Oh my, it WAS the meshgrid! Thank you so much! When reading the coordinates like: lat = FB.variables['lat'][:,:] lon = FB.variables['lon'][:,:]
And plotting (without meshgrid!): m.pcolormesh(lon, lat, masked_fb, latlon=True) it works! Now I feel stupid. And I think the longitudes and latitudes are not monotonic, but I don't know the way to check this, other than checking the array like lon[:] in terminal. Is there a better way? And thank you again! Bill Wang -- View this message in context: http://matplotlib.1069221.n5.nabble.com/Data-plotting-in-a-wrong-place-tp43580p43588.html Sent from the matplotlib - users mailing list archive at Nabble.com. ------------------------------------------------------------------------------ Open source business process management suite built on Java and Eclipse Turn processes into business applications with Bonita BPM Community Edition Quickly connect people, data, and systems into organized workflows Winner of BOSSIE, CODIE, OW2 and Gartner awards http://p.sf.net/sfu/Bonitasoft _______________________________________________ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
