Atom (measure theory)

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In mathematics, more precisely in measure theory, an atom is a measurable set which has positive measure and contains no set of smaller but positive measure. A measure which has no atoms is called non-atomic or atomless.

Definition

Given a measurable space (X, \Sigma) and a measure \mu on that space, a set A\subset X in \Sigma is called an atom if

\mu(A)>0

and for any measurable subset B \subset A with

\mu(B)<\mu(A)

the set B has measure zero.

Examples

  • Consider the set X={1, 2, ..., 9, 10} and let the sigma-algebra \Sigma be the power set of X. Define the measure \mu of a set to be its cardinality, that is, the number of elements in the set. Then, each of the singletons {i}, for i=1,2, ..., 9, 10 is an atom.
  • Consider the Lebesgue measure on the real line. This measure has no atoms.

Non-atomic measures

A measure which has no atoms is called non-atomic. In other words, a measure is non-atomic if for any measurable set A with  \mu (A) >0 there exists a measurable subset B of A such that

 \mu(A) > \mu (B) > 0. \,

A non-atomic measure with at least one positive value has an infinite number of distinct values, as starting with a set A with  \mu (A) >0 one can construct a decreasing sequence of measurable sets

A=A_1\supset A_2 \supset A_3 \supset \cdots

such that

\mu(A)=\mu(A_1) > \mu(A_2) > \mu(A_3) > \cdots > 0.

This may not be true for measures having atoms; see the first example above.

It turns out that non-atomic measures actually have a continuum of values. It can be proved that if μ is a non-atomic measure and A is a measurable set with \mu (A) >0, then for any real number b satisfying

\mu (A) \geq b \geq0\,

there exists a measurable subset B of A such that

\mu(B)=b.\,

This theorem is due to Wacław Sierpiński.[1][2] It is reminiscent of the intermediate value theorem for continuous functions.

Sketch of proof of Sierpiński's theorem on non-atomic measures. A slightly stronger statement, which however makes the proof easier, is that if (X,\Sigma, \mu) is a non-atomic measure space and \mu(X)=c, there exists a function S:[0, c]\to\Sigma that is monotone with respect to inclusion, and a right-inverse to \mu:\Sigma\to[0,\,c]. That is, there exists a one-parameter family of measurable sets S(t) such that for all 0\leq t \leq t'\leq c

S(t)\subset S(t'),
\mu\left (S(t)\right)=t.

The proof easily follows from Zorn's lemma applied to the set of all monotone partial sections to \mu :

\Gamma:=\{S:D\to\Sigma\; :\; D\subset[0,\,c],\, S\; \mathrm{ monotone }, \forall t\in D\; (\mu\left (S(t)\right)=t)\},

ordered by inclusion of graphs, \mathrm{graph}(S)\subset \mathrm{graph}(S'). It's then standard to show that every chain in \Gamma has an upper bound in \Gamma, and that any maximal element of \Gamma has domain [0,c], proving the claim.

See also

Notes

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References

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