United States presidential election in Kentucky, 1836

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Main article: United States presidential election, 1836
United States presidential election in Kentucky, 1836
← 1832 November 3 – December 7, 1836 1840 →
  WHenryHarrison.png MartinVanBuren.png
Nominee William Henry Harrison Martin Van Buren
Party Whig Democratic
Home state Ohio New York
Running mate Francis Granger Richard Johnson
Electoral vote 15 0
Popular vote 36,861 33,229
Percentage 52.59% 47.41%
Elections in Kentucky
Seal of Kentucky.svg
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The 1836 United States presidential election in Kentucky took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for President and Vice President.

Kentucky voted for Whig candidate William Henry Harrison over the Democratic candidate, Martin Van Buren. Harrison won Kentucky by a margin of 5.18%.

Results

United States presidential election in Kentucky, 1836[1]
Party Candidate Votes Percentage Electoral votes
Whig William Henry Harrison 36,861 52.59% 15
Democratic Martin Van Buren 33,229 47.41% 0
Totals 70,090 100.0% 15

References

  1. ↑ Lua error in package.lua at line 80: module 'strict' not found.
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