sched, sysctl: Delete an unnecessary check before unregister_sysctl_table()

elfring · Ingo Molnar · commit 781b0203423c · 2015-08-03T12:21:21.000+02:00
The unregister_sysctl_table() function tests whether its argument is NULL and then returns immediately. Thus the test around the call is not needed. This issue was detected by using the Coccinelle software. Signed-off-by: Markus Elfring <elfring@users.sourceforge.net> Signed-off-by: Peter Zijlstra (Intel) <peterz@infradead.org> Cc: Linus Torvalds <torvalds@linux-foundation.org> Cc: Mike Galbraith <efault@gmx.de> Cc: Peter Zijlstra <peterz@infradead.org> Cc: Thomas Gleixner <tglx@linutronix.de> Link: http://lkml.kernel.org/r/5597877E.3060503@users.sourceforge.net Signed-off-by: Ingo Molnar <mingo@kernel.org>
diff --git a/kernel/sched/core.c b/kernel/sched/core.c
@@ -5311,8 +5311,7 @@ static void register_sched_domain_sysctl(void)
 /* may be called multiple times per register */
 static void unregister_sched_domain_sysctl(void)
 {
-	if (sd_sysctl_header)
-		unregister_sysctl_table(sd_sysctl_header);
+	unregister_sysctl_table(sd_sysctl_header);
 	sd_sysctl_header = NULL;
 	if (sd_ctl_dir[0].child)
 		sd_free_ctl_entry(&sd_ctl_dir[0].child);
