"Any Type" not supported #36
Labels
Comments
|
@diogobaeder this is tricky one. I need to have #34 AnyOf supprt done first. |
|
No problem. I was actually trying to use "Any Type" as a hack in place of |
Merged
|
I'm also trying to use the any type. It's sort of working but I receive an unmarshaller warning that seems like it should just be removed? I'm using the following schema and data. TemplateField:
type: object
properties:
name:
type: string
default:
nullable: true{
"name": "foo",
"default": None
} |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment
"Any Type" is part of the specification ( https://swagger.io/docs/specification/data-models/data-types/#any ), however this library does not support it.
The problem seems that, when creating the
Schemafor a schema spec that has{}as its value (meaning "anything can be used as input here"), it is created with anobjecttype - see here: https://github.com/p1c2u/openapi-core/blob/master/openapi_core/schemas.py#L179 - it tries to infer "object" by default.After checking the schema types ( https://github.com/p1c2u/openapi-core/blob/master/openapi_core/enums.py#L27 ) I can see that "any" is not there.
Please let me know if you need help with implementing that.
Thanks,
Diogo
The text was updated successfully, but these errors were encountered: