1990 UEFA European Under-18 Championship
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(Redirected from 1990 UEFA European Under-18 Football Championship)
Tournament details | |
---|---|
Host country | Hungary |
Dates | 24 July - 29 July |
Teams | 8 |
Final positions | |
Champions | Soviet Union (6th title) |
Runners-up | Portugal |
Third place | Spain |
Fourth place | England |
Tournament statistics | |
Matches played | 10 |
Goals scored | 25 (2.5 per match) |
The UEFA European Under-18 Championship 1990 Final Tournament was held in Hungary. It also served as the European qualification for the 1991 FIFA World Youth Championship.
Contents
Teams
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The following teams qualified for the tournament:
- Belgium
- England
- Hungary (host, but still qualified)
- Portugal
- Republic of Ireland
- Soviet Union
- Spain
- Sweden
Squads
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Quarter-finals
24 July 1990
|
Portugal | 1 – 1 | Hungary |
---|---|---|
Torres 47' | Szabados 44' | |
Penalties | ||
J. Costa Pilar Figo |
3–1 | Halmai |
Semifinals
Places 5-8
Places 1–4
Third Place Match
Final
29 July 1990
|
Soviet Union | 0 – 0 | Portugal |
---|---|---|
Penalties | ||
Pokhlebaev Kandaurov Loukine Sharan |
4–2 | Bento Figo Xavier |
1990 UEFA European Under-18 Championship |
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Soviet Union Sixth title |
Qualification to World Youth Championship
The six best performing teams qualified for the 1991 FIFA World Youth Championship.