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0027: Remove Element #3

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30 changes: 30 additions & 0 deletions 0027-Remove_Element/main.ts
Original file line number Diff line number Diff line change
@@ -0,0 +1,30 @@
// let nums = [3, 2, 2, 3],
// val = 3,
// expectedNums = [2, 2];
let nums = [0, 1, 2, 2, 3, 0, 4, 2],
val = 2,
expectedNums = [0, 1, 3, 0, 4];

function removeElement(nums: number[], val: number): number {
let slowIndex = 0;
for (let fastIndex = 0; fastIndex < nums.length; fastIndex++) {
if (nums[fastIndex] !== val) {
nums[slowIndex] = nums[fastIndex];
slowIndex++;
}
}
return slowIndex;
}

let k = removeElement(nums, val);

console.assert(k === expectedNums.length, "Length mismatch");

nums.slice(0, k).sort((a, b) => a - b);

for (let i = 0; i < k; i++) {
console.assert(nums[i] === expectedNums[i], `Element mismatch at index ${i}`);
}

console.log(k);
console.log(nums);
50 changes: 50 additions & 0 deletions 0027-Remove_Element/readme.md
Original file line number Diff line number Diff line change
@@ -0,0 +1,50 @@
# 27. Remove Element

Given an integer array `nums` and an integer `val`, remove all occurrences of `val` in `nums` [in-place](https://en.wikipedia.org/wiki/In-place_algorithm). The order of the elements may be changed. Then return the number of elements in `nums` which are not equal to `val`.

Consider the number of elements in `nums` which are not equal to `val` be `k`, to get accepted, you need to do the following things:

- Change the array `nums` such that the first `k` elements of `nums` contain the elements which are not equal to `val`. The remaining elements of `nums` are not important as well as the size of `nums`.
- Return `k`.

### Custom Judge:

The judge will test your solution with the following code:

```
int[] nums = [...]; // Input array
int val = ...; // Value to remove
int[] expectedNums = [...]; // The expected answer with correct length.
// It is sorted with no values equaling val.

int k = removeElement(nums, val); // Calls your implementation

assert k == expectedNums.length;
sort(nums, 0, k); // Sort the first k elements of nums
for (int i = 0; i < actualLength; i++) {
assert nums[i] == expectedNums[i];
}
```

If all assertions pass, then your solution will be accepted.

### Example 1:

> <span style="color: white;">Input: </span>nums = [3, 2, 2, 3], val = 3<br>
> <span style="color: white;">Output: </span>2, nums = [2, 2, _, _]<br>
> <span style="color: white;">Explanation: </span>Your function should return k = 2, with the first two elements of nums being 2.<br>
> It does not matter what you leave beyond the returned k (hence they are underscores).

### Example 2:

> <span style="color: white;">Input: </span>nums = [0, 1, 2, 2, 3, 0, 4, 2], val = 2<br>
> <span style="color: white;">Output: </span>5, nums = [0, 1, 4, 0, 3, _, _, _]<br>
> <span style="color: white;">Explanation: </span>Your function should return k = 5, with the first five elements of nums containing 0, 0, 1, 3, and 4.<br>
Note that the five elements can be returned in any order.<br>
It does not matter what you leave beyond the returned k (hence they are underscores).

### Constraints:

- `0 <= nums.length <= 100`
- `0 <= nums[i] <= 50`
- `0 <= val <= 100`