United States presidential election in Ohio, 1828

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Main article: United States presidential election, 1828
United States presidential election in Ohio, 1828
← 1824 October 31 – December 2, 1828 1832 →
  Andrew Jackson.jpg JohnQAdams.png
Nominee Andrew Jackson John Quincy Adams
Party Democratic National Republican
Home state Tennessee Massachusetts
Running mate John C. Calhoun Richard Rush
Electoral vote 16 0
Popular vote 67,597 63,396
Percentage 51.60% 48.40%

Lua error in package.lua at line 80: module 'strict' not found. The 1828 United States presidential election in Ohio took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose 16 representatives, or electors to the Electoral College, who voted for President and Vice President.

Ohio voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, John Quincy Adams. Jackson won Ohio by a margin of 3.2%.

Results

United States presidential election in Ohio, 1828[1]
Party Candidate Votes Percentage Electoral votes
Democratic Andrew Jackson 67,597 51.60% 16
National Republican John Quincy Adams 63,396 48.40% 0
Totals 130,993 100.0% 16

References

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  1. ↑ Lua error in package.lua at line 80: module 'strict' not found.
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