TheAlgorithms · raklaptudirm · Sep 9, 2021 · Sep 6, 2021 · Sep 6, 2021 · Sep 6, 2021
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+/*
+    Problem statement and Explanation : https://www.geeksforgeeks.org/check-if-a-number-is-a-krishnamurthy-number-or-not-2/
+
+    krishnamurthy number is a number the sum of the all fectorial of the all dights is equal to the number itself.
+    145 => 1! + 4! + 5! = 1  + 24 + 120 = 145
+*/
+
+// factorail utility method.
+const factorial = (n) => {
+  let fact = 1
+  while (n !== 0) {
+    fact = fact * n
+    n--
+  }
+  return fact
+}
+
+/**
+ * krishnamurthy number is a number the sum of the factorial of the all dights is equal to the number itself.
+ * @param {Number} number a number for checking is krishnamurthy number or not.
+ * @returns return correspond boolean vlaue, if the number is krishnamurthy number return `true` else return `false`.
+ * @example 145 => 1! + 4! + 5! = 1  + 24 + 120 = 145
+ */
+const CheckKishnamurthyNumber = (number) => {
+  // firstly, check that input is a number or not.
+  if (typeof number !== 'number') {
+    return new TypeError('Argument is not a number.')
+  }
+  // create a variable to store the sum of all digits factorial.
+  let sumOfAllDigitFactorial = 0
+  // convert the number to string for convenience.
+  let newNumber = number
+  // Extract number digits using the remainder method.
+  while (newNumber > 0) {
+    const lastDigit = newNumber % 10
+    // calculate each digit factorial.
+    sumOfAllDigitFactorial += factorial(lastDigit)
+    newNumber = Math.floor(newNumber / 10)
+  }
+  // if the sumOftheFactorial is equal to the given number it means the number is a Krishnamurthy number.
+  return sumOfAllDigitFactorial === number
+}
+
+module.exports = CheckKishnamurthyNumber
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+/*
+    Problem statement and Explanation : https://en.wikipedia.org/wiki/Coprime_integers
+
+    In number theory, two integers a and b are coprime, relatively prime or
+    mutually prime if the only positive integer that is a divisor of both
+    of them is Consequently, any prime number that divides one of a
+    or b does not divide the other. This is equivalent to their greatest
+    common divisor (gcd) being. One says also a is prime to b or a
+    is coprime with b.
+*/
+
+// Here we use a GetEuclidGCD method as a utility.
+const GetEuclidGCD = (arg1, arg2) => {
+  let less = arg1 > arg2 ? arg2 : arg1
+  for (less; less >= 2; less--) {
+    if ((arg1 % less === 0) && (arg2 % less === 0)) return (less)
+  }
+  return (less)
+}
+
+// CoPrimeCheck function return the boolean in respect of the given number is co-prime or not.
+/**
+ * CoPrimeCheck function return the boolean in respect of the given number is co-prime or not.
+ * @param {Number} firstNumber first number for checking is prime or not.
+ * @param {Number} secondNumber second number for checking is prime or not.
+ * @returns return correspond boolean value, if both number are co-prime return `true`, else return `false`.
+ */
+const CoPrimeCheck = (firstNumber, secondNumber) => {
+  // firstly, check that input is a number or not.
+  if (typeof firstNumber !== 'number' || typeof secondNumber !== 'number') {
+    return new TypeError('Argument is not a number.')
+  }
+  /*
+    This is the most efficient algorithm for checking co-primes
+    if the GCD of both the numbers is 1 that means they are co-primes.
+    */
+  return GetEuclidGCD(firstNumber, secondNumber) === 1
+}
+
+module.exports = CoPrimeCheck