Skip to content

Conversation

fendorio
Copy link

@fendorio fendorio commented Oct 2, 2017

I've added an example of using WizardHandler.wizard(), specifically, i've added an example of using the function's name parameter to identify a specific wizard element in the view.

I've elaborated on the example of the usage of the  'WizardHandler.wizard' function, specifically, giving an example of using the name parameter to identify a specific wizard
Sign up for free to join this conversation on GitHub. Already have an account? Sign in to comment
Labels
None yet
Projects
None yet
Development

Successfully merging this pull request may close these issues.

1 participant