1876 United States presidential election in Vermont
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 County Results
Hayes 50–60% 60–70% 70–80% 80–90%
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| Elections in Vermont |
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The 1876 United States presidential election in Vermont took place on November 7, 1876, as part of the 1876 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for president and vice president.
Vermont voted for the Republican nominee, Rutherford B. Hayes, over the Democratic nominee, Samuel J. Tilden. Hayes won Vermont by a margin of 36.92%.
With 68.30% of the popular vote, Vermont would be Hayes' strongest victory in terms of percentage in the popular vote.[1]
Results
[edit]| 1876 United States presidential election in Vermont[2] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Republican | Rutherford B. Hayes of Ohio | William A. Wheeler of New York | 44,091 | 68.30% | 5 | 100.00% | ||
| Democratic | Samuel J. Tilden of New York | Thomas A. Hendricks of Indiana | 20,254 | 31.38% | 0 | 0.00% | ||
| N/A | Others | Others | 208 | 0.32% | 0 | 0.00% | ||
| Total | 64,553 | 100.00% | 5 | 100.00% | ||||
See also
[edit]References
[edit]- ^ "1876 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
- ^ "1876 Presidential General Election Results - Vermont".
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