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Jan 16, 2021
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1 change: 1 addition & 0 deletions README.md
Original file line number Diff line number Diff line change
Expand Up @@ -338,6 +338,7 @@ _If you like this project, please leave me a star._ ★
|819|[Most Common Word](https://leetcode.com/problems/most-common-word/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_819.java) | |Easy| HashMap
|814|[Binary Tree Pruning](https://leetcode.com/problems/binary-tree-pruning/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_814.java) | |Medium| recursion, DFS
|811|[Subdomain Visit Count](https://leetcode.com/problems/subdomain-visit-count/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_811.java) | |Easy| HashMap
|809|[Expressive Words](https://leetcode.com/problems/expressive-words/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_809.java) | |Medium|
|807|[Max Increase to Keep City Skyline](https://leetcode.com/problems/max-increase-to-keep-city-skyline/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_807.java) | |Medium|
|806|[Number of Lines To Write String](https://leetcode.com/problems/number-of-lines-to-write-string/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_806.java) | |Easy|
|804|[Unique Morse Code Words](https://leetcode.com/problems/unique-morse-code-words/)|[Solution](../master/src/main/java/com/fishercoder/solutions/_804.java) | |Easy|
Expand Down
64 changes: 64 additions & 0 deletions src/main/java/com/fishercoder/solutions/_809.java
Original file line number Diff line number Diff line change
@@ -0,0 +1,64 @@
package com.fishercoder.solutions;

public class _809 {
public static class Solution1 {
public int expressiveWords (String S, String[] words ) {
int ans = 0;
for (String w : words) {
if (check(S, w)) {
ans++;
}
}
return ans;
}
private boolean check (String S, String w) {
int i = 0;
int j = 0;
/* Logic is to check whether character at same index of S and w are same
if same,
1. Find the consecutive number of occurrences of the char in S (say len1) and w ( say len2)
2. If len1 == len 2 , move to the next char in S and w
3. If len1 >= 3 and len2 < len1, means we can make the char in w stretchy to match len1
4. else, return false, because it's not possible to stretch the char in w
*/
while (i < S.length() && j < w.length()) {
char ch1 = S.charAt(i);
char ch2 = w.charAt(j);

int len1 = getLen(S, i);
int len2 = getLen(w, j);
if (ch1 == ch2) {
if (len1 == len2) {
i = i + len1;
j = j + len2;
}
else if (len1 >= 3 && len2 < len1) {
i = i + len1;
j = j + len2;
}
else {
return false;
}
}
else {
return false;
}
}
return i == S.length() && j == w.length();
}

private int getLen (String value, int i) {
i = i + 1;
int count = 1;
for(int j = i; j<value.length(); j++) {
if(value.charAt(j) == value.charAt(i-1)) {
count++;
}
else {
break;
}
}
return count;
}
}
}
25 changes: 25 additions & 0 deletions src/test/java/com/fishercoder/_809Test.java
Original file line number Diff line number Diff line change
@@ -0,0 +1,25 @@
package com.fishercoder;

import com.fishercoder.solutions._809;
import org.junit.BeforeClass;
import org.junit.Test;

import static junit.framework.TestCase.assertEquals;

public class _809Test {
private static _809.Solution1 solution1;
private String[] words;
private String S;

@BeforeClass
public static void setup() {
solution1 = new _809.Solution1();
}

@Test
public void test1() {
words = new String[] {"hello", "hi", "helo"};
S = "heeellooo";
assertEquals(1, solution1.expressiveWords(S, words));
}
}