFour/0500~0599/0519.Random-Flip-Matrix.md" >}})|Medium||||40.0%| +|0523|Continuous Subarray Sum|[Go]({{< relref "/ChapterFour/0500~0599/0523.Continuous-Subarray-Sum.md" >}})|Medium||||28.5%| +|0528|Random Pick with Weight|[Go]({{< relref "/ChapterFour/0500~0599/0528.Random-Pick-with-Weight.md" >}})|Medium||||46.1%| +|0537|Complex Number Multiplication|[Go]({{< relref "/ChapterFour/0500~0599/0537.Complex-Number-Multiplication.md" >}})|Medium||||71.4%| +|0598|Range Addition II|[Go]({{< relref "/ChapterFour/0500~0599/0598.Range-Addition-II.md" >}})|Easy||||55.3%| +|0628|Maximum Product of Three Numbers|[Go]({{< relref "/ChapterFour/0600~0699/0628.Maximum-Product-of-Three-Numbers.md" >}})|Easy| O(n)| O(1)||45.9%| +|0633|Sum of Square Numbers|[Go]({{< relref "/ChapterFour/0600~0699/0633.Sum-of-Square-Numbers.md" >}})|Medium||||34.4%| +|0667|Beautiful Arrangement II|[Go]({{< relref "/ChapterFour/0600~0699/0667.Beautiful-Arrangement-II.md" >}})|Medium||||59.8%| +|0668|Kth Smallest Number in Multiplication Table|[Go]({{< relref "/ChapterFour/0600~0699/0668.Kth-Smallest-Number-in-Multiplication-Table.md" >}})|Hard||||51.4%| +|0710|Random Pick with Blacklist|[Go]({{< relref "/ChapterFour/0700~0799/0710.Random-Pick-with-Blacklist.md" >}})|Hard||||33.5%| +|0728|Self Dividing Numbers|[Go]({{< relref "/ChapterFour/0700~0799/0728.Self-Dividing-Numbers.md" >}})|Easy||||77.9%| +|0762|Prime Number of Set Bits in Binary Representation|[Go]({{< relref "/ChapterFour/0700~0799/0762.Prime-Number-of-Set-Bits-in-Binary-Representation.md" >}})|Easy||||68.0%| +|0775|Global and Local Inversions|[Go]({{< relref "/ChapterFour/0700~0799/0775.Global-and-Local-Inversions.md" >}})|Medium||||43.3%| +|0781|Rabbits in Forest|[Go]({{< relref "/ChapterFour/0700~0799/0781.Rabbits-in-Forest.md" >}})|Medium||||54.7%| +|0793|Preimage Size of Factorial Zeroes Function|[Go]({{< relref "/ChapterFour/0700~0799/0793.Preimage-Size-of-Factorial-Zeroes-Function.md" >}})|Hard||||43.2%| +|0810|Chalkboard XOR Game|[Go]({{< relref "/ChapterFour/0800~0899/0810.Chalkboard-XOR-Game.md" >}})|Hard||||55.8%| +|0812|Largest Triangle Area|[Go]({{< relref "/ChapterFour/0800~0899/0812.Largest-Triangle-Area.md" >}})|Easy||||59.9%| +|0836|Rectangle Overlap|[Go]({{< relref "/ChapterFour/0800~0899/0836.Rectangle-Overlap.md" >}})|Easy||||43.9%| +|0869|Reordered Power of 2|[Go]({{< relref "/ChapterFour/0800~0899/0869.Reordered-Power-of-2.md" >}})|Medium||||63.5%| +|0877|Stone Game|[Go]({{< relref "/ChapterFour/0800~0899/0877.Stone-Game.md" >}})|Medium||||69.7%| +|0878|Nth Magical Number|[Go]({{< relref "/ChapterFour/0800~0899/0878.Nth-Magical-Number.md" >}})|Hard||||35.4%| +|0887|Super Egg Drop|[Go]({{< relref "/ChapterFour/0800~0899/0887.Super-Egg-Drop.md" >}})|Hard||||27.1%| +|0891|Sum of Subsequence Widths|[Go]({{< relref "/ChapterFour/0800~0899/0891.Sum-of-Subsequence-Widths.md" >}})|Hard| O(n log n)| O(1)||36.7%| +|0892|Surface Area of 3D Shapes|[Go]({{< relref "/ChapterFour/0800~0899/0892.Surface-Area-of-3D-Shapes.md" >}})|Easy||||64.0%| +|0910|Smallest Range II|[Go]({{< relref "/ChapterFour/0900~0999/0910.Smallest-Range-II.md" >}})|Medium||||35.2%| +|0914|X of a Kind in a Deck of Cards|[Go]({{< relref "/ChapterFour/0900~0999/0914.X-of-a-Kind-in-a-Deck-of-Cards.md" >}})|Easy||||31.2%| +|0920|Number of Music Playlists|[Go]({{< relref "/ChapterFour/0900~0999/0920.Number-of-Music-Playlists.md" >}})|Hard||||50.7%| +|0927|Three Equal Parts|[Go]({{< relref "/ChapterFour/0900~0999/0927.Three-Equal-Parts.md" >}})|Hard||||39.6%| +|0952|Largest Component Size by Common Factor|[Go]({{< relref "/ChapterFour/0900~0999/0952.Largest-Component-Size-by-Common-Factor.md" >}})|Hard||||40.0%| +|0970|Powerful Integers|[Go]({{< relref "/ChapterFour/0900~0999/0970.Powerful-Integers.md" >}})|Medium||||43.6%| +|0973|K Closest Points to Origin|[Go]({{< relref "/ChapterFour/0900~0999/0973.K-Closest-Points-to-Origin.md" >}})|Medium||||65.7%| +|0976|Largest Perimeter Triangle|[Go]({{< relref "/ChapterFour/0900~0999/0976.Largest-Perimeter-Triangle.md" >}})|Easy| O(n log n)| O(log n) ||54.7%| +|0989|Add to Array-Form of Integer|[Go]({{< relref "/ChapterFour/0900~0999/0989.Add-to-Array-Form-of-Integer.md" >}})|Easy||||47.1%| +|0991|Broken Calculator|[Go]({{< relref "/ChapterFour/0900~0999/0991.Broken-Calculator.md" >}})|Medium||||54.1%| +|0996|Number of Squareful Arrays|[Go]({{< relref "/ChapterFour/0900~0999/0996.Number-of-Squareful-Arrays.md" >}})|Hard| O(n log n)| O(n) ||49.2%| +|1006|Clumsy Factorial|[Go]({{< relref "/ChapterFour/1000~1099/1006.Clumsy-Factorial.md" >}})|Medium||||55.5%| +|1017|Convert to Base -2|[Go]({{< relref "/ChapterFour/1000~1099/1017.Convert-to-Base-2.md" >}})|Medium||||60.9%| +|1025|Divisor Game|[Go]({{< relref "/ChapterFour/1000~1099/1025.Divisor-Game.md" >}})|Easy| O(1)| O(1)||67.6%| +|1030|Matrix Cells in Distance Order|[Go]({{< relref "/ChapterFour/1000~1099/1030.Matrix-Cells-in-Distance-Order.md" >}})|Easy||||69.7%| +|1037|Valid Boomerang|[Go]({{< relref "/ChapterFour/1000~1099/1037.Valid-Boomerang.md" >}})|Easy||||37.0%| +|1040|Moving Stones Until Consecutive II|[Go]({{< relref "/ChapterFour/1000~1099/1040.Moving-Stones-Until-Consecutive-II.md" >}})|Medium||||55.9%| +|1073|Adding Two Negabinary Numbers|[Go]({{< relref "/ChapterFour/1000~1099/1073.Adding-Two-Negabinary-Numbers.md" >}})|Medium||||36.5%| +|1093|Statistics from a Large Sample|[Go]({{< relref "/ChapterFour/1000~1099/1093.Statistics-from-a-Large-Sample.md" >}})|Medium||||43.5%| +|1104|Path In Zigzag Labelled Binary Tree|[Go]({{< relref "/ChapterFour/1100~1199/1104.Path-In-Zigzag-Labelled-Binary-Tree.md" >}})|Medium||||75.1%| +|1137|N-th Tribonacci Number|[Go]({{< relref "/ChapterFour/1100~1199/1137.N-th-Tribonacci-Number.md" >}})|Easy||||63.7%| +|1154|Day of the Year|[Go]({{< relref "/ChapterFour/1100~1199/1154.Day-of-the-Year.md" >}})|Easy||||49.6%| +|1175|Prime Arrangements|[Go]({{< relref "/ChapterFour/1100~1199/1175.Prime-Arrangements.md" >}})|Easy||||54.7%| +|1185|Day of the Week|[Go]({{< relref "/ChapterFour/1100~1199/1185.Day-of-the-Week.md" >}})|Easy||||57.4%| +|1201|Ugly Number III|[Go]({{< relref "/ChapterFour/1200~1299/1201.Ugly-Number-III.md" >}})|Medium||||28.9%| +|1217|Minimum Cost to Move Chips to The Same Position|[Go]({{< relref "/ChapterFour/1200~1299/1217.Minimum-Cost-to-Move-Chips-to-The-Same-Position.md" >}})|Easy||||71.9%| +|1232|Check If It Is a Straight Line|[Go]({{< relref "/ChapterFour/1200~1299/1232.Check-If-It-Is-a-Straight-Line.md" >}})|Easy||||40.3%| +|1252|Cells with Odd Values in a Matrix|[Go]({{< relref "/ChapterFour/1200~1299/1252.Cells-with-Odd-Values-in-a-Matrix.md" >}})|Easy||||78.5%| +|1266|Minimum Time Visiting All Points|[Go]({{< relref "/ChapterFour/1200~1299/1266.Minimum-Time-Visiting-All-Points.md" >}})|Easy||||79.1%| +|1281|Subtract the Product and Sum of Digits of an Integer|[Go]({{< relref "/ChapterFour/1200~1299/1281.Subtract-the-Product-and-Sum-of-Digits-of-an-Integer.md" >}})|Easy||||86.6%| +|1290|Convert Binary Number in a Linked List to Integer|[Go]({{< relref "/ChapterFour/1200~1299/1290.Convert-Binary-Number-in-a-Linked-List-to-Integer.md" >}})|Easy||||82.1%| +|1304|Find N Unique Integers Sum up to Zero|[Go]({{< relref "/ChapterFour/1300~1399/1304.Find-N-Unique-Integers-Sum-up-to-Zero.md" >}})|Easy||||76.9%| +|1317|Convert Integer to the Sum of Two No-Zero Integers|[Go]({{< relref "/ChapterFour/1300~1399/1317.Convert-Integer-to-the-Sum-of-Two-No-Zero-Integers.md" >}})|Easy||||55.4%| +|1442|Count Triplets That Can Form Two Arrays of Equal XOR|[Go]({{< relref "/ChapterFour/1400~1499/1442.Count-Triplets-That-Can-Form-Two-Arrays-of-Equal-XOR.md" >}})|Medium||||76.1%| +|1486|XOR Operation in an Array|[Go]({{< relref "/ChapterFour/1400~1499/1486.XOR-Operation-in-an-Array.md" >}})|Easy||||84.6%| +|1512|Number of Good Pairs|[Go]({{< relref "/ChapterFour/1500~1599/1512.Number-of-Good-Pairs.md" >}})|Easy||||88.2%| +|1518|Water Bottles|[Go]({{< relref "/ChapterFour/1500~1599/1518.Water-Bottles.md" >}})|Easy||||60.5%| +|1551|Minimum Operations to Make Array Equal|[Go]({{< relref "/ChapterFour/1500~1599/1551.Minimum-Operations-to-Make-Array-Equal.md" >}})|Medium||||81.5%| +|1573|Number of Ways to Split a String|[Go]({{< relref "/ChapterFour/1500~1599/1573.Number-of-Ways-to-Split-a-String.md" >}})|Medium||||32.5%| +|1641|Count Sorted Vowel Strings|[Go]({{< relref "/ChapterFour/1600~1699/1641.Count-Sorted-Vowel-Strings.md" >}})|Medium||||77.4%| +|1648|Sell Diminishing-Valued Colored Balls|[Go]({{< relref "/ChapterFour/1600~1699/1648.Sell-Diminishing-Valued-Colored-Balls.md" >}})|Medium||||30.4%| +|1680|Concatenation of Consecutive Binary Numbers|[Go]({{< relref "/ChapterFour/1600~1699/1680.Concatenation-of-Consecutive-Binary-Numbers.md" >}})|Medium||||57.0%| +|1685|Sum of Absolute Differences in a Sorted Array|[Go]({{< relref "/ChapterFour/1600~1699/1685.Sum-of-Absolute-Differences-in-a-Sorted-Array.md" >}})|Medium||||63.5%| +|1688|Count of Matches in Tournament|[Go]({{< relref "/ChapterFour/1600~1699/1688.Count-of-Matches-in-Tournament.md" >}})|Easy||||83.1%| +|1690|Stone Game VII|[Go]({{< relref "/ChapterFour/1600~1699/1690.Stone-Game-VII.md" >}})|Medium||||58.1%| +|1716|Calculate Money in Leetcode Bank|[Go]({{< relref "/ChapterFour/1700~1799/1716.Calculate-Money-in-Leetcode-Bank.md" >}})|Easy||||66.1%| +|1742|Maximum Number of Balls in a Box|[Go]({{< relref "/ChapterFour/1700~1799/1742.Maximum-Number-of-Balls-in-a-Box.md" >}})|Easy||||73.6%| +|2038|Remove Colored Pieces if Both Neighbors are the Same Color|[Go]({{< relref "/ChapterFour/2000~2099/2038.Remove-Colored-Pieces-if-Both-Neighbors-are-the-Same-Color.md" >}})|Medium||||57.9%| +|2165|Smallest Value of the Rearranged Number|[Go]({{< relref "/ChapterFour/2100~2199/2165.Smallest-Value-of-the-Rearranged-Number.md" >}})|Medium||||51.4%| +|2169|Count Operations to Obtain Zero|[Go]({{< relref "/ChapterFour/2100~2199/2169.Count-Operations-to-Obtain-Zero.md" >}})|Easy||||75.2%| +|2180|Count Integers With Even Digit Sum|[Go]({{< relref "/ChapterFour/2100~2199/2180.Count-Integers-With-Even-Digit-Sum.md" >}})|Easy||||65.5%| +|2183|Count Array Pairs Divisible by K|[Go]({{< relref "/ChapterFour/2100~2199/2183.Count-Array-Pairs-Divisible-by-K.md" >}})|Hard||||28.3%| |------------|-------------------------------------------------------|-------| ----------------| ---------------|-------------|-------------|-------------| diff --git a/website/content/ChapterTwo/Segment_Tree.md b/website/content/ChapterTwo/Segment_Tree.md index 8ae70545a..85d41ea58 100644 --- a/website/content/ChapterTwo/Segment_Tree.md +++ b/website/content/ChapterTwo/Segment_Tree.md @@ -37,18 +37,18 @@ weight: 18 | No. | Title | Solution | Difficulty | TimeComplexity | SpaceComplexity |Favorite| Acceptance | |:--------:|:------- | :--------: | :----------: | :----: | :-----: | :-----: |:-----: | -|0218|The Skyline Problem|[Go]({{< relref "/ChapterFour/0200~0299/0218.The-Skyline-Problem.md" >}})|Hard| O(n log n)| O(n)|❤️|36.7%| -|0307|Range Sum Query - Mutable|[Go]({{< relref "/ChapterFour/0300~0399/0307.Range-Sum-Query-Mutable.md" >}})|Medium| O(1)| O(n)||37.1%| -|0315|Count of Smaller Numbers After Self|[Go]({{< relref "/ChapterFour/0300~0399/0315.Count-of-Smaller-Numbers-After-Self.md" >}})|Hard| O(n log n)| O(n)||42.4%| -|0327|Count of Range Sum|[Go]({{< relref "/ChapterFour/0300~0399/0327.Count-of-Range-Sum.md" >}})|Hard| O(n log n)| O(n)|❤️|36.4%| -|0493|Reverse Pairs|[Go]({{< relref "/ChapterFour/0400~0499/0493.Reverse-Pairs.md" >}})|Hard| O(n log n)| O(n)||27.3%| -|0699|Falling Squares|[Go]({{< relref "/ChapterFour/0600~0699/0699.Falling-Squares.md" >}})|Hard| O(n log n)| O(n)|❤️|43.4%| -|0715|Range Module|[Go]({{< relref "/ChapterFour/0700~0799/0715.Range-Module.md" >}})|Hard| O(log n)| O(n)|❤️|41.0%| -|0732|My Calendar III|[Go]({{< relref "/ChapterFour/0700~0799/0732.My-Calendar-III.md" >}})|Hard| O(log n)| O(n)|❤️|62.5%| -|0850|Rectangle Area II|[Go]({{< relref "/ChapterFour/0800~0899/0850.Rectangle-Area-II.md" >}})|Hard| O(n log n)| O(n)|❤️|48.5%| -|1157|Online Majority Element In Subarray|[Go]({{< relref "/ChapterFour/1100~1199/1157.Online-Majority-Element-In-Subarray.md" >}})|Hard| O(log n)| O(n)|❤️|41.0%| -|1353|Maximum Number of Events That Can Be Attended|[Go]({{< relref "/ChapterFour/1300~1399/1353.Maximum-Number-of-Events-That-Can-Be-Attended.md" >}})|Medium||||30.6%| -|1649|Create Sorted Array through Instructions|[Go]({{< relref "/ChapterFour/1600~1699/1649.Create-Sorted-Array-through-Instructions.md" >}})|Hard||||36.7%| +|0218|The Skyline Problem|[Go]({{< relref "/ChapterFour/0200~0299/0218.The-Skyline-Problem.md" >}})|Hard| O(n log n)| O(n)|❤️|41.9%| +|0307|Range Sum Query - Mutable|[Go]({{< relref "/ChapterFour/0300~0399/0307.Range-Sum-Query-Mutable.md" >}})|Medium| O(1)| O(n)||40.7%| +|0315|Count of Smaller Numbers After Self|[Go]({{< relref "/ChapterFour/0300~0399/0315.Count-of-Smaller-Numbers-After-Self.md" >}})|Hard| O(n log n)| O(n)||42.6%| +|0327|Count of Range Sum|[Go]({{< relref "/ChapterFour/0300~0399/0327.Count-of-Range-Sum.md" >}})|Hard| O(n log n)| O(n)|❤️|35.8%| +|0493|Reverse Pairs|[Go]({{< relref "/ChapterFour/0400~0499/0493.Reverse-Pairs.md" >}})|Hard| O(n log n)| O(n)||30.9%| +|0699|Falling Squares|[Go]({{< relref "/ChapterFour/0600~0699/0699.Falling-Squares.md" >}})|Hard| O(n log n)| O(n)|❤️|44.7%| +|0715|Range Module|[Go]({{< relref "/ChapterFour/0700~0799/0715.Range-Module.md" >}})|Hard| O(log n)| O(n)|❤️|44.6%| +|0729|My Calendar I|[Go]({{< relref "/ChapterFour/0700~0799/0729.My-Calendar-I.md" >}})|Medium||||56.8%| +|0732|My Calendar III|[Go]({{< relref "/ChapterFour/0700~0799/0732.My-Calendar-III.md" >}})|Hard| O(log n)| O(n)|❤️|71.5%| +|0850|Rectangle Area II|[Go]({{< relref "/ChapterFour/0800~0899/0850.Rectangle-Area-II.md" >}})|Hard| O(n log n)| O(n)|❤️|53.9%| +|1157|Online Majority Element In Subarray|[Go]({{< relref "/ChapterFour/1100~1199/1157.Online-Majority-Element-In-Subarray.md" >}})|Hard| O(log n)| O(n)|❤️|41.8%| +|1649|Create Sorted Array through Instructions|[Go]({{< relref "/ChapterFour/1600~1699/1649.Create-Sorted-Array-through-Instructions.md" >}})|Hard||||37.5%| |------------|-------------------------------------------------------|-------| ----------------| ---------------|-------------|-------------|-------------| diff --git a/website/content/ChapterTwo/Sliding_Window.md b/website/content/ChapterTwo/Sliding_Window.md index 6f78461d5..f0e75b163 100644 --- a/website/content/ChapterTwo/Sliding_Window.md +++ b/website/content/ChapterTwo/Sliding_Window.md @@ -29,24 +29,41 @@ weight: 17 | No. | Title | Solution | Difficulty | TimeComplexity | SpaceComplexity |Favorite| Acceptance | |:--------:|:------- | :--------: | :----------: | :----: | :-----: | :-----: |:-----: | -|0003|Longest Substring Without Repeating Characters|[Go]({{< relref "/ChapterFour/0001~0099/0003.Longest-Substring-Without-Repeating-Characters.md" >}})|Medium| O(n)| O(1)|❤️|31.6%| -|0076|Minimum Window Substring|[Go]({{< relref "/ChapterFour/0001~0099/0076.Minimum-Window-Substring.md" >}})|Hard| O(n)| O(n)|❤️|36.3%| -|0239|Sliding Window Maximum|[Go]({{< relref "/ChapterFour/0200~0299/0239.Sliding-Window-Maximum.md" >}})|Hard| O(n * k)| O(n)|❤️|44.8%| -|0395|Longest Substring with At Least K Repeating Characters|[Go]({{< relref "/ChapterFour/0300~0399/0395.Longest-Substring-with-At-Least-K-Repeating-Characters.md" >}})|Medium||||43.7%| -|0424|Longest Repeating Character Replacement|[Go]({{< relref "/ChapterFour/0400~0499/0424.Longest-Repeating-Character-Replacement.md" >}})|Medium| O(n)| O(1) ||48.5%| -|0480|Sliding Window Median|[Go]({{< relref "/ChapterFour/0400~0499/0480.Sliding-Window-Median.md" >}})|Hard| O(n * log k)| O(k)|❤️|39.0%| -|0567|Permutation in String|[Go]({{< relref "/ChapterFour/0500~0599/0567.Permutation-in-String.md" >}})|Medium| O(n)| O(1)|❤️|44.6%| -|0978|Longest Turbulent Subarray|[Go]({{< relref "/ChapterFour/0900~0999/0978.Longest-Turbulent-Subarray.md" >}})|Medium| O(n)| O(1)|❤️|46.7%| -|0992|Subarrays with K Different Integers|[Go]({{< relref "/ChapterFour/0900~0999/0992.Subarrays-with-K-Different-Integers.md" >}})|Hard| O(n)| O(n)|❤️|50.9%| -|0995|Minimum Number of K Consecutive Bit Flips|[Go]({{< relref "/ChapterFour/0900~0999/0995.Minimum-Number-of-K-Consecutive-Bit-Flips.md" >}})|Hard| O(n)| O(1)|❤️|50.2%| -|1004|Max Consecutive Ones III|[Go]({{< relref "/ChapterFour/1000~1099/1004.Max-Consecutive-Ones-III.md" >}})|Medium| O(n)| O(1) ||61.0%| -|1040|Moving Stones Until Consecutive II|[Go]({{< relref "/ChapterFour/1000~1099/1040.Moving-Stones-Until-Consecutive-II.md" >}})|Medium| O(n log n)| O(1) |❤️|54.3%| -|1052|Grumpy Bookstore Owner|[Go]({{< relref "/ChapterFour/1000~1099/1052.Grumpy-Bookstore-Owner.md" >}})|Medium| O(n log n)| O(1) ||56.0%| -|1074|Number of Submatrices That Sum to Target|[Go]({{< relref "/ChapterFour/1000~1099/1074.Number-of-Submatrices-That-Sum-to-Target.md" >}})|Hard| O(n^3)| O(n) |❤️|64.9%| -|1208|Get Equal Substrings Within Budget|[Go]({{< relref "/ChapterFour/1200~1299/1208.Get-Equal-Substrings-Within-Budget.md" >}})|Medium||||44.4%| -|1423|Maximum Points You Can Obtain from Cards|[Go]({{< relref "/ChapterFour/1400~1499/1423.Maximum-Points-You-Can-Obtain-from-Cards.md" >}})|Medium||||47.0%| -|1438|Longest Continuous Subarray With Absolute Diff Less Than or Equal to Limit|[Go]({{< relref "/ChapterFour/1400~1499/1438.Longest-Continuous-Subarray-With-Absolute-Diff-Less-Than-or-Equal-to-Limit.md" >}})|Medium||||44.5%| -|1658|Minimum Operations to Reduce X to Zero|[Go]({{< relref "/ChapterFour/1600~1699/1658.Minimum-Operations-to-Reduce-X-to-Zero.md" >}})|Medium||||33.3%| +|0003|Longest Substring Without Repeating Characters|[Go]({{< relref "/ChapterFour/0001~0099/0003.Longest-Substring-Without-Repeating-Characters.md" >}})|Medium| O(n)| O(1)|❤️|33.8%| +|0030|Substring with Concatenation of All Words|[Go]({{< relref "/ChapterFour/0001~0099/0030.Substring-with-Concatenation-of-All-Words.md" >}})|Hard||||31.2%| +|0076|Minimum Window Substring|[Go]({{< relref "/ChapterFour/0001~0099/0076.Minimum-Window-Substring.md" >}})|Hard| O(n)| O(n)|❤️|40.9%| +|0187|Repeated DNA Sequences|[Go]({{< relref "/ChapterFour/0100~0199/0187.Repeated-DNA-Sequences.md" >}})|Medium||||47.0%| +|0209|Minimum Size Subarray Sum|[Go]({{< relref "/ChapterFour/0200~0299/0209.Minimum-Size-Subarray-Sum.md" >}})|Medium||||45.0%| +|0219|Contains Duplicate II|[Go]({{< relref "/ChapterFour/0200~0299/0219.Contains-Duplicate-II.md" >}})|Easy||||42.6%| +|0220|Contains Duplicate III|[Go]({{< relref "/ChapterFour/0200~0299/0220.Contains-Duplicate-III.md" >}})|Hard||||22.1%| +|0239|Sliding Window Maximum|[Go]({{< relref "/ChapterFour/0200~0299/0239.Sliding-Window-Maximum.md" >}})|Hard| O(n * k)| O(n)|❤️|46.3%| +|0395|Longest Substring with At Least K Repeating Characters|[Go]({{< relref "/ChapterFour/0300~0399/0395.Longest-Substring-with-At-Least-K-Repeating-Characters.md" >}})|Medium||||44.8%| +|0424|Longest Repeating Character Replacement|[Go]({{< relref "/ChapterFour/0400~0499/0424.Longest-Repeating-Character-Replacement.md" >}})|Medium| O(n)| O(1) ||52.0%| +|0438|Find All Anagrams in a String|[Go]({{< relref "/ChapterFour/0400~0499/0438.Find-All-Anagrams-in-a-String.md" >}})|Medium||||50.2%| +|0480|Sliding Window Median|[Go]({{< relref "/ChapterFour/0400~0499/0480.Sliding-Window-Median.md" >}})|Hard| O(n * log k)| O(k)|❤️|41.1%| +|0567|Permutation in String|[Go]({{< relref "/ChapterFour/0500~0599/0567.Permutation-in-String.md" >}})|Medium| O(n)| O(1)|❤️|44.3%| +|0632|Smallest Range Covering Elements from K Lists|[Go]({{< relref "/ChapterFour/0600~0699/0632.Smallest-Range-Covering-Elements-from-K-Lists.md" >}})|Hard||||61.0%| +|0643|Maximum Average Subarray I|[Go]({{< relref "/ChapterFour/0600~0699/0643.Maximum-Average-Subarray-I.md" >}})|Easy||||43.7%| +|0658|Find K Closest Elements|[Go]({{< relref "/ChapterFour/0600~0699/0658.Find-K-Closest-Elements.md" >}})|Medium||||46.8%| +|0713|Subarray Product Less Than K|[Go]({{< relref "/ChapterFour/0700~0799/0713.Subarray-Product-Less-Than-K.md" >}})|Medium||||45.8%| +|0718|Maximum Length of Repeated Subarray|[Go]({{< relref "/ChapterFour/0700~0799/0718.Maximum-Length-of-Repeated-Subarray.md" >}})|Medium||||51.3%| +|0862|Shortest Subarray with Sum at Least K|[Go]({{< relref "/ChapterFour/0800~0899/0862.Shortest-Subarray-with-Sum-at-Least-K.md" >}})|Hard||||26.0%| +|0904|Fruit Into Baskets|[Go]({{< relref "/ChapterFour/0900~0999/0904.Fruit-Into-Baskets.md" >}})|Medium||||43.7%| +|0930|Binary Subarrays With Sum|[Go]({{< relref "/ChapterFour/0900~0999/0930.Binary-Subarrays-With-Sum.md" >}})|Medium||||52.2%| +|0978|Longest Turbulent Subarray|[Go]({{< relref "/ChapterFour/0900~0999/0978.Longest-Turbulent-Subarray.md" >}})|Medium| O(n)| O(1)|❤️|47.2%| +|0992|Subarrays with K Different Integers|[Go]({{< relref "/ChapterFour/0900~0999/0992.Subarrays-with-K-Different-Integers.md" >}})|Hard| O(n)| O(n)|❤️|54.6%| +|0995|Minimum Number of K Consecutive Bit Flips|[Go]({{< relref "/ChapterFour/0900~0999/0995.Minimum-Number-of-K-Consecutive-Bit-Flips.md" >}})|Hard| O(n)| O(1)|❤️|51.2%| +|1004|Max Consecutive Ones III|[Go]({{< relref "/ChapterFour/1000~1099/1004.Max-Consecutive-Ones-III.md" >}})|Medium| O(n)| O(1) ||63.2%| +|1052|Grumpy Bookstore Owner|[Go]({{< relref "/ChapterFour/1000~1099/1052.Grumpy-Bookstore-Owner.md" >}})|Medium| O(n log n)| O(1) ||57.1%| +|1208|Get Equal Substrings Within Budget|[Go]({{< relref "/ChapterFour/1200~1299/1208.Get-Equal-Substrings-Within-Budget.md" >}})|Medium||||48.6%| +|1234|Replace the Substring for Balanced String|[Go]({{< relref "/ChapterFour/1200~1299/1234.Replace-the-Substring-for-Balanced-String.md" >}})|Medium||||37.2%| +|1423|Maximum Points You Can Obtain from Cards|[Go]({{< relref "/ChapterFour/1400~1499/1423.Maximum-Points-You-Can-Obtain-from-Cards.md" >}})|Medium||||52.2%| +|1438|Longest Continuous Subarray With Absolute Diff Less Than or Equal to Limit|[Go]({{< relref "/ChapterFour/1400~1499/1438.Longest-Continuous-Subarray-With-Absolute-Diff-Less-Than-or-Equal-to-Limit.md" >}})|Medium||||48.3%| +|1658|Minimum Operations to Reduce X to Zero|[Go]({{< relref "/ChapterFour/1600~1699/1658.Minimum-Operations-to-Reduce-X-to-Zero.md" >}})|Medium||||37.6%| +|1695|Maximum Erasure Value|[Go]({{< relref "/ChapterFour/1600~1699/1695.Maximum-Erasure-Value.md" >}})|Medium||||57.6%| +|1696|Jump Game VI|[Go]({{< relref "/ChapterFour/1600~1699/1696.Jump-Game-VI.md" >}})|Medium||||46.1%| +|1763|Longest Nice Substring|[Go]({{< relref "/ChapterFour/1700~1799/1763.Longest-Nice-Substring.md" >}})|Easy||||61.5%| +|1984|Minimum Difference Between Highest and Lowest of K Scores|[Go]({{< relref "/ChapterFour/1900~1999/1984.Minimum-Difference-Between-Highest-and-Lowest-of-K-Scores.md" >}})|Easy||||54.5%| |------------|-------------------------------------------------------|-------| ----------------| ---------------|-------------|-------------|-------------| diff --git a/website/content/ChapterTwo/Sort.md b/website/content/ChapterTwo/Sort.md deleted file mode 100644 index 50b2215df..000000000 --- a/website/content/ChapterTwo/Sort.md +++ /dev/null @@ -1,65 +0,0 @@ ---- -title: 2.14 ✅ Sort -type: docs -weight: 14 ---- - -# Sort - -![](https://img.halfrost.com/Leetcode/Sort.png) - -- 深刻的理解多路快排。第 75 题。 -- 链表的排序，插入排序(第 147 题)和归并排序(第 148 题) -- 桶排序和基数排序。第 164 题。 -- "摆动排序"。第 324 题。 -- 两两不相邻的排序。第 767 题，第 1054 题。 -- "饼子排序"。第 969 题。 - - -| No. | Title | Solution | Difficulty | TimeComplexity | SpaceComplexity |Favorite| Acceptance | -|:--------:|:------- | :--------: | :----------: | :----: | :-----: | :-----: |:-----: | -|0056|Merge Intervals|[Go]({{< relref "/ChapterFour/0001~0099/0056.Merge-Intervals.md" >}})|Medium| O(n log n)| O(log n)||41.5%| -|0057|Insert Interval|[Go]({{< relref "/ChapterFour/0001~0099/0057.Insert-Interval.md" >}})|Medium| O(n)| O(1)||35.4%| -|0075|Sort Colors|[Go]({{< relref "/ChapterFour/0001~0099/0075.Sort-Colors.md" >}})|Medium| O(n)| O(1)|❤️|50.0%| -|0147|Insertion Sort List|[Go]({{< relref "/ChapterFour/0100~0199/0147.Insertion-Sort-List.md" >}})|Medium| O(n^2)| O(1) |❤️|44.8%| -|0148|Sort List|[Go]({{< relref "/ChapterFour/0100~0199/0148.Sort-List.md" >}})|Medium|O(n log n)| O(log n)|❤️|46.9%| -|0164|Maximum Gap|[Go]({{< relref "/ChapterFour/0100~0199/0164.Maximum-Gap.md" >}})|Hard| O(n log n)| O(log n) |❤️|37.2%| -|0179|Largest Number|[Go]({{< relref "/ChapterFour/0100~0199/0179.Largest-Number.md" >}})|Medium| O(n log n)| O(log n) |❤️|30.9%| -|0220|Contains Duplicate III|[Go]({{< relref "/ChapterFour/0200~0299/0220.Contains-Duplicate-III.md" >}})|Medium| O(n log n)| O(1) |❤️|21.4%| -|0242|Valid Anagram|[Go]({{< relref "/ChapterFour/0200~0299/0242.Valid-Anagram.md" >}})|Easy| O(n)| O(n) ||59.0%| -|0274|H-Index|[Go]({{< relref "/ChapterFour/0200~0299/0274.H-Index.md" >}})|Medium| O(n)| O(n) ||36.5%| -|0315|Count of Smaller Numbers After Self|[Go]({{< relref "/ChapterFour/0300~0399/0315.Count-of-Smaller-Numbers-After-Self.md" >}})|Hard||||42.4%| -|0324|Wiggle Sort II|[Go]({{< relref "/ChapterFour/0300~0399/0324.Wiggle-Sort-II.md" >}})|Medium| O(n)| O(n)|❤️|30.9%| -|0327|Count of Range Sum|[Go]({{< relref "/ChapterFour/0300~0399/0327.Count-of-Range-Sum.md" >}})|Hard||||36.4%| -|0349|Intersection of Two Arrays|[Go]({{< relref "/ChapterFour/0300~0399/0349.Intersection-of-Two-Arrays.md" >}})|Easy| O(n)| O(n) ||65.5%| -|0350|Intersection of Two Arrays II|[Go]({{< relref "/ChapterFour/0300~0399/0350.Intersection-of-Two-Arrays-II.md" >}})|Easy| O(n)| O(n) ||52.2%| -|0493|Reverse Pairs|[Go]({{< relref "/ChapterFour/0400~0499/0493.Reverse-Pairs.md" >}})|Hard||||27.3%| -|0524|Longest Word in Dictionary through Deleting|[Go]({{< relref "/ChapterFour/0500~0599/0524.Longest-Word-in-Dictionary-through-Deleting.md" >}})|Medium| O(n)| O(1) ||50.2%| -|0710|Random Pick with Blacklist|[Go]({{< relref "/ChapterFour/0700~0799/0710.Random-Pick-with-Blacklist.md" >}})|Hard| O(n)| O(n) ||33.1%| -|0767|Reorganize String|[Go]({{< relref "/ChapterFour/0700~0799/0767.Reorganize-String.md" >}})|Medium| O(n log n)| O(log n) |❤️|50.3%| -|0853|Car Fleet|[Go]({{< relref "/ChapterFour/0800~0899/0853.Car-Fleet.md" >}})|Medium| O(n log n)| O(log n) ||44.6%| -|0922|Sort Array By Parity II|[Go]({{< relref "/ChapterFour/0900~0999/0922.Sort-Array-By-Parity-II.md" >}})|Easy| O(n)| O(1) ||70.7%| -|0969|Pancake Sorting|[Go]({{< relref "/ChapterFour/0900~0999/0969.Pancake-Sorting.md" >}})|Medium| O(n log n)| O(log n) |❤️|68.8%| -|0973|K Closest Points to Origin|[Go]({{< relref "/ChapterFour/0900~0999/0973.K-Closest-Points-to-Origin.md" >}})|Medium| O(n log n)| O(log n) ||64.7%| -|0976|Largest Perimeter Triangle|[Go]({{< relref "/ChapterFour/0900~0999/0976.Largest-Perimeter-Triangle.md" >}})|Easy| O(n log n)| O(log n) ||59.4%| -|1030|Matrix Cells in Distance Order|[Go]({{< relref "/ChapterFour/1000~1099/1030.Matrix-Cells-in-Distance-Order.md" >}})|Easy| O(n^2)| O(1) ||68.3%| -|1054|Distant Barcodes|[Go]({{< relref "/ChapterFour/1000~1099/1054.Distant-Barcodes.md" >}})|Medium| O(n log n)| O(log n) |❤️|44.3%| -|1122|Relative Sort Array|[Go]({{< relref "/ChapterFour/1100~1199/1122.Relative-Sort-Array.md" >}})|Easy||||68.1%| -|1235|Maximum Profit in Job Scheduling|[Go]({{< relref "/ChapterFour/1200~1299/1235.Maximum-Profit-in-Job-Scheduling.md" >}})|Hard||||47.8%| -|1305|All Elements in Two Binary Search Trees|[Go]({{< relref "/ChapterFour/1300~1399/1305.All-Elements-in-Two-Binary-Search-Trees.md" >}})|Medium||||77.8%| -|1329|Sort the Matrix Diagonally|[Go]({{< relref "/ChapterFour/1300~1399/1329.Sort-the-Matrix-Diagonally.md" >}})|Medium||||81.6%| -|1353|Maximum Number of Events That Can Be Attended|[Go]({{< relref "/ChapterFour/1300~1399/1353.Maximum-Number-of-Events-That-Can-Be-Attended.md" >}})|Medium||||30.6%| -|1636|Sort Array by Increasing Frequency|[Go]({{< relref "/ChapterFour/1600~1699/1636.Sort-Array-by-Increasing-Frequency.md" >}})|Easy||||67.0%| -|1640|Check Array Formation Through Concatenation|[Go]({{< relref "/ChapterFour/1600~1699/1640.Check-Array-Formation-Through-Concatenation.md" >}})|Easy||||59.7%| -|1647|Minimum Deletions to Make Character Frequencies Unique|[Go]({{< relref "/ChapterFour/1600~1699/1647.Minimum-Deletions-to-Make-Character-Frequencies-Unique.md" >}})|Medium||||55.6%| -|1648|Sell Diminishing-Valued Colored Balls|[Go]({{< relref "/ChapterFour/1600~1699/1648.Sell-Diminishing-Valued-Colored-Balls.md" >}})|Medium||||30.7%| -|1691|Maximum Height by Stacking Cuboids|[Go]({{< relref "/ChapterFour/1600~1699/1691.Maximum-Height-by-Stacking-Cuboids.md" >}})|Hard||||50.5%| -|1710|Maximum Units on a Truck|[Go]({{< relref "/ChapterFour/1700~1799/1710.Maximum-Units-on-a-Truck.md" >}})|Easy||||69.9%| -|------------|-------------------------------------------------------|-------| ----------------| ---------------|-------------|-------------|-------------| - - ----------------------------------------------- - diff --git a/website/content/ChapterTwo/Sorting.md b/website/content/ChapterTwo/Sorting.md new file mode 100755 index 000000000..f50ce2687 --- /dev/null +++ b/website/content/ChapterTwo/Sorting.md @@ -0,0 +1,136 @@ +--- +title: 2.14 ✅ Sorting +type: docs +weight: 14 +--- + +# Sorting + +![](https://img.halfrost.com/Leetcode/Sort.png) + +- 深刻的理解多路快排。第 75 题。 +- 链表的排序，插入排序(第 147 题)和归并排序(第 148 题) +- 桶排序和基数排序。第 164 题。 +- "摆动排序"。第 324 题。 +- 两两不相邻的排序。第 767 题，第 1054 题。 +- "饼子排序"。第 969 题。 + + +| No. | Title | Solution | Difficulty | TimeComplexity | SpaceComplexity |Favorite| Acceptance | +|:--------:|:------- | :--------: | :----------: | :----: | :-----: | :-----: |:-----: | +|0015|3Sum|[Go]({{< relref "/ChapterFour/0001~0099/0015.3Sum.md" >}})|Medium||||32.6%| +|0016|3Sum Closest|[Go]({{< relref "/ChapterFour/0001~0099/0016.3Sum-Closest.md" >}})|Medium||||45.8%| +|0018|4Sum|[Go]({{< relref "/ChapterFour/0001~0099/0018.4Sum.md" >}})|Medium||||35.9%| +|0049|Group Anagrams|[Go]({{< relref "/ChapterFour/0001~0099/0049.Group-Anagrams.md" >}})|Medium||||66.7%| +|0056|Merge Intervals|[Go]({{< relref "/ChapterFour/0001~0099/0056.Merge-Intervals.md" >}})|Medium| O(n log n)| O(log n)||46.2%| +|0075|Sort Colors|[Go]({{< relref "/ChapterFour/0001~0099/0075.Sort-Colors.md" >}})|Medium| O(n)| O(1)|❤️|58.5%| +|0088|Merge Sorted Array|[Go]({{< relref "/ChapterFour/0001~0099/0088.Merge-Sorted-Array.md" >}})|Easy||||46.6%| +|0147|Insertion Sort List|[Go]({{< relref "/ChapterFour/0100~0199/0147.Insertion-Sort-List.md" >}})|Medium| O(n^2)| O(1) |❤️|51.0%| +|0148|Sort List|[Go]({{< relref "/ChapterFour/0100~0199/0148.Sort-List.md" >}})|Medium|O(n log n)| O(log n)|❤️|55.1%| +|0164|Maximum Gap|[Go]({{< relref "/ChapterFour/0100~0199/0164.Maximum-Gap.md" >}})|Hard| O(n log n)| O(log n) |❤️|43.3%| +|0169|Majority Element|[Go]({{< relref "/ChapterFour/0100~0199/0169.Majority-Element.md" >}})|Easy||||63.9%| +|0179|Largest Number|[Go]({{< relref "/ChapterFour/0100~0199/0179.Largest-Number.md" >}})|Medium| O(n log n)| O(log n) |❤️|34.5%| +|0215|Kth Largest Element in an Array|[Go]({{< relref "/ChapterFour/0200~0299/0215.Kth-Largest-Element-in-an-Array.md" >}})|Medium||||66.1%| +|0217|Contains Duplicate|[Go]({{< relref "/ChapterFour/0200~0299/0217.Contains-Duplicate.md" >}})|Easy||||61.4%| +|0220|Contains Duplicate III|[Go]({{< relref "/ChapterFour/0200~0299/0220.Contains-Duplicate-III.md" >}})|Hard| O(n log n)| O(1) |❤️|22.1%| +|0229|Majority Element II|[Go]({{< relref "/ChapterFour/0200~0299/0229.Majority-Element-II.md" >}})|Medium||||45.0%| +|0242|Valid Anagram|[Go]({{< relref "/ChapterFour/0200~0299/0242.Valid-Anagram.md" >}})|Easy| O(n)| O(n) ||63.0%| +|0268|Missing Number|[Go]({{< relref "/ChapterFour/0200~0299/0268.Missing-Number.md" >}})|Easy||||62.5%| +|0274|H-Index|[Go]({{< relref "/ChapterFour/0200~0299/0274.H-Index.md" >}})|Medium| O(n)| O(n) ||38.3%| +|0324|Wiggle Sort II|[Go]({{< relref "/ChapterFour/0300~0399/0324.Wiggle-Sort-II.md" >}})|Medium| O(n)| O(n)|❤️|33.3%| +|0347|Top K Frequent Elements|[Go]({{< relref "/ChapterFour/0300~0399/0347.Top-K-Frequent-Elements.md" >}})|Medium||||64.2%| +|0349|Intersection of Two Arrays|[Go]({{< relref "/ChapterFour/0300~0399/0349.Intersection-of-Two-Arrays.md" >}})|Easy| O(n)| O(n) ||70.9%| +|0350|Intersection of Two Arrays II|[Go]({{< relref "/ChapterFour/0300~0399/0350.Intersection-of-Two-Arrays-II.md" >}})|Easy| O(n)| O(n) ||56.0%| +|0354|Russian Doll Envelopes|[Go]({{< relref "/ChapterFour/0300~0399/0354.Russian-Doll-Envelopes.md" >}})|Hard||||38.0%| +|0368|Largest Divisible Subset|[Go]({{< relref "/ChapterFour/0300~0399/0368.Largest-Divisible-Subset.md" >}})|Medium||||41.5%| +|0378|Kth Smallest Element in a Sorted Matrix|[Go]({{< relref "/ChapterFour/0300~0399/0378.Kth-Smallest-Element-in-a-Sorted-Matrix.md" >}})|Medium||||61.7%| +|0389|Find the Difference|[Go]({{< relref "/ChapterFour/0300~0399/0389.Find-the-Difference.md" >}})|Easy||||59.9%| +|0414|Third Maximum Number|[Go]({{< relref "/ChapterFour/0400~0499/0414.Third-Maximum-Number.md" >}})|Easy||||33.2%| +|0435|Non-overlapping Intervals|[Go]({{< relref "/ChapterFour/0400~0499/0435.Non-overlapping-Intervals.md" >}})|Medium||||50.3%| +|0436|Find Right Interval|[Go]({{< relref "/ChapterFour/0400~0499/0436.Find-Right-Interval.md" >}})|Medium||||50.8%| +|0451|Sort Characters By Frequency|[Go]({{< relref "/ChapterFour/0400~0499/0451.Sort-Characters-By-Frequency.md" >}})|Medium||||70.1%| +|0455|Assign Cookies|[Go]({{< relref "/ChapterFour/0400~0499/0455.Assign-Cookies.md" >}})|Easy||||49.9%| +|0462|Minimum Moves to Equal Array Elements II|[Go]({{< relref "/ChapterFour/0400~0499/0462.Minimum-Moves-to-Equal-Array-Elements-II.md" >}})|Medium||||60.0%| +|0475|Heaters|[Go]({{< relref "/ChapterFour/0400~0499/0475.Heaters.md" >}})|Medium||||36.5%| +|0506|Relative Ranks|[Go]({{< relref "/ChapterFour/0500~0599/0506.Relative-Ranks.md" >}})|Easy||||60.5%| +|0524|Longest Word in Dictionary through Deleting|[Go]({{< relref "/ChapterFour/0500~0599/0524.Longest-Word-in-Dictionary-through-Deleting.md" >}})|Medium| O(n)| O(1) ||51.0%| +|0532|K-diff Pairs in an Array|[Go]({{< relref "/ChapterFour/0500~0599/0532.K-diff-Pairs-in-an-Array.md" >}})|Medium||||41.2%| +|0561|Array Partition|[Go]({{< relref "/ChapterFour/0500~0599/0561.Array-Partition.md" >}})|Easy||||77.2%| +|0581|Shortest Unsorted Continuous Subarray|[Go]({{< relref "/ChapterFour/0500~0599/0581.Shortest-Unsorted-Continuous-Subarray.md" >}})|Medium||||36.4%| +|0594|Longest Harmonious Subsequence|[Go]({{< relref "/ChapterFour/0500~0599/0594.Longest-Harmonious-Subsequence.md" >}})|Easy||||53.5%| +|0611|Valid Triangle Number|[Go]({{< relref "/ChapterFour/0600~0699/0611.Valid-Triangle-Number.md" >}})|Medium||||50.5%| +|0628|Maximum Product of Three Numbers|[Go]({{< relref "/ChapterFour/0600~0699/0628.Maximum-Product-of-Three-Numbers.md" >}})|Easy||||45.9%| +|0632|Smallest Range Covering Elements from K Lists|[Go]({{< relref "/ChapterFour/0600~0699/0632.Smallest-Range-Covering-Elements-from-K-Lists.md" >}})|Hard||||61.0%| +|0645|Set Mismatch|[Go]({{< relref "/ChapterFour/0600~0699/0645.Set-Mismatch.md" >}})|Easy||||42.7%| +|0658|Find K Closest Elements|[Go]({{< relref "/ChapterFour/0600~0699/0658.Find-K-Closest-Elements.md" >}})|Medium||||46.8%| +|0692|Top K Frequent Words|[Go]({{< relref "/ChapterFour/0600~0699/0692.Top-K-Frequent-Words.md" >}})|Medium||||57.2%| +|0710|Random Pick with Blacklist|[Go]({{< relref "/ChapterFour/0700~0799/0710.Random-Pick-with-Blacklist.md" >}})|Hard| O(n)| O(n) ||33.5%| +|0719|Find K-th Smallest Pair Distance|[Go]({{< relref "/ChapterFour/0700~0799/0719.Find-K-th-Smallest-Pair-Distance.md" >}})|Hard||||36.7%| +|0720|Longest Word in Dictionary|[Go]({{< relref "/ChapterFour/0700~0799/0720.Longest-Word-in-Dictionary.md" >}})|Medium||||52.0%| +|0726|Number of Atoms|[Go]({{< relref "/ChapterFour/0700~0799/0726.Number-of-Atoms.md" >}})|Hard||||52.1%| +|0747|Largest Number At Least Twice of Others|[Go]({{< relref "/ChapterFour/0700~0799/0747.Largest-Number-At-Least-Twice-of-Others.md" >}})|Easy||||47.1%| +|0767|Reorganize String|[Go]({{< relref "/ChapterFour/0700~0799/0767.Reorganize-String.md" >}})|Medium| O(n log n)| O(log n) |❤️|52.9%| +|0786|K-th Smallest Prime Fraction|[Go]({{< relref "/ChapterFour/0700~0799/0786.K-th-Smallest-Prime-Fraction.md" >}})|Medium||||51.6%| +|0791|Custom Sort String|[Go]({{< relref "/ChapterFour/0700~0799/0791.Custom-Sort-String.md" >}})|Medium||||69.1%| +|0792|Number of Matching Subsequences|[Go]({{< relref "/ChapterFour/0700~0799/0792.Number-of-Matching-Subsequences.md" >}})|Medium||||51.6%| +|0825|Friends Of Appropriate Ages|[Go]({{< relref "/ChapterFour/0800~0899/0825.Friends-Of-Appropriate-Ages.md" >}})|Medium||||46.3%| +|0826|Most Profit Assigning Work|[Go]({{< relref "/ChapterFour/0800~0899/0826.Most-Profit-Assigning-Work.md" >}})|Medium||||44.9%| +|0846|Hand of Straights|[Go]({{< relref "/ChapterFour/0800~0899/0846.Hand-of-Straights.md" >}})|Medium||||56.2%| +|0853|Car Fleet|[Go]({{< relref "/ChapterFour/0800~0899/0853.Car-Fleet.md" >}})|Medium| O(n log n)| O(log n) ||50.3%| +|0869|Reordered Power of 2|[Go]({{< relref "/ChapterFour/0800~0899/0869.Reordered-Power-of-2.md" >}})|Medium||||63.5%| +|0870|Advantage Shuffle|[Go]({{< relref "/ChapterFour/0800~0899/0870.Advantage-Shuffle.md" >}})|Medium||||51.8%| +|0881|Boats to Save People|[Go]({{< relref "/ChapterFour/0800~0899/0881.Boats-to-Save-People.md" >}})|Medium||||53.1%| +|0888|Fair Candy Swap|[Go]({{< relref "/ChapterFour/0800~0899/0888.Fair-Candy-Swap.md" >}})|Easy||||60.7%| +|0891|Sum of Subsequence Widths|[Go]({{< relref "/ChapterFour/0800~0899/0891.Sum-of-Subsequence-Widths.md" >}})|Hard||||36.6%| +|0910|Smallest Range II|[Go]({{< relref "/ChapterFour/0900~0999/0910.Smallest-Range-II.md" >}})|Medium||||35.1%| +|0922|Sort Array By Parity II|[Go]({{< relref "/ChapterFour/0900~0999/0922.Sort-Array-By-Parity-II.md" >}})|Easy| O(n)| O(1) ||70.7%| +|0923|3Sum With Multiplicity|[Go]({{< relref "/ChapterFour/0900~0999/0923.3Sum-With-Multiplicity.md" >}})|Medium||||45.3%| +|0969|Pancake Sorting|[Go]({{< relref "/ChapterFour/0900~0999/0969.Pancake-Sorting.md" >}})|Medium| O(n log n)| O(log n) |❤️|70.1%| +|0973|K Closest Points to Origin|[Go]({{< relref "/ChapterFour/0900~0999/0973.K-Closest-Points-to-Origin.md" >}})|Medium| O(n log n)| O(log n) ||65.7%| +|0976|Largest Perimeter Triangle|[Go]({{< relref "/ChapterFour/0900~0999/0976.Largest-Perimeter-Triangle.md" >}})|Easy| O(n log n)| O(log n) ||54.6%| +|0977|Squares of a Sorted Array|[Go]({{< relref "/ChapterFour/0900~0999/0977.Squares-of-a-Sorted-Array.md" >}})|Easy||||71.9%| +|1005|Maximize Sum Of Array After K Negations|[Go]({{< relref "/ChapterFour/1000~1099/1005.Maximize-Sum-Of-Array-After-K-Negations.md" >}})|Easy||||50.9%| +|1030|Matrix Cells in Distance Order|[Go]({{< relref "/ChapterFour/1000~1099/1030.Matrix-Cells-in-Distance-Order.md" >}})|Easy| O(n^2)| O(1) ||69.7%| +|1040|Moving Stones Until Consecutive II|[Go]({{< relref "/ChapterFour/1000~1099/1040.Moving-Stones-Until-Consecutive-II.md" >}})|Medium||||55.9%| +|1051|Height Checker|[Go]({{< relref "/ChapterFour/1000~1099/1051.Height-Checker.md" >}})|Easy||||75.6%| +|1054|Distant Barcodes|[Go]({{< relref "/ChapterFour/1000~1099/1054.Distant-Barcodes.md" >}})|Medium| O(n log n)| O(log n) |❤️|45.8%| +|1122|Relative Sort Array|[Go]({{< relref "/ChapterFour/1100~1199/1122.Relative-Sort-Array.md" >}})|Easy||||68.6%| +|1170|Compare Strings by Frequency of the Smallest Character|[Go]({{< relref "/ChapterFour/1100~1199/1170.Compare-Strings-by-Frequency-of-the-Smallest-Character.md" >}})|Medium||||61.5%| +|1200|Minimum Absolute Difference|[Go]({{< relref "/ChapterFour/1200~1299/1200.Minimum-Absolute-Difference.md" >}})|Easy||||69.6%| +|1235|Maximum Profit in Job Scheduling|[Go]({{< relref "/ChapterFour/1200~1299/1235.Maximum-Profit-in-Job-Scheduling.md" >}})|Hard||||53.4%| +|1296|Divide Array in Sets of K Consecutive Numbers|[Go]({{< relref "/ChapterFour/1200~1299/1296.Divide-Array-in-Sets-of-K-Consecutive-Numbers.md" >}})|Medium||||56.5%| +|1300|Sum of Mutated Array Closest to Target|[Go]({{< relref "/ChapterFour/1300~1399/1300.Sum-of-Mutated-Array-Closest-to-Target.md" >}})|Medium||||43.6%| +|1305|All Elements in Two Binary Search Trees|[Go]({{< relref "/ChapterFour/1300~1399/1305.All-Elements-in-Two-Binary-Search-Trees.md" >}})|Medium||||79.8%| +|1329|Sort the Matrix Diagonally|[Go]({{< relref "/ChapterFour/1300~1399/1329.Sort-the-Matrix-Diagonally.md" >}})|Medium||||83.3%| +|1337|The K Weakest Rows in a Matrix|[Go]({{< relref "/ChapterFour/1300~1399/1337.The-K-Weakest-Rows-in-a-Matrix.md" >}})|Easy||||72.1%| +|1353|Maximum Number of Events That Can Be Attended|[Go]({{< relref "/ChapterFour/1300~1399/1353.Maximum-Number-of-Events-That-Can-Be-Attended.md" >}})|Medium||||32.5%| +|1383|Maximum Performance of a Team|[Go]({{< relref "/ChapterFour/1300~1399/1383.Maximum-Performance-of-a-Team.md" >}})|Hard||||48.5%| +|1385|Find the Distance Value Between Two Arrays|[Go]({{< relref "/ChapterFour/1300~1399/1385.Find-the-Distance-Value-Between-Two-Arrays.md" >}})|Easy||||66.5%| +|1464|Maximum Product of Two Elements in an Array|[Go]({{< relref "/ChapterFour/1400~1499/1464.Maximum-Product-of-Two-Elements-in-an-Array.md" >}})|Easy||||79.9%| +|1465|Maximum Area of a Piece of Cake After Horizontal and Vertical Cuts|[Go]({{< relref "/ChapterFour/1400~1499/1465.Maximum-Area-of-a-Piece-of-Cake-After-Horizontal-and-Vertical-Cuts.md" >}})|Medium||||40.9%| +|1608|Special Array With X Elements Greater Than or Equal X|[Go]({{< relref "/ChapterFour/1600~1699/1608.Special-Array-With-X-Elements-Greater-Than-or-Equal-X.md" >}})|Easy||||60.5%| +|1619|Mean of Array After Removing Some Elements|[Go]({{< relref "/ChapterFour/1600~1699/1619.Mean-of-Array-After-Removing-Some-Elements.md" >}})|Easy||||65.7%| +|1636|Sort Array by Increasing Frequency|[Go]({{< relref "/ChapterFour/1600~1699/1636.Sort-Array-by-Increasing-Frequency.md" >}})|Easy||||69.5%| +|1647|Minimum Deletions to Make Character Frequencies Unique|[Go]({{< relref "/ChapterFour/1600~1699/1647.Minimum-Deletions-to-Make-Character-Frequencies-Unique.md" >}})|Medium||||59.1%| +|1648|Sell Diminishing-Valued Colored Balls|[Go]({{< relref "/ChapterFour/1600~1699/1648.Sell-Diminishing-Valued-Colored-Balls.md" >}})|Medium||||30.5%| +|1657|Determine if Two Strings Are Close|[Go]({{< relref "/ChapterFour/1600~1699/1657.Determine-if-Two-Strings-Are-Close.md" >}})|Medium||||56.3%| +|1665|Minimum Initial Energy to Finish Tasks|[Go]({{< relref "/ChapterFour/1600~1699/1665.Minimum-Initial-Energy-to-Finish-Tasks.md" >}})|Hard||||56.3%| +|1679|Max Number of K-Sum Pairs|[Go]({{< relref "/ChapterFour/1600~1699/1679.Max-Number-of-K-Sum-Pairs.md" >}})|Medium||||57.3%| +|1691|Maximum Height by Stacking Cuboids|[Go]({{< relref "/ChapterFour/1600~1699/1691.Maximum-Height-by-Stacking-Cuboids.md" >}})|Hard||||54.4%| +|1710|Maximum Units on a Truck|[Go]({{< relref "/ChapterFour/1700~1799/1710.Maximum-Units-on-a-Truck.md" >}})|Easy||||73.8%| +|1818|Minimum Absolute Sum Difference|[Go]({{< relref "/ChapterFour/1800~1899/1818.Minimum-Absolute-Sum-Difference.md" >}})|Medium||||30.4%| +|1846|Maximum Element After Decreasing and Rearranging|[Go]({{< relref "/ChapterFour/1800~1899/1846.Maximum-Element-After-Decreasing-and-Rearranging.md" >}})|Medium||||58.9%| +|1877|Minimize Maximum Pair Sum in Array|[Go]({{< relref "/ChapterFour/1800~1899/1877.Minimize-Maximum-Pair-Sum-in-Array.md" >}})|Medium||||79.9%| +|1984|Minimum Difference Between Highest and Lowest of K Scores|[Go]({{< relref "/ChapterFour/1900~1999/1984.Minimum-Difference-Between-Highest-and-Lowest-of-K-Scores.md" >}})|Easy||||54.4%| +|2037|Minimum Number of Moves to Seat Everyone|[Go]({{< relref "/ChapterFour/2000~2099/2037.Minimum-Number-of-Moves-to-Seat-Everyone.md" >}})|Easy||||82.1%| +|2164|Sort Even and Odd Indices Independently|[Go]({{< relref "/ChapterFour/2100~2199/2164.Sort-Even-and-Odd-Indices-Independently.md" >}})|Easy||||65.0%| +|2165|Smallest Value of the Rearranged Number|[Go]({{< relref "/ChapterFour/2100~2199/2165.Smallest-Value-of-the-Rearranged-Number.md" >}})|Medium||||51.4%| +|2171|Removing Minimum Number of Magic Beans|[Go]({{< relref "/ChapterFour/2100~2199/2171.Removing-Minimum-Number-of-Magic-Beans.md" >}})|Medium||||42.1%| +|------------|-------------------------------------------------------|-------| ----------------| ---------------|-------------|-------------|-------------| + + +---------------------------------------------- + diff --git a/website/content/ChapterTwo/Stack.md b/website/content/ChapterTwo/Stack.md index bda3810b7..5b5c28b9a 100644 --- a/website/content/ChapterTwo/Stack.md +++ b/website/content/ChapterTwo/Stack.md @@ -17,49 +17,63 @@ weight: 5 | No. | Title | Solution | Difficulty | TimeComplexity | SpaceComplexity |Favorite| Acceptance | |:--------:|:------- | :--------: | :----------: | :----: | :-----: | :-----: |:-----: | -|0020|Valid Parentheses|[Go]({{< relref "/ChapterFour/0001~0099/0020.Valid-Parentheses.md" >}})|Easy| O(log n)| O(1)||40.0%| -|0042|Trapping Rain Water|[Go]({{< relref "/ChapterFour/0001~0099/0042.Trapping-Rain-Water.md" >}})|Hard| O(n)| O(1)|❤️|51.8%| -|0071|Simplify Path|[Go]({{< relref "/ChapterFour/0001~0099/0071.Simplify-Path.md" >}})|Medium| O(n)| O(n)|❤️|35.0%| -|0084|Largest Rectangle in Histogram|[Go]({{< relref "/ChapterFour/0001~0099/0084.Largest-Rectangle-in-Histogram.md" >}})|Hard| O(n)| O(n)|❤️|37.5%| -|0094|Binary Tree Inorder Traversal|[Go]({{< relref "/ChapterFour/0001~0099/0094.Binary-Tree-Inorder-Traversal.md" >}})|Medium| O(n)| O(1)||66.5%| -|0103|Binary Tree Zigzag Level Order Traversal|[Go]({{< relref "/ChapterFour/0100~0199/0103.Binary-Tree-Zigzag-Level-Order-Traversal.md" >}})|Medium| O(n)| O(n)||50.6%| -|0144|Binary Tree Preorder Traversal|[Go]({{< relref "/ChapterFour/0100~0199/0144.Binary-Tree-Preorder-Traversal.md" >}})|Medium| O(n)| O(1)||58.0%| -|0145|Binary Tree Postorder Traversal|[Go]({{< relref "/ChapterFour/0100~0199/0145.Binary-Tree-Postorder-Traversal.md" >}})|Medium| O(n)| O(1)||58.2%| -|0150|Evaluate Reverse Polish Notation|[Go]({{< relref "/ChapterFour/0100~0199/0150.Evaluate-Reverse-Polish-Notation.md" >}})|Medium| O(n)| O(1)||38.4%| -|0155|Min Stack|[Go]({{< relref "/ChapterFour/0100~0199/0155.Min-Stack.md" >}})|Easy| O(n)| O(n)||46.9%| -|0173|Binary Search Tree Iterator|[Go]({{< relref "/ChapterFour/0100~0199/0173.Binary-Search-Tree-Iterator.md" >}})|Medium| O(n)| O(1)||60.8%| -|0224|Basic Calculator|[Go]({{< relref "/ChapterFour/0200~0299/0224.Basic-Calculator.md" >}})|Hard| O(n)| O(n)||38.3%| -|0225|Implement Stack using Queues|[Go]({{< relref "/ChapterFour/0200~0299/0225.Implement-Stack-using-Queues.md" >}})|Easy| O(n)| O(n)||48.1%| -|0227|Basic Calculator II|[Go]({{< relref "/ChapterFour/0200~0299/0227.Basic-Calculator-II.md" >}})|Medium||||38.9%| -|0232|Implement Queue using Stacks|[Go]({{< relref "/ChapterFour/0200~0299/0232.Implement-Queue-using-Stacks.md" >}})|Easy| O(n)| O(n)||52.9%| -|0331|Verify Preorder Serialization of a Binary Tree|[Go]({{< relref "/ChapterFour/0300~0399/0331.Verify-Preorder-Serialization-of-a-Binary-Tree.md" >}})|Medium| O(n)| O(1)||41.2%| -|0341|Flatten Nested List Iterator|[Go]({{< relref "/ChapterFour/0300~0399/0341.Flatten-Nested-List-Iterator.md" >}})|Medium||||56.0%| -|0385|Mini Parser|[Go]({{< relref "/ChapterFour/0300~0399/0385.Mini-Parser.md" >}})|Medium||||34.7%| -|0394|Decode String|[Go]({{< relref "/ChapterFour/0300~0399/0394.Decode-String.md" >}})|Medium| O(n)| O(n)||53.1%| -|0402|Remove K Digits|[Go]({{< relref "/ChapterFour/0400~0499/0402.Remove-K-Digits.md" >}})|Medium| O(n)| O(1)||28.7%| -|0456|132 Pattern|[Go]({{< relref "/ChapterFour/0400~0499/0456.132-Pattern.md" >}})|Medium| O(n)| O(n)||30.7%| -|0496|Next Greater Element I|[Go]({{< relref "/ChapterFour/0400~0499/0496.Next-Greater-Element-I.md" >}})|Easy| O(n)| O(n)||66.0%| -|0503|Next Greater Element II|[Go]({{< relref "/ChapterFour/0500~0599/0503.Next-Greater-Element-II.md" >}})|Medium| O(n)| O(n)||58.9%| -|0636|Exclusive Time of Functions|[Go]({{< relref "/ChapterFour/0600~0699/0636.Exclusive-Time-of-Functions.md" >}})|Medium| O(n)| O(n)||55.2%| -|0682|Baseball Game|[Go]({{< relref "/ChapterFour/0600~0699/0682.Baseball-Game.md" >}})|Easy| O(n)| O(n)||67.5%| -|0726|Number of Atoms|[Go]({{< relref "/ChapterFour/0700~0799/0726.Number-of-Atoms.md" >}})|Hard| O(n)| O(n) |❤️|51.0%| -|0735|Asteroid Collision|[Go]({{< relref "/ChapterFour/0700~0799/0735.Asteroid-Collision.md" >}})|Medium| O(n)| O(n) ||43.4%| -|0739|Daily Temperatures|[Go]({{< relref "/ChapterFour/0700~0799/0739.Daily-Temperatures.md" >}})|Medium| O(n)| O(n) ||64.9%| -|0844|Backspace String Compare|[Go]({{< relref "/ChapterFour/0800~0899/0844.Backspace-String-Compare.md" >}})|Easy| O(n)| O(n) ||47.2%| -|0856|Score of Parentheses|[Go]({{< relref "/ChapterFour/0800~0899/0856.Score-of-Parentheses.md" >}})|Medium| O(n)| O(n)||64.9%| -|0880|Decoded String at Index|[Go]({{< relref "/ChapterFour/0800~0899/0880.Decoded-String-at-Index.md" >}})|Medium| O(n)| O(n)||28.2%| -|0895|Maximum Frequency Stack|[Go]({{< relref "/ChapterFour/0800~0899/0895.Maximum-Frequency-Stack.md" >}})|Hard| O(n)| O(n) ||63.3%| -|0901|Online Stock Span|[Go]({{< relref "/ChapterFour/0900~0999/0901.Online-Stock-Span.md" >}})|Medium| O(n)| O(n) ||61.5%| -|0907|Sum of Subarray Minimums|[Go]({{< relref "/ChapterFour/0900~0999/0907.Sum-of-Subarray-Minimums.md" >}})|Medium| O(n)| O(n)|❤️|33.1%| -|0921|Minimum Add to Make Parentheses Valid|[Go]({{< relref "/ChapterFour/0900~0999/0921.Minimum-Add-to-Make-Parentheses-Valid.md" >}})|Medium| O(n)| O(n)||75.0%| -|0946|Validate Stack Sequences|[Go]({{< relref "/ChapterFour/0900~0999/0946.Validate-Stack-Sequences.md" >}})|Medium| O(n)| O(n)||64.5%| -|1003|Check If Word Is Valid After Substitutions|[Go]({{< relref "/ChapterFour/1000~1099/1003.Check-If-Word-Is-Valid-After-Substitutions.md" >}})|Medium| O(n)| O(1)||56.7%| -|1019|Next Greater Node In Linked List|[Go]({{< relref "/ChapterFour/1000~1099/1019.Next-Greater-Node-In-Linked-List.md" >}})|Medium| O(n)| O(1)||58.3%| -|1021|Remove Outermost Parentheses|[Go]({{< relref "/ChapterFour/1000~1099/1021.Remove-Outermost-Parentheses.md" >}})|Easy| O(n)| O(1)||79.2%| -|1047|Remove All Adjacent Duplicates In String|[Go]({{< relref "/ChapterFour/1000~1099/1047.Remove-All-Adjacent-Duplicates-In-String.md" >}})|Easy| O(n)| O(1)||71.5%| -|1209|Remove All Adjacent Duplicates in String II|[Go]({{< relref "/ChapterFour/1200~1299/1209.Remove-All-Adjacent-Duplicates-in-String-II.md" >}})|Medium||||57.7%| -|1249|Minimum Remove to Make Valid Parentheses|[Go]({{< relref "/ChapterFour/1200~1299/1249.Minimum-Remove-to-Make-Valid-Parentheses.md" >}})|Medium||||64.3%| -|1673|Find the Most Competitive Subsequence|[Go]({{< relref "/ChapterFour/1600~1699/1673.Find-the-Most-Competitive-Subsequence.md" >}})|Medium||||45.5%| +|0020|Valid Parentheses|[Go]({{< relref "/ChapterFour/0001~0099/0020.Valid-Parentheses.md" >}})|Easy| O(log n)| O(1)||40.2%| +|0032|Longest Valid Parentheses|[Go]({{< relref "/ChapterFour/0001~0099/0032.Longest-Valid-Parentheses.md" >}})|Hard||||32.8%| +|0042|Trapping Rain Water|[Go]({{< relref "/ChapterFour/0001~0099/0042.Trapping-Rain-Water.md" >}})|Hard| O(n)| O(1)|❤️|59.2%| +|0071|Simplify Path|[Go]({{< relref "/ChapterFour/0001~0099/0071.Simplify-Path.md" >}})|Medium| O(n)| O(n)|❤️|39.3%| +|0084|Largest Rectangle in Histogram|[Go]({{< relref "/ChapterFour/0001~0099/0084.Largest-Rectangle-in-Histogram.md" >}})|Hard| O(n)| O(n)|❤️|42.6%| +|0094|Binary Tree Inorder Traversal|[Go]({{< relref "/ChapterFour/0001~0099/0094.Binary-Tree-Inorder-Traversal.md" >}})|Easy| O(n)| O(1)||73.8%| +|0114|Flatten Binary Tree to Linked List|[Go]({{< relref "/ChapterFour/0100~0199/0114.Flatten-Binary-Tree-to-Linked-List.md" >}})|Medium||||61.8%| +|0143|Reorder List|[Go]({{< relref "/ChapterFour/0100~0199/0143.Reorder-List.md" >}})|Medium||||52.5%| +|0144|Binary Tree Preorder Traversal|[Go]({{< relref "/ChapterFour/0100~0199/0144.Binary-Tree-Preorder-Traversal.md" >}})|Easy| O(n)| O(1)||66.8%| +|0145|Binary Tree Postorder Traversal|[Go]({{< relref "/ChapterFour/0100~0199/0145.Binary-Tree-Postorder-Traversal.md" >}})|Easy| O(n)| O(1)||67.9%| +|0150|Evaluate Reverse Polish Notation|[Go]({{< relref "/ChapterFour/0100~0199/0150.Evaluate-Reverse-Polish-Notation.md" >}})|Medium| O(n)| O(1)||45.7%| +|0155|Min Stack|[Go]({{< relref "/ChapterFour/0100~0199/0155.Min-Stack.md" >}})|Medium| O(n)| O(n)||52.3%| +|0173|Binary Search Tree Iterator|[Go]({{< relref "/ChapterFour/0100~0199/0173.Binary-Search-Tree-Iterator.md" >}})|Medium| O(n)| O(1)||69.7%| +|0224|Basic Calculator|[Go]({{< relref "/ChapterFour/0200~0299/0224.Basic-Calculator.md" >}})|Hard| O(n)| O(n)||42.4%| +|0225|Implement Stack using Queues|[Go]({{< relref "/ChapterFour/0200~0299/0225.Implement-Stack-using-Queues.md" >}})|Easy| O(n)| O(n)||58.6%| +|0227|Basic Calculator II|[Go]({{< relref "/ChapterFour/0200~0299/0227.Basic-Calculator-II.md" >}})|Medium||||42.4%| +|0232|Implement Queue using Stacks|[Go]({{< relref "/ChapterFour/0200~0299/0232.Implement-Queue-using-Stacks.md" >}})|Easy| O(n)| O(n)||63.2%| +|0234|Palindrome Linked List|[Go]({{< relref "/ChapterFour/0200~0299/0234.Palindrome-Linked-List.md" >}})|Easy||||50.2%| +|0331|Verify Preorder Serialization of a Binary Tree|[Go]({{< relref "/ChapterFour/0300~0399/0331.Verify-Preorder-Serialization-of-a-Binary-Tree.md" >}})|Medium| O(n)| O(1)||44.6%| +|0341|Flatten Nested List Iterator|[Go]({{< relref "/ChapterFour/0300~0399/0341.Flatten-Nested-List-Iterator.md" >}})|Medium||||61.8%| +|0385|Mini Parser|[Go]({{< relref "/ChapterFour/0300~0399/0385.Mini-Parser.md" >}})|Medium||||36.9%| +|0394|Decode String|[Go]({{< relref "/ChapterFour/0300~0399/0394.Decode-String.md" >}})|Medium| O(n)| O(n)||57.9%| +|0402|Remove K Digits|[Go]({{< relref "/ChapterFour/0400~0499/0402.Remove-K-Digits.md" >}})|Medium| O(n)| O(1)||30.6%| +|0445|Add Two Numbers II|[Go]({{< relref "/ChapterFour/0400~0499/0445.Add-Two-Numbers-II.md" >}})|Medium||||59.6%| +|0456|132 Pattern|[Go]({{< relref "/ChapterFour/0400~0499/0456.132-Pattern.md" >}})|Medium| O(n)| O(n)||32.4%| +|0496|Next Greater Element I|[Go]({{< relref "/ChapterFour/0400~0499/0496.Next-Greater-Element-I.md" >}})|Easy| O(n)| O(n)||71.4%| +|0503|Next Greater Element II|[Go]({{< relref "/ChapterFour/0500~0599/0503.Next-Greater-Element-II.md" >}})|Medium| O(n)| O(n)||63.2%| +|0581|Shortest Unsorted Continuous Subarray|[Go]({{< relref "/ChapterFour/0500~0599/0581.Shortest-Unsorted-Continuous-Subarray.md" >}})|Medium||||36.4%| +|0589|N-ary Tree Preorder Traversal|[Go]({{< relref "/ChapterFour/0500~0599/0589.N-ary-Tree-Preorder-Traversal.md" >}})|Easy||||75.9%| +|0636|Exclusive Time of Functions|[Go]({{< relref "/ChapterFour/0600~0699/0636.Exclusive-Time-of-Functions.md" >}})|Medium| O(n)| O(n)||61.2%| +|0682|Baseball Game|[Go]({{< relref "/ChapterFour/0600~0699/0682.Baseball-Game.md" >}})|Easy| O(n)| O(n)||74.3%| +|0726|Number of Atoms|[Go]({{< relref "/ChapterFour/0700~0799/0726.Number-of-Atoms.md" >}})|Hard| O(n)| O(n) |❤️|52.1%| +|0735|Asteroid Collision|[Go]({{< relref "/ChapterFour/0700~0799/0735.Asteroid-Collision.md" >}})|Medium| O(n)| O(n) ||44.4%| +|0739|Daily Temperatures|[Go]({{< relref "/ChapterFour/0700~0799/0739.Daily-Temperatures.md" >}})|Medium| O(n)| O(n) ||66.3%| +|0844|Backspace String Compare|[Go]({{< relref "/ChapterFour/0800~0899/0844.Backspace-String-Compare.md" >}})|Easy| O(n)| O(n) ||48.1%| +|0853|Car Fleet|[Go]({{< relref "/ChapterFour/0800~0899/0853.Car-Fleet.md" >}})|Medium||||50.3%| +|0856|Score of Parentheses|[Go]({{< relref "/ChapterFour/0800~0899/0856.Score-of-Parentheses.md" >}})|Medium| O(n)| O(n)||64.8%| +|0880|Decoded String at Index|[Go]({{< relref "/ChapterFour/0800~0899/0880.Decoded-String-at-Index.md" >}})|Medium| O(n)| O(n)||28.3%| +|0895|Maximum Frequency Stack|[Go]({{< relref "/ChapterFour/0800~0899/0895.Maximum-Frequency-Stack.md" >}})|Hard| O(n)| O(n) ||66.6%| +|0897|Increasing Order Search Tree|[Go]({{< relref "/ChapterFour/0800~0899/0897.Increasing-Order-Search-Tree.md" >}})|Easy||||78.4%| +|0901|Online Stock Span|[Go]({{< relref "/ChapterFour/0900~0999/0901.Online-Stock-Span.md" >}})|Medium| O(n)| O(n) ||65.2%| +|0907|Sum of Subarray Minimums|[Go]({{< relref "/ChapterFour/0900~0999/0907.Sum-of-Subarray-Minimums.md" >}})|Medium| O(n)| O(n)|❤️|35.8%| +|0921|Minimum Add to Make Parentheses Valid|[Go]({{< relref "/ChapterFour/0900~0999/0921.Minimum-Add-to-Make-Parentheses-Valid.md" >}})|Medium| O(n)| O(n)||75.8%| +|0946|Validate Stack Sequences|[Go]({{< relref "/ChapterFour/0900~0999/0946.Validate-Stack-Sequences.md" >}})|Medium| O(n)| O(n)||67.7%| +|1003|Check If Word Is Valid After Substitutions|[Go]({{< relref "/ChapterFour/1000~1099/1003.Check-If-Word-Is-Valid-After-Substitutions.md" >}})|Medium| O(n)| O(1)||58.2%| +|1006|Clumsy Factorial|[Go]({{< relref "/ChapterFour/1000~1099/1006.Clumsy-Factorial.md" >}})|Medium||||55.4%| +|1019|Next Greater Node In Linked List|[Go]({{< relref "/ChapterFour/1000~1099/1019.Next-Greater-Node-In-Linked-List.md" >}})|Medium| O(n)| O(1)||59.9%| +|1021|Remove Outermost Parentheses|[Go]({{< relref "/ChapterFour/1000~1099/1021.Remove-Outermost-Parentheses.md" >}})|Easy| O(n)| O(1)||80.6%| +|1047|Remove All Adjacent Duplicates In String|[Go]({{< relref "/ChapterFour/1000~1099/1047.Remove-All-Adjacent-Duplicates-In-String.md" >}})|Easy| O(n)| O(1)||69.7%| +|1111|Maximum Nesting Depth of Two Valid Parentheses Strings|[Go]({{< relref "/ChapterFour/1100~1199/1111.Maximum-Nesting-Depth-of-Two-Valid-Parentheses-Strings.md" >}})|Medium||||73.0%| +|1190|Reverse Substrings Between Each Pair of Parentheses|[Go]({{< relref "/ChapterFour/1100~1199/1190.Reverse-Substrings-Between-Each-Pair-of-Parentheses.md" >}})|Medium||||65.9%| +|1209|Remove All Adjacent Duplicates in String II|[Go]({{< relref "/ChapterFour/1200~1299/1209.Remove-All-Adjacent-Duplicates-in-String-II.md" >}})|Medium||||56.2%| +|1249|Minimum Remove to Make Valid Parentheses|[Go]({{< relref "/ChapterFour/1200~1299/1249.Minimum-Remove-to-Make-Valid-Parentheses.md" >}})|Medium||||65.8%| +|1614|Maximum Nesting Depth of the Parentheses|[Go]({{< relref "/ChapterFour/1600~1699/1614.Maximum-Nesting-Depth-of-the-Parentheses.md" >}})|Easy||||82.3%| +|1653|Minimum Deletions to Make String Balanced|[Go]({{< relref "/ChapterFour/1600~1699/1653.Minimum-Deletions-to-Make-String-Balanced.md" >}})|Medium||||58.9%| +|1673|Find the Most Competitive Subsequence|[Go]({{< relref "/ChapterFour/1600~1699/1673.Find-the-Most-Competitive-Subsequence.md" >}})|Medium||||49.3%| +|1700|Number of Students Unable to Eat Lunch|[Go]({{< relref "/ChapterFour/1700~1799/1700.Number-of-Students-Unable-to-Eat-Lunch.md" >}})|Easy||||68.7%| |------------|-------------------------------------------------------|-------| ----------------| ---------------|-------------|-------------|-------------| diff --git a/website/content/ChapterTwo/String.md b/website/content/ChapterTwo/String.md index c6b05107f..240b6b1ac 100644 --- a/website/content/ChapterTwo/String.md +++ b/website/content/ChapterTwo/String.md @@ -9,68 +9,186 @@ weight: 2 | No. | Title | Solution | Difficulty | TimeComplexity | SpaceComplexity |Favorite| Acceptance | |:--------:|:------- | :--------: | :----------: | :----: | :-----: | :-----: |:-----: | -|0003|Longest Substring Without Repeating Characters|[Go]({{< relref "/ChapterFour/0001~0099/0003.Longest-Substring-Without-Repeating-Characters.md" >}})|Medium| O(n)| O(1)|❤️|31.6%| -|0005|Longest Palindromic Substring|[Go]({{< relref "/ChapterFour/0001~0099/0005.Longest-Palindromic-Substring.md" >}})|Medium||||30.7%| -|0006|ZigZag Conversion|[Go]({{< relref "/ChapterFour/0001~0099/0006.ZigZag-Conversion.md" >}})|Medium||||38.4%| -|0008|String to Integer (atoi)|[Go]({{< relref "/ChapterFour/0001~0099/0008.String-to-Integer-atoi.md" >}})|Medium||||15.8%| -|0012|Integer to Roman|[Go]({{< relref "/ChapterFour/0001~0099/0012.Integer-to-Roman.md" >}})|Medium||||57.2%| -|0013|Roman to Integer|[Go]({{< relref "/ChapterFour/0001~0099/0013.Roman-to-Integer.md" >}})|Easy||||57.1%| -|0017|Letter Combinations of a Phone Number|[Go]({{< relref "/ChapterFour/0001~0099/0017.Letter-Combinations-of-a-Phone-Number.md" >}})|Medium| O(log n)| O(1)||50.0%| -|0020|Valid Parentheses|[Go]({{< relref "/ChapterFour/0001~0099/0020.Valid-Parentheses.md" >}})|Easy| O(log n)| O(1)||40.0%| -|0022|Generate Parentheses|[Go]({{< relref "/ChapterFour/0001~0099/0022.Generate-Parentheses.md" >}})|Medium| O(log n)| O(1)||65.9%| -|0028|Implement strStr()|[Go]({{< relref "/ChapterFour/0001~0099/0028.Implement-strStr.md" >}})|Easy| O(n)| O(1)||35.4%| -|0030|Substring with Concatenation of All Words|[Go]({{< relref "/ChapterFour/0001~0099/0030.Substring-with-Concatenation-of-All-Words.md" >}})|Hard| O(n)| O(n)|❤️|26.4%| -|0032|Longest Valid Parentheses|[Go]({{< relref "/ChapterFour/0001~0099/0032.Longest-Valid-Parentheses.md" >}})|Hard||||29.9%| -|0043|Multiply Strings|[Go]({{< relref "/ChapterFour/0001~0099/0043.Multiply-Strings.md" >}})|Medium||||35.2%| -|0049|Group Anagrams|[Go]({{< relref "/ChapterFour/0001~0099/0049.Group-Anagrams.md" >}})|Medium| O(n log n)| O(n)||59.9%| -|0067|Add Binary|[Go]({{< relref "/ChapterFour/0001~0099/0067.Add-Binary.md" >}})|Easy||||47.4%| -|0071|Simplify Path|[Go]({{< relref "/ChapterFour/0001~0099/0071.Simplify-Path.md" >}})|Medium| O(n)| O(n)||35.0%| -|0076|Minimum Window Substring|[Go]({{< relref "/ChapterFour/0001~0099/0076.Minimum-Window-Substring.md" >}})|Hard| O(n)| O(n)|❤️|36.3%| -|0091|Decode Ways|[Go]({{< relref "/ChapterFour/0001~0099/0091.Decode-Ways.md" >}})|Medium| O(n)| O(n)||27.0%| -|0093|Restore IP Addresses|[Go]({{< relref "/ChapterFour/0001~0099/0093.Restore-IP-Addresses.md" >}})|Medium| O(n)| O(n)|❤️|38.0%| -|0115|Distinct Subsequences|[Go]({{< relref "/ChapterFour/0100~0199/0115.Distinct-Subsequences.md" >}})|Hard||||40.1%| -|0125|Valid Palindrome|[Go]({{< relref "/ChapterFour/0100~0199/0125.Valid-Palindrome.md" >}})|Easy| O(n)| O(1)||38.7%| -|0126|Word Ladder II|[Go]({{< relref "/ChapterFour/0100~0199/0126.Word-Ladder-II.md" >}})|Hard| O(n)| O(n^2)|❤️|23.9%| -|0151|Reverse Words in a String|[Go]({{< relref "/ChapterFour/0100~0199/0151.Reverse-Words-in-a-String.md" >}})|Medium||||24.3%| -|0227|Basic Calculator II|[Go]({{< relref "/ChapterFour/0200~0299/0227.Basic-Calculator-II.md" >}})|Medium||||38.9%| -|0344|Reverse String|[Go]({{< relref "/ChapterFour/0300~0399/0344.Reverse-String.md" >}})|Easy| O(n)| O(1)||70.8%| -|0345|Reverse Vowels of a String|[Go]({{< relref "/ChapterFour/0300~0399/0345.Reverse-Vowels-of-a-String.md" >}})|Easy| O(n)| O(1)||45.3%| -|0385|Mini Parser|[Go]({{< relref "/ChapterFour/0300~0399/0385.Mini-Parser.md" >}})|Medium||||34.7%| -|0387|First Unique Character in a String|[Go]({{< relref "/ChapterFour/0300~0399/0387.First-Unique-Character-in-a-String.md" >}})|Easy||||54.1%| -|0537|Complex Number Multiplication|[Go]({{< relref "/ChapterFour/0500~0599/0537.Complex-Number-Multiplication.md" >}})|Medium||||68.4%| -|0541|Reverse String II|[Go]({{< relref "/ChapterFour/0500~0599/0541.Reverse-String-II.md" >}})|Easy||||49.6%| -|0557|Reverse Words in a String III|[Go]({{< relref "/ChapterFour/0500~0599/0557.Reverse-Words-in-a-String-III.md" >}})|Easy||||72.6%| -|0632|Smallest Range Covering Elements from K Lists|[Go]({{< relref "/ChapterFour/0600~0699/0632.Smallest-Range-Covering-Elements-from-K-Lists.md" >}})|Hard||||54.7%| -|0647|Palindromic Substrings|[Go]({{< relref "/ChapterFour/0600~0699/0647.Palindromic-Substrings.md" >}})|Medium||||62.8%| -|0696|Count Binary Substrings|[Go]({{< relref "/ChapterFour/0600~0699/0696.Count-Binary-Substrings.md" >}})|Easy||||61.2%| -|0767|Reorganize String|[Go]({{< relref "/ChapterFour/0700~0799/0767.Reorganize-String.md" >}})|Medium| O(n log n)| O(log n) |❤️|50.3%| -|0819|Most Common Word|[Go]({{< relref "/ChapterFour/0800~0899/0819.Most-Common-Word.md" >}})|Easy||||45.5%| -|0842|Split Array into Fibonacci Sequence|[Go]({{< relref "/ChapterFour/0800~0899/0842.Split-Array-into-Fibonacci-Sequence.md" >}})|Medium| O(n^2)| O(1)|❤️|37.0%| -|0856|Score of Parentheses|[Go]({{< relref "/ChapterFour/0800~0899/0856.Score-of-Parentheses.md" >}})|Medium| O(n)| O(n)||64.9%| -|0916|Word Subsets|[Go]({{< relref "/ChapterFour/0900~0999/0916.Word-Subsets.md" >}})|Medium||||52.8%| -|0925|Long Pressed Name|[Go]({{< relref "/ChapterFour/0900~0999/0925.Long-Pressed-Name.md" >}})|Easy| O(n)| O(1)||37.1%| -|0966|Vowel Spellchecker|[Go]({{< relref "/ChapterFour/0900~0999/0966.Vowel-Spellchecker.md" >}})|Medium||||51.9%| -|1003|Check If Word Is Valid After Substitutions|[Go]({{< relref "/ChapterFour/1000~1099/1003.Check-If-Word-Is-Valid-After-Substitutions.md" >}})|Medium| O(n)| O(1)||56.7%| -|1108|Defanging an IP Address|[Go]({{< relref "/ChapterFour/1100~1199/1108.Defanging-an-IP-Address.md" >}})|Easy||||88.4%| -|1170|Compare Strings by Frequency of the Smallest Character|[Go]({{< relref "/ChapterFour/1100~1199/1170.Compare-Strings-by-Frequency-of-the-Smallest-Character.md" >}})|Medium||||60.4%| -|1189|Maximum Number of Balloons|[Go]({{< relref "/ChapterFour/1100~1199/1189.Maximum-Number-of-Balloons.md" >}})|Easy||||62.2%| -|1221|Split a String in Balanced Strings|[Go]({{< relref "/ChapterFour/1200~1299/1221.Split-a-String-in-Balanced-Strings.md" >}})|Easy||||84.3%| -|1234|Replace the Substring for Balanced String|[Go]({{< relref "/ChapterFour/1200~1299/1234.Replace-the-Substring-for-Balanced-String.md" >}})|Medium||||34.7%| -|1249|Minimum Remove to Make Valid Parentheses|[Go]({{< relref "/ChapterFour/1200~1299/1249.Minimum-Remove-to-Make-Valid-Parentheses.md" >}})|Medium||||64.3%| -|1332|Remove Palindromic Subsequences|[Go]({{< relref "/ChapterFour/1300~1399/1332.Remove-Palindromic-Subsequences.md" >}})|Easy||||68.4%| -|1455|Check If a Word Occurs As a Prefix of Any Word in a Sentence|[Go]({{< relref "/ChapterFour/1400~1499/1455.Check-If-a-Word-Occurs-As-a-Prefix-of-Any-Word-in-a-Sentence.md" >}})|Easy||||65.4%| -|1461|Check If a String Contains All Binary Codes of Size K|[Go]({{< relref "/ChapterFour/1400~1499/1461.Check-If-a-String-Contains-All-Binary-Codes-of-Size-K.md" >}})|Medium||||54.2%| -|1573|Number of Ways to Split a String|[Go]({{< relref "/ChapterFour/1500~1599/1573.Number-of-Ways-to-Split-a-String.md" >}})|Medium||||31.4%| -|1614|Maximum Nesting Depth of the Parentheses|[Go]({{< relref "/ChapterFour/1600~1699/1614.Maximum-Nesting-Depth-of-the-Parentheses.md" >}})|Easy||||82.7%| -|1624|Largest Substring Between Two Equal Characters|[Go]({{< relref "/ChapterFour/1600~1699/1624.Largest-Substring-Between-Two-Equal-Characters.md" >}})|Easy||||58.5%| -|1653|Minimum Deletions to Make String Balanced|[Go]({{< relref "/ChapterFour/1600~1699/1653.Minimum-Deletions-to-Make-String-Balanced.md" >}})|Medium||||51.8%| -|1662|Check If Two String Arrays are Equivalent|[Go]({{< relref "/ChapterFour/1600~1699/1662.Check-If-Two-String-Arrays-are-Equivalent.md" >}})|Easy||||82.5%| -|1668|Maximum Repeating Substring|[Go]({{< relref "/ChapterFour/1600~1699/1668.Maximum-Repeating-Substring.md" >}})|Easy||||38.6%| -|1678|Goal Parser Interpretation|[Go]({{< relref "/ChapterFour/1600~1699/1678.Goal-Parser-Interpretation.md" >}})|Easy||||85.2%| -|1684|Count the Number of Consistent Strings|[Go]({{< relref "/ChapterFour/1600~1699/1684.Count-the-Number-of-Consistent-Strings.md" >}})|Easy||||81.8%| -|1694|Reformat Phone Number|[Go]({{< relref "/ChapterFour/1600~1699/1694.Reformat-Phone-Number.md" >}})|Easy||||64.9%| -|1704|Determine if String Halves Are Alike|[Go]({{< relref "/ChapterFour/1700~1799/1704.Determine-if-String-Halves-Are-Alike.md" >}})|Easy||||79.0%| -|1736|Latest Time by Replacing Hidden Digits|[Go]({{< relref "/ChapterFour/1700~1799/1736.Latest-Time-by-Replacing-Hidden-Digits.md" >}})|Easy||||41.2%| +|0003|Longest Substring Without Repeating Characters|[Go]({{< relref "/ChapterFour/0001~0099/0003.Longest-Substring-Without-Repeating-Characters.md" >}})|Medium| O(n)| O(1)|❤️|33.8%| +|0005|Longest Palindromic Substring|[Go]({{< relref "/ChapterFour/0001~0099/0005.Longest-Palindromic-Substring.md" >}})|Medium||||32.4%| +|0006|Zigzag Conversion|[Go]({{< relref "/ChapterFour/0001~0099/0006.Zigzag-Conversion.md" >}})|Medium||||44.8%| +|0008|String to Integer (atoi)|[Go]({{< relref "/ChapterFour/0001~0099/0008.String-to-Integer-atoi.md" >}})|Medium||||16.6%| +|0012|Integer to Roman|[Go]({{< relref "/ChapterFour/0001~0099/0012.Integer-to-Roman.md" >}})|Medium||||62.0%| +|0013|Roman to Integer|[Go]({{< relref "/ChapterFour/0001~0099/0013.Roman-to-Integer.md" >}})|Easy||||58.5%| +|0014|Longest Common Prefix|[Go]({{< relref "/ChapterFour/0001~0099/0014.Longest-Common-Prefix.md" >}})|Easy||||40.9%| +|0017|Letter Combinations of a Phone Number|[Go]({{< relref "/ChapterFour/0001~0099/0017.Letter-Combinations-of-a-Phone-Number.md" >}})|Medium| O(log n)| O(1)||56.5%| +|0020|Valid Parentheses|[Go]({{< relref "/ChapterFour/0001~0099/0020.Valid-Parentheses.md" >}})|Easy| O(log n)| O(1)||40.2%| +|0022|Generate Parentheses|[Go]({{< relref "/ChapterFour/0001~0099/0022.Generate-Parentheses.md" >}})|Medium| O(log n)| O(1)||72.5%| +|0028|Find the Index of the First Occurrence in a String|[Go]({{< relref "/ChapterFour/0001~0099/0028.Find-the-Index-of-the-First-Occurrence-in-a-String.md" >}})|Easy| O(n)| O(1)||39.0%| +|0030|Substring with Concatenation of All Words|[Go]({{< relref "/ChapterFour/0001~0099/0030.Substring-with-Concatenation-of-All-Words.md" >}})|Hard| O(n)| O(n)|❤️|31.2%| +|0032|Longest Valid Parentheses|[Go]({{< relref "/ChapterFour/0001~0099/0032.Longest-Valid-Parentheses.md" >}})|Hard||||32.8%| +|0043|Multiply Strings|[Go]({{< relref "/ChapterFour/0001~0099/0043.Multiply-Strings.md" >}})|Medium||||39.2%| +|0049|Group Anagrams|[Go]({{< relref "/ChapterFour/0001~0099/0049.Group-Anagrams.md" >}})|Medium| O(n log n)| O(n)||66.7%| +|0058|Length of Last Word|[Go]({{< relref "/ChapterFour/0001~0099/0058.Length-of-Last-Word.md" >}})|Easy||||42.8%| +|0065|Valid Number|[Go]({{< relref "/ChapterFour/0001~0099/0065.Valid-Number.md" >}})|Hard||||18.7%| +|0067|Add Binary|[Go]({{< relref "/ChapterFour/0001~0099/0067.Add-Binary.md" >}})|Easy||||52.4%| +|0071|Simplify Path|[Go]({{< relref "/ChapterFour/0001~0099/0071.Simplify-Path.md" >}})|Medium| O(n)| O(n)||39.3%| +|0076|Minimum Window Substring|[Go]({{< relref "/ChapterFour/0001~0099/0076.Minimum-Window-Substring.md" >}})|Hard| O(n)| O(n)|❤️|40.9%| +|0091|Decode Ways|[Go]({{< relref "/ChapterFour/0001~0099/0091.Decode-Ways.md" >}})|Medium| O(n)| O(n)||32.7%| +|0093|Restore IP Addresses|[Go]({{< relref "/ChapterFour/0001~0099/0093.Restore-IP-Addresses.md" >}})|Medium| O(n)| O(n)|❤️|47.4%| +|0097|Interleaving String|[Go]({{< relref "/ChapterFour/0001~0099/0097.Interleaving-String.md" >}})|Medium||||37.3%| +|0115|Distinct Subsequences|[Go]({{< relref "/ChapterFour/0100~0199/0115.Distinct-Subsequences.md" >}})|Hard||||44.4%| +|0125|Valid Palindrome|[Go]({{< relref "/ChapterFour/0100~0199/0125.Valid-Palindrome.md" >}})|Easy| O(n)| O(1)||44.3%| +|0126|Word Ladder II|[Go]({{< relref "/ChapterFour/0100~0199/0126.Word-Ladder-II.md" >}})|Hard| O(n)| O(n^2)|❤️|27.5%| +|0127|Word Ladder|[Go]({{< relref "/ChapterFour/0100~0199/0127.Word-Ladder.md" >}})|Hard||||37.1%| +|0131|Palindrome Partitioning|[Go]({{< relref "/ChapterFour/0100~0199/0131.Palindrome-Partitioning.md" >}})|Medium||||64.8%| +|0151|Reverse Words in a String|[Go]({{< relref "/ChapterFour/0100~0199/0151.Reverse-Words-in-a-String.md" >}})|Medium||||32.7%| +|0168|Excel Sheet Column Title|[Go]({{< relref "/ChapterFour/0100~0199/0168.Excel-Sheet-Column-Title.md" >}})|Easy||||35.5%| +|0171|Excel Sheet Column Number|[Go]({{< relref "/ChapterFour/0100~0199/0171.Excel-Sheet-Column-Number.md" >}})|Easy||||62.0%| +|0179|Largest Number|[Go]({{< relref "/ChapterFour/0100~0199/0179.Largest-Number.md" >}})|Medium||||34.5%| +|0187|Repeated DNA Sequences|[Go]({{< relref "/ChapterFour/0100~0199/0187.Repeated-DNA-Sequences.md" >}})|Medium||||46.9%| +|0205|Isomorphic Strings|[Go]({{< relref "/ChapterFour/0200~0299/0205.Isomorphic-Strings.md" >}})|Easy||||42.9%| +|0208|Implement Trie (Prefix Tree)|[Go]({{< relref "/ChapterFour/0200~0299/0208.Implement-Trie-Prefix-Tree.md" >}})|Medium||||62.7%| +|0211|Design Add and Search Words Data Structure|[Go]({{< relref "/ChapterFour/0200~0299/0211.Design-Add-and-Search-Words-Data-Structure.md" >}})|Medium||||44.0%| +|0212|Word Search II|[Go]({{< relref "/ChapterFour/0200~0299/0212.Word-Search-II.md" >}})|Hard||||36.4%| +|0224|Basic Calculator|[Go]({{< relref "/ChapterFour/0200~0299/0224.Basic-Calculator.md" >}})|Hard||||42.4%| +|0227|Basic Calculator II|[Go]({{< relref "/ChapterFour/0200~0299/0227.Basic-Calculator-II.md" >}})|Medium||||42.4%| +|0242|Valid Anagram|[Go]({{< relref "/ChapterFour/0200~0299/0242.Valid-Anagram.md" >}})|Easy||||63.0%| +|0257|Binary Tree Paths|[Go]({{< relref "/ChapterFour/0200~0299/0257.Binary-Tree-Paths.md" >}})|Easy||||61.4%| +|0290|Word Pattern|[Go]({{< relref "/ChapterFour/0200~0299/0290.Word-Pattern.md" >}})|Easy||||41.7%| +|0297|Serialize and Deserialize Binary Tree|[Go]({{< relref "/ChapterFour/0200~0299/0297.Serialize-and-Deserialize-Binary-Tree.md" >}})|Hard||||55.4%| +|0299|Bulls and Cows|[Go]({{< relref "/ChapterFour/0200~0299/0299.Bulls-and-Cows.md" >}})|Medium||||49.4%| +|0301|Remove Invalid Parentheses|[Go]({{< relref "/ChapterFour/0300~0399/0301.Remove-Invalid-Parentheses.md" >}})|Hard||||47.2%| +|0306|Additive Number|[Go]({{< relref "/ChapterFour/0300~0399/0306.Additive-Number.md" >}})|Medium||||31.1%| +|0318|Maximum Product of Word Lengths|[Go]({{< relref "/ChapterFour/0300~0399/0318.Maximum-Product-of-Word-Lengths.md" >}})|Medium||||59.9%| +|0331|Verify Preorder Serialization of a Binary Tree|[Go]({{< relref "/ChapterFour/0300~0399/0331.Verify-Preorder-Serialization-of-a-Binary-Tree.md" >}})|Medium||||44.6%| +|0344|Reverse String|[Go]({{< relref "/ChapterFour/0300~0399/0344.Reverse-String.md" >}})|Easy| O(n)| O(1)||76.7%| +|0345|Reverse Vowels of a String|[Go]({{< relref "/ChapterFour/0300~0399/0345.Reverse-Vowels-of-a-String.md" >}})|Easy| O(n)| O(1)||50.1%| +|0383|Ransom Note|[Go]({{< relref "/ChapterFour/0300~0399/0383.Ransom-Note.md" >}})|Easy||||58.2%| +|0385|Mini Parser|[Go]({{< relref "/ChapterFour/0300~0399/0385.Mini-Parser.md" >}})|Medium||||36.9%| +|0387|First Unique Character in a String|[Go]({{< relref "/ChapterFour/0300~0399/0387.First-Unique-Character-in-a-String.md" >}})|Easy||||59.6%| +|0389|Find the Difference|[Go]({{< relref "/ChapterFour/0300~0399/0389.Find-the-Difference.md" >}})|Easy||||59.9%| +|0392|Is Subsequence|[Go]({{< relref "/ChapterFour/0300~0399/0392.Is-Subsequence.md" >}})|Easy||||47.6%| +|0394|Decode String|[Go]({{< relref "/ChapterFour/0300~0399/0394.Decode-String.md" >}})|Medium||||57.9%| +|0395|Longest Substring with At Least K Repeating Characters|[Go]({{< relref "/ChapterFour/0300~0399/0395.Longest-Substring-with-At-Least-K-Repeating-Characters.md" >}})|Medium||||44.8%| +|0402|Remove K Digits|[Go]({{< relref "/ChapterFour/0400~0499/0402.Remove-K-Digits.md" >}})|Medium||||30.6%| +|0409|Longest Palindrome|[Go]({{< relref "/ChapterFour/0400~0499/0409.Longest-Palindrome.md" >}})|Easy||||54.2%| +|0412|Fizz Buzz|[Go]({{< relref "/ChapterFour/0400~0499/0412.Fizz-Buzz.md" >}})|Easy||||69.9%| +|0423|Reconstruct Original Digits from English|[Go]({{< relref "/ChapterFour/0400~0499/0423.Reconstruct-Original-Digits-from-English.md" >}})|Medium||||51.3%| +|0424|Longest Repeating Character Replacement|[Go]({{< relref "/ChapterFour/0400~0499/0424.Longest-Repeating-Character-Replacement.md" >}})|Medium||||51.9%| +|0433|Minimum Genetic Mutation|[Go]({{< relref "/ChapterFour/0400~0499/0433.Minimum-Genetic-Mutation.md" >}})|Medium||||52.3%| +|0434|Number of Segments in a String|[Go]({{< relref "/ChapterFour/0400~0499/0434.Number-of-Segments-in-a-String.md" >}})|Easy||||37.2%| +|0438|Find All Anagrams in a String|[Go]({{< relref "/ChapterFour/0400~0499/0438.Find-All-Anagrams-in-a-String.md" >}})|Medium||||50.2%| +|0451|Sort Characters By Frequency|[Go]({{< relref "/ChapterFour/0400~0499/0451.Sort-Characters-By-Frequency.md" >}})|Medium||||70.1%| +|0474|Ones and Zeroes|[Go]({{< relref "/ChapterFour/0400~0499/0474.Ones-and-Zeroes.md" >}})|Medium||||46.8%| +|0488|Zuma Game|[Go]({{< relref "/ChapterFour/0400~0499/0488.Zuma-Game.md" >}})|Hard||||33.9%| +|0500|Keyboard Row|[Go]({{< relref "/ChapterFour/0500~0599/0500.Keyboard-Row.md" >}})|Easy||||69.5%| +|0520|Detect Capital|[Go]({{< relref "/ChapterFour/0500~0599/0520.Detect-Capital.md" >}})|Easy||||57.0%| +|0524|Longest Word in Dictionary through Deleting|[Go]({{< relref "/ChapterFour/0500~0599/0524.Longest-Word-in-Dictionary-through-Deleting.md" >}})|Medium||||51.0%| +|0535|Encode and Decode TinyURL|[Go]({{< relref "/ChapterFour/0500~0599/0535.Encode-and-Decode-TinyURL.md" >}})|Medium||||85.9%| +|0537|Complex Number Multiplication|[Go]({{< relref "/ChapterFour/0500~0599/0537.Complex-Number-Multiplication.md" >}})|Medium||||71.4%| +|0541|Reverse String II|[Go]({{< relref "/ChapterFour/0500~0599/0541.Reverse-String-II.md" >}})|Easy||||50.5%| +|0551|Student Attendance Record I|[Go]({{< relref "/ChapterFour/0500~0599/0551.Student-Attendance-Record-I.md" >}})|Easy||||48.2%| +|0557|Reverse Words in a String III|[Go]({{< relref "/ChapterFour/0500~0599/0557.Reverse-Words-in-a-String-III.md" >}})|Easy||||81.9%| +|0567|Permutation in String|[Go]({{< relref "/ChapterFour/0500~0599/0567.Permutation-in-String.md" >}})|Medium||||44.3%| +|0583|Delete Operation for Two Strings|[Go]({{< relref "/ChapterFour/0500~0599/0583.Delete-Operation-for-Two-Strings.md" >}})|Medium||||59.8%| +|0599|Minimum Index Sum of Two Lists|[Go]({{< relref "/ChapterFour/0500~0599/0599.Minimum-Index-Sum-of-Two-Lists.md" >}})|Easy||||53.4%| +|0609|Find Duplicate File in System|[Go]({{< relref "/ChapterFour/0600~0699/0609.Find-Duplicate-File-in-System.md" >}})|Medium||||67.7%| +|0647|Palindromic Substrings|[Go]({{< relref "/ChapterFour/0600~0699/0647.Palindromic-Substrings.md" >}})|Medium||||66.8%| +|0648|Replace Words|[Go]({{< relref "/ChapterFour/0600~0699/0648.Replace-Words.md" >}})|Medium||||62.7%| +|0676|Implement Magic Dictionary|[Go]({{< relref "/ChapterFour/0600~0699/0676.Implement-Magic-Dictionary.md" >}})|Medium||||57.0%| +|0677|Map Sum Pairs|[Go]({{< relref "/ChapterFour/0600~0699/0677.Map-Sum-Pairs.md" >}})|Medium||||56.8%| +|0692|Top K Frequent Words|[Go]({{< relref "/ChapterFour/0600~0699/0692.Top-K-Frequent-Words.md" >}})|Medium||||57.2%| +|0696|Count Binary Substrings|[Go]({{< relref "/ChapterFour/0600~0699/0696.Count-Binary-Substrings.md" >}})|Easy||||65.5%| +|0709|To Lower Case|[Go]({{< relref "/ChapterFour/0700~0799/0709.To-Lower-Case.md" >}})|Easy||||82.4%| +|0720|Longest Word in Dictionary|[Go]({{< relref "/ChapterFour/0700~0799/0720.Longest-Word-in-Dictionary.md" >}})|Medium||||52.0%| +|0721|Accounts Merge|[Go]({{< relref "/ChapterFour/0700~0799/0721.Accounts-Merge.md" >}})|Medium||||56.3%| +|0726|Number of Atoms|[Go]({{< relref "/ChapterFour/0700~0799/0726.Number-of-Atoms.md" >}})|Hard||||52.1%| +|0745|Prefix and Suffix Search|[Go]({{< relref "/ChapterFour/0700~0799/0745.Prefix-and-Suffix-Search.md" >}})|Hard||||41.2%| +|0748|Shortest Completing Word|[Go]({{< relref "/ChapterFour/0700~0799/0748.Shortest-Completing-Word.md" >}})|Easy||||59.3%| +|0752|Open the Lock|[Go]({{< relref "/ChapterFour/0700~0799/0752.Open-the-Lock.md" >}})|Medium||||55.6%| +|0763|Partition Labels|[Go]({{< relref "/ChapterFour/0700~0799/0763.Partition-Labels.md" >}})|Medium||||79.7%| +|0767|Reorganize String|[Go]({{< relref "/ChapterFour/0700~0799/0767.Reorganize-String.md" >}})|Medium| O(n log n)| O(log n) |❤️|52.9%| +|0771|Jewels and Stones|[Go]({{< relref "/ChapterFour/0700~0799/0771.Jewels-and-Stones.md" >}})|Easy||||88.2%| +|0784|Letter Case Permutation|[Go]({{< relref "/ChapterFour/0700~0799/0784.Letter-Case-Permutation.md" >}})|Medium||||73.8%| +|0791|Custom Sort String|[Go]({{< relref "/ChapterFour/0700~0799/0791.Custom-Sort-String.md" >}})|Medium||||69.1%| +|0792|Number of Matching Subsequences|[Go]({{< relref "/ChapterFour/0700~0799/0792.Number-of-Matching-Subsequences.md" >}})|Medium||||51.6%| +|0794|Valid Tic-Tac-Toe State|[Go]({{< relref "/ChapterFour/0700~0799/0794.Valid-Tic-Tac-Toe-State.md" >}})|Medium||||35.1%| +|0811|Subdomain Visit Count|[Go]({{< relref "/ChapterFour/0800~0899/0811.Subdomain-Visit-Count.md" >}})|Medium||||75.5%| +|0816|Ambiguous Coordinates|[Go]({{< relref "/ChapterFour/0800~0899/0816.Ambiguous-Coordinates.md" >}})|Medium||||56.3%| +|0819|Most Common Word|[Go]({{< relref "/ChapterFour/0800~0899/0819.Most-Common-Word.md" >}})|Easy||||44.8%| +|0820|Short Encoding of Words|[Go]({{< relref "/ChapterFour/0800~0899/0820.Short-Encoding-of-Words.md" >}})|Medium||||60.6%| +|0821|Shortest Distance to a Character|[Go]({{< relref "/ChapterFour/0800~0899/0821.Shortest-Distance-to-a-Character.md" >}})|Easy||||71.3%| +|0828|Count Unique Characters of All Substrings of a Given String|[Go]({{< relref "/ChapterFour/0800~0899/0828.Count-Unique-Characters-of-All-Substrings-of-a-Given-String.md" >}})|Hard||||51.6%| +|0830|Positions of Large Groups|[Go]({{< relref "/ChapterFour/0800~0899/0830.Positions-of-Large-Groups.md" >}})|Easy||||51.8%| +|0838|Push Dominoes|[Go]({{< relref "/ChapterFour/0800~0899/0838.Push-Dominoes.md" >}})|Medium||||57.0%| +|0839|Similar String Groups|[Go]({{< relref "/ChapterFour/0800~0899/0839.Similar-String-Groups.md" >}})|Hard||||48.0%| +|0842|Split Array into Fibonacci Sequence|[Go]({{< relref "/ChapterFour/0800~0899/0842.Split-Array-into-Fibonacci-Sequence.md" >}})|Medium| O(n^2)| O(1)|❤️|38.4%| +|0844|Backspace String Compare|[Go]({{< relref "/ChapterFour/0800~0899/0844.Backspace-String-Compare.md" >}})|Easy||||48.1%| +|0856|Score of Parentheses|[Go]({{< relref "/ChapterFour/0800~0899/0856.Score-of-Parentheses.md" >}})|Medium| O(n)| O(n)||64.8%| +|0859|Buddy Strings|[Go]({{< relref "/ChapterFour/0800~0899/0859.Buddy-Strings.md" >}})|Easy||||29.2%| +|0880|Decoded String at Index|[Go]({{< relref "/ChapterFour/0800~0899/0880.Decoded-String-at-Index.md" >}})|Medium||||28.3%| +|0884|Uncommon Words from Two Sentences|[Go]({{< relref "/ChapterFour/0800~0899/0884.Uncommon-Words-from-Two-Sentences.md" >}})|Easy||||66.3%| +|0890|Find and Replace Pattern|[Go]({{< relref "/ChapterFour/0800~0899/0890.Find-and-Replace-Pattern.md" >}})|Medium||||77.6%| +|0916|Word Subsets|[Go]({{< relref "/ChapterFour/0900~0999/0916.Word-Subsets.md" >}})|Medium||||53.7%| +|0921|Minimum Add to Make Parentheses Valid|[Go]({{< relref "/ChapterFour/0900~0999/0921.Minimum-Add-to-Make-Parentheses-Valid.md" >}})|Medium||||75.8%| +|0925|Long Pressed Name|[Go]({{< relref "/ChapterFour/0900~0999/0925.Long-Pressed-Name.md" >}})|Easy| O(n)| O(1)||33.1%| +|0942|DI String Match|[Go]({{< relref "/ChapterFour/0900~0999/0942.DI-String-Match.md" >}})|Easy||||77.3%| +|0949|Largest Time for Given Digits|[Go]({{< relref "/ChapterFour/0900~0999/0949.Largest-Time-for-Given-Digits.md" >}})|Medium||||35.2%| +|0953|Verifying an Alien Dictionary|[Go]({{< relref "/ChapterFour/0900~0999/0953.Verifying-an-Alien-Dictionary.md" >}})|Easy||||54.5%| +|0966|Vowel Spellchecker|[Go]({{< relref "/ChapterFour/0900~0999/0966.Vowel-Spellchecker.md" >}})|Medium||||51.4%| +|0981|Time Based Key-Value Store|[Go]({{< relref "/ChapterFour/0900~0999/0981.Time-Based-Key-Value-Store.md" >}})|Medium||||52.3%| +|0984|String Without AAA or BBB|[Go]({{< relref "/ChapterFour/0900~0999/0984.String-Without-AAA-or-BBB.md" >}})|Medium||||43.1%| +|0990|Satisfiability of Equality Equations|[Go]({{< relref "/ChapterFour/0900~0999/0990.Satisfiability-of-Equality-Equations.md" >}})|Medium||||50.5%| +|1002|Find Common Characters|[Go]({{< relref "/ChapterFour/1000~1099/1002.Find-Common-Characters.md" >}})|Easy||||68.5%| +|1003|Check If Word Is Valid After Substitutions|[Go]({{< relref "/ChapterFour/1000~1099/1003.Check-If-Word-Is-Valid-After-Substitutions.md" >}})|Medium| O(n)| O(1)||58.2%| +|1021|Remove Outermost Parentheses|[Go]({{< relref "/ChapterFour/1000~1099/1021.Remove-Outermost-Parentheses.md" >}})|Easy||||80.6%| +|1028|Recover a Tree From Preorder Traversal|[Go]({{< relref "/ChapterFour/1000~1099/1028.Recover-a-Tree-From-Preorder-Traversal.md" >}})|Hard||||73.3%| +|1047|Remove All Adjacent Duplicates In String|[Go]({{< relref "/ChapterFour/1000~1099/1047.Remove-All-Adjacent-Duplicates-In-String.md" >}})|Easy||||69.7%| +|1048|Longest String Chain|[Go]({{< relref "/ChapterFour/1000~1099/1048.Longest-String-Chain.md" >}})|Medium||||59.2%| +|1078|Occurrences After Bigram|[Go]({{< relref "/ChapterFour/1000~1099/1078.Occurrences-After-Bigram.md" >}})|Easy||||63.6%| +|1079|Letter Tile Possibilities|[Go]({{< relref "/ChapterFour/1000~1099/1079.Letter-Tile-Possibilities.md" >}})|Medium||||76.0%| +|1108|Defanging an IP Address|[Go]({{< relref "/ChapterFour/1100~1199/1108.Defanging-an-IP-Address.md" >}})|Easy||||89.1%| +|1111|Maximum Nesting Depth of Two Valid Parentheses Strings|[Go]({{< relref "/ChapterFour/1100~1199/1111.Maximum-Nesting-Depth-of-Two-Valid-Parentheses-Strings.md" >}})|Medium||||73.0%| +|1143|Longest Common Subsequence|[Go]({{< relref "/ChapterFour/1100~1199/1143.Longest-Common-Subsequence.md" >}})|Medium||||58.4%| +|1154|Day of the Year|[Go]({{< relref "/ChapterFour/1100~1199/1154.Day-of-the-Year.md" >}})|Easy||||49.6%| +|1160|Find Words That Can Be Formed by Characters|[Go]({{< relref "/ChapterFour/1100~1199/1160.Find-Words-That-Can-Be-Formed-by-Characters.md" >}})|Easy||||67.5%| +|1170|Compare Strings by Frequency of the Smallest Character|[Go]({{< relref "/ChapterFour/1100~1199/1170.Compare-Strings-by-Frequency-of-the-Smallest-Character.md" >}})|Medium||||61.5%| +|1178|Number of Valid Words for Each Puzzle|[Go]({{< relref "/ChapterFour/1100~1199/1178.Number-of-Valid-Words-for-Each-Puzzle.md" >}})|Hard||||46.3%| +|1189|Maximum Number of Balloons|[Go]({{< relref "/ChapterFour/1100~1199/1189.Maximum-Number-of-Balloons.md" >}})|Easy||||61.0%| +|1190|Reverse Substrings Between Each Pair of Parentheses|[Go]({{< relref "/ChapterFour/1100~1199/1190.Reverse-Substrings-Between-Each-Pair-of-Parentheses.md" >}})|Medium||||65.9%| +|1202|Smallest String With Swaps|[Go]({{< relref "/ChapterFour/1200~1299/1202.Smallest-String-With-Swaps.md" >}})|Medium||||57.7%| +|1208|Get Equal Substrings Within Budget|[Go]({{< relref "/ChapterFour/1200~1299/1208.Get-Equal-Substrings-Within-Budget.md" >}})|Medium||||48.5%| +|1209|Remove All Adjacent Duplicates in String II|[Go]({{< relref "/ChapterFour/1200~1299/1209.Remove-All-Adjacent-Duplicates-in-String-II.md" >}})|Medium||||56.2%| +|1221|Split a String in Balanced Strings|[Go]({{< relref "/ChapterFour/1200~1299/1221.Split-a-String-in-Balanced-Strings.md" >}})|Easy||||85.1%| +|1234|Replace the Substring for Balanced String|[Go]({{< relref "/ChapterFour/1200~1299/1234.Replace-the-Substring-for-Balanced-String.md" >}})|Medium||||37.2%| +|1239|Maximum Length of a Concatenated String with Unique Characters|[Go]({{< relref "/ChapterFour/1200~1299/1239.Maximum-Length-of-a-Concatenated-String-with-Unique-Characters.md" >}})|Medium||||52.2%| +|1249|Minimum Remove to Make Valid Parentheses|[Go]({{< relref "/ChapterFour/1200~1299/1249.Minimum-Remove-to-Make-Valid-Parentheses.md" >}})|Medium||||65.8%| +|1268|Search Suggestions System|[Go]({{< relref "/ChapterFour/1200~1299/1268.Search-Suggestions-System.md" >}})|Medium||||66.2%| +|1332|Remove Palindromic Subsequences|[Go]({{< relref "/ChapterFour/1300~1399/1332.Remove-Palindromic-Subsequences.md" >}})|Easy||||76.2%| +|1396|Design Underground System|[Go]({{< relref "/ChapterFour/1300~1399/1396.Design-Underground-System.md" >}})|Medium||||73.6%| +|1446|Consecutive Characters|[Go]({{< relref "/ChapterFour/1400~1499/1446.Consecutive-Characters.md" >}})|Easy||||61.2%| +|1455|Check If a Word Occurs As a Prefix of Any Word in a Sentence|[Go]({{< relref "/ChapterFour/1400~1499/1455.Check-If-a-Word-Occurs-As-a-Prefix-of-Any-Word-in-a-Sentence.md" >}})|Easy||||64.2%| +|1461|Check If a String Contains All Binary Codes of Size K|[Go]({{< relref "/ChapterFour/1400~1499/1461.Check-If-a-String-Contains-All-Binary-Codes-of-Size-K.md" >}})|Medium||||56.6%| +|1573|Number of Ways to Split a String|[Go]({{< relref "/ChapterFour/1500~1599/1573.Number-of-Ways-to-Split-a-String.md" >}})|Medium||||32.5%| +|1576|Replace All ?'s to Avoid Consecutive Repeating Characters|[Go]({{< relref "/ChapterFour/1500~1599/1576.Replace-All-s-to-Avoid-Consecutive-Repeating-Characters.md" >}})|Easy||||48.3%| +|1614|Maximum Nesting Depth of the Parentheses|[Go]({{< relref "/ChapterFour/1600~1699/1614.Maximum-Nesting-Depth-of-the-Parentheses.md" >}})|Easy||||82.3%| +|1624|Largest Substring Between Two Equal Characters|[Go]({{< relref "/ChapterFour/1600~1699/1624.Largest-Substring-Between-Two-Equal-Characters.md" >}})|Easy||||59.1%| +|1629|Slowest Key|[Go]({{< relref "/ChapterFour/1600~1699/1629.Slowest-Key.md" >}})|Easy||||59.2%| +|1647|Minimum Deletions to Make Character Frequencies Unique|[Go]({{< relref "/ChapterFour/1600~1699/1647.Minimum-Deletions-to-Make-Character-Frequencies-Unique.md" >}})|Medium||||59.1%| +|1653|Minimum Deletions to Make String Balanced|[Go]({{< relref "/ChapterFour/1600~1699/1653.Minimum-Deletions-to-Make-String-Balanced.md" >}})|Medium||||58.9%| +|1657|Determine if Two Strings Are Close|[Go]({{< relref "/ChapterFour/1600~1699/1657.Determine-if-Two-Strings-Are-Close.md" >}})|Medium||||56.3%| +|1662|Check If Two String Arrays are Equivalent|[Go]({{< relref "/ChapterFour/1600~1699/1662.Check-If-Two-String-Arrays-are-Equivalent.md" >}})|Easy||||83.5%| +|1663|Smallest String With A Given Numeric Value|[Go]({{< relref "/ChapterFour/1600~1699/1663.Smallest-String-With-A-Given-Numeric-Value.md" >}})|Medium||||66.8%| +|1668|Maximum Repeating Substring|[Go]({{< relref "/ChapterFour/1600~1699/1668.Maximum-Repeating-Substring.md" >}})|Easy||||39.5%| +|1678|Goal Parser Interpretation|[Go]({{< relref "/ChapterFour/1600~1699/1678.Goal-Parser-Interpretation.md" >}})|Easy||||86.5%| +|1684|Count the Number of Consistent Strings|[Go]({{< relref "/ChapterFour/1600~1699/1684.Count-the-Number-of-Consistent-Strings.md" >}})|Easy||||82.2%| +|1689|Partitioning Into Minimum Number Of Deci-Binary Numbers|[Go]({{< relref "/ChapterFour/1600~1699/1689.Partitioning-Into-Minimum-Number-Of-Deci-Binary-Numbers.md" >}})|Medium||||89.2%| +|1694|Reformat Phone Number|[Go]({{< relref "/ChapterFour/1600~1699/1694.Reformat-Phone-Number.md" >}})|Easy||||65.1%| +|1704|Determine if String Halves Are Alike|[Go]({{< relref "/ChapterFour/1700~1799/1704.Determine-if-String-Halves-Are-Alike.md" >}})|Easy||||77.7%| +|1736|Latest Time by Replacing Hidden Digits|[Go]({{< relref "/ChapterFour/1700~1799/1736.Latest-Time-by-Replacing-Hidden-Digits.md" >}})|Easy||||42.4%| +|1758|Minimum Changes To Make Alternating Binary String|[Go]({{< relref "/ChapterFour/1700~1799/1758.Minimum-Changes-To-Make-Alternating-Binary-String.md" >}})|Easy||||58.3%| +|1763|Longest Nice Substring|[Go]({{< relref "/ChapterFour/1700~1799/1763.Longest-Nice-Substring.md" >}})|Easy||||61.6%| +|1816|Truncate Sentence|[Go]({{< relref "/ChapterFour/1800~1899/1816.Truncate-Sentence.md" >}})|Easy||||83.0%| +|2038|Remove Colored Pieces if Both Neighbors are the Same Color|[Go]({{< relref "/ChapterFour/2000~2099/2038.Remove-Colored-Pieces-if-Both-Neighbors-are-the-Same-Color.md" >}})|Medium||||57.9%| +|2096|Step-By-Step Directions From a Binary Tree Node to Another|[Go]({{< relref "/ChapterFour/2000~2099/2096.Step-By-Step-Directions-From-a-Binary-Tree-Node-to-Another.md" >}})|Medium||||48.4%| +|2167|Minimum Time to Remove All Cars Containing Illegal Goods|[Go]({{< relref "/ChapterFour/2100~2199/2167.Minimum-Time-to-Remove-All-Cars-Containing-Illegal-Goods.md" >}})|Hard||||40.7%| +|2182|Construct String With Repeat Limit|[Go]({{< relref "/ChapterFour/2100~2199/2182.Construct-String-With-Repeat-Limit.md" >}})|Medium||||52.2%| |------------|-------------------------------------------------------|-------| ----------------| ---------------|-------------|-------------|-------------| diff --git a/website/content/ChapterTwo/Tree.md b/website/content/ChapterTwo/Tree.md index 9df76ee9c..ebd6b5b9b 100644 --- a/website/content/ChapterTwo/Tree.md +++ b/website/content/ChapterTwo/Tree.md @@ -9,75 +9,90 @@ weight: 6 | No. | Title | Solution | Difficulty | TimeComplexity | SpaceComplexity |Favorite| Acceptance | |:--------:|:------- | :--------: | :----------: | :----: | :-----: | :-----: |:-----: | -|0094|Binary Tree Inorder Traversal|[Go]({{< relref "/ChapterFour/0001~0099/0094.Binary-Tree-Inorder-Traversal.md" >}})|Medium| O(n)| O(1)||66.5%| -|0095|Unique Binary Search Trees II|[Go]({{< relref "/ChapterFour/0001~0099/0095.Unique-Binary-Search-Trees-II.md" >}})|Medium||||43.2%| -|0096|Unique Binary Search Trees|[Go]({{< relref "/ChapterFour/0001~0099/0096.Unique-Binary-Search-Trees.md" >}})|Medium| O(n^2)| O(n)||54.8%| -|0098|Validate Binary Search Tree|[Go]({{< relref "/ChapterFour/0001~0099/0098.Validate-Binary-Search-Tree.md" >}})|Medium| O(n)| O(1)||29.0%| -|0099|Recover Binary Search Tree|[Go]({{< relref "/ChapterFour/0001~0099/0099.Recover-Binary-Search-Tree.md" >}})|Hard| O(n)| O(1)||42.9%| -|0100|Same Tree|[Go]({{< relref "/ChapterFour/0100~0199/0100.Same-Tree.md" >}})|Easy| O(n)| O(1)||54.3%| -|0101|Symmetric Tree|[Go]({{< relref "/ChapterFour/0100~0199/0101.Symmetric-Tree.md" >}})|Easy| O(n)| O(1)||48.6%| -|0102|Binary Tree Level Order Traversal|[Go]({{< relref "/ChapterFour/0100~0199/0102.Binary-Tree-Level-Order-Traversal.md" >}})|Medium| O(n)| O(1)||57.1%| -|0103|Binary Tree Zigzag Level Order Traversal|[Go]({{< relref "/ChapterFour/0100~0199/0103.Binary-Tree-Zigzag-Level-Order-Traversal.md" >}})|Medium| O(n)| O(n)||50.6%| -|0104|Maximum Depth of Binary Tree|[Go]({{< relref "/ChapterFour/0100~0199/0104.Maximum-Depth-of-Binary-Tree.md" >}})|Easy| O(n)| O(1)||68.5%| -|0105|Construct Binary Tree from Preorder and Inorder Traversal|[Go]({{< relref "/ChapterFour/0100~0199/0105.Construct-Binary-Tree-from-Preorder-and-Inorder-Traversal.md" >}})|Medium||||52.6%| -|0106|Construct Binary Tree from Inorder and Postorder Traversal|[Go]({{< relref "/ChapterFour/0100~0199/0106.Construct-Binary-Tree-from-Inorder-and-Postorder-Traversal.md" >}})|Medium||||50.3%| -|0107|Binary Tree Level Order Traversal II|[Go]({{< relref "/ChapterFour/0100~0199/0107.Binary-Tree-Level-Order-Traversal-II.md" >}})|Medium| O(n)| O(1)||55.6%| -|0108|Convert Sorted Array to Binary Search Tree|[Go]({{< relref "/ChapterFour/0100~0199/0108.Convert-Sorted-Array-to-Binary-Search-Tree.md" >}})|Easy| O(n)| O(1)||61.1%| -|0110|Balanced Binary Tree|[Go]({{< relref "/ChapterFour/0100~0199/0110.Balanced-Binary-Tree.md" >}})|Easy| O(n)| O(1)||44.9%| -|0111|Minimum Depth of Binary Tree|[Go]({{< relref "/ChapterFour/0100~0199/0111.Minimum-Depth-of-Binary-Tree.md" >}})|Easy| O(n)| O(1)||39.9%| -|0112|Path Sum|[Go]({{< relref "/ChapterFour/0100~0199/0112.Path-Sum.md" >}})|Easy| O(n)| O(1)||42.8%| -|0113|Path Sum II|[Go]({{< relref "/ChapterFour/0100~0199/0113.Path-Sum-II.md" >}})|Medium| O(n)| O(1)||49.7%| -|0114|Flatten Binary Tree to Linked List|[Go]({{< relref "/ChapterFour/0100~0199/0114.Flatten-Binary-Tree-to-Linked-List.md" >}})|Medium| O(n)| O(1)||52.6%| -|0124|Binary Tree Maximum Path Sum|[Go]({{< relref "/ChapterFour/0100~0199/0124.Binary-Tree-Maximum-Path-Sum.md" >}})|Hard| O(n)| O(1)||35.7%| -|0129|Sum Root to Leaf Numbers|[Go]({{< relref "/ChapterFour/0100~0199/0129.Sum-Root-to-Leaf-Numbers.md" >}})|Medium| O(n)| O(1)||51.5%| -|0144|Binary Tree Preorder Traversal|[Go]({{< relref "/ChapterFour/0100~0199/0144.Binary-Tree-Preorder-Traversal.md" >}})|Medium| O(n)| O(1)||58.0%| -|0145|Binary Tree Postorder Traversal|[Go]({{< relref "/ChapterFour/0100~0199/0145.Binary-Tree-Postorder-Traversal.md" >}})|Medium| O(n)| O(1)||58.2%| -|0173|Binary Search Tree Iterator|[Go]({{< relref "/ChapterFour/0100~0199/0173.Binary-Search-Tree-Iterator.md" >}})|Medium| O(n)| O(1)||60.8%| -|0199|Binary Tree Right Side View|[Go]({{< relref "/ChapterFour/0100~0199/0199.Binary-Tree-Right-Side-View.md" >}})|Medium| O(n)| O(1)||56.7%| -|0222|Count Complete Tree Nodes|[Go]({{< relref "/ChapterFour/0200~0299/0222.Count-Complete-Tree-Nodes.md" >}})|Medium| O(n)| O(1)||49.9%| -|0226|Invert Binary Tree|[Go]({{< relref "/ChapterFour/0200~0299/0226.Invert-Binary-Tree.md" >}})|Easy| O(n)| O(1)||67.5%| -|0230|Kth Smallest Element in a BST|[Go]({{< relref "/ChapterFour/0200~0299/0230.Kth-Smallest-Element-in-a-BST.md" >}})|Medium| O(n)| O(1)||63.1%| -|0235|Lowest Common Ancestor of a Binary Search Tree|[Go]({{< relref "/ChapterFour/0200~0299/0235.Lowest-Common-Ancestor-of-a-Binary-Search-Tree.md" >}})|Easy| O(n)| O(1)||52.3%| -|0236|Lowest Common Ancestor of a Binary Tree|[Go]({{< relref "/ChapterFour/0200~0299/0236.Lowest-Common-Ancestor-of-a-Binary-Tree.md" >}})|Medium| O(n)| O(1)||49.6%| -|0257|Binary Tree Paths|[Go]({{< relref "/ChapterFour/0200~0299/0257.Binary-Tree-Paths.md" >}})|Easy| O(n)| O(1)||54.3%| -|0297|Serialize and Deserialize Binary Tree|[Go]({{< relref "/ChapterFour/0200~0299/0297.Serialize-and-Deserialize-Binary-Tree.md" >}})|Hard||||50.4%| -|0337|House Robber III|[Go]({{< relref "/ChapterFour/0300~0399/0337.House-Robber-III.md" >}})|Medium||||52.0%| -|0404|Sum of Left Leaves|[Go]({{< relref "/ChapterFour/0400~0499/0404.Sum-of-Left-Leaves.md" >}})|Easy| O(n)| O(1)||52.4%| -|0437|Path Sum III|[Go]({{< relref "/ChapterFour/0400~0499/0437.Path-Sum-III.md" >}})|Medium| O(n)| O(1)||48.4%| -|0508|Most Frequent Subtree Sum|[Go]({{< relref "/ChapterFour/0500~0599/0508.Most-Frequent-Subtree-Sum.md" >}})|Medium||||59.3%| -|0513|Find Bottom Left Tree Value|[Go]({{< relref "/ChapterFour/0500~0599/0513.Find-Bottom-Left-Tree-Value.md" >}})|Medium||||62.9%| -|0515|Find Largest Value in Each Tree Row|[Go]({{< relref "/ChapterFour/0500~0599/0515.Find-Largest-Value-in-Each-Tree-Row.md" >}})|Medium| O(n)| O(n)||62.5%| -|0530|Minimum Absolute Difference in BST|[Go]({{< relref "/ChapterFour/0500~0599/0530.Minimum-Absolute-Difference-in-BST.md" >}})|Easy||||55.1%| -|0538|Convert BST to Greater Tree|[Go]({{< relref "/ChapterFour/0500~0599/0538.Convert-BST-to-Greater-Tree.md" >}})|Medium||||60.0%| -|0563|Binary Tree Tilt|[Go]({{< relref "/ChapterFour/0500~0599/0563.Binary-Tree-Tilt.md" >}})|Easy||||53.4%| -|0572|Subtree of Another Tree|[Go]({{< relref "/ChapterFour/0500~0599/0572.Subtree-of-Another-Tree.md" >}})|Easy||||44.6%| -|0589|N-ary Tree Preorder Traversal|[Go]({{< relref "/ChapterFour/0500~0599/0589.N-ary-Tree-Preorder-Traversal.md" >}})|Easy||||74.3%| -|0623|Add One Row to Tree|[Go]({{< relref "/ChapterFour/0600~0699/0623.Add-One-Row-to-Tree.md" >}})|Medium||||53.0%| -|0637|Average of Levels in Binary Tree|[Go]({{< relref "/ChapterFour/0600~0699/0637.Average-of-Levels-in-Binary-Tree.md" >}})|Easy| O(n)| O(n)||66.2%| -|0653|Two Sum IV - Input is a BST|[Go]({{< relref "/ChapterFour/0600~0699/0653.Two-Sum-IV-Input-is-a-BST.md" >}})|Easy||||56.4%| -|0662|Maximum Width of Binary Tree|[Go]({{< relref "/ChapterFour/0600~0699/0662.Maximum-Width-of-Binary-Tree.md" >}})|Medium||||39.7%| -|0669|Trim a Binary Search Tree|[Go]({{< relref "/ChapterFour/0600~0699/0669.Trim-a-Binary-Search-Tree.md" >}})|Medium||||64.3%| -|0684|Redundant Connection|[Go]({{< relref "/ChapterFour/0600~0699/0684.Redundant-Connection.md" >}})|Medium||||59.2%| -|0685|Redundant Connection II|[Go]({{< relref "/ChapterFour/0600~0699/0685.Redundant-Connection-II.md" >}})|Hard||||33.2%| -|0783|Minimum Distance Between BST Nodes|[Go]({{< relref "/ChapterFour/0700~0799/0783.Minimum-Distance-Between-BST-Nodes.md" >}})|Easy||||54.3%| -|0834|Sum of Distances in Tree|[Go]({{< relref "/ChapterFour/0800~0899/0834.Sum-of-Distances-in-Tree.md" >}})|Hard||||46.8%| -|0863|All Nodes Distance K in Binary Tree|[Go]({{< relref "/ChapterFour/0800~0899/0863.All-Nodes-Distance-K-in-Binary-Tree.md" >}})|Medium||||58.3%| -|0872|Leaf-Similar Trees|[Go]({{< relref "/ChapterFour/0800~0899/0872.Leaf-Similar-Trees.md" >}})|Easy||||64.5%| -|0897|Increasing Order Search Tree|[Go]({{< relref "/ChapterFour/0800~0899/0897.Increasing-Order-Search-Tree.md" >}})|Easy||||74.7%| -|0938|Range Sum of BST|[Go]({{< relref "/ChapterFour/0900~0999/0938.Range-Sum-of-BST.md" >}})|Easy||||83.3%| -|0968|Binary Tree Cameras|[Go]({{< relref "/ChapterFour/0900~0999/0968.Binary-Tree-Cameras.md" >}})|Hard||||39.0%| -|0971|Flip Binary Tree To Match Preorder Traversal|[Go]({{< relref "/ChapterFour/0900~0999/0971.Flip-Binary-Tree-To-Match-Preorder-Traversal.md" >}})|Medium||||50.1%| -|0979|Distribute Coins in Binary Tree|[Go]({{< relref "/ChapterFour/0900~0999/0979.Distribute-Coins-in-Binary-Tree.md" >}})|Medium||||70.0%| -|0987|Vertical Order Traversal of a Binary Tree|[Go]({{< relref "/ChapterFour/0900~0999/0987.Vertical-Order-Traversal-of-a-Binary-Tree.md" >}})|Hard||||39.1%| -|0993|Cousins in Binary Tree|[Go]({{< relref "/ChapterFour/0900~0999/0993.Cousins-in-Binary-Tree.md" >}})|Easy| O(n)| O(1)||52.3%| -|1026|Maximum Difference Between Node and Ancestor|[Go]({{< relref "/ChapterFour/1000~1099/1026.Maximum-Difference-Between-Node-and-Ancestor.md" >}})|Medium||||69.8%| -|1028|Recover a Tree From Preorder Traversal|[Go]({{< relref "/ChapterFour/1000~1099/1028.Recover-a-Tree-From-Preorder-Traversal.md" >}})|Hard||||71.1%| -|1038|Binary Search Tree to Greater Sum Tree|[Go]({{< relref "/ChapterFour/1000~1099/1038.Binary-Search-Tree-to-Greater-Sum-Tree.md" >}})|Medium||||82.7%| -|1110|Delete Nodes And Return Forest|[Go]({{< relref "/ChapterFour/1100~1199/1110.Delete-Nodes-And-Return-Forest.md" >}})|Medium||||67.9%| -|1123|Lowest Common Ancestor of Deepest Leaves|[Go]({{< relref "/ChapterFour/1100~1199/1123.Lowest-Common-Ancestor-of-Deepest-Leaves.md" >}})|Medium||||68.1%| -|1145|Binary Tree Coloring Game|[Go]({{< relref "/ChapterFour/1100~1199/1145.Binary-Tree-Coloring-Game.md" >}})|Medium||||51.2%| -|1302|Deepest Leaves Sum|[Go]({{< relref "/ChapterFour/1300~1399/1302.Deepest-Leaves-Sum.md" >}})|Medium||||85.4%| -|1305|All Elements in Two Binary Search Trees|[Go]({{< relref "/ChapterFour/1300~1399/1305.All-Elements-in-Two-Binary-Search-Trees.md" >}})|Medium||||77.8%| +|0094|Binary Tree Inorder Traversal|[Go]({{< relref "/ChapterFour/0001~0099/0094.Binary-Tree-Inorder-Traversal.md" >}})|Easy| O(n)| O(1)||73.8%| +|0095|Unique Binary Search Trees II|[Go]({{< relref "/ChapterFour/0001~0099/0095.Unique-Binary-Search-Trees-II.md" >}})|Medium||||52.3%| +|0096|Unique Binary Search Trees|[Go]({{< relref "/ChapterFour/0001~0099/0096.Unique-Binary-Search-Trees.md" >}})|Medium| O(n^2)| O(n)||59.6%| +|0098|Validate Binary Search Tree|[Go]({{< relref "/ChapterFour/0001~0099/0098.Validate-Binary-Search-Tree.md" >}})|Medium| O(n)| O(1)||32.0%| +|0099|Recover Binary Search Tree|[Go]({{< relref "/ChapterFour/0001~0099/0099.Recover-Binary-Search-Tree.md" >}})|Medium| O(n)| O(1)||51.0%| +|0100|Same Tree|[Go]({{< relref "/ChapterFour/0100~0199/0100.Same-Tree.md" >}})|Easy| O(n)| O(1)||58.1%| +|0101|Symmetric Tree|[Go]({{< relref "/ChapterFour/0100~0199/0101.Symmetric-Tree.md" >}})|Easy| O(n)| O(1)||54.3%| +|0102|Binary Tree Level Order Traversal|[Go]({{< relref "/ChapterFour/0100~0199/0102.Binary-Tree-Level-Order-Traversal.md" >}})|Medium| O(n)| O(1)||64.3%| +|0103|Binary Tree Zigzag Level Order Traversal|[Go]({{< relref "/ChapterFour/0100~0199/0103.Binary-Tree-Zigzag-Level-Order-Traversal.md" >}})|Medium| O(n)| O(n)||56.9%| +|0104|Maximum Depth of Binary Tree|[Go]({{< relref "/ChapterFour/0100~0199/0104.Maximum-Depth-of-Binary-Tree.md" >}})|Easy| O(n)| O(1)||73.9%| +|0105|Construct Binary Tree from Preorder and Inorder Traversal|[Go]({{< relref "/ChapterFour/0100~0199/0105.Construct-Binary-Tree-from-Preorder-and-Inorder-Traversal.md" >}})|Medium||||61.5%| +|0106|Construct Binary Tree from Inorder and Postorder Traversal|[Go]({{< relref "/ChapterFour/0100~0199/0106.Construct-Binary-Tree-from-Inorder-and-Postorder-Traversal.md" >}})|Medium||||60.0%| +|0107|Binary Tree Level Order Traversal II|[Go]({{< relref "/ChapterFour/0100~0199/0107.Binary-Tree-Level-Order-Traversal-II.md" >}})|Medium| O(n)| O(1)||61.1%| +|0108|Convert Sorted Array to Binary Search Tree|[Go]({{< relref "/ChapterFour/0100~0199/0108.Convert-Sorted-Array-to-Binary-Search-Tree.md" >}})|Easy| O(n)| O(1)||69.8%| +|0109|Convert Sorted List to Binary Search Tree|[Go]({{< relref "/ChapterFour/0100~0199/0109.Convert-Sorted-List-to-Binary-Search-Tree.md" >}})|Medium||||60.2%| +|0110|Balanced Binary Tree|[Go]({{< relref "/ChapterFour/0100~0199/0110.Balanced-Binary-Tree.md" >}})|Easy| O(n)| O(1)||49.0%| +|0111|Minimum Depth of Binary Tree|[Go]({{< relref "/ChapterFour/0100~0199/0111.Minimum-Depth-of-Binary-Tree.md" >}})|Easy| O(n)| O(1)||44.4%| +|0112|Path Sum|[Go]({{< relref "/ChapterFour/0100~0199/0112.Path-Sum.md" >}})|Easy| O(n)| O(1)||48.2%| +|0113|Path Sum II|[Go]({{< relref "/ChapterFour/0100~0199/0113.Path-Sum-II.md" >}})|Medium| O(n)| O(1)||57.1%| +|0114|Flatten Binary Tree to Linked List|[Go]({{< relref "/ChapterFour/0100~0199/0114.Flatten-Binary-Tree-to-Linked-List.md" >}})|Medium| O(n)| O(1)||61.8%| +|0116|Populating Next Right Pointers in Each Node|[Go]({{< relref "/ChapterFour/0100~0199/0116.Populating-Next-Right-Pointers-in-Each-Node.md" >}})|Medium||||60.4%| +|0124|Binary Tree Maximum Path Sum|[Go]({{< relref "/ChapterFour/0100~0199/0124.Binary-Tree-Maximum-Path-Sum.md" >}})|Hard| O(n)| O(1)||39.2%| +|0129|Sum Root to Leaf Numbers|[Go]({{< relref "/ChapterFour/0100~0199/0129.Sum-Root-to-Leaf-Numbers.md" >}})|Medium| O(n)| O(1)||61.0%| +|0144|Binary Tree Preorder Traversal|[Go]({{< relref "/ChapterFour/0100~0199/0144.Binary-Tree-Preorder-Traversal.md" >}})|Easy| O(n)| O(1)||66.8%| +|0145|Binary Tree Postorder Traversal|[Go]({{< relref "/ChapterFour/0100~0199/0145.Binary-Tree-Postorder-Traversal.md" >}})|Easy| O(n)| O(1)||67.9%| +|0173|Binary Search Tree Iterator|[Go]({{< relref "/ChapterFour/0100~0199/0173.Binary-Search-Tree-Iterator.md" >}})|Medium| O(n)| O(1)||69.7%| +|0199|Binary Tree Right Side View|[Go]({{< relref "/ChapterFour/0100~0199/0199.Binary-Tree-Right-Side-View.md" >}})|Medium| O(n)| O(1)||61.6%| +|0222|Count Complete Tree Nodes|[Go]({{< relref "/ChapterFour/0200~0299/0222.Count-Complete-Tree-Nodes.md" >}})|Medium| O(n)| O(1)||60.5%| +|0226|Invert Binary Tree|[Go]({{< relref "/ChapterFour/0200~0299/0226.Invert-Binary-Tree.md" >}})|Easy| O(n)| O(1)||74.7%| +|0230|Kth Smallest Element in a BST|[Go]({{< relref "/ChapterFour/0200~0299/0230.Kth-Smallest-Element-in-a-BST.md" >}})|Medium| O(n)| O(1)||70.1%| +|0235|Lowest Common Ancestor of a Binary Search Tree|[Go]({{< relref "/ChapterFour/0200~0299/0235.Lowest-Common-Ancestor-of-a-Binary-Search-Tree.md" >}})|Medium| O(n)| O(1)||61.5%| +|0236|Lowest Common Ancestor of a Binary Tree|[Go]({{< relref "/ChapterFour/0200~0299/0236.Lowest-Common-Ancestor-of-a-Binary-Tree.md" >}})|Medium| O(n)| O(1)||58.8%| +|0257|Binary Tree Paths|[Go]({{< relref "/ChapterFour/0200~0299/0257.Binary-Tree-Paths.md" >}})|Easy| O(n)| O(1)||61.4%| +|0297|Serialize and Deserialize Binary Tree|[Go]({{< relref "/ChapterFour/0200~0299/0297.Serialize-and-Deserialize-Binary-Tree.md" >}})|Hard||||55.4%| +|0331|Verify Preorder Serialization of a Binary Tree|[Go]({{< relref "/ChapterFour/0300~0399/0331.Verify-Preorder-Serialization-of-a-Binary-Tree.md" >}})|Medium||||44.6%| +|0337|House Robber III|[Go]({{< relref "/ChapterFour/0300~0399/0337.House-Robber-III.md" >}})|Medium||||53.9%| +|0341|Flatten Nested List Iterator|[Go]({{< relref "/ChapterFour/0300~0399/0341.Flatten-Nested-List-Iterator.md" >}})|Medium||||61.8%| +|0404|Sum of Left Leaves|[Go]({{< relref "/ChapterFour/0400~0499/0404.Sum-of-Left-Leaves.md" >}})|Easy| O(n)| O(1)||56.7%| +|0429|N-ary Tree Level Order Traversal|[Go]({{< relref "/ChapterFour/0400~0499/0429.N-ary-Tree-Level-Order-Traversal.md" >}})|Medium||||70.7%| +|0437|Path Sum III|[Go]({{< relref "/ChapterFour/0400~0499/0437.Path-Sum-III.md" >}})|Medium| O(n)| O(1)||48.0%| +|0508|Most Frequent Subtree Sum|[Go]({{< relref "/ChapterFour/0500~0599/0508.Most-Frequent-Subtree-Sum.md" >}})|Medium||||64.9%| +|0513|Find Bottom Left Tree Value|[Go]({{< relref "/ChapterFour/0500~0599/0513.Find-Bottom-Left-Tree-Value.md" >}})|Medium||||66.9%| +|0515|Find Largest Value in Each Tree Row|[Go]({{< relref "/ChapterFour/0500~0599/0515.Find-Largest-Value-in-Each-Tree-Row.md" >}})|Medium| O(n)| O(n)||64.6%| +|0530|Minimum Absolute Difference in BST|[Go]({{< relref "/ChapterFour/0500~0599/0530.Minimum-Absolute-Difference-in-BST.md" >}})|Easy||||57.3%| +|0538|Convert BST to Greater Tree|[Go]({{< relref "/ChapterFour/0500~0599/0538.Convert-BST-to-Greater-Tree.md" >}})|Medium||||67.8%| +|0543|Diameter of Binary Tree|[Go]({{< relref "/ChapterFour/0500~0599/0543.Diameter-of-Binary-Tree.md" >}})|Easy||||56.8%| +|0559|Maximum Depth of N-ary Tree|[Go]({{< relref "/ChapterFour/0500~0599/0559.Maximum-Depth-of-N-ary-Tree.md" >}})|Easy||||71.7%| +|0563|Binary Tree Tilt|[Go]({{< relref "/ChapterFour/0500~0599/0563.Binary-Tree-Tilt.md" >}})|Easy||||60.0%| +|0572|Subtree of Another Tree|[Go]({{< relref "/ChapterFour/0500~0599/0572.Subtree-of-Another-Tree.md" >}})|Easy||||46.4%| +|0589|N-ary Tree Preorder Traversal|[Go]({{< relref "/ChapterFour/0500~0599/0589.N-ary-Tree-Preorder-Traversal.md" >}})|Easy||||75.9%| +|0617|Merge Two Binary Trees|[Go]({{< relref "/ChapterFour/0600~0699/0617.Merge-Two-Binary-Trees.md" >}})|Easy||||78.6%| +|0623|Add One Row to Tree|[Go]({{< relref "/ChapterFour/0600~0699/0623.Add-One-Row-to-Tree.md" >}})|Medium||||59.5%| +|0637|Average of Levels in Binary Tree|[Go]({{< relref "/ChapterFour/0600~0699/0637.Average-of-Levels-in-Binary-Tree.md" >}})|Easy| O(n)| O(n)||71.8%| +|0653|Two Sum IV - Input is a BST|[Go]({{< relref "/ChapterFour/0600~0699/0653.Two-Sum-IV-Input-is-a-BST.md" >}})|Easy||||61.0%| +|0662|Maximum Width of Binary Tree|[Go]({{< relref "/ChapterFour/0600~0699/0662.Maximum-Width-of-Binary-Tree.md" >}})|Medium||||40.7%| +|0669|Trim a Binary Search Tree|[Go]({{< relref "/ChapterFour/0600~0699/0669.Trim-a-Binary-Search-Tree.md" >}})|Medium||||66.4%| +|0700|Search in a Binary Search Tree|[Go]({{< relref "/ChapterFour/0700~0799/0700.Search-in-a-Binary-Search-Tree.md" >}})|Easy||||77.7%| +|0701|Insert into a Binary Search Tree|[Go]({{< relref "/ChapterFour/0700~0799/0701.Insert-into-a-Binary-Search-Tree.md" >}})|Medium||||74.3%| +|0703|Kth Largest Element in a Stream|[Go]({{< relref "/ChapterFour/0700~0799/0703.Kth-Largest-Element-in-a-Stream.md" >}})|Easy||||55.5%| +|0783|Minimum Distance Between BST Nodes|[Go]({{< relref "/ChapterFour/0700~0799/0783.Minimum-Distance-Between-BST-Nodes.md" >}})|Easy||||59.3%| +|0834|Sum of Distances in Tree|[Go]({{< relref "/ChapterFour/0800~0899/0834.Sum-of-Distances-in-Tree.md" >}})|Hard||||59.1%| +|0863|All Nodes Distance K in Binary Tree|[Go]({{< relref "/ChapterFour/0800~0899/0863.All-Nodes-Distance-K-in-Binary-Tree.md" >}})|Medium||||62.2%| +|0872|Leaf-Similar Trees|[Go]({{< relref "/ChapterFour/0800~0899/0872.Leaf-Similar-Trees.md" >}})|Easy||||67.6%| +|0897|Increasing Order Search Tree|[Go]({{< relref "/ChapterFour/0800~0899/0897.Increasing-Order-Search-Tree.md" >}})|Easy||||78.4%| +|0938|Range Sum of BST|[Go]({{< relref "/ChapterFour/0900~0999/0938.Range-Sum-of-BST.md" >}})|Easy||||85.9%| +|0958|Check Completeness of a Binary Tree|[Go]({{< relref "/ChapterFour/0900~0999/0958.Check-Completeness-of-a-Binary-Tree.md" >}})|Medium||||56.2%| +|0968|Binary Tree Cameras|[Go]({{< relref "/ChapterFour/0900~0999/0968.Binary-Tree-Cameras.md" >}})|Hard||||46.6%| +|0971|Flip Binary Tree To Match Preorder Traversal|[Go]({{< relref "/ChapterFour/0900~0999/0971.Flip-Binary-Tree-To-Match-Preorder-Traversal.md" >}})|Medium||||50.0%| +|0979|Distribute Coins in Binary Tree|[Go]({{< relref "/ChapterFour/0900~0999/0979.Distribute-Coins-in-Binary-Tree.md" >}})|Medium||||72.2%| +|0987|Vertical Order Traversal of a Binary Tree|[Go]({{< relref "/ChapterFour/0900~0999/0987.Vertical-Order-Traversal-of-a-Binary-Tree.md" >}})|Hard||||45.1%| +|0993|Cousins in Binary Tree|[Go]({{< relref "/ChapterFour/0900~0999/0993.Cousins-in-Binary-Tree.md" >}})|Easy| O(n)| O(1)||54.6%| +|1022|Sum of Root To Leaf Binary Numbers|[Go]({{< relref "/ChapterFour/1000~1099/1022.Sum-of-Root-To-Leaf-Binary-Numbers.md" >}})|Easy||||73.6%| +|1026|Maximum Difference Between Node and Ancestor|[Go]({{< relref "/ChapterFour/1000~1099/1026.Maximum-Difference-Between-Node-and-Ancestor.md" >}})|Medium||||75.8%| +|1028|Recover a Tree From Preorder Traversal|[Go]({{< relref "/ChapterFour/1000~1099/1028.Recover-a-Tree-From-Preorder-Traversal.md" >}})|Hard||||73.3%| +|1038|Binary Search Tree to Greater Sum Tree|[Go]({{< relref "/ChapterFour/1000~1099/1038.Binary-Search-Tree-to-Greater-Sum-Tree.md" >}})|Medium||||85.5%| +|1104|Path In Zigzag Labelled Binary Tree|[Go]({{< relref "/ChapterFour/1100~1199/1104.Path-In-Zigzag-Labelled-Binary-Tree.md" >}})|Medium||||75.1%| +|1110|Delete Nodes And Return Forest|[Go]({{< relref "/ChapterFour/1100~1199/1110.Delete-Nodes-And-Return-Forest.md" >}})|Medium||||69.3%| +|1123|Lowest Common Ancestor of Deepest Leaves|[Go]({{< relref "/ChapterFour/1100~1199/1123.Lowest-Common-Ancestor-of-Deepest-Leaves.md" >}})|Medium||||70.9%| +|1145|Binary Tree Coloring Game|[Go]({{< relref "/ChapterFour/1100~1199/1145.Binary-Tree-Coloring-Game.md" >}})|Medium||||51.7%| +|1302|Deepest Leaves Sum|[Go]({{< relref "/ChapterFour/1300~1399/1302.Deepest-Leaves-Sum.md" >}})|Medium||||86.7%| +|1305|All Elements in Two Binary Search Trees|[Go]({{< relref "/ChapterFour/1300~1399/1305.All-Elements-in-Two-Binary-Search-Trees.md" >}})|Medium||||79.8%| +|1600|Throne Inheritance|[Go]({{< relref "/ChapterFour/1600~1699/1600.Throne-Inheritance.md" >}})|Medium||||63.6%| +|1609|Even Odd Tree|[Go]({{< relref "/ChapterFour/1600~1699/1609.Even-Odd-Tree.md" >}})|Medium||||54.3%| +|2096|Step-By-Step Directions From a Binary Tree Node to Another|[Go]({{< relref "/ChapterFour/2000~2099/2096.Step-By-Step-Directions-From-a-Binary-Tree-Node-to-Another.md" >}})|Medium||||48.4%| |------------|-------------------------------------------------------|-------| ----------------| ---------------|-------------|-------------|-------------| diff --git a/website/content/ChapterTwo/Two_Pointers.md b/website/content/ChapterTwo/Two_Pointers.md index cf7cd4c5c..6959d5ff8 100644 --- a/website/content/ChapterTwo/Two_Pointers.md +++ b/website/content/ChapterTwo/Two_Pointers.md @@ -32,65 +32,85 @@ weight: 3 | No. | Title | Solution | Difficulty | TimeComplexity | SpaceComplexity |Favorite| Acceptance | |:--------:|:------- | :--------: | :----------: | :----: | :-----: | :-----: |:-----: | -|0003|Longest Substring Without Repeating Characters|[Go]({{< relref "/ChapterFour/0001~0099/0003.Longest-Substring-Without-Repeating-Characters.md" >}})|Medium| O(n)| O(1)|❤️|31.6%| -|0011|Container With Most Water|[Go]({{< relref "/ChapterFour/0001~0099/0011.Container-With-Most-Water.md" >}})|Medium| O(n)| O(1)||52.9%| -|0015|3Sum|[Go]({{< relref "/ChapterFour/0001~0099/0015.3Sum.md" >}})|Medium| O(n^2)| O(n)|❤️|28.4%| -|0016|3Sum Closest|[Go]({{< relref "/ChapterFour/0001~0099/0016.3Sum-Closest.md" >}})|Medium| O(n^2)| O(1)|❤️|46.4%| -|0018|4Sum|[Go]({{< relref "/ChapterFour/0001~0099/0018.4Sum.md" >}})|Medium| O(n^3)| O(n^2)|❤️|35.2%| -|0019|Remove Nth Node From End of List|[Go]({{< relref "/ChapterFour/0001~0099/0019.Remove-Nth-Node-From-End-of-List.md" >}})|Medium| O(n)| O(1)||36.2%| -|0026|Remove Duplicates from Sorted Array|[Go]({{< relref "/ChapterFour/0001~0099/0026.Remove-Duplicates-from-Sorted-Array.md" >}})|Easy| O(n)| O(1)||46.9%| -|0027|Remove Element|[Go]({{< relref "/ChapterFour/0001~0099/0027.Remove-Element.md" >}})|Easy| O(n)| O(1)||49.6%| -|0028|Implement strStr()|[Go]({{< relref "/ChapterFour/0001~0099/0028.Implement-strStr.md" >}})|Easy| O(n)| O(1)||35.4%| -|0030|Substring with Concatenation of All Words|[Go]({{< relref "/ChapterFour/0001~0099/0030.Substring-with-Concatenation-of-All-Words.md" >}})|Hard| O(n)| O(n)|❤️|26.4%| -|0042|Trapping Rain Water|[Go]({{< relref "/ChapterFour/0001~0099/0042.Trapping-Rain-Water.md" >}})|Hard| O(n)| O(1)|❤️|51.8%| -|0061|Rotate List|[Go]({{< relref "/ChapterFour/0001~0099/0061.Rotate-List.md" >}})|Medium| O(n)| O(1)||32.0%| -|0075|Sort Colors|[Go]({{< relref "/ChapterFour/0001~0099/0075.Sort-Colors.md" >}})|Medium| O(n)| O(1)|❤️|50.0%| -|0076|Minimum Window Substring|[Go]({{< relref "/ChapterFour/0001~0099/0076.Minimum-Window-Substring.md" >}})|Hard| O(n)| O(n)|❤️|36.3%| -|0080|Remove Duplicates from Sorted Array II|[Go]({{< relref "/ChapterFour/0001~0099/0080.Remove-Duplicates-from-Sorted-Array-II.md" >}})|Medium| O(n)| O(1||46.5%| -|0086|Partition List|[Go]({{< relref "/ChapterFour/0001~0099/0086.Partition-List.md" >}})|Medium| O(n)| O(1)|❤️|44.9%| -|0088|Merge Sorted Array|[Go]({{< relref "/ChapterFour/0001~0099/0088.Merge-Sorted-Array.md" >}})|Easy| O(n)| O(1)|❤️|40.9%| -|0125|Valid Palindrome|[Go]({{< relref "/ChapterFour/0100~0199/0125.Valid-Palindrome.md" >}})|Easy| O(n)| O(1)||38.7%| -|0141|Linked List Cycle|[Go]({{< relref "/ChapterFour/0100~0199/0141.Linked-List-Cycle.md" >}})|Easy| O(n)| O(1)|❤️|43.2%| -|0142|Linked List Cycle II|[Go]({{< relref "/ChapterFour/0100~0199/0142.Linked-List-Cycle-II.md" >}})|Medium| O(n)| O(1)|❤️|40.1%| -|0167|Two Sum II - Input array is sorted|[Go]({{< relref "/ChapterFour/0100~0199/0167.Two-Sum-II-Input-array-is-sorted.md" >}})|Easy| O(n)| O(1)||55.8%| -|0209|Minimum Size Subarray Sum|[Go]({{< relref "/ChapterFour/0200~0299/0209.Minimum-Size-Subarray-Sum.md" >}})|Medium| O(n)| O(1)||39.9%| -|0234|Palindrome Linked List|[Go]({{< relref "/ChapterFour/0200~0299/0234.Palindrome-Linked-List.md" >}})|Easy| O(n)| O(1)||42.2%| -|0283|Move Zeroes|[Go]({{< relref "/ChapterFour/0200~0299/0283.Move-Zeroes.md" >}})|Easy| O(n)| O(1)||58.7%| -|0287|Find the Duplicate Number|[Go]({{< relref "/ChapterFour/0200~0299/0287.Find-the-Duplicate-Number.md" >}})|Medium| O(n)| O(1)|❤️|58.0%| -|0344|Reverse String|[Go]({{< relref "/ChapterFour/0300~0399/0344.Reverse-String.md" >}})|Easy| O(n)| O(1)||70.8%| -|0345|Reverse Vowels of a String|[Go]({{< relref "/ChapterFour/0300~0399/0345.Reverse-Vowels-of-a-String.md" >}})|Easy| O(n)| O(1)||45.3%| -|0349|Intersection of Two Arrays|[Go]({{< relref "/ChapterFour/0300~0399/0349.Intersection-of-Two-Arrays.md" >}})|Easy| O(n)| O(n) ||65.5%| -|0350|Intersection of Two Arrays II|[Go]({{< relref "/ChapterFour/0300~0399/0350.Intersection-of-Two-Arrays-II.md" >}})|Easy| O(n)| O(n) ||52.2%| -|0424|Longest Repeating Character Replacement|[Go]({{< relref "/ChapterFour/0400~0499/0424.Longest-Repeating-Character-Replacement.md" >}})|Medium| O(n)| O(1) ||48.5%| -|0457|Circular Array Loop|[Go]({{< relref "/ChapterFour/0400~0499/0457.Circular-Array-Loop.md" >}})|Medium||||30.4%| -|0524|Longest Word in Dictionary through Deleting|[Go]({{< relref "/ChapterFour/0500~0599/0524.Longest-Word-in-Dictionary-through-Deleting.md" >}})|Medium| O(n)| O(1) ||50.2%| -|0532|K-diff Pairs in an Array|[Go]({{< relref "/ChapterFour/0500~0599/0532.K-diff-Pairs-in-an-Array.md" >}})|Medium| O(n)| O(n)||35.6%| -|0567|Permutation in String|[Go]({{< relref "/ChapterFour/0500~0599/0567.Permutation-in-String.md" >}})|Medium| O(n)| O(1)|❤️|44.6%| -|0632|Smallest Range Covering Elements from K Lists|[Go]({{< relref "/ChapterFour/0600~0699/0632.Smallest-Range-Covering-Elements-from-K-Lists.md" >}})|Hard||||54.7%| -|0713|Subarray Product Less Than K|[Go]({{< relref "/ChapterFour/0700~0799/0713.Subarray-Product-Less-Than-K.md" >}})|Medium| O(n)| O(1)||40.6%| -|0763|Partition Labels|[Go]({{< relref "/ChapterFour/0700~0799/0763.Partition-Labels.md" >}})|Medium| O(n)| O(1)|❤️|78.1%| -|0826|Most Profit Assigning Work|[Go]({{< relref "/ChapterFour/0800~0899/0826.Most-Profit-Assigning-Work.md" >}})|Medium| O(n log n)| O(n)||39.4%| -|0828|Count Unique Characters of All Substrings of a Given String|[Go]({{< relref "/ChapterFour/0800~0899/0828.Count-Unique-Characters-of-All-Substrings-of-a-Given-String.md" >}})|Hard| O(n)| O(1)|❤️|46.9%| -|0838|Push Dominoes|[Go]({{< relref "/ChapterFour/0800~0899/0838.Push-Dominoes.md" >}})|Medium| O(n)| O(n)||50.1%| -|0844|Backspace String Compare|[Go]({{< relref "/ChapterFour/0800~0899/0844.Backspace-String-Compare.md" >}})|Easy| O(n)| O(n) ||47.2%| -|0845|Longest Mountain in Array|[Go]({{< relref "/ChapterFour/0800~0899/0845.Longest-Mountain-in-Array.md" >}})|Medium| O(n)| O(1) ||38.7%| -|0881|Boats to Save People|[Go]({{< relref "/ChapterFour/0800~0899/0881.Boats-to-Save-People.md" >}})|Medium| O(n log n)| O(1) ||49.1%| -|0904|Fruit Into Baskets|[Go]({{< relref "/ChapterFour/0900~0999/0904.Fruit-Into-Baskets.md" >}})|Medium| O(n log n)| O(1) ||43.0%| -|0923|3Sum With Multiplicity|[Go]({{< relref "/ChapterFour/0900~0999/0923.3Sum-With-Multiplicity.md" >}})|Medium| O(n^2)| O(n) ||41.0%| -|0925|Long Pressed Name|[Go]({{< relref "/ChapterFour/0900~0999/0925.Long-Pressed-Name.md" >}})|Easy| O(n)| O(1)||37.1%| -|0930|Binary Subarrays With Sum|[Go]({{< relref "/ChapterFour/0900~0999/0930.Binary-Subarrays-With-Sum.md" >}})|Medium| O(n)| O(n) |❤️|44.9%| -|0977|Squares of a Sorted Array|[Go]({{< relref "/ChapterFour/0900~0999/0977.Squares-of-a-Sorted-Array.md" >}})|Easy| O(n)| O(1)||71.8%| -|0986|Interval List Intersections|[Go]({{< relref "/ChapterFour/0900~0999/0986.Interval-List-Intersections.md" >}})|Medium| O(n)| O(1)||68.6%| -|0992|Subarrays with K Different Integers|[Go]({{< relref "/ChapterFour/0900~0999/0992.Subarrays-with-K-Different-Integers.md" >}})|Hard| O(n)| O(n)|❤️|50.9%| -|1004|Max Consecutive Ones III|[Go]({{< relref "/ChapterFour/1000~1099/1004.Max-Consecutive-Ones-III.md" >}})|Medium| O(n)| O(1) ||61.0%| -|1093|Statistics from a Large Sample|[Go]({{< relref "/ChapterFour/1000~1099/1093.Statistics-from-a-Large-Sample.md" >}})|Medium| O(n)| O(1) ||48.6%| -|1234|Replace the Substring for Balanced String|[Go]({{< relref "/ChapterFour/1200~1299/1234.Replace-the-Substring-for-Balanced-String.md" >}})|Medium||||34.7%| -|1658|Minimum Operations to Reduce X to Zero|[Go]({{< relref "/ChapterFour/1600~1699/1658.Minimum-Operations-to-Reduce-X-to-Zero.md" >}})|Medium||||33.3%| -|1695|Maximum Erasure Value|[Go]({{< relref "/ChapterFour/1600~1699/1695.Maximum-Erasure-Value.md" >}})|Medium||||49.2%| +|0011|Container With Most Water|[Go]({{< relref "/ChapterFour/0001~0099/0011.Container-With-Most-Water.md" >}})|Medium| O(n)| O(1)||54.0%| +|0015|3Sum|[Go]({{< relref "/ChapterFour/0001~0099/0015.3Sum.md" >}})|Medium| O(n^2)| O(n)|❤️|32.6%| +|0016|3Sum Closest|[Go]({{< relref "/ChapterFour/0001~0099/0016.3Sum-Closest.md" >}})|Medium| O(n^2)| O(1)|❤️|45.8%| +|0018|4Sum|[Go]({{< relref "/ChapterFour/0001~0099/0018.4Sum.md" >}})|Medium| O(n^3)| O(n^2)|❤️|35.9%| +|0019|Remove Nth Node From End of List|[Go]({{< relref "/ChapterFour/0001~0099/0019.Remove-Nth-Node-From-End-of-List.md" >}})|Medium| O(n)| O(1)||41.0%| +|0026|Remove Duplicates from Sorted Array|[Go]({{< relref "/ChapterFour/0001~0099/0026.Remove-Duplicates-from-Sorted-Array.md" >}})|Easy| O(n)| O(1)||51.5%| +|0027|Remove Element|[Go]({{< relref "/ChapterFour/0001~0099/0027.Remove-Element.md" >}})|Easy| O(n)| O(1)||53.0%| +|0028|Find the Index of the First Occurrence in a String|[Go]({{< relref "/ChapterFour/0001~0099/0028.Find-the-Index-of-the-First-Occurrence-in-a-String.md" >}})|Easy| O(n)| O(1)||39.0%| +|0031|Next Permutation|[Go]({{< relref "/ChapterFour/0001~0099/0031.Next-Permutation.md" >}})|Medium||||37.5%| +|0042|Trapping Rain Water|[Go]({{< relref "/ChapterFour/0001~0099/0042.Trapping-Rain-Water.md" >}})|Hard| O(n)| O(1)|❤️|59.2%| +|0061|Rotate List|[Go]({{< relref "/ChapterFour/0001~0099/0061.Rotate-List.md" >}})|Medium| O(n)| O(1)||36.1%| +|0075|Sort Colors|[Go]({{< relref "/ChapterFour/0001~0099/0075.Sort-Colors.md" >}})|Medium| O(n)| O(1)|❤️|58.5%| +|0080|Remove Duplicates from Sorted Array II|[Go]({{< relref "/ChapterFour/0001~0099/0080.Remove-Duplicates-from-Sorted-Array-II.md" >}})|Medium| O(n)| O(1||52.3%| +|0082|Remove Duplicates from Sorted List II|[Go]({{< relref "/ChapterFour/0001~0099/0082.Remove-Duplicates-from-Sorted-List-II.md" >}})|Medium||||45.9%| +|0086|Partition List|[Go]({{< relref "/ChapterFour/0001~0099/0086.Partition-List.md" >}})|Medium| O(n)| O(1)|❤️|52.0%| +|0088|Merge Sorted Array|[Go]({{< relref "/ChapterFour/0001~0099/0088.Merge-Sorted-Array.md" >}})|Easy| O(n)| O(1)|❤️|46.6%| +|0125|Valid Palindrome|[Go]({{< relref "/ChapterFour/0100~0199/0125.Valid-Palindrome.md" >}})|Easy| O(n)| O(1)||44.3%| +|0141|Linked List Cycle|[Go]({{< relref "/ChapterFour/0100~0199/0141.Linked-List-Cycle.md" >}})|Easy| O(n)| O(1)|❤️|47.4%| +|0142|Linked List Cycle II|[Go]({{< relref "/ChapterFour/0100~0199/0142.Linked-List-Cycle-II.md" >}})|Medium| O(n)| O(1)|❤️|48.7%| +|0143|Reorder List|[Go]({{< relref "/ChapterFour/0100~0199/0143.Reorder-List.md" >}})|Medium||||52.5%| +|0148|Sort List|[Go]({{< relref "/ChapterFour/0100~0199/0148.Sort-List.md" >}})|Medium||||55.1%| +|0151|Reverse Words in a String|[Go]({{< relref "/ChapterFour/0100~0199/0151.Reverse-Words-in-a-String.md" >}})|Medium||||32.7%| +|0160|Intersection of Two Linked Lists|[Go]({{< relref "/ChapterFour/0100~0199/0160.Intersection-of-Two-Linked-Lists.md" >}})|Easy||||54.3%| +|0167|Two Sum II - Input Array Is Sorted|[Go]({{< relref "/ChapterFour/0100~0199/0167.Two-Sum-II-Input-Array-Is-Sorted.md" >}})|Medium| O(n)| O(1)||60.0%| +|0189|Rotate Array|[Go]({{< relref "/ChapterFour/0100~0199/0189.Rotate-Array.md" >}})|Medium||||39.4%| +|0202|Happy Number|[Go]({{< relref "/ChapterFour/0200~0299/0202.Happy-Number.md" >}})|Easy||||54.8%| +|0234|Palindrome Linked List|[Go]({{< relref "/ChapterFour/0200~0299/0234.Palindrome-Linked-List.md" >}})|Easy| O(n)| O(1)||50.2%| +|0283|Move Zeroes|[Go]({{< relref "/ChapterFour/0200~0299/0283.Move-Zeroes.md" >}})|Easy| O(n)| O(1)||61.4%| +|0287|Find the Duplicate Number|[Go]({{< relref "/ChapterFour/0200~0299/0287.Find-the-Duplicate-Number.md" >}})|Medium| O(n)| O(1)|❤️|59.1%| +|0344|Reverse String|[Go]({{< relref "/ChapterFour/0300~0399/0344.Reverse-String.md" >}})|Easy| O(n)| O(1)||76.7%| +|0345|Reverse Vowels of a String|[Go]({{< relref "/ChapterFour/0300~0399/0345.Reverse-Vowels-of-a-String.md" >}})|Easy| O(n)| O(1)||50.1%| +|0349|Intersection of Two Arrays|[Go]({{< relref "/ChapterFour/0300~0399/0349.Intersection-of-Two-Arrays.md" >}})|Easy| O(n)| O(n) ||70.9%| +|0350|Intersection of Two Arrays II|[Go]({{< relref "/ChapterFour/0300~0399/0350.Intersection-of-Two-Arrays-II.md" >}})|Easy| O(n)| O(n) ||56.0%| +|0392|Is Subsequence|[Go]({{< relref "/ChapterFour/0300~0399/0392.Is-Subsequence.md" >}})|Easy||||47.6%| +|0455|Assign Cookies|[Go]({{< relref "/ChapterFour/0400~0499/0455.Assign-Cookies.md" >}})|Easy||||49.9%| +|0457|Circular Array Loop|[Go]({{< relref "/ChapterFour/0400~0499/0457.Circular-Array-Loop.md" >}})|Medium||||32.6%| +|0475|Heaters|[Go]({{< relref "/ChapterFour/0400~0499/0475.Heaters.md" >}})|Medium||||36.5%| +|0524|Longest Word in Dictionary through Deleting|[Go]({{< relref "/ChapterFour/0500~0599/0524.Longest-Word-in-Dictionary-through-Deleting.md" >}})|Medium| O(n)| O(1) ||51.0%| +|0532|K-diff Pairs in an Array|[Go]({{< relref "/ChapterFour/0500~0599/0532.K-diff-Pairs-in-an-Array.md" >}})|Medium| O(n)| O(n)||41.2%| +|0541|Reverse String II|[Go]({{< relref "/ChapterFour/0500~0599/0541.Reverse-String-II.md" >}})|Easy||||50.5%| +|0557|Reverse Words in a String III|[Go]({{< relref "/ChapterFour/0500~0599/0557.Reverse-Words-in-a-String-III.md" >}})|Easy||||81.9%| +|0567|Permutation in String|[Go]({{< relref "/ChapterFour/0500~0599/0567.Permutation-in-String.md" >}})|Medium| O(n)| O(1)|❤️|44.3%| +|0581|Shortest Unsorted Continuous Subarray|[Go]({{< relref "/ChapterFour/0500~0599/0581.Shortest-Unsorted-Continuous-Subarray.md" >}})|Medium||||36.4%| +|0611|Valid Triangle Number|[Go]({{< relref "/ChapterFour/0600~0699/0611.Valid-Triangle-Number.md" >}})|Medium||||50.5%| +|0633|Sum of Square Numbers|[Go]({{< relref "/ChapterFour/0600~0699/0633.Sum-of-Square-Numbers.md" >}})|Medium||||34.4%| +|0653|Two Sum IV - Input is a BST|[Go]({{< relref "/ChapterFour/0600~0699/0653.Two-Sum-IV-Input-is-a-BST.md" >}})|Easy||||61.0%| +|0658|Find K Closest Elements|[Go]({{< relref "/ChapterFour/0600~0699/0658.Find-K-Closest-Elements.md" >}})|Medium||||46.8%| +|0696|Count Binary Substrings|[Go]({{< relref "/ChapterFour/0600~0699/0696.Count-Binary-Substrings.md" >}})|Easy||||65.5%| +|0719|Find K-th Smallest Pair Distance|[Go]({{< relref "/ChapterFour/0700~0799/0719.Find-K-th-Smallest-Pair-Distance.md" >}})|Hard||||36.7%| +|0763|Partition Labels|[Go]({{< relref "/ChapterFour/0700~0799/0763.Partition-Labels.md" >}})|Medium| O(n)| O(1)|❤️|79.7%| +|0795|Number of Subarrays with Bounded Maximum|[Go]({{< relref "/ChapterFour/0700~0799/0795.Number-of-Subarrays-with-Bounded-Maximum.md" >}})|Medium||||52.8%| +|0821|Shortest Distance to a Character|[Go]({{< relref "/ChapterFour/0800~0899/0821.Shortest-Distance-to-a-Character.md" >}})|Easy||||71.3%| +|0825|Friends Of Appropriate Ages|[Go]({{< relref "/ChapterFour/0800~0899/0825.Friends-Of-Appropriate-Ages.md" >}})|Medium||||46.3%| +|0826|Most Profit Assigning Work|[Go]({{< relref "/ChapterFour/0800~0899/0826.Most-Profit-Assigning-Work.md" >}})|Medium| O(n log n)| O(n)||44.9%| +|0832|Flipping an Image|[Go]({{< relref "/ChapterFour/0800~0899/0832.Flipping-an-Image.md" >}})|Easy||||80.8%| +|0838|Push Dominoes|[Go]({{< relref "/ChapterFour/0800~0899/0838.Push-Dominoes.md" >}})|Medium| O(n)| O(n)||57.0%| +|0844|Backspace String Compare|[Go]({{< relref "/ChapterFour/0800~0899/0844.Backspace-String-Compare.md" >}})|Easy| O(n)| O(n) ||48.1%| +|0845|Longest Mountain in Array|[Go]({{< relref "/ChapterFour/0800~0899/0845.Longest-Mountain-in-Array.md" >}})|Medium| O(n)| O(1) ||40.2%| +|0870|Advantage Shuffle|[Go]({{< relref "/ChapterFour/0800~0899/0870.Advantage-Shuffle.md" >}})|Medium||||51.8%| +|0876|Middle of the Linked List|[Go]({{< relref "/ChapterFour/0800~0899/0876.Middle-of-the-Linked-List.md" >}})|Easy||||75.6%| +|0881|Boats to Save People|[Go]({{< relref "/ChapterFour/0800~0899/0881.Boats-to-Save-People.md" >}})|Medium| O(n log n)| O(1) ||53.1%| +|0922|Sort Array By Parity II|[Go]({{< relref "/ChapterFour/0900~0999/0922.Sort-Array-By-Parity-II.md" >}})|Easy||||70.7%| +|0923|3Sum With Multiplicity|[Go]({{< relref "/ChapterFour/0900~0999/0923.3Sum-With-Multiplicity.md" >}})|Medium| O(n^2)| O(n) ||45.3%| +|0925|Long Pressed Name|[Go]({{< relref "/ChapterFour/0900~0999/0925.Long-Pressed-Name.md" >}})|Easy| O(n)| O(1)||33.1%| +|0942|DI String Match|[Go]({{< relref "/ChapterFour/0900~0999/0942.DI-String-Match.md" >}})|Easy||||77.3%| +|0969|Pancake Sorting|[Go]({{< relref "/ChapterFour/0900~0999/0969.Pancake-Sorting.md" >}})|Medium||||70.1%| +|0977|Squares of a Sorted Array|[Go]({{< relref "/ChapterFour/0900~0999/0977.Squares-of-a-Sorted-Array.md" >}})|Easy| O(n)| O(1)||71.9%| +|0986|Interval List Intersections|[Go]({{< relref "/ChapterFour/0900~0999/0986.Interval-List-Intersections.md" >}})|Medium| O(n)| O(1)||71.3%| +|1040|Moving Stones Until Consecutive II|[Go]({{< relref "/ChapterFour/1000~1099/1040.Moving-Stones-Until-Consecutive-II.md" >}})|Medium||||55.9%| +|1048|Longest String Chain|[Go]({{< relref "/ChapterFour/1000~1099/1048.Longest-String-Chain.md" >}})|Medium||||59.2%| +|1089|Duplicate Zeros|[Go]({{< relref "/ChapterFour/1000~1099/1089.Duplicate-Zeros.md" >}})|Easy||||51.5%| +|1332|Remove Palindromic Subsequences|[Go]({{< relref "/ChapterFour/1300~1399/1332.Remove-Palindromic-Subsequences.md" >}})|Easy||||76.2%| +|1385|Find the Distance Value Between Two Arrays|[Go]({{< relref "/ChapterFour/1300~1399/1385.Find-the-Distance-Value-Between-Two-Arrays.md" >}})|Easy||||66.5%| +|1679|Max Number of K-Sum Pairs|[Go]({{< relref "/ChapterFour/1600~1699/1679.Max-Number-of-K-Sum-Pairs.md" >}})|Medium||||57.3%| +|1721|Swapping Nodes in a Linked List|[Go]({{< relref "/ChapterFour/1700~1799/1721.Swapping-Nodes-in-a-Linked-List.md" >}})|Medium||||67.2%| +|1877|Minimize Maximum Pair Sum in Array|[Go]({{< relref "/ChapterFour/1800~1899/1877.Minimize-Maximum-Pair-Sum-in-Array.md" >}})|Medium||||79.9%| |------------|-------------------------------------------------------|-------| ----------------| ---------------|-------------|-------------|-------------| - ----------------------------------------------

⬅️上一页

diff --git a/website/content/ChapterTwo/Union_Find.md b/website/content/ChapterTwo/Union_Find.md index 482b5f578..391edabe5 100644 --- a/website/content/ChapterTwo/Union_Find.md +++ b/website/content/ChapterTwo/Union_Find.md @@ -19,28 +19,32 @@ weight: 16 | No. | Title | Solution | Difficulty | TimeComplexity | SpaceComplexity |Favorite| Acceptance | |:--------:|:------- | :--------: | :----------: | :----: | :-----: | :-----: |:-----: | -|0128|Longest Consecutive Sequence|[Go]({{< relref "/ChapterFour/0100~0199/0128.Longest-Consecutive-Sequence.md" >}})|Hard| O(n)| O(n)|❤️|46.6%| -|0130|Surrounded Regions|[Go]({{< relref "/ChapterFour/0100~0199/0130.Surrounded-Regions.md" >}})|Medium| O(m\*n)| O(m\*n)||29.9%| -|0200|Number of Islands|[Go]({{< relref "/ChapterFour/0200~0299/0200.Number-of-Islands.md" >}})|Medium| O(m\*n)| O(m\*n)||49.7%| -|0399|Evaluate Division|[Go]({{< relref "/ChapterFour/0300~0399/0399.Evaluate-Division.md" >}})|Medium| O(n)| O(n)||54.7%| -|0547|Number of Provinces|[Go]({{< relref "/ChapterFour/0500~0599/0547.Number-of-Provinces.md" >}})|Medium| O(n^2)| O(n)||60.9%| -|0684|Redundant Connection|[Go]({{< relref "/ChapterFour/0600~0699/0684.Redundant-Connection.md" >}})|Medium| O(n)| O(n)||59.2%| -|0685|Redundant Connection II|[Go]({{< relref "/ChapterFour/0600~0699/0685.Redundant-Connection-II.md" >}})|Hard| O(n)| O(n)||33.2%| -|0721|Accounts Merge|[Go]({{< relref "/ChapterFour/0700~0799/0721.Accounts-Merge.md" >}})|Medium| O(n)| O(n)|❤️|52.5%| -|0765|Couples Holding Hands|[Go]({{< relref "/ChapterFour/0700~0799/0765.Couples-Holding-Hands.md" >}})|Hard| O(n)| O(n)|❤️|55.6%| -|0778|Swim in Rising Water|[Go]({{< relref "/ChapterFour/0700~0799/0778.Swim-in-Rising-Water.md" >}})|Hard| O(n^2)| O(n)|❤️|55.1%| -|0803|Bricks Falling When Hit|[Go]({{< relref "/ChapterFour/0800~0899/0803.Bricks-Falling-When-Hit.md" >}})|Hard| O(n^2)| O(n)|❤️|32.0%| -|0839|Similar String Groups|[Go]({{< relref "/ChapterFour/0800~0899/0839.Similar-String-Groups.md" >}})|Hard| O(n^2)| O(n)||41.8%| -|0924|Minimize Malware Spread|[Go]({{< relref "/ChapterFour/0900~0999/0924.Minimize-Malware-Spread.md" >}})|Hard| O(m\*n)| O(n)||41.9%| -|0928|Minimize Malware Spread II|[Go]({{< relref "/ChapterFour/0900~0999/0928.Minimize-Malware-Spread-II.md" >}})|Hard| O(m\*n)| O(n)|❤️|41.5%| -|0947|Most Stones Removed with Same Row or Column|[Go]({{< relref "/ChapterFour/0900~0999/0947.Most-Stones-Removed-with-Same-Row-or-Column.md" >}})|Medium| O(n)| O(n)||55.7%| -|0952|Largest Component Size by Common Factor|[Go]({{< relref "/ChapterFour/0900~0999/0952.Largest-Component-Size-by-Common-Factor.md" >}})|Hard| O(n)| O(n)|❤️|36.5%| -|0959|Regions Cut By Slashes|[Go]({{< relref "/ChapterFour/0900~0999/0959.Regions-Cut-By-Slashes.md" >}})|Medium| O(n^2)| O(n^2)|❤️|67.2%| -|0990|Satisfiability of Equality Equations|[Go]({{< relref "/ChapterFour/0900~0999/0990.Satisfiability-of-Equality-Equations.md" >}})|Medium| O(n)| O(n)||47.2%| -|1202|Smallest String With Swaps|[Go]({{< relref "/ChapterFour/1200~1299/1202.Smallest-String-With-Swaps.md" >}})|Medium||||49.1%| -|1319|Number of Operations to Make Network Connected|[Go]({{< relref "/ChapterFour/1300~1399/1319.Number-of-Operations-to-Make-Network-Connected.md" >}})|Medium||||55.6%| -|1579|Remove Max Number of Edges to Keep Graph Fully Traversable|[Go]({{< relref "/ChapterFour/1500~1599/1579.Remove-Max-Number-of-Edges-to-Keep-Graph-Fully-Traversable.md" >}})|Hard||||46.4%| -|1631|Path With Minimum Effort|[Go]({{< relref "/ChapterFour/1600~1699/1631.Path-With-Minimum-Effort.md" >}})|Medium||||50.0%| +|0128|Longest Consecutive Sequence|[Go]({{< relref "/ChapterFour/0100~0199/0128.Longest-Consecutive-Sequence.md" >}})|Medium| O(n)| O(n)|❤️|48.5%| +|0130|Surrounded Regions|[Go]({{< relref "/ChapterFour/0100~0199/0130.Surrounded-Regions.md" >}})|Medium| O(m\*n)| O(m\*n)||36.7%| +|0200|Number of Islands|[Go]({{< relref "/ChapterFour/0200~0299/0200.Number-of-Islands.md" >}})|Medium| O(m\*n)| O(m\*n)||57.0%| +|0399|Evaluate Division|[Go]({{< relref "/ChapterFour/0300~0399/0399.Evaluate-Division.md" >}})|Medium| O(n)| O(n)||59.6%| +|0547|Number of Provinces|[Go]({{< relref "/ChapterFour/0500~0599/0547.Number-of-Provinces.md" >}})|Medium| O(n^2)| O(n)||63.7%| +|0684|Redundant Connection|[Go]({{< relref "/ChapterFour/0600~0699/0684.Redundant-Connection.md" >}})|Medium| O(n)| O(n)||62.2%| +|0685|Redundant Connection II|[Go]({{< relref "/ChapterFour/0600~0699/0685.Redundant-Connection-II.md" >}})|Hard| O(n)| O(n)||34.1%| +|0695|Max Area of Island|[Go]({{< relref "/ChapterFour/0600~0699/0695.Max-Area-of-Island.md" >}})|Medium||||71.8%| +|0721|Accounts Merge|[Go]({{< relref "/ChapterFour/0700~0799/0721.Accounts-Merge.md" >}})|Medium| O(n)| O(n)|❤️|56.3%| +|0765|Couples Holding Hands|[Go]({{< relref "/ChapterFour/0700~0799/0765.Couples-Holding-Hands.md" >}})|Hard| O(n)| O(n)|❤️|56.6%| +|0778|Swim in Rising Water|[Go]({{< relref "/ChapterFour/0700~0799/0778.Swim-in-Rising-Water.md" >}})|Hard| O(n^2)| O(n)|❤️|59.8%| +|0785|Is Graph Bipartite?|[Go]({{< relref "/ChapterFour/0700~0799/0785.Is-Graph-Bipartite.md" >}})|Medium||||53.1%| +|0803|Bricks Falling When Hit|[Go]({{< relref "/ChapterFour/0800~0899/0803.Bricks-Falling-When-Hit.md" >}})|Hard| O(n^2)| O(n)|❤️|34.4%| +|0839|Similar String Groups|[Go]({{< relref "/ChapterFour/0800~0899/0839.Similar-String-Groups.md" >}})|Hard| O(n^2)| O(n)||48.0%| +|0924|Minimize Malware Spread|[Go]({{< relref "/ChapterFour/0900~0999/0924.Minimize-Malware-Spread.md" >}})|Hard| O(m\*n)| O(n)||42.1%| +|0928|Minimize Malware Spread II|[Go]({{< relref "/ChapterFour/0900~0999/0928.Minimize-Malware-Spread-II.md" >}})|Hard| O(m\*n)| O(n)|❤️|42.7%| +|0947|Most Stones Removed with Same Row or Column|[Go]({{< relref "/ChapterFour/0900~0999/0947.Most-Stones-Removed-with-Same-Row-or-Column.md" >}})|Medium| O(n)| O(n)||58.9%| +|0952|Largest Component Size by Common Factor|[Go]({{< relref "/ChapterFour/0900~0999/0952.Largest-Component-Size-by-Common-Factor.md" >}})|Hard| O(n)| O(n)|❤️|40.0%| +|0959|Regions Cut By Slashes|[Go]({{< relref "/ChapterFour/0900~0999/0959.Regions-Cut-By-Slashes.md" >}})|Medium| O(n^2)| O(n^2)|❤️|69.1%| +|0990|Satisfiability of Equality Equations|[Go]({{< relref "/ChapterFour/0900~0999/0990.Satisfiability-of-Equality-Equations.md" >}})|Medium| O(n)| O(n)||50.5%| +|1020|Number of Enclaves|[Go]({{< relref "/ChapterFour/1000~1099/1020.Number-of-Enclaves.md" >}})|Medium||||65.5%| +|1202|Smallest String With Swaps|[Go]({{< relref "/ChapterFour/1200~1299/1202.Smallest-String-With-Swaps.md" >}})|Medium||||57.7%| +|1254|Number of Closed Islands|[Go]({{< relref "/ChapterFour/1200~1299/1254.Number-of-Closed-Islands.md" >}})|Medium||||64.1%| +|1319|Number of Operations to Make Network Connected|[Go]({{< relref "/ChapterFour/1300~1399/1319.Number-of-Operations-to-Make-Network-Connected.md" >}})|Medium||||62.1%| +|1579|Remove Max Number of Edges to Keep Graph Fully Traversable|[Go]({{< relref "/ChapterFour/1500~1599/1579.Remove-Max-Number-of-Edges-to-Keep-Graph-Fully-Traversable.md" >}})|Hard||||53.2%| +|1631|Path With Minimum Effort|[Go]({{< relref "/ChapterFour/1600~1699/1631.Path-With-Minimum-Effort.md" >}})|Medium||||55.7%| |------------|-------------------------------------------------------|-------| ----------------| ---------------|-------------|-------------|-------------| diff --git a/website/content/ChapterTwo/_index.md b/website/content/ChapterTwo/_index.md index af78a6c3e..6aa84542e 100644 --- a/website/content/ChapterTwo/_index.md +++ b/website/content/ChapterTwo/_index.md @@ -24,6 +24,6 @@ weight: 2 ---------------------------------------------- diff --git a/website/content/_index.md b/website/content/_index.md index e9a44e0b5..50500e868 100644 --- a/website/content/_index.md +++ b/website/content/_index.md @@ -34,7 +34,7 @@ type: docs ## 关于作者 -笔者是一个刚刚入行一年半的 gopher 新人，还请各位大佬多多指点小弟我。大学参加了 3 年 ACM-ICPC，但是由于资质不高，没有拿到一块金牌。所以在算法方面，我对自己的评价算是新手吧。参加 ACM-ICPC 最大的收获是训练了思维能力，这种能力也会运用到生活中。其次是认识了很多国内很聪明的选手，看到了自己和他们的差距。最后，就是那 200 多页，有些自己都没有完全理解的，打印的密密麻麻的[算法模板](https://github.com/halfrost/LeetCode-Go/releases/tag/Special)。知识学会了，终身都是自己的，没有学会，那些知识都是身外之物。 +笔者是一个刚刚入行一年半的 gopher 新人，还请各位大佬多多指点小弟我。大学参加了 3 年 ACM-ICPC，但是由于资质不高，没有拿到一块金牌。所以在算法方面，我对自己的评价算是新手吧。参加 ACM-ICPC 最大的收获是训练了思维能力，这种能力也会运用到生活中。其次是认识了很多国内很聪明的选手，看到了自己和他们的差距。最后，就是那 200 多页，有些自己都没有完全理解的，打印的密密麻麻的[算法模板](https://github.com/halfrost/leetcode-go/releases/tag/Special)。知识学会了，终身都是自己的，没有学会，那些知识都是身外之物。 笔者从 2019 年 3 月 25 号开始刷题，到 2020 年 3 月 25 号，整整一年的时间。原计划是每天一题。实际上每天有时候不止一题，最终完成了 600+： @@ -48,7 +48,7 @@ type: docs ## 关于书中的代码 -代码都放在 [github repo](https://github.com/halfrost/LeetCode-Go/tree/master/leetcode) 中，按题号可以搜索到题目。 +代码都放在 [github repo](https://github.com/halfrost/leetcode-go/tree/master/leetcode) 中，按题号可以搜索到题目。 本书题目的代码都已经 beats 100% 了。没有 beats 100% 题解就没有放到本书中了。那些题目笔者会继续优化到 100% 再放进来。 有可能读者会问，为何要追求 beats 100%。笔者认为优化到 beats 100% 才算是把这题做出感觉了。有好几道 Hard 题，笔者都用暴力解法 AC 了，然后只 beats 了 5%。这题就如同没做一样。而且面试中如果给了这样的答案，面试官也不会满意，“还有没有更优解？”。如果通过自己的思考能给出更优解，面试官会更满意一些。 diff --git a/website/resources/_gen/assets/scss/leetcode/book.scss_50fc8c04e12a2f59027287995557ceff.content b/website/resources/_gen/assets/scss/leetcode/book.scss_50fc8c04e12a2f59027287995557ceff.content index fca253c6d..a30d53838 100644 --- a/website/resources/_gen/assets/scss/leetcode/book.scss_50fc8c04e12a2f59027287995557ceff.content +++ b/website/resources/_gen/assets/scss/leetcode/book.scss_50fc8c04e12a2f59027287995557ceff.content @@ -1 +1 @@ -:root{--gray-100: #f8f9fa;--gray-200: #e9ecef;--gray-500: #adb5bd;--color-link: #0055bb;--color-visited-link: #8440f1;--body-background: white;--body-font-color: black;--icon-filter: none;--hint-color-info: #6bf;--hint-color-warning: #fd6;--hint-color-danger: #f66}/*!normalize.css v8.0.1 | MIT License | 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.book-expand input[type=checkbox]:checked+.book-expand-content{display:block}.markdown .book-tabs{margin-top:1rem;margin-bottom:1rem;border:1px solid var(--gray-200);border-radius:.25rem;overflow:hidden;display:flex;flex-wrap:wrap}.markdown .book-tabs label{display:inline-block;padding:.5rem 1rem;border-bottom:1px transparent;cursor:pointer}.markdown .book-tabs .book-tabs-content{order:999;width:100%;border-top:1px solid var(--gray-100);padding:1rem;display:none}.markdown .book-tabs input[type=radio]:checked+label{border-bottom:1px solid var(--color-link)}.markdown .book-tabs input[type=radio]:checked+label+.book-tabs-content{display:block}.markdown .book-tabs input[type=radio]:focus+label{outline-style:auto;outline-color:currentColor;outline-color:-webkit-focus-ring-color}.markdown .book-columns{margin-left:-1rem;margin-right:-1rem}.markdown .book-columns>div{margin:1rem 0;min-width:10rem;padding:0 1rem}.markdown a.book-btn{display:inline-block;font-size:.875rem;color:var(--color-link);line-height:2rem;padding:0 1rem;border:1px solid var(--color-link);border-radius:.25rem;cursor:pointer}.markdown a.book-btn:hover{text-decoration:none}.markdown .book-hint.info{border-color:#6bf;background-color:rgba(102,187,255,.1)}.markdown .book-hint.warning{border-color:#fd6;background-color:rgba(255,221,102,.1)}.markdown .book-hint.danger{border-color:#f66;background-color:rgba(255,102,102,.1)}.js-toggle-wrapper{display:table;margin:1rem 0 0 5px;flex:1}.js-toggle{touch-action:pan-x;display:inline-block;position:relative;cursor:pointer;background-color:transparent;border:0;padding:0;-webkit-touch-callout:none;user-select:none;-webkit-tap-highlight-color:transparent;-webkit-tap-highlight-color:transparent}.js-toggle-screenreader-only{border:0;clip:rect(0 0 0 0);height:1px;margin:-1px;overflow:hidden;padding:0;position:absolute;width:1px}.js-toggle-track{width:60px;height:34px;padding:0;transition:all .2s ease}.js-toggle-track-check{position:absolute;width:17px;height:17px;left:5px;top:0;bottom:0;margin-top:auto;margin-bottom:auto;line-height:0;opacity:0;transition:opacity .25s ease}.js-toggle--checked .js-toggle-track-check{opacity:1;transition:opacity .25s ease}.js-toggle-track-x{position:absolute;width:17px;height:17px;right:5px;top:0;bottom:0;margin-top:auto;margin-bottom:auto;line-height:0;opacity:1;transition:opacity .25s ease}.js-toggle--checked .js-toggle-track-x{opacity:0}.js-toggle-thumb{position:absolute;top:1px;left:1px;width:30px;height:32px;box-sizing:border-box;transition:all .5s cubic-bezier(0.23,1,0.32,1)0ms;transform:translateX(0)}.js-toggle--checked .js-toggle-thumb{transform:translateX(26px);border-color:#19ab27}.magic{display:flex}body.dark-mode,body.dark-mode main *{background:#2d2d2d;color:#f5f5f5}[data-theme=dark]{--gray-100: rgba(255, 255, 255, 0.1);--gray-200: rgba(255, 255, 255, 0.2);--body-background: #343a40;--body-font-color: #e9ecef;--color-link: #84b2ff;--color-visited-link: #b88dff;--icon-filter: brightness(0) invert(1)}[data-theme=light]{--gray-100: #f8f9fa;--gray-200: #e9ecef;--body-background: white;--body-font-color: black;--color-link: #05b;--color-visited-link: #8440f1;--icon-filter: none} \ No newline at end of file diff --git a/website/resources/_gen/assets/scss/leetcode/book.scss_50fc8c04e12a2f59027287995557ceff.json b/website/resources/_gen/assets/scss/leetcode/book.scss_50fc8c04e12a2f59027287995557ceff.json index 1f6f11ebf..7a885da44 100644 --- a/website/resources/_gen/assets/scss/leetcode/book.scss_50fc8c04e12a2f59027287995557ceff.json +++ b/website/resources/_gen/assets/scss/leetcode/book.scss_50fc8c04e12a2f59027287995557ceff.json @@ -1 +1 @@ -{"Target":"book.min.52cf8c29cd59421d82760763db0286dd4a257c2c1b4d56b6edd110938a13a18a.css","MediaType":"text/css","Data":{"Integrity":"sha256-Us+MKc1ZQh2Cdgdj2wKG3UolfCwbTVa27dEQk4oToYo="}} \ No newline at end of file +{"Target":"book.min.fcdb1f07040371dc4d234f40698d15b7fb50f2dc9982bcd0898d9806ff4e07f8.css","MediaType":"text/css","Data":{"Integrity":"sha256-/NsfBwQDcdxNI09AaY0Vt/tQ8tyZgrzQiY2YBv9OB/g="}} \ No newline at end of file diff --git a/website/themes/book/README.md b/website/themes/book/README.md index fc2f078e5..052730c5d 100644 --- a/website/themes/book/README.md +++ b/website/themes/book/README.md @@ -163,6 +163,13 @@ disableKinds = ['taxonomy', 'taxonomyTerm'] # Set source repository location. # Used for 'Last Modified' and 'Edit this page' links. BookRepo = 'https://github.com/alex-shpak/hugo-book' + + # Specifies commit portion of the link to the page's last modified commit hash for 'doc' page + # type. + # Required if 'BookRepo' param is set. + # Value used to construct a URL consisting of BookRepo/BookCommitPath/ + # Github uses 'commit', Bitbucket uses 'commits' + BookCommitPath = 'commit' # Enable 'Edit this page' links for 'doc' page type. # Disabled by default. Uncomment to enable. Requires 'BookRepo' param. @@ -254,6 +261,7 @@ There are few empty partials you can override in `layouts/partials/` | `assets/_custom.scss` | Customise or override scss styles | | `assets/_variables.scss` | Override default SCSS variables | | `assets/_fonts.scss` | Replace default font with custom fonts (e.g. local files or remote like google fonts) | +| `assets/mermaid.json` | Replace Mermaid initialization config | ### Plugins diff --git a/website/themes/book/assets/_main.scss b/website/themes/book/assets/_main.scss index 6c044cb54..7085e3648 100644 --- a/website/themes/book/assets/_main.scss +++ b/website/themes/book/assets/_main.scss @@ -125,6 +125,14 @@ ul.pagination { input.toggle:checked + label + ul { display: block; } + + input.toggle + label::after { + content: "▸"; + } + + input.toggle:checked + label::after { + content: "▾"; + } } .book-section-flat { @@ -206,7 +214,7 @@ ul.pagination { } .book-toc { - flex: 0 0 $toc-width; + // flex: 0 0 $toc-width; // 使 toc 靠右贴边 font-size: $font-size-12; .book-toc-content { diff --git a/website/themes/book/assets/plugins/_scrollbars.scss b/website/themes/book/assets/plugins/_scrollbars.scss index fb465439b..00625827b 100644 --- a/website/themes/book/assets/plugins/_scrollbars.scss +++ b/website/themes/book/assets/plugins/_scrollbars.scss @@ -12,15 +12,15 @@ } :hover::-webkit-scrollbar-thumb { - background: $gray-500; + background: var(--gray-500); } // MS body { - -ms-overflow-style: -ms-autohiding-scrollbar + -ms-overflow-style: -ms-autohiding-scrollbar; } // Future .book-menu nav { - scrollbar-color: transparent $gray-500; + scrollbar-color: transparent var(--gray-500); } diff --git a/website/themes/book/exampleSite/config.toml b/website/themes/book/exampleSite/config.toml index 165bc1051..dfd9a31cc 100644 --- a/website/themes/book/exampleSite/config.toml +++ b/website/themes/book/exampleSite/config.toml @@ -75,10 +75,17 @@ enableGitInfo = true # Used for 'Last Modified' and 'Edit this page' links. BookRepo = 'https://github.com/alex-shpak/hugo-book' + # (Optional, default 'commit') Specifies commit portion of the link to the page's last modified + # commit hash for 'doc' page type. + # Requires 'BookRepo' param. + # Value used to construct a URL consisting of BookRepo/BookCommitPath/ + # Github uses 'commit', Bitbucket uses 'commits' + # BookCommitPath = 'commit' + # Enable "Edit this page" links for 'doc' page type. # Disabled by default. Uncomment to enable. Requires 'BookRepo' param. # Edit path must point to root directory of repo. - BookEditPath = 'edit/master/exampleSite' + BookEditPath = 'edit/main/exampleSite' # Configure the date format used on the pages # - In git information @@ -108,4 +115,4 @@ enableGitInfo = true # /!\ This is an experimental feature, might be removed or changed at any time # (Optional, experimental, default false) Enables a drop-down menu for translations only if a translation is present. - BookTranslatedOnly = true + BookTranslatedOnly = false diff --git a/website/themes/book/exampleSite/config.yaml b/website/themes/book/exampleSite/config.yaml index 4d582bc64..4f439c689 100644 --- a/website/themes/book/exampleSite/config.yaml +++ b/website/themes/book/exampleSite/config.yaml @@ -71,10 +71,17 @@ params: # Used for 'Last Modified' and 'Edit this page' links. BookRepo: https://github.com/alex-shpak/hugo-book + # (Optional, default 'commit') Specifies commit portion of the link to the page's last modified + # commit hash for 'doc' page type. + # Requires 'BookRepo' param. + # Value used to construct a URL consisting of BookRepo/BookCommitPath/ + # Github uses 'commit', Bitbucket uses 'commits' + # BookCommitPath: commit + # Enable "Edit this page" links for 'doc' page type. # Disabled by default. Uncomment to enable. Requires 'BookRepo' param. # Edit path must point to root directory of repo. - BookEditPath: edit/master/exampleSite + BookEditPath: edit/main/exampleSite # Configure the date format used on the pages # - In git information @@ -104,4 +111,4 @@ params: # /!\ This is an experimental feature, might be removed or changed at any time # (Optional, experimental, default false) Enables a drop-down menu for translations only if a translation is present. - BookTranslatedOnly: true + BookTranslatedOnly: false diff --git a/website/themes/book/exampleSite/content.bn/_index.md b/website/themes/book/exampleSite/content.bn/_index.md new file mode 100644 index 000000000..85c03e006 --- /dev/null +++ b/website/themes/book/exampleSite/content.bn/_index.md @@ -0,0 +1,79 @@ +--- +title: ভূমিকা +type: docs +--- + +# বাংলা ভাষায় শুরু করুন + +{{< columns >}} +## অস্ট্রিস চিপসে ফুর্তিভা + +Est in vagis et Pittheus tu arge accipiter regia iram vocatur nurus. Omnes ut +olivae sensit **arma sorori** deducit, inesset **crudus**, ego vetuere aliis, +modo arsit? Utinam rapta fiducia valuere litora _adicit cursu_, ad facies + +<---> + +## সুইস কোটা ভোটে + +Ea _furtique_ risere fratres edidit terrae magis. Colla tam mihi tenebat: +miseram excita suadent es pecudes iam. Concilio _quam_ velatus posset ait quod +nunc! Fragosis suae dextra geruntur functus vulgata. +{{< /columns >}} + + +## টেম্পোরার নিশি + +Lorem **markdownum** emicat gestu. Cannis sol pressit ducta. **Est** Idaei, +tremens ausim se tutaeque, illi ulnis hausit, sed, lumina cutem. Quae avis +sequens! + + var panel = ram_design; + if (backup + system) { + file.readPoint = network_native; + sidebar_engine_device(cell_tftp_raster, + dual_login_paper.adf_vci.application_reader_design( + graphicsNvramCdma, lpi_footer_snmp, integer_model)); + } + public_keyboard_docking += error.controller_gibibyte_plug.ip(4, + asciiPetaflops, software(supercomputer_compatible_status + 4)); + dynamic_disk.indexModeLaptop = bufferTftpReality; + var export_vlog_sequence = trinitron_flowchart + supercomputer_cluster_rj( + -1, toolbar_powerpoint_query, -2 / multiprocessing_impression); + +## Locis suis novi cum suoque decidit eadem + +Idmoniae ripis, at aves, ali missa adest, ut _et autem_, et ab? Venit spes +versus finis sermonibus patefecit murum nec est sine oculis. _Ille_ inmota +macies domoque caelestia cadit tantummodo scelus procul, corde! + +1. Dolentem capi parte rostro alvum habentem pudor +2. Fulgentia sanguine paret +3. E punior consurgit lentus +4. Vox hasta eras micantes + +## Facibus pharetrae indetonsusque indulsit sic incurrite foliis + +Nefandam et prisci palmas! Blandita cutis flectitur montis macies, te _nati_ +Latiis; turbaque inferias. Virginis tibi peracta avidusque facies caper nec, e +at ademptae, mira. + + direct *= font(inputScareware(sliHome), crossplatform.byte( + ppl_encryption.excel_e_rte(integratedModelModifier), timeVirtual, + floating_speakers.media_printer(us, yahoo, primaryPhp))); + friendly_metal_flatbed(cd, isoPrimaryStorage(reader), dmaMirrored); + if (parse_flash_cron.metalGif(1, adServiceDevice, utility)) { + adf -= operation_cdma_samba; + imapGif.switch += torrent; + } else { + pmu.disk_captcha = digital_ppp_pci + recursionTransistor(5, dram); + ajax_service += grayscalePythonLock; + google_scroll_capacity = ftp + engine_dslam_sidebar / tape - 1; + } + drive_rw = zipTftp; + var suffix = software_router_extension.dimm_ddr(-5, + kernel_digital_minisite); + +Vocavit toto; alas **mitis** maestus in liquidarum ab legi finitimosque dominam +tibi subitus; Orionis vertitur nota. Currere alti etiam seroque cernitis +innumeris miraturus amplectique collo sustinet quemque! Litora ante turba? diff --git a/website/themes/book/exampleSite/content/docs/shortcodes/mermaid.md b/website/themes/book/exampleSite/content/docs/shortcodes/mermaid.md index 3a617bcc0..c37e6b20e 100644 --- a/website/themes/book/exampleSite/content/docs/shortcodes/mermaid.md +++ b/website/themes/book/exampleSite/content/docs/shortcodes/mermaid.md @@ -2,6 +2,13 @@ [Mermaid](https://mermaidjs.github.io/) is library for generating svg charts and diagrams from text. +{{< hint info >}} +**Override Mermaid Initialization Config** + +To override the [initialization config](https://mermaid-js.github.io/mermaid/#/Setup) for Mermaid, +create a `mermaid.json` file in your `assets` folder! +{{< /hint >}} + ## Example {{< columns >}} @@ -36,3 +43,4 @@ sequenceDiagram {{< /mermaid >}} {{< /columns >}} + diff --git a/website/themes/book/exampleSite/resources/_gen/assets/scss/book.scss_50fc8c04e12a2f59027287995557ceff.content b/website/themes/book/exampleSite/resources/_gen/assets/scss/book.scss_50fc8c04e12a2f59027287995557ceff.content index fe47da816..d6ea2eecc 100644 --- a/website/themes/book/exampleSite/resources/_gen/assets/scss/book.scss_50fc8c04e12a2f59027287995557ceff.content +++ b/website/themes/book/exampleSite/resources/_gen/assets/scss/book.scss_50fc8c04e12a2f59027287995557ceff.content @@ -1 +1 @@ -:root{--gray-100: #f8f9fa;--gray-200: #e9ecef;--gray-500: #adb5bd;--color-link: #0055bb;--color-visited-link: #8440f1;--body-background: white;--body-font-color: black;--icon-filter: none;--hint-color-info: #6bf;--hint-color-warning: #fd6;--hint-color-danger: #f66}/*!normalize.css v8.0.1 | MIT License | github.com/necolas/normalize.css*/html{line-height:1.15;-webkit-text-size-adjust:100%}body{margin:0}main{display:block}h1{font-size:2em;margin:.67em 0}hr{box-sizing:content-box;height:0;overflow:visible}pre{font-family:monospace,monospace;font-size:1em}a{background-color:transparent}abbr[title]{border-bottom:none;text-decoration:underline;text-decoration:underline dotted}b,strong{font-weight:bolder}code,kbd,samp{font-family:monospace,monospace;font-size:1em}small{font-size:80%}sub,sup{font-size:75%;line-height:0;position:relative;vertical-align:baseline}sub{bottom:-.25em}sup{top:-.5em}img{border-style:none}button,input,optgroup,select,textarea{font-family:inherit;font-size:100%;line-height:1.15;margin:0}button,input{overflow:visible}button,select{text-transform:none}button,[type=button],[type=reset],[type=submit]{-webkit-appearance:button}button::-moz-focus-inner,[type=button]::-moz-focus-inner,[type=reset]::-moz-focus-inner,[type=submit]::-moz-focus-inner{border-style:none;padding:0}button:-moz-focusring,[type=button]:-moz-focusring,[type=reset]:-moz-focusring,[type=submit]:-moz-focusring{outline:1px dotted ButtonText}fieldset{padding:.35em .75em .625em}legend{box-sizing:border-box;color:inherit;display:table;max-width:100%;padding:0;white-space:normal}progress{vertical-align:baseline}textarea{overflow:auto}[type=checkbox],[type=radio]{box-sizing:border-box;padding:0}[type=number]::-webkit-inner-spin-button,[type=number]::-webkit-outer-spin-button{height:auto}[type=search]{-webkit-appearance:textfield;outline-offset:-2px}[type=search]::-webkit-search-decoration{-webkit-appearance:none}::-webkit-file-upload-button{-webkit-appearance:button;font:inherit}details{display:block}summary{display:list-item}template{display:none}[hidden]{display:none}.flex{display:flex}.flex-auto{flex:1 1 auto}.flex-even{flex:1 1}.flex-wrap{flex-wrap:wrap}.justify-start{justify-content:flex-start}.justify-end{justify-content:flex-end}.justify-center{justify-content:center}.justify-between{justify-content:space-between}.align-center{align-items:center}.mx-auto{margin:0 auto}.text-center{text-align:center}.text-left{text-align:left}.text-right{text-align:right}.hidden{display:none}input.toggle{height:0;width:0;overflow:hidden;opacity:0;position:absolute}.clearfix::after{content:"";display:table;clear:both}html{font-size:16px;scroll-behavior:smooth;touch-action:manipulation}body{min-width:20rem;color:var(--body-font-color);background:var(--body-background);letter-spacing:.33px;font-weight:400;text-rendering:optimizeLegibility;-webkit-font-smoothing:antialiased;-moz-osx-font-smoothing:grayscale;box-sizing:border-box}body *{box-sizing:inherit}h1,h2,h3,h4,h5{font-weight:400}a{text-decoration:none;color:var(--color-link)}img{vertical-align:baseline}:focus{outline-style:auto;outline-color:currentColor;outline-color:-webkit-focus-ring-color}aside nav ul{padding:0;margin:0;list-style:none}aside nav ul li{margin:1em 0;position:relative}aside nav ul a{display:block}aside nav ul a:hover{opacity:.5}aside nav ul ul{padding-inline-start:1rem}ul.pagination{display:flex;justify-content:center;list-style-type:none}ul.pagination .page-item a{padding:1rem}.container{max-width:80rem;margin:0 auto}.book-icon{filter:var(--icon-filter)}.book-brand{margin-top:0}.book-brand img{height:1.5em;width:auto;vertical-align:middle;margin-inline-end:.5rem}.book-menu{flex:0 0 16rem;font-size:.875rem}.book-menu .book-menu-content{width:16rem;padding:1rem;background:var(--body-background);position:fixed;top:0;bottom:0;overflow-x:hidden;overflow-y:auto}.book-menu a,.book-menu label{color:inherit;cursor:pointer;word-wrap:break-word}.book-menu a.active{color:var(--color-link)}.book-menu input.toggle+label+ul{display:none}.book-menu input.toggle:checked+label+ul{display:block}.book-section-flat{margin-bottom:2rem}.book-section-flat:not(:first-child){margin-top:2rem}.book-section-flat>a,.book-section-flat>span,.book-section-flat>label{font-weight:bolder}.book-section-flat>ul{padding-inline-start:0}.book-page{min-width:20rem;flex-grow:1;padding:1rem}.book-post{margin-bottom:3rem}.book-header{display:none;margin-bottom:1rem}.book-header label{line-height:0}.book-search{position:relative;margin:1rem 0;border-bottom:1px solid transparent}.book-search input{width:100%;padding:.5rem;border:0;border-radius:.25rem;background:var(--gray-100);color:var(--body-font-color)}.book-search input:required+.book-search-spinner{display:block}.book-search .book-search-spinner{position:absolute;top:0;margin:.5rem;margin-inline-start:calc(100% - 1.5rem);width:1rem;height:1rem;border:1px solid transparent;border-top-color:var(--body-font-color);border-radius:50%;animation:spin 1s ease infinite}@keyframes spin{100%{transform:rotate(360deg)}}.book-search small{opacity:.5}.book-toc{flex:0 0 16rem;font-size:.75rem}.book-toc .book-toc-content{width:16rem;padding:1rem;position:fixed;top:0;bottom:0;overflow-x:hidden;overflow-y:auto}.book-toc img{height:1em}.book-toc nav>ul>li:first-child{margin-top:0}.book-footer{padding-top:1rem;font-size:.875rem}.book-footer img{height:1em;margin-inline-end:.5rem}.book-comments{margin-top:1rem}.book-languages{position:relative;overflow:visible;padding:1rem;margin:-1rem}.book-languages ul{margin:0;padding:0;list-style:none}.book-languages ul li{white-space:nowrap;cursor:pointer}.book-languages:hover .book-languages-list,.book-languages:focus .book-languages-list,.book-languages:focus-within .book-languages-list{display:block}.book-languages .book-languages-list{display:none;position:absolute;bottom:100%;left:0;padding:.5rem 0;background:var(--body-background);box-shadow:0 0 .25rem rgba(0,0,0,.1)}.book-languages .book-languages-list li 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+1 @@ -{"Target":"book.min.6c7c6446dfdee7c8c933e9bbc6e80ee3ed6c913b2a59519f2092c3c6a9d63e55.css","MediaType":"text/css","Data":{"Integrity":"sha256-bHxkRt/e58jJM+m7xugO4+1skTsqWVGfIJLDxqnWPlU="}} \ No newline at end of file +{"Target":"book.min.5ac6c2989f0943405962be6800b442aef429ef26ade26545ecf0617a21d1197a.css","MediaType":"text/css","Data":{"Integrity":"sha256-WsbCmJ8JQ0BZYr5oALRCrvQp7yat4mVF7PBheiHRGXo="}} \ No newline at end of file diff --git a/website/themes/book/exampleSite/resources/_gen/assets/scss/example/book.scss_50fc8c04e12a2f59027287995557ceff.content b/website/themes/book/exampleSite/resources/_gen/assets/scss/example/book.scss_50fc8c04e12a2f59027287995557ceff.content deleted file mode 100644 index 33ab91412..000000000 --- a/website/themes/book/exampleSite/resources/_gen/assets/scss/example/book.scss_50fc8c04e12a2f59027287995557ceff.content +++ /dev/null @@ -1 +0,0 @@ -@charset "UTF-8";/*!normalize.css v8.0.1 | MIT License | 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a.book-btn{display:inline-block;font-size:.875rem;color:#05b;line-height:2rem;padding:0 1rem;border:1px solid #05b;border-radius:.25rem;cursor:pointer}.markdown a.book-btn:hover{text-decoration:none}.markdown .book-hint.info{border-left-color:#6bf;background-color:rgba(102,187,255,.1)}.markdown .book-hint.warning{border-left-color:#fd6;background-color:rgba(255,221,102,.1)}.markdown .book-hint.danger{border-left-color:#f66;background-color:rgba(255,102,102,.1)} \ No newline at end of file diff --git a/website/themes/book/exampleSite/resources/_gen/assets/scss/example/book.scss_50fc8c04e12a2f59027287995557ceff.json b/website/themes/book/exampleSite/resources/_gen/assets/scss/example/book.scss_50fc8c04e12a2f59027287995557ceff.json deleted file mode 100644 index 293c3d66a..000000000 --- a/website/themes/book/exampleSite/resources/_gen/assets/scss/example/book.scss_50fc8c04e12a2f59027287995557ceff.json +++ /dev/null @@ -1 +0,0 @@ -{"Target":"book.min.284c8fc21ced13c579d9027a9d14893c56b243c6045001180391cebb4cc36ab8.css","MediaType":"text/css","Data":{"Integrity":"sha256-KEyPwhztE8V52QJ6nRSJPFayQ8YEUAEYA5HOu0zDarg="}} \ No newline at end of file diff --git a/website/themes/book/i18n/bn.yaml b/website/themes/book/i18n/bn.yaml new file mode 100644 index 000000000..853b72745 --- /dev/null +++ b/website/themes/book/i18n/bn.yaml @@ -0,0 +1,14 @@ +- id: Search + translation: অনুসন্ধান + +- id: Edit this page + translation: এই পৃষ্ঠাটি সম্পাদনা করুন + +- id: Last modified by + translation: সর্বশেষ সম্পাদনা করেছেন + +- id: Expand + translation: বিস্তৃত করা + +- id: bookSearchConfig + translation: '{ cache: true }' diff --git a/website/themes/book/i18n/zh-TW.yaml b/website/themes/book/i18n/zh-TW.yaml new file mode 100644 index 000000000..7ed7f3af5 --- /dev/null +++ b/website/themes/book/i18n/zh-TW.yaml @@ -0,0 +1,20 @@ +- id: Search + translation: 搜索 + +- id: Edit this page + translation: 編輯頁面 + +- id: Last modified by + translation: 最後修改者 + +- id: Expand + translation: 展開 + +- id: bookSearchConfig + translation: | + { + encode: false, + tokenize: function(str) { + return str.replace(/[\x00-\x7F]/g, '').split(''); + } + } diff --git a/website/themes/book/layouts/_default/baseof.html b/website/themes/book/layouts/_default/baseof.html index cf2065de2..b30c0bee4 100644 --- a/website/themes/book/layouts/_default/baseof.html +++ b/website/themes/book/layouts/_default/baseof.html @@ -1,5 +1,5 @@ - + {{ hugo.Generator }} @@ -7,7 +7,7 @@ {{ partial "docs/inject/head" . }} - + diff --git a/website/themes/book/layouts/partials/docs/footer.html b/website/themes/book/layouts/partials/docs/footer.html index afffc2495..b506f18c5 100644 --- a/website/themes/book/layouts/partials/docs/footer.html +++ b/website/themes/book/layouts/partials/docs/footer.html @@ -6,7 +6,8 @@ {{ if and .GitInfo .Site.Params.BookRepo }}
{{- $date := partial "docs/date" (dict "Date" .GitInfo.AuthorDate.Local "Format" .Site.Params.BookDateFormat) -}} - + {{- $commitPath := default "commit" .Site.Params.BookCommitPath -}} + Calendar {{ $date }} @@ -15,7 +16,7 @@ {{ if and .File .Site.Params.BookRepo .Site.Params.BookEditPath }}
- + Edit {{ i18n "Edit this page" }} diff --git a/website/themes/book/layouts/partials/docs/menu-filetree.html b/website/themes/book/layouts/partials/docs/menu-filetree.html index 3ca9db215..a4835b214 100644 --- a/website/themes/book/layouts/partials/docs/menu-filetree.html +++ b/website/themes/book/layouts/partials/docs/menu-filetree.html @@ -34,7 +34,6 @@ {{- partial "docs/title" .Page -}} - ▾ {{ else if .Page.Content }} diff --git a/website/themes/book/layouts/partials/docs/post-meta.html b/website/themes/book/layouts/partials/docs/post-meta.html index c56a52814..01adf8b7c 100644 --- a/website/themes/book/layouts/partials/docs/post-meta.html +++ b/website/themes/book/layouts/partials/docs/post-meta.html @@ -1,4 +1,4 @@ -{{ with .Date}} +{{ with .Date }}
{{ partial "docs/date" (dict "Date" . "Format" $.Site.Params.BookDateFormat) }}
{{ end }} @@ -11,3 +11,13 @@
{{ partial "docs/date" (dict "Date" . "Format" $.Site.Params.BookDateFormat)
{{ end }} {{ end }} + +{{ if .Params.image }} +

+ {{ with .Resources.GetMatch .Params.image }} + + {{ else }} + + {{ end }} +

+{{ end }} diff --git a/website/themes/book/layouts/posts/list.html b/website/themes/book/layouts/posts/list.html index 12207c861..badf0f618 100644 --- a/website/themes/book/layouts/posts/list.html +++ b/website/themes/book/layouts/posts/list.html @@ -2,7 +2,7 @@ {{ range sort .Paginator.Pages }}

- {{ .Title }} + {{ partial "docs/title.html" . }}

{{ partial "docs/post-meta" . }}

diff --git a/website/themes/book/layouts/posts/single.html b/website/themes/book/layouts/posts/single.html index 00df69702..301ca1eee 100644 --- a/website/themes/book/layouts/posts/single.html +++ b/website/themes/book/layouts/posts/single.html @@ -1,12 +1,10 @@ {{ define "main" }}

{{ end }} diff --git a/website/themes/book/layouts/shortcodes/button.html b/website/themes/book/layouts/shortcodes/button.html index 98d2cdda4..337a50f42 100644 --- a/website/themes/book/layouts/shortcodes/button.html +++ b/website/themes/book/layouts/shortcodes/button.html @@ -8,5 +8,5 @@ {{ $ref = relref $ . }} {{ end }} - {{ $.Inner }} + {{ $.Inner | markdownify }} diff --git a/website/themes/book/layouts/taxonomy/taxonomy.html b/website/themes/book/layouts/taxonomy/taxonomy.html index 12207c861..badf0f618 100644 --- a/website/themes/book/layouts/taxonomy/taxonomy.html +++ b/website/themes/book/layouts/taxonomy/taxonomy.html @@ -2,7 +2,7 @@ {{ range sort .Paginator.Pages }}