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1 | 1 | class Solution {
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2 |
| - public int minReorder(int n, int[][] connections) { |
3 |
| - Map<Integer, Set<Integer>> map = new HashMap<>(); |
4 |
| - Set<String> set = new HashSet<>(); |
5 |
| - for (int[] connection : connections) { |
6 |
| - map.computeIfAbsent(connection[0], k -> new HashSet<>()).add(connection[1]); |
7 |
| - map.computeIfAbsent(connection[1], k -> new HashSet<>()).add(connection[0]); |
8 |
| - set.add(connection[0] + "->" + connection[1]); |
9 |
| - } |
10 |
| - Queue<Integer> queue = new LinkedList<>(); |
11 |
| - queue.add(0); |
12 |
| - int numOfReorders = 0; |
13 |
| - boolean[] visited = new boolean[n]; |
14 |
| - visited[0] = true; |
15 |
| - while (!queue.isEmpty()) { |
16 |
| - int removed = queue.remove(); |
17 |
| - for (int connection : map.getOrDefault(removed, new HashSet<>())) { |
18 |
| - if (visited[connection]) { |
19 |
| - continue; |
| 2 | + public int minReorder(int n, int[][] connections) { |
| 3 | + Map<Integer, List<List<Integer>>> graph = new HashMap<>(); |
| 4 | + for (int[] conn : connections) { |
| 5 | + graph.computeIfAbsent(conn[0], k -> new ArrayList<>()).add(List.of(conn[1], 1)); |
| 6 | + graph.computeIfAbsent(conn[1], k -> new ArrayList<>()).add(List.of(conn[0], 0)); |
20 | 7 | }
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21 |
| - visited[connection] = true; |
22 |
| - if (!set.contains(connection + "->" + removed)) { |
23 |
| - numOfReorders++; |
| 8 | + int[] count = {0}; |
| 9 | + bfs(0, n, graph, count); |
| 10 | + return count[0]; |
| 11 | + } |
| 12 | + |
| 13 | + private void bfs(int node, int n, Map<Integer, List<List<Integer>>> graph, int[] count) { |
| 14 | + Queue<Integer> queue = new LinkedList<>(); |
| 15 | + boolean[] visited = new boolean[n]; |
| 16 | + visited[node] = true; |
| 17 | + queue.add(node); |
| 18 | + while (!queue.isEmpty()) { |
| 19 | + int removed = queue.remove(); |
| 20 | + for (List<Integer> conn : graph.getOrDefault(removed, new ArrayList<>())) { |
| 21 | + int neighbor = conn.get(0); |
| 22 | + int direction = conn.get(1); |
| 23 | + if (!visited[neighbor]) { |
| 24 | + count[0] += direction; |
| 25 | + visited[neighbor] = true; |
| 26 | + queue.add(neighbor); |
| 27 | + } |
| 28 | + } |
24 | 29 | }
|
25 |
| - queue.add(connection); |
26 |
| - } |
27 | 30 | }
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28 |
| - return numOfReorders; |
29 |
| - } |
30 | 31 | }
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