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FIX str.decode in python2.6 does not take keyword arguments [backport to 1.4.x] #3850

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Dec 12, 2014
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FIX str.decode in python2.6 does not take keyword arguments [backport to 1.4.x] #3850

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2 changes: 1 addition & 1 deletion lib/matplotlib/type1font.py
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Original file line number Diff line number Diff line change
Expand Up @@ -216,7 +216,7 @@ def _parse(self):
# The spec calls this an ASCII format; in Python 2.x we could
# just treat the strings and names as opaque bytes but let's
# turn them into proper Unicode, and be lenient in case of high bytes.
convert = lambda x: x.decode('ascii', errors='replace')
convert = lambda x: x.decode('ascii')
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https://docs.python.org/2/library/stdtypes.html Seems to suggest that the problem is the keyword, not the error handling. I think this can be changed to x.decode('ascii', 'replace')

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https://docs.python.org/2/library/stdtypes.html#str.decode <-should be this link

for token, value in filtered:
if token is self._name and value.startswith(b'/'):
key = convert(value[1:])
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