Skip to content

Update and rename Minimum sum partition to MinimumSumPartition.java #1383

New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

Merged
merged 1 commit into from Aug 2, 2020
Merged
Show file tree
Hide file tree
Changes from all commits
Commits
File filter

Filter by extension

Filter by extension

Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
78 changes: 0 additions & 78 deletions DynamicProgramming/Minimum sum partition

This file was deleted.

73 changes: 73 additions & 0 deletions DynamicProgramming/MinimumSumPartition.java
Original file line number Diff line number Diff line change
@@ -0,0 +1,73 @@
// Partition a set into two subsets such that the difference of subset sums is minimum

/*
Input: arr[] = {1, 6, 11, 5}
Output: 1
Explanation:
Subset1 = {1, 5, 6}, sum of Subset1 = 12
Subset2 = {11}, sum of Subset2 = 11

Input: arr[] = {36, 7, 46, 40}
Output: 23
Explanation:
Subset1 = {7, 46} ; sum of Subset1 = 53
Subset2 = {36, 40} ; sum of Subset2 = 76
*/

import java.util.*;
import java.lang.*;
import java.io.*;
class GFG
{
public static void main (String[] args)
{
Scanner sc=new Scanner(System.in);
int t=sc.nextInt();
while(t-->0)
{
int n=sc.nextInt();
int arr[]=new int[n];
int sum=0;
for(int i=0;i<n;i++)
{
arr[i]=sc.nextInt();
sum+=arr[i];
}
int ans[]=new int[sum];
ans=subset(arr,sum);
int min=Integer.MAX_VALUE;
for(int i=0;i<ans.length;i++)
min=Math.min(min,(sum-2*ans[i]));
System.out.println(min);
}
}
static int[] subset(int arr[],int sum)
{
int n=arr.length;
boolean dp[][]=new boolean[n+1][sum+1];
for(int i=0;i<=n;i++)
dp[i][0]=true;
for(int i=1;i<=sum;i++)
dp[0][i]=false;
// subset sum concept
for(int i=1;i<=n;i++)
{
for(int j=1;j<=sum;j++)
{
if(arr[i-1]<=j)
dp[i][j]=dp[i-1][j-arr[i-1]] || dp[i-1][j];
else
dp[i][j]=dp[i-1][j];
}
}
//storing last dp column whose value is true till sum/2
int index[]=new int[sum];
int p=0;
for(int i=0;i<=sum/2;i++)
{
if(dp[n][i]==true)
index[p++]=i;
}
return index;
}
}