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“我们已经提过 auto 不能用于函数形参进行类型推导” 这里是否是表述错误呢?
The text was updated successfully, but these errors were encountered:
是的,他这里应该有点问题,C++20 之后可以进行函数形参类型推导
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C++14 中 auto 已经可以用于函数函数模板形参推导,只是局限于泛型 lambda 中。
auto
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问题描述
“我们已经提过 auto 不能用于函数形参进行类型推导” 这里是否是表述错误呢?
The text was updated successfully, but these errors were encountered: