fmt.Printf("%p", x) does not work if x has a String method. #1024
Labels
Comments
same is true of %d. it was a conscious choice to clean things up. i suspect this is working as intended; leaving for rob. Owner changed to r...@golang.org. Status changed to Accepted. |
Here's a related and to my mind more serious inconsistency.
Println of one argument is supposed to be like Printf with "%v\n" but
this program prints two different lines:
package main
import "fmt"
type T int
func (t T) Format(f fmt.State, c int) {
fmt.Fprintf(f, "-formatted-")
}
func main() {
fmt.Printf("%v\n", T(1))
fmt.Println(T(1))
}
|
|
This issue was closed by revision b21611b. Status changed to Fixed. |
This issue was closed.
Sign up for free
to subscribe to this conversation on GitHub.
Already have an account?
Sign in.
the following code prints "%p(string=hello)". this is a direct consequence of the recent changes to fmt to switch on type first, but it's not helpful behaviour and it's not easy to work around without importing reflect and rewriting fmtUintptrGetter. might i suggest that fmt.printField only check for Stringer/GoStringer when the verb can actually process a string. package main import "fmt" type T struct{} func main() { fmt.Printf("%p\n", &T{}) } func (x *T) String() string { return "hello" }The text was updated successfully, but these errors were encountered: